Complex powers at a boundary

Reconstructed by GPT-6 Astra (OpenAI), Ultra reasoning effort, 4 October 2026. Public domain (CC0).

The upper and lower traces of a complex power differ because the logarithm approaches the negative axis with arguments and . At a negative integer that difference is concentrated at zero. We will derive this point term by multiplying a vanishing branch coefficient by its meromorphic pole.

The proof uses Finite parts of singular powers, including its supplied gamma proof. The full Fourier transform, Gaussian normalization, two-sided inversion and distributional transposes are proved in the accompanying Schwartz Fourier foundations, F1–F5. The circle power-series theorem and identity principle are proved in Cauchy kernels and distributional boundary limits, Corollary 2.2, and Gluing holomorphic sides, Lemma 3.2. The common scalar and integration foundations supply calculus and dominated convergence. We prove the complete Fourier–Laplace limit here, including every complex parameter.

The Fourier transform fixes the phase

The Schwartz space has seminorms , for nonnegative integers . Its continuous complex-linear dual is . The conventions are

Foundation F2 bounds every output seminorm by finitely many input seminorms; F3–F4 prove that these are inverse continuous maps. On distributions set There is no conjugation in this pairing. Foundation F5 proves the corresponding inverse, weak continuity, and where . These identities do not require a square-integral extension.

The normalized powers on Schwartz tests

Write , the entire reciprocal constructed in the gamma companion, and let be the normalized one-sided family from U016.

Lemma 1.1. There is a unique entire extension of to tempered distributions. If is an integer and , it is Every fixed parameter derivative satisfies a common finite Schwartz-seminorm bound on compact parameter sets.

Proof. Fix a compact parameter set and choose with On , the absolute integrand is bounded by . On , choose an integer and use Both majorants are integrable. Parameter differentiation adds powers . At zero the integral is , by gamma-companion (G1). At infinity the substitution reduces the comparison to a polynomial times , integrable by that same elementary estimate. Weighted sup norms are finite sums of Schwartz seminorm bounds, by F1. Derivatives of are bounded on each compact parameter set. Thus all the asserted functional bounds hold.

The complex difference quotient of is its logarithmic derivative integrated along the parameter segment, as in gamma-companion (G2). The preceding bounds on a slightly larger parameter disk dominate that quotient and each subsequent derivative. They prove entire scalar pairings and identify their derivatives.

On compact tests (1.3) is exactly U016, Lemma N1. Compact tests are dense in , by F1, formula (F3). Thus two versions with different agree on all Schwartz tests; every parameter is covered by one of the regions. The same density proves uniqueness. A compact test supported in the negative half-line and all its derivatives vanish on , so has support there for every .

All of U016's identities for , its meromorphic multiple , and its reflected family hold on Schwartz tests: the operators preserve , and compact-test equality extends by density. Laurent coefficients are tempered by the compact-parameter bounds and ordinary scalar products of their convergent power series. In particular and , .

The damped Euler integral at every parameter

Put . We prove the actual distributional limit

Lemma H0 (the right-half-plane logarithm). On , , define Then , , and for .

Proof. The real partial derivatives of the real part are , ; those of the imaginary part are , . The continuous-partials differentiability theorem in the scalar foundation therefore gives the complex derivative . The derivative of vanishes. On the convex right half-plane integrate that derivative along the straight segment from 1 to . The quotient is one at 1, proving the exponential identity. The formula on the positive axis follows from real logarithm and arctangent.

Lemma H1 (Euler transform with positive real parameter). For and ,

Proof. For real , substitute into the Euler integral defining . This gives before multiplying by ; the gamma companion proves .

For in a compact subset of the right half-plane, there is with . Differentiating times in adds , dominated by . This is integrable both at zero and infinity, and the fundamental-theorem difference quotient justifies each complex derivative. Both sides of (H1) are consequently holomorphic in . They agree on the positive real axis. To see why this is sufficient, expand their difference on a disk about any positive point using U013, Corollary 2.2. Its real-axis derivatives all vanish, so its power-series coefficients vanish. The identity principle from U014 then propagates zero across the connected right half-plane.

Lemma H2 (damping and its limit). For every , the damped distribution , supported in , has Fourier transform for . It tends to in as . Both this convergence and its Fourier-transformed version hold locally uniformly in after pairing with any Schwartz test, including every fixed parameter derivative.

Proof. To define the multiplier globally without exponential growth on the negative half-line, choose a smooth equal to zero for and one for , and use . Its derivatives are bounded for each , so F1 makes it a Schwartz multiplier. Different such choices agree near the support of , and their difference times vanishes on compact tests, hence on all Schwartz tests by density. We may therefore write unambiguously.

Choose with . Formula (1.3) gives its pairing as For , the product derivative is On this is bounded by a fixed finite sum of rapidly decreasing derivatives of . The bounds used in Lemma 1.1 dominate the integral at zero and infinity, uniformly in . At zero damping, the term tends to and every term tends to zero. Dominated convergence proves the asserted limit to .

The distributional product rule follows by applying the ordinary product rule to tests. Iterating it on compact tests, where near the support, gives Here U016 gives ; cutoff derivatives away from the support contribute zero. Both sides are tempered, so density extends the identity to .

Since , the damped is an function. Its Fourier transform is , by (H1) and F5's agreement of the integral and distributional transforms. Transforming (H3) and using (F17) gives The last equality uses , so an integer power and the chosen logarithmic power agree. The function on the right is smooth and polynomially bounded for fixed , hence tempered.

Weak Fourier continuity from (F15) now proves (1.4). For the final uniformity assertion, take a compact parameter set and one valid on a neighborhood of it. Every fixed parameter derivative of (H2) is a finite sum with bounded derivatives of and factors . The common bounds from Lemma 1.1 dominate their absolute values. In the difference between damped and undamped integrands the factors and tend to zero independently of . The same dominated bound therefore controls the supremum over that compact set. Replace by to obtain the Fourier assertion.

Rotating the branch

On the cut plane , use with , and . The scalar foundation's circle parametrization gives this argument; on each local angular interval its derivatives are those computed in H0, so . Define by the limits of .

Proposition 1.2 (quarter-turn transport). Both limits exist in for every , and define entire families:

Proof. The argument of belongs to . Multiplication by moves it to , without crossing a cut. Consequently Use (1.4) with and divide by the scalar phase. For the upper trace, multiplication by similarly gives Reflect the variable in (1.4) and divide by this phase. Lemma 1.1 and the continuous test operators show that the pairings in (1.5) are entire, with locally uniform finite-seminorm bounds for all parameter derivatives. H2 also proves convergence of the approximating boundary families with those parameter derivatives.

A branch coefficient cancels a meromorphic pole

Let and , the meromorphic one-sided powers of U016.

Theorem 2.1. Away from negative integers, For an integer , their entire values are In particular,

Proof. First let . For and , if , then If , a constant bounds the power on this interval. Outside it a fixed power of bounds the magnitude. Multiplication by a Schwartz test is therefore dominated by an integrable function. The limiting arguments are zero on and on . Dominated convergence proves (2.1) on every Schwartz test in this half-plane.

For each test, the left side is entire and the right side meromorphic. U016 proves the meromorphic identity principle from local Laurent series and the holomorphic identity theorem. It extends (2.1) away from the discrete poles, and shows that their singular parts cancel.

For the value at a pole put . U016 supplies These are also Laurent expansions on Schwartz tests, by Lemma 1.1 and the scalar gamma expansion. The exponential series gives By the definition of a distributional derivative, . Hence and . The extra constant from the product of phase and pole is . The other constants add to , exactly U016's symmetric finite part. This proves (2.2), and subtraction proves (2.3).

For nonexceptional parameters the jump is . Its value at a negative integer must be computed as a limit of the product: The separate factor has a pole there. At nonnegative integers , both traces are instead : the binomial expansion of and the integrability of every polynomial times a Schwartz test prove this directly.

Differentiation and scaling have no exceptional parameter

For , let .

Proposition 3.1. For all ,

Proof. U016 proves , , and meromorphically. Test substitution shows , , and . Apply these identities to (2.1); use . This gives all three formulas where the parameter and shifted parameters avoid the poles. Each side of each asserted formula, tested against a fixed Schwartz function, is entire by Proposition 1.2 and the continuity of the test operations in F1. The identity principle extends the formulas to every .

For example , so their derivative is zero. The positive and negative Heaviside derivatives cancel in this combined family. At negative integers both the symmetric finite part and the point term in (2.2) have the indicated homogeneous degree.

Corollary 3.2 (one-sided Fourier support). For every , The upper transform is supported in , and the lower transform in .

Proof. Apply to (1.5), then use , commutation with reflection, and . Lemma 1.1 gives the support of ; reflecting it gives the other inclusion.

A parameter derivative produces logarithmic traces

Define . The local bounds in Proposition 1.2 prove that this is an entire tempered family.

Theorem 4.1. For every and , At zero the family has the explicit value and spatial derivative

Proof. Pair (3.1) with a Schwartz test and differentiate the scalar entire identities. Each spatial operation is a fixed continuous test transpose, so the same test applied to the parameter derivative gives its spatial derivative, multiplication or dilation. Ordinary product differentiation gives exactly (4.1).

On a disk about with , (2.1) is an ordinary pair of one-sided integrals. The parameter derivative at zero is dominated near zero by a constant times . At infinity Schwartz decay dominates both the power and its logarithm. Thus differentiation under these integrals gives on both sides, together with on the negative side from the phase derivative. This proves the first line of (4.2). Set in (4.1) and use (2.2) with and U016's to obtain the second line.

These are also the actual boundary traces of , because H2 and Proposition 1.2 justify parameter differentiation of the converging boundary families. A direct check at gives the same conclusion: for the negative part of is at most , its positive part is bounded for , and the argument is at most in absolute value. The tail has at most logarithmic growth. Dominated convergence against Schwartz tests applies.

Exercises

Exercise 1 (basic: square-root traces). Determine both half-line formulas and the upper-minus-lower jump at degrees and . Verify local integrability and temperedness.

Exercise 2 (intermediate: the third pole). Compute the limit of at from its Laurent factors. Evaluate the result on a test with .

Exercise 3 (intermediate: Fourier phases). Compute the Fourier transforms of , , and , and give their supports.

Exercise 4 (advanced: logarithmic jump). Find , its spatial derivative, and its positive-dilation law. Account for the logarithmic scaling term.

Exercise 5 (intermediate: a mixed second-order pole). For , find , and as symmetric finite parts and point jets. Verify the multiplication sign directly on tests.

Exercise 6 (advanced: translation and scale). Let and . Find both boundary traces of and their derivatives. Explain the dependence on .

Complete solutions

Solution 1. At degree , both traces are for . For , the phases give above and below. Their difference is . At degree , both equal for ; on they are respectively and . The jump is . Each exponent exceeds , giving finite integrals on a neighborhood of zero. At infinity there is polynomial growth, so foundation F5 proves temperedness.

Solution 2. Write . The sine series gives ; the reflected residue gives . Their product with tends to . Since , the answer is . The factorial is , and the even delta derivative contributes no additional minus sign.

Solution 3. At , , and the phases in (3.2) are and . Hence Their supports are the closed positive and negative half-lines: a compact test in the complementary open half-line pairs to zero, while a nonnegative nonzero test in any open interval on the indicated side gives a nonzero pairing. At , and , so . Its support is exactly , since tests with prescribed nonzero second derivative at zero exist by multiplying by a cutoff equal to one there. This also checks the transform of the polynomial .

Solution 4. Subtracting (4.2) gives . Directly, because a Schwartz test vanishes at the infinite endpoint. Thus the derivative of the jump is . Formula (4.1) at zero gives the same added term for both signs, since both . Subtraction cancels those terms, so .

Solution 5. Since , (2.2) gives The average and (3.1) imply and . Also , hence . It follows that As a second check, (3.1) gives . Their point terms are and , with the same total.

Solution 6. Multiplication by positive preserves the argument on the cut plane, so . Translations preserve , as proved in F1; thus translated boundary limits remain valid on every test. The two traces are Their derivatives, by translation of (4.2), are Here the translated principal value is defined by translating the test in the already proved principal value at zero. The added constant has zero distributional derivative: its pairing with is zero by the vanishing endpoints. Therefore changing changes the trace by that constant and leaves its derivative unchanged.

Programme proof locations and freely accessible sources

The accompanying selected earlier programme foundations retain their stated CC0 1.0 licences and notices. This lesson and the newly written Schwartz Fourier companion are CC0.