Elementary Algebra 2e — Original English

Solve Applications Modeled by Quadratic Equations

Solve Applications of the Quadratic Formula

We solved some applications that are modeled by quadratic equations earlier, when the only method we had to solve them was factoring. Now that we have more methods to solve quadratic equations, we will take another look at applications. To get us started, we will copy our usual Problem Solving Strategy here so we can follow the steps.

We have solved number applications that involved consecutive even integers and consecutive odd integers by modeling the situation with linear equations. Remember, we noticed each even integer is 2 more than the number preceding it. If we call the first one n, then the next one is n+2. The next one would be n+2+2 or n+4. This is also true when we use odd integers. One set of even integers and one set of odd integers are shown below.

Consecutive even integersConsecutive odd integers64,66,6877,79,81n1steven integern+22ndconsecutive even integern+43rdconsecutive even integern1stodd integern+22ndconsecutive odd integern+43rdconsecutive odd integer

Some applications of consecutive odd integers or consecutive even integers are modeled by quadratic equations. The notation above will be helpful as you name the variables.

The product of two consecutive odd integers is 195. Find the integers.

Solution

Solution

Step 1. Read the problem.
Step 2. Identify what we are looking for. We are looking for two consecutive odd integers.
Step 3. Name what we are looking for. Let n= the first odd integer.
n+2= the next odd integer
Step 4. Translate into an equation. State the problem in one sentence. "The product of two consecutive odd integers is 195." The product of the first odd integer and the second odd integer is 195.
Translate into an equation The image displays the mathematical equation n(n+2) = 195, where 'n' is a variable.
Step 5. Solve the equation. Distribute. A mathematical equation is displayed on a white background, reading 'n squared plus 2n equals 195'.
Subtract 195 to get the equation in standard form. Two quadratic equations are displayed: the general form 'ax^2 + bx + c = 0' in red, followed by a specific example, 'n^2 + 2n - 195 = 0,' in black text.
Identify the a, b, c values. The image displays mathematical variables with their assigned values: a = 1, b = 2, and c = -195, presented in different colors against a white background.
Write the quadratic equation. The quadratic formula, solving for 'n' using coefficients a, b, and c.
Then substitute in the values of a, b, c.. The quadratic formula is shown with specific values substituted for solving n. The equation features -2 ×1 square root of (2^2 - 4 * 1 * -195), all divided by (2 * 1), with some values highlighted.
Simplify. A mathematical equation is displayed, showing n equals a fraction where the numerator is -2 plus or minus the square root of 4 plus 780, all divided by 2.
A mathematical equation shows 'n equals negative 2 plus or minus the square root of 784, all divided by 2' on a white background. This is a step in solving a quadratic equation.
Simplify the radical. A mathematical equation shows 'n' is equal to a fraction where the numerator is '-2 plus or minus 28' and the denominator is '2'.
Rewrite to show two solutions. The image displays two expressions for 'n': n = (-2 + 28) / 2 and n = (-2 - 28) / 2. These typically represent the two roots found when solving a quadratic equation.
Solve each equation. Two mathematical equations are displayed horizontally on a white background: 'n = 26/2' and 'n = -30/2'. The equations show the variable 'n' being defined by fractions.
The image displays the equations 'n = 13' and 'n = -15' in a simple, clear font on a white background.
There are two values of n that are solutions. This will give us two pairs of consecutive odd integers for our solution. First odd integer n=13
next odd integer n+2
13+2
15
First odd integer n=−15
next odd integer n+2
−15+2
−13
Step 6. Check the answer.
Do these pairs work?
Are they consecutive odd integers?
Is their product 195?


13,15,yes−13,−15,yes1315=195,yes−13(−15)=195,yes
Step 7. Answer the question. The two consecutive odd integers whose product is 195 are 13, 15, and −13, −15.

We will use the formula for the area of a triangle to solve the next example.

Recall that, when we solve geometry applications, it is helpful to draw the figure.

An architect is designing the entryway of a restaurant. She wants to put a triangular window above the doorway. Due to energy restrictions, the window can have an area of 120 square feet and the architect wants the width to be 4 feet more than twice the height. Find the height and width of the window.

Solution

Solution

Step 1. Read the problem.
Draw a picture.
A triangle with its height labeled 'h' and its base labeled '2h + 4', indicating dimensions for a geometric problem or calculation.
Step 2. Identify what we are looking for. We are looking for the height and width.
Step 3. Name what we are looking for. Let h= the height of the triangle.
2h+4= the width of the triangle
Step 4. Translate. We know the area. Write the formula for the area of a triangle.
The image displays the mathematical formula for the area of a triangle, A = (1/2)bh, where A represents the area, b is the base, and h is the height.
Step 5. Solve the equation. Substitute in the values. The image shows the mathematical equation '120 = 1/2(2h + 4)h' centered on a white background. The equation involves numbers and the variable 'h', representing a quadratic relationship.
Distribute. A mathematical equation 120 = h² + 2h is displayed in the center of a white background.
This is a quadratic equation, rewrite it in standard form. Two quadratic equations are presented: the general form ax^2 + bx + c = 0 in red, and a specific instance h^2 + 2h - 120 = 0 in black on a white background.
Solve the equation using the Quadratic Formula. Identify the a, b, c values. A mathematical expression displaying variables and their values: a = 1 (light blue), b = 2 (red), and c = -√120 (yellow-green), all on a white background.
Write the quadratic equation. The quadratic formula is displayed, showing h equals the quantity negative b plus or minus the square root of b squared minus 4ac, all divided by 2a.
Then substitute in the values of a, b, c.. Mathematical expression showing the quadratic formula applied to find 'h', with specific values substituted.
Simplify. A mathematical equation for 'h' is shown: h equals a fraction where the numerator is -2 plus or minus the square root of (4 plus 480), and the denominator is 2.
The image shows the mathematical equation h = (-2 ± sqrt(484)) / 2.
Simplify the radical. A mathematical equation is displayed on a white background: h = (-2  A mathematical equation is displayed on a white background: h = (-2 ± 22) / 2.
Rewrite to show two solutions. The two values for 'h' from a quadratic solution: h = (-2 + 22) / 2 and h = (-2 - 22) / 2.
Simplify. Two mathematical equations are displayed on a white background. The first equation is h = 20/2, and the second is h = -24/2, with a comma separating the two expressions.
Since h is the height of a window, a value of h=12 does not make sense. Mathematical notation featuring 'h = 10' and the full expression 'b = 12' crossed out, suggesting a correction or an abandoned calculation.
The height of the triangle: h=10

The width of the triangle: 2h+4
210+4
24
Step 6. Check the answer. Does a triangle with a height 10 and width 24 have area 120? Yes.
Step 7. Answer the question. The height of the triangular window is 10 feet and the width is 24 feet.

Notice that the solutions were integers. That tells us that we could have solved the equation by factoring.

When we wrote the equation in standard form, h2+2h120=0, we could have factored it. If we did, we would have solved the equation (h+12)(h10)=0.

In the two preceding examples, the number in the radical in the Quadratic Formula was a perfect square and so the solutions were rational numbers. If we get an irrational number as a solution to an application problem, we will use a calculator to get an approximate value.

The Pythagorean Theorem gives the relation between the legs and hypotenuse of a right triangle. We will use the Pythagorean Theorem to solve the next example.

Rene is setting up a holiday light display. He wants to make a ‘tree’ in the shape of two right triangles, as shown below, and has two 10-foot strings of lights to use for the sides. He will attach the lights to the top of a pole and to two stakes on the ground. He wants the height of the pole to be the same as the distance from the base of the pole to each stake. How tall should the pole be?

Solution

Solution

Step 1. Read the problem. Draw a picture. A geometric diagram displaying a triangle with a vertical line segment from the apex to the base. One of the sloped sides is labeled with the number '10,' and two downward arrows indicate points at the base.
Step 2. Identify what we are looking for. We are looking for the height of the pole.
Step 3. Name what we are looking for. The distance from the base of the pole to either stake is the same as the height of the pole. Let x= the height of the pole.
x= the distance from the pole to stake
Each side is a right triangle. We draw a picture of one of them. A right-angled triangle is shown with two equal sides labeled 'x' and the hypotenuse labeled '10'.
Step 4. Translate into an equation. We can use the Pythagorean Theorem to solve for x.
Write the Pythagorean Theorem. a2+b2=c2
Step 5. Solve the equation. Substitute. x2+x2=102
Simplify. 2x2=100
Divide by 2 to isolate the variable. 2x22=1002
Simplify. x2=50
Use the Square Root Property. x=±50
Simplify the radical. x=±52
Rewrite to show two solutions. x=52
x=52
Approximate this number to the nearest tenth with a calculator. x7.1
Step 6. Check the answer.
Check on your own in the Pythagorean Theorem.
Step 7. Answer the question. The pole should be about 7.1 feet tall.

Mike wants to put 150 square feet of artificial turf in his front yard. This is the maximum area of artificial turf allowed by his homeowners association. He wants to have a rectangular area of turf with length one foot less than three times the width. Find the length and width. Round to the nearest tenth of a foot.

Solution

Solution

Step 1. Read the problem. Draw a picture. A rectangle is shown with its dimensions labeled algebraically: the width is 'w' and the length is '3w-1'.
Step 2. Identify what we are looking for. We are looking for the length and width.
Step 3. Name what we are looking for. Let w= the width of the rectangle.
3w1= the length of the rectangle
Step 4. Translate into an equation.
We know the area. Write the formula for the area of a rectangle.
The mathematical formula for calculating area: A = L * W.
Step 5. Solve the equation. Substitute in the values. A mathematical equation is displayed on a white background, which reads 150 = (3w - 1)w. The numbers and variables are in a dark gray font.
Distribute. A mathematical equation is displayed on a white background: 150 = 3w^2 - W. The numbers and variables are in a dark gray font.
This is a quadratic equation, rewrite it in standard form. Two quadratic equations are displayed: the general form ax^2 + bx + c = 0, and a specific example 3w^2 - w - 150 = 0.
Solve the equation using the Quadratic Formula.
Identify the a, b, c values. The image displays the variable assignments a = 3, b = -1, c = -150, written in a horizontal line with different colors for each assignment: 'a' in light blue, 'b' in red, and 'c' in yellow.
Write the Quadratic Formula. The quadratic formula with 'w' as the variable, showing w equals negative b plus or minus the square root of b squared minus 4ac, all divided by 2a.
Then substitute in the values of a, b, c. The quadratic formula with substituted values for a (3, blue), b (-1, red), and c (-150, yellow) to solve for W.
Simplify. The image shows a mathematical equation where W is calculated as the fraction of (1 plus or minus the square root of (1 + 1800)) all divided by 6.
A mathematical equation shows W equals the fraction of one plus or minus the square root of 1801, all divided by six.
Rewrite to show two solutions. Two mathematical expressions for 'w' are displayed, showing the solutions to a quadratic equation involving a square root and division by six: w = (1 + √1801)/6 and w = (1 - √1801)/6.
Approximate the answers using a calculator.
We eliminate the negative solution for the width.
Mathematical steps showing the calculation of width (w ≈ 7.2) and length (L ≈ 3w - 1, resulting in L ≈ 20.6), with a negative 'w' value crossed out as invalid.
Step 6. Check the answer.
Make sure that the answers make sense.
Step 7. Answer the question. The width of the rectangle is approximately 7.2 feet and the length 20.6 feet.

The height of a projectile shot upwards is modeled by a quadratic equation. The initial velocity, v0, propels the object up until gravity causes the object to fall back down.

We can use the formula for projectile motion to find how many seconds it will take for a firework to reach a specific height.

A firework is shot upwards with initial velocity 130 feet per second. How many seconds will it take to reach a height of 260 feet? Round to the nearest tenth of a second.

Solution

Solution

Step 1. Read the problem.
Step 2. Identify what we are looking for. We are looking for the number of seconds, which is time.
Step 3. Name what we are looking for. Let t= the number of seconds.
Step 4. Translate into an equation. Use the formula.
h=−16t2+v0t
Step 5. Solve the equation.
We know the velocity v0 is 130 feet per second.
The height is 260 feet. Substitute the values. A mathematical equation is displayed on a white background, which reads '260 = -16t^2 + 130t'.
This is a quadratic equation, rewrite it in standard form. Two quadratic equations are shown, with the general form ax^2 + bx + c = 0 in red text, followed by a specific example, 16t^2 - 130t + 260 = 0, in black text.
Solve the equation using the Quadratic Formula.
Identify the a, b, c values. The image displays the variables and their assigned numerical values: a = 16, b = -130, and c = 260, presented in different colors on a white background.
Write the Quadratic Formula. The quadratic formula, t equals negative b plus or minus the square root of b squared minus 4ac, all divided by 2a, is displayed on a white background.
Then substitute in the values of a, b, c. A mathematical equation for 't' using the quadratic formula is displayed, with 'a' as 16 (light blue), 'b' as -130 (red), and 'c' as 260 (yellow), to find the roots of a quadratic equation.
Simplify. A mathematical equation for 't' involves 130 plus or minus the square root of the difference between 16,900 and 16,640, with the entire expression divided by 32. This formula is commonly used in solving quadratic equations or statistical problems.
A mathematical equation is displayed on a white background: t = (130 ± √260) / 32.
Rewrite to show two solutions. Two mathematical solutions for 't' are presented, each as a fraction: (130 + sqrt(260))/32 and (130 - sqrt(260))/32.
Approximate the answers with a calculator. t4.6 seconds, t3.6
Step 6. Check the answer.
The check is left to you.
Step 7. Answer the question. The firework will go up and then fall back down.
As the firework goes up, it will reach 260 feet after
approximately 3.6 seconds. It will also pass that
height on the way down at 4.6 seconds.
A vivid firework traces an upward arc, exploding into a bright, starburst-like display of orange and yellow sparks against a clean white background.

Key Concepts

  • Area of a Triangle For a triangle with base, b, and height, h, the area, A, is given by the formula: A=12bh
    A diagram illustrating a triangle with its base labeled 'b' and its height labeled 'h'. The height 'h' is drawn from the apex perpendicular to the base 'b', dividing the original triangle into two smaller right-angled triangles.
  • Pythagorean Theorem In any right triangle, where a and b are the lengths of the legs, and c is the length of the hypothenuse, a2+b2=c2
    A right-angled triangle with sides labeled a, b, and hypotenuse c, commonly used to demonstrate the Pythagorean theorem.
  • Projectile motion The height in feet, h, of an object shot upwards into the air with initial velocity, v0, after t seconds can be modeled by the formula:
    h=−16t2+v0t

Practice Makes Perfect

Solve Applications of the Quadratic Formula

In the following exercises, solve by using methods of factoring, the square root principle, or the Quadratic Formula. Round your answers to the nearest tenth.

The product of two consecutive odd numbers is 255. Find the numbers.

Solution

Two consecutive odd numbers whose product is 255 are 15 and 17, and −15 and −17.

The product of two consecutive even numbers is 360. Find the numbers.

The product of two consecutive even numbers is 624. Find the numbers.

Solution

Two consecutive even numbers whose product is 624 are 24 and 26, and −26 and −24.

The product of two consecutive odd numbers is 1023. Find the numbers.

The product of two consecutive odd numbers is 483. Find the numbers.

Solution

Two consecutive odd numbers whose product is 483 are 21 and 23, and −21 and −23.

The product of two consecutive even numbers is 528. Find the numbers.

A triangle with area 45 square inches has a height that is two less than four times the width. Find the height and width of the triangle.

Solution

The width of the triangle is 5 inches and the height is 18 inches.

The width of a triangle is six more than twice the height. The area of the triangle is 88 square yards. Find the height and width of the triangle.

The hypotenuse of a right triangle is twice the length of one of its legs. The length of the other leg is three feet. Find the lengths of the three sides of the triangle. Round to the nearest tenth.

Solution

The leg of the right triangle is 1.7 feet and the hypotenuse is 3.4 feet.

The hypotenuse of a right triangle is 10 cm long. One of the triangle’s legs is three times the length of the other leg. Find the lengths of the three sides of the triangle. Round to the nearest tenth.

A farmer plans to fence off sections of a rectangular corral. The diagonal distance from one corner of the corral to the opposite corner is five yards longer than the width of the corral. The length of the corral is three times the width. Find the length of the diagonal of the corral. Round to the nearest tenth.

The image shows rectangle with the long sides horizontal. A diagonal line runs from the top left corner of the rectangle to the bottom right corner.
Solution

The length of the diagonal of the fence is 7.3 yards.

Nautical flags are used to represent letters of the alphabet. The flag for the letter O consists of a yellow right triangle and a red right triangle which are sewn together along their hypotenuse to form a square. The adjoining side of the two triangles is three inches longer than a side of the flag. Find the length of the side of the flag.

The image shows a square with a diagonal line running from the top left corner to the bottom right corner. The diagonal splits the square into two right triangles. The lower triangle is red and the upper triangle is yellow.

The length of a rectangular driveway is five feet more than three times the width. The area is 350 square feet. Find the length and width of the driveway.

Solution

The width of the driveway is 10 feet and its length is 35 feet.

A rectangular lawn has area 140 square yards. Its width that is six less than twice the length. What are the length and width of the lawn?

A firework rocket is shot upward at a rate of 640 ft/sec. Use the projectile formula h=−16t2+v0t to determine when the height of the firework rocket will be 1200 feet.

Solution

The rocket will reach 1,200 feet on its way up in 2 seconds and on the way down in 38 seconds.

An arrow is shot vertically upward at a rate of 220 feet per second. Use the projectile formula h=−16t2+v0t to determine when height of the arrow will be 400 feet.

Everyday Math

A bullet is fired straight up from a BB gun with initial velocity 1120 feet per second at an initial height of 8 feet. Use the formula h=−16t2+v0t+8 to determine how many seconds it will take for the bullet to hit the ground. (That is, when will h=0 ?)

Solution

70 seconds

A city planner wants to build a bridge across a lake in a park. To find the length of the bridge, he makes a right triangle with one leg and the hypotenuse on land and the bridge as the other leg. The length of the hypotenuse is 340 feet and the leg is 160 feet. Find the length of the bridge.

The image shows a right triangle with a horizontal side stretching across a lake, a vertical side on the left labeled a and the hypotenuse connecting the two.

Writing Exercises

Make up a problem involving the product of two consecutive odd integers. Start by choosing two consecutive odd integers. What are your integers? What is the product of your integers? Solve the equation n(n+2)=p, where p is the product you found in part (b). Did you get the numbers you started with?

Solution

answers will vary
answers will vary answers will vary answers will vary

Make up a problem involving the product of two consecutive even integers. Start by choosing two consecutive even integers. What are your integers? What is the product of your integers? Solve the equation n(n+2)=p, where p is the product you found in part (b). Did you get the numbers you started with?

Self Check

After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

This table has two rows and four columns. The first row is a header row and it labels each column. The first column is labeled "I can …", the second "Confidently", the third “With some help” and the last "No–I don’t get it". In the “I can…” column the next row reads “solve applications of the quadratic formula.” The remaining columns are blank.

On a scale of 1–10, how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?

consecutive even integers
Consecutive even integers are even integers that follow right after one another. If an even integer is represented by n, the next consecutive even integer is n+2, and the next after that is n+4.
consecutive odd integers
Consecutive odd integers are odd integers that follow right after one another. If an odd integer is represented by n, the next consecutive odd integer is n+2, and the next after that is n+4.