Intermediate Algebra 2e — Original English

Arithmetic Sequences

Determine if a Sequence is Arithmetic

The last section introduced sequences and now we will look at two specific types of sequences that each have special properties. In this section we will look at arithmetic sequences and in the next section, geometric sequences.

An arithmetic sequence is a sequence where the difference between consecutive terms is constant. The difference between consecutive terms in an arithmetic sequence, anan1, is d, the common difference, for n greater than or equal to two.

This figure has two rows and three columns. The first row reads “7”, “10”,”13”, “16”, “19”, “22”, and an ellipsis, “10 minus 7, divided by 3”, “13 minus 10, divided by 3”, “16 minus 13, divided by 3”, nth term equals nth term minus 1 divided by d”

In each of these sequences, the difference between consecutive terms is constant, and so the sequence is arithmetic.

Determine if each sequence is arithmetic. If so, indicate the common difference.

5,9,13,17,21,25,

4,9,12,17,20,25,

10,3,−4,−11,−18,−25,

Solution

To determine if the sequence is arithmetic, we find the difference of the consecutive terms shown.


Example of calculating the common difference for a given arithmetic sequence.



Find the difference of
the consecutive terms.
5,9,13,1721,25, 95139171321172521 44444
The sequence is arithmetic. The common difference is d=4.


This table demonstrates how to determine if a sequence is arithmetic by calculating consecutive term differences, concluding that the example sequence is not arithmetic.



Find the difference of
the consecutive terms.
4,9,12,1720,25, 94129171220172520 53535
The sequence is not arithmetic as all the differences between
the consecutive terms are not the same.
There is no common difference.


Demonstration of finding the common difference for an arithmetic sequence by subtracting consecutive terms, using a specific numerical example.



Find the difference of
the consecutive terms.
10,3,−4,−11−18,−25, 310−43−11(−4)−18(−11)−25(−18) −7−7−7−7−7
The sequence is arithmetic. The common difference is d=−7.

If we know the first term, a1, and the common difference, d, we can list a finite number of terms of the sequence.

Write the first five terms of the sequence where the first term is 5 and the common difference is d=−6.

Solution

We start with the first term and add the common difference. Then we add the common difference to that result to get the next term, and so on.

a1a2a3a4a555+(−6)−1+(−6)−7+(−6)−13+(−6)−1−7−13−19

The sequence is 5,−1,−7,−13,−19,

Find the General Term (nth Term) of an Arithmetic Sequence

Just as we found a formula for the general term of a sequence, we can also find a formula for the general term of an arithmetic sequence.

Let’s write the first few terms of a sequence where the first term is a1 and the common difference is d. We will then look for a pattern.

As we look for a pattern we see that each term starts with a1.

This figures shows an image of a sequence.

The first term adds 0d to the a1, the second term adds 1d, the third term adds 2d, the fourth term adds 3d, and the fifth term adds 4d. The number of ds that were added to a1 is one less than the number of the term. This leads us to the following

an=a1+(n1)d

We will use this formula in the next example to find the 15th term of a sequence.

Find the fifteenth term of a sequence where the first term is 3 and the common difference is 6.

Solution
Calculation of the 15th term of an arithmetic sequence using the formula a_n = a_1 + (n-1)d.
To find the fifteenth term, a15, use the
formula with a1=3andd=6.
an=a1+(n1)d
Substitute in the values. a15=3+(151)6
Simplify. a15=3+(14)6
a15=87

Sometimes we do not know the first term and we must use other given information to find it before we find the requested term.

Find the twelfth term of a sequence where the seventh term is 10 and the common difference is −2. Give the formula for the general term.

Solution
This table illustrates the step-by-step calculation for finding the first, 12th, and general terms of an arithmetic sequence.
To first find the first term, a1, use the
formula with a7=10,n=7,andd=−2.
an=a1+(n1)d
Substitute in the values. 10=a1+(71)(−2)
Simplify. 10=a1+(6)(−2)
10=a112
a1=22
Find the twelfth term, a12, using the
formula with a1=22,n=12,andd=−2.
an=a1+(n1)d
Substitute in the values. a12=22+(121)(−2)
Simplify. a12=22+(11)(−2)
a12=0
The twelfth term of the sequence is 0, a12=0.
To find the general term, substitute
the values into the formula.
an=a1+(n1)d
an=22+(n1)(−2)
an=222n+2
The general term is an=−2n+24.

Sometimes the information given leads us to two equations in two unknowns. We then use our methods for solving systems of equations to find the values needed.

Find the first term and common difference of a sequence where the fifth term is 19 and the eleventh term is 37. Give the formula for the general term.

Solution

Since we know two terms, we can make a system of equations using the formula for the general term.

The formula for the nth term of an arithmetic sequence, expressed as a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the term number, and d is the common difference.
We know the value of a5 and a11, so we will use n=5 and n=11. This image displays two equations representing specific terms of an arithmetic sequence. The first equation, a_5 = a_1 + (5 - 1)d, calculates the 5th term (a_5). The second equation, a_11 = a_1 + (11 - 1)d, calculates the 11th term (a_11). In both formulas, a_1 represents the first term of the sequence and d represents the common difference.
Substitute in the values, a5=19 and a11=37. A system of two linear equations, 19 = a_1 + (5 - 1)d and 37 = a_1 + (11 - 1)d, used to find the first term (a_1) and common difference (d) of an arithmetic sequence. Key numbers are highlighted in red.
Simplify. A system of two linear equations is presented, with the first equation being 19 = a1 + 4d and the second equation being 37 = a1 + 10d, enclosed by a brace on the left.
Prepare to eliminate the a1 term by multiplying the top equation by −1.
Add the equations.
This image illustrates the elimination method for solving a system of linear equations. By adding the two equations, 'a1' is eliminated, leading to 18 = 6d, and subsequently d = 3.

Substituting d=3 back into the first equation.

The equation 19 = a₁ + 4 • 3 is displayed, where the dot multiplication sign and the number 3 are colored red.
Solve for a1. A mathematical equation shown in two lines. The first line is 19 = a sub 1 + 12, and the second line is the solution, 7 = a sub 1.

Use the formula with a1=7 and d=3.

The image shows the formula for the nth term of an arithmetic progression, which is a_n = a_1 + (n-1)d.
Substitute in the values. The image shows the mathematical formula a_n = 7 + (n - 1)3, which represents an arithmetic sequence where a_n is the nth term, 7 is the first term, and 3 is the common difference.
Simplify. Two lines of mathematical equations showing the simplification of an algebraic expression: a_n = 7 + 3n - 3 is simplified to a_n = 3n + 4.
The first term is a1=7.
The common difference is d=3.

The general term of the sequence is an=3n+4.

Find the Sum of the First n Terms of an Arithmetic Sequence

As with the general sequences, it is often useful to find the sum of an arithmetic sequence. The sum, Sn, of the first n terms of any arithmetic sequence is written as Sn=a1+a2+a3+...+an. To find the sum by merely adding all the terms can be tedious. So we can also develop a formula to find the sum of a sequence using the first and last term of the sequence.

We can develop this new formula by first writing the sum by starting with the first term, a1, and keep adding a d to get the next term as:

Sn=a1+(a1+d)+(a1+2d)++an.

We can also reverse the order of the terms and write the sum by starting with an and keep subtracting d to get the next term as

Sn=an+(and)+(an2d)++a1.

If we add these two expressions for the sum of the first n terms of an arithmetic sequence, we can derive a formula for the sum of the first n terms of any arithmetic series.

Sn=a1+(a1+d)+(a1+2d)++an+Sn=an+(and)+(an2d)++a1_________________________________________________________2Sn=(a1+an)+(a1+an)+(a1+an)++(a1+an)

Because there are n sums of (a1+an) on the right side of the equation, we rewrite the right side as n(a1+an).

2Sn=n(a1+an)

We divide by two to solve for Sn.

Sn=n2(a1+an)

This gives us a general formula for the sum of the first n terms of an arithmetic sequence.

We apply this formula in the next example where the first few terms of the sequence are given.

Find the sum of the first 30 terms of the arithmetic sequence: 8, 13, 18, 23, 28, …

Solution

To find the sum, we will use the formula Sn=n2(a1+an). We know a1=8, d=5 and n=30, but we need to find an in order to use the sum formula.

Illustrates the step-by-step calculation of the nth term and the sum of the first n terms for an arithmetic sequence.
an=a1+(n1)d
Findanwherea1=8,d=5andn=30. a30=8+(301)5
Simplify. a30=8+(29)5
a30=153
Knowinga1=8,n=30,anda30=153,
use the sum formula.
Sn=n2(a1+an)
Substitute in the values. S30=302(8+153)
Simplify. S30=15(161)
Simplify. S30=2,415

In the next example, we are given the general term for the sequence and are asked to find the sum of the first 50 terms.

Find the sum of the first 50 terms of the arithmetic sequence whose general term is an=3n4.

Solution

To find the sum, we will use the formula Sn=n2(a1+an). We know n=50, but we need to find a1 and an in order to use the sum formula.

A mathematical equation is displayed on a white background: a subscript n equals 3n minus 4.
Find a1, by substituting n=1. The calculation of the first term, a_1, from the expression 3 * 1 - 4, resulting in a_1 = -1. The value '1' is highlighted in red, indicating its substitution.
Find an by substituting n=50. Mathematical expressions show the nth term of a sequence as a_n = 3n - 4, and its 50th term calculated as a_50 = 3 * 50 - 4, highlighting the substituted value 50.
Simplify. The mathematical equation a_50 = 146 is displayed on a white background, representing the 50th term of a sequence equaling 146.
Knowing n=50,a1=−1, and a50=146 use the sum formula. The formula for the sum of the first 'n' terms of an arithmetic sequence is shown: S_n = (n/2)(a_1 + a_n).
Substitute in the values. A mathematical equation for the sum of an arithmetic sequence, S_n = (50/2)(-1 + 146), which is S_n = 25 * 145.
Simplify. A mathematical equation shows S with a subscript 50, an equals sign, 25, and (145), indicating S_50 = 25(145).
Simplify. A mathematical equation S with a subscript 50, followed by an equals sign and the number 3,625, is displayed against a white background.

In the next example we are given the sum in summation notation. To add all the terms would be tedious, so we extract the information needed to use the formula to find the sum of the first n terms.

Find the sum: i=125(4i+7).

Solution

To find the sum, we will use the formula Sn=n2(a1+an). We know n=25, but we need to find a1 and an in order to use the sum formula.

Expand the summation notation. A mathematical equation shows the expansion of a summation expression from i=1 to 25 for (4i + 7), illustrating the first few terms and the last term of the series.
Simplify. A mathematical equation showing the expansion of the summation of 4i + 7 from i=1 to 25, resulting in the series 11 + 15 + 19 + ... + 107.
Identify a1. A mathematical equation is displayed on a white background, reading 'a_1 = 11' in black text.
Identify a25. A mathematical expression shows 'a sub 25 equals 107' on a plain white background.
Knowing n=25,a1=11, and a25=107
use the sum formula.
A white background displays the mathematical formula S_n = n/2 (a_1 + a_n), which is used to calculate the sum of an arithmetic sequence, representing S sub n equals n over 2 times the quantity of a sub 1 plus a sub n.
Substitute in the values. A mathematical equation shows S_25 equals 25 divided by 2, multiplied by the sum of 11 and 107, representing the sum of an arithmetic series.
Simplify. A mathematical equation shows S subscript 25 equals 25 over 2 multiplied by 118, displayed in black text on a white background.
Simplify. The mathematical equation S₂₅ = 1,475 is displayed in black text against a plain white background, indicating a sum or a value for an indexed variable.

Key Concepts

  • General Term (nth term) of an Arithmetic Sequence
    The general term of an arithmetic sequence with first term a1 and the common difference d is
    an=a1+(n1)d
  • Sum of the First n Terms of an Arithmetic Sequence
    The sum, Sn, of the first n terms of an arithmetic sequence, where a1 is the first term and an is the nth term is
    Sn=n2(a1+an)

Practice Makes Perfect

Determine if a Sequence is Arithmetic

In the following exercises, determine if each sequence is arithmetic, and if so, indicate the common difference.

4,12,20,28,36,44,

Solution

The sequence is arithmetic with common difference d=8.

−7,−2,3,8,13,18,

−15,−16,3,12,21,30,

Solution

The sequence is not arithmetic.

11,5,−1,−713,−19,

8,5,2,−1,−4,−7,

Solution

The sequence is arithmetic with common difference d=−3.

15,5,−5,−15,−25,−35,

In the following exercises, write the first five terms of each sequence with the given first term and common difference.

a1=11 and d=7

Solution

11,18,25,32,39

a1=18 and d=9

a1=−7 and d=4

Solution

−7,−3,1,5,9

a1=−8 and d=5

a1=14 and d=−9

Solution

14,5,−4,−13,−22

a1=−3 and d=−3

Find the General Term (nth Term) of an Arithmetic Sequence

In the following exercises, find the term described using the information provided.

Find the twenty-first term of a sequence where the first term is three and the common difference is eight.

Solution

163

Find the twenty-third term of a sequence where the first term is six and the common difference is four.

Find the thirtieth term of a sequence where the first term is −14 and the common difference is five.

Solution

131

Find the fortieth term of a sequence where the first term is −19 and the common difference is seven.

Find the sixteenth term of a sequence where the first term is 11 and the common difference is −6.

Solution

−79

Find the fourteenth term of a sequence where the first term is eight and the common difference is −3.

Find the twentieth term of a sequence where the fifth term is −4 and the common difference is −2. Give the formula for the general term.

Solution

a20=−34. The general term is an=−2n+6.

Find the thirteenth term of a sequence where the sixth term is −1 and the common difference is −4. Give the formula for the general term.

Find the eleventh term of a sequence where the third term is 19 and the common difference is five. Give the formula for the general term.

Solution

a11=59. The general term is an=5n+4.

Find the fifteenth term of a sequence where the tenth term is 17 and the common difference is seven. Give the formula for the general term.

Find the eighth term of a sequence where the seventh term is −8 and the common difference is −5. Give the formula for the general term.

Solution

a8=−13. The general term is an=−5n+27.

Find the fifteenth term of a sequence where the tenth term is −11 and the common difference is −3. Give the formula for the general term.

In the following exercises, find the first term and common difference of the sequence with the given terms. Give the formula for the general term.

The second term is 14 and the thirteenth term is 47.

Solution

a1=11,d=3. The general term is an=3n+8.

The third term is 18 and the fourteenth term is 73.

The second term is 13 and the tenth term is −51.

Solution

a1=21,d=−8. The general term is an=−8n+29.

The third term is four and the tenth term is −38.

The fourth term is −6 and the fifteenth term is 27.

Solution

a1=−15,d=3. The general term is an=3n18.

The third term is −13 and the seventeenth term is 15.

Find the Sum of the First n Terms of an Arithmetic Sequence

In the following exercises, find the sum of the first 30 terms of each arithmetic sequence.

11,14,17,20,23,

Solution

1,635

12,18,24,30,36,

8,5,2,−1,−4,

Solution

−1,065

16,10,4,−2,−8,

−17,−15,−13,−11,−9,

Solution

360

−15,−12,−9,−6,−3,

In the following exercises, find the sum of the first 50 terms of the arithmetic sequence whose general term is given.

an=5n1

Solution

6,325

an=2n+7

an=−3n+5

Solution

–3,575

an=−4n+3

In the following exercises, find each sum.

i=140(8i7)

Solution

6,280

i=145(7i5)

i=150(3i+6)

Solution

4,125

i=125(4i+3)

i=135(−6i2)

Solution

−3,850

i=130(−5i+1)

Writing Exercises

In your own words, explain how to determine whether a sequence is arithmetic.

Solution

Answers will vary.

In your own words, explain how the first two terms are used to find the tenth term. Show an example to illustrate your explanation.

In your own words, explain how to find the general term of an arithmetic sequence.

Solution

Answers will vary.

In your own words, explain how to find the sum of the first n terms of an arithmetic sequence without adding all the terms.

Self Check

After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

This figure shows a chart with four rows and four columns. The first row is the header row and reads, “I can”, “Confidently”, “With some help”, and “No, I don’t get it!” The column, beginning with second row reads 1. Determine if a Sequence is Arithmetic, 2. Find the General Term (nth term) of Arithmetic Sequence, and 3. Find the sum of the first Terms of an Arithmetic Sequence”. The remaining columns are blank.

After reviewing this checklist, what will you do to become confident for all objectives?

arithmetic sequence
An arithmetic sequence is a sequence where the difference between consecutive terms is constant.
common difference
The difference between consecutive terms in an arithmetic sequence, anan1, is d, the common difference, for n greater than or equal to two.