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\olchapter{sfr}{infinite}{Infinite Sets}\begin{editorial}This chapter on infinite sets is taken from Tim Button's \emph{OpenSet Theory}.\end{editorial}\olfileid{sfr}{infinite}{hilbert}\olsection{Hilbert's Hotel}The set of the natural numbers is obviously infinite. So, if we do notwant to \emph{help ourselves} to the natural numbers, our first stepmust be characterize an infinite set in terms that do not requirementioning the natural numbers themselves. Here is a nice approach,presented by Hilbert in a lecture from 1924. He asks us to imagine\begin{quote}[\ldots] a hotel with a finite number of rooms. All of these roomsshould be occupied by exactly one guest. If the guests now swap theirrooms somehow, [but] so that each room still contains no more than oneperson, then no rooms will become free, and the hotel-owner cannot inthis way create a new place for a newly arriving guest [\ldots\textparagraph \ldots]Now we stipulate that the hotel shall have infinitely many numberedrooms $1$, $2$, $3$, $4$, $5$, \dots, each of which is occupied byexactly one guest. As soon as a new guest comes along, the owner onlyneeds to move each of the old guests into the room associated with thenumber one higher, and room~$1$ will be free for the newly-arrivingguest.\begin{center}\begin{tikzpicture}[scale = .75]\foreach \x in {1, 2, 3, 4, 5, 6, 7, 8, 9}{\node (\x a) at (\x, 1) {\small{\x}};\node (\x b) at (\x, 2) {\small{\x}};}\node (dotsa) at (10, 1) {\small{\ldots}};\node (dotsb) at (10, 2) {\small{\ldots}};\draw[->] (1b)--(2a);\draw[->] (2b)--(3a);\draw[->] (3b)--(4a);\draw[->] (4b)--(5a);\draw[->] (5b)--(6a);\draw[->] (6b)--(7a);\draw[->] (7b)--(8a);\draw[->] (8b)--(9a);\draw[->] (9b)--(dotsa);\draw (1,1) circle (.4);\end{tikzpicture}\end{center}(published in \citealt[730]{EwaldSieg2013}; our translation)\end{quote}The crucial point is that Hilbert's Hotel has infinitely many rooms;and we can take his explanation to define what it means to say this.Indeed, this was Dedekind's approach (presented here, of course, withmassive anachronism; Dedekind's definition is from\citeyear{Dedekind1888}):\begin{defn}\ollabel{defn:DedekindInfinite}A set $A$ is \emph{Dedekind infinite} iff there is !!a{injection}from~$A$ to a proper subset of~$A$. That is, there is some $o \in A$and !!a{injection} $f \colon A \to A$ such that $o \notin \ran{f}$.\end{defn}\olfileid{sfr}{infinite}{dedekind}\olsection{Dedekind Algebras}We not only want natural numbers to be infinite; we want them to havecertain (algebraic) properties: they need to behave well underaddition, multiplication, and so forth.Dedekind's idea was to take the idea of the \emph{successor function}as basic, and then characterise the numbers as those with thefollowing properties:\begin{enumerate}\item There is a number, $0$, which is not the successor of any number\\i.e., $0 \notin \ran{s}$\\i.e., $\forall x\ s(x) \neq 0$\item Distinct numbers have distinct successors\\i.e., $s$ is !!a{injection}\\i.e., $\forall x \forall y (s(x) = s(y) \lif x = y)$\item\ollabel{repeatedapplication} Every number is obtained from$0$ by repeated applications of the successor function.\end{enumerate}The first two conditions are easy to deal with using first-order logic(see above). But we cannot deal with \olref{repeatedapplication} justusing first-order logic. Dedekind's breakthrough was to reformulatecondition \olref{repeatedapplication}, set-theoretically, as follows:\begin{enumerate}\item[3$'$.] The natural numbers are the smallest set that is\emph{closed under the successor function}: that is, if we apply$s$ to any !!{element} of the set, we obtain another !!{element}of the set.\end{enumerate}But we shall need to spell this out slowly.\begin{defn}\ollabel{Closure}For any function $f$, the set $X$ is $f$-\emph{closed} {iff}$(\forall x \in X)f(x) \in X$. Now define, for any $o$:$$\closureofunder{f}{o} = \bigcap\Setabs{X}{o \in X\text{ and }X\text{ is $f$-closed}}$$\end{defn}So $\closureofunder{f}{o}$ is the intersection of all the $f$-closedsets with $o$ as !!a{element}. Intuitively, then,$\closureofunder{f}{o}$ is the \emph{smallest} $f$-closed set with $o$as !!a{element}. This next result makes that intuitive thoughtprecise;\begin{lem}\ollabel{closureproperties}For any function $f$ and any $o \in A$:\begin{enumerate}\item\ollabel{closurehaselem} $o \in \closureofunder{f}{o}$; and\item\ollabel{closureclosed} $\closureofunder{f}{o}$ is $f$-closed; and\item\ollabel{closuresmallest} if $X$ is $f$-closed and $o \inX$, then $\closureofunder{f}{o} \subseteq X$\end{enumerate}\end{lem}\begin{proof}Note that there is at least one $f$-closed set with $o$ as !!a{element}, namely $\ran{f}\cup\{o\}$. So $\closureofunder{f}{o}$, the intersection of \emph{all}such sets, exists. We must now check\olref{closurehaselem}--\olref{closuresmallest}.Concerning \olref{closurehaselem}: $o \in \closureofunder{f}{o}$ as it is anintersection of sets which all have $o$ as !!a{element}.Concerning \olref{closureclosed}: suppose $x \in \closureofunder{f}{o}$. So if $o \in X$ and $X$ is $f$-closed, then $x \in X$, and now $f(x) \in X$ as $X$ is$f$-closed. So $f(x) \in \closureofunder{f}{o}$.Concerning \olref{closuresmallest}: quite generally, if $X\in C$ then $\bigcap C \subseteq X$.\end{proof}Using this, we can say:\begin{defn}A \emph{Dedekind algebra} is a set $A$ together with a function $f\colon A \to A$ and some $o \in A$ such that:\begin{enumerate}\item \ollabel{ded:proper} $o \notin \ran{f}$\item \ollabel{ded:injection} $f$ is !!a{injection}\item \ollabel{ded:closure} $A = \closureofunder{f}{o}$\end{enumerate}\end{defn}Since $A = \closureofunder{f}{o}$, our earlier result tells us that$A$ is the smallest $f$-closed set with $o$ as !!a{element}. Clearly aDedekind algebra is Dedekind infinite; just look at clauses\olref{ded:proper} and \olref{ded:injection} of the definition. Butthe more exciting fact is that any Dedekind infinite set can be turnedinto a Dedekind algebra.\begin{thm}\ollabel{thm:DedekindInfiniteAlgebra}If there is a Dedekind infinite set, then there is a Dedekind algebra.\end{thm}\begin{proof}Let $D$ be Dedekind infinite. So there is an injection $g \colon D \toD$ and an element $o \in D \setminus \ran{g}$. Now let $A =\closureofunder{g}{o}$; by \olref{closureproperties}, $A$ exists and $o \in A$. Let $f =\funrestrictionto{g}{A}$. We will show that $A, f, o$ comprise a Dedekindalgebra.Concerning \olref{ded:proper}: $o \notin \ran{g}$ and $\ran{f}\subseteq \ran{g}$ so $o\notin \ran{f}$.Concerning \olref{ded:injection}: $g$ is an injection on $D$; so $f\subseteq g$ must be an injection.Concerning \olref{ded:closure}: by \olref{closureproperties}, $A$ is $g$-closed; a fortiori, $A$ is $f$-closed. So $\closureofunder{f}{o} \subseteq A$ by \olref{closureproperties}. Since also $\closureofunder{f}{o}$ is $f$-closed and $f = \funrestrictionto{g}{A}$, it follows that $\closureofunder{f}{o}$ is $g$-closed. So $A \subseteq \closureofunder{f}{o}$ by \olref{closureproperties}.\end{proof}\olfileid{sfr}{infinite}{induction}\olsection[Arithmetical Induction]{Dedekind Algebras and Arithmetical Induction}Crucially, now, a Dedekind algebra---indeed, \emph{any} Dedekindalgebra---will serve as a surrogate for the natural numbers. This isthanks to the following trivial consequence:\begin{thm}[Arithmetical induction]\ollabel{thm:dedinfiniteinduction}Let $N, s, o$ comprise a Dedekind algebra. Then for any set $X$:\begin{center}if $o \in X$ and $(\forall {n} \in N \cap X){s}({n}) \in X$, {then} $N \subseteq X$.\end{center}\end{thm}\begin{proof}By the definition of a Dedekind algebra, $N = \closureofunder{s}{o}$.Now if both ${o} \in X$ and $(\forall {n} \in N)(n \in X \lif{s}({n}) \in X)$, then $N = \closureofunder{s}{o} \subseteq X$.\end{proof}Since induction is characteristic of the natural numbers, the point isthis. Given any Dedekind infinite set, we can form a Dedekind algebra,and use that algebra as our surrogate for the natural numbers.Admittedly, \olref{thm:dedinfiniteinduction} formulates induction in\emph{set-theoretic} terms. But we can easily put the principle interms which might be more familiar:\begin{cor}\ollabel{natinductionschema}Let $N, s, o$ comprise a Dedekind algebra. Then for any formula$\phi(x)$, which may have parameters:\begin{center}if $\phi(o)$ and $(\forall {n} \in N)(\phi(n)\lif\phi({s}({n})))$, {then} $(\forall n \in N)\phi(n)$\end{center}\end{cor}\begin{proof}Let $X = \Setabs{n \in N}{\phi(n)}$, and now use\olref{thm:dedinfiniteinduction}\end{proof}In this result, we spoke of a formula ``having parameters''. What thismeans, roughly, is that for any objects $c_1, \ldots, c_k$, we canwork with $\phi(x, c_1, \ldots, c_k)$. More precisely, we can statethe result without mentioning ``parameters'' as follows. For anyformula $\phi(x, v_1, \ldots, v_k)$, whose free variables are alldisplayed, we have:\begin{align*}\forall v_1 \ldots \forall v_k((&\phi(o, v_1,\ldots, v_k) \land {}\\& (\forall x \in N)(\phi(x,v_1, \ldots, v_k) \lif \phi(s(x), v_1,\ldots, v_k))) \lif {}\\&\hspace{3em} (\forall x \in N)\phi(x, v_1,\ldots, v_k))\end{align*}Evidently, speaking of ``having parameters'' can make things mucheasier to read. (In \olref[sth][][]{part}, we will use this devicerather frequently.)Returning to Dedekind algebras: given any Dedekind algebra, we canalso define the usual arithmetical functions of addition,multiplication and exponentiation. This is non-trivial, however, andit involves the technique of \emph{recursive definition}. That is atechnique which we shall introduce and justify much later, and in amuch more general context. (Enthusiasts might want to revisit thisafter \olref[sth][ord-arithmetic][]{chap}, or perhaps read an alternativetreatment, such as \citealt[pp.~95--8]{Potter2004}.) But, where $N, s, o$comprise a Dedekind algebra, we will ultimately be able to stipulate thefollowing:\begin{align*}{a} + {o} &= {a} & & & {a} \times {o} &= {o} & & & {a}^{o} &= s(o)\\{a} + {s}({b}) &= {s}({a}+{b}) &&& {a} \times {s}({b}) &= ({a}\times {b}) + {a} & & & {a}^{{s}({b})} &= {a}^{b} \times {a}\end{align*}and show that these behave as one would hope.\olfileid{sfr}{infinite}{dedekindsproof}\olsection[Dedekind's ``Proof'']{Dedekind's ``Proof'' of theExistence of an Infinite Set}In this chapter, we have offered a set-theoretic treatment of thenatural numbers, in terms of Dedekind algebras. In\olref[arith][ref]{sec}, we reflected on the philosophicalsignificance of the arithmetisation of analysis (among other things).Now we should reflect on the significance of what we have achievedhere.Throughout \olref[sfr][arith][]{chap}, we took the natural numbers asgiven, and used them to construct the integers, rationals, and reals,explicitly. In this chapter, we have not given an explicitconstruction of the natural numbers. We have just shown that,\emph{given any Dedekind infinite set}, we can define a set which willbehave just like we want~$\Nat$ to behave.Obviously, then, we cannot claim to have answered a metaphysicalquestion, such as \emph{which objects are the natural numbers}. Butthat's a good thing. After all, in \olref[sfr][arith][ref]{sec}, weemphasized that we would be wrong to think of the definition of$\Real$ as the set of Dedekind cuts as a \emph{discovery}, rather thana convenient stipulation. The crucial observation is that the Dedekindcuts exemplify the key mathematical properties of the realnumbers. So too here: the crucial observation is that \emph{any}Dedekind algebra exemplifies the key mathematical properties of thenatural numbers. (Indeed, Dedekind pushed this point home by provingthat all Dedekind algebras are \emph{isomorphic} (\citeyear[Theorems132--3]{Dedekind1888}). It is no surprise, then, that manycontemporary ``structuralists'' cite Dedekind as a forerunner.)Moreover, we have shown how to embed the theory of the naturalnumbers into a na\"ive simple set theory, which itself still remainsrather informal, but which doesn't (apparently) assume the naturalnumbers as given. So, we may be on the way to realising Dedekind'sown ambitious project, which he explained thus:\begin{quote}In science nothing capable of proof ought to be believed withoutproof. Though this demand seems reasonable, I cannot regard it ashaving been met even in the most recent methods of laying thefoundations of the simplest science; viz., that part of logicwhich deals with the theory of numbers. In speaking of arithmetic(algebra, analysis) as merely a part of logic I mean to imply thatI consider the number-concept entirely independent of the notionsor intuitions of space and time---that I rather consider it animmediate product of the pure laws of thought.\citep[preface]{Dedekind1888}\end{quote}Dedekind's bold idea is this. We have just shown how to build thenatural numbers using (na\"ive) set theory alone. In\olref[sfr][arith][]{chap}, we saw how to construct the reals giventhe natural numbers and some set theory. So, perhaps, ``arithmetic(algebra, analysis)'' turn out to be ``merely a part of logic'' (inDedekind's extended sense of the word ``logic'').That's the idea. But hold on for a moment. Our construction of aDedekind algebra (our surrogate for the natural numbers) isconditional on the existence of a Dedekind infinite set. (Just lookback to \olref[sfr][infinite][dedekind]{thm:DedekindInfiniteAlgebra}.)Unless the existence of a Dedekind infinite set can be established via``logic'' or ``the pure laws of thought'', the project stalls.So, \emph{can} the existence of a Dedekind infinite set be establishedby ``the pure laws of thought''? Here was Dedekind's effort:\begin{quote}My own realm of thoughts, i.e., the totality $S$ of all things whichcan be objects of my thought, is infinite. For if $s$ signifies anelement of~$S$, then the thought $s'$ that~$s$ can be an object ofmy thought, is itself an element of~$S$. If we regard this as animage $\phi(s)$ of the element~$s$, then \dots~$S$ is [Dedekind]infinite, which was to be proved.\citep[\S66]{Dedekind1888}\end{quote}This is quite an astonishing thing to find in the middle of a bookwhich largely consists of highly rigorous mathematical proofs. Tworemarks are worth making.First: this ``proof'' scarcely has what we would now recognize as a``mathematical'' character. It speaks of psychological objects(thoughts), and merely \emph{possible} ones at that.Second: at least as we have presented Dedekind algebras, this``proof'' has a straightforward technical shortcoming. If Dedekind'sargument is successful, it establishes only that there are infinitelymany things (specifically, infinitely many thoughts). But Dedekindalso needs to give us a reason to regard~$S$ as a single \emph{set},with infinitely many !!{element}s, rather than thinking of~$S$ as\emph{some things} (in the plural).The fact that Dedekind did not see a gap here might suggest that hisuse of the word ``totality'' does not precisely track \emph{our} useof the word ``set''.\footnote{Indeed, we have other reasons to thinkit did not; see \citet[p.~23]{Potter2004}.} But this would not betoo surprising. The project we have pursued in the last twochapters---a ``construction'' of the naturals, and from them a``construction'' of the integers, reals and rationals---has all beencarried out na\"ively. We have helped ourselves to this set, or thatset, as and when we have needed them, without laying down many generalprinciples concerning exactly which sets exist, and when. But we knowthat we need \emph{some} general principles, for otherwise we willfall into Russell's Paradox.The time has come for us to outgrow our na\"ivety.\olfileid{sfr}{infinite}{card-sb}\olsection{Appendix: Proving Schr\"oder-Bernstein}Before we depart from na\"ive set theory, we have one last na\"ive(but sophisticated!) proof to consider. This is a proof ofSchr\"oder-Bernstein (\olref[sfr][siz][sb]{thm:schroder-bernstein}): if$\cardle{A}{B}$ and $\cardle{B}{A}$ then $\cardeq{A}{B}$; i.e., given!!{injection}s $f \colon A \to B$ and $g \colon B \to A$ there is!!a{bijection} $h \colon A \to B$.In this chapter, we followed Dedekind's notion of \emph{closures}. Infact, Dedekind provided a lovely proof of Schr\"oder-Bernstein using this notion, and wewill present it here. The proof closely follows\citet[pp.~157--8]{Potter2004}, if you want a slightly different butessentially similar treatment. A little googling will also convinceyou that this is a theorem---rather like the irrationality of$\sqrt{2}$---for which \emph{many} interesting and different proofsexist.Using similar notation as \olref[sfr][infinite][dedekind]{Closure},let\[\Closureofunder{f}{B} = \bigcap \Setabs{X}{B \subseteq X\text{ and $X$ is $f$-closed}}\]for each set $B$ and function~$f$. Defined thus,$\Closureofunder{f}{B}$ is the smallest $f$-closed set containing~$B$,in that:\begin{lem}\ollabel{Closureprops}For any function $f$, and any $B$:\begin{enumerate}\item\ollabel{Closurehaselem} $B \subseteq \Closureofunder{f}{B}$; and\item\ollabel{Closureclosed} $\Closureofunder{f}{B}$ is $f$-closed; and\item\ollabel{Closuresmallest} if $X$ is $f$-closed and $B\subseteq X$, then $\Closureofunder{f}{B} \subseteq X$.\end{enumerate}\end{lem}\begin{proof}Exactly as in \olref[sfr][infinite][dedekind]{closureproperties}.\end{proof}We need one last fact to get to Schr\"oder-Bernstein:\begin{prop}\ollabel{sbhelper}If $A \subseteq B \subseteq C$ and $A \approx C$, then $\cardeq{\cardeq{A}{B}}{C}$.\end{prop}\begin{proof}Given !!a{bijection} $f \colon C \to A$, let $F =\Closureofunder{f}{C \setminus B}$ and define a function $g$ withdomain $C$ as follows:\[g(x) =\begin{cases}f(x) &\text{if $x \in F$}\\x & \text{otherwise}\end{cases}\]We'll show that $g$ is !!a{bijection} from $C \to B$, from which itwill follow that $\comp{f^{-1}}{g} \colon A \to B$ is !!a{bijection},completing the proof.First we claim that if $x \in F$ but $y\notin F$ then $g(x) \neqg(y)$. For reductio suppose otherwise, so that $y = g(y) = g(x) =f(x)$. Since $x \in F$ and $F$ is $f$-closed by \olref{Closureprops},we have $y = f(x) \in F$, a contradiction.Now suppose $g(x) = g(y)$. So, by the above, $x \in F$ iff $y \in F$.If $x, y \in F$, then $f(x) = g (x) = g(y) = f(y)$ so that $x = y$since $f$ is !!a{bijection}. If $x, y \notin F$, then $x = g(x) =g(y) = y$. So $g$ is !!a{injection}.It remains to show that $\ran{g} = B$. So fix $x \in B \subseteq C$.If $x \notin F$, then $g(x) = x$. If $x \in F$, then $x = f(y)$ forsome $y \in F$, since otherwise $F \setminus \{x\}$ would be $f$-closed and extend $C\setminus B$, which is impossible by \olref{Closureprops}; now $g(y) = f(y) = x$.\end{proof}Finally, here is the proof of the main result. Recall that given afunction $h$ and set $D$, we define $\funimage{h}{D} = \Setabs{h(x)}{x\in D}$.\begin{proof}[Proof of Schr\"oder-Bernstein] Let $f \colon A \to B$and $g \colon B \to A$ be !!{injection}s. Since $\funimage{f}{A}\subseteq B$ we have that $\funimage{g}{\funimage{f}{A}} \subseteqg[B] \subseteq A$. Also, $\comp{f}{g} \colon A \to\funimage{g}{\funimage{f}{A}}$ is an !!{injection} since both $g$ and$f$ are; and indeed $\comp{f}{g}$ is !!a{bijection}, just by the waywe defined its codomain. So$\cardeq{\funimage{g}{\funimage{f}{A}}}{A}$, and hence by\olref{sbhelper} there is !!a{bijection} $h \colon A \to\funimage{g}{B}$. Moreover, $g^{-1}$ is !!a{bijection}$\funimage{g}{B} \to B$. So $\comp{h}{g^{-1}} \colon A \to B$ is!!a{bijection}.\end{proof}\OLEndPartHook
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structure-00048\olchapter{Infinite Sets}
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structure-00049\olsection{Hilbert's Hotel}Line 14 · source-correction · records
TR007-SOURCE-PROSE-001must be characterize an infinite set in terms that do not requireLine 25 · formula-context · records
projected-formula-0002755 projected-formula-0002756 projected-formula-0002757 projected-formula-0002758 projected-formula-0002759Now we stipulate that the hotel shall have infinitely many numberedLine 26 · formula · records
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projected-formula-0002760number one higher, and room~$1$ will be free for the newly-arrivingLine 30 · formula-context · records
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projected-env-000400 projected-formula-0002761\begin{defn}\ollabel{defn:DedekindInfinite}Line 61 · formal-object, formula, formula-context · records
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projected-env-000400 projected-formula-0002765 projected-formula-0002766\end{defn}
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projected-formula-0002767 projected-formula-0002768\item There is a number, $0$, which is not the successor of any numberLine 21 · formula, formula-context · records
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projected-formula-0002768 projected-formula-0002769\\i.e., $\forall x\ s(x) \neq 0$Line 23 · formula-context · records
projected-formula-0002769 projected-formula-0002770\item Distinct numbers have distinct successorsLine 24 · formula, formula-context · records
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projected-formula-0002770 projected-formula-0002771\\i.e., $\forall x \forall y (s(x) = s(y) \lif x = y)$Line 26 · formula-context · records
projected-formula-0002771 projected-formula-0002772\item\ollabel{repeatedapplication} Every number is obtained fromLine 27 · formula · records
projected-formula-0002772$0$ by repeated applications of the successor function.Line 28 · formula-context · records
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projected-formula-0002773\begin{enumerate}Line 34 · formula · records
projected-formula-0002773\item[3$'$.] The natural numbers are the smallest set that isLine 35 · formula-context · records
projected-formula-0002773 projected-formula-0002774\emph{closed under the successor function}: that is, if we applyLine 36 · formula · records
projected-formula-0002774$s$ to any !!{element} of the set, we obtain another !!{element}Line 37 · formula-context · records
projected-formula-0002774of the set.Line 41 · formal-object, formula-context · records
projected-env-000403 projected-formula-0002775 projected-formula-0002776 projected-formula-0002777\begin{defn}\ollabel{Closure}Line 42 · formal-object, formula, formula-context · records
projected-env-000403 projected-formula-0002775 projected-formula-0002776 projected-formula-0002777 projected-formula-0002778 projected-formula-0002779For any function $f$, the set $X$ is $f$-\emph{closed} {iff}Line 43 · formal-object, formula, formula-context · records
projected-env-000403 projected-formula-0002775 projected-formula-0002776 projected-formula-0002777 projected-formula-0002778 projected-formula-0002779 projected-formula-0002780$(\forall x \in X)f(x) \in X$. Now define, for any $o$:Line 44 · formal-object, formula, formula-context · records
projected-env-000403 projected-formula-0002778 projected-formula-0002779 projected-formula-0002780$$\closureofunder{f}{o} = \bigcap\Setabs{X}{o \in X\text{ and }XLine 45 · formal-object, formula-context · records
projected-env-000403 projected-formula-0002780\text{ is $f$-closed}}$$Line 46 · formal-object · records
projected-env-000403\end{defn}Line 48 · formula, formula-context · records
projected-formula-0002781 projected-formula-0002782 projected-formula-0002783So $\closureofunder{f}{o}$ is the intersection of all the $f$-closedLine 49 · formula, formula-context · records
projected-formula-0002781 projected-formula-0002782 projected-formula-0002783 projected-formula-0002784 projected-formula-0002785 projected-formula-0002786sets with $o$ as !!a{element}. Intuitively, then,Line 50 · formula, formula-context · records
projected-formula-0002783 projected-formula-0002784 projected-formula-0002785 projected-formula-0002786$\closureofunder{f}{o}$ is the \emph{smallest} $f$-closed set with $o$Line 51 · formula-context · records
projected-formula-0002784 projected-formula-0002785 projected-formula-0002786as !!a{element}. This next result makes that intuitive thoughtLine 53 · formal-object, formula-context · records
projected-env-000405 projected-formula-0002787 projected-formula-0002788\begin{lem}\ollabel{closureproperties}Line 54 · formal-object, formula · records
projected-env-000405 projected-formula-0002787 projected-formula-0002788For any function $f$ and any $o \in A$:Line 55 · formal-object, formula-context · records
projected-env-000405 projected-formula-0002787 projected-formula-0002788 projected-formula-0002789\begin{enumerate}Line 56 · formal-object, formula, formula-context · records
projected-env-000405 projected-formula-0002789 projected-formula-0002790 projected-formula-0002791\item\ollabel{closurehaselem} $o \in \closureofunder{f}{o}$; andLine 57 · formal-object, formula, formula-context · records
projected-env-000405 projected-formula-0002789 projected-formula-0002790 projected-formula-0002791 projected-formula-0002792 projected-formula-0002793 projected-formula-0002794\item\ollabel{closureclosed} $\closureofunder{f}{o}$ is $f$-closed; andLine 58 · formal-object, formula, formula-context · records
projected-env-000405 projected-formula-0002790 projected-formula-0002791 projected-formula-0002792 projected-formula-0002793 projected-formula-0002794 projected-formula-0002795\item\ollabel{closuresmallest} if $X$ is $f$-closed and $o \inLine 59 · formal-object, formula, formula-context · records
projected-env-000405 projected-formula-0002792 projected-formula-0002793 projected-formula-0002794 projected-formula-0002795X$, then $\closureofunder{f}{o} \subseteq X$Line 60 · formal-object, formula-context · records
projected-env-000405 projected-formula-0002795\end{enumerate}Line 61 · formal-object · records
projected-env-000405\end{lem}Line 63 · formula-context · records
projected-formula-0002796 projected-formula-0002797 projected-formula-0002798\begin{proof}Line 64 · formula, formula-context · records
projected-formula-0002796 projected-formula-0002797 projected-formula-0002798 projected-formula-0002799Note that there is at least one $f$-closed set with $o$ as !!a{element}, namely $\ran{f}\cupLine 65 · formula, formula-context · records
projected-formula-0002796 projected-formula-0002797 projected-formula-0002798 projected-formula-0002799\{o\}$. So $\closureofunder{f}{o}$, the intersection of \emph{all}Line 66 · formula-context · records
projected-formula-0002799such sets, exists. We must now checkLine 67 · reference · records
reference-000113 reference-000114[olref reference to sfr:infinite:dedekind:closurehaselem][olref reference to sfr:infinite:dedekind:closuresmallest]Line 69 · formula, formula-context, reference · records
projected-formula-0002800 projected-formula-0002801 reference-000115Concerning \olref{closurehaselem}: $o \in \closureofunder{f}{o}$ as it is an[olref reference to sfr:infinite:dedekind:closurehaselem]Line 70 · formula, formula-context · records
projected-formula-0002800 projected-formula-0002801intersection of sets which all have $o$ as !!a{element}.Line 72 · formula, formula-context, reference · records
projected-formula-0002802 projected-formula-0002803 projected-formula-0002804 projected-formula-0002805 projected-formula-0002806 projected-formula-0002807 projected-formula-0002808 projected-formula-0002809 projected-formula-0002810 reference-000116Concerning \olref{closureclosed}: suppose $x \in \closureofunder{f}{o}$. So if $o \in X$ and $X$ is $f$-closed, then $x \in X$, and now $f(x) \in X$ as $X$ is[olref reference to sfr:infinite:dedekind:closureclosed]Line 73 · formula, formula-context · records
projected-formula-0002802 projected-formula-0002803 projected-formula-0002804 projected-formula-0002805 projected-formula-0002806 projected-formula-0002807 projected-formula-0002808 projected-formula-0002809 projected-formula-0002810$f$-closed. So $f(x) \in \closureofunder{f}{o}$.Line 75 · formula, formula-context, reference · records
projected-formula-0002811 projected-formula-0002812 reference-000117Concerning \olref{closuresmallest}: quite generally, if $X[olref reference to sfr:infinite:dedekind:closuresmallest]Line 76 · formula, formula-context · records
projected-formula-0002811 projected-formula-0002812\in C$ then $\bigcap C \subseteq X$.Line 77 · formula-context · records
projected-formula-0002812\end{proof}Line 81 · formal-object, formula-context · records
projected-env-000408 projected-formula-0002813 projected-formula-0002814\begin{defn}Line 82 · formal-object, formula, formula-context · records
projected-env-000408 projected-formula-0002813 projected-formula-0002814 projected-formula-0002815A \emph{Dedekind algebra} is a set $A$ together with a function $fLine 83 · formal-object, formula, formula-context · records
projected-env-000408 projected-formula-0002813 projected-formula-0002814 projected-formula-0002815\colon A \to A$ and some $o \in A$ such that:Line 84 · formal-object, formula-context · records
projected-env-000408 projected-formula-0002815 projected-formula-0002816\begin{enumerate}Line 85 · formal-object, formula, formula-context · records
projected-env-000408 projected-formula-0002816 projected-formula-0002817\item \ollabel{ded:proper} $o \notin \ran{f}$Line 86 · formal-object, formula, formula-context · records
projected-env-000408 projected-formula-0002816 projected-formula-0002817 projected-formula-0002818\item \ollabel{ded:injection} $f$ is !!a{injection}Line 87 · formal-object, formula, formula-context · records
projected-env-000408 projected-formula-0002817 projected-formula-0002818\item \ollabel{ded:closure} $A = \closureofunder{f}{o}$Line 88 · formal-object, formula-context · records
projected-env-000408 projected-formula-0002818\end{enumerate}Line 89 · formal-object · records
projected-env-000408\end{defn}Line 91 · formula, formula-context · records
projected-formula-0002819 projected-formula-0002820 projected-formula-0002821 projected-formula-0002822Since $A = \closureofunder{f}{o}$, our earlier result tells us thatLine 92 · formula, formula-context · records
projected-formula-0002819 projected-formula-0002820 projected-formula-0002821 projected-formula-0002822$A$ is the smallest $f$-closed set with $o$ as !!a{element}. Clearly aLine 93 · formula-context · records
projected-formula-0002820 projected-formula-0002821 projected-formula-0002822Dedekind algebra is Dedekind infinite; just look at clausesLine 94 · reference · records
reference-000118 reference-000119[olref reference to sfr:infinite:dedekind:ded:injection][olref reference to sfr:infinite:dedekind:ded:proper]Line 98 · formal-object · records
projected-env-000409\begin{thm}\ollabel{thm:DedekindInfiniteAlgebra}Line 99 · formal-object · records
projected-env-000409If there is a Dedekind infinite set, then there is a Dedekind algebra.Line 100 · formal-object · records
projected-env-000409\end{thm}Line 102 · formula-context · records
projected-formula-0002823 projected-formula-0002824\begin{proof}Line 103 · formula, formula-context · records
projected-formula-0002823 projected-formula-0002824 projected-formula-0002825 projected-formula-0002826Let $D$ be Dedekind infinite. So there is an injection $g \colon D \toLine 104 · formula, formula-context · records
projected-formula-0002823 projected-formula-0002824 projected-formula-0002825 projected-formula-0002826 projected-formula-0002827 projected-formula-0002828 projected-formula-0002829D$ and an element $o \in D \setminus \ran{g}$. Now let $A =Line 105 · formula, formula-context, reference · records
projected-formula-0002825 projected-formula-0002826 projected-formula-0002827 projected-formula-0002828 projected-formula-0002829 projected-formula-0002830 reference-000120[olref reference to sfr:infinite:dedekind:closureproperties]\closureofunder{g}{o}$; by \olref{closureproperties}, $A$ exists and $o \in A$. Let $f =Line 106 · formula, formula-context · records
projected-formula-0002827 projected-formula-0002828 projected-formula-0002829 projected-formula-0002830\funrestrictionto{g}{A}$. We will show that $A, f, o$ comprise a DedekindLine 107 · formula-context · records
projected-formula-0002830algebra.Line 109 · formula, formula-context, reference · records
projected-formula-0002831 projected-formula-0002832 projected-formula-0002833 reference-000121Concerning \olref{ded:proper}: $o \notin \ran{g}$ and $\ran{f}[olref reference to sfr:infinite:dedekind:ded:proper]Line 110 · formula, formula-context · records
projected-formula-0002831 projected-formula-0002832 projected-formula-0002833\subseteq \ran{g}$ so $o\notin \ran{f}$.Line 112 · formula, reference · records
projected-formula-0002834 projected-formula-0002835 projected-formula-0002836 reference-000122Concerning \olref{ded:injection}: $g$ is an injection on $D$; so $f[olref reference to sfr:infinite:dedekind:ded:injection]Line 113 · formula-context · records
projected-formula-0002834 projected-formula-0002835 projected-formula-0002836\subseteq g$ must be an injection.Line 115 · formula, reference · records
projected-formula-0002837 projected-formula-0002838 projected-formula-0002839 projected-formula-0002840 projected-formula-0002841 projected-formula-0002842 projected-formula-0002843 projected-formula-0002844 projected-formula-0002845 projected-formula-0002846 projected-formula-0002847 reference-000123 reference-000124 reference-000125 reference-000126Concerning \olref{ded:closure}: by \olref{closureproperties}, $A$ is $g$-closed; a fortiori, $A$ is $f$-closed. So $\closureofunder{f}{o} \subseteq A$ by \olref{closureproperties}. Since also $\closureofunder{f}{o}$ is $f$-closed and $f = \funrestrictionto{g}{A}$, it follows that $\closureofunder{f}{o}$ is $g$-closed. So $A \subseteq \closureofunder{f}{o}$ by \olref{closureproperties}.[olref reference to sfr:infinite:dedekind:closureproperties][olref reference to sfr:infinite:dedekind:ded:closure]Line 116 · formula-context · records
projected-formula-0002837 projected-formula-0002838 projected-formula-0002839 projected-formula-0002840 projected-formula-0002841 projected-formula-0002842 projected-formula-0002843 projected-formula-0002844 projected-formula-0002845 projected-formula-0002846 projected-formula-0002847\end{proof}
content/sets-functions-relations/infinite/dedekind-induction.tex
44 exact source-coordinate anchors materialized from the accepted slice ledgers.
Line 10 · structure · records
structure-00051\olsection{Dedekind Algebras and Arithmetical Induction}Line 16 · formal-object, formula-context · records
projected-env-000412 projected-formula-0002848 projected-formula-0002849\begin{thm}[Arithmetical induction]\ollabel{thm:dedinfiniteinduction}Line 17 · formal-object, formula · records
projected-env-000412 projected-formula-0002848 projected-formula-0002849Let $N, s, o$ comprise a Dedekind algebra. Then for any set $X$:Line 18 · formal-object, formula-context · records
projected-env-000412 projected-formula-0002848 projected-formula-0002849 projected-formula-0002850 projected-formula-0002851 projected-formula-0002852\begin{center}Line 19 · formal-object, formula · records
projected-env-000412 projected-formula-0002850 projected-formula-0002851 projected-formula-0002852if $o \in X$ and $(\forall {n} \in N \cap X){s}({n}) \in X$, {then} $N \subseteq X$.Line 20 · formal-object, formula-context · records
projected-env-000412 projected-formula-0002850 projected-formula-0002851 projected-formula-0002852\end{center}Line 21 · formal-object · records
projected-env-000412\end{thm}Line 23 · formula-context · records
projected-formula-0002853\begin{proof}Line 24 · formula, formula-context · records
projected-formula-0002853 projected-formula-0002854 projected-formula-0002855By the definition of a Dedekind algebra, $N = \closureofunder{s}{o}$.Line 25 · formula, formula-context · records
projected-formula-0002853 projected-formula-0002854 projected-formula-0002855 projected-formula-0002856Now if both ${o} \in X$ and $(\forall {n} \in N)(n \in X \lifLine 26 · formula, formula-context · records
projected-formula-0002854 projected-formula-0002855 projected-formula-0002856{s}({n}) \in X)$, then $N = \closureofunder{s}{o} \subseteq X$.Line 27 · formula-context · records
projected-formula-0002856\end{proof}Line 33 · reference · records
reference-000127[olref reference to sfr:infinite:induction:thm:dedinfiniteinduction]Line 37 · formal-object, formula-context · records
projected-env-000415 projected-formula-0002857\begin{cor}\ollabel{natinductionschema}Line 38 · formal-object, formula, formula-context · records
projected-env-000415 projected-formula-0002857 projected-formula-0002858Let $N, s, o$ comprise a Dedekind algebra. Then for any formulaLine 39 · formal-object, formula, formula-context · records
projected-env-000415 projected-formula-0002857 projected-formula-0002858$\phi(x)$, which may have parameters:Line 40 · formal-object, formula-context · records
projected-env-000415 projected-formula-0002858 projected-formula-0002859 projected-formula-0002860\begin{center}Line 41 · formal-object, formula, formula-context · records
projected-env-000415 projected-formula-0002859 projected-formula-0002860 projected-formula-0002861if $\phi(o)$ and $(\forall {n} \in N)(\phi(n)\lifLine 42 · formal-object, formula, formula-context · records
projected-env-000415 projected-formula-0002859 projected-formula-0002860 projected-formula-0002861\phi({s}({n})))$, {then} $(\forall n \in N)\phi(n)$Line 43 · formal-object, formula-context · records
projected-env-000415 projected-formula-0002861\end{center}Line 44 · formal-object · records
projected-env-000415\end{cor}Line 46 · formula-context · records
projected-formula-0002862\begin{proof}Line 47 · formula · records
projected-formula-0002862Let $X = \Setabs{n \in N}{\phi(n)}$, and now useLine 48 · formula-context, reference · records
projected-formula-0002862 reference-000128[olref reference to sfr:infinite:induction:thm:dedinfiniteinduction]\olref{thm:dedinfiniteinduction}Line 51 · formula-context · records
projected-formula-0002863In this result, we spoke of a formula ``having parameters''. What thisLine 52 · formula, formula-context · records
projected-formula-0002863 projected-formula-0002864means, roughly, is that for any objects $c_1, \ldots, c_k$, we canLine 53 · formula, formula-context · records
projected-formula-0002863 projected-formula-0002864work with $\phi(x, c_1, \ldots, c_k)$. More precisely, we can stateLine 54 · formula-context · records
projected-formula-0002864 projected-formula-0002865the result without mentioning ``parameters'' as follows. For anyLine 55 · formula · records
projected-formula-0002865formula $\phi(x, v_1, \ldots, v_k)$, whose free variables are allLine 56 · formula-context · records
projected-formula-0002865 projected-formula-0002866displayed, we have:Line 57 · formal-object, formula · records
projected-env-000417 projected-formula-0002866\begin{align*}Line 58 · formal-object, formula-context · records
projected-env-000417 projected-formula-0002866\forall v_1 \ldots \forall v_k((&\phi(o, v_1,\ldots, v_k) \land {}\\Line 59 · formal-object · records
projected-env-000417& (\forall x \in N)(\phi(x,v_1, \ldots, v_k) \lif \phi(s(x), v_1,\ldots, v_k))) \lif {}\\Line 60 · formal-object · records
projected-env-000417&\hspace{3em} (\forall x \in N)\phi(x, v_1,\ldots, v_k))Line 61 · formal-object · records
projected-env-000417\end{align*}Line 63 · reference · records
reference-000129[olref reference to sth:::part]Line 72 · formula-context, reference · records
projected-formula-0002867 reference-000130[olref reference to sth:ord-arithmetic::chap]after \olref[sth][ord-arithmetic][]{chap}, or perhaps read an alternativeLine 73 · formula, reference · records
projected-formula-0002867 reference-000131[citealt reference to Potter2004]treatment, such as \citealt[pp.~95--8]{Potter2004}.) But, where $N, s, o$Line 74 · formula-context · records
projected-formula-0002867comprise a Dedekind algebra, we will ultimately be able to stipulate theLine 75 · formula-context · records
projected-formula-0002868following:Line 76 · formal-object, formula · records
projected-env-000418 projected-formula-0002868\begin{align*}Line 77 · formal-object, formula-context · records
projected-env-000418 projected-formula-0002868{a} + {o} &= {a} & & & {a} \times {o} &= {o} & & & {a}^{o} &= s(o)\\Line 78 · formal-object · records
projected-env-000418{a} + {s}({b}) &= {s}({a}+{b}) &&& {a} \times {s}({b}) &= ({a}\times {b}) + {a} & & & {a}^{{s}({b})} &= {a}^{b} \times {a}Line 79 · formal-object · records
projected-env-000418\end{align*}
content/sets-functions-relations/infinite/dedekinds-proof.tex
26 exact source-coordinate anchors materialized from the accepted slice ledgers.
Line 11 · structure · records
structure-00052\olsection{Dedekind's ``Proof'' of the Existence of an Infinite Set}Line 16 · reference · records
reference-000132[olref reference to sfr:arith:ref:sec]Line 21 · reference · records
reference-000133[olref reference to sfr:arith::chap]Line 25 · formula-context · records
projected-formula-0002869\emph{given any Dedekind infinite set}, we can define a set which willLine 26 · formula · records
projected-formula-0002869behave just like we want~$\Nat$ to behave.Line 30 · reference · records
reference-000134[olref reference to sfr:arith:ref:sec]Line 31 · formula-context · records
projected-formula-0002870emphasized that we would be wrong to think of the definition ofLine 32 · formula · records
projected-formula-0002870$\Real$ as the set of Dedekind cuts as a \emph{discovery}, rather thanLine 33 · formula-context · records
projected-formula-0002870a convenient stipulation. The crucial observation is that the DedekindLine 38 · reference · records
reference-000135[citeyear reference to Dedekind1888]Line 57 · reference · records
reference-000136[citep reference to Dedekind1888]Line 61 · reference · records
reference-000137[olref reference to sfr:arith::chap]Line 69 · reference · records
reference-000138[olref reference to sfr:infinite:dedekind:thm:DedekindInfiniteAlgebra]Line 75 · formula-context · records
projected-formula-0002871\begin{quote}Line 76 · formula, formula-context · records
projected-formula-0002871 projected-formula-0002872My own realm of thoughts, i.e., the totality $S$ of all things whichLine 77 · formula, formula-context · records
projected-formula-0002871 projected-formula-0002872 projected-formula-0002873 projected-formula-0002874 projected-formula-0002875can be objects of my thought, is infinite. For if $s$ signifies anLine 78 · formula, formula-context · records
projected-formula-0002872 projected-formula-0002873 projected-formula-0002874 projected-formula-0002875 projected-formula-0002876element of~$S$, then the thought $s'$ that~$s$ can be an object ofLine 79 · formula, formula-context · records
projected-formula-0002873 projected-formula-0002874 projected-formula-0002875 projected-formula-0002876 projected-formula-0002877 projected-formula-0002878 projected-formula-0002879my thought, is itself an element of~$S$. If we regard this as anLine 80 · formula, formula-context · records
projected-formula-0002876 projected-formula-0002877 projected-formula-0002878 projected-formula-0002879image $\phi(s)$ of the element~$s$, then \dots~$S$ is [Dedekind]Line 81 · formula-context · records
projected-formula-0002877 projected-formula-0002878 projected-formula-0002879infinite, which was to be proved.Line 82 · reference · records
reference-000139[citep reference to Dedekind1888]Line 95 · formula-context · records
projected-formula-0002880many things (specifically, infinitely many thoughts). But DedekindLine 96 · formula, formula-context · records
projected-formula-0002880 projected-formula-0002881also needs to give us a reason to regard~$S$ as a single \emph{set},Line 97 · formula, formula-context · records
projected-formula-0002880 projected-formula-0002881with infinitely many !!{element}s, rather than thinking of~$S$ asLine 98 · formula-context · records
projected-formula-0002881\emph{some things} (in the plural).Line 103 · reference · records
reference-000140[citet reference to Potter2004]
content/sets-functions-relations/infinite/card-sb.tex
67 exact source-coordinate anchors materialized from the accepted slice ledgers.
Line 7 · structure · records
structure-00053\olsection{Appendix: Proving Schr\"oder-Bernstein}Line 11 · formula-context, reference · records
projected-formula-0002882 projected-formula-0002883 projected-formula-0002884 reference-000141Schr\"oder-Bernstein (\olref[sfr][siz][sb]{thm:schroder-bernstein}): if[olref reference to sfr:siz:sb:thm:schroder-bernstein]Line 12 · formula, formula-context · records
projected-formula-0002882 projected-formula-0002883 projected-formula-0002884 projected-formula-0002885 projected-formula-0002886$\cardle{A}{B}$ and $\cardle{B}{A}$ then $\cardeq{A}{B}$; i.e., givenLine 13 · formula, formula-context · records
projected-formula-0002882 projected-formula-0002883 projected-formula-0002884 projected-formula-0002885 projected-formula-0002886 projected-formula-0002887!!{injection}s $f \colon A \to B$ and $g \colon B \to A$ there isLine 14 · formula, formula-context · records
projected-formula-0002885 projected-formula-0002886 projected-formula-0002887!!a{bijection} $h \colon A \to B$.Line 19 · reference · records
reference-000142[citet reference to Potter2004]Line 21 · formula-context · records
projected-formula-0002888you that this is a theorem---rather like the irrationality ofLine 22 · formula · records
projected-formula-0002888$\sqrt{2}$---for which \emph{many} interesting and different proofsLine 23 · formula-context · records
projected-formula-0002888exist.Line 25 · reference · records
reference-000143[olref reference to sfr:infinite:dedekind:Closure]Line 26 · formula-context · records
projected-formula-0002889letLine 27 · formula · records
projected-formula-0002889\[Line 28 · formula-context · records
projected-formula-0002889\Closureofunder{f}{B} = \bigcap \Setabs{X}{B \subseteq XLine 30 · formula-context · records
projected-formula-0002890 projected-formula-0002891\]Line 31 · formula, formula-context · records
projected-formula-0002890 projected-formula-0002891 projected-formula-0002892 projected-formula-0002893 projected-formula-0002894for each set $B$ and function~$f$. Defined thus,Line 32 · formula, formula-context · records
projected-formula-0002890 projected-formula-0002891 projected-formula-0002892 projected-formula-0002893 projected-formula-0002894$\Closureofunder{f}{B}$ is the smallest $f$-closed set containing~$B$,Line 33 · formula-context · records
projected-formula-0002892 projected-formula-0002893 projected-formula-0002894in that:Line 35 · formal-object, formula-context · records
projected-env-000422 projected-formula-0002895 projected-formula-0002896\begin{lem}\ollabel{Closureprops}Line 36 · formal-object, formula · records
projected-env-000422 projected-formula-0002895 projected-formula-0002896For any function $f$, and any $B$:Line 37 · formal-object, formula-context · records
projected-env-000422 projected-formula-0002895 projected-formula-0002896 projected-formula-0002897\begin{enumerate}Line 38 · formal-object, formula, formula-context · records
projected-env-000422 projected-formula-0002897 projected-formula-0002898 projected-formula-0002899\item\ollabel{Closurehaselem} $B \subseteq \Closureofunder{f}{B}$; andLine 39 · formal-object, formula, formula-context · records
projected-env-000422 projected-formula-0002897 projected-formula-0002898 projected-formula-0002899 projected-formula-0002900 projected-formula-0002901 projected-formula-0002902\item\ollabel{Closureclosed} $\Closureofunder{f}{B}$ is $f$-closed; andLine 40 · formal-object, formula, formula-context · records
projected-env-000422 projected-formula-0002898 projected-formula-0002899 projected-formula-0002900 projected-formula-0002901 projected-formula-0002902 projected-formula-0002903\item\ollabel{Closuresmallest} if $X$ is $f$-closed and $BLine 41 · formal-object, formula, formula-context · records
projected-env-000422 projected-formula-0002900 projected-formula-0002901 projected-formula-0002902 projected-formula-0002903\subseteq X$, then $\Closureofunder{f}{B} \subseteq X$.Line 42 · formal-object, formula-context · records
projected-env-000422 projected-formula-0002903\end{enumerate}Line 43 · formal-object · records
projected-env-000422\end{lem}Line 46 · reference · records
reference-000144[olref reference to sfr:infinite:dedekind:closureproperties]Line 51 · formal-object, formula-context · records
projected-env-000424 projected-formula-0002904 projected-formula-0002905 projected-formula-0002906\begin{prop}\ollabel{sbhelper}Line 52 · formal-object, formula, source-correction · records
TR007-SOURCE-FORMULA-002 projected-env-000424 projected-formula-0002904 projected-formula-0002905 projected-formula-0002906If $A \subseteq B \subseteq C$ and $A \approx C$, then $\cardeq{\cardeq{A}{B}}{C}$.Line 53 · formal-object, formula-context · records
projected-env-000424 projected-formula-0002904 projected-formula-0002905 projected-formula-0002906\end{prop}Line 55 · formula-context · records
projected-formula-0002907 projected-formula-0002908\begin{proof}Line 56 · formula, formula-context · records
projected-formula-0002907 projected-formula-0002908 projected-formula-0002909Given !!a{bijection} $f \colon C \to A$, let $F =Line 57 · formula, formula-context · records
projected-formula-0002907 projected-formula-0002908 projected-formula-0002909 projected-formula-0002910\Closureofunder{f}{C \setminus B}$ and define a function $g$ withLine 58 · formula, formula-context · records
projected-formula-0002909 projected-formula-0002910 projected-formula-0002911domain $C$ as follows:Line 59 · formula, formula-context · records
projected-formula-0002910 projected-formula-0002911\[Line 60 · formula-context · records
projected-formula-0002911g(x) =Line 65 · formula-context · records
projected-formula-0002912 projected-formula-0002913\]Line 66 · formula, formula-context · records
projected-formula-0002912 projected-formula-0002913 projected-formula-0002914We'll show that $g$ is !!a{bijection} from $C \to B$, from which itLine 67 · formula, formula-context · records
projected-formula-0002912 projected-formula-0002913 projected-formula-0002914will follow that $\comp{f^{-1}}{g} \colon A \to B$ is !!a{bijection},Line 68 · formula-context · records
projected-formula-0002914completing the proof.Line 70 · formula, formula-context · records
projected-formula-0002915 projected-formula-0002916 projected-formula-0002917 projected-formula-0002918First we claim that if $x \in F$ but $y\notin F$ then $g(x) \neqLine 71 · formula, formula-context · records
projected-formula-0002915 projected-formula-0002916 projected-formula-0002917 projected-formula-0002918 projected-formula-0002919 projected-formula-0002920 projected-formula-0002921g(y)$. For reductio suppose otherwise, so that $y = g(y) = g(x) =Line 72 · formula, formula-context, reference · records
projected-formula-0002918 projected-formula-0002919 projected-formula-0002920 projected-formula-0002921 projected-formula-0002922 reference-000145[olref reference to sfr:infinite:card-sb:Closureprops]f(x)$. Since $x \in F$ and $F$ is $f$-closed by \olref{Closureprops},Line 73 · formula, formula-context · records
projected-formula-0002919 projected-formula-0002920 projected-formula-0002921 projected-formula-0002922we have $y = f(x) \in F$, a contradiction.Line 75 · formula, formula-context · records
projected-formula-0002923 projected-formula-0002924 projected-formula-0002925 projected-formula-0002926 projected-formula-0002927 projected-formula-0002928Now suppose $g(x) = g(y)$. So, by the above, $x \in F$ iff $y \in F$.Line 76 · formula, formula-context · records
projected-formula-0002923 projected-formula-0002924 projected-formula-0002925 projected-formula-0002926 projected-formula-0002927 projected-formula-0002928 projected-formula-0002929 projected-formula-0002930 projected-formula-0002931If $x, y \in F$, then $f(x) = g (x) = g(y) = f(y)$ so that $x = y$Line 77 · formula, formula-context · records
projected-formula-0002926 projected-formula-0002927 projected-formula-0002928 projected-formula-0002929 projected-formula-0002930 projected-formula-0002931 projected-formula-0002932since $f$ is !!a{bijection}. If $x, y \notin F$, then $x = g(x) =Line 78 · formula, formula-context · records
projected-formula-0002929 projected-formula-0002930 projected-formula-0002931 projected-formula-0002932g(y) = y$. So $g$ is !!a{injection}.Line 80 · formula, formula-context · records
projected-formula-0002933 projected-formula-0002934 projected-formula-0002935 projected-formula-0002936 projected-formula-0002937 projected-formula-0002938It remains to show that $\ran{g} = B$. So fix $x \in B \subseteq C$.Line 81 · formula, formula-context · records
projected-formula-0002933 projected-formula-0002934 projected-formula-0002935 projected-formula-0002936 projected-formula-0002937 projected-formula-0002938 projected-formula-0002939 projected-formula-0002940 projected-formula-0002941 projected-formula-0002942 projected-formula-0002943If $x \notin F$, then $g(x) = x$. If $x \in F$, then $x = f(y)$ forLine 82 · formula, formula-context, reference · records
projected-formula-0002935 projected-formula-0002936 projected-formula-0002937 projected-formula-0002938 projected-formula-0002939 projected-formula-0002940 projected-formula-0002941 projected-formula-0002942 projected-formula-0002943 reference-000146[olref reference to sfr:infinite:card-sb:Closureprops]some $y \in F$, since otherwise $F \setminus \{x\}$ would be $f$-closed and extend $C\setminus B$, which is impossible by \olref{Closureprops}; now $g(y) = f(y) = x$.Line 83 · formula-context · records
projected-formula-0002939 projected-formula-0002940 projected-formula-0002941 projected-formula-0002942 projected-formula-0002943\end{proof}Line 85 · formula-context · records
projected-formula-0002944 projected-formula-0002945 projected-formula-0002946Finally, here is the proof of the main result. Recall that given aLine 86 · formula · records
projected-formula-0002944 projected-formula-0002945 projected-formula-0002946function $h$ and set $D$, we define $\funimage{h}{D} = \Setabs{h(x)}{xLine 87 · formula-context · records
projected-formula-0002944 projected-formula-0002945 projected-formula-0002946\in D}$.Line 89 · formula, formula-context · records
projected-formula-0002947 projected-formula-0002948 projected-formula-0002949\begin{proof}[Proof of Schr\"oder-Bernstein] Let $f \colon A \to B$Line 90 · formula, formula-context · records
projected-formula-0002947 projected-formula-0002948 projected-formula-0002949 projected-formula-0002950and $g \colon B \to A$ be !!{injection}s. Since $\funimage{f}{A}Line 91 · formula, formula-context · records
projected-formula-0002948 projected-formula-0002949 projected-formula-0002950 projected-formula-0002951\subseteq B$ we have that $\funimage{g}{\funimage{f}{A}} \subseteqLine 92 · formula, formula-context · records
projected-formula-0002950 projected-formula-0002951 projected-formula-0002952g[B] \subseteq A$. Also, $\comp{f}{g} \colon A \toLine 93 · formula, formula-context · records
projected-formula-0002951 projected-formula-0002952 projected-formula-0002953 projected-formula-0002954\funimage{g}{\funimage{f}{A}}$ is an !!{injection} since both $g$ andLine 94 · formula, formula-context · records
projected-formula-0002952 projected-formula-0002953 projected-formula-0002954$f$ are; and indeed $\comp{f}{g}$ is !!a{bijection}, just by the wayLine 95 · formula-context · records
projected-formula-0002953 projected-formula-0002954 projected-formula-0002955we defined its codomain. SoLine 96 · formula, formula-context · records
projected-formula-0002955 projected-formula-0002956$\cardeq{\funimage{g}{\funimage{f}{A}}}{A}$, and hence byLine 97 · formula, formula-context, reference · records
projected-formula-0002955 projected-formula-0002956 projected-formula-0002957 reference-000147[olref reference to sfr:infinite:card-sb:sbhelper]\olref{sbhelper} there is !!a{bijection} $h \colon A \toLine 98 · formula, formula-context · records
projected-formula-0002956 projected-formula-0002957 projected-formula-0002958 projected-formula-0002959\funimage{g}{B}$. Moreover, $g^{-1}$ is !!a{bijection}Line 99 · formula, formula-context · records
projected-formula-0002957 projected-formula-0002958 projected-formula-0002959$\funimage{g}{B} \to B$. So $\comp{h}{g^{-1}} \colon A \to B$ isLine 100 · formula-context · records
projected-formula-0002958 projected-formula-0002959!!a{bijection}.
content/sets-functions-relations/sets-functions-relations-complete.tex
0 exact source-coordinate anchors materialized from the accepted slice ledgers.