The principal genus theorem

Written by GPT-6.1 Sol (OpenAI) in Codex, Ultra setting, October 2026. Self-checked by the writing AI. Public domain (CC0).

For a quadratic field, genus characters record congruence information about ideal classes. The principal genus theorem says exactly how much information they lose: its kernel consists of squares. For a general Galois extension, Noether replaces one ideal class by a family of classes and its multiplication defects. The arithmetic condition on those defects is local splitting of a crossed-product algebra. We prove her reduction with that condition intact.

Take first Hilbert 90 in Noether's form and Galois descent, Discrete valuation rings and Dedekind domains, and Hilbert's ramification theory in Galois extensions. Recall the particular facts needed from the latter: the Galois group acts transitively on primes above a prime of the ground field; the stabilizer is its decomposition group; the completed extension has this group; and an unramified completed extension is cyclic, generated by residue-field Frobenius. We also use completions and ideal norms. The elementary ideal-class and norm background is available in Norms of ideals, the ideal class group, and modules over Dedekind domains.

Throughout, \(L/K\) is a finite Galois extension of number fields, \(G=\operatorname{Gal}(L/K)\), and group actions are on the left. Let \(I_L\) be the multiplicative group of nonzero fractional ideals, \(P_L\) its principal-ideal subgroup, and \(\operatorname{Cl}(L)=I_L/P_L\) its ordinary class group. At real places, positivity will enter local norm conditions explicitly. We do not silently replace an ordinary class group by a narrow one. In an imaginary quadratic field they coincide.

1. The arithmetic inputs

Two global statements are imported, with their scope specified.

Hasse norm theorem. If \(L/K\) is cyclic and \(a\in K^\times\), then \(a\) is a global field norm if and only if it is a norm from \(L_w/K_v\) at every place \(v\) of \(K\), for one, equivalently every, \(w\mid v\). See [Milne CFT, Chapter VIII, Theorem 3.1]. Norms from the product \(L\otimes_K K_v\) give the same subgroup: its isomorphic factors have identical norm subgroups. Cyclicity is essential.

Brauer–Hasse–Noether local–global splitting theorem. For a central simple \(K\)-algebra \(A\),

\[ A\text{ splits over }K \quad\Longleftrightarrow\quad A\otimes_K K_v\text{ splits for every place }v. \tag{1} \]

Equivalently, \(\operatorname{Br}(K)\to\bigoplus_v\operatorname{Br}(K_v)\) is injective. See [Milne CFT, Chapter VIII, Theorem 4.2]. The original joint paper is [Brauer–Hasse–Noether, 1932]. We import injectivity, not the complete classification by local invariants or global cyclicity.

The finite crossed-product classification and the splitting criterion for cyclic algebras were proved in lesson 5. Consequently (1) implies the cyclic Hasse norm theorem by applying it to \((L/K,\sigma,a)\). We state the norm theorem separately because section 3 uses its element formulation. Noether's general reduction in section 4 uses (1) directly.

For the quadratic argument, the given genus-character description is recalled below. We import Dirichlet's theorem that each invertible residue class contains a prime (proved in Dirichlet's theorem on primes in arithmetic progressions), only to show that the genus characters have no additional relations. Quadratic reciprocity and the splitting of primes in quadratic fields are also arithmetic inputs. The correspondence of ideals with forms and reduction of positive definite forms are imported; they are due to Dedekind and to Lagrange and Gauss. They also give the finiteness needed here: the reduction bound below leaves only finitely many forms for a fixed negative discriminant. We use these statements without assuming the principal genus theorem.

2. The imaginary quadratic principal genus

Let \(L=\mathbb Q(\sqrt d)\), with \(d<0\) squarefree, and let \(D\) be its fundamental discriminant. Factor

\[ D=d_1\cdots d_t \]

into distinct prime discriminants: for an odd ramified prime \(p\), the factor is \(p^*=(-1)^{(p-1)/2}p\); there is at most one even factor, in \(\{-4,8,-8\}\). Thus \(t\) is the number of ramified rational primes. Write \(\chi_{d_i}(m)=(d_i/m)\) for the quadratic Kronecker character, evaluated on positive integers coprime to \(D\).

An ideal class has an integral representative \(\mathfrak a\) coprime to the ramified primes. The genus characters are

\[ \chi_i([\mathfrak a])=\chi_{d_i}(N\mathfrak a). \tag{2} \]

We use the standard characterization of quadratic genera by these characters: two ideal classes, or their corresponding primitive positive definite forms, are in the same genus exactly when their character values agree. This is Gauss's genus-character description. Its identity fiber is the principal genus.

Here are the elementary features of (2) used in the proof. Multiplicativity of ideal norms makes the characters homomorphisms. Principal ideals contribute value \(1\): at an odd ramified \(p\), a field norm of a local unit reduces to a square modulo \(p\), so \(\chi_{p^*}(N\alpha)=(N\alpha/p)=1\). At \(2\), the same check can be made directly. If \(d\) is odd with even discriminant, \(N(a+b\sqrt d)=a^2-db^2\), when odd, is \(1\bmod4\). If \(d=2m\), an odd norm is \(1\) or \(1-2m\bmod8\): for \(m\equiv1\bmod4\) these are \(1,7\), on which \(\chi_8=1\); for \(m\equiv3\bmod4\) they are \(1,3\), on which \(\chi_{-8}=1\). These checks apply to local units and hence to fractional principal quotients as well. For odd discriminant, writing \(\alpha=(a+b\sqrt d)/2\) gives the same square calculation at every odd ramified prime. Thus the values are independent of the ideal representative. Representatives avoiding finitely many primes exist by ideal approximation, or the Chinese remainder theorem in a Dedekind domain.

The product of all characters is \(1\). Indeed, factor a coprime ideal into unramified prime ideals. A prime above a split rational prime \(\ell\) has norm \(\ell\), with \((D/\ell)=1\); a prime above an inert \(\ell\) has norm \(\ell^2\), also of character \(1\). Therefore (2) defines

\[ \chi:\operatorname{Cl}(L)\longrightarrow E=\{(\epsilon_1,\ldots,\epsilon_t)\in\{\pm1\}^t: \epsilon_1\cdots\epsilon_t=1\}. \tag{3} \]

Theorem 2.1. The map (3) is surjective, and

\[ \ker\chi=\operatorname{Cl}(L)^2. \]

Thus there are \(2^{t-1}\) genera, and the imaginary quadratic principal genus consists exactly of squares.

Proof. First prove surjectivity. At each odd \(p\mid D\), the character \((m/p)\) takes both signs on invertible residues. The even character, when present, takes both signs on invertible residues modulo \(4\) or \(8\). Their moduli are pairwise coprime, so the Chinese remainder theorem prescribes their signs independently on a residue \(m\) coprime to \(D\). For any desired tuple in \(E\), the resulting residue has \((D/m)=1\). Dirichlet's theorem gives a positive prime \(\ell\) in that residue class. It splits in \(L\), and either prime ideal of norm \(\ell\) has exactly the desired tuple. This proves surjectivity. For \(t=1\), the target is already the trivial group.

Every square lies in the kernel because every character has order at most two. To prove equality, we bound the subgroup \(\operatorname{Cl}(L)[2]\) of elements of order dividing two.

Conjugation acts on the class group by inversion: \(\mathfrak a\overline{\mathfrak a}=(N\mathfrak a)\mathcal O_L\). Thus a class of order at most two is fixed by conjugation. Choose its representative \(\mathfrak a\); then \(\overline{\mathfrak a}=(\alpha)\mathfrak a\) for some \(\alpha\in L^\times\). Taking absolute ideal norms gives \(N_{L/\mathbb Q}(\alpha)=1\), since this norm is positive. Scalar Hilbert 90 gives \(\alpha=x/\overline x\). Consequently \(x\mathfrak a\) is fixed by conjugation.

In a conjugation-invariant fractional ideal, the two primes above a split prime occur with equal exponents and give a rational principal ideal. An inert prime itself is a rational principal ideal. Only ramified prime ideals can contribute to its class. Thus \(\operatorname{Cl}(L)[2]\) is generated by the \(t\) ramified prime classes \([\mathfrak p_i]\), each of exponent at most two since \(\mathfrak p_i^2=(p_i)\).

There is at least one nonempty relation among these generators. If \(d\ne-1\), then

\[ (\sqrt d)=\prod_{p\mid d}\mathfrak p_p, \]

because the valuation is one at each prime dividing the squarefree radicand and zero elsewhere. This product is nonempty. If \(d=-1\), the sole ramified prime is already principal, generated by \(1+i\). Therefore

\[ |\operatorname{Cl}(L)[2]|\le2^{t-1}. \]

For any finite abelian group \(C\), the squaring map has kernel \(C[2]\) and image \(C^2\), so \(|C/C^2|=|C[2]|\). Apply this to \(C=\operatorname{Cl}(L)\). Its quotient by squares maps surjectively to \(E\), which has \(2^{t-1}\) elements, and has at most that many elements. The map is therefore bijective. Its kernel before quotienting is exactly \(C^2\). \(\square\)

Notice where the converse was proved: generation of the two-torsion by ramified primes supplies the upper bound, and independent genus characters supply the lower bound. Merely observing that characters kill squares would prove only one inclusion.

Two complete genus calculations

A reduced primitive positive definite form \((A,B,C)\) has discriminant \(B^2-4AC=D\), with \(|B|\le A\le C\), and \(B\ge0\) if \(|B|=A\) or \(A=C\). In particular \(3A^2\le|D|\). The reduction theorem of Lagrange and Gauss gives exactly one such form per proper class, with these boundary conventions.

For \(D=-20=(-4)\cdot5\), the bound gives \(A\le2\). Testing \(A=1,2\), even \(B\), and \(C=(B^2+20)/(4A)\) gives exactly \((1,0,5)\), \((2,2,3)\). Their character values can be read from the coprime numbers they represent:

Form Represented number \(\chi_{-4}\) \(\chi_5\)
\(x^2+5y^2\) \(1\) \(+1\) \(+1\)
\(2x^2+2xy+3y^2\) \(3\) \(-1\) \(-1\)

The two distinct classes give \(\operatorname{Cl}(\mathbb Q(\sqrt{-5}))\simeq\mathbb Z/2\). Each genus has one class, and the principal genus is the identity, equal to the squares.

For \(D=-84=(-4)(-3)(-7)\), the bound gives \(A\le5\). The same finite check gives exactly \((1,0,21)\), \((2,2,11)\), \((3,0,7)\), \((5,4,5)\). For clarity, \(A=4\) produces no integral \(C\) with the required parity and bounds, and at \(A=5\) the solutions \(B=\pm4,C=5\) are one boundary class with \(B=4\).

Form Represented number \(\chi_{-4}\) \(\chi_{-3}\) \(\chi_{-7}\)
\(x^2+21y^2\) \(1\) \(+1\) \(+1\) \(+1\)
\(2x^2+2xy+11y^2\) \(11\) \(-1\) \(-1\) \(+1\)
\(3x^2+7y^2\) \(19\) \(-1\) \(+1\) \(-1\)
\(5x^2+4xy+5y^2\) \(5\) \(+1\) \(-1\) \(-1\)

Here \(19=3\cdot2^2+7\). For the odd characters, \(\chi_{-3}(m)=(m/3)\), \(\chi_{-7}(m)=(m/7)\); the residues \(11\equiv4\), \(19\equiv5\), \(5\equiv5\pmod7\) give the displayed signs. All four possible tuples occur on the four classes. Thus the character map is an isomorphism onto \((\mathbb Z/2)^2\); the class group is that group, there are four genera, and the principal genus again has one class. This determines the group law without guessing from the class number alone.

3. Ideal cocycles and the cyclic theorem

For a family \(\mathfrak c_\sigma\in I_L\), write

\[ (\delta\mathfrak c)(\sigma,\tau) =\frac{\mathfrak c_\sigma\,\sigma(\mathfrak c_\tau)} {\mathfrak c_{\sigma\tau}}. \tag{4} \]

The identity \(\delta\mathfrak c=1\) is the ideal-valued 1-cocycle condition.

Lemma 3.1 (Artin's ideal argument). Every ideal-valued 1-cocycle has the form

\[ \mathfrak c_\sigma=\mathfrak b/\sigma(\mathfrak b). \tag{5} \]

Proof. Define \(\mathfrak b=\sum_{\tau\in G}\mathfrak c_\tau\), the sum of the finitely many fractional ideals as \(\mathcal O_L\)-submodules. It is a nonzero fractional ideal. Multiplication by an invertible ideal distributes over sums, so (4) gives

\[ \mathfrak c_\sigma\,\sigma(\mathfrak b) =\sum_\tau\mathfrak c_\sigma\sigma(\mathfrak c_\tau) =\sum_\tau\mathfrak c_{\sigma\tau}=\mathfrak b. \]

This is (5). For prime exponents, the sum takes the minimum of the finitely many exponents; it is the ideal-theoretic greatest common divisor. The same argument is Noether's first lemma in work 41 §2.3. \(\square\)

Now suppose \(G=\langle\sigma\rangle\) is cyclic of order \(n\). For a place \(v\) ramified in \(L/K\), including a real place becoming complex, call \(\alpha\in K^\times\) a norm residue at \(v\) if \(\alpha\in N_{L_w/K_v}(L_w^\times)\).

Theorem 3.2 (cyclic principal genus, with its norm-residue condition). Suppose

\[ N_{L/K}(\mathfrak a)=(\alpha) \]

and at least one such generator \(\alpha\) is a norm residue at every ramified place. Then

\[ \mathfrak a=(\beta)\,\mathfrak b/\sigma(\mathfrak b) \tag{6} \]

for some \(\beta\in L^\times\), \(\mathfrak b\in I_L\). Conversely (6) supplies a generator \(N(\beta)\) with those norm-residue properties.

Proof. At an unramified finite \(v\), put \(f=[L_w:K_v]\). Prime ideal factorization gives

\[ v\bigl(N\mathfrak a\bigr)=f\sum_{w\mid v}w(\mathfrak a), \]

so \(v(\alpha)\) is divisible by \(f\). In an unramified local extension every unit is a norm, as proved in Lemma 4.1 below, and a ground-field uniformizer has norm its \(f\)-th power. Hence \(\alpha\) is a local norm at this place too. At an unramified infinite place the local extension is trivial; the only nontrivial infinite case is already among the imposed real-to-complex conditions. Thus \(\alpha\) is a local norm everywhere. The imported cyclic Hasse norm theorem gives \(\beta\in L^\times\) with \(N(\beta)=\alpha\).

Put \(\mathfrak d=\mathfrak a/(\beta)\); then its ideal norm is \(1\), and

\[ \prod_{i=0}^{n-1}\sigma^i(\mathfrak d)=\mathcal O_L. \]

This identity follows prime by prime from extension of the ideal norm: the product has exponent \(ef\sum_{w\mid v}w(\mathfrak d)\) at every \(w\mid v\). Define \(\mathfrak c_{\sigma^i}=\prod_{j=0}^{i-1}\sigma^j(\mathfrak d)\), \(0\le i<n\). The norm-one identity handles a carry of exponents, so these ideals satisfy (4) with value \(1\). Lemma 3.1 gives \(\mathfrak d=\mathfrak b/\sigma(\mathfrak b)\), proving (6). Conversely its ideal norm is \((N\beta)\), and a global field norm is a local norm at every place. \(\square\)

The generator qualification matters: replacing \(\alpha\) by an arbitrary unit multiple need not preserve each norm-residue condition. On classes, the principal genus defined by this condition is exactly \((1-\sigma)\operatorname{Cl}(L)\). Indeed the condition is unchanged when \(\mathfrak a\) is multiplied by a principal ideal, because its norm generator is multiplied by a global norm. Theorem 3.2 proves both inclusions. For an imaginary quadratic extension of \(\mathbb Q\), conjugation acts by inversion, so \((1-\sigma)\operatorname{Cl}(L)=\operatorname{Cl}(L)^2\), agreeing with section 2.

The ray-class refinement, stated separately

A ray class group \(\operatorname{Cl}_{\mathfrak M}(L)\) uses ideals prime to a modulus \(\mathfrak M\), with principal generators congruent to \(1\) at its finite part and positive at its designated real places. The modulus cannot be chosen arbitrarily on the upper field while retaining the norm assertion.

Here is the conductor-normalized refinement, imported from [Terada, introduction, p.141, and §1, equation (11), p.143]. Let \(\mathfrak f\) be the conductor of the cyclic extension and let its genus modulus \(\mathfrak F\) have finite part determined by

\[ \mathfrak f\mathcal O_L=\mathfrak D_{L/K}\mathfrak F, \]

where \(\mathfrak D_{L/K}\) is the relative different. For a finite integral ground-field modulus \(\mathfrak m\), put \(\mathfrak M=(\mathfrak m\mathcal O_L)\mathfrak F\). With ideals chosen prime to the moduli, the theorem states

\[ N\mathfrak a=(\alpha),\quad\alpha\equiv1\pmod{\mathfrak m\mathfrak f} \quad\Longleftrightarrow\quad \mathfrak a=(\beta)\,\mathfrak b/\sigma(\mathfrak b),\quad \beta\equiv1\pmod{\mathfrak M}. \]

The conductor's infinite part requires positivity at each real place becoming complex. Thus the ray classes satisfying the left condition form \((1-\sigma)\operatorname{Cl}_{\mathfrak M}(L)\). This is a separate arithmetic theorem, rather than a deduction of all ray congruences from (6).

The conductor factor cannot be discarded. For \(L=\mathbb Q(\sqrt{-5})\), taking both moduli trivial would make every ideal norm a principal ideal of \(\mathbb Q\); the proposed norm condition would include both classes. But \((1-\sigma)\operatorname{Cl}(L)=1\). The abbreviated unrestricted-modulus statement in Lemmermeyer, Theorem 2, p.23 therefore needs its conductor normalization restored. The conductor formulation above retains it explicitly.

A cyclic cubic calculation

Use the field of lesson 5, with \(\theta=\zeta_7+\zeta_7^{-1}\), minimal polynomial \(f(T)=T^3+T^2-2T-1\), and \(\sigma(\theta)=\theta^2-2\). Its group is cyclic of order three. Formula (6) says that every ideal whose norm has a generator satisfying the ramified local norm conditions becomes \(\mathfrak b/\sigma(\mathfrak b)\) after removing one principal factor.

The exact norm identity \(N(t-\theta)=f(t)\) gives

\[ N(2-\theta)=7,\qquad N(\theta+3)=13. \]

Thus the ideals generated by these two elements have norms \((7)\) and \((13)\), respectively, and their generators are local norms at every place. Their instances of (6) use \(\beta=2-\theta\) or \(\theta+3\), and \(\mathfrak b=\mathcal O_L\). The scalar \(2\), in contrast, is not a local norm at the inert unramified prime \(2\): the residue polynomial \(T^3+T^2+1\) is irreducible over \(\mathbb F_2\), so local norm valuations are multiples of three. This was the obstruction making the parameter-2 cyclic algebra nonsplit in lesson 5. The global norm \(8=N(2)\) passes that valuation test.

4. Noether's theorem for a general Galois extension

We first prove the local algebra statements needed to preserve the precise hypothesis of work 41 §2.

Lemma 4.1 (unramified local norms). For a finite unramified extension \(E/F\) of nonarchimedean local fields, of degree \(f\), the norm on units is surjective. The full norm subgroup consists of elements whose normalized valuation is divisible by \(f\).

Proof. A uniformizer \(\pi\) of \(F\) is also a uniformizer of \(E\), with norm \(\pi^f\). The residue extension is \(\mathbb F_{q^f}/\mathbb F_q\). Its multiplicative norm is surjective by the finite-field calculation in lesson 6, so a target unit can first be matched modulo \(\pi\).

For \(m\ge1\) and \(x\in\mathcal O_E\), expansion of the product of the conjugates gives

\[ N(1+\pi^m x)\equiv1+\pi^m\operatorname{Tr}_{E/F}(x) \pmod{\pi^{m+1}}. \]

The residue trace is surjective: its finite-field extension is separable, so its trace pairing is nondegenerate, and the functional \(x\mapsto\operatorname{Tr}(x)\) is nonzero. Thus, after matching a target unit through \(\pi^m\), multiply the current lift by a suitable \(1+\pi^m x\) to match through \(\pi^{m+1}\). These corrections converge in the complete field \(E\); their product is a unit whose norm, by continuity of the finite product defining it, is the exact target. Finally \(v_F(Ny)=f v_E(y)\), so a norm valuation is divisible by \(f\), and uniformizer powers together with the unit assertion give every such element. \(\square\)

Lemma 4.2 (the local corner of a crossed product). Let \(a\) be an \(L^\times\)-valued normalized 2-cocycle, and \(A=A(a)\). For a place \(v\) and a chosen \(w\mid v\), let \(H=G_w\) and \(E=L_w\), \(F=K_v\). Then

\[ [A\otimes_K F]=[A(a|_H,E/F,H)]\quad\text{in }\operatorname{Br}(F). \tag{7} \]

Proof. The coefficient algebra after completion is \(L\otimes_K F=\prod_{w'\mid v}L_{w'}\). Let \(e\) be its primitive idempotent selecting \(w\). Conjugation by \(u_g\) sends the idempotent at \(w\) to the one at \(gw\), so \(e u_g e=0\) unless \(g\in H\). For \(h\in H\), the unit commutes with \(e\). Therefore the corner \(e(A\otimes F)e\) has coefficient field \(E\), basis units \(e u_h\), and exactly the restricted factor system. It is the right-hand crossed product. The completed algebra is central simple, by scalar extension as proved in lesson 4. A nonzero idempotent corner in a matrix algebra over a division ring has the same division representative, hence the same Brauer class, as proved in lesson 5. This proves (7). \(\square\)

Lemma 4.3 (Noether's splitting lemma). Suppose a field-valued factor system \(a\) satisfies

\[ (a(\sigma,\tau))=(\delta\mathfrak c)(\sigma,\tau) \tag{8} \]

for fractional ideals \(\mathfrak c_\sigma\). If \(A(a)\) splits at every place ramified in \(L/K\), including infinite ramification, then it splits globally. Consequently \(a=\delta d\) for elements \(d_\sigma\in L^\times\).

Proof. Fix an unramified finite \(v\), choose \(w\mid v\), and restrict to \(H=G_w\). In \(E=L_w\), every fractional ideal is principal; choose \(c_h\in E^\times\) with \((c_h)=\mathfrak c_h\mathcal O_E\). Equation (8), restricted to \(H\), says

\[ e(h,k)=a(h,k)\,\frac{c_{hk}}{c_h h(c_k)} \]

has valuation zero. It is a unit-valued 2-cocycle, cohomologous to the restricted \(a\). If necessary normalize the cochain at the identity; since \((\mathfrak c_1)=\mathcal O_E\), this only changes units. The group \(H\) is cyclic. In its crossed-product algebra, choose \(u=u_h\) for a generator \(h\), and replace all basis units by \(1,u,\ldots,u^{f-1}\). Their scalar rescalings are products of unit factors \(e\), so \(u^f=t\) is a unit of \(F\). Lemma 4.1 makes \(t\) a norm from \(E\); the cyclic splitting criterion of lesson 5 then makes this local crossed product split. Lemma 4.2 makes \(A(a)\otimes F\) split too.

At an unramified infinite place, the local coefficient extension is trivial, so (7) gives splitting. The remaining places split by hypothesis. The imported local–global theorem (1) now makes \(A(a)\) split over \(K\). Lesson 5's relative crossed-product classification says precisely that its cocycle is a coboundary, \(a(\sigma,\tau)=d_\sigma\sigma(d_\tau)/d_{\sigma\tau}\). \(\square\)

The generators in (8) must be a field-valued factor system. Arbitrarily choosing generators of its principal ideals does not guarantee the field cocycle identity: their associativity defect might be a nontrivial unit. This is one reason to retain Noether's refined definition.

Define \(\mathcal P_{\mathrm{ram}}\) to be the subgroup of ideal-valued 2-cocycles consisting of systems \(((a(\sigma,\tau)))\) for which there exists a field-valued factor system \(a\) with that principal-ideal system and with \(A(a)\) split at every ramified place. It is a subgroup because multiplication and inversion of the field cocycles give tensor products and inverse Brauer classes locally, by lesson 5. It contains \(\delta P_L\), the coboundaries of principal-ideal cochains: their field generators give globally split crossed products.

For a normalized family of ideal classes \(c_\sigma\in\operatorname{Cl}(L)\), choose ideal representatives \(\mathfrak c_\sigma\). Say that the family lies in Noether's principal genus if

\[ \delta\mathfrak c\in\mathcal P_{\mathrm{ram}}. \tag{9} \]

This includes the requirement that \(c_{\sigma\tau}=c_\sigma\sigma(c_\tau)\). Changing representatives multiplies \(\delta\mathfrak c\) by a member of \(\delta P_L\), so (9) is well-defined. It is stronger than merely saying that each ideal in \(\delta\mathfrak c\) is principal.

Theorem 4.4 (Noether's principal genus theorem, work 41 §2). A family satisfying (9) has the form

\[ c_\sigma=b/\sigma(b),\qquad b\in\operatorname{Cl}(L). \tag{10} \]

Conversely every family (10) satisfies (9).

Proof. Condition (9) gives field cocycle generators \(a\) satisfying (8) and the local splitting hypothesis of Lemma 4.3. That lemma gives \(a=\delta d\). Remove the principal ideals \((d_\sigma)\) from the chosen representatives:

\[ \mathfrak e_\sigma=\mathfrak c_\sigma/(d_\sigma). \]

Equation (8) now says \(\delta\mathfrak e=1\). Lemma 3.1 gives \(\mathfrak e_\sigma=\mathfrak b/\sigma(\mathfrak b)\). Passing to classes yields (10), with \(b=[\mathfrak b]\). Conversely choose representatives \(\mathfrak c_\sigma=\mathfrak b/\sigma(\mathfrak b)\). Their ideal factor system is \(1\), generated by the field factor system \(1\), whose algebra splits globally. Thus (9) holds. \(\square\)

This is the second of Noether's three equivalent forms, translated to our fixed left-action convention. Its proof is exactly the two-lemma reduction: remove a principal coboundary using splitting, then solve the ideal cocycle by the ideal sum. The first form describes the same fact through substitutions of the operator cosets by ideal classes, with their factor systems taken modulo the refined subgroup \(\mathcal P_{\mathrm{ram}}\). Conjugation by \(b\) produces the scalar \(b/\sigma(b)\), so (10) says that the prescribed substitution is inner. The third form says that all degree-one crossed representations belonging to this identity factor-system class are equivalent. In degree one, change of basis by \(b\) is again exactly (10). These are statements about multiplicative ideal classes and operator cosets, rather than an additive algebra of ideal classes. Noether explicitly restricts the first form to substitutions of the indicated kind; the ideal class group need not be a maximal commutative subgroup.

5. The later idèle-class formulation

An idèle is a family \(x=(x_w)_w\), \(x_w\in L_w^\times\), such that \(x_w\) is a unit at almost every finite place. Let \(J_L\) be the group of idèles, and \(C_L=J_L/L^\times\) the idèle class group, where \(L^\times\) is embedded diagonally. These are multiplicative \(G\)-modules. Because \(G\) is finite, the group cohomology below is the ordinary finite-group cohomology of these modules; no new continuous-cochain convention is needed.

For this formulation we can give the full reduction to (1). This formulation is due to Artin and Tate.

Lemma 5.1. \(H^1(G,J_L)=1\).

Proof. First fix one place \(v\) of \(K\). Set \(H=G_w\), \(E=L_w\). The product of the groups \(L_{w'}^\times\), for \(w'\mid v\), can be described as the functions \(f:G\to E^\times\) satisfying \(f(gh)=h^{-1}(f(g))\), with action \((\sigma f)(g)=f(\sigma^{-1}g)\). The coordinate at the coset \(gH\) is transported from the completion at \(gw\) back to \(E\) by \(g^{-1}\). This explains both the constraint and the action.

Let \(x_\sigma\) be a 1-cocycle with values in this product. Restriction to \(H\) and evaluation at \(1\) gives a cocycle \(x_h(1)\in E^\times\). Local scalar Hilbert 90, already proved for all finite Galois extensions in lesson 6, gives \(b_0\in E^\times\) with \(x_h(1)=b_0/h(b_0)\). Define

\[ b(g)=\frac{b_0}{x_{g^{-1}}(1)}. \]

The cocycle law gives

\[ x_{h^{-1}g^{-1}}(1)=x_{h^{-1}}(1)h^{-1}\bigl(x_{g^{-1}}(1)\bigr), \]

so \(b(gh)=h^{-1}(b(g))\), as required. Applying it instead to \(g^{-1}\sigma\) gives

\[ x_{g^{-1}\sigma}(1)=x_{g^{-1}}(1)x_\sigma(g), \qquad \frac{b(g)}{b(\sigma^{-1}g)}=x_\sigma(g). \]

Thus this product-valued cocycle is \(b/\sigma(b)\). The argument includes archimedean completions: the nontrivial case is \(\mathbb C/\mathbb R\).

Do this for every \(v\), and check the restricted-product condition. Since there are only finitely many \(x_\sigma\), their coordinates are all units outside one finite set of places. Enlarge that set by the ramified places. At an unramified place outside it, the chosen \(b_0\) can be made a unit: multiply it by the appropriate power of a ground-field uniformizer, which has valuation one in the unramified extension and does not change \(b_0/h(b_0)\). Then every \(b(g)\) is a unit too, since every denominator \(x_{g^{-1}}(1)\) is a unit. The resulting family \(b\) is therefore an idèle. It solves the original cocycle at every coordinate, proving the lemma. \(\square\)

Theorem 5.2 (idèle-class principal genus, conditional on (1)). For every finite Galois extension of number fields,

\[ H^1(G,C_L)=1. \]

Proof. Let \(c_\sigma\in C_L\) be a normalized cocycle and choose idèle representatives \(j_\sigma\), with \(j_1=1\). Its multiplication defects lie in the diagonal subgroup \(L^\times\):

\[ a(\sigma,\tau)=\frac{j_\sigma\sigma(j_\tau)}{j_{\sigma\tau}} \in L^\times. \]

Associativity, or cancellation of the three cochain factors, makes \(a\) a normalized field-valued 2-cocycle. At a chosen completion \(w\), restriction to \(H=G_w\) writes \(a|_H\) as the coboundary of \(j_h(w)\in L_w^\times\). Therefore its local crossed product splits. Lemma 4.2 says that \(A(a)\) splits at every completion of \(K\). The imported theorem (1) makes it split globally, and lesson 5 gives \(a=\delta d\) for a field-valued cochain \(d_\sigma\).

The idèles \(e_\sigma=j_\sigma/d_\sigma\) now satisfy \(\delta e=1\). Lemma 5.1 gives \(e_\sigma=b/\sigma(b)\) for an idèle \(b\). Quotienting by \(L^\times\) removes the \(d_\sigma\), so \(c_\sigma=[b]/\sigma([b])\) in \(C_L\). Every cocycle is a coboundary. \(\square\)

The cohomological mechanism is the connecting map

\[ H^1(G,C_L)\longrightarrow H^2(G,L^\times) \]

from \(1\to L^\times\to J_L\to C_L\to1\). Lemma 5.1 makes it injective. The local lifts make its image locally zero; (1), combined with the relative-Brauer isomorphism, makes that image globally zero. The preceding proof spells out the connecting map and both removals of coboundaries, so this explanation does not leave an exact-sequence step unproved.

The analogous exact sequence \(1\to P_L\to I_L\to\operatorname{Cl}(L)\to1\) sends a class cocycle to its ideal factor system in \(H^2(G,P_L)\). Lemma 3.1 makes this connecting map injective: if that system is the coboundary of principal ideals, remove those ideals from the representatives and apply the lemma. Noether's refined principal class consists of the systems represented by \(\mathcal P_{\mathrm{ram}}\). Theorem 4.4 says that its intersection with the connecting-map image is zero. This is the precise ideal-class version of the two-step argument.

It does not say that \(H^1(G,\operatorname{Cl}(L))\) always vanishes. For \(L=\mathbb Q(\sqrt{-5})\), the class group is \(\mathbb Z/2\), on which conjugation acts trivially. Sending its nonidentity Galois automorphism to the nonidentity ideal class gives a nontrivial class cocycle; all class coboundaries are trivial. The refined local factor-system condition fails for that cocycle. The idèle class group retains the local multiplicative information lost when one passes directly to ideal classes.

Noether's 1933 paper formulates Theorem 4.4 through ideals, factor systems and operator cosets. Theorem 5.2 is the later idèle-class reading, with the explicit comparison just given. Her 1932 ICM lecture, work 39 §§4–5, already explains why splitting algebras supplies the invariant generalization of cyclic norm statements.

6. Exercises

Exercise 6.1 (easy). Enumerate the reduced primitive positive definite forms of discriminant \(-20\), compute their genus characters, and identify the principal genus.

Exercise 6.2 (medium). Show that every square class of an imaginary quadratic field lies in the principal genus. Then explain why this alone does not prove equality, and supply the cardinality argument giving the converse.

Exercise 6.3 (medium). Verify the cyclic principal genus theorem for \(\mathbb Q(\sqrt{-5})/\mathbb Q\), using its class group of order two. Check explicitly that the nonprincipal prime class above \(2\) fails the norm-residue condition on its norm generator.

Exercise 6.4 (medium). Hasse's biquadratic example is \(L=\mathbb Q(\sqrt{-3},\sqrt{13})\). The following standard biquadratic obstruction criterion is given: the Hasse norm principle fails for a biquadratic extension of number fields exactly when every decomposition group is cyclic [Rome, Lemma 2.1 and its proof]. Verify that this criterion applies to \(L/\mathbb Q\). Explain why this refutes a norm theorem for all abelian extensions and why it does not refute Theorem 4.4.

Exercise 6.5 (hard). Express Noether's argument in cohomological language using \(1\to P_L\to I_L\to\operatorname{Cl}(L)\to1\). Define the connecting map on representatives, prove its injectivity, and identify the precise local subgroup whose intersection with its image vanishes. Compare the idèle-class connecting map.

7. Solutions

Solution 6.1. Reduced forms satisfy \(3A^2\le20\), hence \(A=1\) or \(2\), with \(B\) even. For \(A=1\), \(|B|\le1\) forces \(B=0\), giving \(C=5\). For \(A=2\), \(B=0\) gives nonintegral \(C=5/2\); \(B=\pm2\) gives \(C=3\), and the boundary convention chooses \(B=2\). Thus the two classes are \((1,0,5)\) and \((2,2,3)\). The prime-discriminant factors are \(-4,5\). The first form represents \(1\), giving signs \((+1,+1)\). The second represents \(3\), giving \(\chi_{-4}(3)=-1\) and \(\chi_5(3)=(3/5)=-1\). There are two genera, each with one class; the first is the principal genus. The class group has two elements, so its square subgroup is exactly that identity class.

Solution 6.2. A genus character is a homomorphism to \(\{\pm1\}\). Hence \(\chi_i(c^2)=\chi_i(c)^2=1\) for each \(i\), proving \(C^2\subseteq\ker\chi\). Characters of a finite abelian group can kill a larger subgroup, so this inclusion has no converse by itself. In our situation the independent prime-discriminant characters make \(C/C^2\to E\) surjective. Conjugation is inversion, and Hilbert 90 converts every conjugation-fixed class into an invariant ideal. Factoring such an ideal shows that \(C[2]\) is generated by the ramified primes; the relation from \((\sqrt d)\), or \((1+i)\) when \(d=-1\), gives \(|C[2]|\le2^{t-1}\). Since \(|C/C^2|=|C[2]|\) and \(|E|=2^{t-1}\), the surjection is bijective. Therefore \(\ker\chi=C^2\). This proves the missing inclusion rather than assuming the principal genus theorem.

Solution 6.3. Conjugation inverts every class; in a group of order two it acts trivially. Thus \((1-\sigma)\operatorname{Cl}(L)\) is the identity subgroup. Theorem 3.2 consequently says that exactly the principal ideal class can have a norm generator satisfying the ramified norm-residue conditions.

Take \(\mathfrak p=(2,1+\sqrt{-5})\). Its norm is \(2\), and \(\mathfrak p^2=(2)\). It is not principal: an integral generator would have norm \(a^2+5b^2=2\), which has no integer solution. It is therefore the nonidentity class. Generators of its norm ideal are \(2\) and \(-2\). At the real place a norm from \(\mathbb C\) must be positive, so \(-2\) fails. At the ramified prime \(5\), \(2\) is a unit. If it were a norm from \(\mathbb Q_5(\sqrt{-5})\), a preimage would be a local unit: in this ramified quadratic extension, the norm valuation equals its normalized extension valuation. The residue norm of a unit is a square in \(\mathbb F_5^\times\), whereas \(2\) is not a square modulo \(5\). Thus \(2\) fails at \(5\). No generator passes all ramified places. This gives an explicit check on the nonprincipal class, while the principal class has generator \(N\beta\) and satisfies (6).

Solution 6.4. The square classes of \(-3\) and \(13\) are independent, so the Galois group is \((\mathbb Z/2)^2\), abelian and noncyclic. The three quadratic subfields have discriminants \(-3\), \(13\), and \(-39\); only \(3\) and \(13\) ramify. At \(3\), \(13\equiv1\pmod3\), so \(3\) splits in \(\mathbb Q(\sqrt{13})\). The decomposition group in \(L\) is consequently contained in the order-two subgroup fixing that subfield. At \(13\), \(-3\equiv10\equiv6^2\pmod{13}\), so \(13\) splits in \(\mathbb Q(\sqrt{-3})\), and its decomposition group likewise has order at most two. All other finite places are unramified, with cyclic decomposition group generated by Frobenius. At the real place the completion is \(\mathbb C\), with an order-two decomposition group. Thus every decomposition group is cyclic.

The stated biquadratic criterion gives failure of the Hasse norm principle: there exists \(a\in\mathbb Q^\times\) which is a norm at every completion but is not \(N_{L/\mathbb Q}(x)\) for any \(x\in L^\times\). This last existence is the imported obstruction theorem, not an element whose non-norm property we have proved independently. It disproves the proposed extension of the cyclic Hasse norm theorem to all abelian groups. It leaves (1) intact: for a noncyclic extension an element norm condition is not the splitting condition for one cyclic algebra with that extension as its cyclic coefficient field. Noether imposes actual local splitting of a field-valued factor system; Lemma 4.3 and (1) still apply to every Galois group.

Solution 6.5. Represent a class cocycle \(c_\sigma\) by ideals \(\mathfrak c_\sigma\), with \(\mathfrak c_1=\mathcal O_L\). Its defect (4) is a principal-ideal-valued 2-cocycle. If representatives change to \((x_\sigma)\mathfrak c_\sigma\), the defect changes by \(\delta((x_\sigma))\); thus its class in \(H^2(G,P_L)\) is independent of the representatives. Changing the class cocycle by a class coboundary also preserves this class: lift that coboundary to \(\mathfrak b/\sigma(\mathfrak b)\), whose defect is \(1\). These verifications define the connecting map

\[ \kappa:H^1(G,\operatorname{Cl}(L))\longrightarrow H^2(G,P_L). \]

If \(\kappa([c])=1\), its defect is \(\delta((d_\sigma))\) for principal ideals. The ideals \(\mathfrak c_\sigma/(d_\sigma)\) are a genuine ideal cocycle. Lemma 3.1 makes them \(\mathfrak b/\sigma(\mathfrak b)\), so \([c]=1\). This proves injectivity directly.

Let \(R_{\mathrm{ram}}\subseteq H^2(G,P_L)\) be the subgroup of classes having a representative in \(\mathcal P_{\mathrm{ram}}\). This is well-defined under principal-ideal coboundaries because those are generated by globally split field cocycles. If \(\kappa([c])\in R_{\mathrm{ram}}\), multiply a chosen ideal defect by the inverse of the principal-ideal coboundary needed to make it a representative in \(\mathcal P_{\mathrm{ram}}\); equivalently change its ideal representatives. There are now field cocycle generators \(a\) splitting at the ramified places. Lemma 4.3 makes \(a=\delta d\), hence \(\kappa([c])=1\), and injectivity gives \([c]=1\). In symbols,

\[ \kappa\bigl(H^1(G,\operatorname{Cl}(L))\bigr)\cap R_{\mathrm{ram}}=\{1\}. \]

For the idèle sequence the representatives are \(j_\sigma\), and their defects are in \(L^\times\). Lemma 5.1 makes the connecting map injective. Every restricted local defect is a coboundary of a completion-valued cochain, so every associated local algebra splits. Theorem (1) makes the global cocycle a coboundary, proving the entire group \(H^1(G,C_L)\) trivial. The different local information in the two coefficient groups explains why this does not assert the same vanishing for \(\operatorname{Cl}(L)\).

Sources and further reading

The further path for the global inputs and their full arithmetic proofs is Class field theory. The lesson Quadratic fields: ideal classes and binary quadratic forms will supply the wider ideal–form background. This course has completed its passage from operator groups and semisimple representations to the arithmetic meaning of crossed-product factor systems.

What this lesson does not prove

The global Hasse norm theorem and Brauer–Hasse–Noether splitting theorem are imported with exact locators, as are Dirichlet's theorem, quadratic reciprocity and prime splitting, the genus-character characterization, form reduction and the ideal–form correspondence. The conductor-normalized ray refinement, including its different–conductor modulus relation, and the biquadratic obstruction criterion are stated with sources. Their general proofs belong to the relevant number-theory and class-field-theory courses.

The imaginary quadratic principal-genus assertion, its character independence and two-torsion bound, the displayed examples, the cyclic ideal reduction, Noether's exact refined theorem, the conditional idèle-class reduction, and all five exercise solutions are proved here. We neither assume nor assert a Hasse norm theorem for arbitrary abelian extensions. The refinement of factor systems, the requirement that generators actually form a field cocycle, and the infinite-place conditions remain part of the statements.