Prealgebra 2e — Original English

Multiply Whole Numbers

Use Multiplication Notation

Suppose you were asked to count all these pennies shown in Figure 1.

An image of 3 horizontal rows of pennies, each row containing 8 pennies.

Would you count the pennies individually? Or would you count the number of pennies in each row and add that number 3 times.

8+8+8

Multiplication is a way to represent repeated addition. So instead of adding 8 three times, we could write a multiplication expression.

3×8

We call each number being multiplied a factor and the result the product. We read 3×8 as three times eight, and the result as the product of three and eight.

There are several symbols that represent multiplication. These include the symbol × as well as the dot, ·, and parentheses ().

Translate from math notation to words:

  1. 7×6
  2. 12·14
  3. 6(13)
Solution

Solution

  • We read this as seven times six and the result is the product of seven and six.
  • We read this as twelve times fourteen and the result is the product of twelve and fourteen.
  • We read this as six times thirteen and the result is the product of six and thirteen.

Model Multiplication of Whole Numbers

There are many ways to model multiplication. Unlike in the previous sections where we used base-10 blocks, here we will use counters to help us understand the meaning of multiplication. A counter is any object that can be used for counting. We will use round blue counters.

Model: 3×8.

Solution

Solution

To model the product 3×8, we’ll start with a row of 8 counters.
An image of a horizontal row of 8 counters.

The other factor is 3, so we’ll make 3 rows of 8 counters.
An image of 3 horizontal rows of counters, each row containing 8 counters.

Now we can count the result. There are 24 counters in all.

3×8=24

If you look at the counters sideways, you’ll see that we could have also made 8 rows of 3 counters. The product would have been the same. We’ll get back to this idea later.

Multiply Whole Numbers

In order to multiply without using models, you need to know all the one digit multiplication facts. Make sure you know them fluently before proceeding in this section.

Table 2 shows the multiplication facts. Each box shows the product of the number down the left column and the number across the top row. If you are unsure about a product, model it. It is important that you memorize any number facts you do not already know so you will be ready to multiply larger numbers.

× 0 1 2 3 4 5 6 7 8 9
0 0 0 0 0 0 0 0 0 0 0
1 0 1 2 3 4 5 6 7 8 9
2 0 2 4 6 8 10 12 14 16 18
3 0 3 6 9 12 15 18 21 24 27
4 0 4 8 12 16 20 24 28 32 36
5 0 5 10 15 20 25 30 35 40 45
6 0 6 12 18 24 30 36 42 48 54
7 0 7 14 21 28 35 42 49 56 63
8 0 8 16 24 32 40 48 56 64 72
9 0 9 18 27 36 45 54 63 72 81

What happens when you multiply a number by zero? You can see that the product of any number and zero is zero. This is called the Multiplication Property of Zero.

Multiply:
  1. 0·11
  2. (42)0
Solution

Solution

This table demonstrates the Zero Property of Multiplication with examples and rules, illustrating that any number multiplied by zero equals zero.
0·11
The product of any number and zero is zero. 0
(42)0
Multiplying by zero results in zero. 0

What happens when you multiply a number by one? Multiplying a number by one does not change its value. We call this fact the Identity Property of Multiplication, and 1 is called the multiplicative identity.

Multiply:
  1. (11)1
  2. 1·42
Solution

Solution

Illustrates the identity property of multiplication with examples where any number multiplied by one retains its original value.
(11)1
The product of any number and one is the number. 11
1·42
Multiplying by one does not change the value. 42

Earlier in this chapter, we learned that the Commutative Property of Addition states that changing the order of addition does not change the sum. We saw that 8+9=17 is the same as 9+8=17.

Is this also true for multiplication? Let’s look at a few pairs of factors.

4·7=287·4=28
9·7=637·9=63
8·9=729·8=72

When the order of the factors is reversed, the product does not change. This is called the Commutative Property of Multiplication.

Multiply:
  1. 8·7
  2. 7·8
Solution

Solution

Multiplication problems 8x7 and 7x8 demonstrating their shared result of 56.
8·7
Multiply. 56
7·8
Multiply. 56

Changing the order of the factors does not change the product.

To multiply numbers with more than one digit, it is usually easier to write the numbers vertically in columns just as we did for addition and subtraction.

27×3___

We start by multiplying 3 by 7.

3×7=21

We write the 1 in the ones place of the product. We carry the 2 tens by writing 2 above the tens place.

The image shows a vertical multiplication problem of 27 times 3. An arrow indicates the 2 carried from 3 x 7 = 21 is in the tens place. Another arrow indicates the remaining 1 from 3 x 7 = 21 is written in the ones place below.

Then we multiply the 3 by the 2, and add the 2 above the tens place to the product. So 3×2=6, and 6+2=8. Write the 8 in the tens place of the product.

A vertical multiplication problem showing 27 multiplied by 3, resulting in 81. An arrow indicates that the '8' in 81 is derived from (3 x 2) + the '2' carried from 3 x 7 = 21.

The product is 81.

When we multiply two numbers with a different number of digits, it’s usually easier to write the smaller number on the bottom. You could write it the other way, too, but this way is easier to work with.

Multiply: 15·4.

Solution

Solution

Step-by-step vertical multiplication of 15 by 4, showing both explanatory text and mathematical calculation at each stage.
Write the numbers so the digits 5 and 4 line up vertically. 15 ×4_____
Multiply 4 by the digit in the ones place of 15. 45=20.
Write 0 in the ones place of the product and carry the 2 tens. 125 ×4_____ 0
Multiply 4 by the digit in the tens place of 15. 41=4.
Add the 2 tens we carried. 4+2=6.
Write the 6 in the tens place of the product. 125 ×4_____ 60

Multiply: 286·5.

Solution

Solution

Step-by-step vertical multiplication of a three-digit number by a single-digit number.
Write the numbers so the digits 5 and 6 line up vertically. 286 ×5_____
Multiply 5 by the digit in the ones place of 286. 56=30.
Write the 0 in the ones place of the product and carry the 3 to the tens place.Multiply 5 by the digit in the tens place of 286. 58=40. 2836 ×5_____ 0
Add the 3 tens we carried to get 40+3=43.
Write the 3 in the tens place of the product and carry the 4 to the hundreds place.
24836 ×5_____ 30
Multiply 5 by the digit in the hundreds place of 286. 52=10.
Add the 4 hundreds we carried to get 10+4=14.
Write the 4 in the hundreds place of the product and the 1 to the thousands place.
24836 ×5_____ 1,430

When we multiply by a number with two or more digits, we multiply by each of the digits separately, working from right to left. Each separate product of the digits is called a partial product. When we write partial products, we must make sure to line up the place values.

Multiply: 62(87).

Solution

Solution

This table illustrates the step-by-step process of multiplying two-digit numbers (e.g., 87 x 62) with corresponding visual aids.
Write the numbers so each place lines up vertically. A vertical multiplication problem setup showing 62 multiplied by 87.
Start by multiplying 7 by 62. Multiply 7 by the digit in the ones place of 62. 72=14. Write the 4 in the ones place of the product and carry the 1 to the tens place. A vertical multiplication problem setup showing 62 multiplied by 87. Red digits indicate carried numbers ('1' above '6') and the unit digit of the first partial product ('4' below the line from 7x2=14).
Multiply 7 by the digit in the tens place of 62. 76=42. Add the 1 ten we carried. 42+1=43. Write the 3 in the tens place of the product and the 4 in the hundreds place. A vertical long multiplication problem showing 62 multiplied by 87. The first partial product, 62 x 7, is displayed as 434, along with red carry-over digits '1' and '6' above '62'.
The first partial product is 434.
Now, write a 0 under the 4 in the ones place of the next partial product as a placeholder since we now multiply the digit in the tens place of 87 by 62. Multiply 8 by the digit in the ones place of 62. 82=16. Write the 6 in the next place of the product, which is the tens place. Carry the 1 to the tens place. Vertical long multiplication problem: 62 multiplied by 87. The steps show 62 x 7 = 434 and 2 x 8 = 16 with the remainder 1 written above in the tens place and 6 written below in the tens place to create the number 60.
Multiply 8 by 6, the digit in the tens place of 62, then add the 1 ten we carried to get 49. Write the 9 in the hundreds place of the product and the 4 in the thousands place. Vertical long multiplication problem: 62 multiplied by 87. The steps show 62 x 7 = 434 and 62 x 80 = 4960, with red digits indicating carries and the second partial product.
The second partial product is 4960. Add the partial products. Vertical long multiplication problem: 62 multiplied by 87. This step shows the partial products 434 added to 4960 resulting in an answer of 5394.

The product is 5,394.

Multiply:
  1. 47·10
  2. 47·100.
Solution

Solution

This table demonstrates the long multiplication method for multiplying a two-digit number by powers of ten (10 and 100), showing the detailed steps for each calculation.
47·10. 47×10___00470___470
47·100 47×100_____000004700_____4,700

When we multiplied 47 times 10, the product was 470. Notice that 10 has one zero, and we put one zero after 47 to get the product. When we multiplied 47 times 100, the product was 4,700. Notice that 100 has two zeros and we put two zeros after 47 to get the product.

Do you see the pattern? If we multiplied 47 times 10,000, which has four zeros, we would put four zeros after 47 to get the product 470,000.

Multiply: (354)(438).

Solution

Solution

There are three digits in the factors so there will be 3 partial products. We do not have to write the 0 as a placeholder as long as we write each partial product in the correct place.
An image of the multiplication problem “354 times 438” worked out vertically. 354 is the top number, 438 is the second number. Below 438 is a multiplication bar. Below the bar is the number 2,832. 2832 has the label “Multiply 8 times 354”. Below 2832 is the number 1,062;  1062 has the label “Multiply 3 times 354”.  Below 1062 is the number 1,416; 1416 has the label “Multiply 4 times 354”.  Below this is a bar and below the bar is the number “155,052”, with the label “Add the partial products”.

Multiply: (896)201.

Solution

Solution

There should be 3 partial products. The second partial product will be the result of multiplying 896 by 0.
An image of the multiplication problem “896 times 201” worked out vertically. 896 is the top number, the 8 in the hundreds place, the 9 in the tens place, the 6 in the ones place. 201 is the second number,  the 2 in the hundreds place, the 0 in the tens place, the 1 in the ones place. Below 201 is a multiplcation bar. Below the bar is the number 896, the 8 in the hundreds place, the 9 in the tens place, the 6 in the ones place. 896 has the label “Multiply 1 times 896”. Below 896 is the number “000”, the 0 in the thousands place, the 0 in the hundreds place, and the 0 in the tens place. “000” has the label “Multiply 0 times 896”.  Below “000” is the number 1792, the 1 in the hundred thousands place, the 7 in the ten thousands place, the 9 in the thousands place, and the 2 in the hundreds place. 1792 has the label “Multiply 2 times 896”.  Below this is a bar and below the bar is the number “180,096”, with the label “Add the partial products”.

Notice that the second partial product of all zeros doesn’t really affect the result. We can place a zero as a placeholder in the tens place and then proceed directly to multiplying by the 2 in the hundreds place, as shown.

Multiply by 10, but insert only one zero as a placeholder in the tens place. Multiply by 200, putting the 2 from the 12. 2·6=12 in the hundreds place.

896×201_____89617920__________180,096

When there are three or more factors, we multiply the first two and then multiply their product by the next factor. For example:

Step-by-step demonstration of multiplying three numbers (8 × 3 × 2).
to multiply 832
first multiply 83 242
then multiply 242. 48

Translate Word Phrases to Math Notation

Earlier in this section, we translated math notation into words. Now we’ll reverse the process and translate word phrases into math notation. Some of the words that indicate multiplication are given in Table 11.

Operation Word Phrase Example Expression
Multiplication times
product
twice
3 times 8
the product of 3 and 8
twice 4
3×8,3·8,(3)(8),
(3)8,or3(8)
2·4

Translate and simplify: the product of 12 and 27.

Solution

Solution

The word product tells us to multiply. The words of 12 and 27 tell us the two factors.

Steps demonstrating the translation of a word problem ("the product of 12 and 27") into a mathematical expression and its calculated result.
the product of 12 and 27
Translate. 1227
Multiply. 324

Translate and simplify: twice two hundred eleven.

Solution

Solution

The word twice tells us to multiply by 2.

This table illustrates the process of translating a verbal mathematical phrase into an algebraic expression and then solving for the numerical result.
twice two hundred eleven
Translate. 2(211)
Multiply. 422

Multiply Whole Numbers in Applications

We will use the same strategy we used previously to solve applications of multiplication. First, we need to determine what we are looking for. Then we write a phrase that gives the information to find it. We then translate the phrase into math notation and simplify to get the answer. Finally, we write a sentence to answer the question.

Humberto bought 4 sheets of stamps. Each sheet had 20 stamps. How many stamps did Humberto buy?

Solution

Solution

We are asked to find the total number of stamps.

This table demonstrates a step-by-step process for translating a word problem into a mathematical expression, performing the calculation, and providing the final answer.
Write a phrase for the total. the product of 4 and 20
Translate to math notation. 420
Multiply. A vertical multiplication problem showing 20 multiplied by 4, with the result 80, written in a clear, dark blue font on a white background.
Write a sentence to answer the question. Humberto bought 80 stamps.

When Rena cooks rice, she uses twice as much water as rice. How much water does she need to cook 4 cups of rice?

Solution

Solution

We are asked to find how much water Rena needs.

This table illustrates the step-by-step process of translating a word problem into a mathematical expression and deriving the final numerical solution.
Write as a phrase. twice as much as 4 cups
Translate to math notation. 24
Multiply to simplify. 8
Write a sentence to answer the question. Rena needs 8 cups of water for 4 cups of rice.

Van is planning to build a patio. He will have 8 rows of tiles, with 14 tiles in each row. How many tiles does he need for the patio?

Solution

Solution

We are asked to find the total number of tiles.

This table illustrates the step-by-step process of translating a word phrase into mathematical notation, solving it, and providing a final answer.
Write a phrase. the product of 8 and 14
Translate to math notation. 814
Multiply to simplify. 134×8___112
Write a sentence to answer the question. Van needs 112 tiles for his patio.

If we want to know the size of a wall that needs to be painted or a floor that needs to be carpeted, we will need to find its area. The area is a measure of the amount of surface that is covered by the shape. Area is measured in square units. We often use square inches, square feet, square centimeters, or square miles to measure area. A square centimeter is a square that is one centimeter (cm.) on a side. A square inch is a square that is one inch on each side, and so on.

An image of two squares, one larger than the other. The smaller square is 1 centimeter by 1 centimeter and has the label “1 square centimeter”. The larger square is 1 inch by 1 inch and has the label “1 square inch”.

For a rectangular figure, the area is the product of the length and the width. Figure 3 shows a rectangular rug with a length of 2 feet and a width of 3 feet. Each square is 1 foot wide by 1 foot long, or 1 square foot. The rug is made of 6 squares. The area of the rug is 6 square feet.

An image of a rectangle containing 6 blocks, 2 feet tall and 3 feet wide. This image has the label “2 times 3 = 6 feet squared”.
The area of a rectangle is the product of its length and its width, or 6 square feet.

Jen’s kitchen ceiling is a rectangle that measures 9 feet long by 12 feet wide. What is the area of Jen’s kitchen ceiling?

Solution

Solution

We are asked to find the area of the kitchen ceiling.

This table illustrates the step-by-step process of solving an area word problem, from phrasing and notation to calculation and the final answer.
Write a phrase for the area. the product of 9 and 12
Translate to math notation. 912
Multiply. 112×9___108
Answer with a sentence. The area of Jen's kitchen ceiling is 108 square feet.

Key Concepts

Operation Notation Expression Read as Result
Multiplication ×
·
()
3×8
3·8
3(8)
three times eight the product of 3 and 8
  • Multiplication Property of Zero
    • The product of any number and 0 is 0.
      a0=0
      0a=0
  • Identity Property of Multiplication
    • The product of any number and 1 is the number.
      1a=a
      a1=a
  • Commutative Property of Multiplication
    • Changing the order of the factors does not change their product.
      ab=ba
  • Multiply two whole numbers to find the product.
    1. Write the numbers so each place value lines up vertically.
    2. Multiply the digits in each place value.
    3. Work from right to left, starting with the ones place in the bottom number.
    4. Multiply the bottom number by the ones digit in the top number, then by the tens digit, and so on.
    5. If a product in a place value is more than 9, carry to the next place value.
    6. Write the partial products, lining up the digits in the place values with the numbers above. Repeat for the tens place in the bottom number, the hundreds place, and so on.
    7. Insert a zero as a placeholder with each additional partial product.
    8. Add the partial products.

Practice Makes Perfect

Use Multiplication Notation

In the following exercises, translate from math notation to words.

4×7

Solution

four times seven; the product of four and seven

8×6

5·12

Solution

five times twelve; the product of five and twelve

3·9

(10)(25)

Solution

ten times twenty-five; the product of ten and twenty-five

(20)(15)

42(33)

Solution

forty-two times thirty-three; the product of forty-two and thirty-three

39(64)

Model Multiplication of Whole Numbers

In the following exercises, model the multiplication.

3×6

Solution


The image shows how gray circles can be set up to demonstrate the multiplication problem of 3 × 6.

4×5

5×9

Solution


A rectangular array of 45 grey circles, arranged in 5 rows and 9 columns. Below the array, the multiplication equation '5 x 9 = 45' is displayed, illustrating the product of the rows and columns.

3×9

Multiply Whole Numbers

In the following exercises, fill in the missing values in each chart.

An image of a table with 11 columns and 11 rows. The cells in the first row and first column are shaded darker than the other cells. The first column has the values “x; 0; 1; 2; 3; 4; 5; 6; 7; 8; 9”. The second column has the values “0; 0; 0; null; 0; 0; 0; 0; null; 0; 0”. The third column has the values “1; 0; 1; 2; null; 4; 5; 6; null; 8; 9”. The fourth column has the values “2; 0; 2; 4; 6; null; 10; 12; 14; null; 18”. The fifth column has the values “3; null; 3; 6; null; null; 15; null; 21; 24; null”. The sixth column has the values “4; 0; null; 8; 12; 16; null; 24; null; null; 36”. The seventh column has the values “5; 0; null; null; 15; 20; null; null; 35; null; 45”. The eighth column has the values “6; 0; 6; 12; null; null; 30; null; null; 48; null”. The ninth column has the values “7; 0; 7; null; 21; 28; null; 42; null; null; null”. The tenth column has the values “8; null; 8; null; null; 32; 40; null; 56; 64; 72”. The eleventh column has the values “9; 0; null; 18; 27; null, null; 54; 63; null; null”.
Solution


An image of a table with 11 columns and 11 rows. The cells in the first row and first column are shaded darker than the other cells. The cells contain numbers and answers to the problem.

An image of a table with 11 columns and 11 rows. The cells in the first row and first column are shaded darker than the other cells. The first column has the values “x; 0; 1; 2; 3; 4; 5; 6; 7; 8; 9”. The second column has the values “0; 0; 0; 0 pink; 0; 0; 0; 0; 0; 0; 0”. The third column has the values “1; 0; 1; 2; 3; 4; 5; 6; 7; 8; 9”. The fourth column has the values “2; 0; 2; 4; 6; 8; 10; 12; 14; 16; 18”. The fifth column has the values “3; 0; 3; 6; 9; 12; 15; 18; 21; 24; 27”. The sixth column has the values “4; 0; 4; 8; 12; 16; 20; 24; 28; 32; 36”. The seventh column has the values “5; 0; 5; 10; 15; 20; 25; 30; 35; 40; 45”. The eighth column has the values “6; 0; 6; 12; 18; 24; 30; 36; 42; 48; 54”. The ninth column has the values “7; 0; 7; 14; 21; 28; 35; 42; 49; 56; 63”. The tenth column has the values “8; 0; 8; 16; 24; 32; 40; 48; 56; 64; 72”. The eleventh column has the values “9; 0; 9; 18; 27; 36, 45; 54; 63; 72; 81”.
An image of a table with 8 columns and 7 rows. The cells in the first row and first column are shaded darker than the other cells. The cells not in the first row or column are all null.  The first column has the values “x; 4; 5; 6; 7; 8; 9”. The first row has the values “x; 3; 4; 5; 6; 7; 8; 9”.
Solution


An image of a table with 8 columns and 7 rows. The cells in the first row and first column are shaded darker than the other cells. The cells contain numbers and answers to the problem.

PROD: An image of a table with 7 columns and 8 rows. The cells in the first row and first column are shaded darker than the other cells. The cells not in the first row or column are all null.  The first column has the values “x; 3; 4; 5; 6; 7; 8; 9”. The first row has the values “x; 4; 5; 6; 7; 8; 9”.
An image of a table with 8 columns and 5 rows. The cells in the first row and first column are shaded darker than the other cells. The cells not in the first row or column are all null.  The first row has the values “x; 3; 4; 5; 6; 7; 8; 9”. The first column has the values “x;  6; 7; 8; 9”.
Solution


An image of a table with 8 columns and 5 rows. The cells in the first row and first column are shaded darker than the other cells. The cells contain numbers and answers to the problem.

An image of a table with 5 columns and 8 rows. The cells in the first row and first column are shaded darker than the other cells. The cells not in the first row or column are all null. The first column has the values “x; 3; 4; 5; 6; 7; 8; 9”. The first row has the values “x; 6; 7; 8; 9”.
PROD: An image of a table with 6 columns and 6 rows. The cells in the first row and first column are shaded darker than the other cells. The cells not in the first row or column are all null.  The first column has the values “x; 5; 6; 7; 8; 9”. The first row has the values “x; 5; 6; 7; 8; 9”.
Solution


A dark teal and grey multiplication table showing the products of numbers 5 through 9. The rows and columns are labeled with these numbers, and the grid displays their respective multiplication results.

An image of a table with 6 columns and 6 rows. The cells in the first row and first column are shaded darker than the other cells. The cells not in the first row or column are all null.  The first column has the values “x; 5; 6; 7; 8; 9”. The first row has the values “x; 5; 6; 7; 8; 9”.

In the following exercises, multiply.

0·15

Solution

0

0·41

(99)0

Solution

0

(77)0

1·43

Solution

43

1·34

(28)1

Solution

28

(65)1

1(240,055)

Solution

240,055

1(189,206)

  1. 7·6
  2. 6·7
Solution
  1. 42
  2. 42
  1. 8×9
  2. 9×8

(79)(5)

Solution

395

(58)(4)

275·6

Solution

1,650

638·5

3,421×7

Solution

23,947

9,143×3

52(38)

Solution

1,976

37(45)

96·73

Solution

7,008

89·56

27×85

Solution

2,295

53×98

23·10

Solution

230

19·10

(100)(36)

Solution

3,600

(100)(25)

1,000(88)

Solution

88,000

1,000(46)

50×1,000,000

Solution

50,000,000

30×1,000,000

247×139

Solution

34,333

156×328

586(721)

Solution

422,506

472(855)

915·879

Solution

804,285

968·926

(104)(256)

Solution

26,624

(103)(497)

348(705)

Solution

245,340

485(602)

2,719×543

Solution

1,476,417

3,581×724

Translate Word Phrases to Math Notation

In the following exercises, translate and simplify.

the product of 18 and 33

Solution

18 · 33; 594

the product of 15 and 22

fifty-one times sixty-seven

Solution

51(67); 3,417

forty-eight times seventy-one

twice 249

Solution

2(249); 498

twice 589

ten times three hundred seventy-five

Solution

10(375); 3,750

ten times two hundred fifty-five

Mixed Practice

In the following exercises, simplify.

38×37

Solution

1,406

86×29

415267

Solution

148

341285

6,251+4,749

Solution

11,000

3,816+8,184

(56)(204)

Solution

11,424

(77)(801)

947·0

Solution

0

947+0

15,382+1

Solution

15,383

15,382·1

In the following exercises, translate and simplify.

the difference of 50 and 18

Solution

50 − 18; 32

the difference of 90 and 66

twice 35

Solution

2(35); 70

twice 140

20 more than 980

Solution

20 + 980; 1,000

65 more than 325

the product of 12 and 875

Solution

12(875); 10,500

the product of 15 and 905

subtract 74 from 89

Solution

89 − 74; 15

subtract 45 from 99

the sum of 3,075 and 95

Solution

3,075 + 95; 3,170

the sum of 6,308 and 724

366 less than 814

Solution

814 − 366; 448

388 less than 925

Multiply Whole Numbers in Applications

In the following exercises, solve.

Party supplies Tim brought 9 six-packs of soda to a club party. How many cans of soda did Tim bring?

Solution

Tim brought 54 cans of soda to the party.

Sewing Kanisha is making a quilt. She bought 6 cards of buttons. Each card had four buttons on it. How many buttons did Kanisha buy?

Field trip Seven school busses let off their students in front of a museum in Washington, DC. Each school bus had 44 students. How many students were there?

Solution

There were 308 students.

Gardening Kathryn bought 8 flats of impatiens for her flower bed. Each flat has 24 flowers. How many flowers did Kathryn buy?

Charity Rey donated 15 twelve-packs of t-shirts to a homeless shelter. How many t-shirts did he donate?

Solution

Rey donated 180 t-shirts.

School There are 28 classrooms at Anna C. Scott elementary school. Each classroom has 26 student desks. What is the total number of student desks?

Recipe Stephanie is making punch for a party. The recipe calls for twice as much fruit juice as club soda. If she uses 10 cups of club soda, how much fruit juice should she use?

Solution

Stephanie should use 20 cups of fruit juice.

Gardening Hiroko is putting in a vegetable garden. He wants to have twice as many lettuce plants as tomato plants. If he buys 12 tomato plants, how many lettuce plants should he get?

Government The United States Senate has twice as many senators as there are states in the United States. There are 50 states. How many senators are there in the United States Senate?

Solution

There are 100 senators in the U.S. senate.

Recipe Andrea is making potato salad for a buffet luncheon. The recipe says the number of servings of potato salad will be twice the number of pounds of potatoes. If she buys 30 pounds of potatoes, how many servings of potato salad will there be?

Painting Jane is painting one wall of her living room. The wall is rectangular, 13 feet wide by 9 feet high. What is the area of the wall?

Solution

The area of the wall is 117 square feet.

Home décor Shawnte bought a rug for the hall of her apartment. The rug is 3 feet wide by 18 feet long. What is the area of the rug?

Room size The meeting room in a senior center is rectangular, with length 42 feet and width 34 feet. What is the area of the meeting room?

Solution

The area of the room is 1,428 square feet.

Gardening June has a vegetable garden in her yard. The garden is rectangular, with length 23 feet and width 28 feet. What is the area of the garden?

NCAA basketball According to NCAA regulations, the dimensions of a rectangular basketball court must be 94 feet by 50 feet. What is the area of the basketball court?

Solution

The area of the court is 4,700 square feet.

NCAA football According to NCAA regulations, the dimensions of a rectangular football field must be 360 feet by 160 feet. What is the area of the football field?

Everyday Math

Stock market Javier owns 300 shares of stock in one company. On Tuesday, the stock price rose $12 per share. How much money did Javier’s portfolio gain?


Solution

Javier’s portfolio gained $3,600.

Salary Carlton got a $200 raise in each paycheck. He gets paid 24 times a year. How much higher is his new annual salary?

Writing Exercises

How confident do you feel about your knowledge of the multiplication facts? If you are not fully confident, what will you do to improve your skills?

Solution

Answers will vary.

How have you used models to help you learn the multiplication facts?

Self Check

After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

A self-assessment chart for multiplication skills, including using notation, modeling, multiplying whole numbers, translating word phrases, and applying multiplication.

On a scale of 1–10, how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?

product
The product is the result of multiplying two or more numbers.