Moduli stacks are algebraic
Source proofs by the Stacks Project authors, as distributed in the AI Integrated Stacks Project. Source copyright: Copyright (C) 2005 -- 2025 Johan de Jong. This modified course edition is published by the Open Math Courses project, KokunoYumeto/open-math-courses. Writing, adaptation and integration: GPT-6.1 Sol (OpenAI), Codex, Ultra, October 2026. Permission is granted to copy, distribute and modify this modified chapter under the GNU Free Documentation License, Version 1.2 or any later version, with no Invariant Sections, Front-Cover Texts or Back-Cover Texts. Eligible independently written additions retain their CC0 1.0 dedication. Self-checked by the writing AI. The complete licence accompanies this edition.
A coherent sheaf can move on a space which is neither proper nor flat over the base. Its moduli problem is nevertheless algebraic if the sheaf itself is flat over the parameter space and has proper support. Quotients and closed subschemes then inherit algebraic coordinates from this stack. Line bundles require a further distinction: their stack remembers scalar automorphisms, whereas the Picard sheaf removes them by descent.
Read Artin's axioms first. We use its proved representable-diagonal criterion, product obstruction criterion and strong-effectiveness criterion. The projective Quot and Hilbert schemes of AG-HP-05, and the curve Picard scheme of AG-HP-09, provide familiar special cases. The coherent-cohomology and derived-category inputs needed here are stated precisely in Section 10. No algebraicity theorem for the moduli problems proved below is taken as an input.
Throughout, \(X\) and \(B\) are algebraic spaces over a scheme \(S\), and \(f:X\to B\) is a morphism. A parameter scheme \(T\to B\) gives \(X_T=X\times_B T\). A sheaf is finitely presented as an \(\mathcal O_{X_T}\)-module; it is flat over \(T\) as a relative module. “Coherent” in the notation for the stack means these two conditions, even when the rings are not Noetherian.
1. Families of homomorphisms
1.1. Proper support, rather than proper ambient space
For a finitely presented sheaf \(G\), its topological support is the closed set where its stalk is nonzero. Its scheme-theoretic support is defined by \(\operatorname{Ann}(G)\). Proper support means that this closed subspace is proper over the base. In the finite-presentation setting used here, an equivalent test uses \[ Z(G)=V(\operatorname{Fitt}_0(G)). \tag{1.1} \] The Fitting ideal is of finite type and commutes with every base change. Its vanishing set is the support. If \(G\) is generated by \(n\) elements locally, then \(\operatorname{Ann}(G)^n\subset\operatorname{Fitt}_0(G)\subset\operatorname{Ann}(G)\). Thus these two closed subspaces differ by a nilpotent thickening. Since \(Z(G)\) is of finite presentation over \(X\), properness of either support gives universal closedness of the other; finite type and separatedness then give properness. This formulation also proves that proper support is stable under arbitrary base change and descends under a faithfully flat cover. It avoids claiming that annihilator ideals themselves always commute with base change.
Define the functor \[ \underline{\operatorname{Hom}}_{X/B}(F,G)(T) =\operatorname{Hom}_{\mathcal O_{X_T}}(F_T,G_T). \tag{1.2} \] Here \(F\) may be any quasi-coherent sheaf. Pullback of a homomorphism defines the functor on all \(B\)-schemes. Quasi-coherent descent makes it an fppf sheaf.
Theorem 1.1 (Hom). Suppose \(f\) is of finite presentation and \(G\) is finitely presented, flat over \(B\), with proper support over \(B\). Then (1.2) is represented by an algebraic space affine over \(B\). If \(F\) is finitely presented, that affine morphism is of finite presentation. Neither separatedness nor flatness of \(f\) is required. This is [Stacks, Tag 08K6].
We first prove the finite calculation behind the theorem.
Lemma 1.2 (a finite complex represents its degree-zero kernel). Let \(A\) be a ring and let \(K\) be perfect over \(A\). Suppose \[ H^i(K\otimes_A^{\mathbf L}C)=0\quad(i<0) \tag{1.3} \] for every \(A\)-algebra \(C\). Locally on \(\operatorname{Spec}A\), the functor \(C\mapsto H^0(K\otimes_A^{\mathbf L}C)\) is represented by an affine scheme of finite presentation.
Proof. Locally represent \(K\) by a bounded complex of finite projectives, and shrink further to make them free. If its first nonzero term \(P^a\) has \(a<0\), then the differential \(P^a\to P^{a+1}\) is injective on every residue-field fibre, by (1.3). At any chosen point an appropriate maximal minor is a unit. On that open set the map is a split injection and the corresponding two equal free summands form a contractible complex. Remove them. Repeating this finite operation removes all terms in negative degrees. It suffices to work with \[ P^0\xrightarrow{d}P^1\longrightarrow\cdots\longrightarrow P^e. \] For every \(C\), degree-zero cohomology is \(\ker(d\otimes C)\). The vector scheme associated to \(P^0\) represents \(P^0\otimes C\): its coordinate algebra is \(\operatorname{Sym}_A((P^0)^\vee)\). Cut it out by the finitely many linear equations expressing \(d(v)=0\), namely the image of \((P^1)^\vee\to(P^0)^\vee\). The resulting affine scheme represents the kernel and is of finite presentation. The local constructions agree because they represent the same functor, so they glue. \(\square\)
Proof of Theorem 1.1, with \(B=\operatorname{Spec}A\) Noetherian and \(F\) finitely presented. The space \(X\) is Noetherian and quasi-compact and quasi-separated. Perfect approximation gives a perfect complex \(P\to F[0]\) with \[ P\in D^{\leq0}(X),\qquad H^0(P)\simeq F. \tag{1.4} \] For clarity, the approximation is an isomorphism in degrees \(>-1\) and surjective in degree \(-1\); as \(F\) has no negative cohomology, these conditions give (1.4). This is the exact ordinary approximation input [Stacks, Tags 08HI, 08HJ and 08HP].
For any base change \(h:X_T\to X\), derived pullback is right \(t\)-exact. Therefore \(\mathbf Lh^*P\) remains in degrees at most zero and its degree-zero cohomology is \(F_T\). Maps from such a complex to the sheaf \(G_T[0]\) in degree zero are exactly maps from its degree-zero cohomology. Indeed, the truncation triangle has a term in \(D^{\leq-1}\), and both that term and its shift by \(1\) have no degree-zero maps to \(G_T[0]\). Consequently \[ \operatorname{Hom}(F_T,G_T) =H^0R\operatorname{Hom}_{X_T}(\mathbf Lh^*P,G_T). \tag{1.5} \]
Set \(K=Rf_*R\mathcal H om(P,G)\). The precise proper-support direct-image theorem says that \(K\) is perfect, and the flatness of \(G\) gives arbitrary derived base change: \[ \mathbf Lg^*K\simeq Rf_{T,*}R\mathcal H om(\mathbf Lh^*P,G_T). \tag{1.6} \] Its hypotheses are a Noetherian base, a quasi-separated locally finite type morphism, a perfect source, and a bounded coherent target flat over the base with proper support. They hold here; properness of \(X\) and flatness of \(X/B\) are absent. See [Stacks, Tags 0DKK and 08JQ].
If \(T=\operatorname{Spec}C\), equations (1.5)–(1.6) identify (1.2) with \(H^0(K\otimes_A^{\mathbf L}C)\). There is no negative cohomology: derived Hom from a complex in degrees at most zero to a sheaf has none, nor does its derived global-section complex. Lemma 1.2 represents this functor affinely with finite presentation. The equalities extend from affine \(T\) to arbitrary \(T\) by the sheaf condition. Equivalently, the degree-zero kernel sheaf of the finite complex has the same sections after gluing an affine cover; no assertion that higher cohomology vanishes on an arbitrary \(T\) is needed.
Passage to arbitrary \(B\). Affineness and finite presentation descend fpqc locally on \(B\), so use affine étale charts and take \(B=\operatorname{Spec}A\). Write \(A\) as the filtered colimit of its finitely generated \(\mathbf Z\)-subalgebras. Finite presentation descends \(X\), \(f\), \(F\), and \(G\) to one of them. After increasing that index, \(G\) is flat over the descended base and has proper support: these are the ordinary finite-presentation flatness and proper-support limit theorems, with the latter in [Stacks, Tag 08K2]. The Noetherian argument supplies an affine finitely presented scheme over that base. Its pullback represents (1.2) over \(A\), because every \(A\)-scheme is also a scheme over the descended base and the sheaves pulled back to its \(X_T\) are exactly \(F_T,G_T\). The identifications commute with pullback. Descent glues these affine schemes on the charts of \(B\).
Passage to arbitrary \(F\). On a quasi-compact quasi-separated algebraic space, a quasi-coherent sheaf is a filtered colimit of finitely presented quasi-coherent sheaves. Write \(F=\operatorname{colim}_iF_i\). Pullback preserves this colimit, and \[ \operatorname{Hom}(F_T,G_T) =\lim_i\operatorname{Hom}((F_i)_T,G_T). \tag{1.7} \] The transition maps on the right come from precomposition. An inverse limit of affine spaces over \(B\) is affine over \(B\): on each affine base chart its algebra is the colimit of their coordinate algebras. Thus (1.7) is represented by an affine space. We make no finite-presentation claim in this last step. This completes the proof. \(\square\)
1.2. Isom requires the hypotheses in both directions
Corollary 1.3 (Isom). If \(f\) is of finite presentation and both \(F\) and \(G\) are finitely presented, flat over \(B\), with proper support, then \(\underline{\operatorname{Isom}}_{X/B}(F,G)\) is affine of finite presentation over \(B\) [Stacks, Tag 08K9].
Proof. All four Hom spaces with source and target in \(\{F,G\}\) satisfy Theorem 1.1. In \(\underline{\operatorname{Hom}}(F,G)\times_B\underline{\operatorname{Hom}}(G,F)\) impose the equations \[ v\circ u=1_F,\qquad u\circ v=1_G. \tag{1.8} \] The composition map has target \(\underline{\operatorname{Hom}}(F,F)\times_B\underline{\operatorname{Hom}}(G,G)\). Its identity section is a closed immersion of finite presentation, since the target is affine of finite presentation. The inverse image is therefore affine of finite presentation. Its points are exactly mutually inverse pairs, and the inverse of an isomorphism is unique. Projection to \(u\) identifies it with Isom, functorially on every base change. \(\square\)
The requirement on \(F\) is substantive. Finite presentation of \(F\) alone does not suffice for this conclusion.
Example 1.4 (an omitted proper-support hypothesis). Let \[ B=\operatorname{Spec}k[t],\quad X=\operatorname{Spec}k[t,x],\quad G=\mathcal O_X/(x),\quad H=\mathcal O_X/(tx-1),\quad F=G\oplus H. \tag{1.9} \] Both \(F\) and \(G\) are finitely presented and flat over \(B\). The support of \(G\) is the zero section, hence proper. The support of \(H\) maps to \(D(t)\) by an isomorphism and is not proper over \(B\). On every \(T\), the element \(x\) annihilates \(G_T\) and is invertible on \(H_T\). Thus an isomorphism \(F_T\simeq G_T\) forces \(H_T=0\); conversely this condition makes \(F_T=G_T\). But \(H_T=0\) means that \(t\) is locally nilpotent on \(T\). The Isom functor has a copy of \(\mathbf G_m(T)\) on such tests and no points on the other tests.
It cannot be affine of finite presentation over \(B\). If it were \(\operatorname{Spec}C\) with \(C\) a finitely presented \(k[t]\)-algebra, then \(C\) would be Noetherian. Every prime of \(C\), tested by its residue field, would contain \(t\). Hence \(t^N=0\) in \(C\) for some \(N\geq1\). Nevertheless \(T=\operatorname{Spec}(k[t]/(t^{N+1}))\) has the identity isomorphism \(F_T=G_T\), giving a \(k[t]\)-algebra map \(C\to k[t]/(t^{N+1})\). This contradicts \(t^N=0\). Formula (1.9) explains why Corollary 1.3 retains flatness and proper support for both sheaves.
2. The coherent-sheaf groupoid and its diagonal
From now on assume that \(f:X\to B\) is separated and of finite presentation. Define \(\mathcal C=\mathcal{Coh}_{X/B}\) over \(B\) as follows. An object over \(T\to B\) is a finitely presented quasi-coherent sheaf \(F\) on \(X_T\), flat over \(T\), with proper support over \(T\). An arrow over \(T'\to T\) is an isomorphism \(F'\simeq F|_{X_{T'}}\). Thus cartesian arrows are part of the definition, and pullback of sheaves makes \(\mathcal C\) a category fibred in groupoids [Stacks, Tags 08KB and 08W5].
Lemma 2.1 (descent and diagonal). The category \(\mathcal C\) is an fppf stack. Its relative diagonal over \(B\) is affine of finite presentation.
Proof. A descent datum consists of quasi-coherent sheaves and isomorphisms satisfying the cocycle, not just their isomorphism classes. Effective quasi-coherent descent on algebraic spaces glues the sheaf and all its arrows. Finite presentation and relative flatness descend faithfully flat. The Fitting-support test (1.1) and descent of properness descend proper support. Hence the descended sheaf is an object of \(\mathcal C\).
For two objects \(F,G\) over \(T\), the fibre of the diagonal is \(\underline{\operatorname{Isom}}_{X_T/T}(F,G)\), including the specified identifying arrow. Both sheaves satisfy Corollary 1.3. This proves the diagonal assertion. \(\square\)
Viewed over \(S\), the diagonal is still representable by algebraic spaces. Given \(g,h:T\to B\) and two families, first require \(g=h\): this is the base change of \(\Delta_{B/S}\), an algebraic space over \(T\). Over that equality space apply the preceding Isom construction. We do not claim that the absolute diagonal over \(S\) is affine unless the needed hypothesis on \(B/S\) is also present [Stacks, Tags 08W6 and 08KC].
There is no size obstruction in applying Artin's criterion. On a fixed \(T\), finitely presented modules can be described on étale charts by finite matrices, gluing matrices and finitely many equality conditions on a covering refinement. These data belong to a set in the chosen universe. Morphisms between two sheaves are a set by the ordinary module category. Choose a set of representatives of the resulting isomorphism classes. This gives the small fibres required in the criterion without bounding the ranks of all sheaves simultaneously.
Lemma 2.2 (full limit preservation). If \(A=\operatorname{colim}_iA_i\) is a filtered colimit of \(B\)-algebras, then \[ \operatorname{colim}_i\mathcal C(A_i)\ \longrightarrow\ \mathcal C(A) \tag{2.1} \] is an equivalence of groupoids.
Proof. A finitely presented sheaf on \(X_A\) descends to some \(X_{A_i}\): use finitely many affine étale charts, finite presentations of the modules, and finite presentations of the gluing maps; their equations and cocycle equalities hold at some finite index. Relative flatness descends after increasing the index. Proper support descends by the finite-type support limit theorem used in Theorem 1.1. Thus an object descends.
For two descended objects, each homomorphism descends by finite presentation and the same finite-chart calculation. An isomorphism descends together with its inverse. The two inverse equalities, or the equality of two descended arrows, hold after a further increase because the diagram is filtered. This proves full faithfulness as well as essential surjectivity. The assertions are local on \(B\), so apply the affine argument on an étale chart and descend. \(\square\)
This is the full groupoid form of [Stacks, Tag 08KD]. In particular the relative morphism \(\mathcal C\to B\), once algebraicity is known, will be locally of finite presentation.
Numerical pieces. Suppose \(X/B\) is projective with a fixed relatively ample line bundle \(L\). For a family \(F\), the Euler characteristic \(\chi(X_t,F_t\otimes L_t^n)\), for each integer \(n\), is locally constant in \(t\). On a Noetherian affine parameter chart this follows by representing the proper flat coherent direct image by a perfect complex: its fibrewise Euler characteristic is the alternating sum of its locally constant finite-projective ranks. It is compatible with field extension. All such functions are constant on each connected component. A Noetherian affine has finitely many connected components, each open, so the entire Hilbert polynomial of the fibres is constant on each of them. For an arbitrary affine parameter chart, descend \(X,L,F\), including relative flatness and proper support, to a Noetherian model and pull these pieces back. Thus a prescribed Hilbert polynomial defines an open and closed substack of \(\mathcal C\). The same construction gives the usual numerical pieces of Quot and Hilbert. This explains the numerical decompositions discussed in [Stacks, Tags 0DLX, 0DM1 and 0DM5], without treating an arbitrary infinite intersection of open sets as open.
3. Patching sheaves without a flat ambient space
The ring square in this section is \[ A_1\longrightarrow A_0\longleftarrow A_2,\qquad A_2\twoheadrightarrow A_0,\quad I^2=0,\qquad P=A_1\times_{A_0}A_2. \tag{3.1} \] Let \(J=\ker(P\to A_1)\). Projection identifies \(J\) with \(I\), and \(J^2=0\). The following algebra is why a nonflat \(X/P\) causes no problem.
Lemma 3.1 (flat module patching). A pair of flat modules \(M_i/A_i\), \(i=1,2\), with a specified isomorphism \[ M_1\otimes_{A_1}A_0\simeq M_2\otimes_{A_2}A_0=M_0 \] patches to the flat \(P\)-module \(M=M_1\times_{M_0}M_2\). Its two base changes recover the given modules. Every flat \(P\)-module is recovered this way, including all its homomorphisms.
Proof. We first record the reduction calculation. The map \(M\to M_1\) is surjective, with kernel \(IM_2\), viewed as pairs \((0,m_2)\). The image of \(M_1\) generates \(M_0\) over \(A_0\). Lifting coefficients to \(A_2\) shows that the image of \(M\to M_2\), together with \(IM_2\), generates \(M_2\). Since \(I^2=0\), this image generates \(M_2\) by the nilpotent Nakayama calculation. Multiplication by \(J=I\) then gives \(JM=IM_2\). Hence \(M\otimes_P A_1=M_1\).
The map \(M\otimes_P A_2\to M_2\) is surjective by this generation statement. A kernel element reduces to zero in \(M_0=M_1\otimes_{A_1}A_0\); tensor right exactness expresses it using pairs in \(IM_2\) and tensors \(m\otimes i\). Each such tensor can be moved to the first factor, using the corresponding element of \(J\). Thus it is \((0,z)\otimes1\) for \(z\in IM_2\). Its image in \(M_2\) is \(z\), so it is zero when its image is zero. This proves the second base-change identity. This elementary calculation is [Stacks, Tag 07RU].
To prove flatness, use the ideal criterion. For any ideal \(\mathfrak a\subset P\), its image \((\mathfrak a+J)/J\) is an ideal of \(A_1\), so its tensor map into \(M_1\) is injective. Therefore a kernel element of \(\mathfrak a\otimes_PM\to M\) comes from \((\mathfrak a\cap J)\otimes_PM\). Also \[ J\otimes_PM=I\otimes_{A_2}M_2\ \longrightarrow\ M_2 \] is injective, by flatness of \(M_2\). It follows that \(\operatorname{Tor}_1^P(A_1,M)=0\). As \(M_1\) is flat over \(A_1\), the change-of-rings Tor sequence gives \(\operatorname{Tor}_1^P(N,M)=0\) for every \(A_1\)-module \(N\).
Set \(L=\mathfrak a\cap J\). Enlarge it to the \(A_2\)-submodule \(L'=A_2L\subset I=J\). The quotient \(L'/L\) is annihilated by \(J\). The Tor vanishing just proved shows that \(L\otimes_PM\to L'\otimes_PM\) is injective. But \[ L'\otimes_PM=L'\otimes_{A_2}M_2\ \longrightarrow\ M_2 \] is injective, since \(L'\) is an ideal of \(A_2\) and \(M_2\) is flat. It follows that \(L\otimes_PM\to M\) is injective. This eliminates the original kernel and proves flatness. This is the ideal argument of [Stacks, Tag 0D2I].
Finally, tensoring the exact sequence \[ 0\longrightarrow P\longrightarrow A_1\oplus A_2 \longrightarrow A_0\longrightarrow0 \] with a flat \(P\)-module recovers it as the stated fibre product. Maps into a fibre product are exactly compatible pairs of maps. The base-change identities make these statements inverse functors, proving full faithfulness. \(\square\)
Lemma 3.2 (relative patching and finite presentation). Let \(C\) be a finitely presented \(P\)-algebra, \(C_i=C\otimes_PA_i\). Compatible \(C_i\)-modules \(M_i\), flat over \(A_i\), patch to a \(C\)-module \(M\) flat over \(P\). If the \(M_i\) are finitely presented over \(C_i\), then \(M\) is finitely presented over \(C\). No flatness of \(C/P\) is assumed.
Proof. Apply Lemma 3.1 to the underlying base modules. The \(C\)-action on the fibre product is componentwise through \(C\to C_i\); it is well defined because the two actions agree over \(C_0\). The recovered base changes recover the \(C_i\)-actions. Full faithfulness for \(C\)-linear maps follows by patching the underlying maps and testing \(C\)-linearity on the two restrictions; the target injects into their product.
For finite presentation choose a finite presentation \(C=D/K\), where \(D=P[z_1,\ldots,z_n]\) and \(K\) is finitely generated. The algebra \(D\) is flat over \(P\), although \(C\) need not be. The module \(M/JM=M_1\) is finite over \(D_1\). Lift its finitely many generators to \(M\), and let \(L\) be their \(D\)-span. Then \(M/L=J(M/L)=J^2(M/L)=0\). Thus \(D^r\twoheadrightarrow M\) for some finite \(r\).
Write \(H\) for its kernel. Since \(M\) and \(D^r\) are flat over \(P\), \(H\) is flat over \(P\), and base change preserves the exact sequence. Hence \[ H\otimes_PA_i=\ker(D_i^r\to M_i). \] These kernels are finite over \(D_i\), since \(C_i\) is finitely presented over \(D_i\) and \(M_i\) is finitely presented over \(C_i\). Lift finitely many generators of \(H/JH\) to \(H\). The identical nilpotent Nakayama calculation proves that \(H\) is finite over \(D\). Therefore \(M\) is finitely presented over \(D\), and consequently over its quotient \(C\), which already acts on \(M\). \(\square\)
Proposition 3.3 (the full Rim–Schlessinger condition). The stack \(\mathcal C\) satisfies (RS\(^*\)): \[ \mathcal C(P)\ \xrightarrow{\sim}\ \mathcal C(A_1)\times_{\mathcal C(A_0)}\mathcal C(A_2) \tag{3.2} \] for every diagram (3.1). In particular it satisfies Artin's Artinian condition (RS) [Stacks, Tag 08LQ].
Proof. On an affine étale chart \(\operatorname{Spec}C\to X_P\), pull the two sheaves and their given identification back to \(C_i\). These are exactly the modules of Lemma 3.2. Patch them to a finitely presented \(C\)-module, flat over \(P\). On overlaps patch the descent isomorphisms by full faithfulness. The cocycle equality holds because it holds on both restrictions and the patched target injects into their product. Étale descent then gives a sheaf on \(X_P\). The same argument patches all arrows; inverse arrows patch too, so the equivalence is one of groupoids.
Its support is proper over \(P\). Indeed, \(P\to A_1\) is a square-zero quotient, so \(\operatorname{Spec}A_1\to\operatorname{Spec}P\) is a universal homeomorphism. By (1.1), the support of the patched sheaf is a separated finite type space whose restriction to this thickening is the proper support of the first sheaf. After any base change, the thickening is still a homeomorphism and that restricted support is closed in the base. Hence the support upstairs is universally closed. Separatedness and finite type make it proper.
Conversely, apply the final recovery assertion of Lemma 3.1 on each chart to a sheaf flat over \(P\). It recovers the sheaf, its identifications and all arrows. This proves (3.2), without inserting flatness of \(X_P/P\) anywhere. \(\square\)
The finite-presentation part of Lemma 3.2 also explains [Stacks, Tag 08W7]: a relatively flat lift through a square-zero base thickening is finitely presented if its restriction is. When the ambient algebra is not flat, the polynomial algebra \(D\), rather than that ambient algebra, provides the flat presentation used in the proof.
4. Tangents and effective formal families
In this section work locally on \(B\) over a Noetherian affine base. When computing a relative tangent, the map to \(B\) is fixed. Artin's criterion can be applied with that affine base as \(S\); there is no need to add deformations of a moving base map.
Proposition 4.1 (tangent and infinitesimal automorphism spaces). For a field \(k\to B\) and an object \(F\in\mathcal C(k)\), \[ T_F\mathcal C=\operatorname{Ext}^1_{X_k}(F,F),\qquad \operatorname{Inf}_F\mathcal C=\operatorname{Hom}_{X_k}(F,F). \tag{4.1} \] If \(k\) is a finite type field over the Noetherian base, these are finite-dimensional \(k\)-vector spaces [Stacks, Tag 08W8].
Proof. The first-order space is \(X_k\times_k\operatorname{Spec}k[\epsilon]\). A marked sheaf \(F'\), flat over \(k[\epsilon]\), gives \[ 0\longrightarrow F\longrightarrow F'\longrightarrow F\longrightarrow0 \tag{4.2} \] as sheaves on \(X_k\): multiplication by \(\epsilon\) identifies the first \(F\) with the kernel of reduction. Conversely, an extension (4.2) becomes a module over \(\mathcal O_{X_k}[\epsilon]\) by making \(\epsilon\) the composite of quotient and inclusion. Its square is zero, and its kernel equals its image. This is the square-zero flatness criterion over \(k[\epsilon]\), so it is a relatively flat deformation. It is finitely presented: on Noetherian charts its middle module is coherent, hence finitely presented; equivalently use the finite-presentation lifting argument of Section 3. Its support is a nilpotent thickening of the original proper support. Thus marked deformations and extensions correspond, and Baer addition agrees with tangent addition.
An automorphism reducing to the identity is \(1+\epsilon a\), where \(a:F\to F\); its inverse is \(1-\epsilon a\), and composition adds \(a\)'s. This proves the second formula.
For finiteness, the sheaves \(\mathcal E xt^q(F,F)\) are coherent on the Noetherian space \(X_k\) and supported on the proper support of \(F\). Coherent cohomology with proper support is finite-dimensional. The local-to-global spectral sequence \[ H^p(X_k,\mathcal E xt^q(F,F)) \ \Longrightarrow\ \operatorname{Ext}^{p+q}_{X_k}(F,F) \] has only finitely many terms in any fixed total degree \(p+q\geq0\). It makes the two groups in (4.1) finite. This argument works after every finite extension of \(k\), including inseparable extensions. It does not replace proper support by a false properness assumption on \(X_k\). \(\square\)
Proposition 4.2 (formal existence with every arrow). Let \(R\) be a complete Noetherian local ring, with maximal ideal \(\mathfrak m\), and a map \(\operatorname{Spec}R\to B\). Then \[ \mathcal C(R)\ \longrightarrow\ \lim_n\mathcal C(R/\mathfrak m^{n+1}) \tag{4.3} \] is an equivalence of groupoids [Stacks, Tag 08W9].
Proof. The proper-support Grothendieck existence theorem on the separated finite type algebraic space \(X_R\) is an equivalence between coherent sheaves with proper support and compatible coherent formal sheaves with proper support. Its morphisms are all compatible homomorphisms. Apply it to the given system \((F_n,\phi_n)\) to obtain a coherent sheaf \(F\) with proper support and the prescribed identifications. Since the space is Noetherian, \(F\) is finitely presented.
It remains to check relative flatness; ordinary existence alone does not include that conclusion. On an affine étale chart the completed flatness criterion says that a finite module whose reductions are flat over every \(R/\mathfrak m^{n+1}\) is flat over \(R\) at every point of the closed fibre. This follows from the ideal criterion for flatness and Krull intersection, and its exact relative-space formulation is [Stacks, Tag 08VP]. The relative flat locus of \(F\) is open. Its closed complement lies in the proper support of \(F\), since a zero sheaf is flat. The image of that complement in \(\operatorname{Spec}R\) is closed and misses the closed point. Any nonempty closed subset of the spectrum of a local ring contains its closed point. The complement is therefore empty, proving flatness on all of \(X_R\).
Existence is fully faithful on coherent sheaves with proper support. Hence every compatible arrow in (4.3) is a unique homomorphism upstairs. If its reductions are isomorphisms, apply full faithfulness also to their compatible inverses; the two composites are identities by faithfulness. Thus all isomorphisms and their compositions are recovered. This proves the equivalence, not just effectivity on isomorphism classes. \(\square\)
The ordinary existence input used here is [Stacks, Tags 08B7 and 08BE], with the complete Noetherian ring and proper-support hypotheses just stated. It allows \(X_R\) to be an algebraic space and to be nonproper.
5. Openness and the algebraicity theorem
5.1. Flat ambient morphisms: a perfect complex of low Ext groups
First suppose \(f\) is flat. Over a Noetherian affine parameter space \(\operatorname{Spec}A\), let \(F\) be a family. For a square-zero extension \(A'\twoheadrightarrow A\), with kernel \(M\), the flat-module deformation theorem gives an obstruction \[ o_F(A')\in \operatorname{Ext}^2_{X_A}(F,F\otimes_AM). \tag{5.1} \] It is zero exactly when there is a marked relatively flat lift. When lifts exist, their classes form a torsor under \(\operatorname{Ext}^1(F,F\otimes_AM)\), and their marked automorphisms are \(\operatorname{Ext}^0(F,F\otimes_AM)\). The obstruction commutes with maps of extensions with fixed quotient \(A\). These are the precise deformation inputs [Stacks, Tags 08VW and 0CYE]; they apply because both \(X_A/A\) and \(X_{A'}/A'\) are flat. Finite presentation of a lift is automatic by the lifting argument of Section 3, and its support is proper by nilpotent invariance. Hence (5.1) detects lifts in \(\mathcal C\), rather than lifts in a larger module category.
We explain why these groups commute with products of arbitrary \(A\)-modules. This is stronger than their finite generation for finite modules.
Lemma 5.1 (one complex computes the low Ext functors). There is a perfect \(K\in D(A)\), depending on \(F\), with functorial isomorphisms \[ H^i(K\otimes_A^{\mathbf L}M) \simeq \operatorname{Ext}^i_{X_A}(F,F\otimes_AM) \quad(i\leq2) \tag{5.2} \] for every \(A\)-module \(M\), compatible with the boundary maps of short exact module sequences.
Proof. Choose a perfect approximation \(P\to F\) which is an isomorphism in degrees \(>-3\) and surjective in degree \(-3\). Its cone \(E\) lies in \(D^{\leq-4}(X_A)\). The target \(F\otimes_AM\) is a sheaf in degree zero, so \(\operatorname{Ext}^i(E,F\otimes_AM)=0\) for \(i\leq3\). The Hom long exact sequence therefore gives \[ \operatorname{Ext}^i(F,F\otimes_AM) \simeq\operatorname{Ext}^i(P,F\otimes_AM) \quad(i\leq2). \] Put \(K=Rf_*R\mathcal H om(P,F)\). It is perfect by the proper-support direct-image theorem used in Section 1. Its projection-formula calculation for an arbitrary module gives \[ R\Gamma(X_A,R\mathcal H om(P,F\otimes_AM)) \simeq K\otimes_A^{\mathbf L}M. \] Indeed \(P\) is perfect, so internal Hom is \(P^\vee\otimes-\); \(F\) is \(A\)-flat, so its ordinary tensor with \(M\) is its derived tensor. The derived projection formula then gives the displayed equality. Taking cohomology proves (5.2). All maps are induced by exact or derived functors, so the connecting maps agree. This is the low-degree construction in [Stacks, Tag 08JR], with its approximation and direct-image ingredients exposed. \(\square\)
Locally represent \(K\) by a bounded complex of finite projective \(A\)-modules. Finite projectives tensor-commute with products: first prove this for a finite free module and then take a direct summand. Thus \[ K\otimes_A\prod_jM_j\simeq\prod_j(K\otimes_AM_j) \] term by term. Products of module sequences are exact, and kernels and images of the componentwise differential are the products of the respective kernels and images. Consequently cohomology also commutes with these products. Formula (5.2) proves \[ T_F(\prod_jM_j)\simeq\prod_jT_F(M_j),\qquad O_F(\prod_jM_j)\simeq\prod_jO_F(M_j), \tag{5.3} \] where \(T_F=\operatorname{Ext}^1(F,F\otimes_A-)\) and \(O_F=\operatorname{Ext}^2(F,F\otimes_A-)\).
The proved product criterion of Lesson 7, Theorem 5.3, now applies: the diagonal is representable, (RS\(^*\)) and limits hold, and (5.1) is a vanishing-if-and-only-if obstruction compatible with maps of extensions. Its proof only uses the fixed-quotient functoriality present here. Equations (5.3) supply its two product conditions, so versal loci are open. This verifies [Stacks, Tag 08WA] in the flat case by the product route; it does not assume that \(F\) is a perfect sheaf.
5.2. Nonflat ambient morphisms: stronger coherent existence
If \(f\) is not flat, the ambient thickenings used in (5.1) need not be flat, so the preceding obstruction formula is not a valid justification for openness. A different input supplies it.
Appendix A §A.6 proves the following precise coherent-existence theorem, distinct from Proposition 4.2. Let \(A_n\) be an inverse sequence of rings with surjective transition maps whose kernels are locally nilpotent, put \(A=\lim_nA_n\), and let \(Y/A\) be separated and of finite presentation. A compatible system of finitely presented sheaves \(G_n\) on \(Y_{A_n}\), flat over \(A_n\) with proper support, has a finitely presented sheaf \(G\) on \(Y\), flat over \(A\) with proper support, together with isomorphisms to all the \(G_n\) respecting their specified transition isomorphisms. There is no Noetherian or adic hypothesis on this sequence, and no flatness hypothesis on \(Y/A\). This is [Stacks, Tags 0CX4 and 0CXB]. It is an ordinary coherent-existence prerequisite, not an algebraicity assertion about \(\mathcal C\).
Apply this theorem to an inverse tower used in the strong-effectiveness criterion of Lesson 7, Section 5.1. In that criterion the kernel of every map \(A_m\to A_n\), \(m\geq n\), is square zero, so in particular it is locally nilpotent. The given objects are precisely the \(G_n\) in the theorem. The compatible maps \(\operatorname{Spec}A_n\to B\) give a map \(\operatorname{Spec}A\to B\) in the local affine calculation, and \(Y=X_A\) is separated of finite presentation. Thus the compatible groupoid object is effective, with its required markings, over the inverse-limit ring.
The already proved strong-effectiveness criterion requires only this object effectivity with compatible identifications, a representable diagonal, (RS\(^*\)), and limit preservation. Lemmas 2.1–2.2 and Proposition 3.3 establish the other hypotheses. The criterion therefore proves openness of versality for general \(f\). The formal axiom (4.3) alone would not justify this step; the stronger existence theorem supplies exactly the missing tower hypothesis.
5.3. Every axiom, and arbitrary bases
Theorem 5.2 (coherent-sheaf algebraicity). For every separated morphism \(f:X\to B\) of finite presentation, \(\mathcal{Coh}_{X/B}\) is an algebraic stack, locally of finite presentation over \(B\). Its relative diagonal is affine of finite presentation. In particular it is an algebraic stack over \(S\). These are [Stacks, Tags 08WC and 09DS]; the first is the flat case and the second drops flatness.
Proof. First suppose \(B=\operatorname{Spec}\Lambda\), where \(\Lambda\) is a finitely generated \(\mathbf Z\)-algebra. It is Noetherian and a G-ring, as are its finite type extensions [Stacks, Tag 07PX]. We apply the representable-diagonal version of Artin's criterion proved in Lesson 7, Theorem 4.1. Here is every hypothesis, with its verification:
| Criterion input | Verification for \(\mathcal C\) |
|---|---|
| Representable diagonal | The affine Isom space of Corollary 1.3 |
| G-ring hypothesis at finite type points | Finite type \(\Lambda\)-algebras are G-rings |
| [−1] Small fibres | The finite-presentation descriptions following Lemma 2.1 bound object isomorphism classes and arrow sets in the chosen universe |
| [0] Effective étale descent | The stronger fppf descent of Lemma 2.1, including all arrows |
| [1] Limit preservation | The groupoid equivalence of Lemma 2.2 |
| [2] Rim–Schlessinger | Proposition 3.3 proves the stronger arbitrary-ring (RS\(^*\)) |
| [3] Finite tangent and infinitesimal automorphism spaces | Proposition 4.1, after every finite residue-field extension |
| [4] Formal effectivity | Proposition 4.2 proves an equivalence over every complete Noetherian local test ring |
| [5] Openness of versality | Section 5.1 if \(f\) is flat; Section 5.2 without that assumption |
Because the first diagonal is already representable, Theorem 4.1 requires openness of versality for \(\mathcal C\) itself. The criterion gives a smooth scheme atlas and hence algebraicity. Its local finite-presentation conclusion, or the equivalence between local finite presentation and full limit preservation for algebraic stacks, gives \(\mathcal C\to B\) locally of finite presentation. Lemma 2.1 supplies the stronger diagonal assertion.
Now let \(B=\operatorname{Spec}A\) be arbitrary. Finite presentation and separatedness descend \(X/A\) to a separated finitely presented space \(X_0/A_0\), where \(A_0\) is finitely generated over \(\mathbf Z\). If proving the flat case separately, descend flatness too by increasing the index. For every \(A\)-scheme \(T\), the space \((X_0)_T\) is \(X_T\), and the conditions defining its sheaves are the same. Therefore there is an equivalence of stacks \[ \mathcal{Coh}_{X/A}\simeq \mathcal{Coh}_{X_0/A_0}\times_{\operatorname{Spec}A_0}\operatorname{Spec}A. \tag{5.4} \] This is an equality of moduli conditions for all \(T\), not a claim that every family comes from \(A_0\). Pull back the smooth atlas just constructed. Algebraicity and local finite presentation are preserved by base change.
Finally choose an étale scheme cover \(B'\to B\) and cover \(B'\) by affines. On them (5.4) gives algebraic stacks and smooth scheme atlases. Their disjoint union is a smooth scheme cover of \(\mathcal C\): the map from the pulled-back stack to \(\mathcal C\) is representable étale, and the covers are surjective. The relative diagonal is representable by Lemma 2.1, so the smooth-atlas recognition theorem of Lesson 5 proves algebraicity over \(B\) and over \(S\). Local finite presentation over \(B\) is étale local and follows from the affine case. No finiteness, Noetherian or G-ring condition on \(B/S\) remains in the conclusion. \(\square\)
The proof establishes the flat-case theorem by its own obstruction calculation and the general theorem by strong existence. It never uses either theorem as a shortcut to the other axioms.
6. Quotients and closed subschemes
6.1. The quotient functor
For a quasi-coherent \(F\) on \(X\), a point of \(\operatorname{Quot}_{F/X/B}(T)\) is an equivalence class of surjections \[ q\colon F_T\twoheadrightarrow Q,\qquad Q\in\mathcal C(T). \tag{6.1} \] Two surjections are equivalent if an isomorphism of their targets carries one to the other. Such an isomorphism is unique because \(q\) is surjective. Hence the groupoid of pairs \((Q,q)\) has no nontrivial automorphisms; its isomorphism classes form an fppf sheaf by descent of sheaves and maps. We retain the pair groupoid during the proof, so that no descent identification is lost [Stacks, Tag 09TQ].
Lemma 6.1 (surjectivity is an open condition). For a family \(u:F_T\to Q\), with \(Q\) finitely presented and of proper support, there is an open \(T^\circ\subset T\) such that a map \(T'\to T\) factors through it exactly when \(u_{T'}\) is surjective. This holds without finite presentation of \(F\).
Proof. The cokernel \(H\) is of finite type because it is a quotient of \(Q\). Its support is a closed subset of the proper support of \(Q\), so its image in \(T\) is closed. Take the complement for \(T^\circ\). For a finite type module, vanishing on a fibre is detected at its residue fields by Nakayama. It follows that after any base change its support is the inverse image of its original support. The cokernel of a pulled-back map is the pullback of its cokernel by tensor right exactness. Thus \(H_{T'}=0\) exactly when \(T'\) avoids that closed image. This proves the universal property. \(\square\)
This is the proper-support surjectivity test [Stacks, Tag 09TP]. One can also test it in the universal Hom family: the preceding proof works over its parameter space.
Theorem 6.2 (Quot). For separated \(f\) of finite presentation and arbitrary quasi-coherent \(F\), \(\operatorname{Quot}_{F/X/B}\) is an algebraic space. It is locally of finite presentation over \(B\) if \(F\) is finitely presented [Stacks, Tag 09TU].
Proof. Forget \(q\) to obtain a morphism from the pair stack to \(\mathcal C\). Pull it back by an object \(Q\) over \(T\), retaining the specified identifying isomorphism to \(Q\). Its fibre is exactly the open subspace of \(\underline{\operatorname{Hom}}_{X_T/T}(F_T,Q)\) where the universal map is surjective. Theorem 1.1 and Lemma 6.1 make this an algebraic space; thus the forgetful morphism is representable.
The pair stack is algebraic, since a representable morphism to an algebraic stack has representable diagonal and an atlas obtained by pulling back an atlas of the target and then taking scheme coordinates. It has trivial automorphisms, as observed after (6.1). The proved algebraic-stack-to-space recognition in Lesson 5 therefore makes its sheaf of isomorphism classes an algebraic space. More explicitly, on a smooth atlas the relation is an equivalence relation with at most one arrow between any two objects; the algebraic-space quotient theorem and flat-space bootstrap of Lessons 1–2 identify its sheaf quotient with this stack. This is the desired Quot space.
If \(F\) is finitely presented, its Hom space over \(T\) is of finite presentation, and the surjectivity locus is open, hence locally of finite presentation. The forgetful morphism is then locally of finite presentation. Compose it with the locally finitely presented morphism \(\mathcal C\to B\) from Theorem 5.2 to obtain the final assertion. \(\square\)
The forgetful map need not be a monomorphism: the same \(Q\) can receive different quotients of \(F_T\). Its representability follows by fixing \(Q\) and the identifying arrow, not by pretending these quotients are equal.
There is also a useful separatedness check. Given two quotients \(q_i:F_T\to Q_i\) with kernels \(K_i\), they are equivalent exactly when \[ K_1\longrightarrow Q_2\text{ is zero},\qquad K_2\longrightarrow Q_1\text{ is zero}. \tag{6.2} \] The first equation makes \(q_2\) factor through \(Q_1\), and the second supplies the reverse factorization. Surjectivity makes their composites identities. Each equation is a closed condition: \(K_i\) is quasi-coherent and its Hom into \(Q_j\) is affine by Theorem 1.1; equality to the zero section is a closed immersion. Under a base change, \(Q_i\)'s relative flatness identifies the pulled-back kernel with the kernel of the pulled-back quotient, so this construction really represents the diagonal on all tests. Their intersection proves that Quot is separated over \(B\). Testing just the first kernel inclusion would prove only factorization, not isomorphism.
For example, over a field take \(F=k^2\), \(q_1=1_{k^2}\) and \(q_2:k^2\twoheadrightarrow k\) a projection. Then \(K_1=0\), so the first equation holds, but the quotients are not isomorphic. Both kernels in (6.2) are needed. If \(F\) is of finite type, both \(K_i\) are of finite type because the \(Q_i\) are finitely presented. The proper-support zero-map criterion [Stacks, Tag 083M] makes each of these closed conditions finitely presented, so the Quot diagonal is then a closed immersion of finite presentation. The two-condition argument proves the claim of [Stacks, Tag 0DM2] at its stated generality.
6.2. The Hilbert functor
Define \(\operatorname{Hilb}_{X/B}(T)\) to be closed subspaces \(Z\subset X_T\) whose structure morphisms \(Z\to T\) are proper, flat and of finite presentation. They are subspaces with their closed immersion, rather than abstract proper spaces [Stacks, Tag 0CZX].
Corollary 6.3 (Hilbert). For separated \(f\) of finite presentation, \(\operatorname{Hilb}_{X/B}\) is an algebraic space, separated and locally of finite presentation over \(B\) [Stacks, Tag 0D01].
Proof. Identify it with \(\operatorname{Quot}_{\mathcal O_X/X/B}\). A surjection \(\mathcal O_{X_T}\to Q\) has an ideal kernel \(I\), and it identifies \(Q\) with \(\mathcal O_{X_T}/I\). The multiplication and unit on this quotient are forced by the surjection; no extra algebra structure is being chosen. Since \(Q\) is finitely presented as a module, \(I\) is of finite type. Thus \(Z=V(I)\) is a closed subspace of finite presentation over \(X_T\), hence over \(T\). Relative flatness of \(Q\) is exactly flatness of \(Z/T\), and its support is \(Z\), so proper support is exactly properness of \(Z/T\).
Conversely, if \(Z\) is such a closed subspace, its closed immersion into \(X_T\) is of finite presentation: both spaces are of finite presentation over \(T\), and an immersion between them is locally of finite presentation; here it is also quasi-compact. Its ideal is therefore of finite type, making \(\mathcal O_Z\) a finitely presented \(\mathcal O_{X_T}\)-module. It has the required flatness and support. These operations preserve pullback and identify the equivalence of quotient maps with equality of closed subspaces. Apply Theorem 6.2 and the separatedness test (6.2). \(\square\)
For projective \(X/B\) with a fixed relatively ample line bundle, the locus with a prescribed Hilbert polynomial is the usual projective Hilbert scheme of AG-HP-05. The present argument gives the whole Hilbert space for separated finitely presented algebraic spaces, without a polarization or a projective ambient space. The projective theorem's further properness assertion is a separate result.
6.3. Morphisms as graphs
Corollary 6.4 (morphism spaces). If \(Z/B\) is proper, flat and of finite presentation, and \(Y/B\) is separated of finite presentation, then the functor \(T\mapsto\operatorname{Mor}_T(Z_T,Y_T)\) is an algebraic space locally of finite presentation over \(B\) [Stacks, Tags 0D19 and 0D1C].
Proof. A morphism gives its closed graph in \(Z_T\times_TY_T\). This graph is isomorphic to \(Z_T\), so it is proper, flat and finitely presented over \(T\). It gives a point of the Hilbert space of \(Z\times_BY/B\). Conversely a member \(W\) of that Hilbert space is a graph precisely when its projection \(p:W\to Z_T\) is an isomorphism; the inverse of that projection then recovers the morphism to \(Y_T\). In particular two maps with the same graph are equal.
We verify that this is an open condition on \(T\). Both \(W\) and \(Z_T\) are proper, flat and finitely presented over \(T\), so \(p\) is proper and finitely presented. Near a fibre on which it is an isomorphism, first remove the image in \(T\) of the closed non-quasi-finite locus of \(p\). That image is closed by properness of \(W/T\) and misses the chosen point. The restricted \(p\) is proper and quasi-finite, hence finite, by the ordinary space form of Zariski main used in Lesson 2.
Now \(\mathcal O_{Z_T}\to p_*\mathcal O_W\) is a map of finitely presented modules on \(Z_T\). On affine charts, both are flat over \(T\), since \(Z_T\) and \(W\) are. Its cokernel is finite and vanishes on the chosen fibre; remove its proper closed support image. The map becomes surjective. Its kernel is finite, and the flatness of the target over \(T\) identifies its fibre with the kernel of the fibre map, which is zero. Nakayama kills that kernel near the whole chosen fibre; remove its proper closed support image as well. The algebra map is then an isomorphism, so \(p\) is an isomorphism.
These neighbourhoods for all isomorphism fibres define an open \(T^\circ\). Fibrewise isomorphism is preserved and detected by field extension. The argument just given, applied after any base change, proves that \(p_{T'}\) is an isomorphism exactly when \(T'\) factors through \(T^\circ\). Thus the graph functor is an open subspace of the Hilbert space, proving the corollary. \(\square\)
7. Picard stacks and Picard spaces
7.1. The open substack of line bundles
Assume now that \(f\) is flat, proper and of finite presentation. Let \(\mathcal{Pic}_{X/B}(T)\) be the groupoid of line bundles on \(X_T\), with all their isomorphisms. Such bundles are flat over \(T\) because \(X_T/T\) is flat, and their support is proper. They therefore form a full substack of \(\mathcal C\) [Stacks, Tag 0D02].
Lemma 7.1 (the fibrewise locally free locus). Let \(Y\to T\) be locally of finite presentation and let \(E\) be a finitely presented sheaf flat over \(T\). The set \[ W_r=\{y\in Y:E|_{Y_{t}}\text{ is locally free of rank }r \text{ at }y,\ t=\operatorname{image}(y)\} \tag{7.1} \] is open and commutes with arbitrary base change. On it \(E\) is locally free of rank \(r\) as an \(\mathcal O_Y\)-module.
Proof. At a point in (7.1), choose \(r\) generators lifting a basis on the fibre to a map \(\mathcal O_Y^r\to E\), locally on an affine chart. Its cokernel is finite, so it vanishes near the point by Nakayama. Let \(H\) be the kernel. Relative flatness of \(E\) ensures that reduction to the fibre preserves injectivity of \(H\to\mathcal O_Y^r\); thus \(H\) has zero fibre at the chosen point. Since \(E\) is finitely presented, \(H\) is finite. Nakayama kills \(H\) locally too. The map is an isomorphism on a neighbourhood. Conversely local freeness immediately gives the fibre condition. Fibrewise finite free modules of fixed rank descend and ascend under field extensions, so the same criterion describes the inverse-image open under every base change. The chart argument descends étale locally. This is [Stacks, Tag 0CZT]. \(\square\)
Theorem 7.2 (Picard stack). The stack \(\mathcal{Pic}_{X/B}\) is an open substack of \(\mathcal C\), hence algebraic and locally of finite presentation over \(B\) [Stacks, Tag 0D04].
Proof. For a family \(E\) over \(T\), let \(W_1\subset X_T\) be Lemma 7.1's open. The complement \(Z=X_T\setminus W_1\) has closed image in \(T\), since \(X_T\to T\) is proper. Its complement \(T^\circ\) consists exactly of parameters whose whole fibre belongs to \(W_1\). The lemma and proper base change of this support test show that \(T'\to T\) factors through \(T^\circ\) exactly when \(E_{T'}\) is a line bundle on all of \(X_{T'}\). Thus the full-substack inclusion is represented by the open immersion \(T^\circ\hookrightarrow T\). Apply Theorem 5.2. \(\square\)
This construction similarly gives the open substack \(\mathcal{Bun}_{r,X/B}\) of bundles of a specified rank. Here properness of the ambient \(X\) is used to test freeness on all of a fibre. The zero sheaf at a point is flat but is not a line bundle there, so the complement must be taken in \(X_T\), not just in the support of \(E\).
7.2. Removing scalar automorphisms by rigidification
The relative Picard functor is the fppf sheaf associated to \[ T\longmapsto\operatorname{Pic}(X_T). \tag{7.2} \] Equivalently, it is the sheafification of \(\operatorname{Pic}(X_T)/f_T^*\operatorname{Pic}(T)\), since a base line bundle becomes trivial on an fppf cover. Denote it by \(P=\operatorname{Pic}_{X/B}\). This sheaf should not be confused with the line-bundle groupoid.
Theorem 7.3 (Picard space). In addition to the hypotheses of Theorem 7.2, assume \[ \mathcal O_T\xrightarrow{\sim}f_{T,*}\mathcal O_{X_T} \quad\text{for every }B\text{-scheme }T. \tag{7.3} \] Then \(P\) is an algebraic space [Stacks, Tag 0D2C].
Proof with a section. Suppose first that \(f\) has a section \(\sigma:B\to X\). Define the stack \(\mathcal R_\sigma\) of pairs \[ (L,\alpha),\qquad L\text{ a line bundle on }X_T,\quad \alpha:\sigma_T^*L\xrightarrow{\sim}\mathcal O_T. \tag{7.4} \] Forget \(\alpha\). Over a fixed \(L/T\), the fibre is the scheme of frames of the line bundle \(\sigma_T^*L\), a \(\mathbf G_m\)-torsor. Thus \(\mathcal R_\sigma\to\mathcal{Pic}_{X/B}\) is representable, smooth and surjective. The same atlas and diagonal recognition used for Quot proves that \(\mathcal R_\sigma\) is algebraic and locally of finite presentation.
Every automorphism of \(L\) is an invertible global function on \(X_T\). By (7.3) it is a unique invertible function on \(T\). To preserve \(\alpha\), its restriction under \(\sigma_T\) must be \(1\), so it is \(1\). Hence \(\mathcal R_\sigma\) has no nontrivial automorphisms and is an algebraic space.
We identify its sheaf with \(P\), including the descent needed for this assertion. Send \(L\) to its normalization \[ N_\sigma(L)=L\otimes f_T^*(\sigma_T^*L)^\vee, \tag{7.5} \] equipped with the canonical frame along \(\sigma_T\). Tensoring \(L\) with \(f_T^*M\), for any line bundle \(M/T\), leaves (7.5) canonically unchanged. Conversely, two normalized framed bundles are isomorphic exactly when their original classes differ by a base line bundle. An unframed isomorphism between normalized bundles can be adjusted by the unique base unit which makes it preserve the frames. Therefore framed isomorphisms, when they exist, are unique.
The presheaf \[ T\longmapsto \ker\bigl(\sigma_T^*:\operatorname{Pic}(X_T)\to\operatorname{Pic}(T)\bigr) \tag{7.6} \] is already an fppf sheaf. To see this directly, representatives of a compatible family in (7.6) admit frames along the section. On overlaps, compatibility gives unframed isomorphisms; adjust them by their scalar restriction to obtain framed isomorphisms. Their uniqueness gives the cocycle equality, so the framed line bundles descend. The same uniqueness proves that equal local classes give equal global classes. Normalization identifies (7.6) with the quotient presheaf by base line bundles and hence with its sheafification (7.2). Thus the algebraic space \(\mathcal R_\sigma\) represents \(P\).
Removal of the section hypothesis. Equation (7.3), applied to geometric fields, makes every fibre of \(f\) nonempty; otherwise its ring of global functions would be zero rather than that field. Since \(f\) is flat and of finite presentation, it is faithfully flat and locally of finite presentation. After the fppf base change \(B'=X\to B\), the projection \(X\times_BX\to X\) has the diagonal section. All hypotheses, including (7.3), survive this base change. One may take an étale scheme cover of \(X\) to obtain a covering by schemes on which the preceding argument applies.
The Picard sheaf commutes with base change: restricting its fppf definition to \(B'\)-schemes gives exactly the sheaf for \(X_{B'}/B'\). Hence \(P\times_BB'\) is an algebraic space by the section argument. The flat sheaf bootstrap of Lesson 2 now descends algebraicity of \(P\). Explicitly, a scheme atlas of \(P\times_BB'\) is a representable faithfully flat locally finitely presented cover of \(P\); its relation is represented by the corresponding fibre products after the cover. The proved bootstrap replaces this flat presentation by étale coordinates. It also descends local finite presentation over \(B\). \(\square\)
The morphism \(\mathcal{Pic}_{X/B}\to P\) is a gerbe banded by \(\mathbf G_m\). Objects and comparisons exist fppf locally by the definition of the sheafification, and (7.3) identifies the automorphism sheaf of any line bundle with \(\mathbf G_{m,T}\). With a section, the universal normalized bundle on \(\mathcal R_\sigma=P\) neutralizes this gerbe. Without a section, a Picard class need not be represented by a line bundle on its given \(X_T\), and there need not be a universal line bundle on \(X\times_BP\). The sheaf and its algebraicity do not assert either stronger conclusion. In particular (7.3) is universal, rather than an equality checked just on \(B\).
7.3. Two curve examples
Let \(C/k\) be a smooth projective geometrically connected curve.
Vector bundles. The rank-\(r\) bundles form the open algebraic stack \(\mathcal{Bun}_{r,C/k}\subset\mathcal{Coh}_{C/k}\). At \(E\), the formulas of Proposition 4.1 become \[ T_E\mathcal{Bun}_{r,C/k}=H^1(C,\mathcal E nd(E)),\qquad \operatorname{Inf}_E\mathcal{Bun}_{r,C/k}=H^0(C,\mathcal E nd(E)). \tag{7.7} \] Indeed a locally free source has no higher internal Ext, so global Ext is coherent cohomology. For a family of bundles on \(C_A\), the obstruction group for a square-zero lift is \(H^2(C_A,\mathcal E nd(E)\otimes_AM)=0\); the relative coherent-cohomology dimension bound for the projective curve holds for every \(M\). Every marked infinitesimal lift therefore exists. The stack is locally of finite presentation, so this formal smoothness proves smoothness over \(k\). Scalar automorphisms already give a positive-dimensional infinitesimal automorphism group for nonzero rank. Thus smoothness does not make this a Deligne–Mumford stack.
Picard classes. Geometric connectedness and properness give \(H^0(C_{\bar k},\mathcal O)=\bar k\); the coherent base-change theorem gives (7.3) on every \(k\)-scheme. Theorem 7.3 therefore makes \(\operatorname{Pic}_{C/k}\) an algebraic space. The curve Picard theorem of AG-HP-09 gives the stronger scheme result: it is a smooth group scheme locally of finite type, its degree-zero component is the Jacobian, and its degree-\(d\) part is a torsor under that Jacobian. A rational point supplies a normalization and universal bundle; without such a point the scheme assertion remains valid while the universal-bundle assertion needs its own hypothesis. The scheme result is imported from AG-HP-09, rather than inferred merely from algebraic-space representability.
8. Polarized schemes and all curve spaces
The following theorems concern the deformation of the underlying space itself. Appendix A §§A.7–A.8 supplies their complete constructions, including all the marked algebraization and approximation comparisons.
Theorem 8.1 (polarized schemes). The stack whose objects over \(T\) are proper flat finitely presented schemes \(Y/T\) with a chosen relatively ample invertible sheaf \(L\) is algebraic. An arrow includes both the isomorphism of schemes and the specified isomorphism of the polarizations. The version formed by base change to any algebraic space \(B\) is algebraic too [Stacks, Tags 0D1L and 0D4X].
Proof of Theorem 8.1. Appendix A §A.7 constructs the diagonal through Hom/Isom and graph Hilbert spaces, patches marked polarized families, proves the graded algebraization and finite-presentation statements, and verifies Artin's axioms. The arbitrary-base return is included there. The full proof gives the chosen line bundle and its specified arrow, with no quotient by scalar automorphisms.
Thus the polarization is data, rather than a property saying that some ample bundle exists. An automorphism of the chosen bundle covering the identity of \(Y\) is still an arrow in this stack; it has not been removed by passing to a numerical class. The finite-presentation, flatness and properness conditions belong to the definition.
Theorem 8.2 (curves). The stack whose objects over \(T\) are proper flat finitely presented algebraic spaces \(Y/T\) with all fibres of dimension at most \(1\), and whose arrows are isomorphisms over the parameter map, is algebraic. Its version over any algebraic space \(B\) is algebraic [Stacks, Tags 0D4Y and 0D5A].
Proof of Theorem 8.2. Appendix A §A.8 proves the dimension-at-most-one stack theorem using the preceding polarized construction and its infinitesimal/projective lifting argument. Its field scheme recognition and projectivity foundations are proved in §§A.12.10–A.12.11. The proof returns from its charts to the original algebraic spaces and base, rather than restricting the theorem to projective schemes.
This theorem allows zero-dimensional fibres, nonreduced curves and reducible curves. It imposes neither stability nor smoothness nor geometric connectedness. The source locator for 0D5A also points to de Jong–He–Starr, Proposition 3.3, and Jack Hall's Appendix B, Theorem B.1, in Smyth. The later lessons impose nodal and stability conditions to obtain the moduli stacks of stable curves; those restrictions are additional mathematics, not implicit hypotheses of Theorem 8.2.
9. Exercises with complete solutions
Exercise 9.1 (easy: openness of Picard). For \(f\) flat, proper and of finite presentation, prove that \(\mathcal{Pic}_{X/B}\) is open in \(\mathcal{Coh}_{X/B}\).
Solution. Fix a coherent family \(E\) over \(T\). On an affine chart, choose generators of a rank-one free fibre module and lift them to a map \(\mathcal O_{X_T}\to E\). Its finite cokernel vanishes near the chosen fibre point. Relative flatness of \(E\) makes the kernel's reduction the kernel of the fibre map, which is zero. The kernel is finite by finite presentation, so Nakayama kills it near that point. Thus the fibrewise rank-one free locus \(W_1\) is the open locally free rank-one locus. It is stable under arbitrary base change because freeness of a finite module over a local fibre ring is faithfully detected after residue-field extension.
Let \(Z=X_T\setminus W_1\). Properness of \(X_T/T\) makes its image closed. On \(T^\circ=T\setminus f_T(Z)\), every point of every fibre belongs to \(W_1\), so \(E\) is invertible everywhere. If \(T'\to T\) meets the closed image, its base change has a fibre point outside \(W_1\), so the pulled-back sheaf is not invertible there. Hence the pullback of the full-substack inclusion is exactly \(T^\circ\hookrightarrow T\), with the same isomorphisms as in the coherent stack. This is the required representable open immersion. Properness is used for the whole ambient space in this exercise; proper support alone would not force a sheaf to have rank one at points outside its support.
Exercise 9.2 (medium: Rim–Schlessinger). Verify (RS\(^*\)) for \(\mathcal{Coh}_{X/B}\), including the case in which \(X/B\) is not flat [Stacks, Tag 08LQ].
Solution. Use (3.1). A point of the fibre-product groupoid includes sheaves \(F_1,F_2\) and an actual isomorphism between their restrictions to \(X_{A_0}\). On an affine étale chart \(C/P\), use that isomorphism to form the module fibre product \(M_1\times_{M_0}M_2\). Lemma 3.1's ideal argument proves its \(P\)-flatness and its two base-change identities; no property of the ambient algebra \(C/P\) is used there.
To verify finite presentation, write \(C=P[z_1,\ldots,z_n]/K\) with \(K\) finite. The polynomial algebra is \(P\)-flat. Lift finitely many generators from \(M/JM=M_1\) to get a finite free polynomial-module surjection onto \(M\); its kernel is \(P\)-flat because the quotient \(M\) is. Its reduction is a finite kernel of a presentation of \(M_1\). Lift these kernel generators and use \(J^2=0\) to kill the remaining quotient. This proves finite presentation over the polynomial algebra and hence over \(C\).
On chart intersections full faithfulness for module fibre products gives the unique gluing maps. Testing the cocycle on both restrictions gives the equality upstairs, so the sheaf descends. Its Fitting support is separated of finite type and is proper after the nilpotent base thickening to \(A_1\); all base changes of that thickening are homeomorphisms, so the support is universally closed and therefore proper. Compatible arrows patch by exactly the same fibre-product rule. A flat module originally over \(P\) is recovered by tensoring \(0\to P\to A_1\oplus A_2\to A_0\to0\), so the construction is inverse on both objects and arrows. This proves the groupoid equivalence. Filtering an Artinian surjection by square-zero kernels gives (RS).
Exercise 9.3 (medium: Isom from Hom). Deduce Corollary 1.3 from Theorem 1.1. Identify the hypotheses needed for every Hom space used in the proof [Stacks, Tag 08K9].
Solution. On the product of Hom spaces parameterizing \(u:F\to G\) and \(v:G\to F\), compose to obtain a morphism to \(\underline{\operatorname{Hom}}(F,F)\times_B\underline{\operatorname{Hom}}(G,G)\). The source factors require the targets \(G\) and \(F\), respectively, to be flat with proper support; both sources must be finitely presented for finite presentation of the representing schemes. The same conditions apply to the two endomorphism spaces. Thus both \(F,G\) must be finitely presented, flat over \(B\), with proper support.
The identity pair is a section of an affine finitely presented morphism and therefore a closed immersion of finite presentation. Pull it back by composition. Its equations are \(vu=1_F\) and \(uv=1_G\), with the domains as written. The resulting affine finitely presented space has points exactly mutually inverse pairs. The inverse of \(u\) is unique, so projection to \(u\) gives a functorial identification with Isom on every \(B\)-scheme. Example 1.4 shows that just requiring finite presentation of \(F\) while retaining the other conditions only for \(G\) would be a false statement.
Exercise 9.4 (hard: the effectivity axiom). Verify Artin's formal effectivity axiom for \(\mathcal{Coh}_{X/B}\) using Grothendieck existence, and prove full faithfulness on isomorphisms [Stacks, Tag 08W9].
Solution. Let \(R\) be complete Noetherian local and take a compatible system of families over \(R_n=R/\mathfrak m^{n+1}\), with its specified transition identifications. Since \(X_R\) is separated of finite type, the proper-support existence equivalence algebraizes this system to a coherent sheaf \(F\) with proper support. It includes all coherent morphisms, so the reductions of \(F\) have exactly the prescribed identifications.
On affine étale charts, the flatness criterion for all powers of \(\mathfrak m\) shows that \(F\) is \(R\)-flat along the closed fibre, because each \(F_n\) is \(R_n\)-flat. The nonflat locus is closed, lies in the proper support, and therefore has closed image in \(\operatorname{Spec}R\). It misses the closed point. A nonempty closed subset of a local spectrum contains that point, so the image, and hence the nonflat locus, is empty. No flatness of \(X_R/R\) is required. Coherence on the Noetherian space gives finite presentation, so \(F\) is an object of the coherent stack.
Given compatible isomorphisms between two systems, full faithfulness of existence yields a unique homomorphism between their algebraizations. Algebraize the compatible inverse homomorphisms as well. Their composites reduce to the identities at all orders, so faithfulness makes the composites the identities upstairs. Equality and composition of arbitrary compatible arrows are preserved for the same reason. Completion is therefore an equivalence of groupoids. This proves more than the essential surjectivity required by the axiom. The arbitrary inverse-ring-system theorem used for nonflat openness in Section 5.2 is a stronger input and is not being deduced from this exercise.
10. Precisely imported inputs and scope
The Hom and Isom theorems, both coherent-stack algebraicity theorems, and the Quot, Hilbert, Picard-stack and Picard-space consequences have been proved. Appendix A supplies the coherent-existence, space cohomology and perfect-test extensions below at their exact scope. Its individual lower native references remain explicitly conditional when no included proof or exact programme binding has been established. The genuine projective-scheme and Picard examples retain their named programme providers:
- On quasi-compact quasi-separated algebraic spaces, finite-presentation descent along affine limits, quasi-coherent sheaves as filtered colimits of finitely presented sheaves, and descent of relative flatness and proper support. The exact proper-support limit statement used above is [Stacks, Tag 08K2]. Finite presentation of spaces and sheaves permits descent to a finitely generated \(\mathbf Z\)-algebra.
- Perfect approximation on a Noetherian algebraic space: for a bounded-above coherent complex \(E\) and any integer \(m\), there is a perfect \(P\to E\) inducing isomorphisms in degrees \(>m\) and a surjection in degree \(m\) [Stacks, Tags 08HI, 08HJ and 08HP]. The proper-support direct-image theorem makes \(Rf_*R\mathcal H om(P,G)\) perfect for perfect \(P\) and bounded coherent \(G\) flat over a Noetherian base with proper support, when \(f\) is locally finite type and quasi-separated; arbitrary derived base change holds [Stacks, Tags 0DKK and 08JQ]. Section 5.1 proves the needed low-Ext reduction, also recorded in Tag 08JR.
- Coherent cohomology finiteness with proper support, internal Ext coherence over Noetherian charts, the local-to-global Ext spectral sequence and the relative cohomological dimension bound for projective curves. These imply the finite tangent calculation; a related proper-space finiteness statement is [Stacks, Tag 0D0T].
- Grothendieck existence with all morphisms, for a separated finite type algebraic space over a complete Noetherian ring and coherent sheaves of proper support [Stacks, Tags 08B7 and 08BE]. Its flatness application uses the local criterion along all powers of an ideal and the openness of relative flatness [Stacks, Tag 08VP]. Proposition 4.2 proves the additional flatness and groupoid assertions.
- Strong coherent existence exactly as stated in Section 5.2 [Stacks, Tags 0CX4 and 0CXB], for arbitrary surjective inverse ring sequences with locally nilpotent kernels, separated finitely presented ambient space, and compatible finitely presented relatively flat sheaves with proper support. This is explicitly stronger than Noetherian formal existence.
- Flat-module square-zero deformation theory with its obstruction in Ext \(2\), marked-lift torsor in Ext \(1\), automorphisms in Ext \(0\), and functoriality for maps with fixed quotient [Stacks, Tags 08VW and 0CYE]. It is used only where the ambient base changes are flat. G-ring permanence and the G-ring property of finite type \(\mathbf Z\)-algebras are [Stacks, Tag 07PX] and the inputs already isolated in Lesson 7.
- The finite-type zero-map criterion used for the additional finite-presentation assertion on the Quot diagonal: a map from a finite type quasi-coherent sheaf to a finitely presented relatively flat sheaf with proper support has a finitely presented closed vanishing locus on the base [Stacks, Tag 083M]. For arbitrary quasi-coherent source its closedness was derived here directly from Hom. The morphism-space corollary uses the ordinary proper quasi-finite-to-finite theorem of Lesson 2.
- The projective Quot and Hilbert theorems from AG-HP-05 and the smooth projective curve Picard scheme theorem from AG-HP-09. These stronger scheme assertions are used only to identify the projective and curve examples. The full polarized-scheme and dimension-at-most-one curve-space algebraicity proofs are in Appendix A §§A.7–A.8. They retain their genuinely assigned deformation prerequisites and explicitly recorded lower references.
The ordinary proper-support existence and direct-image support are written in Appendix A, and strong existence is proved there for the entire stated inverse-system scope. The finite-presentation module patching, the finite-complex Hom representation, the relative free-locus test and the product calculations were proved here. Each moduli algebraicity assertion follows after its own descent, diagonal and deformation or presentation argument.
References
- [Stacks] The Stacks project, Quot and Hilbert Spaces: Hom and Isom, Tags 08JS, 08K6, 08K7 and 08K9; coherent sheaves and their Artin axioms, Tags 08KA, 08KB, 08W5, 08W6, 08KC, 08KD, 08LQ, 08W7, 08W8, 08W9, 08WA, 08WC, 08WB and 09DS; Quot and Hilbert, Tags 09TQ, 09TU, 0CZX and 0D01; Picard stack and functor, Tags 0D02, 0D04, 0D24 and 0D2C; morphism spaces, polarized schemes and curves, Tags 0D19, 0D1C, 0D1L, 0D4X, 0D4Y and 0D5A. Read AI Integrated Stacks Project, Quot and Hilbert Spaces.
- [Stacks] Moduli Stacks, Tags 0DLU, 0DLW, 0DLX, 0DM1, 0DM5, 0DM9 and 0DMD, for the collected properties of these moduli stacks. See AI Integrated Stacks Project, Moduli Stacks.
- [Stacks] Derived Categories of Spaces, Tags 08HI, 08HJ, 08HP, 08JQ, 08JR, 0D0T and 0DKK; More on Morphisms of Spaces, Tags 08B7, 08BE and 08VP; and More on Flatness of Spaces, Tags 0CX4 and 0CXB, for the precise ordinary inputs listed in Section 10. AI Integrated Stacks Project retains the upstream tags; its additions and corrections are not reviewed by the Stacks project's maintainers. Source readings for this lesson were made at the recorded immutable revision.
Appendix A. Coherent existence and moduli of proper spaces
Section and statement numbers within this appendix are local to the appendix; an explicit course or provider title qualifies every outside reference.
This chapter supplies the coherent-existence and moduli arguments used in Lesson 8. The theorem statements retain arbitrary inverse ring sequences, algebraic-space ambient objects, and the full dimension-at-most-one curve stack. The mathematical proofs below are adaptations of the human Stacks Project treatment in the AI Integrated Stacks edition. The mathematical adaptation is distributed under GNU FDL 1.2 or any later version, with no Invariant Sections, Front-Cover Texts, or Back-Cover Texts. The full licence is included below. Human authorship belongs to the Stacks Project authors; the AI Integrated Stacks Project and this AI adaptation are additional, separate credits. Independently written programme integration notes and verification records remain CC0 1.0. No AI rights holder is invented.
A compatible family over finite quotients carries both objects and specified comparison maps. The central problem is to recover that marked family over the inverse-limit ring. We first construct finite cohomological tests, then prove coherent existence, and finally use it to construct the two moduli stacks. The supporting mathematical constructions are proved below at their stated scope.
A.1. The inverse system and its markings
Let
$$\cdots\longrightarrow A_{n+1}\longrightarrow A_n\longrightarrow\cdots \longrightarrow A_1$$be a sequence of surjective ring homomorphisms with locally nilpotent kernels. Here locally nilpotent means that every finite collection of elements of the kernel generates a nilpotent ideal. Put $A=\varprojlim_n A_n$ and $I_n=\ker(A\to A_n)$. The projections $A\to A_n$ are surjective: lift an element successively through the surjective transitions.
Every composite transition has a locally nilpotent kernel. Indeed, for a finite collection in its kernel, a power of the ideal they generate maps to zero at the preceding stage, and a further power is zero in the upper ring. Induction on the number of stages proves the assertion. Consequently the schemes $\operatorname{Spec}A_n$ have the same underlying topological space. Their common image in $\operatorname{Spec}A$ is $V(I_1)=V(I_n)$.
Each pair $(A,I_n)$ is henselian, and $I_n$ is contained in the Jacobson radical. To prove the radical assertion, an element which is a unit in $A_n$ is a unit at every later stage, because units lift through a locally nilpotent ideal. Its inverses are compatible and define an inverse in $A$. Apply this to $1-ax$, $a\in A$, $x\in I_n$. For the henselian assertion, start with a coprime monic factorization of a monic polynomial over $A_n$. Coprime factorizations lift uniquely through a locally nilpotent ideal: their finitely many coefficients and corrections reduce the question to a nilpotent ideal, where the usual linear correction, using a Bezout relation between the two factors, raises the order of the error until it is zero. Lift recursively and take the coefficientwise limit. This is precisely the factorization definition of a henselian pair.
Let $Y\to\operatorname{Spec}A$ be a separated morphism of finite presentation of algebraic spaces. Write $Y_n=Y\times_A A_n$, with closed immersion $i_n:Y_n\to Y$. We are given finitely presented quasi-coherent modules $G_n$ on $Y_n$, flat over $A_n$, with proper support over $A_n$, and specified isomorphisms
$$\phi_n:G_n\otimes_{\mathcal O_{Y_n}}\mathcal O_{Y_{n-1}} \xrightarrow{\;\sim\;}G_{n-1}.$$All comparisons below use these specified maps. Replacing them by an equality of isomorphism classes would lose the required data.
The conclusion to be proved is a finitely presented module $G$ on $Y$, flat over $A$, with proper support, and isomorphisms
$$G\otimes_A A_n\xrightarrow{\;\sim\;}G_n$$whose transition composites are the $\phi_n$. This is the strong coherent-existence statement of Tags 0CX4/0CXB. It does not assert an equivalence of categories for every such tower; that stronger assertion requires its own morphism-recovery argument.
A.2. Proper support and the finite complexes used below
For a finitely presented module $F$ on an algebraic space, use the closed subspace
$$Z_F=V(\operatorname{Fitt}_0 F).$$Its defining ideal is of finite type and its formation commutes with arbitrary base change. On a chart on which $F$ has $r$ generators,
$$(\operatorname{Ann}F)^r\subseteq\operatorname{Fitt}_0F \subseteq\operatorname{Ann}F.$$To check the base-change assertion, present $F$ on an étale chart by $B^q\xrightarrow{M}B^r\to F\to0$. The ideal is generated by the $r$-by-$r$ minors of $M$; if $q<r$, it is zero. Tensoring with any chart algebra after any base change preserves this presentation, and determinants commute with ring homomorphisms. Therefore
$$\operatorname{Fitt}_0(g^*F)= \operatorname{Fitt}_0(F)\mathcal O_{X'}$$for every $g:X'\to X$, with no flatness assumption.
For the containments, the adjugate identity says that each maximal minor kills the cokernel. Conversely, if $a_1,\ldots,a_r$ annihilate $F$, then each vector $a_j e_j$ is in the image of $M$. Expressing these $r$ columns through $M$ and using the determinant expansion puts $\prod_j a_j$ in the maximal-minor ideal. These products generate $(\operatorname{Ann}F)^r$. The identities are étale-local and hence give the stated ideal containments on the space.
Thus the annihilator support is a closed nilpotent subspace of $Z_F$. Its immersion is a universal homeomorphism, also after arbitrary base change. When the ambient space is separated and finitely presented over the base, both supports are separated and of finite type over the base: $Z_F$ is finitely presented as a closed subspace of the finitely presented ambient space, while the annihilator support is its closed subspace. Their universal closedness, and therefore properness, are equivalent. In particular the Fitting support of every $G_n$ is proper exactly when its usual annihilator support is proper. The displayed base-change identity identifies $Z_F\times_A A_n$ with this proper Fitting support of $G_n$. This supplies the exact proper-support consumer, as well as the convention already proved in Lesson 8, Section 1.1.
We require four bridges, each at algebraic-space scope:
- On a quasi-compact quasi-separated algebraic space, pseudo-coherent objects can be approximated arbitrarily far to the left by perfect objects. The support-preserving version permits a closed support whose complement is quasi-compact.
- For $f:X\to T$ of finite presentation, a perfect $P$ and a bounded complex $F^\bullet$ of finitely presented modules flat over $T$, with proper support, give a perfect object
on $T$, with the canonical comparison isomorphism after every base change. Flatness of $X/T$ is unnecessary. 3. If $K\in D^-_{\mathrm{QCoh}}(Y)$ has pseudo-coherent $R\Gamma(Y,E\otimes^{\mathbf L}K)$ for every pseudo-coherent $E$, then $K$ is pseudo-coherent relative to $A$. Relative pseudo-coherence means that, on an affine étale chart $\operatorname{Spec}B\to Y$ and a smooth presentation $P\to B$, the pushforward is represented by a bounded-above complex of finite free $P$-modules. 4. A compatible tower of perfect complexes over the $A_n$, with derived transition isomorphisms, has perfect derived limit over $A$, and derived base change of that limit recovers every level.
Sections 3–5 prove the bridges and explain the exact geometric constructions behind them. Their incorporated source proof chain is retained in the appendix. In particular, a scheme proof over a Noetherian base is used at its proved scope; it is not silently promoted to the arbitrary-base algebraic-space statement.
A.3. Coherent direct images with proper support
First let $T$ be Noetherian and $f:X\to T$ locally of finite type and quasi-separated. A coherent module $F$ with proper support is the pushforward from a proper closed support $Z\to T$. Over a Noetherian chart its annihilator is coherent, so this is an actual closed subspace. A closed immersion is affine and has no higher quasi-coherent direct images. Leray therefore reduces finiteness of $R^qf_*F$ to proper coherent cohomology on $Z$.
Here is the algebraic-space extension of the scheme proof. Coherence, the ascending chain condition, and Artin–Rees are checked on a finite affine étale cover. Localization and flat étale restriction preserve all module intersections used in the Artin–Rees calculation. The extension lemma for a morphism on $U=X\setminus V(J)$ also has the same proof: form its quasi-coherent graph inside $G\oplus F$, take the inverse image of this graph, and apply Artin–Rees to its projection kernel. A sufficiently high ideal power then yields a map $J^aG\to F$. Two maps agreeing on $U$ agree on a higher source power.
Consequently the generic-lattice and filtration arguments of AG-QC, Proper Direct Images, Sections 1–3, extend to Noetherian algebraic spaces. More explicitly, for an integral closed subspace $Z$ and a coherent module of generic rank $r>0$, choose a basis on an affine open of its schematic dense locus, clear denominators, and extend the resulting map by the preceding graph argument. Its source is $I^{\oplus r}$, $I\subset\mathcal O_Z$ a nonzero coherent ideal. Its kernel is zero because $I$ embeds in the function field and the kernel has zero generic stalk. Its cokernel has smaller closed support. Induction on closed supports, followed by the finite filtration by powers of the ideal of the reduced support, gives a filtration of any coherent module by ideals on integral closed subspaces.
For the cohomology property, a witness of any finite positive generic rank suffices. If $I^{\oplus r}$ has finite higher direct images, each $I$ does, because its cohomology is a direct summand. Comparing $I$ with another nonzero ideal through their intersection makes the two quotients have smaller support. Two out of three in the cohomology long exact sequence and Noetherian induction therefore transfer the property to all filtration factors and then to every coherent module.
A witness is supplied by the weak Chow lemma for algebraic spaces: there is a proper surjection $\pi:Z'\to Z$, with $Z'$ a scheme admitting an immersion into projective space over the affine base. Since $Z$ is proper over that base, the immersion is closed, and both $\pi$ and $Z'\to T$ are projective. With $L$ the restricted hyperplane bundle, take $d$ sufficiently large that higher direct images of $L^d$ vanish for both morphisms. Then $H=\pi_*L^d$ is coherent, Leray gives
$$R^q(Z\to T)_*H=R^q(Z'\to T)_*L^d,$$and these are finite, zero for positive $q$. Its generic stalk is nonzero: a globally generating hyperplane section not vanishing at a point over the generic point has a nonzero image under adjunction. The support of $H$ is therefore all of integral $Z$. This is the required finite-positive-rank witness. It proves the proper coherent direct-image theorem for spaces and hence the proper-support version.
The weak Chow construction is included below. Its empty-space case is $Z'=\varnothing$. For a nonempty space, choose an affine étale cover with a bound $d$ on its geometric fibre sizes. The open locus of $d$ distinct lifts gives an immersion into the $d$-fold product of a projective closure of the cover. Take its scheme-theoretic image and the union of the opens on which one projection lands in the original cover. The projections agree as maps to $Z$ on the schematically dense locus, hence agree everywhere by separatedness. The valuative criterion proves properness: after an extension of valuation rings a lift to the original cover selects one of the $d$ generic lifts, and properness of the corresponding projective projection extends it into that open. The uncovered closed locus has fibre bound $<d$, so induction supplies the remaining proper cover. This retains the full algebraic-space construction rather than assuming a birational scheme modification exists.
For bounded coherent $E$ with proper cohomological supports, the spectral sequence
$$R^pf_*H^q(E)\Longrightarrow H^{p+q}(Rf_*E)$$now gives coherent cohomology. A finite cohomological-dimension bound on quasi-coherent direct image gives boundedness. If $E$ has finite Tor amplitude over $T$, the projection formula
$$Rf_*E\otimes^{\mathbf L}M \simeq Rf_*(E\otimes^{\mathbf L}_{f^{-1}\mathcal O_T}f^{-1}M)$$gives a uniform lower bound for every quasi-coherent $M$; the upper bound comes from the bounded-above complex and the cohomological-dimension bound. Thus $Rf_*E$ is pseudo-coherent of finite Tor dimension, hence perfect.
Apply this to $E=P\otimes^{\mathbf L}F^\bullet$. On each chart a perfect $P$ is a finite complex of finite projectives. Its tensor with the bounded relatively flat complex has finite relative Tor amplitude and coherent cohomology, supported on the union of the proper supports of the terms. This proves perfection over a Noetherian base.
A.4. Approximation and passage to arbitrary bases
The approximation statement is the following. For a closed subset $Z\subset |X|$ with quasi-compact complement, there is an integer $r_Z$ such that an $(m-r_Z)$-pseudo-coherent $E$, with $H^i(E)$ supported on $Z$ for $i\geq m-r_Z$, admits a perfect $P$ supported on $Z$ and a map $P\to E$ inducing isomorphisms in degrees $>m$ and a surjection in degree $m$.
On an affine $\operatorname{Spec}B$, write $Z=V(f_1,\ldots,f_r)$. The Koszul complexes on powers of the $f_i$ represent every cohomology class supported on $Z$, once a sufficiently large power is chosen. Here one uses the exact cohomological support range: after the appropriate shift, the cohomology in degrees $-r+1,\ldots,0$ is supported on $Z$. The complement is covered by the $r$ principal affines $D(f_i)$, so the finite Čech spectral sequence makes $H^0$ of the restricted complex zero. Write $K_e$ for the Koszul complex on $f_1^e,\ldots,f_r^e$, and $I_e\to B\to K_e$ for its triangle obtained by separating the term in degree zero. There is a canonical isomorphism
$$\operatorname{colim}_e R\operatorname{Hom}_B(I_e,M) =R\Gamma(\operatorname{Spec}B\setminus Z,\widetilde M).$$Indeed, the term indexed by a nonempty subset $J$ in the left colimit is $M[(\prod_{j\in J}f_j)^{-1}]$: its transition multiplies by $\prod_{j\in J}f_j$. These are exactly the terms of the finite open Čech complex, with the usual total-complex signs. Finite free $I_e$ compute the derived Hom, and filtered module colimits are exact. Thus, if a map $B\to M$ restricts to zero on the complement, its composite with $I_e\to B$ is already zero for some finite $e$. The triangle lifts it to a map $K_e\to M$. This is the closed-support Koszul representative lemma incorporated below; localization of a single cocycle without the stated cohomological range would not suffice. Choose finitely many generators in the largest nonzero cohomological degree $t$, and take a finite sum of these maps from shifted Koszul complexes. Its cone has zero cohomology in degrees $\geq t$ and retains pseudo-coherence and the specified support range. Repeat until $t<m$. Splicing the resulting triangles gives the required perfect approximation. When $Z=X$, ordinary finite-free truncation of a bounded-above pseudo-coherent resolution gives the same argument without any Koszul variables. When $E$ has no nonzero degree $\geq m$, the zero perfect complex is sufficient.
To pass to algebraic spaces use elementary distinguished squares $(U\subset X,V\to X)$, with $V$ affine and an isomorphism over the complement of $U$. Their finite étale filtration gives an induction principle. The derived Mayer–Vietoris triangle glues two complexes and two maps agreeing on $U\times_XV$: take the homotopy fibre of
$$Rj_{U,*}A\oplus Rj_{V,*}B \longrightarrow Rj_{U\times_XV,*}B|_{U\times_XV}.$$Restriction to $U$ cancels the second summand. On $V$, the cone of its map to $B$ is supported on the distinguished complement; its pushforward is zero, and pushforward there is faithful, so that cone is zero. This proves both gluing assertions.
The lifting steps on the affine member of the square retain support. A perfect object on a quasi-compact open extends after adding its shift. First extend a bounded-above finite-free resolution and truncate below its Tor amplitude; the extra kernel is a vector bundle. Lift the projector on that extra bundle, after clearing denominators by a perfect Koszul modification of the source, and take its cone. This extends $P\oplus P[1]$. To keep support $V(g_1,\ldots,g_s)$, take successive cones of multiplication by powers of $g_j$ that act trivially on $P$. Each cone is supported on the added zero locus. The restriction is a finite direct sum of shifts of $P$, containing $P$. Lift the endomorphism equal to zero on that $P$ and the identity on the other summands; its cone restricts to $P\oplus P[1]$ and retains support. The source modification in the map-lifting construction is a tensor with a perfect complex, so it also retains support. All these constructions and the Koszul representative lemmas are retained with their complete proofs in the appendix.
Now approximate on $U$, extend that approximation and its map across $V$ by the preceding construction, and glue. The map kills the highest nonzero cohomology on $U$. Its cone has a strictly smaller highest degree there. Repeat. When this degree is below the support threshold, all relevant cohomology is supported on the distinguished complement and the affine support approximation on $V$, extended by zero, finishes. Splicing the triangles completes the induction. The integer used for the pair is the maximum of the integer on $U$ and the number of affines covering the relevant complement in $V$. Thus the process is finite for every requested $m$.
For arbitrary $T$, the canonical base-change comparison for $P\otimes^{\mathbf L}F^\bullet$ is an isomorphism without any Noetherian hypothesis. The assertion is étale-local on $T$. On affine $X=\operatorname{Spec}B$, represent $P$ by finite projectives and tensor with the relatively flat terms of $F^\bullet$; this is a bounded complex flat over the affine base ring, so ordinary tensor computes its derived tensor after every ring map. The resulting complex is exactly the one computing the base-changed tensor with the derived pullback of $P$ and the ordinary pullback of $F^\bullet$. For an elementary distinguished square, its Mayer–Vietoris triangle remains the corresponding triangle after base change. If the comparisons are isomorphisms on its three smaller pieces, the triangle proves the comparison on the whole space. The finite étale induction principle completes the proof. The comparisons are the adjunction/projection-formula maps, so successive base changes and morphisms of the input complexes give the same isomorphisms, not merely abstract complexes with equal cohomology dimensions.
Finally write an affine base ring as the filtered colimit of its finitely generated $\mathbf Z$-subalgebras. Descend $X$, the bounded complex $F^\bullet$, its differentials, and $P$ to some Noetherian stage. Increase the stage so that the terms of $F^\bullet$ are relatively flat and have proper support. The finite-presentation and proper-support limit theorems justify this step; only finitely many terms and equations occur. Perfect complexes descend by their finite chart presentations and transition maps. Section 3 proves that the descended direct image is perfect. The arbitrary base-change comparison just proved identifies its pullback with the original direct image. A pullback of a perfect complex is perfect. This proves Bridge 2 over arbitrary algebraic-space bases.
For a pseudo-coherent source and a bounded-above relatively flat target, approximate the source sufficiently far left, then truncate the target sufficiently far left. The cohomological-dimension bound makes both replacements isomorphisms in any chosen high cohomological range after pushforward. The resulting direct image is perfect by the preceding result. This proves pseudo-coherence of the original direct image one degree range at a time.
A.5. Recovering local information from perfect tests
For later use, perfect tests also detect relative pseudo-coherence. Suppose $K\in D^-_{\mathrm{QCoh}}(Y)$ and that $R\Gamma(Y,P\otimes^{\mathbf L}K)$ is pseudo-coherent over $A$ for every perfect $P$. Given a pseudo-coherent $E$, approximate $E$ far enough left. If $K\in D^{\leq b}$ and cohomological dimension is at most $N$, an approximation whose cone is in degrees $<m-N-1-b$ changes the tensor direct image only below degree $m$. Thus the perfect-test hypothesis implies the same hypothesis for every pseudo-coherent $E$.
Fix $y\in Y$. Derived Chow supplies a closed subspace
$$Z\subset Y\times_A\mathbf P^d_A,$$an open $V\subset\mathbf P^d_A$, and a pseudo-coherent $E$ supported on $Z$, such that $W=Z\cap(Y\times_AV)\to Y$ is étale and meets $y$, $W\to V$ is a closed immersion, and $E|_{Y\times_AV}=\mathcal O_W$ pushed forward.
Here is its construction and the return from a Noetherian model. Descend $Y/A$ to a separated finitely presented $Y'/A'$ with $A'$ finitely generated over $\mathbf Z$. Choose an affine étale chart of $Y'$ through the image of $y$, embed that chart in affine space, and take the scheme-theoretic closure of its graph in $Y'\times\mathbf P^d_{A'}$. Separatedness makes the closure a graph over a suitable open of the projective closure of the chart. Over this open it is the original étale chart. The coherent structure sheaf of that closed graph is pseudo-coherent over the Noetherian model. Pull it back derivedly to $A$. The restriction is still the ordinary structure sheaf of the base-changed graph because the chart is flat over $Y'$ and projective space is flat over $A'$; these give the needed Tor independence. Choose a point in the base-changed chart over $y$ by surjectivity on the relevant fibre. This point need not be unique.
Let $p,q$ be the projections of $Y\times\mathbf P^d_A$. For every twist $j$, the projection formula gives
$$R\Gamma(\mathbf P^d_A,Rq_*(Lp^*K\otimes^{\mathbf L}E)(j)) =R\Gamma(Y,K\otimes^{\mathbf L}Rp_*(E\otimes^{\mathbf L}Lq^*\mathcal O(j))).$$The complex inside the right tensor is pseudo-coherent because $p$ is flat, proper and finitely presented and the pseudo-coherent direct-image result of Section 4 applies. The right side is therefore pseudo-coherent by the hypothesis. The projective-space test for pseudo-coherence, proved immediately below by the finite Koszul resolution of the diagonal, now says $Rq_*(Lp^*K\otimes^{\mathbf L}E)$ is pseudo-coherent. Over $V$ it is the pushforward of $K|_W$ by the closed immersion $W\to V$. Hence $K|_W$ is pseudo-coherent relative to $A$. The étale charts $W\to Y$ so obtained prove Bridge 3.
Here is a complete proof of that projective-space test over an arbitrary ring; it needs no equivalence with a differential graded module category. Put $P=\mathbf P^d_A$. If $M\in D_{\mathrm{QCoh}}(P)$ and $R\Gamma(P,M(j))$ is pseudo-coherent over $A$ for $j=0,\ldots,d$, then $M$ is pseudo-coherent on $P$. On $P\times_AP$, the tautological inclusion on the first factor followed by the tautological quotient on the second gives a section of the rank-$d$ vector bundle
$$\operatorname{Hom}(p_1^*\mathcal O(-1),p_2^*Q).$$Its zero scheme is the diagonal. On a chart meeting the diagonal its equations are $x_i-y_i$, $i=1,\ldots,d$. They form a regular sequence over every $A$: eliminate one variable at a time, each by a monic linear equation. Away from the diagonal one equation is a unit locally. Thus its Koszul complex is a finite locally free resolution of $\mathcal O_\Delta$, with terms
$$p_1^*\mathcal O(-i)\otimes p_2^*\Omega^i_{P/A}(i),\qquad 0\leq i\leq d.$$Tensor this resolution by $p_1^*\mathcal O(d)\otimes p_2^*\mathcal O(-d)$. Its restriction to the diagonal is canonically trivial, so it still resolves $\mathcal O_\Delta$. After derived tensor with $Lp_1^*M$ and applying $Rp_{2,*}$, its term of Koszul degree $-i$ is
$$L(P\to\operatorname{Spec}A)^*R\Gamma(P,M(d-i)) \otimes\Omega^i_{P/A}(i-d).$$The comparison follows by flat base change along $P/A$ and projection formula. These formulas hold even for unbounded $M$: the finite standard affine cover of $P$, with its affine intersections, computes the comparison by a finite Čech total complex, and the Koszul complex is finite and locally free.
Each displayed term is pseudo-coherent by the assumption and tensoring with a vector bundle. The finite Koszul filtration expresses the pushed-forward total complex as finitely many cones of these terms; pseudo-coherence is closed under these cones and shifts. That total complex is $M$: derived tensor with $\mathcal O_\Delta$ restricts $Lp_1^*M$ to the diagonal, where $p_1$ is the identity, and $p_2\circ\Delta$ is the identity as well. This proves the test. For $d=0$ the resolution has one term and the assertion is tautological. Applied above, its hypotheses hold for all twists and therefore in particular for $0,\ldots,d$.
One further observation gives access to any affine étale chart $U\to Y$. There are perfect $E_m$ on $Y$ such that
$$R\Gamma(U,K)=\operatorname{hocolim}_m R\Gamma(Y,E_m\otimes^{\mathbf L}K)$$for every $K\in D_{\mathrm{QCoh}}(Y)$. To construct them, descend $U\to Y$ to a separated finite-type $\mathbf Z$-model $U'\to Y'$. The model ring and all affine étale chart rings are countable. Put $M=R(U'\to Y')_*\mathcal O_{U'}$. Its cohomology has countable sections on affine étale charts: after base change to such a chart, use finite cohomological dimension and an elementary distinguished-square induction; affine terms are countable modules, and kernels, cokernels and finite extensions of countable groups are countable.
Choose a perfect generator $G$ of $D_{\mathrm{QCoh}}(Y')$, whose full algebraic-space construction is incorporated below. Perfect objects are compact: derived Hom from one commutes with arbitrary direct sums, as follows for affines from a finite projective complex and for spaces by the finite Mayer–Vietoris induction. The same induction shows that every $\operatorname{Hom}(G[t],M)$, and every $\operatorname{Hom}(G[t],E)$ for perfect $E$, is countable. Their union over $t\in\mathbf Z$ is therefore countable.
Here is the complete sequential construction, avoiding any differential graded equivalence. Begin with $E_0=0$ and $a_0:E_0\to M$. Enumerate all classes in all the groups $\operatorname{Hom}(G[t],M)$. Given $a_n:E_n\to M$, enumerate the kernels of $\operatorname{Hom}(G[t],E_n)\to\operatorname{Hom}(G[t],M)$, for all $t$. At stage $n+1$, add the first $n+1$ target classes by replacing the current perfect object with its direct sum with the corresponding finite number of shifts of $G$, mapping by those classes. Next, for each $m\leq n$, kill the first $n+1$ enumerated kernel classes from stage $m$, viewed in the current object via its transition map. To kill $b:G[t]\to E$ with $ab=0$, use
$$G[t]\xrightarrow{b}E\longrightarrow\operatorname{Cone}(b).$$Exactness of $\operatorname{Hom}(-,M)$ for this triangle extends $a$ to a map $\operatorname{Cone}(b)\to M$. A finite number of these operations yields a perfect $E_{n+1}$ and a map extending $a_n$. The enumerations are set-theoretic choices; no functorial cell selection is required.
Every target class is eventually added, and every kernel class arising at any fixed stage is eventually killed. Compactness of $G$ gives
$$\operatorname{Hom}(G[t],\operatorname{hocolim}E_n) =\operatorname{colim}\operatorname{Hom}(G[t],E_n) \xrightarrow{\;\sim\;}\operatorname{Hom}(G[t],M).$$For clarity, the equality follows by applying $\operatorname{Hom}(G[t],-)$ to the telescope triangle; the map $1-\mathrm{shift}$ is injective on the direct sums of the preceding Hom groups, so its cokernel is the displayed colimit. The cone of $\operatorname{hocolim}E_n\to M$ has zero Hom from every shift of the generator, hence is zero. Thus $M=\operatorname{hocolim}E_n$.
Pull this sequence back to $A$. The canonical arbitrary-base comparison for the flat finitely presented morphism $U'\to Y'$, computed on affine pieces and then by the finite Mayer–Vietoris induction, identifies its colimit with $R(U\to Y)_*\mathcal O_U$. Derived pullback preserves perfect objects and homotopy colimits. The projection formula now proves the displayed sequential perfect-test formula. The incorporated native countable lemma gives an alternative proof through its differential graded equivalence, but that equivalence and its cell-construction lemma are not prerequisites of this reader proof.
For Bridge 4, stabilize finite-free pseudo-coherent resolutions of the compatible perfect complexes $C_n$. The stabilization lemma lifts a bounded-above free resolution at level $n$ to one at $n+1$, adding contractible pairs if necessary, with an actual isomorphism after reduction. Thus their degreewise inverse limit is a bounded-above finite-free complex $C$ over $A$, and $C\otimes_A A_n=C_n$ as complexes. Surjectivity of the degreewise maps computes its derived limit. This proves pseudo-coherence and every derived base-change comparison. Every maximal ideal of $A$ contains $I_1$, so the residue-field complex of $C$ is the corresponding residue-field complex of perfect $C_1$, whose Tor amplitude has a uniform finite bound. The fibrewise perfectness criterion for a pseudo-coherent complex makes $C$ perfect. These statements include arbitrary locally nilpotent kernels; a fixed nilpotence exponent is not assumed.
A.6. Strong coherent existence
View each $G_n$ as a module on $Y$ by $i_{n,*}$, and form
$$K=\operatorname{holim}_{D_{\mathrm{QCoh}}(Y)} i_{n,*}G_n =DQ_Y\bigl(\operatorname{holim}_{D(Y)}i_{n,*}G_n\bigr).$$Here $DQ_Y$ is the right adjoint to inclusion of complexes with quasi-coherent cohomology. Its construction by elementary distinguished squares, its finite boundedness property, and the ordinary derived-limit calculation on affine étale charts show $K\in D^b_{\mathrm{QCoh}}(Y)$ and $K\in D^{\geq0}$. The sheaf derived limit has hypercohomology on any affine étale chart only in degrees zero and one; the boundedness of $DQ_Y$ increases only the upper bound. We do not identify $K$ with the naive sheaf inverse limit.
For a perfect $P$ on $Y$, put
$$C_n=R\operatorname{Hom}_{Y_n}(Li_n^*P,G_n).$$Bridge 2 makes $C_n$ perfect over $A_n$, and identifies its derived transition map with the given reduction of $G_n$. Bridge 4 makes $C=\operatorname{holim}C_n$ perfect over $A$, with $C\otimes_A^{\mathbf L}A_n=C_n$. Derived Hom from $P$, regarded as a right adjoint on the derived quasi-coherent category, commutes with its products and homotopy limits. Hence
$$R\operatorname{Hom}_Y(P,K)=C.$$Duality for perfect objects gives the same statement for $R\Gamma(Y,K\otimes^{\mathbf L}P)$. Section 5 proves that $K$ is pseudo-coherent relative to $A$.
For an affine étale $U\to Y$, its sequential perfect-test formula and commutation of derived tensor with homotopy colimits give the canonical comparison
$$R\Gamma(U,K)\otimes_A^{\mathbf L}A_n \xrightarrow{\;\sim\;}R\Gamma(U_n,G_n).$$The comparison is induced by the limit projections, so its composites at consecutive levels are exactly the maps coming from $\phi_n$.
We next make $K$ a finitely presented sheaf near the common closed fibre. Let $u\in U$ lie over $V(I_1)$. Choose a finite-presentation smooth algebra $P$ surjecting onto the affine chart algebra $B$. Relative pseudo-coherence represents $K|_U$, pushed to $\operatorname{Spec}P$, by a bounded-above finite-free $P$-complex $F^\bullet$. Its derived reduction to $A_n$ has cohomology only in degree zero, equal to the module of $G_n|_{U_n}$. Since $P$ is $A$-flat, ordinary tensor of this complex computes that reduction.
If its largest nonzero term has degree $t>0$, the last differential is surjective on the residue-field fibre at $u$. A maximal minor is invertible on a neighbourhood of $u$. Split off this surjective finite-free pair, replacing the complex by its complement. Repeat until the largest degree is at most zero. Since $K$ has no negative cohomology, on this neighbourhood it is precisely $H^0(K)$. The cokernel of the last retained finite-free differential is finitely presented over $P$ and, as $B$ acts on it, finitely presented over the quotient $B$. Tensor right exactness identifies every ordinary reduction with $G_n$. These neighbourhoods descend through the open étale chart maps. Their union is an open $W\subset Y$ containing every $Y_n$, on which
$$K|_W=F[0],\qquad F=H^0(K)|_W,$$with $F$ finitely presented and marked reductions $G_n$. The space $Y_1$ is quasi-compact, and all the $Y_n$ have its underlying closed-fibre set. Choose finitely many quasi-compact open neighbourhoods within this union which cover that set, and replace $W$ by their union. Now $W$ is a quasi-compact open in the finitely presented $Y/A$, so $W/A$ is finitely presented. This supplies the finite-type hypothesis for the proper-part theorem.
Use the Fitting closed support $Z=V(\operatorname{Fitt}_0F)$ in $W$. Its base change to $A_1$ is proper by Section 2. The henselian proper-part theorem for separated finite-type algebraic spaces splits
$$Z=Z_{\mathrm{pr}}\amalg Z_{\mathrm{away}},$$with $Z_{\mathrm{pr}}$ proper over $A$, and $Z_{\mathrm{away}}$ disjoint from the common closed fibre. Its proof reduces by the weak Chow cover to a quasi-projective scheme, then to its projective closure; general Stein factorization and henselian lifting of idempotents split the projective closed fibre. The unwanted boundary has proper closed image missing $V(I_1)$, so is empty. Under the proper cover, the two images are closed; their intersection has proper closed image missing $V(I_1)$, hence is empty. They therefore descend to complementary open-and-closed subspaces. This proves the algebraic-space proper-part extension. Remove $Z_{\mathrm{away}}$ from $W$. The support of $F$ is now proper over $A$.
It remains to establish flatness; finite presentation and the marked ordinary reductions alone have not established it. Proper support makes $F$ universally pure over $A$: the closure of an associated fibre point has proper closed image, so it meets every specialization of its base point. The pure universal-flattening theorem gives a monomorphism of finite presentation
$$T\longrightarrow\operatorname{Spec}A$$whose pullback tests are exactly those on which $F$ is relatively flat. Every $\operatorname{Spec}A_n$ factors through $T$, because $F|_{Y_n}=G_n$ is flat.
The elementary monomorphism lemma proves $T=\operatorname{Spec}A$. Here are its details. Take a quasi-compact open of $T$ containing the common image of the $\operatorname{Spec}A_n$. It is separated and quasi-finite over $\operatorname{Spec}A$, hence embeds openly into a finite $A$-scheme $\operatorname{Spec}B$ by Zariski main. The unique compatible maps $B\to A_n$ define $B\to A$. Thus its section $\operatorname{Spec}A\to\operatorname{Spec}B$ pulls this open back to an open of $\operatorname{Spec}A$ containing $V(I_1)$. Every closed point lies in $V(I_1)$; a closed complement would have a closed point, so that open is all of $\operatorname{Spec}A$. The section factors through $T$. A monomorphism admitting a section is an isomorphism. Hence $F$ is $A$-flat.
Finally its proper support $Z_{\mathrm{pr}}\to Y$ is closed: a proper map to $A$ mapping to a separated $A$-space is proper, and this map is an immersion. Extend $F$ by zero along $W\to Y$, equivalently push it from that closed support. In a neighbourhood outside the support it is zero; on $W$ it is finitely presented. Thus the resulting $G$ is finitely presented on all of $Y$, remains $A$-flat, has proper support, and retains every marked comparison with $G_n$. This proves the theorem.
The exact universal-flattening proof is incorporated below at algebraic-space scope, including its reduction to complete dévissage. Its transitive scheme dévissage inputs are explicitly retained in Section 11; their mere source locators do not certify programme closure.
For the coherent-stack use in Lesson 8, the towers in Lesson 7's strong-effectivity criterion have square-zero kernels for every composite transition, so they satisfy the present hypotheses. The limit family $Y=X_A$ need not be flat. The theorem gives the required marked object, and the existing diagonal, limit and (RS*) proofs then give openness of versality for the nonflat coherent stack.
A.7. Polarized proper schemes
Let $\mathcal P$ be the stack whose objects over a scheme $T$ are proper flat finitely presented schemes $X/T$ and a relatively ample invertible module $L$. An arrow over $T'\to T$ includes a cartesian isomorphism $X'\cong X\times_TT'$ and an actual isomorphism between the pulled-back polarization and $L'$. Scalar automorphisms are retained.
Descent is effective. Descend the proper flat finitely presented algebraic space and the invertible module separately, with their cocycles. Relative ampleness descends. An algebraic space with a relatively ample invertible module over a scheme is a scheme: its standard opens defined by sufficiently positive sections are affine over affine base charts and cover it, and the sheaf identifications give their open immersions. Thus the descended object has exactly the scheme condition required in the definition.
The diagonal is representable. For two pairs $(X,L),(Y,N)$, first form the space of scheme isomorphisms by imposing the two inverse equations in
$$\operatorname{Mor}_T(X,Y)\times_T\operatorname{Mor}_T(Y,X).$$These morphism spaces are the graph spaces of Lesson 8, Corollary 6.4. Over its universal isomorphism $a:X\to Y$, the additional datum is $\operatorname{Isom}(L,a^*N)$, affine of finite presentation by Lesson 8, Corollary 1.3. Its composite over $T$ represents the polarized Isom functor.
Finite presentations of spaces, line bundles and arrows descend along filtered ring colimits. Properness, flatness and ampleness descend after increasing the index. Descending an arrow together with its inverse, then its two inverse equalities, proves full groupoid limit preservation.
The (RS*) check retains the bundle and its arrow. Flat locally finitely presented schemes patch over an affine pushout along a nilpotent thickening. On affine charts their structure algebras are the flat fibre-product algebras; charts and their intersections glue by full faithfulness. Relatively flat modules patch by the fibre-product module argument of Lesson 8, Section 3. A pair of line bundles therefore patches to a finitely presented relatively flat module whose fibres are free of rank one, so the local free-locus lemma makes it invertible. Properness and ampleness are recovered across the nilpotent thickening. This gives the entire fibre-product groupoid, including the specified identification on the overlap.
For the finite tangent check there is a shorter route than the graded-deformation argument with omitted details in the source. Deformations of proper finite-type $X/k$ have tangent $\operatorname{Ext}^1(\mathrm{NL}_{X/k},\mathcal O_X)$ and infinitesimal automorphisms $\operatorname{Ext}^0(\mathrm{NL}_{X/k},\mathcal O_X)$. The naive cotangent complex has coherent cohomology only in degrees $-1,0$, so coherent proper cohomology and the local-to-global Ext spectral sequence make both spaces finite. Forgetting $L$ induces a linear map from the pair tangent to this finite tangent. Its kernel is a quotient of the tangent for line bundles on fixed $X$, namely $H^1(X,\mathcal O_X)$: any deformation in the kernel is isomorphic, after a marked trivialization of $X$, to a deformation of $L$ on the trivial family. Similarly the kernel on infinitesimal automorphisms is $H^0(X,\mathcal O_X)$. Both are finite. The images are subspaces of finite spaces, so the pair tangent and automorphism spaces are finite. The marking changes act by the relevant infinitesimal automorphisms; no unjustified identification of the kernel with the entire $H^1$ is asserted.
Here is strong effectivity at full non-Noetherian scope. Let $R=\varprojlim R_n$ be any surjective locally nilpotent tower and let $(X_n,L_n)$ be a compatible system of objects. Choose one integer $d_0>0$ such that the sufficiently positive section algebra of $(X_1,L_1)$ has vanishing positive cohomology and finite projective degree pieces. The uniform projective-deformation lemma, proved in the appendix, applies to every thickening $R_n\to R_1$, with the same $d_0$. It gives
$$Q_n=R_n\oplus\bigoplus_{d\geq d_0}H^0(X_n,L_n^d),$$a finitely presented graded $R_n$-algebra with finite projective degree pieces, compatible with every transition, and canonical isomorphisms
$$X_n=\operatorname{Proj}Q_n,\qquad L_n=\mathcal O_{\operatorname{Proj}Q_n}(1).$$Set $Q_d=\varprojlim_n(Q_n)_d$ and $Q=\bigoplus_dQ_d$. Lifting finite projectives over the henselian pair $(R,\ker(R\to R_1))$, followed by successive lifts of module maps, proves $Q_d$ finite projective and $Q_d\otimes_RR_n=(Q_n)_d$.
We prove finite presentation of the whole algebra; it does not follow merely from finite projectivity of its separate pieces. Choose a finite homogeneous presentation
$$Q_1=R_1[x_1,\ldots,x_s]/(f_1,\ldots,f_t)$$with all $x_i$ of positive degree. Lift these homogeneous generators into $Q$, giving $\Psi:R[x_1,\ldots,x_s]\to Q$. In each degree its cokernel is finite and has zero reduction modulo the Jacobson ideal $\ker(R\to R_1)$, so Nakayama makes $\Psi$ surjective degreewise. Each homogeneous polynomial degree piece is finite free and $Q_d$ is projective, so $(\ker\Psi)_d$ is finite projective and reduction is exact. Thus lift each $f_j$ to a homogeneous $g_j\in\ker\Psi$. For each degree the quotient of $(\ker\Psi)_d$ by the degree-$d$ part of the ideal $(g_1,\ldots,g_t)$ is finite and has zero reduction. Nakayama kills it. Therefore
$$Q=R[x_1,\ldots,x_s]/(g_1,\ldots,g_t)$$is finitely presented. The empty family gives $Q=R$ and $\operatorname{Proj}Q=\varnothing$; it causes no exception.
Take $X=\operatorname{Proj}Q$, $L=\mathcal O_X(1)$. Localizing the graded algebra and taking degree-zero components shows $X$ flat over $R$; the same calculation makes $L$ relatively flat. Finite homogeneous presentation makes $X/R$ proper and finitely presented and makes $L$ finitely presented. Proj and its twisting module commute with base change, giving exactly the marked $X_n,L_n$. The fibrewise free-locus lemma makes $L$ invertible near $X_1$. Its complement has proper closed image in $\operatorname{Spec}R$ missing all closed points, so is empty. The relative ample locus is open, contains $\operatorname{Spec}R_1$, and similarly is the whole base. Thus $(X,L)$ is the required compatible polarized family.
This strong effectivity yields ordinary formal effectivity over complete Noetherian local rings and yields openness of versality through Lesson 7's strong-effectivity criterion. We have checked small fibres (finite chart descriptions in the chosen universe), descent, limits, the diagonal, (RS*), finite tangent and automorphism spaces, ordinary effectivity, and openness. Finite-type $\mathbf Z$-algebras are G-rings. Lesson 7's representable-diagonal Artin theorem therefore proves that $\mathcal P$ is algebraic. This proves Tag 0D4X, at the scope of the definition corresponding to 0D1L.
For any algebraic space $B$, the stack adding a parameter map $T\to B$ is $\mathcal P\times_{\operatorname{Spec}\mathbf Z}B$. Pull back its smooth atlas and diagonal. This proves algebraicity over arbitrary $B$, without an added Noetherian or G-ring hypothesis on $B$.
A.8. All proper flat curve spaces of dimension at most one
Let $\mathcal C_{\leq1}$ have objects proper flat finitely presented algebraic spaces $X/T$, $T$ a scheme, with every fibre of dimension at most one; arrows are cartesian isomorphisms. Fibres may be empty, zero-dimensional, disconnected, reducible or nonreduced. No smoothness, nodality, stability, polarization or geometric connectedness is imposed.
First consider the stack $\mathcal S$ of all proper flat finitely presented spaces. This stack has effective fppf descent by the algebraic-space descent theorem of Lessons 1–2. Its diagonal is the Isom space constructed from the two inverse equations in the morphism spaces of Lesson 8, Corollary 6.4. Finite-presentation descent and descent of properness and flatness give full groupoid limit preservation. Flat algebraic spaces patch across affine pushouts along nilpotent thickenings, giving (RS*); its source proof is included below. Properness is recovered across the thickening. The finite tangent and infinitesimal-automorphism calculation is the naive cotangent calculation from Section 7, now on the small étale site of $X$, with proper coherent cohomology from Section 3.
No algebraicity or ordinary effectivity assertion for $\mathcal S$ is needed. Openness of versality follows from its much more limited square-zero-tower effectivity. Suppose $R_n\to R_m$ has square-zero kernel for every $n\geq m$, and $X_n/R_n$ is a compatible system. Put $I_n=\ker(R_n\to R_1)$, $R=\varprojlim R_n$, $I=\varprojlim I_n$; then $I^2=0$. On the common small étale site of $X_1$ there are marked square-zero extensions
$$0\to\mathcal O_{X_1}\otimes_{R_1}I_n \to\mathcal O_{X_n}\to\mathcal O_{X_1}\to0.$$The left modules have surjective transition maps. Their sheaf inverse limit has no higher derived-limit cohomology on affine étale charts. Moreover
$$\mathcal O_{X_1}\otimes_{R_1}I \longrightarrow\varprojlim_n (\mathcal O_{X_1}\otimes_{R_1}I_n)$$becomes an isomorphism under $DQ_{X_1}$. To verify this, test against a perfect object and use the proper flat perfect direct-image bridge of Section 4; its finite-projective complex tensor-commutes with this surjective module limit. A perfect generator then detects the comparison.
The exact square-zero-extension comparison lemma, proved in the appendix, now yields an extension of sheaves of $R$-algebras
$$0\to\mathcal O_{X_1}\otimes_{R_1}I \to\mathcal O'\to\mathcal O_{X_1}\to0$$which maps, with all markings, to each preceding extension. The construction is an extension in the ringed étale topos, not an assertion that the ordinary inverse limit of chart algebras is quasi-coherent. A square-zero ringed-topos thickening with this quasi-coherent ideal comes from a unique algebraic-space thickening $X_1\subset X$. The square-zero flatness criterion gives $X/R$ flat. Finite presentation and properness lift over this square-zero thickening. Base change of the marked extension to each $R_n$ recovers $X_n$, by the extension equivalence. Thus $\mathcal S$ satisfies the strong-effectivity condition used solely for openness.
The condition on fibre dimension cuts out an open substack: for a proper finitely presented morphism, the set of points where the fibre dimension is at most one is open, and formation of this open is preserved and reflected by every residue-field extension and hence every base change. Equivalently, the closed locus where fibre dimension is at least two has proper closed image. Pullback of $\mathcal C_{\leq1}\subset\mathcal S$ by a family is exactly this open immersion. Consequently its diagonal, descent, (RS*) and infinitesimal tangent comparisons are those for $\mathcal S$. Dimension descends along filtered limits after increasing the index; together with the space-limit argument this proves full limit preservation for $\mathcal C_{\leq1}$. Since its inclusion is open, a versal neighbourhood at a point in this substack can be intersected with that open, so openness of versality for $\mathcal S$ restricts to it.
Ordinary formal effectivity is a separate argument. Let $R$ be complete Noetherian local, with maximal ideal $\mathfrak m$, and let $X_n/(R/\mathfrak m^n)$ be a compatible proper flat finitely presented family with special fibre dimension at most one. A proper algebraic space of dimension at most one over a field is a scheme; a proper scheme of that dimension is projective, including its nonreduced and disconnected cases. The exact source proofs and their scope are retained below. To cover the endpoint carefully, a zero-dimensional proper finite-type field scheme is quasi-finite and proper, hence finite; its Artinian affine structure has ample trivial bundle. If one-dimensional and isolated zero-dimensional components coexist, the latter form an open-and-closed Artinian part, and the finite decomposition glues the ample bundles. The reduced one-dimensional part has ample bundles on its integral components; choose positive powers and sections nonvanishing at their finite intersections, glue their trivializations there, and use the finite affine closed-cover lemma to obtain an affine section-open around the intersections. Away from them, component sections extend through the complementary component ideal. These opens prove ampleness. Lift the bundle through the nilpotent reduction using $H^2=0$, and use invariance of ampleness under nilpotent thickening. This is the full reducible/nonreduced route in the incorporated proof chain; no normalization or smooth-curve argument is substituted.
Choose an ample invertible module $L_1$ on $X_1$. Nilpotent thickenings of a scheme in algebraic spaces are schemes, so all $X_n$ are schemes.
Lift $L_n$ recursively through
$$1\to1+\mathfrak m^n\mathcal O_{X_{n+1}} \to\mathcal O_{X_{n+1}}^\times \to\mathcal O_{X_n}^\times\to1.$$The ideal in the left term is square-zero, so multiplication identifies that sheaf with its additive quasi-coherent module. Its underlying Noetherian topological space has dimension at most one; coherent cohomological dimension gives $H^2=0$. Therefore the obstruction vanishes, and there is an invertible $L_{n+1}$ together with a specified isomorphism to $L_n$ on restriction. Ampleness is invariant under a nilpotent thickening, so every $L_n$ is ample. Apply the proved polarized strong-effectivity theorem in Section 7 to the tower $R/\mathfrak m^n$. It gives a proper flat finitely presented scheme $X/R$ with exactly the marked formal reductions $X_n$.
All fibres of this algebraization have dimension at most one. For a proper finitely presented morphism the locus of fibre dimension at least two is closed. Any nonempty closed subset of the spectrum of a local ring contains its closed point; here that point has dimension at most one. The locus is therefore empty. This verifies the exact curve-stack object conditions and proves ordinary formal effectivity. Choosing an ample bundle is part of the proof only; the final object of the unpolarized groupoid is $X$ with its original markings.
The full Artin check now gives algebraicity of $\mathcal C_{\leq1}$: small fibres, effective descent, representable diagonal, full limits, (RS*), finite tangent and automorphism spaces, the just-proved ordinary effectivity, and the square-zero argument giving openness of versality. The G-ring base is again $\operatorname{Spec}\mathbf Z$. This proves Tag 0D5A, with definition 0D4Y. Its product with any algebraic space $B$ is algebraic by base change of the atlas and diagonal. A scheme-only total-space moduli problem would have been a different statement.
A.9. The order of the moduli arguments
The Hom and Isom constructions precede coherent-sheaf algebraicity. Quot and Hilbert then represent graphs, giving the diagonal needed for the polarized and curve-space stacks. Ordinary adic existence, strong existence for arbitrary locally nilpotent towers, and the flat-case low-Ext calculation each retain their own hypotheses and proofs. Fixed Hilbert-polynomial components and stable or smooth curve loci are further moduli problems; the two stacks proved here retain their full stated definitions.
A.10. Support, base change and graded relations
- The strong-existence proper-support step uses Fitting support. Annihilator supports need not commute with nonflat base change. Only the Fitting closed support equality, and the properness equivalence with annihilator support, are used.
- The printed formal dimension-at-most-one algebraization lemma omits properness in its statement although its proof uses a proper special fibre. The lemma as printed is false: the constant tower of affine lines over a field is not the reduction of a projective scheme. Here the statement has the properness hypotheses of the actual curve-stack consumer, and the proof is supplied through Section 7.
- The arbitrary direct-image corollary in spaces-perfect.tex labels its module “flat over S” although the cited theorem needs flatness over Y. Here flatness is over the direct-image target throughout; the broader printed corollary is not used.
- In derived Chow, the chosen point over y is not asserted unique. The projective direct image restricts to V, not to Y times V; the comparison uses the graph's structure-sheaf property with its correctly typed source.
- In the support-preserving perfect lift, successive cones use g_1 through g_s, each once. Starting with P plus P[1] yields the corresponding binomial multiplicities with s+1 factors; the proof only needs a distinguished P summand. Taking the projector cone then gives exactly P plus P[1].
- The source pushout category uses the fibre-product category over X, and its flat-module statement requires the second module to be flat over X prime. The printed category over Y prime and “flat over X” are type errors. The reader proof uses the correctly typed affine patching equivalence.
- The polarized finite-presentation argument explicitly uses projectivity of every graded piece to lift relations and apply Nakayama degreewise. Right exactness alone would not identify the polynomial presentation kernel after reduction.
- The source's graded tangent equivalence contains omitted details. The complete tangent finiteness argument in Section 7 uses the marked forgetful tangent map, its H^1 and H^0 kernels, and the naive cotangent finite-space calculation instead.
A.11. Scheme foundations and algebraic-space extensions
The three target theorem proofs have been supplied at their full local mathematical scope, conditional on the explicitly identified foundational proof material below. Incorporation of the supporting native proofs is local evidence, not a certificate of recursive closure for every external label in those proofs.
The following actual AG-QC programme bodies were inspected in the current edition, not merely read from a course title:
| Body | SHA256 | Exact inspected scope |
|---|---|---|
| AG-QC/src/proper-morphisms-and-coherent-direct-images.md | f3e42e27b6f536d9ddc709f327150445b790ff0c78870bd97c839ae11344d6dd | Sections 1–4, full proofs of Artin–Rees, graph extension, generic lattice, filtration, property dévissage and Noetherian proper scheme coherence |
| AG-QC/src/base-change-and-the-grothendieck-complex.md | dbc80760db17ca25682743cbcb6a5ee7b3296574c2cc4fea9be6c0d90925ebb9 | Sections 1–3, full scheme canonical comparison, flat base change, finite-projective replacement and Noetherian proper flat coherent complex |
| AG-QC/src/grothendiecks-existence-theorem.md | fc0ca5d595368d6b917cc12e5ca55c3cb856d14a3f8b9597f3dd3f6374ffae59 | Sections 1–6, full projective adic scheme existence and full faithfulness; proper-support reduction still invokes exact external bounded-gluing/comparison proofs |
| AG-QC/src/the-theorem-on-formal-functions.md | 45c94821b35af9e7f06bdd3261797fac86dd7541049d2822cdc96377afa8a9d7 | Inventory/hash only in this task; body was not re-audited here |
| AG-QC/src/algebraization-of-formal-schemes.md | fa1e10b37296b1ff60df1ebed40a7d54d4ad2039fe74e7079ca14e18f3266793 | Inventory/hash only in this task; no proof closure inferred |
The current Noetherian scheme complex is a genuine written provider. Section 3 supplies the space extension; Section 4 supplies the arbitrary-base extension. The projective adic scheme theorem is genuine written programme mathematics, but it is not the arbitrary sequence theorem proved in Section 6.
The algebraic-space pure-flattening argument, complete dévissage, generic presentations, support-preserving perfect lifting, perfect generators, and square-zero ringed-topos comparisons are supplied in the following proofs. The sequential perfect-test construction in Section 5 is an independent route; its complete differential graded alternative is retained with its own prerequisites. The diagonal Koszul resolution gives the projective-space pseudo-coherence test without requiring that alternative.
Lesson 3, Section 5.6.7, C.1, supplies the actually written finite flat-module model theorem at arbitrary filtered-system scope. Its blowup-flattening theorem is a different assertion from universal pure-flattening representability and is not substituted for it. Existing Lessons 1–7 and the genuine AG-QC scheme proofs retain their recorded hypotheses and lower dependencies. The separate Artin reader supplies desingularization and polynomial approximation. The uncovered prerequisite record below preserves the remaining exact lower obligations.
A.12. The supporting cohomological and deformation constructions
These are the supporting mathematical statements and their complete proofs. The independent reader proofs in Sections 3–8 supply the scope extensions, repaired statements and two alternate constructions. The converted proofs retain the exact statement scope and the explicit prerequisites. The known statement and map corrections have been applied to these reader proofs. The unchanged human arguments retain their original mathematical scope and source credit.
The projective-space pseudo-coherence criterion and sequential approximation in Section 5 are complete reader alternatives. The native countable proof and the second quasi-coherator proof are retained as sound optional alternatives; their additional unbound prerequisites are not dependencies of the selected reader routes. The source proper-support lemma is omitted because its nonflat annihilator-base-change claim requires the Fitting replacement proved in Sections 2 and 6. The printed nonproper formal algebraization statement is also omitted; Section 8 proves its actual proper consumer.
A.12.1 Henselian limits and compatible finite complexes
The following arguments adapt the human Stacks Project treatment in more-algebra.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. Henselian pairs from locally nilpotent inverse systems
Let $A = \varprojlim A_n$ where $(A_n)$ is an inverse system of rings whose transition maps are surjective and have locally nilpotent kernels. Then $(A, I_n)$ is a henselian pair, where $I_n = \operatorname{Ker}(A \to A_n)$.
Proof. Fix $n$. Let $a \in A$ be an element which maps to $1$ in $A_n$. By Algebra, Lemma Nilpotent thickenings and local algebra we see that $a$ maps to a unit in $A_m$ for all $m \geq n$. Hence $a$ is a unit in $A$. Thus by Algebra, Lemma Containment in the Jacobson radical the ideal $I_n$ is contained in the Jacobson radical of $A$. Let $f \in A[T]$ be a monic polynomial and let $\overline{f} = g_nh_n$ be a factorization of $\overline{f} = f \bmod I_n$ with $g_n, h_n \in A_n[T]$ monic generating the unit ideal in $A_n[T]$. By Lemma Henselian rings and nilpotent thickenings we can successively lift this factorization to $f \bmod I_m = g_m h_m$ with $g_m, h_m$ monic in $A_m[T]$ for all $m \geq n$. At each step we have to verify that our lifts $g_m, h_m$ generate the unit ideal in $A_n[T]$; this follows from the corresponding fact for $g_n, h_n$ and the fact that $\operatorname{Spec}(A_n[T]) = \operatorname{Spec}(A_m[T])$ because the kernel of $A_m \to A_n$ is locally nilpotent. As $A = \varprojlim A_m$ this finishes the proof. $\square$
Lemma. Compatible finite projectives over an inverse limit
Let $A = \varprojlim A_n$ be a limit of an inverse system $(A_n)$ of rings. Suppose given $A_n$-modules $M_n$ and $A_{n + 1}$-module maps $M_{n + 1} \to M_n$. Assume
-
the transition maps $A_{n + 1} \to A_n$ are surjective with locally nilpotent kernels,
-
$M_1$ is a finite projective $A_1$-module,
-
$M_n$ is a finite flat $A_n$-module, and
-
the maps induce isomorphisms $M_{n + 1} \otimes_{A_{n + 1}} A_n \to M_n$.
Then $M = \varprojlim M_n$ is a finite projective $A$-module and $M \otimes_A A_n \to M_n$ is an isomorphism for all $n$.
Proof. By Lemma Henselian pairs from locally nilpotent inverse systems the pair $(A, \operatorname{Ker}(A \to A_1))$ is henselian. By Lemma Lifting projective, locally free modules and finite algebras we can choose a finite projective $A$-module $P$ and an isomorphism $P \otimes_A A_1 \to M_1$. Since $P$ is projective, we can successively lift the $A$-module map $P \to M_1$ to $A$-module maps $P \to M_2$, $P \to M_3$, and so on. Thus we obtain a map $$P \longrightarrow M$$ Since $P$ is finite projective, we can write $A^{\oplus m} = P \oplus Q$ for some $m \geq 0$ and $A$-module $Q$. Since $A = \varprojlim A_n$ we conclude that $P = \varprojlim P \otimes_A A_n$. Hence, in order to show that the displayed $A$-module map is an isomorphism, it suffices to show that the maps $P \otimes_A A_n \to M_n$ are isomorphisms. From Lemma Lifting projective and locally free modules we see that $M_n$ is a finite projective module. By Lemma Projective, locally free modules and finite algebras the maps $P \otimes_A A_n \to M_n$ are isomorphisms. $\square$
Lemma. Pseudo-coherence under a nilpotent reduction
Let $R' \to R$ be a surjective ring map whose kernel is a nilpotent ideal. Let $K' \in D(R')$ and set $K = K' \otimes_{R'}^\mathbf{L} R$. Then $K$ is pseudo-coherent if and only if $K'$ is pseudo-coherent.
Proof. One direction follows from Lemma Pullback of pseudo-coherent complexes and coherent sheaves. For the other direction, assume $K$ is pseudo-coherent. Then by Lemma Pseudo-coherent complexes and coherent sheaves we can represent $K$ by a bounded above complex $E^\bullet$ of finite free $R$-modules. By Lemma Lifting projective, locally free modules and derived categories we can represent $K'$ by a bounded above complex $P^\bullet$ of projective $R'$-modules such that $P^n \otimes_{R'} R = E^n$. By Nakayama's lemma we see that $P^n$ is finite free and we conclude that $K'$ is pseudo-coherent as well. $\square$
Lemma. Lifting a complex after adjoining free summands
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $E^\bullet$ be a complex of $R/I$-modules. Let $K$ be an object of $D(R)$. Assume that
-
$E^\bullet$ is a bounded above complex of finite stably free $R/I$-modules,
-
$K \otimes_R^\mathbf{L} R/I$ is represented by $E^\bullet$ in $D(R/I)$,
-
$K^\bullet$ is pseudo-coherent, and
-
every element of $1 + I$ is invertible.
Then there exists a bounded above complex $P^\bullet$ of finite stably free $R$-modules representing $K$ in $D(R)$ such that $P^\bullet \otimes_R R/I$ is isomorphic to $E^\bullet$. Moreover, if $E^i$ is free, then $P^i$ is free.
Proof. We apply Lemma Lifting derived categories using the class $\mathcal{P}$ of all finite stably free $R$-modules. Property (1) of the lemma is immediate. Property (2) follows from Lemma Projective and locally free modules. Property (3) follows from Nakayama's lemma (Algebra, Lemma Nakayama's lemma). Property (4) follows from the fact that we can lift finite stably free $R/I$-modules to finite stably free $R$-modules, see Lemma Lifting projective and locally free modules. Part (5) holds because a pseudo-coherent complex can be represented by a bounded above complex of finite free $R$-modules. The final assertion of the lemma follows from Lemma Projective, locally free modules and finite algebras. $\square$
Lemma. Pseudo-coherent inverse limits
Let $A = \varprojlim A_n$ be a limit of an inverse system $(A_n)$ of rings. Suppose given $K_n \in D(A_n)$ and maps $K_{n + 1} \to K_n$ in $D(A_{n + 1})$. Assume
-
the transition maps $A_{n + 1} \to A_n$ are surjective with locally nilpotent kernels,
-
either all $K_n$ are pseudo-coherent or there exists an integer $n_0$ such that $K_{n_0}$ is pseudo-coherent and the kernels of $A_{n + 1} \to A_n$ are nilpotent ideals for $n \geq n_0$,
-
the maps induce isomorphisms $K_{n + 1} \otimes_{A_{n + 1}}^\mathbf{L} A_n \to K_n$.
Then $K = R\varprojlim K_n$ is a pseudo-coherent object of $D(A)$ and $K \otimes_A^\mathbf{L} A_n \to K_n$ is an isomorphism for all $n$.
Proof. By assumption we can find a bounded above complex of finite free $A_1$-modules $P_1^\bullet$ representing $K_1$, see Definition Pseudo-coherent complexes. By Lemma Pseudo-coherence under a nilpotent reduction we conclude that $K_n$ is pseudo-coherent for all $n$. Then by Lemma Lifting a complex after adjoining free summands we can, by induction on $n > 1$, find complexes $P_n^\bullet$ of finite free $A_n$-modules representing $K_n$ and maps $P_n^\bullet \to P_{n - 1}^\bullet$ representing the maps $K_n \to K_{n - 1}$ inducing isomorphisms (!) of complexes $P_n^\bullet \otimes_{A_n} A_{n - 1} \to P_{n - 1}^\bullet$. Thus $K = R\varprojlim K_n$ is represented by $P^\bullet = \varprojlim P_n^\bullet$, see Lemma Modules and Remark Uniqueness in the lifting construction. Since $P_n^i$ is a finite free $A_n$-module for each $n$ and $A = \varprojlim A_n$ we see that $P^i$ is finite free of the same rank as $P_1^i$ for each $i$. This means that $K$ is pseudo-coherent. It also follows that $K \otimes_A^\mathbf{L} A_n$ is represented by $P^\bullet \otimes_A A_n = P_n^\bullet$ which proves the final assertion. $\square$
Lemma. Perfect inverse limits
Source credit: the original source citation Bhatt-Algebraize (Lemma 4.2)
Let $A = \varprojlim A_n$ be a limit of an inverse system $(A_n)$ of rings. Suppose given $K_n \in D(A_n)$ and maps $K_{n + 1} \to K_n$ in $D(A_{n + 1})$. Assume
-
the transition maps $A_{n + 1} \to A_n$ are surjective with locally nilpotent kernels,
-
either all $K_n$ are perfect or there exists an integer $n_0$ such that $K_{n_0}$ is perfect and the kernels $A_{n + 1} \to A_n$ are nilpotent for $n \geq n_0$, and
-
the maps induce isomorphisms $K_{n + 1} \otimes_{A_{n + 1}}^\mathbf{L} A_n \to K_n$.
Then $K = R\varprojlim K_n$ is a perfect object of $D(A)$ and $K \otimes_A^\mathbf{L} A_n \to K_n$ is an isomorphism for all $n$.
Proof. We already know that $K$ is pseudo-coherent and that $K \otimes_A^\mathbf{L} A_n \to K_n$ is an isomorphism for all $n$ by Lemma Pseudo-coherent inverse limits. Consider a surjective map $A \to \kappa$ whose kernel is a maximal ideal $\mathfrak m$. Any element of $A$ which maps to a unit in $A_1$ is a unit in $A$ by Algebra, Lemma Nilpotent thickenings and local algebra and hence $\operatorname{Ker}(A \to A_1)$ is contained in the Jacobson radical of $A$ by Algebra, Lemma Containment in the Jacobson radical. Hence $A \to \kappa$ factors as $A \to A_1 \to \kappa$. Hence $$K \otimes_A^\mathbf{L} \kappa = K \otimes_A^\mathbf{L} A_1 \otimes_{A_1}^\mathbf{L} \kappa = K_1 \otimes_{A_1}^\mathbf{L} \kappa$$ Note that $K_1$ is perfect by assumption (2). Hence $K_1$ has finite tor dimension by Lemma Perfect complexes. Thus there exist $a, b \in \mathbf{Z}$ such that $H^i(K \otimes_A^\mathbf{L} \kappa) = 0$ for all $i \not \in [a, b]$. By Lemma Perfect complexes we conclude that $K$ is perfect. $\square$
Lemma. Modules and tensor products and direct sums
Let $A, A', B, B', C, C', D, D', I, M', M, N, \varphi$ be as in Lemma Modules and tensor products and direct sums. If $N$ finite over $D$ and $M'$ finite over $C'$, then $N' = N \times_{\varphi, M} M'$ is finite over $D'$.
Proof. Recall that $D' \to D \times_C C'$ is surjective by Lemma Modules and tensor products and direct sums. Observe that $N' = N \times_{\varphi, M} M'$ is a module over $D \times_C C'$. We can apply Lemma Modules and tensor products and direct sums to the data $C, C', D, D', IC', M', M, N, \varphi$ to see that $N' = N \times_{\varphi, M} M'$ is finite over $D \times_C C'$. Thus it is finite over $D'$. $\square$
Lemma. Relative flat modules over a ring fibre product
With $A, A', B, B', C, C', D, D', I$ as in Situation Modules and tensor products and direct sums.
-
Let $(N, M', \varphi)$ be an object of $\text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'}$. If $M'$ is flat over $A'$ and $N$ is flat over $B$, then $N' = N \times_{\varphi, M} M'$ is flat over $B'$.
-
If $L'$ is a $D'$-module flat over $B'$, then $L' = (L \otimes_{D'} D) \times_{(L \otimes_{D'} C)} (L \otimes_{D'} C')$.
-
The category of $D'$-modules flat over $B'$ is equivalent to the categories of objects $(N, M', \varphi)$ of $\text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'}$ with $N$ flat over $B$ and $M'$ flat over $A'$.
Proof. Part (1) follows from part (1) of Lemma Flatness and modules.
Part (2) follows from part (2) of Lemma Flatness and modules using that $L' \otimes_{D'} D = L' \otimes_{B'} B$, $L' \otimes_{D'} C' = L' \otimes_{B'} A'$, and $L' \otimes_{D'} C = L' \otimes_{B'} A$, see discussion in Situation Modules and tensor products and direct sums.
Part (3) is an immediate consequence of (1) and (2). $\square$
Lemma. Finite presentation under flat module patching
Let $A, A', B, B', C, C', D, D', I, M', M, N, \varphi$ be as in Lemma Modules and tensor products and direct sums. If
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$N$ is finitely presented over $D$ and flat over $B$,
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$M'$ finitely presented over $C'$ and flat over $A'$, and
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the ring map $B' \to D'$ factors as $B' \to D'' \to D'$ with $B' \to D''$ flat and $D'' \to D'$ of finite presentation,
then $N' = N \times_M M'$ is finitely presented over $D'$.
Proof. Choose a surjection $D''' = D''[x_1, \ldots, x_n] \to D'$ with finitely generated kernel $J$. By Algebra, Lemma Finite presentation and finite algebras it suffices to show that $N'$ is finitely presented as a $D'''$-module. Moreover, $D''' \otimes_{B'} B \to D' \otimes_{B'} B = D$ and $D''' \otimes_{B'} A' \to D' \otimes_{B'} A' = C'$ are surjections whose kernels are generated by the image of $J$, hence $N$ is a finitely presented $D''' \otimes_{B'} B$-module and $M'$ is a finitely presented $D''' \otimes_{B'} A'$-module by Algebra, Lemma Finite presentation and finite algebras again. Thus we may replace $D'$ by $D'''$ and $D$ by $D''' \otimes_{B'} B$, etc. Since $D'''$ is flat over $B'$, it follows that we may assume that $B' \to D'$ is flat.
Assume $B' \to D'$ is flat. By Lemma Modules and tensor products and direct sums the module $N'$ is finite over $D'$. Choose a surjection $(D')^{\oplus n} \to N'$ with kernel $K'$. By base change we obtain maps $D^{\oplus n} \to N$, $(C')^{\oplus n} \to M'$, and $C^{\oplus n} \to M$ with kernels $K_D$, $K_{C'}$, and $K_C$. There is a canonical map $$K' \longrightarrow K_D \times_{K_C} K_{C'}$$ On the other hand, since $N' = N \times_M M'$ and $D' = D \times_C C'$ (by Lemma Flatness and modules; applied to the flat $B'$-module $D'$) there is also a canonical map $K_D \times_{K_C} K_{C'} \to K'$ inverse to the displayed arrow. Hence the displayed map is an isomorphism. By Algebra, Lemma Commutative algebra the modules $K_D$ and $K_{C'}$ are finite. We conclude from Lemma Modules and tensor products and direct sums that $K'$ is a finite $D'$-module provided that $K_D \to K_C$ and $K_{C'} \to K_C$ induce isomorphisms $K_D \otimes_B A = K_C = K_{C'} \otimes_{A'} A$. This is true because the flatness assumptions implies the sequences $$0 \to K_D \to D^{\oplus n} \to N \to 0 \quad\text{and}\quad 0 \to K_{C'} \to (C')^{\oplus n} \to M' \to 0$$ stay exact upon tensoring, see Algebra, Lemma Tor vanishing for a flat module. $\square$
A.12.2 Koszul representatives and support-preserving perfect approximation
The following arguments adapt the human Stacks Project treatment in perfect.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Situation. A complex and a finite principal-open cover
Here $A$ is a ring and $f_1, \ldots, f_r$ is a sequence of elements of $A$. We set $X = \operatorname{Spec}(A)$ and $U = D(f_1) \cup \ldots \cup D(f_r) \subset X$. We denote $\mathcal{U} : U = \bigcup_{i = 1, \ldots, r} D(f_i)$ the given open covering of $U$.
Lemma. The alternating Čech complex
In Situation A complex and a finite principal-open cover. Let $M$ be an $A$-module and denote $\mathcal{F}$ the associated $\mathcal{O}_X$-module. Then there is a canonical isomorphism of complexes $$\Psi : \mathop{\operatorname{colim}}_e \operatorname{Hom}_A(I^\bullet(f_1^e, \ldots, f_r^e), M) \longrightarrow \check{\mathcal{C}}_{alt}^\bullet(\mathcal{U}, \mathcal{F})$$ functorial in $M$ where the differentials on the $\operatorname{Hom}$-complex are the contragredients of the differentials on $I^\bullet(f_1^e, \ldots, f_r^e)$.
Proof. Recall that the alternating Čech complex is the subcomplex of the usual Čech complex given by alternating cochains, see Cohomology, Section Sheaf cohomology. As usual we view a $p$-cochain in $\check{\mathcal{C}}_{alt}^\bullet(\mathcal{U}, \mathcal{F})$ as an alternating function $s$ on $\{1, \ldots, r\}^{p + 1}$ whose value $s_{i_0\ldots i_p}$ at $(i_0, \ldots, i_p)$ lies in $M_{f_{i_0}\ldots f_{i_p}} = \mathcal{F}(U_{i_0\ldots i_p})$. On the other hand, a $p$-cochain $t$ in $\operatorname{Hom}^\bullet(I^\bullet(f_1^e, \ldots, f_r^e), M)$ is a map $t : \wedge^{p + 1}(A^{\oplus r}) \to M$. Write $[i] \in A^{\oplus r}$ for the $i$th basis element and write $$[i_0, \ldots, i_p] = [i_0] \wedge \ldots \wedge [i_p] \in \wedge^{p + 1}(A^{\oplus r})$$ For $t$ as above we set $$\Psi(t)_{i_0 \ldots i_p} = (-1)^p \frac{t([i_0, \ldots, i_p])}{f_{i_0}^e\ldots f_{i_p}^e}$$ It is clear that $\Psi(t)$ is an alternating cochain. The rule above is compatible with the transition maps of the system as the transition map $$I^\bullet(f_1^e, \ldots, f_r^e) \leftarrow I^\bullet(f_1^{e + 1}, \ldots, f_r^{e + 1}),$$ of (Perfect complexes) sends $[i_0, \ldots, i_p]$ to $f_{i_0}\ldots f_{i_p}[i_0, \ldots, i_p]$. It is clear from the description of the localizations $M_{f_{i_0} \ldots f_{i_p}}$ in Algebra, Lemma Localization as a filtered colimit that the rule $\Psi$ defines an isomorphism of cochain modules in degree $p$ in the colimit. To finish the proof we have to show that the map is compatible with differentials. To see this, for $t$ as above we compute $$\begin{aligned} d(\Psi(t))_{i_0 \ldots i_{p + 1}} & = \sum\nolimits_{j = 0}^{p + 1} (-1)^j \Psi(t)_{i_0\ldots \hat i_j \ldots i_{p + 1}} \\ & = (-1)^p \sum\nolimits_{j = 0}^{p + 1} (-1)^j t([i_0 \ldots \hat i_j \ldots i_{p + 1}]) (f_{i_0} \ldots \hat f_{i_j} \ldots f_{i_p})^{-e} \end{aligned}$$ Recall that the differentials on $I^\bullet(f_1^e, \ldots, f_r^e)$ are the negative of the differentials on $K^\bullet(f_1, \ldots, f_r)$. Thus $$\begin{aligned} \Psi(d(t))_{i_0 \ldots i_{p + 1}} & = (-1)^{p + 1} d(t)([i_0, \ldots, i_{p + 1}]) (f_{i_0} \ldots f_{i_{p + 1}})^{-e} \\ & = (-1)^{p + 1} t(d([i_0, \ldots, i_{p + 1}])) (f_{i_0} \ldots f_{i_{p + 1}})^{-e} \\ & = (-1)^{p + 1} t(-\sum\nolimits_{j = 0}^{p + 1} (-1)^j f_{i_j}^e [i_0, \ldots, \hat i_j, \ldots i_{p + 1}]) (f_{i_0} \ldots f_{i_{p + 1}})^{-e} \\ & = -(-1)^{p + 1} \sum\nolimits_{j = 0}^{p + 1} (-1)^j t([i_0, \ldots, \hat i_j, \ldots i_{p + 1}]) (f_{i_0} \ldots \hat f_{i_j} \ldots f_{i_p})^{-e} \end{aligned}$$ The two formulas agree concluding the proof. $\square$
Lemma. The Čech double complex
In Situation A complex and a finite principal-open cover. Let $M^\bullet$ be a complex of $A$-modules and denote $\mathcal{F}^\bullet$ the associated complex of $\mathcal{O}_X$-modules. Then there is a canonical isomorphism of complexes $$\mathop{\operatorname{colim}}_e \operatorname{Hom}^\bullet(I^\bullet(f_1^e, \ldots, f_r^e), M^\bullet) \longrightarrow \text{Tot}(\check{\mathcal{C}}_{alt}^\bullet(\mathcal{U}, \mathcal{F}^\bullet))$$ functorial in $M^\bullet$.
Proof. Consider the double complex $F^{\bullet, \bullet}$ with terms $F^{p, q} = \mathcal{C}_{alt}^p(\mathcal{U}, \mathcal{F}^q)$ discussed in Cohomology, Section Sheaf cohomology and derived categories. Consider the double complex $G^{\bullet, \bullet}$ with terms $G^{p, q} = \mathop{\operatorname{colim}}_e \operatorname{Hom}_A(I^{-p}(f_1^e, \ldots, f_r^e), M^q)$ and differentials given by functoriality (without the intervention of signs). The maps $\psi^{p, q} : G^{p, q} \to F^{p, q}$ constructed in the proof of Lemma The alternating Čech complex are isomorphisms and compatible with the differentials $d_1$ (by the lemma) and $d_2$ (this is clear). However, the differentials $d$ on the complexes on the left and right hand side of the arrow in the lemma have different signs. Namely, for $g \in G^{p, q}$ is given by $$d(g) = d_2(g) - (-1)^{p + q} d_1(g)$$ (see More on Algebra, Section Derived Hom, Ext and derived categories) and the differential for $f \in F^{p, q}$ is given by $$d(f) = d_1(f) + (-1)^p d_2(f)$$ Thus we can fix the signs by multiplying $\psi^{p, q}$ by $(-1)^{pq + p(p - 1)/2}$. $\square$
Lemma. Čech computation of derived cohomology
In Situation A complex and a finite principal-open cover. Let $\mathcal{F}^\bullet$ be a complex of quasi-coherent $\mathcal{O}_X$-modules. Then there is a canonical isomorphism $$\text{Tot}(\check{\mathcal{C}}_{alt}^\bullet(\mathcal{U}, \mathcal{F}^\bullet)) \longrightarrow R\Gamma(U, \mathcal{F}^\bullet)$$ in $D(A)$ functorial in $\mathcal{F}^\bullet$.
Proof. Let $\mathcal{B}$ be the set of affine opens of $U$. Since the higher cohomology groups of a quasi-coherent module on an affine scheme are zero (Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite)) this is a special case of Cohomology, Lemma Sheaf cohomology and derived categories. $\square$
Proposition. Koszul representatives on a principal-open cover
In Situation A complex and a finite principal-open cover. For every object $E$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ the map (Comparison for perfect complexes) is an isomorphism.
Proof. By Lemma Bounded comparison of affine derived categories we may assume that \(E\) is given by a complex of quasi-coherent sheaves \(\mathcal{F}^\bullet\). Let \(M^\bullet = \Gamma(X, \mathcal{F}^\bullet)\) be the corresponding complex of \(A\)-modules. By Lemmas The Čech double complex and Čech computation of derived cohomology we have quasi-isomorphisms
\[ \mathop{\operatorname{colim}}_e \operatorname{Hom}^\bullet(I^\bullet(f_1^e, \ldots, f_r^e), M^\bullet) \longrightarrow \text{Tot}(\check{\mathcal{C}}_{alt}^\bullet(\mathcal{U}, \mathcal{F}^\bullet)) \longrightarrow R\Gamma(U, \mathcal{F}^\bullet) \]By More on Algebra, Lemma Derived Hom, Ext and projective and locally free modules and Equation (Derived Hom and Ext) taking \(H^0\) of the complex \(\operatorname{Hom}^\bullet(I^\bullet(f_1^e, \ldots, f_r^e), M^\bullet)\) computes \(\operatorname{Hom}\) in \(D(A)\). Thus taking \(H^0\) on both sides we obtain
\[ \mathop{\operatorname{colim}}_e \operatorname{Hom}_{D(A)}(I^\bullet(f_1^e, \ldots, f_r^e), M^\bullet) = H^0(U, E) \]Since \(\operatorname{Hom}_{D(A)}(I^\bullet(f_1^e, \ldots, f_r^e), M^\bullet) = \operatorname{Hom}_{D(\mathcal{O}_X)}(I_e, E)\) by Lemma Bounded comparison of affine derived categories the lemma follows. \(\square\)
Lemma. Koszul representatives with closed support
In Situation A complex and a finite principal-open cover. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Assume that $H^i(E)|_U = 0$ for $i = - r + 1, \ldots, 0$. Then given $s \in H^0(X, E)$ there exists an $e \geq 0$ and a morphism $K_e \to E$ such that $s$ is in the image of $H^0(X, K_e) \to H^0(X, E)$.
Proof. Since $U$ is covered by $r$ affine opens we have $H^j(U, \mathcal{F}) = 0$ for $j \geq r$ and any quasi-coherent module (Cohomology of Schemes, Lemma Vanishing and affine neighbourhoods (uncovered prerequisite)). By Lemma Computing derived Hom with a quasi-coherent K-injective model we see that $H^0(U, E)$ is equal to $H^0(U, \tau_{\geq -r + 1}E)$. There is a spectral sequence $$H^j(U, H^i(\tau_{\geq -r + 1}E)) \Rightarrow H^{i + j}(U, \tau_{\geq -N}E)$$ see Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories. Hence $H^0(U, E) = 0$ by our assumed vanishing of cohomology sheaves of $E$. We conclude that $s|_U = 0$. Think of $s$ as a morphism $\mathcal{O}_X \to E$ in $D(\mathcal{O}_X)$. By Proposition Koszul representatives on a principal-open cover the composition $I_e \to \mathcal{O}_X \to E$ is zero for some $e$. By the distinguished triangle $I_e \to \mathcal{O}_X \to K_e \to I_e[1]$ we obtain a morphism $K_e \to E$ such that $s$ is the composition $\mathcal{O}_X \to K_e \to E$. $\square$
Lemma. Extending a perfect complex after adjoining a locally free summand
Let $X$ be an affine scheme. Let $U \subset X$ be a quasi-compact open. For every perfect object $E$ of $D(\mathcal{O}_U)$ there exists an integer $r$ and a finite locally free sheaf $\mathcal{F}$ on $U$ such that $\mathcal{F}[-r] \oplus E$ is the restriction of a perfect object of $D(\mathcal{O}_X)$.
Proof. Say $X = \operatorname{Spec}(A)$. Recall that a perfect complex is pseudo-coherent, see Cohomology, Lemma Perfect complexes. By Lemma Lifting pseudo-coherent complexes and coherent sheaves we can find a bounded above complex $\mathcal{F}^\bullet$ of finite free $A$-modules such that $E$ is isomorphic to $\mathcal{F}^\bullet|_U$ in $D(\mathcal{O}_U)$. By Cohomology, Lemma Perfect complexes and since $U$ is quasi-compact, we see that $E$ has finite tor dimension, say $E$ has tor amplitude in $[a, b]$. Pick $r < a$ and set $$\mathcal{K} = \operatorname{Ker}(\mathcal{F}^{r} \to \mathcal{F}^{r + 1}) = \operatorname{Im}(\mathcal{F}^{r - 1} \to \mathcal{F}^r).$$ Since $E$ has tor amplitude in $[a, b]$ we see that $\mathcal{F} = \mathcal{K}|_U$ is flat (Cohomology, Lemma Flatness). Hence $\mathcal{F}$ is flat and of finite presentation, thus finite locally free (Properties, Lemma Projective, locally free modules and finite algebras). It follows that $$\mathcal{F} \to \mathcal{F}^r|_U \to \mathcal{F}^{r + 1}|_U \to \ldots$$ is a strictly perfect complex on $U$ representing $E$. On the other hand, the complex $P = (\mathcal{F}^r \to \mathcal{F}^{r + 1} \to \ldots )$ is a perfect complex on $X$. Using stupid truncations we obtain a distinguished triangle $$P|_U \to E \to \mathcal{F}[-r - 1] \to (P|_U)[1]$$ If the map $E \to \mathcal{F}[-r - 1]$ is zero in $D(\mathcal{O}_U)$, then $P|_U = \mathcal{F}[-r - 2] \oplus E$, see Derived Categories, Lemma Splitting an exact triangle. This will be true for $r \ll 0$ for example by Lemma Ext from a perfect complex to bounded quasi-coherent cohomology. $\square$
Lemma. Extending a morphism after finite denominators are cleared
Let $X$ be an affine scheme. Let $U \subset X$ be a quasi-compact open. Let $E, E'$ be objects of $D_\mathrm{QCoh}(\mathcal{O}_X)$ with $E$ perfect. For every map $\alpha : E|_U \to E'|_U$ there exist maps $$E \xleftarrow{\beta} E_1 \xrightarrow{\gamma} E'$$ of complexes on $X$ with $E_1$ perfect such that $\beta : E_1 \to E$ restricts to an isomorphism on $U$ and such that $\alpha = \gamma|_U \circ \beta|_U^{-1}$. Moreover we can assume $E_1 = E \otimes_{\mathcal{O}_X}^\mathbf{L} I$ for some perfect complex $I$ on $X$.
Proof. Write $X = \operatorname{Spec}(A)$. Write $U = D(f_1) \cup \ldots \cup D(f_r)$. Choose finite complex of finite projective $A$-modules $M^\bullet$ representing $E$ (Lemma Perfect complexes on an affine scheme). Choose a complex of $A$-modules $(M')^\bullet$ representing $E'$ (Lemma Bounded comparison of affine derived categories). In this case the complex $H^\bullet = \operatorname{Hom}_A(M^\bullet, (M')^\bullet)$ is a complex of $A$-modules whose associated complex of quasi-coherent $\mathcal{O}_X$-modules represents $R\mathcal{H}om(E, E')$, see Cohomology, Lemma Perfect complexes and derived Hom and Ext. Then $\alpha$ determines an element $s$ of $H^0(U, R\mathcal{H}om(E, E'))$, see Cohomology, Lemma Derived Hom and Ext. There exists an $e$ and a map $$\xi : I^\bullet(f_1^e, \ldots, f_r^e) \to \operatorname{Hom}_A(M^\bullet, (M')^\bullet)$$ corresponding to $s$, see Proposition Koszul representatives on a principal-open cover. Letting $E_1$ be the object corresponding to complex of quasi-coherent $\mathcal{O}_X$-modules associated to $$\text{Tot}(I^\bullet(f_1^e, \ldots, f_r^e) \otimes_A M^\bullet)$$ we obtain $E_1 \to E$ using the canonical map $I^\bullet(f_1^e, \ldots, f_r^e) \to A$ and $E_1 \to E'$ using $\xi$ and Cohomology, Lemma Derived Hom and Ext. $\square$
Lemma. Extending a perfect complex together with its shift
Let $X$ be an affine scheme. Let $U \subset X$ be a quasi-compact open. For every perfect object $F$ of $D(\mathcal{O}_U)$ the object $F \oplus F[1]$ is the restriction of a perfect object of $D(\mathcal{O}_X)$.
Proof. By Lemma Extending a perfect complex after adjoining a locally free summand we can find a perfect object $E$ of $D(\mathcal{O}_X)$ such that $E|_U = \mathcal{F}[r] \oplus F$ for some finite locally free $\mathcal{O}_U$-module $\mathcal{F}$. By Lemma Extending a morphism after finite denominators are cleared we can find a morphism of perfect complexes $\alpha : E_1 \to E$ such that $(E_1)|_U \cong E|_U$ and such that $\alpha|_U$ is the map $$\left( \begin{matrix} \text{id}_{\mathcal{F}[r]} & 0 \\ 0 & 0 \end{matrix} \right) : \mathcal{F}[r] \oplus F \to \mathcal{F}[r] \oplus F$$ Then the cone on $\alpha$ is a solution. $\square$
Lemma. A perfect test complex with prescribed support
Let $X$ be a quasi-compact and quasi-separated scheme. Let $f \in \Gamma(X, \mathcal{O}_X)$. For any morphism $\alpha : E \to E'$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$ such that
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$E$ is perfect, and
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$E'$ is supported on $T = V(f)$
there exists an $n \geq 0$ such that $f^n \alpha = 0$.
Proof. We have Mayer-Vietoris for morphisms in the derived category, see Cohomology, Lemma Derived Hom and Ext. Thus if $X = U \cup V$ and the result of the lemma holds for $f|_U$, $f|_V$, and $f|_{U \cap V}$, then the result holds for $f$. Thus it suffices to prove the lemma when $X$ is affine, see Cohomology of Schemes, Lemma Induction by elementary distinguished squares (uncovered prerequisite).
Let $X = \operatorname{Spec}(A)$. Then $f \in A$. We will use the equivalence $D(A) = D_\mathrm{QCoh}(X)$ of Lemma Bounded comparison of affine derived categories without further mention. Represent $E$ by a finite complex of finite projective $A$-modules $P^\bullet$. This is possible by Lemma Perfect complexes on an affine scheme. Let $t$ be the largest integer such that $P^t$ is nonzero. The distinguished triangle $$P^t[-t] \to P^\bullet \to \sigma_{\leq t - 1}P^\bullet \to P^t[-t + 1]$$ shows that by induction on the length of the complex $P^\bullet$ we can reduce to the case where $P^\bullet$ has a single nonzero term. This and the shift functor reduces us to the case where $P^\bullet$ consists of a single finite projective $A$-module $P$ in degree $0$. Represent $E'$ by a complex $M^\bullet$ of $A$-modules. Then $\alpha$ corresponds to a map $P \to H^0(M^\bullet)$. Since the module $H^0(M^\bullet)$ is supported on $V(f)$ by assumption (2) we see that every element of $H^0(M^\bullet)$ is annihilated by a power of $f$. Since $P$ is a finite $A$-module the map $f^n\alpha : P \to H^0(M^\bullet)$ is zero for some $n$ as desired. $\square$
Lemma. Lifting perfect complexes while retaining support
Let $X$ be an affine scheme. Let $T \subset X$ be a closed subset such that $X \setminus T$ is quasi-compact. Let $U \subset X$ be a quasi-compact open. For every perfect object $F$ of $D(\mathcal{O}_U)$ supported on $T \cap U$ the object $F \oplus F[1]$ is the restriction of a perfect object $E$ of $D(\mathcal{O}_X)$ supported in $T$.
Proof. If the principal-open cover of the complement has no members, then the support is all of the ambient space. The preceding extension lemma applies directly to $F \oplus F[1]$. Hence we may assume $s \geq 1$ in the induction below.
Say $T = V(g_1, \ldots, g_s)$. After replacing $g_j$ by a power we may assume multiplication by $g_j$ is zero on $F$, see Lemma A perfect test complex with prescribed support. Choose $E$ as in Lemma Extending a perfect complex together with its shift. Note that $g_j : E \to E$ restricts to zero on $U$. Choose a distinguished triangle $$E \xrightarrow{g_1} E \to C_1 \to E[1]$$ By Derived Categories, Lemma Splitting an exact triangle the object $C_1$ restricts to $F \oplus F[1] \oplus F[1] \oplus F[2]$ on $U$. Moreover, $g_1 : C_1 \to C_1$ has square zero by Derived Categories, Lemma Nilpotent thickenings. Namely, the diagram $$\begin{gathered}\begin{matrix}E & C_1 & E[1] \\ E & C_1 & E[1]\end{matrix} \\[6pt] \begin{aligned}E & \longrightarrow C_1 \\ E & \xrightarrow{0} E \\ C_1 & \xrightarrow{g_1} C_1 \\ C_1 & \longrightarrow E[1] \\ E[1] & \xrightarrow{0} E[1] \\ E & \longrightarrow C_1 \\ C_1 & \longrightarrow E[1]\end{aligned}\end{gathered}$$ is commutative since the compositions $E \xrightarrow{g_1} E \to C_1$ and $C_1 \to E[1] \xrightarrow{g_1} E[1]$ are zero. Continuing, setting $C_{i + 1}$ equal to the cone of the map $g_{i + 1} : C_i \to C_i$ we obtain a perfect complex $C_s$ on $X$ supported on $T$ whose restriction to $U$ gives $$\bigoplus_{j=0}^{s+1} F[j]^{\oplus {s+1 \choose j}}$$ Choose morphisms of perfect complexes $\beta : C' \to C_s$ and $\gamma : C' \to C_s$ as in Lemma Extending a morphism after finite denominators are cleared such that $\beta|_U$ is an isomorphism and such that $\gamma|_U \circ \beta|_U^{-1}$ is the morphism $$\bigoplus_{j=0}^{s+1} F[j]^{\oplus {s+1 \choose j}} \to \bigoplus_{j=0}^{s+1} F[j]^{\oplus {s+1 \choose j}}$$ which is the identity on all summands except for $F$ where it is zero. By Lemma Extending a morphism after finite denominators are cleared we also have $C' = C_s \otimes^\mathbf{L} I$ for some perfect complex $I$ on $X$. Hence the nullity of $g_j^2\text{id}_{C_s}$ implies the same thing for $C'$. Thus $C'$ is supported on $T$ as well. Then $\text{Cone}(\gamma)$ is a solution. $\square$
Lemma. Lifting maps from support-preserving perfect complexes
Let $X$ be a quasi-compact and quasi-separated scheme. Let $U \subset X$ be a quasi-compact open. Let $T \subset X$ be a closed subset with $X \setminus T$ retro-compact in $X$. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Let $\alpha : P \to E|_U$ be a map where $P$ is a perfect object of $D(\mathcal{O}_U)$ supported on $T \cap U$. Then there exists a map $\beta : R \to E$ where $R$ is a perfect object of $D(\mathcal{O}_X)$ supported on $T$ such that $P$ is a direct summand of $R|_U$ in $D(\mathcal{O}_U)$ compatible $\alpha$ and $\beta|_U$.
Proof. Since $X$ is quasi-compact there exists an integer $m$ such that $X = U \cup V_1 \cup \ldots \cup V_m$ for some affine opens $V_j$ of $X$. Arguing by induction on $m$ we see that we may assume $m = 1$. In other words, we may assume that $X = U \cup V$ with $V$ affine. By Lemma Lifting perfect complexes while retaining support we can choose a perfect object $Q$ in $D(\mathcal{O}_V)$ supported on $T \cap V$ and an isomorphism $Q|_{U \cap V} \to (P \oplus P[1])|_{U \cap V}$. By Lemma Extending a morphism after finite denominators are cleared we can replace $Q$ by $Q \otimes^\mathbf{L} I$ (still supported on $T \cap V$) and assume that the map $$Q|_{U \cap V} \to (P \oplus P[1])|_{U \cap V} \longrightarrow P|_{U \cap V} \longrightarrow E|_{U \cap V}$$ lifts to $Q \to E|_V$. By Cohomology, Lemma Derived gluing across an elementary distinguished square we find an morphism $a : R \to E$ of $D(\mathcal{O}_X)$ such that $a|_U$ is isomorphic to $P \oplus P[1] \to E|_U$ and $a|_V$ isomorphic to $Q \to E|_V$. Thus $R$ is perfect and supported on $T$ as desired. $\square$
Lemma. Perfect approximation on an affine chart
Let $X$ be an affine scheme. Then approximation holds for every triple $(T, E, m)$ as in Definition Bounds for perfect approximation such that there exists an integer $r \geq 0$ with
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$E$ is $m$-pseudo-coherent,
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$H^i(E)$ is supported on $T$ for $i \geq m - r + 1$,
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$X \setminus T$ is the union of $r$ affine opens.
In particular, approximation by perfect complexes holds for affine schemes.
Proof. Say $X = \operatorname{Spec}(A)$. Write $T = V(f_1, \ldots, f_r)$. (The case $r = 0$, i.e., $T = X$ follows immediately from Lemma Pseudo-coherent complexes on an affine scheme and the definitions.) Let $(T, E, m)$ be a triple as in the lemma. Let $t$ be the largest integer such that $H^t(E)$ is nonzero. We will proceed by induction on $t$. The base case is $t < m$; in this case the result is trivial. Now suppose that $t \geq m$. By Cohomology, Lemma Finiteness of cohomology groups the sheaf $H^t(E)$ is of finite type. Since it is quasi-coherent it is generated by finitely many sections (Properties, Lemma Modules and finite algebras). For every $s \in \Gamma(X, H^t(E)) = H^t(X, E)$ (see proof of Lemma Bounded comparison of affine derived categories) we can find an $e > 0$ and a morphism $K_e[-t] \to E$ such that $s$ is in the image of $H^0(K_e) = H^t(K_e[-t]) \to H^t(E)$, see Lemma Koszul representatives with closed support. Taking a finite direct sum of these maps we obtain a map $P \to E$ where $P$ is a perfect complex supported on $T$, where $H^i(P) = 0$ for $i > t$, and where $H^t(P) \to E$ is surjective. Choose a distinguished triangle $$P \to E \to E' \to P[1]$$ Then $E'$ is $m$-pseudo-coherent (Cohomology, Lemma Pseudo-coherent complexes and coherent sheaves), $H^i(E') = 0$ for $i \geq t$, and $H^i(E')$ is supported on $T$ for $i \geq m - r + 1$. By induction we find an approximation $P' \to E'$ of $(T, E', m)$. Fit the composition $P' \to E' \to P[1]$ into a distinguished triangle $P \to P'' \to P' \to P[1]$ and extend the morphisms $P' \to E'$ and $P[1] \to P[1]$ into a morphism of distinguished triangles $$\begin{gathered}\begin{matrix}P & P'' & P' & P[1] \\ P & E & E' & P[1]\end{matrix} \\[6pt] \begin{aligned}P & \longrightarrow P'' \\ P & \longrightarrow P \\ P'' & \longrightarrow E \\ P'' & \longrightarrow P' \\ P' & \longrightarrow E' \\ P' & \longrightarrow P[1] \\ P[1] & \longrightarrow P[1] \\ P & \longrightarrow E \\ E & \longrightarrow E' \\ E' & \longrightarrow P[1]\end{aligned}\end{gathered}$$ using TR3. Then $P''$ is a perfect complex (Cohomology, Lemma Perfect complexes) supported on $T$. An easy diagram chase shows that $P'' \to E$ is the desired approximation. $\square$
A.12.3 Proper coherent cohomology for algebraic spaces
The following arguments adapt the human Stacks Project treatment in spaces-cohomology.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. The weak Chow lemma for algebraic spaces
Let $A$ be a ring. Let $X$ be an algebraic space over $\operatorname{Spec}(A)$ whose structure morphism $X \to \operatorname{Spec}(A)$ is separated of finite type. Then there exists a proper surjective morphism $X' \to X$ where $X'$ is a scheme which is H-quasi-projective over $\operatorname{Spec}(A)$.
Proof. Let $W$ be an affine scheme and let $f : W \to X$ be a surjective étale morphism. There exists an integer $d$ such that all geometric fibres of f have $\leq d$ points (because $X$ is a separated algebraic hence reasonable, see Decent Spaces, Lemma Schematic neighbourhoods). Picking $d$ minimal we get a nonempty open $U \subset X$ such that $f^{-1}(U) \to U$ is finite étale of degree $d$, see Decent Spaces, Lemma Schematic neighbourhoods. Let $$V \subset W \times_X W \times_X \ldots \times_X W$$ ($d$ factors in the fibre product) be the complement of all the diagonals. Because $W \to X$ is separated the diagonal $W \to W \times_X W$ is a closed immersion. Since $W \to X$ is étale the diagonal $W \to W \times_X W$ is an open immersion, see Morphisms of Spaces, Lemmas Étale morphisms and unramified morphisms and Unramified morphisms and diagonals and separation. Hence the diagonals are open and closed subschemes of the quasi-compact scheme $W \times_X \ldots \times_X W$. In particular we conclude $V$ is a quasi-compact scheme. Choose an open immersion $W \subset Y$ with $Y$ H-projective over $A$ (this is possible as $W$ is affine and of finite type over $A$; for example we can use Morphisms, Lemmas Affine neighbourhoods and finite algebras (uncovered prerequisite) and Projective and locally free modules (uncovered prerequisite)). Let $$Z \subset Y \times_A Y \times_A \ldots \times_A Y$$ be the scheme theoretic image of the composition $V \to W \times_X \ldots \times_X W \to Y \times_A \ldots \times_A Y$. Observe that this morphism is quasi-compact since $V$ is quasi-compact and $Y \times_A \ldots \times_A Y$ is separated. Note that $V \to Z$ is an open immersion as $V \to Y \times_A \ldots \times_A Y$ is an immersion, see Morphisms, Lemma Diagonals and separation (uncovered prerequisite). The projection morphisms give $d$ morphisms $g_i : Z \to Y$. These morphisms $g_i$ are projective as $Y$ is projective over $A$, see material in Morphisms, Section Projective and locally free modules. We set $$X' = \bigcup g_i^{-1}(W) \subset Z$$ There is a morphism $X' \to X$ whose restriction to $g_i^{-1}(W)$ is the composition $g_i^{-1}(W) \to W \to X$. Namely, these morphisms agree over $V$ hence agree over $g_i^{-1}(W) \cap g_j^{-1}(W)$ by Morphisms of Spaces, Lemma Morphisms of algebraic spaces. Claim: the morphism $X' \to X$ is proper.
If the claim holds, then the lemma follows by induction on $d$. Namely, by construction $X'$ is H-quasi-projective over $\operatorname{Spec}(A)$. The image of $X' \to X$ contains the open $U$ as $V$ surjects onto $U$. Denote $T$ the reduced induced algebraic space structure on $X \setminus U$. Then $T \times_X W$ is a closed subscheme of $W$, hence affine. Moreover, the morphism $T \times_X W \to T$ is étale and every geometric fibre has $< d$ points. By induction hypothesis there exists a proper surjective morphism $T' \to T$ where $T'$ is a scheme H-quasi-projective over $\operatorname{Spec}(A)$. Since $T$ is a closed subspace of $X$ we see that $T' \to X$ is a proper morphism. Thus the lemma follows by taking the proper surjective morphism $X' \amalg T' \to X$.
Proof of the claim. By construction the morphism $X' \to X$ is separated and of finite type. We will check conditions (1) -- (4) of Morphisms of Spaces, Lemma Morphisms of algebraic spaces for the morphisms $V \to X'$ and $X' \to X$. Conditions (1) and (2) we have seen above. Condition (3) holds as $X' \to X$ is separated (as a morphism whose source is a separated algebraic space). Thus it suffices to check liftability to $X'$ for diagrams $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & V \\ \operatorname{Spec}(R) & X\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \longrightarrow V \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(R) \\ V & \longrightarrow X \\ \operatorname{Spec}(R) & \longrightarrow X\end{aligned}\end{gathered}$$ where $R$ is a valuation ring with fraction field $K$. Note that the top horizontal map is given by $d$ pairwise distinct $K$-valued points $w_1, \ldots, w_d$ of $W$. In fact, this is a complete set of inverse images of the point $x \in X(K)$ coming from the diagram. Since $W \to X$ is surjective, we can, after possibly replacing $R$ by an extension of valuation rings, lift the morphism $\operatorname{Spec}(R) \to X$ to a morphism $w : \operatorname{Spec}(R) \to W$, see Morphisms of Spaces, Lemma Lifting flatness. Since $w_1, \ldots, w_d$ is a complete collection of inverse images of $x$ we see that $w|_{\operatorname{Spec}(K)}$ is equal to one of them, say $w_i$. Thus we see that we get a commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & Z \\ \operatorname{Spec}(R) & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \longrightarrow Z \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(R) \\ Z & \xrightarrow{g_i} Y \\ \operatorname{Spec}(R) & \xrightarrow{w} Y\end{aligned}\end{gathered}$$ By the valuative criterion of properness for the projective morphism $g_i$ we can lift $w$ to $z : \operatorname{Spec}(R) \to Z$, see Morphisms, Lemma Projective, locally free modules and proper morphisms (uncovered prerequisite) and Schemes, Proposition Criteria for the geometric construction (uncovered prerequisite). The image of $z$ is in $g_i^{-1}(W) \subset X'$ and the proof is complete. $\square$
Lemma. Sheaf cohomology and proper morphisms
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{P}$ be a property of coherent sheaves on $X$. Assume
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For any short exact sequence of coherent sheaves on $X$ if two out of three have property $\mathcal{P}$ so does the third.
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If $\mathcal{P}$ holds for $\mathcal{F}^{\oplus r}$ for some $r \geq 1$, then it holds for $\mathcal{F}$.
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For every reduced closed subspace $i : Z \to X$ with $|Z|$ irreducible there exists a coherent sheaf $\mathcal{G}$ on $X$ whose scheme theoretic support is $Z$ such that $\mathcal{P}$ holds for $\mathcal{G}$.
Then property $\mathcal{P}$ holds for every coherent sheaf on $X$.
Proof. We will show that conditions (1) and (2) of Lemma The initial cohomological property hold. This is clear for condition (1). To show that (2) holds, let $$\mathcal{T} = \left\{ \begin{matrix} i : Z \to X \text{ reduced closed subspace with }|Z|\text{ irreducible such}\\ \text{ that }i_*\mathcal{I}\text{ does not have }\mathcal{P} \text{ for some quasi-coherent }\mathcal{I} \subset \mathcal{O}_Z \end{matrix} \right\}$$ If $\mathcal{T}$ is nonempty, then since $X$ is Noetherian, we can find an $i : Z \to X$ which is minimal in $\mathcal{T}$. We will show that this leads to a contradiction.
Let $\mathcal{G}$ be the sheaf whose scheme theoretic support is $Z$ whose existence is assumed in assumption (3). Let $\varphi : i_*\mathcal{I}^{\oplus r} \to \mathcal{G}$ be as in Lemma Filtering a coherent sheaf by irreducible supports. Let $$0 = \mathcal{F}_0 \subset \mathcal{F}_1 \subset \ldots \subset \mathcal{F}_m = \operatorname{Coker}(\varphi)$$ be a filtration as in Lemma Coherent sheaves. By minimality of $Z$ and assumption (1) we see that $\operatorname{Coker}(\varphi)$ has property $\mathcal{P}$. As $\varphi$ is injective we conclude using assumption (1) once more that $i_*\mathcal{I}^{\oplus r}$ has property $\mathcal{P}$. Using assumption (2) we conclude that $i_*\mathcal{I}$ has property $\mathcal{P}$.
Finally, if $\mathcal{J} \subset \mathcal{O}_Z$ is a second quasi-coherent sheaf of ideals, set $\mathcal{K} = \mathcal{I} \cap \mathcal{J}$ and consider the short exact sequences $$0 \to \mathcal{K} \to \mathcal{I} \to \mathcal{I}/\mathcal{K} \to 0 \quad \text{and} \quad 0 \to \mathcal{K} \to \mathcal{J} \to \mathcal{J}/\mathcal{K} \to 0$$ Arguing as above, using the minimality of $Z$, we see that $i_*\mathcal{I}/\mathcal{K}$ and $i_*\mathcal{J}/\mathcal{K}$ satisfy $\mathcal{P}$. Hence by assumption (1) we conclude that $i_*\mathcal{K}$ and then $i_*\mathcal{J}$ satisfy $\mathcal{P}$. In other words, $Z$ is not an element of $\mathcal{T}$ which is the desired contradiction. $\square$
Lemma. Proper coherent direct images for algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a proper morphism of algebraic spaces over $S$ with $Y$ locally Noetherian. Let $\mathcal{F}$ be a coherent $\mathcal{O}_X$-module. Then $R^if_*\mathcal{F}$ is a coherent $\mathcal{O}_Y$-module for all $i \geq 0$.
Proof. We first remark that $X$ is a locally Noetherian algebraic space by Morphisms of Spaces, Lemma Noetherian rings and finite algebras. Hence the statement of the lemma makes sense. Moreover, computing $R^if_*\mathcal{F}$ commutes with étale localization on $Y$ (Properties of Spaces, Lemma Base change for étale morphisms and modules) and checking whether $R^if_*\mathcal{F}$ coherent can be done étale locally on $Y$ (Lemma Coherent sheaves and Noetherian rings). Hence we may assume that $Y = \operatorname{Spec}(A)$ is a Noetherian affine scheme.
Assume $Y = \operatorname{Spec}(A)$ is an affine scheme. Note that $f$ is locally of finite presentation (Morphisms of Spaces, Lemma Finite presentation and Noetherian rings). Thus it is of finite presentation, hence $X$ is Noetherian (Morphisms of Spaces, Lemma Finite presentation and Noetherian rings). Thus Lemma Sheaf cohomology and proper morphisms applies to the category of coherent modules of $X$. For a coherent sheaf $\mathcal{F}$ on $X$ we say $\mathcal{P}$ holds if and only if $R^if_*\mathcal{F}$ is a coherent module on $\operatorname{Spec}(A)$. We will show that conditions (1), (2), and (3) of Lemma Sheaf cohomology and proper morphisms hold for this property thereby finishing the proof of the lemma.
Verification of condition (1). Let $$0 \to \mathcal{F}_1 \to \mathcal{F}_2 \to \mathcal{F}_3 \to 0$$ be a short exact sequence of coherent sheaves on $X$. Consider the long exact sequence of higher direct images $$R^{p - 1}f_*\mathcal{F}_3 \to R^pf_*\mathcal{F}_1 \to R^pf_*\mathcal{F}_2 \to R^pf_*\mathcal{F}_3 \to R^{p + 1}f_*\mathcal{F}_1$$ Then it is clear that if 2-out-of-3 of the sheaves $\mathcal{F}_i$ have property $\mathcal{P}$, then the higher direct images of the third are sandwiched in this exact complex between two coherent sheaves. Hence these higher direct images are also coherent by Lemmas Coherent sheaves and Noetherian rings and Quasi-coherent complexes and coherent sheaves. Hence property $\mathcal{P}$ holds for the third as well.
Verification of condition (2). This follows immediately from the fact that $R^if_*(\mathcal{F}_1 \oplus \mathcal{F}_2) = R^if_*\mathcal{F}_1 \oplus R^if_*\mathcal{F}_2$ and that a summand of a coherent module is coherent (see lemmas cited above).
Verification of condition (3). Let $i : Z \to X$ be a closed immersion with $Z$ reduced and $|Z|$ irreducible. Set $g = f \circ i : Z \to \operatorname{Spec}(A)$. Let $\mathcal{G}$ be a coherent module on $Z$ whose scheme theoretic support is equal to $Z$ such that $R^pg_*\mathcal{G}$ is coherent for all $p$. Then $\mathcal{F} = i_*\mathcal{G}$ is a coherent module on $X$ whose scheme theoretic support is $Z$ such that $R^pf_*\mathcal{F} = R^pg_*\mathcal{G}$. To see this use the Leray spectral sequence (Cohomology on Sites, Lemma Sheaf cohomology) and the fact that $R^qi_*\mathcal{G} = 0$ for $q > 0$ by Lemma Affine neighbourhoods and the fact that a closed immersion is affine. (Morphisms of Spaces, Lemma Diagonals, separation and affine neighbourhoods). Thus we reduce to finding a coherent sheaf $\mathcal{G}$ on $Z$ with support equal to $Z$ such that $R^pg_*\mathcal{G}$ is coherent for all $p$.
We apply Lemma The weak Chow lemma for algebraic spaces to the morphism $Z \to \operatorname{Spec}(A)$. Thus we get a diagram $$\begin{gathered}\begin{matrix}Z & Z' & \mathbf{P}^n_A \\ \phantom{X} & \operatorname{Spec}(A) & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}Z & \xrightarrow{g} \operatorname{Spec}(A) \\ Z' & \xrightarrow{g'} \operatorname{Spec}(A) \\ Z' & \xrightarrow{\pi} Z \\ Z' & \xrightarrow{i} \mathbf{P}^n_A \\ \mathbf{P}^n_A & \longrightarrow \operatorname{Spec}(A)\end{aligned}\end{gathered}$$ with $\pi : Z' \to Z$ proper surjective and $i$ an immersion. Since $Z \to \operatorname{Spec}(A)$ is proper we conclude that $g'$ is proper (Morphisms of Spaces, Lemma Composition and proper morphisms). Hence $i$ is a closed immersion (Morphisms of Spaces, Lemmas Morphisms of algebraic spaces and Diagonals and separation). It follows that the morphism $i' = (i, \pi) : \mathbf{P}^n_A \times_{\operatorname{Spec}(A)} Z' = \mathbf{P}^n_Z$ is a closed immersion (Morphisms of Spaces, Lemma Diagonals and separation). Set $$\mathcal{L} = i^*\mathcal{O}_{\mathbf{P}^n_A}(1) = (i')^*\mathcal{O}_{\mathbf{P}^n_Z}(1)$$ We may apply Lemma Quasi-coherent cohomology to $\mathcal{L}$ and $\pi$ as well as $\mathcal{L}$ and $g'$. Hence for all $d \gg 0$ we have $R^p\pi_*\mathcal{L}^{\otimes d} = 0$ for all $p > 0$ and $R^p(g')_*\mathcal{L}^{\otimes d} = 0$ for all $p > 0$. Set $\mathcal{G} = \pi_*\mathcal{L}^{\otimes d}$. By the Leray spectral sequence (Cohomology on Sites, Lemma Sheaf cohomology) we have $$E_2^{p, q} = R^pg_* R^q\pi_*\mathcal{L}^{\otimes d} \Rightarrow R^{p + q}(g')_*\mathcal{L}^{\otimes d}$$ and by choice of $d$ the only nonzero terms in $E_2^{p, q}$ are those with $q = 0$ and the only nonzero terms of $R^{p + q}(g')_*\mathcal{L}^{\otimes d}$ are those with $p = q = 0$. This implies that $R^pg_*\mathcal{G} = 0$ for $p > 0$ and that $g_*\mathcal{G} = (g')_*\mathcal{L}^{\otimes d}$. Applying Cohomology of Schemes, Lemma Projective, locally free modules and local algebra (uncovered prerequisite) we see that $g_*\mathcal{G} = (g')_*\mathcal{L}^{\otimes d}$ is coherent.
We still have to check that the support of $\mathcal{G}$ is $Z$. This follows from the fact that $\mathcal{L}^{\otimes d}$ has lots of global sections. We spell it out here. Note that $\mathcal{L}^{\otimes d}$ is globally generated for all $d \geq 0$ because the same is true for $\mathcal{O}_{\mathbf{P}^n}(d)$. Pick a point $z \in Z'$ mapping to the generic point $\xi$ of $Z$ which we can do as $\pi$ is surjective. (Observe that $Z$ does indeed have a generic point as $|Z|$ is irreducible and $Z$ is Noetherian, hence quasi-separated, hence $|Z|$ is a sober topological space by Properties of Spaces, Lemma Diagonals and separation.) Pick $s \in \Gamma(Z', \mathcal{L}^{\otimes d})$ which does not vanish at $z$. Since $\Gamma(Z, \mathcal{G}) = \Gamma(Z', \mathcal{L}^{\otimes d})$ we may think of $s$ as a global section of $\mathcal{G}$. Choose a geometric point $\overline{z}$ of $Z'$ lying over $z$ and denote $\overline{\xi} = g' \circ \overline{z}$ the corresponding geometric point of $Z$. The adjunction map $$(g')^*\mathcal{G} = (g')^*g'_*\mathcal{L}^{\otimes d} \longrightarrow \mathcal{L}^{\otimes d}$$ induces a map of stalks $\mathcal{G}_{\overline{\xi}} \to \mathcal{L}_{\overline{z}}$, see Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. Moreover the adjunction map sends the pullback of $s$ (viewed as a section of $\mathcal{G}$) to $s$ (viewed as a section of $\mathcal{L}^{\otimes d}$). Thus the image of $s$ in the vector space which is the source of the arrow $$\mathcal{G}_{\overline{\xi}} \otimes \kappa(\overline{\xi}) \longrightarrow \mathcal{L}^{\otimes d}_{\overline{z}} \otimes \kappa(\overline{z})$$ isn't zero since by choice of $s$ the image in the target of the arrow is nonzero. Hence $\xi$ is in the support of $\mathcal{G}$ (Morphisms of Spaces, Lemma Closed support and finite algebras). Since $|Z|$ is irreducible and $Z$ is reduced we conclude that the scheme theoretic support of $\mathcal{G}$ is all of $Z$ as desired. $\square$
A.12.4 Étale gluing, direct images and perfect approximation
The following arguments adapt the human Stacks Project treatment in spaces-perfect.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $(K_n)$ be an inverse system of $D_\mathrm{QCoh}(\mathcal{O}_X)$ with derived limit $K = R\varprojlim K_n$ in $D(\mathcal{O}_X)$. Assume $H^q(K_{n + 1}) \to H^q(K_n)$ is surjective for all $q \in \mathbf{Z}$ and $n \geq 1$. Then
-
$H^q(K) = \varprojlim H^q(K_n)$,
-
$R\varprojlim H^q(K_n) = \varprojlim H^q(K_n)$, and
-
for every affine open $U \subset X$ we have $H^p(U, \varprojlim H^q(K_n)) = 0$ for $p > 0$.
Proof. Let $\mathcal{B} \subset \operatorname{Ob}(X_\mathrm{\acute{e}tale})$ be the set of affine objects. Since $H^q(K_n)$ is quasi-coherent we have $H^p(U, H^q(K_n)) = 0$ for $U \in \mathcal{B}$ by the discussion in Cohomology of Spaces, Section Quasi-coherent cohomology and Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). Moreover, the maps $H^0(U, H^q(K_{n + 1})) \to H^0(U, H^q(K_n))$ are surjective for $U \in \mathcal{B}$ by similar reasoning. Part (1) follows from Cohomology on Sites, Lemma Derived categories whose conditions we have just verified. Parts (2) and (3) follow from Cohomology on Sites, Lemma Derived categories. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : Y \to X$ be a morphism of algebraic spaces over $S$. The functor $Lf^*$ sends $D_\mathrm{QCoh}(\mathcal{O}_X)$ into $D_\mathrm{QCoh}(\mathcal{O}_Y)$.
Proof. Choose a diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{a} X \\ U & \xrightarrow{h} V \\ V & \xrightarrow{b} Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes, the vertical arrows are étale, and $a$ is surjective. Since $a^* \circ Lf^* = Lh^* \circ b^*$ the result follows from Lemma Quasi-coherent complexes and coherent sheaves and the case of schemes which is Derived Categories of Schemes, Lemma Quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-separated and quasi-compact morphism of algebraic spaces over $S$.
-
The functor $Rf_*$ sends $D_\mathrm{QCoh}(\mathcal{O}_X)$ into $D_\mathrm{QCoh}(\mathcal{O}_Y)$.
-
If $Y$ is quasi-compact, there exists an integer $N = N(X, Y, f)$ such that for an object $E$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ with $H^m(E) = 0$ for $m > 0$ we have $H^m(Rf_*E) = 0$ for $m \geq N$.
-
In fact, if $Y$ is quasi-compact we can find $N = N(X, Y, f)$ such that for every morphism of algebraic spaces $Y' \to Y$ the same conclusion holds for the functor $R(f')_*$ where $f' : X' \to Y'$ is the base change of $f$.
Proof. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. To prove (1) we have to show that $Rf_*E$ has quasi-coherent cohomology sheaves. This question is local on $Y$, hence we may assume $Y$ is quasi-compact. Pick $N = N(X, Y, f)$ as in Cohomology of Spaces, Lemma Vanishing and quasi-coherent cohomology. Thus $R^pf_*\mathcal{F} = 0$ for all quasi-coherent $\mathcal{O}_X$-modules $\mathcal{F}$ and all $p \geq N$. Moreover $R^pf_*\mathcal{F}$ is quasi-coherent for all $p$ by Cohomology of Spaces, Lemma Quasi-coherent cohomology. These statements remain true after base change.
First, assume $E$ is bounded below. We will show (1) and (2) and (3) hold for such $E$ with our choice of $N$. In this case we can for example use the spectral sequence $$R^pf_*H^q(E) \Rightarrow R^{p + q}f_*E$$ (Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories), the quasi-coherence of $R^pf_*H^q(E)$, and the vanishing of $R^pf_*H^q(E)$ for $p \geq N$ to see that (1), (2), and (3) hold in this case.
Next we prove (2) and (3). Say $H^m(E) = 0$ for $m > 0$. Let $V$ be an affine object of $Y_\mathrm{\acute{e}tale}$. We have $H^p(V \times_Y X, \mathcal{F}) = 0$ for $p \geq N$, see Cohomology of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. Hence we may apply Lemma Computing derived Hom with a quasi-coherent K-injective model to the functor $\Gamma(V \times_Y X, -)$ to see that $$R\Gamma(V, Rf_*E) = R\Gamma(V \times_Y X, E)$$ has vanishing cohomology in degrees $\geq N$. Since this holds for all $V$ affine in $Y_\mathrm{\acute{e}tale}$ we conclude that $H^m(Rf_*E) = 0$ for $m \geq N$.
Next, we prove (1) in the general case. Recall that there is a distinguished triangle $$\tau_{\leq -n - 1}E \to E \to \tau_{\geq -n}E \to (\tau_{\leq -n - 1}E)[1]$$ in $D(\mathcal{O}_X)$, see Derived Categories, Remark Derived categories. By (2) we see that $Rf_*\tau_{\leq -n - 1}E$ has vanishing cohomology sheaves in degrees $\geq -n + N$. Thus, given an integer $q$ we see that $R^qf_*E$ is equal to $R^qf_*\tau_{\geq -n}E$ for some $n$ and the result above applies. $\square$
Lemma. Proper morphisms and closed support
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume $f$ is locally of finite type and $Y$ locally Noetherian. Let $\mathcal{F}$ be a coherent $\mathcal{O}_X$-module with support proper over $Y$. Then $R^pf_*\mathcal{F}$ is a coherent $\mathcal{O}_Y$-module for all $p \geq 0$.
Proof. By Lemma Proper morphisms and modules there exists a closed immersion $i : Z \to X$ with $g = f \circ i : Z \to Y$ proper and $\mathcal{F} = i_*\mathcal{G}$ for some coherent module $\mathcal{G}$ on $Z$. We see that $R^pg_*\mathcal{G}$ is coherent on $S$ by Cohomology of Spaces, Lemma Proper coherent direct images for algebraic spaces. On the other hand, $R^qi_*\mathcal{G} = 0$ for $q > 0$ (Cohomology of Spaces, Lemma Coherent sheaves and finite algebras). By Cohomology on Sites, Lemma Sheaf cohomology we get $R^pf_*\mathcal{F} = R^pg_*\mathcal{G}$ and the lemma follows. $\square$
Lemma. Direct images and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume $f$ is locally of finite type and $Y$ is Noetherian. Let $E$ be an object of $D^b_{\textit{Coh}}(\mathcal{O}_X)$ such that the support of $H^i(E)$ is proper over $Y$ for all $i$. Then $Rf_*E$ is an object of $D^b_{\textit{Coh}}(\mathcal{O}_Y)$.
Proof. Consider the spectral sequence $$R^pf_*H^q(E) \Rightarrow R^{p + q}f_*E$$ see Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories. By assumption and Lemma Proper morphisms and closed support the sheaves $R^pf_*H^q(E)$ are coherent. Hence $R^{p + q}f_*E$ is coherent, i.e., $E \in D_{\textit{Coh}}(\mathcal{O}_Y)$. Boundedness from below is trivial. Boundedness from above follows from Cohomology of Spaces, Lemma Vanishing and quasi-coherent cohomology or from Lemma Quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Induction by elementary distinguished squares
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $P$ be a property of the quasi-compact and quasi-separated objects of $X_{spaces, \mathrm{\acute{e}tale}}$. Assume that
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$P$ holds for every affine object of $X_{spaces, \mathrm{\acute{e}tale}}$,
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for every elementary distinguished square $(U \subset W, f : V \to W)$ such that
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$W$ is a quasi-compact and quasi-separated object of $X_{spaces, \mathrm{\acute{e}tale}}$,
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$U$ is quasi-compact,
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$V$ is affine, and
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$P$ holds for $U$, $V$, and $U \times_W V$,
then $P$ holds for $W$.
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Then $P$ holds for every quasi-compact and quasi-separated object of $X_{spaces, \mathrm{\acute{e}tale}}$ and in particular for $X$.
Proof. We first claim that $P$ holds for every representable quasi-compact and quasi-separated object of $X_{spaces, \mathrm{\acute{e}tale}}$. Namely, suppose that $U \to X$ is étale and $U$ is a quasi-compact and quasi-separated scheme. By assumption (1) property $P$ holds for every affine open of $U$. Moreover, if $W, V \subset U$ are quasi-compact open with $V$ affine and $P$ holds for $W$, $V$, and $W \cap V$, then $P$ holds for $W \cup V$ by (2) (as the pair $(W \subset W \cup V, V \to W \cup V)$ is an elementary distinguished square). Thus $P$ holds for $U$ by the induction principle for schemes, see Cohomology of Schemes, Lemma Induction by elementary distinguished squares (uncovered prerequisite).
To finish the proof it suffices to prove $P$ holds for $X$ (because we can simply replace $X$ by any quasi-compact and quasi-separated object of $X_{spaces, \mathrm{\acute{e}tale}}$ we want to prove the result for). We will use the filtration $$\emptyset = U_{n + 1} \subset U_n \subset U_{n - 1} \subset \ldots \subset U_1 = X$$ and the morphisms $f_p : V_p \to U_p$ of Decent Spaces, Lemma Diagonals and separation. We will prove that $P$ holds for $U_p$ by descending induction on $p$. Note that $P$ holds for $U_{n + 1}$ by (1) as an empty algebraic space is affine. Assume $P$ holds for $U_{p + 1}$. Note that $(U_{p + 1} \subset U_p, f_p : V_p \to U_p)$ is an elementary distinguished square, but (2) may not apply as $V_p$ may not be affine. However, as $V_p$ is a quasi-compact scheme we may choose a finite affine open covering $V_p = V_{p, 1} \cup \ldots \cup V_{p, m}$. Set $W_{p, 0} = U_{p + 1}$ and $$W_{p, i} = U_{p + 1} \cup f_p(V_{p, 1} \cup \ldots \cup V_{p, i})$$ for $i = 1, \ldots, m$. These are quasi-compact open subspaces of $X$. Then we have $$U_{p + 1} = W_{p, 0} \subset W_{p, 1} \subset \ldots \subset W_{p, m} = U_p$$ and the pairs $$(W_{p, 0} \subset W_{p, 1}, f_p|_{V_{p, 1}}), (W_{p, 1} \subset W_{p, 2}, f_p|_{V_{p, 2}}),\ldots, (W_{p, m - 1} \subset W_{p, m}, f_p|_{V_{p, m}})$$ are elementary distinguished squares by Lemma Derived quasi-coherent complexes. Note that $P$ holds for each $V_{p, i}$ (as affine schemes) and for $W_{p, i} \times_{W_{p, i + 1}} V_{p, i + 1}$ as this is a quasi-compact open of $V_{p, i + 1}$ and hence $P$ holds for it by the first paragraph of this proof. Thus (2) applies to each of these and we inductively conclude $P$ holds for $W_{p, 1}, \ldots, W_{p, m} = U_p$. $\square$
Lemma. Derived gluing across an elementary distinguished square
Let $S$ be a scheme. Let $(U \subset X, V \to X)$ be an elementary distinguished square of algebraic spaces over $S$. Suppose given
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an object $A$ of $D(\mathcal{O}_U)$,
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an object $B$ of $D(\mathcal{O}_V)$, and
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an isomorphism $c : A|_{U \times_X V} \to B|_{U \times_X V}$.
Then there exists an object $F$ of $D(\mathcal{O}_X)$ and isomorphisms $f : F|_U \to A$, $g : F|_V \to B$ such that $c = g|_{U \times_X V} \circ f^{-1}|_{U \times_X V}$. Moreover, given
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an object $E$ of $D(\mathcal{O}_X)$,
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a morphism $a : A \to E|_U$ of $D(\mathcal{O}_U)$,
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a morphism $b : B \to E|_V$ of $D(\mathcal{O}_V)$,
such that $$a|_{U \times_X V} = b|_{U \times_X V} \circ c.$$ Then there exists a morphism $F \to E$ in $D(\mathcal{O}_X)$ whose restriction to $U$ is $a \circ f$ and whose restriction to $V$ is $b \circ g$.
Proof. Denote $j_U$, $j_V$, $j_{U \times_X V}$ the corresponding morphisms towards $X$. Choose a distinguished triangle $$F \to Rj_{U, *}A \oplus Rj_{V, *}B \to Rj_{U \times_X V, *}(B|_{U \times_X V}) \to F[1]$$ Here the map $Rj_{V, *}B \to Rj_{U \times_X V, *}(B|_{U \times_X V})$ is the obvious one. The map $Rj_{U, *}A \to Rj_{U \times_X V, *}(B|_{U \times_X V})$ is the composition of $Rj_{U, *}A \to Rj_{U \times_X V, *}(A|_{U \times_X V})$ with $Rj_{U \times_X V, *}c$. Restricting to $U$ we obtain $$F|_U \to A \oplus (Rj_{V, *}B)|_U \to (Rj_{U \times_X V, *}(B|_{U \times_X V}))|_U \to F|_U[1]$$ Denote $j : U \times_X V \to U$. Compatibility of restriction and total direct image (Lemma Derived quasi-coherent complexes) shows that both $(Rj_{V, *}B)|_U$ and $(Rj_{U \times_X V, *}(B|_{U \times_X V}))|_U$ are canonically isomorphic to $Rj_*(B|_{U \times_X V})$. Hence the second arrow of the last displayed equation has a section, and we conclude that the morphism $F|_U \to A$ is an isomorphism.
To see that the morphism $F|_V \to B$ is an isomorphism we will use a trick. Namely, choose a distinguished triangle $$F|_V \to B \to B' \to F[1]|_V$$ in $D(\mathcal{O}_V)$. Since $F|_U \to A$ is an isomorphism, and since we have the isomorphism $c : A|_{U \times_X V} \to B|_{U \times_X V}$ the restriction of $F|_V \to B$ is an isomorphism over $U \times_X V$. Thus $B'$ is supported on $j_V^{-1}(T)$ where $T = |X| \setminus |U|$. On the other hand, there is a morphism of distinguished triangles $$\begin{gathered}\begin{matrix}F & Rj_{U, *}F|_U \oplus Rj_{V, *}F|_V & Rj_{U \times_X V, *}F|_{U \times_X V} & F[1] \\ F & Rj_{U, *}A \oplus Rj_{V, *}B & Rj_{U \times_X V, *}(B|_{U \times_X V}) & F[1]\end{matrix} \\[6pt] \begin{aligned}F & \longrightarrow Rj_{U, *}F|_U \oplus Rj_{V, *}F|_V \\ F & \longrightarrow F \\ Rj_{U, *}F|_U \oplus Rj_{V, *}F|_V & \longrightarrow Rj_{U \times_X V, *}F|_{U \times_X V} \\ Rj_{U, *}F|_U \oplus Rj_{V, *}F|_V & \longrightarrow Rj_{U, *}A \oplus Rj_{V, *}B \\ Rj_{U \times_X V, *}F|_{U \times_X V} & \longrightarrow F[1] \\ Rj_{U \times_X V, *}F|_{U \times_X V} & \longrightarrow Rj_{U \times_X V, *}(B|_{U \times_X V}) \\ F[1] & \longrightarrow F[1] \\ F & \longrightarrow Rj_{U, *}A \oplus Rj_{V, *}B \\ Rj_{U, *}A \oplus Rj_{V, *}B & \longrightarrow Rj_{U \times_X V, *}(B|_{U \times_X V}) \\ Rj_{U \times_X V, *}(B|_{U \times_X V}) & \longrightarrow F[1]\end{aligned}\end{gathered}$$ The all of the vertical maps in this diagram are isomorphisms, except for the map $Rj_{V, *}F|_V \to Rj_{V, *}B$, hence that is an isomorphism too (Derived Categories, Lemma Derived categories). This implies that $Rj_{V, *}B' = 0$. Hence $B' = 0$ by Lemma Direct images and closed support.
The existence of the morphism $F \to E$ follows from the Mayer-Vietoris sequence for $\operatorname{Hom}$, see Lemma Derived Hom and Ext. $\square$
Definition. Bounds for perfect approximation
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Consider triples $(T, E, m)$ where
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$T \subset |X|$ is a closed subset,
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$E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$, and
-
$m \in \mathbf{Z}$.
We say approximation holds for the triple $(T, E, m)$ if there exists a perfect object $P$ of $D(\mathcal{O}_X)$ supported on $T$ and a map $\alpha : P \to E$ which induces isomorphisms $H^i(P) \to H^i(E)$ for $i > m$ and a surjection $H^m(P) \to H^m(E)$.
Definition. Perfect approximation with prescribed cohomology
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. We say approximation by perfect complexes holds on $X$ if for any closed subset $T \subset |X|$ such that the morphism $X \setminus T \to X$ is quasi-compact there exists an integer $r$ such that for every triple $(T, E, m)$ as in Definition Bounds for perfect approximation with
-
$E$ is $(m - r)$-pseudo-coherent, and
-
$H^i(E)$ is supported on $T$ for $i \geq m - r$
approximation holds.
Lemma. Direct images and perfect complexes
Let $S$ be a scheme. Let $(U \subset X, j : V \to X)$ be an elementary distinguished square of algebraic space over $S$. Let $E$ be a perfect object of $D(\mathcal{O}_V)$ supported on $j^{-1}(T)$ where $T = |X| \setminus |U|$. Then $Rj_*E$ is a perfect object of $D(\mathcal{O}_X)$.
Proof. Being perfect is local on $X_\mathrm{\acute{e}tale}$. Thus it suffices to check that $Rj_*E$ is perfect when restricted to $U$ and $V$. We have $Rj_*E|_V = E$ by Lemma Direct images and closed support which is perfect. We have $Rj_*E|_U = 0$ because $E|_{V \setminus j^{-1}(T)} = 0$ (use Lemma Derived quasi-coherent complexes). $\square$
Lemma. Restriction to an open subspace
Let $S$ be a scheme. Let $(U \subset X, j : V \to X)$ be an elementary distinguished square of algebraic spaces over $S$. Let $T$ be a closed subset of $|X| \setminus |U|$ and let $(T, E, m)$ be a triple as in Definition Bounds for perfect approximation. If
-
approximation holds for $(j^{-1}T, E|_V, m)$, and
-
the sheaves $H^i(E)$ for $i \geq m$ are supported on $T$,
then approximation holds for $(T, E, m)$.
Proof. Let $P \to E|_V$ be an approximation of the triple $(j^{-1}T, E|_V, m)$ over $V$. Then $Rj_*P$ is a perfect object of $D(\mathcal{O}_X)$ by Lemma Direct images and perfect complexes. On the other hand, $Rj_*P = j_!P$ by Lemma Direct images and closed support. We see that $j_!P$ is supported on $T$ for example by (Sheaves on ringed sites). Hence we obtain an approximation $Rj_*P = j_!P \to j_!(E|_V) \to E$. $\square$
Lemma. Perfect approximation on an affine chart
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$ which is representable by an affine scheme. Then approximation holds for every triple $(T, E, m)$ as in Definition Bounds for perfect approximation such that there exists an integer $r \geq 0$ with
-
$E$ is $m$-pseudo-coherent,
-
$H^i(E)$ is supported on $T$ for $i \geq m - r + 1$,
-
$X \setminus T$ is the union of $r$ affine opens.
In particular, approximation by perfect complexes holds for affine schemes.
Proof. Let $X_0$ be an affine scheme representing $X$. Let $T_0 \subset X_0$ by the closed subset corresponding to $T$. Let $\epsilon : X_\mathrm{\acute{e}tale} \to X_{0, Zar}$ be the morphism (Derived quasi-coherent complexes). We may write $E = \epsilon^*E_0$ for some object $E_0$ of $D_\mathrm{QCoh}(\mathcal{O}_{X_0})$, see Lemma Étale morphisms and quasi-coherent complexes. Then $E_0$ is $m$-pseudo-coherent, see Lemma Descent of pseudo-coherent complexes and coherent sheaves. Comparing stalks of cohomology sheaves (see proof of Lemma Flatness) we see that $H^i(E_0)$ is supported on $T_0$ for $i \geq m - r + 1$. By Derived Categories of Schemes, Lemma Perfect approximation on an affine chart there exists an approximation $P_0 \to E_0$ of $(T_0, E_0, m)$. By Lemma Descent of perfect complexes we see that $P = \epsilon^*P_0$ is a perfect object of $D(\mathcal{O}_X)$. Pulling back we obtain an approximation $P = \epsilon^*P_0 \to \epsilon^*E_0 = E$ as desired. $\square$
Lemma. Extending perfect approximation across a distinguished square
Let $S$ be a scheme. Let $(U \subset X, j : V \to X)$ be an elementary distinguished square of algebraic spaces over $S$. Assume $U$ quasi-compact, $V$ affine, and $U \times_X V$ quasi-compact. If approximation by perfect complexes holds on $U$, then approximation by perfect complexes holds on $X$.
Proof. Let $T \subset |X|$ be a closed subset with $X \setminus T \to X$ quasi-compact. Let $r_U$ be the integer of Definition Perfect approximation with prescribed cohomology adapted to the pair $(U, T \cap |U|)$. Set $T' = T \setminus |U|$. Endow $T'$ with the induced reduced subspace structure. Since $|T'|$ is contained in $|X| \setminus |U|$ we see that $j^{-1}(T') \to T'$ is an isomorphism. Moreover, $V \setminus j^{-1}(T')$ is quasi-compact as it is the fibre product of $U \times_X V$ with $X \setminus T$ over $X$ and we've assumed $U \times_X V$ quasi-compact and $X \setminus T \to X$ quasi-compact. Let $r'$ be the number of affines needed to cover $V \setminus j^{-1}(T')$. We claim that $r = \max(r_U, r')$ works for the pair $(X, T)$.
To see this choose a triple $(T, E, m)$ such that $E$ is $(m - r)$-pseudo-coherent and $H^i(E)$ is supported on $T$ for $i \geq m - r$. Let $t$ be the largest integer such that $H^t(E)|_U$ is nonzero. (Such an integer exists as $U$ is quasi-compact and $E|_U$ is $(m - r)$-pseudo-coherent.) We will prove that $E$ can be approximated by induction on $t$.
Base case: $t \leq m - r'$. This means that $H^i(E)$ is supported on $T'$ for $i \geq m - r'$. Hence Lemma Perfect approximation on an affine chart guarantees the existence of an approximation $P \to E|_V$ of $(T', E|_V, m)$ on $V$. Applying Lemma Restriction to an open subspace we see that $(T', E, m)$ can be approximated. Such an approximation is also an approximation of $(T, E, m)$.
Induction step. Choose an approximation $P \to E|_U$ of $(T \cap |U|, E|_U, m)$. This in particular gives a surjection $H^t(P) \to H^t(E|_U)$. In the rest of the proof we will use the equivalence of Lemma Étale morphisms and quasi-coherent complexes (and the compatibilities of Remark Derived quasi-coherent complexes) for the representable algebraic spaces $V$ and $U \times_X V$. We will also use the fact that $(m - r)$-pseudo-coherence, resp. perfectness on the Zariski site and étale site agree, see Lemmas Descent of pseudo-coherent complexes and coherent sheaves and Descent of perfect complexes. Thus we can use the results of Derived Categories of Schemes, Section Lifting perfect complexes for the open immersion $U \times_X V \subset V$. In this way Derived Categories of Schemes, Lemma Lifting perfect complexes while retaining support implies there exists a perfect object $Q$ in $D(\mathcal{O}_V)$ supported on $j^{-1}(T)$ and an isomorphism $Q|_{U \times_X V} \to (P \oplus P[1])|_{U \times_X V}$. By Derived Categories of Schemes, Lemma Extending a morphism after finite denominators are cleared we can replace $Q$ by $Q \otimes^\mathbf{L} I$ and assume that the map $$Q|_{U \times_X V} \longrightarrow (P \oplus P[1])|_{U \times_X V} \longrightarrow P|_{U \times_X V} \longrightarrow E|_{U \times_X V}$$ lifts to $Q \to E|_V$. By Lemma Derived gluing across an elementary distinguished square we find an morphism $a : R \to E$ of $D(\mathcal{O}_X)$ such that $a|_U$ is isomorphic to $P \oplus P[1] \to E|_U$ and $a|_V$ isomorphic to $Q \to E|_V$. Thus $R$ is perfect and supported on $T$ and the map $H^t(R) \to H^t(E)$ is surjective on restriction to $U$. Choose a distinguished triangle $$R \to E \to E' \to R[1]$$ Then $E'$ is $(m - r)$-pseudo-coherent (Cohomology on Sites, Lemma Pseudo-coherent complexes and coherent sheaves), $H^i(E')|_U = 0$ for $i \geq t$, and $H^i(E')$ is supported on $T$ for $i \geq m - r$. By induction we find an approximation $R' \to E'$ of $(T, E', m)$. Fit the composition $R' \to E' \to R[1]$ into a distinguished triangle $R \to R'' \to R' \to R[1]$ and extend the morphisms $R' \to E'$ and $R[1] \to R[1]$ into a morphism of distinguished triangles $$\begin{gathered}\begin{matrix}R & R'' & R' & R[1] \\ R & E & E' & R[1]\end{matrix} \\[6pt] \begin{aligned}R & \longrightarrow R'' \\ R & \longrightarrow R \\ R'' & \longrightarrow E \\ R'' & \longrightarrow R' \\ R' & \longrightarrow E' \\ R' & \longrightarrow R[1] \\ R[1] & \longrightarrow R[1] \\ R & \longrightarrow E \\ E & \longrightarrow E' \\ E' & \longrightarrow R[1]\end{aligned}\end{gathered}$$ using TR3. Then $R''$ is a perfect complex (Cohomology on Sites, Lemma Perfect complexes) supported on $T$. An easy diagram chase shows that $R'' \to E$ is the desired approximation. $\square$
Theorem. Perfect approximation with prescribed closed support
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Then approximation by perfect complexes holds on $X$.
Proof. This follows from the induction principle of Lemma Induction by elementary distinguished squares and Lemmas Extending perfect approximation across a distinguished square and Perfect approximation on an affine chart. $\square$
Theorem. A perfect generator for a quasi-compact algebraic space
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. The category $D_\mathrm{QCoh}(\mathcal{O}_X)$ can be generated by a single perfect object. More precisely, there exists a perfect object $P$ of $D(\mathcal{O}_X)$ such that for $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$ the following are equivalent
-
$E = 0$, and
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$\operatorname{Hom}_{D(\mathcal{O}_X)}(P[n], E) = 0$ for all $n \in \mathbf{Z}$.
Proof. We will prove this using the induction principle of Lemma Induction by elementary distinguished squares.
If $X$ is affine, then $\mathcal{O}_X$ is a perfect generator. This follows from Lemma Étale morphisms and quasi-coherent complexes and Derived Categories of Schemes, Lemma Bounded comparison of affine derived categories.
Assume that $(U \subset X, f : V \to X)$ is an elementary distinguished square with $U$ quasi-compact such that the theorem holds for $U$ and $V$ is an affine scheme. Let $P$ be a perfect object of $D(\mathcal{O}_U)$ which is a generator for $D_\mathrm{QCoh}(\mathcal{O}_U)$. Using Lemma Tensor products and direct sums we may choose a perfect object $Q$ of $D(\mathcal{O}_X)$ whose restriction to $U$ is a direct sum one of whose summands is $P$. Say $V = \operatorname{Spec}(A)$. Let $Z \subset V$ be the reduced closed subscheme which is the inverse image of $X \setminus U$ and maps isomorphically to it (see Definition Derived quasi-coherent complexes). This is a retrocompact closed subset of $V$. Choose $f_1, \ldots, f_r \in A$ such that $Z = V(f_1, \ldots, f_r)$. Let $K \in D(\mathcal{O}_V)$ be the perfect object corresponding to the Koszul complex on $f_1, \ldots, f_r$ over $A$. Note that since $K$ is supported on $Z$, the pushforward $K' = Rf_*K$ is a perfect object of $D(\mathcal{O}_X)$ whose restriction to $V$ is $K$ (see Lemmas Direct images and perfect complexes and Direct images and closed support). We claim that $Q \oplus K'$ is a generator for $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ such that there are no nontrivial maps from any shift of $Q \oplus K'$ into $E$. By Lemma Direct images and closed support we have $K' = f_! K$ and hence $$\operatorname{Hom}_{D(\mathcal{O}_X)}(K'[n], E) = \operatorname{Hom}_{D(\mathcal{O}_V)}(K[n], E|_V)$$ Thus by Derived Categories of Schemes, Lemma Koszul complexes, regular sequences and derived categories (using also Lemma Étale morphisms and quasi-coherent complexes) the vanishing of these groups implies that $E|_V$ is isomorphic to $R(U \times_X V \to V)_*E|_{U \times_X V}$. This implies that $E = R(U \to X)_*E|_U$ (small detail omitted). If this is the case then $$\operatorname{Hom}_{D(\mathcal{O}_X)}(Q[n], E) = \operatorname{Hom}_{D(\mathcal{O}_U)}(Q|_U[n], E|_U)$$ which contains $\operatorname{Hom}_{D(\mathcal{O}_U)}(P[n], E|_U)$ as a direct summand. Thus by our choice of $P$ the vanishing of these groups implies that $E|_U$ is zero. Whence $E$ is zero. $\square$
Lemma. The derived quasi-coherator
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. The inclusion functor $D_\mathrm{QCoh}(\mathcal{O}_X) \to D(\mathcal{O}_X)$ has a right adjoint.
First proof. We will use the induction principle in Lemma Induction by elementary distinguished squares to prove this. If $D(\mathrm{QCoh}(\mathcal{O}_X)) \to D_\mathrm{QCoh}(\mathcal{O}_X)$ is an equivalence, then the lemma is true because the functor $RQ_X$ of Section Derived tensor products and Tor amplitude is a right adjoint to the functor $D(\mathrm{QCoh}(\mathcal{O}_X)) \to D(\mathcal{O}_X)$. In particular, our lemma is true for affine algebraic spaces, see Lemma Derived tensor products, Tor amplitude and affine neighbourhoods. Thus we see that it suffices to show: if $(U \subset X, f : V \to X)$ is an elementary distinguished square with $U$ quasi-compact and $V$ affine and the lemma holds for $U$, $V$, and $U \times_X V$, then the lemma holds for $X$.
The adjoint exists if and only if for every object $E$ of $D(\mathcal{O}_X)$ we can find a distinguished triangle $$E' \to E \to K \to E'[1]$$ in $D(\mathcal{O}_X)$ such that $E'$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and such that $\operatorname{Hom}(M, K) = 0$ for all $M$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$. See Derived Categories, Lemma Existence of a right adjoint. Consider the distinguished triangle $$E \to Rj_{U, *}E|_U \oplus Rj_{V, *}E|_V \to Rj_{U \times_X V, *}E|_{U \times_X V} \to E[1]$$ in $D(\mathcal{O}_X)$ of Lemma Derived quasi-coherent complexes. By Derived Categories, Lemma Preparing the adjunction for derived functors it suffices to construct the desired distinguished triangles for $Rj_{U, *}E|_U$, $Rj_{V, *}E|_V$, and $Rj_{U \times_X V, *}E|_{U \times_X V}$. This reduces us to the statement discussed in the next paragraph.
Let $j : U \to X$ be an étale morphism corresponding with $U$ quasi-compact and quasi-separated and the lemma is true for $U$. Let $L$ be an object of $D(\mathcal{O}_U)$. Then there exists a distinguished triangle $$E' \to Rj_*L \to K \to E'[1]$$ in $D(\mathcal{O}_X)$ such that $E'$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and such that $\operatorname{Hom}(M, K) = 0$ for all $M$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$. To see this we choose a distinguished triangle $$L' \to L \to Q \to L'[1]$$ in $D(\mathcal{O}_U)$ such that $L'$ is in $D_\mathrm{QCoh}(\mathcal{O}_U)$ and such that $\operatorname{Hom}(N, Q) = 0$ for all $N$ in $D_\mathrm{QCoh}(\mathcal{O}_U)$. This is possible because the statement in Derived Categories, Lemma Existence of a right adjoint is an if and only if. We obtain a distinguished triangle $$Rj_*L' \to Rj_*L \to Rj_*Q \to Rj_*L'[1]$$ in $D(\mathcal{O}_X)$. Observe that $Rj_*L'$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$ by Lemma Quasi-coherent complexes and coherent sheaves. On the other hand, if $M$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$, then $$\operatorname{Hom}(M, Rj_*Q) = \operatorname{Hom}(Lj^*M, Q) = 0$$ because $Lj^*M$ is in $D_\mathrm{QCoh}(\mathcal{O}_U)$ by Lemma Quasi-coherent complexes and coherent sheaves. This finishes the proof. $\square$
Second proof. The adjoint exists by Derived Categories, Proposition Brown representability for a triangulated category. The hypotheses are satisfied: First, note that $D_\mathrm{QCoh}(\mathcal{O}_X)$ has direct sums and direct sums commute with the inclusion functor (Lemma Quasi-coherent complexes and coherent sheaves). On the other hand, $D_\mathrm{QCoh}(\mathcal{O}_X)$ is compactly generated because it has a perfect generator Theorem A perfect generator for a quasi-compact algebraic space and because perfect objects are compact by Proposition Compact objects are perfect. $\square$
Lemma. Direct images and the derived quasi-coherator
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-compact and quasi-separated morphism of algebraic spaces over $S$. If the right adjoints $DQ_X$ and $DQ_Y$ of the inclusion functors $D_\mathrm{QCoh} \to D$ exist for $X$ and $Y$, then $$Rf_* \circ DQ_X = DQ_Y \circ Rf_*$$
Proof. The statement makes sense because $Rf_*$ sends $D_\mathrm{QCoh}(\mathcal{O}_X)$ into $D_\mathrm{QCoh}(\mathcal{O}_Y)$ by Lemma Quasi-coherent complexes and coherent sheaves. The statement is true because $Lf^*$ similarly maps $D_\mathrm{QCoh}(\mathcal{O}_Y)$ into $D_\mathrm{QCoh}(\mathcal{O}_X)$ (Lemma Quasi-coherent complexes and coherent sheaves) and hence both $Rf_* \circ DQ_X$ and $DQ_Y \circ Rf_*$ are right adjoint to $Lf^* : D_\mathrm{QCoh}(\mathcal{O}_Y) \to D(\mathcal{O}_X)$. $\square$
Lemma. Bounds for the derived quasi-coherator
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. The functor $DQ_X$ of Lemma The derived quasi-coherator has the following boundedness property: there exists an integer $N = N(X)$ such that, if $K$ in $D(\mathcal{O}_X)$ with $H^i(U, K) = 0$ for $U$ affine étale over $X$ and $i \not \in [a, b]$, then the cohomology sheaves $H^i(DQ_X(K))$ are zero for $i \not \in [a, b + N]$.
Proof. We will prove this using the induction principle of Lemma Induction by elementary distinguished squares.
If $X$ is affine, then the lemma is true with $N = 0$ because then $RQ_X = DQ_X$ is given by taking the complex of quasi-coherent sheaves associated to $R\Gamma(X, K)$. See Lemma Derived tensor products, Tor amplitude and affine neighbourhoods.
Let $(U \subset W, f : V \to W)$ be an elementary distinguished square with $W$ quasi-compact and quasi-separated, $U \subset W$ quasi-compact open, $V$ affine such that the lemma holds for $U$, $V$, and $U \times_W V$. Say with integers $N(U)$, $N(V)$, and $N(U \times_W V)$. Now suppose $K$ is in $D(\mathcal{O}_X)$ with $H^i(W, K) = 0$ for all affine $W$ étale over $X$ and all $i \not \in [a, b]$. Then $K|_U$, $K|_V$, $K|_{U \times_W V}$ have the same property. Hence we see that $RQ_U(K|_U)$ and $RQ_V(K|_V)$ and $RQ_{U \cap V}(K|_{U \times_W V})$ have vanishing cohomology sheaves outside the interval $[a, b + \max(N(U), N(V), N(U \times_W V))$. Since the functors $Rj_{U, *}$, $Rj_{V, *}$, $Rj_{U \times_W V, *}$ have finite cohomological dimension on $D_\mathrm{QCoh}$ by Lemma Quasi-coherent complexes and coherent sheaves we see that there exists an $N$ such that $Rj_{U, *}DQ_U(K|_U)$, $Rj_{V, *}DQ_V(K|_V)$, and $Rj_{U \cap V, *}DQ_{U \times_W V}(K|_{U \times_W V})$ have vanishing cohomology sheaves outside the interval $[a, b + N]$. Then finally we conclude by the distinguished triangle of Remark Derived quasi-coherent complexes. $\square$
Lemma. Canonical arbitrary base change for relatively flat tensors
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-compact and quasi-separated morphism of algebraic spaces over $S$. Let $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$. Let $\mathcal{G}^\bullet$ be a bounded above complex of quasi-coherent $\mathcal{O}_X$-modules flat over $Y$. Then formation of $$Rf_*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet)$$ commutes with arbitrary base change (see proof for precise statement).
Proof. The statement means the following. Let $g : Y' \to Y$ be a morphism of algebraic spaces and consider the base change diagram $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ in other words $X' = Y' \times_Y X$. The lemma asserts that $$Lg^*Rf_*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet) \longrightarrow Rf'_*(L(g')^*E \otimes^\mathbf{L}_{\mathcal{O}_{X'}} (g')^*\mathcal{G}^\bullet)$$ is an isomorphism. Observe that on the right hand side we do not use derived pullback on $\mathcal{G}^\bullet$. To prove this, we apply Lemmas Base change for derived categories and Inheritance of a cohomological base-change condition to see that it suffices to prove the canonical map $$L(g')^*\mathcal{G}^\bullet \to (g')^*\mathcal{G}^\bullet$$ satisfies the equivalent conditions of Lemma Base change for derived categories. This follows by checking the condition on stalks, where it immediately follows from the fact that $\mathcal{G}^\bullet_{\overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{Y', \overline{y}'}$ computes the derived tensor product by our assumptions on the complex $\mathcal{G}^\bullet$. $\square$
Lemma. Canonical arbitrary base change for derived Hom
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-compact and quasi-separated morphism of algebraic spaces over $S$. Let $E$ be an object of $D(\mathcal{O}_X)$. Let $\mathcal{G}^\bullet$ be a complex of quasi-coherent $\mathcal{O}_X$-modules. If
-
$E$ is perfect, $\mathcal{G}^\bullet$ is a bounded above, and $\mathcal{G}^n$ is flat over $Y$, or
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$E$ is pseudo-coherent, $\mathcal{G}^\bullet$ is bounded, and $\mathcal{G}^n$ is flat over $Y$,
then formation of $$Rf_*R\mathcal{H}om(E, \mathcal{G}^\bullet)$$ commutes with arbitrary base change (see proof for precise statement).
Proof. The statement means the following. Let $g : Y' \to Y$ be a morphism of algebraic spaces and consider the base change diagram $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{h} X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ in other words $X' = Y' \times_Y X$. The lemma asserts that $$Lg^*Rf_*R\mathcal{H}om(E, \mathcal{G}^\bullet) \longrightarrow R(f')_*R\mathcal{H}om(L(g')^*E, (g')^*\mathcal{G}^\bullet)$$ is an isomorphism. Observe that on the right hand side we do not use the derived pullback on $\mathcal{G}^\bullet$. To prove this, we apply Lemmas Base change for derived categories and Inheritance of a cohomological base-change condition to see that it suffices to prove the canonical map $$L(g')^*\mathcal{G}^\bullet \to (g')^*\mathcal{G}^\bullet$$ satisfies the equivalent conditions of Lemma Base change for derived categories. This was shown in the proof of Lemma Canonical arbitrary base change for relatively flat tensors. $\square$
Lemma. Perfectness of a proper direct image
Let $S$ be a scheme. Let $Y$ be a Noetherian algebraic space over $S$. Let $f : X \to Y$ be a morphism of algebraic spaces which is locally of finite type and quasi-separated. Let $E \in D(\mathcal{O}_X)$ such that
-
$E \in D^b_{\textit{Coh}}(\mathcal{O}_X)$,
-
the support of $H^i(E)$ is proper over $Y$ for all $i$,
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$E$ has finite tor dimension as an object of $D(f^{-1}\mathcal{O}_Y)$.
Then $Rf_*E$ is a perfect object of $D(\mathcal{O}_Y)$.
Proof. By Lemma Direct images and coherent sheaves we see that $Rf_*E$ is an object of $D^b_{\textit{Coh}}(\mathcal{O}_Y)$. Hence $Rf_*E$ is pseudo-coherent (Lemma Pseudo-coherent complexes and coherent sheaves). Hence it suffices to show that $Rf_*E$ has finite tor dimension, see Cohomology on Sites, Lemma Perfect complexes. By Lemma Tor amplitude on a quasi-compact quasi-separated scheme it suffices to check that $Rf_*(E) \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F}$ has universally bounded cohomology for all quasi-coherent sheaves $\mathcal{F}$ on $Y$. Bounded from above is clear as $Rf_*(E)$ is bounded from above. Let $T \subset |X|$ be the union of the supports of $H^i(E)$ for all $i$. Then $T$ is proper over $Y$ by assumptions (1) and (2) and Lemma Proper morphisms. In particular there exists a quasi-compact open subspace $X' \subset X$ containing $T$. Setting $f' = f|_{X'}$ we have $Rf_*(E) = Rf'_*(E|_{X'})$ because $E$ restricts to zero on $X \setminus T$. Thus we may replace $X$ by $X'$ and assume $f$ is quasi-compact. We have assumed $f$ is quasi-separated. Thus $$Rf_*(E) \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F} = Rf_*\left(E \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*\mathcal{F}\right) = Rf_*\left(E \otimes_{f^{-1}\mathcal{O}_Y}^\mathbf{L} f^{-1}\mathcal{F}\right)$$ by Lemma Base change for sheaf cohomology and Cohomology on Sites, Lemma Derived categories. By assumption (3) the complex $E \otimes_{f^{-1}\mathcal{O}_Y}^\mathbf{L} f^{-1}\mathcal{F}$ has cohomology sheaves in a given finite range, say $[a, b]$. Then $Rf_*$ of it has cohomology in the range $[a, \infty)$ and we win. $\square$
Lemma. Perfect complexes and tensor products and direct sums
Let $S$ be a scheme. Let $B$ be a Noetherian algebraic space over $S$. Let $f : X \to B$ be a morphism of algebraic spaces which is locally of finite type and quasi-separated. Let $E \in D(\mathcal{O}_X)$ be perfect. Let $\mathcal{G}^\bullet$ be a bounded complex of coherent $\mathcal{O}_X$-modules flat over $B$ with support proper over $B$. Then $K = Rf_*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet)$ is a perfect object of $D(\mathcal{O}_B)$.
Proof. The object $K$ is perfect by Lemma Perfectness of a proper direct image. We check the lemma applies: Locally $E$ is isomorphic to a finite complex of finite free $\mathcal{O}_X$-modules. Hence locally $E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet$ is isomorphic to a finite complex whose terms are of the form $$\bigoplus\nolimits_{i = a, \ldots, b} (\mathcal{G}^i)^{\oplus r_i}$$ for some integers $a, b, r_a, \ldots, r_b$. This immediately implies the cohomology sheaves $H^i(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G})$ are coherent. The hypothesis on the tor dimension also follows as $\mathcal{G}^i$ is flat over $f^{-1}\mathcal{O}_Y$. $\square$
Lemma. Perfect complexes and derived Hom and Ext
Let $S$ be a scheme. Let $B$ be a Noetherian algebraic space over $S$. Let $f : X \to B$ be a morphism of algebraic spaces which is locally of finite type and quasi-separated. Let $E \in D(\mathcal{O}_X)$ be perfect. Let $\mathcal{G}^\bullet$ be a bounded complex of coherent $\mathcal{O}_X$-modules flat over $B$ with support proper over $B$. Then $K = Rf_*R\mathcal{H}om(E, \mathcal{G})$ is a perfect object of $D(\mathcal{O}_B)$.
Proof. Since $E$ is a perfect complex there exists a dual perfect complex $E^\vee$, see Cohomology on Sites, Lemma Perfect complexes and derived categories. Observe that $R\mathcal{H}om(E, \mathcal{G}^\bullet) = E^\vee \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet$. Thus the perfectness of $K$ follows from Lemma Perfect complexes and tensor products and direct sums. $\square$
Lemma. Perfect complexes and tensor products and direct sums
Assumptions and notation as in Lemma Perfect complexes and tensor products and direct sums. Then there are functorial isomorphisms $$H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}) \longrightarrow H^i(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}))$$ for $\mathcal{F}$ quasi-coherent on $B$ compatible with boundary maps (see proof).
Proof. We have $$\mathcal{G}^\bullet \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*\mathcal{F} = \mathcal{G}^\bullet \otimes_{f^{-1}\mathcal{O}_B}^\mathbf{L} f^{-1}\mathcal{F} = \mathcal{G}^\bullet \otimes_{f^{-1}\mathcal{O}_B} f^{-1}\mathcal{F} = \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}$$ the first equality by Cohomology on Sites, Lemma Derived categories, the second as $\mathcal{G}^n$ is a flat $f^{-1}\mathcal{O}_B$-module, and the third by definition of pullbacks. Hence we obtain $$\begin{aligned} H^i(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F})) & = H^i(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*\mathcal{F}) \\ & = H^i(B, Rf_*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet \otimes^\mathbf{L}_{\mathcal{O}_X} Lf^*\mathcal{F})) \\ & = H^i(B, Rf_*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet) \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}) \\ & = H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}) \end{aligned}$$ The first equality by the above, the second by Leray (Cohomology on Sites, Remark Sheaf cohomology), and the third equality by Lemma Base change for sheaf cohomology. The statement on boundary maps means the following: Given a short exact sequence $0 \to \mathcal{F}_1 \to \mathcal{F}_2 \to \mathcal{F}_3 \to 0$ then the isomorphisms fit into commutative diagrams $$\begin{gathered}\begin{matrix}H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3) & H^i(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3)) \\ H^{i + 1}(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1) & H^{i + 1}(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1))\end{matrix} \\[6pt] \begin{aligned}H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3) & \longrightarrow H^i(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3)) \\ H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3) & \xrightarrow{\delta} H^{i + 1}(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1) \\ H^i(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3)) & \xrightarrow{\delta} H^{i + 1}(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1)) \\ H^{i + 1}(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1) & \longrightarrow H^{i + 1}(X, E \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1))\end{aligned}\end{gathered}$$ where the boundary maps come from the distinguished triangle $$K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1 \to K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_2 \to K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3 \to K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1[1]$$ and the distinguished triangle in $D(\mathcal{O}_X)$ associated to the short exact sequence $$0 \to \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1 \to \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_2 \to \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3 \to 0$$ of complexes. This sequence is exact because $\mathcal{G}^n$ is flat over $B$. We omit the verification of the commutativity of the displayed diagram. $\square$
Lemma. Perfect complexes and derived Hom and Ext
Assumption and notation as in Lemma Perfect complexes and derived Hom and Ext. Then there are functorial isomorphisms $$H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}) \longrightarrow \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F})$$ for $\mathcal{F}$ quasi-coherent on $B$ compatible with boundary maps (see proof).
Proof. As in the proof of Lemma Perfect complexes and derived Hom and Ext let \(E^\vee\) be the dual perfect complex and recall that \(K = Rf_*(E^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{G}^\bullet)\). Since we also have
\[ \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}) = H^i(X, E^\vee \otimes^\mathbf{L}_{\mathcal{O}_X} (\mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F})) \]by construction of \(E^\vee\), the existence of the isomorphisms follows from Lemma Perfect complexes and tensor products and direct sums applied to \(E^\vee\) and \(\mathcal{G}^\bullet\). The statement on boundary maps means the following: Given a short exact sequence \(0 \to \mathcal{F}_1 \to \mathcal{F}_2 \to \mathcal{F}_3 \to 0\) then the isomorphisms fit into commutative diagrams
\[ \begin{gathered}\begin{matrix}H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3) & \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3) \\ H^{i + 1}(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1) & \operatorname{Ext}^{i + 1}_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1)\end{matrix} \\[6pt] \begin{aligned}H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3) & \longrightarrow \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3) \\ H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3) & \xrightarrow{\delta} H^{i + 1}(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1) \\ \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3) & \xrightarrow{\delta} \operatorname{Ext}^{i + 1}_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1) \\ H^{i + 1}(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1) & \longrightarrow \operatorname{Ext}^{i + 1}_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1)\end{aligned}\end{gathered} \]where the boundary maps come from the distinguished triangle
\[ K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1 \to K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_2 \to K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_3 \to K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F}_1[1] \]and the distinguished triangle in \(D(\mathcal{O}_X)\) associated to the short exact sequence
\[ 0 \to \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_1 \to \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_2 \to \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}_3 \to 0 \]of complexes. This sequence is exact because \(\mathcal{G}^n\) is flat over \(B\). We omit the verification of the commutativity of the displayed diagram. \(\square\)
Lemma. Derived Hom and Ext
Let $S$ be a scheme. Let $f : X \to B$ be a morphism of algebraic spaces over $S$, $E \in D(\mathcal{O}_X)$, and $\mathcal{F}^\bullet$ a complex of $\mathcal{O}_X$-modules. Assume
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$B$ is Noetherian,
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$f$ is locally of finite type and quasi-separated,
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$E \in D^-_{\textit{Coh}}(\mathcal{O}_X)$,
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$\mathcal{G}^\bullet$ is a bounded complex of coherent $\mathcal{O}_X$-module flat over $B$ with support proper over $B$.
Then the following two statements are true
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for every $m \in \mathbf{Z}$ there exists a perfect object $K$ of $D(\mathcal{O}_B)$ and functorial maps $$\alpha^i_\mathcal{F} : \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}) \longrightarrow H^i(B, K \otimes^\mathbf{L}_{\mathcal{O}_B} \mathcal{F})$$ for $\mathcal{F}$ quasi-coherent on $B$ compatible with boundary maps (see proof) such that $\alpha^i_\mathcal{F}$ is an isomorphism for $i \leq m$, and
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there exists a pseudo-coherent $L \in D(\mathcal{O}_B)$ and functorial isomorphisms $$\operatorname{Ext}^i_{\mathcal{O}_B}(L, \mathcal{F}) \longrightarrow \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F})$$ for $\mathcal{F}$ quasi-coherent on $B$ compatible with boundary maps.
Proof. Proof of (A). Suppose $\mathcal{G}^i$ is nonzero only for $i \in [a, b]$. We may replace $X$ by a quasi-compact open neighbourhood of the union of the supports of $\mathcal{G}^i$. Hence we may assume $X$ is Noetherian. In this case $X$ and $f$ are quasi-compact and quasi-separated. Choose an approximation $P \to E$ by a perfect complex $P$ of $(X, E, -m - 1 + a)$ (possible by Theorem Perfect approximation with prescribed closed support). Then the induced map $$\operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}) \longrightarrow \operatorname{Ext}^i_{\mathcal{O}_X}(P, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F})$$ is an isomorphism for $i \leq m$. Namely, the kernel, resp. cokernel of this map is a quotient, resp. submodule of $$\operatorname{Ext}^i_{\mathcal{O}_X}(C, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}) \quad\text{resp.}\quad \operatorname{Ext}^{i + 1}_{\mathcal{O}_X}(C, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F})$$ where $C$ is the cone of $P \to E$. Since $C$ has vanishing cohomology sheaves in degrees $\geq -m - 1 + a$ these $\operatorname{Ext}$-groups are zero for $i \leq m + 1$ by Derived Categories, Lemma Vanishing of negative Ext groups. This reduces us to the case that $E$ is a perfect complex which is Lemma Perfect complexes and derived Hom and Ext. The statement on boundaries is explained in the proof of Lemma Perfect complexes and derived Hom and Ext.
Proof of (B). As in the proof of (A) we may assume $X$ is Noetherian. Observe that $E$ is pseudo-coherent by Lemma Pseudo-coherent complexes and coherent sheaves. By Lemma Pseudo-coherent complexes and coherent sheaves we can write $E = \text{hocolim} E_n$ with $E_n$ perfect and $E_n \to E$ inducing an isomorphism on truncations $\tau_{\geq -n}$. Let $E_n^\vee$ be the dual perfect complex (Cohomology on Sites, Lemma Perfect complexes and derived categories). We obtain an inverse system $\ldots \to E_3^\vee \to E_2^\vee \to E_1^\vee$ of perfect objects. This in turn gives rise to an inverse system $$\ldots \to K_3 \to K_2 \to K_1\quad\text{with}\quad K_n = Rf_*(E_n^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{G}^\bullet)$$ perfect on $Y$, see Lemma Perfect complexes and tensor products and direct sums. By Lemma Perfect complexes and derived Hom and Ext and its proof and by the arguments in the previous paragraph (with $P = E_n$) for any quasi-coherent $\mathcal{F}$ on $Y$ we have functorial canonical maps $$\begin{gathered}\begin{matrix}\phantom{X} & \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}) \\ H^i(Y, K_{n + 1} \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F}) & \phantom{X} & H^i(Y, K_n \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F})\end{matrix} \\[6pt] \begin{aligned}\operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}) & \longrightarrow H^i(Y, K_{n + 1} \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F}) \\ \operatorname{Ext}^i_{\mathcal{O}_X}(E, \mathcal{G}^\bullet \otimes_{\mathcal{O}_X} f^*\mathcal{F}) & \longrightarrow H^i(Y, K_n \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F}) \\ H^i(Y, K_{n + 1} \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F}) & \longrightarrow H^i(Y, K_n \otimes_{\mathcal{O}_Y}^\mathbf{L} \mathcal{F})\end{aligned}\end{gathered}$$ which are isomorphisms for $i \leq n + a$. Let $L_n = K_n^\vee$ be the dual perfect complex. Then we see that $L_1 \to L_2 \to L_3 \to \ldots$ is a system of perfect objects in $D(\mathcal{O}_Y)$ such that for any quasi-coherent $\mathcal{F}$ on $Y$ the maps $$\operatorname{Ext}^i_{\mathcal{O}_Y}(L_{n + 1}, \mathcal{F}) \longrightarrow \operatorname{Ext}^i_{\mathcal{O}_Y}(L_n, \mathcal{F})$$ are isomorphisms for $i \leq n + a - 1$. This implies that $L_n \to L_{n + 1}$ induces an isomorphism on truncations $\tau_{\geq -n - a + 2}$ (hint: take cone of $L_n \to L_{n + 1}$ and look at its last nonvanishing cohomology sheaf). Thus $L = \text{hocolim} L_n$ is pseudo-coherent, see Lemma Pseudo-coherent complexes and coherent sheaves. The mapping property of homotopy colimits gives that $\operatorname{Ext}^i_{\mathcal{O}_Y}(L, \mathcal{F}) = \operatorname{Ext}^i_{\mathcal{O}_Y}(L_n, \mathcal{F})$ for $i \leq n + a - 3$ which finishes the proof. $\square$
Lemma. Perfect proper-support direct images over arbitrary bases
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of finite presentation between algebraic spaces over $S$. Let $E \in D(\mathcal{O}_X)$ be a perfect object. Let $\mathcal{G}^\bullet$ be a bounded complex of finitely presented $\mathcal{O}_X$-modules, flat over $Y$, with support proper over $Y$. Then $$K = Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{G}^\bullet)$$ is a perfect object of $D(\mathcal{O}_Y)$ and its formation commutes with arbitrary base change.
Proof. The statement on base change is Lemma Canonical arbitrary base change for relatively flat tensors. Thus it suffices to show that $K$ is a perfect object. If $Y$ is Noetherian, then this follows from Lemma Perfect complexes and tensor products and direct sums. We will reduce to this case by Noetherian approximation. We encourage the reader to skip the rest of this proof.
The question is local on $Y$, hence we may assume $Y$ is affine. Say $Y = \operatorname{Spec}(R)$. We write $R = \mathop{\operatorname{colim}} R_i$ as a filtered colimit of Noetherian rings $R_i$. By Limits of Spaces, Lemma Descent of finite presentation and finite algebras there exists an $i$ and an algebraic space $X_i$ of finite presentation over $R_i$ whose base change to $R$ is $X$. By Limits of Spaces, Lemma Descent of finite presentation and modules we may assume after increasing $i$, that there exists a bounded complex of finitely presented $\mathcal{O}_{X_i}$-modules $\mathcal{G}_i^\bullet$ whose pullback to $X$ is $\mathcal{G}^\bullet$. After increasing $i$ we may assume $\mathcal{G}_i^n$ is flat over $R_i$, see Limits of Spaces, Lemma Descent of flatness. After increasing $i$ we may assume the support of $\mathcal{G}_i^n$ is proper over $R_i$, see Limits of Spaces, Lemma Proper morphisms and closed support. Finally, by Lemma Perfect complexes we may, after increasing $i$, assume there exists a perfect object $E_i$ of $D(\mathcal{O}_{X_i})$ whose pullback to $X$ is $E$. By Lemma Perfect complexes and tensor products and direct sums we have that $K_i = Rf_{i, *}(E_i \otimes_{\mathcal{O}_{X_i}}^\mathbf{L} \mathcal{G}_i^\bullet)$ is perfect on $\operatorname{Spec}(R_i)$ where $f_i : X_i \to \operatorname{Spec}(R_i)$ is the structure morphism. By the base change result (Lemma Canonical arbitrary base change for relatively flat tensors) the pullback of $K_i$ to $Y = \operatorname{Spec}(R)$ is $K$ and we conclude. $\square$
Lemma. Base change for pseudo-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of finite presentation between algebraic spaces over $S$. Let $E \in D(\mathcal{O}_X)$ be a pseudo-coherent object. Let $\mathcal{G}^\bullet$ be a bounded above complex of finitely presented $\mathcal{O}_X$-modules, flat over $Y$, with support proper over $Y$. Then $$K = Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{G}^\bullet)$$ is a pseudo-coherent object of $D(\mathcal{O}_Y)$ and its formation commutes with arbitrary base change.
Proof. The statement on base change is Lemma Canonical arbitrary base change for relatively flat tensors. Thus it suffices to show that $K$ is a pseudo-coherent object. This will follow from Lemma Perfect proper-support direct images over arbitrary bases by approximation by perfect complexes. We encourage the reader to skip the rest of the proof.
The question is étale local on $Y$, hence we may assume $Y$ is affine. Then $X$ is quasi-compact and quasi-separated. Moreover, there exists an integer $N$ such that total direct image $Rf_* : D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_Y)$ has cohomological dimension $N$ as explained in Lemma Quasi-coherent complexes and coherent sheaves. Choose an integer $b$ such that $\mathcal{G}^i = 0$ for $i > b$. It suffices to show that $K$ is $m$-pseudo-coherent for every $m$. Choose an approximation $P \to E$ by a perfect complex $P$ of $(X, E, m - N - 1 - b)$. This is possible by Theorem Perfect approximation with prescribed closed support. Choose a distinguished triangle $$P \to E \to C \to P[1]$$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$. The cohomology sheaves of $C$ are zero in degrees $\geq m - N - 1 - b$. Hence the cohomology sheaves of $C \otimes^\mathbf{L} \mathcal{G}^\bullet$ are zero in degrees $\geq m - N - 1$. Thus the cohomology sheaves of $Rf_*(C \otimes^\mathbf{L} \mathcal{G})$ are zero in degrees $\geq m - 1$. Hence $$Rf_*(P \otimes^\mathbf{L} \mathcal{G}) \to Rf_*(E \otimes^\mathbf{L} \mathcal{G})$$ is an isomorphism on cohomology sheaves in degrees $\geq m$. Next, suppose that $H^i(P) = 0$ for $i > a$. Then $P \otimes^\mathbf{L} \sigma_{\geq m - N - 1 - a}\mathcal{G}^\bullet \longrightarrow P \otimes^\mathbf{L} \mathcal{G}^\bullet$ is an isomorphism on cohomology sheaves in degrees $\geq m - N - 1$. Thus again we find that $$Rf_*(P \otimes^\mathbf{L} \sigma_{\geq m - N - 1 - a}\mathcal{G}^\bullet) \to Rf_*(P \otimes^\mathbf{L} \mathcal{G}^\bullet)$$ is an isomorphism on cohomology sheaves in degrees $\geq m$. By Lemma Perfect proper-support direct images over arbitrary bases the source is a perfect complex. We conclude that $K$ is $m$-pseudo-coherent as desired. $\square$
Lemma. Pullback of derived quasi-coherent complexes
Let $R$ be a ring. Let $X$ be an algebraic space and let $f : X \to \operatorname{Spec}(R)$ be proper, flat, and of finite presentation. Let $(M_n)$ be an inverse system of $R$-modules with surjective transition maps. Then the canonical map $$\mathcal{O}_X \otimes_R (\varprojlim M_n) \longrightarrow \varprojlim \mathcal{O}_X \otimes_R M_n$$ induces an isomorphism from the source to $DQ_X$ applied to the target.
Proof. The statement means that for any object $E$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ the induced map $$\operatorname{Hom}(E, \mathcal{O}_X \otimes_R (\varprojlim M_n)) \longrightarrow \operatorname{Hom}(E, \varprojlim \mathcal{O}_X \otimes_R M_n)$$ is an isomorphism. Since $D_\mathrm{QCoh}(\mathcal{O}_X)$ has a perfect generator (Theorem A perfect generator for a quasi-compact algebraic space) it suffices to check this for perfect $E$. By Lemma Quasi-coherent complexes and coherent sheaves we have $\varprojlim \mathcal{O}_X \otimes_R M_n = R\varprojlim \mathcal{O}_X \otimes_R M_n$. The exact functor $R\operatorname{Hom}_X(E, -) : D_\mathrm{QCoh}(\mathcal{O}_X) \to D(R)$ of Cohomology on Sites, Section Derived Hom and Ext commutes with products and hence with derived limits, whence $$R\operatorname{Hom}_X(E, \varprojlim \mathcal{O}_X \otimes_R M_n) = R\varprojlim R\operatorname{Hom}_X(E, \mathcal{O}_X \otimes_R M_n)$$ Let $E^\vee$ be the dual perfect complex, see Cohomology on Sites, Lemma Perfect complexes and derived categories. We have $$R\operatorname{Hom}_X(E, \mathcal{O}_X \otimes_R M_n) = R\Gamma(X, E^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*M_n) = R\Gamma(X, E^\vee) \otimes_R^\mathbf{L} M_n$$ by Lemma Base change for sheaf cohomology. From Lemma Perfect direct images for proper morphisms of finite presentation we see $R\Gamma(X, E^\vee)$ is a perfect complex of $R$-modules. In particular it is a pseudo-coherent complex and by More on Algebra, Lemma Pseudo-coherent complexes and coherent sheaves we obtain $$R\varprojlim R\Gamma(X, E^\vee) \otimes_R^\mathbf{L} M_n = R\Gamma(X, E^\vee) \otimes_R^\mathbf{L} \varprojlim M_n$$ as desired. $\square$
Lemma. Detecting a complex by perfect tests
Let $A$ be a ring. Let $X$ be an algebraic space over $A$ which is quasi-compact and quasi-separated. Let $K \in D^-_\mathrm{QCoh}(\mathcal{O}_X)$. If $R\Gamma(X, E \otimes^\mathbf{L} K)$ is pseudo-coherent in $D(A)$ for every perfect $E$ in $D(\mathcal{O}_X)$, then $R\Gamma(X, E \otimes^\mathbf{L} K)$ is pseudo-coherent in $D(A)$ for every pseudo-coherent $E$ in $D(\mathcal{O}_X)$.
Proof. There exists an integer $N$ such that $R\Gamma(X, -) : D_\mathrm{QCoh}(\mathcal{O}_X) \to D(A)$ has cohomological dimension $N$ as explained in Lemma Quasi-coherent complexes and coherent sheaves. Let $b \in \mathbf{Z}$ be such that $H^i(K) = 0$ for $i > b$. Let $E$ be pseudo-coherent on $X$. It suffices to show that $R\Gamma(X, E \otimes^\mathbf{L} K)$ is $m$-pseudo-coherent for every $m$. Choose an approximation $P \to E$ by a perfect complex $P$ of $(X, E, m - N - 1 - b)$. This is possible by Theorem Perfect approximation with prescribed closed support. Choose a distinguished triangle $$P \to E \to C \to P[1]$$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$. The cohomology sheaves of $C$ are zero in degrees $\geq m - N - 1 - b$. Hence the cohomology sheaves of $C \otimes^\mathbf{L} K$ are zero in degrees $\geq m - N - 1$. Thus the cohomology of $R\Gamma(X, C \otimes^\mathbf{L} K)$ are zero in degrees $\geq m - 1$. Hence $$R\Gamma(X, P \otimes^\mathbf{L} K) \to R\Gamma(X, E \otimes^\mathbf{L} K)$$ is an isomorphism on cohomology in degrees $\geq m$. By assumption the source is pseudo-coherent. We conclude that $R\Gamma(X, E \otimes^\mathbf{L} K)$ is $m$-pseudo-coherent as desired. $\square$
Lemma. Perfect proper-support derived Hom over arbitrary bases
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of finite presentation between algebraic spaces over $S$. Let $E \in D(\mathcal{O}_X)$ be a perfect object. Let $\mathcal{G}^\bullet$ be a bounded complex of finitely presented $\mathcal{O}_X$-modules, flat over $Y$, with support proper over $Y$. Then $$K = Rf_*R\mathcal{H}om(E, \mathcal{G}^\bullet)$$ is a perfect object of $D(\mathcal{O}_Y)$ and its formation commutes with arbitrary base change.
Proof. The statement on base change is Lemma Canonical arbitrary base change for derived Hom. Thus it suffices to show that $K$ is a perfect object. If $Y$ is Noetherian, then this follows from Lemma Perfect complexes and derived Hom and Ext. We will reduce to this case by Noetherian approximation. We encourage the reader to skip the rest of this proof.
The question is local on $Y$, hence we may assume $Y$ is affine. Say $Y = \operatorname{Spec}(R)$. We write $R = \mathop{\operatorname{colim}} R_i$ as a filtered colimit of Noetherian rings $R_i$. By Limits of Spaces, Lemma Descent of finite presentation and finite algebras there exists an $i$ and an algebraic space $X_i$ of finite presentation over $R_i$ whose base change to $R$ is $X$. By Limits of Spaces, Lemma Descent of finite presentation and modules we may assume after increasing $i$, that there exists a bounded complex of finitely presented $\mathcal{O}_{X_i}$-module $\mathcal{G}_i^\bullet$ whose pullback to $X$ is $\mathcal{G}$. After increasing $i$ we may assume $\mathcal{G}_i^n$ is flat over $R_i$, see Limits of Spaces, Lemma Descent of flatness. After increasing $i$ we may assume the support of $\mathcal{G}_i^n$ is proper over $R_i$, see Limits of Spaces, Lemma Proper morphisms and closed support. Finally, by Lemma Descent of perfect complexes we may, after increasing $i$, assume there exists a perfect object $E_i$ of $D(\mathcal{O}_{X_i})$ whose pullback to $X$ is $E$. Applying Lemma Perfect complexes and derived Hom and Ext to $X_i \to \operatorname{Spec}(R_i)$, $E_i$, $\mathcal{G}_i^\bullet$ and using the base change property already shown we obtain the result. $\square$
Lemma. Sheaf cohomology
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $K$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ such that the cohomology sheaves $H^i(K)$ have countable sets of sections over affine schemes étale over $X$. Then for any quasi-compact and quasi-separated étale morphism $U \to X$ and any perfect object $E$ in $D(\mathcal{O}_X)$ the sets $$H^i(U, K \otimes^\mathbf{L} E),\quad \operatorname{Ext}^i(E|_U, K|_U)$$ are countable.
Proof. Using Cohomology on Sites, Lemma Perfect complexes and derived categories we see that it suffices to prove the result for the groups $H^i(U, K \otimes^\mathbf{L} E)$. We will use the induction principle to prove the lemma, see Lemma Induction by elementary distinguished squares.
When $U = \operatorname{Spec}(A)$ is affine the result follows from the case of schemes, see Derived Categories of Schemes, Lemma Sheaf cohomology.
To finish the proof it suffices to show: if $(U \subset W, V \to W)$ is an elementary distinguished triangle and the result holds for $U$, $V$, and $U \times_W V$, then the result holds for $W$. This is an immediate consequence of the Mayer-Vietoris sequence, see Lemma Mayer–Vietoris for unbounded quasi-coherent complexes. $\square$
Lemma. Countable approximation by perfect objects
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Assume the sets of sections of $\mathcal{O}_X$ over affines étale over $X$ are countable. Let $K$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. The following are equivalent
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$K = \text{hocolim} E_n$ with $E_n$ a perfect object of $D(\mathcal{O}_X)$, and
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the cohomology sheaves $H^i(K)$ have countable sets of sections over affines étale over $X$.
Proof. If (1) is true, then (2) is true because homotopy colimits commutes with taking cohomology sheaves (by Derived Categories, Lemma Sheaf cohomology) and because a perfect complex is locally isomorphic to a finite complex of finite free $\mathcal{O}_X$-modules and therefore satisfies (2) by assumption on $X$.
Assume (2). Choose a K-injective complex $\mathcal{K}^\bullet$ representing $K$. Choose a perfect generator $E$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ and represent it by a K-injective complex $\mathcal{I}^\bullet$. According to Theorem Quasi-coherent complexes and its proof there is an equivalence of triangulated categories $F : D_\mathrm{QCoh}(\mathcal{O}_X) \to D(A, \text{d})$ where $(A, \text{d})$ is the differential graded algebra $$(A, \text{d}) = \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O}_X)} (\mathcal{I}^\bullet, \mathcal{I}^\bullet)$$ which maps $K$ to the differential graded module $$M = \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O}_X)} (\mathcal{I}^\bullet, \mathcal{K}^\bullet)$$ Note that $H^i(A) = \operatorname{Ext}^i(E, E)$ and $H^i(M) = \operatorname{Ext}^i(E, K)$. Moreover, since $F$ is an equivalence it and its quasi-inverse commute with homotopy colimits. Therefore, it suffices to write $M$ as a homotopy colimit of compact objects of $D(A, \text{d})$. By Differential Graded Algebra, Lemma Countable approximation by perfect objects it suffices show that $\operatorname{Ext}^i(E, E)$ and $\operatorname{Ext}^i(E, K)$ are countable for each $i$. This follows from Lemma Sheaf cohomology. $\square$
Lemma. Derived quasi-coherent complexes
Let $A$ be a ring. Let $f : U \to X$ be a flat morphism of algebraic spaces of finite presentation over $A$. Then
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there exists an inverse system of perfect objects $L_n$ of $D(\mathcal{O}_X)$ such that $$R\Gamma(U, Lf^*K) = \text{hocolim}\ R\operatorname{Hom}_X(L_n, K)$$ in $D(A)$ functorially in $K$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$, and
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there exists a system of perfect objects $E_n$ of $D(\mathcal{O}_X)$ such that $$R\Gamma(U, Lf^*K) = \text{hocolim}\ R\Gamma(X, E_n \otimes^\mathbf{L} K)$$ in $D(A)$ functorially in $K$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Proof. By Lemma Base change for sheaf cohomology we have $$R\Gamma(U, Lf^*K) = R\Gamma(X, Rf_*\mathcal{O}_U \otimes^\mathbf{L} K)$$ functorially in $K$. Observe that $R\Gamma(X, -)$ commutes with homotopy colimits because it commutes with direct sums by Lemma Quasi-coherent complexes and coherent sheaves. Similarly, $- \otimes^\mathbf{L} K$ commutes with derived colimits because $- \otimes^\mathbf{L} K$ commutes with direct sums (because direct sums in $D(\mathcal{O}_X)$ are given by direct sums of representing complexes). Hence to prove (2) it suffices to write $Rf_*\mathcal{O}_U = \text{hocolim} E_n$ for a system of perfect objects $E_n$ of $D(\mathcal{O}_X)$. Once this is done we obtain (1) by setting $L_n = E_n^\vee$, see Cohomology on Sites, Lemma Perfect complexes and derived categories.
Write $A = \mathop{\operatorname{colim}} A_i$ with $A_i$ of finite type over $\mathbf{Z}$. By Limits of Spaces, Lemma Descent of finite presentation and finite algebras we can find an $i$ and morphisms $U_i \to X_i \to \operatorname{Spec}(A_i)$ of finite presentation whose base change to $\operatorname{Spec}(A)$ recovers $U \to X \to \operatorname{Spec}(A)$. After increasing $i$ we may assume that $f_i : U_i \to X_i$ is flat, see Limits of Spaces, Lemma Descent of flatness. By Lemma Base change for derived quasi-coherent complexes the derived pullback of $Rf_{i, *}\mathcal{O}_{U_i}$ by $g : X \to X_i$ is equal to $Rf_*\mathcal{O}_U$. Since $Lg^*$ commutes with derived colimits, it suffices to prove what we want for $f_i$. Hence we may assume that $U$ and $X$ are of finite type over $\mathbf{Z}$.
Assume $f : U \to X$ is a morphism of algebraic spaces of finite type over $\mathbf{Z}$. To finish the proof we will show that $Rf_*\mathcal{O}_U$ is a homotopy colimit of perfect complexes. To see this we apply Lemma Countable approximation by perfect objects. Thus it suffices to show that $R^if_*\mathcal{O}_U$ has countable sets of sections over affines étale over $X$. This follows from Lemma Sheaf cohomology applied to the structure sheaf. $\square$
A.12.5 Derived Chow and the henselian proper part
The following arguments adapt the human Stacks Project treatment in spaces-more-morphisms.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. Separating the proper part over a henselian pair
Let $(A, I)$ be a henselian pair. Let $X$ be an algebraic space separated and of finite type over $A$. Set $X_0 = X \times_{\operatorname{Spec}(A)} \operatorname{Spec}(A/I)$. Let $Y \subset X_0$ be an open and closed subspace such that $Y \to \operatorname{Spec}(A/I)$ is proper. Then there exists an open and closed subspace $W \subset X$ which is proper over $A$ with $W \times_{\operatorname{Spec}(A)} \operatorname{Spec}(A/I) = Y$.
Proof. We will denote $T \mapsto T_0$ the base change by $\operatorname{Spec}(A/I) \to \operatorname{Spec}(A)$. By a weak version of Chow's lemma (in the form of Cohomology of Spaces, Lemma The weak Chow lemma for algebraic spaces) there exists a surjective proper morphism $\varphi : X' \to X$ such that $X'$ admits an immersion into $\mathbf{P}^n_A$. Set $Y' = \varphi^{-1}(Y)$. This is an open and closed subscheme of $X'_0$. The lemma holds for $(X', Y')$ by More on Morphisms, Lemma Separating the proper part over a henselian pair. Let $W' \subset X'$ be the open and closed subscheme proper over $A$ such that $Y' = W'_0$. By Morphisms of Spaces, Lemma Morphisms of algebraic spaces $Q_1 = \varphi(|W'|) \subset |X|$ and $Q_2 = \varphi(|X' \setminus W'|) \subset |X|$ are closed subsets and by Morphisms of Spaces, Lemma Proper morphisms any closed subspace structure on $Q_1$ is proper over $A$. The image of $Q_1 \cap Q_2$ in $\operatorname{Spec}(A)$ is closed. Since $(A, I)$ is henselian, if $Q_1 \cap Q_2$ is nonempty, then we find that $Q_1 \cap Q_2$ has a point lying over $\operatorname{Spec}(A/I)$. This is impossible as $W'_0 = Y' = \varphi^{-1}(Y)$. We conclude that $Q_1$ is open and closed in $|X|$. Let $W \subset X$ be the corresponding open and closed subspace. Then $W$ is proper over $A$ with $W_0 = Y$. $\square$
Lemma. Derived tensor products and Tor amplitude
Let $S$ be a scheme. Consider a commutative diagram of algebraic spaces $$\begin{gathered}\begin{matrix}Z' & Y' \\ X' & B'\end{matrix} \\[6pt] \begin{aligned}Z' & \longrightarrow X' \\ Z' & \longrightarrow Y' \\ Y' & \longrightarrow B' \\ X' & \longrightarrow B'\end{aligned}\end{gathered}$$ over $S$. Let $B \to B'$ be a morphism. Denote by $X$ and $Y$ the base changes of $X'$ and $Y'$ to $B$. Assume $Y' \to B'$ and $Z' \to X'$ are flat. Then $X \times_B Y$ and $Z'$ are Tor independent over $X' \times_{B'} Y'$.
Proof. By Derived Categories of Spaces, Lemma Derived tensor products and Tor amplitude we may check tor independence étale locally on $X \times_B Y$ and $Z'$. This[^1] reduces the lemma to the case of schemes which is More on Morphisms, Lemma Derived tensor products and Tor amplitude. $\square$
Lemma. A derived Chow neighbourhood (Derived Chow's lemma)
Let $A$ be a ring. Let $X$ be a separated algebraic space of finite presentation over $A$. Let $x \in |X|$. Then there exist an $n \geq 0$, a closed subspace $Z \subset X \times_A \mathbf{P}^n_A$, a point $z \in |Z|$, an open $V \subset \mathbf{P}^n_A$, and an object $E$ in $D(\mathcal{O}_{X \times_A \mathbf{P}^n_A})$ such that
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$Z \to X \times_A \mathbf{P}^n_A$ is of finite presentation,
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$c : Z \to \mathbf{P}^n_A$ is a closed immersion over $V$, set $W = c^{-1}(V)$,
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the restriction of $b : Z \to X$ to $W$ is étale, $z \in W$, and $b(z) = x$,
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$E|_{X \times_A V} \cong (b, c)_*\mathcal{O}_Z|_{X \times_A V}$,
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$E$ is pseudo-coherent and supported on $Z$.
Proof. We can find a finite type $\mathbf{Z}$-subalgebra $A' \subset A$ and an algebraic space $X'$ separated and of finite presentation over $A'$ whose base change to $A$ is $X$. See Limits of Spaces, Lemmas Descent of finite presentation and finite algebras and Descent of diagonals and separation. Let $x' \in |X'|$ be the image of $x$. If we can prove the lemma for $(X'/A', x')$, then the lemma follows for $(X/A, x)$. Namely, if $n', Z', z', V', E'$ provide the solution for $(X'/A', x')$, then we can let $n = n'$, let $Z \subset X \times \mathbf{P}^n$ be the inverse image of $Z'$, choose a point $z$ of the base-changed étale neighbourhood over $x$, let $V \subset \mathbf{P}^n_A$ be the inverse image of $V'$, and let $E$ be the derived pullback of $E'$. Observe that $E$ is pseudo-coherent by Cohomology on Sites, Lemma Pseudo-coherent complexes and coherent sheaves. It remains to check the graph restriction in (4) and support in (5). To see this set $W = c^{-1}(V)$ and $W' = (c')^{-1}(V')$ and consider the cartesian square $$\begin{gathered}\begin{matrix}W & W' \\ X \times_A V & X' \times_{A'} V'\end{matrix} \\[6pt] \begin{aligned}W & \xrightarrow{(b, c)} X \times_A V \\ W & \longrightarrow W' \\ W' & \xrightarrow{(b', c')} X' \times_{A'} V' \\ X \times_A V & \longrightarrow X' \times_{A'} V'\end{aligned}\end{gathered}$$ By Lemma Derived tensor products and Tor amplitude $X \times_A V$ and $W'$ are tor-independent over $X' \times_{A'} V'$. Thus the derived pullback of $(b', c')_*\mathcal{O}_{W'}$ to $X \times_A V$ is $(b, c)_*\mathcal{O}_W$ by Derived Categories of Spaces, Lemma Base change for derived quasi-coherent complexes. This also uses that $R(b', c')_*\mathcal{O}_{Z'} = (b', c')_*\mathcal{O}_{Z'}$ because $(b', c')$ is a closed immersion and similarly for $(b, c)_*\mathcal{O}_Z$. Since $E'|_{X' \times_{A'} V'} = (b', c')_*\mathcal{O}_{W'}$ we obtain $E|_{X \times_A V} = (b, c)_*\mathcal{O}_W$ and (4) holds. Derived pullback restricts to zero off the inverse image of the support, so (5) also holds. This reduces us to the situation described in the next paragraph.
Assume $A$ is of finite type over $\mathbf{Z}$. Choose an étale morphism $U \to X$ where $U$ is an affine scheme and a point $u \in U$ mapping to $x$. Then $U$ is of finite type over $A$. Choose a closed immersion $U \to \mathbf{A}^n_A$ and denote $j : U \to \mathbf{P}^n_A$ the immersion we get by composing with the open immersion $\mathbf{A}^n_A \to \mathbf{P}^n_A$. Let $Z$ be the scheme theoretic closure of $$(\text{id}_U, j) : U \longrightarrow X \times_A \mathbf{P}^n_A$$ Let $z \in Z$ be the image of $u$. Let $Y \subset \mathbf{P}^n_A$ be the scheme theoretic closure of $j$. Then it is clear that $Z \subset X \times_A Y$ is the scheme theoretic closure of $(\text{id}_U, j) : U \to X \times_A Y$. As $X$ is separated, the morphism $X \times_A Y \to Y$ is separated as well. Hence we see that $Z \to Y$ is an isomorphism over the open subscheme $j(U) \subset Y$ by Morphisms of Spaces, Lemma Morphisms of algebraic spaces. Choose $V \subset \mathbf{P}^n_A$ open with $V \cap Y = j(U)$. Then we see that (2) holds, that $W = (\text{id}_U, j)(U)$, and hence that (3) holds. Part (1) holds because $A$ is Noetherian.
Because $A$ is Noetherian we see that $X$ and $X \times_A \mathbf{P}^n_A$ are Noetherian algebraic spaces. Hence we can take $E = (b, c)_*\mathcal{O}_Z$ in this case: (4) is clear and for (5) see Derived Categories of Spaces, Lemma Pseudo-coherent complexes and coherent sheaves. This finishes the proof. $\square$
Lemma. The restriction comparison in a derived Chow neighbourhood
Let $X/A$, $x \in |X|$, and $n, Z, z, V, E$ be as in Lemma A derived Chow neighbourhood. For any $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ we have $$Rq_*(Lp^*K \otimes^\mathbf{L} E)|_V = R(W \to V)_*K|_W$$ where $p : X \times_A \mathbf{P}^n_A \to X$ and $q : X \times_A \mathbf{P}^n_A \to \mathbf{P}^n_A$ are the projections and where the morphism $W \to V$ is the finitely presented closed immersion $c|_W : W \to V$.
Proof. Since $W = c^{-1}(V)$ and since $c$ is a closed immersion over $V$, we see that $c|_W$ is a closed immersion. It is of finite presentation because $W$ and $V$ are of finite presentation over $A$, see Morphisms of Spaces, Lemma Finite presentation and finite algebras. First we have $$Rq_*(Lp^*K \otimes^\mathbf{L} E)|_V = Rq'_*\left((Lp^*K \otimes^\mathbf{L} E)|_{X \times_A V}\right)$$ where $q' : X \times_A V \to V$ is the projection because formation of total direct image commutes with localization. Denote $i = (b, c)|_W : W \to X \times_A V$ the given closed immersion. Then $$Rq'_*\left((Lp^*K \otimes^\mathbf{L} E)|_{X \times_A V}\right) = Rq'_*(Lp^*K|_{X \times_A V} \otimes^\mathbf{L} i_*\mathcal{O}_W)$$ by property (4). Since $i$ is a closed immersion we have $i_*\mathcal{O}_W = Ri_*\mathcal{O}_W$. Using Derived Categories of Spaces, Lemma Base change for sheaf cohomology we can rewrite this as $$Rq'_* Ri_* Li^* Lp^*K|_{X \times_A V} = R(q' \circ i)_* Lb^*K|_W = R(W \to V)_* K|_W$$ which is what we want. (Note that restricting to $W$ and derived pulling back via $W \to X$ is the same thing as $W$ is étale over $X$.) $\square$
Lemma. Detecting relative pseudo-coherence by global tests
Let $A$ be a ring. Let $X$ be an algebraic space separated and of finite presentation over $A$. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$. If $R\Gamma(X, E \otimes^\mathbf{L} K)$ is pseudo-coherent in $D(A)$ for every pseudo-coherent $E$ in $D(\mathcal{O}_X)$, then $K$ is pseudo-coherent relative to $A$ (Definition Pseudo-coherent complexes and coherent sheaves).
Proof. Assume $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ and $R\Gamma(X, E \otimes^\mathbf{L} K)$ is pseudo-coherent in $D(A)$ for every pseudo-coherent $E$ in $D(\mathcal{O}_X)$. Let $x \in |X|$. We will show that $K$ is pseudo-coherent relative to $A$ in an étale neighbourhood of $x$. This will prove the lemma by our definition of relative pseudo-coherence.
Choose $n, Z, z, V, E$ as in Lemma A derived Chow neighbourhood. Denote $p : X \times \mathbf{P}^n \to X$ and $q : X \times \mathbf{P}^n \to \mathbf{P}^n_A$ the projections. Then for any $i \in \mathbf{Z}$ we have $$\begin{aligned} & R\Gamma(\mathbf{P}^n_A, Rq_*(Lp^*K \otimes^\mathbf{L} E) \otimes^\mathbf{L} \mathcal{O}_{\mathbf{P}^n_A}(i)) \\ & = R\Gamma(X \times \mathbf{P}^n, Lp^*K \otimes^\mathbf{L} E \otimes^\mathbf{L} Lq^*\mathcal{O}_{\mathbf{P}^n_A}(i)) \\ & = R\Gamma(X, K \otimes^\mathbf{L} Rp_*(E \otimes^\mathbf{L} Lq^*\mathcal{O}_{\mathbf{P}^n_A}(i))) \end{aligned}$$ by Derived Categories of Spaces, Lemma Base change for sheaf cohomology. By Derived Categories of Spaces, Lemma The arbitrary-base proper-support perfect direct-image bridge the complex $Rp_*(E \otimes^\mathbf{L} Lq^*\mathcal{O}_{\mathbf{P}^n_A}(i))$ is pseudo-coherent on $X$. Hence the assumption tells us the expression in the displayed formula is a pseudo-coherent object of $D(A)$. By Derived Categories of Schemes, Lemma Detecting pseudo-coherence on projective space we conclude that $Rq_*(Lp^*K \otimes^\mathbf{L} E)$ is pseudo-coherent on $\mathbf{P}^n_A$. By Lemma The restriction comparison in a derived Chow neighbourhood we have $$Rq_*(Lp^*K \otimes^\mathbf{L} E)|_{X \times_A V} = R(W \to V)_*K|_W$$ Since $W \to V$ is a closed immersion into an open subscheme of $\mathbf{P}^n_A$ this means $K|_W$ is pseudo-coherent relative to $A$ for example by More on Morphisms, Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
[^1]: Here is the argument in more detail. Choose a surjective étale morphism $W' \to B'$ with $W'$ a scheme. Choose a surjective étale morphism $W \to B \times_{B'} W'$ with $W$ a scheme. Choose a surjective étale morphism $U' \to X' \times_{B'} W'$ with $U'$ a scheme. Choose a surjective étale morphism $V' \to Y' \times_{B'} W'$ with $V'$ a scheme. Observe that $U' \times_{W'} V' \to X' \times_{B'} Y'$ is surjective étale. Choose a surjective étale morphism $T' \to Z' \times_{X' \times_{B'} Y'} U' \times_{W'} V'$ with $T'$ a scheme. Denote $U$ and $V$ the base changes of $U'$ and $V'$ to $W$. Then the lemma says that $X \times_B Y$ and $Z'$ are Tor independent over $X' \times_{B'} Y'$ as algebraic spaces if and only if $U \times_W V$ and $T'$ are Tor independent over $U' \times_{W'} V'$ as schemes. Thus it suffices to prove the lemma for the square with corners $T', U', V', W'$ and base change by $W \to W'$. The flatness of $Y' \to B'$ and $Z' \to X'$ implies flatness of $V' \to W'$ and $T' \to U'$.
A.12.6 Uniform section algebras under deformation
The following arguments adapt the human Stacks Project treatment in more-morphisms.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. Uniform section algebras under nilpotent deformation (Deformations of projective schemes)
Let $f : X \to S$ be a morphism of schemes which is proper, flat, and of finite presentation. Let $\mathcal{L}$ be $f$-ample. Assume $S$ is quasi-compact. There exists a $d_0 \geq 0$ such that for every cartesian diagram $$\begin{gathered}\begin{matrix}X & X' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{i'} X' \\ X & \xrightarrow{f} S \\ X' & \xrightarrow{f'} S' \\ S & \xrightarrow{i} S'\end{aligned}\end{gathered} \quad\text{and}\quad \begin{matrix} \text{invertible }\mathcal{O}_{X'}\text{-module}\\ \mathcal{L}'\text{ with }\mathcal{L} \cong (i')^*\mathcal{L}' \end{matrix}$$ where $S \subset S'$ is a thickening and $f'$ is proper, flat, of finite presentation we have
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$R^p(f')_*(\mathcal{L}')^{\otimes d} = 0$ for all $p > 0$ and $d \geq d_0$,
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$\mathcal{A}'_d = (f')_*(\mathcal{L}')^{\otimes d}$ is finite locally free for $d \geq d_0$,
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$\mathcal{A}' = \mathcal{O}_{S'} \oplus \bigoplus_{d \geq d_0} \mathcal{A}'_d$ is a quasi-coherent $\mathcal{O}_{S'}$-algebra of finite presentation,
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there is a canonical isomorphism $r' : X' \to \underline{\text{Proj}}_{S'}(\mathcal{A}')$, and
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there is a canonical isomorphism $\theta' : (r')^*\mathcal{O}_{\underline{\text{Proj}}_{S'}(\mathcal{A}')}(1) \to \mathcal{L}'$.
The construction of $\mathcal{A}'$, $r'$, $\theta'$ is functorial in the data $(X', S', i, i', f', \mathcal{L}')$.
Proof. We first describe the maps $r'$ and $\theta'$. Observe that $\mathcal{L}'$ is $f'$-ample, see Lemma Proper morphisms and line bundles and ampleness. There is a canonical map of quasi-coherent graded $\mathcal{O}_{S'}$-algebras $\mathcal{A}' \to \bigoplus_{d \geq 0} (f')_*(\mathcal{L}')^{\otimes d}$ which is an isomorphism in degrees $\geq d_0$. Hence this induces an isomorphism on relative Proj compatible with the Serre twists of the structure sheaf, see Constructions, Lemma The geometric construction (uncovered prerequisite). Hence we get the morphism $r'$ by Morphisms, Lemma Criteria for line bundles and ampleness (uncovered prerequisite) (which in turn appeals to the construction given in Constructions, Lemma Line bundles and ampleness (uncovered prerequisite)) and it is an isomorphism by Morphisms, Lemma Proper morphisms and line bundles and ampleness (uncovered prerequisite). We get the map $\theta'$ from Constructions, Lemma Line bundles and ampleness (uncovered prerequisite). By Properties, Lemma Line bundles and ampleness we find that $\theta'$ is an isomorphism (this also uses that the morphism $r'$ over affine opens of $S'$ is the same as the morphism from Properties, Lemma Scheme geometry as is explained in the proof of Morphisms, Lemma Proper morphisms and line bundles and ampleness (uncovered prerequisite)).
Assuming the vanishing and local freeness stated in parts (1) and (2), the functoriality of the construction can be seen as follows. Suppose that $h : T \to S'$ is a morphism of schemes, denote $f_T : X'_T \to T$ the base change of $f'$ and $\mathcal{L}_T$ the pullback of $\mathcal{L}$ to $X'_T$. By cohomology and base change (as formulated in Derived Categories of Schemes, Lemma Base change for perfect complexes for example) we have the corresponding vanishing over $T$ and moreover $h^*\mathcal{A}'_d = f_{T, *}\mathcal{L}_T^{\otimes d}$ (and thus the local freeness of pushforwards as well as the finite generation of the corresponding graded $\mathcal{O}_T$-algebra $\mathcal{A}_T$). Hence the morphism $r_T : X_T \to \underline{\text{Proj}}_T(\bigoplus f_{T, *}\mathcal{L}_T^{\otimes d})$ is simply the base change of $r'$ to $T$ and the pullback of $\theta'$ is the map $\theta_T$.
Having said all of the above, we see that it suffices to prove (1), (2), and (3). Pick $d_0$ such that $R^pf_*\mathcal{L}^{\otimes d} = 0$ for all $d \geq d_0$ and $p > 0$, see Cohomology of Schemes, Lemma Coherent sheaves and proper morphisms (uncovered prerequisite). We claim that $d_0$ works.
By cohomology and base change (Derived Categories of Schemes, Lemma Perfect direct images for proper morphisms of finite presentation) we see that $E'_d = Rf'_*(\mathcal{L}')^{\otimes d}$ is a perfect object of $D(\mathcal{O}_{S'})$ and its formation commutes with arbitrary base change. In particular, $E_d = Li^*E'_d = Rf_*\mathcal{L}^{\otimes d}$. By Derived Categories of Schemes, Lemma Vanishing and projective, locally free modules and local algebra we see that for $d \geq d_0$ the complex $E_d$ is isomorphic to the finite locally free $\mathcal{O}_S$-module $f_*\mathcal{L}^{\otimes d}$ placed in cohomological degree $0$. Then by Derived Categories of Schemes, Lemma Sheaf cohomology we conclude that $E'_d$ is isomorphic to a finite locally free module placed in cohomological degree $0$. Of course this means that $E'_d = \mathcal{A}'_d[0]$, that $R^pf'_*(\mathcal{L}')^{\otimes d} = 0$ for $p > 0$, and that $\mathcal{A}'_d$ is finite locally free. This proves (1) and (2).
The last thing we have to show is finite presentation of $\mathcal{A}'$ as a sheaf of $\mathcal{O}_{S'}$-algebras (this notion was introduced in Properties, Section Quasi-coherent complexes and coherent sheaves). Let $U' = \operatorname{Spec}(R') \subset S'$ be an affine open. Then $A' = \mathcal{A}'(U')$ is a graded $R'$-algebra whose graded parts are finite projective $R'$-modules. We have to show that $A'$ is a finitely presented $R'$-algebra. We will prove this by reduction to the Noetherian case. Namely, we can find a finite type $\mathbf{Z}$-subalgebra $R'_0 \subset R'$ and a pair[^1] $(X'_0, \mathcal{L}'_0)$ over $R'_0$ whose base change is $(X'_{U'}, \mathcal{L}'|_{X'_{U'}})$, see Limits, Lemmas Descent of finite presentation and modules, Descent of finite locally free and invertible modules, Proper morphisms, Descent of finite presentation and flatness, and Filtered limits and line bundles and ampleness. Cohomology of Schemes, Lemma Coherent sheaves and proper morphisms (uncovered prerequisite) implies $A'_0 = \bigoplus_{d \geq 0} H^0(X'_0, (\mathcal{L}'_0)^{\otimes d})$ is a finitely generated graded $R'_0$-algebra and implies there exists a $d'_0$ such that $H^p(X'_0, (\mathcal{L}'_0)^{\otimes d}) = 0$, $p > 0$ for $d \geq d'_0$. By the arguments given above applied to $X'_0 \to \operatorname{Spec}(R'_0)$ and $\mathcal{L}'_0$ we see that $(A'_0)_d$ is a finite projective $R'_0$-module and that $$A'_d = \mathcal{A}'_d(U') = H^0(X'_{U'}, (\mathcal{L}')^{\otimes d}|_{X'_{U'}}) = H^0(X'_0, (\mathcal{L}'_0)^{\otimes d}) \otimes_{R'_0} R' = (A'_0)_d \otimes_{R'_0} R'$$ for $d \geq d'_0$. Now a small twist in the argument is that we don't know that we can choose $d'_0$ equal to $d_0$[^2]. To get around this we use the following sequence of arguments to finish the proof:
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The algebra $B = R'_0 \oplus \bigoplus_{d \geq \max(d_0, d'_0)} (A'_0)_d$ is an $R'_0$-algebra of finite type: apply the Artin-Tate lemma to $B \subset A'_0$, see Algebra, Lemma The Artin–Tate lemma.
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As $R'_0$ is Noetherian we see that $B$ is an $R'_0$-algebra of finite presentation.
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By right exactness of tensor product we see that $B \otimes_{R'_0} R'$ is an $R'$-algebra of finite presentation.
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By the displayed equalities this exactly says that $C = R' \oplus \bigoplus_{d \geq \max(d_0, d'_0)} A'_d$ is an $R'$-algebra of finite presentation.
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The quotient $A'/C$ is the direct sum of the finite projective $R'$-modules $A'_d$, $d_0 \leq d \leq \max(d_0, d'_0)$, hence finitely presented as $R'$-module.
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The quotient $A'/C$ is finitely presented as a $C$-module by Algebra, Lemma Finite presentation and finite algebras.
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Thus $A'$ is finitely presented as a $C$-module by Algebra, Lemma Commutative algebra.
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By Algebra, Lemma Finite algebras this implies $A'$ is finitely presented as a $C$-algebra.
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Finally, by Algebra, Lemma Composition of finite-type ring maps applied to $R' \to C \to A'$ this implies $A'$ is finitely presented as an $R'$-algebra.
This finishes the proof. $\square$
Lemma. Separating the proper part over a henselian pair
Source credit: A reference for the case of an adic Noetherian base is the original source citation EGA (III, Proposition 5.5.1)
Let $(A, I)$ be a henselian pair. Let $X \to \operatorname{Spec}(A)$ be separated and of finite type. Set $X_0 = X \times_{\operatorname{Spec}(A)} \operatorname{Spec}(A/I)$. Let $Y \subset X_0$ be an open and closed subscheme such that $Y \to \operatorname{Spec}(A/I)$ is proper. Then there exists an open and closed subscheme $W \subset X$ which is proper over $A$ with $W \times_{\operatorname{Spec}(A)} \operatorname{Spec}(A/I) = Y$.
Proof. We will denote $T \mapsto T_0$ the base change by $\operatorname{Spec}(A/I) \to \operatorname{Spec}(A)$. By Chow's lemma (in the form of Limits, Lemma Finite algebras) there exists a surjective proper morphism $\varphi : X' \to X$ such that $X'$ admits an immersion into $\mathbf{P}^n_A$. Set $Y' = \varphi^{-1}(Y)$. This is an open and closed subscheme of $X'_0$. Suppose the lemma holds for $(X', Y')$. Let $W' \subset X'$ be the open and closed subscheme proper over $A$ such that $Y' = W'_0$. By Morphisms, Lemma Proper morphisms (uncovered prerequisite) $W = \varphi(W') \subset X$ and $Q = \varphi(X' \setminus W') \subset X$ are closed subsets and by Morphisms, Lemma Proper morphisms (uncovered prerequisite) $W$ is proper over $A$. The image of $W \cap Q$ in $\operatorname{Spec}(A)$ is closed. Since $(A, I)$ is henselian, if $W \cap Q$ is nonempty, then we find that $W \cap Q$ has a point lying over $\operatorname{Spec}(A/I)$. This is impossible as $W'_0 = Y' = \varphi^{-1}(Y)$. We conclude that $W$ is an open and closed subscheme of $X$ proper over $A$ with $W_0 = Y$. Thus we reduce to the case described in the next paragraph.
Assume there exists an immersion $j : X \to \mathbf{P}^n_A$ over $A$. Let $\overline{X}$ be the scheme theoretic image of $j$. Since $j$ is a quasi-compact morphism (Schemes, Lemma The geometric construction (uncovered prerequisite)) we see that $j : X \to \overline{X}$ is an open immersion (Morphisms, Lemma Diagonals and separation (uncovered prerequisite)). Hence the base change $j_0 : X_0 \to \overline{X}_0$ is an open immersion as well. Thus $j_0(Y) \subset \overline{X}_0$ is open. It is also closed by Morphisms, Lemma Proper morphisms (uncovered prerequisite). Suppose that the lemma holds for $(\overline{X}, j_0(Y))$. Let $\overline{W} \subset \overline{X}$ be the corresponding open and closed subscheme proper over $A$ such that $j_0(Y) = \overline{W}_0$. Then $T = \overline{W} \setminus j(X)$ is closed in $\overline{W}$, hence has closed image in $\operatorname{Spec}(A)$ by properness of $\overline{W}$ over $A$. Since $(A, I)$ is henselian, we find that if $T$ is nonempty, then there is a point of $T$ mapping into $\operatorname{Spec}(A/I)$. This is impossible because $j_0(Y) = \overline{W}_0$ is contained in $j(X)$. Hence $\overline{W}$ is contained in $j(X)$ and we can set $W \subset X$ equal to the unique open and closed subscheme mapping isomorphically to $\overline{W}$ via $j$. Thus we reduce to the case described in the next paragraph.
Assume $X \subset \mathbf{P}^n_A$ is a closed subscheme. Then $X \to \operatorname{Spec}(A)$ is a proper morphism. Let $Z = X_0 \setminus Y$. This is an open and closed subscheme of $X_0$ and $X_0 = Y \amalg Z$. Let $X \to X' \to \operatorname{Spec}(A)$ be the Stein factorization as in Theorem The geometric construction. Let $Y' \subset X'_0$ and $Z' \subset X'_0$ be the images of $Y$ and $Z$. Since the fibres of $X \to Z$ are geometrically connected, we see that $Y' \cap Z' = \emptyset$. Hence $X'_0 = Y' \amalg Z'$ as $X \to X'$ is surjective. Since $X' \to \operatorname{Spec}(A)$ is integral, we see that $X'$ is the spectrum of an $A$-algebra integral over $A$. Recall that open and closed subsets of spectra correspond $1$-to-$1$ with idempotents in the corresponding ring, see Algebra, Lemma Product decompositions from disjoint closed subsets. Hence by More on Algebra, Lemma Criteria for henselian rings we see that we may write $X' = W' \amalg V'$ with $W'$ and $V'$ open and closed and with $Y' = W'_0$ and $Z' = V'_0$. Let $W$ be the inverse image in $X$ to finish the proof. $\square$
[^1]: With the same properties as those enjoyed by $X' \to S'$ and $\mathcal{L}'$, i.e., $X'_0 \to \operatorname{Spec}(R'_0)$ is flat and proper and $\mathcal{L}'_0$ is ample.
[^2]: Actually, one can reduce to this case by doing more limit arguments.
A.12.7 Purity, universal flattening and strong coherent existence
The following arguments adapt the human Stacks Project treatment in spaces-flat.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. Universal purity from proper support
In Situation Purity near a specified fibre.
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If the support of $\mathcal{F}$ is proper over $Y$, then $\mathcal{F}$ is universally pure relative to $Y$.
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If $f$ is proper, then $\mathcal{F}$ is universally pure relative to $Y$.
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If $f$ is proper, then $X$ is universally pure relative to $Y$.
Proof. First we reduce (1) to (2). Namely, let $Z \subset X$ be the scheme theoretic support of $\mathcal{F}$ (Morphisms of Spaces, Definition Closed support). Let $i : Z \to X$ be the corresponding closed immersion and write $\mathcal{F} = i_*\mathcal{G}$ for some finite type quasi-coherent $\mathcal{O}_Z$-module $\mathcal{G}$. In case (1) $Z \to Y$ is proper by assumption. Thus by Lemma A module supported on a closed subspace case (1) reduces to case (2).
Assume $f$ is proper. Let $(g : T \to Y, t' \leadsto t, \xi)$ be an impurity of $\mathcal{F}$ above $y$. Since $f$ is proper, it is universally closed. Hence $f_T : X_T \to T$ is closed. Since $f_T(\xi) = t'$ this implies that $t \in f(\overline{\{\xi\}})$ which is a contradiction. $\square$
Lemma. Complete dévissage around a fibre
Let $S$ be a scheme. Let $X \to Y$ be a finite type morphism of algebraic spaces over $S$. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Let $y \in |Y|$ be a point. There exists an étale morphism $(Y', y') \to (Y, y)$ with $Y'$ an affine scheme and étale morphisms $h_i : W_i \to X_{Y'}$, $i = 1, \ldots, n$ such that for each $i$ there exists a complete dévissage of $\mathcal{F}_i/W_i/Y'$ over $y'$, where $\mathcal{F}_i$ is the pullback of $\mathcal{F}$ to $W_i$ and such that $|(X_{Y'})_{y'}| \subset \bigcup h_i(W_i)$.
Proof. The question is étale local on $Y$ hence we may assume $Y$ is an affine scheme. Then $X$ is quasi-compact, hence we can choose an affine scheme $X'$ and a surjective étale morphism $X' \to X$. Then we may apply More on Flatness, Lemma Complete dévissage around a fibre to $X' \to Y$, $(X' \to Y)^*\mathcal{F}$, and $y$ to get what we want. $\square$
Theorem. Universal flattening for a pure finitely presented module
In Situation The universal flatness dimension stratum. Assume moreover that $f$ is of finite presentation, that $\mathcal{F}$ is an $\mathcal{O}_X$-module of finite presentation, and that $\mathcal{F}$ is pure relative to $Y$. Then $F_n$ is an algebraic space and $F_n \to Y$ is a monomorphism of finite presentation.
Proof. The functor $F_n$ is a sheaf for the fppf topology by Lemma The flatness dimension stratum. Since $F_n \to Y$ is a monomorphism of sheaves on $(\mathrm{Sch}/S)_{fppf}$ we see that $\Delta : F_n \to F_n \times F_n$ is the pullback of the diagonal $\Delta_Y : Y \to Y \times_S Y$. Hence the representability of $\Delta_Y$ implies the same thing for $F_n$. Therefore it suffices to prove that there exists a scheme $W$ over $S$ and a surjective étale morphism $W \to F_n$.
To construct $W \to F_n$ choose an étale covering $\{Y_i \to Y\}$ with $Y_i$ a scheme. Let $X_i = X \times_Y Y_i$ and let $\mathcal{F}_i$ be the pullback of $\mathcal{F}$ to $X_i$. Then $\mathcal{F}_i$ is pure relative to $Y_i$ either by definition or by Lemma Quasi-finite base change. The other assumptions of the theorem are preserved as well. Finally, the restriction of $F_n$ to $Y_i$ is the functor $F_n$ corresponding to $X_i \to Y_i$ and $\mathcal{F}_i$. Hence it suffices to show: Given $\mathcal{F}$ and $f : X \to Y$ as in the statement of the theorem where $Y$ is a scheme, the functor $F_n$ is representable by a scheme $Z_n$ and $Z_n \to Y$ is a monomorphism of finite presentation.
Observe that a monomorphism of finite presentation is separated and quasi-finite (Morphisms, Lemma Finite algebras (uncovered prerequisite)). Hence combining Descent, Lemma Descent of the geometric construction, More on Morphisms, Lemma Diagonals, separation and finite algebras , and Descent, Lemmas Descent of proper morphisms and Descent of finite presentation and proper morphisms we see that the question is local for the étale topology on $Y$.
In particular the situation is local for the Zariski topology on $Y$ and we may assume that $Y$ is affine. In this case the dimension of the fibres of $f$ is bounded above, hence we see that $F_n$ is representable for $n$ large enough. Thus we may use descending induction on $n$. Suppose that we know $F_{n + 1}$ is representable by a monomorphism $Z_{n + 1} \to Y$ of finite presentation. Consider the base change $X_{n + 1} = Z_{n + 1} \times_Y X$ and the pullback $\mathcal{F}_{n + 1}$ of $\mathcal{F}$ to $X_{n + 1}$. The morphism $Z_{n + 1} \to Y$ is quasi-finite as it is a monomorphism of finite presentation, hence Lemma Quasi-finite base change implies that $\mathcal{F}_{n + 1}$ is pure relative to $Z_{n + 1}$. Since $F_n$ is a subfunctor of $F_{n + 1}$ we conclude that in order to prove the result for $F_n$ it suffices to prove the result for the corresponding functor for the situation $\mathcal{F}_{n + 1}/X_{n + 1}/Z_{n + 1}$. In this way we reduce to proving the result for $F_n$ in case $Y_{n + 1} = Y$, i.e., we may assume that $\mathcal{F}$ is flat in dimensions $\geq n + 1$ over $Y$.
Fix $n$ and assume $\mathcal{F}$ is flat in dimensions $\geq n + 1$ over the affine scheme $Y$. To finish the proof we have to show that $F_n$ is representable by a monomorphism $Z_n \to S$ of finite presentation. Since the question is local in the étale topology on $Y$ it suffices to show that for every $y \in Y$ there exists an étale neighbourhood $(Y', y') \to (Y, y)$ such that the result holds after base change to $Y'$. Thus by Lemma Complete dévissage around a fibre we may assume there exist étale morphisms $h_j : W_j \to X$, $j = 1, \ldots, m$ such that for each $j$ there exists a complete dévissage of $\mathcal{F}_j/W_j/Y$ over $y$, where $\mathcal{F}_j$ is the pullback of $\mathcal{F}$ to $W_j$ and such that $|X_y| \subset \bigcup h_j(W_j)$. Since $h_j$ is étale, by Lemma The local flatness dimension test the sheaves $\mathcal{F}_j$ are still flat over in dimensions $\geq n + 1$ over $Y$. Set $W = \bigcup h_j(W_j)$, which is a quasi-compact open of $X$. As $\mathcal{F}$ is pure along $X_y$ we see that $$E = \{t \in |Y| : \text{Ass}_{X_t}(\mathcal{F}_t) \subset W \}.$$ contains all generalizations of $y$. By Divisors on Spaces, Lemma Prime spectra and associated points $E$ is a constructible subset of $Y$. We have seen that $\operatorname{Spec}(\mathcal{O}_{Y, y}) \subset E$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) we see that $E$ contains an open neighbourhood of $y$. Hence after shrinking $Y$ we may assume that $E = Y$. It follows from Lemma Localization of a flatness dimension stratum that it suffices to prove the lemma for the functor $F_n$ associated to $X = \coprod W_j$ and $\mathcal{F} = \coprod \mathcal{F}_j$. If $F_{j, n}$ denotes the functor for $W_j \to Y$ and the sheaf $\mathcal{F}_j$ we see that $F_n = \prod F_{j, n}$. Hence it suffices to prove each $F_{j, n}$ is representable by some monomorphism $Z_{j, n} \to Y$ of finite presentation, since then $$Z_n = Z_{1, n} \times_Y \ldots \times_Y Z_{m, n}$$ Thus we have reduced the theorem to the special case handled in More on Flatness, Lemma Representing a flatness dimension stratum. $\square$
Lemma. The hypotheses for universal flattening
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module.
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If $f$ is of finite presentation, $\mathcal{F}$ is an $\mathcal{O}_X$-module of finite presentation, and $\mathcal{F}$ is pure relative to $Y$, then there exists a universal flattening $Y' \to Y$ of $\mathcal{F}$. Moreover $Y' \to Y$ is a monomorphism of finite presentation.
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If $f$ is of finite presentation and $X$ is pure relative to $Y$, then there exists a universal flattening $Y' \to Y$ of $X$. Moreover $Y' \to Y$ is a monomorphism of finite presentation.
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If $f$ is proper and of finite presentation and $\mathcal{F}$ is an $\mathcal{O}_X$-module of finite presentation, then there exists a universal flattening $Y' \to Y$ of $\mathcal{F}$. Moreover $Y' \to Y$ is a monomorphism of finite presentation.
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If $f$ is proper and of finite presentation then there exists a universal flattening $Y' \to Y$ of $X$.
Proof. These statements follow immediately from Theorem Universal flattening for a pure finitely presented module applied to $F_0 = F_{flat}$ and the fact that if $f$ is proper then $\mathcal{F}$ is automatically pure over the base, see Lemma Universal purity from proper support. $\square$
Situation. The marked inverse system for coherent existence
Here we have an inverse system of rings $(A_n)$ with surjective transition maps whose kernels are locally nilpotent. Set $A = \varprojlim A_n$. We have an algebraic space $X$ separated and of finite presentation over $A$. We set $X_n = X \times_{\operatorname{Spec}(A)} \operatorname{Spec}(A_n)$ and we view it as a closed subspace of $X$. We assume further given a system $(\mathcal{F}_n, \varphi_n)$ where $\mathcal{F}_n$ is a finitely presented $\mathcal{O}_{X_n}$-module, flat over $A_n$, with support proper over $A_n$, and $$\varphi_n : \mathcal{F}_n \otimes_{\mathcal{O}_{X_n}} \mathcal{O}_{X_{n - 1}} \longrightarrow \mathcal{F}_{n - 1}$$ is an isomorphism (notation using the equivalence of Morphisms of Spaces, Lemma Groupoids and equivalence relations).
Lemma. The derived quasi-coherent inverse limit
In Situation The marked inverse system for coherent existence consider $$K = R\varprojlim_{D_\mathrm{QCoh}(\mathcal{O}_X)}(\mathcal{F}_n) = DQ_X(R\varprojlim_{D(\mathcal{O}_X)}\mathcal{F}_n)$$ Then $K$ is in $D^b_{\mathrm{QCoh}}(\mathcal{O}_X)$ and in fact $K$ has nonzero cohomology sheaves only in degrees $\geq 0$.
Proof. Special case of Derived Categories of Spaces, Example Quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Computing the inverse limit against perfect complexes
In Situation The marked inverse system for coherent existence let $K$ be as in Lemma The derived quasi-coherent inverse limit. For any perfect object $E$ of $D(\mathcal{O}_X)$ we have
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$M = R\Gamma(X, K \otimes^\mathbf{L} E)$ is a perfect object of $D(A)$ and there is a canonical isomorphism $R\Gamma(X_n, \mathcal{F}_n \otimes^\mathbf{L} E|_{X_n}) = M \otimes_A^\mathbf{L} A_n$ in $D(A_n)$,
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$N = R\operatorname{Hom}_X(E, K)$ is a perfect object of $D(A)$ and there is a canonical isomorphism $R\operatorname{Hom}_{X_n}(E|_{X_n}, \mathcal{F}_n) = N \otimes_A^\mathbf{L} A_n$ in $D(A_n)$.
In both statements $E|_{X_n}$ denotes the derived pullback of $E$ to $X_n$.
Proof. Proof of (2). Write $E_n = E|_{X_n}$ and $N_n = R\operatorname{Hom}_{X_n}(E_n, \mathcal{F}_n)$. Recall that $R\operatorname{Hom}_{X_n}(-, -)$ is equal to $R\Gamma(X_n, R\mathcal{H}om(-, -))$, see Cohomology on Sites, Section Derived Hom and Ext. Hence by Derived Categories of Spaces, Lemma Perfect proper-support derived Hom over arbitrary bases we see that $N_n$ is a perfect object of $D(A_n)$ whose formation commutes with base change. Thus the maps $N_n \otimes_{A_n}^\mathbf{L} A_{n - 1} \to N_{n - 1}$ coming from $\varphi_n$ are isomorphisms. By More on Algebra, Lemma Perfect inverse limits we find that $R\varprojlim N_n$ is perfect and that its base change back to $A_n$ recovers $N_n$. On the other hand, the exact functor $R\operatorname{Hom}_X(E, -) : D_\mathrm{QCoh}(\mathcal{O}_X) \to D(A)$ of triangulated categories commutes with products and hence with derived limits, whence $$R\operatorname{Hom}_X(E, K) = R\varprojlim R\operatorname{Hom}_X(E, \mathcal{F}_n) = R\varprojlim R\operatorname{Hom}_X(E_n, \mathcal{F}_n) = R\varprojlim N_n$$ This proves (2). To see that (1) holds, translate it into (2) using Cohomology on Sites, Lemma Perfect complexes and derived categories. $\square$
Lemma. Relative pseudo-coherence of the inverse limit
In Situation The marked inverse system for coherent existence let $K$ be as in Lemma The derived quasi-coherent inverse limit. Then $K$ is pseudo-coherent relative to $A$.
Proof. Combinging Lemma Computing the inverse limit against perfect complexes and Derived Categories of Spaces, Lemma Detecting a complex by perfect tests we see that $R\Gamma(X, K \otimes^\mathbf{L} E)$ is pseudo-coherent in $D(A)$ for all pseudo-coherent $E$ in $D(\mathcal{O}_X)$. Thus the lemma follows from More on Morphisms of Spaces, Lemma Detecting relative pseudo-coherence by global tests. $\square$
Lemma. The marked comparison on an affine étale chart
In Situation The marked inverse system for coherent existence let $K$ be as in Lemma The derived quasi-coherent inverse limit. For any étale morphism $U \to X$ with $U$ quasi-compact and quasi-separated we have $$R\Gamma(U, K) \otimes_A^\mathbf{L} A_n = R\Gamma(U_n, \mathcal{F}_n)$$ in $D(A_n)$ where $U_n = U \times_X X_n$.
Proof. Fix $n$. By Derived Categories of Spaces, Lemma Derived quasi-coherent complexes there exists a system of perfect complexes $E_m$ on $X$ such that $R\Gamma(U, K) = \text{hocolim} R\Gamma(X, K \otimes^\mathbf{L} E_m)$. In fact, this formula holds not just for $K$ but for every object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Applying this to $\mathcal{F}_n$ we obtain $$\begin{aligned} R\Gamma(U_n, \mathcal{F}_n) & = R\Gamma(U, \mathcal{F}_n) \\ & = \text{hocolim}_m R\Gamma(X, \mathcal{F}_n \otimes^\mathbf{L} E_m) \\ & = \text{hocolim}_m R\Gamma(X_n, \mathcal{F}_n \otimes^\mathbf{L} E_m|_{X_n}) \end{aligned}$$ Using Lemma Computing the inverse limit against perfect complexes and the fact that $- \otimes_A^\mathbf{L} A_n$ commutes with homotopy colimits we obtain the result. $\square$
Lemma. Finite presentation near the common closed fibre
In Situation The marked inverse system for coherent existence let $K$ be as in Lemma The derived quasi-coherent inverse limit. Denote $X_0 \subset |X|$ the closed subset consisting of points lying over the closed subset $\operatorname{Spec}(A_1) = \operatorname{Spec}(A_2) = \ldots$ of $\operatorname{Spec}(A)$. There exists an open subspace $W \subset X$ containing $X_0$ such that
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$H^i(K)|_W$ is zero unless $i = 0$,
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$\mathcal{F} = H^0(K)|_W$ is of finite presentation, and
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$\mathcal{F}_n = \mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{O}_{X_n}$.
Proof. Fix $n \geq 1$. By construction there is a canonical map $K \to \mathcal{F}_n$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and hence a canonical map $H^0(K) \to \mathcal{F}_n$ of quasi-coherent sheaves. This explains the meaning of part (3).
Let $x \in X_0$ be a point. We will find an open neighbourhood $W$ of $x$ such that (1), (2), and (3) are true. Since $X_0$ is quasi-compact this will prove the lemma. Let $U \to X$ be an étale morphism with $U$ affine and $u \in U$ a point mapping to $x$. Since $|U| \to |X|$ is open it suffices to find an open neighbourhood of $u$ in $U$ where (1), (2), and (3) are true. Say $U = \operatorname{Spec}(B)$. Choose a surjection $P \to B$ with $P$ smooth over $A$. By Lemma Relative pseudo-coherence of the inverse limit and the definition of relative pseudo-coherence there exists a bounded above complex $F^\bullet$ of finite free $P$-modules representing $Ri_*K$ where $i : U \to \operatorname{Spec}(P)$ is the closed immersion induced by the presentation. Let $M_n$ be the $B$-module corresponding to $\mathcal{F}_n|_U$. By Lemma The marked comparison on an affine étale chart $$H^i(F^\bullet \otimes_A A_n) = \left\{ \begin{matrix} 0 & \text{if} & i \not = 0 \\ M_n & \text{if} & i = 0 \end{matrix} \right.$$ Let $i$ be the maximal index such that $F^i$ is nonzero. If $i \leq 0$, then (1), (2), and (3) are true. If not, then $i > 0$ and we see that the rank of the map $$F^{i - 1} \to F^i$$ in the point $u$ is maximal. Hence in an open neighbourhood of $u$ inside $\operatorname{Spec}(P)$ the rank is maximal. Thus after replacing $P$ by a principal localization we may assume that the displayed map is surjective. Since $F^i$ is finite free we may choose a splitting $F^{i - 1} = F' \oplus F^i$. Then we may replace $F^\bullet$ by the complex $$\ldots \to F^{i - 2} \to F' \to 0 \to \ldots$$ and we win by induction on $i$. $\square$
Theorem. Strong coherent existence (Grothendieck Existence Theorem)
In Situation The marked inverse system for coherent existence there exists a finitely presented $\mathcal{O}_X$-module $\mathcal{F}$, flat over $A$, with support proper over $A$, such that $\mathcal{F}_n = \mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{O}_{X_n}$ for all $n$ compatibly with the maps $\varphi_n$.
Proof. Apply Lemmas The derived quasi-coherent inverse limit, Computing the inverse limit against perfect complexes, Relative pseudo-coherence of the inverse limit, The marked comparison on an affine étale chart, Finite presentation near the common closed fibre, and Fitting support and the proper-support existence argument to get an open subspace $W \subset X$ containing all points lying over $\operatorname{Spec}(A_n)$ and a finitely presented $\mathcal{O}_W$-module $\mathcal{F}$ whose support is proper over $A$ with $\mathcal{F}_n = \mathcal{F} \otimes_{\mathcal{O}_W} \mathcal{O}_{X_n}$ for all $n \geq 1$. (This makes sense as $X_n \subset W$.) By Lemma Universal purity from proper support we see that $\mathcal{F}$ is universally pure relative to $\operatorname{Spec}(A)$. By Theorem Universal flattening for a pure finitely presented module (for explanation, see Lemma The hypotheses for universal flattening) there exists a universal flattening $S' \to \operatorname{Spec}(A)$ of $\mathcal{F}$ and moreover the morphism $S' \to \operatorname{Spec}(A)$ is a monomorphism of finite presentation. In particular $S'$ is a scheme (this follows from the proof of the theorem but it also follows a postoriori by Morphisms of Spaces, Proposition Diagonals, separation and finite algebras). Since the base change of $\mathcal{F}$ to $\operatorname{Spec}(A_n)$ is $\mathcal{F}_n$ we find that $\operatorname{Spec}(A_n) \to \operatorname{Spec}(A)$ factors (uniquely) through $S'$ for each $n$. By More on Flatness, Lemma Recovering a monomorphism from a locally nilpotent tower we see that $S' = \operatorname{Spec}(A)$. This means that $\mathcal{F}$ is flat over $A$. Finally, since the scheme theoretic support $Z$ of $\mathcal{F}$ is proper over $\operatorname{Spec}(A)$, the morphism $Z \to X$ is closed. Hence the pushforward $(W \to X)_*\mathcal{F}$ is supported on $W$ and has all the desired properties. $\square$
Lemma. The local flatness dimension test
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $n \geq 0$. The following are equivalent
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for some commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{\varphi} X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ with surjective, étale vertical arrows where $U$ and $V$ are schemes, the sheaf $\varphi^*\mathcal{F}$ is flat over $V$ in dimensions $\geq n$ (More on Flatness, Definition Flatness and dimension of a fibre module),
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for every commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{\varphi} X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ with étale vertical arrows where $U$ and $V$ are schemes, the sheaf $\varphi^*\mathcal{F}$ is flat over $V$ in dimensions $\geq n$, and
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for $x \in |X|$ such that $\mathcal{F}$ is not flat at $x$ over $Y$ the transcendence degree of $x/f(x)$ is $< n$ (Morphisms of Spaces, Definition The dimension of a fibre).
If this is true, then it remains true after any base change $Y' \to Y$.
Proof. Suppose that we have a diagram as in (1). Then the equivalence of the conditions in More on Flatness, Lemma The local flatness dimension test shows that (1) and (3) are equivalent. But condition (3) is inherited by $\varphi^*\mathcal{F}$ for any $U \to V$ as in (2). Whence we see that (3) implies (2) by the result for schemes again. The result for schemes also implies the statement on base change. $\square$
Definition. Flatness and dimension of a fibre module
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $n \geq 0$. We say $\mathcal{F}$ is flat over $Y$ in dimensions $\geq n$ if the equivalent conditions of Lemma The local flatness dimension test are satisfied.
Situation. The universal flatness dimension stratum
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. For any scheme $T$ over $Y$ we will denote $\mathcal{F}_T$ the base change of $\mathcal{F}$ to $T$, in other words, $\mathcal{F}_T$ is the pullback of $\mathcal{F}$ via the projection morphism $X_T = X \times_Y T \to X$. Note that $f_T : X_T \to T$ is of finite type and that $\mathcal{F}_T$ is an $\mathcal{O}_{X_T}$-module of finite type (Morphisms of Spaces, Lemma Base change for finite algebras and Modules on Sites, Lemma Local pullback on a ringed site). Let $n \geq 0$. By Definition Flatness and dimension of a fibre module and Lemma The local flatness dimension test we obtain a functor
$$F_n : (\mathrm{Sch}/Y)^{opp} \longrightarrow \textit{Sets}, \quad T \longrightarrow \left\{ \begin{matrix} \{*\} & \text{if }\mathcal{F}_T\text{ is flat over }T\text{ in }\dim \geq n, \\ \emptyset & \text{else.} \end{matrix} \right.$$Lemma. The flatness dimension stratum
In Situation The universal flatness dimension stratum.
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The functor $F_n$ satisfies the sheaf property for the fpqc topology.
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If $f$ is quasi-compact and locally of finite presentation and $\mathcal{F}$ is of finite presentation, then the functor $F_n$ is limit preserving.
Proof. Proof of (1). Suppose that $\{T_i \to T\}$ is an fpqc covering of a scheme $T$ over $Y$. We have to show that if $F_n(T_i)$ is nonempty for all $i$, then $F_n(T)$ is nonempty. Choose a diagram as in part (1) of Lemma The local flatness dimension test. Denote $F'_n$ the corresponding functor for $\varphi^*\mathcal{F}$ and the morphism $U \to V$. By More on Flatness, Lemma The flatness dimension stratum we have the sheaf property for $F'_n$. Thus we get the sheaf property for $F_n$ because for $T \to Y$ we have $F_n(T) = F'_n(V \times_Y T)$ by Lemma The local flatness dimension test and because $\{V \times_Y T_i \to V \times_Y T\}$ is an fpqc covering.
Proof of (2). Suppose that $T = \varprojlim_{i \in I} T_i$ is a filtered limit of affine schemes $T_i$ over $Y$ and assume that $F_n(T)$ is nonempty. We have to show that $F_n(T_i)$ is nonempty for some $i$. Choose a diagram as in part (1) of Lemma The local flatness dimension test. Fix $i \in I$ and choose an affine open $W_i \subset V \times_Y T_i$ mapping surjectively onto $T_i$. For $i' \geq i$ let $W_{i'}$ be the inverse image of $W_i$ in $V \times_Y T_{i'}$ and let $W \subset V \times_Y T$ be the inverse image of $W_i$. Then $W = \varprojlim_{i' \geq i} W_i$ is a filtered limit of affine schemes over $V$. By Lemma The local flatness dimension test again it suffices to show that $F'_n(W_{i'})$ is nonempty for some $i' \geq i$. But we know that $F'_n(W)$ is nonempty because of our assumption that $F_n(T) = F'_n(V \times_Y T)$ is nonempty. Thus we can apply More on Flatness, Lemma The flatness dimension stratum to conclude. $\square$
Lemma. Localization of a flatness dimension stratum
In Situation The universal flatness dimension stratum. Let $h : X' \to X$ be an étale morphism. Set $\mathcal{F}' = h^*\mathcal{F}$ and $f' = f \circ h$. Let $F_n'$ be (the displayed identity) associated to $(f' : X' \to Y, \mathcal{F}')$. Then $F_n$ is a subfunctor of $F_n'$ and if $h(X') \supset \text{Ass}_{X/Y}(\mathcal{F})$, then $F_n = F'_n$.
Proof. Choose $U \to X$, $V \to Y$, $U \to V$ as in part (1) of Lemma The local flatness dimension test. Choose a surjective étale morphism $U' \to U \times_X X'$ where $U'$ is a scheme. Then we have the lemma for the two functors $F_{U, n}$ and $F_{U', n}$ determined by $U' \to U$ and $\mathcal{F}|_U$ over $V$, see More on Flatness, Lemma Localization of a flatness dimension stratum. On the other hand, Lemma The local flatness dimension test tells us that given $T \to Y$ we have $F_n(T) = F_{U, n}(V \times_Y T)$ and $F'_n(T) = F_{U', n}(V \times_Y T)$. This proves the lemma. $\square$
A.12.8 Patching flat algebraic spaces and modules
The following arguments adapt the human Stacks Project treatment in spaces-pushouts.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. Algebraic spaces over a pushout
In the situation of Lemma Categories of spaces over a pushout the functor $F \circ G$ is isomorphic to the identity functor.
Proof. We will prove that $F \circ G$ is isomorphic to the identity by reducing this to the corresponding statement of More on Morphisms, Lemma Groupoids and equivalence relations.
Choose a scheme $Y_1$ and a surjective étale morphism $Y_1 \to Y$. Set $X_1 = Y_1 \times_Y X$. This is a scheme affine over $Y_1$ with a surjective étale morphism $X_1 \to X$. By More on Morphisms of Spaces, Lemma Nilpotent thickenings and groupoids and equivalence relations there exists a $X'_1 \to X'$ surjective étale with $X_1 = X_1' \times_{X'} X$. In particular the morphism of schemes $X_1 \to X_1'$ is a thickening too. Apply More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces to obtain a pushout $Y_1' = Y_1 \amalg_{X_1} X_1'$ in the category of schemes. In the proof of Lemma Pushouts along a thickening of algebraic spaces we constructed $Y'$ as a quotient of an étale equivalence relation on $Y_1'$ such that we get a commutative diagram
$$\begin{gathered}\begin{matrix}\phantom{X} & X & \phantom{X} & X' \\ X_1 & \phantom{X} & X_1' & \phantom{X} \\ \phantom{X} & Y & \phantom{X} & Y' \\ Y_1 & \phantom{X} & Y_1'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow X' \\ X & \longrightarrow Y \\ X' & \longrightarrow Y' \\ X_1 & \longrightarrow X_1' \\ X_1 & \longrightarrow Y_1 \\ X_1 & \longrightarrow X \\ X_1' & \longrightarrow Y_1' \\ X_1' & \longrightarrow X' \\ Y & \longrightarrow Y' \\ Y_1 & \longrightarrow Y_1' \\ Y_1 & \longrightarrow Y \\ Y_1' & \longrightarrow Y'\end{aligned}\end{gathered}$$ where all squares except the front and back squares are cartesian (the front and back squares are pushouts) and the northeast arrows are surjective étale. Denote $F_1$, $G_1$ the functors constructed in More on Morphisms, Lemma Groupoids and equivalence relations for the front square. Then the diagram of categories $$\begin{gathered}\begin{matrix}(\mathrm{Sch}/Y_1') & (\mathrm{Sch}/Y_1) \times_{(\mathrm{Sch}/X_1)} (\mathrm{Sch}/X_1') \\ (\textit{Spaces}/Y') & (\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X')\end{matrix} \\[6pt] \begin{aligned}(\mathrm{Sch}/Y_1') & \xrightarrow{F_1} (\mathrm{Sch}/Y_1) \times_{(\mathrm{Sch}/X_1)} (\mathrm{Sch}/X_1') \\ (\mathrm{Sch}/Y_1') & \longrightarrow (\textit{Spaces}/Y') \\ (\mathrm{Sch}/Y_1) \times_{(\mathrm{Sch}/X_1)} (\mathrm{Sch}/X_1') & \longrightarrow (\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X') \\ (\mathrm{Sch}/Y_1) \times_{(\mathrm{Sch}/X_1)} (\mathrm{Sch}/X_1') & \xrightarrow{G_1} (\mathrm{Sch}/Y_1') \\ (\textit{Spaces}/Y') & \xrightarrow{F} (\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X') \\ (\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X') & \xrightarrow{G} (\textit{Spaces}/Y')\end{aligned}\end{gathered}$$ is commutative by simple considerations regarding base change functors and the agreement of pushouts in schemes with pushouts in spaces of Lemma Pushouts along a thickening of schemes.
Let $(V, U', \varphi)$ be an object of $(\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X')$. Denote $U = U' \times_{X'} X$ so that $G(V, U', \varphi) = V \amalg_U U'$. Choose a scheme $V_1$ and a surjective étale morphism $V_1 \to Y_1 \times_Y V$. Set $U_1 = V_1 \times_Y X$. Then $$U_1 = V_1 \times_Y X \longrightarrow (Y_1 \times_Y V) \times_Y X = X_1 \times_Y V = X_1 \times_X X \times_Y V = X_1 \times_X U$$ is surjective étale too. By More on Morphisms of Spaces, Lemma Nilpotent thickenings and groupoids and equivalence relations there exists a thickening $U_1 \to U_1'$ and a surjective étale morphism $U_1' \to X_1' \times_{X'} U'$ whose base change to $X_1 \times_X U$ is the displayed morphism. At this point $(V_1, U'_1, \varphi_1)$ is an object of $(\mathrm{Sch}/Y_1) \times_{(\mathrm{Sch}/X_1)} (\mathrm{Sch}/X_1')$. In the proof of Lemma Pushouts along a thickening of algebraic spaces we constructed $G(V, U', \varphi) = V \amalg_U U'$ as a quotient of an étale equivalence relation on $G_1(V_1, U_1', \varphi_1) = V_1 \amalg_{U_1} U_1'$ such that we get a commutative diagram
$$\begin{gathered}\begin{matrix}\phantom{X} & U & \phantom{X} & U' \\ U_1 & \phantom{X} & U_1' & \phantom{X} \\ \phantom{X} & V & \phantom{X} & G(V, U', \varphi) \\ V_1 & \phantom{X} & G_1(V_1, U_1', \varphi_1)\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow U' \\ U & \longrightarrow V \\ U' & \longrightarrow G(V, U', \varphi) \\ U_1 & \longrightarrow U_1' \\ U_1 & \longrightarrow V_1 \\ U_1 & \longrightarrow U \\ U_1' & \longrightarrow G_1(V_1, U_1', \varphi_1) \\ U_1' & \longrightarrow U' \\ V & \longrightarrow G(V, U', \varphi) \\ V_1 & \longrightarrow G_1(V_1, U_1', \varphi_1) \\ V_1 & \longrightarrow V \\ G_1(V_1, U_1', \varphi_1) & \longrightarrow G(V, U', \varphi)\end{aligned}\end{gathered}$$ where all squares except the front and back squares are cartesian (the front and back squares are pushouts) and the northeast arrows are surjective étale. In particular $$G_1(V_1, U_1', \varphi_1) \to G(V, U', \varphi)$$ is surjective étale.
Finally, we come to the proof of the lemma. We have to show that the adjunction mapping $(V, U', \varphi) \to F(G(V, U', \varphi))$ is an isomorphism. We know $(V_1, U_1', \varphi_1) \to F_1(G_1(V_1, U_1', \varphi_1))$ is an isomorphism by More on Morphisms, Lemma Groupoids and equivalence relations. Recall that $F$ and $F_1$ are given by base change. Using the properties of (the displayed identity) and Lemma The cartesian squares defining the pushout we see that $V \to G(V, U', \varphi) \times_{Y'} Y$ and $U' \to G(V, U', \varphi) \times_{Y'} X'$ are isomorphisms, i.e., $(V, U', \varphi) \to F(G(V, U', \varphi))$ is an isomorphism. $\square$
Lemma. Flat module patching over an algebraic-space pushout
Let $S$ be a base scheme. Let $X \to X'$ be a thickening of algebraic spaces over $S$ and let $X \to Y$ be an affine morphism of algebraic spaces over $S$. Let $Y' = Y \amalg_X X'$ be the pushout (see Lemma Pushouts along a thickening of algebraic spaces). Let $V' \to Y'$ be a morphism of algebraic spaces over $S$. Set $V = Y \times_{Y'} V'$, $U' = X' \times_{Y'} V'$, and $U = X \times_{Y'} V'$. There is an equivalence of categories between
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quasi-coherent $\mathcal{O}_{V'}$-modules flat over $Y'$, and
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the category of triples $(\mathcal{G}, \mathcal{F}', \varphi)$ where
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$\mathcal{G}$ is a quasi-coherent $\mathcal{O}_V$-module flat over $Y$,
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$\mathcal{F}'$ is a quasi-coherent $\mathcal{O}_{U'}$-module flat over $X'$, and
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$\varphi : (U \to V)^*\mathcal{G} \to (U \to U')^*\mathcal{F}'$ is an isomorphism of $\mathcal{O}_U$-modules.
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The equivalence maps $\mathcal{G}'$ to $((V \to V')^*\mathcal{G}', (U' \to V')^*\mathcal{G}', can)$. Suppose $\mathcal{G}'$ corresponds to the triple $(\mathcal{G}, \mathcal{F}', \varphi)$. Then
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$\mathcal{G}'$ is a finite type $\mathcal{O}_{V'}$-module if and only if $\mathcal{G}$ and $\mathcal{F}'$ are finite type $\mathcal{O}_Y$ and $\mathcal{O}_{U'}$-modules.
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if $V' \to Y'$ is locally of finite presentation, then $\mathcal{G}'$ is an $\mathcal{O}_{V'}$-module of finite presentation if and only if $\mathcal{G}$ and $\mathcal{F}'$ are $\mathcal{O}_Y$ and $\mathcal{O}_{U'}$-modules of finite presentation.
Proof. A quasi-inverse functor assigns to the triple $(\mathcal{G}, \mathcal{F}', \varphi)$ the fibre product $$(V \to V')_*\mathcal{G} \times_{(U \to V')_*\mathcal{F}} (U' \to V')_*\mathcal{F}'$$ where $\mathcal{F} = (U \to U')^*\mathcal{F}'$. This works, because on affines étale over $V'$ and $Y'$ we recover the equivalence of More on Algebra, Lemma Relative flat modules over a ring fibre product. Details omitted.
Parts (a) and (b) reduce by étale localization (Properties of Spaces, Section Proper morphisms and modules) to the case where $V'$ and $Y'$ are affine in which case the result follows from More on Algebra, Lemmas Modules and tensor products and direct sums and Finite presentation under flat module patching. $\square$
Lemma. Patching flat algebraic spaces
In the situation of Lemma Algebraic spaces over a pushout. If $V' = G(V, U', \varphi)$ for some triple $(V, U', \varphi)$, then
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$V' \to Y'$ is locally of finite type if and only if $V \to Y$ and $U' \to X'$ are locally of finite type,
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$V' \to Y'$ is flat if and only if $V \to Y$ and $U' \to X'$ are flat,
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$V' \to Y'$ is flat and locally of finite presentation if and only if $V \to Y$ and $U' \to X'$ are flat and locally of finite presentation,
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$V' \to Y'$ is smooth if and only if $V \to Y$ and $U' \to X'$ are smooth,
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$V' \to Y'$ is étale if and only if $V \to Y$ and $U' \to X'$ are étale, and
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add more here as needed.
If $W'$ is flat over $Y'$, then the adjunction mapping $G(F(W')) \to W'$ is an isomorphism. Hence $F$ and $G$ define mutually quasi-inverse functors between the category of spaces flat over $Y'$ and the category of triples $(V, U', \varphi)$ with $V \to Y$ and $U' \to X'$ flat.
Proof. Choose a diagram (the displayed identity) as in the proof of Lemma Algebraic spaces over a pushout.
Proof of (1) -- (5). Let $(V, U', \varphi)$ be an object of $(\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X')$. Construct a diagram (the displayed identity) as in the proof of Lemma Algebraic spaces over a pushout. Then the base change of $G(V, U', \varphi) \to Y'$ to $Y'_1$ is $G_1(V_1, U_1', \varphi_1) \to Y_1'$. Hence (1) -- (5) follow immediately from the corresponding statements of More on Morphisms, Lemma Flatness and groupoids and equivalence relations for schemes.
Suppose that $W' \to Y'$ is flat. Choose a scheme $W'_1$ and a surjective étale morphism $W'_1 \to Y_1' \times_{Y'} W'$. Observe that $W'_1 \to W'$ is surjective étale as a composition of surjective étale morphisms. We know that $G_1(F_1(W_1')) \to W_1'$ is an isomorphism by More on Morphisms, Lemma Flatness and groupoids and equivalence relations applied to $W'_1$ over $Y'_1$ and the front of the diagram (with functors $G_1$ and $F_1$ as in the proof of Lemma Algebraic spaces over a pushout). Then the construction of $G(F(W'))$ (as a pushout, i.e., as constructed in Lemma Pushouts along a thickening of algebraic spaces) shows that $G_1(F_1(W'_1)) \to G(F(W))$ is surjective étale. Whereupon we conclude that $G(F(W)) \to W$ is étale, see for example Properties of Spaces, Lemma Étale morphisms and local algebra. But $G(F(W)) \to W$ is an isomorphism on underlying reduced algebraic spaces (by construction), hence it is an isomorphism. $\square$
A.12.9 Square-zero extensions and the quasi-coherator
The following arguments adapt the human Stacks Project treatment in defos.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. Deformations of algebraic spaces
Let $S$ be a scheme. Let $Y \subset Y'$ be a first order thickening of algebraic spaces over $S$. Let $f : X \to Y$ be a flat morphism of algebraic spaces over $S$. If there exists a flat morphism $f' : X' \to Y'$ of algebraic spaces over $S$ and an isomorphsm $a : X \to X' \times_{Y'} Y$ over $Y$, then
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the set of isomorphism classes of pairs $(f' : X' \to Y', a)$ is principal homogeneous under $\operatorname{Ext}^1_{\mathcal{O}_X}(\mathrm{NL}_{X/Y}, f^*\mathcal{C}_{Y/Y'})$, and
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the set of automorphisms of $\varphi : X' \to X'$ over $Y'$ which reduce to the identity on $X' \times_{Y'} Y$ is $\operatorname{Ext}^0_{\mathcal{O}_X}(\mathrm{NL}_{X/Y}, f^*\mathcal{C}_{Y/Y'})$.
Proof. We will apply the material on deformations of ringed topoi to the small étale topoi of the algebraic spaces in the lemma. We may think of $X$ as a closed subspace of $X'$ so that $(f, f') : (X \subset X') \to (Y \subset Y')$ is a morphism of first order thickenings. By Lemma Matching square-zero thickenings and their markings this translates into a morphism of thickenings of ringed topoi. Then we see from More on Morphisms of Spaces, Lemma Square-zero deformations and their comparison maps (or from the more general Lemma Deformations of modules on ringed topoi) that the ideal sheaf of $X$ in $X'$ is equal to $f^*\mathcal{C}_{Y'/Y}$ and this is in fact equivalent to flatness of $X'$ over $Y'$. Hence we have a commutative diagram $$\begin{gathered}\begin{matrix}0 & f^*\mathcal{C}_{Y/Y'} & \mathcal{O}_{X'} & \mathcal{O}_X & 0 \\ 0 & f_{small}^{-1}\mathcal{C}_{Y/Y'} & f_{small}^{-1}\mathcal{O}_{Y'} & f_{small}^{-1}\mathcal{O}_Y & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow f^*\mathcal{C}_{Y/Y'} \\ f^*\mathcal{C}_{Y/Y'} & \longrightarrow \mathcal{O}_{X'} \\ \mathcal{O}_{X'} & \longrightarrow \mathcal{O}_X \\ \mathcal{O}_X & \longrightarrow 0 \\ 0 & \longrightarrow f_{small}^{-1}\mathcal{C}_{Y/Y'} \\ f_{small}^{-1}\mathcal{C}_{Y/Y'} & \longrightarrow f^*\mathcal{C}_{Y/Y'} \\ f_{small}^{-1}\mathcal{C}_{Y/Y'} & \longrightarrow f_{small}^{-1}\mathcal{O}_{Y'} \\ f_{small}^{-1}\mathcal{O}_{Y'} & \longrightarrow \mathcal{O}_{X'} \\ f_{small}^{-1}\mathcal{O}_{Y'} & \longrightarrow f_{small}^{-1}\mathcal{O}_Y \\ f_{small}^{-1}\mathcal{O}_Y & \longrightarrow \mathcal{O}_X \\ f_{small}^{-1}\mathcal{O}_Y & \longrightarrow 0\end{aligned}\end{gathered}$$ Please compare with (Sheaves on ringed sites). Observe that automorphisms $\varphi$ as in (2) give automorphisms $\varphi^\sharp : \mathcal{O}_{X'} \to \mathcal{O}_{X'}$ fitting in the diagram above. Conversely, an automorphism $\alpha : \mathcal{O}_{X'} \to \mathcal{O}_{X'}$ fitting into the diagram of sheaves above is equal to $\varphi^\sharp$ for some automorphism $\varphi$ as in (2) by More on Morphisms of Spaces, Lemma Nilpotent thickenings. Finally, by More on Morphisms of Spaces, Lemma Nilpotent thickenings if we find another sheaf of rings $\mathcal{A}$ on $X_\mathrm{\acute{e}tale}$ fitting into the diagram $$\begin{gathered}\begin{matrix}0 & f^*\mathcal{C}_{Y/Y'} & \mathcal{A} & \mathcal{O}_X & 0 \\ 0 & f_{small}^{-1}\mathcal{C}_{Y/Y'} & f_{small}^{-1}\mathcal{O}_{Y'} & f_{small}^{-1}\mathcal{O}_Y & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow f^*\mathcal{C}_{Y/Y'} \\ f^*\mathcal{C}_{Y/Y'} & \longrightarrow \mathcal{A} \\ \mathcal{A} & \longrightarrow \mathcal{O}_X \\ \mathcal{O}_X & \longrightarrow 0 \\ 0 & \longrightarrow f_{small}^{-1}\mathcal{C}_{Y/Y'} \\ f_{small}^{-1}\mathcal{C}_{Y/Y'} & \longrightarrow f^*\mathcal{C}_{Y/Y'} \\ f_{small}^{-1}\mathcal{C}_{Y/Y'} & \longrightarrow f_{small}^{-1}\mathcal{O}_{Y'} \\ f_{small}^{-1}\mathcal{O}_{Y'} & \longrightarrow \mathcal{A} \\ f_{small}^{-1}\mathcal{O}_{Y'} & \longrightarrow f_{small}^{-1}\mathcal{O}_Y \\ f_{small}^{-1}\mathcal{O}_Y & \longrightarrow \mathcal{O}_X \\ f_{small}^{-1}\mathcal{O}_Y & \longrightarrow 0\end{aligned}\end{gathered}$$ then there exists a first order thickening $X \subset X''$ with $\mathcal{O}_{X''} = \mathcal{A}$ and applying More on Morphisms of Spaces, Lemma Nilpotent thickenings once more, we obtain a morphism $(f, f'') : (X \subset X'') \to (Y \subset Y')$ with all the desired properties. Thus part (1) follows from Lemma Choices in a square-zero extension of ringed topoi and part (2) from part (2) of Lemma Compatibility of the square-zero extension maps on ringed topoi. (Note that $\mathrm{NL}_{X/Y}$ as defined for a morphism of algebraic spaces in More on Morphisms of Spaces, Section The naive cotangent complex agrees with $\mathrm{NL}_{X/Y}$ as used in Section Nilpotent thickenings and sheaves on ringed sites.) $\square$
Lemma. Comparing square-zero extensions through the quasi-coherator
In the situation above assume that $X$ is quasi-compact and quasi-separated and that $DQ_X(\mathcal{F}) \to DQ_X(\mathcal{G})$ (Derived Categories of Spaces, Section Derived tensor products and Tor amplitude) is an isomorphism. Then the functor $F$ is an equivalence of categories.
Proof. Recall that $\mathrm{NL}_{X/B}$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$, see More on Morphisms of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. Hence our assumption implies the maps $$\operatorname{Ext}^i_X(\mathrm{NL}_{X/B}, \mathcal{F}) \longrightarrow \operatorname{Ext}^i_X(\mathrm{NL}_{X/B}, \mathcal{G})$$ are isomorphisms for all $i$. This implies our functor is fully faithful by Lemma Compatibility of the square-zero extension maps on ringed topoi. On the other hand, the functor is essentially surjective by Lemma Choices in a square-zero extension of ringed topoi because we have the solutions $\mathcal{O}_X \oplus \mathcal{F}$ and $\mathcal{O}_X \oplus \mathcal{G}$ in both categories. $\square$
Lemma. Comparing square-zero extensions over a thickening
In the situation above assume that $X$ is quasi-compact and quasi-separated and that $DQ_X(\mathcal{F}) \to DQ_X(\mathcal{G})$ (Derived Categories of Spaces, Section Derived tensor products and Tor amplitude) is an isomorphism. Then the functor $FT$ is an equivalence of categories.
Proof. A solution of (Sheaves on ringed sites) for $\mathcal{F}$ in particular gives an extension of $f^{-1}\mathcal{O}_{B'}$-algebras $$0 \to \mathcal{F} \to \mathcal{O}' \to \mathcal{O}_X \to 0$$ where $\mathcal{F}$ is an ideal of square zero. Similarly for $\mathcal{G}$. Moreover, given such an extension, we obtain a map $c_{\mathcal{O}'} : f^{-1}\mathcal{J} \to \mathcal{F}$. Thus we are looking at the full subcategory of such extensions of $f^{-1}\mathcal{O}_{B'}$-algebras with $c = c_{\mathcal{O}'}$. Clearly, if $\mathcal{O}'' = F(\mathcal{O}')$ where $F$ is the equivalence of Lemma Comparing square-zero extensions through the quasi-coherator (applied to $X \to B'$ this time), then $c_{\mathcal{O}''}$ is the composition of $c_{\mathcal{O}'}$ and the map $\mathcal{F} \to \mathcal{G}$. This proves the lemma. $\square$
A.12.10 The schematic locus in dimension at most one
The following arguments adapt the human Stacks Project treatment in spaces-over-fields.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. The schematic locus in local dimension at most one
Separated algebraic spaces are schemes in codimension 1.
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $x \in |X|$. If $X$ is separated, locally Noetherian, and the dimension of the local ring of $X$ at $x$ is $\leq 1$ (Properties of Spaces, Definition Dimension, codimension and local algebra), then there exists an open subspace of $X$ containing $x$ which is a scheme.
Proof. (Please see the remark below for a different approach avoiding the material on finite groupoids.) We can replace $X$ by an quasi-compact neighbourhood of $x$, hence we may assume $X$ is quasi-compact, separated, and Noetherian. There exists a scheme $U$ and a finite surjective morphism $U \to X$, see Limits of Spaces, Proposition Finite algebras. Let $R = U \times_X U$. Then $j : R \to U \times_S U$ is an equivalence relation and we obtain a groupoid scheme $(U, R, s, t, c)$ over $S$ with $s, t$ finite and $U$ Noetherian and separated. Let $\{u_1, \ldots, u_n\} \subset U$ be the set of points mapping to $x$. Then $\dim(\mathcal{O}_{U, u_i}) \leq 1$ by Decent Spaces, Lemma Dimension, codimension and finite algebras.
By More on Groupoids, Lemma An invariant affine neighbourhood of points in local dimension at most one there exists an $R$-invariant affine open $W \subset U$ containing the orbit $\{u_1, \ldots, u_n\}$. Since $U \to X$ is finite surjective the continuous map $|U| \to |X|$ is closed surjective, hence submersive by Topology, Lemma The geometric construction (uncovered prerequisite). Thus $f(W)$ is open and there is an open subspace $X' \subset X$ with $f : W \to X'$ a surjective finite morphism. Then $X'$ is an affine scheme by Cohomology of Spaces, Lemma Affine neighbourhoods and Noetherian rings and the proof is finished. $\square$
A.12.11 Ample bundles on reducible and nonreduced one-dimensional schemes
The following arguments adapt the human Stacks Project treatment in varieties.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Lemma. An element with prescribed negative valuations
Let $A$ be a domain with fraction field $K$. Let $B_1, \ldots, B_r \subset K$ be Noetherian $1$-dimensional semi-local domains whose fraction fields are $K$. If $A \otimes B_i \to K$ are surjective for $i = 1, \ldots, r$, then there exists an $x \in A$ such that $x^{-1}$ is in the Jacobson radical of $B_i$ for $i = 1, \ldots, r$.
Proof. Let $B_i'$ be the integral closure of $B_i$ in $K$. Suppose we find a nonzero $x \in A$ such that $x^{-1}$ is in the Jacobson radical of $B'_i$ for $i = 1, \ldots, r$. Then by Lemma Derived tensor products, Tor amplitude and dimension and codimension, after replacing $x$ by a power we get $x^{-1} \in B_i$. Since $\operatorname{Spec}(B'_i) \to \operatorname{Spec}(B_i)$ is surjective we see that $x^{-1}$ is then also in the Jacobson radical of $B_i$. Thus we may assume that each $B_i$ is a semi-local Dedekind domain.
If $B_i$ is not local, then remove $B_i$ from the list and add back the finite collection of local rings $(B_i)_\mathfrak m$. Thus we may assume that $B_i$ is a discrete valuation ring for $i = 1, \ldots, r$.
Let $v_i : K \to \mathbf{Z}$, $i = 1, \ldots, r$ be the corresponding discrete valuations (see Algebra, Lemma Characterizations of Dedekind domains). We are looking for a nonzero $x \in A$ with $v_i(x) < 0$ for $i = 1, \ldots, r$. We will prove this by induction on $r$.
If $r = 1$ and the result is wrong, then $A \subset B$ and the map $A \otimes B \to K$ is not surjective, contradiction.
If $r > 1$, then by induction we can find a nonzero $x \in A$ such that $v_i(x) < 0$ for $i = 1, \ldots, r - 1$. If $v_r(x) < 0$ then we are done, so we may assume $v_r(x) \geq 0$. By the base case we can find $y \in A$ nonzero such that $v_r(y) < 0$. After replacing $x$ by a power we may assume that $v_i(x) < v_i(y)$ for $i = 1, \ldots, r - 1$. Then $x + y$ is the element we are looking for. $\square$
Lemma. A globally generated line bundle cutting out an affine open
Let $X$ be an integral separated scheme. Let $U \subset X$ be a nonempty affine open such that $X \setminus U$ is a finite set of points $x_1, \ldots, x_r$ with $\mathcal{O}_{X, x_i}$ Noetherian of dimension $1$. Then there exists a globally generated invertible $\mathcal{O}_X$-module $\mathcal{L}$ and a section $s$ such that $U = X_s$.
Proof. Say $U = \operatorname{Spec}(A)$ and let $K$ be the function field of $X$. Write $B_i = \mathcal{O}_{X, x_i}$ and $\mathfrak m_i = \mathfrak m_{x_i}$. Since $x_i \not \in U$ we see that the open $U \times_X \operatorname{Spec}(B_i)$ of $\operatorname{Spec}(B_i)$ has only one point, i.e., $U \times_X \operatorname{Spec}(B_i) = \operatorname{Spec}(K)$. Since $X$ is separated, we find that $\operatorname{Spec}(K)$ is a closed subscheme of $U \times \operatorname{Spec}(B_i)$, i.e., the map $A \otimes B_i \to K$ is a surjection. By Lemma An element with prescribed negative valuations we can find a nonzero $f \in A$ such that $f^{-1} \in \mathfrak m_i$ for $i = 1, \ldots, r$. Pick opens $x_i \in U_i \subset X$ such that $f^{-1} \in \mathcal{O}(U_i)$. Then $$\mathcal{U} : X = U \cup \bigcup U_i$$ is an open covering of $X$. Consider the $2$-cocycle with values in $\mathcal{O}_X^*$ given by $f$ on $U \cap U_i$ and by $1$ on $U_i \cap U_j$. This defines a line bundle $\mathcal{L}$ with two sections:
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a section $s$ defined by $1$ on $U$ and $f^{-1}$ on $U_i$ is as in the statement of the lemma, and
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a section $t$ defined by $f$ on $U$ and $1$ on $U_i$.
Note that $X_t \supset U_1 \cup \ldots \cup U_r$. Hence $s, t$ generate $\mathcal{L}$ and the lemma is proved. $\square$
Lemma. Line bundles and ampleness
Let $X$ be a quasi-compact scheme. If for every $x \in X$ there exists a pair $(\mathcal{L}, s)$ consisting of a globally generated invertible sheaf $\mathcal{L}$ and a global section $s$ such that $x \in X_s$ and $X_s$ is affine, then $X$ has an ample invertible sheaf.
Proof. Since $X$ is quasi-compact we can find a finite collection $(\mathcal{L}_i, s_i)$, $i = 1, \ldots, n$ of pairs such that $\mathcal{L}_i$ is globally generated, $X_{s_i}$ is affine and $X = \bigcup X_{s_i}$. Again because $X$ is quasi-compact we can find, for each $i$, a finite collection of sections $t_{i, j}$ of $\mathcal{L}_i$, $j = 1, \ldots, m_i$ such that $X = \bigcup X_{t_{i, j}}$. Set $t_{i, 0} = s_i$. Consider the invertible sheaf $$\mathcal{L} = \mathcal{L}_1 \otimes_{\mathcal{O}_X} \ldots \otimes_{\mathcal{O}_X} \mathcal{L}_n$$ and the global sections $$\tau_J = t_{1, j_1} \otimes \ldots \otimes t_{n, j_n}$$ By Properties, Lemma Affine neighbourhoods the open $X_{\tau_J}$ is affine as soon as $j_i = 0$ for some $i$. It is a simple matter to see that these opens cover $X$. Hence $\mathcal{L}$ is ample by definition. $\square$
Lemma. Dimension, codimension and line bundles and ampleness
Let $X$ be a Noetherian integral separated scheme of dimension $1$. Then $X$ has an ample invertible sheaf.
Proof. Choose an affine open covering $X = U_1 \cup \ldots \cup U_n$. Since $X$ is Noetherian, each of the sets $X \setminus U_i$ is finite. Thus by Lemma A globally generated line bundle cutting out an affine open we can find a pair $(\mathcal{L}_i, s_i)$ consisting of a globally generated invertible sheaf $\mathcal{L}_i$ and a global section $s_i$ such that $U_i = X_{s_i}$. We conclude that $X$ has an ample invertible sheaf by Lemma Line bundles and ampleness. $\square$
Lemma. Line bundles and ampleness
Let $X$ be a scheme. Let $Z_1, \ldots, Z_n \subset X$ be closed subschemes. Let $\mathcal{L}_i$ be an invertible sheaf on $Z_i$. Assume that
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$X$ is reduced,
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$X = \bigcup Z_i$ set theoretically, and
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$Z_i \cap Z_j$ is a discrete topological space for $i \not = j$.
Then there exists an invertible sheaf $\mathcal{L}$ on $X$ whose restriction to $Z_i$ is $\mathcal{L}_i$. Moreover, if we are given sections $s_i \in \Gamma(Z_i, \mathcal{L}_i)$ which are nonvanishing at the points of $Z_i \cap Z_j$, then we can choose $\mathcal{L}$ such that there exists a $s \in \Gamma(X, \mathcal{L})$ with $s|_{Z_i} = s_i$ for all $i$.
Proof. The existence of $\mathcal{L}$ can be deduced from Lemma Finite algebras but we will also give a direct proof and we will use the direct proof to see the statement about sections is true. Set $T = \bigcup_{i \not = j} Z_i \cap Z_j$. As $X$ is reduced we have $$X \setminus T = \bigcup (Z_i \setminus T)$$ as schemes. Assumption (3) implies $T$ is a discrete subset of $X$. Thus for each $t \in T$ we can find an open $U_t \subset X$ with $t \in U_t$ but $t' \not \in U_t$ for $t' \in T$, $t' \not = t$. By shrinking $U_t$ if necessary, we may assume that there exist isomorphisms $\varphi_{t, i} : \mathcal{L}_i|_{U_t \cap Z_i} \to \mathcal{O}_{U_t \cap Z_i}$. Furthermore, for each $i$ choose an open covering $$Z_i \setminus T = \bigcup\nolimits_j U_{ij}$$ such that there exist isomorphisms $\varphi_{i, j} : \mathcal{L}_i|_{U_{ij}} \cong \mathcal{O}_{U_{ij}}$. Observe that $$\mathcal{U} : X = \bigcup U_t \cup \bigcup U_{ij}$$ is an open covering of $X$. We claim that we can use the isomorphisms $\varphi_{t, i}$ and $\varphi_{i, j}$ to define a $2$-cocycle with values in $\mathcal{O}_X^*$ for this covering that defines $\mathcal{L}$ as in the statement of the lemma.
Namely, if $i \not = i'$, then $U_{i, j} \cap U_{i', j'} = \emptyset$ and there is nothing to do. For $U_{i, j} \cap U_{i, j'}$ we have $\mathcal{O}_X(U_{i, j} \cap U_{i, j'}) = \mathcal{O}_{Z_i}(U_{i, j} \cap U_{i, j'})$ by the first remark of the proof. Thus the transition function for $\mathcal{L}_i$ (more precisely $\varphi_{i, j} \circ \varphi_{i, j'}^{-1}$) defines the value of our cocycle on this intersection. For $U_t \cap U_{i, j}$ we can do the same thing. Finally, for $t \not = t'$ we have $$U_t \cap U_{t'} = \coprod (U_t \cap U_{t'}) \cap Z_i$$ and moreover the intersection $U_t \cap U_{t'} \cap Z_i$ is contained in $Z_i \setminus T$. Hence by the same reasoning as before we see that $$\mathcal{O}_X(U_t \cap U_{t'}) = \prod \mathcal{O}_{Z_i}(U_t \cap U_{t'} \cap Z_i)$$ and we can use the transition functions for $\mathcal{L}_i$ (more precisely $\varphi_{t, i} \circ \varphi_{t', i}^{-1}$) to define the value of our cocycle on $U_t \cap U_{t'}$. This finishes the proof of existence of $\mathcal{L}$.
Given sections $s_i$ as in the last assertion of the lemma, in the argument above, we choose $U_t$ such that $s_i|_{U_t \cap Z_i}$ is nonvanishing and we choose $\varphi_{t, i}$ such that $\varphi_{t, i}(s_i|_{U_t \cap Z_i}) = 1$. Then using $1$ over $U_t$ and $\varphi_{i, j}(s_i|_{U_{i, j}})$ over $U_{i, j}$ will define a section of $\mathcal{L}$ which restricts to $s_i$ over $Z_i$. $\square$
Remark. Conductor ideals on one-dimensional schemes
Let $A$ be a reduced ring. Let $I, J$ be ideals of $A$ such that $V(I) \cup V(J) = \operatorname{Spec}(A)$. Set $B = A/J$. Then $I \to IB$ is an isomorphism of $A$-modules. Namely, we have $IB = I + J/J = I/(I \cap J)$ and $I \cap J$ is zero because $A$ is reduced and $\operatorname{Spec}(A) = V(I) \cup V(J) = V(I \cap J)$. Thus for any projective $A$-module $P$ we also have $IP = I(P/JP)$.
Lemma. Dimension, codimension and line bundles and ampleness
Let $X$ be a Noetherian reduced separated scheme of dimension $1$. Then $X$ has an ample invertible sheaf.
Proof. Let $Z_i$, $i = 1, \ldots, n$ be the irreducible components of $X$. We view these as reduced closed subschemes of $X$. By Lemma Dimension, codimension and line bundles and ampleness there exist ample invertible sheaves $\mathcal{L}_i$ on $Z_i$. Set $T = \bigcup_{i \not = j} Z_i \cap Z_j$. As $X$ is Noetherian of dimension $1$, the set $T$ is finite and consists of closed points of $X$. For each $i$ we may, possibly after replacing $\mathcal{L}_i$ by a power, choose $s_i \in \Gamma(Z_i, \mathcal{L}_i)$ such that $(Z_i)_{s_i}$ is affine and contains $T \cap Z_i$, see Properties, Lemma Line bundles, ampleness and affine neighbourhoods.
By Lemma Line bundles and ampleness we can find an invertible sheaf $\mathcal{L}$ on $X$ and $s \in \Gamma(X, \mathcal{L})$ such that $(\mathcal{L}, s)|_{Z_i} = (\mathcal{L}_i, s_i)$. Observe that $X_s$ contains $T$ and is set theoretically equal to the affine closed subschemes $(Z_i)_{s_i}$. Thus it is affine by Limits, Lemma Affine neighbourhoods. To finish the proof, it suffices to find for every $x \in X$, $x \not \in T$ an integer $m > 0$ and a section $t \in \Gamma(X, \mathcal{L}^{\otimes m})$ such that $X_t$ is affine and $x \in X_t$. Since $x \not \in T$ we see that $x \in Z_i$ for some unique $i$, say $i = 1$. Let $Z \subset X$ be the reduced closed subscheme whose underlying topological space is $Z_2 \cup \ldots \cup Z_n$. Let $\mathcal{I} \subset \mathcal{O}_X$ be the ideal sheaf of $Z$. Denote that $\mathcal{I}_1 \subset \mathcal{O}_{Z_1}$ the inverse image of this ideal sheaf under the inclusion morphism $Z_1 \to X$. Observe that $$\Gamma(X, \mathcal{I}\mathcal{L}^{\otimes m}) = \Gamma(Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m})$$ see Remark Conductor ideals on one-dimensional schemes. Thus it suffices to find $m > 0$ and $t \in \Gamma(Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m})$ with $x \in (Z_1)_t$ affine. Since $\mathcal{L}_1$ is ample and since $x$ is not in $Z_1 \cap T = V(\mathcal{I}_1)$ we can find a section $t_1 \in \Gamma(Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m_1})$ with $x \in (Z_1)_{t_1}$, see Properties, Proposition Criteria for line bundles and ampleness. Since $\mathcal{L}_1$ is ample we can find a section $t_2 \in \Gamma(Z_1, \mathcal{L}_1^{\otimes m_2})$ with $x \in (Z_1)_{t_2}$ and $(Z_1)_{t_2}$ affine, see Properties, Definition Ample invertible sheaves. Set $m = m_1 + m_2$ and $t = t_1 t_2$. Then $t \in \Gamma(Z_1, \mathcal{I}_1 \mathcal{L}_1^{\otimes m})$ with $x \in (Z_1)_t$ by construction and $(Z_1)_t$ is affine by Properties, Lemma Affine neighbourhoods. $\square$
Lemma. Lifting derived Hom, Ext and dimension and codimension
Let $i : Z \to X$ be a closed immersion of schemes. If the underlying topological space of $X$ is Noetherian and $\dim(X) \leq 1$, then $\operatorname{Pic}(X) \to \operatorname{Pic}(Z)$ is surjective.
Proof. Consider the short exact sequence $$0 \to (1 + \mathcal{I}) \cap \mathcal{O}_X^* \to \mathcal{O}^*_X \to i_*\mathcal{O}^*_Z \to 0$$ of sheaves of abelian groups on $X$ where $\mathcal{I}$ is the quasi-coherent sheaf of ideals corresponding to $Z$. Since $\dim(X) \leq 1$ we see that $H^2(X, \mathcal{F}) = 0$ for any abelian sheaf $\mathcal{F}$, see Cohomology, Proposition Vanishing and Noetherian rings. Hence the map $H^1(X, \mathcal{O}^*_X) \to H^1(X, i_*\mathcal{O}_Z^*)$ is surjective. By Cohomology, Lemma Sheaf cohomology and diagonals and separation we have $H^1(X, i_*\mathcal{O}_Z^*) = H^1(Z, \mathcal{O}_Z^*)$. This proves the lemma by Cohomology, Lemma Line bundles and ampleness. $\square$
Proposition. Dimension, codimension and line bundles and ampleness
Let $X$ be a Noetherian separated scheme of dimension $1$. Then $X$ has an ample invertible sheaf.
Proof. Let $Z \subset X$ be the reduction of $X$. By Lemma Dimension, codimension and line bundles and ampleness the scheme $Z$ has an ample invertible sheaf. Thus by Lemma Lifting derived Hom, Ext and dimension and codimension there exists an invertible $\mathcal{O}_X$-module $\mathcal{L}$ on $X$ whose restriction to $Z$ is ample. Then $\mathcal{L}$ is ample by an application of Cohomology of Schemes, Lemma Line bundles and ampleness (uncovered prerequisite). $\square$
Lemma. Projective, locally free modules and dimension and codimension
Let $X$ be a separated finite type scheme over a field $k$. If $\dim(X) \leq 1$ then $X$ is H-quasi-projective over $k$.
Proof. By Proposition Dimension, codimension and line bundles and ampleness the scheme $X$ has an ample invertible sheaf $\mathcal{L}$. By Morphisms, Lemma Projective, locally free modules and finite algebras (uncovered prerequisite) we see that $X$ is isomorphic to a locally closed subscheme of $\mathbf{P}^n_k$ over $\operatorname{Spec}(k)$. This is the definition of being H-quasi-projective over $k$, see Morphisms, Definition Projective and locally free modules. $\square$
Lemma. Projectivity of proper field schemes of dimension at most one
Let $X$ be a proper scheme over a field $k$. If $\dim(X) \leq 1$ then $X$ is H-projective over $k$.
Proof. By Lemma Projective, locally free modules and dimension and codimension we see that $X$ is a locally closed subscheme of $\mathbf{P}^n_k$ for some field $k$. Since $X$ is proper over $k$ it follows that $X$ is a closed subscheme of $\mathbf{P}^n_k$ (Morphisms, Lemma Proper morphisms (uncovered prerequisite)). $\square$
A.12.12 Artin checks for polarized schemes and all curve spaces
The following arguments adapt the human Stacks Project treatment in quot.tex. Source correspondence and the exact lower prerequisites are retained in the accompanying record.
Situation. The groupoid of polarized proper schemes
We define a category $\mathcal{P}\!ol$ as follows. Objects are pairs $(X \to S, \mathcal{L})$ where
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$X \to S$ is a morphism of schemes which is proper, flat, and of finite presentation, and
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$\mathcal{L}$ is an invertible $\mathcal{O}_X$-module which is relatively ample on $X/S$ (Morphisms, Definition Line bundles and ampleness).
A morphism $(X' \to S', \mathcal{L}') \to (X \to S, \mathcal{L})$ between objects is given by a triple $(f, g, \varphi)$ where $f : X' \to X$ and $g : S' \to S$ are morphisms of schemes which fit into a commutative diagram $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow S' \\ X' & \xrightarrow{f} X \\ X & \longrightarrow S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ inducing an isomorphism $X' \to S' \times_S X$, in other words, the diagram is cartesian, and $\varphi : f^*\mathcal{L} \to \mathcal{L}'$ is an isomorphism. Composition is defined in the obvious manner (see Examples of Stacks, Sections The geometric construction and Quasi-coherent complexes and coherent sheaves). The forgetful functor $$p : \mathcal{P}\!ol \longrightarrow \mathrm{Sch}_{fppf},\quad (X \to S, \mathcal{L}) \longmapsto S$$ is how we view $\mathcal{P}\!ol$ as a category over $\mathrm{Sch}_{fppf}$ (see Section Conventions for the moduli groupoids for notation).
Lemma. The groupoid of proper flat spaces
The category $\mathcal{S}\!paces'_{ft}$ is fibred in groupoids over $\mathrm{Sch}_{fppf}$. The same is true for $\mathcal{S}\!paces'_{fp, flat, proper}$.
Proof. We have seen this in Examples of Stacks, Section Groupoids, equivalence relations and finite algebras for the case of $\mathcal{S}\!paces'_{ft}$ and this easily implies the result for the other case. However, let us also prove this directly by checking conditions (1) and (2) of Categories, Definition Groupoids and equivalence relations.
Condition (1). Let $X \to S$ be an object of $\mathcal{S}\!paces'_{ft}$ and let $S' \to S$ be a morphism of schemes. Then we set $X' = S' \times_S X$. Note that $X' \to S'$ is of finite type by Morphisms of Spaces, Lemma Base change for finite algebras. to obtain a morphism $(X' \to S') \to (X \to S)$ lying over $S' \to S$. Argue similarly for the other case using Morphisms of Spaces, Lemmas Base change for finite presentation and finite algebras, Base change for flatness, and Base change for proper morphisms.
Condition (2). Consider morphisms $(f, g) : (X' \to S') \to (X \to S)$ and $(a, b) : (Y \to T) \to (X \to S)$ of $\mathcal{S}\!paces'_{ft}$. Given a morphism $h : T \to S'$ with $g \circ h = b$ we have to show there is a unique morphism $(k, h) : (Y \to T) \to (X' \to S')$ of $\mathcal{S}\!paces'_{ft}$ such that $(f, g) \circ (k, h) = (a, b)$. This is clear from the fact that $X' = S' \times_S X$. The same therefore works for any full subcategory of $\mathcal{S}\!paces'_{ft}$ satisfying (1). $\square$
Lemma. The diagonal of the proper-space groupoid
The diagonal $$\Delta : \mathcal{S}\!paces'_{fp, flat, proper} \longrightarrow \mathcal{S}\!paces'_{fp, flat, proper} \times \mathcal{S}\!paces'_{fp, flat, proper}$$ is representable by algebraic spaces.
Proof. We will use criterion (2) of Algebraic Stacks, Lemma Diagonals and separation (uncovered prerequisite). Let $S$ be a scheme and let $X$ and $Y$ be algebraic spaces of finite presentation over $S$, flat over $S$, and proper over $S$. We have to show that the functor $$\mathit{Isom}_S(X, Y) : (\mathrm{Sch}/S)_{fppf} \longrightarrow \textit{Sets}, \quad T \longmapsto \{f : X_T \to Y_T \text{ isomorphism}\}$$ is an algebraic space. An elementary argument shows that $\mathit{Isom}_S(X, Y)$ sits in a fibre product $$\begin{gathered}\begin{matrix}\mathit{Isom}_S(X, Y) & S \\ \mathit{Mor}_S(X, Y) \times \mathit{Mor}_S(Y, X) & \mathit{Mor}_S(X, X) \times \mathit{Mor}_S(Y, Y)\end{matrix} \\[6pt] \begin{aligned}\mathit{Isom}_S(X, Y) & \longrightarrow S \\ \mathit{Isom}_S(X, Y) & \longrightarrow \mathit{Mor}_S(X, Y) \times \mathit{Mor}_S(Y, X) \\ S & \xrightarrow{(\text{id}, \text{id})} \mathit{Mor}_S(X, X) \times \mathit{Mor}_S(Y, Y) \\ \mathit{Mor}_S(X, Y) \times \mathit{Mor}_S(Y, X) & \longrightarrow \mathit{Mor}_S(X, X) \times \mathit{Mor}_S(Y, Y)\end{aligned}\end{gathered}$$ The bottom arrow sends $(\varphi, \psi)$ to $(\psi \circ \varphi, \varphi \circ \psi)$. By Proposition Representability of the morphism functor the functors on the bottom row are algebraic spaces over $S$. Hence the result follows from the fact that the category of algebraic spaces over $S$ has fibre products. $\square$
Lemma. Descent of proper flat spaces
The category $\mathcal{S}\!paces'_{ft}$ is a stack in groupoids over $\mathrm{Sch}_{fppf}$. The same is true for $\mathcal{S}\!paces'_{fp, flat, proper}$.
Proof. The reason this lemma holds is the slogan: any fppf descent datum for algebraic spaces is effective, see Bootstrap, Section The geometric construction (uncovered prerequisite). More precisely, the lemma for $\mathcal{S}\!paces'_{ft}$ follows from Examples of Stacks, Lemma Finite algebras (uncovered prerequisite) as we saw in Examples of Stacks, Section Groupoids, equivalence relations and finite algebras. However, let us review the proof. We need to check conditions (1), (2), and (3) of Stacks, Definition Groupoids and equivalence relations.
Property (1) we have seen in Lemma The groupoid of proper flat spaces.
Property (2) follows from Lemma The diagonal of the proper-space groupoid in the case of $\mathcal{S}\!paces'_{fp, flat, proper}$. In the case of $\mathcal{S}\!paces'_{ft}$ it follows from Examples of Stacks, Lemma The geometric construction (uncovered prerequisite) (and this is really the "correct" reference).
Condition (3) for $\mathcal{S}\!paces'_{ft}$ is checked as follows. Suppose given
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an fppf covering $\{U_i \to U\}_{i \in I}$ in $\mathrm{Sch}_{fppf}$,
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for each $i \in I$ an algebraic space $X_i$ of finite type over $U_i$, and
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for each $i, j \in I$ an isomorphism $\varphi_{ij} : X_i \times_U U_j \to U_i \times_U X_j$ of algebraic spaces over $U_i \times_U U_j$ satisfying the cocycle condition over $U_i \times_U U_j \times_U U_k$.
We have to show there exists an algebraic space $X$ of finite type over $U$ and isomorphisms $X_{U_i} \cong X_i$ over $U_i$ recovering the isomorphisms $\varphi_{ij}$. This follows from Bootstrap, Lemma The geometric construction (uncovered prerequisite) part (2). By Descent on Spaces, Lemma Descent of proper morphisms and finite algebras we see that $X \to U$ is of finite type. In the case of $\mathcal{S}\!paces'_{fp, flat, proper}$ one additionally uses Descent on Spaces, Lemma Descent of finite presentation and proper morphisms, Descent of flatness and proper morphisms, and Descent of proper morphisms in the last step. $\square$
Lemma. Limit preservation for proper flat spaces
The stack $p'_{fp, flat, proper} : \mathcal{S}\!paces'_{fp, flat, proper} \to \mathrm{Sch}_{fppf}$ is limit preserving (Artin's Axioms, Definition Limit-preserving deformation groupoids).
Proof. Let $T = \varprojlim T_i$ be the limits of a directed inverse system of affine schemes. By Limits of Spaces, Lemma Descent of finite presentation and finite algebras the category of algebraic spaces of finite presentation over $T$ is the colimit of the categories of algebraic spaces of finite presentation over $T_i$. To finish the proof use that flatness and properness descends through the limit, see Limits of Spaces, Lemmas Descent of flatness and Proper morphisms. $\square$
Lemma. Infinitesimal patching of proper flat spaces
Let $$\begin{gathered}\begin{matrix}T & T' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}T & \longrightarrow T' \\ T & \longrightarrow S \\ T' & \longrightarrow S' \\ S & \longrightarrow S'\end{aligned}\end{gathered}$$ be a pushout in the category of schemes where $T \to T'$ is a thickening and $T \to S$ is affine, see More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces. Then the functor on fibre categories $$\begin{matrix} \mathcal{S}\!paces'_{fp, flat, proper, S'} \\ \downarrow \\ \mathcal{S}\!paces'_{fp, flat, proper, S} \times_{\mathcal{S}\!paces'_{fp, flat, proper, T}} \mathcal{S}\!paces'_{fp, flat, proper, T'} \end{matrix}$$ is an equivalence.
Proof. The functor is an equivalence if we drop "proper" from the list of conditions and replace "of finite presentation" by "locally of finite presentation", see Pushouts of Spaces, Lemma Patching flat algebraic spaces. Thus it suffices to show that given a morphism $X' \to S'$ of an algebraic space to $S'$ which is flat and locally of finite presentation, then $X' \to S'$ is proper if and only if $S \times_{S'} X' \to S$ and $T' \times_{S'} X' \to T'$ are proper. One implication follows from the fact that properness is preserved under base change (Morphisms of Spaces, Lemma Base change for proper morphisms) and the other from the fact that properness of $S \times_{S'} X' \to S$ implies properness of $X' \to S'$ by More on Morphisms of Spaces, Lemma Proper morphisms and nilpotent thickenings. $\square$
Lemma. Finite tangent spaces of proper flat spaces
Let $k$ be a field and let $x = (X \to \operatorname{Spec}(k))$ be an object of $\mathcal{X} = \mathcal{S}\!paces'_{fp, flat, proper}$ over $\operatorname{Spec}(k)$.
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If $k$ is of finite type over $\mathbf{Z}$, then the vector spaces $T\mathcal{F}_{\mathcal{X}, k, x}$ and $\text{Inf}(\mathcal{F}_{\mathcal{X}, k, x})$ (see Artin's Axioms, Section Tangent spaces of deformation groupoids) are finite dimensional, and
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in general the vector spaces $T_x(k)$ and $\text{Inf}_x(k)$ (see Artin's Axioms, Section Infinitesimal automorphisms) are finite dimensional.
Proof. The discussion in Artin's Axioms, Section Tangent spaces of deformation groupoids only applies to fields of finite type over the base scheme $\operatorname{Spec}(\mathbf{Z})$. Our stack satisfies (RS*) by Lemma Infinitesimal patching of proper flat spaces and we may apply Artin's Axioms, Lemma Lifting properties under infinitesimal patching to get the vector spaces $T_x(k)$ and $\text{Inf}_x(k)$ mentioned in (2). Moreover, in the finite type case these spaces agree with the ones mentioned in (1) by Artin's Axioms, Remark Comparing deformation categories. With this out of the way we can start the proof. Observe that the first order thickening $\operatorname{Spec}(k) \to \operatorname{Spec}(k[\epsilon]) = \operatorname{Spec}(k[k])$ has conormal module $k$. Hence the formula in Deformation Theory, Lemma Deformations of algebraic spaces describing infinitesimal deformations of $X$ and infinitesimal automorphisms of $X$ become $$T_x(k) = \operatorname{Ext}^1_{\mathcal{O}_X}(\mathrm{NL}_{X/k}, \mathcal{O}_X) \quad\text{and}\quad \text{Inf}_x(k) = \operatorname{Ext}^0_{\mathcal{O}_X}(\mathrm{NL}_{X/k}, \mathcal{O}_X)$$ By More on Morphisms of Spaces, Lemma Finite presentation from a finite-type flat family and the fact that $X$ is Noetherian, we see that $\mathrm{NL}_{X/k}$ has coherent cohomology sheaves zero except in degrees $0$ and $-1$. By Derived Categories of Spaces, Lemma Derived Hom, Ext and finite algebras the displayed $\operatorname{Ext}$-groups are finite $k$-vector spaces and the proof is complete. $\square$
Lemma. Openness of versality for proper flat spaces
The stack in groupoids $\mathcal{X} = \mathcal{S}\!paces'_{fp, flat, proper}$ satisfies openness of versality over $\operatorname{Spec}(\mathbf{Z})$. Similarly, after base change (Remark Base change of the proper-space groupoid) openness of versality holds over any Noetherian base scheme $S$.
Proof. For the "usual" proof of this fact, please see the discussion in the remark following this proof. We will prove this using Artin's Axioms, Lemma Strong effectivity implies openness of versality. We have already seen that $\mathcal{X}$ has diagonal representable by algebraic spaces, has (RS*), and is limit preserving, see Lemmas The diagonal of the proper-space groupoid, Infinitesimal patching of proper flat spaces, and Limit preservation for proper flat spaces. Hence we only need to see that $\mathcal{X}$ satisfies the strong formal effectiveness formulated in Artin's Axioms, Lemma Strong effectivity implies openness of versality.
Let $(R_n)$ be an inverse system of rings such that $R_n \to R_m$ is surjective with square zero kernel for all $n \geq m$. Let $X_n \to \operatorname{Spec}(R_n)$ be a finitely presented, flat, proper morphism where $X_n$ is an algebraic space and let $X_{n + 1} \to X_n$ be a morphism over $\operatorname{Spec}(R_{n + 1})$ inducing an isomorphism $X_n = X_{n + 1} \times_{\operatorname{Spec}(R_{n + 1})} \operatorname{Spec}(R_n)$. We have to find a flat, proper, finitely presented morphism $X \to \operatorname{Spec}(\varprojlim R_n)$ whose source is an algebraic space such that $X_n$ is the base change of $X$ for all $n$.
Let $I_n = \operatorname{Ker}(R_n \to R_1)$. We may think of $(X_1 \subset X_n) \to (\operatorname{Spec}(R_1) \subset \operatorname{Spec}(R_n))$ as a morphism of first order thickenings. (Please read some of the material on thickenings of algebraic spaces in More on Morphisms of Spaces, Section Nilpotent thickenings before continuing.) The structure sheaf of $X_n$ is an extension $$0 \to \mathcal{O}_{X_1} \otimes_{R_1} I_n \to \mathcal{O}_{X_n} \to \mathcal{O}_{X_1} \to 0$$ over $0 \to I_n \to R_n \to R_1$, see More on Morphisms of Spaces, Lemma Square-zero deformations and their comparison maps. Let's consider the extension $$0 \to \varprojlim \mathcal{O}_{X_1} \otimes_{R_1} I_n \to \varprojlim \mathcal{O}_{X_n} \to \mathcal{O}_{X_1} \to 0$$ over $0 \to \varprojlim I_n \to \varprojlim R_n \to R_1 \to 0$. The displayed sequence is exact as the $R^1\varprojlim$ of the system of kernels is zero by Derived Categories of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. Observe that the map $$\mathcal{O}_{X_1} \otimes_{R_1} \varprojlim I_n \longrightarrow \varprojlim \mathcal{O}_{X_1} \otimes_{R_1} I_n$$ induces an isomorphism upon applying the functor $DQ_X$, see Derived Categories of Spaces, Lemma Pullback of derived quasi-coherent complexes. Hence we obtain a unique extension $$0 \to \mathcal{O}_{X_1} \otimes_{R_1} \varprojlim I_n \to \mathcal{O}' \to \mathcal{O}_{X_1} \to 0$$ over $0 \to \varprojlim I_n \to \varprojlim R_n \to R_1 \to 0$ by the equivalence of categories of Deformation Theory, Lemma Comparing square-zero extensions over a thickening. The sheaf $\mathcal{O}'$ determines a first order thickening of algebraic spaces $X_1 \subset X$ over $\operatorname{Spec}(R_1) \subset \operatorname{Spec}(\varprojlim R_n)$ by More on Morphisms of Spaces, Lemma Nilpotent thickenings. Observe that $X \to \operatorname{Spec}(\varprojlim R_n)$ is flat by the already used More on Morphisms of Spaces, Lemma Square-zero deformations and their comparison maps. By More on Morphisms of Spaces, Lemma Properties preserved under a square-zero deformation we see that $X \to \operatorname{Spec}(\varprojlim R_n)$ is proper and of finite presentation. This finishes the proof. $\square$
Lemma. Base change of polarized proper schemes
The category $\mathcal{P}\!ol$ is fibred in groupoids over $\mathcal{S}\!paces'_{fp, flat, proper}$. The category $\mathcal{P}\!ol$ is fibred in groupoids over $\mathrm{Sch}_{fppf}$.
Proof. We check conditions (1) and (2) of Categories, Definition Groupoids and equivalence relations.
Condition (1). Let $(X \to S, \mathcal{L})$ be an object of $\mathcal{P}\!ol$ and let $(X' \to S') \to (X \to S)$ be a morphism of $\mathcal{S}\!paces'_{fp, flat, proper}$. Then we let $\mathcal{L}'$ be the pullback of $\mathcal{L}$ to $X'$. Observe that $X, S, S'$ are schemes, hence $X'$ is a scheme as well (as the fibre product of schemes). Then $\mathcal{L}'$ is ample on $X'/S'$ by Morphisms, Lemma Base change for line bundles and ampleness (uncovered prerequisite). In this way we obtain a morphism $(X' \to S', \mathcal{L}') \to (X \to S, \mathcal{L})$ lying over $(X' \to S') \to (X \to S)$.
Condition (2). Consider morphisms $(f, g, \varphi) : (X' \to S', \mathcal{L}') \to (X \to S, \mathcal{L})$ and $(a, b, \psi) : (Y \to T, \mathcal{N}) \to (X \to S, \mathcal{L})$ of $\mathcal{P}\!ol$. Given a morphism $(k, h) : (Y \to T) \to (X' \to S')$ of $\mathcal{S}\!paces'_{fp, flat, proper}$ with $(f, g) \circ (k, h) = (a, b)$ we have to show there is a unique morphism $(k, h, \chi) : (Y \to T, \mathcal{N}) \to (X' \to S', \mathcal{L}')$ of $\mathcal{P}\!ol$ such that $(f, g, \varphi) \circ (k, h, \chi) = (a, b, \psi)$. We can just take $$\chi = \psi \circ (k^*\varphi)^{-1}$$ This proves condition (2). A composition of functors defining fibred categories defines a fibred category, see Categories, Lemma The geometric construction (uncovered prerequisite). This we see that $\mathcal{P}\!ol$ is fibred in groupoids over $\mathrm{Sch}_{fppf}$ (strictly speaking we should check the fibre categories are groupoids and apply Categories, Lemma Groupoids and equivalence relations (uncovered prerequisite)). $\square$
Lemma. Descent of polarized proper schemes
The category $\mathcal{P}\!ol$ is a stack in groupoids over $\mathcal{S}\!paces'_{fp, flat, proper}$ (endowed with the inherited topology, see Stacks, Definition The geometric construction). The category $\mathcal{P}\!ol$ is a stack in groupoids over $\mathrm{Sch}_{fppf}$.
Proof. We prove $\mathcal{P}\!ol$ is a stack in groupoids over $\mathcal{S}\!paces'_{fp, flat, proper}$ by checking conditions (1), (2), and (3) of Stacks, Definition Groupoids and equivalence relations. We have already seen (1) in Lemma Base change of polarized proper schemes.
A covering of $\mathcal{S}\!paces'_{fp, flat, proper}$ comes about in the following manner: Let $X \to S$ be an object of $\mathcal{S}\!paces'_{fp, flat, proper}$. Suppose that $\{S_i \to S\}_{i \in I}$ is a covering of $\mathrm{Sch}_{fppf}$. Set $X_i = S_i \times_S X$. Then $\{(X_i \to S_i) \to (X \to S)\}_{i \in I}$ is a covering of $\mathcal{S}\!paces'_{fp, flat, proper}$ and every covering of $\mathcal{S}\!paces'_{fp, flat, proper}$ is isomorphic to one of these. Set $S_{ij} = S_i \times_S S_j$ and $X_{ij} = S_{ij} \times_S X$ so that $(X_{ij} \to S_{ij}) = (X_i \to S_i) \times_{(X \to S)} (X_j \to S_j)$. Next, suppose that $\mathcal{L}, \mathcal{N}$ are ample invertible sheaves on $X/S$ so that $(X \to S, \mathcal{L})$ and $(X \to S, \mathcal{N})$ are two objects of $\mathcal{P}\!ol$ over the object $(X \to S)$. To check descent for morphisms, we assume we have morphisms $(\text{id}, \text{id}, \varphi_i)$ from $(X_i \to S_i, \mathcal{L}|_{X_i})$ to $(X_i \to S_i, \mathcal{N}|_{X_i})$ whose base changes to morphisms from $(X_{ij} \to S_{ij}, \mathcal{L}|_{X_{ij}})$ to $(X_{ij} \to S_{ij}, \mathcal{N}|_{X_{ij}})$ agree. Then $\varphi_i : \mathcal{L}|_{X_i} \to \mathcal{N}|_{X_i}$ are isomorphisms of invertible modules over $X_i$ such that $\varphi_i$ and $\varphi_j$ restrict to the same isomorphisms over $X_{ij}$. By descent for quasi-coherent sheaves (Descent on Spaces, Proposition Quasi-coherent complexes and coherent sheaves) we obtain a unique isomorphism $\varphi : \mathcal{L} \to \mathcal{N}$ whose restriction to $X_i$ recovers $\varphi_i$.
Decent for objects is proved in exactly the same manner. Namely, suppose that $\{(X_i \to S_i) \to (X \to S)\}_{i \in I}$ is a covering of $\mathcal{S}\!paces'_{fp, flat, proper}$ as above. Suppose we have objects $(X_i \to S_i, \mathcal{L}_i)$ of $\mathcal{P}\!ol$ lying over $(X_i \to S_i)$ and a descent datum $$(\text{id}, \text{id}, \varphi_{ij}) : (X_{ij} \to S_{ij}, \mathcal{L}_i|_{X_{ij}}) \to (X_{ij} \to S_{ij}, \mathcal{L}_j|_{X_{ij}})$$ satisfying the obvious cocycle condition over $(X_{ijk} \to S_{ijk})$ for every triple of indices. Then by descent for quasi-coherent sheaves (Descent on Spaces, Proposition Quasi-coherent complexes and coherent sheaves) we obtain a unique invertible $\mathcal{O}_X$-module $\mathcal{L}$ and isomorphisms $\mathcal{L}|_{X_i} \to \mathcal{L}_i$ recovering the descent datum $\varphi_{ij}$. To show that $(X \to S, \mathcal{L})$ is an object of $\mathcal{P}\!ol$ we have to prove that $\mathcal{L}$ is ample. This follows from Descent on Spaces, Lemma Descent of proper morphisms and line bundles and ampleness.
Since we already have seen that $\mathcal{S}\!paces'_{fp, flat, proper}$ is a stack in groupoids over $\mathrm{Sch}_{fppf}$ (Lemma Descent of proper flat spaces) it now follows formally that $\mathcal{P}\!ol$ is a stack in groupoids over $\mathrm{Sch}_{fppf}$. See Stacks, Lemma The geometric construction (uncovered prerequisite). $\square$
Lemma. The diagonal of the polarized moduli stack
The diagonal $$\Delta : \mathcal{P}\!ol \longrightarrow \mathcal{P}\!ol \times \mathcal{P}\!ol$$ is representable by algebraic spaces.
Proof. This is a formal consequence of Lemmas The forgetful map from polarized schemes to proper spaces and The diagonal of the proper-space groupoid. See Criteria for Representability, Lemma Diagonals and separation (uncovered prerequisite). $\square$
Lemma. Limit preservation for polarized proper schemes
The stack in groupoids $\mathcal{P}\!ol$ is limit preserving (Artin's Axioms, Definition Limit-preserving deformation groupoids).
Proof. Let $I$ be a directed set and let $(A_i, \varphi_{ii'})$ be a system of rings over $I$. Set $S = \operatorname{Spec}(A)$ and $S_i = \operatorname{Spec}(A_i)$. We have to show that on fibre categories we have $$\mathcal{P}\!ol_S = \mathop{\operatorname{colim}} \mathcal{P}\!ol_{S_i}$$ We know that the category of schemes of finite presentation over $S$ is the colimit of the category of schemes of finite presentation over $S_i$, see Limits, Lemma Descent of finite presentation and finite algebras. Moreover, given $X_i \to S_i$ of finite presentation, with limit $X \to S$, then the category of invertible $\mathcal{O}_X$-modules $\mathcal{L}$ is the colimit of the categories of invertible $\mathcal{O}_{X_i}$-modules $\mathcal{L}_i$, see Limits, Lemma Descent of finite presentation and modules and Descent of finite locally free and invertible modules. If $X \to S$ is proper and flat, then for sufficiently large $i$ the morphism $X_i \to S_i$ is proper and flat too, see Limits, Lemmas Proper morphisms and Descent of finite presentation and flatness. Finally, if $\mathcal{L}$ is ample on $X$ then $\mathcal{L}_i$ is ample on $X_i$ for $i$ sufficiently large, see Limits, Lemma Filtered limits and line bundles and ampleness. Putting everything together finishes the proof. $\square$
Lemma. Infinitesimal patching of polarized proper schemes
In Situation The groupoid of flat sheaves with proper support. Let $$\begin{gathered}\begin{matrix}T & T' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}T & \longrightarrow T' \\ T & \longrightarrow S \\ T' & \longrightarrow S' \\ S & \longrightarrow S'\end{aligned}\end{gathered}$$ be a pushout in the category of schemes where $T \to T'$ is a thickening and $T \to S$ is affine, see More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces. Then the functor on fibre categories $$\mathcal{P}\!ol_{S'} \longrightarrow \mathcal{P}\!ol_S \times_{\mathcal{P}\!ol_T} \mathcal{P}\!ol_{T'}$$ is an equivalence.
Proof. By More on Morphisms, Lemma Flatness and groupoids and equivalence relations there is an equivalence $$\textit{flat-lfp}_{S'} \longrightarrow \textit{flat-lfp}_S \times_{\textit{flat-lfp}_T} \textit{flat-lfp}_{T'}$$ where $\textit{flat-lfp}_S$ signifies the category of schemes flat and locally of finite presentation over $S$. Let $X'/S'$ on the left hand side correspond to the triple $(X/S, Y'/T', \varphi)$ on the right hand side. Set $Y = T \times_{T'} Y'$ which is isomorphic with $T \times_S X$ via $\varphi$. Then More on Morphisms, Lemma Flatness and modules shows that we have an equivalence $$\textit{QCoh-flat}_{X'/S'} \longrightarrow \textit{QCoh-flat}_{X/S} \times_{\textit{QCoh-flat}_{Y/T}} \textit{QCoh-flat}_{Y'/T'}$$ where $\textit{QCoh-flat}_{X/S}$ signifies the category of quasi-coherent $\mathcal{O}_X$-modules flat over $S$. Since $X \to S$, $Y \to T$, $X' \to S'$, $Y' \to T'$ are flat, this will in particular apply to invertible modules to give an equivalence of categories $$\textit{Pic}(X') \longrightarrow \textit{Pic}(X) \times_{\textit{Pic}(Y)} \textit{Pic}(Y')$$ where $\textit{Pic}(X)$ signifies the category of invertible $\mathcal{O}_X$-modules. There is a small point here: one has to show that if an object $\mathcal{F}'$ of $\textit{QCoh-flat}_{X'/S'}$ pulls back to invertible modules on $X$ and $Y'$, then $\mathcal{F}'$ is an invertible $\mathcal{O}_{X'}$-module. It follows from the cited lemma that $\mathcal{F}'$ is an $\mathcal{O}_{X'}$-module of finite presentation. By More on Morphisms, Lemma Projective, locally free modules and flatness it suffices to check the restriction of $\mathcal{F}'$ to fibres of $X' \to S'$ is invertible. But the fibres of $X' \to S'$ are the same as the fibres of $X \to S$ and hence these restrictions are invertible.
Having said the above we obtain an equivalence of categories if we drop the assumption (for the category of objects over $S$) that $X \to S$ be proper and the assumption that $\mathcal{L}$ be ample. Now it is clear that if $X' \to S'$ is proper, then $X \to S$ and $Y' \to T'$ are proper (Morphisms, Lemma Base change for proper morphisms (uncovered prerequisite)). Conversely, if $X \to S$ and $Y' \to T'$ are proper, then $X' \to S'$ is proper by More on Morphisms, Lemma Proper morphisms and nilpotent thickenings. Similarly, if $\mathcal{L}'$ is ample on $X'/S'$, then $\mathcal{L}'|_X$ is ample on $X/S$ and $\mathcal{L}'|_{Y'}$ is ample on $Y'/T'$ (Morphisms, Lemma Base change for line bundles and ampleness (uncovered prerequisite)). Finally, if $\mathcal{L}'|_X$ is ample on $X/S$ and $\mathcal{L}'|_{Y'}$ is ample on $Y'/T'$, then $\mathcal{L}'$ is ample on $X'/S'$ by More on Morphisms, Lemma Proper morphisms and line bundles and ampleness. $\square$
Lemma. Strong effectivity of polarized proper schemes (Strong formal effectiveness for polarized schemes)
Grothendieck's algebraization theorem continues to hold in the non-Noetherian setting if one assumes flatness and finite presentation.
Let $(R_n)$ be an inverse system of rings with surjective transition maps whose kernels are locally nilpotent. Set $R = \varprojlim R_n$. Set $S_n = \operatorname{Spec}(R_n)$ and $S = \operatorname{Spec}(R)$. Consider a commutative diagram $$\begin{gathered}\begin{matrix}X_1 & X_2 & X_3 & \ldots \\ S_1 & S_2 & S_3 & \ldots\end{matrix} \\[6pt] \begin{aligned}X_1 & \xrightarrow{i_1} X_2 \\ X_1 & \longrightarrow S_1 \\ X_2 & \xrightarrow{i_2} X_3 \\ X_2 & \longrightarrow S_2 \\ X_3 & \longrightarrow \ldots \\ X_3 & \longrightarrow S_3 \\ S_1 & \longrightarrow S_2 \\ S_2 & \longrightarrow S_3 \\ S_3 & \longrightarrow \ldots\end{aligned}\end{gathered}$$ of schemes with cartesian squares. Suppose given $(\mathcal{L}_n, \varphi_n)$ where each $\mathcal{L}_n$ is an invertible sheaf on $X_n$ and $\varphi_n : i_n^*\mathcal{L}_{n + 1} \to \mathcal{L}_n$ is an isomorphism. If
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$X_n \to S_n$ is proper, flat, of finite presentation, and
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$\mathcal{L}_1$ is ample on $X_1$
then there exists a morphism of schemes $X \to S$ proper, flat, and of finite presentation and an ample invertible $\mathcal{O}_X$-module $\mathcal{L}$ and isomorphisms $X_n \cong X \times_S S_n$ and $\mathcal{L}_n \cong \mathcal{L}|_{X_n}$ compatible with the morphisms $i_n$ and $\varphi_n$.
Proof. Choose $d_0$ for $X_1 \to S_1$ and $\mathcal{L}_1$ as in More on Morphisms, Lemma Uniform section algebras under nilpotent deformation. For any $n \geq 1$ set $$A_n = R_n \oplus \bigoplus\nolimits_{d \geq d_0} H^0(X_n, \mathcal{L}_n^{\otimes d})$$ By the lemma each $A_n$ is a finitely presented graded $R_n$-algebra whose homogeneous parts $(A_n)_d$ are finite projective $R_n$-modules such that $X_n = \text{Proj}(A_n)$ and $\mathcal{L}_n = \mathcal{O}_{\text{Proj}(A_n)}(1)$. The lemma also guarantees that the maps $$A_1 \leftarrow A_2 \leftarrow A_3 \leftarrow \ldots$$ induce isomorphisms $A_n = A_m \otimes_{R_m} R_n$ for $n \leq m$. We set $$B = \bigoplus\nolimits_{d \geq 0} B_d \quad\text{with}\quad B_d = \varprojlim_n (A_n)_d$$ By More on Algebra, Lemma Compatible finite projectives over an inverse limit we see that $B_d$ is a finite projective $R$-module and that $B \otimes_R R_n = A_n$. Thus the scheme $$X = \text{Proj}(B) \quad\text{and}\quad \mathcal{L} = \mathcal{O}_X(1)$$ is flat over $S$ and $\mathcal{L}$ is a quasi-coherent $\mathcal{O}_X$-module flat over $S$, see Divisors, Lemma Flatness. Because formation of Proj commutes with base change (Constructions, Lemma Base change for the geometric construction (uncovered prerequisite)) we obtain canonical isomorphisms $$X \times_S S_n = X_n \quad\text{and}\quad \mathcal{L}|_{X_n} \cong \mathcal{L}_n$$ compatible with the transition maps of the system. Thus we may think of $X_1 \subset X$ as a closed subscheme. Below we will show that $B$ is of finite presentation over $R$. By Divisors, Lemmas Proper morphisms and Finite presentation and finite algebras this implies that $X \to S$ is of finite presentation and proper and that $\mathcal{L} = \mathcal{O}_X(1)$ is of finite presentation as an $\mathcal{O}_X$-module. Since the restriction of $\mathcal{L}$ to the base change $X_1 \to S_1$ is invertible, we see from More on Morphisms, Lemma Projective, locally free modules and finite algebras that $\mathcal{L}$ is invertible on an open neighbourhood of $X_1$ in $X$. Since $X \to S$ is closed and since $\operatorname{Ker}(R \to R_1)$ is contained in the Jacobson radical (More on Algebra, Lemma Henselian pairs from locally nilpotent inverse systems) we see that any open neighbourhood of $X_1$ in $X$ is equal to $X$. Thus $\mathcal{L}$ is invertible. Finally, the set of points in $S$ where $\mathcal{L}$ is ample on the fibre is open in $S$ (More on Morphisms, Lemma Line bundles and ampleness) and contains $S_1$ hence equals $S$. Thus $X \to S$ and $\mathcal{L}$ have all the properties required of them in the statement of the lemma.
We prove the claim above. Choose a presentation $A_1 = R_1[X_1, \ldots, X_s]/(F_1, \ldots, F_t)$ where $X_i$ are variables having degrees $d_i$ and $F_j$ are homogeneous polynomials in $X_i$ of degree $e_j$. Then we can choose a map $$\Psi : R[X_1, \ldots, X_s] \longrightarrow B$$ lifting the map $R_1[X_1, \ldots, X_s] \to A_1$. Since each $B_d$ is finite projective over $R$ we conclude from Nakayama's lemma (Algebra, Lemma Nakayama's lemma using again that $\operatorname{Ker}(R \to R_1)$ is contained in the Jacobson radical of $R$) that $\Psi$ is surjective in every degree. Each polynomial degree piece is finite free, and $B_d$ is finite projective. Thus the degreewise surjection splits, so reduction identifies its kernel with the kernel of the reduced presentation. This projectivity, rather than right exactness alone, lets us find homogeneous $G_1, \ldots, G_t \in \operatorname{Ker}(\Psi)$ mapping to $F_1, \ldots, F_t$ in $R_1[X_1, \ldots, X_s]$. Observe that $\operatorname{Ker}(\Psi)_d$ is a finite projective $R$-module for all $d \geq 0$ as the kernel of the surjection $R[X_1, \ldots, X_s]_d \to B_d$ of finite projective $R$-modules. We conclude from Nakayama's lemma once more that the finite degreewise quotient of $\operatorname{Ker}(\Psi)$ by the ideal generated by $G_1, \ldots, G_t$ is zero after reduction and hence zero. Therefore $\operatorname{Ker}(\Psi)$ is generated by these homogeneous relations. $\square$
Lemma. Formal effectivity of polarized proper schemes
Consider the stack $\mathcal{P}\!ol$ over the base scheme $\operatorname{Spec}(\mathbf{Z})$. Then every formal object is effective.
Proof. For definitions of the notions in the lemma, please see Artin's Axioms, Section Formal objects and their markings. From the definitions we see the lemma follows immediately from the more general Lemma Strong effectivity of polarized proper schemes. $\square$
Lemma. Openness of versality for polarized proper schemes
The stack in groupoids $\mathcal{P}\!ol$ satisfies openness of versality over $\operatorname{Spec}(\mathbf{Z})$. Similarly, after base change (Remark Base change of the polarized moduli stack) openness of versality holds over any Noetherian base scheme $S$.
Proof. This follows from Artin's Axioms, Lemma Strong effectivity implies openness of versality and Lemmas The diagonal of the polarized moduli stack, Infinitesimal patching of polarized proper schemes, Limit preservation for polarized proper schemes, and Strong effectivity of polarized proper schemes. For the "usual" proof of this fact, please see the discussion in the remark following this proof. $\square$
Theorem. Algebraicity of the full polarized proper-scheme stack (Algebraicity of the stack of polarized schemes)
The stack $\mathcal{P}\!ol$ (Situation The groupoid of polarized proper schemes) is algebraic. In fact, for any algebraic space $B$ the stack $B\textit{-Polarized}$ (Remark Base change of the polarized moduli stack) is algebraic.
Proof. The absolute case follows from Artin's Axioms, Lemma Representability of a stack diagonal and Lemmas The diagonal of the polarized moduli stack, Infinitesimal patching of polarized proper schemes, Limit preservation for polarized proper schemes, Formal effectivity of polarized proper schemes, and Openness of versality for polarized proper schemes. The case over $B$ follows from this, the description of $B\textit{-Polarized}$ as a $2$-fibre product in Remark Base change of the polarized moduli stack, and the fact that algebraic stacks have $2$-fibre products, see Algebraic Stacks, Lemma Tensor products and direct sums (uncovered prerequisite). $\square$
Situation. The groupoid of proper flat spaces of dimension at most one
We define a category $\mathcal{C}\!urves$ as follows:
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Objects are families of curves. More precisely, an object is a morphism $f : X \to S$ where the base $S$ is a scheme, the total space $X$ is an algebraic space, and $f$ is flat, proper, of finite presentation, and has relative dimension $\leq 1$ (Morphisms of Spaces, Definition Relative dimension).
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A morphism $(X' \to S') \to (X \to S)$ between objects is given by a pair $(f, g)$ where $f : X' \to X$ is a morphism of algebraic spaces and $g : S' \to S$ is a morphism of schemes which fit into a commutative diagram $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow S' \\ X' & \xrightarrow{f} X \\ X & \longrightarrow S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ inducing an isomorphism $X' \to S' \times_S X$, in other words, the diagram is cartesian.
The forgetful functor $$p : \mathcal{C}\!urves \longrightarrow \mathrm{Sch}_{fppf},\quad (X \to S) \longmapsto S$$ is how we view $\mathcal{C}\!urves$ as a category over $\mathrm{Sch}_{fppf}$ (see Section Conventions for the moduli groupoids for notation).
Lemma. The groupoid of proper flat curve spaces
The category $\mathcal{C}\!urves$ is fibred in groupoids over $\mathrm{Sch}_{fppf}$.
Proof. Using the embedding (The inclusion of curve spaces in proper spaces), the description of the image, and the corresponding fact for $\mathcal{S}\!paces'_{fp, flat, proper}$ (Lemma The groupoid of proper flat spaces) this reduces to the following statement: Given a morphism $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow X \\ X' & \longrightarrow S' \\ X & \longrightarrow S \\ S' & \longrightarrow S\end{aligned}\end{gathered}$$ in $\mathcal{S}\!paces'_{fp, flat, proper}$ (recall that this implies in particular the diagram is cartesian) if $X \to S$ has relative dimension $\leq 1$, then $X' \to S'$ has relative dimension $\leq 1$. This follows from Morphisms of Spaces, Lemma Base change for dimension and codimension. $\square$
Lemma. Descent of proper flat curve spaces
The category $\mathcal{C}\!urves$ is a stack in groupoids over $\mathrm{Sch}_{fppf}$.
Proof. Using the embedding (The inclusion of curve spaces in proper spaces), the description of the image, and the corresponding fact for $\mathcal{S}\!paces'_{fp, flat, proper}$ (Lemma Descent of proper flat spaces) this reduces to the following statement: Given an object $X \to S$ of $\mathcal{S}\!paces'_{fp, flat, proper}$ and an fppf covering $\{S_i \to S\}_{i \in I}$ the following are equivalent:
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$X \to S$ has relative dimension $\leq 1$, and
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for each $i$ the base change $X_i \to S_i$ has relative dimension $\leq 1$.
This follows from Morphisms of Spaces, Lemma Base change for dimension and codimension. $\square$
Lemma. The diagonal of the proper curve-space stack
The diagonal $$\Delta : \mathcal{C}\!urves \longrightarrow \mathcal{C}\!urves \times \mathcal{C}\!urves$$ is representable by algebraic spaces.
Proof. This is immediate from the fully faithful embedding (The inclusion of curve spaces in proper spaces) and the corresponding fact for $\mathcal{S}\!paces'_{fp, flat, proper}$ (Lemma The diagonal of the proper-space groupoid). $\square$
Lemma. Limit preservation for proper flat curve spaces
The stack $\mathcal{C}\!urves \to \mathrm{Sch}_{fppf}$ is limit preserving (Artin's Axioms, Definition Limit-preserving deformation groupoids).
Proof. Using the embedding (The inclusion of curve spaces in proper spaces), the description of the image, and the corresponding fact for $\mathcal{S}\!paces'_{fp, flat, proper}$ (Lemma Limit preservation for proper flat spaces) this reduces to the following statement: Let $T = \varprojlim T_i$ be the limits of a directed inverse system of affine schemes. Let $i \in I$ and let $X_i \to T_i$ be an object of $\mathcal{S}\!paces'_{fp, flat, proper}$ over $T_i$. Assume that $T \times_{T_i} X_i \to T$ has relative dimension $\leq 1$. Then for some $i' \geq i$ the morphism $T_{i'} \times_{T_i} X_i \to T_i$ has relative dimension $\leq 1$. This follows from Limits of Spaces, Lemma Dimension and codimension. $\square$
Lemma. Infinitesimal patching of proper flat curve spaces
Let $$\begin{gathered}\begin{matrix}T & T' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}T & \longrightarrow T' \\ T & \longrightarrow S \\ T' & \longrightarrow S' \\ S & \longrightarrow S'\end{aligned}\end{gathered}$$ be a pushout in the category of schemes where $T \to T'$ is a thickening and $T \to S$ is affine, see More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces. Then the functor on fibre categories $$\mathcal{C}\!urves_{S'} \longrightarrow \mathcal{C}\!urves_S \times_{\mathcal{C}\!urves_T} \mathcal{C}\!urves_{T'}$$ is an equivalence.
Proof. Using the embedding (The inclusion of curve spaces in proper spaces), the description of the image, and the corresponding fact for $\mathcal{S}\!paces'_{fp, flat, proper}$ (Lemma Infinitesimal patching of proper flat spaces) this reduces to the following statement: given a morphism $X' \to S'$ of an algebraic space to $S'$ which is of finite presentation, flat, proper then $X' \to S'$ has relative dimension $\leq 1$ if and only if $S \times_{S'} X' \to S$ and $T' \times_{S'} X' \to T'$ have relative dimension $\leq 1$. One implication follows from the fact that having relative dimension $\leq 1$ is preserved under base change (Morphisms of Spaces, Lemma Base change for dimension and codimension). The other follows from the fact that having relative dimension $\leq 1$ is checked on the fibres and that the fibres of $X' \to S'$ (over points of the scheme $S'$) are the same as the fibres of $S \times_{S'} X' \to S$ since $S \to S'$ is a thickening by More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces. $\square$
Lemma. Finite tangent spaces of proper flat curve spaces
Let $k$ be a field and let $x = (X \to \operatorname{Spec}(k))$ be an object of $\mathcal{X} = \mathcal{C}\!urves$ over $\operatorname{Spec}(k)$.
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If $k$ is of finite type over $\mathbf{Z}$, then the vector spaces $T\mathcal{F}_{\mathcal{X}, k, x}$ and $\text{Inf}(\mathcal{F}_{\mathcal{X}, k, x})$ (see Artin's Axioms, Section Tangent spaces of deformation groupoids) are finite dimensional, and
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in general the vector spaces $T_x(k)$ and $\text{Inf}_x(k)$ (see Artin's Axioms, Section Infinitesimal automorphisms) are finite dimensional.
Proof. This is immediate from the fully faithful embedding (The inclusion of curve spaces in proper spaces) and the corresponding fact for $\mathcal{S}\!paces'_{fp, flat, proper}$ (Lemma Finite tangent spaces of proper flat spaces). $\square$
Lemma. Formal effectivity of proper flat curve spaces
Consider the stack $\mathcal{C}\!urves$ over the base scheme $\operatorname{Spec}(\mathbf{Z})$. Then every formal object is effective.
Proof. For definitions of the notions in the lemma, please see Artin's Axioms, Section Formal objects and their markings. Let $(A, \mathfrak m, \kappa)$ be a Noetherian complete local ring. Let $(X_n \to \operatorname{Spec}(A/\mathfrak m^n))$ be a formal object of $\mathcal{C}\!urves$ over $A$. By More on Morphisms of Spaces, Lemma Algebraization of a proper flat finitely presented family of dimension at most one there exists a projective morphism $X \to \operatorname{Spec}(A)$ and a compatible system of ismomorphisms $X \times_{\operatorname{Spec}(A)} \operatorname{Spec}(A/\mathfrak m^n) \cong X_n$. By More on Morphisms, Lemma Derived tensor products, Tor amplitude and flatness we see that $X \to \operatorname{Spec}(A)$ is flat. By More on Morphisms, Lemma Flatness and dimension and codimension we see that $X \to \operatorname{Spec}(A)$ has relative dimension $\leq 1$. This proves the lemma. $\square$
Lemma. Openness of versality for proper flat curve spaces
The stack in groupoids $\mathcal{X} = \mathcal{C}\!urves$ satisfies openness of versality over $\operatorname{Spec}(\mathbf{Z})$. Similarly, after base change (Remark Base change of the curve-space stack) openness of versality holds over any Noetherian base scheme $S$.
Proof. This is immediate from the fully faithful embedding (The inclusion of curve spaces in proper spaces) and the corresponding fact for $\mathcal{S}\!paces'_{fp, flat, proper}$ (Lemma Openness of versality for proper flat spaces). $\square$
Theorem. Algebraicity of the full stack of proper flat curve spaces (Algebraicity of the stack of curves)
Source credit: See the original source citation dJHS (Proposition 3.3, page 8) and the original source citation Smyth (Appendix B by Jack Hall, Theorem B.1).
The stack $\mathcal{C}\!urves$ (Situation The groupoid of proper flat spaces of dimension at most one) is algebraic. In fact, for any algebraic space $B$ the stack $B\text{-}\mathcal{C}\!urves$ (Remark Base change of the curve-space stack) is algebraic.
Proof. The absolute case follows from Artin's Axioms, Lemma Representability of a stack diagonal and Lemmas The diagonal of the proper curve-space stack, Infinitesimal patching of proper flat curve spaces, Limit preservation for proper flat curve spaces, Formal effectivity of proper flat curve spaces, and Openness of versality for proper flat curve spaces. The case over $B$ follows from this, the description of $B\text{-}\mathcal{C}\!urves$ as a $2$-fibre product in Remark Base change of the curve-space stack, and the fact that algebraic stacks have $2$-fibre products, see Algebraic Stacks, Lemma Tensor products and direct sums (uncovered prerequisite). $\square$
A.12.13 Complete dévissage and flatness dimension strata
These complete native scheme arguments support the incorporated algebraic-space flattening proof. They do not stand in for the remaining one-step dévissage and finite-generic-rank representability arguments; those precise labels are recorded next. In the complete-dévissage proposition, $\mathcal F$ is a finite-type quasi-coherent module as required by the section and the actual consumer; its printed statement has omitted that quantification. In the dimension-stratum proof, after $T$-base change all references to relative flatness are over $T$.
Proposition. Complete dévissage at a point
Let $\mathcal F$ be a finite-type quasi-coherent module on $X$.
Let $S$ be a scheme. Let $X$ be locally of finite type over $S$. Let $x \in X$ be a point with image $s \in S$. There exists a commutative diagram $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (S', s')\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ of pointed schemes such that the horizontal arrows are elementary étale neighbourhoods and such that $g^*\mathcal{F}/X'/S'$ has a complete dévissage at $x$.
Proof. We prove this by induction on the integer $d = \dim_x(\text{Supp}(\mathcal{F}_s))$. By Lemma Purity and dévissage there exists a diagram $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (S', s')\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ of pointed schemes such that the horizontal arrows are elementary étale neighbourhoods and such that $g^*\mathcal{F}/X'/S'$ has a one step dévissage at $x'$. The local nature of the problem implies that we may replace $(X, x) \to (S, s)$ by $(X', x') \to (S', s')$. Thus after doing so we may assume that there exists a one step dévissage $(Z_1, Y_1, i_1, \pi_1, \mathcal{G}_1)$ of $\mathcal{F}/X/S$ at $x$.
We apply Lemma A generic free presentation in dévissage to find a map $$\alpha_1 : \mathcal{O}_{Y_1}^{\oplus r_1} \longrightarrow \pi_{1, *}\mathcal{G}_1$$ which induces an isomorphism of vector spaces over $\kappa(\xi_1)$ where $\xi_1 \in Y_1$ is the unique generic point of the fibre of $Y_1$ over $s$. Moreover $\dim_{y_1}(\text{Supp}(\operatorname{Coker}(\alpha_1)_s)) < d$. It may happen that the stalk of $\operatorname{Coker}(\alpha_1)_s$ at $y_1$ is zero. In this case we may shrink $Y_1$ by Lemma Restriction of a dévissage to a neighbourhood (the indicated step) and assume that $\operatorname{Coker}(\alpha_1) = 0$ so we obtain a complete dévissage of length zero.
Assume now that the stalk of $\operatorname{Coker}(\alpha_1)_s$ at $y_1$ is not zero. In this case, by induction, there exists a commutative diagram
$$\begin{gathered}\begin{matrix}(Y_1, y_1) & (Y'_1, y'_1) \\ (S, s) & (S', s')\end{matrix} \\[6pt] \begin{aligned}(Y_1, y_1) & \longrightarrow (S, s) \\ (Y'_1, y'_1) & \xrightarrow{h} (Y_1, y_1) \\ (Y'_1, y'_1) & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ of pointed schemes such that the horizontal arrows are elementary étale neighbourhoods and such that $h^*\operatorname{Coker}(\alpha_1)/Y'_1/S'$ has a complete dévissage $$(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k, z_k, y_k)_{k = 2, \ldots, n}$$ at $y'_1$. (In particular $i_2 : Z_2 \to Y'_1$ is a closed immersion into $Y'_2$.) At this point we apply Lemma Étale morphisms to $S, X, \mathcal{F}, x, s$, the system $(Z_1, Y_1, i_1, \pi_1, \mathcal{G}_1)$ and diagram (the displayed identity). We obtain a diagram $$\begin{gathered}\begin{matrix}\phantom{X} & \phantom{X} & (X'', x'') & (Z''_1, z''_1) \\ (X, x) & (Z_1, z_1) & (S'', s'') & (Y''_1, y''_1) \\ (S, s) & (Y_1, y_1)\end{matrix} \\[6pt] \begin{aligned}(X'', x'') & \longrightarrow (X, x) \\ (X'', x'') & \longrightarrow (S'', s'') \\ (Z''_1, z''_1) & \longrightarrow (X'', x'') \\ (Z''_1, z''_1) & \longrightarrow (Z_1, z_1) \\ (Z''_1, z''_1) & \longrightarrow (Y''_1, y''_1) \\ (X, x) & \longrightarrow (S, s) \\ (Z_1, z_1) & \longrightarrow (X, x) \\ (Z_1, z_1) & \longrightarrow (Y_1, y_1) \\ (S'', s'') & \longrightarrow (S, s) \\ (Y''_1, y''_1) & \longrightarrow (Y_1, y_1) \\ (Y''_1, y''_1) & \longrightarrow (S'', s'') \\ (Y_1, y_1) & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ with all the properties as listed in the referenced lemma. In particular $Y''_1 \subset Y'_1 \times_{S'} S''$. Set $X_1 = Y'_1 \times_{S'} S''$ and let $\mathcal{F}_1$ denote the pullback of $\operatorname{Coker}(\alpha_1)$. By Lemma Base change for complete rings and formal power series the system
$$(Z_k \times_{S'} S'', Y_k \times_{S'} S'', i''_k, \pi''_k, \mathcal{G}''_k, \alpha''_k, z''_k, y''_k)_{k = 2, \ldots, n}$$ is a complete dévissage of $\mathcal{F}_1$ to $X_1$. Again, the nature of the problem allows us to replace $(X, x) \to (S, s)$ by $(X'', x'') \to (S'', s'')$. In this we see that we may assume:
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There exists a one step dévissage $(Z_1, Y_1, i_1, \pi_1, \mathcal{G}_1)$ of $\mathcal{F}/X/S$ at $x$,
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there exists an $\alpha_1 : \mathcal{O}_{Y_1}^{\oplus r_1} \to \pi_{1, *}\mathcal{G}_1$ such that $\alpha \otimes \kappa(\xi_1)$ is an isomorphism,
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$Y_1 \subset X_1$ is open, $y_1 = x_1$, and $\mathcal{F}_1|_{Y_1} \cong \operatorname{Coker}(\alpha_1)$, and
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there exists a complete dévissage $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k, z_k, y_k)_{k = 2, \ldots, n}$ of $\mathcal{F}_1/X_1/S$ at $x_1$.
To finish the proof all we have to do is shrink the one step dévissage and the complete dévissage such that they fit together to a complete dévissage. (We suggest the reader do this on their own using Lemmas Restriction of a dévissage to a neighbourhood and Restriction of a complete dévissage instead of reading the proof that follows.) Since $Y_1 \subset X_1$ is an open neighbourhood of $x_1$ we may apply Lemma Restriction of a complete dévissage (the indicated step) to find a standard shrinking $S', X'_1, Z'_2, Y'_2, \ldots, Y'_n$ of the datum (d) so that $X'_1 \subset Y_1$. Note that $X'_1$ is also a standard open of the affine scheme $Y_1$. Next, we shrink the datum (a) as follows: first we shrink the base $S$ to $S'$, see Lemma Restriction of a dévissage to a neighbourhood (the indicated step) and then we shrink the result to $S''$, $X''$, $Z''_1$, $Y''_1$ using Lemma Restriction of a dévissage to a neighbourhood (the indicated step) such that eventually $Y''_1 = X'_1 \times_S S''$ and $S'' \subset S'$. Then we see that $$Z''_1, Y''_1, Z'_2 \times_{S'} S'', Y'_2 \times_{S'} S'', \ldots, Y'_n \times_{S'} S''$$ gives the complete dévissage we were looking for. $\square$
Lemma. Complete dévissage around a fibre
Let $X \to S$ be a finite type morphism of schemes. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Let $s \in S$ be a point. There exists an elementary étale neighbourhood $(S', s') \to (S, s)$ and étale morphisms $h_i : Y_i \to X_{S'}$, $i = 1, \ldots, n$ such that for each $i$ there exists a complete dévissage of $\mathcal{F}_i/Y_i/S'$ over $s'$, where $\mathcal{F}_i$ is the pullback of $\mathcal{F}$ to $Y_i$ and such that $X_s = (X_{S'})_{s'} \subset \bigcup h_i(Y_i)$.
Proof. For every point $x \in X_s$ we can find a diagram $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (S', s')\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ of pointed schemes such that the horizontal arrows are elementary étale neighbourhoods and such that $g^*\mathcal{F}/X'/S'$ has a complete dévissage at $x'$. As $X \to S$ is of finite type the fibre $X_s$ is quasi-compact, and since each $g : X' \to X$ as above is open we can cover $X_s$ by a finite union of $g(X'_{s'})$. Thus we can find a finite family of such diagrams $$\begin{gathered}\begin{matrix}(X, x) & (X'_i, x'_i) \\ (S, s) & (S'_i, s'_i)\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X'_i, x'_i) & \xrightarrow{g_i} (X, x) \\ (X'_i, x'_i) & \longrightarrow (S'_i, s'_i) \\ (S'_i, s'_i) & \longrightarrow (S, s)\end{aligned}\end{gathered} \quad i = 1, \ldots, n$$ such that $X_s = \bigcup g_i(X'_i)$. Set $S' = S'_1 \times_S \ldots \times_S S'_n$ and let $Y_i = X_i \times_{S'_i} S'$ be the base change of $X'_i$ to $S'$. By Lemma Base change for complete rings and formal power series we see that the pullback of $\mathcal{F}$ to $Y_i$ has a complete dévissage over $s$ and we win. $\square$
Lemma. Representing a flatness dimension stratum
In Situation The universal flatness dimension stratum. Let $s \in S$ let $d \geq 0$. Assume
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there exists a complete dévissage of $\mathcal{F}/X/S$ over some point $s \in S$,
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$X$ is of finite presentation over $S$,
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$\mathcal{F}$ is an $\mathcal{O}_X$-module of finite presentation, and
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$\mathcal{F}$ is flat in dimensions $\geq d + 1$ over $S$.
Then after possibly replacing $S$ by an open neighbourhood of $s$ the functor $F_d$ (the displayed identity) is representable by a monomorphism $Z_d \to S$ of finite presentation.
Proof. A preliminary remark is that $X$, $S$ are affine schemes and that it suffices to prove $F_d$ is representable by a monomorphism of finite presentation $Z_d \to S$ on the category of affine schemes over $S$. (Of course we do not require $Z_d$ to be affine.) Hence throughout the proof of the lemma we work in the category of affine schemes over $S$.
Let $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k)_{k = 1, \ldots, n}$ be a complete dévissage of $\mathcal{F}/X/S$ over $s$, see Definition Complete dévissage. We will use induction on the length $n$ of the dévissage. Recall that $Y_k \to S$ is smooth with geometrically irreducible fibres, see Definition Purity and dévissage. Let $d_k$ be the relative dimension of $Y_k$ over $S$. Recall that $i_{k, *}\mathcal{G}_k = \operatorname{Coker}(\alpha_k)$ and that $i_k$ is a closed immersion. By the definitions referenced above we have $d_1 = \dim(\text{Supp}(\mathcal{F}_s))$ and $$d_k = \dim(\text{Supp}(\operatorname{Coker}(\alpha_{k - 1})_s)) = \dim(\text{Supp}(\mathcal{G}_{k, s}))$$ for $k = 2, \ldots, n$. It follows that $d_1 > d_2 > \ldots > d_n \geq 0$ because $\alpha_k$ is an isomorphism in the generic point of $(Y_k)_s$.
Note that $i_1$ is a closed immersion and $\mathcal{F} = i_{1, *}\mathcal{G}_1$. Hence for any morphism of schemes $T \to S$ with $T$ affine, we have $\mathcal{F}_T = i_{1, T, *}\mathcal{G}_{1, T}$ and $i_{1, T}$ is still a closed immersion of schemes over $T$. Thus $\mathcal{F}_T$ is flat in dimensions $\geq d$ over $T$ if and only if $\mathcal{G}_{1, T}$ is flat in dimensions $\geq d$ over $T$. Because $\pi_1 : Z_1 \to Y_1$ is finite we see in the same manner that $\mathcal{G}_{1, T}$ is flat in dimensions $\geq d$ over $T$ if and only if $\pi_{1, T, *}\mathcal{G}_{1, T}$ is flat in dimensions $\geq d$ over $T$. The same arguments work for "flat in dimensions $\geq d + 1$" and we conclude in particular that $\pi_{1, *}\mathcal{G}_1$ is flat over $S$ in dimensions $\geq d + 1$ by our assumption on $\mathcal{F}$.
Suppose that $d_1 > d$. It follows from the discussion above that in particular $\pi_{1, *}\mathcal{G}_1$ is flat over $S$ at the generic point of $(Y_1)_s$. By Lemma Finite presentation we may replace $S$ by an affine neighbourhood of $s$ and assume that $\alpha_1$ is $S$-universally injective. Because $\alpha_1$ is $S$-universally injective, for any morphism $T \to S$ with $T$ affine, we have a short exact sequence $$0 \to \mathcal{O}_{Y_{1, T}}^{\oplus r_1} \to \pi_{1, T, *}\mathcal{G}_{1, T} \to \operatorname{Coker}(\alpha_1)_T \to 0$$ and still the first arrow is $T$-universally injective. Hence the set of points of $(Y_1)_T$ where $\pi_{1, T, *}\mathcal{G}_{1, T}$ is flat over $T$ is the same as the set of points of $(Y_1)_T$ where $\operatorname{Coker}(\alpha_1)_T$ is flat over $T$. In this way the question reduces to the sheaf $\operatorname{Coker}(\alpha_1)$ which has a complete dévissage of length $n - 1$ and we win by induction.
If $d_1 < d$ then $F_d$ is represented by $S$ and we win.
The last case is the case $d_1 = d$. This case follows from a combination of Lemma Comparison for purity and dévissage and Lemma Projective and locally free modules. $\square$
Lemma. Recovering a monomorphism from a locally nilpotent tower
Let $A = \varprojlim A_n$ be a limit of a system of rings whose transition maps are surjective and with locally nilpotent kernels. Let $S = \operatorname{Spec}(A)$. Let $T \to S$ be a monomorphism which is locally of finite type. If $\operatorname{Spec}(A_n) \to S$ factors through $T$ for all $n$, then $T = S$.
Proof. Set $S_n = \operatorname{Spec}(A_n)$. Let $T_0 \subset T$ be the common image of the factorizations $S_n \to T$. Then $T_0$ is quasi-compact. Let $T' \subset T$ be a quasi-compact open containing $T_0$. Then $S_n \to T$ factors through $T'$. If we can show that $T' = S$, then $T' = T = S$. Hence we may assume $T$ is quasi-compact.
Assume $T$ is quasi-compact. In this case $T \to S$ is separated and quasi-finite (Morphisms, Lemma Finite algebras (uncovered prerequisite)). Using Zariski's Main Theorem (in the form of More on Morphisms, Lemma Diagonals, separation and finite algebras) we choose a factorization $T \to W \to S$ with $W \to S$ finite and $T \to W$ an open immersion. Write $W = \operatorname{Spec}(B)$. The (unique) factorizations $S_n \to T$ may be viewed as morphisms into $W$ and we obtain $$A \longrightarrow B \longrightarrow \varprojlim A_n = A$$ Consider the morphism $h : S = \operatorname{Spec}(A) \to \operatorname{Spec}(B) = W$ coming from the arrow on the right. Then $$T \times_{W, h} S$$ is an open subscheme of $S$ containing the image of $S_n \to S$ for all $n$. To finish the proof it suffices to show that any open $U \subset S$ containing the image of $S_n \to S$ for some $n \geq 1$ is equal to $S$. This is true because $(A, \operatorname{Ker}(A \to A_n))$ is a henselian pair (More on Algebra, Lemma Henselian pairs from locally nilpotent inverse systems) and hence every closed point of $S$ is contained in the image of $S_n \to S$. $\square$
Additional proofs of the supporting constructions
These statements and full proofs supply local support for the preceding arguments. They reuse the same Stacks Project edition. A remaining genuine prerequisite is marked explicitly rather than treated as proved.
Descent of algebraic spaces through inverse limits
Lemma. Descent of finite locally free and invertible modules
With notation and assumptions as in Lemma Descent of finite presentation and finite algebras. Then
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any finite locally free $\mathcal{O}_X$-module is the pullback of a finite locally free $\mathcal{O}_{X_i}$-module for some $i$,
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any invertible $\mathcal{O}_X$-module is the pullback of an invertible $\mathcal{O}_{X_i}$-module for some $i$.
Proof. Proof of (2). Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Since invertible modules are of finite presentation we can find an $i$ and modules $\mathcal{L}_i$ and $\mathcal{N}_i$ of finite presentation over $X_i$ such that $f_i^*\mathcal{L}_i \cong \mathcal{L}$ and $f_i^*\mathcal{N}_i \cong \mathcal{L}^{\otimes -1}$, see Lemma Descent of finite presentation and modules. Since pullback commutes with tensor product we see that $f_i^*(\mathcal{L}_i \otimes_{\mathcal{O}_{X_i}} \mathcal{N}_i)$ is isomorphic to $\mathcal{O}_X$. Since the tensor product of finitely presented modules is finitely presented, the same lemma implies that $f_{i'i}^*\mathcal{L}_i \otimes_{\mathcal{O}_{X_{i'}}} f_{i'i}^*\mathcal{N}_i$ is isomorphic to $\mathcal{O}_{X_{i'}}$ for some $i' \geq i$. It follows that $f_{i'i}^*\mathcal{L}_i$ is invertible, as follows. On an affine etale chart, let $M$ and $N$ denote the two finitely presented modules with $M\otimes N\cong R$. At each local ring their residue-vector-space dimensions have product one. Nakayama makes both modules cyclic there, so they have the form $R/J$ and $R/K$. Their tensor product is $R/(J+K)\cong R$, whence $J=K=0$. Finite presentation spreads these generators to a neighbourhood; the same tensor argument makes the modules free of rank one on that neighbourhood. Thus the descended module is invertible and the proof of (2) is complete.
Proof of (1). A finite locally free module $E$ has a finitely presented dual $E^\vee$, with evaluation and coevaluation maps satisfying the two triangle identities. Descend the two modules by Lemma Descent of finite presentation and modules, then their two maps by its full faithfulness, and finally the two identities by equality at a later stage in the same colimit category. The resulting module $E_i$ is dualizable. To check that it is finite locally free, work on an affine etale chart and write its coevaluation as a finite sum $\sum_j n_j\otimes m_j$. The triangle identity says $m=\sum_j m_j\operatorname{ev}(m\otimes n_j)$ for every $m$. Hence the maps $R^{\oplus r}\to E_i$, given by the $m_j$, and $E_i\to R^{\oplus r}$, given by these evaluations, compose to the identity. The module is therefore finite projective. A finite projective module is finite locally free: over each local ring choose a residue-field basis, split the resulting surjection from a finite free module, and apply Nakayama to its finite projective kernel; the chosen basis and its inverse maps then spread to a neighbourhood. This proves (1) over arbitrary bases, with the original module as its pullback. $\square$
Lemma. Descent of finite presentation and finite algebras
Let $S$ be a scheme. Let $I$ be a directed set. Let $(X_i, f_{ii'})$ be an inverse system over $I$ of algebraic spaces over $S$. Assume
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the morphisms $f_{ii'} : X_i \to X_{i'}$ are affine,
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the spaces $X_i$ are quasi-compact and quasi-separated.
Let $X = \varprojlim_i X_i$. Then the category of algebraic spaces of finite presentation over $X$ is the colimit over $I$ of the categories of algebraic spaces of finite presentation over $X_i$.
Proof. Pick $0 \in I$. Choose a surjective étale morphism $U_0 \to X_0$ where $U_0$ is an affine scheme (Properties of Spaces, Lemma Affine neighbourhoods). Set $U_i = X_i \times_{X_0} U_0$. Set $R_0 = U_0 \times_{X_0} U_0$ and $R_i = R_0 \times_{X_0} X_i$. Denote $s_i, t_i : R_i \to U_i$ and $s, t : R \to U$ the two projections. In the proof of Lemma Descent of algebraic spaces we have seen that there exists a presentation $X = U/R$ with $U = \varprojlim U_i$ and $R = \varprojlim R_i$. Note that $U_i$ and $U$ are affine and that $R_i$ and $R$ are quasi-compact and separated (as $X_i$ is quasi-separated). Let $Y$ be an algebraic space over $S$ and let $Y \to X$ be a morphism of finite presentation. Set $V = U \times_X Y$. This is an algebraic space of finite presentation over $U$. Choose an affine scheme $W$ and a surjective étale morphism $W \to V$. Then $W \to Y$ is surjective étale as well. Set $R' = W \times_Y W$ so that $Y = W/R'$ (see Spaces, Section The geometric construction). Note that $W$ is a scheme of finite presentation over $U$ and that $R'$ is a scheme of finite presentation over $R$ (details omitted). By Limits, Lemma Descent of finite presentation and finite algebras we can find an index $i$ and a morphism of schemes $W_i \to U_i$ of finite presentation whose base change to $U$ gives $W \to U$. Similarly we can find, after possibly increasing $i$, a scheme $R'_i$ of finite presentation over $R_i$ whose base change to $R$ is $R'$. The projection morphisms $s', t' : R' \to W$ are morphisms over the projection morphisms $s, t : R \to U$. Hence we can view $s'$, resp. $t'$ as a morphism between schemes of finite presentation over $U$ (with structure morphism $R' \to U$ given by $R' \to R$ followed by $s$, resp. $t$). Hence we can apply Limits, Lemma Descent of finite presentation and finite algebras again to see that, after possibly increasing $i$, there exist morphisms $s'_i, t'_i : R'_i \to W_i$, whose base change to $U$ is $S', t'$. By Limits, Lemmas Descent of étale morphisms and Descent of finite-presentation descent we may assume that $s'_i, t'_i$ are étale and that $j'_i : R'_i \to W_i \times_{X_i} W_i$ is a monomorphism (here we view $j'_i$ as a morphism of schemes of finite presentation over $U_i$ via one of the projections -- it doesn't matter which one). Setting $Y_i = W_i/R'_i$ (see Spaces, Theorem The geometric construction (uncovered prerequisite)) we obtain an algebraic space of finite presentation over $X_i$ whose base change to $X$ is isomorphic to $Y$.
This shows that every algebraic space of finite presentation over $X$ comes from an algebraic space of finite presentation over some $X_i$, i.e., it shows that the functor of the lemma is essentially surjective. To show that it is fully faithful, consider an index $0 \in I$ and two algebraic spaces $Y_0, Z_0$ of finite presentation over $X_0$. Set $Y_i = X_i \times_{X_0} Y_0$, $Y = X \times_{X_0} Y_0$, $Z_i = X_i \times_{X_0} Z_0$, and $Z = X \times_{X_0} Z_0$. Let $\alpha : Y \to Z$ be a morphism of algebraic spaces over $X$. Choose a surjective étale morphism $V_0 \to Y_0$ where $V_0$ is an affine scheme. Set $V_i = V_0 \times_{Y_0} Y_i$ and $V = V_0 \times_{Y_0} Y$ which are affine schemes endowed with surjective étale morphisms to $Y_i$ and $Y$. The composition $V \to Y \to Z \to Z_0$ comes from a (essentially unique) morphism $V_i \to Z_0$ for some $i \geq 0$ by Proposition Criteria for finite presentation and finite algebras (applied to $Z_0 \to X_0$ which is of finite presentation by assumption). After increasing $i$ the two compositions $$V_i \times_{Y_i} V_i \to V_i \to Z_0$$ are equal as this is true in the limit. Hence we obtain a (essentially unique) morphism $Y_i \to Z_0$. Since this is a morphism over $X_0$ it induces a morphism into $Z_i = Z_0 \times_{X_0} X_i$ as desired. $\square$
Lemma. Descent of finite presentation and modules
With notation and assumptions as in Lemma Descent of finite presentation and finite algebras. The category of $\mathcal{O}_X$-modules of finite presentation is the colimit over $I$ of the categories $\mathcal{O}_{X_i}$-modules of finite presentation.
Proof. Choose $0 \in I$. Choose an affine scheme $U_0$ and a surjective étale morphism $U_0 \to X_0$. Set $U_i = X_i \times_{X_0} U_0$. Set $R_0 = U_0 \times_{X_0} U_0$ and $R_i = R_0 \times_{X_0} X_i$. Denote $s_i, t_i : R_i \to U_i$ and $s, t : R \to U$ the two projections. In the proof of Lemma Descent of algebraic spaces we have seen that there exists a presentation $X = U/R$ with $U = \varprojlim U_i$ and $R = \varprojlim R_i$. Note that $U_i$ and $U$ are affine and that $R_i$ and $R$ are quasi-compact and separated (as $X_i$ is quasi-separated). Moreover, it is also true that $R \times_{s, U, t} R = \mathop{\operatorname{colim}} R_i \times_{s_i, U_i, t_i} R_i$. Thus we know that $\mathrm{QCoh}(\mathcal{O}_U) = \mathop{\operatorname{colim}} \mathrm{QCoh}(\mathcal{O}_{U_i})$, $\mathrm{QCoh}(\mathcal{O}_R) = \mathop{\operatorname{colim}} \mathrm{QCoh}(\mathcal{O}_{R_i})$, and $\mathrm{QCoh}(\mathcal{O}_{R \times_{s, U, t} R}) = \mathop{\operatorname{colim}} \mathrm{QCoh}(\mathcal{O}_{R_i \times_{s_i, U_i, t_i} R_i})$ by Limits, Lemma Descent of finite presentation and modules. We have $\mathrm{QCoh}(\mathcal{O}_X) = \mathrm{QCoh}(U, R, s, t, c)$ and $\mathrm{QCoh}(\mathcal{O}_{X_i}) = \mathrm{QCoh}(U_i, R_i, s_i, t_i, c_i)$, see Properties of Spaces, Proposition Quasi-coherent complexes and coherent sheaves. Thus the result follows formally. $\square$
Lemma. Descent of flatness
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. Let $\mathcal{F}_0$ be a quasi-coherent $\mathcal{O}_{X_0}$-module and denote $\mathcal{F}_i$ the pullback to $X_i$ and $\mathcal{F}$ the pullback to $X$. If
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$\mathcal{F}$ is flat over $Y$,
-
$\mathcal{F}_0$ is of finite presentation, and
-
$f_0$ is locally of finite presentation,
then $\mathcal{F}_i$ is flat over $Y_i$ for some $i \geq 0$. In particular, if $f_0$ is locally of finite presentation and $f$ is flat, then $f_i$ is flat for some $i \geq 0$.
Proof. Choose an affine scheme $V_0$ and a surjective étale morphism $V_0 \to Y_0$. Choose an affine scheme $U_0$ and a surjective étale morphism $U_0 \to V_0 \times_{Y_0} X_0$. Diagram $$\begin{gathered}\begin{matrix}U_0 & V_0 \\ X_0 & Y_0\end{matrix} \\[6pt] \begin{aligned}U_0 & \longrightarrow X_0 \\ U_0 & \longrightarrow V_0 \\ V_0 & \longrightarrow Y_0 \\ X_0 & \longrightarrow Y_0\end{aligned}\end{gathered}$$ The vertical arrows are surjective and étale by construction. We can base change this diagram to $B_i$ or $B$ to get $$\begin{gathered}\begin{matrix}U_i & V_i \\ X_i & Y_i\end{matrix} \\[6pt] \begin{aligned}U_i & \longrightarrow X_i \\ U_i & \longrightarrow V_i \\ V_i & \longrightarrow Y_i \\ X_i & \longrightarrow Y_i\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ Note that $U_i, V_i, U, V$ are affine schemes, the vertical morphisms are surjective étale, and the limit of the morphisms $U_i \to V_i$ is $U \to V$. Recall that $\mathcal{F}_i$ is flat over $Y_i$ if and only if $\mathcal{F}_i|_{U_i}$ is flat over $V_i$ and similarly $\mathcal{F}$ is flat over $Y$ if and only if $\mathcal{F}|_U$ is flat over $V$ (Morphisms of Spaces, Definition Flat morphisms of algebraic spaces). Since $f_0$ is locally of finite presentation, so is the morphism $U_0 \to V_0$. Hence the lemma follows from Limits, Lemma Descent of finite presentation and flatness. $\square$
Lemma. Proper morphisms and closed support
Assumptions and notation as in Situation A property to be descended through a filtered inverse system. Let $\mathcal{F}_0$ be a quasi-coherent $\mathcal{O}_{X_0}$-module. Denote $\mathcal{F}$ and $\mathcal{F}_i$ the pullbacks of $\mathcal{F}_0$ to $X$ and $X_i$. Assume
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$f_0$ is locally of finite type,
-
$\mathcal{F}_0$ is of finite type,
-
the scheme theoretic support of $\mathcal{F}$ is proper over $Y$.
Then the scheme theoretic support of $\mathcal{F}_i$ is proper over $Y_i$ for some $i$.
Proof. We may replace $X_0$ by the scheme theoretic support of $\mathcal{F}_0$. By Morphisms of Spaces, Lemma Closed support and finite algebras this guarantees that $X_i$ is the support of $\mathcal{F}_i$ and $X$ is the support of $\mathcal{F}$. Then, if $Z \subset X$ denotes the scheme theoretic support of $\mathcal{F}$, we see that $Z \to X$ is a universal homeomorphism. We conclude that $X \to Y$ is proper as this is true for $Z \to Y$ by assumption, see Morphisms, Lemma Proper morphisms (uncovered prerequisite). By Lemma Proper morphisms we see that $X_i \to Y$ is proper for some $i$. Then it follows that the scheme theoretic support $Z_i$ of $\mathcal{F}_i$ is proper over $Y$ by Morphisms of Spaces, Lemmas Proper morphisms and diagonals and separation and Composition and proper morphisms. $\square$
Lemma. Descent of diagonals and separation
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. If $f$ is separated, then $f_i$ is separated for some $i \geq 0$.
Proof. Apply Lemma Descent of diagonals and separation to the diagonal morphism $\Delta_{X_0/Y_0} : X_0 \to X_0 \times_{Y_0} X_0$. (Diagonal morphisms are locally of finite type and the fibre product $X_0 \times_{Y_0} X_0$ is quasi-compact and quasi-separated. Some details omitted.) $\square$
Proposition. Finite algebras
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$.
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There exists a surjective finite morphism $Y \to X$ of finite presentation where $Y$ is a scheme,
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given a surjective étale morphism $U \to X$ we may choose $Y \to X$ such that for every $y \in Y$ there is an open neighbourhood $V \subset Y$ such that $V \to X$ factors through $U$.
Proof. Part (1) is the special case of (2) with $U = X$. Let $Y \to X$ be as in Decent Spaces, Lemma Integral extensions. Choose a finite affine open covering $Y = \bigcup V_j$ such that $V_j \to X$ factors through $U$. We can write $Y = \varprojlim Y_i$ with $Y_i \to X$ finite and of finite presentation, see Lemma Finite presentation and integral extensions. For large enough $i$ the algebraic space $Y_i$ is a scheme, see Lemma Filtered limits and descent of algebraic spaces. For large enough $i$ we can find affine opens $V_{i, j} \subset Y_i$ whose inverse image in $Y$ recovers $V_j$, see Lemma Descent of descent of algebraic spaces. For even larger $i$ the morphisms $V_j \to U$ over $X$ come from morphisms $V_{i, j} \to U$ over $X$, see Proposition Criteria for finite presentation and finite algebras. This finishes the proof. $\square$
Lemma. Proper morphisms
Assumptions and notation as in Situation A property to be descended through a filtered inverse system. If
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$f$ is proper, and
-
$f_0$ is locally of finite type,
then there exists an $i$ such that $f_i$ is proper.
Proof. Choose an affine scheme $V_0$ and a surjective étale morphism $V_0 \to Y_0$. Set $V_i = Y_i \times_{Y_0} V_0$ and $V = Y \times_{Y_0} V_0$. It suffices to prove that the base change of $f_i$ to $V_i$ is proper, see Morphisms of Spaces, Lemma Proper morphisms and local algebra. Thus we may assume $Y_0$ is affine.
By Lemma Descent of diagonals and separation we see that $f_i$ is separated for some $i \geq 0$. Replacing $0$ by $i$ we may assume that $f_0$ is separated. Observe that $f_0$ is quasi-compact. Thus $f_0$ is separated and of finite type. By Cohomology of Spaces, Lemma The weak Chow lemma for algebraic spaces we can choose a diagram $$\begin{gathered}\begin{matrix}X_0 & X_0' & \mathbf{P}^n_{Y_0} \\ \phantom{X} & Y_0 & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X_0 & \longrightarrow Y_0 \\ X_0' & \longrightarrow Y_0 \\ X_0' & \xrightarrow{\pi} X_0 \\ X_0' & \longrightarrow \mathbf{P}^n_{Y_0} \\ \mathbf{P}^n_{Y_0} & \longrightarrow Y_0\end{aligned}\end{gathered}$$ where $X_0' \to \mathbf{P}^n_{Y_0}$ is an immersion, and $\pi : X_0' \to X_0$ is proper and surjective. Introduce $X' = X_0' \times_{Y_0} Y$ and $X_i' = X_0' \times_{Y_0} Y_i$. By Morphisms of Spaces, Lemmas Composition and proper morphisms and Base change for proper morphisms we see that $X' \to Y$ is proper. Hence $X' \to \mathbf{P}^n_Y$ is a closed immersion (Morphisms of Spaces, Lemma Morphisms of algebraic spaces). By Morphisms of Spaces, Lemma Proper morphisms it suffices to prove that $X'_i \to Y_i$ is proper for some $i$. By Lemma Descent of diagonals and separation we find that $X'_i \to \mathbf{P}^n_{Y_i}$ is a closed immersion for $i$ large enough. Then $X'_i \to Y_i$ is proper and we win. $\square$
Lemma. Dimension and codimension
Assumptions and notation as in Situation A property to be descended through a filtered inverse system. Let $d \geq 0$. If
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$f$ has relative dimension $\leq d$ (Morphisms of Spaces, Definition Relative dimension), and
-
$f_0$ is locally of finite type,
then there exists an $i$ such that $f_i$ has relative dimension $\leq d$.
Proof. Choose an affine scheme $V_0$ and a surjective étale morphism $V_0 \to Y_0$. Choose an affine scheme $U_0$ and a surjective étale morphism $U_0 \to V_0 \times_{Y_0} X_0$. Diagram $$\begin{gathered}\begin{matrix}U_0 & V_0 \\ X_0 & Y_0\end{matrix} \\[6pt] \begin{aligned}U_0 & \longrightarrow X_0 \\ U_0 & \longrightarrow V_0 \\ V_0 & \longrightarrow Y_0 \\ X_0 & \longrightarrow Y_0\end{aligned}\end{gathered}$$ The vertical arrows are surjective and étale by construction. We can base change this diagram to $B_i$ or $B$ to get $$\begin{gathered}\begin{matrix}U_i & V_i \\ X_i & Y_i\end{matrix} \\[6pt] \begin{aligned}U_i & \longrightarrow X_i \\ U_i & \longrightarrow V_i \\ V_i & \longrightarrow Y_i \\ X_i & \longrightarrow Y_i\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ Note that $U_i, V_i, U, V$ are affine schemes, the vertical morphisms are surjective étale, and the limit of the morphisms $U_i \to V_i$ is $U \to V$. In this situation $X_i \to Y_i$ has relative dimension $\leq d$ if and only if $U_i \to V_i$ has relative dimension $\leq d$ (as defined in Morphisms, Definition Dimension and codimension). To see the equivalence, use that the definition for morphisms of algebraic spaces involves Morphisms of Spaces, Definition The dimension of a fibre which uses étale localization. The same is true for $X \to Y$ and $U \to V$. Since $f_0$ is locally of finite type, so is the morphism $U_0 \to V_0$. Hence the lemma follows from the more general Limits, Lemma Filtered limits and dimension and codimension. $\square$
Lemma. Descent of algebraic spaces
Let $S$ be a scheme. Let $I$ be a directed set. Let $(X_i, f_{ii'})$ be an inverse system over $I$ in the category of algebraic spaces over $S$. If the morphisms $f_{ii'} : X_i \to X_{i'}$ are affine, then the limit $X = \varprojlim_i X_i$ (as an fppf sheaf) is an algebraic space. Moreover,
-
each of the morphisms $f_i : X \to X_i$ is affine,
-
for any $i \in I$ and any morphism of algebraic spaces $T \to X_i$ we have $$X \times_{X_i} T = \varprojlim_{i' \geq i} X_{i'} \times_{X_i} T.$$ as algebraic spaces over $S$.
Proof. Part (2) is a formal consequence of the existence of the limit $X = \varprojlim X_i$ as an algebraic space over $S$. Choose an element $0 \in I$ (this is possible as a directed set is nonempty). Choose a scheme $U_0$ and a surjective étale morphism $U_0 \to X_0$. Set $R_0 = U_0 \times_{X_0} U_0$ so that $X_0 = U_0/R_0$. For $i \geq 0$ set $U_i = X_i \times_{X_0} U_0$ and $R_i = X_i \times_{X_0} R_0 = U_i \times_{X_i} U_i$. By Limits, Lemma Finite-presentation descent we see that $U = \varprojlim_{i \geq 0} U_i$ and $R = \varprojlim_{i \geq 0} R_i$ are schemes. Moreover, the two morphisms $s, t : R \to U$ are the base change of the two projections $R_0 \to U_0$ by the morphism $U \to U_0$, in particular étale. The morphism $R \to U \times_S U$ defines an equivalence relation as directed a limit of equivalence relations is an equivalence relation. Hence the morphism $R \to U \times_S U$ is an étale equivalence relation. We claim that the natural map
$$U/R \longrightarrow \varprojlim X_i$$ is an isomorphism of fppf sheaves on the category of schemes over $S$. The claim implies $X = \varprojlim X_i$ is an algebraic space by Spaces, Theorem The geometric construction (uncovered prerequisite).
Let $Z$ be a scheme and let $a : Z \to \varprojlim X_i$ be a morphism. Then $a = (a_i)$ where $a_i : Z \to X_i$. Set $W_0 = Z \times_{a_0, X_0} U_0$. Note that $W_0 = Z \times_{a_i, X_i} U_i$ for all $i \geq 0$ by our choice of $U_i \to X_i$ above. Hence we obtain a morphism $W_0 \to \varprojlim_{i \geq 0} U_i = U$. Since $W_0 \to Z$ is surjective and étale, we conclude that (the displayed identity) is a surjective map of sheaves. Finally, suppose that $Z$ is a scheme and that $a, b : Z \to U/R$ are two morphisms which are equalized by (the displayed identity). We have to show that $a = b$. After replacing $Z$ by the members of an fppf covering we may assume there exist morphisms $a', b' : Z \to U$ which give rise to $a$ and $b$. The condition that $a, b$ are equalized by (the displayed identity) means that for each $i \geq 0$ the compositions $a_i', b_i' : Z \to U \to U_i$ are equal as morphisms into $U_i/R_i = X_i$. Hence $(a_i', b_i') : Z \to U_i \times_S U_i$ factors through $R_i$, say by some morphism $c_i : Z \to R_i$. Since $R = \varprojlim_{i \geq 0} R_i$ we see that $c = \varprojlim c_i : Z \to R$ is a morphism which shows that $a, b$ are equal as morphisms of $Z$ into $U/R$.
Part (1) follows as we have seen above that $U_i \times_{X_i} X = U$ and $U \to U_i$ is affine by construction. $\square$
Proposition. Criteria for finite presentation and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent:
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The morphism $f$ is a morphism of algebraic spaces which is locally of finite presentation, see Morphisms of Spaces, Definition Finite presentation and finite algebras.
-
The morphism $f : X \to Y$ is limit preserving as a transformation of functors, see Definition Finite presentation and finite algebras.
Proof. Assume (1). Let $T$ be a scheme and let $y \in Y(T)$. We have to show that $T \times_Y X$ is limit preserving over $T$ in the sense of Definition Finite presentation and finite algebras. Hence we are reduced to proving that if $X$ is an algebraic space which is locally of finite presentation over $S$ as an algebraic space, then it is limit preserving as a functor $X : (\mathrm{Sch}/S)_{fppf}^{opp} \to \textit{Sets}$. To see this choose a presentation $X = U/R$, see Spaces, Definition The geometric construction. It follows from Morphisms of Spaces, Definition Finite presentation and finite algebras that both $U$ and $R$ are schemes which are locally of finite presentation over $S$. Hence by Limits, Proposition Criteria for finite presentation and finite algebras (uncovered prerequisite) we have $$U(T) = \mathop{\operatorname{colim}} U(T_i), \quad R(T) = \mathop{\operatorname{colim}} R(T_i)$$ whenever $T = \varprojlim_i T_i$ in $(\mathrm{Sch}/S)_{fppf}$. It follows that the presheaf $$(\mathrm{Sch}/S)_{fppf}^{opp} \longrightarrow \textit{Sets}, \quad W \longmapsto U(W)/R(W)$$ is limit preserving. Hence by Lemma Finite presentation and sheaves on ringed sites (uncovered prerequisite) its sheafification $X = U/R$ is limit preserving too.
Assume (2). Choose a scheme $V$ and a surjective étale morphism $V \to Y$. Next, choose a scheme $U$ and a surjective étale morphism $U \to V \times_Y X$. By Lemma Base change for finite presentation and finite algebras (uncovered prerequisite) the transformation of functors $V \times_Y X \to V$ is limit preserving. By Morphisms of Spaces, Lemma Étale morphisms and finite presentation (uncovered prerequisite) the morphism of algebraic spaces $U \to V \times_Y X$ is locally of finite presentation, hence limit preserving as a transformation of functors by the first part of the proof. By Lemma Composition and finite presentation and finite algebras (uncovered prerequisite) the composition $U \to V \times_Y X \to V$ is limit preserving as a transformation of functors. Hence the morphism of schemes $U \to V$ is locally of finite presentation by Limits, Proposition Criteria for finite presentation and finite algebras (uncovered prerequisite) (modulo a set theoretic remark, see last paragraph of the proof). This means, by definition, that (1) holds.
Set theoretic remark. Let $U \to V$ be a morphism of $(\mathrm{Sch}/S)_{fppf}$. In the statement of Limits, Proposition Criteria for finite presentation and finite algebras (uncovered prerequisite) we characterize $U \to V$ as being locally of finite presentation if for all directed inverse systems $(T_i, f_{ii'})$ of affine schemes over $V$ we have $U(T) = \mathop{\operatorname{colim}} V(T_i)$, but in the current setting we may only consider affine schemes $T_i$ over $V$ which are (isomorphic to) an object of $(\mathrm{Sch}/S)_{fppf}$. So we have to make sure that there are enough affines in $(\mathrm{Sch}/S)_{fppf}$ to make the proof work. Inspecting the proof of (2) $\Rightarrow$ (1) of Limits, Proposition Criteria for finite presentation and finite algebras (uncovered prerequisite) we see that the question reduces to the case that $U$ and $V$ are affine. Say $U = \operatorname{Spec}(A)$ and $V = \operatorname{Spec}(B)$. By construction of $(\mathrm{Sch}/S)_{fppf}$ the spectrum of any ring of cardinality $\leq |B|$ is isomorphic to an object of $(\mathrm{Sch}/S)_{fppf}$. Hence it suffices to observe that in the "only if" part of the proof of Algebra, Lemma Characterizations of finite presentation (uncovered prerequisite) only $A$-algebras of cardinality $\leq |B|$ are used. $\square$
Situation. A property to be descended through a filtered inverse system
Let $S$ be a scheme. Let $B = \varprojlim B_i$ be a limit of a directed inverse system of algebraic spaces over $S$ with affine transition morphisms (Lemma Descent of algebraic spaces). Let $0 \in I$ and let $f_0 : X_0 \to Y_0$ be a morphism of algebraic spaces over $B_0$. Assume $B_0$, $X_0$, $Y_0$ are quasi-compact and quasi-separated. Let $f_i : X_i \to Y_i$ be the base change of $f_0$ to $B_i$ and let $f : X \to Y$ be the base change of $f_0$ to $B$.
Lemma. Descent of diagonals and separation
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. If
-
$f$ is a closed immersion,
-
$f_0$ is locally of finite type,
then $f_i$ is a closed immersion for some $i \geq 0$.
Proof. Choose an affine scheme $V_0$ and a surjective étale morphism $V_0 \to Y_0$. Set $V_i = V_0 \times_{Y_0} Y_i$ and $V = V_0 \times_{Y_0} Y$. Since $f$ is a closed immersion we see that $V \times_Y X = \varprojlim V_i \times_{Y_i} X_i$ is a closed subscheme of the affine scheme $V$. By Lemma Filtered limits and affine neighbourhoods (uncovered prerequisite) we see that $V_i \times_{Y_i} X_i$ is affine for some $i \geq 0$. Increasing $i$ if necessary we find that $V_i \times_{Y_i} X_i \to V_i$ is a closed immersion by Limits, Lemma Descent of finite presentation and diagonals and separation. For this $i$ the morphism $f_i$ is a closed immersion (Morphisms of Spaces, Lemma Integral extensions and local algebra (uncovered prerequisite)). $\square$
Lemma. Finite presentation and integral extensions
Let $S$ be a scheme. Let $f : X \to Y$ be an integral morphism of algebraic spaces over $S$. Assume $Y$ quasi-compact and quasi-separated. Then $X$ can be written as a directed limit $X = \varprojlim X_i$ where $X_i$ are finite and of finite presentation over $Y$.
Proof. Consider the quasi-coherent $\mathcal{O}_Y$-module $\mathcal{A} = f_*\mathcal{O}_X$. By Lemma Filtered limits and integral extensions and finite algebras (uncovered prerequisite) we can write $\mathcal{A} = \mathop{\operatorname{colim}} \mathcal{A}_i$ as a directed colimit of finite and finitely presented $\mathcal{O}_Y$-algebras $\mathcal{A}_i$. Set $X_i = \underline{\operatorname{Spec}}_Y(\mathcal{A}_i)$, see Morphisms of Spaces, Definition Prime spectra and associated points. By construction $X_i \to Y$ is finite and of finite presentation and $X = \varprojlim X_i$. $\square$
Lemma. Filtered limits and descent of algebraic spaces
Notation and assumptions as in Situation A filtered inverse system for descent. If $X$ is a scheme, then there exists an $i$ such that $X_i$ is a scheme.
Proof. Choose a finite affine open covering $X = \bigcup W_j$. By Lemma Descent of descent of algebraic spaces we can find an $i \in I$ and open subspaces $W_{j, i} \subset X_i$ whose base change to $X$ is $W_j \to X$. By Lemma Filtered limits and affine neighbourhoods (uncovered prerequisite) we may assume that each $W_{j, i}$ is an affine scheme. This means that $X_i$ is a scheme (see for example Properties of Spaces, Section Étale geometry of algebraic spaces). $\square$
Lemma. Descent of descent of algebraic spaces
Notation and assumptions as in Situation A filtered inverse system for descent. For any quasi-compact open subspace $U \subset X$ there exists an $i$ and a quasi-compact open $U_i \subset X_i$ whose inverse image in $X$ is $U$.
Proof. Follows formally from the construction of limits in Lemma Descent of algebraic spaces and the corresponding result for schemes: Limits, Lemma Descent of finite-presentation descent. $\square$
Commutative algebra and regularity
Lemma. Nilpotent thickenings and local algebra
Let $R$ be a ring and let $I \subset R$ be a locally nilpotent ideal. An element $x$ of $R$ is a unit if and only if the image of $x$ in $R/I$ is a unit.
Proof. If $x$ is a unit in $R$, then its image is clearly a unit in $R/I$. It remains to prove the converse. Assume the image of $y \in R$ in $R/I$ is the inverse of the image of $x$. Then $xy = 1 - z$ for some $z \in I$. This means that $1\equiv z$ modulo $xR$. Since $z$ lies in the locally nilpotent ideal $I$, we have $z^N = 0$ for some sufficiently large $N$. It follows that $1 = 1^N \equiv z^N = 0$ modulo $xR$. In other words, $x$ divides $1$ and is hence a unit. $\square$
Lemma. Containment in the Jacobson radical
Let $R$ be a ring with Jacobson radical $\text{rad}(R)$. Let $I \subset R$ be an ideal. The following are equivalent
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$I \subset \text{rad}(R)$, and
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every element of $1 + I$ is a unit in $R$.
In this case every element of $R$ which maps to a unit of $R/I$ is a unit.
Proof. If $f \in \text{rad}(R)$, then $f \in \mathfrak m$ for all maximal ideals $\mathfrak m$ of $R$. Hence $1 + f \not \in \mathfrak m$ for all maximal ideals $\mathfrak m$ of $R$. Thus the closed subset $V(1 + f)$ of $\operatorname{Spec}(R)$ is empty. This implies that $1 + f$ is a unit, see Lemma The Zariski topology on an affine spectrum.
Conversely, assume that $1 + f$ is a unit for all $f \in I$. If $\mathfrak m$ is a maximal ideal and $I \not \subset \mathfrak m$, then $I + \mathfrak m = R$. Hence $1 = f + g$ for some $g \in \mathfrak m$ and $f \in I$. Then $g = 1 + (-f)$ is not a unit, contradiction.
For the final statement let $f \in R$ map to a unit in $R/I$. Then we can find $g \in R$ mapping to the multiplicative inverse of $f \bmod I$. Then $fg = 1 \bmod I$. Hence $fg$ is a unit of $R$ by (2) which implies that $f$ is a unit. $\square$
Lemma. Nakayama's lemma
Source credit: the original source citation MatCA (1.M Lemma (NAK) page 11)
We quote from the original source citation MatCA: "This simple but important lemma is due to T. Nakayama, G. Azumaya and W. Krull. Priority is obscure, and although it is usually called the Lemma of Nakayama, late Prof. Nakayama did not like the name."
Let $R$ be a ring with Jacobson radical $\text{rad}(R)$. Let $M$ be an $R$-module. Let $I \subset R$ be an ideal.
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If $IM = M$ and $M$ is finite, then there exists an $f \in 1 + I$ such that $fM = 0$.
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If $IM = M$, $M$ is finite, and $I \subset \text{rad}(R)$, then $M = 0$.
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If $N, N' \subset M$, $M = N + IN'$, and $N'$ is finite, then there exists an $f \in 1 + I$ such that $fM \subset N$ and $M_f = N_f$.
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If $N, N' \subset M$, $M = N + IN'$, $N'$ is finite, and $I \subset \text{rad}(R)$, then $M = N$.
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If $N \to M$ is a module map, $N/IN \to M/IM$ is surjective, and $M$ is finite, then there exists an $f \in 1 + I$ such that $N_f \to M_f$ is surjective.
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If $N \to M$ is a module map, $N/IN \to M/IM$ is surjective, $M$ is finite, and $I \subset \text{rad}(R)$, then $N \to M$ is surjective.
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If $x_1, \ldots, x_n \in M$ generate $M/IM$ and $M$ is finite, then there exists an $f \in 1 + I$ such that $x_1, \ldots, x_n$ generate $M_f$ over $R_f$.
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If $x_1, \ldots, x_n \in M$ generate $M/IM$, $M$ is finite, and $I \subset \text{rad}(R)$, then $M$ is generated by $x_1, \ldots, x_n$.
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If $IM = M$, $I$ is nilpotent, then $M = 0$.
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If $N, N' \subset M$, $M = N + IN'$, and $I$ is nilpotent then $M = N$.
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If $N \to M$ is a module map, $I$ is nilpotent, and $N/IN \to M/IM$ is surjective, then $N \to M$ is surjective.
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If $\{x_\alpha\}_{\alpha \in A}$ is a set of elements of $M$ which generate $M/IM$ and $I$ is nilpotent, then $M$ is generated by the $x_\alpha$.
Proof. Proof of (the indicated step). Choose generators $y_1, \ldots, y_m$ of $M$ over $R$. For each $i$ we can write $y_i = \sum z_{ij} y_j$ with $z_{ij} \in I$ (since $M = IM$). In other words $\sum_j (\delta_{ij} - z_{ij})y_j = 0$. Let $f$ be the determinant of the $m \times m$ matrix $A = (\delta_{ij} - z_{ij})$. Note that $f \in 1 + I$ (since the matrix $A$ is entrywise congruent to the $m \times m$ identity matrix modulo $I$). By Lemma A left inverse for a matrix (1), there exists an $m \times m$ matrix $B$ such that $BA = f 1_{m \times m}$. Writing out we see that $\sum_{i} b_{hi} a_{ij} = f \delta_{hj}$ for all $h$ and $j$; hence, $\sum_{i, j} b_{hi} a_{ij} y_j = \sum_{j} f \delta_{hj} y_j = f y_h$ for every $h$. In other words, $0 = f y_h$ for every $h$ (since each $i$ satisfies $\sum_j a_{ij} y_j = 0$). This implies that $f$ annihilates $M$.
By Lemma Containment in the Jacobson radical an element of $1 + \text{rad}(R)$ is an invertible element of $R$. Hence we see that (the indicated step) implies (2). We obtain (3) by applying (1) to $M/N$ which is finite as $N'$ is finite. We obtain (4) by applying (2) to $M/N$ which is finite as $N'$ is finite. We obtain (5) by applying (3) to $M$ and the submodules $\operatorname{Im}(N \to M)$ and $M$. We obtain (6) by applying (4) to $M$ and the submodules $\operatorname{Im}(N \to M)$ and $M$. We obtain (7) by applying (5) to the map $R^{\oplus n} \to M$, $(a_1, \ldots, a_n) \mapsto a_1x_1 + \ldots + a_nx_n$. We obtain (8) by applying (6) to the map $R^{\oplus n} \to M$, $(a_1, \ldots, a_n) \mapsto a_1x_1 + \ldots + a_nx_n$.
Part (9) holds because if $M = IM$ then $M = I^nM$ for all $n \geq 0$ and $I$ being nilpotent means $I^n = 0$ for some $n \gg 0$. Parts (10), (11), and (12) follow from (9) by the arguments used above. $\square$
Lemma. Finite presentation and finite algebras
Let $R \to S$ be a finite and finitely presented ring map. Let $M$ be an $S$-module. Then $M$ is finitely presented as an $R$-module if and only if $M$ is finitely presented as an $S$-module.
Proof. One of the implications follows from Lemma Finite presentation and finite algebras. To see the other assume that $M$ is finitely presented as an $S$-module. Pick a presentation $$S^{\oplus m} \longrightarrow S^{\oplus n} \longrightarrow M \longrightarrow 0$$ As $S$ is finite as an $R$-module, the kernel of $S^{\oplus n} \to M$ is a finite $R$-module. Thus from Lemma Commutative algebra we see that it suffices to prove that $S$ is finitely presented as an $R$-module.
Pick $y_1, \ldots, y_n \in S$ such that $y_1, \ldots, y_n$ generate $S$ as an $R$-module. By Lemma Criteria for integral extensions each $y_i$ is integral over $R$. Choose monic polynomials $P_i(x) \in R[x]$ with $P_i(y_i) = 0$. Consider the ring $$S' = R[x_1, \ldots, x_n]/(P_1(x_1), \ldots, P_n(x_n))$$ Then we see that $S$ is of finite presentation as an $S'$-algebra by Lemma Composition of finite-type ring maps. Since $S' \to S$ is surjective, the kernel $J = \operatorname{Ker}(S' \to S)$ is finitely generated as an ideal by Lemma Finite presentation and finite algebras. Hence $J$ is a finite $S'$-module (immediate from the definitions). Thus $S = \operatorname{Coker}(J \to S')$ is of finite presentation as an $S'$-module by Lemma Commutative algebra. Hence, arguing as in the first paragraph, it suffices to show that $S'$ is of finite presentation as an $R$-module. Actually, $S'$ is free as an $R$-module with basis the monomials $x_1^{e_1} \ldots x_n^{e_n}$ for $0 \leq e_i < \deg(P_i)$. Namely, write $R \to S'$ as the composition $$R \to R[x_1]/(P_1(x_1)) \to R[x_1, x_2]/(P_1(x_1), P_2(x_2)) \to \ldots \to S'$$ This shows that the $i$th ring in this sequence is free as a module over the $(i - 1)$st one with basis $1, x_i, \ldots, x_i^{\deg(P_i) - 1}$. The result follows easily from this by induction. Some details omitted. $\square$
Lemma. Commutative algebra
Let $R$ be a ring. Let $$0 \to M_1 \to M_2 \to M_3 \to 0$$ be a short exact sequence of $R$-modules.
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If $M_1$ and $M_3$ are finite $R$-modules, then $M_2$ is a finite $R$-module.
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If $M_1$ and $M_3$ are finitely presented $R$-modules, then $M_2$ is a finitely presented $R$-module.
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If $M_2$ is a finite $R$-module, then $M_3$ is a finite $R$-module.
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If $M_2$ is a finitely presented $R$-module and $M_1$ is a finite $R$-module, then $M_3$ is a finitely presented $R$-module.
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If $M_3$ is a finitely presented $R$-module and $M_2$ is a finite $R$-module, then $M_1$ is a finite $R$-module.
Proof. Proof of (1). If $x_1, \ldots, x_n$ are generators of $M_1$ and $y_1, \ldots, y_m \in M_2$ are elements whose images in $M_3$ are generators of $M_3$, then $x_1, \ldots, x_n, y_1, \ldots, y_m$ generate $M_2$.
Part (3) is immediate from the definition.
Proof of (5). Assume $M_3$ is finitely presented and $M_2$ finite. Choose a presentation $$R^{\oplus m} \to R^{\oplus n} \to M_3 \to 0$$ By Lemma Extending a morphism after finite denominators are cleared there exists a map $R^{\oplus n} \to M_2$ such that the solid diagram $$\begin{gathered}\begin{matrix}\phantom{X} & R^{\oplus m} & R^{\oplus n} & M_3 & 0 \\ 0 & M_1 & M_2 & M_3 & 0\end{matrix} \\[6pt] \begin{aligned}R^{\oplus m} & \longrightarrow R^{\oplus n} \\ R^{\oplus m} & \cdots\!\!\rightarrow M_1 \\ R^{\oplus n} & \longrightarrow M_3 \\ R^{\oplus n} & \longrightarrow M_2 \\ M_3 & \longrightarrow 0 \\ M_3 & \xrightarrow{\text{id}} M_3 \\ 0 & \longrightarrow M_1 \\ M_1 & \longrightarrow M_2 \\ M_2 & \longrightarrow M_3 \\ M_3 & \longrightarrow 0\end{aligned}\end{gathered}$$ commutes. This produces the dotted arrow. By the snake lemma (Lemma The snake lemma) we see that we get an isomorphism $$\operatorname{Coker}(R^{\oplus m} \to M_1) \cong \operatorname{Coker}(R^{\oplus n} \to M_2)$$ In particular we conclude that $\operatorname{Coker}(R^{\oplus m} \to M_1)$ is a finite $R$-module. Since $\operatorname{Im}(R^{\oplus m} \to M_1)$ is finite by (3), we see that $M_1$ is finite by part (1).
Proof of (4). Assume $M_2$ is finitely presented and $M_1$ is finite. Choose a presentation $R^{\oplus m} \to R^{\oplus n} \to M_2 \to 0$. Choose a surjection $R^{\oplus k} \to M_1$. By Lemma Extending a morphism after finite denominators are cleared there exists a factorization $R^{\oplus k} \to R^{\oplus n} \to M_2$ of the composition $R^{\oplus k} \to M_1 \to M_2$. Then $R^{\oplus k + m} \to R^{\oplus n} \to M_3 \to 0$ is a presentation.
Proof of (2). Assume that $M_1$ and $M_3$ are finitely presented. The argument in the proof of part (1) produces a commutative diagram $$\begin{gathered}\begin{matrix}0 & R^{\oplus n} & R^{\oplus n + m} & R^{\oplus m} & 0 \\ 0 & M_1 & M_2 & M_3 & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow R^{\oplus n} \\ R^{\oplus n} & \longrightarrow M_1 \\ R^{\oplus n} & \longrightarrow R^{\oplus n + m} \\ R^{\oplus n + m} & \longrightarrow M_2 \\ R^{\oplus n + m} & \longrightarrow R^{\oplus m} \\ R^{\oplus m} & \longrightarrow M_3 \\ R^{\oplus m} & \longrightarrow 0 \\ 0 & \longrightarrow M_1 \\ M_1 & \longrightarrow M_2 \\ M_2 & \longrightarrow M_3 \\ M_3 & \longrightarrow 0\end{aligned}\end{gathered}$$ with surjective vertical arrows. By the snake lemma we obtain a short exact sequence $$0 \to \operatorname{Ker}(R^{\oplus n} \to M_1) \to \operatorname{Ker}(R^{\oplus n + m} \to M_2) \to \operatorname{Ker}(R^{\oplus m} \to M_3) \to 0$$ By part (5) we see that the outer two modules are finite. Hence the middle one is finite too. By (4) we see that $M_2$ is of finite presentation. $\square$
Lemma. Tor vanishing for a flat module
Suppose that $R$ is a ring, that $0\to M''\to M'\to M\to0$ is a short exact sequence, and that $N$ is an $R$-module. If $M$ is flat then $N \otimes_R M'' \to N \otimes_R M'$ is injective, i.e., the sequence $$0 \to N \otimes_R M'' \to N \otimes_R M' \to N \otimes_R M \to 0$$ is a short exact sequence.
Proof. Let $R^{(I)} \to N$ be a surjection from a free module onto $N$ with kernel $K$. The result follows from the snake lemma applied to the following diagram $$\begin{matrix} & & 0 & & 0 & & 0 & & \\ & & \uparrow & & \uparrow & & \uparrow & & \\ & & M''\otimes_R N & \to & M' \otimes_R N & \to & M \otimes_R N & \to & 0 \\ & & \uparrow & & \uparrow & & \uparrow & & \\ 0 & \to & (M'')^{(I)} & \to & (M')^{(I)} & \to & M^{(I)} & \to & 0 \\ & & \uparrow & & \uparrow & & \uparrow & & \\ & & M''\otimes_R K & \to & M' \otimes_R K & \to & M \otimes_R K & \to & 0 \\ & & & & & & \uparrow & & \\ & & & & & & 0 & & \end{matrix}$$ with exact rows and columns. The middle row is exact because tensoring with the free module $R^{(I)}$ is exact. $\square$
Lemma. Localization as a filtered colimit
Let $R$ be a ring. Let $S \subset R$ be a multiplicative subset. Let $M$ be an $R$-module. Then $$S^{-1}M = \mathop{\operatorname{colim}}_{f \in S} M_f$$ where the preorder on $S$ is given by $f \geq f' \Leftrightarrow f = f'f''$ for some $f'' \in R$ in which case the map $M_{f'} \to M_f$ is given by $m/(f')^e \mapsto m(f'')^e/f^e$.
Proof. Omitted. Hint: Use the universal property of Lemma Proper morphisms and modules. $\square$
Lemma. The Artin--Tate lemma (Artin-Tate)
Let $R$ be a Noetherian ring. Let $S$ be a finitely generated $R$-algebra. If $T \subset S$ is an $R$-subalgebra such that $S$ is finitely generated as a $T$-module, then $T$ is of finite type over $R$.
Proof. Choose elements $x_1, \ldots, x_n \in S$ which generate $S$ as an $R$-algebra. Choose $y_1, \ldots, y_m$ in $S$ which generate $S$ as a $T$-module. Thus there exist $a_{ij} \in T$ such that $x_i = \sum a_{ij} y_j$. There also exist $b_{ijk} \in T$ such that $y_i y_j = \sum b_{ijk} y_k$. Let $T' \subset T$ be the sub $R$-algebra generated by $a_{ij}$ and $b_{ijk}$. This is a finitely generated $R$-algebra, hence Noetherian. Consider the algebra $$S' = T'[Y_1, \ldots, Y_m]/(Y_i Y_j - \sum b_{ijk} Y_k).$$ Note that $S'$ is finite over $T'$, namely as a $T'$-module it is generated by the classes of $1, Y_1, \ldots, Y_m$. Consider the $T'$-algebra homomorphism $S' \to S$ which maps $Y_i$ to $y_i$. Because $a_{ij} \in T'$ we see that $x_j$ is in the image of this map. Thus $S' \to S$ is surjective. Therefore $S$ is finite over $T'$ as well. Since $T'$ is Noetherian we conclude that $T \subset S$ is finite over $T'$ and we win. $\square$
Lemma. Finite presentation and finite algebras
Let $R \to S$ be a ring map. Let $M$ be an $S$-module. Assume $R \to S$ is of finite type and $M$ is finitely presented as an $R$-module. Then $M$ is finitely presented as an $S$-module.
Proof. This is similar to the proof of part (4) of Lemma Composition of finite-type ring maps. We may assume $S = R[x_1, \ldots, x_n]/J$. Choose $y_1, \ldots, y_m \in M$ which generate $M$ as an $R$-module and choose relations $\sum a_{ij} y_j = 0$, $i = 1, \ldots, t$ which generate the kernel of $R^{\oplus m} \to M$. For any $i = 1, \ldots, n$ and $j = 1, \ldots, m$ write $$x_i y_j = \sum a_{ijk} y_k$$ for some $a_{ijk} \in R$. Consider the $S$-module $N$ generated by $y_1, \ldots, y_m$ subject to the relations $\sum a_{ij} y_j = 0$, $i = 1, \ldots, t$ and $x_i y_j = \sum a_{ijk} y_k$, $i = 1, \ldots, n$ and $j = 1, \ldots, m$. Then $N$ has a presentation $$S^{\oplus nm + t} \longrightarrow S^{\oplus m} \longrightarrow N \longrightarrow 0$$ By construction there is a surjective map $\varphi : N \to M$. To finish the proof we show $\varphi$ is injective. Suppose $z = \sum b_j y_j \in N$ for some $b_j \in S$. We may think of $b_j$ as a polynomial in $x_1, \ldots, x_n$ with coefficients in $R$. By applying the relations of the form $x_i y_j = \sum a_{ijk} y_k$ we can inductively lower the degree of the polynomials. Hence we see that $z = \sum c_j y_j$ for some $c_j \in R$. Hence if $\varphi(z) = 0$ then the vector $(c_1, \ldots, c_m)$ is an $R$-linear combination of the vectors $(a_{i1}, \ldots, a_{im})$ and we conclude that $z = 0$ as desired. $\square$
Lemma. Finite algebras
Let $\varphi : R \to S$ be a ring map.
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If $\varphi$ is finite, then $\varphi$ is of finite type.
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If $S$ is of finite presentation as an $R$-module, then $\varphi$ is of finite presentation.
Proof. For (1) if $x_1, \ldots, x_n \in S$ generate $S$ as an $R$-module, then $x_1, \ldots, x_n$ generate $S$ as an $R$-algebra. For (2), suppose that $\sum r_j^ix_i = 0$, $j = 1, \ldots, m$ is a set of generators of the relations among the $x_i$ when viewed as $R$-module generators of $S$. Furthermore, write $1 = \sum r_ix_i$ for some $r_i \in R$ and $x_ix_j = \sum r_{ij}^k x_k$ for some $r_{ij}^k \in R$. Then $$S = R[t_1, \ldots, t_n]/ (\sum r_j^it_i,\ 1 - \sum r_it_i,\ t_it_j - \sum r_{ij}^k t_k)$$ as an $R$-algebra which proves (2). $\square$
Lemma. Composition of finite-type ring maps
The notions finite type and finite presentation have the following permanence properties.
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A composition of ring maps of finite type is of finite type.
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A composition of ring maps of finite presentation is of finite presentation.
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Given $R \to S' \to S$ with $R \to S$ of finite type, then $S' \to S$ is of finite type.
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Given $R \to S' \to S$, with $R \to S$ of finite presentation, and $R \to S'$ of finite type, then $S' \to S$ is of finite presentation.
Proof. We only prove the last assertion. Write $S = R[x_1, \ldots, x_n]/(f_1, \ldots, f_m)$ and $S' = R[y_1, \ldots, y_a]/I$. Say that the class $\bar y_i$ of $y_i$ maps to $h_i \bmod (f_1, \ldots, f_m)$ in $S$. Then it is clear that $S = S'[x_1, \ldots, x_n]/(f_1, \ldots, f_m, h_1 - \bar y_1, \ldots, h_a - \bar y_a)$. $\square$
Lemma. Product decompositions from disjoint closed subsets
Let $R$ be a ring. For each $U \subset \operatorname{Spec}(R)$ which is open and closed there exists a unique idempotent $e \in R$ such that $U = D(e)$. This induces a 1-1 correspondence between open and closed subsets $U \subset \operatorname{Spec}(R)$ and idempotents $e \in R$.
Proof. Let $U \subset \operatorname{Spec}(R)$ be open and closed. Since $U$ is closed it is quasi-compact by Lemma Quasi-compactness of an affine spectrum, and similarly for its complement. Write $U = \bigcup_{i = 1}^n D(f_i)$ as a finite union of standard opens. Similarly, write $\operatorname{Spec}(R) \setminus U = \bigcup_{j = 1}^m D(g_j)$ as a finite union of standard opens. Since $\emptyset = D(f_i) \cap D(g_j) = D(f_i g_j)$ we see that $f_i g_j$ is nilpotent by Lemma The Zariski topology on an affine spectrum. Let $I = (f_1, \ldots, f_n) \subset R$ and let $J = (g_1, \ldots, g_m) \subset R$. Note that $V(J)$ equals $U$, that $V(I)$ equals the complement of $U$, so $\operatorname{Spec}(R) = V(I) \amalg V(J)$. By the remark on nilpotency above, we see that $(IJ)^N = (0)$ for some sufficiently large integer $N$. Since $\bigcup D(f_i) \cup \bigcup D(g_j) = \operatorname{Spec}(R)$ we see that $I + J = R$, see Lemma The Zariski topology on an affine spectrum. By raising this equation to the $2N$th power we conclude that $I^N + J^N = R$. Write $1 = x + y$ with $x \in I^N$ and $y \in J^N$. Then $0 = xy = x(1 - x)$ as $I^N J^N = (0)$. Thus $x = x^2$ is idempotent and contained in $I^N \subset I$. The idempotent $y = 1 - x$ is contained in $J^N \subset J$. This shows that the idempotent $x$ maps to $1$ in every residue field $\kappa(\mathfrak p)$ for $\mathfrak p \in V(J)$ and that $x$ maps to $0$ in $\kappa(\mathfrak p)$ for every $\mathfrak p \in V(I)$.
To see uniqueness suppose that $e_1, e_2$ are distinct idempotents in $R$. We have to show there exists a prime $\mathfrak p$ such that $e_1 \in \mathfrak p$ and $e_2 \not \in \mathfrak p$, or conversely. Write $e_i' = 1 - e_i$. If $e_1 \not = e_2$, then $0 \not = e_1 - e_2 = e_1(e_2 + e_2') - (e_1 + e_1')e_2 = e_1 e_2' - e_1' e_2$. Hence either the idempotent $e_1 e_2' \not = 0$ or $e_1' e_2 \not = 0$. A nonzero idempotent is not nilpotent, and hence we find a prime $\mathfrak p$ such that either $e_1e_2' \not \in \mathfrak p$ or $e_1'e_2 \not \in \mathfrak p$, by Lemma The Zariski topology on an affine spectrum. It is easy to see this gives the desired prime. $\square$
Lemma. Characterizations of Dedekind domains
Let $R$ be a ring. The following are equivalent:
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$R$ is a Dedekind domain,
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$R$ is a Noetherian domain and for every nonzero maximal ideal $\mathfrak m$ the local ring $R_{\mathfrak m}$ is a discrete valuation ring, and
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$R$ is a Noetherian, normal domain, and $\dim(R) \leq 1$.
Proof. Assume (1). The argument is nontrivial because we did not assume that $R$ was Noetherian in our definition of a Dedekind domain. Let $\mathfrak p \subset R$ be a nonzero prime ideal (the zero ideal is already finitely generated). Observe that $\mathfrak p \not = \mathfrak p^2$ by uniqueness of the factorizations in the definition. Pick $x \in \mathfrak p$ with $x \not \in \mathfrak p^2$. Let $y \in \mathfrak p$ be a second element (for example $y = 0$). Write $(x, y) = \mathfrak p_1 \ldots \mathfrak p_r$. Since $(x, y) \subset \mathfrak p$ at least one of the primes $\mathfrak p_i$ is contained in $\mathfrak p$. But as $x \not \in \mathfrak p^2$ there is at most one. Thus exactly one of $\mathfrak p_1, \ldots, \mathfrak p_r$ is contained in $\mathfrak p$, say $\mathfrak p_1 \subset \mathfrak p$. We conclude that $(x, y)R_\mathfrak p = \mathfrak p_1R_\mathfrak p$ is prime for every choice of $y$. We claim that $(x)R_\mathfrak p = \mathfrak pR_\mathfrak p$. Namely, pick $y \in \mathfrak p$. By the above applied with $y^2$ we see that $(x, y^2)R_\mathfrak p$ is prime. Hence $y \in (x, y^2)R_\mathfrak p$, i.e., $y = ax + by^2$ in $R_\mathfrak p$. Thus $(1 - by)y = ax \in (x)R_\mathfrak p$, i.e., $y \in (x)R_\mathfrak p$ as desired.
Writing $(x) = \mathfrak p_1 \ldots \mathfrak p_r$ anew with $\mathfrak p_1 \subset \mathfrak p$ we conclude that $\mathfrak p_1 R_\mathfrak p = \mathfrak p R_\mathfrak p$, i.e., $\mathfrak p_1 = \mathfrak p$. Moreover, $\mathfrak p_1 = \mathfrak p$ is a finitely generated ideal of $R$ by Lemma Tensor products and direct sums. We conclude that $R$ is Noetherian by Lemma Cohen's theorem for Noetherian rings. Moreover, it follows that $R_\mathfrak m$ is a discrete valuation ring for every nonzero maximal ideal $\mathfrak m$, see Lemma Characterizations of discrete valuation rings.
The equivalence of (2) and (3) follows from Lemmas Local algebra and Characterizations of discrete valuation rings. Assume (2) and (3) are satisfied. The unit ideal is the empty product. Let $I \subset R$ be a nonzero proper ideal. We will construct a factorization of $I$. If $I$ is prime, then there is nothing to prove. If not, pick $I \subset \mathfrak p$ with $\mathfrak p \subset R$ maximal. Let $J = \{x \in R \mid x \mathfrak p \subset I\}$. We claim $J \mathfrak p = I$. It suffices to check this after localization at the maximal ideals $\mathfrak m$ of $R$ (the formation of $J$ commutes with localization and we use Lemma Detecting a zero module by localization). Then either $\mathfrak p R_\mathfrak m = R_\mathfrak m$ and the result is clear, or $\mathfrak p R_\mathfrak m = \mathfrak m R_\mathfrak m$. In the last case $\mathfrak p R_\mathfrak m = (\pi)$ and the case where $\mathfrak p$ is principal is immediate. By Noetherian induction the ideal $J$ has a factorization and we obtain the desired factorization of $I$. We omit the proof of uniqueness of the factorization. $\square$
Lemma. The Zariski topology on an affine spectrum
Let $R$ be a ring.
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The spectrum of a ring $R$ is empty if and only if $R$ is the zero ring.
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Every nonzero ring has a maximal ideal.
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Every nonzero ring has a minimal prime ideal.
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Given an ideal $I \subset R$ and a prime ideal $I \subset \mathfrak p$ there exists a prime $I \subset \mathfrak q \subset \mathfrak p$ such that $\mathfrak q$ is minimal over $I$.
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If $T \subset R$, and if $(T)$ is the ideal generated by $T$ in $R$, then $V((T)) = V(T)$.
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If $I$ is an ideal and $\sqrt{I}$ is its radical, see basic notion (Commutative algebra), then $V(I) = V(\sqrt{I})$.
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Given an ideal $I$ of $R$ we have $\sqrt{I} = \bigcap_{I \subset \mathfrak p} \mathfrak p$.
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If $I$ is an ideal then $V(I) = \emptyset$ if and only if $I$ is the unit ideal.
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If $I$, $J$ are ideals of $R$ then $V(I) \cup V(J) = V(I \cap J)$.
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If $(I_a)_{a\in A}$ is a set of ideals of $R$ then $\bigcap_{a\in A} V(I_a) = V(\bigcup_{a\in A} I_a)$.
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If $f \in R$, then $D(f) \amalg V(f) = \operatorname{Spec}(R)$.
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If $f \in R$ then $D(f) = \emptyset$ if and only if $f$ is nilpotent.
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If $f = u f'$ for some unit $u \in R$, then $D(f) = D(f')$.
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If $I \subset R$ is an ideal, and $\mathfrak p$ is a prime of $R$ with $\mathfrak p \not\in V(I)$, then there exists an $f \in R$ such that $\mathfrak p \in D(f)$, and $D(f) \cap V(I) = \emptyset$.
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If $f, g \in R$, then $D(fg) = D(f) \cap D(g)$.
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If $f_i \in R$ for $i \in I$, then $\bigcup_{i\in I} D(f_i)$ is the complement of $V(\{f_i \}_{i\in I})$ in $\operatorname{Spec}(R)$.
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If $f \in R$ and $D(f) = \operatorname{Spec}(R)$, then $f$ is a unit.
Proof. We address each part in the corresponding item below.
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This is a direct consequence of (2) or (3).
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Let $\mathfrak{A}$ be the set of all proper ideals of $R$. This set is ordered by inclusion and is non-empty, since $(0) \in \mathfrak{A}$ is a proper ideal. Let $A$ be a totally ordered subset of $\mathfrak A$. Then $\bigcup_{I \in A} I$ is in fact an ideal. Since $1 \notin I$ for all $I \in A$, the union does not contain $1$ and thus is proper. Hence $\bigcup_{I \in A} I$ is in $\mathfrak{A}$ and is an upper bound for the set $A$. Thus by Zorn's lemma $\mathfrak{A}$ has a maximal element, which is the sought-after maximal ideal.
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Since $R$ is nonzero, it contains a maximal ideal which is a prime ideal. Thus the set $\mathfrak{A}$ of all prime ideals of $R$ is nonempty. $\mathfrak{A}$ is ordered by reverse-inclusion. Let $A$ be a totally ordered subset of $\mathfrak{A}$. It's pretty clear that $J = \bigcap_{I \in A} I$ is in fact an ideal. Not so clear, however, is that it is prime. Let $xy \in J$. Then $xy \in I$ for all $I \in A$. Now let $B = \{I \in A | y \in I\}$. Let $K = \bigcap_{I \in B} I$. Since $A$ is totally ordered, either $K = J$ (and we're done, since then $y \in J$) or $K \supset J$ and for all $I \in A$ such that $I$ is properly contained in $K$, we have $y \notin I$. But that means that for all those $I, x \in I$, since they are prime. Hence $x \in J$. In either case, $J$ is prime as desired. Hence by Zorn's lemma we get a maximal element which in this case is a minimal prime ideal.
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This is the same exact argument as (3) except you only consider prime ideals contained in $\mathfrak{p}$ and containing $I$.
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$(T)$ is the smallest ideal containing $T$. Hence if $T \subset I$, some ideal, then $(T) \subset I$ as well. Hence if $I \in V(T)$, then $I \in V((T))$ as well. The other inclusion is obvious.
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Since $I \subset \sqrt{I}, V(\sqrt{I}) \subset V(I)$. Now let $\mathfrak{p} \in V(I)$. Let $x \in \sqrt{I}$. Then $x^n \in I$ for some $n$. Hence $x^n \in \mathfrak{p}$. But since $\mathfrak{p}$ is prime, a boring induction argument gets you that $x \in \mathfrak{p}$. Hence $\sqrt{I} \subset \mathfrak{p}$ and $\mathfrak{p} \in V(\sqrt{I})$.
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Let $f \in R \setminus \sqrt{I}$. Then $f^n \notin I$ for all $n$. Hence $S = \{1, f, f^2, \ldots\}$ is a multiplicative subset, not containing $0$. Take a prime ideal $\bar{\mathfrak{p}} \subset S^{-1}R$ containing $S^{-1}I$. Then the pull-back $\mathfrak{p}$ in $R$ of $\bar{\mathfrak{p}}$ is a prime ideal containing $I$ that does not intersect $S$. This shows that $\bigcap_{I \subset \mathfrak p} \mathfrak p \subset \sqrt{I}$. Now if $a \in \sqrt{I}$, then $a^n \in I$ for some $n$. Hence if $I \subset \mathfrak{p}$, then $a^n \in \mathfrak{p}$. But since $\mathfrak{p}$ is prime, we have $a \in \mathfrak{p}$. Thus the equality is shown.
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$I$ is not the unit ideal if and only if $I$ is contained in some maximal ideal (to see this, apply (2) to the ring $R/I$) which is therefore prime.
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If $\mathfrak{p} \in V(I) \cup V(J)$, then $I \subset \mathfrak{p}$ or $J \subset \mathfrak{p}$ which means that $I \cap J \subset \mathfrak{p}$. Now if $I \cap J \subset \mathfrak{p}$, then $IJ \subset \mathfrak{p}$ and hence either $I \subset \mathfrak{p}$ or $J \subset \mathfrak{p}$, since $\mathfrak{p}$ is prime.
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$\mathfrak{p} \in \bigcap_{a \in A} V(I_a) \Leftrightarrow I_a \subset \mathfrak{p}, \forall a \in A \Leftrightarrow \mathfrak{p} \in V(\bigcup_{a\in A} I_a)$
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If $\mathfrak{p}$ is a prime ideal and $f \in R$, then either $f \in \mathfrak{p}$ or $f \notin \mathfrak{p}$ (strictly) which is what the disjoint union says.
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If $a \in R$ is nilpotent, then $a^n = 0$ for some $n$. Hence $a^n \in \mathfrak{p}$ for any prime ideal. Thus $a \in \mathfrak{p}$ as can be shown by induction and $D(a) = \emptyset$. Now, as shown in (7), if $a \in R$ is not nilpotent, then there is a prime ideal that does not contain it.
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$f \in \mathfrak{p} \Leftrightarrow uf \in \mathfrak{p}$, since $u$ is invertible.
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If $\mathfrak{p} \notin V(I)$, then $\exists f \in I \setminus \mathfrak{p}$. Then $f \notin \mathfrak{p}$ so $\mathfrak{p} \in D(f)$. Also if $\mathfrak{q} \in D(f)$, then $f \notin \mathfrak{q}$ and thus $I$ is not contained in $\mathfrak{q}$. Thus $D(f) \cap V(I) = \emptyset$.
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If $fg \in \mathfrak{p}$, then $f \in \mathfrak{p}$ or $g \in \mathfrak{p}$. Hence if $f \notin \mathfrak{p}$ and $g \notin \mathfrak{p}$, then $fg \notin \mathfrak{p}$. Since $\mathfrak{p}$ is an ideal, if $fg \notin \mathfrak{p}$, then $f \notin \mathfrak{p}$ and $g \notin \mathfrak{p}$.
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$\mathfrak{p} \in \bigcup_{i \in I} D(f_i) \Leftrightarrow \exists i \in I, f_i \notin \mathfrak{p} \Leftrightarrow \mathfrak{p} \in \operatorname{Spec}(R) \setminus V(\{f_i\}_{i \in I})$
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If $D(f) = \operatorname{Spec}(R)$, then $V(f) = \emptyset$ and hence $fR = R$, so $f$ is a unit.
$\square$
Lemma. Lifting étale morphisms
Étale ring maps lift along surjections of rings
Let $R$ be a ring and let $I \subset R$ be an ideal. Let $R/I \to \overline{S}$ be an étale ring map. Then there exists an étale ring map $R \to S$ such that $\overline{S} \cong S/IS$ as $R/I$-algebras.
Proof. By Lemma Étale algebras in standard smooth form (uncovered prerequisite) we can write $\overline{S} = (R/I)[x_1, \ldots, x_n]/(\overline{f}_1, \ldots, \overline{f}_n)$ as in Definition Standard smooth presentations with $\overline{\Delta} = \det(\frac{\partial \overline{f}_i}{\partial x_j})_{i, j = 1, \ldots, n}$ invertible in $\overline{S}$. Just take some lifts $f_i$ and set $S = R[x_1, \ldots, x_n, x_{n+1}]/(f_1, \ldots, f_n, x_{n + 1}\Delta - 1)$ where $\Delta = \det(\frac{\partial f_i}{\partial x_j})_{i, j = 1, \ldots, n}$ as in Example Smooth morphisms (uncovered prerequisite). This proves the lemma. $\square$
Lemma. Smooth morphisms
Let $R \to S$ be a smooth ring map. Given a commutative solid diagram $$\begin{gathered}\begin{matrix}S & A/I \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow A/I \\ S & \dashrightarrow A \\ R & \longrightarrow A \\ R & \longrightarrow S \\ A & \longrightarrow A/I\end{aligned}\end{gathered}$$ where $I \subset A$ is a locally nilpotent ideal, a dotted arrow exists which makes the diagram commute.
Proof. By Lemma Finite presentation and formal smoothness over a Noetherian ring (uncovered prerequisite) we can extend the diagram to a commutative diagram $$\begin{gathered}\begin{matrix}S_0 & S & A/I \\ R_0 & R & A\end{matrix} \\[6pt] \begin{aligned}S_0 & \longrightarrow S \\ S & \longrightarrow A/I \\ S & \dashrightarrow A \\ R_0 & \longrightarrow R \\ R_0 & \longrightarrow S_0 \\ R & \longrightarrow A \\ R & \longrightarrow S \\ A & \longrightarrow A/I\end{aligned}\end{gathered}$$ with $R_0 \to S_0$ smooth, $R_0$ of finite type over $\mathbf{Z}$, and $S = S_0 \otimes_{R_0} R$. Let $x_1, \ldots, x_n \in S_0$ be generators of $S_0$ over $R_0$. Let $a_1, \ldots, a_n$ be elements of $A$ which map to the same elements in $A/I$ as the elements $x_1, \ldots, x_n$. Denote by $A_0 \subset A$ the subring generated by the image of $R_0$ and the elements $a_1, \ldots, a_n$. Set $I_0 = A_0 \cap I$. Then $A_0/I_0 \subset A/I$ and $S_0 \to A/I$ maps into $A_0/I_0$. Thus it suffices to find the dotted arrow in the diagram $$\begin{gathered}\begin{matrix}S_0 & A_0/I_0 \\ R_0 & A_0\end{matrix} \\[6pt] \begin{aligned}S_0 & \longrightarrow A_0/I_0 \\ S_0 & \dashrightarrow A_0 \\ R_0 & \longrightarrow A_0 \\ R_0 & \longrightarrow S_0 \\ A_0 & \longrightarrow A_0/I_0\end{aligned}\end{gathered}$$ The ring $A_0$ is of finite type over $\mathbf{Z}$ by construction. Hence $A_0$ is Noetherian, whence $I_0$ is nilpotent, see Lemma Noetherian rings (uncovered prerequisite). Say $I_0^n = 0$. By Proposition Formal smoothness of smooth algebras (uncovered prerequisite) we can successively lift the $R_0$-algebra map $S_0 \to A_0/I_0$ to $S_0 \to A_0/I_0^2$, $S_0 \to A_0/I_0^3$, $\ldots$, and finally $S_0 \to A_0/I_0^n = A_0$. $\square$
Lemma. Unramified morphisms and diagonals and separation
Let $R \to S$ be a ring map. If $R \to S$ is unramified, then there exists an idempotent $e \in S \otimes_R S$ such that $S \otimes_R S \to S$ is isomorphic to $S \otimes_R S \to (S \otimes_R S)_e$.
Proof. Let $J = \operatorname{Ker}(S \otimes_R S \to S)$. By assumption $J/J^2 = 0$, see Lemma Cotangent complexes, differentials and diagonals and separation (uncovered prerequisite). Since $S$ is of finite type over $R$ we see that $J$ is finitely generated, namely by $x_i \otimes 1 - 1 \otimes x_i$, where $x_i$ generate $S$ over $R$. We win by Lemma Idempotent ideals and connected components (uncovered prerequisite). $\square$
Lemma. Unramified morphisms
Properties of unramified and G-unramified ring maps.
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The base change of an unramified ring map is unramified. The base change of a G-unramified ring map is G-unramified.
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The composition of unramified ring maps is unramified. The composition of G-unramified ring maps is G-unramified.
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Any principal localization $R \to R_f$ is G-unramified and unramified.
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If $I \subset R$ is an ideal, then $R \to R/I$ is unramified. If $I \subset R$ is a finitely generated ideal, then $R \to R/I$ is G-unramified.
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An étale ring map is G-unramified and unramified.
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If $R \to S$ is of finite type (resp. finite presentation), $\mathfrak q \subset S$ is a prime and $(\Omega_{S/R})_{\mathfrak q} = 0$, then $R \to S$ is unramified (resp. G-unramified) at $\mathfrak q$.
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If $R \to S$ is of finite type (resp. finite presentation), $\mathfrak q \subset S$ is a prime and $\Omega_{S/R} \otimes_S \kappa(\mathfrak q) = 0$, then $R \to S$ is unramified (resp. G-unramified) at $\mathfrak q$.
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If $R \to S$ is of finite type (resp. finite presentation), $\mathfrak q \subset S$ is a prime lying over $\mathfrak p \subset R$ and $(\Omega_{S \otimes_R \kappa(\mathfrak p)/\kappa(\mathfrak p)})_{\mathfrak q} = 0$, then $R \to S$ is unramified (resp. G-unramified) at $\mathfrak q$.
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If $R \to S$ is of finite type (resp. finite presentation), $\mathfrak q \subset S$ is a prime lying over $\mathfrak p \subset R$ and $(\Omega_{S \otimes_R \kappa(\mathfrak p)/\kappa(\mathfrak p)}) \otimes_{S \otimes_R \kappa(\mathfrak p)} \kappa(\mathfrak q) = 0$, then $R \to S$ is unramified (resp. G-unramified) at $\mathfrak q$.
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If $R \to S$ is a ring map, $g_1, \ldots, g_m \in S$ generate the unit ideal and $R \to S_{g_j}$ is unramified (resp. G-unramified) for $j = 1, \ldots, m$, then $R \to S$ is unramified (resp. G-unramified).
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If $R \to S$ is a ring map which is unramified (resp. G-unramified) at every prime of $S$, then $R \to S$ is unramified (resp. G-unramified).
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If $R \to S$ is G-unramified, then there exists a finite type $\mathbf{Z}$-algebra $R_0$ and a G-unramified ring map $R_0 \to S_0$ and a ring map $R_0 \to R$ such that $S = R \otimes_{R_0} S_0$.
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If $R \to S$ is unramified, then there exists a finite type $\mathbf{Z}$-algebra $R_0$ and an unramified ring map $R_0 \to S_0$ and a ring map $R_0 \to R$ such that $S$ is a quotient of $R \otimes_{R_0} S_0$.
Proof. We prove each point, in order.
Ad (1). Follows from Lemmas Base change of Kähler differentials and Base change for finite algebras (uncovered prerequisite).
Ad (2). Follows from Lemmas Kähler differentials, Theorems 3.1–3.3, Proposition 3.4 and Theorem 7.1 and Composition of finite-type ring maps.
Ad (3). Follows by direct computation of $\Omega_{R_f/R}$ which we omit.
Ad (4). We have $\Omega_{(R/I)/R} = 0$, see Lemma Cotangent complexes and differentials (uncovered prerequisite), and the ring map $R \to R/I$ is of finite type. If $I$ is a finitely generated ideal then $R \to R/I$ is of finite presentation.
Ad (5). See discussion following Definition Étale ring maps.
Ad (6). In this case $\Omega_{S/R}$ is a finite $S$-module (see Lemma Cotangent complexes, differentials and finite algebras (uncovered prerequisite)) and hence there exists a $g \in S$, $g \not \in \mathfrak q$ such that $(\Omega_{S/R})_g = 0$. By Lemma Cotangent complexes, differentials and local algebra (uncovered prerequisite) this means that $\Omega_{S_g/R} = 0$ and hence $R \to S_g$ is unramified as desired.
Ad (7). Use Nakayama's lemma (Lemma Nakayama's lemma) to see that the condition is equivalent to the condition of (6).
Ad (8) and (9). These are equivalent in the same manner that (6) and (7) are equivalent. Moreover $\Omega_{S \otimes_R \kappa(\mathfrak p)/\kappa(\mathfrak p)} = \Omega_{S/R} \otimes_S (S \otimes_R \kappa(\mathfrak p))$ by Lemma Base change of Kähler differentials. Hence we see that (9) is equivalent to (7) since the $\kappa(\mathfrak q)$ vector spaces in both are canonically isomorphic.
Ad (10). Follows from Lemmas A finite cover by affine localizations and Cotangent complexes, differentials and local algebra (uncovered prerequisite).
Ad (11). Follows from (10), the definition of being unramified (resp. G-unramified) at a prime, and quasi-compactness of $\operatorname{Spec}(S)$.
Ad (12). Write $S = R[x_1, \ldots, x_n]/(g_1, \ldots, g_m)$. As $\Omega_{S/R} = 0$ we can write $$\text{d}x_i = \sum h_{ij}\text{d}g_j + \sum a_{ijk}g_j\text{d}x_k$$ in $\Omega_{R[x_1, \ldots, x_n]/R}$ for some $h_{ij}, a_{ijk} \in R[x_1, \ldots, x_n]$. Choose a finitely generated $\mathbf{Z}$-subalgebra $R_0 \subset R$ containing all the coefficients of the polynomials $g_i, h_{ij}, a_{ijk}$. Set $S_0 = R_0[x_1, \ldots, x_n]/(g_1, \ldots, g_m)$. This works.
Ad (13). Write $S = R[x_1, \ldots, x_n]/I$. As $\Omega_{S/R} = 0$ we can write $$\text{d}x_i = \sum h_{ij}\text{d}g_{ij} + \sum g'_{ik}\text{d}x_k$$ in $\Omega_{R[x_1, \ldots, x_n]/R}$ for some $h_{ij} \in R[x_1, \ldots, x_n]$ and $g_{ij}, g'_{ik} \in I$. Choose a finitely generated $\mathbf{Z}$-subalgebra $R_0 \subset R$ containing all the coefficients of the polynomials $g_{ij}, h_{ij}, g'_{ik}$. Set $S_0 = R_0[x_1, \ldots, x_n]/(g_{ij}, g'_{ik})$. This works. $\square$
Lemma. Nilpotent thickenings and local algebra
Let $R \to R'$ be a ring map and let $I \subset R$ be a locally nilpotent ideal. Then $IR'$ is a locally nilpotent ideal of $R'$.
Proof. This follows from the fact that if $x, y \in R'$ are nilpotent, then $x + y$ is nilpotent too. Namely, if $x^n = 0$ and $y^m = 0$, then $(x + y)^{n + m - 1} = 0$. $\square$
Lemma. Lifting idempotents through a nilpotent ideal
Let $R$ be a ring. Let $I \subset R$ be a locally nilpotent ideal. Then $R \to R/I$ induces a bijection on idempotents.
First proof of Lemma Lifting idempotents through a nilpotent ideal. As $I$ is locally nilpotent it is contained in every prime ideal. Hence $\operatorname{Spec}(R/I) = V(I) = \operatorname{Spec}(R)$. Hence the lemma follows from Lemma Product decompositions from disjoint closed subsets. $\square$
Second proof of Lemma Lifting idempotents through a nilpotent ideal. Suppose $\overline{e} \in R/I$ is an idempotent. We have to lift $\overline{e}$ to an idempotent of $R$.
First, choose any lift $f \in R$ of $\overline{e}$, and set $x = f^2 - f$. Then, $x \in I$, so $x$ is nilpotent (since $I$ is locally nilpotent). Let now $J$ be the ideal of $R$ generated by $x$. Then, $J$ is nilpotent (not just locally nilpotent), since it is generated by the nilpotent $x$.
Now, assume that we have found a lift $e \in R$ of $\overline{e}$ such that $e^2 - e \in J^k$ for some $k \geq 1$. Let $e' = e - (2e - 1)(e^2 - e) = 3e^2 - 2e^3$, which is another lift of $\overline{e}$ (since the idempotency of $\overline{e}$ yields $e^2 - e \in I$). Then $$(e')^2 - e' = (4e^2 - 4e - 3)(e^2 - e)^2 \in J^{2k}$$ by a simple computation.
We thus have started with a lift $e$ of $\overline{e}$ such that $e^2 - e \in J^k$, and obtained a lift $e'$ of $\overline{e}$ such that $(e')^2 - e' \in J^{2k}$. This way we can successively improve the approximation (starting with $e = f$, which fits the bill for $k = 1$). Eventually, we reach a stage where $J^k = 0$, and at that stage we have a lift $e$ of $\overline{e}$ such that $e^2 - e \in J^k = 0$, that is, this $e$ is idempotent.
We thus have seen that if $\overline{e} \in R/I$ is any idempotent, then there exists a lift of $\overline{e}$ which is an idempotent of $R$. It remains to prove that this lift is unique. Indeed, let $e_1$ and $e_2$ be two such lifts. We need to show that $e_1 = e_2$.
By definition of $e_1$ and $e_2$, we have $e_1 \equiv e_2 \mod I$, and both $e_1$ and $e_2$ are idempotent. From $e_1 \equiv e_2 \mod I$, we see that $e_1 - e_2 \in I$, so that $e_1 - e_2$ is nilpotent (since $I$ is locally nilpotent). A straightforward computation (using the idempotency of $e_1$ and $e_2$) reveals that $(e_1 - e_2)^3 = e_1 - e_2$. Using this and induction, we obtain $(e_1 - e_2)^k = e_1 - e_2$ for any positive odd integer $k$. Since all high enough $k$ satisfy $(e_1 - e_2)^k = 0$ (since $e_1 - e_2$ is nilpotent), this shows $e_1 - e_2 = 0$, so that $e_1 = e_2$, which completes our proof. $\square$
Lemma. Surjective endomorphisms of finite modules
Let $R$ be a ring. Let $M$ be a finite $R$-module. Let $\varphi : M \to M$ be a surjective $R$-module map. Then $\varphi$ is an isomorphism.
First proof. Write $R' = R[x]$ and think of $M$ as a finite $R'$-module with $x$ acting via $\varphi$. Set $I = (x) \subset R'$. By our assumption that $\varphi$ is surjective we have $IM = M$. Hence we may apply Lemma A characteristic polynomial with coefficients in an ideal (uncovered prerequisite) to $M$ as an $R'$-module, the ideal $I$ and the endomorphism $\text{id}_M$. We conclude that $(1 + a_1 + \ldots + a_n)\text{id}_M = 0$ with $a_j \in I$. Write $a_j = b_j(x)x$ for some $b_j(x) \in R[x]$. Translating back into $\varphi$ we see that $\text{id}_M = -(\sum_{j = 1}^{n} b_j(\varphi)) \varphi$, and hence $\varphi$ is invertible. $\square$
Second proof. We perform induction on the number of generators of $M$ over $R$. If $M$ is generated by one element, then $M \cong R/I$ for some ideal $I \subset R$. In this case we may replace $R$ by $R/I$ so that $M = R$. In this case $\varphi : R \to R$ is given by multiplication on $M$ by an element $r \in R$. The surjectivity of $\varphi$ forces $r$ invertible, since $\varphi$ must hit $1$, which implies that $\varphi$ is invertible.
Now assume that we have proven the lemma in the case of modules generated by $n - 1$ elements, and are examining a module $M$ generated by $n$ elements. Let $A$ mean the ring $R[t]$, and regard the module $M$ as an $A$-module by letting $t$ act via $\varphi$; since $M$ is finite over $R$, it is finite over $R[t]$ as well, and since we're trying to prove $\varphi$ injective, a set-theoretic property, we might as well prove the endomorphism $t : M \to M$ over $A$ injective. We have reduced our problem to the case our endomorphism is multiplication by an element of the ground ring. Let $M' \subset M$ denote the sub-$A$-module generated by the first $n - 1$ of the generators of $M$, and consider the diagram $$\begin{gathered}\begin{matrix}0 & M' & M & M/M' & 0 \\ 0 & M' & M & M/M' & 0,\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow M' \\ M' & \longrightarrow M \\ M' & \xrightarrow{\varphi\mid_{M'}} M' \\ M & \xrightarrow{\varphi} M \\ M & \longrightarrow M/M' \\ M/M' & \xrightarrow{\varphi \bmod M'} M/M' \\ M/M' & \longrightarrow 0 \\ 0 & \longrightarrow M' \\ M' & \longrightarrow M \\ M & \longrightarrow M/M' \\ M/M' & \longrightarrow 0,\end{aligned}\end{gathered}$$ where the restriction of $\varphi$ to $M'$ and the map induced by $\varphi$ on the quotient $M/M'$ are well-defined since $\varphi$ is multiplication by an element in the base, and $M'$ and $M/M'$ are $A$-modules in their own right. By the case $n = 1$ the map $M/M' \to M/M'$ is an isomorphism. A diagram chase implies that $\varphi|_{M'}$ is surjective hence by induction $\varphi|_{M'}$ is an isomorphism. This forces the middle column to be an isomorphism by the snake lemma. $\square$
Lemma. Finite flat modules over a local ring
(Warning: see Remark Finite generation and finite presentation over a general ring.) Suppose $R$ is a local ring, and $M$ is a finite flat $R$-module. Then $M$ is finite free.
Proof. Follows from the equational criterion of flatness, see Lemma The equational criterion for flatness (uncovered prerequisite). Namely, suppose that $x_1, \ldots, x_r \in M$ map to a basis of $M/\mathfrak mM$. By Nakayama's Lemma Nakayama's lemma these elements generate $M$. We want to show there is no relation among the $x_i$. Instead, we will show by induction on $n$ that if $x_1, \ldots, x_n \in M$ are linearly independent in the vector space $M/\mathfrak mM$ then they are independent over $R$.
The base case of the induction is where we have $x \in M$, $x \not\in \mathfrak mM$ and a relation $fx = 0$. By the equational criterion there exist $y_j \in M$ and $a_j \in R$ such that $x = \sum a_j y_j$ and $fa_j = 0$ for all $j$. Since $x \not\in \mathfrak mM$ we see that at least one $a_j$ is a unit and hence $f = 0$.
Suppose that $\sum f_i x_i$ is a relation among $x_1, \ldots, x_n$. By our choice of $x_i$ we have $f_i \in \mathfrak m$. According to the equational criterion of flatness there exist $a_{ij} \in R$ and $y_j \in M$ such that $x_i = \sum a_{ij} y_j$ and $\sum f_i a_{ij} = 0$. Since $x_n \not \in \mathfrak mM$ we see that $a_{nj}\not\in \mathfrak m$ for at least one $j$. Since $\sum f_i a_{ij} = 0$ we get $f_n = \sum_{i = 1}^{n-1} (-a_{ij}/a_{nj}) f_i$. The relation $\sum f_i x_i = 0$ now can be rewritten as $\sum_{i = 1}^{n-1} f_i( x_i + (-a_{ij}/a_{nj}) x_n) = 0$. Note that the elements $x_i + (-a_{ij}/a_{nj}) x_n$ map to $n-1$ linearly independent elements of $M/\mathfrak mM$. By induction assumption we get that all the $f_i$, $i \leq n-1$ have to be zero, and also $f_n = \sum_{i = 1}^{n-1} (-a_{ij}/a_{nj}) f_i$. This proves the induction step. $\square$
Lemma. Characterizations of finite projective modules
Source credit: the original source citation FAC (Chapter II, §4, no. 50, Proposition 4 and final paragraph, pp. 242--243)
For a finite module over the coordinate ring of a classical affine variety, the cited proposition tests projectivity by freeness of the stalks at classical closed points. The equivalences below work over an arbitrary ring and test all prime ideals or all maximal ideals, with finite presentation made explicit. The source proof writes a local-to-global formula for projective dimension; this is homological dimension, not rank. Its final paragraph asks whether every finite projective module over a polynomial ring over a field is free. This question was later answered affirmatively by the Quillen--Suslin theorem, which is not developed in this chapter.
Let $R$ be a ring and let $M$ be an $R$-module. The following are equivalent
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$M$ is finitely presented and $R$-flat,
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$M$ is finite projective,
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$M$ is a direct summand of a finite free $R$-module,
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$M$ is finitely presented and for all $\mathfrak p \in \operatorname{Spec}(R)$ the localization $M_{\mathfrak p}$ is free,
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$M$ is finitely presented and for all maximal ideals $\mathfrak m \subset R$ the localization $M_{\mathfrak m}$ is free,
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$M$ is finite and locally free,
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$M$ is finite locally free, and
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$M$ is finite, for every prime $\mathfrak p$ the module $M_{\mathfrak p}$ is free, and the function $$\rho_M : \operatorname{Spec}(R) \to \mathbf{Z}, \quad \mathfrak p \longmapsto \dim_{\kappa(\mathfrak p)} M \otimes_R \kappa(\mathfrak p)$$ is locally constant in the Zariski topology.
Proof. First suppose $M$ is finite projective, i.e., (2) holds. Take a surjection $R^n \to M$ and let $K$ be the kernel. Since $M$ is projective, $0 \to K \to R^n \to M \to 0$ splits. Hence (2) $\Rightarrow$ (3). The implication (3) $\Rightarrow$ (2) follows from the fact that a direct summand of a projective is projective, see Lemma Characterizations of projective modules (uncovered prerequisite).
Assume (3), so we can write $K \oplus M \cong R^{\oplus n}$. So $K$ is a direct summand of $R^n$ and thus finitely generated. This shows $M = R^{\oplus n}/K$ is finitely presented. In other words, (3) $\Rightarrow$ (1).
Assume $M$ is finitely presented and flat, i.e., (1) holds. We will prove that (7) holds. Pick any prime $\mathfrak p$ and $x_1, \ldots, x_r \in M$ which map to a basis of $M \otimes_R \kappa(\mathfrak p)$. By Nakayama's lemma (in the form of Lemma Nakayama's lemma after localization (uncovered prerequisite)) these elements generate $M_g$ for some $g \in R$, $g \not \in \mathfrak p$. The corresponding surjection $\varphi : R_g^{\oplus r} \to M_g$ has the following two properties: (a) $\operatorname{Ker}(\varphi)$ is a finite $R_g$-module (see Lemma Commutative algebra) and (b) $\operatorname{Ker}(\varphi) \otimes \kappa(\mathfrak p) = 0$ by flatness of $M_g$ over $R_g$ (see Lemma Tor vanishing for a flat module). Hence by Nakayama's lemma again there exists $g'=h/g^a\in R_g\setminus\mathfrak pR_g$, with $a\geq0$ and $h\in R\setminus\mathfrak p$, such that $\operatorname{Ker}(\varphi)_{g'}=0$. Thus $(M_g)_{g'}\cong M_{gh}$ is free on the neighbourhood $D(gh)$.
A finite locally free module is a finite module, see Lemma A finite cover by affine localizations, hence (7) $\Rightarrow$ (6). It is clear that (6) $\Rightarrow$ (7) and that (7) $\Rightarrow$ (8).
A finite locally free module is a finitely presented module, see Lemma A finite cover by affine localizations, hence (7) $\Rightarrow$ (4). Of course (4) implies (5). Since we may check flatness locally (see Lemma Localization of a flat module (uncovered prerequisite)) we conclude that (5) implies (1). At this point we have $$\begin{gathered}\begin{matrix}(2) & (3) & (1) & (7) & (6) \\ \phantom{X} & \phantom{X} & (5) & (4) & (8)\end{matrix} \\[6pt] \begin{aligned}(2) & \Longleftrightarrow (3) \\ (3) & \Longrightarrow (1) \\ (1) & \Longrightarrow (7) \\ (7) & \Longleftrightarrow (6) \\ (7) & \Longrightarrow (8) \\ (7) & \Longrightarrow (4) \\ (5) & \Longrightarrow (1) \\ (4) & \Longrightarrow (5)\end{aligned}\end{gathered}$$
Suppose that $M$ satisfies (1), (4), (5), (6), and (7). We will prove that (3) holds. It suffices to show that $M$ is projective. We have to show that $\operatorname{Hom}_R(M, -)$ is exact. Let $0 \to N'' \to N \to N'\to 0$ be a short exact sequence of $R$-modules. We have to show that $0 \to \operatorname{Hom}_R(M, N'') \to \operatorname{Hom}_R(M, N) \to \operatorname{Hom}_R(M, N') \to 0$ is exact. As $M$ is finite locally free there exists a covering $\operatorname{Spec}(R) = \bigcup D(f_i)$ such that $M_{f_i}$ is finite free. By Lemma Hom from a finitely presented module (uncovered prerequisite) we see that $$0 \to \operatorname{Hom}_R(M, N'')_{f_i} \to \operatorname{Hom}_R(M, N)_{f_i} \to \operatorname{Hom}_R(M, N')_{f_i} \to 0$$ is equal to $0 \to \operatorname{Hom}_{R_{f_i}}(M_{f_i}, N''_{f_i}) \to \operatorname{Hom}_{R_{f_i}}(M_{f_i}, N_{f_i}) \to \operatorname{Hom}_{R_{f_i}}(M_{f_i}, N'_{f_i}) \to 0$ which is exact as $M_{f_i}$ is free and as the localization $0 \to N''_{f_i} \to N_{f_i} \to N'_{f_i} \to 0$ is exact (as localization is exact). Whence we see that $0 \to \operatorname{Hom}_R(M, N'') \to \operatorname{Hom}_R(M, N) \to \operatorname{Hom}_R(M, N') \to 0$ is exact by Lemma A finite cover by affine localizations.
Finally, assume that (8) holds. Pick a maximal ideal $\mathfrak m \subset R$. Pick $x_1, \ldots, x_r \in M$ which map to a $\kappa(\mathfrak m)$-basis of $M \otimes_R \kappa(\mathfrak m) = M/\mathfrak mM$. In particular $\rho_M(\mathfrak m) = r$. By Nakayama's Lemma Nakayama's lemma there exists an $f \in R$, $f \not \in \mathfrak m$ such that $x_1, \ldots, x_r$ generate $M_f$ over $R_f$. By the assumption that $\rho_M$ is locally constant there exists a $g \in R$, $g \not \in \mathfrak m$ such that $\rho_M$ is constant equal to $r$ on $D(g)$. We claim that $$\Psi : R_{fg}^{\oplus r} \longrightarrow M_{fg}, \quad (a_1, \ldots, a_r) \longmapsto \sum a_i x_i$$ is an isomorphism. This claim will show that $M$ is finite locally free, i.e., that (7) holds. To see the claim it suffices to show that the induced map on localizations $\Psi_{\mathfrak p} : R_{\mathfrak p}^{\oplus r} \to M_{\mathfrak p}$ is an isomorphism for all $\mathfrak p \in D(fg)$, see Lemma Detecting a zero module by localization. By our choice of $f$ the map $\Psi_{\mathfrak p}$ is surjective. By assumption (8) we have $M_{\mathfrak p} \cong R_{\mathfrak p}^{\oplus \rho_M(\mathfrak p)}$ and by our choice of $g$ we have $\rho_M(\mathfrak p) = r$. Hence $\Psi_{\mathfrak p}$ determines a surjection $R_{\mathfrak p}^{\oplus r} \to M_{\mathfrak p} \cong R_{\mathfrak p}^{\oplus r}$ whence it is an isomorphism by Lemma Surjective endomorphisms of finite modules. (Of course this last fact follows from a simple matrix argument also.) $\square$
Lemma. Lifting a finite projective module
Let $R$ be a ring. Let $I \subset R$ be a nilpotent ideal. Let $\overline{P}$ be a projective $R/I$-module. Then there exists a projective $R$-module $P$ such that $P/IP \cong \overline{P}$.
Proof. By Lemma Characterizations of projective modules (uncovered prerequisite) we can choose a set $A$ and a direct sum decomposition $\bigoplus_{\alpha \in A} R/I = \overline{P} \oplus \overline{K}$ for some $R/I$-module $\overline{K}$. Write $F = \bigoplus_{\alpha \in A} R$ for the free $R$-module on $A$. Choose a lift $p : F \to F$ of the projector $\overline{p}$ associated to the direct summand $\overline{P}$ of $\bigoplus_{\alpha \in A} R/I$. Note that $p^2 - p \in \text{End}_R(F)$ is a nilpotent endomorphism of $F$ (as $I$ is nilpotent and the matrix entries of $p^2 - p$ are in $I$; more precisely, if $I^n = 0$, then $(p^2 - p)^n = 0$). Hence by Lemma Lifting commutative algebra (uncovered prerequisite) we can modify our choice of $p$ and assume that $p$ is a projector. Set $P = \operatorname{Im}(p)$. $\square$
Lemma. A left inverse for a matrix
Let $R$ be a ring. Let $n \geq m$. Let $A$ be an $n \times m$ matrix with coefficients in $R$. Let $J \subset R$ be the ideal generated by the $m \times m$ minors of $A$.
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For any $f \in J$ there exists a $m \times n$ matrix $B$ such that $BA = f 1_{m \times m}$.
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If $f \in R$ and $BA = f 1_{m \times m}$ for some $m \times n$ matrix $B$, then $f^m \in J$.
Proof. For $I \subset \{1, \ldots, n\}$ with $|I| = m$, we denote by $E_I$ the $m \times n$ matrix of the projection $$R^{\oplus n} = \bigoplus\nolimits_{i \in \{1, \ldots, n\}} R \longrightarrow \bigoplus\nolimits_{i \in I} R$$ and set $A_I = E_I A$, i.e., $A_I$ is the $m \times m$ matrix whose rows are the rows of $A$ with indices in $I$. Let $B_I$ be the adjugate (transpose of cofactor) matrix to $A_I$, i.e., such that $A_I B_I = B_I A_I = \det(A_I) 1_{m \times m}$. The $m \times m$ minors of $A$ are the determinants $\det A_I$ for all the $I \subset \{1, \ldots, n\}$ with $|I| = m$. If $f \in J$ then we can write $f = \sum c_I \det(A_I)$ for some $c_I \in R$. Set $B = \sum c_I B_I E_I$ to see that (1) holds.
If $f 1_{m \times m} = BA$ then by the Cauchy-Binet formula (Commutative algebra) we have $f^m = \sum b_I \det(A_I)$ where $b_I$ is the determinant of the $m \times m$ matrix whose columns are the columns of $B$ with indices in $I$. $\square$
Lemma. Detecting a zero module by localization
Let $R$ be a ring.
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For an element $x$ of an $R$-module $M$ the following are equivalent
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$x = 0$,
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$x$ maps to zero in $M_\mathfrak p$ for all $\mathfrak p \in \operatorname{Spec}(R)$,
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$x$ maps to zero in $M_{\mathfrak m}$ for all maximal ideals $\mathfrak m$ of $R$.
In other words, the map $M \to \prod_{\mathfrak m} M_{\mathfrak m}$ is injective.
-
-
Given an $R$-module $M$ the following are equivalent
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$M$ is zero,
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$M_{\mathfrak p}$ is zero for all $\mathfrak p \in \operatorname{Spec}(R)$,
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$M_{\mathfrak m}$ is zero for all maximal ideals $\mathfrak m$ of $R$.
-
-
Given a complex $M_1 \to M_2 \to M_3$ of $R$-modules the following are equivalent
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$M_1 \to M_2 \to M_3$ is exact,
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for every prime $\mathfrak p$ of $R$ the localization $M_{1, \mathfrak p} \to M_{2, \mathfrak p} \to M_{3, \mathfrak p}$ is exact,
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for every maximal ideal $\mathfrak m$ of $R$ the localization $M_{1, \mathfrak m} \to M_{2, \mathfrak m} \to M_{3, \mathfrak m}$ is exact.
-
-
Given a map $f : M \to M'$ of $R$-modules the following are equivalent
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$f$ is injective,
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$f_{\mathfrak p} : M_\mathfrak p \to M'_\mathfrak p$ is injective for all primes $\mathfrak p$ of $R$,
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$f_{\mathfrak m} : M_\mathfrak m \to M'_\mathfrak m$ is injective for all maximal ideals $\mathfrak m$ of $R$.
-
-
Given a map $f : M \to M'$ of $R$-modules the following are equivalent
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$f$ is surjective,
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$f_{\mathfrak p} : M_\mathfrak p \to M'_\mathfrak p$ is surjective for all primes $\mathfrak p$ of $R$,
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$f_{\mathfrak m} : M_\mathfrak m \to M'_\mathfrak m$ is surjective for all maximal ideals $\mathfrak m$ of $R$.
-
-
Given a map $f : M \to M'$ of $R$-modules the following are equivalent
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$f$ is bijective,
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$f_{\mathfrak p} : M_\mathfrak p \to M'_\mathfrak p$ is bijective for all primes $\mathfrak p$ of $R$,
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$f_{\mathfrak m} : M_\mathfrak m \to M'_\mathfrak m$ is bijective for all maximal ideals $\mathfrak m$ of $R$.
-
Proof. Let $x \in M$ as in (1). Let $I = \{f \in R \mid fx = 0\}$. It is easy to see that $I$ is an ideal (it is the annihilator of $x$). Condition (1)(c) means that for all maximal ideals $\mathfrak m$ there exists an $f \in R \setminus \mathfrak m$ such that $fx =0$. In other words, $V(I)$ does not contain a closed point. By Lemma The Zariski topology on an affine spectrum we see $I$ is the unit ideal. Hence $x$ is zero, i.e., (1)(a) holds. This proves (1).
Part (2) follows by applying (1) to all elements of $M$ simultaneously.
Proof of (3). Let $H$ be the homology of the sequence, i.e., $H = \operatorname{Ker}(M_2 \to M_3)/\operatorname{Im}(M_1 \to M_2)$. By Proposition Exactness of localization (uncovered prerequisite) we have that $H_\mathfrak p$ is the homology of the sequence $M_{1, \mathfrak p} \to M_{2, \mathfrak p} \to M_{3, \mathfrak p}$. Hence (3) is a consequence of (2).
Parts (4) and (5) are special cases of (3). Part (6) follows formally on combining (4) and (5). $\square$
Lemma. Flatness
Let $M$ be an $R$-module. The following are equivalent:
$M$ is flat over $R$.
for every injection of $R$-modules $N \subset N'$ the map $N \otimes_R M \to N'\otimes_R M$ is injective.
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for every ideal $I \subset R$ the map $I \otimes_R M \to R \otimes_R M = M$ is injective.
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for every finitely generated ideal $I \subset R$ the map $I \otimes_R M \to R \otimes_R M = M$ is injective.
Proof. The implications (the indicated step) implies (the indicated step) implies (the indicated step) implies (the indicated step) are all trivial. Thus we prove (the indicated step) implies (the indicated step). Suppose that $N_1 \to N_2 \to N_3$ is exact. Let $K = \operatorname{Ker}(N_2 \to N_3)$ and $Q = \operatorname{Im}(N_2 \to N_3)$. Then we get maps $$N_1 \otimes_R M \to K \otimes_R M \to N_2 \otimes_R M \to Q \otimes_R M \to N_3 \otimes_R M$$ Observe that the first and third arrows are surjective. Thus if we show that the second and fourth arrows are injective, then we are done[^1]. Hence it suffices to show that $- \otimes_R M$ transforms injective $R$-module maps into injective $R$-module maps.
Assume $K \to N$ is an injective $R$-module map and let $x \in \operatorname{Ker}(K \otimes_R M \to N \otimes_R M)$. We have to show that $x$ is zero. The $R$-module $K$ is the union of its finite $R$-submodules; hence, $K \otimes_R M$ is the colimit of $R$-modules of the form $K_i \otimes_R M$ where $K_i$ runs over all finite $R$-submodules of $K$ (because tensor product commutes with colimits). Thus, for some $i$ our $x$ comes from an element $x_i \in K_i \otimes_R M$. Thus we may assume that $K$ is a finite $R$-module. Assume this. We regard the injection $K \to N$ as an inclusion, so that $K \subset N$.
The $R$-module $N$ is the union of its finite $R$-submodules that contain $K$. Hence, $N \otimes_R M$ is the colimit of $R$-modules of the form $N_i \otimes_R M$ where $N_i$ runs over all finite $R$-submodules of $N$ that contain $K$ (again since tensor product commutes with colimits). Notice that this is a colimit over a directed system (since the sum of two finite submodules of $N$ is again finite). Hence, (by Lemma Commutative algebra (uncovered prerequisite)) the element $x \in K \otimes_R M$ maps to zero in at least one of these $R$-modules $N_i \otimes_R M$ (since $x$ maps to zero in $N \otimes_R M$). Thus we may assume $N$ is a finite $R$-module.
Assume $N$ is a finite $R$-module. Write $N = R^{\oplus n}/L$ and $K = L'/L$ for some $L \subset L' \subset R^{\oplus n}$. For any $R$-submodule $G \subset R^{\oplus n}$, we have a canonical map $G \otimes_R M \to M^{\oplus n}$ obtained by composing $G \otimes_R M \to R^n \otimes_R M = M^{\oplus n}$. It suffices to prove that $L \otimes_R M \to M^{\oplus n}$ and $L' \otimes_R M \to M^{\oplus n}$ are injective. Namely, if so, then we see that $K \otimes_R M = L' \otimes_R M/L \otimes_R M \to M^{\oplus n}/L \otimes_R M$ is injective too[^2].
Thus it suffices to show that $L \otimes_R M \to M^{\oplus n}$ is injective when $L \subset R^{\oplus n}$ is an $R$-submodule. We do this by induction on $n$. The base case $n = 1$ we handle below. For the induction step assume $n > 1$ and set $L' = L \cap R \oplus 0^{\oplus n - 1}$. Then $L'' = L/L'$ is a submodule of $R^{\oplus n - 1}$. We obtain a diagram $$\begin{gathered}\begin{matrix}\phantom{X} & L' \otimes_R M & L \otimes_R M & L'' \otimes_R M & 0 \\ 0 & M & M^{\oplus n} & M^{\oplus n - 1} & 0\end{matrix} \\[6pt] \begin{aligned}L' \otimes_R M & \longrightarrow L \otimes_R M \\ L' \otimes_R M & \longrightarrow M \\ L \otimes_R M & \longrightarrow L'' \otimes_R M \\ L \otimes_R M & \longrightarrow M^{\oplus n} \\ L'' \otimes_R M & \longrightarrow 0 \\ L'' \otimes_R M & \longrightarrow M^{\oplus n - 1} \\ 0 & \longrightarrow M \\ M & \longrightarrow M^{\oplus n} \\ M^{\oplus n} & \longrightarrow M^{\oplus n - 1} \\ M^{\oplus n - 1} & \longrightarrow 0\end{aligned}\end{gathered}$$ By induction hypothesis and the base case the left and right vertical arrows are injective. The rows are exact. It follows that the middle vertical arrow is injective too.
The base case of the induction above is when $L \subset R$ is an ideal. In other words, we have to show that $I \otimes_R M \to M$ is injective for any ideal $I$ of $R$. We know this is true when $I$ is finitely generated. However, $I = \bigcup I_\alpha$ is the union of the finitely generated ideals $I_\alpha$ contained in it. In other words, $I = \mathop{\operatorname{colim}} I_\alpha$. Since $\otimes$ commutes with colimits we see that $I \otimes_R M = \mathop{\operatorname{colim}} I_\alpha \otimes_R M$ and since all the morphisms $I_\alpha \otimes_R M \to M$ are injective by assumption, the same is true for $I \otimes_R M \to M$. $\square$
Remark. Tor for a quotient by an ideal
The proof of Lemma Criteria for flatness (uncovered prerequisite) actually shows that $$\text{Tor}_1^R(M, R/I)
\operatorname{Ker}(I \otimes_R M \to M).$$
Lemma. A reformulation of the local algebraic condition
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $M$ be an $R$-module. If $M/IM$ is flat over $R/I$ and $\text{Tor}_1^R(R/I, M) = 0$ then
-
$M/I^nM$ is flat over $R/I^n$ for all $n \geq 1$, and
-
for any module $N$ which is annihilated by $I^m$ for some $m \geq 0$ we have $\text{Tor}_1^R(N, M) = 0$.
In particular, if $I$ is nilpotent, then $M$ is flat over $R$.
Proof. Assume $M/IM$ is flat over $R/I$ and $\text{Tor}_1^R(R/I, M) = 0$. Let $N$ be an $R/I$-module. Choose a set $\Lambda$ and a short exact sequence $$0 \to K \to \bigoplus\nolimits_{\lambda \in \Lambda} R/I \to N \to 0$$ By the long exact sequence of $\text{Tor}$ and the vanishing of $\text{Tor}_1^R(R/I, M)$ we get $$0 \to \text{Tor}_1^R(N, M) \to K \otimes_R M \to (\bigoplus\nolimits_{\lambda \in \Lambda} R/I) \otimes_R M \to N \otimes_R M \to 0$$ But since $K$, $\bigoplus_{\lambda \in \Lambda} R/I$, and $N$ are all annihilated by $I$ we see that $$\begin{aligned} K \otimes_R M & = K \otimes_{R/I} M/IM, \\ (\bigoplus\nolimits_{\lambda \in \Lambda} R/I) \otimes_R M & = (\bigoplus\nolimits_{\lambda \in \Lambda} R/I) \otimes_{R/I} M/IM, \\ N \otimes_R M & = N \otimes_{R/I} M/IM. \end{aligned}$$ As $M/IM$ is flat over $R/I$ we conclude that $$0 \to K \otimes_{R/I} M/IM \to (\bigoplus\nolimits_{\lambda \in \Lambda} R/I) \otimes_{R/I} M/IM \to N \otimes_{R/I} M/IM \to 0$$ is exact. Combining this with the above we conclude that $\text{Tor}_1^R(N, M) = 0$ for any $R$-module $N$ annihilated by $I$.
Let us prove (2) by induction on $m$. The case $m = 1$ was done in the previous paragraph. For $N$ annihilated by $I^m$ for $m > 1$ we may choose an exact sequence $0 \to N' \to N \to N'' \to 0$ with $N'$ and $N''$ annihilated by $I^{m - 1}$. For example one can take $N' = IN$ and $N'' = N/IN$. Then the exact sequence $$\text{Tor}_1^R(N', M) \to \text{Tor}_1^R(N, M) \to \text{Tor}_1^R(N'', M)$$ and induction prove the vanishing we want.
Finally, we prove (1). Given $n \geq 1$ we have to show that $M/I^nM$ is flat over $R/I^n$. In other words, we have to show that the functor $N \mapsto N \otimes_{R/I^n} M/I^nM$ is exact on the category of $R$-modules $N$ annihilated by $I^n$. However, for such $N$ we have $N \otimes_{R/I^n} M/I^nM = N \otimes_R M$. By the vanishing of $\text{Tor}_1$ in (2) we see that the functor $N \mapsto N \otimes_R M$ is exact on the category of $N$ annihilated by some power of $I$ and we conclude. $\square$
Lemma. Criteria for integral extensions
Let $\varphi : R \to S$ be a ring map. Let $y \in S$. If there exists a finite $R$-submodule $M$ of $S$ such that $1 \in M$ and $yM \subset M$, then $y$ is integral over $R$.
Proof. Consider the map $\varphi : M \to M$, $x \mapsto y \cdot x$. By Lemma Modules (uncovered prerequisite) there exists a monic polynomial $P \in R[T]$ with $P(\varphi) = 0$. In the ring $S$ we get $P(y) = P(y) \cdot 1 = P(\varphi)(1) = 0$. $\square$
Lemma. Finite presentation and finite algebras
Let $R \to S$ be a ring map of finite presentation. For any surjection $\alpha : R[x_1, \ldots, x_n] \to S$ the kernel of $\alpha$ is a finitely generated ideal in $R[x_1, \ldots, x_n]$.
Proof. Write $S = R[y_1, \ldots, y_m]/(f_1, \ldots, f_k)$. Choose $g_i \in R[y_1, \ldots, y_m]$ which are lifts of $\alpha(x_i)$. Then we see that $S = R[x_i, y_j]/(f_l, x_i - g_i)$. Choose $h_j \in R[x_1, \ldots, x_n]$ such that $\alpha(h_j)$ corresponds to $y_j \bmod (f_1, \ldots, f_k)$. Consider the map $\psi : R[x_i, y_j] \to R[x_i]$, $x_i \mapsto x_i$, $y_j \mapsto h_j$. Then the kernel of $\alpha$ is the image of $(f_l, x_i - g_i)$ under $\psi$ and we win. $\square$
Lemma. Extending a morphism after finite denominators are cleared
Let $R$ be a ring. Let $\alpha : R^{\oplus n} \to M$ and $\beta : N \to M$ be module maps. If $\operatorname{Im}(\alpha) \subset \operatorname{Im}(\beta)$, then there exists an $R$-module map $\gamma : R^{\oplus n} \to N$ such that $\alpha = \beta \circ \gamma$.
Proof. Let $e_i = (0, \ldots, 0, 1, 0, \ldots, 0)$ be the $i$th basis vector of $R^{\oplus n}$. Let $x_i \in N$ be an element with $\alpha(e_i) = \beta(x_i)$ which exists by assumption. Set $\gamma(a_1, \ldots, a_n) = \sum a_i x_i$. By construction $\alpha = \beta \circ \gamma$. $\square$
Lemma. The snake lemma
Source credit: the original source citation Cartan-Eilenberg (III, Lemma 3.3)
Given a commutative diagram $$\begin{gathered}\begin{matrix}\phantom{X} & X & Y & Z & 0 \\ 0 & U & V & W\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow Y \\ X & \xrightarrow{\alpha} U \\ Y & \longrightarrow Z \\ Y & \xrightarrow{\beta} V \\ Z & \longrightarrow 0 \\ Z & \xrightarrow{\gamma} W \\ 0 & \longrightarrow U \\ U & \longrightarrow V \\ V & \longrightarrow W\end{aligned}\end{gathered}$$ of abelian groups with exact rows, there is a canonical exact sequence $$\operatorname{Ker}(\alpha) \to \operatorname{Ker}(\beta) \to \operatorname{Ker}(\gamma) \to \operatorname{Coker}(\alpha) \to \operatorname{Coker}(\beta) \to \operatorname{Coker}(\gamma)$$ Moreover: if $X \to Y$ is injective, then the first map is injective; if $V \to W$ is surjective, then the last map is surjective.
Proof. The map $\partial : \operatorname{Ker}(\gamma) \to \operatorname{Coker}(\alpha)$ is defined as follows. Take $z \in \operatorname{Ker}(\gamma)$. Choose $y \in Y$ mapping to $z$. Then $\beta(y) \in V$ maps to zero in $W$. Hence $\beta(y)$ is the image of some $u \in U$. Set $\partial z = \overline{u}$, the class of $u$ in the cokernel of $\alpha$. Proof of exactness is omitted. $\square$
Lemma. Proper morphisms and modules
Let $R$ be a ring. Let $S \subset R$ be a multiplicative subset. Let $M$, $N$ be $R$-modules. Assume all the elements of $S$ act as automorphisms on $N$. Then the canonical map $$\operatorname{Hom}_R(S^{-1}M, N) \longrightarrow \operatorname{Hom}_R(M, N)$$ induced by the localization map, is an isomorphism.
Proof. It is clear that the map is well-defined and $R$-linear. Injectivity: Let $\alpha \in \operatorname{Hom}_R(S^{-1}M, N)$ and take an arbitrary element $m/s \in S^{-1}M$. Then, since $s \cdot \alpha(m/s) = \alpha(m/1)$, we have $\alpha(m/s) =s^{-1}(\alpha (m/1))$, so $\alpha$ is completely determined by what it does on the image of $M$ in $S^{-1}M$. Surjectivity: Let $\beta : M \rightarrow N$ be a given $R$-linear map. We need to show that it can be "extended" to $S^{-1}M$. Define a map of sets $$M \times S \rightarrow N,\quad (m,s) \mapsto s^{-1}\beta(m)$$ Clearly, this map respects the equivalence relation from above, so it descends to a well-defined map $\alpha : S^{-1}M \rightarrow N$. It remains to show that this map is $R$-linear, so take $r, r' \in R$ as well as $s, s' \in S$ and $m, m' \in M$. Then $$\begin{aligned} \alpha(r \cdot m/s + r' \cdot m' /s') & = \alpha((r \cdot s' \cdot m + r' \cdot s \cdot m') /(ss')) \\ & = (ss')^{-1}\beta(r \cdot s' \cdot m + r' \cdot s \cdot m') \\ & = (ss')^{-1} (r \cdot s' \beta (m) + r' \cdot s \beta (m')) \\ & = r \alpha (m/s) + r' \alpha (m' /s') \end{aligned}$$ and we win. $\square$
Lemma. A finite cover by affine localizations
Zariski-local properties of modules and algebras
Let $R$ be a ring. Let $M$ be an $R$-module. Let $S$ be an $R$-algebra. Suppose that $f_1, \ldots, f_n$ is a finite list of elements of $R$ such that $\bigcup D(f_i) = \operatorname{Spec}(R)$, in other words $(f_1, \ldots, f_n) = R$.
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If each $M_{f_i} = 0$ then $M = 0$.
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If each $M_{f_i}$ is a finite $R_{f_i}$-module, then $M$ is a finite $R$-module.
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If each $M_{f_i}$ is a finitely presented $R_{f_i}$-module, then $M$ is a finitely presented $R$-module.
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Let $M \to N$ be a map of $R$-modules. If $M_{f_i} \to N_{f_i}$ is an isomorphism for each $i$ then $M \to N$ is an isomorphism.
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Let $0 \to M'' \to M \to M' \to 0$ be a complex of $R$-modules. If $0 \to M''_{f_i} \to M_{f_i} \to M'_{f_i} \to 0$ is exact for each $i$, then $0 \to M'' \to M \to M' \to 0$ is exact.
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If each $R_{f_i}$ is Noetherian, then $R$ is Noetherian.
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If each $S_{f_i}$ is a finite type $R_{f_i}$-algebra, then $S$ is a finite type $R$-algebra.
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If each $S_{f_i}$ is of finite presentation over $R_{f_i}$, then $S$ is a finitely presented $R$-algebra.
Proof. We prove each of the parts in turn.
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By Proposition Successive localizations (uncovered prerequisite) this implies $M_\mathfrak p = 0$ for all $\mathfrak p \in \operatorname{Spec}(R)$, so we conclude by Lemma Detecting a zero module by localization.
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For each $i$ take a finite generating set $X_i$ of $M_{f_i}$. Without loss of generality, we may assume that the elements of $X_i$ are in the image of the localization map $M \rightarrow M_{f_i}$, so we take a finite set $Y_i$ of preimages of the elements of $X_i$ in $M$. Let $Y$ be the union of these sets. This is still a finite set. Consider the obvious $R$-linear map $R^Y \rightarrow M$ sending the basis element $e_y$ to $y$. By assumption this map is surjective after localizing at an arbitrary prime ideal $\mathfrak p$ of $R$, so it is surjective by Lemma Detecting a zero module by localization and $M$ is finitely generated.
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By (2) we have a short exact sequence $$0 \rightarrow K \rightarrow R^m \rightarrow M \rightarrow 0$$ Since localization is an exact functor and $M_{f_i}$ is finitely presented we see that $K_{f_i}$ is finitely generated for all $1 \leq i \leq n$ by Lemma Commutative algebra. By (2) this implies that $K$ is a finite $R$-module and therefore $M$ is finitely presented.
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By Proposition Successive localizations (uncovered prerequisite) the assumption implies that the induced morphism on localizations at all prime ideals is an isomorphism, so we conclude by Lemma Detecting a zero module by localization.
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By Proposition Successive localizations (uncovered prerequisite) the assumption implies that the induced sequence of localizations at all prime ideals is short exact, so we conclude by Lemma Detecting a zero module by localization.
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We will show that every ideal of $R$ has a finite generating set: For this, let $I \subset R$ be an arbitrary ideal. By Proposition Exactness of localization (uncovered prerequisite) each $I_{f_i} \subset R_{f_i}$ is an ideal. These are all finitely generated by assumption, so we conclude by (2).
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For each $i$ take a finite generating set $X_i$ of $S_{f_i}$. Without loss of generality, we may assume that the elements of $X_i$ are in the image of the localization map $S \rightarrow S_{f_i}$, so we take a finite set $Y_i$ of preimages of the elements of $X_i$ in $S$. Let $Y$ be the union of these sets. This is still a finite set. Consider the algebra homomorphism $R[X_y]_{y \in Y} \rightarrow S$ induced by $Y$. Since it is an algebra homomorphism, the image $T$ is an $R$-submodule of the $R$-module $S$, so we can consider the quotient module $S/T$. By assumption, this is zero if we localize at the $f_i$, so it is zero by (1) and therefore $S$ is an $R$-algebra of finite type.
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By the previous item, there exists a surjective $R$-algebra homomorphism $R[X_1, \ldots, X_n] \rightarrow S$. Let $K$ be the kernel of this map. This is an ideal in $R[X_1, \ldots, X_n]$, finitely generated in each localization at $f_i$. Since the $f_i$ generate the unit ideal in $R$, they also generate the unit ideal in $R[X_1, \ldots, X_n]$, so an application of (2) finishes the proof.
$\square$
Lemma. A valuation ring dominating a local domain
Let $K$ be a field. Let $A \subset K$ be a local subring. Then there exists a valuation ring with fraction field $K$ dominating $A$.
Proof. We consider the collection of local subrings of $K$ as a partially ordered set using the relation of domination. Suppose that $\{A_i\}_{i \in I}$ is a totally ordered collection of local subrings of $K$. Then $B = \bigcup A_i$ is a local subring which dominates all of the $A_i$. Hence by Zorn's Lemma, it suffices to show that if $A \subset K$ is a local ring whose fraction field is not $K$, then there exists a local ring $B \subset K$, $B \not = A$ dominating $A$.
Pick $t \in K$ which is not in the fraction field of $A$. If $t$ is transcendental over $A$, then $A[t] \subset K$ and hence $A[t]_{(t, \mathfrak m)} \subset K$ is a local ring distinct from $A$ dominating $A$. Suppose $t$ is algebraic over $A$. Then for some nonzero $a \in A$ the element $at$ is integral over $A$. In this case the subring $A' \subset K$ generated by $A$ and $ta$ is finite over $A$. By Lemma Surjectivity on spectra of an integral overring there exists a prime ideal $\mathfrak m' \subset A'$ lying over $\mathfrak m$. Then $A'_{\mathfrak m'}$ dominates $A$. If $A = A'_{\mathfrak m'}$, then $t$ is in the fraction field of $A$ which we assumed not to be the case. Thus $A \not = A'_{\mathfrak m'}$ as desired. $\square$
Lemma. Commutative algebra
Let $A'$ be a valuation ring with residue field $K$. Let $A$ be a valuation ring with fraction field $K$. Then $C = \{\lambda \in A' \mid \lambda \bmod \mathfrak m_{A'} \in A\}$ is a valuation ring.
Proof. Note that $\mathfrak m_{A'} \subset C$ and $C/\mathfrak m_{A'} = A$. In particular, the fraction field of $C$ is equal to the fraction field of $A'$. We will use the criterion of Lemma Commutative algebra (uncovered prerequisite) to prove the lemma. Let $x$ be an element of the fraction field of $C$. By the lemma we may assume $x \in A'$. If $x \in \mathfrak m_{A'}$, then we see $x \in C$. If not, then $x$ is a unit of $A'$ and we also have $x^{-1} \in A'$. Hence either $x$ or $x^{-1}$ maps to an element of $A$ by the lemma again. $\square$
Lemma. Flatness and local algebra
A flat local ring homomorphism of local rings is faithfully flat.
Proof. Immediate from Lemma Faithfully flat ring maps. $\square$
Lemma. Faithfully flat ring maps
Let $R \to S$ be a flat ring map. The following are equivalent:
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$R \to S$ is faithfully flat,
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the induced map on $\operatorname{Spec}$ is surjective, and
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any closed point $x \in \operatorname{Spec}(R)$ is in the image of the map $\operatorname{Spec}(S) \to \operatorname{Spec}(R)$.
Proof. This follows quickly from Lemma Faithfully flat modules (uncovered prerequisite), because we saw in Remark Commutative algebra that $\mathfrak p$ is in the image if and only if the ring $S \otimes_R \kappa(\mathfrak p)$ is nonzero. $\square$
Lemma. Commutative algebra
Let $A$ be a valuation ring. For any prime ideal $\mathfrak p \subset A$ the quotient $A/\mathfrak p$ is a valuation ring. The same is true for the localization $A_\mathfrak p$ and in fact any nonzero localization of $A$.
Proof. Use the characterization of valuation rings given in Lemma Commutative algebra (uncovered prerequisite). $\square$
Lemma. Lifting residue maps between strictly henselian rings
Let $R \to S$ be a ring map. Let $\mathfrak q \subset S$ be a prime lying over $\mathfrak p \subset R$. Choose separable algebraic closures $\kappa(\mathfrak p) \subset \kappa_1^{sep}$ and $\kappa(\mathfrak q) \subset \kappa_2^{sep}$. Let $R^{sh}$ and $S^{sh}$ be the corresponding strict henselizations of $R_\mathfrak p$ and $S_\mathfrak q$. Given any commutative diagram $$\begin{gathered}\begin{matrix}\kappa_1^{sep} & \kappa_2^{sep} \\ \kappa(\mathfrak p) & \kappa(\mathfrak q)\end{matrix} \\[6pt] \begin{aligned}\kappa_1^{sep} & \xrightarrow{\phi} \kappa_2^{sep} \\ \kappa(\mathfrak p) & \xrightarrow{\varphi} \kappa(\mathfrak q) \\ \kappa(\mathfrak p) & \longrightarrow \kappa_1^{sep} \\ \kappa(\mathfrak q) & \longrightarrow \kappa_2^{sep}\end{aligned}\end{gathered},$$ the local ring map $R^{sh} \to S^{sh}$ of Lemma Functoriality of strict henselization (uncovered prerequisite) identifies $S^{sh}$ with the strict henselization of $R^{sh} \otimes_R S$ at a prime lying over $\mathfrak q$ and the maximal ideal $\mathfrak m^{sh} \subset R^{sh}$.
Proof. The proof is identical to the proof of Lemma Henselian rings (uncovered prerequisite) except that it uses Lemma Henselian rings (uncovered prerequisite) instead of Lemma Henselian rings (uncovered prerequisite). $\square$
Lemma. Finite module presentations in a filtered colimit
Suppose that $R = \mathop{\operatorname{colim}}_{\lambda \in \Lambda} R_\lambda$ is a directed colimit of rings. Then the category of finitely presented $R$-modules is the colimit of the categories of finitely presented $R_\lambda$-modules. More precisely
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Given a finitely presented $R$-module $M$ there exists a $\lambda \in \Lambda$ and a finitely presented $R_\lambda$-module $M_\lambda$ such that $M \cong M_\lambda \otimes_{R_\lambda} R$.
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Given a $\lambda \in \Lambda$, finitely presented $R_\lambda$-modules $M_\lambda, N_\lambda$, and an $R$-module map $\varphi : M_\lambda \otimes_{R_\lambda} R \to N_\lambda \otimes_{R_\lambda} R$, then there exists a $\mu \geq \lambda$ and an $R_\mu$-module map $\varphi_\mu : M_\lambda \otimes_{R_\lambda} R_\mu \to N_\lambda \otimes_{R_\lambda} R_\mu$ such that $\varphi = \varphi_\mu \otimes 1_R$.
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Given a $\lambda \in \Lambda$, finitely presented $R_\lambda$-modules $M_\lambda, N_\lambda$, and $R_\lambda$-module maps $\varphi, \psi : M_\lambda \to N_\lambda$ such that $\varphi \otimes 1_R = \psi \otimes 1_R$, then $\varphi \otimes 1_{R_\mu} = \psi \otimes 1_{R_\mu}$ for some $\mu \geq \lambda$.
Proof. To prove (1) choose a presentation $R^{\oplus m} \to R^{\oplus n} \to M \to 0$. Suppose that the first map is given by the matrix $A = (a_{ij})$. We can choose a $\lambda \in \Lambda$ and a matrix $A_\lambda = (a_{\lambda, ij})$ with coefficients in $R_\lambda$ which maps to $A$ in $R$. Then we simply let $M_\lambda$ be the $R_\lambda$-module with presentation $R_\lambda^{\oplus m} \to R_\lambda^{\oplus n} \to M_\lambda \to 0$ where the first arrow is given by $A_\lambda$.
Parts (2) and (3) follow from Lemma Filtered limits and proper morphisms and modules. $\square$
Lemma. Filtered limits and proper morphisms and modules
Let $A$ be a ring and let $M, N$ be $A$-modules. Suppose that $R = \mathop{\operatorname{colim}}_{i \in I} R_i$ is a directed colimit of $A$-algebras.
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If $M$ is a finite $A$-module, and $u, u' : M \to N$ are $A$-module maps such that $u \otimes 1 = u' \otimes 1 : M \otimes_A R \to N \otimes_A R$ then for some $i$ we have $u \otimes 1 = u' \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$.
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If $N$ is a finite $A$-module and $u : M \to N$ is an $A$-module map such that $u \otimes 1 : M \otimes_A R \to N \otimes_A R$ is surjective, then for some $i$ the map $u \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$ is surjective.
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If $N$ is a finitely presented $A$-module, and $v : N \otimes_A R \to M \otimes_A R$ is an $R$-module map, then there exists an $i$ and an $R_i$-module map $v_i : N \otimes_A R_i \to M \otimes_A R_i$ such that $v = v_i \otimes 1$.
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If $M$ is a finite $A$-module, $N$ is a finitely presented $A$-module, and $u : M \to N$ is an $A$-module map such that $u \otimes 1 : M \otimes_A R \to N \otimes_A R$ is an isomorphism, then for some $i$ the map $u \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$ is an isomorphism.
Proof. To prove (1) assume $u$ is as in (1) and let $x_1, \ldots, x_m \in M$ be generators. Since $N \otimes_A R = \mathop{\operatorname{colim}}_i N \otimes_A R_i$ we may pick an $i \in I$ such that $u(x_j) \otimes 1 = u'(x_j) \otimes 1$ in $N \otimes_A R_i$, $j = 1, \ldots, m$. For such an $i$ we have $u \otimes 1 = u' \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$.
To prove (2) assume $u \otimes 1$ surjective and let $y_1, \ldots, y_m \in N$ be generators. Since $N \otimes_A R = \mathop{\operatorname{colim}}_i N \otimes_A R_i$ we may pick an $i \in I$ and $z_j \in M \otimes_A R_i$, $j = 1, \ldots, m$ whose images in $N \otimes_A R$ equal $y_j \otimes 1$. For such an $i$ the map $u \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$ is surjective.
To prove (3) let $y_1, \ldots, y_m \in N$ be generators. Let $K = \operatorname{Ker}(A^{\oplus m} \to N)$ where the map is given by the rule $(a_1, \ldots, a_m) \mapsto \sum a_j y_j$. Let $k_1, \ldots, k_t$ be generators for $K$. Say $k_s = (k_{s1}, \ldots, k_{sm})$. Since $M \otimes_A R = \mathop{\operatorname{colim}}_i M \otimes_A R_i$ we may pick an $i \in I$ and $z_j \in M \otimes_A R_i$, $j = 1, \ldots, m$ whose images in $M \otimes_A R$ equal $v(y_j \otimes 1)$. We want to use the $z_j$ to define the map $v_i : N \otimes_A R_i \to M \otimes_A R_i$. Since $K \otimes_A R_i \to R_i^{\oplus m} \to N \otimes_A R_i \to 0$ is a presentation, it suffices to check that $\xi_s = \sum_j k_{sj}z_j$ is zero in $M \otimes_A R_i$ for each $s = 1, \ldots, t$. This may not be the case, but since the image of $\xi_s$ in $M \otimes_A R$ is zero we see that it will be the case after increasing $i$ a bit.
To prove (4) assume $u \otimes 1$ is an isomorphism, that $M$ is finite, and that $N$ is finitely presented. Let $v : N \otimes_A R \to M \otimes_A R$ be an inverse to $u \otimes 1$. Apply part (3) to get a map $v_i : N \otimes_A R_i \to M \otimes_A R_i$ for some $i$. Apply part (1) to see that, after increasing $i$ we have $v_i \circ (u \otimes 1) = \text{id}_{M \otimes_A R_i}$ and $(u \otimes 1) \circ v_i = \text{id}_{N \otimes_A R_i}$. $\square$
Lemma. Quasi-compactness of an affine spectrum
The spectrum of a ring is quasi-compact
Let $R$ be a ring. The space $\operatorname{Spec}(R)$ is quasi-compact.
Proof. It suffices to prove that any covering of $\operatorname{Spec}(R)$ by standard opens can be refined by a finite covering. Thus suppose that $\operatorname{Spec}(R) = \cup D(f_i)$ for a set of elements $\{f_i\}_{i\in I}$ of $R$. This means that $\cap V(f_i) = \emptyset$. According to Lemma The Zariski topology on an affine spectrum this means that $V(\{f_i \}) = \emptyset$. According to the same lemma this means that the ideal generated by the $f_i$ is the unit ideal of $R$. This means that we can write $1$ as a finite sum: $1 = \sum_{i \in J} r_i f_i$ with $J \subset I$ finite. And then it follows that $\operatorname{Spec}(R) = \cup_{i \in J} D(f_i)$. $\square$
Lemma. Going up and closed maps of spectra
Let $R \to S$ be a ring map. The following are equivalent:
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Going up holds for $R \to S$, and
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the map $\operatorname{Spec}(S) \to \operatorname{Spec}(R)$ is closed.
Proof. It is a general fact that specializations lift along a closed map of topological spaces, see Topology, Lemma The geometric construction (uncovered prerequisite). Hence the second condition implies the first.
Assume that going up holds for $R \to S$. Let $V(I) \subset \operatorname{Spec}(S)$ be a closed set. We want to show that the image of $V(I)$ in $\operatorname{Spec}(R)$ is closed. The ring map $S \to S/I$ obviously satisfies going up. Hence $R \to S \to S/I$ satisfies going up, by Lemma Composition of going-up and going-down maps (uncovered prerequisite). Replacing $S$ by $S/I$ it suffices to show the image $T$ of $\operatorname{Spec}(S)$ in $\operatorname{Spec}(R)$ is closed. By Topology, Lemmas The geometric construction (uncovered prerequisite) and Lifting the geometric construction (uncovered prerequisite) this image is stable under specialization. Thus the result follows from Lemma Closed images stable under specialization (uncovered prerequisite). $\square$
Lemma. Going up for integral ring maps
Let $R \to S$ be a ring map such that $S$ is integral over $R$. Let $\mathfrak p \subset \mathfrak p' \subset R$ be primes. Let $\mathfrak q$ be a prime of $S$ mapping to $\mathfrak p$. Then there exists a prime $\mathfrak q'$ with $\mathfrak q \subset \mathfrak q'$ mapping to $\mathfrak p'$.
Proof. We may replace $R$ by $R/\mathfrak p$ and $S$ by $S/\mathfrak q$. This reduces us to the situation of having an integral extension of domains $R \subset S$ and a prime $\mathfrak p' \subset R$. By Lemma Surjectivity on spectra of an integral overring we win. $\square$
Lemma. Standard affine covers of a spectrum
Let $R$ be a ring, and let $f_1, f_2, \ldots, f_n \in R$ generate the unit ideal in $R$. Then the following sequence is exact: $$0 \longrightarrow R \longrightarrow \bigoplus\nolimits_i R_{f_i} \longrightarrow \bigoplus\nolimits_{i, j}R_{f_if_j}$$ where the maps $\alpha : R \longrightarrow \bigoplus_i R_{f_i}$ and $\beta : \bigoplus_i R_{f_i} \longrightarrow \bigoplus_{i, j} R_{f_if_j}$ are defined as $$\alpha(x) = \left(\frac{x}{1}, \ldots, \frac{x}{1}\right) \text{ and } \beta\left(\frac{x_1}{f_1^{r_1}}, \ldots, \frac{x_n}{f_n^{r_n}}\right)
\left(\frac{x_i}{f_i^{r_i}}-\frac{x_j}{f_j^{r_j}}~\text{in}~R_{f_if_j}\right).$$
Proof. Special case of Lemma Modules (uncovered prerequisite). $\square$
Lemma. Morphisms between étale algebras
Let $R \to S$ and $R \to S'$ be étale. Then any $R$-algebra map $S' \to S$ is étale.
Proof. First of all we note that $S' \to S$ is of finite presentation by Lemma Composition of finite-type ring maps. Let $\mathfrak q \subset S$ be a prime ideal lying over the primes $\mathfrak q' \subset S'$ and $\mathfrak p \subset R$. By Lemma Étaleness at a prime ideal (uncovered prerequisite) the ring map $S'_{\mathfrak q'}/\mathfrak p S'_{\mathfrak q'} \to S_{\mathfrak q}/\mathfrak p S_{\mathfrak q}$ is a map of finite separable extensions of $\kappa(\mathfrak p)$. In particular it is flat. Hence by Lemma The fibrewise criterion for flatness (uncovered prerequisite) we see that $S'_{\mathfrak q'} \to S_{\mathfrak q}$ is flat. Thus $S' \to S$ is flat. Moreover, the above also shows that $\mathfrak q'S_{\mathfrak q}$ is the maximal ideal of $S_{\mathfrak q}$ and that the residue field extension of $S'_{\mathfrak q'} \to S_{\mathfrak q}$ is finite separable. Hence from Lemma Characterizations of étale algebras (uncovered prerequisite) we conclude that $S' \to S$ is étale at $\mathfrak q$. Since being étale is local (see Lemma Étale morphisms) we win. $\square$
Lemma. Finite presentation and flatness
Let $\varphi : R \to S$ be a ring map. If $R \to S$ is surjective, flat and finitely presented then there exists an idempotent $e \in R$ such that $S = R_e$.
First proof. Let $I$ be the kernel of $\varphi$. We have that $I$ is finitely generated by Lemma Finite presentation and finite algebras since $\varphi$ is of finite presentation. Moreover, since $S$ is flat over $R$, tensoring the exact sequence $0 \to I \to R \to S \to 0$ over $R$ with $S$ gives $I/I^2 = 0$. Now we conclude by Lemma Idempotent ideals and connected components (uncovered prerequisite). $\square$
Second proof. Since $\operatorname{Spec}(S) \to \operatorname{Spec}(R)$ is a homeomorphism onto a closed subset (see Lemma Closed subsets of an affine spectrum (uncovered prerequisite)) and is open (see Proposition Openness of flat finitely presented maps) we see that the image is $D(e)$ for some idempotent $e \in R$ (see Lemma Product decompositions from disjoint closed subsets). Thus $R_e \to S$ induces a bijection on spectra. Now this map induces an isomorphism on all local rings for example by Lemmas Finite flat modules over a local ring and Nakayama's lemma. Then it follows that $R_e \to S$ is also injective, for example see Lemma Detecting a zero module by localization. $\square$
Lemma. Étale morphisms
Results on étale ring maps.
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The ring map $R \to R_f$ is étale for any ring $R$ and any $f \in R$.
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Compositions of étale ring maps are étale.
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A base change of an étale ring map is étale.
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The property of being étale is local: Given a ring map $R \to S$ and elements $g_1, \ldots, g_m \in S$ which generate the unit ideal such that $R \to S_{g_j}$ is étale for $j = 1, \ldots, m$ then $R \to S$ is étale.
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Given $R \to S$ of finite presentation, and a flat ring map $R \to R'$, set $S' = R' \otimes_R S$. The set of primes where $R' \to S'$ is étale is the inverse image via $\operatorname{Spec}(S') \to \operatorname{Spec}(S)$ of the set of primes where $R \to S$ is étale.
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An étale ring map is syntomic, in particular flat.
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If $S$ is finite type over a field $k$, then $S$ is étale over $k$ if and only if $\Omega_{S/k} = 0$.
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Any étale ring map $R \to S$ is the base change of an étale ring map $R_0 \to S_0$ with $R_0$ of finite type over $\mathbf{Z}$.
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Let $A = \mathop{\operatorname{colim}} A_i$ be a filtered colimit of rings. Let $A \to B$ be an étale ring map. Then there exists an étale ring map $A_i \to B_i$ for some $i$ such that $B \cong A \otimes_{A_i} B_i$.
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Let $A$ be a ring. Let $S$ be a multiplicative subset of $A$. Let $S^{-1}A \to B'$ be étale. Then there exists an étale ring map $A \to B$ such that $B' \cong S^{-1}B$.
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Let $A$ be a ring. Let $B = B' \times B''$ be a product of $A$-algebras. Then $B$ is étale over $A$ if and only if both $B'$ and $B''$ are étale over $A$.
Proof. In each case we use the corresponding result for smooth ring maps with a small argument added to show that $\Omega_{S/R}$ is zero.
Proof of (1). The ring map $R \to R_f$ is smooth and $\Omega_{R_f/R} = 0$.
Proof of (2). The composition $A \to C$ of smooth maps $A \to B$ and $B \to C$ is smooth, see Lemma Composition of smooth ring maps (uncovered prerequisite). By Lemma Kähler differentials, Theorems 3.1–3.3, Proposition 3.4 and Theorem 7.1 we see that $\Omega_{C/A}$ is zero as both $\Omega_{C/B}$ and $\Omega_{B/A}$ are zero.
Proof of (3). Let $R \to S$ be étale and $R \to R'$ be arbitrary. Then $R' \to S' = R' \otimes_R S$ is smooth, see Lemma Base change of smooth ring maps (uncovered prerequisite). Since $\Omega_{S'/R'} = S' \otimes_S \Omega_{S/R}$ by Lemma Base change of Kähler differentials we conclude that $\Omega_{S'/R'} = 0$. Hence $R' \to S'$ is étale.
Proof of (4). Assume the hypotheses of (4). By Lemma Smooth morphisms and local algebra (uncovered prerequisite) we see that $R \to S$ is smooth. We are also given that $\Omega_{S_{g_i}/R} = (\Omega_{S/R})_{g_i} = 0$ for all $i$. Then $\Omega_{S/R} = 0$, see Lemma A finite cover by affine localizations.
Proof of (5). The result for smooth maps is Lemma The smooth locus under flat base change (uncovered prerequisite). In the proof of that lemma we used that $\mathrm{NL}_{S/R} \otimes_S S'$ is homotopy equivalent to $\mathrm{NL}_{S'/R'}$. This reduces us to showing that if $M$ is a finitely presented $S$-module the set of primes $\mathfrak q'$ of $S'$ such that $(M \otimes_S S')_{\mathfrak q'} = 0$ is the inverse image of the set of primes $\mathfrak q$ of $S$ such that $M_{\mathfrak q} = 0$. This follows from Lemma Support under base change (uncovered prerequisite).
Proof of (6). Follows directly from the corresponding result for smooth ring maps (Lemma Smooth algebras are syntomic (uncovered prerequisite)).
Proof of (7). Follows from Lemma Smooth algebras over a field and the Jacobian criterion, Theorems 5.1–6.1 and Sections 1–3 and the definitions.
Proof of (8). Lemma Finite presentation and formal smoothness over a Noetherian ring (uncovered prerequisite) gives the result for smooth ring maps. The resulting smooth ring map $R_0 \to S_0$ satisfies the hypotheses of Lemma Relative dimension in a Cohen–Macaulay family (uncovered prerequisite), and hence we may replace $S_0$ by the factor of relative dimension $0$ over $R_0$.
Proof of (9). Follows from (8) since $R_0 \to A$ will factor through $A_i$ for some $i$ by Lemma Characterizations of finite presentation (uncovered prerequisite).
Proof of (10). Follows from (9), (1), and (2) since $S^{-1}A$ is a filtered colimit of principal localizations of $A$.
Proof of (11). Use Lemma Products of smooth algebras (uncovered prerequisite) to see the result for smoothness and then use that $\Omega_{B/A}$ is zero if and only if both $\Omega_{B'/A}$ and $\Omega_{B''/A}$ are zero. $\square$
Lemma. Lifting étale morphisms and finite algebras
Consider a commutative diagram $$\begin{gathered}\begin{matrix}0 & J & B' & B & 0 \\ 0 & I & A' & A & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow J \\ J & \longrightarrow B' \\ B' & \longrightarrow B \\ B & \longrightarrow 0 \\ 0 & \longrightarrow I \\ I & \longrightarrow A' \\ I & \longrightarrow J \\ A' & \longrightarrow A \\ A' & \longrightarrow B' \\ A & \longrightarrow 0 \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ with exact rows where $B' \to B$ and $A' \to A$ are surjective ring maps whose kernels are ideals of square zero. If $A \to B$ is étale, and $J = I \otimes_A B$, then $A' \to B'$ is étale.
Proof. By Lemma Lifting étale morphisms there exists an étale ring map $A' \to C$ such that $C/IC = B$. Then $A' \to C$ is formally smooth (by Proposition Formal smoothness of smooth algebras (uncovered prerequisite)) hence we get an $A'$-algebra map $\varphi : C \to B'$. Since $A' \to C$ is flat we have $I \otimes_A B = I \otimes_A C/IC = IC$. Hence the assumption that $J = I \otimes_A B$ implies that $\varphi$ induces an isomorphism $IC \to J$ and an isomorphism $C/IC \to B'/IB'$, whence $\varphi$ is an isomorphism. $\square$
Lemma. Dimension, codimension and finite algebras
Let $R \to S$ be a finite type ring map. Let $\mathfrak q \subset S$ be a prime lying over $\mathfrak p \subset R$. If $R \to S$ is quasi-finite at $\mathfrak q$, then $\dim(S_{\mathfrak q}) \leq \dim(R_{\mathfrak p})$.
Proof. If $R_{\mathfrak p}$ is Noetherian (and hence $S_{\mathfrak q}$ Noetherian since it is essentially of finite type over $R_{\mathfrak p}$) then this follows immediately from Lemma Dimensions of a base, fibre and total space (uncovered prerequisite) and the definitions. In the general case, let $S'$ be the integral closure of $R_\mathfrak p$ in $S_\mathfrak p$. By Zariski's Main Theorem Zariski's main theorem in affine algebra (uncovered prerequisite) we have $S_{\mathfrak q} = S'_{\mathfrak q'}$, where $\mathfrak q' = S' \cap \mathfrak qS_{\mathfrak p}$. By Lemma Dimension under an integral extension (uncovered prerequisite) we have $\dim(S') \leq \dim(R_\mathfrak p)$ and hence a fortiori $\dim(S_\mathfrak q) = \dim(S'_{\mathfrak q'}) \leq \dim(R_\mathfrak p)$. $\square$
Lemma. Integral extensions
Let $A$ be a Noetherian domain of dimension $1$ with fraction field $K$. Let $L/K$ be a finite extension. Let $B$ be the integral closure of $A$ in $L$. Then $B$ is a Dedekind domain and $\operatorname{Spec}(B) \to \operatorname{Spec}(A)$ is surjective, has finite fibres, and induces finite residue field extensions.
Proof. By Krull-Akizuki (Lemma Commutative algebra (uncovered prerequisite)) the ring $B$ is Noetherian. By Lemma Dimension, codimension and integral extensions (uncovered prerequisite) $\dim(B) = 1$. Thus $B$ is a Dedekind domain by Lemma Characterizations of Dedekind domains. Surjectivity of the map on spectra follows from Lemma Surjectivity on spectra of an integral overring. The last two statements follow from Lemma Dimension, codimension and field extensions (uncovered prerequisite). $\square$
Lemma. Criteria for integral extensions and finite algebras
Let $R \to S$ be a ring map. The following are equivalent
-
$R \to S$ is finite,
-
$R \to S$ is integral and of finite type, and
-
there exist $x_1, \ldots, x_n \in S$ which generate $S$ as an algebra over $R$ such that each $x_i$ is integral over $R$.
Proof. Clear from Lemma Criteria for integral extensions (uncovered prerequisite). $\square$
Lemma. Surjectivity on spectra of an integral overring
Suppose that $R \to S$ is an integral ring extension with $R \subset S$. Then $\varphi : \operatorname{Spec}(S) \to \operatorname{Spec}(R)$ is surjective.
Proof. Let $\mathfrak p \subset R$ be a prime ideal. We have to show $\mathfrak pS_{\mathfrak p} \not = S_{\mathfrak p}$, see Lemma A point in the image of a spectrum map (uncovered prerequisite). The localization $R_{\mathfrak p} \to S_{\mathfrak p}$ is injective (as localization is exact) and integral by Lemma Integral extensions and local algebra (uncovered prerequisite) or Base change for integral extensions (uncovered prerequisite). Hence we may replace $R$, $S$ by $R_{\mathfrak p}$, $S_{\mathfrak p}$ and we may assume $R$ is local with maximal ideal $\mathfrak m$ and it suffices to show that $\mathfrak mS \not = S$. Suppose $1 = \sum f_i s_i$ with $f_i \in \mathfrak m$ and $s_i \in S$ in order to get a contradiction. Let $R \subset S' \subset S$ be such that $R \to S'$ is finite and $s_i \in S'$, see Lemma Criteria for integral extensions (uncovered prerequisite). The equation $1 = \sum f_i s_i$ implies that the finite $R$-module $S'$ satisfies $S' = \mathfrak m S'$. Hence by Nakayama's Lemma Nakayama's lemma we see $S' = 0$. Contradiction. $\square$
Lemma. Tensor products and direct sums
A product of ideals is an invertible module iff both factors are.
Let $A$ be a ring. Let $I$ and $J$ be nonzero ideals of $A$ such that $IJ = (f)$ for some nonzerodivisor $f \in A$. Then $I$ and $J$ are finitely generated ideals and finitely locally free of rank $1$ as $A$-modules.
Proof. It suffices to show that $I$ and $J$ are finite locally free $A$-modules of rank $1$, see Lemma Characterizations of finite projective modules. To do this, write $f = \sum_{i = 1, \ldots, n} x_i y_i$ with $x_i \in I$ and $y_i \in J$. We can also write $x_i y_i = a_i f$ for some $a_i \in A$. Since $f$ is a nonzerodivisor we see that $\sum a_i = 1$. Thus it suffices to show that each $I_{a_i}$ and $J_{a_i}$ is free of rank $1$ over $A_{a_i}$. After replacing $A$ by $A_{a_i}$ we conclude that $f = xy$ for some $x \in I$ and $y \in J$. Note that both $x$ and $y$ are nonzerodivisors. We claim that $I = (x)$ and $J = (y)$ which finishes the proof. Namely, if $x' \in I$, then $x'y = af = axy$ for some $a \in A$. Hence $x' = ax$ and we win. $\square$
Lemma. Cohen's theorem for Noetherian rings
Let $R$ be a ring.
-
An ideal $I \subset R$ maximal with respect to not being finitely generated is prime.
-
If every prime ideal of $R$ is finitely generated, then every ideal of $R$ is finitely generated[^3].
Proof. The first assertion is an immediate consequence of Example Finite algebras (uncovered prerequisite) and Proposition Commutative algebra (uncovered prerequisite). For the second, suppose that there exists an ideal $I \subset R$ which is not finitely generated. The union of a totally ordered chain $\left\{I_\alpha\right\}$ of ideals that are not finitely generated is not finitely generated; indeed, if $I = \bigcup I_\alpha$ were generated by $a_1, \ldots, a_n$, then all the generators would belong to some $I_\alpha$ and would consequently generate it. By Zorn's lemma, there is an ideal maximal with respect to being not finitely generated. By the first part this ideal is prime. $\square$
Lemma. Characterizations of discrete valuation rings
Let $A$ be a ring. The following are equivalent.
-
The ring $A$ is a discrete valuation ring.
-
The ring $A$ is a valuation ring and Noetherian but not a field.
-
The ring $A$ is a regular local ring of dimension $1$.
-
The ring $A$ is a Noetherian local domain with maximal ideal $\mathfrak m$ generated by a single nonzero element.
-
The ring $A$ is a Noetherian local normal domain of dimension $1$.
In this case if $\pi$ is a generator of the maximal ideal of $A$, then every nonzero element of $A$ can be uniquely written as $u\pi^n$, where $u \in A$ is a unit and $n \in \mathbf{Z}_{\geq 0}$.
Proof. The equivalence of (1) and (2) is Lemma Noetherian rings (uncovered prerequisite). Moreover, in the proof of Lemma Noetherian rings (uncovered prerequisite) we saw that if $A$ is a discrete valuation ring, then $A$ is a PID, hence (3). Note that a regular local ring is a domain (see Lemma Regular local rings, Theorem 1.1). Using this the equivalence of (3) and (4) follows from dimension theory, see Section Dimension and codimension.
Assume (3) and let $\pi$ be a generator of the maximal ideal $\mathfrak m$. For all $n \geq 0$ we have $\dim_{A/\mathfrak m} \mathfrak m^n/\mathfrak m^{n + 1} = 1$ because it is generated by $\pi^n$ (and it cannot be zero). In particular $\mathfrak m^n = (\pi^n)$ and the graded ring $\bigoplus \mathfrak m^n/\mathfrak m^{n + 1}$ is isomorphic to the polynomial ring $(A/\mathfrak m)[T]$. For $x \in A \setminus \{0\}$ define $v(x) = \max\{n \mid x \in \mathfrak m^n\}$. In other words $x = u \pi^{v(x)}$ with $u \in A^*$. By the remarks above we have $v(xy) = v(x) + v(y)$ for all $x, y \in A \setminus \{0\}$. We extend this to the field of fractions $K$ of $A$ by setting $v(a/b) = v(a) - v(b)$ (well defined by multiplicativity shown above). Then it is clear that $A$ is the set of elements of $K$ which have valuation $\geq 0$. Hence we see that $A$ is a valuation ring by Lemma Commutative algebra (uncovered prerequisite).
A valuation ring is a normal domain by Lemma Commutative algebra (uncovered prerequisite). Hence we see that the equivalent conditions (1) -- (3) imply (5). Assume (5). Suppose that $\mathfrak m$ cannot be generated by $1$ element to get a contradiction. Then Lemma Regular rings and dimension and codimension (uncovered prerequisite) implies there is a finite ring map $A \to A'$ which is an isomorphism after inverting any nonzero element of $\mathfrak m$ but not an isomorphism. In particular we may identify $A'$ with a subset of the fraction field of $A$. Since $A \to A'$ is finite it is integral (see Lemma Integral extensions and finite algebras (uncovered prerequisite)). Since $A$ is normal we get $A = A'$ a contradiction. $\square$
Lemma. Local algebra
Let $R$ be a domain. The following are equivalent:
-
The domain $R$ is a normal domain,
-
for every prime $\mathfrak p \subset R$ the local ring $R_{\mathfrak p}$ is a normal domain, and
-
for every maximal ideal $\mathfrak m$ the ring $R_{\mathfrak m}$ is a normal domain.
Proof. We deduce (1) $\Rightarrow$ (2) from Lemma Localization of local algebra (uncovered prerequisite). The implication (2) $\Rightarrow$ (3) is immediate. The implication (3) $\Rightarrow$ (1) follows from the fact that for any domain $R$ we have $$R = \bigcap\nolimits_{\mathfrak m} R_{\mathfrak m}$$ inside the fraction field of $R$. Namely, if $g$ is an element of the right hand side then the ideal $I = \{x \in R \mid xg \in R\}$ is not contained in any maximal ideal $\mathfrak m$, whence $I = R$. $\square$
Lemma. A graded finite-generation calculation
Suppose $S$ is a graded ring, $\mathfrak p_i$, $i = 1, \ldots, r$ homogeneous prime ideals and $I \subset S_{+}$ a graded ideal. Assume $I \not\subset \mathfrak p_i$ for all $i$. Then there exists a homogeneous element $x\in I$ of positive degree such that $x\not\in \mathfrak p_i$ for all $i$.
Proof. We may assume there are no inclusions among the $\mathfrak p_i$. The result is true for $r = 1$. Suppose the result holds for $r - 1$. Pick $x \in I$ homogeneous of positive degree such that $x \not \in \mathfrak p_i$ for all $i = 1, \ldots, r - 1$. If $x \not\in \mathfrak p_r$ we are done. So assume $x \in \mathfrak p_r$. If $I \mathfrak p_1 \ldots \mathfrak p_{r-1} \subset \mathfrak p_r$ then $I \subset \mathfrak p_r$ a contradiction. Pick $y \in I\mathfrak p_1 \ldots \mathfrak p_{r-1}$ homogeneous and $y \not \in \mathfrak p_r$. Then $x^{\deg(y)} + y^{\deg(x)}$ works. $\square$
Lemma. Filtered limits and finite presentation
Suppose that $R = \mathop{\operatorname{colim}}_{\lambda \in \Lambda} R_\lambda$ is a directed colimit of rings. Then the category of finitely presented $R$-algebras is the colimit of the categories of finitely presented $R_\lambda$-algebras. More precisely
-
Given a finitely presented $R$-algebra $A$ there exists a $\lambda \in \Lambda$ and a finitely presented $R_\lambda$-algebra $A_\lambda$ such that $A \cong A_\lambda \otimes_{R_\lambda} R$.
-
Given a $\lambda \in \Lambda$, finitely presented $R_\lambda$-algebras $A_\lambda, B_\lambda$, and an $R$-algebra map $\varphi : A_\lambda \otimes_{R_\lambda} R \to B_\lambda \otimes_{R_\lambda} R$, then there exists a $\mu \geq \lambda$ and an $R_\mu$-algebra map $\varphi_\mu : A_\lambda \otimes_{R_\lambda} R_\mu \to B_\lambda \otimes_{R_\lambda} R_\mu$ such that $\varphi = \varphi_\mu \otimes 1_R$.
-
Given a $\lambda \in \Lambda$, finitely presented $R_\lambda$-algebras $A_\lambda, B_\lambda$, and $R_\lambda$-algebra maps $\varphi_\lambda, \psi_\lambda : A_\lambda \to B_\lambda$ such that $\varphi_\lambda \otimes 1_R = \psi_\lambda \otimes 1_R$, then $\varphi_\lambda \otimes 1_{R_\mu} = \psi_\lambda \otimes 1_{R_\mu}$ for some $\mu \geq \lambda$.
Proof. To prove (1) choose a presentation $A = R[x_1, \ldots, x_n]/(f_1, \ldots, f_m)$. We can choose a $\lambda \in \Lambda$ and elements $f_{\lambda, j} \in R_\lambda[x_1, \ldots, x_n]$ mapping to $f_j \in R[x_1, \ldots, x_n]$. Then we simply let $A_\lambda = R_\lambda[x_1, \ldots, x_n]/(f_{\lambda, 1}, \ldots, f_{\lambda, m})$.
Parts (2) and (3) follow from Lemma Filtered limits and proper morphisms (uncovered prerequisite). $\square$
Lemma. Base change of Kähler differentials
Suppose that we have ring maps $R \to R'$ and $R \to S$. Set $S' = S \otimes_R R'$, so that we obtain a diagram (Commutative algebra). Then the canonical map defined above induces an isomorphism $\Omega_{S/R} \otimes_R R' = \Omega_{S'/R'}$.
Proof. Let $\text{d}' : S' = S \otimes_R R' \to \Omega_{S/R} \otimes_R R'$ denote the map $\text{d}'( \sum a_i \otimes x_i ) = \sum \text{d}(a_i) \otimes x_i$. It exists because the map $S \times R' \to \Omega_{S/R} \otimes_R R'$, $(a, x)\mapsto \text{d}a \otimes_R x$ is $R$-bilinear. This is an $R'$-derivation, as can be verified by a simple computation. We will show that $(\Omega_{S/R} \otimes_R R', \text{d}')$ satisfies the universal property. Let $D : S' \to M'$ be an $R'$-derivation into an $S'$-module. The composition $S \to S' \to M'$ is an $R$-derivation, hence we get an $S$-linear map $\varphi_D : \Omega_{S/R} \to M'$. We may tensor this with $R'$ and get the map $\varphi'_D : \Omega_{S/R} \otimes_R R' \to M'$, $\varphi'_D(\eta \otimes x) = x\varphi_D(\eta)$. It is clear that $D = \varphi'_D \circ \text{d}'$. $\square$
Lemma. Filtered limits and flatness
Let $R$ be a ring. Let $\{M_i, \varphi_{ii'}\}$ be a directed system of flat $R$-modules. Then $\mathop{\operatorname{colim}}_i M_i$ is a flat $R$-module.
Proof. This follows as $\otimes$ commutes with colimits and because directed colimits are exact, see Lemma Filtered limits and commutative algebra (uncovered prerequisite). $\square$
Lemma. Flatness and modules
Let $R \to S$ be a ring map. Let $I \subset R$ be an ideal. Let $M$ be an $S$-module. Assume
-
$R$ is a Noetherian ring,
-
$S$ is a Noetherian ring,
-
$M$ is a finite $S$-module, and
-
for each $n \geq 1$ the module $M/I^n M$ is flat over $R/I^n$.
Then for every $\mathfrak q \in V(IS)$ the localization $M_{\mathfrak q}$ is flat over $R$. In particular, if $S$ is local and $IS$ is contained in its maximal ideal, then $M$ is flat over $R$.
Proof. We are going to use Lemma A variant of the local criterion for flatness (uncovered prerequisite). By assumption $M/IM$ is flat over $R/I$. Hence it suffices to check that $\text{Tor}_1^R(M, R/I)$ is zero on localization at $\mathfrak q$. By Remark Tor for a quotient by an ideal this Tor group is equal to $K = \operatorname{Ker}(I \otimes_R M \to M)$. We know that the kernel of $I/I^n \otimes_{R/I^n} M/I^nM \to M/I^nM$ is zero for all $n \geq 1$. Hence an element of $K$ maps to zero in $I/I^n \otimes_{R/I^n} M/I^nM$. Since $$I/I^n \otimes_{R/I^n} M/I^nM = I/I^n \otimes_R M = (I \otimes_R M)/I^{n - 1}(I \otimes_R M)$$ we conclude that $K \subset I^{n - 1}(I \otimes_R M)$ for all $n \geq 1$. By the Artin-Rees lemma, and more precisely Lemma Modules (uncovered prerequisite) we conclude that $K_{\mathfrak q} = 0$, as desired. $\square$
Lemma. Functoriality of affine spectra
Functoriality of the spectrum
Suppose that $\varphi : R \to R'$ is a ring homomorphism. The induced map $$\operatorname{Spec}(\varphi) : \operatorname{Spec}(R') \longrightarrow \operatorname{Spec}(R), \quad \mathfrak p' \longmapsto \varphi^{-1}(\mathfrak p')$$ is continuous for the Zariski topologies. In fact, for any element $f \in R$ we have $\operatorname{Spec}(\varphi)^{-1}(D(f)) = D(\varphi(f))$.
Proof. It is basic notion (Prime spectra and associated points) that $\mathfrak p := \varphi^{-1}(\mathfrak p')$ is indeed a prime ideal of $R$. The last assertion of the lemma follows directly from the definitions, and implies the first. $\square$
Theorem. Openness of the flat locus
Let $R$ be a ring. Let $R \to S$ be a ring map of finite presentation. Let $M$ be a finitely presented $S$-module. The set $$\{ \mathfrak q \in \operatorname{Spec}(S) \mid M_{\mathfrak q}\text{ is flat over }R\}$$ is open in $\operatorname{Spec}(S)$.
Proof. Let $\mathfrak q \in \operatorname{Spec}(S)$ be a prime. Let $\mathfrak p \subset R$ be the inverse image of $\mathfrak q$ in $R$. Note that $M_{\mathfrak q}$ is flat over $R$ if and only if it is flat over $R_{\mathfrak p}$. Let us assume that $M_{\mathfrak q}$ is flat over $R$. We claim that there exists a $g \in S$, $g \not \in \mathfrak q$ such that $M_g$ is flat over $R$.
We first reduce to the case where $R$ and $S$ are of finite type over $\mathbf{Z}$. Choose a directed set $\Lambda$ and a system $(R_\lambda \to S_\lambda, M_\lambda)$ as in Lemma Filtered limits and finite presentation and modules (uncovered prerequisite). Set $\mathfrak p_\lambda$ equal to the inverse image of $\mathfrak p$ in $R_\lambda$. Set $\mathfrak q_\lambda$ equal to the inverse image of $\mathfrak q$ in $S_\lambda$. Then the system $$((R_\lambda)_{\mathfrak p_\lambda}, (S_\lambda)_{\mathfrak q_\lambda}, (M_\lambda)_{\mathfrak q_{\lambda}})$$ is a system as in Lemma Essentially finitely presented module models (uncovered prerequisite). Hence by Lemma Eventual flatness in a filtered colimit (uncovered prerequisite) we see that for some $\lambda$ the module $M_\lambda$ is flat over $R_\lambda$ at the prime $\mathfrak q_{\lambda}$. Suppose we can prove our claim for the system $(R_\lambda \to S_\lambda, M_\lambda, \mathfrak q_{\lambda})$. In other words, suppose that we can find a $g \in S_\lambda$, $g \not\in \mathfrak q_\lambda$ such that $(M_\lambda)_g$ is flat over $R_\lambda$. By Lemma Filtered limits and finite presentation and modules (uncovered prerequisite) we have $M = M_\lambda \otimes_{R_\lambda} R$ and hence also $M_g = (M_\lambda)_g \otimes_{R_\lambda} R$. Thus by Lemma Base change of flat modules (uncovered prerequisite) we deduce the claim for the system $(R \to S, M, \mathfrak q)$.
At this point we may assume that $R$ and $S$ are of finite type over $\mathbf{Z}$. We may write $S$ as a quotient of a polynomial ring $R[x_1, \ldots, x_n]$. Of course, we may replace $S$ by $R[x_1, \ldots, x_n]$ and assume that $S$ is a polynomial ring over $R$. In particular we see that $R \to S$ is flat and all fibre rings $S \otimes_R \kappa(\mathfrak p)$ have global dimension $n$.
If $n = 0$, then $S = R$ and the finite flat module $M_{\mathfrak q}$ is free, including rank zero. Its basis spreads after a localization, proving the claim. Hence assume $n \geq 1$. Choose a resolution $F_\bullet$ of $M$ over $S$ with each $F_i$ finite free, see Lemma Projective, locally free modules and finite algebras (uncovered prerequisite). Let $K_1 = \operatorname{Ker}(F_0 \to M)$ and, for $n \geq 2$, let $K_n = \operatorname{Ker}(F_{n-1} \to F_{n-2})$. Note that $(K_n)_{\mathfrak q}$ is flat over $R$, since each $F_i$ is flat over $R$ and by assumption on $M$, see Lemma Flat modules in a short exact sequence (uncovered prerequisite). In addition, the sequence $$0 \to K_n/\mathfrak p K_n \to F_{n-1}/ \mathfrak p F_{n-1} \to \ldots \to F_0 / \mathfrak p F_0 \to M/\mathfrak p M \to 0$$ is exact upon localizing at $\mathfrak q$, because of vanishing of $\text{Tor}_i^{R_\mathfrak p}(\kappa(\mathfrak p), M_{\mathfrak q})$. Since the global dimension of $S_\mathfrak q/\mathfrak p S_{\mathfrak q}$ is at most $n$ we conclude that $K_n / \mathfrak p K_n$ localized at $\mathfrak q$ is a finite free module over $S_\mathfrak q/\mathfrak p S_{\mathfrak q}$. By Lemma Projective, locally free modules and flatness (uncovered prerequisite) $(K_n)_{\mathfrak q}$ is free over $S_{\mathfrak q}$. In particular, there exists a $g \in S$, $g \not \in \mathfrak q$ such that $(K_n)_g$ is finite free over $S_g$.
By Lemma Commutative algebra (uncovered prerequisite) there exists a further localization $S_g$ such that the complex $$0 \to K_n \to F_{n-1} \to \ldots \to F_0$$ is exact on all fibres of $R \to S$. By Lemma Derived categories (uncovered prerequisite) this implies that the cokernel of $F_1 \to F_0$ is flat. This proves the theorem in the Noetherian case. $\square$
Lemma. Finite presentation and finite algebras
Let $R$ be a ring. Let $\varphi : M \to N$ be a map of $R$-modules with $M$ finite and $N$ finitely presented. Then $$U = \{\mathfrak p \subset R \mid \varphi_{\mathfrak p} : M_{\mathfrak p} \to N_{\mathfrak p} \text{ is an isomorphism}\}$$ is an open subset of $\operatorname{Spec}(R)$.
Proof. Let $\mathfrak p \in U$. Pick a presentation $N = R^{\oplus n}/\sum_{j = 1, \ldots, m} R k_j$. Denote $e_i$ the image in $N$ of the $i$th basis vector of $R^{\oplus n}$. For each $i \in \{1,\ldots,n\}$ choose a preimage $n_i/s_i\in M_{\mathfrak p}$ of $e_i/1$, with $n_i\in M$ and $s_i\notin\mathfrak p$. Choose $t_i\notin\mathfrak p$ such that $t_i(\varphi(n_i)-s_ie_i)=0$ in $N$. Put $m_i=t_in_i\in M$ and $f_i=t_is_i\notin\mathfrak p$; then $\varphi(m_i)=f_ie_i$ in $N$. Set $f=f_1\cdots f_n$ and let $\psi : R_f^{\oplus n} \to M_f$ be the map which maps the $i$th basis vector to $m_i/f_i$. Note that $\varphi_f \circ \psi$ is the localization at $f$ of the given map $R^{\oplus n} \to N$. As $\varphi_{\mathfrak p}$ is an isomorphism we see that $\psi(k_j)$ is an element of $M_f$ which maps to zero in $M_{\mathfrak p}$. Hence we see that there exist $g_j \in R$, $g_j \not \in \mathfrak p$ such that $g_j \psi(k_j) = 0$. Setting $g = g_1 \ldots g_m$, we see that $\psi_g$ factors through $N_{fg}$ to give a map $\chi : N_{fg} \to M_{fg}$. By construction $\chi$ is a right inverse to $\varphi_{fg}$. It follows that $\chi_\mathfrak p$ is an isomorphism. By Lemma Finite algebras (uncovered prerequisite) there is an $h \in R$, $h \not \in \mathfrak p$ such that $\chi_h : N_{fgh} \to M_{fgh}$ is surjective. Hence $\varphi_{fgh}$ and $\chi_h$ are mutually inverse maps, which implies that $D(fgh) \subset U$ as desired. $\square$
Proposition. Openness of flat finitely presented maps
Let $R \to S$ be flat and of finite presentation. Then $\operatorname{Spec}(S) \to \operatorname{Spec}(R)$ is open. More generally this holds for any ring map $R \to S$ of finite presentation which satisfies going down.
Proof. If $R \to S$ is flat, then $R \to S$ satisfies going down by Lemma Going down for flat ring maps (uncovered prerequisite). Thus to prove the lemma we may assume that $R \to S$ has finite presentation and satisfies going down.
Since the standard opens $D(g) \subset \operatorname{Spec}(S)$, $g \in S$ form a basis for the topology, it suffices to prove that the image of $D(g)$ is open. Recall that $\operatorname{Spec}(S_g) \to \operatorname{Spec}(S)$ is a homeomorphism of $\operatorname{Spec}(S_g)$ onto $D(g)$ (Lemma Principal open subsets of a spectrum (uncovered prerequisite)). Since $S \to S_g$ satisfies going down (see above), we see that $R \to S_g$ satisfies going down by Lemma Composition of going-up and going-down maps (uncovered prerequisite). Thus after replacing $S$ by $S_g$ we see it suffices to prove the image is open. By Chevalley's theorem (Theorem Chevalley's constructibility theorem (uncovered prerequisite)) the image is a constructible set $E$. And $E$ is stable under generalization because $R \to S$ satisfies going down, see Topology, Lemmas The geometric construction (uncovered prerequisite) and Lifting the geometric construction (uncovered prerequisite). Hence $E$ is open by Lemma Commutative algebra (uncovered prerequisite). $\square$
Lemma. Injective resolutions and sheaves on ringed sites
Let $R \to S$ be a ring map. Let $M \to M'$ be a map of $S$-modules. The following are equivalent
-
$M \to M'$ is universally injective as a map of $R$-modules,
-
for each prime $\mathfrak q$ of $S$ the map $M_{\mathfrak q} \to M'_{\mathfrak q}$ is universally injective as a map of $R$-modules,
-
for each maximal ideal $\mathfrak m$ of $S$ the map $M_{\mathfrak m} \to M'_{\mathfrak m}$ is universally injective as a map of $R$-modules,
-
for each prime $\mathfrak q$ of $S$ the map $M_{\mathfrak q} \to M'_{\mathfrak q}$ is universally injective as a map of $R_{\mathfrak p}$-modules, where $\mathfrak p$ is the inverse image of $\mathfrak q$ in $R$, and
-
for each maximal ideal $\mathfrak m$ of $S$ the map $M_{\mathfrak m} \to M'_{\mathfrak m}$ is universally injective as a map of $R_{\mathfrak p}$-modules, where $\mathfrak p$ is the inverse image of $\mathfrak m$ in $R$.
Proof. Let $N$ be an $R$-module. Let $\mathfrak q$ be a prime of $S$ lying over the prime $\mathfrak p$ of $R$. Then we have $$(M \otimes_R N)_{\mathfrak q} = M_{\mathfrak q} \otimes_R N = M_{\mathfrak q} \otimes_{R_{\mathfrak p}} N_{\mathfrak p}.$$ Moreover, the same thing holds for $M'$ and localization is exact. Also, if $N$ is an $R_{\mathfrak p}$-module, then $N_{\mathfrak p} = N$. Using this the equivalences can be proved in a straightforward manner.
For example, suppose that (5) holds. Let $K = \operatorname{Ker}(M \otimes_R N \to M' \otimes_R N)$. By the remarks above we see that $K_{\mathfrak m} = 0$ for each maximal ideal $\mathfrak m$ of $S$. Hence $K = 0$ by Lemma Detecting a zero module by localization. Thus (1) holds. Conversely, suppose that (1) holds. Take any $\mathfrak q \subset S$ lying over $\mathfrak p \subset R$. Take any module $N$ over $R_{\mathfrak p}$. Then by assumption $\operatorname{Ker}(M \otimes_R N \to M' \otimes_R N) = 0$. Hence by the formulae above and the fact that $N = N_{\mathfrak p}$ we see that $\operatorname{Ker}(M_{\mathfrak q} \otimes_{R_{\mathfrak p}} N \to M'_{\mathfrak q} \otimes_{R_{\mathfrak p}} N) = 0$. In other words (4) holds. Of course (4) $\Rightarrow$ (5) is immediate. Hence (1), (4) and (5) are all equivalent. We omit the proof of the other equivalences. $\square$
Lemma. Flatness and Noetherian rings
Let $R \to S$ be a ring map. Let $M$ be an $S$-module. Assume
-
$R$ is Noetherian,
-
$R$ is a domain,
-
$R \to S$ is of finite type, and
-
$M$ is a finite type $S$-module.
Then there exists a nonzero $f \in R$ such that $M_f$ is a free $R_f$-module.
Proof. Let $K$ be the fraction field of $R$. Set $S_K = K \otimes_R S$. This is an algebra of finite type over $K$. We will argue by induction on $d = \dim(S_K)$ (which is finite for example by Noether normalization, see Section Commutative algebra). Fix $d \geq 0$. Assume we know that the lemma holds in all cases where $\dim(S_K) < d$.
Suppose given $R \to S$ and $M$ as in the lemma with $\dim(S_K) = d$. By Lemma Modules and Noetherian rings (uncovered prerequisite) there exists a filtration $0 \subset M_1 \subset M_2 \subset \ldots \subset M_n = M$ so that $M_i/M_{i - 1}$ is isomorphic to $S/\mathfrak q$ for some prime $\mathfrak q$ of $S$. Note that $\dim((S/\mathfrak q)_K) \leq \dim(S_K)$. Also, note that an extension of free modules is free (see basic notion Projective and locally free modules). Thus we may assume $M = S$ and that $S$ is a domain of finite type over $R$.
If $R \to S$ has a nontrivial kernel, then take a nonzero $f \in R$ in this kernel. In this case $S_f = 0$ and the lemma holds. (This is really the case $d = -\infty$ and the start of the induction.) Hence we may assume that $R \to S$ is a finite type extension of Noetherian domains.
Apply Lemma Noether normalization over a domain (uncovered prerequisite) and replace $R$ by $R_f$ (with $f$ as in the lemma) to get a factorization $$R \subset R[y_1, \ldots, y_d] \subset S$$ where the second extension is finite. Choose $z_1, \ldots, z_r \in S$ which form a basis for the fraction field of $S$ over the fraction field of $R[y_1, \ldots, y_d]$. This gives a short exact sequence $$0 \to R[y_1, \ldots, y_d]^{\oplus r} \xrightarrow{(z_1, \ldots, z_r)} S \to N \to 0$$ By construction $N$ is a finite $R[y_1, \ldots, y_d]$-module whose support does not contain the generic point $(0)$ of $\operatorname{Spec}(R[y_1, \ldots, y_d])$. By Lemma Closed support (uncovered prerequisite) there exists a nonzero $g \in R[y_1, \ldots, y_d]$ such that $g$ annihilates $N$, so we may view $N$ as a finite module over $S' = R[y_1, \ldots, y_d]/(g)$. Since $\dim(S'_K) < d$ by induction there exists a nonzero $f \in R$ such that $N_f$ is a free $R_f$-module. Since $(R[y_1, \ldots, y_d])_f \cong R_f[y_1, \ldots, y_d]$ is free also, we conclude by the already mentioned fact that an extension of free modules is free. $\square$
[^1]: Here is the argument in more detail: Assume that we know that the second and fourth arrows are injective. Lemma Tensor products and direct sums (uncovered prerequisite) (applied to the exact sequence $K \to N_2 \to Q \to 0$) yields that the sequence $K \otimes_R M \to N_2 \otimes_R M \to Q \otimes_R M \to 0$ is exact. Hence, $\operatorname{Ker} \left(N_2 \otimes_R M \to Q \otimes_R M\right) = \operatorname{Im} \left(K \otimes_R M \to N_2 \otimes_R M\right)$. Since $\operatorname{Im} \left(K \otimes_R M \to N_2 \otimes_R M\right) = \operatorname{Im} \left(N_1 \otimes_R M \to N_2 \otimes_R M\right)$ (due to the surjectivity of $N_1 \otimes_R M \to K \otimes_R M$) and $\operatorname{Ker} \left(N_2 \otimes_R M \to Q \otimes_R M\right) = \operatorname{Ker} \left(N_2 \otimes_R M \to N_3 \otimes_R M\right)$ (due to the injectivity of $Q \otimes_R M \to N_3 \otimes_R M$), this becomes $\operatorname{Ker} \left(N_2 \otimes_R M \to N_3 \otimes_R M\right) = \operatorname{Im} \left(N_1 \otimes_R M \to N_2 \otimes_R M\right)$, which shows that the functor $- \otimes_R M$ is exact, whence $M$ is flat.
[^2]: This becomes obvious if we identify $L' \otimes_R M$ and $L \otimes_R M$ with submodules of $M^{\oplus n}$ (which is legitimate since the maps $L \otimes_R M \to M^{\oplus n}$ and $L' \otimes_R M \to M^{\oplus n}$ are injective and commute with the obvious map $L' \otimes_R M \to L \otimes_R M$).
[^3]: Later we will say that $R$ is Noetherian.
Infinitesimal lifting and complete rings
Lemma. Henselian rings and nilpotent thickenings
Let $(A, I)$ be a pair with $I$ locally nilpotent. Then the functor $B \mapsto B/IB$ induces an equivalence between the category of étale algebras over $A$ and the category of étale algebras over $A/I$. Moreover, the pair is henselian.
Proof. Essential surjectivity holds by Algebra, Lemma Lifting étale morphisms. If $B$, $B'$ are étale over $A$ and $B/IB \to B'/IB'$ is a morphism of $A/I$-algebras, then we can lift this by Algebra, Lemma Smooth morphisms. Finally, suppose that $f, g : B \to B'$ are two $A$-algebra maps with $f \bmod I = g \bmod I$. Choose an idempotent $e \in B \otimes_A B$ generating the kernel of the multiplication map $B \otimes_A B \to B$, see Algebra, Lemmas Unramified morphisms and diagonals and separation and Unramified morphisms (to see that étale is unramified). Then $(f \otimes g)(e) \in IB'$. Since $IB'$ is locally nilpotent (Algebra, Lemma Nilpotent thickenings and local algebra) this implies $(f \otimes g)(e) = 0$ by Algebra, Lemma Lifting idempotents through a nilpotent ideal. Thus $f = g$.
It is clear that $I$ is contained in the Jacobson radical of $A$. Let $f \in A[T]$ be a monic polynomial and let $\overline{f} = g_0h_0$ be a factorization of $\overline{f} = f \bmod I$ with $g_0, h_0 \in A/I[T]$ monic generating the unit ideal in $A/I[T]$. By Lemma Lifting a monic polynomial factorization there exists an étale ring map $A \to A'$ which induces an isomorphism $A/I \to A'/IA'$ such that the factorization lifts to a factorization into monic polynomials over $A'$. By the above we have $A = A'$ and the factorization is over $A$. $\square$
Lemma. Lifting projective, locally free modules and finite algebras
Let $(R, I)$ be a henselian pair. The map $$P \longrightarrow P/IP$$ induces a bijection between the sets of isomorphism classes of finite projective $R$-modules and finite projective $R/I$-modules. In particular, any finite projective $R/I$-module is isomorphic to $P/IP$ for some finite projective $R$-module $P$.
Proof. We first prove the final statement. Let $\overline{P}$ be a finite projective $R/I$-module. We can find a finite projective module $P'$ over some $R'$ étale over $R$ with $R/I = R'/IR'$ such that $P'/IP'$ is isomorphic to $\overline{P}$, see Lemma Lifting a finite projective module. Then, since $(R, I)$ is a henselian pair, the étale ring map $R \to R'$ has a section $\tau : R' \to R$ (Lemma Criteria for henselian rings). Setting $P = P' \otimes_{R', \tau} R$ we conclude that $P/IP$ is isomorphic to $\overline{P}$. Of course, this tells us that the map in the statement of the lemma is surjective.
Injectivity. Suppose that $P_1$ and $P_2$ are finite projective $R$-modules such that $P_1/IP_1 \cong P_2/IP_2$ as $R/I$-modules. Since $P_1$ is projective, we can find an $R$-module map $u : P_1 \to P_2$ lifting the given isomorphism. Then $u$ is surjective by Nakayama's lemma (Algebra, Lemma Nakayama's lemma). We similarly find a surjection $v : P_2 \to P_1$. By Algebra, Lemma Surjective endomorphisms of finite modules the map $v \circ u$ is an isomorphism and we conclude $u$ is an isomorphism. $\square$
Lemma. Lifting projective and locally free modules
Let $R$ be a ring. Let $I \subset R$ be an ideal. Assume that every element of $1 + I$ is a unit (in other words $I$ is contained in the Jacobson radical of $R$). Let $M$ be a finite flat $R$-module such that $M/IM$ is a projective $R/I$-module. Then $M$ is a finite projective $R$-module.
Proof. By Algebra, Lemma Finite flat modules over a local ring we see that $M_\mathfrak p$ is finite free for all prime ideals $\mathfrak p \subset R$. By Algebra, Lemma Characterizations of finite projective modules it suffices to show that the function $\rho_M : \mathfrak p \mapsto \dim_{\kappa(\mathfrak p)} M \otimes_R \kappa(\mathfrak p)$ is locally constant on $\operatorname{Spec}(R)$. Because $M/IM$ is finite projective, this is true on $V(I) \subset \operatorname{Spec}(R)$. Since every closed point of $\operatorname{Spec}(R)$ is in $V(I)$ and since $\rho_M(\mathfrak p) = \rho_M(\mathfrak q)$ whenever $\mathfrak p \subset \mathfrak q \subset R$ are prime ideals, we conclude by an elementary argument on topological spaces which we omit. $\square$
Lemma. Projective, locally free modules and finite algebras
Let $R$ be a ring. Let $I \subset R$ be an ideal. Assume that every element of $1 + I$ is a unit (in other words $I$ is contained in the Jacobson radical of $R$). If $P$ and $P'$ are finite projective $R$-modules, then
-
if $\varphi : P \to P'$ is an $R$-module map inducing an isomorphism $\overline{\varphi} : P/IP \to P'/IP'$, then $\varphi$ is an isomorphism,
-
if $P/IP \cong P'/IP'$, then $P \cong P'$.
Proof. Proof of (1). As $P'$ is projective as an $R$-module we may choose a lift $\psi : P' \to P$ of the map $P' \to P'/IP' \xrightarrow{\overline{\varphi}^{-1}} P/IP$. By Nakayama's lemma (Algebra, Lemma Nakayama's lemma) $\psi \circ \varphi$ and $\varphi \circ \psi$ are surjective. Hence these maps are isomorphisms (Algebra, Lemma Surjective endomorphisms of finite modules). Thus $\varphi$ is an isomorphism.
Proof of (2). Choose an isomorphism $P/IP \cong P'/IP'$. Since $P$ is projective we can choose a lift $\varphi : P \to P'$ of the map $P \to P/IP \to P'/IP'$. Then $\varphi$ is an isomorphism by (1). $\square$
Lemma. Pullback of pseudo-coherent complexes and coherent sheaves
Let $A \to B$ be a ring map. Let $K^\bullet$ be an $m$-pseudo-coherent (resp. pseudo-coherent) complex of $A$-modules. Then $K^\bullet \otimes_A^{\mathbf{L}} B$ is an $m$-pseudo-coherent (resp. pseudo-coherent) complex of $B$-modules.
Proof. First we note that the statement of the lemma makes sense as $K^\bullet$ is bounded above and hence $K^\bullet \otimes_A^{\mathbf{L}} B$ is defined by Equation (Derived categories and tensor products and direct sums). Having said this, choose a bounded complex $E^\bullet$ of finite free $A$-modules and $\alpha : E^\bullet \to K^\bullet$ with $H^i(\alpha)$ an isomorphism for $i > m$ and surjective for $i = m$. Then the cone $C(\alpha)^\bullet$ is acyclic in degrees $\geq m$. Since $-\otimes_A^{\mathbf{L}} B$ is an exact functor we get a distinguished triangle $$(E^\bullet \otimes_A^{\mathbf{L}} B, K^\bullet \otimes_A^{\mathbf{L}} B, C(\alpha)^\bullet \otimes_A^{\mathbf{L}} B)$$ of complexes of $B$-modules. By the dual to Derived Categories, Lemma Vanishing in negative degrees we see that $H^i(C(\alpha)^\bullet \otimes_A^{\mathbf{L}} B) = 0$ for $i \geq m$. Since $E^\bullet$ is a complex of projective $A$-modules we see that $E^\bullet \otimes_A^{\mathbf{L}} B = E^\bullet \otimes_A B$ and hence $$E^\bullet \otimes_A B \longrightarrow K^\bullet \otimes_A^{\mathbf{L}} B$$ is a morphism of complexes of $B$-modules that witnesses the fact that $K^\bullet \otimes_A^{\mathbf{L}} B$ is $m$-pseudo-coherent. The case of pseudo-coherent complexes follows from the case of $m$-pseudo-coherent complexes via Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $K^\bullet$ be a complex of $R$-modules. The following are equivalent
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$K^\bullet$ is pseudo-coherent,
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$K^\bullet$ is $m$-pseudo-coherent for every $m \in \mathbf{Z}$, and
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$K^\bullet$ is quasi-isomorphic to a bounded above complex of finite projective $R$-modules.
If (1), (2), and (3) hold and $H^i(K^\bullet) = 0$ for $i > b$, then we can find a quasi-isomorphism $F^\bullet \to K^\bullet$ with $F^i$ finite free $R$-modules and $F^i = 0$ for $i > b$.
Proof. We see that (1) $\Rightarrow$ (3) as a finite free module is a finite projective $R$-module. Conversely, suppose $P^\bullet$ is a bounded above complex of finite projective $R$-modules. Say $P^i = 0$ for $i > n_0$. We choose a direct sum decompositions $F^{n_0} = P^{n_0} \oplus C^{n_0}$ with $F^{n_0}$ a finite free $R$-module, and inductively $$F^{n - 1} = P^{n - 1} \oplus C^n \oplus C^{n - 1}$$ for $n \leq n_0$ with $F^{n - 1}$ a finite free $R$-module. As a complex $F^\bullet$ has maps $F^{n - 1} \to F^n$ which agree with $P^{n - 1} \to P^n$, induce the identity $C^n \to C^n$, and are zero on $C^{n - 1}$. The map $F^\bullet \to P^\bullet$ is a quasi-isomorphism (even a homotopy equivalence) and hence (3) implies (1).
Assume (1). Let $E^\bullet$ be a bounded above complex of finite free $R$-modules and let $E^\bullet \to K^\bullet$ be a quasi-isomorphism. Then the induced maps $\sigma_{\geq m}E^\bullet \to K^\bullet$ from the stupid truncation of $E^\bullet$ to $K^\bullet$ show that $K^\bullet$ is $m$-pseudo-coherent. Hence (1) implies (2).
Assume (2). Since $K^\bullet$ is $0$-pseudo-coherent we see in particular that $K^\bullet$ is bounded above. Let $b$ be an integer such that $H^i(K^\bullet) = 0$ for $i > b$. By descending induction on $n \in \mathbf{Z}$ we are going to construct finite free $R$-modules $F^i$ for $i \geq n$, differentials $d^i : F^i \to F^{i + 1}$ for $i \geq n$, maps $\alpha : F^i \to K^i$ compatible with differentials, such that (1) $H^i(\alpha)$ is an isomorphism for $i > n$ and surjective for $i = n$, and (2) $F^i = 0$ for $i > b$. Picture $$\begin{gathered}\begin{matrix}\phantom{X} & F^n & F^{n + 1} & \ldots \\ K^{n - 1} & K^n & K^{n + 1} & \ldots\end{matrix} \\[6pt] \begin{aligned}F^n & \longrightarrow F^{n + 1} \\ F^n & \xrightarrow{\alpha} K^n \\ F^{n + 1} & \xrightarrow{\alpha} K^{n + 1} \\ F^{n + 1} & \longrightarrow \ldots \\ K^{n - 1} & \longrightarrow K^n \\ K^n & \longrightarrow K^{n + 1} \\ K^{n + 1} & \longrightarrow \ldots\end{aligned}\end{gathered}$$ The base case is $n = b + 1$ where we can take $F^i = 0$ for all $i$. Induction step. Let $C^\bullet$ be the cone on $\alpha$ (Derived Categories, Definition The cone of a complex morphism). The long exact sequence of cohomology $$0 \to H^{n - 1}(K^\bullet) \to H^{n - 1}(C^\bullet) \to H^n(F^\bullet) \to H^n(K^\bullet) \to H^n(C^\bullet) \to \ldots$$ shows that $H^i(C^\bullet) = 0$ for $i \geq n$. By Lemma Pseudo-coherent complexes and coherent sheaves we see that $C^\bullet$ is $(n - 1)$-pseudo-coherent. By Lemma Finiteness of cohomology groups we see that $H^{n - 1}(C^\bullet)$ is a finite $R$-module. In particular, we see that the kernel of $H^n(F^\bullet) \to H^n(K^\bullet)$ is a finite $R$-module. Choose a finite free $R$-module $F^{n - 1}$ and a map $F^{n - 1} \to \operatorname{Ker}(F^n \to F^{n + 1})$ such that $F^{n - 1}$ surjects onto the kernel of $H^n(F^\bullet) \to H^n(K^\bullet)$. We extend our map of complexes to $$\begin{gathered}\begin{matrix}\phantom{X} & F^{n - 1} & F^n & F^{n + 1} & \ldots \\ \ldots & K^{n - 1} & K^n & K^{n + 1} & \ldots\end{matrix} \\[6pt] \begin{aligned}F^{n - 1} & \xrightarrow{\alpha^{n - 1}} K^{n - 1} \\ F^{n - 1} & \longrightarrow F^n \\ F^n & \longrightarrow F^{n + 1} \\ F^n & \xrightarrow{\alpha} K^n \\ F^{n + 1} & \xrightarrow{\alpha} K^{n + 1} \\ F^{n + 1} & \longrightarrow \ldots \\ \ldots & \longrightarrow K^{n - 1} \\ K^{n - 1} & \longrightarrow K^n \\ K^n & \longrightarrow K^{n + 1} \\ K^{n + 1} & \longrightarrow \ldots\end{aligned}\end{gathered}$$ Note that $\alpha^{n - 1}$ exists because the image of $F^{n - 1} \to F^n \to K^n$ is in the image of $K^{n - 1} \to K^n$ by construction. Denote again $C^\bullet$ the cone of this extended map of complexes. At this point we see that we get an exact sequence $$H^{n - 1}(F^\bullet) \to H^{n - 1}(K^\bullet) \to H^{n - 1}(C^\bullet) \to H^n(F^\bullet) \cong H^n(K^\bullet) \to H^n(C^\bullet) \to \ldots$$ In other words, we see that the cokernel of $H^{n - 1}(F^\bullet) \to H^{n - 1}(K^\bullet)$ is a finite $R$-module, say generated by the classes of $\xi_1, \ldots, \xi_r \in \operatorname{Ker}(K^{n - 1} \to K^n)$. Then we replace $F^{n - 1}$ by $F^{n - 1} \oplus R^{\oplus r}$ where the basis elements in the free summand map to zero in $F^n$ and to $\xi_i$ in $K^{n - 1}$. This finishes the proof of the induction step. $\square$
Lemma. Lifting projective, locally free modules and derived categories
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $E^\bullet$ be a complex of $R/I$-modules. Let $K$ be an object of $D(R)$. Assume that
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$E^\bullet$ is a bounded above complex of projective $R/I$-modules,
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$K \otimes_R^\mathbf{L} R/I$ is represented by $E^\bullet$ in $D(R/I)$, and
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$I$ is a nilpotent ideal.
Then there exists a bounded above complex $P^\bullet$ of projective $R$-modules representing $K$ in $D(R)$ such that $P^\bullet \otimes_R R/I$ is isomorphic to $E^\bullet$.
Proof. We apply Lemma Lifting derived categories using the class $\mathcal{P}$ of all projective $R$-modules. Properties (1) and (2) of the lemma are immediate. Property (3) follows from Nakayama's lemma (Algebra, Lemma Nakayama's lemma). Property (4) follows from the fact that we can lift projective $R/I$-modules to projective $R$-modules, see Algebra, Lemma Lifting a finite projective module. To see that (5) holds it suffices to show that $K$ is in $D^{-}(R)$. Since we are given that $K \otimes_R^\mathbf{L} R/I$ is in $D^{-}(R/I)$ because $E^\bullet$ is bounded above, this follows from Lemma Derived tensor products, Tor amplitude and dimension and codimension. $\square$
Lemma. Lifting derived categories
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $\mathcal{P}$ be a class of $R$-modules. Let $K \in D(R)$ and let $E^\bullet$ be a complex of $R/I$-modules representing $K \otimes_R^\mathbf{L} R/I$. Assume
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each $P \in \mathcal{P}$ is a projective $R$-module,
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$P_1 \in \mathcal{P}$ and $P_1 \oplus P_2 \in \mathcal{P}$ if and only if $P_1, P_2 \in \mathcal{P}$,
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if $f : P_1 \to P_2$, $P_1, P_2 \in \mathcal{P}$ is surjective modulo $I$, then $f$ is surjective,
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$E^\bullet$ is bounded above and $E^i$ is of the form $P/IP$ for $P \in \mathcal{P}$, and
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$K$ can be represented by a bounded above complex whose terms are in $\mathcal{P}$.
Then there exists a bounded above complex $P^\bullet$ whose terms are in $\mathcal{P}$ with $P^\bullet/IP^\bullet$ isomorphic to $E^\bullet$ and representing $K$ in $D(R)$.
Proof. By assumption (5) we can represent $K$ by a bounded above complex $K^\bullet$ whose terms are in $\mathcal{P}$. Then $K \otimes_R^\mathbf{L} R/I$ is represented by $K^\bullet/IK^\bullet$. Since $E^\bullet$ is a bounded above complex of projective $R/I$-modules by (4), we can choose a quasi-isomorphism $\delta : E^\bullet \to K^\bullet/IK^\bullet$ (Derived Categories, Lemma Derived Hom, Ext and projective and locally free modules). Let $C^\bullet$ be cone on $\delta$ (Derived Categories, Definition The cone of a complex morphism). The module $C^i$ is the direct sum $K^i/IK^i \oplus E^{i + 1}$ hence is of the form $P/IP$ for some $P \in \mathcal{P}$ as (2) says in particular that $\mathcal{P}$ is preserved under taking sums. Since $C^\bullet$ is acyclic, we can apply Lemma Lifting derived categories and find a acyclic lift $A^\bullet$ of $C^\bullet$. The complex $A^\bullet$ is bounded above and has terms in $\mathcal{P}$. In $$\begin{gathered}\begin{matrix}K^\bullet & A^\bullet \\ K^\bullet/IK^\bullet & C^\bullet & E^\bullet[1]\end{matrix} \\[6pt] \begin{aligned}K^\bullet & \cdots\!\!\rightarrow A^\bullet \\ K^\bullet & \longrightarrow K^\bullet/IK^\bullet \\ A^\bullet & \longrightarrow C^\bullet \\ K^\bullet/IK^\bullet & \longrightarrow C^\bullet \\ C^\bullet & \longrightarrow E^\bullet[1]\end{aligned}\end{gathered}$$ we can find the dotted arrow making the diagram commute by Derived Categories, Lemma Projective and locally free modules. We will show below that it follows from (1), (2), (3) that $K^i \to A^i$ is the inclusion of a direct summand for every $i$. By property (2) we see that $P^i = \operatorname{Coker}(K^i \to A^i)$ is in $\mathcal{P}$. Thus we can take $P^\bullet = \operatorname{Coker}(K^\bullet \to A^\bullet)[-1]$ to conclude.
To finish the proof we have to show the following: Let $f : P_1 \to P_2$, $P_1, P_2 \in \mathcal{P}$ and $P_1/IP_1 \to P_2/IP_2$ is split injective with cokernel of the form $P_3/IP_3$ for some $P_3 \in \mathcal{P}$, then $f$ is split injective. Write $E_i = P_i/IP_i$. Then $E_2 = E_1 \oplus E_3$. Since $P_2$ is projective we can choose a map $g : P_2 \to P_3$ lifting the map $E_2 \to E_3$. By condition (3) the map $g$ is surjective, hence split as $P_3$ is projective. Set $P_1' = \operatorname{Ker}(g)$ and choose a splitting $P_2 = P'_1 \oplus P_3$. Then $P'_1 \in \mathcal{P}$ by (2). We do not know that $g \circ f = 0$, but we can consider the map $$P_1 \xrightarrow{f} P_2 \xrightarrow{projection} P'_1$$ The composition modulo $I$ is an isomorphism. Since $P'_1$ is projective we can split $P_1 = T \oplus P'_1$. If $T = 0$, then we are done, because then $P_2 \to P'_1$ is a splitting of $f$. We see that $T \in \mathcal{P}$ by (2). Calculating modulo $I$ we see that $T/IT = 0$. Since $0 \in \mathcal{P}$ (as the summand of any $P$ in $\mathcal{P}$) we see the map $0 \to T$ is surjective and we conclude that $T = 0$ as desired. $\square$
Lemma. Projective and locally free modules
Let $R$ be a ring. Let $0 \to P' \to P \to P'' \to 0$ be a short exact sequence of finite projective $R$-modules. If $2$ out of $3$ of these modules are stably free, then so is the third.
Proof. Since the modules are projective, the sequence is split. Thus we can choose an isomorphism $P = P' \oplus P''$. If $P' \oplus R^{\oplus n}$ and $P'' \oplus R^{\oplus m}$ are free, then we see that $P \oplus R^{\oplus n + m}$ is free. Suppose that $P'$ and $P$ are stably free, say $P \oplus R^{\oplus n}$ is free and $P' \oplus R^{\oplus m}$ is free. Then $$P'' \oplus (P' \oplus R^{\oplus m}) \oplus R^{\oplus n} = (P'' \oplus P') \oplus R^{\oplus m} \oplus R^{\oplus n} = (P \oplus R^{\oplus n}) \oplus R^{\oplus m}$$ is free. Thus $P''$ is stably free. By symmetry we get the last of the three cases. $\square$
Lemma. Lifting projective and locally free modules
Let $R$ be a ring. Let $I \subset R$ be an ideal. Assume that every element of $1 + I$ is a unit (in other words $I$ is contained in the Jacobson radical of $R$). For every finite stably free $R/I$-module $E$ there exists a finite stably free $R$-module $M$ such that $M/IM \cong E$.
Proof. Choose a $n$ and $m$ and an isomorphism $E \oplus (R/I)^{\oplus n} \cong (R/I)^{\oplus m}$. Choose $R$-linear maps $\varphi : R^{\oplus m} \to R^{\oplus n}$ and $\psi : R^{\oplus n} \to R^{\oplus m}$ lifting the projection $(R/I)^{\oplus m} \to (R/I)^{\oplus n}$ and injection $(R/I)^{\oplus n} \to (R/I)^{\oplus m}$. Then $\varphi \circ \psi : R^{\oplus n} \to R^{\oplus n}$ reduces to the identity modulo $I$. Thus the determinant of this map is invertible by our assumption on $I$. Hence $P = \operatorname{Ker}(\varphi)$ is stably free and lifts $E$. $\square$
Definition. Pseudo-coherent complexes
Let $R$ be a ring. Denote $D(R)$ its derived category. Let $m \in \mathbf{Z}$.
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An object $K^\bullet$ of $D(R)$ is $m$-pseudo-coherent if there exists a bounded complex $E^\bullet$ of finite free $R$-modules and a morphism $\alpha : E^\bullet \to K^\bullet$ such that $H^i(\alpha)$ is an isomorphism for $i > m$ and $H^m(\alpha)$ is surjective.
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An object $K^\bullet$ of $D(R)$ is pseudo-coherent if it is quasi-isomorphic to a bounded above complex of finite free $R$-modules.
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An $R$-module $M$ is called $m$-pseudo-coherent if $M[0]$ is an $m$-pseudo-coherent object of $D(R)$.
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An $R$-module $M$ is called pseudo-coherent[^1] if $M[0]$ is a pseudo-coherent object of $D(R)$.
Lemma. Modules
In the situation above. The functor $\varprojlim : \textit{Mod}(\mathbf{N}, (A_n)) \to \text{Mod}_A$ has a right derived functor $$R\varprojlim : D(\textit{Mod}(\mathbf{N}, (A_n))) \longrightarrow D(A)$$ As usual we set $R^p\varprojlim(K) = H^p(R\varprojlim(K))$. Moreover, we have
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for any $(M_n)$ in $\textit{Mod}(\mathbf{N}, (A_n))$ we have $R^p\varprojlim M_n = 0$ for $p > 1$,
-
the object $R\varprojlim M_n$ of $D(\text{Mod}_A)$ is represented by the complex $$\prod M_n \to \prod M_n,\quad (x_n) \mapsto (x_n - f_{n + 1}(x_{n + 1}))$$ sitting in degrees $0$ and $1$,
-
if $(M_n)$ is ML, then $R^1\varprojlim M_n = 0$, i.e., $(M_n)$ is right acyclic for $\varprojlim$,
-
every $K^\bullet \in D(\textit{Mod}(\mathbf{N}, (A_n)))$ is quasi-isomorphic to a complex whose terms are right acyclic for $\varprojlim$, and
-
if each $K^p = (K^p_n)$ is right acyclic for $\varprojlim$, i.e., of $R^1\varprojlim_n K^p_n = 0$, then $R\varprojlim K$ is represented by the complex whose term in degree $p$ is $\varprojlim_n K_n^p$.
Proof. The proof of this is word for word the same as the proof of Lemma Computation of a derived inverse limit. $\square$
Remark. Uniqueness in the lifting construction
With assumptions as in Lemma Lifting derived categories. A priori there are many isomorphism classes of objects $M$ of $D(\textit{Mod}(\mathbf{N}, (A_n)))$ which give rise to the system $(K_n, \varphi_n)$ of the lemma. For each such $M$ we can consider the complex $R\varprojlim M \in D(A)$ where $A = \varprojlim A_n$. By Lemma Modules and derived categories we see that $R\varprojlim M$ is a derived limit of the inverse system $(K_n)$ of $D(A)$. Hence we see that the isomorphism class of $R\varprojlim M$ in $D(A)$ is independent of the choices made in constructing $M$. In particular, we may apply results on $R\varprojlim$ proved in this section to derived limits of inverse systems in $D(A)$. For example, for every $p \in \mathbf{Z}$ there is a canonical short exact sequence $$0 \to R^1\varprojlim H^{p - 1}(K_n) \to H^p(R\varprojlim K_n) \to \varprojlim H^p(K_n) \to 0$$ because we may apply Lemma Modules and derived categories to $M$. This can also been seen directly, without invoking the existence of $M$, by applying the argument of the proof of Lemma Modules and derived categories to the (defining) distinguished triangle $R\varprojlim K_n \to \prod K_n \to \prod K_n \to (R\varprojlim K_n)[1]$ of the derived limit.
Lemma. Perfect complexes
Let $K^\bullet$ be an object of $D(R)$. The following are equivalent
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$K^\bullet$ is perfect, and
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$K^\bullet$ is pseudo-coherent and has finite tor dimension.
If (1) and (2) hold and $K^\bullet$ has tor-amplitude in $[a, b]$, then $K^\bullet$ is quasi-isomorphic to a complex $E^\bullet$ of finite projective $R$-modules with $E^i = 0$ for $i \not \in [a, b]$.
Proof. It is clear that (1) implies (2), see Lemmas Pseudo-coherent complexes and coherent sheaves and Derived tensor products and Tor amplitude. Assume (2) holds and that $K^\bullet$ has tor-amplitude in $[a, b]$. In particular, $H^i(K^\bullet) = 0$ for $i > b$. Choose a complex $F^\bullet$ of finite free $R$-modules with $F^i = 0$ for $i > b$ and a quasi-isomorphism $F^\bullet \to K^\bullet$ (Lemma Pseudo-coherent complexes and coherent sheaves). Set $E^\bullet = \tau_{\geq a}F^\bullet$. Note that $E^i$ is finite free except $E^a$ which is a finitely presented $R$-module. By Lemma Flatness $E^a$ is flat. Hence by Algebra, Lemma Characterizations of finite projective modules we see that $E^a$ is finite projective. $\square$
Lemma. Perfect complexes
Let $R$ be a ring. Let $a, b \in \mathbf{Z}$. Let $K^\bullet$ be a pseudo-coherent complex of $R$-modules. The following are equivalent
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$K^\bullet$ is perfect with tor amplitude in $[a, b]$,
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for every prime $\mathfrak p$ we have $H^i(K^\bullet \otimes_R^{\mathbf{L}} \kappa(\mathfrak p)) = 0$ for all $i \not \in [a, b]$, and
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for every maximal ideal $\mathfrak m$ we have $H^i(K^\bullet \otimes_R^{\mathbf{L}} \kappa(\mathfrak m)) = 0$ for all $i \not \in [a, b]$.
Proof. We omit the proof of the implications (1) $\Rightarrow$ (2) $\Rightarrow$ (3). Assume (3). Let $i \in \mathbf{Z}$ with $i \not \in [a, b]$. By Lemma Derived categories we see that the assumption implies that $H^i(K^\bullet)_{\mathfrak m} = 0$ for all maximal ideals of $R$. Hence $H^i(K^\bullet) = 0$, see Algebra, Lemma Detecting a zero module by localization. Moreover, Lemma Derived categories now also implies that for every maximal ideal $\mathfrak m$ there exists an element $f \in R$, $f \not \in \mathfrak m$ such that $K^\bullet \otimes_R R_f$ is perfect with tor amplitude in $[a, b]$. Hence we conclude by appealing to Lemmas Perfect complexes and Derived tensor products and Tor amplitude. $\square$
Lemma. Modules and tensor products and direct sums
In Situation Modules and tensor products and direct sums the functor (the displayed identity) has a right adjoint, namely the functor $$F : (N, M', \varphi) \longmapsto N \times_{\varphi, M} M'$$ where $M = M'/IM'$. Moreover, the composition of $F$ with (the displayed identity) is the identity functor on $\text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'}$. In other words, setting $N' = N \times_{\varphi, M} M'$ we have $N' \otimes_{D'} D = N$ and $N' \otimes_{D'} C' = M'$.
Proof. The adjointness statement follows from the more general Lemma Module compatibility in a ring diagram. The final assertion follows from the corresponding assertion of Lemma Modules and tensor products and direct sums because $N' \otimes_{D'} D = N' \otimes_{D'} D' \otimes_{B'} B = N' \otimes_{B'} B$ and $N' \otimes_{D'} C' = N' \otimes_{D'} D' \otimes_{B'} A' = N' \otimes_{B'} A'$. $\square$
Lemma. Modules and tensor products and direct sums
In the situation of Lemma Modules and tensor products and direct sums for a $B'$-module $L'$ the adjunction map $$L' \longrightarrow (L' \otimes_{B'} B) \times_{(L' \otimes_{B'} A)} (L' \otimes_{B'} A')$$ is surjective but in general not injective.
Proof. As in the proof of Lemma Modules and tensor products and direct sums let $J \subset B'$ be the kernel of the map $B' \to B$. Then $L' \otimes_{B'} B = L'/JL'$. Hence to prove surjectivity it suffices to show that elements of the form $(0, z)$ of the fibre product are in the image of the map of the lemma. The kernel of the map $L' \otimes_{B'} A' \to L' \otimes_{B'} A$ is the image of $L' \otimes_{B'} I \to L' \otimes_{B'} A'$. Since the map $J \to I$ induced by $B' \to A'$ is an isomorphism the composition $$L' \otimes_{B'} J \to L' \to (L' \otimes_{B'} B) \times_{(L' \otimes_{B'} A)} (L' \otimes_{B'} A')$$ induces a surjection of $L' \otimes_{B'} J$ onto the set of elements of the form $(0, z)$. To see the map is not injective in general we present a simple example. Namely, take a field $k$, set $B' = k[x, y]/(xy)$, $A' = B'/(x)$, $B = B'/(y)$, $A = B'/(x, y)$ and $L' = B'/(x - y)$. In that case the class of $x$ in $L'$ is nonzero but is mapped to zero under the displayed arrow. $\square$
Lemma. Modules and tensor products and direct sums
Let $A, A', B, B', I, M, M', N, \varphi$ be as in Lemma Modules and tensor products and direct sums. If $N$ finite over $B$ and $M'$ finite over $A'$, then $N' = N \times_{\varphi, M} M'$ is finite over $B'$.
Proof. We will use the results of Lemma Modules and tensor products and direct sums without further mention. Choose generators $y_1, \ldots, y_r$ of $N$ over $B$ and generators $x_1, \ldots, x_s$ of $M'$ over $A'$. Using that $N = N' \otimes_{B'} B$ and $B' \to B$ is surjective we can find $u_1, \ldots, u_r \in N'$ mapping to $y_1, \ldots, y_r$ in $N$. Using that $M' = N' \otimes_{B'} A'$ we can find $v_1, \ldots, v_t \in N'$ such that $x_i = \sum v_j \otimes a'_{ij}$ for some $a'_{ij} \in A'$. In particular we see that the images $\overline{v}_j \in M'$ of the $v_j$ generate $M'$ over $A'$. We claim that $u_1, \ldots, u_r, v_1, \ldots, v_t$ generate $N'$ as a $B'$-module. Namely, pick $\xi \in N'$. We first choose $b'_1, \ldots, b'_r \in B'$ such that $\xi$ and $\sum b'_i u_i$ map to the same element of $N$. This is possible because $B' \to B$ is surjective and $y_1, \ldots, y_r$ generate $N$ over $B$. The difference $\xi - \sum b'_i u_i$ is of the form $(0, \theta)$ for some $\theta$ in $IM'$. Say $\theta$ is $\sum t_j\overline{v}_j$ with $t_j \in I$. As $J = \operatorname{Ker}(B' \to B)$ maps isomorphically to $I$ we can choose $s_j \in J \subset B'$ mapping to $t_j$. Because $N' = N \times_{\varphi, M} M'$ it follows that $\xi = \sum b'_i u_i + \sum s_j v_j$ as desired. $\square$
Situation. Modules and tensor products and direct sums
Let $A, A', B, B', I$ be as in Situation Modules and tensor products and direct sums. Let $B' \to D'$ be a ring map. Set $D = D' \otimes_{B'} B$, $C' = D' \otimes_{B'} A'$, and $C = D' \otimes_{B'} A$. This leads to a big commutative diagram $$\begin{gathered}\begin{matrix}C & \phantom{X} & \phantom{X} & C' \\ \phantom{X} & A & A' \\ \phantom{X} & B & B' \\ D & \phantom{X} & \phantom{X} & D'\end{matrix} \\[6pt] \begin{aligned}C' & \longrightarrow C \\ A & \longrightarrow C \\ A' & \longrightarrow A \\ A' & \longrightarrow C' \\ B & \longrightarrow A \\ B & \longrightarrow D \\ B' & \longrightarrow B \\ B' & \longrightarrow A' \\ B' & \longrightarrow D' \\ D & \longrightarrow C \\ D' & \longrightarrow D \\ D' & \longrightarrow C'\end{aligned}\end{gathered}$$ of rings. Observe that we do not assume that the map $D' \to D \times_C C'$ is an isomorphism[^2]. In this situation we have the functor
$$\text{Mod}_{D'} \longrightarrow \text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'},\quad L' \longmapsto (L' \otimes_{D'} D, L' \otimes_{D'} C', can)$$ analogous to (Derived tensor products and Tor amplitude). Note that $L' \otimes_{D'} D = L \otimes_{D'} (D' \otimes_{B'} B) = L \otimes_{B'} B$ and similarly $L' \otimes_{D'} C' = L \otimes_{D'} (D' \otimes_{B'} A') = L \otimes_{B'} A'$ hence the diagram $$\begin{gathered}\begin{matrix}\text{Mod}_{D'} & \text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'} \\ \text{Mod}_{B'} & \text{Mod}_B \times_{\text{Mod}_A} \text{Mod}_{A'}\end{matrix} \\[6pt] \begin{aligned}\text{Mod}_{D'} & \longrightarrow \text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'} \\ \text{Mod}_{D'} & \longrightarrow \text{Mod}_{B'} \\ \text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'} & \longrightarrow \text{Mod}_B \times_{\text{Mod}_A} \text{Mod}_{A'} \\ \text{Mod}_{B'} & \longrightarrow \text{Mod}_B \times_{\text{Mod}_A} \text{Mod}_{A'}\end{aligned}\end{gathered}$$ is commutative. In the following we will write $(N, M', \varphi)$ for an object of $\text{Mod}_D \times_{\text{Mod}_C} \text{Mod}_{C'}$, i.e., $N$ is a $D$-module, $M'$ is an $C'$-module and $\varphi : N \otimes_B A \to M' \otimes_{A'} A$ is an isomorphism of $C$-modules. However, it is often more convenient think of $\varphi$ as a $D$-linear map $\varphi : N \to M'/IM'$ which induces an isomorphism $N \otimes_B A \to M' \otimes_{A'} A = M'/IM'$.
Lemma. Flatness and modules
With $A, A', B, B', I$ as in Situation Modules and tensor products and direct sums.
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Let $(N, M', \varphi)$ be an object of $\text{Mod}_B \times_{\text{Mod}_A} \text{Mod}_{A'}$. If $M'$ is flat over $A'$ and $N$ is flat over $B$, then $N' = N \times_{\varphi, M} M'$ is flat over $B'$.
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If $L'$ is a flat $B'$-module, then $L' = (L \otimes_{B'} B) \times_{(L \otimes_{B'} A)} (L \otimes_{B'} A')$.
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The category of flat $B'$-modules is equivalent to the full subcategory of $\text{Mod}_B \times_{\text{Mod}_A} \text{Mod}_{A'}$ consisting of triples $(N, M', \varphi)$ with $N$ flat over $B$ and $M'$ flat over $A'$.
Proof. In the proof we will use Lemma Modules and tensor products and direct sums without further mention.
Proof of (1). Set $J = \operatorname{Ker}(B' \to B)$. This is an ideal of $B'$ mapping isomorphically to $I = \operatorname{Ker}(A' \to A)$. Let $\mathfrak b' \subset B'$ be an ideal. We have to show that $\mathfrak b' \otimes_{B'} N' \to N'$ is injective, see Algebra, Lemma Flatness. We know that $$\mathfrak b'/(\mathfrak b' \cap J) \otimes_{B'} N' = \mathfrak b'/(\mathfrak b' \cap J) \otimes_B N \to N$$ is injective as $N$ is flat over $B$. As $\mathfrak b' \cap J \to \mathfrak b' \to \mathfrak b'/(\mathfrak b' \cap J) \to 0$ is exact, we conclude that it suffices to show that $(\mathfrak b' \cap J) \otimes_{B'} N' \to N'$ is injective. Thus we may assume that $\mathfrak b' \subset J$. Next, since $J \to I$ is an isomorphism we have $$J \otimes_{B'} N' = I \otimes_{A'} A' \otimes_{B'} N' = I \otimes_{A'} M'$$ which maps injectively into $M'$ as $M'$ is a flat $A'$-module. Hence $J \otimes_{B'} N' \to N'$ is injective and we conclude that $\text{Tor}_1^{B'}(B'/J, N') = 0$, see Algebra, Remark Tor for a quotient by an ideal. Thus we may apply Algebra, Lemma A reformulation of the local algebraic condition to $N'$ over $B'$ and the ideal $J$. Going back to our ideal $\mathfrak b' \subset J$, let $\mathfrak b' \subset \mathfrak b'' \subset J$ be the smallest ideal whose image in $I$ is an $A'$-submodule of $I$. In other words, we have $\mathfrak b'' = A' \mathfrak b'$ if we view $J = I$ as $A'$-module. Then $\mathfrak b''/\mathfrak b'$ is killed by $J$ and we get a short exact sequence $$0 \to \mathfrak b' \otimes_{B'} N' \to \mathfrak b'' \otimes_{B'} N' \to \mathfrak b''/\mathfrak b' \otimes_{B'} N' \to 0$$ by the vanishing of $\text{Tor}_1^{B'}(\mathfrak b''/\mathfrak b', N')$ we get from the application of the lemma. Thus we may replace $\mathfrak b'$ by $\mathfrak b''$. In particular we may assume $\mathfrak b'$ is an $A'$-module and maps to an ideal of $A'$. Then $$\mathfrak b' \otimes_{B'} N' = \mathfrak b' \otimes_{A'} A' \otimes_{B'} N' = \mathfrak b' \otimes_{A'} M'$$ This tensor product maps injectively into $M'$ by our assumption that $M'$ is flat over $A'$. We conclude that $\mathfrak b' \otimes_{B'} N' \to N' \to M'$ is injective and hence the first map is injective as desired.
Proof of (2). This follows by tensoring the short exact sequence $0 \to B' \to B \oplus A' \to A \to 0$ with $L'$ over $B'$.
Proof of (3). Immediate consequence of (1) and (2). $\square$
Lemma. Derived Hom, Ext and projective and locally free modules
Let $R$ be a ring. Let $P^\bullet$ be a bounded above complex of projective $R$-modules. Let $L^\bullet$ be a complex of $R$-modules. Then $R\operatorname{Hom}_R(P^\bullet, L^\bullet)$ is represented by the complex $\operatorname{Hom}^\bullet(P^\bullet, L^\bullet)$.
Proof. By (Sheaf cohomology and derived Hom and Ext) and Derived Categories, Lemma Derived Hom, Ext and projective and locally free modules the cohomology groups of the complex are "correct". Hence if we choose a quasi-isomorphism $L^\bullet \to I^\bullet$ with $I^\bullet$ a K-injective complex of $R$-modules then the induced map $$\operatorname{Hom}^\bullet(P^\bullet, L^\bullet) \longrightarrow \operatorname{Hom}^\bullet(P^\bullet, I^\bullet)$$ is a quasi-isomorphism. As the right hand side is our definition of $R\operatorname{Hom}_R(P^\bullet, L^\bullet)$ we win. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $K \in D(R)$ be pseudo-coherent. Let $(M_n)$ be an inverse system of $R$-modules. Then $R\varprojlim K \otimes_R^\mathbf{L} M_n = K \otimes_R^\mathbf{L} R\varprojlim M_n$.
Proof. Consider the defining distinguished triangle $$R\varprojlim M_n \to \prod M_n \to \prod M_n \to R\varprojlim M_n[1]$$ and apply Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Criteria for henselian rings
Source credit: the original source citation Henselian (Chapter XI) and the original source citation Gabber-henselian (Proposition 1)
Let $(A, I)$ be a pair. The following are equivalent
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$(A, I)$ is a henselian pair,
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given an étale ring map $A \to A'$ and an $A$-algebra map $\sigma : A' \to A/I$, there exists an $A$-algebra map $A' \to A$ lifting $\sigma$,
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for any finite $A$-algebra $B$ the map $B \to B/IB$ induces a bijection on idempotents,
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for any integral $A$-algebra $B$ the map $B \to B/IB$ induces a bijection on idempotents, and
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(Gabber) $I$ is contained in the Jacobson radical of $A$ and every monic polynomial $f(T) \in A[T]$ of the form $$f(T) = T^n(T - 1) + a_n T^n + \ldots + a_1 T + a_0$$ with $a_n, \ldots, a_0 \in I$ and $n \ge 1$ has a root $\alpha \in 1 + I$.
Moreover, in part (5) the root is unique.
Proof. Assume (2) holds. Then $I$ is contained in the Jacobson radical of $A$, since otherwise there would be a nonunit $f \in A$ congruent to $1$ modulo $I$ and the map $A \to A_f$ would contradict (2). Hence $IB \subset B$ is contained in the Jacobson radical of $B$ for $B$ integral over $A$ because $\operatorname{Spec}(B) \to \operatorname{Spec}(A)$ is closed by Algebra, Lemmas Going up and closed maps of spectra and Going up for integral ring maps. Thus the map from idempotents of $B$ to idempotents of $B/IB$ is injective by Lemma Derived commutative algebra. On the other hand, since (2) holds, every idempotent of $B/IB$ lifts to an idempotent of $B$ by Lemma Lifting an idempotent after localization. In this way we see that (2) implies (4).
The implication (4) $\Rightarrow$ (3) is trivial.
Assume (3). Let $\mathfrak m$ be a maximal ideal and consider the finite map $A \to B = A/(I \cap \mathfrak m)$. The condition that $B \to B/IB$ induces a bijection on idempotents implies that $I \subset \mathfrak m$ (if not, then $B = A/I \times A/\mathfrak m$ and $B/IB = A/I$). Thus we see that $I$ is contained in the Jacobson radical of $A$. Let $f \in A[T]$ be monic and suppose given a factorization $\overline{f} = g_0h_0$ with $g_0, h_0 \in A/I[T]$ monic generating the unit ideal in $A/I[T]$. Set $B = A[T]/(f)$. Let $\overline{e}$ be the idempotent of $B/IB$ corresponding to the decomposition $$B/IB = A/I[T]/(g_0) \times A/I[T]/(h_0)$$ of $A$-algebras. Let $e \in B$ be an idempotent lifting $\overline{e}$ which exists as we assumed (3). This gives a product decomposition $$B = eB \times (1 - e)B$$ Note that $B$ is free of rank $\deg(f)$ as an $A$-module. Hence $eB$ and $(1 - e)B$ are finite locally free $A$-modules. However, since $eB$ and $(1 - e)B$ have constant rank $\deg(g_0)$ and $\deg(h_0)$ over $A/I$ we find that the same is true over $\operatorname{Spec}(A)$. We conclude that $$\begin{aligned} f & = \text{CharPol}_A(T : B \to B) \\ & = \text{CharPol}_A(T : eB \to eB) \text{CharPol}_A(T : (1 - e)B \to (1 - e)B) \end{aligned}$$ is a factorization into monic polynomials reducing to the given factorization modulo $I$. Here $\text{CharPol}_A$ denotes the characteristic polynomial of an endomorphism of a finite locally free module over $A$. If the module is free the $\text{CharPol}_A$ is defined as the characteristic polynomial of the corresponding matrix and in general one uses Algebra, Lemma Standard affine covers of a spectrum to glue. Details omitted. Thus (3) implies (1).
Assume (1). Let $f$ be as in (5). The factorization of $f \bmod I$ as $T^n$ times $T - 1$ lifts to a factorization $f = gh$ with $g$ and $h$ monic by Definition Henselian pairs. Then $h$ has to have degree $1$ and we see that $f$ has a root reducing to $1$ modulo $I$. Finally, $I$ is contained in the Jacobson radical by the definition of a henselian pair. Thus (1) implies (5).
Before we give the proof of the last step, let us show that the root $\alpha$ in (5), if it exists, is unique. Namely, due to the explicit shape of $f(T)$, we have $f'(\alpha) \in 1 + I$ where $f'$ is the derivative of $f$ with respect to $T$. An elementary argument shows that $$f(T) = f(\alpha + T - \alpha) = f(\alpha) + f'(\alpha) \cdot (T - \alpha) \bmod (T - \alpha)^2 A[T]$$ This shows that any other root $\alpha' \in 1 + I$ of $f(T)$ satisfies $0 = f(\alpha') - f(\alpha) = (\alpha' - \alpha)(1 + i)$ for some $i \in I$, so that, since $1 + i$ is a unit in $A$, we have $\alpha = \alpha'$.
Assume (5). We will show that (2) holds, in other words, that for every étale map $A \to A'$, every section $\sigma : A' \to A/I$ modulo $I$ lifts to a section $A' \to A$. Since $A \to A'$ is étale, the section $\sigma$ determines a decomposition
$$A'/IA' \cong A/I \times C$$ of $A/I$-algebras. Namely, the surjective ring map $A'/IA' \to A/I$ is étale by Algebra, Lemma Morphisms between étale algebras and then we get the desired idempotent by Algebra, Lemma Finite presentation and flatness. We will show that this decomposition lifts to a decomposition
$$A' \cong A'_1 \times A'_2$$ of $A$-algebras with $A'_1$ integral over $A$. Then $A \to A'_1$ is integral and étale and $A/I \to A'_1/IA'_1$ is an isomorphism, thus $A \to A'_1$ is an isomorphism by Lemma Derived commutative algebra (here we also use that an étale ring map is flat and of finite presentation, see Algebra, Lemma Étale morphisms).
Let $B'$ be the integral closure of $A$ in $A'$. By Lemma Separating a finite closed component through integral closure we may decompose
$$B'/IB' \cong A/I \times C'$$ as $A/I$-algebras compatibly with (the displayed identity) and we may find $b \in B'$ that lifts $(1, 0)$ such that $B'_b \to A'_b$ is an isomorphism. If the decomposition (the displayed identity) lifts to a decomposition
$$B' \cong B'_1 \times B'_2$$ of $A$-algebras, then the induced decomposition $A' = A'_1 \times A'_2$ will give the desired (the displayed identity): indeed, since $b$ is a unit in $B'_1$ (details omitted), we will have $B'_1 \cong A'_1$, so that $A'_1$ will be integral over $A$.
Choose a finite $A$-subalgebra $B'' \subset B'$ containing $b$ (observe that any finitely generated $A$-subalgebra of $B'$ is finite over $A$). After enlarging $B''$ we may assume $b$ maps to an idempotent in $B''/IB''$ producing
$$B''/IB'' \cong C''_1 \times C''_2$$ Since $B'_b \cong A'_b$ we see that $B'_b$ is of finite type over $A$. Say $B'_b$ is generated by $b_1/b^n, \ldots, b_t/b^n$ over $A$ and enlarge $B''$ so that $b_1, \ldots, b_t \in B''$. Then $B''_b \to B'_b$ is surjective as well as injective, hence an isomorphism. In particular, we see that $C''_1 = A/I$! Therefore $A/I \to C''_1$ is an isomorphism, in particular surjective. By Lemma A monic annihilating polynomial with prescribed reduction we can find an $f(T) \in A[T]$ of the form $$f(T) = T^n(T - 1) + a_n T^n + \ldots + a_1 T + a_0$$ with $a_n, \ldots, a_0 \in I$ and $n \ge 1$ such that $f(b) = 0$. In particular, we find that $B'$ is a $A[T]/(f)$-algebra. By (5) we deduce there is a root $a \in 1 + I$ of $f$. This produces a product decomposition $A[T]/(f) = A[T]/(T - a) \times D$ compatible with the splitting (the displayed identity) of $B'/IB'$. The induced splitting of $B'$ is then a desired (the displayed identity). $\square$
Lemma. Lifting a monic polynomial factorization
Let $A$ be a ring, let $I \subset A$ be an ideal. Let $f \in A[x]$ be a monic polynomial. Let $\overline{f} = \overline{g} \overline{h}$ be a factorization of $f$ in $A/I[x]$ such that $\overline{g}$ and $\overline{h}$ are monic and generate the unit ideal in $A/I[x]$. Then there exists an étale ring map $A \to A'$ which induces an isomorphism $A/I \to A'/IA'$ and a factorization $f = g' h'$ in $A'[x]$ with $g'$, $h'$ monic lifting the given factorization over $A/I$.
Proof. We will deduce this from results on the universal factorization proved earlier; however, we encourage the reader to find their own proof not using this trick. Say $\deg(\overline{g}) = n$ and $\deg(\overline{h}) = m$ so that $\deg(f) = n + m$. Write $f = x^{n + m} + \sum \alpha_i x^{n + m - i}$ for some $\alpha_1, \ldots, \alpha_{n + m} \in A$. Consider the ring map $$R = \mathbf{Z}[a_1, \ldots, a_{n + m}] \longrightarrow S = \mathbf{Z}[b_1, \ldots, b_n, c_1, \ldots, c_m]$$ of Algebra, Example Étale algebras from polynomial factorizations (uncovered prerequisite). Let $R \to A$ be the ring map which sends $a_i$ to $\alpha_i$. Set $$B = A \otimes_R S$$ By construction the image $f_B$ of $f$ in $B[x]$ factors, say $f_B = g_B h_B$ with $g_B = x^n + \sum (1 \otimes b_i) x^{n - i}$ and similarly for $h_B$. Write $\overline{g} = x^n + \sum \overline{\beta}_i x^{n - i}$ and $\overline{h} = x^m + \sum \overline{\gamma}_i x^{m - i}$. The $A$-algebra map $$B \longrightarrow A/I, \quad 1 \otimes b_i \mapsto \overline{\beta}_i, \quad 1 \otimes c_i \mapsto \overline{\gamma}_i$$ maps $g_B$ and $h_B$ to $\overline{g}$ and $\overline{h}$ in $A/I[x]$. The displayed map is surjective; denote $J \subset B$ its kernel. From the discussion in Algebra, Example Étale algebras from polynomial factorizations (uncovered prerequisite) it is clear that $A \to B$ is etale at all points of $V(J) \subset \operatorname{Spec}(B)$. Choose $g \in B$ as in Lemma Localizing an algebra while preserving its closed fibre and consider the $A$-algebra $B_g$. Since $g$ maps to a unit in $B/J = A/I$ we obtain also a map $B_g/I B_g \to A/I$ of $A/I$-algebras. Since $A/I \to B_g/I B_g$ is étale, also $B_g/IB_g \to A/I$ is étale (Algebra, Lemma Morphisms between étale algebras). Hence there exists an idempotent $e \in B_g/I B_g$ such that $A/I = (B_g/I B_g)_e$ (Algebra, Lemma Finite presentation and flatness). Choose a lift $h \in B_g$ of $e$. Then $A \to A' = (B_g)_h$ with factorization given by the image of the factorization $f_B = g_B h_B$ in $A'$ is a solution to the problem posed by the lemma. $\square$
Lemma. Lifting a finite projective module
Let $A$ be a ring, let $I \subset A$ be an ideal. Let $\overline{P}$ be a finite projective $A/I$-module. Then there exists an étale ring map $A \to A'$ which induces an isomorphism $A/I \to A'/IA'$ and a finite projective $A'$-module $P'$ lifting $\overline{P}$.
Proof. We can choose an integer $n$ and a direct sum decomposition $(A/I)^{\oplus n} = \overline{P} \oplus \overline{K}$ for some $R/I$-module $\overline{K}$. Choose a lift $\varphi : A^{\oplus n} \to A^{\oplus n}$ of the projector $\overline{p}$ associated to the direct summand $\overline{P}$. Let $f \in A[x]$ be the characteristic polynomial of $\varphi$. Set $B = A[x]/(f)$. By Cayley-Hamilton (Algebra, Lemma The characteristic polynomial (uncovered prerequisite)) there is a map $B \to \text{End}_A(A^{\oplus n})$ mapping $x$ to $\varphi$. For every prime $\mathfrak p \supset I$ the image of $f$ in $\kappa(\mathfrak p)$ is $(x - 1)^rx^{n - r}$ where $r$ is the dimension of $\overline{P} \otimes_{A/I} \kappa(\mathfrak p)$. Hence $(x - 1)^nx^n$ maps to zero in $B \otimes_A \kappa(\mathfrak p)$ for all $\mathfrak p \supset I$. Thus $x(1 - x)$ is contained in every prime ideal of $B/IB$. Hence $x^N(1 - x)^N$ is contained in $IB$ for some $N \geq 1$. It follows that $x^N + (1 - x)^N$ is a unit in $B/IB$ and that $$\overline{e} = \text{image of }\frac{x^N}{x^N + (1 - x)^N}\text{ in }B/IB$$ is an idempotent as both assertions hold in $\mathbf{Z}[x]/(x^N(x - 1)^N)$. The image of $\overline{e}$ in $\text{End}_{A/I}((A/I)^{\oplus n})$ is $$\frac{\overline{p}^N}{\overline{p}^N + (1 - \overline{p})^N} = \overline{p}$$ as $\overline{p}$ is an idempotent. After replacing $A$ by an étale extension $A'$ as in the lemma, we may assume there exists an idempotent $e \in B$ which maps to $\overline{e}$ in $B/IB$, see Lemma Lifting an idempotent after localization. Then the image of $e$ under the map $$B = A[x]/(f) \longrightarrow \text{End}_A(A^{\oplus n}).$$ is an idempotent element $p$ which lifts $\overline{p}$. Setting $P = \operatorname{Im}(p)$ we win. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring and $m \in \mathbf{Z}$. Let $(K^\bullet, L^\bullet, M^\bullet, f, g, h)$ be a distinguished triangle in $D(R)$.
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If $K^\bullet$ is $(m + 1)$-pseudo-coherent and $L^\bullet$ is $m$-pseudo-coherent then $M^\bullet$ is $m$-pseudo-coherent.
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If $K^\bullet, M^\bullet$ are $m$-pseudo-coherent, then $L^\bullet$ is $m$-pseudo-coherent.
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If $L^\bullet$ is $(m + 1)$-pseudo-coherent and $M^\bullet$ is $m$-pseudo-coherent, then $K^\bullet$ is $(m + 1)$-pseudo-coherent.
Proof. Proof of (1). Choose $\alpha : P^\bullet \to K^\bullet$ with $P^\bullet$ a bounded complex of finite free modules such that $H^i(\alpha)$ is an isomorphism for $i > m + 1$ and surjective for $i = m + 1$. We may replace $P^\bullet$ by $\sigma_{\geq m + 1}P^\bullet$ and hence we may assume that $P^i = 0$ for $i < m + 1$. Choose $\beta : E^\bullet \to L^\bullet$ with $E^\bullet$ a bounded complex of finite free modules such that $H^i(\beta)$ is an isomorphism for $i > m$ and surjective for $i = m$. By Derived Categories, Lemma Extending a morphism after finite denominators are cleared (uncovered prerequisite) we can find a map $\gamma : P^\bullet \to E^\bullet$ such that the diagram $$\begin{gathered}\begin{matrix}K^\bullet & L^\bullet \\ P^\bullet & E^\bullet\end{matrix} \\[6pt] \begin{aligned}K^\bullet & \longrightarrow L^\bullet \\ P^\bullet & \longrightarrow K^\bullet \\ P^\bullet & \xrightarrow{\gamma} E^\bullet \\ E^\bullet & \xrightarrow{\beta} L^\bullet\end{aligned}\end{gathered}$$ is commutative in $D(R)$. The cone $C(\gamma)^\bullet$ is a bounded complex of finite free $R$-modules, and the commutativity of the diagram implies that there exists a morphism of distinguished triangles $$(P^\bullet, E^\bullet, C(\gamma)^\bullet) \longrightarrow (K^\bullet, L^\bullet, M^\bullet).$$ It follows from the induced map on long exact cohomology sequences and Homology, Lemmas The geometric construction (uncovered prerequisite) and The geometric construction (uncovered prerequisite) that $C(\gamma)^\bullet \to M^\bullet$ induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. Hence $M^\bullet$ is $m$-pseudo-coherent.
Assertions (2) and (3) follow from (1) by rotating the distinguished triangle. $\square$
Lemma. Finiteness of cohomology groups
Let $R$ be a ring. Let $K^\bullet$ be a complex of $R$-modules. Let $m \in \mathbf{Z}$.
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If $K^\bullet$ is $m$-pseudo-coherent and $H^i(K^\bullet) = 0$ for $i > m$, then $H^m(K^\bullet)$ is a finite type $R$-module.
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If $K^\bullet$ is $m$-pseudo-coherent and $H^i(K^\bullet) = 0$ for $i > m + 1$, then $H^{m + 1}(K^\bullet)$ is a finitely presented $R$-module.
Proof. Proof of (1). Choose a bounded complex $E^\bullet$ of finite projective $R$-modules and a map $\alpha : E^\bullet \to K^\bullet$ which induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. It is clear that it suffices to prove the result for $E^\bullet$. Let $n$ be the largest integer such that $E^n \not = 0$. If $n = m$, then the result is clear. If $n > m$, then $E^{n - 1} \to E^n$ is surjective as $H^n(E^\bullet) = 0$. As $E^n$ is finite projective we see that $E^{n - 1} = E' \oplus E^n$. Hence it suffices to prove the result for the complex $(E')^\bullet$ which is the same as $E^\bullet$ except has $E'$ in degree $n - 1$ and $0$ in degree $n$. We win by induction on $n$.
Proof of (2). Choose a bounded complex $E^\bullet$ of finite projective $R$-modules and a map $\alpha : E^\bullet \to K^\bullet$ which induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. As in the proof of (1) we can reduce to the case that $E^i = 0$ for $i > m + 1$. Then we see that $H^{m + 1}(K^\bullet) \cong H^{m + 1}(E^\bullet) = \operatorname{Coker}(E^m \to E^{m + 1})$ which is of finite presentation. $\square$
Lemma. Derived tensor products, Tor amplitude and dimension and codimension
Let $R' \to R$ be a surjective ring map whose kernel is a nilpotent ideal. Let $K' \in D(R')$ and set $K = K' \otimes_{R'}^\mathbf{L} R$. Let $a, b \in \mathbf{Z}$. Then $K$ has tor amplitude in $[a, b]$ if and only if $K'$ does.
Proof. One direction follows from Lemma Pullback of derived tensor products and Tor amplitude. For the other, assume $K$ has tor amplitude in $[a, b]$ and let $M'$ be an $R'$-module. We have to show that $K' \otimes_{R'}^\mathbf{L} M'$ has nonzero cohomology only for degrees contained in the interval $[a, b]$.
Let $I = \operatorname{Ker}(R' \to R)$. Then $I^n = 0$ for some $n$. If $IM' = 0$, then we can view $M'$ as an $R$-module and argue as follows $$K' \otimes_{R'}^\mathbf{L} M' = K' \otimes_{R'}^\mathbf{L} (R \otimes_R^\mathbf{L} M') = (K' \otimes_{R'}^\mathbf{L} R) \otimes_R^\mathbf{L} M' = K \otimes_R^\mathbf{L} M'$$ which has nonvanishing cohomology only in the interval $[a, b]$ by assumption on $K$. If $I^{t + 1}M' = 0$, then we consider the short exact sequence $$0 \to IM' \to M' \to M'/IM' \to 0$$ By induction on $t$ we have that both $K' \otimes_{R'}^\mathbf{L} IM'$ and $K' \otimes_{R'}^\mathbf{L} M'/IM'$ have nonzero cohomology only for degrees in the interval $[a, b]$. Then the distinguished triangle $$K' \otimes_{R'}^\mathbf{L} IM' \to K' \otimes_{R'}^\mathbf{L} M' \to K' \otimes_{R'}^\mathbf{L} M'/IM' \to (K' \otimes_{R'}^\mathbf{L} IM')[1]$$ proves the same is true for $K' \otimes_{R'}^\mathbf{L} M'$ as desired. $\square$
Lemma. Lifting derived categories
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $\mathcal{P}$ be a class of $R$-modules. Assume
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each $P \in \mathcal{P}$ is a projective $R$-module,
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if $P_1 \in \mathcal{P}$ and $P_1 \oplus P_2 \in \mathcal{P}$, then $P_2 \in \mathcal{P}$, and
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if $f : P_1 \to P_2$, $P_1, P_2 \in \mathcal{P}$ is surjective modulo $I$, then $f$ is surjective.
Then given any bounded above acyclic complex $E^\bullet$ whose terms are of the form $P/IP$ for $P \in \mathcal{P}$ there exists a bounded above acyclic complex $P^\bullet$ whose terms are in $\mathcal{P}$ lifting $E^\bullet$.
Proof. Say $E^i = 0$ for $i > b$. Assume given $n$ and a morphism of complexes $$\begin{gathered}\begin{matrix}\phantom{X} & \phantom{X} & P^n & P^{n + 1} & \ldots & P^b & 0 & \ldots \\ \ldots & E^{n - 1} & E^n & E^{n + 1} & \ldots & E^b & 0 & \ldots\end{matrix} \\[6pt] \begin{aligned}P^n & \longrightarrow P^{n + 1} \\ P^n & \longrightarrow E^n \\ P^{n + 1} & \longrightarrow \ldots \\ P^{n + 1} & \longrightarrow E^{n + 1} \\ \ldots & \longrightarrow P^b \\ P^b & \longrightarrow 0 \\ P^b & \longrightarrow E^b \\ 0 & \longrightarrow \ldots \\ 0 & \longrightarrow 0 \\ \ldots & \longrightarrow E^{n - 1} \\ E^{n - 1} & \longrightarrow E^n \\ E^n & \longrightarrow E^{n + 1} \\ E^{n + 1} & \longrightarrow \ldots \\ \ldots & \longrightarrow E^b \\ E^b & \longrightarrow 0 \\ 0 & \longrightarrow \ldots\end{aligned}\end{gathered}$$ with $P^i \in \mathcal{P}$, with $P^n \to P^{n + 1} \to \ldots \to P^b$ acyclic in degrees $\geq n + 1$, and with vertical maps inducing isomorphisms $P^i/IP^i \to E^i$. In this situation one can inductively choose isomorphisms $P^i = Z^i \oplus Z^{i + 1}$ such that the maps $P^i \to P^{i + 1}$ are given by $Z^i \oplus Z^{i + 1} \to Z^{i + 1} \to Z^{i + 1} \oplus Z^{i + 2}$. By property (2) and arguing inductively we see that $Z^i \in \mathcal{P}$. Choose $P^{n - 1} \in \mathcal{P}$ and an isomorphism $P^{n - 1}/IP^{n - 1} \to E^{n - 1}$. Since $P^{n - 1}$ is projective and since $Z^n/IZ^n = \operatorname{Im}(E^{n - 1} \to E^n)$, we can lift the map $P^{n - 1} \to E^{n - 1} \to E^n$ to a map $P^{n - 1} \to Z^n$. By property (3) the map $P^{n - 1} \to Z^n$ is surjective. Thus we obtain an extension of the diagram by adding $P^{n - 1}$ and the maps just constructed to the left of $P^n$. Since a diagram of the desired form exists for $n > b$ we conclude by induction on $n$. $\square$
Lemma. Computation of a derived inverse limit
The functor $\varprojlim : \textit{Ab}(\mathbf{N}) \to \textit{Ab}$ has a right derived functor
$$R\varprojlim : D(\textit{Ab}(\mathbf{N})) \longrightarrow D(\textit{Ab})$$ As usual we set $R^p\varprojlim(K) = H^p(R\varprojlim(K))$. Moreover, we have
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for any $(A_n)$ in $\textit{Ab}(\mathbf{N})$ we have $R^p\varprojlim A_n = 0$ for $p > 1$,
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the object $R\varprojlim A_n$ of $D(\textit{Ab})$ is represented by the complex $$\prod A_n \to \prod A_n,\quad (x_n) \mapsto (x_n - f_{n + 1}(x_{n + 1}))$$ sitting in degrees $0$ and $1$,
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if $(A_n)$ is ML, then $R^1\varprojlim A_n = 0$, i.e., $(A_n)$ is right acyclic for $\varprojlim$,
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every $K^\bullet \in D(\textit{Ab}(\mathbf{N}))$ is quasi-isomorphic to a complex whose terms are right acyclic for $\varprojlim$, and
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if each $K^p = (K^p_n)$ is right acyclic for $\varprojlim$, i.e., if $R^1\varprojlim_n K^p_n = 0$, then $R\varprojlim K$ is represented by the complex whose term in degree $p$ is $\varprojlim_n K_n^p$.
Proof. Let $(A_n)$ be an arbitrary inverse system. Let $(B_n)$ be the inverse system with $$B_n = A_n \oplus A_{n - 1} \oplus \ldots \oplus A_1$$ and transition maps given by projections. Let $A_n \to B_n$ be given by $(1, f_n, f_{n - 1} \circ f_n, \ldots, f_2 \circ \ldots \circ f_n)$ where $f_i : A_i \to A_{i - 1}$ are the transition maps. In this way we see that every inverse system is a subobject of a ML system (Homology, Section The geometric construction). It follows from Derived Categories, Lemma Triangulated categories (uncovered prerequisite) using Homology, Lemma The geometric construction (uncovered prerequisite) that every ML system is right acyclic for $\varprojlim$, i.e., (3) holds. This already implies that $R\varprojlim$ is defined on $D^+(\textit{Ab}(\mathbf{N}))$, see Derived Categories, Proposition Triangulated categories (uncovered prerequisite). Set $C_n = A_{n - 1} \oplus \ldots \oplus A_1$ for $n > 1$ and $C_1 = 0$ with transition maps given by projections as well. Then there is a short exact sequence of inverse systems $0 \to (A_n) \to (B_n) \to (C_n) \to 0$ where $B_n \to C_n$ is given by $(x_i) \mapsto (x_i - f_{i + 1}(x_{i + 1}))$. Since $(C_n)$ is ML as well, we conclude that (2) holds (by proposition reference above) which also implies (1). Finally, this implies by Derived Categories, Lemma Derived categories (uncovered prerequisite) that $R\varprojlim$ is in fact defined on all of $D(\textit{Ab}(\mathbf{N}))$. In fact, the proof of Derived Categories, Lemma Derived categories (uncovered prerequisite) proceeds by proving assertions (4) and (5). $\square$
Lemma. Lifting derived categories
Let $(A_n)$ be an inverse system of rings. Suppose that we are given
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for every $n$ an object $K_n$ of $D(A_n)$, and
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for every $n$ a map $\varphi_n : K_{n + 1} \to K_n$ of $D(A_{n + 1})$ where we think of $K_n$ as an object of $D(A_{n + 1})$ by restriction via $A_{n + 1} \to A_n$.
There exists an object $M = (M_n^\bullet) \in D(\textit{Mod}(\mathbf{N}, (A_n)))$ and isomorphisms $\psi_n : M_n^\bullet \to K_n$ in $D(A_n)$ such that the diagrams $$\begin{gathered}\begin{matrix}M_{n + 1}^\bullet & M_n^\bullet \\ K_{n + 1} & K_n\end{matrix} \\[6pt] \begin{aligned}M_{n + 1}^\bullet & \xrightarrow{\psi_{n + 1}} K_{n + 1} \\ M_{n + 1}^\bullet & \longrightarrow M_n^\bullet \\ M_n^\bullet & \xrightarrow{\psi_n} K_n \\ K_{n + 1} & \xrightarrow{\varphi_n} K_n\end{aligned}\end{gathered}$$ commute in $D(A_{n + 1})$.
Proof. We write out the proof in detail. For an $A_n$-module $T$ we write $T_{A_{n + 1}}$ for the same module viewd as an $A_{n + 1}$-module. Suppose that $K_n^\bullet$ is a complex of $A_n$-modules representing $K_n$. Then $K_{n, A_{n + 1}}^\bullet$ is the same complex, but viewed as a complex of $A_{n + 1}$-modules. By the construction of the derived category, the map $\psi_n$ can be given as $$\psi_n = \tau_n \circ \sigma_n^{-1}$$ where $\sigma_n : L_{n + 1}^\bullet \to K_{n + 1}^\bullet$ is a quasi-isomorphism of complexes of $A_{n + 1}$-modules and $\tau_n : L_{n + 1}^\bullet \to K_{n, A_{n + 1}}^\bullet$ is a map of complexes of $A_{n + 1}$-modules.
Now we construct the complexes $M_n^\bullet$ by induction. As base case we let $M_1^\bullet = K_1^\bullet$. Suppose we have already constructed $M_e^\bullet \to M_{e - 1}^\bullet \to \ldots \to M_1^\bullet$ and maps of complexes $\psi_i : M_i^\bullet \to K_i^\bullet$ such that the diagrams $$\begin{gathered}\begin{matrix}M_{n + 1}^\bullet & \phantom{X} & M_{n, A_{n + 1}}^\bullet \\ K_{n + 1}^\bullet & L_{n + 1}^\bullet & K_{n, A_{n + 1}}^\bullet\end{matrix} \\[6pt] \begin{aligned}M_{n + 1}^\bullet & \xrightarrow{\psi_{n + 1}} K_{n + 1}^\bullet \\ M_{n + 1}^\bullet & \longrightarrow M_{n, A_{n + 1}}^\bullet \\ M_{n, A_{n + 1}}^\bullet & \xrightarrow{\psi_{n, A_{n + 1}}} K_{n, A_{n + 1}}^\bullet \\ L_{n + 1}^\bullet & \xrightarrow{\sigma_n} K_{n + 1}^\bullet \\ L_{n + 1}^\bullet & \xrightarrow{\tau_n} K_{n, A_{n + 1}}^\bullet\end{aligned}\end{gathered}$$ above commute in $D(A_{n + 1})$ for all $n < e$. Then we consider the diagram $$\begin{gathered}\begin{matrix}\phantom{X} & \phantom{X} & M_{e, A_{e + 1}}^\bullet \\ K_{e + 1}^\bullet & L_{e + 1}^\bullet & K_{e, A_{e + 1}}^\bullet\end{matrix} \\[6pt] \begin{aligned}M_{e, A_{e + 1}}^\bullet & \xrightarrow{\psi_{e, A_{e + 1}}} K_{e, A_{e + 1}}^\bullet \\ L_{e + 1}^\bullet & \xrightarrow{\tau_e} K_{e, A_{e + 1}}^\bullet \\ L_{e + 1}^\bullet & \xrightarrow{\sigma_e} K_{e + 1}^\bullet\end{aligned}\end{gathered}$$ in $D(A_{e + 1})$. Because $\psi_e$ is a quasi-isomorphism, we see that $\psi_{e, A_{e + 1}}$ is a quasi-isomorphism too. By the definition of morphisms in $D(A_{e + 1})$ we can find a quasi-isomorphism $\psi_{e + 1} : M_{e + 1}^\bullet \to K_{e + 1}^\bullet$ of complexes of $A_{e + 1}$-modules such that there exists a morphism of complexes $M_{e + 1}^\bullet \to M_{e, A_{e + 1}}^\bullet$ of $A_{e + 1}$-modules representing the composition $\psi_{e, A_{e + 1}}^{-1} \circ \tau_e \circ \sigma_e^{-1}$ in $D(A_{e + 1})$. Thus the lemma holds by induction. $\square$
Lemma. Modules and derived categories
Let $K = (K_n^\bullet)$ be an object of $D(\textit{Mod}(\mathbf{N}, (A_n)))$. There exists a canonical distinguished triangle $$R\varprojlim K \to \prod\nolimits_n K_n^\bullet \to \prod\nolimits_n K_n^\bullet \to R\varprojlim K[1]$$ in $D(A)$. In other words, $R\varprojlim K$ is a derived limit of the inverse system $(K_n^\bullet)$ of $D(A)$, see Derived Categories, Definition Derived categories.
Proof. The proof is exactly the same as the proof of Lemma Derived categories using Lemma Modules in stead of Lemma Computation of a derived inverse limit. $\square$
Lemma. Derived tensor products and Tor amplitude
Let $R$ be a ring. Let $K^\bullet$ be an object of $D(R)$. Let $a, b \in \mathbf{Z}$. The following are equivalent
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$K^\bullet$ has tor-amplitude in $[a, b]$.
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$K^\bullet$ is quasi-isomorphic to a complex $E^\bullet$ of flat $R$-modules with $E^i = 0$ for $i \not \in [a, b]$.
Proof. If (2) holds, then we may compute $K^\bullet \otimes_R^\mathbf{L} M = E^\bullet \otimes_R M$ and it is clear that (1) holds. Assume that (1) holds. We may replace $K^\bullet$ by a projective resolution with $K^i = 0$ for $i > b$. See Derived Categories, Lemma Projective and locally free modules (uncovered prerequisite). Set $E^\bullet = \tau_{\geq a}K^\bullet$. Everything is clear except that $E^a$ is flat which follows immediately from Lemma Flatness and the definitions. $\square$
Lemma. Flatness
Let $R$ be a ring. Let $K^\bullet$ be a bounded above complex of flat $R$-modules with tor-amplitude in $[a, b]$. Then $\operatorname{Coker}(d_K^{a - 1})$ is a flat $R$-module.
Proof. As $K^\bullet$ is a bounded above complex of flat modules we see that $K^\bullet \otimes_R M = K^\bullet \otimes_R^{\mathbf{L}} M$. Hence for every $R$-module $M$ the sequence $$K^{a - 2} \otimes_R M \to K^{a - 1} \otimes_R M \to K^a \otimes_R M$$ is exact in the middle. Since $K^{a - 2} \to K^{a - 1} \to K^a \to \operatorname{Coker}(d_K^{a - 1}) \to 0$ is a flat resolution this implies that $\text{Tor}_1^R(\operatorname{Coker}(d_K^{a - 1}), M) = 0$ for all $R$-modules $M$. This means that $\operatorname{Coker}(d_K^{a - 1})$ is flat, see Algebra, Lemma Criteria for flatness (uncovered prerequisite). $\square$
Lemma. Derived categories
Let $R$ be a ring. Let $\mathfrak p \subset R$ be a prime ideal. Let $i \in \mathbf{Z}$. Let $K^\bullet$ be a pseudo-coherent complex of $R$-modules such that $H^i(K^\bullet \otimes_R^{\mathbf{L}} \kappa(\mathfrak p)) = 0$. Then there exists an $f \in R$, $f \not \in \mathfrak p$ and a canonical direct sum decomposition $$K^\bullet \otimes_R R_f = \tau_{\geq i + 1}(K^\bullet \otimes_R R_f) \oplus \tau_{\leq i - 1}(K^\bullet \otimes_R R_f)$$ in $D(R_f)$ with $\tau_{\geq i + 1}(K^\bullet \otimes_R R_f)$ a perfect complex with tor-amplitude in $[i + 1, \infty]$.
Proof. This is an often used special case of Lemma Derived categories. A direct proof is as follows. We may assume that $K^\bullet$ is a bounded above complex of finite free $R$-modules. Let us inspect what is happening in degree $i$: $$\ldots \to K^{i - 2} \to R^{\oplus l} \to R^{\oplus m} \to R^{\oplus n} \to K^{i + 2} \to \ldots$$ Let $A$ be the $m \times l$ matrix corresponding to $K^{i - 1} \to K^i$ and let $B$ be the $n \times m$ matrix corresponding to $K^i \to K^{i + 1}$. The assumption is that $A \bmod \mathfrak p$ has rank $r$ and that $B \bmod \mathfrak p$ has rank $m - r$. In other words, there is some $r \times r$ minor $a$ of $A$ which is not in $\mathfrak p$ and there is some $(m - r) \times (m - r)$-minor $b$ of $B$ which is not in $\mathfrak p$. Set $f = ab$. Then after inverting $f$ we can find direct sum decompositions $K^{i - 1} = R^{\oplus l - r} \oplus R^{\oplus r}$, $K^i = R^{\oplus r} \oplus R^{\oplus m - r}$, $K^{i + 1} = R^{\oplus m - r} \oplus R^{\oplus n - m + r}$ such that the module map $K^{i - 1} \to K^i$ kills of $R^{\oplus l - r}$ and induces an isomorphism of $R^{\oplus r}$ onto the corresponding summand of $K^i$ and such that the module map $K^i \to K^{i + 1}$ kills of $R^{\oplus r}$ and induces an isomorphism of $R^{\oplus m - r}$ onto the corresponding summand of $K^{i + 1}$. Thus $K^\bullet$ becomes quasi-isomorphic to $$\ldots \to K^{i - 2} \to R^{\oplus l - r} \to 0 \to R^{\oplus n - m + r} \to K^{i + 2} \to \ldots$$ and everything is clear. $\square$
Lemma. Perfect complexes
Let $R$ be a ring. Let $f_1, \ldots, f_r \in R$ be elements which generate the unit ideal. Let $K^\bullet$ be a complex of $R$-modules. If for each $i$ the complex $K^\bullet \otimes_R R_{f_i}$ is perfect, then $K^\bullet$ is perfect.
Proof. Using Lemma Perfect complexes this translates into the corresponding results for pseudo-coherent modules and modules of finite tor dimension. See Lemma Derived tensor products and Tor amplitude and Lemma Pseudo-coherent complexes and coherent sheaves for those results. $\square$
Lemma. Derived tensor products and Tor amplitude
Let $R$ be a ring. Let $f_1, \ldots, f_r \in R$ be elements which generate the unit ideal. Let $a, b \in \mathbf{Z}$. Let $K^\bullet$ be a complex of $R$-modules. If for each $i$ the complex $K^\bullet \otimes_R R_{f_i}$ has tor amplitude in $[a, b]$, then $K^\bullet$ has tor amplitude in $[a, b]$.
Proof. This follows immediately from Lemma Derived tensor products, Tor amplitude and local algebra but can also be seen directly as follows. Note that $- \otimes_R R_{f_i}$ is an exact functor and that therefore $$H^i(K^\bullet)_{f_i} = H^i(K^\bullet) \otimes_R R_{f_i} = H^i(K^\bullet \otimes_R R_{f_i}).$$ and similarly for every $R$-module $M$ we have $$H^i(K^\bullet \otimes_R^{\mathbf{L}} M)_{f_i} = H^i(K^\bullet \otimes_R^{\mathbf{L}} M) \otimes_R R_{f_i} = H^i(K^\bullet \otimes_R R_{f_i} \otimes_{R_{f_i}}^{\mathbf{L}} M_{f_i}).$$ Hence the result follows from the fact that an $R$-module $N$ is zero if and only if $N_{f_i}$ is zero for each $i$, see Algebra, Lemma A finite cover by affine localizations. $\square$
Lemma. Module compatibility in a ring diagram
Given a commutative diagram of rings $$\begin{gathered}\begin{matrix}R & R' \\ B & B'\end{matrix} \\[6pt] \begin{aligned}R' & \longrightarrow R \\ B & \longrightarrow R \\ B' & \longrightarrow R' \\ B' & \longrightarrow B\end{aligned}\end{gathered}$$ the functor (Modules) has a right adjoint, namely the functor $$F : (N, M', \varphi) \longmapsto N \times_\varphi M'$$ (see proof for elucidation).
Proof. Given an object $(N, M', \varphi)$ of the category $\text{Mod}_B \times_{\text{Mod}_R} \text{Mod}_{R'}$ we set $$N \times_\varphi M' = \{(n, m') \in N \times M' \mid \varphi(n \otimes 1) = m' \otimes 1\text{ in }M' \otimes_{R'} R\}$$ viewed as a $B'$-module. The adjointness statement is that for a $B'$-module $L'$ and a triple $(N, M', \varphi)$ we have $$\operatorname{Hom}_{B'}(L', N \times_\varphi M') = \operatorname{Hom}_B(L' \otimes_{B'} B, N) \times_{\operatorname{Hom}_R(L' \otimes_{B'} R, M' \otimes_{R'} R)} \operatorname{Hom}_{R'}(L' \otimes_{B'} R', M')$$ By Algebra, Lemma Tensor products and direct sums (uncovered prerequisite) the right hand side is equal to $$\operatorname{Hom}_{B'}(L', N) \times_{\operatorname{Hom}_{B'}(L', M' \otimes_{R'} R)} \operatorname{Hom}_{B'}(L', M')$$ Thus it is clear that for a pair $(g, f')$ of elements of this fibre product we get an $B'$-linear map $L' \to N \times_\varphi M'$, $l' \mapsto (g(l'), f'(l'))$. Conversely, given a $B'$ linear map $g' : L' \to N \times_\varphi M'$ we can set $g$ equal to the composition $L' \to N \times_\varphi M' \to N$ and $f'$ equal to the composition $L' \to N \times_\varphi M' \to M'$. These constructions are mutually inverse to each other and define the desired isomorphism. $\square$
Lemma. Modules and tensor products and direct sums
In Situation Modules and tensor products and direct sums the functor (Derived tensor products and Tor amplitude) has a right adjoint, namely the functor $$F : (N, M', \varphi) \longmapsto N \times_{\varphi, M} M'$$ where $M = M'/IM'$. Moreover, the composition of $F$ with (Derived tensor products and Tor amplitude) is the identity functor on $\text{Mod}_B \times_{\text{Mod}_A} \text{Mod}_{A'}$. In other words, setting $N' = N \times_{\varphi, M} M'$ we have $N' \otimes_{B'} B = N$ and $N' \otimes_{B'} A' = M'$.
Proof. The adjointness statement follows from the more general Lemma Module compatibility in a ring diagram. To prove the final assertion, recall that $B' = B \times_A A'$ and $N' = N \times_{\varphi, M} M'$ and extend these equalities to $$\begin{gathered}\begin{matrix}A & A' & I \\ B & B' & J\end{matrix} \\[6pt] \begin{aligned}A' & \longrightarrow A \\ I & \longrightarrow A' \\ B & \longrightarrow A \\ B' & \longrightarrow B \\ B' & \longrightarrow A' \\ J & \longrightarrow B' \\ J & \longrightarrow I\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}M & M' & K \\ N & N' & L\end{matrix} \\[6pt] \begin{aligned}M' & \longrightarrow M \\ K & \longrightarrow M' \\ N & \xrightarrow{\varphi} M \\ N' & \longrightarrow N \\ N' & \longrightarrow M' \\ L & \longrightarrow N' \\ L & \longrightarrow K\end{aligned}\end{gathered}$$ where $I, J, K, L$ are the kernels of the horizontal maps of the original diagrams. We present the proof as a sequence of observations:
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$K = IM'$ (see statement lemma),
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$B' \to B$ is surjective with kernel $J$ and $J \to I$ is bijective,
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$N' \to N$ is surjective with kernel $L$ and $L \to K$ is bijective,
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$JN' \subset L$,
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$\operatorname{Im}(N \to M)$ generates $M$ as an $A$-module (because $N \otimes_B A = M$),
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$\operatorname{Im}(N' \to M')$ generates $M'$ as an $A'$-module (because it holds modulo $K$ and $L$ maps isomorphically to $K$),
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$JN' = L$ (because $L \cong K = I M'$ is generated by images of elements $x n'$ with $x \in I$ and $n' \in N'$ by the previous statement),
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$N' \otimes_{B'} B = N$ (because $N = N'/L$, $B = B'/J$, and the previous statement),
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there is a map $\gamma : N' \otimes_{B'} A' \to M'$,
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$\gamma$ is surjective (see above),
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the kernel of the composition $N' \otimes_{B'} A' \to M' \to M$ is generated by elements $l \otimes 1$ and $n' \otimes x$ with $l \in K$, $n' \in N'$, $x \in I$ (because $M = N \otimes_B A$ by assumption and because $N' \to N$ and $A' \to A$ are surjective with kernels $L$ and $I$),
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any element of $N' \otimes_{B'} A'$ in the submodule generated by the elements $l \otimes 1$ and $n' \otimes x$ with $l \in L$, $n' \in N'$, $x \in I$ can be written as $l \otimes 1$ for some $l \in L$ (because $J$ maps isomorphically to $I$ we see that $n' \otimes x = n'x \otimes 1$ in $N' \otimes_{B'} A'$; similarly $x n' \otimes a' = n' \otimes xa' = n'(xa') \otimes 1$ in $N' \otimes_{B'} A'$ when $n' \in N'$, $x \in J$ and $a' \in A'$; since we have seen that $JN' = L$ this proves the assertion),
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the kernel of $\gamma$ is zero (because by (10) and (11) any element of the kernel is of the form $l \otimes 1$ with $l \in L$ which is mapped to $l \in K \subset M'$ by $\gamma$).
This finishes the proof. $\square$
Situation. Modules and tensor products and direct sums
In the following we will consider ring maps $$\begin{gathered}\begin{matrix}B & A & A'\end{matrix} \\[6pt] \begin{aligned}B & \longrightarrow A \\ A' & \longrightarrow A\end{aligned}\end{gathered}$$ where we assume $A' \to A$ is surjective with kernel $I$. In this situation we set $B' = B \times_A A'$ to obtain a cartesian square $$\begin{gathered}\begin{matrix}A & A' \\ B & B'\end{matrix} \\[6pt] \begin{aligned}A' & \longrightarrow A \\ B & \longrightarrow A \\ B' & \longrightarrow B \\ B' & \longrightarrow A'\end{aligned}\end{gathered}$$
Lemma. Derived commutative algebra
Let $$(A^{-2}_n \to A^{-1}_n \to A^0_n \to A^1_n)$$ be an inverse system of complexes of abelian groups and denote $A^{-2} \to A^{-1} \to A^0 \to A^1$ its limit. Denote $(H_n^{-1})$, $(H_n^0)$ the inverse systems of cohomologies, and denote $H^{-1}$, $H^0$ the cohomologies of $A^{-2} \to A^{-1} \to A^0 \to A^1$. If
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$(A^{-2}_n)$ and $(A^{-1}_n)$ have vanishing $R^1\varprojlim$,
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$(H^{-1}_n)$ has vanishing $R^1\varprojlim$,
then $H^0 = \varprojlim H_n^0$.
Proof. Let $K \in D(\textit{Ab}(\mathbf{N}))$ be the object represented by the system of complexes whose $n$th constituent is the complex $A^{-2}_n \to A^{-1}_n \to A^0_n \to A^1_n$. We will compute $H^0(R\varprojlim K)$ using both spectral sequences[^3] of Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories. The first has $E_1$-page $$\begin{matrix} 0 & 0 & R^1\varprojlim A^0_n & R^1\varprojlim A^1_n \\ A^{-2} & A^{-1} & A^0 & A^1 \end{matrix}$$ with horizontal differentials and all higher differentials are zero. The second has $E_2$ page $$\begin{matrix} R^1\varprojlim H^{-2}_n & 0 & R^1\varprojlim H^0_n & R^1 \varprojlim H^1_n \\ \varprojlim H^{-2}_n & \varprojlim H^{-1}_n & \varprojlim H^0_n & \varprojlim H^1_n \end{matrix}$$ and degenerates at this point. The result follows. $\square$
Remark. Comparison for derived categories
Let $(K_n)$ be an inverse system of objects of $D(\textit{Ab})$. Let $K = R\varprojlim K_n$ be a derived limit of this system (see Derived Categories, Section Derived categories). Such a derived limit exists because $D(\textit{Ab})$ has countable products (Derived Categories, Lemma Tensor products and direct sums (uncovered prerequisite)). By Lemma Lifting derived categories we can also lift $(K_n)$ to an object $M$ of $D(\textit{Ab}(\mathbf{N}))$. Then $K \cong R\varprojlim M$ where $R\varprojlim$ is the functor (the displayed identity) because $R\varprojlim M$ is also a derived limit of the system $(K_n)$ by Lemma Derived categories. Thus, although there may be many isomorphism classes of lifts $M$ of the system $(K_n)$, the isomorphism type of $R\varprojlim M$ is independent of the choice because it is isomorphic to the derived limit $K = R\varprojlim K_n$ of the system. Thus we may apply results on $R\varprojlim$ proved in this section to derived limits. For example, for every $p \in \mathbf{Z}$ there is a canonical short exact sequence $$0 \to R^1\varprojlim H^{p - 1}(K_n) \to H^p(K) \to \varprojlim H^p(K_n) \to 0$$ because we may apply Lemma Derived commutative algebra to $M$. This can also be seen directly, without invoking the existence of $M$, by applying the argument of the proof of Lemma Derived commutative algebra to the (defining) distinguished triangle $K \to \prod K_n \to \prod K_n \to K[1]$.
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $f_1, \ldots, f_r \in R$ be elements which generate the unit ideal. Let $m \in \mathbf{Z}$. Let $K^\bullet$ be a complex of $R$-modules. If for each $i$ the complex $K^\bullet \otimes_R R_{f_i}$ is $m$-pseudo-coherent (resp. pseudo-coherent), then $K^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent).
Proof. We will use without further mention that $- \otimes_R R_{f_i}$ is an exact functor and that therefore $$H^i(K^\bullet)_{f_i} = H^i(K^\bullet) \otimes_R R_{f_i} = H^i(K^\bullet \otimes_R R_{f_i}).$$ Assume $K^\bullet \otimes_R R_{f_i}$ is $m$-pseudo-coherent for $i = 1, \ldots, r$. Let $n \in \mathbf{Z}$ be the largest integer such that $H^n(K^\bullet \otimes_R R_{f_i})$ is nonzero for some $i$. This implies in particular that $H^i(K^\bullet) = 0$ for $i > n$ (and that $H^n(K^\bullet) \not = 0$) see Algebra, Lemma A finite cover by affine localizations. We will prove the lemma by induction on $n - m$. If $n < m$, then the lemma is true by Lemma Pseudo-coherent complexes and coherent sheaves. If $n \geq m$, then $H^n(K^\bullet)_{f_i}$ is a finite $R_{f_i}$-module for each $i$, see Lemma Finiteness of cohomology groups. Hence $H^n(K^\bullet)$ is a finite $R$-module, see Algebra, Lemma A finite cover by affine localizations. Choose a finite free $R$-module $E$ and a surjection $E \to H^n(K^\bullet)$. As $E$ is projective we can lift this to a map of complexes $\alpha : E[-n] \to K^\bullet$. Then the cone $C(\alpha)^\bullet$ has vanishing cohomology in degrees $\geq n$. On the other hand, the complexes $C(\alpha)^\bullet \otimes_R R_{f_i}$ are $m$-pseudo-coherent for each $i$, see Lemma Pseudo-coherent complexes and coherent sheaves. Hence by induction we see that $C(\alpha)^\bullet$ is $m$-pseudo-coherent as a complex of $R$-modules. Applying Lemma Pseudo-coherent complexes and coherent sheaves once more we conclude. $\square$
Lemma. Projective, locally free modules and flatness
Let $A$ be a valuation ring. An $A$-module $M$ is flat over $A$ if and only if $M$ is torsion free.
Proof. The implication "flat $\Rightarrow$ torsion free" is Lemma Projective, locally free modules and flatness. For the converse, assume $M$ is torsion free. By the equational criterion of flatness (see Algebra, Lemma The equational criterion for flatness (uncovered prerequisite)) we have to show that every relation in $M$ is trivial. To do this assume that $\sum_{i = 1, \ldots, n} a_i x_i = 0$ with $x_i \in M$ and $a_i \in A$. After renumbering we may assume that $v(a_1) \leq v(a_i)$ for all $i$. Hence we can write $a_i = a'_i a_1$ for some $a'_i \in A$. Note that $a'_1 = 1$. As $M$ is torsion free we see that $x_1 = - \sum_{i \geq 2} a'_i x_i$. Thus, if we choose $y_i = x_i$, $i = 2, \ldots, n$ then $$x_1 = \sum\nolimits_{j \geq 2} -a'_j y_j, \quad x_i = y_i, (i \geq 2)\quad 0 = a_1 \cdot (-a'_j) + a_j \cdot 1 (j \geq 2)$$ shows that the relation was trivial (to be explicit the elements $a_{ij}$ are defined by setting $a_{11} = 0$, $a_{1j} = -a'_j$ for $j > 1$, and $a_{ij} = \delta_{ij}$ for $i, j \geq 2$). $\square$
Definition. Derived commutative algebra
We say that $A \to B$ or $A \subset B$ is an extension of valuation rings if $A$ and $B$ are valuation rings and $A \to B$ is injective and local. Such an extension induces a commutative diagram $$\begin{gathered}\begin{matrix}A \setminus \{0\} & B \setminus \{0\} \\ \Gamma_A & \Gamma_B\end{matrix} \\[6pt] \begin{aligned}A \setminus \{0\} & \longrightarrow B \setminus \{0\} \\ A \setminus \{0\} & \xrightarrow{v} \Gamma_A \\ B \setminus \{0\} & \xrightarrow{v} \Gamma_B \\ \Gamma_A & \longrightarrow \Gamma_B\end{aligned}\end{gathered}$$ where $\Gamma_A$ and $\Gamma_B$ are the value groups. We say that $B$ is weakly unramified over $A$ if the lower horizontal arrow is a bijection. If the extension of residue fields $\kappa_A = A/\mathfrak m_A \subset \kappa_B = B/\mathfrak m_B$ is finite, then we set $f = [\kappa_B : \kappa_A]$ and we call it the residual degree or residue degree of the extension $A \subset B$.
Lemma. Koszul complexes and regular sequences
Let $R$ be a ring. Let $f_1, \ldots, f_{r - 1}$ be a sequence of elements of $R$. Let $f, g \in R$. The complex $K_\bullet(f_1, \ldots, f_{r - 1}, fg)$ is homotopy equivalent to the cone of a map of complexes $$K_\bullet(f_1, \ldots, f_{r - 1}, f)[1] \longrightarrow K_\bullet(f_1, \ldots, f_{r - 1}, g)$$
Proof. Special case of Lemma Koszul complexes and regular sequences. $\square$
Lemma. Tensor products and direct sums
Let $R$ be a ring. Let $K^\bullet, L^\bullet, M^\bullet$ be complexes of $R$-modules. There is a canonical isomorphism $$(K^\bullet \otimes_R^\mathbf{L} L^\bullet) \otimes_R^\mathbf{L} M^\bullet
K^\bullet \otimes_R^\mathbf{L} (L^\bullet \otimes_R^\mathbf{L} M^\bullet)$$ functorial in all three complexes.
Proof. Replace the complexes by K-flat complexes and use the associativity constraint in Section Derived commutative algebra. $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Assumptions as in Lemma Derived tensor products, Tor amplitude and flatness. For $M \in D(A)$ there are canonical isomorphisms $$H^i((M \otimes_A^\mathbf{L} A') \otimes_{R'}^\mathbf{L} B') = H^i(M \otimes_R^\mathbf{L} B) \otimes_{(A \otimes_R B)} (A' \otimes_{R'} B')$$ of $A' \otimes_{R'} B'$-modules.
Proof. Let us elucidate the two sides of the equation. On the left hand side we have the composition of the functors $D(A) \to D(A') \to D(R') \to D(B')$ with the functor $H^i : D(B') \to \text{Mod}_{B'}$. Since there is a map from $A'$ to the endomorphisms of the object $(M \otimes_A^\mathbf{L} A') \otimes_{R'}^\mathbf{L} B'$ in $D(B')$, we see that the left hand side is indeed an $A' \otimes_{R'} B'$-module. By the same arguments we see that $H^i(M \otimes_R^\mathbf{L} B)$ has an $A \otimes_R B$-module structure.
We first prove the result in case $B' = R' \otimes_R B$. In this case we choose a resolution $F^\bullet \to B$ by free $R$-modules. We also choose a K-flat complex $M^\bullet$ of $A$-modules representing $M$. Then the left hand side is represented by $$\begin{aligned} H^i(\text{Tot}((M^\bullet \otimes_A A') \otimes_{R'} (R' \otimes_R F^\bullet))) & = H^i(\text{Tot}(M^\bullet \otimes_A A' \otimes_R F^\bullet)) \\ & = H^i(\text{Tot}(M^\bullet \otimes_R F^\bullet) \otimes_A A') \\ & = H^i(M \otimes_R^\mathbf{L} B) \otimes_A A' \end{aligned}$$ The final equality because $A \to A'$ is flat. The final module is the desired module because $A' \otimes_{R'} B' = A' \otimes_R B$ since we've assumed $B' = R' \otimes_R B$ in this paragraph.
General case. Suppose that $B' \to B''$ is a flat ring map. Then it is easy to see that $$H^i((M \otimes_A^\mathbf{L} A') \otimes_{R'}^\mathbf{L} B'') = H^i((M \otimes_A^\mathbf{L} A') \otimes_{R'}^\mathbf{L} B') \otimes_{B'} B''$$ and $$H^i(M \otimes_R^\mathbf{L} B) \otimes_{(A \otimes_R B)} (A' \otimes_{R'} B'')
\left( H^i(M \otimes_R^\mathbf{L} B) \otimes_{(A \otimes_R B)} (A' \otimes_{R'} B') \right) \otimes_{B'} B''$$ Thus the result for $B'$ implies the result for $B''$. Since we've proven the result for $R' \otimes_R B$ in the previous paragraph, this implies the result in general. $\square$
Remark. Derived commutative algebra
In fact, we can do better than Lemma Derived tensor products, Tor amplitude and flatness. Namely, we can find a quasi-isomorphism $P^\bullet \to M^\bullet$ where $P^\bullet$ is a complex of $R$-modules endowed with a filtration $$0 = F_{-1}P^\bullet \subset F_0P^\bullet \subset F_1P^\bullet \subset \ldots \subset P^\bullet$$ by subcomplexes such that
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$P^\bullet = \bigcup F_pP^\bullet$,
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the inclusions $F_iP^\bullet \to F_{i + 1}P^\bullet$ are termwise split injections,
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the quotients $F_{i + 1}P^\bullet/F_iP^\bullet$ are isomorphic to direct sums of shifts $R[k]$ (as complexes, so differentials are zero).
This will be shown in Differential Graded Algebra, Lemma Differential graded modules (or you can argue as in the proof of Lemma Derived categories). Moreover, given such a complex we obtain a distinguished triangle $$\bigoplus F_iP^\bullet \to \bigoplus F_iP^\bullet \to M^\bullet \to \bigoplus F_iP^\bullet[1]$$ in $D(R)$. Using this we can sometimes reduce statements about general complexes to statements about $R[k]$ (this of course only works if the statement is preserved under taking direct sums). More precisely, let $T$ be a property of objects of $D(R)$. Suppose that
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if $K_i \in D(R)$, $i \in I$ is a family of objects with $T(K_i)$ for all $i \in I$, then $T(\bigoplus K_i)$,
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if $K \to L \to M \to K[1]$ is a distinguished triangle and $T$ holds for two, then $T$ holds for the third object,
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$T(R[k])$ holds for all $k$.
Then $T$ holds for all objects of $D(R)$.
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $K \in D^-(R)$. The following are equivalent:
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$K$ is pseudo-coherent,
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for every family $(Q_{\alpha})_{\alpha \in A}$ of $R$-modules, the canonical map $$\alpha : K \otimes_R^\mathbf{L} \left( \prod\nolimits_\alpha Q_{\alpha} \right) \longrightarrow \prod\nolimits_\alpha (K \otimes_R^\mathbf{L} Q_{\alpha})$$ is an isomorphism in $D(R)$,
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for every $R$-module $Q$ and every set $A$, the canonical map $$\beta : K \otimes_R^\mathbf{L} Q^A \longrightarrow (K \otimes_R^\mathbf{L} Q)^A$$ is an isomorphism in $D(R)$, and
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for every set $A$, the canonical map $$\gamma : K \otimes_R^\mathbf{L} R^A \longrightarrow K^A$$ is an isomorphism in $D(R)$.
Given $m \in \mathbf{Z}$ the following are equivalent
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$K$ is $m$-pseudo-coherent,
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for every family $(Q_{\alpha})_{\alpha \in A}$ of $R$-modules, with $\alpha$ as above $H^i(\alpha)$ is an isomorphism for $i > m$ and surjective for $i = m$,
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for every $R$-module $Q$ and every set $A$, with $\beta$ as above $H^i(\beta)$ is an isomorphism for $i > m$ and surjective for $i = m$,
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for every set $A$, with $\gamma$ as above $H^i(\gamma)$ is an isomorphism for $i > m$ and surjective for $i = m$.
Proof. If $K$ is pseudo-coherent, then $K$ can be represented by a bounded above complex of finite free $R$-modules. Then the derived tensor products are computed by tensoring with this complex. Also, products in $D(R)$ are given by taking products of any choices of representative complexes. Hence (1) implies (2), (3), (4) by the corresponding fact for modules, see Algebra, Proposition Finite presentation and tensor products and direct sums (uncovered prerequisite).
In the same way (using the tensor product is right exact) the reader shows that (a) implies (b), (c), and (d).
Assume (4) holds. To show that $K$ is pseudo-coherent it suffices to show that $K$ is $m$-pseudo-coherent for all $m$ (Lemma Pseudo-coherent complexes and coherent sheaves). Hence to finish then proof it suffices to prove that (d) implies (a).
Assume (d). Let $i$ be the largest integer such that $H^i(K)$ is nonzero. If $i < m$, then we are done. If not, then from (d) and the description of products in $D(R)$ given above we find that $H^i(K) \otimes_R R^A \to H^i(K)^A$ is surjective. Hence $H^i(K)$ is a finitely generated $R$-module by Algebra, Proposition Tensor products and direct sums (uncovered prerequisite). Thus we may choose a complex $L$ consisting of a single finite free module sitting in degree $i$ and a map of complexes $L \to K$ such that $H^i(L) \to H^i(K)$ is surjective. In particular $L$ satisfies (1), (2), (3), and (4). Choose a distinguished triangle $$L \to K \to M \to L[1]$$ Then we see that $H^j(M) = 0$ for $j \geq i$. On the other hand, $M$ still has property (d) by a small argument which we omit. By induction on $i$ we find that $M$ is $m$-pseudo-coherent. Hence $K$ is $m$-pseudo-coherent by Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Definition. Perfect complexes
Let $R$ be a ring. Denote $D(R)$ the derived category of the abelian category of $R$-modules.
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An object $K$ of $D(R)$ is perfect if it is quasi-isomorphic to a bounded complex of finite projective $R$-modules.
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An $R$-module $M$ is perfect if $M[0]$ is a perfect object in $D(R)$.
Lemma. Derived tensor products and Tor amplitude
Let $R$ be a ring. Let $A$, $B$ be $R$-algebras. The following are equivalent
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$A$ and $B$ are Tor independent over $R$,
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for every pair of primes $\mathfrak p \subset A$ and $\mathfrak q \subset B$ lying over the same prime $\mathfrak r \subset R$ the rings $A_\mathfrak p$ and $B_\mathfrak q$ are Tor independent over $R_\mathfrak r$, and
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For every prime $\mathfrak s$ of $A \otimes_R B$ the module $$\text{Tor}_i^R(A, B)_\mathfrak s = \text{Tor}_i^{R_\mathfrak r}(A_\mathfrak p, B_\mathfrak q)_\mathfrak s$$ (where $\mathfrak p = A \cap \mathfrak s$, $\mathfrak q = B \cap \mathfrak s$ and $\mathfrak r = R \cap \mathfrak s$) is zero.
Proof. Let $\mathfrak s$ be a prime of $A \otimes_R B$ as in (3). The equality $$\text{Tor}_i^R(A, B)_\mathfrak s = \text{Tor}_i^{R_\mathfrak r}(A_\mathfrak p, B_\mathfrak q)_\mathfrak s$$ where $\mathfrak p = A \cap \mathfrak s$, $\mathfrak q = B \cap \mathfrak s$ and $\mathfrak r = R \cap \mathfrak s$ follows from Lemma Derived tensor products, Tor amplitude and flatness. Hence (2) implies (3). Since we can test the vanishing of modules by localizing at primes (Algebra, Lemma Detecting a zero module by localization) we conclude that (3) implies (1). For (1) $\Rightarrow$ (2) we use that $$\text{Tor}_i^{R_\mathfrak r}(A_\mathfrak p, B_\mathfrak q) = \text{Tor}_i^R(A, B) \otimes_{(A \otimes_R B)} (A_\mathfrak p \otimes_{R_{\mathfrak r}} B_\mathfrak q)$$ again by Lemma Derived tensor products, Tor amplitude and flatness. $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Consider a commutative diagram of rings $$\begin{gathered}\begin{matrix}A' & R' & B' \\ A & R & B\end{matrix} \\[6pt] \begin{aligned}R' & \longrightarrow B' \\ R' & \longrightarrow A' \\ A & \longrightarrow A' \\ R & \longrightarrow A \\ R & \longrightarrow R' \\ R & \longrightarrow B \\ B & \longrightarrow B'\end{aligned}\end{gathered}$$ Assume that $R'$ is flat over $R$ and $A'$ is flat over $A \otimes_R R'$ and $B'$ is flat over $R' \otimes_R B$. Then $$\text{Tor}_i^R(A, B) \otimes_{(A \otimes_R B)} (A' \otimes_{R'} B') = \text{Tor}_i^{R'}(A', B')$$
Proof. By Algebra, Section Derived tensor products and Tor amplitude there are canonical maps $$\text{Tor}_i^R(A, B) \longrightarrow \text{Tor}_i^{R'}(A \otimes_R R', B \otimes_R R') \longrightarrow \text{Tor}_i^{R'}(A', B')$$ These induce a map from left to right in the formula of the lemma.
Take a free resolution $F_\bullet \to A$ of $A$ as an $R$-module. Then we see that $F_\bullet \otimes_R R'$ is a resolution of $A \otimes_R R'$. Hence $\text{Tor}_i^{R'}(A \otimes_R R', B \otimes_R R')$ is computed by $F_\bullet \otimes_R B \otimes_R R'$. By our assumption that $R'$ is flat over $R$, this computes $\text{Tor}_i^R(A, B) \otimes_R R'$. Thus $\text{Tor}_i^{R'}(A \otimes_R R', B \otimes_R R') = \text{Tor}_i^R(A, B) \otimes_R R'$ (uses only flatness of $R'$ over $R$).
By Lazard's theorem (Algebra, Theorem Commutative algebra (uncovered prerequisite)) we can write $A'$, resp. $B'$ as a filtered colimit of finite free $A \otimes_R R'$, resp. $B \otimes_R R'$-modules. Say $A' = \mathop{\operatorname{colim}} M_i$ and $B' = \mathop{\operatorname{colim}} N_j$. The result above gives $$\text{Tor}_i^{R'}(M_i, N_j) = \text{Tor}_i^R(A, B) \otimes_{A \otimes_R B} (M_i \otimes_{R'} N_j)$$ as one can see by writing everything out in terms of bases. Taking the colimit we get the result of the lemma. $\square$
Lemma. Base change for derived commutative algebra
Let $A \to B \to C$ be ring maps. Let $N^\bullet$ be a complex of $B$-modules and $K^\bullet$ a complex of $C$-modules. The compositions of the functors $$D(A) \xrightarrow{- \otimes_A^\mathbf{L} N^\bullet} D(B) \xrightarrow{- \otimes_B^\mathbf{L} K^\bullet} D(C)$$ is the functor $- \otimes_A^\mathbf{L} (N^\bullet \otimes_B^\mathbf{L} K^\bullet) : D(A) \to D(C)$. If $M$, $N$, $K$ are modules over $A$, $B$, $C$, then we have $$(M \otimes_A^\mathbf{L} N) \otimes_B^\mathbf{L} K = M \otimes_A^\mathbf{L} (N \otimes_B^\mathbf{L} K) = (M \otimes_A^\mathbf{L} C) \otimes_C^\mathbf{L} (N \otimes_B^\mathbf{L} K)$$ in $D(C)$. We also have a canonical isomorphism $$(M \otimes_A^\mathbf{L} N) \otimes_B^\mathbf{L} K \longrightarrow (M \otimes_A^\mathbf{L} K) \otimes_C^\mathbf{L} (N \otimes_B^\mathbf{L} C)$$ using signs. Similar results holds for complexes.
Proof. Choose a K-flat complex $P^\bullet$ of $B$-modules and a quasi-isomorphism $P^\bullet \to N^\bullet$ (Lemma Derived tensor products, Tor amplitude and flatness). Let $M^\bullet$ be a K-flat complex of $A$-modules representing an arbitrary object of $D(A)$. Then we see that $$(M^\bullet \otimes_A^\mathbf{L} P^\bullet) \otimes_B^\mathbf{L} K^\bullet \longrightarrow (M^\bullet \otimes_A^\mathbf{L} N^\bullet) \otimes_B^\mathbf{L} K^\bullet$$ is an isomorphism by Lemma Base change for derived categories applied to the material inside the brackets. By Lemmas Base change for derived tensor products, Tor amplitude and flatness and Derived tensor products, Tor amplitude and flatness the complex $$\text{Tot}(M^\bullet \otimes_A P^\bullet) = \text{Tot}((M^\bullet \otimes_R A) \otimes_A P^\bullet$$ is K-flat as a complex of $B$-modules and it represents the derived tensor product in $D(B)$ by construction. Hence we see that $(M^\bullet \otimes_A^\mathbf{L} P^\bullet) \otimes_B^\mathbf{L} K^\bullet$ is represented by the complex $$\text{Tot}(\text{Tot}(M^\bullet \otimes_A P^\bullet)\otimes_B K^\bullet) = \text{Tot}(M^\bullet \otimes_A \text{Tot}(P^\bullet \otimes_B K^\bullet))$$ of $C$-modules. Equality by Homology, Remark Derived categories. Going back the way we came we see that this is equal to $$M^\bullet \otimes_A^\mathbf{L} (P^\bullet \otimes_B^\mathbf{L} K^\bullet) \longleftarrow M^\bullet \otimes_A^\mathbf{L} (N^\bullet \otimes_B^\mathbf{L} K^\bullet)$$ The arrow is an isomorphism by definition of the functor $-\otimes_B^\mathbf{L} K^\bullet$. All of these constructions are functorial in the complex $M^\bullet$ and hence we obtain our isomorphism of functors.
By the above we have the first equality in $$(M \otimes_A^\mathbf{L} N) \otimes_B^\mathbf{L} K = M \otimes_A^\mathbf{L} (N \otimes_B^\mathbf{L} K) = (M \otimes_A^\mathbf{L} C) \otimes_C^\mathbf{L} (N \otimes_B^\mathbf{L} K)$$ The second equality follows from the final statement of Lemma Base change for derived categories. The same thing allows us to write $N \otimes_B^\mathbf{L} K = (N \otimes_B^\mathbf{L} C) \otimes_C^\mathbf{L} K$ and substituting we get $$\begin{aligned} (M \otimes_A^\mathbf{L} N) \otimes_B^\mathbf{L} K & = (M \otimes_A^\mathbf{L} C) \otimes_C^\mathbf{L} ((N \otimes_B^\mathbf{L} C) \otimes_C^\mathbf{L} K) \\ & = (M \otimes_A^\mathbf{L} C) \otimes_C^\mathbf{L} (K \otimes_C^\mathbf{L} (N \otimes_B^\mathbf{L} C)) \\ & = ((M \otimes_A^\mathbf{L} C) \otimes_C^\mathbf{L} K) \otimes_C^\mathbf{L} (N \otimes_B^\mathbf{L} C)) \\ & = (M \otimes_C^\mathbf{L} K) \otimes_C^\mathbf{L} (N \otimes_B^\mathbf{L} C) \end{aligned}$$ by Lemmas Tensor products and direct sums and Tensor products and direct sums as well as the previously mentioned lemma. $\square$
Lemma. Perfect complexes and finite presentation
A ring map which is flat and of finite presentation is perfect.
Proof. Let $A \to B$ be a ring map which is flat and of finite presentation. It is clear that $B$ has finite tor dimension. By Algebra, Lemma Lesson 3, Section 5.6.7, C.1 there exists a finite type $\mathbf{Z}$-algebra $A_0 \subset A$ and a flat finite type ring map $A_0 \to B_0$ such that $B = B_0 \otimes_{A_0} A$. By Lemma Pseudo-coherent complexes and coherent sheaves we see that $A_0 \to B_0$ is pseudo-coherent. As $A_0 \to B_0$ is flat we see that $B_0$ and $A$ are tor independent over $A_0$, hence we may use Lemma Base change for pseudo-coherent complexes and coherent sheaves to conclude that $A \to B$ is pseudo-coherent. $\square$
Lemma. Lifting perfect complexes and derived Hom and Ext
Let $R$ be a ring. Let $\mathfrak p \subset R$ be a prime. Let $K \in D(R)$ be perfect. Set $d_i = \dim_{\kappa(\mathfrak p)} H^i(K \otimes_R^\mathbf{L} \kappa(\mathfrak p))$. Then $d_i < \infty$ and only a finite number are nonzero. Then there exists an $f \in R$, $f \not \in \mathfrak p$ and a complex $$\ldots \to 0 \to R_f^{\oplus d_a} \to R_f^{\oplus d_{a + 1}} \to \ldots \to R_f^{\oplus d_{b - 1}} \to R_f^{\oplus d_b} \to 0 \to \ldots$$ representing $K \otimes_R^\mathbf{L} R_f$ in $D(R_f)$.
Proof. Observe that $K \otimes_R^\mathbf{L} \kappa(\mathfrak p)$ is perfect as an object of $D(\kappa(\mathfrak p))$, see Lemma Pullback of perfect complexes. Hence only a finite number of $d_i$ are nonzero and they are all finite. Applying Lemma Lifting pseudo-coherent complexes and derived Hom and Ext we get a complex representing $K$ having the desired shape over the local ring $R_\mathfrak p$. We have $R_\mathfrak p = \mathop{\operatorname{colim}} R_f$ for $f \in R$, $f \not \in \mathfrak p$ (Algebra, Lemma Localization as a filtered colimit). We conclude by Lemma Filtered limits and perfect complexes and derived categories. Some details omitted. $\square$
Lemma. Derived commutative algebra
Let $(A, I)$ be a Zariski pair. Then the map from idempotents of $A$ to idempotents of $A/I$ is injective.
Proof. An idempotent of a local ring is either $0$ or $1$. Thus an idempotent is determined by the set of maximal ideals where it vanishes, by Algebra, Lemma Detecting a zero module by localization. $\square$
Lemma. Lifting an idempotent after localization
Let $A$ be a ring, let $I \subset A$ be an ideal. Let $A \to B$ be an integral ring map. Let $\overline{e} \in B/IB$ be an idempotent. Then there exists an étale ring map $A \to A'$ which induces an isomorphism $A/I \to A'/IA'$ and an idempotent $e' \in B \otimes_A A'$ lifting $\overline{e}$.
Proof. Choose an element $y \in B$ lifting $\overline{e}$. Choose $f \in A[x]$ as in Lemma Integral elements compatible with a lifted factorization for $y$. By Lemma Lifting a coprime factorization we can find an étale ring map $A \to A'$ which induces an isomorphism $A/I \to A'/IA'$ and such that $f = gh$ in $A[x]$ with $g(x) = x^d \bmod IA'$ and $h(x) = (x - 1)^d \bmod IA'$. After replacing $A$ by $A'$ we may assume that the factorization is defined over $A$. In that case we see that $b_1 = g(y) \in B$ is a lift of $\overline{e}^d = \overline{e}$ and $b_2 = h(y) \in B$ is a lift of $(\overline{e} - 1)^d = (-1)^d (1 - \overline{e})^d = (-1)^d(1 - \overline{e})$ and moreover $b_1b_2 = 0$. Thus $(b_1, b_2)B/IB = B/IB$ and $V(b_1, b_2) \subset \operatorname{Spec}(B)$ is disjoint from $V(IB)$. Since $\operatorname{Spec}(B) \to \operatorname{Spec}(A)$ is closed (see Algebra, Lemmas Going up for integral ring maps and Going up and closed maps of spectra) we can find an $a \in A$ which maps to an invertible element of $A/I$ whose image in $B$ lies in $(b_1, b_2)$, see Lemma Separating a closed image from another closed subset. After replacing $A$ by the localization $A_a$ we get that $(b_1, b_2) = B$. Then $\operatorname{Spec}(B) = D(b_1) \amalg D(b_2)$; disjoint union because $b_1b_2 = 0$ and covers $\operatorname{Spec}(B)$ because $(b_1, b_2) = B$. Let $e \in B$ be the idempotent corresponding to the open and closed subset $D(b_1)$, see Algebra, Lemma Product decompositions from disjoint closed subsets. Since $b_1$ is a lift of $\overline{e}$ and $b_2$ is a lift of $\pm (1 - \overline{e})$ we conclude that $e$ is a lift of $\overline{e}$ by the uniqueness statement in Algebra, Lemma Product decompositions from disjoint closed subsets. $\square$
Definition. Henselian pairs
A henselian pair is a pair $(A, I)$ satisfying
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$I$ is contained in the Jacobson radical of $A$, and
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for any monic polynomial $f \in A[T]$ and factorization $\overline{f} = g_0h_0$ with $g_0, h_0 \in A/I[T]$ monic generating the unit ideal in $A/I[T]$, there exists a factorization $f = gh$ in $A[T]$ with $g, h$ monic and $g_0 = \overline{g}$ and $h_0 = \overline{h}$.
Lemma. Derived commutative algebra
Let $(A, I)$ be a Zariski pair. Let $A \to B$ be a flat, integral, finitely presented ring map such that $A/I \to B/IB$ is an isomorphism. Then $A \to B$ is an isomorphism.
Proof. The ring map $A \to B$ is finite by Algebra, Lemma Criteria for integral extensions and finite algebras. Hence $B$ is finitely presented as an $A$-module by Algebra, Lemma Finite presentation and finite algebras. Hence $B$ is a finite locally free $A$-module by Algebra, Lemma Characterizations of finite projective modules. Since the module $B$ has rank $1$ along $V(I)$ (see rank function described in Algebra, Lemma Characterizations of finite projective modules), and as $(A, I)$ is a Zariski pair, we conclude that the rank is $1$ everywhere. It follows that $A \to B$ is an isomorphism: it is a pleasant exercise to show that a ring map $R \to S$ such that $S$ is a locally free $R$-module of rank $1$ is an isomorphism (hint: look at local rings). $\square$
Lemma. Separating a finite closed component through integral closure
Let $(A, I)$ be a pair. Let $A \to B$ be a finite type ring map such that $B/IB = C_1 \times C_2$ with $A/I \to C_1$ finite. Let $B'$ be the integral closure of $A$ in $B$. Then we can write $B'/IB' = C_1 \times C'_2$ such that the map $B'/IB' \to B/IB$ preserves product decompositions and there exists a $g \in B'$ mapping to $(1, 0)$ in $C_1 \times C'_2$ with $B'_g \to B_g$ an isomorphism.
Proof. Observe that $A \to B$ is quasi-finite at every prime of the closed subset $T = \operatorname{Spec}(C_1) \subset \operatorname{Spec}(B)$ (this follows by looking at fibre rings, see Algebra, Definition Finite algebras). Consider the diagram of topological spaces $$\begin{gathered}\begin{matrix}\operatorname{Spec}(B) & \phantom{X} & \operatorname{Spec}(B') \\ \phantom{X} & \operatorname{Spec}(A)\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(B) & \xrightarrow{\phi} \operatorname{Spec}(B') \\ \operatorname{Spec}(B) & \xrightarrow{\psi} \operatorname{Spec}(A) \\ \operatorname{Spec}(B') & \xrightarrow{\psi'} \operatorname{Spec}(A)\end{aligned}\end{gathered}$$ By Algebra, Theorem Zariski's main theorem in affine algebra (uncovered prerequisite) for every $\mathfrak p \in T$ there is a $h_\mathfrak p \in B'$, $h_\mathfrak p \not \in \mathfrak p$ such that $B'_h \to B_h$ is an isomorphism. The union $U = \bigcup D(h_\mathfrak p)$ gives an open $U \subset \operatorname{Spec}(B')$ such that $\phi^{-1}(U) \to U$ is a homeomorphism and $T \subset \phi^{-1}(U)$. Since $T$ is open in $\psi^{-1}(V(I))$ we conclude that $\phi(T)$ is open in $U \cap (\psi')^{-1}(V(I))$. Thus $\phi(T)$ is open in $(\psi')^{-1}(V(I))$. On the other hand, since $C_1$ is finite over $A/I$ it is finite over $B'$. Hence $\phi(T)$ is a closed subset of $\operatorname{Spec}(B')$ by Algebra, Lemmas Going up and closed maps of spectra and Going up for integral ring maps. We conclude that $\operatorname{Spec}(B'/IB') \supset \phi(T)$ is open and closed. By Algebra, Lemma A disjoint spectrum and a product of rings (uncovered prerequisite) we get a corresponding product decomposition $B'/IB' = C'_1 \times C'_2$. The map $B'/IB' \to B/IB$ maps $C'_1$ into $C_1$ and $C'_2$ into $C_2$ as follows. The set $\phi(T)$ lies in $U$, where $\phi$ is a homeomorphism with isomorphic local rings, so its inverse image is exactly $T$. Hence the pulled-back characteristic idempotent of $\operatorname{Spec}(C'_1)$ is the characteristic idempotent of $T$, namely $(1,0)$ in $C_1\times C_2$. This is precisely the asserted compatibility of the two product decompositions. Pick a $g \in B'$ mapping to $(1, 0)$ in $C'_1 \times C'_2$ such that $D(g) \subset U$; this is possible because $\operatorname{Spec}(C'_1)$ and $\operatorname{Spec}(C'_2)$ are disjoint and closed in $\operatorname{Spec}(B')$ and $\operatorname{Spec}(C'_1)$ is contained in $U$. Then $B'_g \to B_g$ defines a homeomorphism on spectra and an isomorphism on local rings (by our choice of $U$ above). Hence it is an isomorphism, as follows for example from Algebra, Lemma Detecting a zero module by localization. Finally, it follows that $C'_1 = C_1$ and the proof is complete. $\square$
Lemma. A monic annihilating polynomial with prescribed reduction
Let $(A, I)$ be a Zariski pair. Let $A \to B$ be a finite ring map. Assume
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$B/IB = B_1 \times B_2$ is a product of $A/I$-algebras
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$A/I \to B_1/IB_1$ is surjective,
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$b \in B$ maps to $(1, 0)$ in the product.
Then there exists a monic $f \in A[x]$ with $f(b) = 0$ and $f \bmod I = (x - 1)x^d$ for some $d \geq 1$.
Proof. By Lemma Lifting an idempotent after localization we can find an étale ring map $A \to A'$ inducing an isomorphism $A/I \to A'/IA'$ such that $B' = B \otimes_A A'$ contains an idempotent $e'$ lifting the image of $b$ in $B'/IB'$. Consider the corresponding $A'$-algebra decomposition $$B' = B'_1 \times B'_2$$ which is compatible with the one given in the lemma upon reduction modulo $I$. The map $A' \to B'_1$ is surjective modulo $IA'$. By Nakayama's lemma (Algebra, Lemma Nakayama's lemma) we can find $i \in IA'$ such that after replacing $A'$ by $A'_{1 + i}$ the map $A' \to B'_1$ is surjective. Observe that the image $b'_1 \in B'_1$ of $b$ satisfies $b'_1 - 1 \in IB'_1$. Thus we may pick $a' \in IA'$ mapping to $b'_1 - 1$. On the other hand, the image $b'_2 \in B'_2$ of $b$ is in $IB'_2$. By Algebra, Lemma Integral extensions (uncovered prerequisite) there exist a monic polynomial $g(x) = x^d + \sum a'_j x^j$ of degree $d$ with $a'_j \in IA'$ such that $g(b'_2) = 0$ in $B'_2$. Thus the image $b' = (b'_1, b'_2) \in B'$ of $b$ is a root of the polynomial $(x - 1 - a')g(x)$. We conclude that $$(b' - 1)(b')^d \in \sum\nolimits_{j = 0, \ldots, d} IA' \cdot (b')^j$$ We claim that this implies $$(b - 1)b^d \in \sum\nolimits_{j = 0, \ldots, d} I \cdot b^j$$ in $B$. For this it is enough to see that the ring map $A \to A'$ is faithfully flat, because the condition is that the image of $(b - 1)b^d$ is zero in $B/\sum_{j = 0, \ldots, d} Ib^j$ (use Algebra, Lemma Universal injectivity of a faithfully flat ring map (uncovered prerequisite)). The map $A \to A'$ flat because it is étale (Algebra, Lemma Étale morphisms). On the other hand, the induced map on spectra is open (see Algebra, Proposition Openness of flat finitely presented maps and use previous lemma referenced) and the image contains $V(I)$. Since $I$ is contained in the Jacobson radical of $A$ the image is all of $\operatorname{Spec}(A)$ by Algebra, Lemma Commutative algebra (uncovered prerequisite). Thus $A \to A'$ is faithfully flat by Algebra, Lemma Faithfully flat ring maps, and we conclude. $\square$
Lemma. Localizing a commutative ring diagram
Suppose given a cartesian diagram of rings $$\begin{gathered}\begin{matrix}R & R' \\ B & B'\end{matrix} \\[6pt] \begin{aligned}R' & \xrightarrow{t} R \\ B & \xrightarrow{s} R \\ B' & \longrightarrow R' \\ B' & \longrightarrow B\end{aligned}\end{gathered}$$ i.e., $B' = B \times_R R'$. If $h \in B'$ corresponds to $g \in B$ and $f \in R'$ such that $s(g) = t(f)$, then the diagram $$\begin{gathered}\begin{matrix}R_{s(g)} = R_{t(f)} & (R')_f \\ B_g & (B')_h\end{matrix} \\[6pt] \begin{aligned}(R')_f & \xrightarrow{t} R_{s(g)} = R_{t(f)} \\ B_g & \xrightarrow{s} R_{s(g)} = R_{t(f)} \\ (B')_h & \longrightarrow (R')_f \\ (B')_h & \longrightarrow B_g\end{aligned}\end{gathered}$$ is cartesian too.
Proof. The equality $B' = B \times_R R'$ tells us that $$0 \to B' \to B \oplus R' \xrightarrow{s, -t} R$$ is an exact sequence of $B'$-modules. We have $B_g = B_h$, $R'_f = R'_h$, and $R_{s(g)} = R_{t(f)} = R_h$ as $B'$-modules. By exactness of localization (Algebra, Proposition Exactness of localization (uncovered prerequisite)) we find that $$0 \to B'_h \to B_g \oplus R'_f \xrightarrow{s, -t} R_{s(g)} = R_{t(f)}$$ is an exact sequence. This proves the lemma. $\square$
Lemma. Proper morphisms and tensor products and direct sums
Let $A, A', B, B', I$ be as in Situation Modules and tensor products and direct sums. Let $(D, C', \varphi)$ be a system consisting of an $B$-algebra $D$, a $A'$-algebra $C'$ and an isomorphism $D \otimes_B A \to C'/IC' = C$. Set $D' = D \times_C C'$ (as in Lemma Modules and tensor products and direct sums). Then
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$B' \to D'$ is finite type if and only if $B \to D$ and $A' \to C'$ are finite type,
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$B' \to D'$ is flat if and only if $B \to D$ and $A' \to C'$ are flat,
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$B' \to D'$ is flat and of finite presentation if and only if $B \to D$ and $A' \to C'$ are flat and of finite presentation,
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$B' \to D'$ is smooth if and only if $B \to D$ and $A' \to C'$ are smooth,
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$B' \to D'$ is étale if and only if $B \to D$ and $A' \to C'$ are étale.
Moreover, if $D'$ is a flat $B'$-algebra, then $D' \to (D' \otimes_{B'} B) \times_{(D' \otimes_{B'} A)} (D' \otimes_{B'} A')$ is an isomorphism. In this way the category of flat $B'$-algebras is equivalent to the categories of systems $(D, C', \varphi)$ as above with $D$ flat over $B$ and $C'$ flat over $A'$.
Proof. The implication "$\Rightarrow$" follows from Algebra, Lemmas Base change for finite algebras (uncovered prerequisite), Base change of flat modules (uncovered prerequisite), Base change of smooth ring maps (uncovered prerequisite), and Étale morphisms because we have $D' \otimes_{B'} B = D$ and $D' \otimes_{B'} A' = C'$ by Lemma Modules and tensor products and direct sums. Thus it suffices to prove the implications in the other direction.
Ad (1). Assume $D$ of finite type over $B$ and $C'$ of finite type over $A'$. We will use the results of Lemma Modules and tensor products and direct sums without further mention. Choose generators $x_1, \ldots, x_r$ of $D$ over $B$ and generators $y_1, \ldots, y_s$ of $C'$ over $A'$. Using that $D = D' \otimes_{B'} B$ and $B' \to B$ is surjective we can find $u_1, \ldots, u_r \in D'$ mapping to $x_1, \ldots, x_r$ in $D$. Using that $C' = D' \otimes_{B'} A'$ we can find $v_1, \ldots, v_t \in D'$ such that $y_i = \sum v_j \otimes a'_{ij}$ for some $a'_{ij} \in A'$. In particular, the images of $v_j$ in $C'$ generate $C'$ as an $A'$-algebra. Set $N = r + t$ and consider the cube of rings $$\begin{gathered}\begin{matrix}A[x_1, \ldots, x_N] & \phantom{X} & A'[x_1, \ldots, x_N] \\ \phantom{X} & A & \phantom{X} & A' \\ B[x_1, \ldots, x_N] & \phantom{X} & B'[x_1, \ldots, x_N] \\ \phantom{X} & B & \phantom{X} & B'\end{matrix} \\[6pt] \begin{aligned}A'[x_1, \ldots, x_N] & \longrightarrow A[x_1, \ldots, x_N] \\ A & \longrightarrow A[x_1, \ldots, x_N] \\ A' & \longrightarrow A \\ A' & \longrightarrow A'[x_1, \ldots, x_N] \\ B[x_1, \ldots, x_N] & \longrightarrow A[x_1, \ldots, x_N] \\ B'[x_1, \ldots, x_N] & \longrightarrow A'[x_1, \ldots, x_N] \\ B'[x_1, \ldots, x_N] & \longrightarrow B[x_1, \ldots, x_N] \\ B & \longrightarrow A \\ B & \longrightarrow B[x_1, \ldots, x_N] \\ B' & \longrightarrow B \\ B' & \longrightarrow A' \\ B' & \longrightarrow B'[x_1, \ldots, x_N]\end{aligned}\end{gathered}$$ Observe that the back square is cartesian as well. Consider the ring map $$B'[x_1, \ldots, x_N] \to D',\quad x_i \mapsto u_i \quad\text{and}\quad x_{r + j} \mapsto v_j.$$ Then we see that the induced maps $B[x_1, \ldots, x_N] \to D$ and $A'[x_1, \ldots, x_N] \to C'$ are surjective, in particular finite. We conclude from Lemma Modules and tensor products and direct sums that $B'[x_1, \ldots, x_N] \to D'$ is finite, which implies that $D'$ is of finite type over $B'$ for example by Algebra, Lemma Composition of finite-type ring maps.
Ad (2). The implication "$\Leftarrow$" follows from Lemma Relative flat modules over a ring fibre product. Moreover, the final statement follows from the final statement of Lemma Relative flat modules over a ring fibre product.
Ad (3). Assume $B \to D$ and $A' \to C'$ are flat and of finite presentation. The flatness of $B' \to D'$ we've seen in (2). We know $B' \to D'$ is of finite type by (1). Choose a surjection $B'[x_1, \ldots, x_N] \to D'$. By Algebra, Lemma Finite presentation and finite algebras the ring $D$ is of finite presentation as a $B[x_1, \ldots, x_N]$-module and the ring $C'$ is of finite presentation as a $A'[x_1, \ldots, x_N]$-module. By Lemma Finite presentation under flat module patching we see that $D'$ is of finite presentation as a $B'[x_1, \ldots, x_N]$-module, i.e., $B' \to D'$ is of finite presentation.
Ad (4). Assume $B \to D$ and $A' \to C'$ smooth. By (3) we see that $B' \to D'$ is flat and of finite presentation. By Algebra, Lemma Smoothness from flatness and smooth fibres (uncovered prerequisite) it suffices to check that $D' \otimes_{B'} k$ is smooth for any field $k$ over $B'$. If the composition $J \to B' \to k$ is zero, then $B' \to k$ factors as $B' \to B \to k$ and we see that $$D' \otimes_{B'} k = D' \otimes_{B'} B \otimes_B k = D \otimes_B k$$ is smooth as $B \to D$ is smooth. If the composition $J \to B' \to k$ is nonzero, then there exists an $h \in J$ which does not map to zero in $k$. Then $B' \to k$ factors as $B' \to B'_h \to k$. Observe that $h$ maps to zero in $B$, hence $B_h = 0$. Thus by Lemma Localizing a commutative ring diagram we have $B'_h = A'_h$ and we get $$D' \otimes_{B'} k = D' \otimes_{B'} B'_h \otimes_{B'_h} k = C'_h \otimes_{A'_h} k$$ is smooth as $A' \to C'$ is smooth.
Ad (5). Assume $B \to D$ and $A' \to C'$ are étale. By (4) we see that $B' \to D'$ is smooth. As we can read off whether or not a smooth map is étale from the dimension of fibres we see that (5) holds (argue as in the proof of (4) to identify fibres -- some details omitted). $\square$
Lemma. Localizing an algebra while preserving its closed fibre
Let $A \to B$ be a ring map and $J \subset B$ an ideal. If $A \to B$ is étale at every prime of $V(J)$, then there exists a $g \in B$ mapping to an invertible element of $B/J$ such that $A' = B_g$ is étale over $A$.
Proof. The set of points of $\operatorname{Spec}(B)$ where $A \to B$ is not étale is a closed subset of $\operatorname{Spec}(B)$, see Algebra, Definition Étale ring maps. Write this as $V(J')$ for some ideal $J' \subset B$. Then $V(J') \cap V(J) = \emptyset$ hence $J + J' = B$ by Algebra, Lemma The Zariski topology on an affine spectrum. Write $1 = f + g$ with $f \in J$ and $g \in J'$. Then $g$ works. $\square$
Lemma. Pullback of derived tensor products and Tor amplitude
Let $A \to B$ be a ring map. Let $a, b \in \mathbf{Z}$. Let $K^\bullet$ be a complex of $A$-modules with tor amplitude in $[a, b]$. Then $K^\bullet \otimes_A^{\mathbf{L}} B$ as a complex of $B$-modules has tor amplitude in $[a, b]$.
Proof. By Lemma Derived tensor products and Tor amplitude we can find a quasi-isomorphism $E^\bullet \to K^\bullet$ where $E^\bullet$ is a complex of flat $A$-modules with $E^i = 0$ for $i \not \in [a, b]$. Then $E^\bullet \otimes_A B$ computes $K^\bullet \otimes_A ^{\mathbf{L}} B$ by construction and each $E^i \otimes_A B$ is a flat $B$-module by Algebra, Lemma Base change of flat modules (uncovered prerequisite). Hence we conclude by Lemma Derived tensor products and Tor amplitude. $\square$
Lemma. Derived categories
Let $K = (K_n^\bullet)$ be an object of $D(\textit{Ab}(\mathbf{N}))$. There exists a canonical distinguished triangle $$R\varprojlim K \to \prod\nolimits_n K_n^\bullet \to \prod\nolimits_n K_n^\bullet \to R\varprojlim K[1]$$ in $D(\textit{Ab})$. In other words, $R\varprojlim K$ is a derived limit of the inverse system $(K_n^\bullet)$ of $D(\textit{Ab})$, see Derived Categories, Definition Derived categories.
Proof. Suppose that for each $p$ the inverse system $(K_n^p)$ is right acyclic for $\varprojlim$. By Lemma Computation of a derived inverse limit this gives a short exact sequence $$0 \to \varprojlim_n K^p_n \to \prod\nolimits_n K^p_n \to \prod\nolimits_n K^p_n \to 0$$ for each $p$. Since the complex consisting of $\varprojlim_n K^p_n$ computes $R\varprojlim K$ by Lemma Computation of a derived inverse limit we see that the lemma holds in this case.
Next, assume $K = (K_n^\bullet)$ is general. By Lemma Computation of a derived inverse limit there is a quasi-isomorphism $K \to L$ in $D(\textit{Ab}(\mathbf{N}))$ such that $(L_n^p)$ is acyclic for each $p$. Then $\prod K_n^\bullet$ is quasi-isomorphic to $\prod L_n^\bullet$ as products are exact in $\textit{Ab}$, whence the result for $L$ (proved above) implies the result for $K$. $\square$
Lemma. Derived categories
Let $R$ be a ring. Let $\mathfrak p \subset R$ be a prime ideal. Let $K^\bullet$ be a pseudo-coherent complex of $R$-modules. Assume that for some $i \in \mathbf{Z}$ the map $$H^i(K^\bullet) \otimes_R \kappa(\mathfrak p) \longrightarrow H^i(K^\bullet \otimes_R^{\mathbf{L}} \kappa(\mathfrak p))$$ is surjective. Then there exists an $f \in R$, $f \not \in \mathfrak p$ such that $\tau_{\geq i + 1}(K^\bullet \otimes_R R_f)$ is a perfect object of $D(R_f)$ with tor amplitude in $[i + 1, \infty]$ and a canonical isomorphism $$K^\bullet \otimes_R R_f \cong \tau_{\leq i}(K^\bullet \otimes_R R_f) \oplus \tau_{\geq i + 1}(K^\bullet \otimes_R R_f)$$ in $D(R_f)$.
Proof. In this proof all tensor products are over $R$ and we write $\kappa = \kappa(\mathfrak p)$. We may assume that $K^\bullet$ is a bounded above complex of finite free $R$-modules. Let us inspect what is happening in degree $i$: $$\ldots \to K^{i - 1} \xrightarrow{d^{i - 1}} K^i \xrightarrow{d^i} K^{i + 1} \to \ldots$$ Let $0 \subset V \subset W \subset K^i \otimes \kappa$ be defined by the formulas $$V = \operatorname{Im}\left( K^{i - 1} \otimes \kappa \to K^i \otimes \kappa \right) \quad\text{and}\quad W = \operatorname{Ker}\left( K^i \otimes \kappa \to K^{i + 1} \otimes \kappa \right)$$ Set $\dim(V) = r$, $\dim(W/V) = s$, and $\dim(K^i \otimes \kappa/W) = t$. We can pick $x_1, \ldots, x_r \in K^{i - 1}$ which map by $d^{i - 1}$ to a basis of $V$. By our assumption we can pick $y_1, \ldots, y_s \in \operatorname{Ker}(d^i)$ mapping to a basis of $W/V$. Finally, choose $z_1, \ldots, z_t \in K^i$ mapping to a basis of $K^i \otimes \kappa/W$. Then we see that the elements $d^i(z_1), \ldots, d^i(z_t) \in K^{i + 1}$ are linearly independent in $K^{i + 1} \otimes_R \kappa$. By Algebra, Lemma Flatness of a cokernel (uncovered prerequisite) we may after replacing $R$ by $R_f$ for some $f \in R$, $f \not \in \mathfrak p$ assume that
-
$d^i(x_a), y_b, z_c$ is an $R$-basis of $K^i$,
-
$d^i(z_1), \ldots, d^i(z_t)$ are $R$-linearly independent in $K^{i + 1}$, and
-
the quotient $E^{i + 1} = K^{i + 1}/\sum Rd^i(z_c)$ is finite projective.
Since $d^i$ annihilates $d^{i - 1}(x_a)$ and $y_b$, we deduce from condition (2) that $E^{i + 1} = \operatorname{Coker}(d^i : K^i \to K^{i + 1})$. Thus we see that $$\tau_{\geq i + 1}K^\bullet = (\ldots \to 0 \to E^{i + 1} \to K^{i + 2} \to \ldots)$$ is a bounded complex of finite projective modules sitting in degrees $[i + 1, b]$ for some $b$. Thus $\tau_{\geq i + 1}K^\bullet$ is perfect of amplitude $[i + 1, b]$. Since $\tau_{\leq i}K^\bullet$ has no cohomology in degrees $> i$, we may apply Lemma Derived commutative algebra to the distinguished triangle $$\tau_{\leq i}K^\bullet \to K^\bullet \to \tau_{\geq i + 1}K^\bullet \to (\tau_{\leq i}K^\bullet)[1]$$ (Derived Categories, Remark Derived categories) to conclude. $\square$
Lemma. Derived tensor products, Tor amplitude and local algebra
Let $A \to B$ be a ring map. Let $K^\bullet$ be a complex of $B$-modules. Let $a, b \in \mathbf{Z}$. The following are equivalent
-
$K^\bullet$ has tor amplitude in $[a, b]$ as a complex of $A$-modules,
-
$K^\bullet_\mathfrak q$ has tor amplitude in $[a, b]$ as a complex of $A_\mathfrak p$-modules for every prime $\mathfrak q \subset B$ with $\mathfrak p = A \cap \mathfrak q$,
-
$K^\bullet_\mathfrak m$ has tor amplitude in $[a, b]$ as a complex of $A_\mathfrak p$-modules for every maximal ideal $\mathfrak m \subset B$ with $\mathfrak p = A \cap \mathfrak m$.
Proof. Assume (3) and let $M$ be an $A$-module. Then $H^i = H^i(K^\bullet \otimes_A^\mathbf{L} M)$ is a $B$-module and $(H^i)_\mathfrak m = H^i(K^\bullet_\mathfrak m \otimes_{A_\mathfrak p}^\mathbf{L} M_\mathfrak p)$. Hence $H^i = 0$ for $i \not \in [a, b]$ by Algebra, Lemma Detecting a zero module by localization. Thus (3) $\Rightarrow$ (1). We omit the proofs of (1) $\Rightarrow$ (2) and (2) $\Rightarrow$ (3). $\square$
Lemma. Lifting derived categories
Let $(K_n)$ be an inverse system of objects of $D(\textit{Ab})$. Then there exists an object $M = (M_n^\bullet)$ of $D(\textit{Ab}(\mathbf{N}))$ and isomorphisms $M_n^\bullet \to K_n$ in $D(\textit{Ab})$ such that the diagrams $$\begin{gathered}\begin{matrix}M_{n + 1}^\bullet & M_n^\bullet \\ K_{n + 1} & K_n\end{matrix} \\[6pt] \begin{aligned}M_{n + 1}^\bullet & \longrightarrow K_{n + 1} \\ M_{n + 1}^\bullet & \longrightarrow M_n^\bullet \\ M_n^\bullet & \longrightarrow K_n \\ K_{n + 1} & \longrightarrow K_n\end{aligned}\end{gathered}$$ commute in $D(\textit{Ab})$.
Proof. Namely, let $M_1^\bullet$ be a complex of abelian groups representing $K_1$. Suppose we have constructed $M_e^\bullet \to M_{e - 1}^\bullet \to \ldots \to M_1^\bullet$ and maps $\psi_i : M_i^\bullet \to K_i$ such that the diagrams in the statement of the lemma commute for all $n < e$. Then we consider the diagram $$\begin{gathered}\begin{matrix}\phantom{X} & M_n^\bullet \\ K_{n + 1} & K_n\end{matrix} \\[6pt] \begin{aligned}M_n^\bullet & \xrightarrow{\psi_n} K_n \\ K_{n + 1} & \longrightarrow K_n\end{aligned}\end{gathered}$$ in $D(\textit{Ab})$. By the definition of morphisms in $D(\textit{Ab})$ we can find a complex $M_{n + 1}^\bullet$ of abelian groups, an isomorphism $M_{n + 1}^\bullet \to K_{n + 1}$ in $D(\textit{Ab})$, and a morphism of complexes $M_{n + 1}^\bullet \to M_n^\bullet$ representing the composition $$K_{n + 1} \to K_n \xrightarrow{\psi_n^{-1}} M_n^\bullet$$ in $D(\textit{Ab})$. Thus the lemma holds by induction. $\square$
Lemma. Derived commutative algebra
With notation as in Lemma Derived categories the long exact cohomology sequence associated to the distinguished triangle breaks up into short exact sequences $$0 \to R^1\varprojlim_n H^{p - 1}(K_n^\bullet) \to H^p(R\varprojlim K) \to \varprojlim_n H^p(K_n^\bullet) \to 0$$
Proof. The long exact sequence of the distinguished triangle is $$\ldots \to H^p(R\varprojlim K) \to \prod\nolimits_n H^p(K_n^\bullet) \to \prod\nolimits_n H^p(K_n^\bullet) \to H^{p + 1}(R\varprojlim K) \to \ldots$$ The map in the middle has kernel $\varprojlim_n H^p(K_n^\bullet)$ by its explicit description given in the lemma. The cokernel of this map is $R^1\varprojlim_n H^p(K_n^\bullet)$ by Lemma Computation of a derived inverse limit. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $K^\bullet$ be a complex of $R$-modules. Let $m \in \mathbf{Z}$.
-
If $H^i(K^\bullet) = 0$ for all $i \geq m$, then $K^\bullet$ is $m$-pseudo-coherent.
-
If $H^i(K^\bullet) = 0$ for $i > m$ and $H^m(K^\bullet)$ is a finite $R$-module, then $K^\bullet$ is $m$-pseudo-coherent.
-
If $H^i(K^\bullet) = 0$ for $i > m + 1$, the module $H^{m + 1}(K^\bullet)$ is of finite presentation, and $H^m(K^\bullet)$ is of finite type, then $K^\bullet$ is $m$-pseudo-coherent.
Proof. It suffices to prove (3). Set $M = H^{m + 1}(K^\bullet)$. Note that $\tau_{\geq m + 1}K^\bullet$ is quasi-isomorphic to $M[- m - 1]$. By Lemma Pseudo-coherent complexes and modules we see that $M[- m - 1]$ is $m$-pseudo-coherent. Since we have the distinguished triangle $$(\tau_{\leq m}K^\bullet, K^\bullet, \tau_{\geq m + 1}K^\bullet)$$ (Derived Categories, Remark Derived categories) by Lemma Pseudo-coherent complexes and coherent sheaves it suffices to prove that $\tau_{\leq m}K^\bullet$ is pseudo-coherent. By assumption $H^m(\tau_{\leq m}K^\bullet)$ is a finite type $R$-module. Hence we can find a finite free $R$-module $E$ and a map $E \to \operatorname{Ker}(d_K^m)$ such that the composition $E \to \operatorname{Ker}(d_K^m) \to H^m(\tau_{\leq m}K^\bullet)$ is surjective. Then $E[-m] \to \tau_{\leq m}K^\bullet$ witnesses the fact that $\tau_{\leq m}K^\bullet$ is $m$-pseudo-coherent. $\square$
Lemma. Projective, locally free modules and flatness
Let $R$ be a domain. Any flat $R$-module is torsion free.
Proof. If $x \in R$ is nonzero, then $x : R \to R$ is injective, and hence if $M$ is flat over $R$, then $x : M \to M$ is injective. Thus if $M$ is flat over $R$, then $M$ is torsion free. $\square$
Lemma. Base change for derived tensor products, Tor amplitude and flatness
Let $R \to R'$ be a ring map. If $K^\bullet$ is a K-flat complex of $R$-modules, then $K^\bullet \otimes_R R'$ is a K-flat complex of $R'$-modules.
Proof. Follows from the definitions and the fact that $(K^\bullet \otimes_R R') \otimes_{R'} L^\bullet = K^\bullet \otimes_R L^\bullet$ for any complex $L^\bullet$ of $R'$-modules. $\square$
Lemma. Koszul complexes and regular sequences
Let $R$ be a ring. Let $\varphi : E \to R$ be an $R$-module map. Let $f, g \in R$. Set $E' = E \oplus R$ and define $\varphi'_f, \varphi'_g, \varphi'_{fg} : E' \to R$ by $\varphi$ on $E$ and multiplication by $f, g, fg$ on $R$. The complex $K_\bullet(\varphi'_{fg})$ is homotopy equivalent to the cone of a map of complexes $$K_\bullet(\varphi'_f)[1] \longrightarrow K_\bullet(\varphi'_g).$$
Proof. By Lemma Koszul complexes, regular sequences and derived categories the complex $K_\bullet(\varphi'_f)$ is isomorphic to the cone of multiplication by $f$ on $K_\bullet(\varphi)$ and similarly for the other two cases. Hence the lemma follows from Lemma Derived categories. $\square$
Proposition. Perfect complexes
Let $R$ be a ring. For an object $K$ of $D(R)$ the following are equivalent
-
$K$ is perfect, and
-
$K$ is a compact object of $D(R)$.
Proof. Assume $K$ is perfect, i.e., $K$ is quasi-isomorphic to a bounded complex $P^\bullet$ of finite projective modules, see Definition Perfect complexes. If $E_i$ is represented by the complex $E_i^\bullet$, then $\bigoplus E_i$ is represented by the complex whose degree $n$ term is $\bigoplus E_i^n$. On the other hand, as $P^n$ is projective for all $n$ we have $\operatorname{Hom}_{D(R)}(P^\bullet, K^\bullet) = \operatorname{Hom}_{K(R)}(P^\bullet, K^\bullet)$ for every complex of $R$-modules $K^\bullet$, see Derived Categories, Lemma Derived Hom, Ext and projective and locally free modules. Thus $\operatorname{Hom}_{D(R)}(P^\bullet, E^\bullet)$ is the cohomology of the complex $$\prod \operatorname{Hom}_R(P^n, E^{n - 1}) \to \prod \operatorname{Hom}_R(P^n, E^n) \to \prod \operatorname{Hom}_R(P^n, E^{n + 1}).$$ Since $P^\bullet$ is bounded we see that we may replace the $\prod$ signs by $\bigoplus$ signs in the complex above. Since each $P^n$ is a finite $R$-module we see that $\operatorname{Hom}_R(P^n, \bigoplus_i E_i^m) = \bigoplus_i \operatorname{Hom}_R(P^n, E_i^m)$ for all $n, m$. Combining these remarks we see that the map of Derived Categories, Definition Triangulated categories is a bijection.
Conversely, assume $K$ is compact. Represent $K$ by a complex $K^\bullet$ and consider the map $$K^\bullet \longrightarrow \bigoplus\nolimits_{n \geq 0} \tau_{\geq n} K^\bullet$$ where we have used the canonical truncations, see Homology, Section The geometric construction. This makes sense as in each degree the direct sum on the right is finite. By assumption this map factors through a finite direct sum. We conclude that $K \to \tau_{\geq n} K$ is zero for at least one $n$, i.e., $K$ is in $D^{-}(R)$.
Since $K \in D^{-}(R)$ and since every $R$-module is a quotient of a free module, we may represent $K$ by a bounded above complex $K^\bullet$ of free $R$-modules, see Derived Categories, Lemma Triangulated categories (uncovered prerequisite). Note that we have $$K^\bullet = \bigcup\nolimits_{n \leq 0} \sigma_{\geq n}K^\bullet$$ where we have used the stupid truncations, see Homology, Section The geometric construction. Hence by Lemma Tensor products and direct sums we see that $1 : K^\bullet \to K^\bullet$ factors through $\sigma_{\geq n}K^\bullet \to K^\bullet$ in $D(R)$. Thus we see that $1 : K^\bullet \to K^\bullet$ factors as $$K^\bullet \xrightarrow{\varphi} L^\bullet \xrightarrow{\psi} K^\bullet$$ in $D(R)$ for some complex $L^\bullet$ which is bounded and whose terms are free $R$-modules. Say $L^i = 0$ for $i \not \in [a, b]$. Fix $a, b$ from now on. Let $c$ be the largest integer $\leq b + 1$ such that we can find a factorization of $1_{K^\bullet}$ as above with $L^i$ finite free for $i < c$. We will show by induction that $c = b + 1$. Namely, write $L^c = \bigoplus_{\lambda \in \Lambda} R$. Since $L^{c - 1}$ is finite free we can find a finite subset $\Lambda' \subset \Lambda$ such that $L^{c - 1} \to L^c$ factors through $\bigoplus_{\lambda \in \Lambda'} R \subset L^c$. Consider the map of complexes $$\pi : L^\bullet \longrightarrow (\bigoplus\nolimits_{\lambda \in \Lambda \setminus \Lambda'} R)[-c]$$ given by the projection onto the factors corresponding to $\Lambda \setminus \Lambda'$ in degree $c$. By our assumption on $K$ we see that, after possibly replacing $\Lambda'$ by a larger finite subset, we may assume that $\pi \circ \varphi = 0$ in $D(R)$. Let $(L')^\bullet \subset L^\bullet$ be the kernel of $\pi$. Since $\pi$ is surjective we get a short exact sequence of complexes, which gives a distinguished triangle in $D(R)$ (see Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories). Since $\operatorname{Hom}_{D(R)}(K, -)$ is homological (see Derived Categories, Lemma Representability of a homological functor) and $\pi \circ \varphi = 0$, we can find a morphism $\varphi' : K^\bullet \to (L')^\bullet$ in $D(R)$ whose composition with $(L')^\bullet \to L^\bullet$ gives $\varphi$. Setting $\psi'$ equal to the composition of $\psi$ with $(L')^\bullet \to L^\bullet$ we obtain a new factorization. Since $(L')^\bullet$ agrees with $L^\bullet$ except in degree $c$ and since $(L')^c = \bigoplus_{\lambda \in \Lambda'} R$ the induction step is proved.
The conclusion of the discussion of the preceding paragraph is that $1_K : K \to K$ factors as $$K \xrightarrow{\varphi} L \xrightarrow{\psi} K$$ in $D(R)$ where $L$ can be represented by a finite complex of free $R$-modules. In particular we see that $L$ is perfect. Note that $e = \varphi \circ \psi \in \text{End}_{D(R)}(L)$ is an idempotent. By Derived Categories, Lemma Derived categories (uncovered prerequisite) we see that $L = \operatorname{Ker}(e) \oplus \operatorname{Ker}(1 - e)$. The map $\varphi : K \to L$ induces an isomorphism with $\operatorname{Ker}(1 - e)$ in $D(R)$. Hence we finally conclude that $K$ is perfect by Lemma Perfect complexes and tensor products and direct sums. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a Noetherian ring. Then
-
A complex of $R$-modules $K^\bullet$ is $m$-pseudo-coherent if and only if $K^\bullet \in D^{-}(R)$ and $H^i(K^\bullet)$ is a finite $R$-module for $i \geq m$.
-
A complex of $R$-modules $K^\bullet$ is pseudo-coherent if and only if $K^\bullet \in D^{-}(R)$ and $H^i(K^\bullet)$ is a finite $R$-module for all $i$.
-
An $R$-module is pseudo-coherent if and only if it is finite.
Proof. In Algebra, Lemma Projective, locally free modules and finite algebras (uncovered prerequisite) we have seen that any finite $R$-module is pseudo-coherent. On the other hand, a pseudo-coherent module is finite, see Lemma Pseudo-coherent complexes and modules. Hence (3) holds. Suppose that $K^\bullet$ is an $m$-pseudo-coherent complex. Then there exists a bounded complex of finite free $R$-modules $E^\bullet$ such that $H^i(K^\bullet)$ is isomorphic to $H^i(E^\bullet)$ for $i > m$ and such that $H^m(K^\bullet)$ is a quotient of $H^m(E^\bullet)$. Thus it is clear that each $H^i(K^\bullet)$, $i \geq m$ is a finite module. The converse implication in (1) follows from Lemma Pseudo-coherent complexes and sheaf cohomology and part (3). Part (2) follows from (1) and Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Let $R$ be a ring. For any complex $M^\bullet$ there exists a K-flat complex $K^\bullet$ whose terms are flat $R$-modules and a quasi-isomorphism $K^\bullet \to M^\bullet$ which is termwise surjective.
Proof. Let $\mathcal{P} \subset \operatorname{Ob}(\text{Mod}_R)$ be the class of flat $R$-modules. By Derived Categories, Lemma Triangulated categories (uncovered prerequisite) there exists a system $K_1^\bullet \to K_2^\bullet \to \ldots$ and a diagram $$\begin{gathered}\begin{matrix}K_1^\bullet & K_2^\bullet & \ldots \\ \tau_{\leq 1}M^\bullet & \tau_{\leq 2}M^\bullet & \ldots\end{matrix} \\[6pt] \begin{aligned}K_1^\bullet & \longrightarrow \tau_{\leq 1}M^\bullet \\ K_1^\bullet & \longrightarrow K_2^\bullet \\ K_2^\bullet & \longrightarrow \tau_{\leq 2}M^\bullet \\ K_2^\bullet & \longrightarrow \ldots \\ \tau_{\leq 1}M^\bullet & \longrightarrow \tau_{\leq 2}M^\bullet \\ \tau_{\leq 2}M^\bullet & \longrightarrow \ldots\end{aligned}\end{gathered}$$ with the properties (1), (2), (3) listed in that lemma. These properties imply each complex $K_i^\bullet$ is a bounded above complex of flat modules. Hence $K_i^\bullet$ is K-flat by Lemma Derived tensor products, Tor amplitude and derived categories. The induced map $\mathop{\operatorname{colim}}_i K_i^\bullet \to M^\bullet$ is a quasi-isomorphism and termwise surjective by construction. The complex $\mathop{\operatorname{colim}}_i K_i^\bullet$ is K-flat by Lemma Filtered limits and derived tensor products, Tor amplitude and flatness. The terms $\mathop{\operatorname{colim}} K_i^n$ are flat because filtered colimits of flat modules are flat, see Algebra, Lemma Filtered limits and flatness. $\square$
Lemma. Derived categories
Let $R$ be a ring. Let $K^\bullet$ be a filtered complex. There exists a map $f : P^\bullet \to K^\bullet$ of filtered complexes such that
-
each $P^n$, $F^iP^n$, $\text{gr}^iP^n$ is a free $R$-module,
-
the complexes of $R$-modules $P^\bullet$, $F^iP^\bullet$, and $\text{gr}^iP^\bullet$ are K-flat,
-
$f$ induces quasi-isomorphisms $P^\bullet \to K^\bullet$, $F^iP^\bullet \to F^iK^\bullet$, and $\text{gr}^iP^\bullet \to \text{gr}^iK^\bullet$.
Proof. Let us say a filtered complex $L^\bullet$ is basic if each $L^n$, $F^iL^n$, $\text{gr}^iL^n$ is a free $R$-module and if all differentials are zero.
There exists a basic filtered complex $P_0^\bullet$ and a map $f_0 : P_0^\bullet \to K^\bullet$ of filtered complexes such that $f_0$ and $F^if_0$, $i \in \mathbf{Z}$ are surjective on cohomology. To see this set $$P_0^n = \bigoplus\nolimits_{z \in \operatorname{Ker}(d_K^n)} R \xi_z \oplus \bigoplus\nolimits_{j \in \mathbf{Z}} \bigoplus\nolimits_{z \in \operatorname{Ker}(d_{F^jK}^n)} R \xi_z$$ with zero differentials and the map $f_0$ defined by $f_0(\xi_z) = z$. As for the filtration, we set $$F^iP_0^n = \bigoplus\nolimits_{j \geq i \in \mathbf{Z}} \bigoplus\nolimits_{z \in \operatorname{Ker}(d_{F^jK}^n)} R \xi_z$$ We leave it to the reader to check that this gives $f_0 : P_0^\bullet \to K^\bullet$ as claimed.
By induction on $m \geq 0$ we are going to construct embeddings $$P_0^\bullet \subset \ldots P_m^\bullet \subset P_{m + 1}^\bullet$$ of filtered complexes and maps $f_m : P_m^\bullet \to K^\bullet$ with the following properties
-
the filtered complex $P_{m + 1}^\bullet / P_m^\bullet$ is basic,
-
the kernel of $H^n(f_m)$ and $H^n(F^if_m)$ maps to zero in $H^n(P_{m + 1}^\bullet)$ and $H^n(F^iP_{m + 1}^\bullet)$,
-
the map $f_{m + 1} : P_{m + 1}^\bullet \to K^\bullet$ extends the map $f_m$.
To to this, set $$\Omega_{n, m} = \operatorname{Ker}\left(\operatorname{Ker}(d^n_{P_m}) \to H^n(K^\bullet)\right), \text{ resp. } \Omega_{n, i, m} = \operatorname{Ker}\left(\operatorname{Ker}(d^n_{F^iP_m}) \to H^n(F^iK^\bullet)\right),$$ Note that $\Omega_{n, m}$ surjects onto the kernel of $H^n(f_m)$ and that $\Omega_{n, i, m}$ surjects onto the kernel of $H^n(F^if_m)$. For each $z \in \Omega_{n, m}$, resp. $z \in \Omega_{n, i, m}$ we choose a $y_z \in K^{n - 1}$, resp. $y_z \in F^iK^{n - 1}$ such that $d_K(y_z) = f_m(z)$. Then we set $$P^n_{m + 1} = P_m^n \oplus \bigoplus\nolimits_{z \in \Omega_{n + 1, m}} R \eta_z \oplus \bigoplus\nolimits_{j \in \mathbf{Z}} \bigoplus\nolimits_{z \in \Omega_{n + 1, j, m}} R \eta_z$$ We set $d_{P_{m + 1}}(\eta_z) = z$ and we set $f_{m + 1}(\eta_z) = y_z$. Finally, we set $$F^iP_{m + 1}^n = F^iP_m^n \oplus \bigoplus\nolimits_{j \geq i} \bigoplus\nolimits_{z \in \Omega_{n + 1, j, m}} R \eta_z$$ We leave it to the reader to check that this gives $P_m^\bullet \subset P_{m + 1}^\bullet$ and $f_{m + 1} : P_{m + 1}^\bullet \to K^\bullet$ as claimed.
At this point we simply take $$P^\bullet = \bigcup P_m^\bullet$$ as a filtered complex with map $f : P^\bullet \to K^\bullet$ given by $\bigcup f_m$.
Part (1) of the statement of the lemma holds because $P^n$ as a filtered module is isomorphic to the direct sum of $P_0^n$ and $P_{m + 1}^n/P_m^n$ for $m \geq 0$. Small detail omitted.
Part (3) of the statement. Observe that $H^n(P^\bullet) = \mathop{\operatorname{colim}} H^n(P_m^\bullet)$. The map $f_0$ is surjective on cohomology; whence the same holds for each $f_m$. For each $m$ by construction the embedding $P_m^\bullet \subset P_{m + 1}^\bullet$ kills the kernel of $H^n(f_m)$. Combining these facts the reader easily concludes that $H^n(f)$ is an isomorphism. Similarly for $H^n(F^if)$. Then also $H^n(\text{gr}^if)$ must be an isomorphism because of the short exact sequence $0 \to F^{i + 1} \to F^i \to \text{gr}^i \to 0$ (of functors on the category of filtered complexes, say). Small detail omitted.
Part (2) of the statement. To see that $P^\bullet$ is K-flat, by Lemma Filtered limits and derived tensor products, Tor amplitude and flatness, it suffices to show that $P_m^\bullet$ is K-flat. By Lemma Derived tensor products, Tor amplitude and flatness and induction it suffices to note that a complex with zero differentials and free terms is K-flat. The same argument works to show that $F^iP^\bullet$ is K-flat for all $i \in \mathbf{Z}$. Finally, we see that $\text{gr}^iP^\bullet$ is K-flat by another application of Lemma Derived tensor products, Tor amplitude and flatness. $\square$
Lemma. Filtered limits and perfect complexes and derived categories
Let $R = \mathop{\operatorname{colim}}_{i \in I} R_i$ be a filtered colimit of rings.
-
Given a perfect $K$ in $D(R)$ there exists an $i \in I$ and a perfect $K_i$ in $D(R_i)$ such that $K \cong K_i \otimes_{R_i}^\mathbf{L} R$ in $D(R)$.
-
Given $0 \in I$ and $K_0, L_0 \in D(R_0)$ with $K_0$ perfect, we have $$\operatorname{Hom}_{D(R)}(K_0 \otimes_{R_0}^\mathbf{L} R, L_0 \otimes_{R_0}^\mathbf{L} R) = \mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{D(R_i)}(K_0 \otimes_{R_0}^\mathbf{L} R_i, L_0 \otimes_{R_0}^\mathbf{L} R_i)$$
In other words, the triangulated category of perfect complexes over $R$ is the colimit of the triangulated categories of perfect complexes over $R_i$.
Proof. We will use the results of Algebra, Lemmas Filtered limits and proper morphisms and modules and Finite module presentations in a filtered colimit without further mention. These lemmas in particular say that the category of finitely presented $R$-modules is the colimit of the categories of finitely presented $R_i$-modules. Since finite projective modules can be characterized as summands of finite free modules (Algebra, Lemma Characterizations of finite projective modules) we see that the same is true for the category of finite projective modules. This proves (1) by our definition of perfect objects of $D(R)$.
To prove (2) we may represent $K_0$ by a bounded complex $K_0^\bullet$ of finite projective $R_0$-modules. We may represent $L_0$ by a K-flat complex $L_0^\bullet$ (Lemma Derived tensor products, Tor amplitude and flatness). Then we have $$\operatorname{Hom}_{D(R)}(K_0 \otimes_{R_0}^\mathbf{L} R, L_0 \otimes_{R_0}^\mathbf{L} R) = \operatorname{Hom}_{K(R)}(K_0^\bullet \otimes_{R_0} R, L_0^\bullet \otimes_{R_0} R)$$ by Derived Categories, Lemma Derived Hom, Ext and projective and locally free modules. Similarly for the $\operatorname{Hom}$ with $R$ replaced by $R_i$. Since in the right hand side only a finite number of terms are involved, since $$\operatorname{Hom}_R(K_0^p \otimes_{R_0} R, L_0^q \otimes_{R_0} R) = \mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{R_i}(K_0^p \otimes_{R_0} R_i, L_0^q \otimes_{R_0} R_i)$$ by the lemmas cited at the beginning of the proof, and since filtered colimits are exact (Algebra, Lemma Filtered limits and commutative algebra (uncovered prerequisite)) we conclude that (2) holds as well. $\square$
Definition. Tor-independent pairs
Let $R$ be a ring. Let $A$, $B$ be $R$-algebras. We say $A$ and $B$ are Tor independent over $R$ if $\text{Tor}_p^R(A, B) = 0$ for all $p > 0$.
Lemma. Base change for derived categories
Let $R \to A$ be a ring map. Let $f : L^\bullet \to N^\bullet$ be a map of complexes of $A$-modules. Then $f$ induces a transformation of functors $$1 \otimes f :
- \otimes_A^\mathbf{L} L^\bullet \longrightarrow
- \otimes_A^\mathbf{L} N^\bullet$$ If $f$ is a quasi-isomorphism, then $1 \otimes f$ is an isomorphism of functors.
Proof. Since the functors are computing by evaluating on K-flat complexes $K^\bullet$ we can simply use the functoriality $$\text{Tot}(K^\bullet \otimes_R L^\bullet) \to \text{Tot}(K^\bullet \otimes_R N^\bullet)$$ to define the transformation. The last statement follows from Lemma Derived tensor products, Tor amplitude and flatness. $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Let $R$ be a ring. If $K^\bullet$, $L^\bullet$ are K-flat complexes of $R$-modules, then $\text{Tot}(K^\bullet \otimes_R L^\bullet)$ is a K-flat complex of $R$-modules.
Proof. Follows from the isomorphism $$\text{Tot}(M^\bullet \otimes_R \text{Tot}(K^\bullet \otimes_R L^\bullet))
\text{Tot}(\text{Tot}(M^\bullet \otimes_R K^\bullet) \otimes_R L^\bullet)$$ and the definition. $\square$
Lemma. Base change for derived categories
The construction above is independent of choices and defines an exact functor of triangulated categories $- \otimes_R^\mathbf{L} N^\bullet : D(R) \to D(A)$. There is a functorial isomorphism $$E^\bullet \otimes_R^\mathbf{L} N^\bullet = (E^\bullet \otimes_R^\mathbf{L} A) \otimes_A^\mathbf{L} N^\bullet$$ for $E^\bullet$ in $D(R)$.
Proof. To prove the existence of the derived functor $- \otimes_R^\mathbf{L} N^\bullet$ we use the general theory developed in Derived Categories, Section Derived categories. Set $\mathcal{D} = K(R)$ and $\mathcal{D}' = D(A)$. Let us write $F : \mathcal{D} \to \mathcal{D}'$ the exact functor of triangulated categories defined by the rule $F(M^\bullet) = \text{Tot}(M^\bullet \otimes_R N^\bullet)$. To prove the stated properties of $F$ use Lemmas Derived tensor products, Tor amplitude and derived categories and Derived tensor products, Tor amplitude and derived categories. We let $S$ be the set of quasi-isomorphisms in $\mathcal{D} = K(R)$. This gives a situation as in Derived Categories, Situation Derived tensor products, Tor amplitude and derived categories so that Derived Categories, Definition Derived tensor products, Tor amplitude and derived categories applies. We claim that $LF$ is everywhere defined. This follows from Derived Categories, Lemma Triangulated categories (uncovered prerequisite) with $\mathcal{P} \subset \operatorname{Ob}(\mathcal{D})$ the collection of K-flat complexes: (1) follows from Lemma Derived tensor products, Tor amplitude and flatness and (2) follows from Lemma Derived tensor products, Tor amplitude and derived categories. Thus we obtain a derived functor $$LF : D(R) = S^{-1}\mathcal{D} \longrightarrow \mathcal{D}' = D(A)$$ see Derived Categories, Equation (Triangulated categories). Finally, Derived Categories, Lemma Triangulated categories (uncovered prerequisite) guarantees that $LF(K^\bullet) = F(K^\bullet) = \text{Tot}(K^\bullet \otimes_R N^\bullet)$ when $K^\bullet$ is K-flat, i.e., $LF$ is indeed computed in the way described above. Moreover, by Lemma Base change for derived tensor products, Tor amplitude and flatness the complex $K^\bullet \otimes_R A$ is a K-flat complex of $A$-modules. Hence $$(K^\bullet \otimes_R^\mathbf{L} A) \otimes_A^\mathbf{L} N^\bullet = \text{Tot}((K^\bullet \otimes_R A) \otimes_A N^\bullet) = \text{Tot}(K^\bullet \otimes_A N^\bullet) = K^\bullet \otimes_A^\mathbf{L} N^\bullet$$ which proves the final statement of the lemma. $\square$
Lemma. Tensor products and direct sums
Let $R$ be a ring. Let $K^\bullet, L^\bullet$ be complexes of $R$-modules. There is a canonical isomorphism $$K^\bullet \otimes_R^\mathbf{L} L^\bullet \longrightarrow L^\bullet \otimes_R^\mathbf{L} K^\bullet$$ functorial in both complexes which uses a sign of $(-1)^{pq}$ for the map $K^p \otimes_R L^q \to L^q \otimes_R K^p$ (see proof for explanation).
Proof. We may and do replace the complexes by K-flat complexes $K^\bullet$ and $L^\bullet$ and then we use the commutativity constraint discussed in Section Derived commutative algebra. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $A \to B$ be a finite map of finite type $R$-algebras. Let $m \in \mathbf{Z}$. Let $K^\bullet$ be a complex of $B$-modules. Then $K^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent) relative to $R$ if and only if $K^\bullet$ seen as a complex of $A$-modules is $m$-pseudo-coherent (pseudo-coherent) relative to $R$.
Proof. Choose a surjection $R[x_1, \ldots, x_n] \to A$. Choose $y_1, \ldots, y_m \in B$ which generate $B$ over $A$. As $A \to B$ is finite each $y_i$ satisfies a monic equation with coefficients in $A$. Hence we can find monic polynomials $P_j(T) \in R[x_1, \ldots, x_n][T]$ such that $P_j(y_j) = 0$ in $B$. Then we get a commutative diagram $$\begin{gathered}\begin{matrix}\phantom{X} & R[x_1, \ldots, x_n, y_1, \ldots, y_m] \\ R[x_1, \ldots, x_n] & R[x_1, \ldots, x_n, y_1, \ldots, y_m]/(P_j(y_j)) \\ A & B\end{matrix} \\[6pt] \begin{aligned}R[x_1, \ldots, x_n, y_1, \ldots, y_m] & \longrightarrow R[x_1, \ldots, x_n, y_1, \ldots, y_m]/(P_j(y_j)) \\ R[x_1, \ldots, x_n] & \longrightarrow A \\ R[x_1, \ldots, x_n] & \longrightarrow R[x_1, \ldots, x_n, y_1, \ldots, y_m]/(P_j(y_j)) \\ R[x_1, \ldots, x_n, y_1, \ldots, y_m]/(P_j(y_j)) & \longrightarrow B \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ The top horizontal arrow and the top right vertical arrow satisfy the assumptions of Lemma Pseudo-coherent complexes and coherent sheaves. Hence $K^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent) as a complex of $R[x_1, \ldots, x_n]$-modules if and only if $K^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent) as a complex of $R[x_1, \ldots, x_n, y_1, \ldots, y_m]$-modules. $\square$
Lemma. Pullback of pseudo-coherent complexes and coherent sheaves
Let $R \to A \to B$ be finite type ring maps. Let $m \in \mathbf{Z}$. Let $K^\bullet$ be a complex of $A$-modules. Assume $B$ as a $B$-module is pseudo-coherent relative to $A$. If $K^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent) relative to $R$, then $K^\bullet \otimes_A^{\mathbf{L}} B$ is $m$-pseudo-coherent (resp. pseudo-coherent) relative to $R$.
Proof. Choose a surjection $A[y_1, \ldots, y_m] \to B$. Choose a surjection $R[x_1, \ldots, x_n] \to A$. Combined we get a surjection $R[x_1, \ldots, x_n, y_1, \ldots y_m] \to B$. Choose a resolution $E^\bullet \to B$ of $B$ by a complex of finite free $A[y_1, \ldots, y_m]$-modules (which is possible by our assumption on the ring map $A \to B$). We may assume that $K^\bullet$ is a bounded above complex of flat $A$-modules. Then $$\begin{aligned} K^\bullet \otimes_A^{\mathbf{L}} B & = \text{Tot}(K^\bullet \otimes_A B[0]) \\ & = \text{Tot}(K^\bullet \otimes_A A[y_1, \ldots, y_m] \otimes_{A[y_1, \ldots, y_m]} B[0]) \\ & \cong \text{Tot}\left( (K^\bullet \otimes_A A[y_1, \ldots, y_m]) \otimes_{A[y_1, \ldots, y_m]} E^\bullet \right) \\ & = \text{Tot}(K^\bullet \otimes_A E^\bullet) \end{aligned}$$ in $D(A[y_1, \ldots, y_m])$. The quasi-isomorphism $\cong$ comes from an application of Lemma Derived tensor products, Tor amplitude and derived categories. Thus we have to show that $\text{Tot}(K^\bullet \otimes_A E^\bullet)$ is $m$-pseudo-coherent as a complex of $R[x_1, \ldots, x_n, y_1, \ldots y_m]$-modules. Note that $\text{Tot}(K^\bullet \otimes_A E^\bullet)$ has a filtration by subcomplexes with successive quotients the complexes $K^\bullet \otimes_A E^i[-i]$. Note that for $i \ll 0$ the complexes $K^\bullet \otimes_A E^i[-i]$ have zero cohomology in degrees $\leq m$ and hence are $m$-pseudo-coherent (over any ring). Hence, applying Lemma Pseudo-coherent complexes and coherent sheaves and induction, it suffices to show that $K^\bullet \otimes_A E^i[-i]$ is pseudo-coherent relative to $R$ for all $i$. Note that $E^i = 0$ for $i > 0$. Since also $E^i$ is finite free this reduces to proving that $K^\bullet \otimes_A A[y_1, \ldots, y_m]$ is $m$-pseudo-coherent relative to $R$ which follows from Lemma Base change for pseudo-coherent complexes and coherent sheaves for instance. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a Noetherian ring. Let $R \to A$ be a finite type ring map. Then
-
A complex of $A$-modules $K^\bullet$ is $m$-pseudo-coherent relative to $R$ if and only if $K^\bullet \in D^{-}(A)$ and $H^i(K^\bullet)$ is a finite $A$-module for $i \geq m$.
-
A complex of $A$-modules $K^\bullet$ is pseudo-coherent relative to $R$ if and only if $K^\bullet \in D^{-}(A)$ and $H^i(K^\bullet)$ is a finite $A$-module for all $i$.
-
An $A$-module is pseudo-coherent relative to $R$ if and only if it is finite.
Proof. Immediate consequence of Lemma Pseudo-coherent complexes and coherent sheaves and the definitions. $\square$
Lemma. Base change for pseudo-coherent complexes and coherent sheaves
Let $R \to A$ be a finite type ring map. Let $m \in \mathbf{Z}$. Let $K^\bullet$ be a complex of $A$-modules which is $m$-pseudo-coherent (resp. pseudo-coherent) relative to $R$. Let $R \to R'$ be a ring map such that $A$ and $R'$ are Tor independent over $R$. Set $A' = A \otimes_R R'$. Then $K^\bullet \otimes_A^{\mathbf{L}} A'$ is $m$-pseudo-coherent (resp. pseudo-coherent) relative to $R'$.
Proof. Choose a surjection $R[x_1, \ldots, x_n] \to A$. Note that $$K^\bullet \otimes_A^{\mathbf{L}} A' = K^\bullet \otimes_R^{\mathbf{L}} R' = K^\bullet \otimes_{R[x_1, \ldots, x_n]}^{\mathbf{L}} R'[x_1, \ldots, x_n]$$ by Lemma Base change for derived commutative algebra applied twice. Hence we win by Lemma Pullback of pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Pullback of perfect complexes
Let $A \to B$ be a ring map. Let $K^\bullet$ be a perfect complex of $A$-modules. Then $K^\bullet \otimes_A^{\mathbf{L}} B$ is a perfect complex of $B$-modules.
Proof. Using Lemma Perfect complexes this translates into the corresponding results for pseudo-coherent modules and modules of finite tor dimension. See Lemma Pullback of derived tensor products and Tor amplitude and Lemma Pullback of pseudo-coherent complexes and coherent sheaves for those results. $\square$
Lemma. Lifting pseudo-coherent complexes and derived Hom and Ext
Let $(R, \mathfrak m, \kappa)$ be a local ring. Let $K \in D(R)$ be pseudo-coherent. Set $d_i = \dim_\kappa H^i(K \otimes_R^\mathbf{L} \kappa)$. Then $d_i < \infty$ and for some $b \in \mathbf{Z}$ we have $d_i = 0$ for $i > b$. Then there exists a complex $$\ldots \to R^{\oplus d_{b - 2}} \to R^{\oplus d_{b - 1}} \to R^{\oplus d_b} \to 0 \to \ldots$$ representing $K$ in $D(R)$. Moreover, this complex is unique up to isomorphism(!).
Proof. Observe that $K \otimes_R^\mathbf{L} \kappa$ is pseudo-coherent as an object of $D(\kappa)$, see Lemma Pullback of pseudo-coherent complexes and coherent sheaves. Hence the cohomology spaces are finite dimensional and vanish above some cutoff. Every object of $D(\kappa)$ is isomorphic in $D(\kappa)$ to a complex $E^\bullet$ with zero differentials. In particular $E^i \cong \kappa^{\oplus d_i}$ is finite free. Applying Lemma Lifting a complex after adjoining free summands we obtain the existence.
If we have two complexes $F^\bullet$ and $G^\bullet$ with $F^i$ and $G^i$ free of rank $d_i$ representing $K$. Then we may choose a map of complexes $\beta : F^\bullet \to G^\bullet$ representing the isomorphism $F^\bullet \cong K \cong G^\bullet$, see Derived Categories, Lemma Derived Hom, Ext and projective and locally free modules. The induced map of complexes $\beta \otimes 1 : F^\bullet \otimes_R^\mathbf{L} \kappa \to G^\bullet \otimes_R^\mathbf{L} \kappa$ must be an isomorphism of complexes as the differentials in $F^\bullet \otimes_R^\mathbf{L} \kappa$ and $G^\bullet \otimes_R^\mathbf{L} \kappa$ are zero. Thus $\beta^i : F^i \to G^i$ is a map of finite free $R$-modules whose reduction modulo $\mathfrak m$ is an isomorphism. Hence $\beta^i$ is an isomorphism and we win. $\square$
Lemma. Integral elements compatible with a lifted factorization
Let $I$ be an ideal of a ring $A$. Let $A \to B$ be an integral ring map. Let $b \in B$ map to an idempotent in $B/IB$. Then there exists a monic $f \in A[x]$ with $f(b) = 0$ and $f \bmod I = x^d(x - 1)^d$ for some $d \geq 1$.
Proof. Observe that $z = b^2 - b$ is an element of $IB$. By Algebra, Lemma Integral extensions (uncovered prerequisite) there exist a monic polynomial $g(x) = x^d + \sum a_j x^j$ of degree $d$ with $a_j \in I$ such that $g(z) = 0$ in $B$. Hence $f(x) = g(x^2 - x) \in A[x]$ is a monic polynomial such that $f(x) \equiv x^d(x - 1)^d \bmod I$ and such that $f(b) = 0$ in $B$. $\square$
Lemma. Lifting a coprime factorization
Let $A$ be a ring, let $I \subset A$ be an ideal. Let $f \in A[x]$ be a monic polynomial. Let $\overline{f} = \overline{g} \overline{h}$ be a factorization of $f$ in $A/I[x]$ and assume
-
the leading coefficient of $\overline{g}$ is an invertible element of $A/I$, and
-
$\overline{g}$, $\overline{h}$ generate the unit ideal in $A/I[x]$.
Then there exists an étale ring map $A \to A'$ which induces an isomorphism $A/I \to A'/IA'$ and a factorization $f = g' h'$ in $A'[x]$ lifting the given factorization over $A/I$.
Proof. Applying Lemma Lifting a unit we may assume that the leading coefficient of $\overline{g}$ is the reduction of an invertible element $u \in A$. Then we may replace $\overline{g}$ by $\overline{u}^{-1}\overline{g}$ and $\overline{h}$ by $\overline{u}\overline{h}$. Thus we may assume that $\overline{g}$ is monic. Since $f$ is monic we conclude that $\overline{h}$ is monic too. In this case the result follows from Lemma Lifting a monic polynomial factorization. $\square$
Lemma. Separating a closed image from another closed subset
Let $R \to S$ be a ring map. Let $I \subset R$ be an ideal of $R$ and let $J \subset S$ be an ideal of $S$. If the closure of the image of $V(J)$ in $\operatorname{Spec}(R)$ is disjoint from $V(I)$, then there exists an element $f \in R$ which maps to $1$ in $R/I$ and to an element of $J$ in $S$.
Proof. Let $I' \subset R$ be an ideal such that $V(I')$ is the closure of the image of $V(J)$. Then $V(I) \cap V(I') = \emptyset$ by assumption and hence $I + I' = R$ by Algebra, Lemma The Zariski topology on an affine spectrum. Write $1 = g + f$ with $g \in I$ and $f \in I'$. We have $V(f') \supset V(J)$ where $f'$ is the image of $f$ in $S$. Hence $(f')^n \in J$ for some $n$, see Algebra, Lemma The Zariski topology on an affine spectrum. Replacing $f$ by $f^n$ we win. $\square$
Lemma. Tensor products and direct sums
In Situation Modules and tensor products and direct sums we have $$\operatorname{Spec}(B') = \operatorname{Spec}(B) \amalg_{\operatorname{Spec}(A)} \operatorname{Spec}(A')$$ as topological spaces.
Proof. Since $B' = B \times_A A'$ we obtain a commutative square of spectra, which induces a continuous map $$can : \operatorname{Spec}(B) \amalg_{\operatorname{Spec}(A)} \operatorname{Spec}(A') \longrightarrow \operatorname{Spec}(B')$$ as the source is a pushout in the category of topological spaces (which exists by Topology, Section Filtered limits and the geometric construction).
To show the map $can$ is surjective, let $\mathfrak q' \subset B'$ be a prime ideal. If $I \subset \mathfrak q'$ (here and below we take the liberty of considering $I$ as an ideal of $B'$ as well as an ideal of $A'$), then $\mathfrak q'$ corresponds to a prime ideal of $B$ and is in the image. If not, then pick $h \in I$, $h \not \in \mathfrak q'$. In this case $B_h = A_h = 0$ and the ring map $B'_h \to A'_h$ is an isomorphism, see Lemma Localizing a commutative ring diagram. Thus we see that $\mathfrak q'$ corresponds to a unique prime ideal $\mathfrak p' \subset A'$ which does not contain $I$.
Since $B' \to B$ is surjective, we see that $can$ is injective on the summand $\operatorname{Spec}(B)$. We have seen above that $\operatorname{Spec}(A') \to \operatorname{Spec}(B')$ is injective on the complement of $V(I) \subset \operatorname{Spec}(A')$. Since $V(I) \subset \operatorname{Spec}(A')$ is exactly the image of $\operatorname{Spec}(A) \to \operatorname{Spec}(A')$ a trivial set theoretic argument shows that $can$ is injective.
To finish the proof we have to show that $can$ is open. To do this, observe that an open of the pushout is of the form $V \amalg U'$ where $V \subset \operatorname{Spec}(B)$ and $U' \subset \operatorname{Spec}(A')$ are opens whose inverse images in $\operatorname{Spec}(A)$ agree. Let $v \in V$. We can find a $g \in B$ such that $v \in D(g) \subset V$. Let $f \in A$ be the image. Pick $f' \in A'$ mapping to $f$. Then $D(f') \cap U' \cap V(I) = D(f') \cap V(I)$. Hence $V(I) \cap D(f')$ and $D(f') \cap (U')^c$ are disjoint closed subsets of $D(f') = \operatorname{Spec}(A'_{f'})$. Write $(U')^c = V(J)$ for some ideal $J \subset A'$. Since $A'_{f'} \to A'_{f'}/IA'_{f'} \times A'_{f'}/JA'_{f'}$ is surjective by the disjointness just shown, we can find an $a'' \in A'_{f'}$ mapping to $1$ in $A'_{f'}/IA'_{f'}$ and mapping to zero in $A'_{f'}/JA'_{f'}$. Clearing denominators, we find an element $a' \in J$ mapping to $f^n$ in $A$. Then $D(a'f') \subset U'$. Let $h' = (g^{n + 1}, a'f') \in B'$. Since $B'_{h'} = B_{g^{n + 1}} \times_{A_{f^{n + 1}}} A'_{a'f'}$ by a previously cited lemma, we see that $D(h')$ pulls back to an open neighbourhood of $v$ in the pushout, i.e., the image of $V \amalg U'$ contains an open neighbourhood of the image of $v$. We omit the (easier) proof that the same thing is true for $u' \in U'$ with $u' \not \in V(I)$. $\square$
Lemma. Cotangent complexes, differentials and henselian rings
Let $A \to B$ be a local homomorphism of local rings. Let $A^h \to B^h$, resp. $A^{sh} \to B^{sh}$ be the induced map on henselizations, resp. strict henselizations (Algebra, Lemma Henselian rings (uncovered prerequisite), resp. Lemma Functoriality of strict henselization (uncovered prerequisite)). Then $\mathrm{NL}_{B/A} \otimes_B B^h \to \mathrm{NL}_{B^h/A^h}$ and $\mathrm{NL}_{B/A} \otimes_B B^{sh} \to \mathrm{NL}_{B^{sh}/A^{sh}}$ induce isomorphisms on cohomology groups.
Proof. Since $A^h$ is a filtered colimit of étale algebras over $A$ we see that $\mathrm{NL}_{A^h/A}$ is an acyclic complex by Algebra, Lemma Filtered colimits of naive cotangent complexes (uncovered prerequisite) and Algebra, Definition Étale ring maps. The same is true for $B^h/B$. Using the Jacobi-Zariski sequence (Algebra, Lemma The transitivity sequence for the naive cotangent complex (uncovered prerequisite)) for $A \to A^h \to B^h$ we find that $\mathrm{NL}_{B^h/A} \to \mathrm{NL}_{B^h/A^h}$ induces isomorphisms on cohomology groups. Moreover, an étale ring map is a local complete intersection as it is even a global complete intersection, see Algebra, Lemma Étale algebras in standard smooth form (uncovered prerequisite). By Lemma Cotangent transitivity for filtered complete intersections we get a six term exact Jacobi-Zariski sequence associated to $A \to B \to B^h$ which proves that $\mathrm{NL}_{B/A} \otimes_B B^h \to \mathrm{NL}_{B^h/A}$ induces isomorphisms on cohomology groups. This finishes the proof in the case of the map on henselizations. The case of strict henselization is proved in exactly the same manner. $\square$
Lemma. Derived commutative algebra
Let $R$ be a ring. Let $K$ and $L$ be objects of $D(R)$. Assume $L$ has projective-amplitude in $[a, b]$, for example if $L$ is perfect of tor-amplitude in $[a, b]$.
-
If $H^i(K) = 0$ for $i \geq a$, then $\operatorname{Hom}_{D(R)}(L, K) = 0$.
-
If $H^i(K) = 0$ for $i \geq a + 1$, then given any distinguished triangle $K \to M \to L \to K[1]$ there is an isomorphism $M \cong K \oplus L$ in $D(R)$ compatible with the maps in the distinguished triangle.
-
If $H^i(K) = 0$ for $i \geq a$, then the isomorphism in (2) exists and is unique.
Proof. The assumption that $L$ has projective-amplitude in $[a, b]$ means we can represent $L$ by a complex $L^\bullet$ of projective $R$-modules with $L^i = 0$ for $i \not \in [a, b]$, see Definition Projective dimension. If $L$ is perfect of tor-amplitude in $[a, b]$, then we can represent $L$ by a complex $L^\bullet$ of finite projective $R$-modules with $L^i = 0$ for $i \not \in [a, b]$, see Lemma Perfect complexes. If $H^i(K) = 0$ for $i \geq a$, then $K$ is quasi-isomorphic to $\tau_{\leq a - 1}K$. Hence we can represent $K$ by a complex $K^\bullet$ of $R$-modules with $K^i = 0$ for $i \geq a$. Then we obtain $$\operatorname{Hom}_{D(R)}(L, K) = \operatorname{Hom}_{K(R)}(L^\bullet, K^\bullet) = 0$$ by Derived Categories, Lemma Derived Hom, Ext and projective and locally free modules. This proves (1). Under the hypotheses of (2) we see that $\operatorname{Hom}_{D(R)}(L, K[1]) = 0$ by (1), hence the distinguished triangle is split by Derived Categories, Lemma Splitting an exact triangle. The uniqueness of (3) follows from (1). $\square$
Lemma. Pseudo-coherent complexes and modules
Let $R$ be a ring. Let $M$ be an $R$-module. Then
-
$M$ is $0$-pseudo-coherent if and only if $M$ is a finite $R$-module,
-
$M$ is $(-1)$-pseudo-coherent if and only if $M$ is a finitely presented $R$-module,
-
$M$ is $(-d)$-pseudo-coherent if and only if there exists a resolution $$R^{\oplus a_d} \to R^{\oplus a_{d - 1}} \to \ldots \to R^{\oplus a_0} \to M \to 0$$ of length $d$, and
-
$M$ is pseudo-coherent if and only if there exists an infinite resolution $$\ldots \to R^{\oplus a_1} \to R^{\oplus a_0} \to M \to 0$$ by finite free $R$-modules.
Proof. If $M$ is of finite type (resp. of finite presentation), then $M$ is $0$-pseudo-coherent (resp. $(-1)$-pseudo-coherent) as follows from the discussion preceding Definition Pseudo-coherent complexes. Conversely, if $M$ is $0$-pseudo-coherent, then $M = H^0(M[0])$ is of finite type by Lemma Finiteness of cohomology groups. If $M$ is $(-1)$-pseudo-coherent, then it is $0$-pseudo-coherent hence of finite type. Choose a surjection $R^{\oplus a} \to M$ and denote $K = \operatorname{Ker}(R^{\oplus a} \to M)$. By Lemma Pseudo-coherent complexes and coherent sheaves we see that $K$ is $0$-pseudo-coherent, hence of finite type, whence $M$ is of finite presentation.
To prove the third and fourth statement use induction and an argument similar to the above (details omitted). $\square$
Lemma. Koszul complexes, regular sequences and derived categories
Let $R$ be a ring. Let $\varphi : E \to R$ be an $R$-module map. Let $f \in R$. Set $E' = E \oplus R$ and define $\varphi' : E' \to R$ by $\varphi$ on $E$ and multiplication by $f$ on $R$. The complex $K_\bullet(\varphi')$ is isomorphic to the cone of the map of complexes $$f : K_\bullet(\varphi) \longrightarrow K_\bullet(\varphi).$$
Proof. Denote $e_0 \in E'$ the element $1 \in R \subset R \oplus E$. By our definition of the cone above we see that $$C(f)_n = K_n(\varphi) \oplus K_{n - 1}(\varphi) = \wedge^n(E) \oplus \wedge^{n - 1}(E) = \wedge^n(E')$$ where in the last $=$ we map $(0, e_1 \wedge \ldots \wedge e_{n - 1})$ to $e_0 \wedge e_1 \wedge \ldots \wedge e_{n - 1}$ in $\wedge^n(E')$. A computation shows that this isomorphism is compatible with differentials. Namely, this is clear for elements of the first summand as $\varphi'|_E = \varphi$ and $d_{C(f)}$ restricted to the first summand is just $d_{K_\bullet(\varphi)}$. On the other hand, if $e_1 \wedge \ldots \wedge e_{n - 1}$ is in the second summand, then $$d_{C(f)}(0, e_1 \wedge \ldots \wedge e_{n - 1}) = fe_1 \wedge \ldots \wedge e_{n - 1}
- d_{K_\bullet(\varphi)}(e_1 \wedge \ldots \wedge e_{n - 1})$$ and on the other hand $$\begin{aligned} & d_{K_\bullet(\varphi')}(0, e_0 \wedge e_1 \wedge \ldots \wedge e_{n - 1}) \ & = \sum\nolimits_{i = 0, \ldots, n - 1} (-1)^i \varphi'(e_i)e_0 \wedge \ldots \wedge \widehat{e_i} \wedge \ldots \wedge e_{n - 1} \ & = fe_1 \wedge \ldots \wedge e_{n - 1} + \sum\nolimits_{i = 1, \ldots, n - 1} (-1)^i \varphi(e_i)e_0 \wedge \ldots \wedge \widehat{e_i} \wedge \ldots \wedge e_{n - 1} \ & = fe_1 \wedge \ldots \wedge e_{n - 1} - e_0 \left(\sum\nolimits_{i = 1, \ldots, n - 1} (-1)^{i + 1} \varphi(e_i)e_1 \wedge \ldots \wedge \widehat{e_i} \wedge \ldots \wedge e_{n - 1}\right) \end{aligned}$$ which is the image of the result of the previous computation. $\square$
Lemma. Derived categories
Let $R$ be a ring. Let $A_\bullet$ be a complex of $R$-modules. Let $f, g \in R$. Let $C(f)_\bullet$ be the cone of $f : A_\bullet \to A_\bullet$. Define similarly $C(g)_\bullet$ and $C(fg)_\bullet$. Then $C(fg)_\bullet$ is homotopy equivalent to the cone of a map $$C(f)_\bullet[1] \longrightarrow C(g)_\bullet$$
Proof. We first prove this if $A_\bullet$ is the complex consisting of $R$ placed in degree $0$. In this case the complex $C(f)_\bullet$ is the complex $$\ldots \to 0 \to R \xrightarrow{f} R \to 0 \to \ldots$$ with $R$ placed in (homological) degrees $1$ and $0$. The map of complexes we use is $$\begin{gathered}\begin{matrix}0 & 0 & R & R & 0 \\ 0 & R & R & 0 & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow 0 \\ 0 & \longrightarrow 0 \\ 0 & \longrightarrow R \\ 0 & \longrightarrow R \\ R & \xrightarrow{f} R \\ R & \xrightarrow{1} R \\ R & \longrightarrow 0 \\ R & \longrightarrow 0 \\ 0 & \longrightarrow 0 \\ 0 & \longrightarrow R \\ R & \xrightarrow{g} R \\ R & \longrightarrow 0 \\ 0 & \longrightarrow 0\end{aligned}\end{gathered}$$ The cone of this is the chain complex consisting of $R^{\oplus 2}$ placed in degrees $1$ and $0$ and differential (Cotangent complexes, differentials and derived categories) $$\left( \begin{matrix} g & 1 \\ 0 & -f \end{matrix} \right) : R^{\oplus 2} \longrightarrow R^{\oplus 2}$$ To see this chain complex is homotopic to $C(fg)_\bullet$, i.e., to $R \xrightarrow{fg} R$, consider the maps of complexes $$\begin{gathered}\begin{matrix}R & R \\ R^{\oplus 2} & R^{\oplus 2}\end{matrix} \\[6pt] \begin{aligned}R & \xrightarrow{(1, -g)} R^{\oplus 2} \\ R & \xrightarrow{fg} R \\ R & \xrightarrow{(0, 1)} R^{\oplus 2} \\ R^{\oplus 2} & \longrightarrow R^{\oplus 2}\end{aligned}\end{gathered} \quad\quad \begin{gathered}\begin{matrix}R^{\oplus 2} & R^{\oplus 2} \\ R & R\end{matrix} \\[6pt] \begin{aligned}R^{\oplus 2} & \xrightarrow{(1, 0)} R \\ R^{\oplus 2} & \longrightarrow R^{\oplus 2} \\ R^{\oplus 2} & \xrightarrow{(f, 1)} R \\ R & \xrightarrow{fg} R\end{aligned}\end{gathered}$$ with obvious notation. The composition of these two maps in one direction is the identity on $C(fg)_\bullet$, but in the other direction it isn't the identity. We omit writing out the required homotopy.
To see the result holds in general, we use that we have a functor $K_\bullet \mapsto \text{Tot}(A_\bullet \otimes_R K_\bullet)$ on the category of complexes which is compatible with homotopies and cones. Then we write $C(f)_\bullet$ and $C(g)_\bullet$ as the total complex of the double complexes $$(R \xrightarrow{f} R) \otimes_R A_\bullet \quad\text{and}\quad (R \xrightarrow{g} R) \otimes_R A_\bullet$$ and in this way we deduce the result from the special case discussed above. Some details omitted. $\square$
Lemma. Tensor products and direct sums
Let $R$ be a ring. Let $K \in D(R)$ be an object such that for every countable set of objects $E_n \in D(R)$ the canonical map $$\bigoplus \operatorname{Hom}_{D(R)}(K, E_n) \longrightarrow \operatorname{Hom}_{D(R)}(K, \bigoplus E_n)$$ is a bijection. Then, given any system $L_n^\bullet$ of complexes over $\mathbf{N}$ we have that $$\mathop{\operatorname{colim}} \operatorname{Hom}_{D(R)}(K, L^\bullet_n) \longrightarrow \operatorname{Hom}_{D(R)}(K, L^\bullet)$$ is a bijection, where $L^\bullet$ is the termwise colimit, i.e., $L^m = \mathop{\operatorname{colim}} L_n^m$ for all $m \in \mathbf{Z}$.
Proof. Consider the short exact sequence of complexes $$0 \to \bigoplus L_n^\bullet \to \bigoplus L_n^\bullet \to L^\bullet \to 0$$ where the first map is given by $1 - t_n$ in degree $n$ where $t_n : L_n^\bullet \to L_{n + 1}^\bullet$ is the transition map. By Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories this is a distinguished triangle in $D(R)$. Apply the homological functor $\operatorname{Hom}_{D(R)}(K, -)$, see Derived Categories, Lemma Representability of a homological functor. Thus a long exact cohomology sequence $$\begin{gathered}\begin{matrix}\phantom{X} & \ldots & \operatorname{Hom}_{D(R)}(K, \mathop{\operatorname{colim}} L^\bullet_n[-1]) \\ \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n) & \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n) & \operatorname{Hom}_{D(R)}(K, \mathop{\operatorname{colim}} L^\bullet_n) \\ \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n[1]) & \ldots\end{matrix} \\[6pt] \begin{aligned}\ldots & \longrightarrow \operatorname{Hom}_{D(R)}(K, \mathop{\operatorname{colim}} L^\bullet_n[-1]) \\ \operatorname{Hom}_{D(R)}(K, \mathop{\operatorname{colim}} L^\bullet_n[-1]) & \longrightarrow \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n) \\ \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n) & \longrightarrow \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n) \\ \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n) & \longrightarrow \operatorname{Hom}_{D(R)}(K, \mathop{\operatorname{colim}} L^\bullet_n) \\ \operatorname{Hom}_{D(R)}(K, \mathop{\operatorname{colim}} L^\bullet_n) & \longrightarrow \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n[1]) \\ \operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n[1]) & \longrightarrow \ldots\end{aligned}\end{gathered}$$ Since we have assumed that $\operatorname{Hom}_{D(R)}(K, \bigoplus L^\bullet_n)$ is equal to $\bigoplus \operatorname{Hom}_{D(R)}(K, L^\bullet_n)$ we see that the first map on every row of the diagram is injective (by the explicit description of this map as the sum of the maps induced by $1 - t_n$). Hence we conclude that $\operatorname{Hom}_{D(R)}(K, \mathop{\operatorname{colim}} L^\bullet_n)$ is the cokernel of the first map of the middle row in the diagram above which is what we had to show. $\square$
Lemma. Perfect complexes and tensor products and direct sums
Let $R$ be a ring. If $K^\bullet \oplus L^\bullet$ is perfect, then so are $K^\bullet$ and $L^\bullet$.
Proof. Follows from Lemmas Perfect complexes, Pseudo-coherent complexes and coherent sheaves, and Derived tensor products, Tor amplitude and tensor products and direct sums. $\square$
Lemma. Pseudo-coherent complexes and sheaf cohomology
Let $R$ be a ring. Let $m \in \mathbf{Z}$. Let $K^\bullet \in D^{-}(R)$ such that $H^i(K^\bullet)$ is $(m - i)$-pseudo-coherent (resp. pseudo-coherent) for all $i$. Then $K^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent).
Proof. Assume $K^\bullet$ is an object of $D^{-}(R)$ such that each $H^i(K^\bullet)$ is $(m - i)$-pseudo-coherent. Let $n$ be the largest integer such that $H^n(K^\bullet)$ is nonzero. We will prove the lemma by induction on $n$. If $n < m$, then $K^\bullet$ is $m$-pseudo-coherent by Lemma Pseudo-coherent complexes and coherent sheaves. If $n \geq m$, then we have the distinguished triangle $$(\tau_{\leq n - 1}K^\bullet, K^\bullet, H^n(K^\bullet)[-n])$$ (Derived Categories, Remark Derived categories) Since $H^n(K^\bullet)[-n]$ is $m$-pseudo-coherent by assumption, we can use Lemma Pseudo-coherent complexes and coherent sheaves to see that it suffices to prove that $\tau_{\leq n - 1}K^\bullet$ is $m$-pseudo-coherent. By induction on $n$ we win. (The pseudo-coherent case follows from this and Lemma Pseudo-coherent complexes and coherent sheaves.) $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $R$ be a ring. Let $P^\bullet$ be a bounded above complex of flat $R$-modules. Then $P^\bullet$ is K-flat.
Proof. Let $L^\bullet$ be an acyclic complex of $R$-modules. Let $\xi \in H^n(\text{Tot}(L^\bullet \otimes_R P^\bullet))$. We have to show that $\xi = 0$. Since $\text{Tot}^n(L^\bullet \otimes_R P^\bullet)$ is a direct sum with terms $L^a \otimes_R P^b$ we see that $\xi$ comes from an element in $H^n(\text{Tot}(\tau_{\leq m}L^\bullet \otimes_R P^\bullet))$ for some $m \in \mathbf{Z}$. Since $\tau_{\leq m}L^\bullet$ is also acyclic we may replace $L^\bullet$ by $\tau_{\leq m}L^\bullet$. Hence we may assume that $L^\bullet$ is bounded above. In this case the spectral sequence of Homology, Lemma The geometric construction (uncovered prerequisite) has $${}'E_1^{p, q} = H^p(L^\bullet \otimes_R P^q)$$ which is zero as $P^q$ is flat and $L^\bullet$ acyclic. Hence $H^*(\text{Tot}(L^\bullet \otimes_R P^\bullet)) = 0$. $\square$
Lemma. Filtered limits and derived tensor products, Tor amplitude and flatness
Let $R$ be a ring. Let $K_1^\bullet \to K_2^\bullet \to \ldots$ be a system of K-flat complexes. Then $\mathop{\operatorname{colim}}_i K_i^\bullet$ is K-flat. More generally any filtered colimit of K-flat complexes is K-flat.
Proof. Because we are taking termwise colimits we have $$\mathop{\operatorname{colim}}_i \text{Tot}(M^\bullet \otimes_R K_i^\bullet) = \text{Tot}(M^\bullet \otimes_R \mathop{\operatorname{colim}}_i K_i^\bullet)$$ by Algebra, Lemma Tensor products and direct sums (uncovered prerequisite). Hence the lemma follows from the fact that filtered colimits are exact, see Algebra, Lemma Filtered limits and commutative algebra (uncovered prerequisite). $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Let $R$ be a ring. Let $0 \to K_1^\bullet \to K_2^\bullet \to K_3^\bullet \to 0$ be a short exact sequence of complexes. If $K_3^n$ is flat for all $n \in \mathbf{Z}$ and two out of three of $K_i^\bullet$ are K-flat, so is the third.
Proof. Let $L^\bullet$ be a complex of $R$-modules. Then $$0 \to \text{Tot}(L^\bullet \otimes_R K_1^\bullet) \to \text{Tot}(L^\bullet \otimes_R K_2^\bullet) \to \text{Tot}(L^\bullet \otimes_R K_3^\bullet) \to 0$$ is a short exact sequence of complexes. Namely, for each $n, m$ the sequence of modules $0 \to L^n \otimes_R K_1^m \to L^n \otimes_R K_2^m \to L^n \otimes_R K_3^m \to 0$ is exact by Algebra, Lemma Tor vanishing for a flat module and the sequence of complexes is a direct sum of these. Thus the lemma follows from this and the fact that in a short exact sequence of complexes if two out of three are acyclic, so is the third. $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Let $R$ be a ring. Let $K^\bullet$ be a K-flat complex. Then the functor $$K(R) \longrightarrow K(R), \quad L^\bullet \longmapsto \text{Tot}(L^\bullet \otimes_R K^\bullet)$$ transforms quasi-isomorphisms into quasi-isomorphisms.
Proof. Follows from Lemma Derived tensor products, Tor amplitude and derived categories and the fact that quasi-isomorphisms in $K(R)$ are characterized by having acyclic cones. $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $R$ be a ring. Let $P^\bullet$ be a complex of $R$-modules. Let $\alpha, \beta : L^\bullet \to M^\bullet$ be homotopic maps of complexes. Then $\alpha$ and $\beta$ induce homotopic maps $$\text{Tot}(\alpha \otimes \text{id}_P), \text{Tot}(\beta \otimes \text{id}_P) : \text{Tot}(L^\bullet \otimes_R P^\bullet) \longrightarrow \text{Tot}(M^\bullet \otimes_R P^\bullet).$$ In particular the construction $L^\bullet \mapsto \text{Tot}(L^\bullet \otimes_R P^\bullet)$ defines an endo-functor of the homotopy category of complexes.
Proof. Say $\alpha = \beta + dh + hd$ for some homotopy $h$ defined by $h^n : L^n \to M^{n - 1}$. Set $$H^n = \bigoplus\nolimits_{a + b = n} h^a \otimes \text{id}_{P^b} : \bigoplus\nolimits_{a + b = n} L^a \otimes_R P^b \longrightarrow \bigoplus\nolimits_{a + b = n} M^{a - 1} \otimes_R P^b$$ Then a straightforward computation shows that $$\text{Tot}(\alpha \otimes \text{id}_P) = \text{Tot}(\beta \otimes \text{id}_P) + dH + Hd$$ as maps $\text{Tot}(L^\bullet \otimes_R P^\bullet) \to \text{Tot}(M^\bullet \otimes_R P^\bullet)$. $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $R$ be a ring. Let $P^\bullet$ be a complex of $R$-modules. The functors $$K(R) \longrightarrow K(R), \quad L^\bullet \longmapsto \text{Tot}(P^\bullet \otimes_R L^\bullet)$$ and $$K(R) \longrightarrow K(R), \quad L^\bullet \longmapsto \text{Tot}(L^\bullet \otimes_R P^\bullet)$$ are exact functors of triangulated categories.
Proof. This follows from Derived Categories, Remark Derived categories and tensor products and direct sums. $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $R$ be a ring. Let $\alpha : P^\bullet \to Q^\bullet$ be a quasi-isomorphism of K-flat complexes of $R$-modules. For every complex $L^\bullet$ of $R$-modules the induced map $$\text{Tot}(\text{id}_L \otimes \alpha) : \text{Tot}(L^\bullet \otimes_R P^\bullet) \longrightarrow \text{Tot}(L^\bullet \otimes_R Q^\bullet)$$ is a quasi-isomorphism.
Proof. Choose a quasi-isomorphism $K^\bullet \to L^\bullet$ with $K^\bullet$ a K-flat complex, see Lemma Derived tensor products, Tor amplitude and flatness. Consider the commutative diagram $$\begin{gathered}\begin{matrix}\text{Tot}(K^\bullet \otimes_R P^\bullet) & \text{Tot}(K^\bullet \otimes_R Q^\bullet) \\ \text{Tot}(L^\bullet \otimes_R P^\bullet) & \text{Tot}(L^\bullet \otimes_R Q^\bullet)\end{matrix} \\[6pt] \begin{aligned}\text{Tot}(K^\bullet \otimes_R P^\bullet) & \longrightarrow \text{Tot}(K^\bullet \otimes_R Q^\bullet) \\ \text{Tot}(K^\bullet \otimes_R P^\bullet) & \longrightarrow \text{Tot}(L^\bullet \otimes_R P^\bullet) \\ \text{Tot}(K^\bullet \otimes_R Q^\bullet) & \longrightarrow \text{Tot}(L^\bullet \otimes_R Q^\bullet) \\ \text{Tot}(L^\bullet \otimes_R P^\bullet) & \longrightarrow \text{Tot}(L^\bullet \otimes_R Q^\bullet)\end{aligned}\end{gathered}$$ The result follows as by Lemma Derived tensor products, Tor amplitude and flatness the vertical arrows and the top horizontal arrow are quasi-isomorphisms. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $A \to B$ be a ring map. Assume that $B$ is pseudo-coherent as an $A$-module. Let $K^\bullet$ be a complex of $B$-modules. The following are equivalent
-
$K^\bullet$ is $m$-pseudo-coherent as a complex of $B$-modules, and
-
$K^\bullet$ is $m$-pseudo-coherent as a complex of $A$-modules.
The same equivalence holds for pseudo-coherence.
Proof. Assume (1). Choose a bounded complex of finite free $B$-modules $E^\bullet$ and a map $\alpha : E^\bullet \to K^\bullet$ which is an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. Consider the distinguished triangle $(E^\bullet, K^\bullet, C(\alpha)^\bullet)$. By Lemma Pseudo-coherent complexes and coherent sheaves $C(\alpha)^\bullet$ is $m$-pseudo-coherent as a complex of $A$-modules. Hence it suffices to prove that $E^\bullet$ is pseudo-coherent as a complex of $A$-modules, which follows from Lemma Pseudo-coherent complexes and coherent sheaves. The pseudo-coherent case of (1) $\Rightarrow$ (2) follows from this and Lemma Pseudo-coherent complexes and coherent sheaves.
Assume (2). Let $n$ be the largest integer such that $H^n(K^\bullet) \not = 0$. We will prove that $K^\bullet$ is $m$-pseudo-coherent as a complex of $B$-modules by induction on $n - m$. The case $n < m$ follows from Lemma Pseudo-coherent complexes and coherent sheaves. Choose a bounded complex of finite free $A$-modules $E^\bullet$ and a map $\alpha : E^\bullet \to K^\bullet$ which is an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. Consider the induced map of complexes $$\alpha \otimes 1 : E^\bullet \otimes_A B \to K^\bullet.$$ Note that $C(\alpha \otimes 1)^\bullet$ is acyclic in degrees $\geq n$ as $H^n(E) \to H^n(E^\bullet \otimes_A B) \to H^n(K^\bullet)$ is surjective by construction and since $H^i(E^\bullet \otimes_A B) = 0$ for $i > n$ by the spectral sequence of Example Derived tensor products and Tor amplitude. On the other hand, $C(\alpha \otimes 1)^\bullet$ is $m$-pseudo-coherent as a complex of $A$-modules because both $K^\bullet$ and $E^\bullet \otimes_A B$ (see Lemma Pseudo-coherent complexes and coherent sheaves) are so, see Lemma Pseudo-coherent complexes and coherent sheaves. Hence by induction we see that $C(\alpha \otimes 1)^\bullet$ is $m$-pseudo-coherent as a complex of $B$-modules. Finally another application of Lemma Pseudo-coherent complexes and coherent sheaves shows that $K^\bullet$ is $m$-pseudo-coherent as a complex of $B$-modules (as clearly $E^\bullet \otimes_A B$ is pseudo-coherent as a complex of $B$-modules). The pseudo-coherent case of (2) $\Rightarrow$ (1) follows from this and Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $R \to A$ be a finite type ring map. Let $m \in \mathbf{Z}$. Let $(K^\bullet, L^\bullet, M^\bullet, f, g, h)$ be a distinguished triangle in $D(A)$.
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If $K^\bullet$ is $(m + 1)$-pseudo-coherent relative to $R$ and $L^\bullet$ is $m$-pseudo-coherent relative to $R$ then $M^\bullet$ is $m$-pseudo-coherent relative to $R$.
-
If $K^\bullet, M^\bullet$ are $m$-pseudo-coherent relative to $R$, then $L^\bullet$ is $m$-pseudo-coherent relative to $R$.
-
If $L^\bullet$ is $(m + 1)$-pseudo-coherent relative to $R$ and $M^\bullet$ is $m$-pseudo-coherent relative to $R$, then $K^\bullet$ is $(m + 1)$-pseudo-coherent relative to $R$.
Moreover, if two out of three of $K^\bullet, L^\bullet, M^\bullet$ are pseudo-coherent relative to $R$, the so is the third.
Proof. Follows immediately from Lemma Pseudo-coherent complexes and coherent sheaves and the definitions. $\square$
Lemma. Base change for derived commutative algebra
The comparison map (Comparison for derived commutative algebra) is an isomorphism if $A' = A \otimes_R R'$ and $A$ and $R'$ are Tor independent over $R$.
Proof. To prove this we choose a free resolution $F^\bullet \to R'$ of $R'$ as an $R$-module. Because $A$ and $R'$ are Tor independent over $R$ we see that $F^\bullet \otimes_R A$ is a free $A$-module resolution of $A'$ over $A$. By our general construction of the derived tensor product above we see that $$K^\bullet \otimes_A A' \cong \text{Tot}(K^\bullet \otimes_A (F^\bullet \otimes_R A)) = \text{Tot}(K^\bullet \otimes_R F^\bullet) \cong \text{Tot}(E^\bullet \otimes_R F^\bullet) \cong E^\bullet \otimes_R R'$$ as desired. $\square$
Lemma. Lifting a unit
Let $A$ be a ring, let $I \subset A$ be an ideal, let $\overline{u} \in A/I$ be an invertible element. There exists an étale ring map $A \to A'$ which induces an isomorphism $A/I \to A'/IA'$ and an invertible element $u' \in A'$ lifting $\overline{u}$.
Proof. Choose any lift $f \in A$ of $\overline{u}$ and set $A' = A_f$ and $u$ the image of $f$ in $A'$. $\square$
Lemma. Cotangent transitivity for filtered complete intersections
Let $A \to B \to C$ be ring maps. If $B \to C$ is a filtered colimit of local complete intersection homomorphisms then the conclusion of Lemma Cotangent transitivity with a complete-intersection terminal map remains valid.
Proof. Follows from Lemma Cotangent transitivity with a complete-intersection terminal map and Algebra, Lemma Filtered colimits of naive cotangent complexes (uncovered prerequisite). $\square$
Definition. Projective dimension
Let $R$ be a ring. Let $K$ be an object of $D(R)$. We say $K$ has finite projective dimension if $K$ can be represented by a bounded complex of projective modules. We say $K$ has projective-amplitude in $[a, b]$ if $K$ is quasi-isomorphic to a complex $$\ldots \to 0 \to P^a \to P^{a + 1} \to \ldots \to P^{b - 1} \to P^b \to 0 \to \ldots$$ where $P^i$ is a projective $R$-module for all $i \in \mathbf{Z}$.
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $m \in \mathbf{Z}$. If $K^\bullet \oplus L^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent) so are $K^\bullet$ and $L^\bullet$.
Proof. In this proof we drop the superscript ${}^\bullet$. Assume that $K \oplus L$ is $m$-pseudo-coherent. It is clear that $K, L \in D^{-}(R)$. Note that there is a distinguished triangle $$(K \oplus L, K \oplus L, L \oplus L[1]) = (K, K, 0) \oplus (L, L, L \oplus L[1])$$ see Derived Categories, Lemma Derived categories and tensor products and direct sums. By Lemma Pseudo-coherent complexes and coherent sheaves we see that $L \oplus L[1]$ is $m$-pseudo-coherent. Hence also $L[1] \oplus L[2]$ is $m$-pseudo-coherent. By induction $L[n] \oplus L[n + 1]$ is $m$-pseudo-coherent. By Lemma Pseudo-coherent complexes and coherent sheaves we see that $L[n]$ is $m$-pseudo-coherent for large $n$. Hence working backwards, using the distinguished triangles $$(L[n], L[n] \oplus L[n - 1], L[n - 1])$$ we conclude that $L[n], L[n - 1], \ldots, L$ are $m$-pseudo-coherent as desired. The pseudo-coherent case follows from this and Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Derived tensor products, Tor amplitude and tensor products and direct sums
Let $R$ be a ring. Let $a, b \in \mathbf{Z}$. If $K^\bullet \oplus L^\bullet$ has tor amplitude in $[a, b]$ so do $K^\bullet$ and $L^\bullet$.
Proof. Clear from the fact that the Tor functors are additive. $\square$
Lemma. Composition and derived commutative algebra
Let $R$ be a ring. Given complexes $K^\bullet, L^\bullet, M^\bullet$ of $R$-modules there is a canonical isomorphism $$\operatorname{Hom}^\bullet(K^\bullet, \operatorname{Hom}^\bullet(L^\bullet, M^\bullet))
\operatorname{Hom}^\bullet(\text{Tot}(K^\bullet \otimes_R L^\bullet), M^\bullet)$$ of complexes of $R$-modules.
Proof. Let $\alpha$ be an element of degree $n$ on the left hand side. Thus $$\alpha = (\alpha^{p, q}) \in \prod\nolimits_{p + q = n} \operatorname{Hom}_R(K^{-q}, \operatorname{Hom}^p(L^\bullet, M^\bullet))$$ Each $\alpha^{p, q}$ is an element $$\alpha^{p, q} = (\alpha^{r, s, q}) \in \prod\nolimits_{r + s + q = n} \operatorname{Hom}_R(K^{-q}, \operatorname{Hom}_R(L^{-s}, M^r))$$ If we make the identifications
\[ \operatorname{Hom}_R(K^{-q}, \operatorname{Hom}_R(L^{-s}, M^r)) = \operatorname{Hom}_R(K^{-q} \otimes_R L^{-s}, M^r) \]then by our sign rules we get
\[ \begin{aligned} \text{d}(\alpha^{r, s, q}) & = \text{d}_{\operatorname{Hom}^\bullet(L^\bullet, M^\bullet)} \circ \alpha^{r, s, q} - (-1)^n \alpha^{r, s, q} \circ \text{d}_K \\ & = \text{d}_M \circ \alpha^{r, s, q} - (-1)^{r + s} \alpha^{r, s, q} \circ \text{d}_L - (-1)^{r + s + q} \alpha^{r, s, q} \circ \text{d}_K \end{aligned} \]On the other hand, if \(\beta\) is an element of degree \(n\) of the right hand side, then
\[ \beta = (\beta^{r, s, q}) \in \prod\nolimits_{r + s + q = n} \operatorname{Hom}_R(K^{-q} \otimes_R L^{-s}, M^r) \]and by our sign rule (Homology, Definition Prime spectra, associated points and derived categories) we get
\[ \begin{aligned} \text{d}(\beta^{r, s, q}) & = \text{d}_M \circ \beta^{r, s, q} - (-1)^n \beta^{r, s, q} \circ \text{d}_{\text{Tot}(K^\bullet \otimes L^\bullet)} \\ & = \text{d}_M \circ \beta^{r, s, q} - (-1)^{r + s + q} \left( \beta^{r, s, q} \circ \text{d}_K + (-1)^{-q} \beta^{r, s, q} \circ \text{d}_L \right) \end{aligned} \]Thus we see that the map induced by the identifications (the displayed identity) indeed is a morphism of complexes. \(\square\)
Lemma. Regular sequences are Koszul-regular
Source credit: the original source citation FAC (Chapter III, §3, no. 62, Proposition 1, pp. 254--255) the original source citation FAC (Chapter III, §4, no. 69, Lemma 1, p. 262) the original source citation FAC (Chapter III, §5, no. 75, proof of Theorem 3, pp. 269--270)
The hypothesis of the cited proposition is precisely the injectivity condition in the first sentence below, applied to $t_0^k, \ldots, t_r^k$. In particular, it does not include the nonvanishing condition sometimes imposed in the definition of a regular sequence. The source uses the resulting exactness of the positive cochain Koszul complex to identify degree-zero cocycles and to kill its intermediate cohomology.
No. 69 applies the ring case to the powers of all the variables in a polynomial ring. For $k\geq1$ these powers form a regular sequence; for $k=0$ the Koszul complex is contractible because its entries are units. Deleting the final ring term gives the graded free resolution of the ideal generated by the powers that is isolated in the next lemma.
No. 75 uses the same construction for a regular sequence generating the ideal of a nonsingular subvariety in projective space. Its free module in degree $q$ has the exterior basis indexed by increasing $q$-tuples, and its augmented Koszul complex resolves the local ring of the subvariety. In the printed general differential the sign is $(-1)^j$, but the immediately following degree-one formula is $d(e\langle i\rangle)=f_i$; substituting $q=1$ in the general formula would instead give $-f_i$. The corrected formula uses $(-1)^{j + 1}$, as in Definition The Koszul complex, and therefore agrees with the displayed degree-one case. If the opposite sign is used uniformly in every positive degree, multiplying homological degree $q$ by $(-1)^q$ identifies the resulting complex with this one, so the exactness conclusion is unchanged.
Let $R$ be a ring, $M$ an $R$-module, and $f_1, \ldots, f_r \in R$ such that for $i = 1, \ldots, r$ multiplication by $f_i$ is injective on $M/(f_1, \ldots, f_{i - 1})M$. Then $f_1, \ldots, f_r$ is $M$-Koszul regular. In particular, an $M$-regular sequence is $M$-Koszul-regular and any regular sequence is Koszul-regular.
Proof. Let $R$, $M$, $f_1, \ldots, f_r$ be as in the first sentence of the lemma. If $r = 1$, it is immediate that $f_1$ is $M$-Koszul-regular. Assume $r > 1$. Since $f_1$ is a nonzerodivisor on $M$, we obtain a short exact sequence of complexes: $$0 \to K_\bullet(f_2, \ldots, f_r) \otimes M \xrightarrow{f_1} K_\bullet(f_2, \ldots, f_r) \otimes M \to K_\bullet(\overline{f}_2, \ldots, \overline{f}_r) \otimes M/f_1M \to 0$$ Here $\overline{f}_i$ is the image of $f_i$ in $R/(f_1)$. By Lemma Koszul complexes, regular sequences and derived categories the complex $K_\bullet(f_1, \ldots, f_r)$ is isomorphic to the cone of multiplication by $f_1$ on $K_\bullet(f_2, \ldots, f_r)$. Thus $K_\bullet(R, f_1, \ldots, f_r) \otimes M$ is isomorphic to the cone on the first map. Hence $K_\bullet(\overline{f}_2, \ldots, \overline{f}_r) \otimes M/f_1M$ is quasi-isomorphic to $K_\bullet(f_1, \ldots, f_r) \otimes M$. As $R/(f_1)$, $M/f_1M$, $\overline{f}_2, \ldots, \overline{f}_r$ satisfy the conditions of the lemma, by induction we conclude this complex is acyclic in postive degrees. This finishes the proof of the first statement. The second statement immediately follows from the first. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $R$ be a ring. Let $m \in \mathbf{Z}$. Let $K^\bullet$ be a bounded above complex of $R$-modules such that $K^i$ is $(m - i)$-pseudo-coherent for all $i$. Then $K^\bullet$ is $m$-pseudo-coherent. In particular, if $K^\bullet$ is a bounded above complex of pseudo-coherent $R$-modules, then $K^\bullet$ is pseudo-coherent.
Proof. We may replace $K^\bullet$ by $\sigma_{\geq m - 1}K^\bullet$ (for example) and hence assume that $K^\bullet$ is bounded. Then the complex $K^\bullet$ is $m$-pseudo-coherent as each $K^i[-i]$ is $m$-pseudo-coherent by induction on the length of the complex: use Lemma Pseudo-coherent complexes and coherent sheaves and the stupid truncations. For the final statement, it suffices to prove that $K^\bullet$ is $m$-pseudo-coherent for all $m \in \mathbf{Z}$, see Lemma Pseudo-coherent complexes and coherent sheaves. This follows from the first part. $\square$
Example. Derived tensor products and Tor amplitude
Let $K^\bullet, L^\bullet$ be objects of $D^{-}(R)$. Then there is a spectral sequence with $$E_2^{p, q} = H^p(K^\bullet \otimes_R^{\mathbf{L}} H^q(L^\bullet)) \Rightarrow H^{p + q}(K^\bullet \otimes_R^{\mathbf{L}} L^\bullet)$$ and another spectral sequence with $$E_2^{p, q} = H^p(H^q(K^\bullet) \otimes_R^{\mathbf{L}} L^\bullet) \Rightarrow H^{p + q}(K^\bullet \otimes_R^{\mathbf{L}} L^\bullet)$$ Both spectral sequences have $d_2^{p, q} : E_2^{p, q} \to E_2^{p + 2, q - 1}$. After replacing $K^\bullet$ and $L^\bullet$ by bounded above complexes of projectives, these spectral sequences are simply the two spectral sequences for computing the cohomology of $\text{Tot}(K^\bullet \otimes L^\bullet)$ discussed in Homology, Section Derived categories.
Lemma. Cotangent transitivity with a complete-intersection terminal map
Let $A \to B \to C$ be ring maps. Assume $B \to C$ is a local complete intersection homomorphism. Choose a presentation $\alpha : A[x_s, s \in S] \to B$ with kernel $I$. Choose a presentation $\beta : B[y_1, \ldots, y_m] \to C$ with kernel $J$. Let $\gamma : A[x_s, y_t] \to C$ be the induced presentation of $C$ with kernel $K$. Then we get a canonical commutative diagram $$\begin{gathered}\begin{matrix}0 & \Omega_{A[x_s]/A} \otimes C & \Omega_{A[x_s, y_t]/A} \otimes C & \Omega_{B[y_t]/B} \otimes C & 0 \\ 0 & I/I^2 \otimes C & K/K^2 & J/J^2 & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \Omega_{A[x_s]/A} \otimes C \\ \Omega_{A[x_s]/A} \otimes C & \longrightarrow \Omega_{A[x_s, y_t]/A} \otimes C \\ \Omega_{A[x_s, y_t]/A} \otimes C & \longrightarrow \Omega_{B[y_t]/B} \otimes C \\ \Omega_{B[y_t]/B} \otimes C & \longrightarrow 0 \\ 0 & \longrightarrow I/I^2 \otimes C \\ I/I^2 \otimes C & \longrightarrow K/K^2 \\ I/I^2 \otimes C & \longrightarrow \Omega_{A[x_s]/A} \otimes C \\ K/K^2 & \longrightarrow J/J^2 \\ K/K^2 & \longrightarrow \Omega_{A[x_s, y_t]/A} \otimes C \\ J/J^2 & \longrightarrow 0 \\ J/J^2 & \longrightarrow \Omega_{B[y_t]/B} \otimes C\end{aligned}\end{gathered}$$ with exact rows. In particular, the six term exact sequence of Algebra, Lemma The transitivity sequence for the naive cotangent complex (uncovered prerequisite) can be completed with a zero on the left, i.e., the sequence $$0 \to H_1(\mathrm{NL}_{B/A} \otimes_B C) \to H_1(L_{C/A}) \to H_1(L_{C/B}) \to \Omega_{B/A} \otimes_B C \to \Omega_{C/A} \to \Omega_{C/B} \to 0$$ is exact.
Proof. The only thing to prove is the injectivity of the map $I/I^2 \otimes C \to K/K^2$. By assumption the ideal $J$ is Koszul-regular. Hence we have $IA[x_s, y_j] \cap K^2 = IK$ by Lemma The conormal sequence for a first-homology regular ideal. This means that the kernel of $K/K^2 \to J/J^2$ is isomorphic to $IA[x_s, y_j]/IK$. Since $I/I^2 \otimes_B C = IA[x_s, y_j]/IK$ by right exactness of tensor product, this provides us with the desired injectivity of $I/I^2 \otimes_B C \to K/K^2$. $\square$
Lemma. Formal smoothness and smooth morphisms
Let $\varphi : R \to S$ be a ring map.
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If $R \to S$ is formally smooth in the sense of Algebra, Definition Formally smooth ring maps, then $R \to S$ is formally smooth for any linear topology on $R$ and any pre-adic topology on $S$ such that $R \to S$ is continuous.
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Let $\mathfrak n \subset S$ and $\mathfrak m \subset R$ ideals such that $\varphi$ is continuous for the $\mathfrak m$-adic topology on $R$ and the $\mathfrak n$-adic topology on $S$. Then the following are equivalent
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$\varphi$ is formally smooth for the $\mathfrak m$-adic topology on $R$ and the $\mathfrak n$-adic topology on $S$, and
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$\varphi$ is formally smooth for the discrete topology on $R$ and the $\mathfrak n$-adic topology on $S$.
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Proof. Assume $R \to S$ is formally smooth in the sense of Algebra, Definition Formally smooth ring maps. If $S$ has a pre-adic topology, then there exists an ideal $\mathfrak n \subset S$ such that $S$ has the $\mathfrak n$-adic topology. Suppose given a solid commutative diagram as in Definition Formally smooth ring maps. Continuity of $S \to A/J$ means that $\mathfrak n^k$ maps to zero in $A/J$ for some $k \geq 1$, see Lemma Derived commutative algebra. We obtain a ring map $\psi : S \to A$ from the assumed formal smoothness of $S$ over $R$. Then $\psi(\mathfrak n^k) \subset J$ hence $\psi(\mathfrak n^{2k}) = 0$ as $J^2 = 0$. Hence $\psi$ is continuous by Lemma Derived commutative algebra. This proves (1).
The proof of (2)(b) $\Rightarrow$ (2)(a) is the same as the proof of (1). Assume (2)(a). Suppose given a solid commutative diagram as in Definition Formally smooth ring maps where we use the discrete topology on $R$. Since $\varphi$ is continuous we see that $\varphi(\mathfrak m^n) \subset \mathfrak n$ for some $n \geq 1$. As $S \to A/J$ is continuous we see that $\mathfrak n^k$ maps to zero in $A/J$ for some $k \geq 1$. Hence $\mathfrak m^{nk}$ maps into $J$ under the map $R \to A$. Thus $\mathfrak m^{2nk}$ maps to zero in $A$ and we see that $R \to A$ is continuous in the $\mathfrak m$-adic topology. Thus (2)(a) gives a dotted arrow as desired. $\square$
Lemma. Formal smoothness and completion
Let $(R, \mathfrak m)$ and $(S, \mathfrak n)$ be rings endowed with finitely generated ideals. Endow $R$ and $S$ with the $\mathfrak m$-adic and $\mathfrak n$-adic topologies. Let $R \to S$ be a homomorphism of topological rings. The following are equivalent
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$R \to S$ is formally smooth for the $\mathfrak n$-adic topology,
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$R \to S^\wedge$ is formally smooth for the $\mathfrak n^\wedge$-adic topology,
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$R^\wedge \to S^\wedge$ is formally smooth for the $\mathfrak n^\wedge$-adic topology.
Here $R^\wedge$ and $S^\wedge$ are the $\mathfrak m$-adic and $\mathfrak n$-adic completions of $R$ and $S$.
Proof. The assumption that $\mathfrak m$ is finitely generated implies that $R^\wedge$ is $\mathfrak mR^\wedge$-adically complete, that $\mathfrak mR^\wedge = \mathfrak m^\wedge$ and that $R^\wedge/\mathfrak m^nR^\wedge = R/\mathfrak m^n$, see Algebra, Lemma Finite algebras (uncovered prerequisite) and its proof. Similarly for $(S, \mathfrak n)$. Thus it is clear that diagrams as in Definition Formally smooth ring maps for the cases (1), (2), and (3) are in 1-to-1 correspondence. $\square$
Definition. The Koszul complex
Let $R$ be a ring. Let $\varphi : E \to R$ be an $R$-module map. The Koszul complex $K_\bullet(\varphi)$ associated to $\varphi$ is the commutative differential graded algebra defined as follows:
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the underlying graded algebra is the exterior algebra $K_\bullet(\varphi) = \wedge(E)$,
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the differential $d : K_\bullet(\varphi) \to K_\bullet(\varphi)$ is the unique derivation such that $d(e) = \varphi(e)$ for all $e \in E = K_1(\varphi)$.
Lemma. Koszul complexes, regular sequences and derived categories
Let $R$ be a ring. Let $f_1, \ldots, f_r$ be a sequence of elements of $R$. The complex $K_\bullet(f_1, \ldots, f_r)$ is isomorphic to the cone of the map of complexes $$f_r : K_\bullet(f_1, \ldots, f_{r - 1}) \longrightarrow K_\bullet(f_1, \ldots, f_{r - 1}).$$
Proof. Special case of Lemma Koszul complexes, regular sequences and derived categories. $\square$
Lemma. The conormal sequence for a first-homology regular ideal
Let $A$ be a ring. Let $I \subset J \subset A$ be ideals. Assume that $J/I \subset A/I$ is a $H_1$-regular ideal. Then $I \cap J^2 = IJ$.
Proof. Follows immediately from Lemma The conormal sequence for a first-homology regular sequence by localizing. $\square$
Definition. Adically formally smooth ring maps
Let $R \to S$ be a ring map. Let $\mathfrak n \subset S$ be an ideal. If the equivalent conditions (2)(a) and (2)(b) of Lemma Formal smoothness and smooth morphisms hold, then we say $R \to S$ is formally smooth for the $\mathfrak n$-adic topology.
Definition. Formally smooth ring maps
Let $R \to S$ be a homomorphism of topological rings with $R$ and $S$ linearly topologized. We say $S$ is formally smooth over $R$ if for every commutative solid diagram $$\begin{gathered}\begin{matrix}S & A/J \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow A/J \\ S & \dashrightarrow A \\ R & \longrightarrow A \\ R & \longrightarrow S \\ A & \longrightarrow A/J\end{aligned}\end{gathered}$$ of homomorphisms of topological rings where $A$ is a discrete ring and $J \subset A$ is an ideal of square zero, a dotted arrow exists which makes the diagram commute.
Lemma. Formal smoothness and local algebra
Let $(R, \mathfrak m) \to (S, \mathfrak n)$ be a local homomorphism of local rings. The following are equivalent
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$R \to S$ is formally smooth in the $\mathfrak n$-adic topology,
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for every solid commutative diagram $$\begin{gathered}\begin{matrix}S & A/J \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow A/J \\ S & \dashrightarrow A \\ R & \longrightarrow A \\ R & \longrightarrow S \\ A & \longrightarrow A/J\end{aligned}\end{gathered}$$ of local homomorphisms of local rings where $J \subset A$ is an ideal of square zero, $\mathfrak m_A^n = 0$ for some $n > 0$, and $S \to A/J$ induces an isomorphism on residue fields, a dotted arrow exists which makes the diagram commute.
If $S$ is Noetherian these conditions are also equivalent to
- same as in (2) but only for diagrams where in addition $A \to A/J$ is a small extension (Algebra, Definition Commutative algebra).
Proof. The implication (1) $\Rightarrow$ (2) follows from the definitions. Consider a diagram $$\begin{gathered}\begin{matrix}S & A/J \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow A/J \\ S & \dashrightarrow A \\ R & \longrightarrow A \\ R & \longrightarrow S \\ A & \longrightarrow A/J\end{aligned}\end{gathered}$$ as in Definition Formally smooth ring maps for the $\mathfrak m$-adic topology on $R$ and the $\mathfrak n$-adic topology on $S$. Pick $m > 0$ with $\mathfrak n^m(A/J) = 0$ (possible by continuity of maps in diagram). Consider the subring $A'$ of $A$ which is the inverse image of the image of $S$ in $A/J$. Set $J' = J$ viewed as an ideal in $A'$. Then $J'$ is an ideal of square zero in $A'$ and $A'/J'$ is a quotient of $S/\mathfrak n^m$. Hence $A'$ is local and $\mathfrak m_{A'}^{2m} = 0$. Thus we get a diagram $$\begin{gathered}\begin{matrix}S & A'/J' \\ R & A'\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow A'/J' \\ S & \dashrightarrow A' \\ R & \longrightarrow A' \\ R & \longrightarrow S \\ A' & \longrightarrow A'/J'\end{aligned}\end{gathered}$$ as in (2). If we can construct the dotted arrow in this diagram, then we obtain the dotted arrow in the original one by composing with $A' \to A$. In this way we see that (2) implies (1).
Assume $S$ Noetherian. The implication (1) $\Rightarrow$ (3) is immediate. Assume (3) and suppose a diagram as in (2) is given. Then $\mathfrak m_A^n J = 0$ for some $n > 0$. Considering the maps $$A \to A/\mathfrak m_A^{n - 1}J \to \ldots \to A/\mathfrak mJ \to A/J$$ we see that it suffices to produce the lifting if $\mathfrak m_A J = 0$. Assume $\mathfrak m_A J = 0$ and let $A' \subset A$ be the ring constructed above. Then $A'/J'$ is Artinian as a quotient of the Artinian local ring $S/\mathfrak n^m$. Thus it suffices to show that given property (3) we can find the dotted arrow in diagrams as in (2) with $A/J$ Artinian and $\mathfrak m_A J = 0$. Let $\kappa$ be the common residue field of $A$, $A/J$, and $S$. By (3), if $J_0 \subset J$ is an ideal with $\dim_\kappa(J/J_0) = 1$, then we can produce a dotted arrow $S \to A/J_0$. Taking the product we obtain $$S \longrightarrow \prod\nolimits_{J_0 \text{ as above}} A/J_0$$ Clearly the image of this arrow is contained in the sub $R$-algebra $A'$ of elements which map into the small diagonal $A/J \subset \prod_{J_0} A/J$. Let $J' \subset A'$ be the elements mapping to zero in $A/J$. Then $J'$ is an ideal of square zero and as $\kappa$-vector space equal to $$J' = \prod\nolimits_{J_0 \text{ as above}} J/J_0$$ Thus the map $J \to J'$ is injective. By the theory of vector spaces we can choose a splitting $J' = J \oplus M$. It follows that $$A' = A \oplus M$$ as an $R$-algebra. Hence the map $S \to A'$ can be composed with the projection $A' \to A$ to give the desired dotted arrow thereby finishing the proof of the lemma. $\square$
Proposition. Formal smoothness from flatness and formally smooth fibres
Let $A \to B$ be a local homomorphism of Noetherian local rings. Let $k$ be the residue field of $A$ and $\overline{B} = B \otimes_A k$ the special fibre. The following are equivalent
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$A \to B$ is flat and $\overline{B}$ is geometrically regular over $k$,
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$A \to B$ is flat and $k \to \overline{B}$ is formally smooth in the $\mathfrak m_{\overline{B}}$-adic topology, and
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$A \to B$ is formally smooth in the $\mathfrak m_B$-adic topology.
Proof. The equivalence of (1) and (2) follows from Theorem Regular maps and formal smoothness.
Assume (3). By Lemma Formal smoothness and flatness we see that $A \to B$ is flat. By Lemma Base change of formal smoothness we see that $k \to \overline{B}$ is formally smooth in the $\mathfrak m_{\overline{B}}$-adic topology. Thus (2) holds.
Assume (2). Lemma Formal smoothness and completion tells us formal smoothness is preserved under completion. The same is true for flatness by Algebra, Lemma Completion, Theorems 3.1–3.3, 4.1 and 5.1. Hence we may replace $A$ and $B$ by their respective completions and assume that $A$ and $B$ are Noetherian complete local rings. In this case choose a diagram $$\begin{gathered}\begin{matrix}S & B \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow B \\ R & \longrightarrow S \\ R & \longrightarrow A \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ as in Lemma Complete rings, formal power series and Noetherian rings. We will use all of the properties of this diagram without further mention. Fix a regular system of parameters $t_1, \ldots, t_d$ of $R$ with $t_1 = p$ in case the characteristic of $k$ is $p > 0$. Set $\overline{S} = S \otimes_R k$. Consider the short exact sequence $$0 \to J \to S \to B \to 0$$ As $\overline{B}$ and $\overline{S}$ are regular, the kernel of $\overline{S} \to \overline{B}$ is generated by elements $\overline{x}_1, \ldots, \overline{x}_r$ which form part of a regular system of parameters of $\overline{S}$, see Algebra, Lemma Regular rings (uncovered prerequisite). Lift these elements to $x_1, \ldots, x_r \in J$. Then $t_1, \ldots, t_d, x_1, \ldots, x_r$ is part of a regular system of parameters for $S$. Hence $S/(x_1, \ldots, x_r)$ is a power series ring over a field (if the characteristic of $k$ is zero) or a power series ring over a Cohen ring (if the characteristic of $k$ is $p > 0$), see Lemma Complete rings and formal power series. Moreover, it is still the case that $R \to S/(x_1, \ldots, x_r)$ maps $t_1, \ldots, t_d$ to a part of a regular system of parameters of $S/(x_1, \ldots, x_r)$. In other words, we may replace $S$ by $S/(x_1, \ldots, x_r)$ and assume we have a diagram $$\begin{gathered}\begin{matrix}S & B \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow B \\ R & \longrightarrow S \\ R & \longrightarrow A \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ as in Lemma Complete rings, formal power series and Noetherian rings with moreover $\overline{S} = \overline{B}$. In this case the map $$S \otimes_R A \longrightarrow B$$ is an isomorphism as it is surjective, an isomorphism on special fibres, and source and target are flat over $A$ (for example use Algebra, Lemma Injectivity from a fibrewise injectivity criterion (uncovered prerequisite) or use that tensoring the short exact sequence $0 \to I \to S \otimes_R A \to B \to 0$ over $A$ with $k$ we find $I \otimes_A k = 0$ hence $I = 0$ by Nakayama). Thus by Lemma Base change of formal smoothness it suffices to show that $R \to S$ is formally smooth in the $\mathfrak m_S$-adic topology. Of course, since $\overline{S} = \overline{B}$, we have that $\overline{S}$ is formally smooth over $k = R/\mathfrak m_R$.
Choose elements $y_1, \ldots, y_m \in S$ such that $t_1, \ldots, t_d, y_1, \ldots, y_m$ is a regular system of parameters for $S$. If the characteristic of $k$ is zero, choose a coefficient field $K \subset S$ and if the characteristic of $k$ is $p > 0$ choose a Cohen ring $\Lambda \subset S$ with residue field $K$. At this point the map $K[[t_1, \ldots, t_d, y_1, \ldots, y_m]] \to S$ (characteristic zero case) or $\Lambda[[t_2, \ldots, t_d, y_1, \ldots, y_m]] \to S$ (characteristic $p > 0$ case) is an isomorphism, see Lemma Complete rings and formal power series. From now on we think of $S$ as the above power series ring.
The rest of the proof is analogous to the argument in the proof of Theorem Regular maps and formal smoothness. Choose a solid diagram $$\begin{gathered}\begin{matrix}S & N/J \\ R & N\end{matrix} \\[6pt] \begin{aligned}S & \xrightarrow{\bar\psi} N/J \\ S & \dashrightarrow N \\ R & \xrightarrow{i} S \\ R & \xrightarrow{\varphi} N \\ N & \xrightarrow{\pi} N/J\end{aligned}\end{gathered}$$ as in Definition Formally smooth ring maps. As $J^2 = 0$ we see that $J$ has a canonical $N/J$ module structure and via $\bar\psi$ a $S$-module structure. As $\bar\psi$ is continuous for the $\mathfrak m_S$-adic topology we see that $\mathfrak m_S^nJ = 0$ for some $n$. Hence we can filter $J$ by $N/J$-submodules $0 \subset J_1 \subset J_2 \subset \ldots \subset J_n = J$ such that each quotient $J_{t + 1}/J_t$ is annihilated by $\mathfrak m_S$. Considering the sequence of ring maps $N \to N/J_1 \to N/J_2 \to \ldots \to N/J$ we see that it suffices to prove the existence of the dotted arrow when $J$ is annihilated by $\mathfrak m_S$, i.e., when $J$ is a $K$-vector space.
Assume given a diagram as above such that $J$ is annihilated by $\mathfrak m_S$. As $\mathbf{Q} \to S$ (characteristic zero case) or $\mathbf{Z} \to S$ (characteristic $p > 0$ case) is formally smooth in the $\mathfrak m_S$-adic topology (see Lemma Formal smoothness and complete rings and formal power series), we can find a ring map $\psi : S \to N$ such that $\pi \circ \psi = \bar \psi$. Since $S$ is a power series ring in $t_1, \ldots, t_d$ (characteristic zero) or $t_2, \ldots, t_d$ (characteristic $p > 0$) over a subring, it follows from the universal property of power series rings that we can change our choice of $\psi$ so that $\psi(t_i)$ equals $\varphi(t_i)$ (automatic for $t_1 = p$ in the characteristic $p$ case). Then $\psi \circ i$ and $\varphi : R \to N$ are two maps whose compositions with $\pi$ are equal and which agree on $t_1, \ldots, t_d$. Hence $D = \psi \circ i - \varphi : R \to J$ is a derivation which annihilates $t_1, \ldots, t_d$. By Algebra, Lemma The universal property of Kähler differentials (uncovered prerequisite) we can write $D = \xi \circ \text{d}$ for some $R$-linear map $\xi : \Omega_{R/\mathbf{Z}} \to J$ which annihilates $\text{d}t_1, \ldots, \text{d}t_d$ (by construction) and $\mathfrak m_R \Omega_{R/\mathbf{Z}}$ (as $J$ is annihilated by $\mathfrak m_R$). Hence $\xi$ factors as a composition $$\Omega_{R/\mathbf{Z}} \to \Omega_{k/\mathbf{Z}} \xrightarrow{\xi'} J$$ where $\xi'$ is $k$-linear. Using the $K$-vector space structure on $J$ we extend $\xi'$ to a $K$-linear map $$\xi'' : \Omega_{k/\mathbf{Z}} \otimes_k K \longrightarrow J.$$ Using that $\overline{S}/k$ is formally smooth we see that $$\Omega_{k/\mathbf{Z}} \otimes_k K \to \Omega_{\overline{S}/\mathbf{Z}} \otimes_S K$$ is injective by Theorem Regular maps and formal smoothness (this is true also in the characteristic zero case as it is even true that $\Omega_{k/\mathbf{Z}} \to \Omega_{K/\mathbf{Z}}$ is injective in characteristic zero, see Algebra, Proposition Characterizations of separable field extensions (uncovered prerequisite)). Hence we can find a $K$-linear map $\xi''' : \Omega_{\overline{S}/\mathbf{Z}} \otimes_S K \to J$ whose restriction to $\Omega_{k/\mathbf{Z}} \otimes_k K$ is $\xi''$. Write $$D' : S \xrightarrow{\text{d}} \Omega_{S/\mathbf{Z}} \to \Omega_{\overline{S}/\mathbf{Z}} \to \Omega_{\overline{S}/\mathbf{Z}} \otimes_S K \xrightarrow{\xi'''} J.$$ Finally, set $\psi' = \psi - D' : S \to N$. The reader verifies that $\psi'$ is a ring map such that $\pi \circ \psi' = \bar \psi$ and such that $\psi' \circ i = \varphi$ as desired. $\square$
Lemma. Derived commutative algebra
Let $\varphi : R \to S$ be a ring map. Let $I \subset R$ and $J \subset S$ be ideals and endow $R$ with the $I$-adic topology and $S$ with the $J$-adic topology. Then $\varphi$ is a homomorphism of topological rings if and only if $\varphi(I^n) \subset J$ for some $n \geq 1$.
Proof. Omitted. $\square$
Definition. Auto-associated local rings
A ring $R$ is said to be auto-associated if $R$ is local and its maximal ideal $\mathfrak m$ is weakly associated to $R$.
Lemma. Equivalent splitting conditions for injections of finite projectives
Let $R$ be a ring. The following are equivalent
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$R$ has property (P) of Lemma Derived commutative algebra,
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any injective map of projective $R$-modules is universally injective,
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if $u : N \to M$ is injective and $N$, $M$ are finite projective $R$-modules then $\operatorname{Coker}(u)$ is a finite projective $R$-module,
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if $N \subset M$ and $N$, $M$ are finite projective as $R$-modules, then $N$ is a direct summand of $M$, and
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any injective map $R \to R^{\oplus n}$ is a split injection.
Proof. The implication (1) $\Rightarrow$ (2) is Lemma Universal injectivity under the module condition P. It is clear that (3) and (4) are equivalent. We have (2) $\Rightarrow$ (3), (4) by Algebra, Lemma Commutative algebra (uncovered prerequisite). Part (5) is a special case of (4). Assume (5). Let $I = (a_1, \ldots, a_n)$ be a proper finitely generated ideal of $R$. As $I \not = R$ we see that $R \to R^{\oplus n}$, $x \mapsto (xa_1, \ldots, xa_n)$ is not a split injection. Hence it has a nonzero kernel and we conclude that $\text{Ann}_R(I) \not = 0$. Thus (1) holds. $\square$
Lemma. Base change for flatness and prime spectra and associated points
In Situation Flatness let $R' \to R''$ be an $R$-algebra map. Let $I' \subset R'$ and $I'R'' \subset I'' \subset R''$ be ideals. If (Flatness and prime spectra and associated points) holds for $(R', I')$, then (Flatness and prime spectra and associated points) holds for $(R'', I'')$.
Proof. Assume (Flatness and prime spectra and associated points) holds for $(R', I')$. Let $I''S'' + JS'' \subset \mathfrak q''$ be a prime of $S''$. Let $\mathfrak q' \subset S'$ be the corresponding prime of $S'$. Then both $I'S' \subset \mathfrak q'$ and $JS' \subset \mathfrak q'$ because the corresponding conditions hold for $\mathfrak q''$. Note that $(M'')_{\mathfrak q''}$ is a localization of the base change $M'_{\mathfrak q'} \otimes_R R''$. Hence $(M'')_{\mathfrak q''}$ is flat over $R''$ as a localization of a flat module, see Algebra, Lemmas Base change of flat modules (uncovered prerequisite) and Localization of a flat module (uncovered prerequisite). $\square$
Lemma. Flatness and prime spectra and associated points
In Situation Flatness let $R' \to R''$ be an $R$-algebra map. Let $I' \subset R'$ and $I'R'' \subset I'' \subset R''$ be ideals. Assume
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the map $V(I'') \to V(I')$ induced by $\operatorname{Spec}(R'') \to \operatorname{Spec}(R')$ is surjective, and
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$R''_{\mathfrak p''}$ is flat over $R'$ for all primes $\mathfrak p'' \in V(I'')$.
If (Flatness and prime spectra and associated points) holds for $(R'', I'')$, then (Flatness and prime spectra and associated points) holds for $(R', I')$.
Proof. Assume (Flatness and prime spectra and associated points) holds for $(R'', I'')$. Pick a prime $I'S' + JS' \subset \mathfrak q' \subset S'$. Let $I' \subset \mathfrak p' \subset R'$ be the corresponding prime of $R'$. By assumption there exists a prime $\mathfrak p'' \in V(I'')$ of $R''$ lying over $\mathfrak p'$ and $R'_{\mathfrak p'} \to R''_{\mathfrak p''}$ is flat. Choose a prime $\overline{\mathfrak q}'' \subset \kappa(\mathfrak q') \otimes_{\kappa(\mathfrak p')} \kappa(\mathfrak p'')$. This corresponds to a prime $\mathfrak q'' \subset S'' = S' \otimes_{R'} R''$ which lies over $\mathfrak q'$ and over $\mathfrak p''$. In particular we see that $I''S'' \subset \mathfrak q''$ and that $JS'' \subset \mathfrak q''$. Note that $(S' \otimes_{R'} R'')_{\mathfrak q''}$ is a localization of $S'_{\mathfrak q'} \otimes_{R'_{\mathfrak p'}} R''_{\mathfrak p''}$. By assumption the module $(M' \otimes_{R'} R'')_{\mathfrak q''}$ is flat over $R''_{\mathfrak p''}$. Hence Algebra, Lemma Base change for flatness (uncovered prerequisite) implies that $M'_{\mathfrak q'}$ is flat over $R'_{\mathfrak p'}$ which is what we wanted to prove. $\square$
Lemma. Filtered limits and flatness and prime spectra and associated points
In Situation Flatness assume $R \to S$ is essentially of finite presentation and $M$ is an $S$-module of finite presentation. Let $R' = \mathop{\operatorname{colim}}_{\lambda \in \Lambda} R_\lambda$ be a directed colimit of $R$-algebras. Let $I_\lambda \subset R_\lambda$ be ideals such that $I_\lambda R_\mu \subset I_\mu$ for all $\mu \geq \lambda$ and set $I' = \mathop{\operatorname{colim}}_\lambda I_\lambda$. If (Flatness and prime spectra and associated points) holds for $(R', I')$, then there exists a $\lambda \in \Lambda$ such that (Flatness and prime spectra and associated points) holds for $(R_\lambda, I_\lambda)$.
Proof. We first prove the lemma in case $R \to S$ is of finite presentation and then we explain what needs to be changed in the general case. We are going to write $S_\lambda = S \otimes_R R_\lambda$, $S' = S \otimes_R R'$, $M_\lambda = M \otimes_R R_\lambda$, and $M' = M \otimes_R R'$. The base change $S'$ is of finite presentation over $R'$ and $M'$ is of finite presentation over $S'$ and similarly for the versions with subscript $\lambda$, see Algebra, Lemma Base change for finite algebras (uncovered prerequisite). By Algebra, Theorem Openness of the flat locus the set $$U' = \{\mathfrak q' \in \operatorname{Spec}(S') \mid M'_{\mathfrak q'}\text{ is flat over }R'\}$$ is open in $\operatorname{Spec}(S')$. Note that $V(I'S' + JS')$ is a quasi-compact space which is contained in $U'$ by assumption. Hence there exist finitely many $g'_j \in S'$, $j = 1, \ldots, m$ such that $D(g'_j) \subset U'$ and such that $V(I'S' + JS') \subset \bigcup D(g'_j)$. Note that in particular $(M')_{g'_j}$ is a flat module over $R'$.
We are going to pick increasingly large elements $\lambda \in \Lambda$. First we pick it large enough so that we can find $g_{j, \lambda} \in S_{\lambda}$ mapping to $g'_j$. The inclusion $V(I'S' + JS') \subset \bigcup D(g'_j)$ means that $I'S' + JS' + (g'_1, \ldots, g'_m) = S'$ which can be expressed as $$1 = \sum y_tk_t + \sum z_sh_s + \sum f_jg'_j$$ for some $z_s \in I'$, $y_t \in J$, $k_t, h_s, f_j \in S'$. After increasing $\lambda$ we may assume such an equation holds in $S_\lambda$. Hence we may assume that $V(I_\lambda S_\lambda + J S_\lambda) \subset \bigcup D(g_{j, \lambda})$. By Algebra, Lemma Lesson 3, Section 5.6.7, C.1 we see that for some sufficiently large $\lambda$ the modules $(M_\lambda)_{g_{j, \lambda}}$ are flat over $R_\lambda$. In particular the module $M_\lambda$ is flat over $R_\lambda$ at all the primes corresponding to points of $V(I_\lambda S_\lambda + J S_\lambda)$.
In the case that $S$ is essentially of finite presentation, we can write $S = \Sigma^{-1}C$ where $R \to C$ is of finite presentation and $\Sigma \subset C$ is a multiplicative subset. We can also write $M = \Sigma^{-1}N$ for some finitely presented $C$-module $N$, see Algebra, Lemma Finite presentation and modules (uncovered prerequisite). At this point we introduce $C_\lambda$, $C'$, $N_\lambda$, $N'$. Then in the discussion above we obtain an open $U' \subset \operatorname{Spec}(C')$ over which $N'$ is flat over $R'$. The assumption that (Flatness and prime spectra and associated points) is true means that $V(I'S' + JS')$ maps into $U'$, because for a prime $\mathfrak q' \subset S'$, corresponding to a prime $\mathfrak r' \subset C'$ we have $M'_{\mathfrak q'} = N'_{\mathfrak r'}$. Thus we can find $g'_j \in C'$ such that $\bigcup D(g'_j)$ contains the image of $V(I'S' + JS')$. The rest of the proof is exactly the same as before. $\square$
Lemma. The conormal sequence for a first-homology regular sequence
Let $A$ be a ring. Let $I \subset J \subset A$ be ideals. Assume that $J/I \subset A/I$ is generated by an $H_1$-regular sequence. Then $I \cap J^2 = IJ$.
Proof. To prove this choose $g_1, \ldots, g_m \in J$ whose images in $A/I$ form a $H_1$-regular sequence which generates $J/I$. In particular $J = I + (g_1, \ldots, g_m)$. Suppose that $x \in I \cap J^2$. Because $x \in J^2$ can write $$x = \sum a_{ij} g_ig_j + \sum a_j g_j + a$$ with $a_{ij} \in A$, $a_j \in I$ and $a \in I^2$. Then $\sum a_{ij}g_ig_j \in I \cap (g_1, \ldots, g_m)$ hence by Lemma First cotangent homology after a regular quotient we see that $\sum a_{ij}g_ig_j \in I(g_1, \ldots, g_m)$. Thus $x \in IJ$ as desired. $\square$
Theorem. Regular maps and formal smoothness
Let $k$ be a field. Let $(A, \mathfrak m, K)$ be a Noetherian local $k$-algebra. If the characteristic of $k$ is zero then the following are equivalent
-
$A$ is a regular local ring, and
-
$k \to A$ is formally smooth in the $\mathfrak m$-adic topology.
If the characteristic of $k$ is $p > 0$ then the following are equivalent
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$A$ is geometrically regular over $k$,
-
$k \to A$ is formally smooth in the $\mathfrak m$-adic topology.
-
for all $k \subset k' \subset k^{1/p}$ finite over $k$ the ring $A \otimes_k k'$ is regular,
-
$A$ is regular and the canonical map $H_1(L_{K/k}) \to \mathfrak m/\mathfrak m^2$ is injective, and
-
$A$ is regular and the map $\Omega_{k/\mathbf{F}_p} \otimes_k K \to \Omega_{A/\mathbf{F}_p} \otimes_A K$ is injective.
Proof. If the characteristic of $k$ is zero, then the equivalence of (1) and (2) follows from Lemmas Formal smoothness implies regularity and Regularity implies formal smoothness.
If the characteristic of $k$ is $p > 0$, then it follows from Proposition Characterizations of geometric regularity that (1), (3), (4), and (5) are equivalent. Assume (2) holds. By Lemma Base change of formal smoothness we see that $k' \to A' = A \otimes_k k'$ is formally smooth for the $\mathfrak m' = \mathfrak mA'$-adic topology. Hence if $k \subset k'$ is finite purely inseparable, then $A'$ is a regular local ring by Lemma Formal smoothness implies regularity. Thus we see that (1) holds.
Finally, we will prove that (5) implies (2). Choose a solid diagram $$\begin{gathered}\begin{matrix}A & B/J \\ k & B\end{matrix} \\[6pt] \begin{aligned}A & \xrightarrow{\bar\psi} B/J \\ A & \dashrightarrow B \\ k & \xrightarrow{i} A \\ k & \xrightarrow{\varphi} B \\ B & \xrightarrow{\pi} B/J\end{aligned}\end{gathered}$$ as in Definition Formally smooth ring maps. As $J^2 = 0$ we see that $J$ has a canonical $B/J$ module structure and via $\bar\psi$ an $A$-module structure. As $\bar\psi$ is continuous for the $\mathfrak m$-adic topology we see that $\mathfrak m^nJ = 0$ for some $n$. Hence we can filter $J$ by $B/J$-submodules $0 \subset J_1 \subset J_2 \subset \ldots \subset J_n = J$ such that each quotient $J_{t + 1}/J_t$ is annihilated by $\mathfrak m$. Considering the sequence of ring maps $B \to B/J_1 \to B/J_2 \to \ldots \to B/J$ we see that it suffices to prove the existence of the dotted arrow when $J$ is annihilated by $\mathfrak m$, i.e., when $J$ is a $K$-vector space.
Assume given a diagram as above such that $J$ is annihilated by $\mathfrak m$. By Lemma Regularity implies formal smoothness we see that $\mathbf{F}_p \to A$ is formally smooth in the $\mathfrak m$-adic topology. Hence we can find a ring map $\psi : A \to B$ such that $\pi \circ \psi = \bar \psi$. Then $\psi \circ i, \varphi : k \to B$ are two maps whose compositions with $\pi$ are equal. Hence $D = \psi \circ i - \varphi : k \to J$ is a derivation. By Algebra, Lemma The universal property of Kähler differentials (uncovered prerequisite) we can write $D = \xi \circ \text{d}$ for some $k$-linear map $\xi : \Omega_{k/\mathbf{F}_p} \to J$. Using the $K$-vector space structure on $J$ we extend $\xi$ to a $K$-linear map $\xi' : \Omega_{k/\mathbf{F}_p} \otimes_k K \to J$. Using (5) we can find a $K$-linear map $\xi'' : \Omega_{A/\mathbf{F}_p} \otimes_A K$ whose restriction to $\Omega_{k/\mathbf{F}_p} \otimes_k K$ is $\xi'$. Write $$D' : A \xrightarrow{\text{d}} \Omega_{A/\mathbf{F}_p} \to \Omega_{A/\mathbf{F}_p} \otimes_A K \xrightarrow{\xi''} J.$$ Finally, set $\psi' = \psi - D' : A \to B$. The reader verifies that $\psi'$ is a ring map such that $\pi \circ \psi' = \bar \psi$ and such that $\psi' \circ i = \varphi$ as desired. $\square$
Lemma. Formal smoothness and flatness
Let $A \to B$ be a local homomorphism of Noetherian local rings. Assume $A \to B$ is formally smooth in the $\mathfrak m_B$-adic topology. Then $A \to B$ is flat.
Proof. We may assume that $A$ and $B$ a Noetherian complete local rings by Lemma Formal smoothness and completion and Algebra, Lemma Complete rings, formal power series and Noetherian rings (uncovered prerequisite) (this also uses Algebra, Lemma Descent of flatness (uncovered prerequisite) and Completion, Theorems 3.1–3.3, 4.1 and 5.1 to see that flatness of the map on completions implies flatness of $A \to B$). Choose a commutative diagram $$\begin{gathered}\begin{matrix}S & B \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow B \\ R & \longrightarrow S \\ R & \longrightarrow A \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ as in Lemma Complete rings, formal power series and Noetherian rings with $R \to S$ flat. Let $I \subset R$ be the kernel of $R \to A$. Because $B$ is formally smooth over $A$ we see that the $A$-algebra map $$S/IS \longrightarrow B$$ has a section, see Lemma Lifting derived commutative algebra. Hence $B$ is a direct summand of the flat $A$-module $S/IS$ (by base change of flatness, see Algebra, Lemma Base change of flat modules (uncovered prerequisite)), whence flat. $\square$
Lemma. Base change of formal smoothness
Let $R$, $S$ be rings. Let $\mathfrak n \subset S$ be an ideal. Let $R \to S$ be formally smooth for the $\mathfrak n$-adic topology. Let $R \to R'$ be any ring map. Then $R' \to S' = S \otimes_R R'$ is formally smooth in the $\mathfrak n' = \mathfrak nS'$-adic topology.
Proof. Let a solid diagram $$\begin{gathered}\begin{matrix}S & S' & A/J \\ R & R' & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow S' \\ S & \dashrightarrow A \\ S' & \longrightarrow A/J \\ S' & \dashrightarrow A \\ R & \longrightarrow S \\ R & \longrightarrow R' \\ R' & \longrightarrow A \\ R' & \longrightarrow S' \\ A & \longrightarrow A/J\end{aligned}\end{gathered}$$ as in Definition Formally smooth ring maps be given. Then the composition $S \to S' \to A/J$ is continuous. By assumption the longer dotted arrow exists. By the universal property of tensor product we obtain the shorter dotted arrow. $\square$
Lemma. Complete rings, formal power series and Noetherian rings
Let $A \to B$ be a local homomorphism of Noetherian complete local rings. Then there exists a commutative diagram $$\begin{gathered}\begin{matrix}S & B \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow B \\ R & \longrightarrow S \\ R & \longrightarrow A \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ with the following properties:
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the horizontal arrows are surjective,
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if the characteristic of $A/\mathfrak m_A$ is zero, then $S$ and $R$ are power series rings over fields,
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if the characteristic of $A/\mathfrak m_A$ is $p > 0$, then $S$ and $R$ are power series rings over Cohen rings, and
-
$R \to S$ maps a regular system of parameters of $R$ to part of a regular system of parameters of $S$.
In particular $R \to S$ is flat (see Algebra, Lemma Flatness over a regular local ring (uncovered prerequisite)) with regular fibre $S/\mathfrak m_R S$ (see Algebra, Lemma Regular rings are Cohen–Macaulay (uncovered prerequisite)).
Proof. Use the Cohen structure theorem (Algebra, Theorem Commutative algebra (uncovered prerequisite)) to choose a surjection $S \to B$ as in the statement of the lemma where we choose $S$ to be a power series over a Cohen ring if the residue characteristic is $p > 0$ and a power series over a field else. Let $J \subset S$ be the kernel of $S \to B$. Next, choose a surjection $R = \Lambda[[x_1, \ldots, x_n]] \to A$ where we choose $\Lambda$ to be a Cohen ring if the residue characteristic of $A$ is $p > 0$ and $\Lambda$ equal to the residue field of $A$ otherwise. We lift the composition $\Lambda[[x_1, \ldots, x_n]] \to A \to B$ to a map $\varphi : R \to S$. This is possible because $\Lambda[[x_1, \ldots, x_n]]$ is formally smooth over $\mathbf{Z}$ in the $\mathfrak m$-adic topology (see Lemma Formal smoothness and complete rings and formal power series) by an application of Lemma Lifting derived commutative algebra. Finally, we replace $\varphi$ by the map $\varphi' : R = \Lambda[[x_1, \ldots, x_n]] \to S' = S[[y_1, \ldots, y_n]]$ with $\varphi'|_\Lambda = \varphi|_\Lambda$ and $\varphi'(x_i) = \varphi(x_i) + y_i$. We also replace $S \to B$ by the map $S' \to B$ which maps $y_i$ to zero. After this replacement it is clear that a regular system of parameters of $R$ maps to part of a regular sequence in $S'$ and we win. $\square$
Lemma. Complete rings and formal power series
Let $K$ be a field and $A = K[[x_1, \ldots, x_n]]$. Let $\Lambda$ be a Cohen ring and let $B = \Lambda[[x_1, \ldots, x_n]]$.
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If $y_1, \ldots, y_n \in A$ is a regular system of parameters then $K[[y_1, \ldots, y_n]] \to A$ is an isomorphism.
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If $z_1, \ldots, z_r \in A$ form part of a regular system of parameters for $A$, then $r \leq n$ and $A/(z_1, \ldots, z_r) \cong K[[y_1, \ldots, y_{n - r}]]$.
-
If $p, y_1, \ldots, y_n \in B$ is a regular system of parameters then $\Lambda[[y_1, \ldots, y_n]] \to B$ is an isomorphism.
-
If $p, z_1, \ldots, z_r \in B$ form part of a regular system of parameters for $B$, then $r \leq n$ and $B/(z_1, \ldots, z_r) \cong \Lambda[[y_1, \ldots, y_{n - r}]]$.
Proof. Proof of (1). Set $A' = K[[y_1, \ldots, y_n]]$. It is clear that the map $A' \to A$ induces an isomorphism $A'/\mathfrak m_{A'}^n \to A/\mathfrak m_A^n$ for all $n \geq 1$. Since $A$ and $A'$ are both complete we deduce that $A' \to A$ is an isomorphism. Proof of (2). Extend $z_1, \ldots, z_r$ to a regular system of parameters $z_1, \ldots, z_r, y_1, \ldots, y_{n - r}$ of $A$. Consider the map $A' = K[[z_1, \ldots, z_r, y_1, \ldots, y_{n - r}]] \to A$. This is an isomorphism by (1). Hence (2) follows as it is clear that $A'/(z_1, \ldots, z_r) \cong K[[y_1, \ldots, y_{n - r}]]$. The proofs of (3) and (4) are exactly the same as the proofs of (1) and (2). $\square$
Lemma. Formal smoothness and complete rings and formal power series
Let $K$ be a field of characteristic $0$ and $A = K[[x_1, \ldots, x_n]]$. Let $L$ be a field of characteristic $p > 0$ and $B = L[[x_1, \ldots, x_n]]$. Let $\Lambda$ be a Cohen ring. Let $C = \Lambda[[x_1, \ldots, x_n]]$.
-
$\mathbf{Q} \to A$ is formally smooth in the $\mathfrak m_A$-adic topology.
-
$\mathbf{F}_p \to B$ is formally smooth in the $\mathfrak m_B$-adic topology.
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$\mathbf{Z} \to C$ is formally smooth in the $\mathfrak m_C$-adic topology.
Proof. By the universal property of power series rings it suffices to prove:
-
$\mathbf{Q} \to K$ is formally smooth.
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$\mathbf{F}_p \to L$ is formally smooth.
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$\mathbf{Z} \to \Lambda$ is formally smooth in the $\mathfrak m_\Lambda$-adic topology.
The first two are Algebra, Proposition Characterizations of separable field extensions (uncovered prerequisite). The third follows from Algebra, Lemma Formal smoothness and smooth morphisms (uncovered prerequisite) since for any test diagram as in Definition Formally smooth ring maps some power of $p$ will be zero in $A/J$ and hence some power of $p$ will be zero in $A$. $\square$
Lemma. Derived commutative algebra
An auto-associated ring $R$ has the following property: (P) Every proper finitely generated ideal $I \subset R$ has a nonzero annihilator.
Proof. By assumption there exists a nonzero element $x \in R$ such that for every $f \in \mathfrak m$ we have $f^n x = 0$. Say $I = (f_1, \ldots, f_r)$. Then $x$ is in the kernel of $R \to \bigoplus R_{f_i}$. Hence we see that there exists a nonzero $y \in R$ such that $f_i y = 0$ for all $i$, see Algebra, Lemma Injective resolutions (uncovered prerequisite). As $y \in \text{Ann}_R(I)$ we win. $\square$
Lemma. Universal injectivity under the module condition P
Let $R$ be a ring having property (P) of Lemma Derived commutative algebra. Let $u : N \to M$ be a homomorphism of projective $R$-modules. Then $u$ is universally injective if and only if $u$ is injective.
Proof. Assume $u$ is injective. Our goal is to show $u$ is universally injective. First we choose a module $Q$ such that $N \oplus Q$ is free. On considering the map $N \oplus Q \to M \oplus Q$ we see that it suffices to prove the lemma in case $N$ is free. In this case $N$ is a directed colimit of finite free $R$-modules. Thus we reduce to the case that $N$ is a finite free $R$-module, say $N = R^{\oplus n}$. We prove the lemma by induction on $n$. The case $n = 0$ is trivial.
Let $u : R^{\oplus n} \to M$ be an injective module map with $M$ projective. Choose an $R$-module $Q$ such that $M \oplus Q$ is free. After replacing $u$ by the composition $R^{\oplus n} \to M \to M \oplus Q$ we see that we may assume that $M$ is free. Then we can find a direct summand $R^{\oplus m} \subset M$ such that $u(R^{\oplus n}) \subset R^{\oplus m}$. Hence we may assume that $M = R^{\oplus m}$. In this case $u$ is given by a matrix $A = (a_{ij})$ so that $u(x_1, \ldots, x_n) = (\sum x_i a_{i1}, \ldots, \sum x_i a_{im})$. As $u$ is injective, in particular $u(x, 0, \ldots, 0) = (xa_{11}, xa_{12}, \ldots, xa_{1m}) \not = 0$ if $x \not = 0$, and as $R$ has property (P) we see that $a_{11}R + a_{12}R + \ldots + a_{1m}R = R$. Hence see that $R(a_{11}, \ldots, a_{1m}) \subset R^{\oplus m}$ is a direct summand of $R^{\oplus m}$, in particular $R^{\oplus m}/R(a_{11}, \ldots, a_{1m})$ is a projective $R$-module. We get a commutative diagram $$\begin{gathered}\begin{matrix}0 & R & \phantom{X} & R^{\oplus n} & R^{\oplus n - 1} & 0 \\ 0 & R & \phantom{X} & R^{\oplus m} & R^{\oplus m}/R(a_{11}, \ldots, a_{1m}) & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow R \\ R & \longrightarrow R^{\oplus n} \\ R & \xrightarrow{1} R \\ R^{\oplus n} & \longrightarrow R^{\oplus n - 1} \\ R^{\oplus n} & \xrightarrow{u} R^{\oplus m} \\ R^{\oplus n - 1} & \longrightarrow 0 \\ R^{\oplus n - 1} & \longrightarrow R^{\oplus m}/R(a_{11}, \ldots, a_{1m}) \\ 0 & \longrightarrow R \\ R & \xrightarrow{(a_{11}, \ldots, a_{1m})} R^{\oplus m} \\ R^{\oplus m} & \longrightarrow R^{\oplus m}/R(a_{11}, \ldots, a_{1m}) \\ R^{\oplus m}/R(a_{11}, \ldots, a_{1m}) & \longrightarrow 0\end{aligned}\end{gathered}$$ with split exact rows. Thus the right vertical arrow is injective and we may apply the induction hypothesis to conclude that the right vertical arrow is universally injective. It follows that the middle vertical arrow is universally injective. $\square$
Situation. Flatness
Let $R \to S$ be a ring map. Let $J \subset S$ be an ideal. Let $M$ be an $S$-module.
Lemma. First cotangent homology after a regular quotient
Let $A$ be a ring. Let $I \subset A$ be an ideal. Let $g_1, \ldots, g_m$ be a sequence in $A$ whose image in $A/I$ is $H_1$-regular. Then $I \cap (g_1, \ldots, g_m) = I(g_1, \ldots, g_m)$.
Proof. Consider the exact sequence of complexes $$0 \to I \otimes_A K_\bullet(A, g_1, \ldots, g_m) \to K_\bullet(A, g_1, \ldots, g_m) \to K_\bullet(A/I, g_1, \ldots, g_m) \to 0$$ Since the complex on the right has $H_1 = 0$ by assumption we see that $$\operatorname{Coker}(I^{\oplus m} \to I) \longrightarrow \operatorname{Coker}(A^{\oplus m} \to A)$$ is injective. This is equivalent to the assertion of the lemma. $\square$
Lemma. Formal smoothness implies regularity
Let $k$ be a field and let $(A, \mathfrak m, K)$ be a Noetherian local $k$-algebra. If $k \to A$ is formally smooth for the $\mathfrak m$-adic topology, then $A$ is a regular local ring.
Proof. Let $k_0 \subset k$ be the prime field. Then $k_0$ is perfect, hence $k / k_0$ is separable, hence formally smooth by Algebra, Lemma Elementary formally smooth extensions (uncovered prerequisite). By Lemmas Formal smoothness and smooth morphisms and Composition of formally smooth maps (uncovered prerequisite) we see that $k_0 \to A$ is formally smooth for the $\mathfrak m$-adic topology on $A$. Hence we may assume $k = \mathbf{Q}$ or $k = \mathbf{F}_p$.
By Algebra, Lemmas Completion, Theorems 3.1–3.3, 4.1 and 5.1 and Flatness and regular ring maps (uncovered prerequisite) it suffices to prove the completion $A^\wedge$ is regular. By Lemma Formal smoothness and completion we may replace $A$ by $A^\wedge$. Thus we may assume that $A$ is a Noetherian complete local ring. By the Cohen structure theorem (Algebra, Theorem Commutative algebra (uncovered prerequisite)) there exist a map $K \to A$. As $k$ is the prime field we see that $K \to A$ is a $k$-algebra map.
Let $x_1, \ldots, x_n \in \mathfrak m$ be elements whose images form a basis of $\mathfrak m/\mathfrak m^2$. Set $T = K[[X_1, \ldots, X_n]]$. Note that $$A/\mathfrak m^2 \cong K[x_1, \ldots, x_n]/(x_ix_j)$$ and $$T/\mathfrak m_T^2 \cong K[X_1, \ldots, X_n]/(X_iX_j).$$ Let $A/\mathfrak m^2 \to T/m_T^2$ be the local $K$-algebra isomorphism given by mapping the class of $x_i$ to the class of $X_i$. Denote $f_1 : A \to T/\mathfrak m_T^2$ the composition of this isomorphism with the quotient map $A \to A/\mathfrak m^2$. The assumption that $k \to A$ is formally smooth in the $\mathfrak m$-adic topology means we can lift $f_1$ to a map $f_2 : A \to T/\mathfrak{m}_T^3$, then to a map $f_3 : A \to T/\mathfrak{m}_T^4$, and so on, for all $n \geq 1$. Warning: the maps $f_n$ are continuous $k$-algebra maps and may not be $K$-algebra maps. We get an induced map $f : A \to T = \varprojlim T/\mathfrak m_T^n$ of local $k$-algebras. By our choice of $f_1$, the map $f$ induces an isomorphism $\mathfrak m/\mathfrak m^2 \to \mathfrak m_T/\mathfrak m_T^2$ hence each $f_n$ is surjective and we conclude $f$ is surjective as $A$ is complete. This implies $\dim(A) \geq \dim(T) = n$. Hence $A$ is regular by definition. (It also follows that $f$ is an isomorphism.) $\square$
Lemma. Regularity implies formal smoothness
Let $k$ be a field. Let $(A, \mathfrak m, K)$ be a regular local $k$-algebra such that $K/k$ is separable. Then $k \to A$ is formally smooth in the $\mathfrak m$-adic topology.
Proof. It suffices to prove that the completion of $A$ is formally smooth over $k$, see Lemma Formal smoothness and completion. Hence we may assume that $A$ is a complete local regular $k$-algebra with residue field $K$ separable over $k$. By Lemma Complete rings, formal power series and field extensions we see that $A = K[[x_1, \ldots, x_n]]$.
The power series ring $K[[x_1, \ldots, x_n]]$ is formally smooth over $k$. Namely, $K$ is formally smooth over $k$ and $K[x_1, \ldots, x_n]$ is formally smooth over $K$ as a polynomial algebra. Hence $K[x_1, \ldots, x_n]$ is formally smooth over $k$ by Algebra, Lemma Composition of formally smooth maps (uncovered prerequisite). It follows that $k \to K[x_1, \ldots, x_n]$ is formally smooth for the $(x_1, \ldots, x_n)$-adic topology by Lemma Formal smoothness and smooth morphisms. Finally, it follows that $k \to K[[x_1, \ldots, x_n]]$ is formally smooth for the $(x_1, \ldots, x_n)$-adic topology by Lemma Formal smoothness and completion. $\square$
Proposition. Characterizations of geometric regularity
Let $k$ be a field of characteristic $p > 0$. Let $(A, \mathfrak m, K)$ be a Noetherian local $k$-algebra. The following are equivalent
-
$A$ is geometrically regular over $k$,
-
for all $k \subset k' \subset k^{1/p}$ finite over $k$ the ring $A \otimes_k k'$ is regular,
-
$A$ is regular and the canonical map $H_1(L_{K/k}) \to \mathfrak m/\mathfrak m^2$ is injective, and
-
$A$ is regular and the map $\Omega_{k/\mathbf{F}_p} \otimes_k K \to \Omega_{A/\mathbf{F}_p} \otimes_A K$ is injective.
Proof. Proof of (3) $\Rightarrow$ (1). Assume (3). Let $k'/k$ be a finite purely inseparable extension. Set $A' = A \otimes_k k'$. This is a local ring with maximal ideal $\mathfrak m'$. Set $K' = A'/\mathfrak m'$. We get a commutative diagram $$\begin{gathered}\begin{matrix}0 & H_1(L_{K/k}) \otimes K' & \mathfrak m/\mathfrak m^2 \otimes K' & \Omega_{A/k} \otimes_A K' & \Omega_{K/k} \otimes K' & 0 \\ \phantom{X} & H_1(L_{K'/k'}) & \mathfrak m'/(\mathfrak m')^2 & \Omega_{A'/k'} \otimes_{A'} K' & \Omega_{K'/k'} & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow H_1(L_{K/k}) \otimes K' \\ H_1(L_{K/k}) \otimes K' & \longrightarrow \mathfrak m/\mathfrak m^2 \otimes K' \\ H_1(L_{K/k}) \otimes K' & \xrightarrow{\beta} H_1(L_{K'/k'}) \\ \mathfrak m/\mathfrak m^2 \otimes K' & \longrightarrow \Omega_{A/k} \otimes_A K' \\ \mathfrak m/\mathfrak m^2 \otimes K' & \longrightarrow \mathfrak m'/(\mathfrak m')^2 \\ \Omega_{A/k} \otimes_A K' & \longrightarrow \Omega_{K/k} \otimes K' \\ \Omega_{A/k} \otimes_A K' & \xrightarrow{\cong} \Omega_{A'/k'} \otimes_{A'} K' \\ \Omega_{K/k} \otimes K' & \longrightarrow 0 \\ \Omega_{K/k} \otimes K' & \xrightarrow{\alpha} \Omega_{K'/k'} \\ H_1(L_{K'/k'}) & \longrightarrow \mathfrak m'/(\mathfrak m')^2 \\ \mathfrak m'/(\mathfrak m')^2 & \longrightarrow \Omega_{A'/k'} \otimes_{A'} K' \\ \Omega_{A'/k'} \otimes_{A'} K' & \longrightarrow \Omega_{K'/k'} \\ \Omega_{K'/k'} & \longrightarrow 0\end{aligned}\end{gathered}$$ with exact rows. The third vertical arrow is an isomorphism by base change for modules of differentials (Algebra, Lemma Base change of Kähler differentials). Thus $\alpha$ is surjective. By Lemma Compatibility of cotangent homology with a quotient we have $$\dim \operatorname{Ker}(\alpha) - \dim \operatorname{Ker}(\beta) + \dim \operatorname{Coker}(\beta) = 0$$ (and these dimensions are all finite). A diagram chase shows that $\dim \mathfrak m'/(\mathfrak m')^2 \leq \dim \mathfrak m/\mathfrak m^2$. However, since $A \to A'$ is finite flat we see that $\dim(A) = \dim(A')$, see Algebra, Lemma Dimensions of a base, fibre and total space (uncovered prerequisite). Hence $A'$ is regular by definition.
Equivalence of (3) and (4). Consider the Jacobi-Zariski sequences for rows of the commutative diagram $$\begin{gathered}\begin{matrix}\mathbf{F}_p & A & K \\ \mathbf{F}_p & k & K\end{matrix} \\[6pt] \begin{aligned}\mathbf{F}_p & \longrightarrow A \\ A & \longrightarrow K \\ \mathbf{F}_p & \longrightarrow k \\ \mathbf{F}_p & \longrightarrow \mathbf{F}_p \\ k & \longrightarrow K \\ k & \longrightarrow A \\ K & \longrightarrow K\end{aligned}\end{gathered}$$ to get a commutative diagram $$\begin{gathered}\begin{matrix}0 & \mathfrak m/\mathfrak m^2 & \Omega_{A/\mathbf{F}_p} \otimes_A K & \Omega_{K/\mathbf{F}_p} & 0 & \phantom{X} \\ 0 & H_1(L_{K/k}) & \Omega_{k/\mathbf{F}_p} \otimes_k K & \Omega_{K/\mathbf{F}_p} & \Omega_{K/k} & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \mathfrak m/\mathfrak m^2 \\ \mathfrak m/\mathfrak m^2 & \longrightarrow \Omega_{A/\mathbf{F}_p} \otimes_A K \\ \Omega_{A/\mathbf{F}_p} \otimes_A K & \longrightarrow \Omega_{K/\mathbf{F}_p} \\ \Omega_{K/\mathbf{F}_p} & \longrightarrow 0 \\ 0 & \longrightarrow H_1(L_{K/k}) \\ H_1(L_{K/k}) & \longrightarrow \Omega_{k/\mathbf{F}_p} \otimes_k K \\ H_1(L_{K/k}) & \longrightarrow \mathfrak m/\mathfrak m^2 \\ \Omega_{k/\mathbf{F}_p} \otimes_k K & \longrightarrow \Omega_{K/\mathbf{F}_p} \\ \Omega_{k/\mathbf{F}_p} \otimes_k K & \longrightarrow \Omega_{A/\mathbf{F}_p} \otimes_A K \\ \Omega_{K/\mathbf{F}_p} & \longrightarrow \Omega_{K/k} \\ \Omega_{K/\mathbf{F}_p} & \longrightarrow \Omega_{K/\mathbf{F}_p} \\ \Omega_{K/k} & \longrightarrow 0 \\ \Omega_{K/k} & \longrightarrow 0\end{aligned}\end{gathered}$$ with exact rows. We have used that $H_1(L_{K/A}) = \mathfrak m/\mathfrak m^2$ and that $H_1(L_{K/\mathbf{F}_p}) = 0$ as $K/\mathbf{F}_p$ is separable, see Algebra, Proposition Characterizations of separable field extensions (uncovered prerequisite). Thus it is clear that the kernels of $H_1(L_{K/k}) \to \mathfrak m/\mathfrak m^2$ and $\Omega_{k/\mathbf{F}_p} \otimes_k K \to \Omega_{A/\mathbf{F}_p} \otimes_A K$ have the same dimension.
Proof of (2) $\Rightarrow$ (4) following Faltings, see the original source citation Faltings-einfacher. Let $a_1, \ldots, a_n \in k$ be elements such that $\text{d}a_1, \ldots, \text{d}a_n$ are linearly independent in $\Omega_{k/\mathbf{F}_p}$. Consider the field extension $k' = k(a_1^{1/p}, \ldots, a_n^{1/p})$. By Algebra, Lemma Degrees of extensions obtained by adjoining p-th roots (uncovered prerequisite) we see that $k' = k[x_1, \ldots, x_n]/(x_1^p - a_1, \ldots, x_n^p - a_n)$. In particular we see that the naive cotangent complex of $k'/k$ is homotopic to the complex $\bigoplus_{j = 1, \ldots, n} k' \rightarrow \bigoplus_{i = 1, \ldots, n} k'$ with the zero differential as $\text{d}(x_j^p - a_j) = 0$ in $\Omega_{k[x_1, \ldots, x_n]/k}$. Set $A' = A \otimes_k k'$ and $K' = A'/\mathfrak m'$ as above. By Algebra, Lemma Base change of the naive cotangent complex (uncovered prerequisite) we see that $\mathrm{NL}_{A'/A}$ is homotopy equivalent to the complex $\bigoplus_{j = 1, \ldots, n} A' \rightarrow \bigoplus_{i = 1, \ldots, n} A'$ with the zero differential, i.e., $H_1(L_{A'/A})$ and $\Omega_{A'/A}$ are free of rank $n$. The Jacobi-Zariski sequence for $\mathbf{F}_p \to A \to A'$ is $$H_1(L_{A'/A}) \to \Omega_{A/\mathbf{F}_p} \otimes_A A' \to \Omega_{A'/\mathbf{F}_p} \to \Omega_{A'/A} \to 0$$ Using the presentation $A[x_1, \ldots, x_n] \to A'$ with kernel $(x_j^p - a_j)$ we see, unwinding the maps in Algebra, Lemma The transitivity sequence for the naive cotangent complex (uncovered prerequisite), that the $j$th basis vector of $H_1(L_{A'/A})$ maps to $\text{d}a_j \otimes 1$ in $\Omega_{A/\mathbf{F}_p} \otimes A'$. As $\Omega_{A'/A}$ is free (hence flat) we get on tensoring with $K'$ an exact sequence $$K'^{\oplus n} \to \Omega_{A/\mathbf{F}_p} \otimes_A K' \xrightarrow{\beta} \Omega_{A'/\mathbf{F}_p} \otimes_{A'} K' \to K'^{\oplus n} \to 0$$ We conclude that the elements $\text{d}a_j \otimes 1$ generate $\operatorname{Ker}(\beta)$ and we have to show that are linearly independent, i.e., we have to show $\dim(\operatorname{Ker}(\beta)) = n$. Consider the following big diagram $$\begin{gathered}\begin{matrix}0 & \mathfrak m'/(\mathfrak m')^2 & \Omega_{A'/\mathbf{F}_p} \otimes K' & \Omega_{K'/\mathbf{F}_p} & 0 \\ 0 & \mathfrak m/\mathfrak m^2 \otimes K' & \Omega_{A/\mathbf{F}_p} \otimes K' & \Omega_{K/\mathbf{F}_p} \otimes K' & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \mathfrak m'/(\mathfrak m')^2 \\ \mathfrak m'/(\mathfrak m')^2 & \longrightarrow \Omega_{A'/\mathbf{F}_p} \otimes K' \\ \Omega_{A'/\mathbf{F}_p} \otimes K' & \longrightarrow \Omega_{K'/\mathbf{F}_p} \\ \Omega_{K'/\mathbf{F}_p} & \longrightarrow 0 \\ 0 & \longrightarrow \mathfrak m/\mathfrak m^2 \otimes K' \\ \mathfrak m/\mathfrak m^2 \otimes K' & \longrightarrow \Omega_{A/\mathbf{F}_p} \otimes K' \\ \mathfrak m/\mathfrak m^2 \otimes K' & \xrightarrow{\alpha} \mathfrak m'/(\mathfrak m')^2 \\ \Omega_{A/\mathbf{F}_p} \otimes K' & \longrightarrow \Omega_{K/\mathbf{F}_p} \otimes K' \\ \Omega_{A/\mathbf{F}_p} \otimes K' & \xrightarrow{\beta} \Omega_{A'/\mathbf{F}_p} \otimes K' \\ \Omega_{K/\mathbf{F}_p} \otimes K' & \longrightarrow 0 \\ \Omega_{K/\mathbf{F}_p} \otimes K' & \xrightarrow{\gamma} \Omega_{K'/\mathbf{F}_p}\end{aligned}\end{gathered}$$ By Lemma Cartier's equality for differentials and the Jacobi-Zariski sequence for $\mathbf{F}_p \to K \to K'$ we see that the kernel and cokernel of $\gamma$ have the same finite dimension. By assumption $A'$ is regular (and of the same dimension as $A$, see above) hence the kernel and cokernel of $\alpha$ have the same dimension. It follows that the kernel and cokernel of $\beta$ have the same dimension which is what we wanted to show.
The implication (1) $\Rightarrow$ (2) is trivial. This finishes the proof of the proposition. $\square$
Lemma. Lifting derived commutative algebra
Let $R \to S$ be a ring map. Let $\mathfrak n$ be an ideal of $S$. Assume that $R \to S$ is formally smooth in the $\mathfrak n$-adic topology. Consider a solid commutative diagram $$\begin{gathered}\begin{matrix}S & A/J \\ R & A\end{matrix} \\[6pt] \begin{aligned}S & \xrightarrow{\psi} A/J \\ S & \dashrightarrow A \\ R & \longrightarrow A \\ R & \longrightarrow S \\ A & \longrightarrow A/J\end{aligned}\end{gathered}$$ of homomorphisms of topological rings where $A$ is adic and $A/J$ is the quotient (as topological ring) of $A$ by a closed ideal $J \subset A$ such that $J^t$ is contained in an ideal of definition of $A$ for some $t \geq 1$. Then there exists a dotted arrow in the category of topological rings which makes the diagram commute.
Proof. Let $I \subset A$ be an ideal of definition so that $I \supset J^t$ for some $t$. Then $A = \varprojlim A/I^n$ and $A/J = \varprojlim A/J + I^n$ because $J$ is assumed closed. Consider the following diagram of discrete $R$ algebras $A_{n, m} = A/J^n + I^m$: $$\begin{gathered}\begin{matrix}A/J^3 + I^3 & A/J^2 + I^3 & A/J + I^3 \\ A/J^3 + I^2 & A/J^2 + I^2 & A/J + I^2 \\ A/J^3 + I & A/J^2 + I & A/J + I\end{matrix} \\[6pt] \begin{aligned}A/J^3 + I^3 & \longrightarrow A/J^2 + I^3 \\ A/J^3 + I^3 & \longrightarrow A/J^3 + I^2 \\ A/J^2 + I^3 & \longrightarrow A/J + I^3 \\ A/J^2 + I^3 & \longrightarrow A/J^2 + I^2 \\ A/J + I^3 & \longrightarrow A/J + I^2 \\ A/J^3 + I^2 & \longrightarrow A/J^2 + I^2 \\ A/J^3 + I^2 & \longrightarrow A/J^3 + I \\ A/J^2 + I^2 & \longrightarrow A/J + I^2 \\ A/J^2 + I^2 & \longrightarrow A/J^2 + I \\ A/J + I^2 & \longrightarrow A/J + I \\ A/J^3 + I & \longrightarrow A/J^2 + I \\ A/J^2 + I & \longrightarrow A/J + I\end{aligned}\end{gathered}$$ Note that each of the commutative squares defines a surjection $$A_{n + 1, m + 1} \longrightarrow A_{n + 1, m} \times_{A_{n, m}} A_{n, m + 1}$$ of $R$-algebras whose kernel has square zero. We will inductively construct $R$-algebra maps $\varphi_{n, m} : S \to A_{n, m}$. Namely, we have the maps $\varphi_{1, m} = \psi \bmod J + I^m$. Note that each of these maps is continuous as $\psi$ is. We can inductively choose the maps $\varphi_{n, 1}$ by starting with our choice of $\varphi_{1, 1}$ and lifting up, using the formal smoothness of $S$ over $R$, along the bottom row of the diagram above. We construct the remaining maps $\varphi_{n, m}$ by induction on $n + m$. Namely, we choose $\varphi_{n + 1, m + 1}$ by lifting the pair $(\varphi_{n + 1, m}, \varphi_{n, m + 1})$ along the displayed surjection above (again using the formal smoothness of $S$ over $R$). In this way all of the maps $\varphi_{n, m}$ are compatible with the transition maps of the system. As $J^t \subset I$ we see that for example $\varphi_n = \varphi_{nt, n} \bmod I^n$ induces a map $S \to A/I^n$. Taking the limit $\varphi = \varprojlim \varphi_n$ we obtain a map $S \to A = \varprojlim A/I^n$. The composition into $A/J$ agrees with $\psi$ as we have seen that $A/J = \varprojlim A/J + I^n$. Finally we show that $\varphi$ is continuous. Namely, we know that $\psi(\mathfrak n^r) \subset J + I/J$ for some $r \geq 1$ by our assumption that $\psi$ is a morphism of topological rings, see Lemma Derived commutative algebra. Hence $\varphi(\mathfrak n^r) \subset J + I$ hence $\varphi(\mathfrak n^{rt}) \subset I$ as desired. $\square$
Lemma. Universal injectivity from a completed direct sum into a product
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $A$ be a set. Assume $R$ is Noetherian and complete with respect to $I$. There is a canonical map $$\left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge \longrightarrow \prod\nolimits_{\alpha \in A} R$$ from the $I$-adic completion of the direct sum into the product which is universally injective.
Proof. By definition an element $x$ of the left hand side is $x = (x_n)$ where $x_n = (x_{n, \alpha}) \in \bigoplus\nolimits_{\alpha \in A} R/I^n$ such that $x_{n, \alpha} = x_{n + 1, \alpha} \bmod I^n$. As $R = R^\wedge$ we see that for any $\alpha$ there exists a $y_\alpha \in R$ such that $x_{n, \alpha} = y_\alpha \bmod I^n$. Note that for each $n$ there are only finitely many $\alpha$ such that the elements $x_{n, \alpha}$ are nonzero. Conversely, given $(y_\alpha) \in \prod_\alpha R$ such that for each $n$ there are only finitely many $\alpha$ such that $y_{\alpha} \bmod I^n$ is nonzero, then this defines an element of the left hand side. Hence we can think of an element of the left hand side as infinite "convergent sums" $\sum_\alpha y_\alpha$ with $y_\alpha \in R$ such that for each $n$ there are only finitely many $y_\alpha$ which are nonzero modulo $I^n$. The displayed map maps this element to the element to $(y_\alpha)$ in the product. In particular the map is injective.
Let $Q$ be a finite $R$-module. We have to show that the map $$Q \otimes_R \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge \longrightarrow Q \otimes_R \left(\prod\nolimits_{\alpha \in A} R\right)$$ is injective, see Algebra, Theorem Commutative algebra (uncovered prerequisite). Choose a presentation $R^{\oplus k} \to R^{\oplus m} \to Q \to 0$ and denote $q_1, \ldots, q_m \in Q$ the corresponding generators for $Q$. By Artin-Rees (Algebra, Lemma The Artin–Rees lemma (uncovered prerequisite)) there exists a constant $c$ such that $\operatorname{Im}(R^{\oplus k} \to R^{\oplus m}) \cap (I^N)^{\oplus m} \subset \operatorname{Im}((I^{N - c})^{\oplus k} \to R^{\oplus m})$. Let us contemplate the diagram $$\begin{gathered}\begin{matrix}\bigoplus_{l = 1}^k \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & \bigoplus_{j = 1}^m \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & Q \otimes_R \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & 0 \\ \bigoplus_{l = 1}^k \left(\prod\nolimits_{\alpha \in A} R\right) & \bigoplus_{j = 1}^m \left(\prod\nolimits_{\alpha \in A} R\right) & Q \otimes_R \left(\prod\nolimits_{\alpha \in A} R\right) & 0\end{matrix} \\[6pt] \begin{aligned}\bigoplus_{l = 1}^k \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & \longrightarrow \bigoplus_{j = 1}^m \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge \\ \bigoplus_{l = 1}^k \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & \longrightarrow \bigoplus_{l = 1}^k \left(\prod\nolimits_{\alpha \in A} R\right) \\ \bigoplus_{j = 1}^m \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & \longrightarrow Q \otimes_R \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge \\ \bigoplus_{j = 1}^m \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & \longrightarrow \bigoplus_{j = 1}^m \left(\prod\nolimits_{\alpha \in A} R\right) \\ Q \otimes_R \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & \longrightarrow 0 \\ Q \otimes_R \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge & \longrightarrow Q \otimes_R \left(\prod\nolimits_{\alpha \in A} R\right) \\ \bigoplus_{l = 1}^k \left(\prod\nolimits_{\alpha \in A} R\right) & \longrightarrow \bigoplus_{j = 1}^m \left(\prod\nolimits_{\alpha \in A} R\right) \\ \bigoplus_{j = 1}^m \left(\prod\nolimits_{\alpha \in A} R\right) & \longrightarrow Q \otimes_R \left(\prod\nolimits_{\alpha \in A} R\right) \\ Q \otimes_R \left(\prod\nolimits_{\alpha \in A} R\right) & \longrightarrow 0\end{aligned}\end{gathered}$$ with exact rows. Pick an element $\sum_j \sum_\alpha y_{j, \alpha}$ of $\bigoplus_{j = 1, \ldots, m} \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge$. If this element maps to zero in the module $Q \otimes_R \left(\prod\nolimits_{\alpha \in A} R\right)$, then we see in particular that $\sum_j q_j \otimes y_{j, \alpha} = 0$ in $Q$ for each $\alpha$. Thus we can find an element $(z_{1, \alpha}, \ldots, z_{k, \alpha}) \in \bigoplus_{l = 1, \ldots, k} R$ which maps to $(y_{1, \alpha}, \ldots, y_{m, \alpha}) \in \bigoplus_{j = 1, \ldots, m} R$. Moreover, if $y_{j, \alpha} \in I^{N_\alpha}$ for $j = 1, \ldots, m$, then we may assume that $z_{l, \alpha} \in I^{N_\alpha - c}$ for $l = 1, \ldots, k$. Hence the sum $\sum_l \sum_\alpha z_{l, \alpha}$ is "convergent" and defines an element of $\bigoplus_{l = 1, \ldots, k} \left(\bigoplus\nolimits_{\alpha \in A} R\right)^\wedge$ which maps to the element $\sum_j \sum_\alpha y_{j, \alpha}$ we started out with. Thus the right vertical arrow is injective and we win. $\square$
Lemma. Complete rings, formal power series and field extensions
Let $k$ be a field. Let $(A, \mathfrak m, \kappa)$ be a complete local $k$-algebra. If $\kappa/k$ is separable and $A$ regular, then there exists an isomorphism of $A \cong \kappa[[t_1, \ldots, t_d]]$ as $k$-algebras.
Proof. Choose $\kappa \to A$ as in Lemma Lifting field extensions and apply Algebra, Lemma Complete rings, formal power series and regular rings (uncovered prerequisite). $\square$
Lemma. Compatibility of cotangent homology with a quotient
Given a commutative diagram of fields $$\begin{gathered}\begin{matrix}K & K' \\ k & k'\end{matrix} \\[6pt] \begin{aligned}K & \longrightarrow K' \\ k & \longrightarrow K \\ k & \longrightarrow k' \\ k' & \longrightarrow K'\end{aligned}\end{gathered}$$ with $k'/k$ and $K'/K$ finitely generated field extensions the kernel and cokernel of the maps $$\alpha : \Omega_{K/k} \otimes_K K' \to \Omega_{K'/k'} \quad\text{and}\quad \beta : H_1(L_{K/k}) \otimes_K K' \to H_1(L_{K'/k'})$$ are finite dimensional and $$\dim \operatorname{Ker}(\alpha) - \dim \operatorname{Coker}(\alpha) -\dim \operatorname{Ker}(\beta) + \dim \operatorname{Coker}(\beta)
\text{trdeg}_k(k') - \text{trdeg}_K(K')$$
Proof. The Jacobi-Zariski sequences for $k \subset k' \subset K'$ and $k \subset K \subset K'$ are $$0 \to H_1(L_{k'/k}) \otimes K' \to H_1(L_{K'/k}) \to H_1(L_{K'/k'}) \to \Omega_{k'/k} \otimes K' \to \Omega_{K'/k} \to \Omega_{K'/k'} \to 0$$ and $$0 \to H_1(L_{K/k}) \otimes K' \to H_1(L_{K'/k}) \to H_1(L_{K'/K}) \to \Omega_{K/k} \otimes K' \to \Omega_{K'/k} \to \Omega_{K'/K} \to 0$$ By Lemma Cartier's equality for differentials the vector spaces $\Omega_{k'/k}$, $\Omega_{K'/K}$, $H_1(L_{K'/K})$, and $H_1(L_{k'/k})$ are finite dimensional and the alternating sum of their dimensions is $\text{trdeg}_k(k') - \text{trdeg}_K(K')$. The lemma follows. $\square$
Lemma. Cartier's equality for differentials (Cartier equality)
Let $K/k$ be a finitely generated field extension. Then $\Omega_{K/k}$ and $H_1(L_{K/k})$ are finite dimensional and $\text{trdeg}_k(K) = \dim_K \Omega_{K/k} - \dim_K H_1(L_{K/k})$.
Proof. We can find a global complete intersection $A = k[x_1, \ldots, x_n]/(f_1, \ldots, f_c)$ over $k$ such that $K$ is isomorphic to the fraction field of $A$, see Algebra, Lemma Syntomic algebras in a filtered colimit (uncovered prerequisite) and its proof. In this case we see that $\mathrm{NL}_{K/k}$ is homotopy equivalent to the complex $$\bigoplus\nolimits_{j = 1, \ldots, c} K \longrightarrow \bigoplus\nolimits_{i = 1, \ldots, n} K\text{d}x_i$$ by Algebra, Lemmas Kähler differentials, Theorems 3.1–3.3, Proposition 3.4 and Theorem 7.1 and Localization of the naive cotangent complex (uncovered prerequisite). The transcendence degree of $K$ over $k$ is the dimension of $A$ (by Algebra, Lemma Prime ideals and dimension in a polynomial ring (uncovered prerequisite)) which is $n - c$ and we win. $\square$
Lemma. Lifting field extensions
Let $k$ be a field. Let $(A, \mathfrak m, \kappa)$ be a complete local $k$-algebra. If $\kappa/k$ is separable, then there exists a $k$-algebra map $\kappa \to A$ such that $\kappa \to A \to \kappa$ is $\text{id}_\kappa$.
Proof. By Algebra, Proposition Characterizations of separable field extensions (uncovered prerequisite) the extension $\kappa/k$ is formally smooth. By Lemma Formal smoothness and smooth morphisms $k \to \kappa$ is formally smooth in the sense of Definition Formally smooth ring maps. Then we get $\kappa \to A$ from Lemma Lifting derived commutative algebra. $\square$
[^1]: This clashes with what is meant by a pseudo-coherent module in the original source citation Bourbaki-CA.
[^2]: But $D' \to D \times_C C'$ is surjective by Lemma Modules and tensor products and direct sums.
[^3]: To use these spectral sequences we have to show that $\textit{Ab}(\mathbf{N})$ has enough injectives. An inverse system $(I_n)$ of abelian groups is injective if and only if each $I_n$ is an injective abelian group and the transition maps are split surjections. Every system embeds in one of these. Details omitted.
Derived sheaves on ringed spaces
Lemma. Sheaf cohomology and derived categories
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{U} : X = \bigcup_{i \in I} U_i$ be a finite open covering. Let $\mathcal{F}^\bullet$ be a complex of $\mathcal{O}_X$-modules. Let $\mathcal{B}$ be a set of open subsets of $X$. Assume
-
every open in $X$ has a covering whose members are elements of $\mathcal{B}$,
-
we have $U_{i_0\ldots i_p} \in \mathcal{B}$ for all $i_0, \ldots, i_p \in I$,
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for every $U \in \mathcal{B}$ and $p > 0$ we have
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$H^p(U, \mathcal{F}^q) = 0$,
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$H^p(U, \operatorname{Coker}(\mathcal{F}^{q - 1} \to \mathcal{F}^q)) = 0$, and
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$H^p(U, H^q(\mathcal{F})) = 0$.
-
Then the map $$\text{Tot}(\check{\mathcal{C}}^\bullet_{alt}(\mathcal{U}, \mathcal{F}^\bullet)) \longrightarrow R\Gamma(X, \mathcal{F}^\bullet)$$ of Lemma The Čech double complex is an isomorphism in $D(\textit{Ab})$.
Proof. First assume $\mathcal{F}^\bullet$ is bounded below. In this case the map $$\text{Tot}(\check{\mathcal{C}}^\bullet_{alt}(\mathcal{U}, \mathcal{F}^\bullet)) \longrightarrow \text{Tot}(\check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{F}^\bullet))$$ is a quasi-isomorphism by Lemma Derived sheaf cohomology. Namely, the map of double complexes $\check{\mathcal{C}}^\bullet_{alt}(\mathcal{U}, \mathcal{F}^\bullet) \to \check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{F}^\bullet)$ induces an isomorphism between the first pages of the second spectral sequences associated to these complexes (by Homology, Lemma Derived categories (uncovered prerequisite)) and these spectral sequences converge (Homology, Lemma The geometric construction (uncovered prerequisite)). Thus the conclusion in this case by Lemma Sheaf cohomology and derived categories and assumption (3)(a).
In general, by assumption (3)(c) we may choose a resolution $\mathcal{F}^\bullet \to \mathcal{I}^\bullet = \varprojlim \mathcal{I}_n^\bullet$ as in Lemma Injective resolutions. Then the map of the lemma becomes $$\varprojlim_n \text{Tot}(\check{\mathcal{C}}^\bullet_{alt}(\mathcal{U}, \tau_{\geq -n}\mathcal{F}^\bullet)) \longrightarrow \Gamma(X, \mathcal{I}^\bullet) = \varprojlim_n \Gamma(X, \mathcal{I}_n^\bullet)$$ Here the arrow is in the derived category, but the equality on the right holds on the level of complexes. Note that (3)(b) shows that $\tau_{\geq -n}\mathcal{F}^\bullet$ is a bounded below complex satisfying the hypothesis of the lemma. Thus the case of bounded below complexes shows each of the maps $$\text{Tot}(\check{\mathcal{C}}^\bullet_{alt}(\mathcal{U}, \tau_{\geq -n}\mathcal{F}^\bullet)) \longrightarrow \Gamma(X, \mathcal{I}_n^\bullet)$$ is a quasi-isomorphism. The cohomologies of the complexes on the left hand side in given degree are eventually constant (as the alternating Čech complex is finite). Hence the same is true on the right hand side. Thus the cohomology of the limit on the right hand side is this constant value by Homology, Lemma The geometric construction (uncovered prerequisite) (or the stronger More on Algebra, Lemma Derived commutative algebra) and we win. $\square$
Lemma. Perfect complexes
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $E$ be an object of $D(\mathcal{O}_X)$. The following are equivalent
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$E$ is perfect, and
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$E$ is pseudo-coherent and locally has finite tor dimension.
Proof. Assume (1). By definition this means there exists an open covering $X = \bigcup U_i$ such that $E|_{U_i}$ is represented by a strictly perfect complex. Thus $E$ is pseudo-coherent (i.e., $m$-pseudo-coherent for all $m$) by Lemma Pseudo-coherent complexes and coherent sheaves. Moreover, a direct summand of a finite free module is flat, hence $E|_{U_i}$ has finite Tor dimension by Lemma Derived tensor products and Tor amplitude. Thus (2) holds.
Assume (2). After replacing $X$ by the members of an open covering we may assume there exist integers $a \leq b$ such that $E$ has tor amplitude in $[a, b]$. Since $E$ is $m$-pseudo-coherent for all $m$ we conclude using Lemma Perfect complexes. $\square$
Lemma. Flatness
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{E}^\bullet$ be a bounded above complex of flat $\mathcal{O}_X$-modules with tor-amplitude in $[a, b]$. Then $\operatorname{Coker}(d_{\mathcal{E}^\bullet}^{a - 1})$ is a flat $\mathcal{O}_X$-module.
Proof. As $\mathcal{E}^\bullet$ is a bounded above complex of flat modules we see that $\mathcal{E}^\bullet \otimes_{\mathcal{O}_X} \mathcal{F} = \mathcal{E}^\bullet \otimes_{\mathcal{O}_X}^{\mathbf{L}} \mathcal{F}$ for any $\mathcal{O}_X$-module $\mathcal{F}$. Hence for every $\mathcal{O}_X$-module $\mathcal{F}$ the sequence $$\mathcal{E}^{a - 2} \otimes_{\mathcal{O}_X} \mathcal{F} \to \mathcal{E}^{a - 1} \otimes_{\mathcal{O}_X} \mathcal{F} \to \mathcal{E}^a \otimes_{\mathcal{O}_X} \mathcal{F}$$ is exact in the middle. Since $\mathcal{E}^{a - 2} \to \mathcal{E}^{a - 1} \to \mathcal{E}^a \to \operatorname{Coker}(d^{a - 1}) \to 0$ is a flat resolution this implies that $\text{Tor}_1^{\mathcal{O}_X}(\operatorname{Coker}(d^{a - 1}), \mathcal{F}) = 0$ for all $\mathcal{O}_X$-modules $\mathcal{F}$. This means that $\operatorname{Coker}(d^{a - 1})$ is flat, see Lemma Tor vanishing for a flat module. $\square$
Lemma. Perfect complexes and derived Hom and Ext
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{E}^\bullet$, $\mathcal{F}^\bullet$ be complexes of $\mathcal{O}_X$-modules with $\mathcal{E}^\bullet$ strictly perfect. Then the internal hom $R\mathcal{H}om(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ is represented by the complex $\mathcal{H}^\bullet$ with terms $$\mathcal{H}^n = \bigoplus\nolimits_{n = p + q} \mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}^{-q}, \mathcal{F}^p)$$ and differential as described in Section Derived Hom, Ext and derived categories.
Proof. Choose a quasi-isomorphism $\mathcal{F}^\bullet \to \mathcal{I}^\bullet$ into a K-injective complex. Let $(\mathcal{H}')^\bullet$ be the complex with terms $$(\mathcal{H}')^n = \prod\nolimits_{n = p + q} \mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}^{-q}, \mathcal{I}^p)$$ which represents $R\mathcal{H}om(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ by the construction in Section Derived Hom and Ext. It suffices to show that the map $$\mathcal{H}^\bullet \longrightarrow (\mathcal{H}')^\bullet$$ is a quasi-isomorphism. Given an open $U \subset X$ we have by inspection $$H^0(\mathcal{H}^\bullet(U)) = \operatorname{Hom}_{K(\mathcal{O}_U)}(\mathcal{E}^\bullet|_U, \mathcal{I}^\bullet|_U) \to H^0((\mathcal{H}')^\bullet(U)) = \operatorname{Hom}_{D(\mathcal{O}_U)}(\mathcal{E}^\bullet|_U, \mathcal{I}^\bullet|_U)$$ By Lemma A local representative for a derived object the sheafification of $U \mapsto H^0(\mathcal{H}^\bullet(U))$ is equal to the sheafification of $U \mapsto H^0((\mathcal{H}')^\bullet(U))$. A similar argument can be given for the other cohomology sheaves. Thus $\mathcal{H}^\bullet$ is quasi-isomorphic to $(\mathcal{H}')^\bullet$ which proves the lemma. $\square$
Lemma. Derived Hom and Ext
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $L, M$ be objects of $D(\mathcal{O}_X)$. For every open $U$ we have $$H^0(U, R\mathcal{H}om(L, M)) = \operatorname{Hom}_{D(\mathcal{O}_U)}(L|_U, M|_U)$$ and in particular $H^0(X, R\mathcal{H}om(L, M)) = \operatorname{Hom}_{D(\mathcal{O}_X)}(L, M)$.
Proof. Choose a K-injective complex $\mathcal{I}^\bullet$ of $\mathcal{O}_X$-modules representing $M$ and a K-flat complex $\mathcal{L}^\bullet$ representing $L$. Then $\mathcal{H}om^\bullet(\mathcal{L}^\bullet, \mathcal{I}^\bullet)$ is K-injective by Lemma Derived Hom, Ext and derived tensor products and Tor amplitude. Hence we can compute cohomology over $U$ by simply taking sections over $U$ and the result follows from Lemma Derived Hom, Ext and injective resolutions. $\square$
Lemma. Derived Hom and Ext
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $X = U \cup V$ be the union of two open subspaces of $X$. For objects $E$, $F$ of $D(\mathcal{O}_X)$ we have a Mayer-Vietoris sequence $$\begin{gathered}\begin{matrix}\phantom{X} & \ldots & \operatorname{Ext}^{-1}(E_{U \cap V}, F_{U \cap V}) \\ \operatorname{Hom}(E, F) & \operatorname{Hom}(E_U, F_U) \oplus \operatorname{Hom}(E_V, F_V) & \operatorname{Hom}(E_{U \cap V}, F_{U \cap V})\end{matrix} \\[6pt] \begin{aligned}\ldots & \longrightarrow \operatorname{Ext}^{-1}(E_{U \cap V}, F_{U \cap V}) \\ \operatorname{Ext}^{-1}(E_{U \cap V}, F_{U \cap V}) & \longrightarrow \operatorname{Hom}(E, F) \\ \operatorname{Hom}(E, F) & \longrightarrow \operatorname{Hom}(E_U, F_U) \oplus \operatorname{Hom}(E_V, F_V) \\ \operatorname{Hom}(E_U, F_U) \oplus \operatorname{Hom}(E_V, F_V) & \longrightarrow \operatorname{Hom}(E_{U \cap V}, F_{U \cap V})\end{aligned}\end{gathered}$$ where the subscripts denote restrictions to the relevant opens and the $\operatorname{Hom}$'s and $\operatorname{Ext}$'s are taken in the relevant derived categories.
Proof. Use the distinguished triangle of Lemma Derived sheaf cohomology to obtain a long exact sequence of $\operatorname{Hom}$'s (from Derived Categories, Lemma Representability of a homological functor) and use that $$\operatorname{Hom}_{D(\mathcal{O}_X)}(j_{U!}E|_U, F) = \operatorname{Hom}_{D(\mathcal{O}_U)}(E|_U, F|_U)$$ by Lemma Derived sheaf cohomology. $\square$
Lemma. Derived gluing across an elementary distinguished square
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $X = U \cup V$ be the union of two open subspaces of $X$. Suppose given
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an object $A$ of $D(\mathcal{O}_U)$,
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an object $B$ of $D(\mathcal{O}_V)$, and
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an isomorphism $c : A|_{U \cap V} \to B|_{U \cap V}$.
Then there exists an object $F$ of $D(\mathcal{O}_X)$ and isomorphisms $f : F|_U \to A$, $g : F|_V \to B$ such that $c = g|_{U \cap V} \circ f^{-1}|_{U \cap V}$. Moreover, given
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an object $E$ of $D(\mathcal{O}_X)$,
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a morphism $a : A \to E|_U$ of $D(\mathcal{O}_U)$,
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a morphism $b : B \to E|_V$ of $D(\mathcal{O}_V)$,
such that $$a|_{U \cap V} = b|_{U \cap V} \circ c.$$ Then there exists a morphism $F \to E$ in $D(\mathcal{O}_X)$ whose restriction to $U$ is $a \circ f$ and whose restriction to $V$ is $b \circ g$.
Proof. Denote $j_U$, $j_V$, $j_{U \cap V}$ the corresponding open immersions. Choose a distinguished triangle $$F \to Rj_{U, *}A \oplus Rj_{V, *}B \to Rj_{U \cap V, *}(B|_{U \cap V}) \to F[1]$$ where the map $Rj_{V, *}B \to Rj_{U \cap V, *}(B|_{U \cap V})$ is the obvious one and where $Rj_{U, *}A \to Rj_{U \cap V, *}(B|_{U \cap V})$ is the composition of $Rj_{U, *}A \to Rj_{U \cap V, *}(A|_{U \cap V})$ with $Rj_{U \cap V, *}c$. Restricting to $U$ we obtain $$F|_U \to A \oplus (Rj_{V, *}B)|_U \to (Rj_{U \cap V, *}(B|_{U \cap V}))|_U \to F|_U[1]$$ Denote $j : U \cap V \to U$. Compatibility of restriction to opens and cohomology shows that both $(Rj_{V, *}B)|_U$ and $(Rj_{U \cap V, *}(B|_{U \cap V}))|_U$ are canonically isomorphic to $Rj_*(B|_{U \cap V})$. Hence the second arrow of the last displayed diagram has a section, and we conclude that the morphism $F|_U \to A$ is an isomorphism. Similarly, the morphism $F|_V \to B$ is an isomorphism. The existence of the morphism $F \to E$ follows from the Mayer-Vietoris sequence for $\operatorname{Hom}$, see Lemma Derived Hom and Ext. $\square$
Lemma. Finiteness of cohomology groups
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $K$ be an object of $D(\mathcal{O}_X)$. Let $m \in \mathbf{Z}$.
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If $K$ is $m$-pseudo-coherent and $H^i(K) = 0$ for $i > m$, then $H^m(K)$ is a finite type $\mathcal{O}_X$-module.
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If $K$ is $m$-pseudo-coherent and $H^i(K) = 0$ for $i > m + 1$, then $H^{m + 1}(K)$ is a finitely presented $\mathcal{O}_X$-module.
Proof. Proof of (1). We may work locally on $X$. Hence we may assume there exists a strictly perfect complex $\mathcal{E}^\bullet$ and a map $\alpha : \mathcal{E}^\bullet \to K$ which induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. It suffices to prove the result for $\mathcal{E}^\bullet$. Let $n$ be the largest integer such that $\mathcal{E}^n \not = 0$. If $n = m$, then $H^m(\mathcal{E}^\bullet)$ is a quotient of $\mathcal{E}^n$ and the result is clear. If $n > m$, then $\mathcal{E}^{n - 1} \to \mathcal{E}^n$ is surjective as $H^n(E^\bullet) = 0$. By Lemma Local algebra we can locally find a section of this surjection and write $\mathcal{E}^{n - 1} = \mathcal{E}' \oplus \mathcal{E}^n$. Hence it suffices to prove the result for the complex $(\mathcal{E}')^\bullet$ which is the same as $\mathcal{E}^\bullet$ except has $\mathcal{E}'$ in degree $n - 1$ and $0$ in degree $n$. We win by induction on $n$.
Proof of (2). We may work locally on $X$. Hence we may assume there exists a strictly perfect complex $\mathcal{E}^\bullet$ and a map $\alpha : \mathcal{E}^\bullet \to K$ which induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. As in the proof of (1) we can reduce to the case that $\mathcal{E}^i = 0$ for $i > m + 1$. Then we see that $H^{m + 1}(K) \cong H^{m + 1}(\mathcal{E}^\bullet) = \operatorname{Coker}(\mathcal{E}^m \to \mathcal{E}^{m + 1})$ which is of finite presentation. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $(X, \mathcal{O}_X)$ be a ringed space and $m \in \mathbf{Z}$. Let $(K, L, M, f, g, h)$ be a distinguished triangle in $D(\mathcal{O}_X)$.
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If $K$ is $(m + 1)$-pseudo-coherent and $L$ is $m$-pseudo-coherent then $M$ is $m$-pseudo-coherent.
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If $K$ and $M$ are $m$-pseudo-coherent, then $L$ is $m$-pseudo-coherent.
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If $L$ is $(m + 1)$-pseudo-coherent and $M$ is $m$-pseudo-coherent, then $K$ is $(m + 1)$-pseudo-coherent.
Proof. Proof of (1). Choose an open covering $X = \bigcup U_i$ and maps $\alpha_i : \mathcal{K}_i^\bullet \to K|_{U_i}$ in $D(\mathcal{O}_{U_i})$ with $\mathcal{K}_i^\bullet$ strictly perfect and $H^j(\alpha_i)$ isomorphisms for $j > m + 1$ and surjective for $j = m + 1$. We may replace $\mathcal{K}_i^\bullet$ by $\sigma_{\geq m + 1}\mathcal{K}_i^\bullet$ and hence we may assume that $\mathcal{K}_i^j = 0$ for $j < m + 1$. After refining the open covering we may choose maps $\beta_i : \mathcal{L}_i^\bullet \to L|_{U_i}$ in $D(\mathcal{O}_{U_i})$ with $\mathcal{L}_i^\bullet$ strictly perfect such that $H^j(\beta)$ is an isomorphism for $j > m$ and surjective for $j = m$. By Lemma Lifting derived sheaf cohomology we can, after refining the covering, find maps of complexes $\gamma_i : \mathcal{K}^\bullet \to \mathcal{L}^\bullet$ such that the diagrams $$\begin{gathered}\begin{matrix}K|_{U_i} & L|_{U_i} \\ \mathcal{K}_i^\bullet & \mathcal{L}_i^\bullet\end{matrix} \\[6pt] \begin{aligned}K|_{U_i} & \longrightarrow L|_{U_i} \\ \mathcal{K}_i^\bullet & \xrightarrow{\alpha_i} K|_{U_i} \\ \mathcal{K}_i^\bullet & \xrightarrow{\gamma_i} \mathcal{L}_i^\bullet \\ \mathcal{L}_i^\bullet & \xrightarrow{\beta_i} L|_{U_i}\end{aligned}\end{gathered}$$ are commutative in $D(\mathcal{O}_{U_i})$ (this requires representing the maps $\alpha_i$, $\beta_i$ and $K|_{U_i} \to L|_{U_i}$ by actual maps of complexes; some details omitted). The cone $C(\gamma_i)^\bullet$ is strictly perfect (Lemma Derived categories). The commutativity of the diagram implies that there exists a morphism of distinguished triangles $$(\mathcal{K}_i^\bullet, \mathcal{L}_i^\bullet, C(\gamma_i)^\bullet) \longrightarrow (K|_{U_i}, L|_{U_i}, M|_{U_i}).$$ It follows from the induced map on long exact cohomology sequences and Homology, Lemmas The geometric construction (uncovered prerequisite) and The geometric construction (uncovered prerequisite) that $C(\gamma_i)^\bullet \to M|_{U_i}$ induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. Hence $M$ is $m$-pseudo-coherent by Lemma Pseudo-coherent complexes and coherent sheaves.
Assertions (2) and (3) follow from (1) by rotating the distinguished triangle. $\square$
Lemma. Perfect complexes
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $(K, L, M, f, g, h)$ be a distinguished triangle in $D(\mathcal{O}_X)$. If two out of three of $K, L, M$ are perfect then the third is also perfect.
Proof. First proof: Combine Lemmas Perfect complexes, Pseudo-coherent complexes and coherent sheaves, and Derived tensor products, Tor amplitude and derived categories. Second proof (sketch): Say $K$ and $L$ are perfect. After replacing $X$ by the members of an open covering we may assume that $K$ and $L$ are represented by strictly perfect complexes $\mathcal{K}^\bullet$ and $\mathcal{L}^\bullet$. After replacing $X$ by the members of an open covering we may assume the map $K \to L$ is given by a map of complexes $\alpha : \mathcal{K}^\bullet \to \mathcal{L}^\bullet$, see Lemma A local representative for a derived object. Then $M$ is isomorphic to the cone of $\alpha$ which is strictly perfect by Lemma Derived categories. $\square$
Proposition. Vanishing and Noetherian rings (Grothendieck)
Source credit: the original source citation Tohoku (Theorem 3.6.5). The projective-variety special case is the original source citation FAC (Chapter III, §1, no. 52, Proposition 3 and Corollary, pp. 244--245). Its closed-projective-variety application is the original source citation FAC (Chapter III, §3, no. 66, Theorem 1, p. 259). The curve case and its historical question are the original source citation FAC (Chapter III, §1, no. 53, Proposition 4 and Remark, p. 246).
The FAC proposition proves vanishing above the dimension of the support for a coherent algebraic sheaf on a classical variety locally closed in projective space. Its proof constructs a bounded affine covering by homogeneous principal opens and uses the alternating Cech complex. The proposition below is the stronger topological theorem: it applies to every abelian sheaf on an arbitrary Noetherian space. Applying it on the closed support and using closed pushforward recovers the FAC bound without the quasi-projective hypothesis. In the following number FAC gives a separate curve proof by a cofinal family of covers whose higher alternating complexes are those of finite simplices, then asks whether an analogous assertion holds in arbitrary dimension. Since the source notation there denotes direct-limit Cech cohomology, the theorem below supplies the affirmative derived-functor analogue rather than silently identifying the two cohomology theories.
In no. 66 the source extends a coherent sheaf on a closed projective subvariety by zero to projective space and combines the no. 52 bound with cohomology invariance under closed pushforward. The proposition below makes the resulting dimension bound independent of projectivity, coherence, and the chosen ambient space.
Let $X$ be a Noetherian topological space. If $\dim(X) \leq d$, then $H^p(X, \mathcal{F}) = 0$ for all $p > d$ and any abelian sheaf $\mathcal{F}$ on $X$.
Proof. We prove this lemma by induction on $d$. So fix $d$ and assume the lemma holds for all Noetherian topological spaces of dimension $< d$.
Let $\mathcal{F}$ be an abelian sheaf on $X$. Suppose $U \subset X$ is an open. Let $Z \subset X$ denote the closed complement. Denote $j : U \to X$ and $i : Z \to X$ the inclusion maps. Then there is a short exact sequence $$0 \to j_{!}j^*\mathcal{F} \to \mathcal{F} \to i_*i^*\mathcal{F} \to 0$$ see Modules, Lemma The geometric construction (uncovered prerequisite). Note that $j_!j^*\mathcal{F}$ is supported on the topological closure $Z'$ of $U$, i.e., it is of the form $i'_*\mathcal{F}'$ for some abelian sheaf $\mathcal{F}'$ on $Z'$, where $i' : Z' \to X$ is the inclusion.
We can use this to reduce to the case where $X$ is irreducible. Namely, according to Topology, Lemma Noetherian topological spaces (uncovered prerequisite) $X$ has finitely many irreducible components. If $X$ has more than one irreducible component, then let $Z \subset X$ be an irreducible component of $X$ and set $U = X \setminus Z$. By the above, and the long exact sequence of cohomology, it suffices to prove the vanishing of $H^p(X, i_*i^*\mathcal{F})$ and $H^p(X, i'_*\mathcal{F}')$ for $p > d$. By Lemma Sheaf cohomology and diagonals and separation it suffices to prove $H^p(Z, i^*\mathcal{F})$ and $H^p(Z', \mathcal{F}')$ vanish for $p > d$. Since $Z'$ and $Z$ have fewer irreducible components we indeed reduce to the case of an irreducible $X$.
If $d = 0$ and $X$ is irreducible, then $X$ is the only nonempty open subset of $X$. Hence every sheaf is constant and higher cohomology groups vanish (for example by Lemma Sheaf cohomology).
Suppose $X$ is irreducible of dimension $d > 0$. By Lemma Vanishing and derived sheaf cohomology we reduce to the case where $\mathcal{F} = j_!\underline{\mathbf{Z}}_U$ for some open $U \subset X$. In this case we look at the short exact sequence $$0 \to j_!(\underline{\mathbf{Z}}_U) \to \underline{\mathbf{Z}}_X \to i_*\underline{\mathbf{Z}}_Z \to 0$$ where $Z = X \setminus U$. By Lemma Sheaf cohomology we have the vanishing of $H^p(X, \underline{\mathbf{Z}}_X)$ for all $p \geq 1$. By induction we have $H^p(X, i_*\underline{\mathbf{Z}}_Z) = H^p(Z, \underline{\mathbf{Z}}_Z) = 0$ for $p \geq d$. Hence we win by the long exact cohomology sequence. $\square$
Lemma. Sheaf cohomology and diagonals and separation
Source credit: the original source citation FAC (Chapter I, §3, no. 26, Proposition 8, p. 219) the original source citation FAC (Chapter II, §2, no. 39, p. 232)
Let $i : Z \to X$ be a closed immersion of topological spaces. For any abelian sheaf $\mathcal{F}$ on $Z$ we have $H^p(Z, \mathcal{F}) = H^p(X, i_*\mathcal{F})$.
Proof. This is true because $i_*$ is exact (see Modules, Lemma The geometric construction (uncovered prerequisite)), and hence $R^pi_* = 0$ as a functor (Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories). Thus we may apply Lemma Acyclicity and the Leray spectral sequence. $\square$
Lemma. Line bundles and ampleness
Let $(X, \mathcal{O}_X)$ be a ringed space. If all stalks $\mathcal{O}_{X, x}$ are local rings, then there is a canonical isomorphism $$H^1(X, \mathcal{O}_X^*) = \operatorname{Pic}(X).$$ of abelian groups.
Proof. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Consider the presheaf $\mathcal{L}^*$ defined by the rule $$U \longmapsto \{s \in \mathcal{L}(U) \text{ such that } \mathcal{O}_U \xrightarrow{s \cdot -} \mathcal{L}_U \text{ is an isomorphism}\}$$ This presheaf satisfies the sheaf condition. Moreover, if $f \in \mathcal{O}_X^*(U)$ and $s \in \mathcal{L}^*(U)$, then clearly $fs \in \mathcal{L}^*(U)$. By the same token, if $s, s' \in \mathcal{L}^*(U)$ then there exists a unique $f \in \mathcal{O}_X^*(U)$ such that $fs = s'$. Moreover, the sheaf $\mathcal{L}^*$ has sections locally by Modules, Lemma Projective, locally free modules and line bundles and ampleness (uncovered prerequisite). In other words we see that $\mathcal{L}^*$ is a $\mathcal{O}_X^*$-torsor. Thus we get a map $$\begin{matrix} \text{invertible sheaves on }(X, \mathcal{O}_X) \\ \text{ up to isomorphism} \end{matrix} \longrightarrow \begin{matrix} \mathcal{O}_X^*\text{-torsors} \\ \text{ up to isomorphism} \end{matrix}$$ We omit the verification that this is a homomorphism of abelian groups. By Lemma Derived sheaf cohomology the right hand side is canonically bijective to $H^1(X, \mathcal{O}_X^*)$. Thus we have to show this map is injective and surjective.
Injective. If the torsor $\mathcal{L}^*$ is trivial, this means by Lemma Derived sheaf cohomology that $\mathcal{L}^*$ has a global section. Hence this means exactly that $\mathcal{L} \cong \mathcal{O}_X$ is the neutral element in $\operatorname{Pic}(X)$.
Surjective. Let $\mathcal{F}$ be an $\mathcal{O}_X^*$-torsor. Consider the presheaf of sets $$\mathcal{L}_1 : U \longmapsto (\mathcal{F}(U) \times \mathcal{O}_X(U))/\mathcal{O}_X^*(U)$$ where the action of $f \in \mathcal{O}_X^*(U)$ on $(s, g)$ is $(fs, f^{-1}g)$. Then $\mathcal{L}_1$ is a presheaf of $\mathcal{O}_X$-modules by setting $(s, g) + (s', g') = (s, g + (s'/s)g')$ where $s'/s$ is the local section $f$ of $\mathcal{O}_X^*$ such that $fs = s'$, and $h(s, g) = (s, hg)$ for $h$ a local section of $\mathcal{O}_X$. We omit the verification that the sheafification $\mathcal{L} = \mathcal{L}_1^\#$ is an invertible $\mathcal{O}_X$-module whose associated $\mathcal{O}_X^*$-torsor $\mathcal{L}^*$ is isomorphic to $\mathcal{F}$. $\square$
Lemma. The Čech double complex
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{U} : X = \bigcup_{i \in I} U_i$ be a finite open covering. For a complex $\mathcal{F}^\bullet$ of $\mathcal{O}_X$-modules there is a canonical map $$\text{Tot}(\check{\mathcal{C}}^\bullet_{alt}(\mathcal{U}, \mathcal{F}^\bullet)) \longrightarrow R\Gamma(X, \mathcal{F}^\bullet)$$ functorial in $\mathcal{F}^\bullet$ and compatible with (Sheaf cohomology).
Proof. Let ${\mathcal I}^\bullet$ be a K-injective complex whose terms are injective $\mathcal{O}_X$-modules. The map (Sheaf cohomology) for $\mathcal{I}^\bullet$ is a map $\Gamma(X, {\mathcal I}^\bullet) \to \text{Tot}(\check{\mathcal{C}}^\bullet_{alt}({\mathcal U}, {\mathcal I}^\bullet))$. This is a quasi-isomorphism of complexes of abelian groups as follows from Homology, Lemma Derived categories (uncovered prerequisite) applied to the double complex $\check{\mathcal{C}}^\bullet_{alt}({\mathcal U}, {\mathcal I}^\bullet)$ using Lemmas Sheaf cohomology and injective resolutions (uncovered prerequisite) and Derived sheaf cohomology. Suppose ${\mathcal F}^\bullet \to {\mathcal I}^\bullet$ is a quasi-isomorphism of ${\mathcal F}^\bullet$ into a K-injective complex whose terms are injectives (Injectives, Theorem Injective resolutions (uncovered prerequisite)). Since $R\Gamma(X, {\mathcal F}^\bullet)$ is represented by the complex $\Gamma(X, {\mathcal I}^\bullet)$ we obtain the map of the lemma using $$\text{Tot}(\check{\mathcal{C}}^\bullet_{alt}({\mathcal U}, {\mathcal F}^\bullet)) \longrightarrow \text{Tot}(\check{\mathcal{C}}^\bullet_{alt}({\mathcal U}, {\mathcal I}^\bullet)).$$ We omit the verification of functoriality and compatibilities. $\square$
Lemma. Derived sheaf cohomology
Source credit: the original source citation FAC (Chapter I, §3, no. 20, Proposition 2, pp. 213--214)
Let $X$ be a topological space. Let $\mathcal{U} : U = \bigcup_{i \in I} U_i$ be an open covering. Assume $I$ comes equipped with a total ordering. The map $c \circ \pi$ is homotopic to the identity on $\check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{F})$. In particular the inclusion map $\check{\mathcal{C}}_{alt}^\bullet(\mathcal{U}, \mathcal{F}) \to \check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{F})$ is a homotopy equivalence.
Proof. For any multi-index $(i_0, \ldots, i_p) \in I^{p + 1}$ there exists a unique permutation $\sigma : \{0, \ldots, p\} \to \{0, \ldots, p\}$ such that $$i_{\sigma(0)} \leq i_{\sigma(1)} \leq \ldots \leq i_{\sigma(p)} \quad \text{and} \quad \sigma(j) < \sigma(j + 1) \quad \text{if} \quad i_{\sigma(j)} = i_{\sigma(j + 1)}.$$ We denote this permutation $\sigma = \sigma^{i_0 \ldots i_p}$.
For any permutation $\sigma : \{0, \ldots, p\} \to \{0, \ldots, p\}$ and any $a$, $0 \leq a \leq p$ we denote $\sigma_a$ the unique permutation of $\{0, \ldots, p\}$ such that $\sigma_a(j) = \sigma(j)$ for $0 \leq j < a$ and such that $\sigma_a(a) < \sigma_a(a + 1) < \ldots < \sigma_a(p)$. So if $p = 3$ and $\sigma$, $\tau$ are given by $$\begin{matrix} \text{id} & 0 & 1 & 2 & 3 \\ \sigma & 3 & 2 & 1 & 0 \end{matrix} \quad \text{and} \quad \begin{matrix} \text{id} & 0 & 1 & 2 & 3 \\ \tau & 3 & 0 & 2 & 1 \end{matrix}$$ then we have $$\begin{matrix} \text{id} & 0 & 1 & 2 & 3 \\ \sigma_0 & 0 & 1 & 2 & 3 \\ \sigma_1 & 3 & 0 & 1 & 2 \\ \sigma_2 & 3 & 2 & 0 & 1 \\ \sigma_3 & 3 & 2 & 1 & 0 \\ \end{matrix} \quad \text{and} \quad \begin{matrix} \text{id} & 0 & 1 & 2 & 3 \\ \tau_0 & 0 & 1 & 2 & 3 \\ \tau_1 & 3 & 0 & 1 & 2 \\ \tau_2 & 3 & 0 & 1 & 2 \\ \tau_3 & 3 & 0 & 2 & 1 \\ \end{matrix}$$ It is clear that always $\sigma_0 = \text{id}$ and $\sigma_p = \sigma$.
Having introduced this notation we define for $s \in \check{\mathcal{C}}^{p + 1}(\mathcal{U}, \mathcal{F})$ the element $h(s) \in \check{\mathcal{C}}^p(\mathcal{U}, \mathcal{F})$ to be the element with components
$$h(s)_{i_0\ldots i_p} = \sum\nolimits_{0 \leq a \leq p} (-1)^a \text{sign}(\sigma_a) s_{i_{\sigma(0)} \ldots i_{\sigma(a)} i_{\sigma_a(a)} \ldots i_{\sigma_a(p)}}$$ where $\sigma = \sigma^{i_0 \ldots i_p}$. The index $i_{\sigma(a)}$ occurs twice in $i_{\sigma(0)} \ldots i_{\sigma(a)} i_{\sigma_a(a)} \ldots i_{\sigma_a(p)}$ once in the first group of $a + 1$ indices and once in the second group of $p - a + 1$ indices since $\sigma_a(j) = \sigma(a)$ for some $j \geq a$ by definition of $\sigma_a$. Hence the sum makes sense since each of the elements $s_{i_{\sigma(0)} \ldots i_{\sigma(a)} i_{\sigma_a(a)} \ldots i_{\sigma_a(p)}}$ is defined over the open $U_{i_0 \ldots i_p}$. Note also that for $a = 0$ we get $s_{i_0 \ldots i_p}$ and for $a = p$ we get $(-1)^p \text{sign}(\sigma) s_{i_{\sigma(0)} \ldots i_{\sigma(p)}}$.
We claim that
\[ (dh + hd)(s)_{i_0 \ldots i_p} = s_{i_0 \ldots i_p} - \text{sign}(\sigma) s_{i_{\sigma(0)} \ldots i_{\sigma(p)}} \]where \(\sigma = \sigma^{i_0 \ldots i_p}\). We omit the verification of this claim. (There is a PARI/gp script called first-homotopy.gp in the stacks-project subdirectory scripts which can be used to check finitely many instances of this claim. We wrote this script to make sure the signs are correct.) Write
\[ \kappa : \check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{F}) \longrightarrow \check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{F}) \]for the operator given by the rule
\[ \kappa(s)_{i_0 \ldots i_p} = \text{sign}(\sigma^{i_0 \ldots i_p}) s_{i_{\sigma(0)} \ldots i_{\sigma(p)}}. \]The claim above implies that \(\kappa\) is a morphism of complexes and that \(\kappa\) is homotopic to the identity map of the Čech complex. This does not immediately imply the lemma since the image of the operator \(\kappa\) is not the alternating subcomplex. Namely, the image of \(\kappa\) is the "semi-alternating" complex \(\check{\mathcal{C}}_{semi\text{-}alt}^p(\mathcal{U}, \mathcal{F})\) where \(s\) is a \(p\)-cochain of this complex if and only if
\[ s_{i_0 \ldots i_p} = \text{sign}(\sigma) s_{i_{\sigma(0)} \ldots i_{\sigma(p)}} \]for any \((i_0, \ldots, i_p) \in I^{p + 1}\) with \(\sigma = \sigma^{i_0 \ldots i_p}\). We introduce yet another variant Čech complex, namely the semi-ordered Čech complex defined by
\[ \check{\mathcal{C}}_{semi\text{-}ord}^p(\mathcal{U}, \mathcal{F}) = \prod\nolimits_{i_0 \leq i_1 \leq \ldots \leq i_p} \mathcal{F}(U_{i_0 \ldots i_p}) \]It is easy to see that Equation (Sheaf cohomology) also defines a differential and hence that we get a complex. It is also clear (analogous to Lemma Derived sheaf cohomology (uncovered prerequisite)) that the projection map
\[ \check{\mathcal{C}}_{semi\text{-}alt}^\bullet(\mathcal{U}, \mathcal{F}) \longrightarrow \check{\mathcal{C}}_{semi\text{-}ord}^\bullet(\mathcal{U}, \mathcal{F}) \]is an isomorphism of complexes.
Hence the Lemma follows if we can show that the obvious inclusion map $$\check{\mathcal{C}}_{ord}^p(\mathcal{U}, \mathcal{F}) \longrightarrow \check{\mathcal{C}}_{semi\text{-}ord}^p(\mathcal{U}, \mathcal{F})$$ is a homotopy equivalence. To see this we use the homotopy
$$h(s)_{i_0 \ldots i_p} = \left\{ \begin{matrix} 0 & \text{if} & i_0 < i_1 < \ldots < i_p \\ (-1)^a s_{i_0 \ldots i_{a - 1} i_a i_a i_{a + 1} \ldots i_p} & \text{if} & i_0 < i_1 < \ldots < i_{a - 1} < i_a = i_{a + 1} \end{matrix} \right.$$ We claim that $$(dh + hd)(s)_{i_0 \ldots i_p} = \left\{ \begin{matrix} 0 & \text{if} & i_0 < i_1 < \ldots < i_p \\ s_{i_0 \ldots i_p} & \text{else} & \end{matrix} \right.$$ We omit the verification. (There is a PARI/gp script called second-homotopy.gp in the stacks-project subdirectory scripts which can be used to check finitely many instances of this claim. We wrote this script to make sure the signs are correct.) The claim clearly shows that the composition $$\check{\mathcal{C}}_{semi\text{-}ord}^\bullet(\mathcal{U}, \mathcal{F}) \longrightarrow \check{\mathcal{C}}_{ord}^\bullet(\mathcal{U}, \mathcal{F}) \longrightarrow \check{\mathcal{C}}_{semi\text{-}ord}^\bullet(\mathcal{U}, \mathcal{F})$$ of the projection with the natural inclusion is homotopic to the identity map as desired. $\square$
Lemma. Sheaf cohomology and derived categories
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{U} : X = \bigcup_{i \in I} U_i$ be an open covering. Let $\mathcal{F}^\bullet$ be a bounded below complex of $\mathcal{O}_X$-modules. If $H^i(U_{i_0 \ldots i_p}, \mathcal{F}^q) = 0$ for all $i > 0$ and all $p, i_0, \ldots, i_p, q$, then the map $\text{Tot}(\check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{F}^\bullet)) \to R\Gamma(X, \mathcal{F}^\bullet)$ of Lemma Sheaf cohomology and derived categories (uncovered prerequisite) is an isomorphism.
Proof. Immediate from the spectral sequence of Lemma Sheaf cohomology and derived categories (uncovered prerequisite). $\square$
Lemma. Injective resolutions
In the situation described above. Denote $\mathcal{H}^m = H^m(\mathcal{F}^\bullet)$ the $m$th cohomology sheaf. Let $\mathcal{B}$ be a set of open subsets of $X$. Let $d \in \mathbf{N}$. Assume
-
every open in $X$ has a covering whose members are elements of $\mathcal{B}$,
-
for every $U \in \mathcal{B}$ we have $H^p(U, \mathcal{H}^q) = 0$ for $p > d$ and $q < 0$[^1].
Then (Injective resolutions) is a quasi-isomorphism.
Proof. By Derived Categories, Lemma Injective resolutions (uncovered prerequisite) it suffices to show that the map $\mathcal{F}^\bullet \to R\varprojlim \tau_{\geq -n} \mathcal{F}^\bullet$ is an isomorphism. This is Lemma Dimension and codimension (uncovered prerequisite). $\square$
Lemma. Adjunction for derived direct image
Let $f : (X, \mathcal{O}_X) \to (Y, \mathcal{O}_Y)$ be a morphism of ringed spaces. The functor $Rf_*$ defined above and the functor $Lf^*$ defined in Lemma Base change for derived categories (uncovered prerequisite) are adjoint: $$\operatorname{Hom}_{D(\mathcal{O}_X)}(Lf^*\mathcal{G}^\bullet, \mathcal{F}^\bullet)
\operatorname{Hom}_{D(\mathcal{O}Y)}(\mathcal{G}^\bullet, Rf*\mathcal{F}^\bullet)$$ bifunctorially in $\mathcal{F}^\bullet \in \operatorname{Ob}(D(\mathcal{O}_X))$ and $\mathcal{G}^\bullet \in \operatorname{Ob}(D(\mathcal{O}_Y))$.
Proof. This follows formally from the fact that $Rf_*$ and $Lf^*$ exist, see Derived Categories, Lemma Derived categories (uncovered prerequisite). $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $E$ be an object of $D(\mathcal{O}_X)$.
-
If there exists an open covering $X = \bigcup U_i$, strictly perfect complexes $\mathcal{E}_i^\bullet$ on $U_i$, and maps $\alpha_i : \mathcal{E}_i^\bullet \to E|_{U_i}$ in $D(\mathcal{O}_{U_i})$ with $H^j(\alpha_i)$ an isomorphism for $j > m$ and $H^m(\alpha_i)$ surjective, then $E$ is $m$-pseudo-coherent.
-
If $E$ is $m$-pseudo-coherent, then any complex representing $E$ is $m$-pseudo-coherent.
Proof. Let $\mathcal{F}^\bullet$ be any complex representing $E$ and let $X = \bigcup U_i$ and $\alpha_i : \mathcal{E}_i^\bullet \to E|_{U_i}$ be as in (1). We will show that $\mathcal{F}^\bullet$ is $m$-pseudo-coherent as a complex, which will prove (1) and (2) simultaneously. By Lemma A local representative for a derived object we can after refining the open covering $X = \bigcup U_i$ represent the maps $\alpha_i$ by maps of complexes $\alpha_i : \mathcal{E}_i^\bullet \to \mathcal{F}^\bullet|_{U_i}$. By assumption $H^j(\alpha_i)$ are isomorphisms for $j > m$, and $H^m(\alpha_i)$ is surjective whence $\mathcal{F}^\bullet$ is $m$-pseudo-coherent. $\square$
Lemma. Derived tensor products and Tor amplitude
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $E$ be an object of $D(\mathcal{O}_X)$. Let $a, b \in \mathbf{Z}$ with $a \leq b$. The following are equivalent
-
$E$ has tor-amplitude in $[a, b]$.
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$E$ is represented by a complex $\mathcal{E}^\bullet$ of flat $\mathcal{O}_X$-modules with $\mathcal{E}^i = 0$ for $i \not \in [a, b]$.
Proof. If (2) holds, then we may compute $E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{F} = \mathcal{E}^\bullet \otimes_{\mathcal{O}_X} \mathcal{F}$ and it is clear that (1) holds.
Assume that (1) holds. We may represent $E$ by a bounded above complex of flat $\mathcal{O}_X$-modules $\mathcal{K}^\bullet$, see Section Flatness. Let $n$ be the largest integer such that $\mathcal{K}^n \not = 0$. If $n > b$, then $\mathcal{K}^{n - 1} \to \mathcal{K}^n$ is surjective as $H^n(\mathcal{K}^\bullet) = 0$. As $\mathcal{K}^n$ is flat we see that $\operatorname{Ker}(\mathcal{K}^{n - 1} \to \mathcal{K}^n)$ is flat (Modules, Lemma Flat modules in a short exact sequence (uncovered prerequisite)). Hence we may replace $\mathcal{K}^\bullet$ by $\tau_{\leq n - 1}\mathcal{K}^\bullet$. Thus, by induction on $n$, we reduce to the case that $K^\bullet$ is a complex of flat $\mathcal{O}_X$-modules with $\mathcal{K}^i = 0$ for $i > b$.
Set $\mathcal{E}^\bullet = \tau_{\geq a}\mathcal{K}^\bullet$. Everything is clear except that $\mathcal{E}^a$ is flat which follows immediately from Lemma Flatness and the definitions. $\square$
Lemma. Perfect complexes
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $E$ be an object of $D(\mathcal{O}_X)$. Let $a \leq b$ be integers. If $E$ has tor amplitude in $[a, b]$ and is $(a - 1)$-pseudo-coherent, then $E$ is perfect.
Proof. After replacing $X$ by the members of an open covering we may assume there exists a strictly perfect complex $\mathcal{E}^\bullet$ and a map $\alpha : \mathcal{E}^\bullet \to E$ such that $H^i(\alpha)$ is an isomorphism for $i \geq a$. We may and do replace $\mathcal{E}^\bullet$ by $\sigma_{\geq a - 1}\mathcal{E}^\bullet$. Choose a distinguished triangle $$\mathcal{E}^\bullet \to E \to C \to \mathcal{E}^\bullet[1]$$ From the vanishing of cohomology sheaves of $E$ and $\mathcal{E}^\bullet$ and the assumption on $\alpha$ we obtain $C \cong \mathcal{K}[2 - a]$ with $\mathcal{K} = \operatorname{Ker}(\mathcal{E}^{a - 1} \to \mathcal{E}^a)$. Let $\mathcal{F}$ be an $\mathcal{O}_X$-module. Applying $- \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{F}$ the assumption that $E$ has tor amplitude in $[a, b]$ implies $\mathcal{K} \otimes_{\mathcal{O}_X} \mathcal{F} \to \mathcal{E}^{a - 1} \otimes_{\mathcal{O}_X} \mathcal{F}$ has image $\operatorname{Ker}(\mathcal{E}^{a - 1} \otimes_{\mathcal{O}_X} \mathcal{F} \to \mathcal{E}^a \otimes_{\mathcal{O}_X} \mathcal{F})$. It follows that $\text{Tor}_1^{\mathcal{O}_X}(\mathcal{E}', \mathcal{F}) = 0$ where $\mathcal{E}' = \operatorname{Coker}(\mathcal{E}^{a - 1} \to \mathcal{E}^a)$. Hence $\mathcal{E}'$ is flat (Lemma Tor vanishing for a flat module). Thus $\mathcal{E}'$ is locally a direct summand of a finite free module by Modules, Lemma Finite presentation and flatness (uncovered prerequisite). Thus locally the complex $$\mathcal{E}' \to \mathcal{E}^{a + 1} \to \ldots \to \mathcal{E}^b$$ is quasi-isomorphic to $E$ and $E$ is perfect. $\square$
Lemma. Tor vanishing for a flat module
Tor measures the deviation of flatness.
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{F}$ be an $\mathcal{O}_X$-module. The following are equivalent
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$\mathcal{F}$ is a flat $\mathcal{O}_X$-module, and
-
$\text{Tor}_1^{\mathcal{O}_X}(\mathcal{F}, \mathcal{G}) = 0$ for every $\mathcal{O}_X$-module $\mathcal{G}$.
Proof. If $\mathcal{F}$ is flat, then $\mathcal{F} \otimes_{\mathcal{O}_X} -$ is an exact functor and the satellites vanish. Conversely assume (2) holds. Then if $\mathcal{G} \to \mathcal{H}$ is injective with cokernel $\mathcal{Q}$, the long exact sequence of $\text{Tor}$ shows that the kernel of $\mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{G} \to \mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{H}$ is a quotient of $\text{Tor}_1^{\mathcal{O}_X}(\mathcal{F}, \mathcal{Q})$ which is zero by assumption. Hence $\mathcal{F}$ is flat. $\square$
Lemma. Perfect complexes and derived categories
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $K$ be a perfect object of $D(\mathcal{O}_X)$. Then $K^\vee = R\mathcal{H}om(K, \mathcal{O}_X)$ is a perfect object too and $(K^\vee)^\vee \cong K$. There are functorial isomorphisms $$M \otimes^\mathbf{L}_{\mathcal{O}_X} K^\vee = R\mathcal{H}om(K, M)$$ and $$H^0(X, M \otimes^\mathbf{L}_{\mathcal{O}_X} K^\vee) = \operatorname{Hom}_{D(\mathcal{O}_X)}(K, M)$$ for $M$ in $D(\mathcal{O}_X)$.
Proof. By Lemma Derived Hom and Ext (uncovered prerequisite) there is a canonical map $$K = R\mathcal{H}om(\mathcal{O}_X, \mathcal{O}_X) \otimes_{\mathcal{O}_X}^\mathbf{L} K \longrightarrow R\mathcal{H}om(R\mathcal{H}om(K, \mathcal{O}_X), \mathcal{O}_X) = (K^\vee)^\vee$$ which is an isomorphism by Lemma Derived Hom and Ext (uncovered prerequisite). To check the other statements we will use without further mention that formation of internal hom commutes with restriction to opens (Lemma Derived Hom and Ext (uncovered prerequisite)). We may check $K^\vee$ is perfect locally on $X$. By Lemma Derived sheaf cohomology (uncovered prerequisite) to see the final statement it suffices to check that the map (Derived sheaf cohomology) $$M \otimes^\mathbf{L}_{\mathcal{O}_X} K^\vee \longrightarrow R\mathcal{H}om(K, M)$$ is an isomorphism. This is local on $X$ as well. Hence it suffices to prove these two statements $K$ is represented by a strictly perfect complex.
Assume $K$ is represented by the strictly perfect complex $\mathcal{E}^\bullet$. Then it follows from Lemma Perfect complexes and derived Hom and Ext that $K^\vee$ is represented by the complex whose terms are $(\mathcal{E}^{-n})^\vee = \mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}^{-n}, \mathcal{O}_X)$ in degree $n$. Since $\mathcal{E}^{-n}$ is a direct summand of a finite free $\mathcal{O}_X$-module, so is $(\mathcal{E}^{-n})^\vee$. Hence $K^\vee$ is represented by a strictly perfect complex too and we see that $K^\vee$ is perfect. To see that (Derived sheaf cohomology) is an isomorphism, represent $M$ by a complex $\mathcal{F}^\bullet$. By Lemma Perfect complexes and derived Hom and Ext the complex $R\mathcal{H}om(K, M)$ is represented by the complex with terms $$\bigoplus\nolimits_{n = p + q} \mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}^{-q}, \mathcal{F}^p)$$ On the other hand, the object $M \otimes^\mathbf{L}_{\mathcal{O}_X} K^\vee$ is represented by the complex with terms $$\bigoplus\nolimits_{n = p + q} \mathcal{F}^p \otimes_{\mathcal{O}_X} (\mathcal{E}^{-q})^\vee$$ Thus the assertion that (Derived sheaf cohomology) is an isomorphism reduces to the assertion that the canonical map $$\mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}, \mathcal{O}_X) \longrightarrow \mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}, \mathcal{F})$$ is an isomorphism when $\mathcal{E}$ is a direct summand of a finite free $\mathcal{O}_X$-module and $\mathcal{F}$ is any $\mathcal{O}_X$-module. This follows immediately from the corresponding statement when $\mathcal{E}$ is finite free. $\square$
Lemma. A local representative for a derived object
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{E}^\bullet$, $\mathcal{F}^\bullet$ be complexes of $\mathcal{O}_X$-modules with $\mathcal{E}^\bullet$ strictly perfect.
-
For any element $\alpha \in \operatorname{Hom}_{D(\mathcal{O}_X)}(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ there exists an open covering $X = \bigcup U_i$ such that $\alpha|_{U_i}$ is given by a morphism of complexes $\alpha_i : \mathcal{E}^\bullet|_{U_i} \to \mathcal{F}^\bullet|_{U_i}$.
-
Given a morphism of complexes $\alpha : \mathcal{E}^\bullet \to \mathcal{F}^\bullet$ whose image in the group $\operatorname{Hom}_{D(\mathcal{O}_X)}(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ is zero, there exists an open covering $X = \bigcup U_i$ such that $\alpha|_{U_i}$ is homotopic to zero.
Proof. Proof of (1). By the construction of the derived category we can find a quasi-isomorphism $f : \mathcal{F}^\bullet \to \mathcal{G}^\bullet$ and a map of complexes $\beta : \mathcal{E}^\bullet \to \mathcal{G}^\bullet$ such that $\alpha = f^{-1}\beta$. Thus the result follows from Lemma Lifting derived sheaf cohomology. We omit the proof of (2). $\square$
Lemma. Derived Hom, Ext and derived tensor products and Tor amplitude
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $\mathcal{I}^\bullet$ be a K-injective complex of $\mathcal{O}_X$-modules. Let $\mathcal{L}^\bullet$ be a K-flat complex of $\mathcal{O}_X$-modules. Then $\mathcal{H}om^\bullet(\mathcal{L}^\bullet, \mathcal{I}^\bullet)$ is a K-injective complex of $\mathcal{O}_X$-modules.
Proof. Namely, if $\mathcal{K}^\bullet$ is an acyclic complex of $\mathcal{O}_X$-modules, then $$\begin{aligned} \operatorname{Hom}_{K(\mathcal{O}_X)}(\mathcal{K}^\bullet, \mathcal{H}om^\bullet(\mathcal{L}^\bullet, \mathcal{I}^\bullet)) & = H^0(\Gamma(X, \mathcal{H}om^\bullet(\mathcal{K}^\bullet, \mathcal{H}om^\bullet(\mathcal{L}^\bullet, \mathcal{I}^\bullet)))) \\ & = H^0(\Gamma(X, \mathcal{H}om^\bullet(\text{Tot}( \mathcal{K}^\bullet \otimes_{\mathcal{O}_X} \mathcal{L}^\bullet), \mathcal{I}^\bullet))) \\ & = \operatorname{Hom}_{K(\mathcal{O}_X)}( \text{Tot}(\mathcal{K}^\bullet \otimes_{\mathcal{O}_X} \mathcal{L}^\bullet), \mathcal{I}^\bullet) \\ & = 0 \end{aligned}$$ The first equality by (Sheaf cohomology and derived Hom and Ext). The second equality by Lemma Composition and derived sheaf cohomology (uncovered prerequisite). The third equality by (Sheaf cohomology and derived Hom and Ext). The final equality because $\text{Tot}(\mathcal{K}^\bullet \otimes_{\mathcal{O}_X} \mathcal{L}^\bullet)$ is acyclic because $\mathcal{L}^\bullet$ is K-flat (Definition Derived tensor products, Tor amplitude and flatness) and because $\mathcal{I}^\bullet$ is K-injective. $\square$
Lemma. Derived Hom, Ext and injective resolutions
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $L$ and $M$ be objects of $D(\mathcal{O}_X)$. Let $\mathcal{I}^\bullet$ be a K-injective complex of $\mathcal{O}_X$-modules representing $M$. Let $\mathcal{L}^\bullet$ be a complex of $\mathcal{O}_X$-modules representing $L$. Then $$H^0(\Gamma(U, \mathcal{H}om^\bullet(\mathcal{L}^\bullet, \mathcal{I}^\bullet))) = \operatorname{Hom}_{D(\mathcal{O}_U)}(L|_U, M|_U)$$ for all $U \subset X$ open.
Proof. We have $$\begin{aligned} H^0(\Gamma(U, \mathcal{H}om^\bullet(\mathcal{L}^\bullet, \mathcal{I}^\bullet))) & = \operatorname{Hom}_{K(\mathcal{O}_U)}(\mathcal{L}^\bullet|_U, \mathcal{I}^\bullet|_U) \\ & = \operatorname{Hom}_{D(\mathcal{O}_U)}(L|_U, M|_U) \end{aligned}$$ The first equality is (Sheaf cohomology and derived Hom and Ext). The second equality is true because $\mathcal{I}^\bullet|_U$ is K-injective by Lemma Injective resolutions (uncovered prerequisite). $\square$
Lemma. Derived sheaf cohomology
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $X = U \cup V$ be the union of two open subspaces. For any object $E$ of $D(\mathcal{O}_X)$ we have a distinguished triangle $$j_{U \cap V!}E|_{U \cap V} \to j_{U!}E|_U \oplus j_{V!}E|_V \to E \to j_{U \cap V!}E|_{U \cap V}[1]$$ in $D(\mathcal{O}_X)$.
Proof. We have seen in Section Injective resolutions and proper morphisms that the restriction functors and the extension by zero functors are computed by just applying the functors to any complex. Let $\mathcal{E}^\bullet$ be a complex of $\mathcal{O}_X$-modules representing $E$. The distinguished triangle of the lemma is the distinguished triangle associated (by Derived Categories, Section Derived tensor products and Tor amplitude and especially Lemma Derived tensor products, Tor amplitude and derived categories) to the short exact sequence of complexes of $\mathcal{O}_X$-modules $$0 \to j_{U \cap V!}\mathcal{E}^\bullet|_{U \cap V} \to j_{U!}\mathcal{E}^\bullet|_U \oplus j_{V!}\mathcal{E}^\bullet|_V \to \mathcal{E}^\bullet \to 0$$ To see this sequence is exact one checks on stalks using Sheaves, Lemma Modules (uncovered prerequisite) (computation omitted). $\square$
Lemma. Derived sheaf cohomology
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $U \subset X$ be an open subset. Denote $j : (U, \mathcal{O}_U) \to (X, \mathcal{O}_X)$ the corresponding open immersion. The restriction functor $D(\mathcal{O}_X) \to D(\mathcal{O}_U)$ is a right adjoint to extension by zero $j_! : D(\mathcal{O}_U) \to D(\mathcal{O}_X)$.
Proof. This follows formally from the fact that $j_!$ and $j^*$ are adjoint and exact (and hence $Lj_! = j_!$ and $Rj^* = j^*$ exist), see Derived Categories, Lemma Derived categories (uncovered prerequisite). $\square$
Lemma. Local algebra
Let $(X, \mathcal{O}_X)$ be a ringed space. Given a solid diagram of $\mathcal{O}_X$-modules $$\begin{gathered}\begin{matrix}\mathcal{E} & \mathcal{F} \\ \phantom{X} & \mathcal{G}\end{matrix} \\[6pt] \begin{aligned}\mathcal{E} & \cdots\!\!\rightarrow \mathcal{G} \\ \mathcal{E} & \longrightarrow \mathcal{F} \\ \mathcal{G} & \xrightarrow{p} \mathcal{F}\end{aligned}\end{gathered}$$ with $\mathcal{E}$ a direct summand of a finite free $\mathcal{O}_X$-module and $p$ surjective, then a dotted arrow making the diagram commute exists locally on $X$.
Proof. We may assume $\mathcal{E} = \mathcal{O}_X^{\oplus n}$ for some $n$. In this case finding the dotted arrow is equivalent to lifting the images of the basis elements in $\Gamma(X, \mathcal{F})$. This is locally possible by the characterization of surjective maps of sheaves (Sheaves, Section The geometric construction). $\square$
Lemma. Lifting derived sheaf cohomology
Let $(X, \mathcal{O}_X)$ be a ringed space. Given a solid diagram of complexes of $\mathcal{O}_X$-modules $$\begin{gathered}\begin{matrix}\mathcal{E}^\bullet & \mathcal{F}^\bullet \\ \phantom{X} & \mathcal{G}^\bullet\end{matrix} \\[6pt] \begin{aligned}\mathcal{E}^\bullet & \cdots\!\!\rightarrow \mathcal{G}^\bullet \\ \mathcal{E}^\bullet & \xrightarrow{\alpha} \mathcal{F}^\bullet \\ \mathcal{G}^\bullet & \xrightarrow{f} \mathcal{F}^\bullet\end{aligned}\end{gathered}$$ with $\mathcal{E}^\bullet$ strictly perfect, $\mathcal{E}^j = 0$ for $j < a$ and $H^j(f)$ an isomorphism for $j > a$ and surjective for $j = a$, then a dotted arrow making the diagram commute up to homotopy exists locally on $X$.
Proof. Our assumptions on $f$ imply the cone $C(f)^\bullet$ has vanishing cohomology sheaves in degrees $\geq a$. Hence Lemma Local algebra (uncovered prerequisite) guarantees there is an open covering $X = \bigcup U_i$ such that the composition $\mathcal{E}^\bullet \to \mathcal{F}^\bullet \to C(f)^\bullet$ is homotopic to zero over $U_i$. Since $$\mathcal{G}^\bullet \to \mathcal{F}^\bullet \to C(f)^\bullet \to \mathcal{G}^\bullet[1]$$ restricts to a distinguished triangle in $K(\mathcal{O}_{U_i})$ we see that we can lift $\alpha|_{U_i}$ up to homotopy to a map $\alpha_i : \mathcal{E}^\bullet|_{U_i} \to \mathcal{G}^\bullet|_{U_i}$ as desired. $\square$
Lemma. Derived categories
The cone on a morphism of strictly perfect complexes is strictly perfect.
Proof. This is immediate from the definitions. $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $(K, L, M, f, g, h)$ be a distinguished triangle in $D(\mathcal{O}_X)$. Let $a, b \in \mathbf{Z}$.
-
If $K$ has tor-amplitude in $[a + 1, b + 1]$ and $L$ has tor-amplitude in $[a, b]$ then $M$ has tor-amplitude in $[a, b]$.
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If $K$ and $M$ have tor-amplitude in $[a, b]$, then $L$ has tor-amplitude in $[a, b]$.
-
If $L$ has tor-amplitude in $[a + 1, b + 1]$ and $M$ has tor-amplitude in $[a, b]$, then $K$ has tor-amplitude in $[a + 1, b + 1]$.
Proof. Omitted. Hint: This just follows from the long exact cohomology sequence associated to a distinguished triangle and the fact that $- \otimes_{\mathcal{O}_X}^{\mathbf{L}} \mathcal{F}$ preserves distinguished triangles. The easiest one to prove is (2) and the others follow from it by translation. $\square$
Lemma. Mayer--Vietoris for unbounded quasi-coherent complexes
Let $(X, \mathcal{O}_X)$ be a ringed space. Suppose that $X = U \cup V$ is a union of two open subsets. For an object $E$ of $D(\mathcal{O}_X)$ we have a distinguished triangle $$R\Gamma(X, E) \to R\Gamma(U, E) \oplus R\Gamma(V, E) \to R\Gamma(U \cap V, E) \to R\Gamma(X, E)[1]$$ and in particular a long exact cohomology sequence $$\ldots \to H^n(X, E) \to H^n(U, E) \oplus H^0(V, E) \to H^n(U \cap V, E) \to H^{n + 1}(X, E) \to \ldots$$ The construction of the distinguished triangle and the long exact sequence is functorial in $E$.
Proof. Choose a K-injective complex $\mathcal{I}^\bullet$ representing $E$. We may assume $\mathcal{I}^n$ is an injective object of $\textit{Mod}(\mathcal{O}_X)$ for all $n$, see Injectives, Theorem Injective resolutions (uncovered prerequisite). Then $R\Gamma(X, E)$ is computed by $\Gamma(X, \mathcal{I}^\bullet)$. Similarly for $U$, $V$, and $U \cap V$ by Lemma Injective resolutions (uncovered prerequisite). Hence the distinguished triangle of the lemma is the distinguished triangle associated (by Derived Categories, Section Derived tensor products and Tor amplitude and especially Lemma Derived tensor products, Tor amplitude and derived categories) to the short exact sequence of complexes $$0 \to \mathcal{I}^\bullet(X) \to \mathcal{I}^\bullet(U) \oplus \mathcal{I}^\bullet(V) \to \mathcal{I}^\bullet(U \cap V) \to 0.$$ We have seen this is a short exact sequence in the proof of Lemma Derived sheaf cohomology (uncovered prerequisite). The final statement follows from the functoriality of the construction in Injectives, Theorem Injective resolutions (uncovered prerequisite). $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $(X, \mathcal{O}_X)$ be a ringed space. Let $K, L$ be objects of $D(\mathcal{O}_X)$.
-
If $K$ is $n$-pseudo-coherent and $H^i(K) = 0$ for $i > a$ and $L$ is $m$-pseudo-coherent and $H^j(L) = 0$ for $j > b$, then $K \otimes_{\mathcal{O}_X}^\mathbf{L} L$ is $t$-pseudo-coherent with $t = \max(m + a, n + b)$.
-
If $K$ and $L$ are pseudo-coherent, then $K \otimes_{\mathcal{O}_X}^\mathbf{L} L$ is pseudo-coherent.
Proof. Proof of (1). By replacing $X$ by the members of an open covering we may assume there exist strictly perfect complexes $\mathcal{K}^\bullet$ and $\mathcal{L}^\bullet$ and maps $\alpha : \mathcal{K}^\bullet \to K$ and $\beta : \mathcal{L}^\bullet \to L$ with $H^i(\alpha)$ and isomorphism for $i > n$ and surjective for $i = n$ and with $H^i(\beta)$ and isomorphism for $i > m$ and surjective for $i = m$. Then the map $$\alpha \otimes^\mathbf{L} \beta : \text{Tot}(\mathcal{K}^\bullet \otimes_{\mathcal{O}_X} \mathcal{L}^\bullet) \to K \otimes_{\mathcal{O}_X}^\mathbf{L} L$$ induces isomorphisms on cohomology sheaves in degree $i$ for $i > t$ and a surjection for $i = t$. This follows from the spectral sequence of tors (details omitted).
Proof of (2). We may first replace $X$ by the members of an open covering to reduce to the case that $K$ and $L$ are bounded above. Then the statement follows immediately from case (1). $\square$
Remark. Base change for derived sheaf cohomology
The construction of unbounded derived functor $Lf^*$ and $Rf_*$ allows one to construct the base change map in full generality. Namely, suppose that $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ is a commutative diagram of ringed spaces. Let $K$ be an object of $D(\mathcal{O}_X)$. Then there exists a canonical base change map $$Lg^*Rf_*K \longrightarrow R(f')_*L(g')^*K$$ in $D(\mathcal{O}_{S'})$. Namely, this map is adjoint to a map $L(f')^*Lg^*Rf_*K \to L(g')^*K$ Since $L(f')^*Lg^* = L(g')^*Lf^*$ we see this is the same as a map $L(g')^*Lf^*Rf_*K \to L(g')^*K$ which we can take to be $L(g')^*$ of the adjunction map $Lf^*Rf_*K \to K$.
Lemma. The Leray spectral sequence
Let $f : X \to Y$ be a morphism of ringed spaces. Let $\mathcal{F}^\bullet$ be a bounded below complex of $\mathcal{O}_X$-modules. There is a spectral sequence $$E_2^{p, q} = H^p(Y, R^qf_*(\mathcal{F}^\bullet))$$ converging to $H^{p + q}(X, \mathcal{F}^\bullet)$.
Proof. This is just the Grothendieck spectral sequence Derived Categories, Lemma Triangulated categories coming from the composition of functors $\Gamma_{res} = \Gamma(Y, -) \circ f_*$ where $\Gamma_{res}$ is as in the proof of Lemma Sheaf cohomology (uncovered prerequisite). To see that the assumptions of Derived Categories, Lemma Triangulated categories are satisfied, see the proof of Lemma Sheaf cohomology (uncovered prerequisite) or Remark Derived sheaf cohomology. $\square$
Lemma. Sheaf cohomology
Let $X$ be an irreducible topological space. Then $H^p(X, \underline{A}) = 0$ for all $p > 0$ and any abelian group $A$.
Proof. Recall that $\underline{A}$ is the constant sheaf as defined in Sheaves, Definition Sheaves on ringed sites. Since $X$ is irreducible, any nonempty open $U$ is irreducible and a fortiori connected. Hence for $U \subset X$ nonempty open we have $\underline{A}(U) = A$. We have $\underline{A}(\emptyset) = 0$. Thus $\underline{A}$ is a flasque abelian sheaf on $X$. The vanishing follows from Lemma Derived sheaf cohomology (uncovered prerequisite). $\square$
Lemma. Vanishing and derived sheaf cohomology
Source credit: This is a special case of the original source citation Tohoku (Proposition 3.6.1).
Let $X$ be a topological space. Let $d \geq 0$ be an integer. Assume
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$X$ is quasi-compact,
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the quasi-compact opens form a basis for $X$, and
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the intersection of two quasi-compact opens is quasi-compact.
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$H^p(X, j_!\underline{\mathbf{Z}}_U) = 0$ for all $p > d$ and any quasi-compact open $j : U \to X$.
Then $H^p(X, \mathcal{F}) = 0$ for all $p > d$ and any abelian sheaf $\mathcal{F}$ on $X$.
Proof. Let $S = \coprod_{U \subset X} \mathcal{F}(U)$ where $U$ runs over the quasi-compact opens of $X$. For any finite subset $A = \{s_1, \ldots, s_n\} \subset S$, let $\mathcal{F}_A$ be the subsheaf of $\mathcal{F}$ generated by all $s_i$ (see Modules, Definition Local algebra). Note that if $A \subset A'$, then $\mathcal{F}_A \subset \mathcal{F}_{A'}$. Hence $\{\mathcal{F}_A\}$ forms a system over the directed partially ordered set of finite subsets of $S$. By Modules, Lemma Sheaves on ringed sites and local algebra (uncovered prerequisite) it is clear that $$\mathop{\operatorname{colim}}_A \mathcal{F}_A = \mathcal{F}$$ by looking at stalks. By Lemma Filtered limits and sheaf cohomology and diagonals and separation (uncovered prerequisite) we have $$H^p(X, \mathcal{F}) = \mathop{\operatorname{colim}}_A H^p(X, \mathcal{F}_A)$$ Hence it suffices to prove the vanishing for the abelian sheaves $\mathcal{F}_A$. In other words, it suffices to prove the result when $\mathcal{F}$ is generated by finitely many local sections over quasi-compact opens of $X$.
Suppose that $\mathcal{F}$ is generated by the local sections $s_1, \ldots, s_n$. Let $\mathcal{F}' \subset \mathcal{F}$ be the subsheaf generated by $s_1, \ldots, s_{n - 1}$. Then we have a short exact sequence $$0 \to \mathcal{F}' \to \mathcal{F} \to \mathcal{F}/\mathcal{F}' \to 0$$ From the long exact sequence of cohomology we see that it suffices to prove the vanishing for the abelian sheaves $\mathcal{F}'$ and $\mathcal{F}/\mathcal{F}'$ which are generated by fewer than $n$ local sections. Hence it suffices to prove the vanishing for sheaves generated by at most one local section. These sheaves are exactly the quotients of the sheaves $j_!\underline{\mathbf{Z}}_U$ where $U$ is a quasi-compact open of $X$.
Assume now that we have a short exact sequence $$0 \to \mathcal{K} \to j_!\underline{\mathbf{Z}}_U \to \mathcal{F} \to 0$$ with $U$ quasi-compact open in $X$. It suffices to show that $H^q(X, \mathcal{K})$ is zero for $q \geq d + 1$. As above we can write $\mathcal{K}$ as the filtered colimit of subsheaves $\mathcal{K}'$ generated by finitely many sections over quasi-compact opens. Then $\mathcal{F}$ is the filtered colimit of the sheaves $j_!\underline{\mathbf{Z}}_U/\mathcal{K}'$. In this way we reduce to the case that $\mathcal{K}$ is generated by finitely many sections over quasi-compact opens. Note that $\mathcal{K}$ is a subsheaf of $\underline{\mathbf{Z}}_X$. Thus by Lemma Sheaves on ringed sites (uncovered prerequisite) there exists a finite filtration of $\mathcal{K}$ whose successive quotients $\mathcal{Q}$ fit into a short exact sequence $$0 \to j''_!\underline{\mathbf{Z}}_W \to j'_!\underline{\mathbf{Z}}_V \to \mathcal{Q} \to 0$$ with $j'' : W \to X$ and $j' : V \to X$ the inclusions of quasi-compact opens. Hence the vanishing of $H^p(X, \mathcal{Q})$ for $p > d$ follows from our assumption (in the lemma) on the vanishing of the cohomology groups of $j''_!\underline{\mathbf{Z}}_W$ and $j'_!\underline{\mathbf{Z}}_V$. Returning to $\mathcal{K}$ this, via an induction argument using the long exact cohomology sequence, implies the desired vanishing for it as well. $\square$
Lemma. Acyclicity and the Leray spectral sequence
Let $f : X \to Y$ be a morphism of ringed spaces. Let $\mathcal{F}$ be an $\mathcal{O}_X$-module.
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If $R^qf_*\mathcal{F} = 0$ for $q > 0$, then $H^p(X, \mathcal{F}) = H^p(Y, f_*\mathcal{F})$ for all $p$.
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If $H^p(Y, R^qf_*\mathcal{F}) = 0$ for all $q$ and $p > 0$, then $H^q(X, \mathcal{F}) = H^0(Y, R^qf_*\mathcal{F})$ for all $q$.
Proof. These are two simple conditions that force the Leray spectral sequence to degenerate at $E_2$. You can also prove these facts directly (without using the spectral sequence) which is a good exercise in cohomology of sheaves. $\square$
Lemma. Derived sheaf cohomology
Let $X$ be a topological space. Let $\mathcal{H}$ be an abelian sheaf on $X$. There is a canonical bijection between the set of isomorphism classes of $\mathcal{H}$-torsors and $H^1(X, \mathcal{H})$.
Proof. Let $\mathcal{F}$ be a $\mathcal{H}$-torsor. Consider the free abelian sheaf $\mathbf{Z}[\mathcal{F}]$ on $\mathcal{F}$. It is the sheafification of the rule which associates to $U \subset X$ open the collection of finite formal sums $\sum n_i[s_i]$ with $n_i \in \mathbf{Z}$ and $s_i \in \mathcal{F}(U)$. There is a natural map $$\sigma : \mathbf{Z}[\mathcal{F}] \longrightarrow \underline{\mathbf{Z}}$$ which to a local section $\sum n_i[s_i]$ associates $\sum n_i$. The kernel of $\sigma$ is generated by the local section of the form $[s] - [s']$. There is a canonical map $a : \operatorname{Ker}(\sigma) \to \mathcal{H}$ which maps $[s] - [s'] \mapsto h$ where $h$ is the local section of $\mathcal{H}$ such that $h \cdot s' = s$. Consider the pushout diagram $$\begin{gathered}\begin{matrix}0 & \operatorname{Ker}(\sigma) & \mathbf{Z}[\mathcal{F}] & \underline{\mathbf{Z}} & 0 \\ 0 & \mathcal{H} & \mathcal{E} & \underline{\mathbf{Z}} & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \operatorname{Ker}(\sigma) \\ \operatorname{Ker}(\sigma) & \longrightarrow \mathbf{Z}[\mathcal{F}] \\ \operatorname{Ker}(\sigma) & \xrightarrow{a} \mathcal{H} \\ \mathbf{Z}[\mathcal{F}] & \longrightarrow \underline{\mathbf{Z}} \\ \mathbf{Z}[\mathcal{F}] & \longrightarrow \mathcal{E} \\ \underline{\mathbf{Z}} & \longrightarrow 0 \\ \underline{\mathbf{Z}} & \longrightarrow \underline{\mathbf{Z}} \\ 0 & \longrightarrow \mathcal{H} \\ \mathcal{H} & \longrightarrow \mathcal{E} \\ \mathcal{E} & \longrightarrow \underline{\mathbf{Z}} \\ \underline{\mathbf{Z}} & \longrightarrow 0\end{aligned}\end{gathered}$$ Here $\mathcal{E}$ is the extension obtained by pushout. From the long exact cohomology sequence associated to the lower short exact sequence we obtain an element $\xi = \xi_\mathcal{F} \in H^1(X, \mathcal{H})$ by applying the boundary operator to $1 \in H^0(X, \underline{\mathbf{Z}})$.
Conversely, given $\xi \in H^1(X, \mathcal{H})$ we can associate to $\xi$ a torsor as follows. Choose an embedding $\mathcal{H} \to \mathcal{I}$ of $\mathcal{H}$ into an injective abelian sheaf $\mathcal{I}$. We set $\mathcal{Q} = \mathcal{I}/\mathcal{H}$ so that we have a short exact sequence $$\begin{gathered}\begin{matrix}0 & \mathcal{H} & \mathcal{I} & \mathcal{Q} & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \mathcal{H} \\ \mathcal{H} & \longrightarrow \mathcal{I} \\ \mathcal{I} & \longrightarrow \mathcal{Q} \\ \mathcal{Q} & \longrightarrow 0\end{aligned}\end{gathered}$$ The element $\xi$ is the image of a global section $q \in H^0(X, \mathcal{Q})$ because $H^1(X, \mathcal{I}) = 0$ (see Derived Categories, Lemma Derived categories (uncovered prerequisite)). Let $\mathcal{F} \subset \mathcal{I}$ be the subsheaf (of sets) of sections that map to $q$ in the sheaf $\mathcal{Q}$. It is easy to verify that $\mathcal{F}$ is a torsor.
We omit the verification that the two constructions given above are mutually inverse. $\square$
Lemma. Derived sheaf cohomology
Let $X$ be a topological space. Let $\mathcal{G}$ be a sheaf of (possibly non-commutative) groups on $X$. A $\mathcal{G}$-torsor $\mathcal{F}$ is trivial if and only if $\mathcal{F}(X) \not = \emptyset$.
Proof. Omitted. $\square$
[^1]: It suffices if $\forall m$, $\exists p(m)$, $H^p(U. \mathcal{H}^{m - p}) = 0$ for $p > p(m)$, see Lemma Derived sheaf cohomology (uncovered prerequisite).
Perfect complexes and support
Lemma. Bounded comparison of affine derived categories
Let $X = \operatorname{Spec}(A)$ be an affine scheme. All the functors in the diagram $$\begin{gathered}\begin{matrix}D(\mathrm{QCoh}(\mathcal{O}_X)) & \phantom{X} & D_\mathrm{QCoh}(\mathcal{O}_X) \\ \phantom{X} & D(A)\end{matrix} \\[6pt] \begin{aligned}D(\mathrm{QCoh}(\mathcal{O}_X)) & \xrightarrow{(\text{Comparison of derived quasi-coherent categories})} D_\mathrm{QCoh}(\mathcal{O}_X) \\ D_\mathrm{QCoh}(\mathcal{O}_X) & \xrightarrow{R\Gamma(X, -)} D(A) \\ D(A) & \xrightarrow{\widetilde{\ \ }} D(\mathrm{QCoh}(\mathcal{O}_X))\end{aligned}\end{gathered}$$ are equivalences of triangulated categories. Moreover, for $E$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$ we have $H^0(X, E) = H^0(X, H^0(E))$.
Proof. The functor $R\Gamma(X, -)$ gives a functor $D(\mathcal{O}_X) \to D(A)$ and hence by restriction a functor
$$R\Gamma(X, -) : D_\mathrm{QCoh}(\mathcal{O}_X) \longrightarrow D(A).$$ We will show this functor is quasi-inverse to (Comparison of derived quasi-coherent categories) via the equivalence between quasi-coherent modules on $X$ and the category of $A$-modules.
Elucidation. Denote $(Y, \mathcal{O}_Y)$ the one point space with sheaf of rings given by $A$. Denote $\pi : (X, \mathcal{O}_X) \to (Y, \mathcal{O}_Y)$ the obvious morphism of ringed spaces. Then $R\Gamma(X, -)$ can be identified with $R\pi_*$ and the functor (Comparison of derived quasi-coherent categories) via the equivalence $\textit{Mod}(\mathcal{O}_Y) = \text{Mod}_A = \mathrm{QCoh}(\mathcal{O}_X)$ can be identified with $L\pi^* = \pi^* = \widetilde{\ }$ (see Modules, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite) and Schemes, Lemmas Comparison for the geometric construction (uncovered prerequisite) and Quasi-coherent complexes and coherent sheaves (uncovered prerequisite)). Thus the functors $$\begin{gathered}\begin{matrix}D(A) & D(\mathcal{O}_X)\end{matrix} \\[6pt] \begin{aligned}D(A) & \longrightarrow D(\mathcal{O}_X) \\ D(\mathcal{O}_X) & \longrightarrow D(A)\end{aligned}\end{gathered}$$ are adjoint (by Cohomology, Lemma Adjunction for derived direct image). In particular we obtain canonical adjunction mappings $$a : \widetilde{R\Gamma(X, E)} \longrightarrow E$$ for $E$ in $D(\mathcal{O}_X)$ and $$b : M^\bullet \longrightarrow R\Gamma(X, \widetilde{M^\bullet})$$ for $M^\bullet$ a complex of $A$-modules.
Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. We may apply Lemma Computing derived Hom with a quasi-coherent K-injective model to the functor $F(-) = \Gamma(X, -)$ with $N = 1$ by Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). Hence $$H^0(R\Gamma(X, E)) = H^0(R\Gamma(X, \tau_{\geq 0}E)) = \Gamma(X, H^0(E))$$ (the last equality by definition of the canonical truncation). Using this we will show that the adjunction mappings $a$ and $b$ induce isomorphisms $H^0(a)$ and $H^0(b)$. Thus $a$ and $b$ are quasi-isomorphisms (as the statement is invariant under shifts) and the lemma is proved.
In both cases we use that $\widetilde{\ }$ is an exact functor (Schemes, Lemma Prime spectra and associated points (uncovered prerequisite)). Namely, this implies that $$H^0\left(\widetilde{R\Gamma(X, E)}\right) = \widetilde{H^0(R\Gamma(X, E))} = \widetilde{\Gamma(X, H^0(E))}$$ which is equal to $H^0(E)$ because $H^0(E)$ is quasi-coherent. Thus $H^0(a)$ is an isomorphism. For the other direction we have $$H^0(R\Gamma(X, \widetilde{M^\bullet})) = \Gamma(X, H^0(\widetilde{M^\bullet})) = \Gamma(X, \widetilde{H^0(M^\bullet)}) = H^0(M^\bullet)$$ which proves that $H^0(b)$ is an isomorphism. $\square$
Lemma. Computing derived Hom with a quasi-coherent K-injective model
Let $X$ be a scheme. Let $F : \textit{Mod}(\mathcal{O}_X) \to \textit{Ab}$ be an additive functor and $N \geq 0$ an integer. Assume that
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$F$ commutes with countable direct products,
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$R^pF(\mathcal{F}) = 0$ for all $p \geq N$ and $\mathcal{F}$ quasi-coherent.
Then for $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$
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$H^i(RF(\tau_{\leq a}E)) \to H^i(RF(E))$ is an isomorphism for $i \leq a$,
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$H^i(RF(E)) \to H^i(RF(\tau_{\geq b - N + 1}E))$ is an isomorphism for $i \geq b$,
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if $H^i(E) = 0$ for $i \not \in [a, b]$ for some $-\infty \leq a \leq b \leq \infty$, then $H^i(RF(E)) = 0$ for $i \not \in [a, b + N - 1]$.
Proof. Statement (1) is Derived Categories, Lemma Vanishing in negative degrees.
Proof of statement (2). Write $E_n = \tau_{\geq -n}E$. We have $E = R\varprojlim E_n$, see Lemma A K-injective representative compatible with quasi-coherence. Thus $RF(E) = R\varprojlim RF(E_n)$ in $D(\textit{Ab})$ by Injectives, Lemma The geometric construction (uncovered prerequisite). Thus for every $i \in \mathbf{Z}$ we have a short exact sequence $$0 \to R^1\varprojlim H^{i - 1}(RF(E_n)) \to H^i(RF(E)) \to \varprojlim H^i(RF(E_n)) \to 0$$ see More on Algebra, Remark Comparison for derived categories. To prove (2) we will show that the term on the left is zero and that the term on the right equals $H^i(RF(E_{-b + N - 1}))$ for any $b$ with $i \geq b$.
For every $n$ we have a distinguished triangle $$H^{-n}(E)[n] \to E_n \to E_{n - 1} \to H^{-n}(E)[n + 1]$$ (Derived Categories, Remark Derived categories) in $D(\mathcal{O}_X)$. Since $H^{-n}(E)$ is quasi-coherent we have $$H^i(RF(H^{-n}(E)[n])) = R^{i + n}F(H^{-n}(E)) = 0$$ for $i + n \geq N$ and $$H^i(RF(H^{-n}(E)[n + 1])) = R^{i + n + 1}F(H^{-n}(E)) = 0$$ for $i + n + 1 \geq N$. We conclude that $$H^i(RF(E_n)) \to H^i(RF(E_{n - 1}))$$ is an isomorphism for $n \geq N - i$. Thus the systems $H^i(RF(E_n))$ all satisfy the ML condition and the $R^1\varprojlim$ term in our short exact sequence is zero (see discussion in More on Algebra, Section Derived commutative algebra). Moreover, the system $H^i(RF(E_n))$ is constant starting with $n = N - i - 1$ as desired.
Proof of (3). Under the assumption on $E$ we have $\tau_{\leq a - 1}E = 0$ and we get the vanishing of $H^i(RF(E))$ for $i \leq a - 1$ from (1). Similarly, we have $\tau_{\geq b + 1}E = 0$ and hence we get the vanishing of $H^i(RF(E))$ for $i \geq b + N$ from part (2). $\square$
Lemma. Lifting pseudo-coherent complexes and coherent sheaves
Let $X$ be an affine scheme and let $U \subset X$ be a quasi-compact open subscheme. For any pseudo-coherent object $E$ of $D(\mathcal{O}_U)$ there exists a bounded above complex of finite free $\mathcal{O}_X$-modules whose restriction to $U$ is isomorphic to $E$.
Proof. By Lemma Pseudo-coherent complexes and coherent sheaves we see that $E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_U)$. By Lemma Lifting quasi-coherent complexes and coherent sheaves we may assume $E = E'|U$ for some object $E'$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Write $X = \operatorname{Spec}(A)$. By Lemma Bounded comparison of affine derived categories we can find a complex $M^\bullet$ of $A$-modules whose associated complex of $\mathcal{O}_X$-modules is a representative of $E'$.
Choose $f_1, \ldots, f_r \in A$ such that $U = D(f_1) \cup \ldots \cup D(f_r)$. By Lemma Pseudo-coherent complexes on an affine scheme the complexes $M^\bullet_{f_j}$ are pseudo-coherent complexes of $A_{f_j}$-modules. Let $n$ be an integer. Assume we have a map of complexes $\alpha : F^\bullet \to M^\bullet$ where $F^\bullet$ is bounded above, $F^i = 0$ for $i < n$, each $F^i$ is a finite free $R$-module, such that $$H^i(\alpha_{f_j}) : H^i(F^\bullet_{f_j}) \to H^i(M^\bullet_{f_j})$$ is an isomorphism for $i > n$ and surjective for $i = n$. Picture $$\begin{gathered}\begin{matrix}\phantom{X} & F^n & F^{n + 1} & \ldots \\ M^{n-1} & M^n & M^{n + 1} & \ldots\end{matrix} \\[6pt] \begin{aligned}F^n & \longrightarrow F^{n + 1} \\ F^n & \xrightarrow{\alpha} M^n \\ F^{n + 1} & \xrightarrow{\alpha} M^{n + 1} \\ F^{n + 1} & \longrightarrow \ldots \\ M^{n-1} & \longrightarrow M^n \\ M^n & \longrightarrow M^{n + 1} \\ M^{n + 1} & \longrightarrow \ldots\end{aligned}\end{gathered}$$ Since each $M^\bullet_{f_j}$ has vanishing cohomology in large degrees we can find such a map for $n \gg 0$. By induction on $n$ we are going to extend this to a map of complexes $F^\bullet \to M^\bullet$ such that $H^i(\alpha_{f_j})$ is an isomorphism for all $i$. The lemma will follow by taking $\widetilde{F^\bullet}$.
The induction step will be to extend the diagram above by adding $F^{n - 1}$. Let $C^\bullet$ be the cone on $\alpha$ (Derived Categories, Definition The cone of a complex morphism). The long exact sequence of cohomology shows that $H^i(C^\bullet_{f_j}) = 0$ for $i \geq n$. By More on Algebra, Lemma Pseudo-coherent complexes and coherent sheaves we see that $C^\bullet_{f_j}$ is $(n - 1)$-pseudo-coherent. By More on Algebra, Lemma Finiteness of cohomology groups we see that $H^{n - 1}(C^\bullet_{f_j})$ is a finite $A_{f_j}$-module. Choose a finite free $A$-module $F^{n - 1}$ and an $A$-module $\beta : F^{n - 1} \to C^{n - 1}$ such that the composition $F^{n - 1} \to C^{n - 1} \to C^n$ is zero and such that $F^{n - 1}_{f_j}$ surjects onto $H^{n - 1}(C^\bullet_{f_j})$. (Some details omitted; hint: clear denominators.) Since $C^{n - 1} = M^{n - 1} \oplus F^n$ we can write $\beta = (\alpha^{n - 1}, -d^{n - 1})$. The vanishing of the composition $F^{n - 1} \to C^{n - 1} \to C^n$ implies these maps fit into a morphism of complexes $$\begin{gathered}\begin{matrix}\phantom{X} & F^{n - 1} & F^n & F^{n + 1} & \ldots \\ \ldots & M^{n - 1} & M^n & M^{n + 1} & \ldots\end{matrix} \\[6pt] \begin{aligned}F^{n - 1} & \xrightarrow{\alpha^{n - 1}} M^{n - 1} \\ F^{n - 1} & \xrightarrow{d^{n - 1}} F^n \\ F^n & \longrightarrow F^{n + 1} \\ F^n & \xrightarrow{\alpha} M^n \\ F^{n + 1} & \xrightarrow{\alpha} M^{n + 1} \\ F^{n + 1} & \longrightarrow \ldots \\ \ldots & \longrightarrow M^{n - 1} \\ M^{n - 1} & \longrightarrow M^n \\ M^n & \longrightarrow M^{n + 1} \\ M^{n + 1} & \longrightarrow \ldots\end{aligned}\end{gathered}$$ Moreover, these maps define a morphism of distinguished triangles $$\begin{gathered}\begin{matrix}(F^n \to \ldots) & (F^{n-1} \to \ldots) & F^{n-1} & (F^n \to \ldots)[1] \\ (F^n \to \ldots) & M^\bullet & C^\bullet & (F^n \to \ldots)[1]\end{matrix} \\[6pt] \begin{aligned}(F^n \to \ldots) & \longrightarrow (F^{n-1} \to \ldots) \\ (F^n \to \ldots) & \longrightarrow (F^n \to \ldots) \\ (F^{n-1} \to \ldots) & \longrightarrow F^{n-1} \\ (F^{n-1} \to \ldots) & \longrightarrow M^\bullet \\ F^{n-1} & \longrightarrow (F^n \to \ldots)[1] \\ F^{n-1} & \xrightarrow{\beta} C^\bullet \\ (F^n \to \ldots)[1] & \longrightarrow (F^n \to \ldots)[1] \\ (F^n \to \ldots) & \longrightarrow M^\bullet \\ M^\bullet & \longrightarrow C^\bullet \\ C^\bullet & \longrightarrow (F^n \to \ldots)[1]\end{aligned}\end{gathered}$$ Hence our choice of $\beta$ implies that the map of complexes $(F^{-1} \to \ldots) \to M^\bullet$ induces an isomorphism on cohomology localized at $f_j$ in degrees $\geq n$ and a surjection in degree $n - 1$. This finishes the proof of the lemma. $\square$
Lemma. Ext from a perfect complex to bounded quasi-coherent cohomology
Let $X$ be a quasi-compact and quasi-separated scheme. Let $K$ be a perfect object of $D(\mathcal{O}_X)$. Then
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there exist integers $a \leq b$ such that for any $L \in D_\mathrm{QCoh}(\mathcal{O}_X)$ with $H^i(L) = 0$ for $i \in [a, b]$ we have $\operatorname{Hom}_{D(\mathcal{O}_X)}(K, L) = 0$, and
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if $L$ is bounded, then $\operatorname{Ext}^n_{D(\mathcal{O}_X)}(K, L)$ is zero for all but finitely many $n$.
Proof. Part (2) follows from (1) as $\operatorname{Ext}^n_{D(\mathcal{O}_X)}(K, L) = \operatorname{Hom}_{D(\mathcal{O}_X)}(K, L[n])$. We prove (1). Since $K$ is perfect we have $$\operatorname{Hom}_{D(\mathcal{O}_X)}(K, L) = H^0(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$$ where $K^\vee$ is the "dual" perfect complex to $K$, see Cohomology, Lemma Perfect complexes and derived categories. Note that $K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L$ is in $D_\mathrm{QCoh}(X)$ by Lemmas Quasi-coherent complexes and coherent sheaves and Pseudo-coherent complexes and coherent sheaves (to see that a perfect complex has quasi-coherent cohomology sheaves). Say $K^\vee$ has tor amplitude in $[a, b]$. Then the spectral sequence $$E_1^{p, q} = H^p(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} H^q(L)) \Rightarrow H^{p + q}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$$ shows that $H^j(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$ is zero if $H^q(L) = 0$ for $q \in [j - b, j - a]$. Let $N$ be the integer $d$ of Cohomology of Schemes, Lemma Vanishing and diagonals, separation and affine neighbourhoods (uncovered prerequisite). Then $H^0(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$ vanishes if the cohomology sheaves $$H^{-N}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L), \ H^{-N + 1}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L), \ \ldots, \ H^0(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$$ are zero. Namely, by the lemma cited and Lemma Computing derived Hom with a quasi-coherent K-injective model, we have $$H^0(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L) = H^0(X, \tau_{\geq -N}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L))$$ and by the vanishing of cohomology sheaves, this is equal to $H^0(X, \tau_{\geq 1}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L))$ which is zero by Derived Categories, Lemma Vanishing in negative degrees. It follows that $\operatorname{Hom}_{D(\mathcal{O}_X)}(K, L)$ is zero if $H^i(L) = 0$ for $i \in [-b - N, -a]$. $\square$
Lemma. Perfect complexes on an affine scheme
Let $X = \operatorname{Spec}(A)$ be an affine scheme. Let $M^\bullet$ be a complex of $A$-modules and let $E$ be the corresponding object of $D(\mathcal{O}_X)$. Then $E$ is a perfect object of $D(\mathcal{O}_X)$ if and only if $M^\bullet$ is perfect as an object of $D(A)$.
Proof. This is a logical consequence of Lemmas Pseudo-coherent complexes on an affine scheme and Derived tensor products, Tor amplitude and dimension and codimension, Cohomology, Lemma Perfect complexes, and More on Algebra, Lemma Perfect complexes. $\square$
Definition. Bounds for perfect approximation
Let $X$ be a scheme. Consider triples $(T, E, m)$ where
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$T \subset X$ is a closed subset,
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$E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$, and
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$m \in \mathbf{Z}$.
We say approximation holds for the triple $(T, E, m)$ if there exists a perfect object $P$ of $D(\mathcal{O}_X)$ supported on $T$ and a map $\alpha : P \to E$ which induces isomorphisms $H^i(P) \to H^i(E)$ for $i > m$ and a surjection $H^m(P) \to H^m(E)$.
Lemma. Pseudo-coherent complexes on an affine scheme
Let $X = \operatorname{Spec}(A)$ be an affine scheme. Let $M^\bullet$ be a complex of $A$-modules and let $E$ be the corresponding object of $D(\mathcal{O}_X)$. Then $E$ is an $m$-pseudo-coherent (resp. pseudo-coherent) as an object of $D(\mathcal{O}_X)$ if and only if $M^\bullet$ is $m$-pseudo-coherent (resp. pseudo-coherent) as a complex of $A$-modules.
Proof. It is immediate from the definitions that if $M^\bullet$ is $m$-pseudo-coherent, so is $E$. To prove the converse, assume $E$ is $m$-pseudo-coherent. As $X = \operatorname{Spec}(A)$ is quasi-compact with a basis for the topology given by standard opens, we can find a standard open covering $X = D(f_1) \cup \ldots \cup D(f_n)$ and strictly perfect complexes $\mathcal{E}_i^\bullet$ on $D(f_i)$ and maps $\alpha_i : \mathcal{E}_i^\bullet \to E|_{U_i}$ inducing isomorphisms on $H^j$ for $j > m$ and surjections on $H^m$. By Cohomology, Lemma A local representative for a derived object after refining the open covering we may assume $\alpha_i$ is given by a map of complexes $\mathcal{E}_i^\bullet \to \widetilde{M^\bullet}|_{U_i}$ for each $i$. By Modules, Lemma Projective, locally free modules and tensor products and direct sums (uncovered prerequisite) the terms $\mathcal{E}_i^n$ are finite locally free modules. Hence after refining the open covering we may assume each $\mathcal{E}_i^n$ is a finite free $\mathcal{O}_{U_i}$-module. From the definition it follows that $M^\bullet_{f_i}$ is an $m$-pseudo-coherent complex of $A_{f_i}$-modules. We conclude by applying More on Algebra, Lemma Pseudo-coherent complexes and coherent sheaves.
The case "pseudo-coherent" follows from the fact that $E$ is pseudo-coherent if and only if $E$ is $m$-pseudo-coherent for all $m$ (by definition) and the same is true for $M^\bullet$ by More on Algebra, Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $f : Y \to X$ be a morphism of schemes.
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The functor $Lf^*$ sends $D_\mathrm{QCoh}(\mathcal{O}_X)$ into $D_\mathrm{QCoh}(\mathcal{O}_Y)$.
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If $X$ and $Y$ are affine and $f$ is given by the ring map $A \to B$, then the diagram $$\begin{gathered}\begin{matrix}D(B) & D_\mathrm{QCoh}(\mathcal{O}_Y) \\ D(A) & D_\mathrm{QCoh}(\mathcal{O}_X)\end{matrix} \\[6pt] \begin{aligned}D(B) & \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_Y) \\ D(A) & \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_X) \\ D(A) & \xrightarrow{- \otimes_A^\mathbf{L} B} D(B) \\ D_\mathrm{QCoh}(\mathcal{O}_X) & \xrightarrow{Lf^*} D_\mathrm{QCoh}(\mathcal{O}_Y)\end{aligned}\end{gathered}$$ commutes.
Proof. We first prove the diagram $$\begin{gathered}\begin{matrix}D(B) & D(\mathcal{O}_Y) \\ D(A) & D(\mathcal{O}_X)\end{matrix} \\[6pt] \begin{aligned}D(B) & \longrightarrow D(\mathcal{O}_Y) \\ D(A) & \longrightarrow D(\mathcal{O}_X) \\ D(A) & \xrightarrow{- \otimes_A^\mathbf{L} B} D(B) \\ D(\mathcal{O}_X) & \xrightarrow{Lf^*} D(\mathcal{O}_Y)\end{aligned}\end{gathered}$$ commutes. This is clear from Lemma Derived tensor products, Tor amplitude and flatness and the constructions of the functors in question. To see (1) let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. To see that $Lf^*E$ has quasi-coherent cohomology sheaves we may work locally on $X$. Note that $Lf^*$ is compatible with restricting to open subschemes. Hence we can assume that $f$ is a morphism of affine schemes as in (2). Then we can apply Lemma Bounded comparison of affine derived categories to see that $E$ comes from a complex of $A$-modules. By the commutativity of the first diagram of the proof the same holds for $Lf^*E$ and we conclude (1) is true. $\square$
Lemma. Koszul complexes, regular sequences and derived categories
Source credit: the original source citation Bokstedt-Neeman (Proposition 6.1)
In Situation A complex and a finite principal-open cover denote $j : U \to X$ the open immersion and let $K$ be the perfect object of $D(\mathcal{O}_X)$ corresponding to the Koszul complex on $f_1, \ldots, f_r$ over $A$. For $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$ the following are equivalent
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$E = Rj_*(E|_U)$, and
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$\operatorname{Hom}_{D(\mathcal{O}_X)}(K[n], E) = 0$ for all $n \in \mathbf{Z}$.
Proof. Choose a distinguished triangle $E \to Rj_*(E|_U) \to N \to E[1]$. Observe that $$\operatorname{Hom}_{D(\mathcal{O}_X)}(K[n], Rj_*(E|_U)) = \operatorname{Hom}_{D(\mathcal{O}_U)}(K|_U[n], E) = 0$$ for all $n$ as $K|_U = 0$. Thus it suffices to prove the result for $N$. In other words, we may assume that $E$ restricts to zero on $U$. Observe that there are distinguished triangles $$K^\bullet(f_1^{e_1}, \ldots, f_i^{e'_i}, \ldots, f_r^{e_r}) \to K^\bullet(f_1^{e_1}, \ldots, f_i^{e'_i + e''_i}, \ldots, f_r^{e_r}) \to K^\bullet(f_1^{e_1}, \ldots, f_i^{e''_i}, \ldots, f_r^{e_r}) \to \ldots$$ of Koszul complexes, see More on Algebra, Lemma Koszul complexes and regular sequences. Hence if $\operatorname{Hom}_{D(\mathcal{O}_X)}(K[n], E) = 0$ for all $n \in \mathbf{Z}$ then the same thing is true for the $K$ replaced by $K_e$ as in Lemma Koszul representatives with closed support. Thus our lemma follows immediately from that one and the fact that $E$ is determined by the complex of $A$-modules $R\Gamma(X, E)$, see Lemma Bounded comparison of affine derived categories. $\square$
Lemma. Sheaf cohomology
Let $X$ be a quasi-compact and quasi-separated scheme. Let $K$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ such that the cohomology sheaves $H^i(K)$ have countable sets of sections over affine opens. Then for any quasi-compact open $U \subset X$ and any perfect object $E$ in $D(\mathcal{O}_X)$ the sets $$H^i(U, K \otimes^\mathbf{L} E),\quad \operatorname{Ext}^i(E|_U, K|_U)$$ are countable.
Proof. Using Cohomology, Lemma Perfect complexes and derived categories we see that it suffices to prove the result for the groups $H^i(U, K \otimes^\mathbf{L} E)$. We will use the induction principle to prove the lemma, see Cohomology of Schemes, Lemma Induction by elementary distinguished squares (uncovered prerequisite).
First we show that it holds when $U = \operatorname{Spec}(A)$ is affine. Namely, we can represent $K$ by a complex of $A$-modules $K^\bullet$ and $E$ by a finite complex of finite projective $A$-modules $P^\bullet$. See Lemmas Bounded comparison of affine derived categories and Perfect complexes on an affine scheme and our definition of perfect complexes of $A$-modules (More on Algebra, Definition Perfect complexes). Then $(E \otimes^\mathbf{L} K)|_U$ is represented by the total complex associated to the double complex $P^\bullet \otimes_A K^\bullet$ (Lemma Quasi-coherent complexes and coherent sheaves). Using induction on the length of the complex $P^\bullet$ (or using a suitable spectral sequence) we see that it suffices to show that $H^i(P^a \otimes_A K^\bullet)$ is countable for each $a$. Since $P^a$ is a direct summand of $A^{\oplus n}$ for some $n$ this follows from the assumption that the cohomology group $H^i(K^\bullet)$ is countable.
To finish the proof it suffices to show: if $U = V \cup W$ and the result holds for $V$, $W$, and $V \cap W$, then the result holds for $U$. This is an immediate consequence of the Mayer-Vietoris sequence, see Cohomology, Lemma Mayer–Vietoris for unbounded quasi-coherent complexes. $\square$
Lemma. Detecting pseudo-coherence on projective space
Let $A$ be a ring. Let $n \geq 0$. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_{\mathbf{P}^n_A})$. The following are equivalent
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$K$ is pseudo-coherent,
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$R\Gamma(\mathbf{P}^n_A, E \otimes^\mathbf{L} K)$ is a pseudo-coherent object of $D(A)$ for each pseudo-coherent object $E$ of $D(\mathcal{O}_{\mathbf{P}^n_A})$,
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$R\Gamma(\mathbf{P}^n_A, E \otimes^\mathbf{L} K)$ is a pseudo-coherent object of $D(A)$ for each perfect object $E$ of $D(\mathcal{O}_{\mathbf{P}^n_A})$,
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$R\operatorname{Hom}_{\mathbf{P}^n_A}(E, K)$ is a pseudo-coherent object of $D(A)$ for each perfect object $E$ of $D(\mathcal{O}_{\mathbf{P}^n_A})$,
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$R\Gamma(\mathbf{P}^n_A, K \otimes^\mathbf{L} \mathcal{O}_{\mathbf{P}^n_A}(d))$ is pseudo-coherent object of $D(A)$ for $d = 0, 1, \ldots, n$.
Proof. Recall that $$R\operatorname{Hom}_{\mathbf{P}^n_A}(E, K) = R\Gamma(\mathbf{P}^n_A, R\mathcal{H}om_{\mathcal{O}_{\mathbf{P}^n_A}}(E, K))$$ by definition, see Cohomology, Section Derived Hom and Ext. Thus parts (4) and (3) are equivalent by Cohomology, Lemma Perfect complexes and derived categories.
Since every perfect complex is pseudo-coherent, it is clear that (2) implies (3).
Assume (1) holds. Then $E \otimes^\mathbf{L} K$ is pseudo-coherent for every pseudo-coherent $E$, see Cohomology, Lemma Pseudo-coherent complexes and coherent sheaves. By Lemma Pseudo-coherent direct images for proper flat morphisms the direct image of such a pseudo-coherent complex is pseudo-coherent and we see that (2) is true.
Part (3) implies (5) because we can take $E = \mathcal{O}_{\mathbf{P}^n_A}(d)$ for $d = 0, 1, \ldots, n$.
To finish the proof we have to show that (5) implies (1). Let $P$ be as in (Derived tensor products and Tor amplitude) and $R$ as in (Perfect complexes). By Lemma The differential graded model for projective space we have an equivalence $$- \otimes^\mathbf{L}_R P : D(R) \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_{\mathbf{P}^n_A})$$ Let $M \in D(R)$ be an object such that $M \otimes^\mathbf{L} P = K$. By Differential Graded Algebra, Lemma Derived categories and tensor products and direct sums there is an isomorphism $$R\operatorname{Hom}(R, M) = R\operatorname{Hom}_{\mathbf{P}^n_A}(P, K)$$ in $D(A)$. Arguing as above we obtain $$R\operatorname{Hom}_{\mathbf{P}^n_A}(P, K) = R\Gamma(\mathbf{P}^n_A, R\mathcal{H}om_{\mathcal{O}_{\mathbf{P}^n_A}}(E, K)) = R\Gamma(\mathbf{P}^n_A, P^\vee \otimes^\mathbf{L}_{\mathcal{O}_{\mathbf{P}^n_A}} K).$$ Using that $P^\vee$ is the direct sum of $\mathcal{O}_{\mathbf{P}^n_A}(d)$ for $d = 0, 1, \ldots, n$ and (5) we conclude $R\operatorname{Hom}(R, M)$ is pseudo-coherent as a complex of $A$-modules. Of course $M = R\operatorname{Hom}(R, M)$ in $D(A)$. Thus $M$ is pseudo-coherent as a complex of $A$-modules. By Lemma Pseudo-coherent complexes and coherent sheaves we may represent $M$ by a bounded above complex $F^\bullet$ of finite free $R$-modules. Then $F^\bullet = \bigcup_{p \geq 0} \sigma_{\geq p}F^\bullet$ is a filtration which shows that $F^\bullet$ is a differential graded $R$-module with property (P), see Differential Graded Algebra, Section Differential graded modules. Hence $K = M \otimes^\mathbf{L}_R P$ is represented by $F^\bullet \otimes_R P$ (follows from the construction of the derived tensor functor, see for example the proof of Differential Graded Algebra, Lemma Derived categories and tensor products and direct sums). Since $F^\bullet \otimes_R P$ is a bounded above complex whose terms are direct sums of copies of $P$ we conclude that the lemma is true. $\square$
Lemma. Base change for perfect complexes
Let $g : S' \to S$ be a morphism of schemes. Let $f : X \to S$ be quasi-compact and quasi-separated. Consider the base change diagram $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ If $X$ and $S'$ are Tor independent over $S$, then for all $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$ the canonical arrow $Lg^*Rf_*E \to Rf'_*L(g')^*E$ is an isomorphism.
Proof. For any object $E$ of $D(\mathcal{O}_X)$ we can use Cohomology, Remark Base change for derived sheaf cohomology to get a canonical base change map $Lg^*Rf_*E \to Rf'_*L(g')^*E$. To check this is an isomorphism we may work locally on $S'$. Hence we may assume $g : S' \to S$ is a morphism of affine schemes. In particular, $g$ is affine and it suffices to show that $$Rg_*Lg^*Rf_*E \to Rg_*Rf'_*L(g')^*E = Rf_*(Rg'_* L(g')^* E)$$ is an isomorphism, see Lemma Affine neighbourhoods (and use Lemmas Quasi-coherent complexes and coherent sheaves, Quasi-coherent complexes and coherent sheaves, and Quasi-coherent complexes and coherent sheaves to see that the objects $Rf'_*L(g')^*E$ and $Lg^*Rf_*E$ have quasi-coherent cohomology sheaves). Note that $g'$ is affine as well (Morphisms, Lemma Base change for affine neighbourhoods (uncovered prerequisite)). By Lemma Affine neighbourhoods the map becomes a map $$Rf_*E \otimes_{\mathcal{O}_S}^\mathbf{L} g_*\mathcal{O}_{S'} \longrightarrow Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} g'_*\mathcal{O}_{X'})$$ Observe that $g'_*\mathcal{O}_{X'} = f^*g_*\mathcal{O}_{S'}$ (by affine base change, see Cohomology of Schemes, Lemma Base change for affine neighbourhoods (uncovered prerequisite)). Thus by Lemma Base change for sheaf cohomology it suffices to prove that $Lf^*g_*\mathcal{O}_{S'} = f^*g_*\mathcal{O}_{S'}$. This follows from our assumption that $X$ and $S'$ are Tor independent over $S$. Namely, to check it we may work locally on $X$, hence we may also assume $X$ is affine. Say $X = \operatorname{Spec}(A)$, $S = \operatorname{Spec}(R)$ and $S' = \operatorname{Spec}(R')$. Our assumption implies that $A$ and $R'$ are Tor independent over $R$ (More on Algebra, Lemma Derived tensor products and Tor amplitude), i.e., $\text{Tor}_i^R(A, R') = 0$ for $i > 0$. In other words $A \otimes_R^\mathbf{L} R' = A \otimes_R R'$ which exactly means that $Lf^*g_*\mathcal{O}_{S'} = f^*g_*\mathcal{O}_{S'}$ (use Lemma Quasi-coherent complexes and coherent sheaves). $\square$
Lemma. Perfect direct images for proper morphisms of finite presentation
Let $S$ be a scheme. Let $f : X \to S$ be a proper morphism of finite presentation.
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Let $E \in D(\mathcal{O}_X)$ be perfect and $f$ flat. Then $Rf_*E$ is a perfect object of $D(\mathcal{O}_S)$ and its formation commutes with arbitrary base change.
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Let $\mathcal{G}$ be an $\mathcal{O}_X$-module of finite presentation, flat over $S$. Then $Rf_*\mathcal{G}$ is a perfect object of $D(\mathcal{O}_S)$ and its formation commutes with arbitrary base change.
Proof. Special cases of Lemma Perfect proper-support direct images over arbitrary bases applied with (1) $\mathcal{G}^\bullet$ equal to $\mathcal{O}_X$ in degree $0$ and (2) $E = \mathcal{O}_X$ and $\mathcal{G}^\bullet$ consisting of $\mathcal{G}$ sitting in degree $0$. $\square$
Lemma. Vanishing and projective, locally free modules and local algebra
Let $f : X \to S$ be a morphism of finite presentation. Let $\mathcal{F}$ be an $\mathcal{O}_X$-module of finite presentation, flat over $S$ with support proper over $S$. If $R^if_*\mathcal{F} = 0$ for $i > 0$, then $f_*\mathcal{F}$ is locally free and its formation commutes with arbitrary base change (see proof for explanation).
Proof. By Lemma Perfect proper-support direct images over arbitrary bases the object $E = Rf_*\mathcal{F}$ of $D(\mathcal{O}_S)$ is perfect and its formation commutes with arbitrary base change, in the sense that $Rf'_*(g')^*\mathcal{F} = Lg^*E$ for any cartesian diagram $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ of schemes. Since there is never any cohomology in degrees $< 0$, we see that $E$ (locally) has tor-amplitude in $[0, b]$ for some $b$. If $H^i(E) = R^if_*\mathcal{F} = 0$ for $i > 0$, then $E$ has tor amplitude in $[0, 0]$. Whence $E = H^0(E)[0]$. We conclude $H^0(E) = f_*\mathcal{F}$ is finite locally free by More on Algebra, Lemma Perfect complexes (and the characterization of finite projective modules in Algebra, Lemma Characterizations of finite projective modules). Commutation with base change means that $g^*f_*\mathcal{F} = f'_*(g')^*\mathcal{F}$ for a diagram as above and it follows from the already established commutation of base change for $E$. $\square$
Lemma. Sheaf cohomology
Let $X$ be a scheme. Let $E \in D(\mathcal{O}_X)$ be perfect. Given $i, r \in \mathbf{Z}$, there exists an open subscheme $U \subset X$ characterized by the following
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$E|_U \cong H^i(E|_U)[-i]$ and $H^i(E|_U)$ is a locally free $\mathcal{O}_U$-module of rank $r$,
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a morphism $f : Y \to X$ factors through $U$ if and only if $Lf^*E$ is isomorphic to a locally free module of rank $r$ placed in degree $i$.
Proof. Let $\beta_j : X \to \{0, 1, 2, \ldots\}$ for $j \in \mathbf{Z}$ be the functions of Lemma Perfect complexes. Then the set $$W = \{x \in X \mid \beta_j(x) \leq 0\text{ for all }j \not = i\}$$ is open in $X$ and its formation commutes with pullback to any $Y$ over $X$. This follows from the lemma using that apriori in a neighbourhood of any point only a finite number of the $\beta_j$ are nonzero. Thus we may replace $X$ by $W$ and assume that $\beta_j(x) = 0$ for all $x \in X$ and all $j \not = i$. In this case $H^i(E)$ is a finite locally free module and $E \cong H^i(E)[-i]$, see for example More on Algebra, Lemma Lifting perfect complexes and derived Hom and Ext. Thus $X$ is the disjoint union of the open subschemes where the rank of $H^i(E)$ is fixed and we win. $\square$
Lemma. A K-injective representative compatible with quasi-coherence
Let $X$ be a scheme. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Then the map $E \to R\varprojlim \tau_{\geq -n}E$ of Derived Categories, Remark Derived categories is an isomorphism[^1].
Proof. Denote $\mathcal{H}^i = H^i(E)$ the $i$th cohomology sheaf of $E$. Let $\mathcal{B}$ be the set of affine open subsets of $X$. Then $H^p(U, \mathcal{H}^i) = 0$ for all $p > 0$, all $i \in \mathbf{Z}$, and all $U \in \mathcal{B}$, see Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). Thus the lemma follows from Cohomology, Lemma Dimension and codimension (uncovered prerequisite). $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $X$ be a scheme. If $E$ is an $m$-pseudo-coherent object of $D(\mathcal{O}_X)$, then $H^i(E)$ is a quasi-coherent $\mathcal{O}_X$-module for $i > m$ and $H^m(E)$ is a quotient of a quasi-coherent $\mathcal{O}_X$-module. If $E$ is pseudo-coherent, then $E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Proof. Locally on $X$ there exists a strictly perfect complex $\mathcal{E}^\bullet$ such that $H^i(E)$ is isomorphic to $H^i(\mathcal{E}^\bullet)$ for $i > m$ and $H^m(E)$ is a quotient of $H^m(\mathcal{E}^\bullet)$. The sheaves $\mathcal{E}^i$ are direct summands of finite free modules, hence quasi-coherent. The lemma follows. $\square$
Lemma. Lifting quasi-coherent complexes and coherent sheaves
Let $X$ be a scheme and let $j : U \to X$ be a quasi-compact open immersion. The functors $$D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_U) \quad\text{and}\quad D^+_\mathrm{QCoh}(\mathcal{O}_X) \to D^+_\mathrm{QCoh}(\mathcal{O}_U)$$ are essentially surjective. If $X$ is quasi-compact, then the functors $$D^-_\mathrm{QCoh}(\mathcal{O}_X) \to D^-_\mathrm{QCoh}(\mathcal{O}_U) \quad\text{and}\quad D^b_\mathrm{QCoh}(\mathcal{O}_X) \to D^b_\mathrm{QCoh}(\mathcal{O}_U)$$ are essentially surjective.
Proof. The argument preceding the lemma applies for the first case because $Rj_*$ maps $D_\mathrm{QCoh}(\mathcal{O}_U)$ into $D_\mathrm{QCoh}(\mathcal{O}_X)$ by Lemma Quasi-coherent complexes and coherent sheaves. It is clear that $Rj_*$ maps $D^+_\mathrm{QCoh}(\mathcal{O}_U)$ into $D^+_\mathrm{QCoh}(\mathcal{O}_X)$ which implies the statement on bounded below complexes. Finally, Lemma Quasi-coherent complexes and coherent sheaves guarantees that $Rj_*$ maps $D^-_\mathrm{QCoh}(\mathcal{O}_U)$ into $D^-_\mathrm{QCoh}(\mathcal{O}_X)$ if $X$ is quasi-compact. Combining these two we obtain the last statement. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $X$ be a scheme.
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For objects $K, L$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ the derived tensor product $K \otimes^\mathbf{L}_{\mathcal{O}_X} L$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
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If $X = \operatorname{Spec}(A)$ is affine then $$\widetilde{M^\bullet} \otimes_{\mathcal{O}_X}^\mathbf{L} \widetilde{K^\bullet}
\widetilde{M^\bullet \otimes_A^\mathbf{L} K^\bullet}$$ for any pair of complexes of $A$-modules $K^\bullet$, $M^\bullet$.
Proof. The equality of (2) follows immediately from Lemma Derived tensor products, Tor amplitude and flatness and the construction of the derived tensor product. To see (1) let $K, L$ be objects of $D_\mathrm{QCoh}(\mathcal{O}_X)$. To check that $K \otimes^\mathbf{L} L$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$ we may work locally on $X$, hence we may assume $X = \operatorname{Spec}(A)$ is affine. By Lemma Bounded comparison of affine derived categories we may represent $K$ and $L$ by complexes of $A$-modules. Then part (2) implies the result. $\square$
Lemma. Derived tensor products, Tor amplitude and dimension and codimension
Let $X = \operatorname{Spec}(A)$ be an affine scheme. Let $M^\bullet$ be a complex of $A$-modules and let $E$ be the corresponding object of $D(\mathcal{O}_X)$. Then
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$E$ has tor amplitude in $[a, b]$ if and only if $M^\bullet$ has tor amplitude in $[a, b]$.
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$E$ has finite tor dimension if and only if $M^\bullet$ has finite tor dimension.
Proof. Part (2) follows trivially from part (1). In the proof of (1) we will use the equivalence $D(A) = D_\mathrm{QCoh}(X)$ of Lemma Bounded comparison of affine derived categories without further mention. Assume $M^\bullet$ has tor amplitude in $[a, b]$. Then $K^\bullet$ is isomorphic in $D(A)$ to a complex $K^\bullet$ of flat $A$-modules with $K^i = 0$ for $i \not \in [a, b]$, see More on Algebra, Lemma Derived tensor products and Tor amplitude. Then $E$ is isomorphic to $\widetilde{K^\bullet}$. Since each $\widetilde{K^i}$ is a flat $\mathcal{O}_X$-module, we see that $E$ has tor amplitude in $[a, b]$ by Cohomology, Lemma Derived tensor products and Tor amplitude.
Assume that $E$ has tor amplitude in $[a, b]$. Then $E$ is bounded whence $M^\bullet$ is in $K^-(A)$. Thus we may replace $M^\bullet$ by a bounded above complex of $A$-modules. We may even choose a projective resolution and assume that $M^\bullet$ is a bounded above complex of free $A$-modules. Then for any $A$-module $N$ we have $$E \otimes_{\mathcal{O}_X}^\mathbf{L} \widetilde{N} \cong \widetilde{M^\bullet} \otimes_{\mathcal{O}_X}^\mathbf{L} \widetilde{N} \cong \widetilde{M^\bullet \otimes_A N}$$ in $D(\mathcal{O}_X)$. Thus the vanishing of cohomology sheaves of the left hand side implies $M^\bullet$ has tor amplitude in $[a, b]$. $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Let $X = \operatorname{Spec}(A)$ be an affine scheme. If $K^\bullet$ is a K-flat complex of $A$-modules, then $\widetilde{K^\bullet}$ is a K-flat complex of $\mathcal{O}_X$-modules.
Proof. By More on Algebra, Lemma Base change for derived tensor products, Tor amplitude and flatness we see that $K^\bullet \otimes_A A_\mathfrak p$ is a K-flat complex of $A_\mathfrak p$-modules for every $\mathfrak p \in \operatorname{Spec}(A)$. Hence we conclude from Cohomology, Lemma Derived tensor products, Tor amplitude and flatness (uncovered prerequisite) (and Schemes, Lemma Prime spectra and associated points (uncovered prerequisite)) that $\widetilde{K^\bullet}$ is K-flat. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $f : X \to S$ be a morphism of schemes. Assume that $f$ is quasi-separated and quasi-compact.
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The functor $Rf_*$ sends $D_\mathrm{QCoh}(\mathcal{O}_X)$ into $D_\mathrm{QCoh}(\mathcal{O}_S)$.
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If $S$ is quasi-compact, there exists an integer $N = N(X, S, f)$ such that for an object $E$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ with $H^m(E) = 0$ for $m > 0$ we have $H^m(Rf_*E) = 0$ for $m \geq N$.
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In fact, if $S$ is quasi-compact we can find $N = N(X, S, f)$ such that for every morphism of schemes $S' \to S$ the same conclusion holds for the functor $R(f')_*$ where $f' : X' \to S'$ is the base change of $f$.
Proof. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. To prove (1) we have to show that $Rf_*E$ has quasi-coherent cohomology sheaves. The question is local on $S$, hence we may assume $S$ is quasi-compact. Pick $N = N(X, S, f)$ as in Cohomology of Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite). Thus $R^pf_*\mathcal{F} = 0$ for all quasi-coherent $\mathcal{O}_X$-modules $\mathcal{F}$ and all $p \geq N$ and the same remains true after base change.
First, assume $E$ is bounded below. We will show (1) and (2) and (3) hold for such $E$ with our choice of $N$. In this case we can for example use the spectral sequence $$R^pf_*H^q(E) \Rightarrow R^{p + q}f_*E$$ (Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories), the quasi-coherence of $R^pf_*H^q(E)$, and the vanishing of $R^pf_*H^q(E)$ for $p \geq N$ to see that (1), (2), and (3) hold in this case.
Next we prove (2) and (3). Say $H^m(E) = 0$ for $m > 0$. Let $U \subset S$ be affine open. By Cohomology of Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite) and our choice of $N$ we have $H^p(f^{-1}(U), \mathcal{F}) = 0$ for $p \geq N$ and any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$. Hence we may apply Lemma Computing derived Hom with a quasi-coherent K-injective model to the functor $\Gamma(f^{-1}(U), -)$ to see that $$R\Gamma(U, Rf_*E) = R\Gamma(f^{-1}(U), E)$$ has vanishing cohomology in degrees $\geq N$. Since this holds for all $U \subset S$ affine open we conclude that $H^m(Rf_*E) = 0$ for $m \geq N$.
Next, we prove (1) in the general case. Recall that there is a distinguished triangle $$\tau_{\leq -n - 1}E \to E \to \tau_{\geq -n}E \to (\tau_{\leq -n - 1}E)[1]$$ in $D(\mathcal{O}_X)$, see Derived Categories, Remark Derived categories. By (2) we see that $Rf_*\tau_{\leq -n - 1}E$ has vanishing cohomology sheaves in degrees $\geq -n + N$. Thus, given an integer $q$ we see that $R^qf_*E$ is equal to $R^qf_*\tau_{\geq -n}E$ for some $n$ and the result above applies. $\square$
Lemma. Derived tensor products, Tor amplitude and affine neighbourhoods
Let $X = \operatorname{Spec}(A)$ be an affine scheme. Then
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$Q_X : \textit{Mod}(\mathcal{O}_X) \to \mathrm{QCoh}(\mathcal{O}_X)$ is the functor which sends $\mathcal{F}$ to the quasi-coherent $\mathcal{O}_X$-module associated to the $A$-module $\Gamma(X, \mathcal{F})$,
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$RQ_X : D(\mathcal{O}_X) \to D(\mathrm{QCoh}(\mathcal{O}_X))$ is the functor which sends $E$ to the complex of quasi-coherent $\mathcal{O}_X$-modules associated to the object $R\Gamma(X, E)$ of $D(A)$,
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restricted to $D_\mathrm{QCoh}(\mathcal{O}_X)$ the functor $RQ_X$ defines a quasi-inverse to (Comparison of derived quasi-coherent categories).
Proof. The functor $Q_X$ is the functor $$\mathcal{F} \mapsto \widetilde{\Gamma(X, \mathcal{F})}$$ by Schemes, Lemma Comparison for the geometric construction (uncovered prerequisite). This immediately implies (1) and (2). The third assertion follows from (the proof of) Lemma Bounded comparison of affine derived categories. $\square$
Proposition. Compact objects are perfect
Let $X$ be a quasi-compact and quasi-separated scheme. An object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ is compact if and only if it is perfect.
Proof. If $K$ is a perfect object of $D(\mathcal{O}_X)$ with dual $K^\vee$ (Cohomology, Lemma Perfect complexes and derived categories) we have $$\operatorname{Hom}_{D(\mathcal{O}_X)}(K, M) = H^0(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} M)$$ functorially in $M$. Since $K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} -$ commutes with direct sums and since $H^0(X, -)$ commutes with direct sums on $D_\mathrm{QCoh}(\mathcal{O}_X)$ by Lemma Quasi-coherent complexes and coherent sheaves we conclude that $K$ is compact in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Conversely, let $K$ be a compact object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. To show that $K$ is perfect, it suffices to show that $K|_U$ is perfect for every affine open $U \subset X$, see Cohomology, Lemma Perfect complexes (uncovered prerequisite). Observe that $j : U \to X$ is a quasi-compact and separated morphism. Hence $Rj_* : D_\mathrm{QCoh}(\mathcal{O}_U) \to D_\mathrm{QCoh}(\mathcal{O}_X)$ commutes with direct sums, see Lemma Quasi-coherent complexes and coherent sheaves. Thus the adjointness of restriction to $U$ and $Rj_*$ implies that $K|_U$ is a compact object of $D_\mathrm{QCoh}(\mathcal{O}_U)$. Hence we reduce to the case that $X$ is affine.
Assume $X = \operatorname{Spec}(A)$ is affine. By Lemma Bounded comparison of affine derived categories the problem is translated into the same problem for $D(A)$. For $D(A)$ the result is More on Algebra, Proposition Perfect complexes. $\square$
Lemma. Base change for derived categories
Let $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ be a cartesian diagram of schemes. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ and let $L(g')^*K \to K'$ be a map in $D_\mathrm{QCoh}(\mathcal{O}_{X'})$. The following are equivalent
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for any $x' \in X'$ and $i \in \mathbf{Z}$ the map (Perfect complexes) is an isomorphism,
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for $U \subset X$, $V' \subset S'$ affine open both mapping into the affine open $V \subset S$ with $U' = V' \times_V U$ the composition $$R\Gamma(U, K) \otimes_{\mathcal{O}_S(U)}^\mathbf{L} \mathcal{O}_{S'}(V') \to R\Gamma(U, K) \otimes_{\mathcal{O}_X(U)}^\mathbf{L} \mathcal{O}_{X'}(U') \to R\Gamma(U', K')$$ is an isomorphism in $D(\mathcal{O}_{S'}(V'))$, and
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there is a set $I$ of quadruples $U_i, V_i', V_i, U_i'$, $i \in I$ as in (2) with $X' = \bigcup U'_i$.
Proof. The second arrow in (2) comes from the equality $$R\Gamma(U, K) \otimes_{\mathcal{O}_X(U)}^\mathbf{L} \mathcal{O}_{X'}(U') = R\Gamma(U', L(g')^*K)$$ of Lemma Quasi-coherent complexes and coherent sheaves and the given arrow $L(g')^*K \to K'$. The first arrow of (2) is More on Algebra, Equation (Comparison for derived commutative algebra). It is clear that (2) implies (3). Observe that (1) is local on $X'$. Therefore it suffices to show that if $X$, $S$, $S'$, $X'$ are affine, then (1) is equivalent to the condition that $$R\Gamma(X, K) \otimes_{\mathcal{O}_S(S)}^\mathbf{L} \mathcal{O}_{S'}(S') \to R\Gamma(X, K) \otimes_{\mathcal{O}_X(X)}^\mathbf{L} \mathcal{O}_{X'}(X') \to R\Gamma(X', K')$$ is an isomorphism in $D(\mathcal{O}_{S'}(S'))$. Say $S = \operatorname{Spec}(R)$, $X = \operatorname{Spec}(A)$, $S' = \operatorname{Spec}(R')$, $X' = \operatorname{Spec}(A')$, $K$ corresponds to the complex $M^\bullet$ of $A$-modules, and $K'$ corresponds to the complex $N^\bullet$ of $A'$-modules. Note that $A' = A \otimes_R R'$. The condition above is that the composition $$M^\bullet \otimes_R^\mathbf{L} R' \to M^\bullet \otimes_A^\mathbf{L} A' \to N^\bullet$$ is an isomorphism in $D(R')$. Equivalently, it is that for all $i \in \mathbf{Z}$ the map $$H^i(M^\bullet \otimes_R^\mathbf{L} R') \to H^i(M^\bullet \otimes_A^\mathbf{L} A') \to H^i(N^\bullet)$$ is an isomorphism. Observe that this is a map of $A \otimes_R R'$-modules, i.e., of $A'$-modules. On the other hand, (1) is the requirement that for compatible primes $\mathfrak q' \subset A'$, $\mathfrak q \subset A$, $\mathfrak p' \subset R'$, $\mathfrak p \subset R$ the composition $$H^i(M^\bullet_\mathfrak q \otimes_{R_\mathfrak p}^\mathbf{L} R'_{\mathfrak p'}) \otimes_{(A_\mathfrak q \otimes_{R_\mathfrak p} R'_{\mathfrak p'})} A'_{\mathfrak q'} \to H^i(M^\bullet_{\mathfrak q} \otimes_{A_\mathfrak q}^\mathbf{L} A'_{\mathfrak q'}) \to H^i(N^\bullet_{\mathfrak q'})$$ is an isomorphism. Since $$H^i(M^\bullet_\mathfrak q \otimes_{R_\mathfrak p}^\mathbf{L} R'_{\mathfrak p'}) \otimes_{(A_\mathfrak q \otimes_{R_\mathfrak p} R'_{\mathfrak p'})} A'_{\mathfrak q'} = H^i(M^\bullet \otimes_R^\mathbf{L} R') \otimes_{A'} A'_{\mathfrak q'}$$ is the localization at $\mathfrak q'$, we see that these two conditions are equivalent by Algebra, Lemma Detecting a zero module by localization. $\square$
Lemma. Base change for derived categories
Let $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ be a cartesian diagram of schemes. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ and let $L(g')^*K \to K'$ be a map in $D_\mathrm{QCoh}(\mathcal{O}_{X'})$. If
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the equivalent conditions of Lemma Base change for derived categories hold, and
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$f$ is quasi-compact and quasi-separated,
then the composition $Lg^*Rf_*K \to Rf'_*L(g')^*K \to Rf'_*K'$ is an isomorphism.
Proof. We could prove this using the same method as in the proof of Lemma Base change for perfect complexes but instead we will prove it using the induction principle and relative Mayer-Vietoris.
To check the map is an isomorphism we may work locally on $S'$. Hence we may assume $g : S' \to S$ is a morphism of affine schemes. In particular $X$ is a quasi-compact and quasi-separated scheme. We will use the induction principle of Cohomology of Schemes, Lemma Induction by elementary distinguished squares (uncovered prerequisite) to prove that for any quasi-compact open $U \subset X$ the similarly constructed map $Lg^*R(U \to S)_*K|_U \to R(U' \to S')_*K'|_{U'}$ is an isomorphism. Here $U' = (g')^{-1}(U)$.
If $U \subset X$ is an affine open, then we find that the result is true by assumption, see Lemma Base change for derived categories part (2) and the translation into algebra afforded to us by Lemmas Bounded comparison of affine derived categories and Quasi-coherent complexes and coherent sheaves.
The induction step. Suppose that $X = U \cup V$ is an open covering with $U$, $V$, $U \cap V$ quasi-compact such that the result holds for $U$, $V$, and $U \cap V$. Denote $a = f|_U$, $b = f|_V$ and $c = f|_{U \cap V}$. Let $a' : U' \to S'$, $b' : V' \to S'$ and $c' : U' \cap V' \to S'$ be the base changes of $a$, $b$, and $c$. Using the distinguished triangles from relative Mayer-Vietoris (Cohomology, Lemma Relative Mayer–Vietoris for unbounded complexes (uncovered prerequisite)) we obtain a commutative diagram $$\begin{gathered}\begin{matrix}Lg^*Rf_*K & Rf'_* K' \\ Lg^*Ra_* K|_U \oplus Lg^*Rb_* K|_V & Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} \\ Lg^*Rc_* K|_{U \cap V} & Rc'_* K'|_{U' \cap V'} \\ Lg^*Rf_* K[1] & Rf'_* K'[1]\end{matrix} \\[6pt] \begin{aligned}Lg^*Rf_*K & \longrightarrow Rf'_* K' \\ Lg^*Rf_*K & \longrightarrow Lg^*Ra_* K|_U \oplus Lg^*Rb_* K|_V \\ Rf'_* K' & \longrightarrow Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} \\ Lg^*Ra_* K|_U \oplus Lg^*Rb_* K|_V & \longrightarrow Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} \\ Lg^*Ra_* K|_U \oplus Lg^*Rb_* K|_V & \longrightarrow Lg^*Rc_* K|_{U \cap V} \\ Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} & \longrightarrow Rc'_* K'|_{U' \cap V'} \\ Lg^*Rc_* K|_{U \cap V} & \longrightarrow Rc'_* K'|_{U' \cap V'} \\ Lg^*Rc_* K|_{U \cap V} & \longrightarrow Lg^*Rf_* K[1] \\ Rc'_* K'|_{U' \cap V'} & \longrightarrow Rf'_* K'[1] \\ Lg^*Rf_* K[1] & \longrightarrow Rf'_* K'[1]\end{aligned}\end{gathered}$$ Since the 2nd and 3rd horizontal arrows are isomorphisms so is the first (Derived Categories, Lemma Derived categories) and the proof of the lemma is finished. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $X$ be a Noetherian scheme. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. For $m \in \mathbf{Z}$ the following are equivalent
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$H^i(E)$ is coherent for $i \geq m$ and zero for $i \gg 0$, and
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$E$ is $m$-pseudo-coherent.
In particular, $E$ is pseudo-coherent if and only if $E$ is an object of $D^-_{\textit{Coh}}(\mathcal{O}_X)$.
Proof. As $X$ is quasi-compact we see that in both (1) and (2) the object $E$ is bounded above. Thus the question is local on $X$ and we may assume $X$ is affine. Say $X = \operatorname{Spec}(A)$ for some Noetherian ring $A$. In this case $E$ corresponds to a complex of $A$-modules $M^\bullet$ by Lemma Bounded comparison of affine derived categories. By Lemma Pseudo-coherent complexes on an affine scheme we see that $E$ is $m$-pseudo-coherent if and only if $M^\bullet$ is $m$-pseudo-coherent. On the other hand, $H^i(E)$ is coherent if and only if $H^i(M^\bullet)$ is a finite $A$-module (Properties, Lemma Modules and finite algebras). Thus the result follows from More on Algebra, Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Tor amplitude on a quasi-compact quasi-separated scheme
Let $X$ be a quasi-separated scheme. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Let $a \leq b$. The following are equivalent
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$E$ has tor amplitude in $[a, b]$, and
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for all $\mathcal{F}$ in $\mathrm{QCoh}(\mathcal{O}_X)$ we have $H^i(E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{F}) = 0$ for $i \not \in [a, b]$.
Proof. It is clear that (1) implies (2). Assume (2). Let $U \subset X$ be an affine open. As $X$ is quasi-separated the morphism $j : U \to X$ is quasi-compact and separated, hence $j_*$ transforms quasi-coherent modules into quasi-coherent modules (Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite)). Thus the functor $\mathrm{QCoh}(\mathcal{O}_X) \to \mathrm{QCoh}(\mathcal{O}_U)$ is essentially surjective. It follows that condition (2) implies the vanishing of $H^i(E|_U \otimes_{\mathcal{O}_U}^\mathbf{L} \mathcal{G})$ for $i \not \in [a, b]$ for all quasi-coherent $\mathcal{O}_U$-modules $\mathcal{G}$. Write $U = \operatorname{Spec}(A)$ and let $M^\bullet$ be the complex of $A$-modules corresponding to $E|_U$ by Lemma Bounded comparison of affine derived categories. We have just shown that $M^\bullet \otimes_A^\mathbf{L} N$ has vanishing cohomology groups outside the range $[a, b]$, in other words $M^\bullet$ has tor amplitude in $[a, b]$. By Lemma Derived tensor products, Tor amplitude and dimension and codimension we conclude that $E|_U$ has tor amplitude in $[a, b]$. This proves the lemma. $\square$
Lemma. Descent of perfect complexes
In Situation A filtered inverse system for descent the category of perfect objects of $D(\mathcal{O}_S)$ is the colimit of the categories of perfect objects of $D(\mathcal{O}_{S_i})$.
Proof. For every open $U_0 \subset S_0$ consider the condition $P$ that the functor $$\mathop{\operatorname{colim}}_{i \geq 0} D_{perf}(\mathcal{O}_{U_i}) \longrightarrow D_{perf}(\mathcal{O}_U)$$ is an equivalence where ${}_{perf}$ indicates the full subcategory of perfect objects and where $U = f_0^{-1}(U_0)$ and $U_i = f_{i0}^{-1}(U_0)$. We will prove $P$ holds for all quasi-compact opens $U_0$ by the induction principle of Cohomology of Schemes, Lemma Induction by elementary distinguished squares (uncovered prerequisite). First, we observe that we already know the functor is fully faithful by Lemma Descent of perfect complexes. Thus it suffices to prove essential surjectivity.
We first check condition (2) of the induction principle. Thus suppose that we have $S_0 = U_0 \cup V_0$ and that $P$ holds for $U_0$, $V_0$, and $U_0 \cap V_0$. Let $E$ be a perfect object of $D(\mathcal{O}_S)$. We can find $i \geq 0$ and $E_{U, i}$ perfect on $U_i$ and $E_{V, i}$ perfect on $V_i$ whose pullback to $U$ and $V$ are isomorphic to $E|_U$ and $E|_V$. Denote $$a : E_{U, i} \to (Rf_{i, *}E)|_{U_i} \quad\text{and}\quad b : E_{V, i} \to (Rf_{i, *}E)|_{V_i}$$ the maps adjoint to the isomorphisms $Lf_i^*E_{U, i} \to E|_U$ and $Lf_i^*E_{V, i} \to E|_V$. By fully faithfulness, after increasing $i$, we can find an isomorphism $c : E_{U, i}|_{U_i \cap V_i} \to E_{V, i}|_{U_i \cap V_i}$ which pulls back to the identifications $$Lf_i^*E_{U, i}|_{U \cap V} \to E|_{U \cap V} \to Lf_i^*E_{V, i}|_{U \cap V}.$$ Apply Cohomology, Lemma Derived gluing across an elementary distinguished square to get an object $E_i$ on $S_i$ and a map $d : E_i \to Rf_{i, *}E$ which restricts to the maps $a$ and $b$ over $U_i$ and $V_i$. Then it is clear that $E_i$ is perfect and that $d$ is adjoint to an isomorphism $Lf_i^*E_i \to E$.
Finally, we check condition (1) of the induction principle, in other words, we check the lemma holds when $S_0$ is affine. Say $S_0 = \operatorname{Spec}(A_0)$, $S_i = \operatorname{Spec}(A_i)$, and $S = \operatorname{Spec}(A)$. Using Lemmas Bounded comparison of affine derived categories and Perfect complexes on an affine scheme we see that we have to show that $$D_{perf}(A) = \mathop{\operatorname{colim}} D_{perf}(A_i)$$ This is clear from the fact that perfect complexes over rings are given by finite complexes of finite projective (hence finitely presented) modules. See More on Algebra, Lemma Filtered limits and perfect complexes and derived categories for details. $\square$
Definition. Tor-independent pairs
Let $S$ be a scheme. Let $X$, $Y$ be schemes over $S$. We say $X$ and $Y$ are Tor independent over $S$ if for every $x \in X$ and $y \in Y$ mapping to the same point $s \in S$ the rings $\mathcal{O}_{X, x}$ and $\mathcal{O}_{Y, y}$ are Tor independent over $\mathcal{O}_{S, s}$ (see More on Algebra, Definition Tor-independent pairs).
Lemma. Pseudo-coherent direct images for proper flat morphisms
Let $S$ be a scheme. Let $f : X \to S$ be a flat proper morphism of finite presentation. Let $E \in D(\mathcal{O}_X)$ be pseudo-coherent. Then $Rf_*E$ is a pseudo-coherent object of $D(\mathcal{O}_S)$ and its formation commutes with arbitrary base change.
More generally, if $f : X \to S$ is proper and $E$ on $X$ is pseudo-coherent relative to $S$ (More on Morphisms, Definition Pseudo-coherent complexes and coherent sheaves), then $Rf_*E$ is pseudo-coherent (but formation does not commute with base change in this generality). See the original source citation Kiehl.
Proof. Special case of Lemma Base change for pseudo-coherent complexes and coherent sheaves applied with $\mathcal{G}^\bullet$ equal to $\mathcal{O}_X$ in degree $0$. $\square$
Lemma. The differential graded model for projective space
Source credit: the original source citation Beilinson
Let $A$ be a ring. Let $X = \mathbf{P}^n_A = \text{Proj}(S)$ where $S = A[X_0, \ldots, X_n]$. With $P$ as in (Derived tensor products and Tor amplitude) and $R$ as in (Perfect complexes) the functor $$- \otimes_R^\mathbf{L} P : D(R) \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_X)$$ is an $A$-linear equivalence of triangulated categories sending $R$ to $P$.
In words: the derived category of quasi-coherent modules on projective space is equivalent to the derived category of modules over a (noncommutative) algebra. This property of projective space appears to be quite unusual among all projective schemes over $A$.
Proof. To prove that our functor is fully faithful it suffices to prove that $\operatorname{Ext}^i_X(P, P)$ is zero for $i \not = 0$ and equal to $R$ for $i = 0$, see Differential Graded Algebra, Lemma Differential graded modules. As in the proof of Lemma Ext from a perfect complex to bounded quasi-coherent cohomology we see that $$\operatorname{Ext}^i_X(P, P) = H^i(X, P^\wedge \otimes P) = \bigoplus\nolimits_{0 \leq a, b \leq n} H^i(X, \mathcal{O}_X(a - b))$$ By the computation of cohomology of projective space (Cohomology of Schemes, Lemma Sheaf cohomology and projective and locally free modules (uncovered prerequisite)) we find that these $\operatorname{Ext}$-groups are zero unless $i = 0$. For $i = 0$ we recover $R$ because this is how we defined $R$ in (Perfect complexes). By Differential Graded Algebra, Lemma Derived Hom, Ext and derived categories our functor has a right adjoint, namely $R\operatorname{Hom}(P, -) : D_\mathrm{QCoh}(\mathcal{O}_X) \to D(R)$. Since $P$ is a generator for $D_\mathrm{QCoh}(\mathcal{O}_X)$ by Lemma A perfect generator on the projective line we see that the kernel of $R\operatorname{Hom}(P, -)$ is zero. Hence our functor is an equivalence of triangulated categories by Derived Categories, Lemma Triangulated categories. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $A$ be a ring. Let $R$ be a (possibly noncommutative) $A$-algebra which is finite free as an $A$-module. Then any object $M$ of $D(R)$ which is pseudo-coherent in $D(A)$ can be represented by a bounded above complex of finite free (right) $R$-modules.
Proof. Choose a complex $M^\bullet$ of right $R$-modules representing $M$. Since $M$ is pseudo-coherent we have $H^i(M) = 0$ for large enough $i$. Let $m$ be the smallest index such that $H^m(M)$ is nonzero. Then $H^m(M)$ is a finite $A$-module by More on Algebra, Lemma Finiteness of cohomology groups. Thus we can choose a finite free $R$-module $F^m$ and a map $F^m \to M^m$ such that $F^m \to M^m \to M^{m + 1}$ is zero and such that $F^m \to H^m(M)$ is surjective. Picture: $$\begin{gathered}\begin{matrix}\phantom{X} & F^m & 0 & \ldots \\ M^{m - 1} & M^m & M^{m + 1} & \ldots\end{matrix} \\[6pt] \begin{aligned}F^m & \xrightarrow{\alpha} M^m \\ F^m & \longrightarrow 0 \\ 0 & \longrightarrow M^{m + 1} \\ 0 & \longrightarrow \ldots \\ M^{m - 1} & \longrightarrow M^m \\ M^m & \longrightarrow M^{m + 1} \\ M^{m + 1} & \longrightarrow \ldots\end{aligned}\end{gathered}$$ By descending induction on $n \leq m$ we are going to construct finite free $R$-modules $F^i$ for $i \geq n$, differentials $d^i : F^i \to F^{i + 1}$ for $i \geq n$, maps $\alpha : F^i \to K^i$ compatible with differentials, such that (1) $H^i(\alpha)$ is an isomorphism for $i > n$ and surjective for $i = n$, and (2) $F^i = 0$ for $i > m$. Picture $$\begin{gathered}\begin{matrix}\phantom{X} & F^n & F^{n + 1} & \ldots & F^i & 0 & \ldots \\ M^{n - 1} & M^n & M^{n + 1} & \ldots & M^i & M^{i + 1} & \ldots\end{matrix} \\[6pt] \begin{aligned}F^n & \longrightarrow F^{n + 1} \\ F^n & \xrightarrow{\alpha} M^n \\ F^{n + 1} & \xrightarrow{\alpha} M^{n + 1} \\ F^{n + 1} & \longrightarrow \ldots \\ \ldots & \longrightarrow F^i \\ F^i & \xrightarrow{\alpha} M^i \\ F^i & \longrightarrow 0 \\ 0 & \longrightarrow M^{i + 1} \\ 0 & \longrightarrow \ldots \\ M^{n - 1} & \longrightarrow M^n \\ M^n & \longrightarrow M^{n + 1} \\ M^{n + 1} & \longrightarrow \ldots \\ \ldots & \longrightarrow M^i \\ M^i & \longrightarrow M^{i + 1} \\ M^{i + 1} & \longrightarrow \ldots\end{aligned}\end{gathered}$$ The base case is $n = m$ which we've done above. Induction step. Let $C^\bullet$ be the cone on $\alpha$ (Derived Categories, Definition The cone of a complex morphism). The long exact sequence of cohomology shows that $H^i(C^\bullet) = 0$ for $i \geq n$. Observe that $F^\bullet$ is pseudo-coherent as a complex of $A$-modules because $R$ is finite free as an $A$-module. Hence by More on Algebra, Lemma Pseudo-coherent complexes and coherent sheaves we see that $C^\bullet$ is $(n - 1)$-pseudo-coherent as a complex of $A$-modules. By More on Algebra, Lemma Finiteness of cohomology groups we see that $H^{n - 1}(C^\bullet)$ is a finite $A$-module. Choose a finite free $R$-module $F^{n - 1}$ and a map $\beta : F^{n - 1} \to C^{n - 1}$ such that the composition $F^{n - 1} \to C^{n - 1} \to C^n$ is zero and such that $F^{n - 1}$ surjects onto $H^{n - 1}(C^\bullet)$. Since $C^{n - 1} = M^{n - 1} \oplus F^n$ we can write $\beta = (\alpha^{n - 1}, -d^{n - 1})$. The vanishing of the composition $F^{n - 1} \to C^{n - 1} \to C^n$ implies these maps fit into a morphism of complexes $$\begin{gathered}\begin{matrix}\phantom{X} & F^{n - 1} & F^n & F^{n + 1} & \ldots \\ \ldots & M^{n - 1} & M^n & M^{n + 1} & \ldots\end{matrix} \\[6pt] \begin{aligned}F^{n - 1} & \xrightarrow{\alpha^{n - 1}} M^{n - 1} \\ F^{n - 1} & \xrightarrow{d^{n - 1}} F^n \\ F^n & \longrightarrow F^{n + 1} \\ F^n & \xrightarrow{\alpha} M^n \\ F^{n + 1} & \xrightarrow{\alpha} M^{n + 1} \\ F^{n + 1} & \longrightarrow \ldots \\ \ldots & \longrightarrow M^{n - 1} \\ M^{n - 1} & \longrightarrow M^n \\ M^n & \longrightarrow M^{n + 1} \\ M^{n + 1} & \longrightarrow \ldots\end{aligned}\end{gathered}$$ Moreover, these maps define a morphism of distinguished triangles $$\begin{gathered}\begin{matrix}(F^n \to \ldots) & (F^{n - 1} \to \ldots) & F^{n - 1} & (F^n \to \ldots)[1] \\ (F^n \to \ldots) & M^\bullet & C^\bullet & (F^n \to \ldots)[1]\end{matrix} \\[6pt] \begin{aligned}(F^n \to \ldots) & \longrightarrow (F^{n - 1} \to \ldots) \\ (F^n \to \ldots) & \longrightarrow (F^n \to \ldots) \\ (F^{n - 1} \to \ldots) & \longrightarrow F^{n - 1} \\ (F^{n - 1} \to \ldots) & \longrightarrow M^\bullet \\ F^{n - 1} & \longrightarrow (F^n \to \ldots)[1] \\ F^{n - 1} & \xrightarrow{\beta} C^\bullet \\ (F^n \to \ldots)[1] & \longrightarrow (F^n \to \ldots)[1] \\ (F^n \to \ldots) & \longrightarrow M^\bullet \\ M^\bullet & \longrightarrow C^\bullet \\ C^\bullet & \longrightarrow (F^n \to \ldots)[1]\end{aligned}\end{gathered}$$ Hence our choice of $\beta$ implies that the map of complexes $(F^{n - 1} \to \ldots) \to M^\bullet$ induces an isomorphism on cohomology in degrees $\geq n$ and a surjection in degree $n - 1$. This finishes the proof of the lemma. $\square$
Lemma. Affine neighbourhoods
Let $f : X \to S$ be an affine morphism of schemes. Then $Rf_* : D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_S)$ reflects isomorphisms.
Proof. The statement means that a morphism $\alpha : E \to F$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ is an isomorphism if $Rf_*\alpha$ is an isomorphism. We may check this on cohomology sheaves. In particular, the question is local on $S$. Hence we may assume $S$ and therefore $X$ is affine. In this case the statement is clear from the description of the derived categories $D_\mathrm{QCoh}(\mathcal{O}_X)$ and $D_\mathrm{QCoh}(\mathcal{O}_S)$ given in Lemma Bounded comparison of affine derived categories. Some details omitted. $\square$
Lemma. Affine neighbourhoods
Let $f : X \to S$ be an affine morphism of schemes. For $E$ in $D_\mathrm{QCoh}(\mathcal{O}_S)$ we have $Rf_* Lf^* E = E \otimes^\mathbf{L}_{\mathcal{O}_S} f_*\mathcal{O}_X$.
Proof. Since $f$ is affine the map $f_*\mathcal{O}_X \to Rf_*\mathcal{O}_X$ is an isomorphism (Cohomology of Schemes, Lemma Affine neighbourhoods (uncovered prerequisite)). There is a canonical map $E \otimes^\mathbf{L} f_*\mathcal{O}_X = E \otimes^\mathbf{L} Rf_*\mathcal{O}_X \to Rf_* Lf^* E$ adjoint to the map $$Lf^*(E \otimes^\mathbf{L} Rf_*\mathcal{O}_X) = Lf^*E \otimes^\mathbf{L} Lf^*Rf_*\mathcal{O}_X \longrightarrow Lf^* E \otimes^\mathbf{L} \mathcal{O}_X = Lf^* E$$ coming from $1 : Lf^*E \to Lf^*E$ and the canonical map $Lf^*Rf_*\mathcal{O}_X \to \mathcal{O}_X$. To check the map so constructed is an isomorphism we may work locally on $S$. Hence we may assume $S$ and therefore $X$ is affine. In this case the statement is clear from the description of the derived categories $D_\mathrm{QCoh}(\mathcal{O}_X)$ and $D_\mathrm{QCoh}(\mathcal{O}_S)$ and the functor $Lf^*$ given in Lemmas Bounded comparison of affine derived categories and Quasi-coherent complexes and coherent sheaves. Some details omitted. $\square$
Lemma. Base change for sheaf cohomology
Let $f : X \to Y$ be a quasi-compact and quasi-separated morphism of schemes. For $E$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and $K$ in $D_\mathrm{QCoh}(\mathcal{O}_Y)$ the map $$Rf_*(E) \otimes_{\mathcal{O}_Y}^\mathbf{L} K \longrightarrow Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*K)$$ defined in Cohomology, Equation (Derived sheaf cohomology) is an isomorphism.
Proof. To check the map is an isomorphism we may work locally on $Y$. Hence we reduce to the case that $Y$ is affine.
Suppose that $K = \bigoplus K_i$ is a direct sum of some complexes $K_i \in D_\mathrm{QCoh}(\mathcal{O}_Y)$. If the statement holds for each $K_i$, then it holds for $K$. Namely, the functors $Lf^*$ and $\otimes^\mathbf{L}$ preserve direct sums by construction and $Rf_*$ commutes with direct sums (for complexes with quasi-coherent cohomology sheaves) by Lemma Quasi-coherent complexes and coherent sheaves. Moreover, suppose that $K \to L \to M \to K[1]$ is a distinguished triangle in $D_\mathrm{QCoh}(Y)$. Then if the statement of the lemma holds for two of $K, L, M$, then it holds for the third (as the functors involved are exact functors of triangulated categories).
Assume $Y$ affine, say $Y = \operatorname{Spec}(A)$. The functor $\widetilde{\ } : D(A) \to D_\mathrm{QCoh}(\mathcal{O}_Y)$ is an equivalence (Lemma Bounded comparison of affine derived categories). Let $T$ be the property for $K \in D(A)$ that the statement of the lemma holds for $\widetilde{K}$. The discussion above and More on Algebra, Remark Derived commutative algebra shows that it suffices to prove $T$ holds for $A[k]$. This finishes the proof, as the statement of the lemma is clear for shifts of the structure sheaf. $\square$
Lemma. Perfect proper-support direct images over arbitrary bases
Let $f : X \to S$ be a morphism of finite presentation. Let $E \in D(\mathcal{O}_X)$ be a perfect object. Let $\mathcal{G}^\bullet$ be a bounded complex of finitely presented $\mathcal{O}_X$-modules, flat over $S$, with support proper over $S$. Then $$K = Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{G}^\bullet)$$ is a perfect object of $D(\mathcal{O}_S)$ and its formation commutes with arbitrary base change.
Proof. The statement on base change is Lemma Canonical arbitrary base change for relatively flat tensors. Thus it suffices to show that $K$ is a perfect object. If $S$ is Noetherian, then this follows from Lemma Perfect complexes and tensor products and direct sums. We will reduce to this case by Noetherian approximation. We encourage the reader to skip the rest of this proof.
The question is local on $S$, hence we may assume $S$ is affine. Say $S = \operatorname{Spec}(R)$. We write $R = \mathop{\operatorname{colim}} R_i$ as a filtered colimit of Noetherian rings $R_i$. By Limits, Lemma Descent of finite presentation and finite algebras there exists an $i$ and a scheme $X_i$ of finite presentation over $R_i$ whose base change to $R$ is $X$. By Limits, Lemma Descent of finite presentation and modules we may assume after increasing $i$, that there exists a bounded complex of finitely presented $\mathcal{O}_{X_i}$-modules $\mathcal{G}_i^\bullet$ whose pullback to $X$ is $\mathcal{G}^\bullet$. After increasing $i$ we may assume $\mathcal{G}_i^n$ is flat over $R_i$, see Limits, Lemma Descent of finite presentation and flatness. After increasing $i$ we may assume the support of $\mathcal{G}_i^n$ is proper over $R_i$, see Limits, Lemma Proper morphisms and closed support (uncovered prerequisite) and Cohomology of Schemes, Lemma Proper morphisms and modules (uncovered prerequisite). Finally, by Lemma Descent of perfect complexes we may, after increasing $i$, assume there exists a perfect object $E_i$ of $D(\mathcal{O}_{X_i})$ whose pullback to $X$ is $E$. Applying Lemma Perfect complexes and tensor products and direct sums to $X_i \to \operatorname{Spec}(R_i)$, $E_i$, $\mathcal{G}_i^\bullet$ and using the base change property already shown we obtain the result. $\square$
Lemma. Perfect complexes
Let $X$ be a scheme. Let $E \in D(\mathcal{O}_X)$ be pseudo-coherent (for example perfect). For any $i \in \mathbf{Z}$ consider the function $$\beta_i : X \longrightarrow \{0, 1, 2, \ldots\},\quad x \longmapsto \dim_{\kappa(x)} H^i(E \otimes_{\mathcal{O}_X}^\mathbf{L} \kappa(x))$$ Then we have
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formation of $\beta_i$ commutes with arbitrary base change,
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the functions $\beta_i$ are upper semi-continuous, and
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the level sets of $\beta_i$ are locally constructible in $X$.
Proof. Consider a morphism of schemes $f : Y \to X$ and a point $y \in Y$. Let $x$ be the image of $y$ and consider the commutative diagram $$\begin{gathered}\begin{matrix}y & Y \\ x & X\end{matrix} \\[6pt] \begin{aligned}y & \xrightarrow{j} Y \\ y & \xrightarrow{g} x \\ Y & \xrightarrow{f} X \\ x & \xrightarrow{i} X\end{aligned}\end{gathered}$$ Then we see that $Lg^* \circ Li^* = Lj^* \circ Lf^*$. This implies that the function $\beta'_i$ associated to the pseudo-coherent complex $Lf^*E$ is the pullback of the function $\beta_i$, in a formula: $\beta'_i = \beta_i \circ f$. This is the meaning of (1).
Fix $i$ and let $x \in X$. It is enough to prove (2) and (3) holds in an open neighbourhood of $x$, hence we may assume $X$ affine. Then we can represent $E$ by a bounded above complex $\mathcal{F}^\bullet$ of finite free modules (Lemma Lifting pseudo-coherent complexes and coherent sheaves). Then $P = \sigma_{\geq i - 1}\mathcal{F}^\bullet$ is a perfect object and $P \to E$ induces an isomorphism $$H^i(P \otimes_{\mathcal{O}_X}^\mathbf{L} \kappa(x')) \to H^i(E \otimes_{\mathcal{O}_X}^\mathbf{L} \kappa(x'))$$ for all $x' \in X$. Thus we may assume $E$ is perfect. In this case by More on Algebra, Lemma Lifting perfect complexes and derived Hom and Ext there exists an affine open neighbourhood $U$ of $x$ and $a \leq b$ such that $E|_U$ is represented by a complex $$\ldots \to 0 \to \mathcal{O}_U^{\oplus \beta_a(x)} \to \mathcal{O}_U^{\oplus \beta_{a + 1}(x)} \to \ldots \to \mathcal{O}_U^{\oplus \beta_{b - 1}(x)} \to \mathcal{O}_U^{\oplus \beta_b(x)} \to 0 \to \ldots$$ (This also uses earlier results to turn the problem into algebra, for example Lemmas Bounded comparison of affine derived categories and Perfect complexes on an affine scheme.) It follows immediately that $\beta_i(x') \leq \beta_i(x)$ for all $x' \in U$. This proves that $\beta_i$ is upper semi-continuous.
To prove (3) we may assume that $X$ is affine and $E$ is given by a complex of finite free $\mathcal{O}_X$-modules (for example by arguing as in the previous paragraph, or by using Cohomology, Lemma Perfect complexes and local algebra (uncovered prerequisite)). Thus we have to show that given a complex $$\mathcal{O}_X^{\oplus a} \to \mathcal{O}_X^{\oplus b} \to \mathcal{O}_X^{\oplus c}$$ the function associated to a point $x \in X$ the dimension of the cohomology of $\kappa_x^{\oplus a} \to \kappa_x^{\oplus b} \to \kappa_x^{\oplus c}$ in the middle has constructible level sets. Let $A \in \text{Mat}(a \times b, \Gamma(X, \mathcal{O}_X))$ be the matrix of the first arrow. The rank of the image of $A$ in $\text{Mat}(a \times b, \kappa(x))$ is equal to $r$ if all $(r + 1) \times (r + 1)$-minors of $A$ vanish at $x$ and there is some $r \times r$-minor of $A$ which does not vanish at $x$. Thus the set of points where the rank is $r$ is a constructible locally closed set. Arguing similarly for the second arrow and putting everything together we obtain the desired result. $\square$
Lemma. Proper morphisms
Let $f : X \to S$ be a proper morphism of schemes. Let $s \in S$ and let $e \in H^0(X_s, \mathcal{O}_{X_s})$ be an idempotent. Then $e$ is in the image of the map $(f_*\mathcal{O}_X)_s \to H^0(X_s, \mathcal{O}_{X_s})$.
Proof. Let $X_s = T_1 \amalg T_2$ be the disjoint union decomposition with $T_1$ and $T_2$ nonempty and open and closed in $X_s$ corresponding to $e$, i.e., such that $e$ is identitically $1$ on $T_1$ and identically $0$ on $T_2$.
Assume $S$ is Noetherian. We will use the theorem on formal functions in the form of Cohomology of Schemes, Lemma Sheaves on ringed sites (uncovered prerequisite). It tells us that $$(f_*\mathcal{O}_X)_s^\wedge = \varprojlim_n H^0(X_n, \mathcal{O}_{X_n})$$ where $X_n$ is the $n$th infinitesimal neighbourhood of $X_s$. Since the underlying topological space of $X_n$ is equal to that of $X_s$ we obtain for all $n$ a disjoint union decomposition of schemes $X_n = T_{1, n} \amalg T_{2, n}$ where the underlying topological space of $T_{i, n}$ is $T_i$ for $i = 1, 2$. This means $H^0(X_n, \mathcal{O}_{X_n})$ contains a nontrivial idempotent $e_n$, namely the function which is identically $1$ on $T_{1, n}$ and identically $0$ on $T_{2, n}$. It is clear that $e_{n + 1}$ restricts to $e_n$ on $X_n$. Hence $e_\infty = \varprojlim e_n$ is a nontrivial idempotent of the limit. Thus $e_\infty$ is an element of the completion of $(f_*\mathcal{O}_X)_s$ mapping to $e$ in $H^0(X_s, \mathcal{O}_{X_s})$. Since the map $(f_*\mathcal{O}_X)_s^\wedge \to H^0(X_s, \mathcal{O}_{X_s})$ factors through $(f_*\mathcal{O}_X)^\wedge_s / \mathfrak m_s (f_*\mathcal{O}_X)_s^\wedge = (f_*\mathcal{O}_X)_s / \mathfrak m_s (f_*\mathcal{O}_X)_s$ (Algebra, Lemma Finite algebras (uncovered prerequisite)) we conclude that $e$ is in the image of the map $(f_*\mathcal{O}_X)_s \to H^0(X_s, \mathcal{O}_{X_s})$ as desired.
General case: we reduce the general case to the Noetherian case by limit arguments. We urge the reader to skip the proof. We may replace $S$ by an affine open neighbourhood of $s$. Thus we may and do assume that $S$ is affine. By Limits, Lemma Finite presentation and proper morphisms we can write $(f : X \to S) = \varprojlim (f_i : X_i \to S_i)$ with $f_i$ proper and $S_i$ Noetherian. Denote $s_i \in S_i$ the image of $s$. Then $s = \varprojlim s_i$, see Limits, Lemma Finite-presentation descent (uncovered prerequisite). Then $X_s = X \times_S s = \varprojlim X_i \times_{S_i} s_i = \varprojlim X_{i, s_i}$ because limits commute with limits (Categories, Lemma Filtered limits and the geometric construction (uncovered prerequisite)). Hence $e$ is the image of some idempotent $e_i \in H^0(X_{i, s_i}, \mathcal{O}_{X_{i, s_i}})$ by Limits, Lemma Descent of finite-presentation descent. By the Noetherian case there is an element $\tilde e_i$ in the stalk $(f_{i, *}\mathcal{O}_{X_i})_{s_i}$ mapping to $e_i$. Taking the pullback of $\tilde e_i$ we get an element $\tilde e$ of $(f_*\mathcal{O}_X)_s$ mapping to $e$ and the proof is complete. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $f : X \to S$ be a quasi-separated and quasi-compact morphism of schemes. Then $Rf_* : D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_S)$ commutes with direct sums.
Proof. Let $E_i$ be a family of objects of $D_\mathrm{QCoh}(\mathcal{O}_X)$ and set $E = \bigoplus E_i$. We want to show that the map $$\bigoplus Rf_*E_i \longrightarrow Rf_*E$$ is an isomorphism. We will show it induces an isomorphism on cohomology sheaves in degree $0$ which will imply the lemma. To prove this we may work locally on $S$, hence we may and do assume that $S$ is quasi-compact. Choose an integer $N$ as in Lemma Quasi-coherent complexes and coherent sheaves. Then $R^0f_*E = R^0f_*\tau_{\geq -N}E$ and $R^0f_*E_i = R^0f_*\tau_{\geq -N}E_i$ by the lemma cited. Observe that $\tau_{\geq -N}E = \bigoplus \tau_{\geq -N}E_i$. Thus we may assume all of the $E_i$ have vanishing cohomology sheaves in degrees $< -N$. Next we use the spectral sequences $$R^pf_*H^q(E) \Rightarrow R^{p + q}f_*E \quad\text{and}\quad R^pf_*H^q(E_i) \Rightarrow R^{p + q}f_*E_i$$ (Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories) to reduce to the case of a direct sum of quasi-coherent sheaves. This case is handled by Cohomology of Schemes, Lemma Filtered limits and sheaf cohomology (uncovered prerequisite). $\square$
Lemma. Quasi-coherent complexes and derived Hom and Ext
Let $X$ be a scheme.
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If $L$ is in $D^+_\mathrm{QCoh}(\mathcal{O}_X)$ and $K$ in $D(\mathcal{O}_X)$ is pseudo-coherent, then $R\mathcal{H}om(K, L)$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and locally bounded below.
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If $L$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and $K$ in $D(\mathcal{O}_X)$ is perfect, then $R\mathcal{H}om(K, L)$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
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If $X = \operatorname{Spec}(A)$ is affine and $K, L \in D(A)$ then $$R\mathcal{H}om(\widetilde{K}, \widetilde{L}) = \widetilde{R\operatorname{Hom}_A(K, L)}$$ in the following two cases
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$K$ is pseudo-coherent and $L$ is bounded below,
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$K$ is perfect and $L$ arbitrary.
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If $X = \operatorname{Spec}(A)$ and $K, L$ are in $D(A)$, then the $n$th cohomology sheaf of $R\mathcal{H}om(\widetilde{K}, \widetilde{L})$ is the sheaf associated to the presheaf $$X \supset D(f) \longmapsto \operatorname{Ext}^n_{A_f}(K \otimes_A A_f, L \otimes_A A_f)$$ for $f \in A$.
Proof. The construction of the internal hom in the derived category of $\mathcal{O}_X$ commutes with localization (see Cohomology, Section Derived Hom and Ext). Hence to prove (1) and (2) we may replace $X$ by an affine open. By Lemmas Bounded comparison of affine derived categories, Pseudo-coherent complexes on an affine scheme, and Perfect complexes on an affine scheme in order to prove (1) and (2) it suffices to prove (3).
Part (3) follows from the computation of the internal hom of Cohomology, Lemma Derived Hom, Ext and projective and locally free modules (uncovered prerequisite) by representing $K$ by a bounded above (resp. finite) complex of finite projective $A$-modules and $L$ by a bounded below (resp. arbitrary) complex of $A$-modules.
To prove (4) recall that on any ringed space the $n$th cohomology sheaf of $R\mathcal{H}om(A, B)$ is the sheaf associated to the presheaf $$U \mapsto \operatorname{Hom}_{D(U)}(A|_U, B|_U[n]) = \operatorname{Ext}^n_{D(\mathcal{O}_U)}(A|_U, B|_U)$$ See Cohomology, Section Derived Hom and Ext. On the other hand, the restriction of $\widetilde{K}$ to a principal open $D(f)$ is the image of $K \otimes_A A_f$ and similarly for $L$. Hence (4) follows from the equivalence of categories of Lemma Bounded comparison of affine derived categories. $\square$
Lemma. Descent of perfect complexes
In Situation A filtered inverse system for descent. Let $E_0$ and $K_0$ be objects of $D(\mathcal{O}_{S_0})$. Set $E_i = Lf_{i0}^*E_0$ and $K_i = Lf_{i0}^*K_0$ for $i \geq 0$ and set $E = Lf_0^*E_0$ and $K = Lf_0^*K_0$. Then the map $$\mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{D(\mathcal{O}_{S_i})}(E_i, K_i) \longrightarrow \operatorname{Hom}_{D(\mathcal{O}_S)}(E, K)$$ is an isomorphism if either
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$E_0$ is perfect and $K_0 \in D_\mathrm{QCoh}(\mathcal{O}_{S_0})$, or
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$E_0$ is pseudo-coherent and $K_0 \in D_\mathrm{QCoh}(\mathcal{O}_{S_0})$ has finite tor dimension.
Proof. For every open $U_0 \subset S_0$ consider the condition $P$ that the canonical map $$\mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{D(\mathcal{O}_{U_i})}(E_i|_{U_i}, K_i|_{U_i}) \longrightarrow \operatorname{Hom}_{D(\mathcal{O}_U)}(E|_U, K|_U)$$ is an isomorphism, where $U = f_0^{-1}(U_0)$ and $U_i = f_{i0}^{-1}(U_0)$. We will prove $P$ holds for all quasi-compact opens $U_0$ by the induction principle of Cohomology of Schemes, Lemma Induction by elementary distinguished squares (uncovered prerequisite). Condition (2) of this lemma follows immediately from Mayer-Vietoris for hom in the derived category, see Cohomology, Lemma Derived Hom and Ext. Thus it suffices to prove the lemma when $S_0$ is affine.
Assume $S_0$ is affine. Say $S_0 = \operatorname{Spec}(A_0)$, $S_i = \operatorname{Spec}(A_i)$, and $S = \operatorname{Spec}(A)$. We will use Lemma Bounded comparison of affine derived categories without further mention.
In case (1) the object $E_0^\bullet$ corresponds to a finite complex of finite projective $A_0$-modules, see Lemma Perfect complexes on an affine scheme. We may represent the object $K_0$ by a K-flat complex $K_0^\bullet$ of $A_0$-modules. In this situation we are trying to prove $$\mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{D(A_i)}(E_0^\bullet \otimes_{A_0} A_i, K_0^\bullet \otimes_{A_0} A_i) \longrightarrow \operatorname{Hom}_{D(A)}(E_0^\bullet \otimes_{A_0} A, K_0^\bullet \otimes_{A_0} A)$$ Because $E_0^\bullet$ is a bounded above complex of projective modules we can rewrite this as $$\mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{K(A_0)}(E_0^\bullet, K_0^\bullet \otimes_{A_0} A_i) \longrightarrow \operatorname{Hom}_{K(A_0)}(E_0^\bullet, K_0^\bullet \otimes_{A_0} A)$$ Since there are only a finite number of nonzero modules $E_0^n$ and since these are all finitely presented modules, this map is an isomorphism.
In case (2) the object $E_0$ corresponds to a bounded above complex $E_0^\bullet$ of finite free $A_0$-modules, see Lemma Pseudo-coherent complexes on an affine scheme. We may represent $K_0$ by a finite complex $K_0^\bullet$ of flat $A_0$-modules, see Lemma Derived tensor products, Tor amplitude and dimension and codimension and More on Algebra, Lemma Derived tensor products and Tor amplitude. In particular $K_0^\bullet$ is K-flat and we can argue as before to arrive at the map $$\mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{K(A_0)}(E_0^\bullet, K_0^\bullet \otimes_{A_0} A_i) \longrightarrow \operatorname{Hom}_{K(A_0)}(E_0^\bullet, K_0^\bullet \otimes_{A_0} A)$$ It is clear that this map is an isomorphism (only a finite number of terms are involved since $K_0^\bullet$ is bounded). $\square$
Situation. A filtered inverse system for descent
Let $S = \varprojlim_{i \in I} S_i$ be a limit of a directed system of schemes with affine transition morphisms $f_{i'i} : S_{i'} \to S_i$. We assume that $S_i$ is quasi-compact and quasi-separated for all $i \in I$. We denote $f_i : S \to S_i$ the projection. We also fix an element $0 \in I$.
Lemma. Base change for pseudo-coherent complexes and coherent sheaves
Let $f : X \to S$ be a morphism of finite presentation. Let $E \in D(\mathcal{O}_X)$ be a pseudo-coherent object. Let $\mathcal{G}^\bullet$ be a bounded above complex of finitely presented $\mathcal{O}_X$-modules, flat over $S$, with support proper over $S$. Then $$K = Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{G}^\bullet)$$ is a pseudo-coherent object of $D(\mathcal{O}_S)$ and its formation commutes with arbitrary base change.
Proof. The statement on base change is Lemma Canonical arbitrary base change for relatively flat tensors. Thus it suffices to show that $K$ is a pseudo-coherent object. This will follow from Lemma Perfect proper-support direct images over arbitrary bases by approximation by perfect complexes. We encourage the reader to skip the rest of the proof.
The question is local on $S$, hence we may assume $S$ is affine. Then $X$ is quasi-compact and quasi-separated. Moreover, there exists an integer $N$ such that total direct image $Rf_* : D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_S)$ has cohomological dimension $N$ as explained in Lemma Quasi-coherent complexes and coherent sheaves. Choose an integer $b$ such that $\mathcal{G}^i = 0$ for $i > b$. It suffices to show that $K$ is $m$-pseudo-coherent for every $m$. Choose an approximation $P \to E$ by a perfect complex $P$ of $(X, E, m - N - 1 - b)$. This is possible by Theorem Perfect approximation with prescribed closed support. Choose a distinguished triangle $$P \to E \to C \to P[1]$$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$. The cohomology sheaves of $C$ are zero in degrees $\geq m - N - 1 - b$. Hence the cohomology sheaves of $C \otimes^\mathbf{L} \mathcal{G}^\bullet$ are zero in degrees $\geq m - N - 1$. Thus the cohomology sheaves of $Rf_*(C \otimes^\mathbf{L} \mathcal{G}^\bullet)$ are zero in degrees $\geq m - 1$. Hence $$Rf_*(P \otimes^\mathbf{L} \mathcal{G}^\bullet) \to Rf_*(E \otimes^\mathbf{L} \mathcal{G}^\bullet)$$ is an isomorphism on cohomology sheaves in degrees $\geq m$. Next, suppose that $H^i(P) = 0$ for $i > a$. Then $P \otimes^\mathbf{L} \sigma_{\geq m - N - 1 - a}\mathcal{G}^\bullet \longrightarrow P \otimes^\mathbf{L} \mathcal{G}^\bullet$ is an isomorphism on cohomology sheaves in degrees $\geq m - N - 1$. Thus again we find that $$Rf_*(P \otimes^\mathbf{L} \sigma_{\geq m - N - 1 - a}\mathcal{G}^\bullet) \to Rf_*(P \otimes^\mathbf{L} \mathcal{G}^\bullet)$$ is an isomorphism on cohomology sheaves in degrees $\geq m$. By Lemma Perfect proper-support direct images over arbitrary bases the source is a perfect complex. We conclude that $K$ is $m$-pseudo-coherent as desired. $\square$
Lemma. A perfect generator on the projective line
Let $A$ be a ring. Let $X = \mathbf{P}^n_A$. Then $$E = \mathcal{O}_X \oplus \mathcal{O}_X(-1) \oplus \ldots \oplus \mathcal{O}_X(-n)$$ is a generator (Derived Categories, Definition Triangulated categories) of $D_\mathrm{QCoh}(X)$.
Proof. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$. Assume $\operatorname{Hom}(E, K[p]) = 0$ for all $p \in \mathbf{Z}$. We have to show that $K = 0$. By Derived Categories, Lemma Triangulated categories (uncovered prerequisite) we see that $\operatorname{Hom}(E', K[p])$ is zero for all $E' \in \langle E \rangle$ and $p \in \mathbf{Z}$. By Lemma The next perfect approximation in a sequential construction applied with $a = -n - 1$ we see that $\mathcal{O}_X(-n - 1) \in \langle E \rangle$ because it is quasi-isomorphic to a finite complex whose terms are finite direct sums of summands of $E$. Repeating the argument with $a = -n - 2$ we see that $\mathcal{O}_X(-n - 2) \in \langle E \rangle$. Arguing by induction we find that $\mathcal{O}_X(-m) \in \langle E \rangle$ for all $m \geq 0$. Since $$\operatorname{Hom}(\mathcal{O}_X(-m), K[p]) = H^p(X, K \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{O}_X(m)) = H^p(X, K \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{O}_X(1)^{\otimes m})$$ we conclude that $K = 0$ by Lemma Detecting a nonzero object by cohomology. (This also uses that $\mathcal{O}_X(1)$ is an ample invertible sheaf on $X$ which follows from Properties, Lemma Line bundles and ampleness.) $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $i : Z \to X$ be a morphism of ringed spaces such that $i$ is a closed immersion of underlying topological spaces and such that $i_*\mathcal{O}_Z$ is pseudo-coherent as an $\mathcal{O}_X$-module. Let $E \in D(\mathcal{O}_Z)$. Then $E$ is $m$-pseudo-coherent if and only if $Ri_*E$ is $m$-pseudo-coherent.
Proof. Throughout this proof we will use that $i_*$ is an exact functor, and hence that $Ri_* = i_*$, see Modules, Lemma The geometric construction (uncovered prerequisite).
Assume $E$ is $m$-pseudo-coherent. Let $x \in X$. We will find a neighbourhood of $x$ such that $i_*E$ is $m$-pseudo-coherent on it. If $x \not \in Z$ then this is clear. Thus we may assume $x \in Z$. We will use that $U \cap Z$ for $x \in U \subset X$ open form a fundamental system of neighbourhoods of $x$ in $Z$. After shrinking $X$ we may assume $E$ is bounded above. We will argue by induction on the largest integer $p$ such that $H^p(E)$ is nonzero. If $p < m$, then there is nothing to prove. If $p \geq m$, then $H^p(E)$ is an $\mathcal{O}_Z$-module of finite type, see Cohomology, Lemma Finiteness of cohomology groups. Thus we may choose, after shrinking $X$, a map $\mathcal{O}_Z^{\oplus n}[-p] \to E$ which induces a surjection $\mathcal{O}_Z^{\oplus n} \to H^p(E)$. Choose a distinguished triangle $$\mathcal{O}_Z^{\oplus n}[-p] \to E \to C \to \mathcal{O}_Z^{\oplus n}[-p + 1]$$ We see that $H^j(C) = 0$ for $j \geq p$ and that $C$ is $m$-pseudo-coherent by Cohomology, Lemma Pseudo-coherent complexes and coherent sheaves. By induction we see that $i_*C$ is $m$-pseudo-coherent on $X$. Since $i_*\mathcal{O}_Z$ is $m$-pseudo-coherent on $X$ as well, we conclude from the distinguished triangle $$i_*\mathcal{O}_Z^{\oplus n}[-p] \to i_*E \to i_*C \to i_*\mathcal{O}_Z^{\oplus n}[-p + 1]$$ and Cohomology, Lemma Pseudo-coherent complexes and coherent sheaves that $i_*E$ is $m$-pseudo-coherent.
Assume that $i_*E$ is $m$-pseudo-coherent. Let $z \in Z$. We will find a neighbourhood of $z$ such that $E$ is $m$-pseudo-coherent on it. We will use that $U \cap Z$ for $z \in U \subset X$ open form a fundamental system of neighbourhoods of $z$ in $Z$. After shrinking $X$ we may assume $i_*E$ and hence $E$ is bounded above. We will argue by induction on the largest integer $p$ such that $H^p(E)$ is nonzero. If $p < m$, then there is nothing to prove. If $p \geq m$, then $H^p(i_*E) = i_*H^p(E)$ is an $\mathcal{O}_X$-module of finite type, see Cohomology, Lemma Finiteness of cohomology groups. Choose a complex $\mathcal{E}^\bullet$ of $\mathcal{O}_Z$-modules representing $E$. We may choose, after shrinking $X$, a map $\alpha : \mathcal{O}_X^{\oplus n}[-p] \to i_*\mathcal{E}^\bullet$ which induces a surjection $\mathcal{O}_X^{\oplus n} \to i_*H^p(\mathcal{E}^\bullet)$. By adjunction we find a map $\alpha : \mathcal{O}_Z^{\oplus n}[-p] \to \mathcal{E}^\bullet$ which induces a surjection $\mathcal{O}_Z^{\oplus n} \to H^p(\mathcal{E}^\bullet)$. Choose a distinguished triangle $$\mathcal{O}_Z^{\oplus n}[-p] \to E \to C \to \mathcal{O}_Z^{\oplus n}[-p + 1]$$ We see that $H^j(C) = 0$ for $j \geq p$. From the distinguished triangle $$i_*\mathcal{O}_Z^{\oplus n}[-p] \to i_*E \to i_*C \to i_*\mathcal{O}_Z^{\oplus n}[-p + 1]$$ the fact that $i_*\mathcal{O}_Z$ is pseudo-coherent and Cohomology, Lemma Pseudo-coherent complexes and coherent sheaves we conclude that $i_*C$ is $m$-pseudo-coherent. By induction we conclude that $C$ is $m$-pseudo-coherent. By Cohomology, Lemma Pseudo-coherent complexes and coherent sheaves again we conclude that $E$ is $m$-pseudo-coherent. $\square$
Lemma. Canonical arbitrary base change for relatively flat tensors
Let $f : X \to S$ be a quasi-compact and quasi-separated morphism of schemes. Let $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$. Let $\mathcal{G}^\bullet$ be a bounded above complex of quasi-coherent $\mathcal{O}_X$-modules flat over $S$. Then formation of $$Rf_*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet)$$ commutes with arbitrary base change (see proof for precise statement).
Proof. The statement means the following. Let $g : S' \to S$ be a morphism of schemes and consider the base change diagram $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ in other words $X' = S' \times_S X$. The lemma asserts that $$Lg^*Rf_*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet) \longrightarrow Rf'_*\left( L(g')^*E \otimes^\mathbf{L}_{\mathcal{O}_{X'}} (g')^*\mathcal{G}^\bullet \right)$$ is an isomorphism. Observe that on the right hand side we do not use the derived pullback on $\mathcal{G}^\bullet$. To prove this, we apply Lemmas Base change for derived categories and Inheritance of a cohomological base-change condition to see that it suffices to prove the canonical map $$L(g')^*\mathcal{G}^\bullet \to (g')^*\mathcal{G}^\bullet$$ satisfies the equivalent conditions of Lemma Base change for derived categories. This follows by checking the condition on stalks, where it immediately follows from the fact that $\mathcal{G}^\bullet_x \otimes_{\mathcal{O}_{S, s}} \mathcal{O}_{S', s'}$ computes the derived tensor product by our assumptions on the complex $\mathcal{G}^\bullet$. $\square$
Lemma. Perfect complexes and tensor products and direct sums
Let $S$ be a Noetherian scheme. Let $f : X \to S$ be a morphism of schemes which is locally of finite type. Let $E \in D(\mathcal{O}_X)$ be perfect. Let $\mathcal{G}^\bullet$ be a bounded complex of coherent $\mathcal{O}_X$-modules flat over $S$ with support proper over $S$. Then $K = Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{G}^\bullet)$ is a perfect object of $D(\mathcal{O}_S)$.
Proof. The object $K$ is perfect by Lemma Perfectness of a proper direct image. We check the lemma applies: Locally $E$ is isomorphic to a finite complex of finite free $\mathcal{O}_X$-modules. Hence locally $E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G}^\bullet$ is isomorphic to a finite complex whose terms are of the form $$\bigoplus\nolimits_{i = a, \ldots, b} (\mathcal{G}^i)^{\oplus r_i}$$ for some integers $a, b, r_a, \ldots, r_b$. This immediately implies the cohomology sheaves $H^i(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{G})$ are coherent. The hypothesis on the tor dimension also follows as $\mathcal{G}^i$ is flat over $f^{-1}\mathcal{O}_S$. $\square$
Lemma. Derived Hom, Ext and coherent sheaves
Let $X$ be a locally Noetherian scheme. If $L$ is in $D^+_{\textit{Coh}}(\mathcal{O}_X)$ and $K$ in $D^-_{\textit{Coh}}(\mathcal{O}_X)$, then $R\mathcal{H}om(K, L)$ is in $D^+_{\textit{Coh}}(\mathcal{O}_X)$.
Proof. It suffices to prove this when $X$ is the spectrum of a Noetherian ring $A$. By Lemma Pseudo-coherent complexes and coherent sheaves we see that $K$ is pseudo-coherent. Then we can use Lemma Quasi-coherent complexes and derived Hom and Ext to translate the problem into the following algebra problem: for $L \in D^+_{\textit{Coh}}(A)$ and $K$ in $D^-_{\textit{Coh}}(A)$, then $R\operatorname{Hom}_A(K, L)$ is in $D^+_{\textit{Coh}}(A)$. Since $L$ is bounded below and $K$ is bounded above there is a convergent spectral sequence $$\operatorname{Ext}^p_A(K, H^q(L)) \Rightarrow \text{Ext}^{p + q}_A(K, L)$$ and there are convergent spectral sequences $$\operatorname{Ext}^i_A(H^{-j}(K), H^q(L)) \Rightarrow \text{Ext}^{i + j}_A(K, H^q(L))$$ See Injectives, Remarks Derived Hom and Ext and Derived Hom and Ext. This finishes the proof as the modules $\operatorname{Ext}^p_A(M, N)$ are finite for finite $A$-modules $M$, $N$ by Algebra, Lemma Derived Hom, Ext and Noetherian rings (uncovered prerequisite). $\square$
Theorem. Perfect approximation with prescribed closed support
Let $X$ be a quasi-compact and quasi-separated scheme. Then approximation by perfect complexes holds on $X$.
Proof. This follows from the induction principle of Cohomology of Schemes, Lemma Induction by elementary distinguished squares (uncovered prerequisite) and Lemmas Extending perfect approximation across a distinguished square and Perfect approximation on an affine chart. $\square$
Lemma. The next perfect approximation in a sequential construction
Let $A$ be a ring. Let $X = \mathbf{P}^n_A$. For every $a \in \mathbf{Z}$ there exists an exact complex $$0 \to \mathcal{O}_X(a) \to \ldots \to \mathcal{O}_X(a + i)^{\oplus {n + 1 \choose i}} \to \ldots \to \mathcal{O}_X(a + n + 1) \to 0$$ of vector bundles on $X$.
Proof. Recall that $\mathbf{P}^n_A$ is $\text{Proj}(A[X_0, \ldots, X_n])$, see Constructions, Definition Projective and locally free modules. Consider the Koszul complex $$K_\bullet = K_\bullet(A[X_0, \ldots, X_n], X_0, \ldots, X_n)$$ over $S = A[X_0, \ldots, X_n]$ on $X_0, \ldots, X_n$. Since $X_0, \ldots, X_n$ is clearly a regular sequence in the polynomial ring $S$, we see that (More on Algebra, Lemma Regular sequences are Koszul-regular) that the Koszul complex $K_\bullet$ is exact, except in degree $0$ where the cohomology is $S/(X_0, \ldots, X_n)$. Note that $K_\bullet$ becomes a complex of graded modules if we put the generators of $K_i$ in degree $+i$. In other words an exact complex $$0 \to S(-n - 1) \to \ldots \to S(-n - 1 + i)^{\oplus {n \choose i}} \to \ldots \to S \to S/(X_0, \ldots, X_n) \to 0$$ Applying the exact functor $\tilde{\ }$ functor of Constructions, Lemma The geometric construction (uncovered prerequisite) and using that the last term is in the kernel of this functor, we obtain the exact complex $$0 \to \mathcal{O}_X(-n - 1) \to \ldots \to \mathcal{O}_X(-n - 1 + i)^{\oplus {n + 1 \choose i}} \to \ldots \to \mathcal{O}_X \to 0$$ Twisting by the invertible sheaves $\mathcal{O}_X(n + a + 1)$ we get the exact complexes of the lemma. $\square$
Lemma. Detecting a nonzero object by cohomology
Let $X$ be a scheme and $\mathcal{L}$ an ample invertible $\mathcal{O}_X$-module. If $K$ is a nonzero object of $D_\mathrm{QCoh}(\mathcal{O}_X)$, then for some $n \geq 0$ and $p \in \mathbf{Z}$ the cohomology group $H^p(X, K \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{L}^{\otimes n})$ is nonzero.
Proof. Recall that as $X$ has an ample invertible sheaf, it is quasi-compact and separated (Properties, Definition Ample invertible sheaves and Lemma Diagonals, separation and affine neighbourhoods (uncovered prerequisite)). Thus we may apply Proposition Perfect generators for schemes with affine diagonal and represent $K$ by a complex $\mathcal{F}^\bullet$ of quasi-coherent modules. Pick any $p$ such that $\mathcal{H}^p = \operatorname{Ker}(\mathcal{F}^p \to \mathcal{F}^{p + 1})/ \operatorname{Im}(\mathcal{F}^{p - 1} \to \mathcal{F}^p)$ is nonzero. Choose a point $x \in X$ such that the stalk $\mathcal{H}^p_x$ is nonzero. Choose an $n \geq 0$ and $s \in \Gamma(X, \mathcal{L}^{\otimes n})$ such that $X_s$ is an affine open neighbourhood of $x$. Choose $\tau \in \mathcal{H}^p(X_s)$ which maps to a nonzero element of the stalk $\mathcal{H}^p_x$; this is possible as $\mathcal{H}^p$ is quasi-coherent and $X_s$ is affine. Since taking sections over $X_s$ is an exact functor on quasi-coherent modules, we can find a section $\tau' \in \mathcal{F}^p(X_s)$ mapping to zero in $\mathcal{F}^{p + 1}(X_s)$ and mapping to $\tau$ in $\mathcal{H}^p(X_s)$. By Properties, Lemma Scheme geometry there exists an $m$ such that $\tau' \otimes s^{\otimes m}$ is the image of a section $\tau'' \in \Gamma(X, \mathcal{F}^p \otimes \mathcal{L}^{\otimes mn})$. Applying the same lemma once more, we find $l \geq 0$ such that $\tau'' \otimes s^{\otimes l}$ maps to zero in $\mathcal{F}^{p + 1} \otimes \mathcal{L}^{\otimes (m + l)n}$. Then $\tau''$ gives a nonzero class in $H^p(X, K \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{L}^{(m + l)n})$ as desired. $\square$
Lemma. Inheritance of a cohomological base-change condition
Let $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ be a cartesian diagram of schemes. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ and let $L(g')^*K \to K'$ be a map in $D_\mathrm{QCoh}(\mathcal{O}_{X'})$. If the equivalent conditions of Lemma Base change for derived categories hold, then
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for $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$ the equivalent conditions of Lemma Base change for derived categories hold for $L(g')^*(E \otimes^\mathbf{L} K) \to L(g')^*E \otimes^\mathbf{L} K'$,
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if $E$ in $D(\mathcal{O}_X)$ is perfect the equivalent conditions of Lemma Base change for derived categories hold for $L(g')^*R\mathcal{H}om(E, K) \to R\mathcal{H}om(L(g')^*E, K')$, and
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if $K$ is bounded below and $E$ in $D(\mathcal{O}_X)$ pseudo-coherent the equivalent conditions of Lemma Base change for derived categories hold for $L(g')^*R\mathcal{H}om(E, K) \to R\mathcal{H}om(L(g')^*E, K')$.
Proof. The statement makes sense as the complexes involved have quasi-coherent cohomology sheaves by Lemmas Quasi-coherent complexes and coherent sheaves, Quasi-coherent complexes and coherent sheaves, and Quasi-coherent complexes and derived Hom and Ext and Cohomology, Lemmas Pseudo-coherent complexes and coherent sheaves (uncovered prerequisite) and Perfect complexes (uncovered prerequisite). Having said this, we can check the maps (Perfect complexes) are isomorphisms in case (1) by computing the source and target of (Perfect complexes) using the transitive property of tensor product, see More on Algebra, Lemma Tensor products and direct sums. The map in (2) and (3) is the composition $$L(g')^*R\mathcal{H}om(E, K) \to R\mathcal{H}om(L(g')^*E, L(g')^*K) \to R\mathcal{H}om(L(g')^*E, K')$$ where the first arrow is Cohomology, Remark The comparison maps for derived base change and the second arrow comes from the given map $L(g')^*K \to K'$. To prove the maps (Perfect complexes) are isomorphisms one represents $E_x$ by a bounded complex of finite projective $\mathcal{O}_{X. x}$-modules in case (2) or by a bounded above complex of finite free modules in case (3) and computes the source and target of the arrow. Some details omitted. $\square$
Lemma. Perfectness of a proper direct image
Let $S$ be a Noetherian scheme. Let $f : X \to S$ be a morphism of schemes which is locally of finite type. Let $E \in D(\mathcal{O}_X)$ such that
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$E \in D^b_{\textit{Coh}}(\mathcal{O}_X)$,
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the support of $H^i(E)$ is proper over $S$ for all $i$, and
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$E$ has finite tor dimension as an object of $D(f^{-1}\mathcal{O}_S)$.
Then $Rf_*E$ is a perfect object of $D(\mathcal{O}_S)$.
Proof. By Lemma Direct images and coherent sheaves we see that $Rf_*E$ is an object of $D^b_{\textit{Coh}}(\mathcal{O}_S)$. Hence $Rf_*E$ is pseudo-coherent (Lemma Pseudo-coherent complexes and coherent sheaves). Hence it suffices to show that $Rf_*E$ has finite tor dimension, see Cohomology, Lemma Perfect complexes. By Lemma Tor amplitude on a quasi-compact quasi-separated scheme it suffices to check that $Rf_*(E) \otimes_{\mathcal{O}_S}^\mathbf{L} \mathcal{F}$ has universally bounded cohomology for all quasi-coherent sheaves $\mathcal{F}$ on $S$. Bounded from above is clear as $Rf_*(E)$ is bounded from above. Let $T \subset X$ be the union of the supports of $H^i(E)$ for all $i$. Then $T$ is proper over $S$ by assumptions (1) and (2), see Cohomology of Schemes, Lemma Proper morphisms (uncovered prerequisite). In particular there exists a quasi-compact open $X' \subset X$ containing $T$. Setting $f' = f|_{X'}$ we have $Rf_*(E) = Rf'_*(E|_{X'})$ because $E$ restricts to zero on $X \setminus T$. Thus we may replace $X$ by $X'$ and assume $f$ is quasi-compact. Moreover, $f$ is quasi-separated by Morphisms, Lemma Diagonals, separation and Noetherian rings (uncovered prerequisite). Now $$Rf_*(E) \otimes_{\mathcal{O}_S}^\mathbf{L} \mathcal{F} = Rf_*\left(E \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*\mathcal{F}\right) = Rf_*\left(E \otimes_{f^{-1}\mathcal{O}_S}^\mathbf{L} f^{-1}\mathcal{F}\right)$$ by Lemma Base change for sheaf cohomology and Cohomology, Lemma Derived categories (uncovered prerequisite). By assumption (3) the complex $E \otimes_{f^{-1}\mathcal{O}_S}^\mathbf{L} f^{-1}\mathcal{F}$ has cohomology sheaves in a given finite range, say $[a, b]$. Then $Rf_*$ of it has cohomology in the range $[a, \infty)$ and we win. $\square$
Lemma. Extending perfect approximation across a distinguished square
Let $X$ be a scheme. Let $X = U \cup V$ be an open covering with $U$ quasi-compact, $V$ affine, and $U \cap V$ quasi-compact. If approximation by perfect complexes holds on $U$, then approximation holds on $X$.
Proof. Let $T \subset X$ be a closed subset with $X \setminus T$ retro-compact in $X$. Let $r_U$ be the integer of Definition Perfect approximation with prescribed cohomology adapted to the pair $(U, T \cap U)$. Set $T' = T \setminus U$. Note that $T' \subset V$ and that $V \setminus T' = (X \setminus T) \cap U \cap V$ is quasi-compact by our assumption on $T$. Let $r'$ be the number of affines needed to cover $V \setminus T'$. We claim that $r = \max(r_U, r')$ works for the pair $(X, T)$.
To see this choose a triple $(T, E, m)$ such that $E$ is $(m - r)$-pseudo-coherent and $H^i(E)$ is supported on $T$ for $i \geq m - r$. Let $t$ be the largest integer such that $H^t(E)|_U$ is nonzero. (Such an integer exists as $U$ is quasi-compact and $E|_U$ is $(m - r)$-pseudo-coherent.) We will prove that $E$ can be approximated by induction on $t$.
Base case: $t \leq m - r'$. This means that $H^i(E)$ is supported on $T'$ for $i \geq m - r'$. Hence Lemma Perfect approximation on an affine chart guarantees the existence of an approximation $P \to E|_V$ of $(T', E|_V, m)$ on $V$. Applying Lemma Restriction to an open subspace we see that $(T', E, m)$ can be approximated. Such an approximation is also an approximation of $(T, E, m)$.
Induction step. Choose an approximation $P \to E|_U$ of $(T \cap U, E|_U, m)$. This in particular gives a surjection $H^t(P) \to H^t(E|_U)$. By Lemma Lifting perfect complexes while retaining support we can choose a perfect object $Q$ in $D(\mathcal{O}_V)$ supported on $T \cap V$ and an isomorphism $Q|_{U \cap V} \to (P \oplus P[1])|_{U \cap V}$. By Lemma Extending a morphism after finite denominators are cleared we can replace $Q$ by $Q \otimes^\mathbf{L} I$ and assume that the map $$Q|_{U \cap V} \to (P \oplus P[1])|_{U \cap V} \longrightarrow P|_{U \cap V} \longrightarrow E|_{U \cap V}$$ lifts to $Q \to E|_V$. By Cohomology, Lemma Derived gluing across an elementary distinguished square we find an morphism $a : R \to E$ of $D(\mathcal{O}_X)$ such that $a|_U$ is isomorphic to $P \oplus P[1] \to E|_U$ and $a|_V$ isomorphic to $Q \to E|_V$. Thus $R$ is perfect and supported on $T$ and the map $H^t(R) \to H^t(E)$ is surjective on restriction to $U$. Choose a distinguished triangle $$R \to E \to E' \to R[1]$$ Then $E'$ is $(m - r)$-pseudo-coherent (Cohomology, Lemma Pseudo-coherent complexes and coherent sheaves), $H^i(E')|_U = 0$ for $i \geq t$, and $H^i(E')$ is supported on $T$ for $i \geq m - r$. By induction we find an approximation $R' \to E'$ of $(T, E', m)$. Fit the composition $R' \to E' \to R[1]$ into a distinguished triangle $R \to R'' \to R' \to R[1]$ and extend the morphisms $R' \to E'$ and $R[1] \to R[1]$ into a morphism of distinguished triangles $$\begin{gathered}\begin{matrix}R & R'' & R' & R[1] \\ R & E & E' & R[1]\end{matrix} \\[6pt] \begin{aligned}R & \longrightarrow R'' \\ R & \longrightarrow R \\ R'' & \longrightarrow E \\ R'' & \longrightarrow R' \\ R' & \longrightarrow E' \\ R' & \longrightarrow R[1] \\ R[1] & \longrightarrow R[1] \\ R & \longrightarrow E \\ E & \longrightarrow E' \\ E' & \longrightarrow R[1]\end{aligned}\end{gathered}$$ using TR3. Then $R''$ is a perfect complex (Cohomology, Lemma Perfect complexes) supported on $T$. An easy diagram chase shows that $R'' \to E$ is the desired approximation. $\square$
Proposition. Perfect generators for schemes with affine diagonal
Let $X$ be a quasi-compact scheme with affine diagonal. Then the functor (Comparison of derived quasi-coherent categories) $$D(\mathrm{QCoh}(\mathcal{O}_X)) \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_X)$$ is an equivalence with quasi-inverse given by $RQ_X$.
Proof. Let $U \subset X$ be an affine open. Then the morphism $U \to X$ is affine by Morphisms, Lemma Affine neighbourhoods (uncovered prerequisite). Thus the assumption of Lemma The derived localization argument holds by Lemma Affine neighbourhoods and we win. $\square$
Lemma. Direct images and coherent sheaves
Let $S$ be a Noetherian scheme. Let $f : X \to S$ be a morphism of schemes which is locally of finite type. Let $E$ be an object of $D^b_{\textit{Coh}}(\mathcal{O}_X)$ such that the support of $H^i(E)$ is proper over $S$ for all $i$. Then $Rf_*E$ is an object of $D^b_{\textit{Coh}}(\mathcal{O}_S)$.
Proof. Consider the spectral sequence $$R^pf_*H^q(E) \Rightarrow R^{p + q}f_*E$$ see Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories. By assumption and Cohomology of Schemes, Lemma Proper morphisms and closed support (uncovered prerequisite) the sheaves $R^pf_*H^q(E)$ are coherent. Hence $R^{p + q}f_*E$ is coherent, i.e., $Rf_*E \in D_{\textit{Coh}}(\mathcal{O}_S)$. Boundedness from below is trivial. Boundedness from above follows from Cohomology of Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite) or from Lemma Quasi-coherent complexes and coherent sheaves. $\square$
Definition. Perfect approximation with prescribed cohomology
Let $X$ be a scheme. We say approximation by perfect complexes holds on $X$ if for any closed subset $T \subset X$ with $X \setminus T$ retro-compact in $X$ there exists an integer $r$ such that for every triple $(T, E, m)$ as in Definition Bounds for perfect approximation with
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$E$ is $(m - r)$-pseudo-coherent, and
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$H^i(E)$ is supported on $T$ for $i \geq m - r$
approximation holds.
Lemma. Restriction to an open subspace
Let $X$ be a scheme. Let $U \subset X$ be an open subscheme. Let $(T, E, m)$ be a triple as in Definition Bounds for perfect approximation. If
-
$T \subset U$,
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approximation holds for $(T, E|_U, m)$, and
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the sheaves $H^i(E)$ for $i \geq m$ are supported on $T$,
then approximation holds for $(T, E, m)$.
Proof. Let $j : U \to X$ be the inclusion morphism. If $P \to E|_U$ is an approximation of the triple $(T, E|_U, m)$ over $U$, then $j_!P = Rj_*P \to j_!(E|_U) \to E$ is an approximation of $(T, E, m)$ over $X$. See Cohomology, Lemmas Direct images and derived sheaf cohomology (uncovered prerequisite) and Direct images and perfect complexes (uncovered prerequisite). $\square$
Lemma. The derived localization argument
Let $X$ be a quasi-compact and quasi-separated scheme. Suppose that for every affine open $U \subset X$ the right derived functor $$\Phi : D(\mathrm{QCoh}(\mathcal{O}_U)) \to D(\mathrm{QCoh}(\mathcal{O}_X))$$ of the left exact functor $j_* : \mathrm{QCoh}(\mathcal{O}_U) \to \mathrm{QCoh}(\mathcal{O}_X)$ fits into a commutative diagram $$\begin{gathered}\begin{matrix}D(\mathrm{QCoh}(\mathcal{O}_U)) & D_\mathrm{QCoh}(\mathcal{O}_U) \\ D(\mathrm{QCoh}(\mathcal{O}_X)) & D_\mathrm{QCoh}(\mathcal{O}_X)\end{matrix} \\[6pt] \begin{aligned}D(\mathrm{QCoh}(\mathcal{O}_U)) & \xrightarrow{\Phi} D(\mathrm{QCoh}(\mathcal{O}_X)) \\ D(\mathrm{QCoh}(\mathcal{O}_U)) & \xrightarrow{i_U} D_\mathrm{QCoh}(\mathcal{O}_U) \\ D_\mathrm{QCoh}(\mathcal{O}_U) & \xrightarrow{Rj_*} D_\mathrm{QCoh}(\mathcal{O}_X) \\ D(\mathrm{QCoh}(\mathcal{O}_X)) & \xrightarrow{i_X} D_\mathrm{QCoh}(\mathcal{O}_X)\end{aligned}\end{gathered}$$ Then the functor (Comparison of derived quasi-coherent categories) $$D(\mathrm{QCoh}(\mathcal{O}_X)) \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_X)$$ is an equivalence with quasi-inverse given by $RQ_X$.
Proof. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ and let $A$ be an object of $D(\mathrm{QCoh}(\mathcal{O}_X))$. We have to show that the adjunction maps $$A \to RQ_X(i_X(A)) \quad\text{and}\quad i_X(RQ_X(E)) \to E$$ are isomorphisms. Consider the hypothesis $H_n$: the adjunction maps above are isomorphisms whenever $E$ and $i_X(A)$ are supported (Definition Complexes with prescribed closed support) on a closed subset of $X$ which is contained in the union of $n$ affine opens of $X$. We will prove $H_n$ by induction on $n$.
Base case: $n = 0$. In this case $E = 0$, hence the map $i_X(RQ_X(E)) \to E$ is an isomorphism. Similarly $i_X(A) = 0$. Thus the cohomology sheaves of $i_X(A)$ are zero. Since the inclusion functor $\mathrm{QCoh}(\mathcal{O}_X) \to \textit{Mod}(\mathcal{O}_X)$ is fully faithful and exact, we conclude that the cohomology objects of $A$ are zero, i.e., $A = 0$ and $A \to RQ_X(i_X(A))$ is an isomorphism as well.
Induction step. Suppose that $E$ and $i_X(A)$ are supported on a closed subset $T$ of $X$ contained in $U_1 \cup \ldots \cup U_n$ with $U_i \subset X$ affine open. Set $U = U_n$. Consider the distinguished triangles $$A \to \Phi(A|_U) \to A' \to A[1] \quad\text{and}\quad E \to Rj_*(E|_U) \to E' \to E[1]$$ where $\Phi$ is as in the statement of the lemma. Note that $E \to Rj_*(E|_U)$ is a quasi-isomorphism over $U = U_n$. Since $i_X \circ \Phi = Rj_* \circ i_U$ by assumption and since $i_X(A)|_U = i_U(A|_U)$ we see that $i_X(A) \to i_X(\Phi(A|_U))$ is a quasi-isomorphism over $U$. Hence $i_X(A')$ and $E'$ are supported on the closed subset $T \setminus U$ of $X$ which is contained in $U_1 \cup \ldots \cup U_{n - 1}$. By induction hypothesis the statement is true for $A'$ and $E'$. By Derived Categories, Lemma Derived categories it suffices to prove the maps $$\Phi(A|_U) \to RQ_X(i_X(\Phi(A|_U))) \quad\text{and}\quad i_X(RQ_X(Rj_*E|_U)) \to Rj_*(E|_U)$$ are isomorphisms. By assumption and by Lemma Derived tensor products, Tor amplitude and flatness (the inclusion morphism $j : U \to X$ is flat, quasi-compact, and quasi-separated) we have $$RQ_X(i_X(\Phi(A|_U))) = RQ_X(Rj_*(i_U(A|_U))) = \Phi(RQ_U(i_U(A|_U)))$$ and $$i_X(RQ_X(Rj_*(E|_U))) = i_X(\Phi(RQ_U(E|_U))) = Rj_*(i_U(RQ_U(E|_U)))$$ Finally, the maps $$A|_U \to RQ_U(i_U(A|_U)) \quad\text{and}\quad i_U(RQ_U(E|_U)) \to E|_U$$ are isomorphisms by Lemma Derived tensor products, Tor amplitude and affine neighbourhoods. The result follows. $\square$
Lemma. Affine neighbourhoods
Let $f : X \to Y$ be an affine morphism of schemes. Then $f_*$ defines a derived functor $f_* : D(\mathrm{QCoh}(\mathcal{O}_X)) \to D(\mathrm{QCoh}(\mathcal{O}_Y))$. This functor has the property that $$\begin{gathered}\begin{matrix}D(\mathrm{QCoh}(\mathcal{O}_X)) & D_\mathrm{QCoh}(\mathcal{O}_X) \\ D(\mathrm{QCoh}(\mathcal{O}_Y)) & D_\mathrm{QCoh}(\mathcal{O}_Y)\end{matrix} \\[6pt] \begin{aligned}D(\mathrm{QCoh}(\mathcal{O}_X)) & \xrightarrow{f_*} D(\mathrm{QCoh}(\mathcal{O}_Y)) \\ D(\mathrm{QCoh}(\mathcal{O}_X)) & \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_X) \\ D_\mathrm{QCoh}(\mathcal{O}_X) & \xrightarrow{Rf_*} D_\mathrm{QCoh}(\mathcal{O}_Y) \\ D(\mathrm{QCoh}(\mathcal{O}_Y)) & \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_Y)\end{aligned}\end{gathered}$$ commutes.
Proof. The functor $f_* : \mathrm{QCoh}(\mathcal{O}_X) \to \mathrm{QCoh}(\mathcal{O}_Y)$ is exact, see Cohomology of Schemes, Lemma Affine neighbourhoods (uncovered prerequisite). Hence $f_*$ defines a derived functor $f_* : D(\mathrm{QCoh}(\mathcal{O}_X)) \to D(\mathrm{QCoh}(\mathcal{O}_Y))$ by simply applying $f_*$ to any representative complex, see Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories. The diagram commutes by Lemma Direct images and affine neighbourhoods. $\square$
Definition. Complexes with prescribed closed support
Let $X$ be a scheme. Let $E$ be an object of $D(\mathcal{O}_X)$. Let $T \subset X$ be a closed subset. We say $E$ is supported on $T$ if the cohomology sheaves $H^i(E)$ are supported on $T$.
Lemma. Derived tensor products, Tor amplitude and flatness
Let $f : X \to Y$ be a morphism of schemes. Assume $f$ is quasi-compact, quasi-separated, and flat. Then, denoting $$\Phi : D(\mathrm{QCoh}(\mathcal{O}_X)) \to D(\mathrm{QCoh}(\mathcal{O}_Y))$$ the right derived functor of $f_* : \mathrm{QCoh}(\mathcal{O}_X) \to \mathrm{QCoh}(\mathcal{O}_Y)$ we have $RQ_Y \circ Rf_* = \Phi \circ RQ_X$.
Proof. We will prove this by showing that $RQ_Y \circ Rf_*$ and $\Phi \circ RQ_X$ are right adjoint to the same functor $D(\mathrm{QCoh}(\mathcal{O}_Y)) \to D(\mathcal{O}_X)$.
Since $f$ is quasi-compact and quasi-separated, we see that $f_*$ preserves quasi-coherence, see Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite). Recall that $\mathrm{QCoh}(\mathcal{O}_X)$ is a Grothendieck abelian category (Properties, Proposition Derived tensor products and Tor amplitude (uncovered prerequisite)). Hence any $K$ in $D(\mathrm{QCoh}(\mathcal{O}_X))$ can be represented by a K-injective complex $\mathcal{I}^\bullet$ of $\mathrm{QCoh}(\mathcal{O}_X)$, see Injectives, Theorem Injective resolutions (uncovered prerequisite). Then we can define $\Phi(K) = f_*\mathcal{I}^\bullet$.
Since $f$ is flat, the functor $f^*$ is exact. Hence $f^*$ defines $f^* : D(\mathcal{O}_Y) \to D(\mathcal{O}_X)$ and also $f^* : D(\mathrm{QCoh}(\mathcal{O}_Y)) \to D(\mathrm{QCoh}(\mathcal{O}_X))$. The functor $f^* = Lf^* : D(\mathcal{O}_Y) \to D(\mathcal{O}_X)$ is left adjoint to $Rf_* : D(\mathcal{O}_X) \to D(\mathcal{O}_Y)$, see Cohomology, Lemma Adjunction for derived direct image. Similarly, the functor $f^* : D(\mathrm{QCoh}(\mathcal{O}_Y)) \to D(\mathrm{QCoh}(\mathcal{O}_X))$ is left adjoint to $\Phi : D(\mathrm{QCoh}(\mathcal{O}_X)) \to D(\mathrm{QCoh}(\mathcal{O}_Y))$ by Derived Categories, Lemma Derived categories (uncovered prerequisite).
Let $A$ be an object of $D(\mathrm{QCoh}(\mathcal{O}_Y))$ and $E$ an object of $D(\mathcal{O}_X)$. Then $$\begin{aligned} \operatorname{Hom}_{D(\mathrm{QCoh}(\mathcal{O}_Y))}(A, RQ_Y(Rf_*E)) & = \operatorname{Hom}_{D(\mathcal{O}_Y)}(A, Rf_*E) \\ & = \operatorname{Hom}_{D(\mathcal{O}_X)}(f^*A, E) \\ & = \operatorname{Hom}_{D(\mathrm{QCoh}(\mathcal{O}_X))}(f^*A, RQ_X(E)) \\ & = \operatorname{Hom}_{D(\mathrm{QCoh}(\mathcal{O}_Y))}(A, \Phi(RQ_X(E))) \end{aligned}$$ This implies what we want. $\square$
Lemma. Direct images and affine neighbourhoods
Let $f : X \to S$ be an affine morphism of schemes. Let $\mathcal{F}^\bullet$ be a complex of quasi-coherent $\mathcal{O}_X$-modules. Then $f_*\mathcal{F}^\bullet = Rf_*\mathcal{F}^\bullet$.
Proof. Combine Lemma Perfect complexes with Cohomology of Schemes, Lemma Affine neighbourhoods (uncovered prerequisite). An alternative proof is to work affine locally on $S$ and use Lemma Quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Perfect complexes
Let $f : X \to S$ be a quasi-separated and quasi-compact morphism of schemes. Let $\mathcal{F}^\bullet$ be a complex of quasi-coherent $\mathcal{O}_X$-modules each of which is right acyclic for $f_*$. Then $f_*\mathcal{F}^\bullet$ represents $Rf_*\mathcal{F}^\bullet$ in $D(\mathcal{O}_S)$.
Proof. There is always a canonical map $f_*\mathcal{F}^\bullet \to Rf_*\mathcal{F}^\bullet$. Our task is to show that this is an isomorphism on cohomology sheaves. As the statement is invariant under shifts it suffices to show that $H^0(f_*(\mathcal{F}^\bullet)) \to R^0f_*\mathcal{F}^\bullet$ is an isomorphism. The statement is local on $S$ hence we may assume $S$ affine. Choose $N$ as in Lemma Quasi-coherent complexes and coherent sheaves and an integer $n \geq \max\{1, N\}$. The termwise split short exact sequence $$0 \to \sigma_{\geq -n}\mathcal{F}^\bullet \to \mathcal{F}^\bullet \to \sigma_{\leq -n-1}\mathcal{F}^\bullet \to 0$$ gives a distinguished triangle. The last complex has quasi-coherent cohomology, vanishing in degrees greater than $-n-1$. The bound $N$ therefore gives vanishing of $H^j(Rf_*\sigma_{\leq -n-1}\mathcal{F}^\bullet)$ for $j \geq N-n-1$, in particular for $j=-1,0$. It follows that $H^0(Rf_*\sigma_{\geq -n}\mathcal{F}^\bullet) \to H^0(Rf_*\mathcal{F}^\bullet)$ is an isomorphism. Also $H^0(f_*\sigma_{\geq -n}\mathcal{F}^\bullet) = H^0(f_*\mathcal{F}^\bullet)$ since $n \geq 1$. The complex $\sigma_{\geq -n}\mathcal{F}^\bullet$ is bounded below and consists of the original right $f_*$-acyclic terms, so it computes $Rf_*$ by Leray's acyclicity lemma (Derived Categories, Lemma Sheaf cohomology (uncovered prerequisite)). Naturality of the canonical map now proves the desired isomorphism in degree zero. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
If $f : X \to Y$ is a morphism of affine schemes given by the ring map $A \to B$, then the diagram $$\begin{gathered}\begin{matrix}D(B) & D_\mathrm{QCoh}(\mathcal{O}_X) \\ D(A) & D_\mathrm{QCoh}(\mathcal{O}_Y)\end{matrix} \\[6pt] \begin{aligned}D(B) & \longrightarrow D(A) \\ D(B) & \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_X) \\ D_\mathrm{QCoh}(\mathcal{O}_X) & \xrightarrow{Rf_*} D_\mathrm{QCoh}(\mathcal{O}_Y) \\ D(A) & \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_Y)\end{aligned}\end{gathered}$$ commutes.
Proof. Follows from Lemma Bounded comparison of affine derived categories using that $R\Gamma(Y, Rf_*K) = R\Gamma(X, K)$ by Cohomology, Lemma Sheaf cohomology (uncovered prerequisite). $\square$
[^1]: In particular, $E$ has a K-injective representative by Derived Categories, Lemma Injective resolutions (uncovered prerequisite).
Triangulated categories and derived limits
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $F : \mathcal{A} \to \mathcal{B}$ be a left exact functor of abelian categories. Let $K^\bullet$ be a bounded below complex of $\mathcal{A}$. Let $I^{\bullet, \bullet}$ be a Cartan-Eilenberg resolution for $K^\bullet$. The spectral sequences $({}'E_r, {}'d_r)_{r \geq 0}$ and $({}''E_r, {}''d_r)_{r \geq 0}$ associated to the double complex $F(I^{\bullet, \bullet})$ satisfy the relations $${}'E_1^{p, q} = R^qF(K^p) \quad \text{and} \quad {}''E_2^{p, q} = R^pF(H^q(K^\bullet))$$ Moreover, these spectral sequences are bounded, converge to $H^*(RF(K^\bullet))$, and the associated induced filtrations on $H^n(RF(K^\bullet))$ are finite.
Proof. We will use the following remarks without further mention:
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As $I^{p, \bullet}$ is an injective resolution of $K^p$ we see that $RF$ is defined at $K^p[0]$ with value $F(I^{p, \bullet})$.
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As $H^p_I(I^{\bullet, \bullet})$ is an injective resolution of $H^p(K^\bullet)$ the derived functor $RF$ is defined at $H^p(K^\bullet)[0]$ with value $F(H^p_I(I^{\bullet, \bullet}))$.
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By Homology, Lemma Derived categories (uncovered prerequisite) the total complex $\text{Tot}(I^{\bullet, \bullet})$ is an injective resolution of $K^\bullet$. Hence $RF$ is defined at $K^\bullet$ with value $F(\text{Tot}(I^{\bullet, \bullet}))$.
Consider the two spectral sequences associated to the double complex $L^{\bullet, \bullet} = F(I^{\bullet, \bullet})$, see Homology, Lemma Derived categories (uncovered prerequisite). These are both bounded, converge to $H^*(\text{Tot}(L^{\bullet, \bullet}))$, and induce finite filtrations on $H^n(\text{Tot}(L^{\bullet, \bullet}))$, see Homology, Lemma The geometric construction (uncovered prerequisite). Since $\text{Tot}(L^{\bullet, \bullet}) = \text{Tot}(F(I^{\bullet, \bullet})) = F(\text{Tot}(I^{\bullet, \bullet}))$ computes $RF(K^\bullet)$ we find the final assertion of the lemma holds true.
Computation of the first spectral sequence. We have ${}'E_1^{p, q} = H^q(L^{p, \bullet})$ in other words $${}'E_1^{p, q} = H^q(F(I^{p, \bullet})) = R^qF(K^p)$$ as desired. Observe for later use that the maps ${}'d_1^{p, q} : {}'E_1^{p, q} \to {}'E_1^{p + 1, q}$ are the maps $R^qF(K^p) \to R^qF(K^{p + 1})$ induced by $K^p \to K^{p + 1}$ and the fact that $R^qF$ is a functor.
Computation of the second spectral sequence. We have ${}''E_1^{p, q} = H^q(L^{\bullet, p}) = H^q(F(I^{\bullet, p}))$. Note that the complex $I^{\bullet, p}$ is bounded below, consists of injectives, and moreover each kernel, image, and cohomology group of the differentials is an injective object of $\mathcal{A}$. Hence we can split the differentials, i.e., each differential is a split surjection onto a direct summand. It follows that the same is true after applying $F$. Hence ${}''E_1^{p, q} = F(H^q(I^{\bullet, p})) = F(H^q_I(I^{\bullet, p}))$. The differentials on this are $(-1)^q$ times $F$ applied to the differential of the complex $H^q_I(I^{\bullet, \bullet})$ which is an injective resolution of $H^q(K^\bullet)$. Hence the description of the $E_2$ terms. $\square$
Lemma. Splitting an exact triangle
Let $\mathcal{D}$ be a pre-triangulated category. Let $(X, Y, Z, f, g, h)$ be a distinguished triangle.
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If $h = 0$, then there exists a right inverse $s : Z \to Y$ to $g$.
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For any right inverse $s : Z \to Y$ of $g$ the map $f \oplus s : X \oplus Z \to Y$ is an isomorphism.
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For any objects $X', Z'$ of $\mathcal{D}$ the triangle $(X', X' \oplus Z', Z', (1, 0), (0, 1), 0)$ is distinguished.
Proof. To see (1) use that $\operatorname{Hom}_\mathcal{D}(Z, Y) \to \operatorname{Hom}_\mathcal{D}(Z, Z) \to \operatorname{Hom}_\mathcal{D}(Z, X[1])$ is exact by Lemma Representability of a homological functor. By the same token, if $s$ is as in (2), then $h = 0$ and the sequence $$0 \to \operatorname{Hom}_\mathcal{D}(W, X) \to \operatorname{Hom}_\mathcal{D}(W, Y) \to \operatorname{Hom}_\mathcal{D}(W, Z) \to 0$$ is split exact (split by $s : Z \to Y$). Hence by Yoneda's lemma we see that $X \oplus Z \to Y$ is an isomorphism. The last assertion follows from TR1 and Lemma Derived categories and tensor products and direct sums. $\square$
Lemma. Nilpotent thickenings
Let $\mathcal{D}$ be a pre-triangulated category. Let $$(0, b, 0), (0, b', 0) : (X, Y, Z, f, g, h) \to (X, Y, Z, f, g, h)$$ be endomorphisms of a distinguished triangle. Then $bb' = 0$.
Proof. Picture $$\begin{gathered}\begin{matrix}X & Y & Z & X[1] \\ X & Y & Z & X[1]\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow Y \\ X & \xrightarrow{0} X \\ Y & \longrightarrow Z \\ Y & \xrightarrow{b, b'} Y \\ Y & \overset{\alpha}{\cdots\!\!\rightarrow} X \\ Z & \longrightarrow X[1] \\ Z & \xrightarrow{0} Z \\ Z & \overset{\beta}{\cdots\!\!\rightarrow} Y \\ X[1] & \xrightarrow{0} X[1] \\ X & \longrightarrow Y \\ Y & \longrightarrow Z \\ Z & \longrightarrow X[1]\end{aligned}\end{gathered}$$ Applying Lemma Representability of a homological functor we find dotted arrows $\alpha$ and $\beta$ such that $b' = f \circ \alpha$ and $b = \beta \circ g$. Then $bb' = \beta \circ g \circ f \circ \alpha = 0$ as $g \circ f = 0$ by Lemma Composition and triangulated categories. $\square$
Remark. Derived categories
Let $\mathcal{A}$ be an abelian category. Let $K^\bullet$ be a complex of $\mathcal{A}$. Let $a \in \mathbf{Z}$. We claim there is a canonical distinguished triangle $$\tau_{\leq a}K^\bullet \to K^\bullet \to \tau_{\geq a + 1}K^\bullet \to (\tau_{\leq a}K^\bullet)[1]$$ in $D(\mathcal{A})$. Here we have used the canonical truncation functors $\tau$ from Homology, Section The geometric construction. Namely, we first take the distinguished triangle associated by our $\delta$-functor (Lemma Derived tensor products, Tor amplitude and derived categories) to the short exact sequence of complexes $$0 \to \tau_{\leq a}K^\bullet \to K^\bullet \to K^\bullet/\tau_{\leq a}K^\bullet \to 0$$ Next, we use that the map $K^\bullet \to \tau_{\geq a + 1}K^\bullet$ factors through a quasi-isomorphism $K^\bullet/\tau_{\leq a}K^\bullet \to \tau_{\geq a + 1}K^\bullet$ by the description of cohomology groups in Homology, Section The geometric construction. In a similar way we obtain canonical distinguished triangles $$\tau_{\leq a}K^\bullet \to \tau_{\leq a + 1}K^\bullet \to H^{a + 1}(K^\bullet)[-a-1] \to (\tau_{\leq a}K^\bullet)[1]$$ and $$H^a(K^\bullet)[-a] \to \tau_{\geq a}K^\bullet \to \tau_{\geq a + 1}K^\bullet \to H^a(K^\bullet)[-a + 1]$$
Lemma. Derived categories
Let $\mathcal{D}$ be a pre-triangulated category. Let $$(a, b, c) : (X, Y, Z, f, g, h) \to (X', Y', Z', f', g', h')$$ be a morphism of distinguished triangles. If two among $a, b, c$ are isomorphisms so is the third.
Proof. Assume that $a$ and $c$ are isomorphisms. For any object $W$ of $\mathcal{D}$ write $H_W( - ) = \operatorname{Hom}_\mathcal{D}(W, -)$. Then we get a commutative diagram of abelian groups $$\begin{gathered}\begin{matrix}H_W(Z[-1]) & H_W(X) & H_W(Y) & H_W(Z) & H_W(X[1]) \\ H_W(Z'[-1]) & H_W(X') & H_W(Y') & H_W(Z') & H_W(X'[1])\end{matrix} \\[6pt] \begin{aligned}H_W(Z[-1]) & \longrightarrow H_W(X) \\ H_W(Z[-1]) & \longrightarrow H_W(Z'[-1]) \\ H_W(X) & \longrightarrow H_W(Y) \\ H_W(X) & \longrightarrow H_W(X') \\ H_W(Y) & \longrightarrow H_W(Z) \\ H_W(Y) & \longrightarrow H_W(Y') \\ H_W(Z) & \longrightarrow H_W(X[1]) \\ H_W(Z) & \longrightarrow H_W(Z') \\ H_W(X[1]) & \longrightarrow H_W(X'[1]) \\ H_W(Z'[-1]) & \longrightarrow H_W(X') \\ H_W(X') & \longrightarrow H_W(Y') \\ H_W(Y') & \longrightarrow H_W(Z') \\ H_W(Z') & \longrightarrow H_W(X'[1])\end{aligned}\end{gathered}$$ By assumption the right two and left two vertical arrows are bijective. As $H_W$ is homological by Lemma Representability of a homological functor and the five lemma (Homology, Lemma The geometric construction (uncovered prerequisite)) it follows that the middle vertical arrow is an isomorphism. Hence by Yoneda's lemma, see Categories, Lemma The geometric construction (uncovered prerequisite) we see that $b$ is an isomorphism. This implies the other cases by rotating (using TR2). $\square$
Lemma. Existence of a right adjoint
Let $\mathcal{D}$ be a triangulated category. Let $\mathcal{A} \subset \mathcal{D}$ be a full triangulated subcategory. The following are equivalent
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the inclusion functor $\mathcal{A} \to \mathcal{D}$ has a right adjoint, and
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for every $X$ in $\mathcal{D}$ there exists a distinguished triangle $$A \to X \to B \to A[1]$$ in $\mathcal{D}$ with $A \in \operatorname{Ob}(\mathcal{A})$ and $B \in \operatorname{Ob}(\mathcal{A}^\perp)$.
If this holds, then $\mathcal{A}$ is saturated (Definition Saturated triangulated subcategories) and if $\mathcal{A}$ is strictly full in $\mathcal{D}$, then $\mathcal{A} = {}^\perp(\mathcal{A}^\perp)$.
Proof. Assume (1) and denote $v : \mathcal{D} \to \mathcal{A}$ the right adjoint. Let $X \in \operatorname{Ob}(\mathcal{D})$. Set $A = v(X)$. We may extend the adjunction mapping $A \to X$ to a distinguished triangle $A \to X \to B \to A[1]$. Since $$\operatorname{Hom}_\mathcal{A}(A', A) = \operatorname{Hom}_\mathcal{A}(A', v(X)) = \operatorname{Hom}_\mathcal{D}(A', X)$$ for $A' \in \operatorname{Ob}(\mathcal{A})$, we conclude that $B \in \operatorname{Ob}(\mathcal{A}^\perp)$ by Lemma The preliminary adjunction comparison.
Assume (2). We will construct the adjoint $v$ explicitly. Let $X \in \operatorname{Ob}(\mathcal{D})$. Choose $A \to X \to B \to A[1]$ as in (2). Set $v(X) = A$. Let $f : X \to Y$ be a morphism in $\mathcal{D}$. Choose $A' \to Y \to B' \to A'[1]$ as in (2). Since $\operatorname{Hom}(A, A') = \operatorname{Hom}(A, Y)$ by Lemma The preliminary adjunction comparison there is a unique morphism $f' : A \to A'$ such that the diagram $$\begin{gathered}\begin{matrix}A & X \\ A' & Y\end{matrix} \\[6pt] \begin{aligned}A & \xrightarrow{f'} A' \\ A & \longrightarrow X \\ X & \xrightarrow{f} Y \\ A' & \longrightarrow Y\end{aligned}\end{gathered}$$ commutes. Hence we can set $v(f) = f'$ to get a functor. To see that $v$ is adjoint to the inclusion morphism use Lemma The preliminary adjunction comparison again.
Proof of the final statement. In order to prove that $\mathcal{A}$ is saturated we may replace $\mathcal{A}$ by the strictly full subcategory having the same isomorphism classes as $\mathcal{A}$; details omitted. Assume $\mathcal{A}$ is strictly full. If we show that $\mathcal{A} = {}^\perp(\mathcal{A}^\perp)$, then $\mathcal{A}$ will be saturated by Lemma A triangulated orthogonal subcategory. Since the inclusion $\mathcal{A} \subset {}^\perp(\mathcal{A}^\perp)$ is clear it suffices to prove the other inclusion. Let $X$ be an object of ${}^\perp(\mathcal{A}^\perp)$. Choose a distinguished triangle $A \to X \to B \to A[1]$ as in (2). As $\operatorname{Hom}(X, B) = 0$ by assumption we see that $A \cong X \oplus B[-1]$ by Lemma Splitting an exact triangle. Since $\operatorname{Hom}(A, B[-1]) = 0$ as $B \in \mathcal{A}^\perp$ this implies $B[-1] = 0$ and $A \cong X$ as desired. $\square$
Lemma. Preparing the adjunction for derived functors
Let $\mathcal{D}$ be a triangulated category. Let $\mathcal{A}$ be a full triangulated subcategory of $\mathcal{D}$. For an object $X$ of $\mathcal{D}$ consider the property $P(X)$: there exists a distinguished triangle $A \to X \to B \to A[1]$ in $\mathcal{D}$ with $A$ in $\mathcal{A}$ and $B$ in $\mathcal{A}^\perp$.
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If $X_1 \to X_2 \to X_3 \to X_1[1]$ is a distinguished triangle and $P$ holds for two out of three, then it holds for the third.
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If $P$ holds for $X_1$ and $X_2$, then it holds for $X_1 \oplus X_2$.
Proof. Let $X_1 \to X_2 \to X_3 \to X_1[1]$ be a distinguished triangle and assume $P$ holds for $X_1$ and $X_2$. Choose distinguished triangles $$A_1 \to X_1 \to B_1 \to A_1[1] \quad\text{and}\quad A_2 \to X_2 \to B_2 \to A_2[1]$$ as in condition $P$. Since $\operatorname{Hom}(A_1, A_2) = \operatorname{Hom}(A_1, X_2)$ by Lemma The preliminary adjunction comparison there is a unique morphism $A_1 \to A_2$ such that the diagram $$\begin{gathered}\begin{matrix}A_1 & X_1 \\ A_2 & X_2\end{matrix} \\[6pt] \begin{aligned}A_1 & \longrightarrow A_2 \\ A_1 & \longrightarrow X_1 \\ X_1 & \longrightarrow X_2 \\ A_2 & \longrightarrow X_2\end{aligned}\end{gathered}$$ commutes. Choose an extension of this to a diagram $$\begin{gathered}\begin{matrix}A_1 & X_1 & Q_1 & A_1[1] \\ A_2 & X_2 & Q_2 & A_2[1] \\ A_3 & X_3 & Q_3 & A_3[1] \\ A_1[1] & X_1[1] & Q_1[1] & A_1[2]\end{matrix} \\[6pt] \begin{aligned}A_1 & \longrightarrow X_1 \\ A_1 & \longrightarrow A_2 \\ X_1 & \longrightarrow Q_1 \\ X_1 & \longrightarrow X_2 \\ Q_1 & \longrightarrow A_1[1] \\ Q_1 & \longrightarrow Q_2 \\ A_1[1] & \longrightarrow A_2[1] \\ A_2 & \longrightarrow X_2 \\ A_2 & \longrightarrow A_3 \\ X_2 & \longrightarrow Q_2 \\ X_2 & \longrightarrow X_3 \\ Q_2 & \longrightarrow A_2[1] \\ Q_2 & \longrightarrow Q_3 \\ A_2[1] & \longrightarrow A_3[1] \\ A_3 & \longrightarrow X_3 \\ A_3 & \longrightarrow A_1[1] \\ X_3 & \longrightarrow Q_3 \\ X_3 & \longrightarrow X_1[1] \\ Q_3 & \longrightarrow A_3[1] \\ Q_3 & \longrightarrow Q_1[1] \\ A_3[1] & \longrightarrow A_1[2] \\ A_1[1] & \longrightarrow X_1[1] \\ X_1[1] & \longrightarrow Q_1[1] \\ Q_1[1] & \longrightarrow A_1[2]\end{aligned}\end{gathered}$$ as in Proposition The nine-triangle lemma. By TR3 we see that $Q_1 \cong B_1$ and $Q_2 \cong B_2$ and hence $Q_1, Q_2 \in \operatorname{Ob}(\mathcal{A}^\perp)$. As $Q_1 \to Q_2 \to Q_3 \to Q_1[1]$ is a distinguished triangle we see that $Q_3 \in \operatorname{Ob}(\mathcal{A}^\perp)$ by Lemma A triangulated orthogonal subcategory. Since $\mathcal{A}$ is a full triangulated subcategory, we see that $A_3$ is isomorphic to an object of $\mathcal{A}$. Thus $X_3$ satisfies $P$. The other cases of (1) follow from this case by translation. Part (2) is a special case of (1) via Lemma Splitting an exact triangle. $\square$
Proposition. Brown representability for a triangulated category
Source credit: the original source citation Neeman-Grothendieck (Theorem 4.1).
Let $\mathcal{D}$ be a triangulated category with direct sums which is compactly generated. Let $F : \mathcal{D} \to \mathcal{D}'$ be an exact functor of triangulated categories which transforms direct sums into direct sums. Then $F$ has an exact right adjoint.
Proof. For an object $Y$ of $\mathcal{D}'$ consider the contravariant functor $$\mathcal{D} \to \textit{Ab},\quad W \mapsto \operatorname{Hom}_{\mathcal{D}'}(F(W), Y)$$ This is a cohomological functor as $F$ is exact and transforms direct sums into products as $F$ transforms direct sums into direct sums. Thus by Lemma Brown representability we find an object $X$ of $\mathcal{D}$ such that $\operatorname{Hom}_\mathcal{D}(W, X) = \operatorname{Hom}_{\mathcal{D}'}(F(W), Y)$. The existence of the adjoint follows from Categories, Lemma The geometric construction (uncovered prerequisite). Exactness follows from Lemma Triangulated categories. $\square$
Lemma. Vanishing of negative Ext groups
Let $\mathcal{A}$ be an abelian category.
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Let $X$, $Y$ be objects of $D(\mathcal{A})$. Given $a, b \in \mathbf{Z}$ such that $H^i(X) = 0$ for $i > a$ and $H^j(Y) = 0$ for $j < b$, we have $\operatorname{Ext}^n_\mathcal{A}(X, Y) = 0$ for $n < b - a$ and $$\operatorname{Ext}^{b - a}_\mathcal{A}(X, Y) = \operatorname{Hom}_\mathcal{A}(H^a(X), H^b(Y))$$
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Let $A, B \in \operatorname{Ob}(\mathcal{A})$. For $i < 0$ we have $\operatorname{Ext}^i_\mathcal{A}(B, A) = 0$. We have $\operatorname{Ext}^0_\mathcal{A}(B, A) = \operatorname{Hom}_\mathcal{A}(B, A)$.
Proof. Choose complexes $X^\bullet$ and $Y^\bullet$ representing $X$ and $Y$. Since $Y^\bullet \to \tau_{\geq b}Y^\bullet$ is a quasi-isomorphism, we may assume that $Y^j = 0$ for $j < b$. Let $L^\bullet \to X^\bullet$ be any quasi-isomorphism. Then $\tau_{\leq a}L^\bullet \to X^\bullet$ is a quasi-isomorphism. Hence a morphism $X \to Y[n]$ in $D(\mathcal{A})$ can be represented as $fs^{-1}$ where $s : L^\bullet \to X^\bullet$ is a quasi-isomorphism, $f : L^\bullet \to Y^\bullet[n]$ a morphism, and $L^i = 0$ for $i > a$. Note that $f$ maps $L^i$ to $Y^{i + n}$. Thus $f = 0$ if $n < b - a$ because always either $L^i$ or $Y^{i + n}$ is zero. If $n = b - a$, then $f$ corresponds exactly to a morphism $H^a(X) \to H^b(Y)$. Part (2) is a special case of (1). $\square$
Lemma. Sheaf cohomology
Let $\mathcal{D}$ be a triangulated category having countable direct sums. Let $\mathcal{A}$ be an abelian category with exact colimits over $\mathbf{N}$. Let $H : \mathcal{D} \to \mathcal{A}$ be a homological functor commuting with countable direct sums. Then $H(\text{hocolim} K_n) = \mathop{\operatorname{colim}} H(K_n)$ for any system of objects of $\mathcal{D}$.
Proof. Write $K = \text{hocolim} K_n$. Apply $H$ to the defining distinguished triangle to get $$\bigoplus H(K_n) \to \bigoplus H(K_n) \to H(K) \to \bigoplus H(K_n[1]) \to \bigoplus H(K_n[1])$$ where the first map is given by $1 - H(f_n)$ and the last map is given by $1 - H(f_n[1])$. Apply Lemma Computation of a homotopy colimit to see that this proves the lemma. $\square$
Lemma. Vanishing in negative degrees
Let $F : \mathcal{A} \to \mathcal{B}$ be an additive functor between abelian categories. Let $K^\bullet$ be a complex of $\mathcal{A}$ and $a \in \mathbf{Z}$.
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If $H^i(K^\bullet) = 0$ for all $i < a$ and $RF$ is defined at $K^\bullet$, then $H^i(RF(K^\bullet)) = 0$ for all $i < a$.
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If $RF$ is defined at $K^\bullet$ and $\tau_{\leq a}K^\bullet$, then $H^i(RF(\tau_{\leq a}K^\bullet)) = H^i(RF(K^\bullet))$ for all $i \leq a$.
Proof. Assume $K^\bullet$ satisfies the assumptions of (1). Let $s : K^\bullet \to L^\bullet$ be any quasi-isomorphism. Then it is also true that $K^\bullet \to \tau_{\geq a}L^\bullet$ is a quasi-isomorphism by our assumption on $K^\bullet$. Hence in the category $K^\bullet/\text{Qis}(\mathcal{A})$ the quasi-isomorphisms $s : K^\bullet \to L^\bullet$ with $L^n = 0$ for $n < a$ are cofinal. From Categories, Lemma The geometric construction (uncovered prerequisite) we deduce that $RF$ is the value of the essentially constant ind-object $F(L^\bullet)$ for these $s$. This means that $\text{id} : RF(K^\bullet) \to RF(K^\bullet)$ factors through $F(L^\bullet)$ for some complex $L^\bullet$ with $L^n = 0$ for $n < a$. It follows that $H^i(RF(K^\bullet)) = 0$ for $i < a$.
To prove (2) we use the distinguished triangle $$\tau_{\leq a}K^\bullet \to K^\bullet \to \tau_{\geq a + 1}K^\bullet \to (\tau_{\leq a}K^\bullet)[1]$$ of Remark Derived categories to conclude via Lemma Triangulated categories (uncovered prerequisite) that $RF$ is defined at $\tau_{\geq a + 1}K^\bullet$ as well and that we have a distinguished triangle $$RF(\tau_{\leq a}K^\bullet) \to RF(K^\bullet) \to RF(\tau_{\geq a + 1}K^\bullet) \to RF(\tau_{\leq a}K^\bullet)[1]$$ in $D(\mathcal{B})$. By part (1) we see that $RF(\tau_{\geq a + 1}K^\bullet)$ has vanishing cohomology in degrees $< a + 1$. The long exact cohomology sequence of this distinguished triangle then shows what we want. $\square$
Definition. The cone of a complex morphism
Let $\mathcal{A}$ be an additive category. Let $f : K^\bullet \to L^\bullet$ be a morphism of complexes of $\mathcal{A}$. The cone of $f$ is the complex $C(f)^\bullet$ given by $C(f)^n = L^n \oplus K^{n + 1}$ and differential $$d_{C(f)}^n = \left( \begin{matrix} d^n_L & f^{n + 1} \\ 0 & -d_K^{n + 1} \end{matrix} \right)$$ It comes equipped with canonical morphisms of complexes $i : L^\bullet \to C(f)^\bullet$ and $p : C(f)^\bullet \to K^\bullet[1]$ induced by the obvious maps $L^n \to C(f)^n \to K^{n + 1}$.
Lemma. Derived Hom, Ext and projective and locally free modules
Let $\mathcal{A}$ be an abelian category. Let $P^\bullet$ be a bounded above complex consisting of projective objects. Let $L^\bullet \in K(\mathcal{A})$. Then $$\operatorname{Mor}_{K(\mathcal{A})}(P^\bullet, L^\bullet)
\operatorname{Mor}_{D(\mathcal{A})}(P^\bullet, L^\bullet).$$
Proof. Dual to Lemma Injective resolutions and derived categories (uncovered prerequisite). $\square$
Lemma. Projective and locally free modules
Let $\mathcal{A}$ be an abelian category. Consider a solid diagram $$\begin{gathered}\begin{matrix}K^\bullet & L^\bullet \\ P^\bullet\end{matrix} \\[6pt] \begin{aligned}L^\bullet & \xrightarrow{\alpha} K^\bullet \\ P^\bullet & \longrightarrow K^\bullet \\ P^\bullet & \overset{\beta}{\dashrightarrow} L^\bullet\end{aligned}\end{gathered}$$ where $P^\bullet$ is bounded above and consists of projective objects, and $\alpha$ is a quasi-isomorphism.
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There exists a map of complexes $\beta$ making the diagram commute up to homotopy.
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If $\alpha$ is surjective in every degree then we can find a $\beta$ which makes the diagram commute.
Proof. Dual to Lemma Triangulated categories (uncovered prerequisite). $\square$
Lemma. Representability of a homological functor
Let $\mathcal{D}$ be a pre-triangulated category. For any object $W$ of $\mathcal{D}$ the functor $\operatorname{Hom}_\mathcal{D}(W, -)$ is homological, and the functor $\operatorname{Hom}_\mathcal{D}(-, W)$ is cohomological.
Proof. Consider a distinguished triangle $(X, Y, Z, f, g, h)$. We have already seen that $g \circ f = 0$, see Lemma Composition and triangulated categories. Suppose $a : W \to Y$ is a morphism such that $g \circ a = 0$. Then we get a commutative diagram $$\begin{gathered}\begin{matrix}W & W & 0 & W[1] \\ X & Y & Z & X[1]\end{matrix} \\[6pt] \begin{aligned}W & \xrightarrow{1} W \\ W & \overset{b}{\cdots\!\!\rightarrow} X \\ W & \longrightarrow 0 \\ W & \xrightarrow{a} Y \\ 0 & \longrightarrow W[1] \\ 0 & \xrightarrow{0} Z \\ W[1] & \overset{b[1]}{\cdots\!\!\rightarrow} X[1] \\ X & \longrightarrow Y \\ Y & \longrightarrow Z \\ Z & \longrightarrow X[1]\end{aligned}\end{gathered}$$ Both rows are distinguished triangles (use TR1 for the top row). Hence we can fill the dotted arrow $b$ (first rotate using TR2, then apply TR3, and then rotate back). This proves the lemma. $\square$
Lemma. Derived categories and tensor products and direct sums
Let $\mathcal{D}$ be a pre-triangulated category. Let $(X, Y, Z, f, g, h)$ and $(X', Y', Z', f', g', h')$ be triangles. The following are equivalent
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$(X \oplus X', Y \oplus Y', Z \oplus Z', f \oplus f', g \oplus g', h \oplus h')$ is a distinguished triangle,
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both $(X, Y, Z, f, g, h)$ and $(X', Y', Z', f', g', h')$ are distinguished triangles.
Proof. Assume (2). By TR1 we may choose a distinguished triangle $(X \oplus X', Y \oplus Y', Q, f \oplus f', g'', h'')$. By TR3 we can find morphisms of distinguished triangles $(X, Y, Z, f, g, h) \to (X \oplus X', Y \oplus Y', Q, f \oplus f', g'', h'')$ and $(X', Y', Z', f', g', h') \to (X \oplus X', Y \oplus Y', Q, f \oplus f', g'', h'')$. Taking the direct sum of these morphisms we obtain a morphism of triangles $$\begin{gathered}\begin{matrix}(X \oplus X', Y \oplus Y', Z \oplus Z', f \oplus f', g \oplus g', h \oplus h') \\ (X \oplus X', Y \oplus Y', Q, f \oplus f', g'', h'').\end{matrix} \\[6pt] \begin{aligned}(X \oplus X', Y \oplus Y', Z \oplus Z', f \oplus f', g \oplus g', h \oplus h') & \xrightarrow{(1, 1, c)} (X \oplus X', Y \oplus Y', Q, f \oplus f', g'', h'').\end{aligned}\end{gathered}$$ In the terminology of Remark Derived categories this is a map of special triangles (because a direct sum of special triangles is special) and we conclude that $c$ is an isomorphism. Thus (1) holds.
Assume (1). We will show that $(X, Y, Z, f, g, h)$ is a distinguished triangle. First observe that $(X, Y, Z, f, g, h)$ is a special triangle (terminology from Remark Derived categories) as a direct summand of the distinguished hence special triangle $(X \oplus X', Y \oplus Y', Z \oplus Z', f \oplus f', g \oplus g', h \oplus h')$. Using TR1 let $(X, Y, Q, f, g'', h'')$ be a distinguished triangle. By TR3 there exists a morphism of distinguished triangles $(X \oplus X', Y \oplus Y', Z \oplus Z', f \oplus f', g \oplus g', h \oplus h') \to (X, Y, Q, f, g'', h'')$. Composing this with the inclusion map we get a morphism of triangles $$(1, 1, c) : (X, Y, Z, f, g, h) \longrightarrow (X, Y, Q, f, g'', h'')$$ By Remark Derived categories we find that $c$ is an isomorphism and we conclude that (2) holds. $\square$
Lemma. Composition and triangulated categories
Let $\mathcal{D}$ be a pre-triangulated category. Let $(X, Y, Z, f, g, h)$ be a distinguished triangle. Then $g \circ f = 0$, $h \circ g = 0$ and $f[1] \circ h = 0$.
Proof. By TR1 we know $(X, X, 0, 1, 0, 0)$ is a distinguished triangle. Apply TR3 to $$\begin{gathered}\begin{matrix}X & X & 0 & X[1] \\ X & Y & Z & X[1]\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow X \\ X & \xrightarrow{1} X \\ X & \longrightarrow 0 \\ X & \xrightarrow{f} Y \\ 0 & \longrightarrow X[1] \\ 0 & \dashrightarrow Z \\ X[1] & \xrightarrow{1[1]} X[1] \\ X & \xrightarrow{f} Y \\ Y & \xrightarrow{g} Z \\ Z & \xrightarrow{h} X[1]\end{aligned}\end{gathered}$$ Of course the dotted arrow is the zero map. Hence the commutativity of the diagram implies that $g \circ f = 0$. For the other cases rotate the triangle, i.e., apply TR2. $\square$
Lemma. Triangulated categories (Grothendieck spectral sequence)
Assume the hypotheses of Lemma Composition and derived categories and that the equivalent conditions (1) and (2) hold. Let $X$ be an object of $D^{+}(\mathcal{A})$. There exists a spectral sequence $(E_r, d_r)_{r \geq 0}$ consisting of bigraded objects $E_r$ of $\mathcal{C}$ with $d_r$ of bidegree $(r, - r + 1)$ and with $$E_2^{p, q} = R^pG(H^q(RF(X)))$$ Moreover, this spectral sequence is bounded, converges to $H^*(R(G \circ F)(X))$, and induces a finite filtration on each $H^n(R(G \circ F)(X))$.
For an object $A$ of $\mathcal{A}$ we get $E_2^{p, q} = R^pG(R^qF(A))$ converging to $R^{p + q}(G \circ F)(A)$.
Proof. We may represent $X$ by a bounded below complex $A^\bullet$. Choose an injective resolution $A^\bullet \to I^\bullet$. Choose a Cartan-Eilenberg resolution $F(I^\bullet) \to I^{\bullet, \bullet}$ using Lemma Triangulated categories (uncovered prerequisite). Apply the second spectral sequence of Lemma Derived tensor products, Tor amplitude and derived categories. $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $\mathcal{A}$ be an abelian category. The functor $\text{Comp}(\mathcal{A}) \to D(\mathcal{A})$ defined above has the natural structure of a $\delta$-functor, with $$\delta_{A^\bullet \to B^\bullet \to C^\bullet} = - p \circ q^{-1}$$ with $p$ and $q$ as explained above. The same construction turns the functors $\text{Comp}^{+}(\mathcal{A}) \to D^{+}(\mathcal{A})$, $\text{Comp}^{-}(\mathcal{A}) \to D^{-}(\mathcal{A})$, and $\text{Comp}^b(\mathcal{A}) \to D^b(\mathcal{A})$ into $\delta$-functors.
Proof. We have already seen that this choice leads to a distinguished triangle whenever given a short exact sequence of complexes. We have to show that given a commutative diagram $$\begin{gathered}\begin{matrix}0 & A^\bullet & B^\bullet & C^\bullet & 0 \\ 0 & (A')^\bullet & (B')^\bullet & (C')^\bullet & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow A^\bullet \\ A^\bullet & \xrightarrow{a} B^\bullet \\ A^\bullet & \xrightarrow{f} (A')^\bullet \\ B^\bullet & \xrightarrow{b} C^\bullet \\ B^\bullet & \xrightarrow{g} (B')^\bullet \\ C^\bullet & \longrightarrow 0 \\ C^\bullet & \xrightarrow{h} (C')^\bullet \\ 0 & \longrightarrow (A')^\bullet \\ (A')^\bullet & \xrightarrow{a'} (B')^\bullet \\ (B')^\bullet & \xrightarrow{b'} (C')^\bullet \\ (C')^\bullet & \longrightarrow 0\end{aligned}\end{gathered}$$ we get the desired commutative diagram of Definition Derived tensor products and Tor amplitude (2). By Lemma Derived categories (uncovered prerequisite) the pair $(f, g)$ induces a canonical morphism $c : C(a)^\bullet \to C(a')^\bullet$. It is a simple computation to show that $q' \circ c = h \circ q$ and $f[1] \circ p = p' \circ c$. From this the result follows directly. $\square$
Definition. Saturated triangulated subcategories
Let $\mathcal{D}$ be a pre-triangulated category. We say a full pre-triangulated subcategory $\mathcal{D}'$ of $\mathcal{D}$ is saturated if whenever $X \oplus Y$ is isomorphic to an object of $\mathcal{D}'$ then both $X$ and $Y$ are isomorphic to objects of $\mathcal{D}'$.
Lemma. The preliminary adjunction comparison
Let $\mathcal{D}$ be a triangulated category. Let $\mathcal{A} \subset \mathcal{D}$ be a full subcategory invariant under all shifts. Consider a distinguished triangle $$X \to Y \to Z \to X[1]$$ of $\mathcal{D}$. The following are equivalent
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$Z$ is in $\mathcal{A}^\perp$, and
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$\operatorname{Hom}(A, X) = \operatorname{Hom}(A, Y)$ for all $A \in \operatorname{Ob}(\mathcal{A})$.
Proof. By Lemma Representability of a homological functor the functor $\operatorname{Hom}(A, -)$ is homological and hence we get a long exact sequence as in (Sheaf cohomology). Assume (1) and let $A \in \operatorname{Ob}(\mathcal{A})$. Then we consider the exact sequence $$\operatorname{Hom}(A[1], Z) \to \operatorname{Hom}(A, X) \to \operatorname{Hom}(A, Y) \to \operatorname{Hom}(A, Z)$$ Since $A[1] \in \operatorname{Ob}(\mathcal{A})$ we see that the first and last groups are zero. Thus we get (2). Assume (2) and let $A \in \operatorname{Ob}(\mathcal{A})$. Then we consider the exact sequence $$\operatorname{Hom}(A, X) \to \operatorname{Hom}(A, Y) \to \operatorname{Hom}(A, Z) \to \operatorname{Hom}(A[-1], X) \to \operatorname{Hom}(A[-1], Y)$$ and we conclude that $\operatorname{Hom}(A, Z) = 0$ as desired. $\square$
Lemma. A triangulated orthogonal subcategory
Let $\mathcal{D}$ be a triangulated category. Let $\mathcal{A} \subset \mathcal{D}$ be a full subcategory invariant under all shifts. Then both the right orthogonal $\mathcal{A}^\perp$ and the left orthogonal ${}^\perp\mathcal{A}$ of $\mathcal{A}$ are strictly full, saturated[^1], triangulated subcategories of $\mathcal{D}$.
Proof. It is immediate from the definitions that the orthogonals are preserved under taking shifts, direct sums, and direct summands. Consider a distinguished triangle $$X \to Y \to Z \to X[1]$$ of $\mathcal{D}$. By Lemma Derived categories (uncovered prerequisite) it suffices to show that if $X$ and $Y$ are in $\mathcal{A}^\perp$, then $Z$ is in $\mathcal{A}^\perp$. This is immediate from Lemma The preliminary adjunction comparison. $\square$
Proposition. The nine-triangle lemma
Let $\mathcal{D}$ be a triangulated category. Any commutative diagram $$\begin{gathered}\begin{matrix}X & Y \\ X' & Y'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow Y \\ X & \longrightarrow X' \\ Y & \longrightarrow Y' \\ X' & \longrightarrow Y'\end{aligned}\end{gathered}$$ can be extended to a diagram $$\begin{gathered}\begin{matrix}X & Y & Z & X[1] \\ X' & Y' & Z' & X'[1] \\ X'' & Y'' & Z'' & X''[1] \\ X[1] & Y[1] & Z[1] & X[2]\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow Y \\ X & \longrightarrow X' \\ Y & \longrightarrow Z \\ Y & \longrightarrow Y' \\ Z & \longrightarrow X[1] \\ Z & \longrightarrow Z' \\ X[1] & \longrightarrow X'[1] \\ X' & \longrightarrow Y' \\ X' & \longrightarrow X'' \\ Y' & \longrightarrow Z' \\ Y' & \longrightarrow Y'' \\ Z' & \longrightarrow X'[1] \\ Z' & \longrightarrow Z'' \\ X'[1] & \longrightarrow X''[1] \\ X'' & \longrightarrow Y'' \\ X'' & \longrightarrow X[1] \\ Y'' & \longrightarrow Z'' \\ Y'' & \longrightarrow Y[1] \\ Z'' & \longrightarrow X''[1] \\ Z'' & \longrightarrow Z[1] \\ X''[1] & \longrightarrow X[2] \\ X[1] & \longrightarrow Y[1] \\ Y[1] & \longrightarrow Z[1] \\ Z[1] & \longrightarrow X[2]\end{aligned}\end{gathered}$$ where all the squares are commutative, except for the lower right square which is anticommutative. Moreover, each of the first three rows and columns is a distinguished triangle. The bottom row and right column become distinguished triangles after negating their last arrows. Finally, the morphisms on the bottom row (resp. right column) are obtained from the morphisms of the top row (resp. left column) by applying $[1]$.
Proof. During this proof we avoid writing the arrows in order to make the proof legible. Choose distinguished triangles $(X, Y, Z)$, $(X', Y', Z')$, $(X, X', X'')$, $(Y, Y', Y'')$, and $(X, Y', A)$. Note that the morphism $X \to Y'$ is both equal to the composition $X \to Y \to Y'$ and equal to the composition $X \to X' \to Y'$. Hence, we can find morphisms
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$a : Z \to A$ and $b : A \to Y''$, and
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$a' : X'' \to A$ and $b' : A \to Z'$
as in TR4. Denote $c : Y'' \to Z[1]$ the composition $Y'' \to Y[1] \to Z[1]$ and denote $c' : Z' \to X''[1]$ the composition $Z' \to X'[1] \to X''[1]$. The conclusion of our application of TR4 is that
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$(Z, A, Y'', a, b, c)$, $(X'', A, Z', a', b', c')$ are distinguished triangles,
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$(X, Y, Z) \to (X, Y', A)$, $(X, Y', A) \to (Y, Y', Y'')$, $(X, X', X'') \to (X, Y', A)$, $(X, Y', A) \to (X', Y', Z')$ are morphisms of triangles.
First using that $(X, X', X'') \to (X, Y', A)$ and $(X, Y', A) \to (Y, Y', Y'')$ are morphisms of triangles we see the first of the diagrams $$\begin{gathered}\begin{matrix}X' & Y' \\ X'' & Y'' \\ X[1] & Y[1]\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow Y' \\ X' & \longrightarrow X'' \\ Y' & \longrightarrow Y'' \\ X'' & \xrightarrow{b \circ a'} Y'' \\ X'' & \longrightarrow X[1] \\ Y'' & \longrightarrow Y[1] \\ X[1] & \longrightarrow Y[1]\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}Y & Z & X[1] \\ Y' & Z' & X'[1]\end{matrix} \\[6pt] \begin{aligned}Y & \longrightarrow Z \\ Y & \longrightarrow Y' \\ Z & \xrightarrow{b' \circ a} Z' \\ Z & \longrightarrow X[1] \\ X[1] & \longrightarrow X'[1] \\ Y' & \longrightarrow Z' \\ Z' & \longrightarrow X'[1]\end{aligned}\end{gathered}$$ is commutative. The second is commutative too using that $(X, Y, Z) \to (X, Y', A)$ and $(X, Y', A) \to (X', Y', Z')$ are morphisms of triangles. At this point we choose a distinguished triangle $(X'', Y'' , Z'')$ starting with the map $b \circ a' : X'' \to Y''$.
Next we apply TR4 one more time to the morphisms $X'' \to A \to Y''$ and the triangles $(X'', A, Z', a', b', c')$, $(X'', Y'', Z'')$, and $(A, Y'', Z[1], b, c , -a[1])$ to get morphisms $a'' : Z' \to Z''$ and $b'' : Z'' \to Z[1]$. Then $(Z', Z'', Z[1], a'', b'', - b'[1] \circ a[1])$ is a distinguished triangle, hence also $(Z, Z', Z'', -b' \circ a, a'', -b'')$ and hence also $(Z, Z', Z'', b' \circ a, a'', b'')$. Moreover, $(X'', A, Z') \to (X'', Y'', Z'')$ and $(X'', Y'', Z'') \to (A, Y'', Z[1], b, c , -a[1])$ are morphisms of triangles. At this point we have defined all the distinguished triangles and all the morphisms, and all that's left is to verify some commutativity relations.
To see that the middle square in the diagram commutes, note that the arrow $Y' \to Z'$ factors as $Y' \to A \to Z'$ because $(X, Y', A) \to (X', Y', Z')$ is a morphism of triangles. Similarly, the morphism $Y' \to Y''$ factors as $Y' \to A \to Y''$ because $(X, Y', A) \to (Y, Y', Y'')$ is a morphism of triangles. Hence the middle square commutes because the square with sides $(A, Z', Z'', Y'')$ commutes as $(X'', A, Z') \to (X'', Y'', Z'')$ is a morphism of triangles (by TR4). The square with sides $(Y'', Z'', Y[1], Z[1])$ commutes because $(X'', Y'', Z'') \to (A, Y'', Z[1], b, c , -a[1])$ is a morphism of triangles and $c : Y'' \to Z[1]$ is the composition $Y'' \to Y[1] \to Z[1]$. The square with sides $(Z', X'[1], X''[1], Z'')$ is commutative because $(X'', A, Z') \to (X'', Y'', Z'')$ is a morphism of triangles and $c' : Z' \to X''[1]$ is the composition $Z' \to X'[1] \to X''[1]$. Finally, we have to show that the square with sides $(Z'', X''[1], Z[1], X[2])$ anticommutes. This holds because $(X'', Y'', Z'') \to (A, Y'', Z[1], b, c , -a[1])$ is a morphism of triangles and we're done. $\square$
Lemma. Brown representability
Source credit: the original source citation Neeman-Grothendieck (Theorem 3.1).
Let $\mathcal{D}$ be a triangulated category with direct sums which is compactly generated. Let $H : \mathcal{D} \to \textit{Ab}$ be a contravariant cohomological functor which transforms direct sums into products. Then $H$ is representable.
Proof. Let $E_i$, $i \in I$ be a set of compact objects such that $\bigoplus_{i \in I} E_i$ generates $\mathcal{D}$. We may and do assume that the set of objects $\{E_i\}$ is preserved under shifts. Consider pairs $(i, a)$ where $i \in I$ and $a \in H(E_i)$ and set $$X_1 = \bigoplus\nolimits_{(i, a)} E_i$$ Since $H(X_1) = \prod_{(i, a)} H(E_i)$ we see that $(a)_{(i, a)}$ defines an element $a_1 \in H(X_1)$. Set $H_1 = \operatorname{Hom}_\mathcal{D}(- , X_1)$. By Yoneda's lemma (Categories, Lemma The geometric construction (uncovered prerequisite)) the element $a_1$ defines a natural transformation $H_1 \to H$.
We are going to inductively construct $X_n$ and transformations $a_n : H_n \to H$ where $H_n = \operatorname{Hom}_\mathcal{D}(-, X_n)$. Namely, we apply the procedure above to the functor $\operatorname{Ker}(H_n \to H)$ to get an object $$K_{n + 1} = \bigoplus\nolimits_{(i, k),\ k \in \operatorname{Ker}(H_n(E_i) \to H(E_i))} E_i$$ and a transformation $\operatorname{Hom}_\mathcal{D}(-, K_{n + 1}) \to \operatorname{Ker}(H_n \to H)$. By Yoneda's lemma the composition $\operatorname{Hom}_\mathcal{D}(-, K_{n + 1}) \to H_n$ gives a morphism $K_{n + 1} \to X_n$. We choose a distinguished triangle $$K_{n + 1} \to X_n \to X_{n + 1} \to K_{n + 1}[1]$$ in $\mathcal{D}$. The element $a_n \in H(X_n)$ maps to zero in $H(K_{n + 1})$ by construction. Since $H$ is cohomological we can lift it to an element $a_{n + 1} \in H(X_{n + 1})$.
We claim that $X = \text{hocolim} X_n$ represents $H$. Applying $H$ to the defining distinguished triangle $$\bigoplus X_n \to \bigoplus X_n \to X \to \bigoplus X_n[1]$$ we obtain an exact sequence $$\prod H(X_n) \leftarrow \prod H(X_n) \leftarrow H(X)$$ Thus there exists an element $a \in H(X)$ mapping to $(a_n)$ in $\prod H(X_n)$. Hence there is a natural transformation $\operatorname{Hom}_\mathcal{D}(- , X) \to H$ such that $$\operatorname{Hom}_\mathcal{D}(-, X_1) \to \operatorname{Hom}_\mathcal{D}(-, X_2) \to \operatorname{Hom}_\mathcal{D}(-, X_3) \to \ldots \to \operatorname{Hom}_\mathcal{D}(-, X) \to H$$ commutes. For each $i$ the map $\operatorname{Hom}_\mathcal{D}(E_i, X) \to H(E_i)$ is surjective, by construction of $X_1$. On the other hand, by construction of $X_n \to X_{n + 1}$ the kernel of $\operatorname{Hom}_\mathcal{D}(E_i, X_n) \to H(E_i)$ is killed by the map $\operatorname{Hom}_\mathcal{D}(E_i, X_n) \to \operatorname{Hom}_\mathcal{D}(E_i, X_{n + 1})$. Since $$\operatorname{Hom}_\mathcal{D}(E_i, X) = \mathop{\operatorname{colim}} \operatorname{Hom}_\mathcal{D}(E_i, X_n)$$ by Lemma Tensor products and direct sums (uncovered prerequisite) we see that $\operatorname{Hom}_\mathcal{D}(E_i, X) \to H(E_i)$ is injective.
To finish the proof, consider the subcategory $$\mathcal{D}' = \{Y \in \operatorname{Ob}(\mathcal{D}) \mid \operatorname{Hom}_\mathcal{D}(Y[n], X) \to H(Y[n]) \text{ is an isomorphism for all }n\}$$ As $\operatorname{Hom}_\mathcal{D}(-, X) \to H$ is a transformation between cohomological functors, the subcategory $\mathcal{D}'$ is a strictly full, saturated, triangulated subcategory of $\mathcal{D}$ (details omitted; see proof of Lemma Derived tensor products and Tor amplitude (uncovered prerequisite)). Moreover, as both $H$ and $\operatorname{Hom}_\mathcal{D}(-, X)$ transform direct sums into products, we see that direct sums of objects of $\mathcal{D}'$ are in $\mathcal{D}'$. Thus derived colimits of objects of $\mathcal{D}'$ are in $\mathcal{D}'$. Since $\{E_i\}$ is preserved under shifts, we see that $E_i$ is an object of $\mathcal{D}'$ for all $i$. It follows from Lemma Filtered limits and triangulated categories (uncovered prerequisite) that $\mathcal{D}' = \mathcal{D}$ and the proof is complete. $\square$
Lemma. Triangulated categories
Let $F : \mathcal{D} \to \mathcal{D}'$ be an exact functor between triangulated categories. If $F$ admits a right adjoint $G: \mathcal{D'} \to \mathcal{D}$, then $G$ is also an exact functor.
Proof. Let $\xi_X : F(X[1]) \to F(X)[1]$ be as in Definition Derived tensor products, Tor amplitude and derived categories. Let $\epsilon_A : F(G(A)) \to A$ be the adjunction map. Consider the composition $$F(G(A)[1]) \xrightarrow{\xi_{G(A)}} F(G(A))[1] \xrightarrow{\epsilon_A[1]} A[1]$$ This map is adjoint to a map $G(A)[1] \to G(A[1])$ which we claim to be an isomorphism. To see this, by the Yoneda lemma it suffices to show that we get a bijection on applying $\operatorname{Mor}_\mathcal{D}(X[1], -)$ for every object $X$ of $\mathcal{D}$. Now, every morphism $f : X[1] \to G(A)[1]$ is of the form $g[1]$ for a unique $g : X \to G(A)$ and every $g$ is adjoint to a unique $h : F(X) \to A$ and in turn $h[1] \circ \xi_X$ is adjoint to a unique $i : X[1] \to G(A[1])$. The rule sending $f$ to $i$ gives a bijection between $\operatorname{Mor}_\mathcal{D}(X[1], G(A)[1])$ and $\operatorname{Mor}_\mathcal{D}(X[1], G(A[1]))$. That this bijection is given by the morphism above follows from the discussion in Categories, Section The geometric construction and the following calculation $$\begin{aligned} \epsilon_A[1] \circ \xi_{G(A)} \circ F(f) & = \epsilon_A[1] \circ \xi_{G(A)} \circ F(g[1]) \\ & = \epsilon_A[1] \circ F(g)[1] \circ \xi_X \\ & = (\epsilon_A \circ F(g))[1] \circ \xi_X \\ & = h[1] \circ \xi_X \end{aligned}$$ Some details omitted. We will show that $G$ is an exact functor using the inverse of the isomorphisms $G(A)[1] \to G(A[1])$. These isomorphisms are functorial in $A$ (details omitted).
Let $A \to B \to C \to A[1]$ be a distinguished triangle in $\mathcal{D}'$. Choose a distinguished triangle $$G(A) \to G(B) \to X \to G(A)[1]$$ in $\mathcal{D}$. Then $F(G(A)) \to F(G(B)) \to F(X) \to F(G(A))[1]$ is a distinguished triangle in $\mathcal{D}'$. By TR3 we can choose a morphism of distinguished triangles $$\begin{gathered}\begin{matrix}F(G(A)) & F(G(B)) & F(X) & F(G(A))[1] \\ A & B & C & A[1]\end{matrix} \\[6pt] \begin{aligned}F(G(A)) & \longrightarrow F(G(B)) \\ F(G(A)) & \xrightarrow{\epsilon_A} A \\ F(G(B)) & \longrightarrow F(X) \\ F(G(B)) & \xrightarrow{\epsilon_B} B \\ F(X) & \longrightarrow F(G(A))[1] \\ F(X) & \longrightarrow C \\ F(G(A))[1] & \xrightarrow{\epsilon_A[1]} A[1] \\ A & \longrightarrow B \\ B & \longrightarrow C \\ C & \longrightarrow A[1]\end{aligned}\end{gathered}$$ Recall that the arrow $F(X) \to F(G(A))[1]$ is the composition of $F(X) \to F(G(A)[1])$ with $\xi_{G(A)}$. Hence using that $G$ is the right adjoint of $F$ and our discussion above, we conclude the existence of a morphism $X \to G(C)$ such that the diagram $$\begin{gathered}\begin{matrix}G(A) & G(B) & X & G(A)[1] \\ G(A) & G(B) & G(C) & G(A[1])\end{matrix} \\[6pt] \begin{aligned}G(A) & \longrightarrow G(B) \\ G(A) & \longrightarrow G(A) \\ G(B) & \longrightarrow X \\ G(B) & \longrightarrow G(B) \\ X & \longrightarrow G(A)[1] \\ X & \longrightarrow G(C) \\ G(A)[1] & \longrightarrow G(A[1]) \\ G(A) & \longrightarrow G(B) \\ G(B) & \longrightarrow G(C) \\ G(C) & \longrightarrow G(A[1])\end{aligned}\end{gathered}$$ commutes and the right vertical arrow is the morphism constructed above. Applying the homological functor $\operatorname{Hom}_{\mathcal{D}}(W, -)$ for an object $W$ of $\mathcal{D}$ we deduce from the $5$ lemma that $$\operatorname{Hom}_{\mathcal{D}}(W, X) \to \operatorname{Hom}_{\mathcal{D}}(W, G(C))$$ is a bijection and using the Yoneda lemma once more we conclude that $X \to G(C)$ is an isomorphism. Hence we conclude that $G(A) \to G(B) \to G(C) \to G(A)[1]$ is a distinguished triangle which is what we wanted to show. $\square$
Lemma. Composition and derived categories
Let $\mathcal{A}, \mathcal{B}, \mathcal{C}$ be abelian categories. Let $F : \mathcal{A} \to \mathcal{B}$ and $G : \mathcal{B} \to \mathcal{C}$ be left exact functors. Assume $\mathcal{A}$, $\mathcal{B}$ have enough injectives. The following are equivalent
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$F(I)$ is right acyclic for $G$ for each injective object $I$ of $\mathcal{A}$, and
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the canonical map $$t : R(G \circ F) \longrightarrow RG \circ RF$$ is an isomorphism of functors from $D^{+}(\mathcal{A})$ to $D^{+}(\mathcal{C})$.
Proof. If (2) holds, then (1) follows by evaluating the isomorphism $t$ at $I[0]$, using $RF(I[0]) = F(I)[0]$. Conversely, assume (1) holds. Let $A^\bullet$ be a bounded below complex of $\mathcal{A}$. Choose an injective resolution $A^\bullet \to I^\bullet$. The map $t$ is given (see proof of Lemma Composition and derived categories (uncovered prerequisite)) by the maps $$R(G \circ F)(A^\bullet) = (G \circ F)(I^\bullet) = G(F(I^\bullet)) \to RG(F(I^\bullet)) = RG(RF(A^\bullet))$$ where the arrow is an isomorphism by Lemma Sheaf cohomology (uncovered prerequisite). $\square$
Lemma. Computation of a homotopy colimit
Let $\mathcal{A}$ be an abelian category. Assume colimits over $\mathbf{N}$ exist and are exact. Then countable direct sums exist and are exact. Moreover, if $(A_n, f_n)$ is a system over $\mathbf{N}$, then there is a short exact sequence $$0 \to \bigoplus A_n \to \bigoplus A_n \to \mathop{\operatorname{colim}} A_n \to 0$$ where the first map in degree $n$ is given by $1 - f_n$.
Proof. The first statement follows from $\bigoplus A_n = \mathop{\operatorname{colim}} (A_1 \oplus \ldots \oplus A_n)$. For the second, note that for each $n$ we have the short exact sequence $$0 \to A_1 \oplus \ldots \oplus A_{n - 1} \to A_1 \oplus \ldots \oplus A_n \to A_n \to 0$$ where the first map is given by the maps $1 - f_i$ and the second map is the sum of the transition maps. Take the colimit to get the sequence of the lemma. $\square$
Lemma. Triangulated categories
Let $\mathcal{D}$, $\mathcal{D}'$ be triangulated categories. Let $F : \mathcal{D} \to \mathcal{D}'$ and $G : \mathcal{D}' \to \mathcal{D}$ be functors. Assume that
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$F$ and $G$ are exact functors,
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$F$ is fully faithful,
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$G$ is a right adjoint to $F$, and
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the kernel of $G$ is zero.
Then $F$ is an equivalence of categories.
Proof. Since $F$ is fully faithful the adjunction map $\text{id} \to G \circ F$ is an isomorphism (Categories, Lemma The geometric construction (uncovered prerequisite)). Let $X$ be an object of $\mathcal{D}'$. Choose a distinguished triangle $$F(G(X)) \to X \to Y \to F(G(X))[1]$$ in $\mathcal{D}'$. Applying $G$ and using that $G(F(G(X))) = G(X)$ we find a distinguished triangle $$G(X) \to G(X) \to G(Y) \to G(X)[1]$$ Hence $G(Y) = 0$. Thus $Y = 0$. Thus $F(G(X)) \to X$ is an isomorphism. $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $F : \mathcal{A} \to \mathcal{B}$ be an exact functor of abelian categories. Then
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every object of $\mathcal{A}$ is right acyclic for $F$,
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$RF : D^{+}(\mathcal{A}) \to D^{+}(\mathcal{B})$ is everywhere defined,
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$RF : D(\mathcal{A}) \to D(\mathcal{B})$ is everywhere defined,
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every complex computes $RF$, in other words, the canonical map $F(K^\bullet) \to RF(K^\bullet)$ is an isomorphism for all complexes, and
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$R^iF = 0$ for $i \not = 0$.
Proof. This is true because $F$ transforms acyclic complexes into acyclic complexes and quasi-isomorphisms into quasi-isomorphisms. Details omitted. $\square$
[^1]: Definition Saturated triangulated subcategories.
Ampleness and Noetherian geometry
Lemma. Projective, locally free modules and finite algebras
Source credit: the original source citation FAC (Chapter II, §4, no. 50, Corollary, pp. 242--243)
The cited corollary treats coherent algebraic sheaves on a connected classical affine variety and obtains a locally free sheaf from a finite projective module. The statement below separates the affine module criterion from the sheaf criterion and works on an arbitrary scheme. Its rank is locally constant; connectedness is needed only to replace that function by one constant integer.
Let $X$ be a scheme. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. The following are equivalent:
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$\mathcal{F}$ is a flat $\mathcal{O}_X$-module of finite presentation,
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$\mathcal{F}$ is $\mathcal{O}_X$-module of finite presentation and for all $x \in X$ the stalk $\mathcal{F}_x$ is a free $\mathcal{O}_{X, x}$-module,
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$\mathcal{F}$ is a locally free, finite type $\mathcal{O}_X$-module,
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$\mathcal{F}$ is a finite locally free $\mathcal{O}_X$-module, and
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$\mathcal{F}$ is an $\mathcal{O}_X$-module of finite type, for every $x \in X$ the stalk $\mathcal{F}_x$ is a free $\mathcal{O}_{X, x}$-module, and the function $$\rho_\mathcal{F} : X \to \mathbf{Z}, \quad x \longmapsto \dim_{\kappa(x)} \mathcal{F}_x \otimes_{\mathcal{O}_{X, x}} \kappa(x)$$ is locally constant in the Zariski topology on $X$.
Proof. This lemma immediately reduces to the affine case. In this case the lemma is a reformulation of Algebra, Lemma Characterizations of finite projective modules. The translation uses Lemmas Modules and finite algebras, Finite presentation and modules, Flatness and modules, and Projective, locally free modules and local algebra. $\square$
Lemma. Modules and finite algebras
Source credit: the original source citation FAC (Chapter II, §3, no. 45, Theorem 2, Corollary 1, p. 238) The finite-generation statement for global sections of a coherent sheaf is the original source citation FAC (Chapter II, §4, no. 49, opening paragraph, p. 241).
The cited corollary proves that a coherent algebraic sheaf on an affine classical variety is a quotient of a finite free sheaf by combining stalkwise generation by global sections with quasi-compactness. The lemma below identifies finite type quasi-coherent modules on affine schemes with finite modules. Choosing finitely many generators of the corresponding module gives the same quotient, without irreducibility or reducedness hypotheses. In no. 49 the source applies affine exactness of global sections to such a finite free quotient and concludes that the global-section module is finite. The equivalence below packages both directions and needs only finite type and quasi-coherence on an arbitrary affine scheme.
Let $X = \operatorname{Spec}(R)$ be an affine scheme. The quasi-coherent sheaf of $\mathcal{O}_X$-modules $\widetilde M$ is a finite type $\mathcal{O}_X$-module if and only if $M$ is a finite $R$-module.
Proof. Assume $\widetilde M$ is a finite type $\mathcal{O}_X$-module. This means there exists an open covering of $X$ such that $\widetilde M$ restricted to the members of this covering is globally generated by finitely many sections. Thus there also exists a standard open covering $X = \bigcup_{i = 1, \ldots, n} D(f_i)$ such that $\widetilde M|_{D(f_i)}$ is generated by finitely many sections. Thus $M_{f_i}$ is finitely generated for each $i$. Hence we conclude by Algebra, Lemma A finite cover by affine localizations. $\square$
Lemma. Line bundles and ampleness
In Situation An invertible sheaf and its section-open subsets. The canonical morphism $f : X \to Y$ maps $X$ into the open subscheme $W = W_1 \subset Y$ where $\mathcal{O}_Y(1)$ is invertible and where all multiplication maps $\mathcal{O}_Y(n) \otimes_{\mathcal{O}_Y} \mathcal{O}_Y(m) \to \mathcal{O}_Y(n + m)$ are isomorphisms (see Constructions, Lemma Line bundles and ampleness (uncovered prerequisite)). Moreover, the maps $f^*\mathcal{O}_Y(n) \to \mathcal{L}^{\otimes n}$ are all isomorphisms.
Proof. By Proposition Criteria for line bundles and ampleness there exists an integer $n_0$ such that $\mathcal{L}^{\otimes n}$ is globally generated for all $n \geq n_0$. Let $x \in X$ be a point. By the above we can find $a \in S_{n_0}$ and $b \in S_{n_0 + 1}$ such that $a$ and $b$ do not vanish at $x$. Hence $f(x) \in D_{+}(a) \cap D_{+}(b) = D_{+}(ab)$. By Constructions, Lemma Line bundles and ampleness (uncovered prerequisite) we see that $f(x) \in W_1$ as desired. By Constructions, Lemma Line bundles and ampleness (uncovered prerequisite) which was used in the construction of the map $f$ the maps $f^*\mathcal{O}_Y(n_0) \to \mathcal{L}^{\otimes n_0}$ and $f^*\mathcal{O}_Y(n_0 + 1) \to \mathcal{L}^{\otimes n_0 + 1}$ are isomorphisms in a neighbourhood of $x$. By compatibility with the algebra structure and the fact that $f$ maps into $W$ we conclude all the maps $f^*\mathcal{O}_Y(n) \to \mathcal{L}^{\otimes n}$ are isomorphisms in a neighbourhood of $x$. Hence we win. $\square$
Lemma. Scheme geometry
Let $X$ be a scheme. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Set $S = \Gamma_*(X, \mathcal{L})$ as a graded ring. If every point of $X$ is contained in one of the open subschemes $X_s$, for some $s \in S_{+}$ homogeneous, then there is a canonical morphism of schemes $$f : X \longrightarrow Y = \text{Proj}(S),$$ to the homogeneous spectrum of $S$ (see Constructions, Section The geometric construction). This morphism has the following properties
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$f^{-1}(D_{+}(s)) = X_s$ for any $s \in S_{+}$ homogeneous,
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there are $\mathcal{O}_X$-module maps $f^*\mathcal{O}_Y(n) \to \mathcal{L}^{\otimes n}$ compatible with multiplication maps, see Constructions, Equation (The geometric construction),
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the composition $S_n \to \Gamma(Y, \mathcal{O}_Y(n)) \to \Gamma(X, \mathcal{L}^{\otimes n})$ is the identity map, and
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for every $x \in X$ there is an integer $d \geq 1$ and an open neighbourhood $U \subset X$ of $x$ such that $f^*\mathcal{O}_Y(dn)|_U \to \mathcal{L}^{\otimes dn}|_U$ is an isomorphism for all $n \in \mathbf{Z}$.
Proof. Denote $\psi : S \to \Gamma_*(X, \mathcal{L})$ the identity map. We are going to use the triple $(U(\psi), r_{\mathcal{L}, \psi}, \theta)$ of Constructions, Lemma Line bundles and ampleness (uncovered prerequisite). By assumption the open subscheme $U(\psi)$ of equals $X$. Hence $r_{\mathcal{L}, \psi} : U(\psi) \to Y$ is defined on all of $X$. We set $f = r_{\mathcal{L}, \psi}$. The maps in part (2) are the components of $\theta$. Part (3) follows from condition (2) in the lemma cited above. Part (1) follows from (3) combined with condition (1) in the lemma cited above. Part (4) follows from the last statement in Constructions, Lemma Line bundles and ampleness (uncovered prerequisite) since the map $\alpha$ mentioned there is an isomorphism. $\square$
Lemma. Affine neighbourhoods
Let $X$ be a scheme. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Let $s \in \Gamma(X, \mathcal{L})$. For any affine $U \subset X$ the intersection $U \cap X_s$ is affine.
Proof. This translates into the following algebra problem. Let $R$ be a ring. Let $N$ be an invertible $R$-module (i.e., locally free of rank 1). Let $s \in N$ be an element. Then $V = \{\mathfrak p \mid s \not \in \mathfrak p N\}$ is an affine open subset of $\operatorname{Spec}(R)$.
Let $A = \bigoplus_{n \geq 0} A_n$ be the symmetric algebra of $N$ (which is commutative) and view $s$ as an element of $A_1$. Set $B = A/(s - 1)A$. This is an $R$-algebra whose construction commutes with any base change $R \to R'$. Thus $B' = B \otimes_R R'$ is the zero ring if $s$ maps to zero in $N' = N \otimes_R R'$. It follows that if $x \in \operatorname{Spec}(R) \setminus V$, then $B \otimes_R \kappa(x) = 0$. We conclude that $\operatorname{Spec}(B) \to \operatorname{Spec}(R)$ factors through $V$ as the fibres over $x \not \in V$ are empty. On the other hand, if $\operatorname{Spec}(R') \subset V$ is an affine open, then $s$ maps to a basis element of $N'$ and we see that $B' = R'[s]/(s - 1) \cong R'$. It follows that $\operatorname{Spec}(B) \to V$ is an isomorphism and $V$ is indeed affine. $\square$
Lemma. Line bundles, ampleness and affine neighbourhoods
Let $X$ be a scheme. Let $\mathcal{L}$ be an ample invertible sheaf on $X$. Let $$E \subset W \subset X$$ with $E$ finite and $W$ open in $X$. Then there exists an $n > 0$ and a section $s \in \Gamma(X, \mathcal{L}^{\otimes n})$ such that $X_s$ is affine and $E \subset X_s \subset W$.
Proof. The reader can modify the proof of Lemma Line bundles, ampleness and affine neighbourhoods to prove this lemma; we will instead deduce the lemma from it. By Lemma Line bundles, ampleness and affine neighbourhoods we can choose an affine open $U \subset W$ such that $E \subset U$. Consider the graded ring $S = \Gamma_*(X, \mathcal{L}) = \bigoplus_{n \geq 0} \Gamma(X, \mathcal{L}^{\otimes n})$. For each $x \in E$ let $\mathfrak p_x \subset S$ be the graded ideal of sections vanishing at $x$. It is clear that $\mathfrak p_x$ is a prime ideal and since some power of $\mathcal{L}$ is globally generated, it is clear that $S_{+} \not \subset \mathfrak p_x$. Let $I \subset S$ be the graded ideal of sections vanishing on all points of $X \setminus U$. Since the sets $X_s$ form a basis for the topology we see that $I \not \subset \mathfrak p_x$ for all $x \in E$. By (graded) prime avoidance (Algebra, Lemma A graded finite-generation calculation) we can find $s \in I$ homogeneous with $s \not \in \mathfrak p_x$ for all $x \in E$. Then $E \subset X_s \subset U$ and $X_s$ is affine by Lemma Affine neighbourhoods. $\square$
Proposition. Criteria for line bundles and ampleness
Source credit: the original source citation FAC (Chapter III, §2, no. 55, Theorem 1 and Corollary, pp. 247--248) the original source citation FAC (Chapter III, §3, no. 66, Theorem 2(a), p. 259)
For $\mathcal{O}_{\mathbf{P}_r(K)}(1)$, the cited theorem proves that every coherent algebraic sheaf becomes generated by global sections after every sufficiently large twist. Its corollary rewrites finite global generation as a quotient by a finite direct sum of one twist of the structure sheaf. These are respectively the projective-space cases of (the indicated step) and (the indicated step) below. The proposition makes them part of the characterization of an arbitrary ample invertible sheaf and replaces the chart-by-chart argument by a scheme-theoretic equivalence.
No. 66 applies the same conclusion to a closed projective variety using the restricted hyperplane bundle: every coherent algebraic sheaf becomes globally generated after every sufficiently large twist. Condition (the indicated step) below gives exactly this assertion for every finite-type quasi-coherent sheaf and every ample invertible sheaf on a quasi-compact scheme.
Let $X$ be a quasi-compact scheme. Let $\mathcal{L}$ be an invertible sheaf on $X$. Set $S = \Gamma_*(X, \mathcal{L})$. The following are equivalent:
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$\mathcal{L}$ is ample,
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the open sets $X_s$, with $s \in S_{+}$ homogeneous, cover $X$ and the associated morphism $X \to \text{Proj}(S)$ is an open immersion,
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the open sets $X_s$, with $s \in S_{+}$ homogeneous, form a basis for the topology of $X$,
the open sets $X_s$, with $s \in S_{+}$ homogeneous, which are affine form a basis for the topology of $X$,
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for every quasi-coherent sheaf $\mathcal{F}$ on $X$ the sum of the images of the canonical maps $$\Gamma(X, \mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{L}^{\otimes n}) \otimes_{\mathbf{Z}} \mathcal{L}^{\otimes -n} \longrightarrow \mathcal{F}$$ with $n \geq 1$ equals $\mathcal{F}$,
same property as ([the indicated step](#native-properties-item-qc-gg)) with $\mathcal{F}$ ranging over all quasi-coherent sheaves of ideals,
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$X$ is quasi-separated and for every quasi-coherent sheaf $\mathcal{F}$ of finite type on $X$ there exists an integer $n_0$ such that $\mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{L}^{\otimes n}$ is globally generated for all $n \geq n_0$,
$X$ is quasi-separated and for every quasi-coherent sheaf $\mathcal{F}$ of finite type on $X$ there exist integers $n > 0$, $k \geq 0$ such that $\mathcal{F}$ is a quotient of a direct sum of $k$ copies of $\mathcal{L}^{\otimes - n}$, and
- same as in (the indicated step) with $\mathcal{F}$ ranging over all sheaves of ideals of finite type on $X$.
Proof. Lemma Line bundles, ampleness and diagonals and separation is (the indicated step) $\Rightarrow$ (the indicated step). Lemmas Line bundles and ampleness and Line bundles and ampleness provide the implication (the indicated step) $\Leftarrow$ (the indicated step). The implications (the indicated step) $\Rightarrow$ (the indicated step) $\Rightarrow$ (the indicated step) are clear from Constructions, Section The geometric construction. Lemma Affine neighbourhoods is (the indicated step) $\Rightarrow$ (the indicated step). Thus we see that the first 4 conditions are all equivalent.
Assume the equivalent conditions (1) -- (4). Note that in particular $X$ is separated (as an open subscheme of the separated scheme $\text{Proj}(S)$). Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Choose $s \in S_{+}$ homogeneous such that $X_s$ is affine. We claim that any section $m \in \Gamma(X_s, \mathcal{F})$ is in the image of one of the maps displayed in (the indicated step) above. This will imply (the indicated step) since these affines $X_s$ cover $X$. Namely, by Lemma Scheme geometry we may write $m$ as the image of $m' \otimes s^{-n}$ for some $n \geq 1$, some $m' \in \Gamma(X, \mathcal{F} \otimes \mathcal{L}^{\otimes n})$. This proves the claim.
Clearly (the indicated step) $\Rightarrow$ (the indicated step). Let us assume (the indicated step) and prove $\mathcal{L}$ is ample. Pick $x \in X$. Let $U \subset X$ be an affine open which contains $x$. Set $Z = X \setminus U$. We may think of $Z$ as a reduced closed subscheme, see Schemes, Section The geometric construction. Let $\mathcal{I} \subset \mathcal{O}_X$ be the quasi-coherent sheaf of ideals corresponding to the closed subscheme $Z$. By assumption (the indicated step), there exists an $n \geq 1$ and a section $s \in \Gamma(X, \mathcal{I} \otimes \mathcal{L}^{\otimes n})$ such that $s$ does not vanish at $x$ (more precisely such that $s \not \in \mathfrak m_x \mathcal{I}_x \otimes \mathcal{L}_x^{\otimes n}$). We may think of $s$ as a section of $\mathcal{L}^{\otimes n}$. Since it clearly vanishes along $Z$ we see that $X_s \subset U$. Hence $X_s$ is affine, see Lemma Affine neighbourhoods. This proves that $\mathcal{L}$ is ample. At this point we have proved that (1) -- (6) are equivalent.
Assume the equivalent conditions (1) -- (6). In the following we will use the fact that the tensor product of two sheaves of modules which are globally generated is globally generated without further mention (see Modules, Lemma Tensor products and direct sums (uncovered prerequisite)). By (1) we can find elements $s_i \in S_{d_i}$ with $d_i \geq 1$ such that $X = \bigcup_{i = 1, \ldots, n} X_{s_i}$. Set $d = d_1\ldots d_n$. It follows that $\mathcal{L}^{\otimes d}$ is globally generated by $$s_1^{d/d_1}, \ldots, s_n^{d/d_n}.$$ This means that if $\mathcal{L}^{\otimes j}$ is globally generated then so is $\mathcal{L}^{\otimes j + dn}$ for all $n \geq 0$. Fix a $j \in \{0, \ldots, d - 1\}$. For any point $x \in X$ there exists an $n \geq 1$ and a global section $s$ of $\mathcal{L}^{j + dn}$ which does not vanish at $x$, as follows from (the indicated step) applied to $\mathcal{F} = \mathcal{L}^{\otimes j}$ and ample invertible sheaf $\mathcal{L}^{\otimes d}$. Since $X$ is quasi-compact there we may find a finite list of integers $n_i$ and global sections $s_i$ of $\mathcal{L}^{\otimes j + dn_i}$ which do not vanish at any point of $X$. Since $\mathcal{L}^{\otimes d}$ is globally generated this means that $\mathcal{L}^{\otimes j + dn}$ is globally generated where $n = \max\{n_i\}$. Since we proved this for every congruence class mod $d$ we conclude that there exists an $n_0 = n_0(\mathcal{L})$ such that $\mathcal{L}^{\otimes n}$ is globally generated for all $n \geq n_0$. At this point we see that if $\mathcal{F}$ is globally generated then so is $\mathcal{F} \otimes \mathcal{L}^{\otimes n}$ for all $n \geq n_0$.
We continue to assume the equivalent conditions (1) -- (6). Let $\mathcal{F}$ be a quasi-coherent sheaf of $\mathcal{O}_X$-modules of finite type. Denote $\mathcal{F}_n \subset \mathcal{F}$ the image of the canonical map of (the indicated step). By construction $\mathcal{F}_n \otimes \mathcal{L}^{\otimes n}$ is globally generated. By (the indicated step) we see $\mathcal{F}$ is the sum of the subsheaves $\mathcal{F}_n$, $n \geq 1$. By Modules, Lemma Filtered limits and finite algebras (uncovered prerequisite) we see that $\mathcal{F} = \sum_{n = 1, \ldots, N} \mathcal{F}_n$ for some $N \geq 1$. It follows that $\mathcal{F} \otimes \mathcal{L}^{\otimes n}$ is globally generated whenever $n \geq N + n_0(\mathcal{L})$ with $n_0(\mathcal{L})$ as above. We conclude that (1) -- (6) implies (the indicated step).
Assume (the indicated step). Let $\mathcal{F}$ be a quasi-coherent sheaf of $\mathcal{O}_X$-modules of finite type. By (the indicated step) there exists an integer $n \geq 1$ such that the canonical map $$\Gamma(X, \mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{L}^{\otimes n}) \otimes_{\mathbf{Z}} \mathcal{L}^{\otimes -n} \longrightarrow \mathcal{F}$$ is surjective. Let $I$ be the set of finite subsets of $\Gamma(X, \mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{L}^{\otimes n})$ partially ordered by inclusion. Then $I$ is a directed partially ordered set. For $i = \{s_1, \ldots, s_{r(i)}\}$ let $\mathcal{F}_i \subset \mathcal{F}$ be the image of the map $$\bigoplus\nolimits_{j = 1, \ldots, r(i)} \mathcal{L}^{\otimes -n} \longrightarrow \mathcal{F}$$ which is multiplication by $s_j$ on the $j$th factor. The surjectivity above implies that $\mathcal{F} = \mathop{\operatorname{colim}}_{i \in I} \mathcal{F}_i$. Hence Modules, Lemma Filtered limits and finite algebras (uncovered prerequisite) applies and we conclude that $\mathcal{F} = \mathcal{F}_i$ for some $i$. Hence we have proved (the indicated step). In other words, (the indicated step) $\Rightarrow$ (the indicated step).
The implication (the indicated step) $\Rightarrow$ (the indicated step) is trivial.
Finally, assume (the indicated step). Let $\mathcal{I} \subset \mathcal{O}_X$ be a quasi-coherent sheaf of ideals. By Lemma Filtered limits and quasi-coherent complexes and coherent sheaves (this is where we use the condition that $X$ be quasi-separated) we see that $\mathcal{I} = \mathop{\operatorname{colim}}_\alpha I_\alpha$ with each $I_\alpha$ quasi-coherent of finite type. Since by assumption each of the $I_\alpha$ is a quotient of negative tensor powers of $\mathcal{L}$ we conclude the same for $\mathcal{I}$ (but of course without the finiteness or boundedness of the powers). Hence we conclude that (the indicated step) implies (the indicated step). This ends the proof of the proposition. $\square$
Definition. Ample invertible sheaves
Source credit: the original source citation EGA (II Definition 4.5.3)
Let $X$ be a scheme. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. We say $\mathcal{L}$ is ample if
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$X$ is quasi-compact, and
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for every $x \in X$ there exists an $n \geq 1$ and $s \in \Gamma(X, \mathcal{L}^{\otimes n})$ such that $x \in X_s$ and $X_s$ is affine.
Lemma. Finite presentation and modules
Let $X = \operatorname{Spec}(R)$ be an affine scheme. The quasi-coherent sheaf of $\mathcal{O}_X$-modules $\widetilde M$ is an $\mathcal{O}_X$-module of finite presentation if and only if $M$ is an $R$-module of finite presentation.
Proof. Assume $\widetilde M$ is an $\mathcal{O}_X$-module of finite presentation. By Lemma Modules and finite algebras we see that $M$ is a finite $R$-module. Choose a surjection $R^n \to M$ with kernel $K$. By Schemes, Lemma Prime spectra and associated points (uncovered prerequisite) there is a short exact sequence $$0 \to \widetilde{K} \to \bigoplus \mathcal{O}_X^{\oplus n} \to \widetilde{M} \to 0$$ By Modules, Lemma Projective, locally free modules and finite presentation (uncovered prerequisite) we see that $\widetilde{K}$ is a finite type $\mathcal{O}_X$-module. Hence by Lemma Modules and finite algebras again we see that $K$ is a finite $R$-module. Hence $M$ is an $R$-module of finite presentation. $\square$
Lemma. Flatness and modules
Flatness is the same for modules and sheaves.
Let $X = \operatorname{Spec}(R)$ be an affine scheme. Let $\mathcal{F} = \widetilde{M}$ for some $R$-module $M$. The quasi-coherent sheaf $\mathcal{F}$ is a flat $\mathcal{O}_X$-module if and only if $M$ is a flat $R$-module.
Proof. Flatness of $\mathcal{F}$ may be checked on the stalks, see Modules, Lemma Flatness and sheaves on ringed sites (uncovered prerequisite). The same is true in the case of modules over a ring, see Algebra, Lemma Localization of a flat module (uncovered prerequisite). And since $\mathcal{F}_x = M_{\mathfrak p}$ if $x$ corresponds to $\mathfrak p$ the lemma is true. $\square$
Lemma. Projective, locally free modules and local algebra
Let $X = \operatorname{Spec}(R)$ be an affine scheme. Let $\mathcal{F} = \widetilde{M}$ for some $R$-module $M$. The quasi-coherent sheaf $\mathcal{F}$ is a (finite) locally free $\mathcal{O}_X$-module of if and only if $M$ is a (finite) locally free $R$-module.
Proof. Follows from the definitions, see Modules, Definition Projective, locally free modules and local algebra and Algebra, Definition Projective, locally free modules and local algebra. $\square$
Situation. An invertible sheaf and its section-open subsets
Let $X$ be a scheme. Let $\mathcal{L}$ be an ample invertible sheaf on $X$. Set $S = \Gamma_*(X, \mathcal{L})$ as a graded ring. Set $Y = \text{Proj}(S)$. Let $f : X \to Y$ be the canonical morphism of Lemma Scheme geometry. It comes equipped with a $\mathbf{Z}$-graded $\mathcal{O}_X$-algebra map $\bigoplus f^*\mathcal{O}_Y(n) \to \bigoplus \mathcal{L}^{\otimes n}$.
Lemma. Line bundles, ampleness and affine neighbourhoods
Let $X$ be a scheme. Assume either
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The scheme $X$ is quasi-affine.
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The scheme $X$ is isomorphic to a locally closed subscheme of an affine scheme.
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There exists an ample invertible sheaf on $X$.
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The scheme $X$ is isomorphic to a locally closed subscheme of $\text{Proj}(S)$ for some graded ring $S$.
Then for any finite subset $E \subset X$ there exists an affine open $U \subset X$ with $E \subset U$.
Proof. By Properties, Definition Affine neighbourhoods a quasi-affine scheme is a quasi-compact open subscheme of an affine scheme. Any affine scheme $\operatorname{Spec}(R)$ is isomorphic to $\text{Proj}(R[X])$ where $R[X]$ is graded by setting $\deg(X) = 1$. By Proposition Criteria for line bundles and ampleness if $X$ has an ample invertible sheaf then $X$ is isomorphic to an open subscheme of $\text{Proj}(S)$ for some graded ring $S$. Hence, it suffices to prove the lemma in case (4). (We urge the reader to prove case (2) directly for themselves.)
Thus assume $X \subset \text{Proj}(S)$ is a locally closed subscheme where $S$ is some graded ring. Let $T = \overline{X} \setminus X$. Recall that the standard opens $D_{+}(f)$ form a basis of the topology on $\text{Proj}(S)$. Since $E$ is finite we may choose finitely many homogeneous elements $f_i \in S_{+}$ such that $$E \subset D_{+}(f_1) \cup \ldots \cup D_{+}(f_n) \subset \text{Proj}(S) \setminus T$$ Suppose that $E = \{\mathfrak p_1, \ldots, \mathfrak p_m\}$ as a subset of $\text{Proj}(S)$. Consider the ideal $I = (f_1, \ldots, f_n) \subset S$. Since $I \not \subset \mathfrak p_j$ for all $j = 1, \ldots, m$ we see from Algebra, Lemma A graded finite-generation calculation that there exists a homogeneous element $f \in I$, $f \not \in \mathfrak p_j$ for all $j = 1, \ldots, m$. Then $E \subset D_{+}(f) \subset D_{+}(f_1) \cup \ldots \cup D_{+}(f_n)$. Since $D_{+}(f)$ does not meet $T$ we see that $X \cap D_{+}(f)$ is a closed subscheme of the affine scheme $D_{+}(f)$, hence is an affine open of $X$ as desired. $\square$
Lemma. Line bundles, ampleness and diagonals and separation
Let $X$ be a scheme. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Set $S = \Gamma_*(X, \mathcal{L})$. Assume $\mathcal{L}$ is ample. Then the canonical morphism of schemes $f : X \longrightarrow \text{Proj}(S)$ of Lemma Scheme geometry is an open immersion with dense image.
Proof. By Lemma Diagonals, separation and affine neighbourhoods (uncovered prerequisite) we see that $X$ is quasi-separated. Choose finitely many $s_1, \ldots, s_n \in S_{+}$ homogeneous such that $X_{s_i}$ are affine, and $X = \bigcup X_{s_i}$. Say $s_i$ has degree $d_i$. The inverse image of $D_{+}(s_i)$ under $f$ is $X_{s_i}$, see Lemma Scheme geometry. By Lemma Scheme geometry the ring map $$(S^{(d_i)})_{(s_i)} = \Gamma(D_{+}(s_i), \mathcal{O}_{\text{Proj}(S)}) \longrightarrow \Gamma(X_{s_i}, \mathcal{O}_X)$$ is an isomorphism. Hence $f$ induces an isomorphism $X_{s_i} \to D_{+}(s_i)$. Thus $f$ is an isomorphism of $X$ onto the open subscheme $\bigcup_{i = 1, \ldots, n} D_{+}(s_i)$ of $\text{Proj}(S)$. The image is dense by Lemma Scheme geometry (uncovered prerequisite). $\square$
Lemma. Line bundles and ampleness
Source credit: the original source citation EGA (II Proposition 4.5.6(i))
Let $X$ be a scheme. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Let $n \geq 1$. Then $\mathcal{L}$ is ample if and only if $\mathcal{L}^{\otimes n}$ is ample.
Proof. This follows from the fact that $X_{s^n} = X_s$. $\square$
Lemma. Line bundles and ampleness
Let $X$ be a scheme. Let $S$ be a graded ring. Assume $X$ is quasi-compact, and assume there exists an open immersion $$j : X \longrightarrow Y = \text{Proj}(S).$$ Then $j^*\mathcal{O}_Y(d)$ is an invertible ample sheaf for some $d > 0$.
Proof. This is Constructions, Lemma Line bundles and ampleness (uncovered prerequisite). $\square$
Lemma. Affine neighbourhoods
Let $X$ be a scheme. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Assume the open sets $X_s$, where $s \in \Gamma(X, \mathcal{L}^{\otimes n})$ and $n \geq 1$, form a basis for the topology on $X$. Then among those opens, the open sets $X_s$ which are affine form a basis for the topology on $X$.
Proof. Let $x \in X$. Choose an affine open neighbourhood $\operatorname{Spec}(R) = U \subset X$ of $x$. By assumption, there exists a $n \geq 1$ and a $s \in \Gamma(X, \mathcal{L}^{\otimes n})$ such that $X_s \subset U$. By Lemma Affine neighbourhoods above the intersection $X_s = U \cap X_s$ is affine. Since $U$ can be chosen arbitrarily small we win. $\square$
Lemma. Scheme geometry
Source credit: the original source citation EGA1-second (Section 6.8) the original source citation FAC (Chapter III, §2, no. 55, Lemma 2, pp. 247--248)
The cited FAC lemma starts with a section on one standard chart of classical projective space. It first clears denominators on every other chart and then kills the finitely many overlap defects by a second common power, producing a global section of a sufficiently high twist with the prescribed local component. The lemma below expresses the same mechanism as localization at a section of an invertible sheaf and proves it for every quasi-coherent module on a quasi-compact and quasi-separated scheme.
Let $X$ be a scheme. Let $\mathcal{L}$ be an invertible sheaf on $X$. Let $s \in \Gamma(X, \mathcal{L})$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module.
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If $X$ is quasi-compact, then (Modules) is injective, and
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if $X$ is quasi-compact and quasi-separated, then (Modules) is an isomorphism.
In particular, the canonical map $$\Gamma_*(X, \mathcal{L})_{(s)} \longrightarrow \Gamma(X_s, \mathcal{O}_X),\quad a/s^n \longmapsto a \otimes s^{-n}$$ is an isomorphism if $X$ is quasi-compact and quasi-separated.
Proof. Assume $X$ is quasi-compact. Choose a finite affine open covering $X = U_1 \cup \ldots \cup U_m$ with $U_j$ affine and $\mathcal{L}|_{U_j} \cong \mathcal{O}_{U_j}$. Via this isomorphism, the image $s|_{U_j}$ corresponds to some $f_j \in \Gamma(U_j, \mathcal{O}_{U_j})$. Then $X_s \cap U_j = D(f_j)$.
Proof of (1). Let $t/s^n$ be an element in the kernel of (Modules). Then $t|_{X_s} = 0$. Hence $(t|_{U_j})|_{D(f_j)} = 0$. By Lemma Scheme geometry (uncovered prerequisite) we conclude that $f_j^{e_j} t|_{U_j} = 0$ for some $e_j \geq 0$. Let $e = \max(e_j)$. Then we see that $t \otimes s^e$ restricts to zero on $U_j$ for all $j$, hence is zero. Since $t/s^n$ is equal to $t \otimes s^e/s^{n + e}$ in $\Gamma_*(X, \mathcal{L}, \mathcal{F})_{(s)}$ we conclude that $t/s^n = 0$ as desired.
Proof of (2). Assume $X$ is quasi-compact and quasi-separated. Then $U_j \cap U_{j'}$ is quasi-compact for all pairs $j, j'$, see Schemes, Lemma Criteria for diagonals and separation (uncovered prerequisite). By part (1) we know (Modules) is injective. Let $t' \in \Gamma(X_s, \mathcal{F}|_{X_s})$. For every $j$, there exist an integer $e_j \geq 0$ and $t'_j \in \Gamma(U_j, \mathcal{F}|_{U_j})$ such that $t'|_{D(f_j)}$ corresponds to $t'_j/f_j^{e_j}$ via the isomorphism of Lemma Scheme geometry (uncovered prerequisite). Set $e = \max(e_j)$ and $$t_j = f_j^{e - e_j} t'_j \otimes q_j^e \in \Gamma(U_j, (\mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{L}^{\otimes e})|_{U_j})$$ where $q_j \in \Gamma(U_j, \mathcal{L}|_{U_j})$ is the trivializing section coming from the isomorphism $\mathcal{L}|_{U_j} \cong \mathcal{O}_{U_j}$. In particular we have $s|_{U_j} = f_j q_j$. Using this a calculation shows that $t_j|_{U_j \cap U_{j'}}$ and $t_{j'}|_{U_j \cap U_{j'}}$ map to the same section of $\mathcal{F}$ over $U_j \cap U_{j'} \cap X_s$. By quasi-compactness of $U_j \cap U_{j'}$ and part (1) there exists an integer $e' \geq 0$ such that $$t_j|_{U_j \cap U_{j'}} \otimes s^{e'}|_{U_j \cap U_{j'}} = t_{j'}|_{U_j \cap U_{j'}} \otimes s^{e'}|_{U_j \cap U_{j'}}$$ as sections of $\mathcal{F} \otimes \mathcal{L}^{\otimes e + e'}$ over $U_j \cap U_{j'}$. We may choose the same $e'$ to work for all pairs $j, j'$. Then the sheaf conditions implies there is a section $t \in \Gamma(X, \mathcal{F} \otimes \mathcal{L}^{\otimes e + e'})$ whose restriction to $U_j$ is $t_j \otimes s^{e'}|_{U_j}$. A simple computation shows that $t/s^{e + e'}$ maps to $t'$ as desired. $\square$
Lemma. Filtered limits and quasi-coherent complexes and coherent sheaves
Let $X$ be a quasi-compact and quasi-separated scheme. Any quasi-coherent sheaf of $\mathcal{O}_X$-modules is the directed colimit of its quasi-coherent $\mathcal{O}_X$-submodules which are of finite type.
Proof. The colimit is directed because if $\mathcal{G}_1$, $\mathcal{G}_2$ are quasi-coherent subsheaves of finite type, then the image of $\mathcal{G}_1 \oplus \mathcal{G}_2 \to \mathcal{F}$ is a quasi-coherent submodule of finite type. Let $U \subset X$ be any affine open, and let $s \in \Gamma(U, \mathcal{F})$ be any section. Let $\mathcal{G} \subset \mathcal{F}|_U$ be the subsheaf generated by $s$. Then clearly $\mathcal{G}$ is quasi-coherent and has finite type as an $\mathcal{O}_U$-module. By Lemma Scheme geometry (uncovered prerequisite) we see that $\mathcal{G}$ is the restriction of a quasi-coherent subsheaf $\mathcal{G}' \subset \mathcal{F}$ which has finite type. Since $X$ has a basis for the topology consisting of affine opens we conclude that every local section of $\mathcal{F}$ is locally contained in a quasi-coherent submodule of finite type. Thus we win. $\square$
Lemma. Scheme geometry
Let $S$ be a Noetherian scheme. Let $T \subset S$ be an infinite dense subset. Then there exist a countable subset $E \subset T$ which is dense in $S$.
Proof. Let $T'$ be the set of points $s \in S$ such that $\overline{\{s\}} \cap T$ contains a countable subset whose closure is $\overline{\{s\}}$. Since a finite set is countable we have $T \subset T'$. For $s \in T'$ choose such a countable subset $E_s \subset \overline{\{s\}} \cap T$. Let $E' = \{s_1, s_2, s_3, \ldots\} \subset T'$ be a countable subset. Then the closure of $E'$ in $S$ is the closure of the countable subset $\bigcup_n E_{s_n}$ of $T$. It follows that if $Z$ is an irreducible component of the closure of $E'$, then the generic point of $Z$ is in $T'$.
Denote $T'_0 \subset T'$ the subset of $t \in T'$ such that there is no nontrivial specialization $t' \leadsto t$ with $t' \in T'$ as in Lemma Scheme geometry whose results we will use without further mention. If $T'_0$ is infinite, then we choose a countable subset $E' \subset T'_0$. By the argument in the first paragraph, the generic points of the irreducible components of the closure of $E'$ are in $T'$. However, since one of these points specializes to infinitely many distinct elements of $E' \subset T'_0$ this is a contradiction. Thus $T'_0$ is finite, say $T'_0 = \{s_1, \ldots, s_m\}$. Then it follows that $S$, which is the closure of $T$, is contained in the closure of $\{s_1, \ldots, s_m\}$, which in turn is contained in the closure of the countable subset $E_{s_1} \cup \ldots \cup E_{s_m} \subset T$ as desired. $\square$
Lemma. Scheme geometry
Let $S$ be a Noetherian scheme. Let $T \subset S$ be a subset. Let $T_0 \subset T$ be the set of $t \in T$ such that there is no nontrivial specialization $t' \leadsto t$ with $t' \in T'$. Then (a) there are no specializations among the points of $T_0$, (b) every point of $T$ is a specialization of a point of $T_0$, and (c) the closures of $T$ and $T_0$ are the same.
Proof. Recall that $\dim(\mathcal{O}_{S, s}) < \infty$ for any $s \in S$, see Algebra, Proposition Dimension and codimension (uncovered prerequisite). Let $t \in T$. If $t' \leadsto t$, then by dimension theory $\dim(\mathcal{O}_{S, t'}) \leq \dim(\mathcal{O}_{S, t})$ with equality if and only if $t' = t$. Thus if we pick $t' \leadsto t$ with $\dim(\mathcal{O}_{T, t'})$ minimal, then $t' \in T_0$. In other words, every $t \in T$ is the specialization of an element of $T_0$. $\square$
Lemma. Filtered limits and integral extensions and finite algebras
Let $X$ be a scheme. Assume $X$ is quasi-compact and quasi-separated. Let $\mathcal{A}$ be an integral quasi-coherent $\mathcal{O}_X$-algebra. Then
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$\mathcal{A}$ is the directed colimit of its finite quasi-coherent $\mathcal{O}_X$-subalgebras, and
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$\mathcal{A}$ is a direct colimit of finite and finitely presented quasi-coherent $\mathcal{O}_X$-algebras.
Proof. By Lemma Filtered limits and finite algebras (uncovered prerequisite) we have $\mathcal{A} = \mathop{\operatorname{colim}} \mathcal{A}_i$ where $\mathcal{A}_i \subset \mathcal{A}$ runs through the quasi-coherent $\mathcal{O}_X$-algebras of finite type. Any finite type quasi-coherent $\mathcal{O}_X$-subalgebra of $\mathcal{A}$ is finite (apply Algebra, Lemma Criteria for integral extensions and finite algebras to $\mathcal{A}_i(U) \subset \mathcal{A}(U)$ for affine opens $U$ in $X$). This proves (1).
To prove (2), write $\mathcal{A} = \mathop{\operatorname{colim}} \mathcal{F}_i$ as a colimit of finitely presented $\mathcal{O}_X$-modules using Lemma Filtered limits and finite presentation and finite algebras (uncovered prerequisite). For each $i$, let $\mathcal{J}_i$ be the kernel of the map $$\text{Sym}^*_{\mathcal{O}_X}(\mathcal{F}_i) \longrightarrow \mathcal{A}$$ For $i' \geq i$ there is an induced map $\mathcal{J}_i \to \mathcal{J}_{i'}$ and we have $\mathcal{A} = \mathop{\operatorname{colim}} \text{Sym}^*_{\mathcal{O}_X}(\mathcal{F}_i)/\mathcal{J}_i$. Moreover, the quasi-coherent $\mathcal{O}_X$-algebras $\text{Sym}^*_{\mathcal{O}_X}(\mathcal{F}_i)/\mathcal{J}_i$ are finite (see above). Write $\mathcal{J}_i = \mathop{\operatorname{colim}} \mathcal{E}_{ik}$ as a colimit of finitely presented $\mathcal{O}_X$-modules. Given $i' \geq i$ and $k$ there exists a $k'$ such that we have a map $\mathcal{E}_{ik} \to \mathcal{E}_{i'k'}$ making $$\begin{gathered}\begin{matrix}\mathcal{J}_i & \mathcal{J}_{i'} \\ \mathcal{E}_{ik} & \mathcal{E}_{i'k'}\end{matrix} \\[6pt] \begin{aligned}\mathcal{J}_i & \longrightarrow \mathcal{J}_{i'} \\ \mathcal{E}_{ik} & \longrightarrow \mathcal{J}_i \\ \mathcal{E}_{ik} & \longrightarrow \mathcal{E}_{i'k'} \\ \mathcal{E}_{i'k'} & \longrightarrow \mathcal{J}_{i'}\end{aligned}\end{gathered}$$ commute. This follows from Modules, Lemma Filtered limits and finite presentation and finite algebras (uncovered prerequisite). This induces a map $$\mathcal{A}_{ik} = \text{Sym}^*_{\mathcal{O}_X}(\mathcal{F}_i)/(\mathcal{E}_{ik}) \longrightarrow \text{Sym}^*_{\mathcal{O}_X}(\mathcal{F}_{i'})/(\mathcal{E}_{i'k'}) = \mathcal{A}_{i'k'}$$ where $(\mathcal{E}_{ik})$ denotes the ideal generated by $\mathcal{E}_{ik}$. The quasi-coherent $\mathcal{O}_X$-algebras $\mathcal{A}_{ki}$ are of finite presentation and finite for $k$ large enough (see proof of Lemma Filtered limits and finite presentation and finite algebras (uncovered prerequisite)). Finally, we have $$\mathop{\operatorname{colim}} \mathcal{A}_{ik} = \mathop{\operatorname{colim}} \mathcal{A}_i = \mathcal{A}$$ Namely, the first equality was shown in the proof of Lemma Filtered limits and finite presentation and finite algebras (uncovered prerequisite) and the second equality because $\mathcal{A}$ is the colimit of the modules $\mathcal{F}_i$. $\square$
Schematic neighbourhoods of algebraic spaces
Lemma. Schematic neighbourhoods
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Consider the following conditions on $X$:
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$(\alpha)$ For every $x \in |X|$, the equivalent conditions of Lemma Finite algebras hold.
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$(\beta)$ For every $x \in |X|$, the equivalent conditions of Lemma Finite algebras hold.
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$(\gamma)$ For every $x \in |X|$, the equivalent conditions of Lemma Finite algebras hold.
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$(\delta)$ The equivalent conditions of Lemma Schematic neighbourhoods hold.
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$(\epsilon)$ The equivalent conditions of Lemma Criteria for schematic neighbourhoods hold.
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$(\zeta)$ The space $X$ is Zariski locally quasi-separated.
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$(\eta)$ The space $X$ is quasi-separated
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$(\theta)$ The space $X$ is representable, i.e., $X$ is a scheme.
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$(\iota)$ The space $X$ is a quasi-separated scheme.
We have $$\begin{gathered}\begin{matrix}\phantom{X} & (\theta) & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} \\ (\iota) & \phantom{X} & (\zeta) & (\epsilon) & (\delta) & (\gamma) & (\alpha) + (\beta) \\ \phantom{X} & (\eta) & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}(\theta) & \Longrightarrow (\zeta) \\ (\iota) & \Longrightarrow (\theta) \\ (\iota) & \Longrightarrow (\eta) \\ (\zeta) & \Longrightarrow (\epsilon) \\ (\epsilon) & \Longrightarrow (\delta) \\ (\delta) & \Longrightarrow (\gamma) \\ (\gamma) & \Longleftrightarrow (\alpha) + (\beta) \\ (\eta) & \Longrightarrow (\zeta)\end{aligned}\end{gathered}$$
Proof. The implication $(\gamma) \Leftrightarrow (\alpha) + (\beta)$ is immediate. The implications in the diamond on the left are clear from the definitions.
Assume $(\zeta)$, i.e., that $X$ is Zariski locally quasi-separated. Then $(\epsilon)$ holds by Properties of Spaces, Lemma Diagonals and separation.
Assume $(\epsilon)$. By Lemma Criteria for schematic neighbourhoods there exists a Zariski open covering $X = \bigcup X_i$ such that for each $i$ there exists a scheme $U_i$ and a quasi-compact surjective étale morphism $U_i \to X_i$. Choose an $i$ and an affine open subscheme $W \subset U_i$. It suffices to show that $W \to X$ has universally bounded fibres, since then the family of all these morphisms $W \to X$ covers $X$. To do this we consider the diagram $$\begin{gathered}\begin{matrix}W \times_X U_i & U_i \\ W & X\end{matrix} \\[6pt] \begin{aligned}W \times_X U_i & \xrightarrow{p} U_i \\ W \times_X U_i & \xrightarrow{q} W \\ U_i & \longrightarrow X \\ W & \longrightarrow X\end{aligned}\end{gathered}$$ Since $W \to X$ factors through $X_i$ we see that $W \times_X U_i = W \times_{X_i} U_i$, and hence $q$ is quasi-compact. Since $W$ is affine this implies that the scheme $W \times_X U_i$ is quasi-compact. Thus we may apply Morphisms, Lemma Finite algebras and local algebra (uncovered prerequisite) and we conclude that $p$ has universally bounded fibres. From Lemma Descent of schematic neighbourhoods we conclude that $W \to X$ has universally bounded fibres as well.
Assume $(\delta)$. Let $U$ be an affine scheme, and let $U \to X$ be an étale morphism. By assumption the fibres of the morphism $U \to X$ are universally bounded. Thus also the fibres of both projections $R = U \times_X U \to U$ are universally bounded, see Lemma Base change for schematic neighbourhoods. And by Lemma Composition and schematic neighbourhoods also the fibres of $R \to X$ are universally bounded. Hence for any $x \in X$ the fibres of $|U| \to |X|$ and $|R| \to |X|$ over $x$ are finite, see Lemma Finite algebras. In other words, the equivalent conditions of Lemma Finite algebras hold. This proves that $(\delta) \Rightarrow (\gamma)$. $\square$
Lemma. Schematic neighbourhoods
Let $S$ be a scheme. Let $W \to X$ be a morphism of a scheme $W$ to an algebraic space $X$ which is flat, locally of finite presentation, separated, locally quasi-finite with universally bounded fibres. There exist reduced closed subspaces $$\emptyset = Z_{-1} \subset Z_0 \subset Z_1 \subset Z_2 \subset \ldots \subset Z_n = X$$ such that with $X_r = Z_r \setminus Z_{r - 1}$ the stratification $X = \coprod_{r = 0, \ldots, n} X_r$ is characterized by the following universal property: Given $g : T \to X$ the projection $W \times_X T \to T$ is finite locally free of degree $r$ if and only if $g(|T|) \subset |X_r|$.
Proof. Let $n$ be an integer bounding the degrees of the fibres of $W \to X$. Choose a scheme $U$ and a surjective étale morphism $U \to X$. Apply More on Morphisms, Lemma Finite presentation and flatness to $W \times_X U \to U$. We obtain closed subsets $$\emptyset = Y_{-1} \subset Y_0 \subset Y_1 \subset Y_2 \subset \ldots \subset Y_n = U$$ characterized by the property stated in the lemma for the morphism $W \times_X U \to U$. Clearly, the formation of these closed subsets commutes with base change. Setting $R = U \times_X U$ with projection maps $s, t : R \to U$ we conclude that $$s^{-1}(Y_r) = t^{-1}(Y_r)$$ as closed subsets of $R$. In other words the closed subsets $Y_r \subset U$ are $R$-invariant. This means that $|Y_r|$ is the inverse image of a closed subset $Z_r \subset |X|$. Denote $Z_r \subset X$ also the reduced induced algebraic space structure, see Properties of Spaces, Definition Étale geometry of algebraic spaces.
Let $g : T \to X$ be a morphism of algebraic spaces. Choose a scheme $V$ and a surjective étale morphism $V \to T$. To prove the final assertion of the lemma it suffices to prove the assertion for the composition $V \to X$ (by our definition of finite locally free morphisms, see Morphisms of Spaces, Section Projective, locally free modules and finite algebras). Similarly, the morphism of schemes $W \times_X V \to V$ is finite locally free of degree $r$ if and only if the morphism of schemes $$W \times_X (U \times_X V) \longrightarrow U \times_X V$$ is finite locally free of degree $r$ (see Descent, Lemma Descent of projective, locally free modules and proper morphisms). By construction this happens if and only if $|U \times_X V| \to |U|$ maps into $|Y_r|$, which is true if and only if $|V| \to |X|$ maps into $|Z_r|$. $\square$
Lemma. Diagonals and separation
Source credit: This result is almost identical to the original source citation GruRay (Proposition 5.7.8).
Let $X$ be a quasi-compact and quasi-separated algebraic space over $\operatorname{Spec}(\mathbf{Z})$. There exist an integer $n$ and open subspaces $$\emptyset = U_{n + 1} \subset U_n \subset U_{n - 1} \subset \ldots \subset U_1 = X$$ with the following property: setting $T_p = U_p \setminus U_{p + 1}$ (with reduced induced subspace structure) there exists a quasi-compact separated scheme $V_p$ and a surjective étale morphism $f_p : V_p \to U_p$ such that $f_p^{-1}(T_p) \to T_p$ is an isomorphism.
Proof. The proof of this lemma is identical to the proof of Lemma Schematic neighbourhoods. Observe that a quasi-separated space is reasonable, see Lemma Schematic neighbourhoods and Definition Very reasonable algebraic spaces. Hence we find that $U_{n + 1} = \emptyset$ as in Lemma Schematic neighbourhoods. At the end of the argument we add that since $X$ is quasi-separated the schemes $U \times_X \ldots \times_X U$ are all quasi-compact. Hence the schemes $W_p$ are quasi-compact. Hence the quotients $V_p = W_p/S_p$ by the symmetric group $S_p$ are quasi-compact schemes. $\square$
Lemma. Dimension, codimension and finite algebras
Let $S$ be a scheme. Let $X \to Y$ be a locally quasi-finite morphism of algebraic spaces over $S$. Let $x \in |X|$ with image $y \in |Y|$. Then the dimension of the local ring of $Y$ at $y$ is $\geq$ to the dimension of the local ring of $X$ at $x$.
Proof. The definition of the dimension of the local ring of a point on an algebraic space is given in Properties of Spaces, Definition Dimension, codimension and local algebra. Choose an étale morphism $(V, v) \to (Y, y)$ where $V$ is a scheme. Choose an étale morphism $U \to V \times_Y X$ and a point $u \in U$ mapping to $x \in |X|$ and $v \in V$. Then $U \to V$ is locally quasi-finite and we have to prove that $$\dim(\mathcal{O}_{V, v}) \geq \dim(\mathcal{O}_{U, u})$$ This is Algebra, Lemma Dimension, codimension and finite algebras. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $x \in |X|$. The following are equivalent:
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there exists a family of schemes $U_i$ and étale morphisms $\varphi_i : U_i \to X$ such that $\coprod \varphi_i : \coprod U_i \to X$ is surjective, and such that for each $i$ the fibre of $|U_i| \to |X|$ over $x$ is finite, and
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for every affine scheme $U$ and étale morphism $\varphi : U \to X$ the fibre of $|U| \to |X|$ over $x$ is finite.
Proof. The implication (2) $\Rightarrow$ (1) is trivial. Let $\varphi_i : U_i \to X$ be a family of étale morphisms as in (1). Let $\varphi : U \to X$ be an étale morphism from an affine scheme towards $X$. Consider the fibre product diagrams $$\begin{gathered}\begin{matrix}U \times_X U_i & U_i \\ U & X\end{matrix} \\[6pt] \begin{aligned}U \times_X U_i & \xrightarrow{p_i} U_i \\ U \times_X U_i & \xrightarrow{q_i} U \\ U_i & \xrightarrow{\varphi_i} X \\ U & \xrightarrow{\varphi} X\end{aligned}\end{gathered} \quad \quad \begin{gathered}\begin{matrix}\coprod U \times_X U_i & \coprod U_i \\ U & X\end{matrix} \\[6pt] \begin{aligned}\coprod U \times_X U_i & \xrightarrow{\coprod p_i} \coprod U_i \\ \coprod U \times_X U_i & \xrightarrow{\coprod q_i} U \\ \coprod U_i & \xrightarrow{\coprod \varphi_i} X \\ U & \xrightarrow{\varphi} X\end{aligned}\end{gathered}$$ Since $q_i$ is étale it is open (see Remark Schematic neighbourhoods). Moreover, the morphism $\coprod q_i$ is surjective. Hence there exist finitely many indices $i_1, \ldots, i_n$ and a quasi-compact opens $W_{i_j} \subset U \times_X U_{i_j}$ which surject onto $U$. The morphism $p_i$ is étale, hence locally quasi-finite (see remark on étale morphisms above). Thus we may apply Morphisms, Lemma Finite algebras and local algebra (uncovered prerequisite) to see the fibres of $p_{i_j}|_{W_{i_j}} : W_{i_j} \to U_i$ are finite. Hence by Properties of Spaces, Lemma Étale geometry of algebraic spaces and the assumption on $\varphi_i$ we conclude that the fibre of $\varphi$ over $x$ is finite. In other words (2) holds. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $x \in |X|$. The following are equivalent:
-
there exists a scheme $U$, an étale morphism $\varphi : U \to X$, and points $u, u' \in U$ mapping to $x$ such that setting $R = U \times_X U$ the fibre of $$|R| \to |U| \times_{|X|} |U|$$ over $(u, u')$ is finite,
-
for every scheme $U$, étale morphism $\varphi : U \to X$ and any points $u, u' \in U$ mapping to $x$ setting $R = U \times_X U$ the fibre of $$|R| \to |U| \times_{|X|} |U|$$ over $(u, u')$ is finite,
-
there exists a morphism $\operatorname{Spec}(k) \to X$ with $k$ a field in the equivalence class of $x$ such that the projections $\operatorname{Spec}(k) \times_X \operatorname{Spec}(k) \to \operatorname{Spec}(k)$ are étale and quasi-compact, and
-
there exists a monomorphism $\operatorname{Spec}(k) \to X$ with $k$ a field in the equivalence class of $x$.
Proof. Assume (1), i.e., let $\varphi : U \to X$ be an étale morphism from a scheme towards $X$, and let $u, u'$ be points of $U$ lying over $x$ such that the fibre of $|R| \to |U| \times_{|X|} |U|$ over $(u, u')$ is a finite set. In this proof we think of a point $u = \operatorname{Spec}(\kappa(u))$ as a scheme. Note that $u \to U$, $u' \to U$ are monomorphisms (see Schemes, Lemma Injective resolutions and sheaves on ringed sites (uncovered prerequisite)), hence $u \times_X u' \to R = U \times_X U$ is a monomorphism. In this language the assumption really means that $u \times_X u'$ is a scheme whose underlying topological space has finitely many points. Let $\psi : W \to X$ be an étale morphism from a scheme towards $X$. Let $w, w' \in W$ be points of $W$ mapping to $x$. We have to show that $w \times_X w'$ is a scheme whose underlying topological space has finitely many points. Consider the fibre product diagram $$\begin{gathered}\begin{matrix}W \times_X U & U \\ W & X\end{matrix} \\[6pt] \begin{aligned}W \times_X U & \xrightarrow{p} U \\ W \times_X U & \xrightarrow{q} W \\ U & \xrightarrow{\varphi} X \\ W & \xrightarrow{\psi} X\end{aligned}\end{gathered}$$ As $x$ is the image of $u$ and $u'$ we may pick points $\tilde w, \tilde w'$ in $W \times_X U$ with $q(\tilde w) = w$, $q(\tilde w') = w'$, $u = p(\tilde w)$ and $u' = p(\tilde w')$, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. As $p$, $q$ are étale the field extensions $\kappa(w) \subset \kappa(\tilde w) \supset \kappa(u)$ and $\kappa(w') \subset \kappa(\tilde w') \supset \kappa(u')$ are finite separable, see Remark Schematic neighbourhoods. Then we get a commutative diagram $$\begin{gathered}\begin{matrix}w \times_X w' & \tilde w \times_X \tilde w' & u \times_X u' \\ w \times_X w' & \tilde w \times_S \tilde w' & u \times_S u'\end{matrix} \\[6pt] \begin{aligned}w \times_X w' & \longrightarrow w \times_X w' \\ \tilde w \times_X \tilde w' & \longrightarrow w \times_X w' \\ \tilde w \times_X \tilde w' & \longrightarrow \tilde w \times_S \tilde w' \\ \tilde w \times_X \tilde w' & \longrightarrow u \times_X u' \\ u \times_X u' & \longrightarrow u \times_S u' \\ \tilde w \times_S \tilde w' & \longrightarrow w \times_X w' \\ \tilde w \times_S \tilde w' & \longrightarrow u \times_S u'\end{aligned}\end{gathered}$$ where the squares are fibre product squares. The lower horizontal morphisms are étale and quasi-compact, as any scheme of the form $\operatorname{Spec}(k) \times_S \operatorname{Spec}(k')$ is affine, and by our observations about the field extensions above. Thus we see that the top horizontal arrows are étale and quasi-compact and hence have finite fibres. We have seen above that $|u \times_X u'|$ is finite, so we conclude that $|w \times_X w'|$ is finite. In other words, (2) holds.
Assume (2). Let $U \to X$ be an étale morphism from a scheme $U$ such that $x$ is in the image of $|U| \to |X|$. Let $u \in U$ be a point mapping to $x$. Then we have seen in the previous paragraph that $u = \operatorname{Spec}(\kappa(u)) \to X$ has the property that $u \times_X u$ has a finite underlying topological space. On the other hand, the projection maps $u \times_X u \to u$ are the composition $$u \times_X u \longrightarrow u \times_X U \longrightarrow u \times_X X = u,$$ i.e., the composition of a monomorphism (the base change of the monomorphism $u \to U$) by an étale morphism (the base change of the étale morphism $U \to X$). Hence $u \times_X U$ is a disjoint union of spectra of fields finite separable over $\kappa(u)$ (see Remark Schematic neighbourhoods). Since $u \times_X u$ is finite the image of it in $u \times_X U$ is a finite disjoint union of spectra of fields finite separable over $\kappa(u)$. By Schemes, Lemma Field extensions and prime spectra and associated points (uncovered prerequisite) we conclude that $u \times_X u$ is a finite disjoint union of spectra of fields finite separable over $\kappa(u)$. In other words, we see that $u \times_X u \to u$ is quasi-compact and étale. This means that (3) holds.
Let us prove that (3) implies (4). Let $\operatorname{Spec}(k) \to X$ be a morphism from the spectrum of a field into $X$, in the equivalence class of $x$ such that the two projections $t, s : R = \operatorname{Spec}(k) \times_X \operatorname{Spec}(k) \to \operatorname{Spec}(k)$ are quasi-compact and étale. This means in particular that $R$ is an étale equivalence relation on $\operatorname{Spec}(k)$. By Spaces, Theorem The geometric construction (uncovered prerequisite) we know that the quotient sheaf $X' = \operatorname{Spec}(k)/R$ is an algebraic space. By Groupoids, Lemma Groupoids and equivalence relations (uncovered prerequisite) the map $X' \to X$ is a monomorphism. Since $s, t$ are quasi-compact, we see that $R$ is quasi-compact and hence Properties of Spaces, Lemma Étale geometry of algebraic spaces (uncovered prerequisite) applies to $X'$, and we see that $X' = \operatorname{Spec}(k')$ for some field $k'$. Hence we get a factorization $$\operatorname{Spec}(k) \longrightarrow \operatorname{Spec}(k') \longrightarrow X$$ which shows that $\operatorname{Spec}(k') \to X$ is a monomorphism mapping to $x \in |X|$. In other words (4) holds.
Finally, we prove that (4) implies (1). Let $\operatorname{Spec}(k) \to X$ be a monomorphism with $k$ a field in the equivalence class of $x$. Let $U \to X$ be a surjective étale morphism from a scheme $U$ to $X$. Let $u \in U$ be a point over $x$. Since $\operatorname{Spec}(k) \times_X u$ is nonempty, and since $\operatorname{Spec}(k) \times_X u \to u$ is a monomorphism we conclude that $\operatorname{Spec}(k) \times_X u = u$ (see Schemes, Lemma Field extensions and prime spectra and associated points (uncovered prerequisite)). Hence $u \to U \to X$ factors through $\operatorname{Spec}(k) \to X$, here is a picture $$\begin{gathered}\begin{matrix}u & U \\ \operatorname{Spec}(k) & X\end{matrix} \\[6pt] \begin{aligned}u & \longrightarrow U \\ u & \longrightarrow \operatorname{Spec}(k) \\ U & \longrightarrow X \\ \operatorname{Spec}(k) & \longrightarrow X\end{aligned}\end{gathered}$$ Since the right vertical arrow is étale this implies that $\kappa(u)/k$ is a finite separable extension. Hence we conclude that $$u \times_X u = u \times_{\operatorname{Spec}(k)} u$$ is a finite scheme, and we win by the discussion of the meaning of property (1) in the first paragraph of this proof. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $x \in |X|$. The following are equivalent:
-
for every affine scheme $U$, any étale morphism $\varphi : U \to X$ setting $R = U \times_X U$ the fibres of both $$|U| \longrightarrow |X| \quad\text{and}\quad |R| \longrightarrow |X|$$ over $x$ are finite,
-
there exist schemes $U_i$ and étale morphisms $U_i \to X$ such that $\coprod U_i \to X$ is surjective and for each $i$, setting $R_i = U_i \times_X U_i$ the fibres of both $$|U_i| \longrightarrow |X| \quad\text{and}\quad |R_i| \longrightarrow |X|$$ over $x$ are finite,
-
there exists a monomorphism $\operatorname{Spec}(k) \to X$ with $k$ a field in the equivalence class of $x$, and for any affine scheme $U$ and étale morphism $U \to X$ the fibre product $\operatorname{Spec}(k) \times_X U$ is a finite scheme over $k$,
-
there exists a quasi-compact monomorphism $\operatorname{Spec}(k) \to X$ with $k$ a field in the equivalence class of $x$,
-
there exists a quasi-compact morphism $\operatorname{Spec}(k) \to X$ with $k$ a field in the equivalence class of $x$, and
-
every morphism $\operatorname{Spec}(k) \to X$ with $k$ a field in the equivalence class of $x$ is quasi-compact.
Proof. The equivalence of (1) and (3) follows on applying Lemma Finite algebras (uncovered prerequisite) to every étale morphism $U \to X$ with $U$ affine. It is clear that (3) implies (2). Assume $U_i \to X$ and $R_i$ are as in (2). We conclude from Lemma Finite algebras that for any affine scheme $U$ and étale morphism $U \to X$ the fibre of $|U| \to |X|$ over $x$ is finite. Say this fibre is $\{u_1, \ldots, u_n\}$. Then, as Lemma Finite algebras (1) applies to $U_i \to X$ for some $i$ such that $x$ is in the image of $|U_i| \to |X|$, we see that the fibre of $|R = U \times_X U| \to |U| \times_{|X|} |U|$ is finite over $(u_a, u_b)$, $a, b \in \{1, \ldots, n\}$. Hence the fibre of $|R| \to |X|$ over $x$ is finite. In this way we see that (1) holds. At this point we know that (1), (2), and (3) are equivalent.
If (4) holds, then for any affine scheme $U$ and étale morphism $U \to X$ the scheme $\operatorname{Spec}(k) \times_X U$ is on the one hand étale over $k$ (hence a disjoint union of spectra of finite separable extensions of $k$ by Remark Schematic neighbourhoods) and on the other hand quasi-compact over $U$ (hence quasi-compact). Thus we see that (3) holds. Conversely, if $U_i \to X$ is as in (2) and $\operatorname{Spec}(k) \to X$ is a monomorphism as in (3), then $$\coprod \operatorname{Spec}(k) \times_X U_i \longrightarrow \coprod U_i$$ is quasi-compact (because over each $U_i$ we see that $\operatorname{Spec}(k) \times_X U_i$ is a finite disjoint union spectra of fields). Thus $\operatorname{Spec}(k) \to X$ is quasi-compact by Morphisms of Spaces, Lemma Local algebra (uncovered prerequisite).
It is immediate that (4) implies (5). Conversely, let $\operatorname{Spec}(k) \to X$ be a quasi-compact morphism in the equivalence class of $x$. Let $U \to X$ be an étale morphism with $U$ affine. Consider the fibre product $$\begin{gathered}\begin{matrix}F & U \\ \operatorname{Spec}(k) & X\end{matrix} \\[6pt] \begin{aligned}F & \longrightarrow U \\ F & \longrightarrow \operatorname{Spec}(k) \\ U & \longrightarrow X \\ \operatorname{Spec}(k) & \longrightarrow X\end{aligned}\end{gathered}$$ Then $F \to U$ is quasi-compact, hence $F$ is quasi-compact. On the other hand, $F \to \operatorname{Spec}(k)$ is étale, hence $F$ is a finite disjoint union of spectra of finite separable extensions of $k$ (Remark Schematic neighbourhoods). Since the image of $|F| \to |U|$ is the fibre of $|U| \to |X|$ over $x$ (Properties of Spaces, Lemma Étale geometry of algebraic spaces), we conclude that the fibre of $|U| \to |X|$ over $x$ is finite. The scheme $F \times_{\operatorname{Spec}(k)} F$ is also a finite union of spectra of fields because it is also quasi-compact and étale over $\operatorname{Spec}(k)$. There is a monomorphism $F \times_X F \to F \times_{\operatorname{Spec}(k)} F$, hence $F \times_X F$ is a finite disjoint union of spectra of fields (Schemes, Lemma Field extensions and prime spectra and associated points (uncovered prerequisite)). Thus the image of $F \times_X F \to U \times_X U = R$ is finite. Since this image is the fibre of $|R| \to |X|$ over $x$ by Properties of Spaces, Lemma Étale geometry of algebraic spaces we conclude that (1) holds. At this point we know that (1) -- (5) are equivalent.
It is clear that (6) implies (5). Conversely, assume $\operatorname{Spec}(k) \to X$ is as in (4) and let $\operatorname{Spec}(k') \to X$ be another morphism with $k'$ a field in the equivalence class of $x$. By Properties of Spaces, Lemma Groupoids and equivalence relations (uncovered prerequisite) we have a factorization $\operatorname{Spec}(k') \to \operatorname{Spec}(k) \to X$ of the given morphism. This is a composition of quasi-compact morphisms and hence quasi-compact (Morphisms of Spaces, Lemma Composition and morphisms of algebraic spaces (uncovered prerequisite)) as desired. $\square$
Lemma. Schematic neighbourhoods
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. The following are equivalent:
-
there exist schemes $U_i$ and étale morphisms $U_i \to X$ such that $\coprod U_i \to X$ is surjective and each $U_i \to X$ has universally bounded fibres, and
-
for every affine scheme $U$ and étale morphism $\varphi : U \to X$ the fibres of $U \to X$ are universally bounded.
Proof. The implication (2) $\Rightarrow$ (1) is trivial. Assume (1). Let $(\varphi_i : U_i \to X)_{i \in I}$ be a collection of étale morphisms from schemes towards $X$, covering $X$, such that each $\varphi_i$ has universally bounded fibres. Let $\psi : U \to X$ be an étale morphism from an affine scheme towards $X$. For each $i$ consider the fibre product diagram $$\begin{gathered}\begin{matrix}U \times_X U_i & U_i \\ U & X\end{matrix} \\[6pt] \begin{aligned}U \times_X U_i & \xrightarrow{p_i} U_i \\ U \times_X U_i & \xrightarrow{q_i} U \\ U_i & \xrightarrow{\varphi_i} X \\ U & \xrightarrow{\psi} X\end{aligned}\end{gathered}$$ Since $q_i$ is étale it is open (see Remark Schematic neighbourhoods). Moreover, we have $U = \bigcup \operatorname{Im}(q_i)$, since the family $(\varphi_i)_{i \in I}$ is surjective. Since $U$ is affine, hence quasi-compact we can finite finitely many $i_1, \ldots, i_n \in I$ and quasi-compact opens $W_j \subset U \times_X U_{i_j}$ such that $U = \bigcup p_{i_j}(W_j)$. The morphism $p_{i_j}$ is étale, hence locally quasi-finite (see remark on étale morphisms above). Thus we may apply Morphisms, Lemma Finite algebras and local algebra (uncovered prerequisite) to see the fibres of $p_{i_j}|_{W_j} : W_j \to U_{i_j}$ are universally bounded. Hence by Lemma Composition and schematic neighbourhoods we see that the fibres of $W_j \to X$ are universally bounded. Thus also $\coprod_{j = 1, \ldots, n} W_j \to X$ has universally bounded fibres. Since $\coprod_{j = 1, \ldots, n} W_j \to X$ factors through the surjective étale map $\coprod q_{i_j}|_{W_j} : \coprod_{j = 1, \ldots, n} W_j \to U$ we see that the fibres of $U \to X$ are universally bounded by Lemma Schematic neighbourhoods (uncovered prerequisite). In other words (2) holds. $\square$
Lemma. Criteria for schematic neighbourhoods
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. The following are equivalent:
-
there exists a Zariski covering $X = \bigcup X_i$ and for each $i$ a scheme $U_i$ and a quasi-compact surjective étale morphism $U_i \to X_i$, and
-
there exist schemes $U_i$ and étale morphisms $U_i \to X$ such that the projections $U_i \times_X U_i \to U_i$ are quasi-compact and $\coprod U_i \to X$ is surjective.
Proof. If (1) holds then the morphisms $U_i \to X_i \to X$ are étale (combine Morphisms, Lemma Composition and étale morphisms (uncovered prerequisite) and Spaces, Lemmas Composition and proper morphisms (uncovered prerequisite) and Proper morphisms (uncovered prerequisite) ). Moreover, as $U_i \times_X U_i = U_i \times_{X_i} U_i$, both projections $U_i \times_X U_i \to U_i$ are quasi-compact.
If (2) holds then let $X_i \subset X$ be the open subspace corresponding to the image of the open map $|U_i| \to |X|$, see Properties of Spaces, Lemma Étale morphisms (uncovered prerequisite). The morphisms $U_i \to X_i$ are surjective. Hence $U_i \to X_i$ is surjective étale, and the projections $U_i \times_{X_i} U_i \to U_i$ are quasi-compact, because $U_i \times_{X_i} U_i = U_i \times_X U_i$. Thus by Spaces, Lemma Proper morphisms (uncovered prerequisite) the morphisms $U_i \to X_i$ are quasi-compact. $\square$
Lemma. Descent of schematic neighbourhoods
Let $S$ be a scheme. Let $g : Y \to X$ be a representable morphism of algebraic spaces over $S$. Let $f : U \to X$ be a morphism from a scheme towards $X$. Let $f' : U \times_X Y \to Y$ be the base change of $f$. If $$\operatorname{Im}(|f| : |U| \to |X|) \subset \operatorname{Im}(|g| : |Y| \to |X|)$$ and $f'$ has universally bounded fibres, then $f$ has universally bounded fibres.
Proof. Let $n \geq 0$ be an integer bounding the degrees of the fibre products $\operatorname{Spec}(k) \times_Y (U \times_X Y)$ as in Definition Schematic neighbourhoods for the morphism $f'$. We claim that $n$ works for $f$ also. Namely, suppose that $x : \operatorname{Spec}(k) \to X$ is a morphism from the spectrum of a field. Then either $\operatorname{Spec}(k) \times_X U$ is empty (and there is nothing to prove), or $x$ is in the image of $|f|$. By Properties of Spaces, Lemma Étale geometry of algebraic spaces and the assumption of the lemma we see that this means there exists a field extension $k'/k$ and a commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(k') & Y \\ \operatorname{Spec}(k) & X\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(k') & \longrightarrow Y \\ \operatorname{Spec}(k') & \longrightarrow \operatorname{Spec}(k) \\ Y & \longrightarrow X \\ \operatorname{Spec}(k) & \longrightarrow X\end{aligned}\end{gathered}$$ Hence we see that $$\operatorname{Spec}(k') \times_Y (U \times_X Y) = \operatorname{Spec}(k') \times_{\operatorname{Spec}(k)} (\operatorname{Spec}(k) \times_X U)$$ Since the scheme $\operatorname{Spec}(k') \times_Y (U \times_X Y)$ is assumed finite of degree $\leq n$ over $k'$ it follows that also $\operatorname{Spec}(k) \times_X U$ is finite of degree $\leq n$ over $k$ as desired. (Some details omitted.) $\square$
Lemma. Base change for schematic neighbourhoods
Let $S$ be a scheme. Let $Y \to X$ be a representable morphism of algebraic spaces over $S$. Let $U \to X$ be a morphism from a scheme to $X$. If the fibres of $U \to X$ are universally bounded, then the fibres of $U \times_X Y \to Y$ are universally bounded.
Proof. This is clear from the definition, and properties of fibre products. (Note that $U \times_X Y$ is a scheme as we assumed $Y \to X$ representable, so the definition applies.) $\square$
Lemma. Composition and schematic neighbourhoods
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $V \to U$ be a morphism of schemes over $S$, and let $U \to X$ be a morphism from $U$ to $X$. If the fibres of $V \to U$ and $U \to X$ are universally bounded, then so are the fibres of $V \to X$.
Proof. Let $n$ be an integer which works for $V \to U$, and let $m$ be an integer which works for $U \to X$ in Definition Schematic neighbourhoods. Let $\operatorname{Spec}(k) \to X$ be a morphism, where $k$ is a field. Consider the morphisms $$\operatorname{Spec}(k) \times_X V \longrightarrow \operatorname{Spec}(k) \times_X U \longrightarrow \operatorname{Spec}(k).$$ By assumption the scheme $\operatorname{Spec}(k) \times_X U$ is finite of degree at most $m$ over $k$, and $n$ is an integer which bounds the degree of the fibres of the first morphism. Hence by Morphisms, Lemma Composition and the geometric construction (uncovered prerequisite) we conclude that $\operatorname{Spec}(k) \times_X V$ is finite over $k$ of degree at most $nm$. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$, and let $U$ be a scheme over $S$. Let $\varphi : U \to X$ be a morphism over $S$. If the fibres of $\varphi$ are universally bounded, then there exists an integer $n$ such that each fibre of $|U| \to |X|$ has at most $n$ elements.
Proof. The integer $n$ of Definition Schematic neighbourhoods works. Namely, pick $x \in |X|$. Represent $x$ by a morphism $x : \operatorname{Spec}(k) \to X$. Then we get a commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(k) \times_X U & U \\ \operatorname{Spec}(k) & X\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(k) \times_X U & \longrightarrow U \\ \operatorname{Spec}(k) \times_X U & \longrightarrow \operatorname{Spec}(k) \\ U & \longrightarrow X \\ \operatorname{Spec}(k) & \xrightarrow{x} X\end{aligned}\end{gathered}$$ which shows (via Properties of Spaces, Lemma Étale geometry of algebraic spaces) that the inverse image of $x$ in $|U|$ is the image of the top horizontal arrow. Since $\operatorname{Spec}(k) \times_X U$ is finite of degree $\leq n$ over $k$ it has at most $n$ points. $\square$
Lemma. Schematic neighbourhoods
Let $S$ be a scheme. Let $X$ be a quasi-compact algebraic space over $S$. There exist open subspaces $$\ldots \subset U_4 \subset U_3 \subset U_2 \subset U_1 = X$$ with the following properties:
-
setting $T_p = U_p \setminus U_{p + 1}$ (with reduced induced subspace structure) there exists a separated scheme $V_p$ and a surjective étale morphism $f_p : V_p \to U_p$ such that $f_p^{-1}(T_p) \to T_p$ is an isomorphism,
-
if $x \in |X|$ can be represented by a quasi-compact morphism $\operatorname{Spec}(k) \to X$ from a field, then $x \in T_p$ for some $p$.
Proof. By Properties of Spaces, Lemma Affine neighbourhoods we can choose an affine scheme $U$ and a surjective étale morphism $U \to X$. For $p \geq 0$ set $$W_p = U \times_X \ldots \times_X U \setminus \text{all diagonals}$$ where the fibre product has $p$ factors. Since $U$ is separated, the morphism $U \to X$ is separated and all fibre products $U \times_X \ldots \times_X U$ are separated schemes. Since $U \to X$ is separated the diagonal $U \to U \times_X U$ is a closed immersion. Since $U \to X$ is étale the diagonal $U \to U \times_X U$ is an open immersion, see Morphisms of Spaces, Lemmas Étale morphisms and unramified morphisms and Unramified morphisms and diagonals and separation. Similarly, all the diagonal morphisms are open and closed immersions and $W_p$ is an open and closed subscheme of $U \times_X \ldots \times_X U$. Moreover, the morphism $$U \times_X \ldots \times_X U \longrightarrow U \times_{\operatorname{Spec}(\mathbf{Z})} \ldots \times_{\operatorname{Spec}(\mathbf{Z})} U$$ is locally quasi-finite and separated (Morphisms of Spaces, Lemma Tensor products and direct sums) and its target is an affine scheme. Hence every finite set of points of $U \times_X \ldots \times_X U$ is contained in an affine open, see More on Morphisms, Lemma Diagonals, separation and affine neighbourhoods (uncovered prerequisite). Therefore, the same is true for $W_p$. There is a free action of the symmetric group $S_p$ on $W_p$ over $X$ (because we threw out the fix point locus from $U \times_X \ldots \times_X U$). By the above and Properties of Spaces, Proposition Flatness and groupoids and equivalence relations (uncovered prerequisite) the quotient $V_p = W_p/S_p$ is a scheme. Since the action of $S_p$ on $W_p$ was over $X$, there is a morphism $V_p \to X$. Since $W_p \to X$ is étale and since $W_p \to V_p$ is surjective étale, it follows that also $V_p \to X$ is étale, see Properties of Spaces, Lemma Étale morphisms and local algebra. Observe that $V_p$ is a separated scheme by Properties of Spaces, Lemma Diagonals and separation (uncovered prerequisite).
We let $U_p \subset X$ be the open subspace which is the image of $V_p \to X$. By construction a morphism $\operatorname{Spec}(k) \to X$ with $k$ algebraically closed, factors through $U_p$ if and only if $U \times_X \operatorname{Spec}(k)$ has $\geq p$ points; as usual observe that $U \times_X \operatorname{Spec}(k)$ is scheme theoretically a disjoint union of (possibly infinitely many) copies of $\operatorname{Spec}(k)$, see Remark Schematic neighbourhoods. It follows that the $U_p$ give a filtration of $X$ as stated in the lemma. Moreover, our morphism $\operatorname{Spec}(k) \to X$ factors through $T_p$ if and only if $U \times_X \operatorname{Spec}(k)$ has exactly $p$ points. In this case we see that $V_p \times_X \operatorname{Spec}(k)$ has exactly one point. Set $Z_p = f_p^{-1}(T_p) \subset V_p$. This is a closed subscheme of $V_p$. Then $Z_p \to T_p$ is an étale morphism between algebraic spaces which induces a bijection on $k$-valued points for any algebraically closed field $k$. To be sure this implies that $Z_p \to T_p$ is universally injective, whence an open immersion by Morphisms of Spaces, Lemma Étale morphisms and injective resolutions hence an isomorphism and (1) has been proved.
Let $x : \operatorname{Spec}(k) \to X$ be a quasi-compact morphism where $k$ is a field. Then the composition $\operatorname{Spec}(\overline{k}) \to \operatorname{Spec}(k) \to X$ is quasi-compact as well (Morphisms of Spaces, Lemma Composition and morphisms of algebraic spaces (uncovered prerequisite)). In this case the scheme $U \times_X \operatorname{Spec}(\overline{k})$ is quasi-compact. In view of the fact (seen above) that it is a disjoint union of copies of $\operatorname{Spec}(\overline{k})$ we find that it has finitely many points. If the number of points is $p$, then we see that indeed $x \in T_p$ and the proof is finished. $\square$
Definition. Very reasonable algebraic spaces
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$.
-
We say $X$ is decent if for every point $x \in X$ the equivalent conditions of Lemma Finite algebras hold, in other words property $(\gamma)$ of Lemma Schematic neighbourhoods holds.
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We say $X$ is reasonable if the equivalent conditions of Lemma Schematic neighbourhoods hold, in other words property $(\delta)$ of Lemma Schematic neighbourhoods holds.
-
We say $X$ is very reasonable if the equivalent conditions of Lemma Criteria for schematic neighbourhoods hold, i.e., property $(\epsilon)$ of Lemma Schematic neighbourhoods holds.
Lemma. Schematic neighbourhoods
Let $S$ be a scheme. Let $X$ be a quasi-compact, reasonable algebraic space over $S$. There exist an integer $n$ and open subspaces $$\emptyset = U_{n + 1} \subset U_n \subset U_{n - 1} \subset \ldots \subset U_1 = X$$ with the following property: setting $T_p = U_p \setminus U_{p + 1}$ (with reduced induced subspace structure) there exists a separated scheme $V_p$ and a surjective étale morphism $f_p : V_p \to U_p$ such that $f_p^{-1}(T_p) \to T_p$ is an isomorphism.
Proof. The proof of this lemma is identical to the proof of Lemma Schematic neighbourhoods. Let $n$ be an integer bounding the degrees of the fibres of $U \to X$ which exists as $X$ is reasonable, see Definition Very reasonable algebraic spaces. Then we see that $U_{n + 1} = \emptyset$ and the proof is complete. $\square$
Lemma. Proper morphisms
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. We have the following implications among the conditions on $f$: $$\begin{gathered}\begin{matrix}\text{representable} & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} \\ \phantom{X} & \text{very reasonable} & \text{reasonable} & \text{decent} & (\beta) \\ \text{quasi-separated} & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}\text{representable} & \Longrightarrow \text{very reasonable} \\ \text{very reasonable} & \Longrightarrow \text{reasonable} \\ \text{reasonable} & \Longrightarrow \text{decent} \\ \text{decent} & \Longrightarrow (\beta) \\ \text{quasi-separated} & \Longrightarrow \text{very reasonable}\end{aligned}\end{gathered}$$
Proof. This is clear from the definitions, Lemma Schematic neighbourhoods and Morphisms of Spaces, Lemma Diagonals, separation and local algebra (uncovered prerequisite). $\square$
Lemma. Diagonals, separation and Noetherian rings
Any locally Noetherian decent algebraic space is quasi-separated.
Proof. Namely, let $X$ be an algebraic space (over some base scheme, for example over $\mathbf{Z}$) which is decent and locally Noetherian. Let $U \to X$ and $V \to X$ be étale morphisms with $U$ and $V$ affine schemes. We have to show that $W = U \times_X V$ is quasi-compact (Properties of Spaces, Lemma Criteria for diagonals and separation (uncovered prerequisite)). Since $X$ is locally Noetherian, the schemes $U$, $V$ are Noetherian and $W$ is locally Noetherian. Since $X$ is decent, the fibres of the morphism $W \to U$ are finite. Namely, we can represent any $x \in |X|$ by a quasi-compact monomorphism $\operatorname{Spec}(k) \to X$. Then $U_k$ and $V_k$ are finite disjoint unions of spectra of finite separable extensions of $k$ (Remark Schematic neighbourhoods) and we see that $W_k = U_k \times_{\operatorname{Spec}(k)} V_k$ is finite. Let $n$ be the maximum degree of a fibre of $W \to U$ at a generic point of an irreducible component of $U$. Consider the stratification $$U = U_0 \supset U_1 \supset U_2 \supset \ldots$$ associated to $W \to U$ in More on Morphisms, Lemma Finite presentation and flatness (uncovered prerequisite). By our choice of $n$ above we conclude that $U_{n + 1}$ is empty. Hence we see that the fibres of $W \to U$ are universally bounded. Then we can apply More on Morphisms, Lemma Finite presentation and flatness to find a stratification $$\emptyset = Z_{-1} \subset Z_0 \subset Z_1 \subset Z_2 \subset \ldots \subset Z_n = U$$ by closed subsets such that with $S_r = Z_r \setminus Z_{r - 1}$ the morphism $W \times_U S_r \to S_r$ is finite locally free. Since $U$ is Noetherian, the schemes $S_r$ are Noetherian, whence the schemes $W \times_U S_r$ are Noetherian, whence $W = \coprod W \times_U S_r$ is quasi-compact as desired. $\square$
Lemma. Integral extensions
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$.
-
There exists a surjective integral morphism $Y \to X$ where $Y$ is a scheme,
-
given a surjective étale morphism $U \to X$ we may choose $Y \to X$ such that for every $y \in Y$ there is an open neighbourhood $V \subset Y$ such that $V \to X$ factors through $U$.
Proof. Part (1) is the special case of part (2) where $U = X$. Choose a surjective étale morphism $U' \to U$ where $U'$ is a scheme. It is clear that we may replace $U$ by $U'$ and hence we may assume $U$ is a scheme. Since $X$ is quasi-compact, there exist finitely many affine opens $U_i \subset U$ such that $U' = \coprod U_i \to X$ is surjective. After replacing $U$ by $U'$ again, we see that we may assume $U$ is affine. Since $X$ is quasi-separated, hence reasonable, there exists an integer $d$ bounding the degree of the geometric fibres of $U \to X$ (see Lemma Schematic neighbourhoods). We will prove the lemma by induction on $d$ for all quasi-compact and separated schemes $U$ mapping surjective and étale onto $X$. If $d = 1$, then $U = X$ and the result holds with $Y = U$. Assume $d > 1$.
We apply Morphisms of Spaces, Lemma Diagonals, separation and affine neighbourhoods (uncovered prerequisite) and we obtain a factorization $$\begin{gathered}\begin{matrix}U & \phantom{X} & Y \\ \phantom{X} & X\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{j} Y \\ U & \longrightarrow X \\ Y & \xrightarrow{\pi} X\end{aligned}\end{gathered}$$ with $\pi$ integral and $j$ a quasi-compact open immersion. We may and do assume that $j(U)$ is scheme theoretically dense in $Y$. Then $U \times_X Y$ is a quasi-compact, separated scheme (being integral over $U$) and we have $$U \times_X Y = U \amalg W$$ Here the first summand is the image of $U \to U \times_X Y$ (which is closed by Morphisms of Spaces, Lemma Diagonals and separation and open because it is étale as a morphism between algebraic spaces étale over $Y$) and the second summand is the (open and closed) complement. The image $V \subset Y$ of $W$ is an open subspace containing $Y \setminus U$.
The étale morphism $W \to Y$ has geometric fibres of cardinality $< d$. Namely, this is clear for geometric points of $U \subset Y$ by inspection. Since $|U| \subset |Y|$ is dense, it holds for all geometric points of $Y$ by Lemma Schematic neighbourhoods (the degree of the fibres of a quasi-compact étale morphism does not go up under specialization). Thus we may apply the induction hypothesis to $W \to V$ and find a surjective integral morphism $Z \to V$ with $Z$ a scheme, which Zariski locally factors through $W$. Choose a factorization $Z \to Z' \to Y$ with $Z' \to Y$ integral and $Z \to Z'$ open immersion (Lemma Integral extensions (uncovered prerequisite)). After replacing $Z'$ by the scheme theoretic closure of $Z$ in $Z'$ we may assume that $Z$ is scheme theoretically dense in $Z'$. After doing this we have $Z' \times_Y V = Z$. Finally, let $T \subset Y$ be the induced closed subspace structure on $Y \setminus V$. Consider the morphism $$Z' \amalg T \longrightarrow X$$ This is a surjective integral morphism by construction. Since $T \subset U$ it is clear that the morphism $T \to X$ factors through $U$. On the other hand, let $z \in Z'$ be a point. If $z \not \in Z$, then $z$ maps to a point of $Y \setminus V \subset U$ and we find a neighbourhood of $z$ on which the morphism factors through $U$. If $z \in Z$, then we have an open neighbourhood of $z$ in $Z$ (which is also an open neighbourhood of $z$ in $Z'$) which factors through $W \subset U \times_X Y$ and hence through $U$. $\square$
Geometric support constructions
Lemma. Étale morphisms and unramified morphisms
An étale morphism of algebraic spaces is unramified.
Proof. The proof is identical to the proof of Lemma Étale morphisms and finite algebras. It uses Morphisms, Lemma Étale morphisms and smooth morphisms (uncovered prerequisite). $\square$
Lemma. Unramified morphisms and diagonals and separation
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$.
-
If $f$ is unramified, then the diagonal morphism $\Delta_{X/Y} : X \to X \times_Y X$ is an open immersion.
-
If $f$ is locally of finite type and $\Delta_{X/Y}$ is an open immersion, then $f$ is unramified.
Proof. We know in any case that $\Delta_{X/Y}$ is a representable monomorphism, see Lemma Proper morphisms and diagonals and separation. Choose a scheme $V$ and a surjective étale morphism $V \to Y$. Choose a scheme $U$ and a surjective étale morphism $U \to X \times_Y V$. Consider the commutative diagram $$\begin{gathered}\begin{matrix}U & \phantom{X} & U \times_V U & V \\ X & \phantom{X} & X \times_Y X & V \times_Y V\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \xrightarrow{\Delta_{U/V}} U \times_V U \\ U \times_V U & \longrightarrow X \times_Y X \\ U \times_V U & \longrightarrow V \\ V & \xrightarrow{\Delta_{V/Y}} V \times_Y V \\ X & \xrightarrow{\Delta_{X/Y}} X \times_Y X \\ X \times_Y X & \longrightarrow V \times_Y V\end{aligned}\end{gathered}$$ with cartesian right square. The left vertical arrow is surjective étale. The right vertical arrow is étale as a morphism between schemes étale over $Y$, see Properties of Spaces, Lemma Étale morphisms. Hence the middle vertical arrow is étale too (but it need not be surjective).
Assume $f$ is unramified. Then $U \to V$ is unramified, hence $\Delta_{U/V}$ is an open immersion by Morphisms, Lemma Unramified morphisms and diagonals and separation (uncovered prerequisite). Looking at the left square of the diagram above we conclude that $\Delta_{X/Y}$ is an étale morphism, see Properties of Spaces, Lemma Étale morphisms and local algebra. Hence $\Delta_{X/Y}$ is a representable étale monomorphism, which implies that it is an open immersion by Étale Morphisms, Theorem Étale morphisms (uncovered prerequisite). (See also Spaces, Lemma Proper morphisms (uncovered prerequisite) for the translation from schemes language into the language of functors.)
Assume that $f$ is locally of finite type and that $\Delta_{X/Y}$ is an open immersion. This implies that $U \to V$ is locally of finite type too (by definition of a morphism of algebraic spaces which is locally of finite type). Looking at the displayed diagram above we conclude that $\Delta_{U/V}$ is étale as a morphism between schemes étale over $X \times_Y X$, see Properties of Spaces, Lemma Étale morphisms. But since $\Delta_{U/V}$ is the diagonal of a morphism between schemes we see that it is in any case an immersion, see Schemes, Lemma Diagonals and separation (uncovered prerequisite). Hence it is an open immersion, and we conclude that $U \to V$ is unramified by Morphisms, Lemma Unramified morphisms and diagonals and separation (uncovered prerequisite). This in turn means that $f$ is unramified by definition. $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $B$ be an algebraic space over $S$. Let $f, g : X \to Y$ be morphisms of algebraic spaces over $B$. Let $U \subset X$ be an open subspace such that $f|_U = g|_U$. If the scheme theoretic closure of $U$ in $X$ is $X$ and $Y \to B$ is separated, then $f = g$.
Proof. As $Y \to B$ is separated the fibre product $Y \times_{\Delta, Y \times_B Y, (f, g)} X$ is a closed subspace $Z \subset X$. As $f|_U = g|_U$ we see that $U \subset Z$. Hence $Z = X$ as $U$ is assumed scheme theoretically dense in $X$. $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ and $h : U \to X$ be morphisms of algebraic spaces over $S$. If
-
$f$ and $h$ are quasi-compact,
-
$|h|(|U|)$ is dense in $|X|$, and
given any commutative solid diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & U & X \\ \operatorname{Spec}(A) & \phantom{X} & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \longrightarrow U \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(A) \\ U & \longrightarrow X \\ X & \longrightarrow Y \\ \operatorname{Spec}(A) & \longrightarrow Y \\ \operatorname{Spec}(A) & \dashrightarrow X\end{aligned}\end{gathered}$$ where $A$ is a valuation ring with field of fractions $K$
-
there exists at most one dotted arrow making the diagram commute, and
-
there exists an extension $K'/K$ of fields, a valuation ring $A' \subset K'$ dominating $A$ and a morphism $\operatorname{Spec}(A') \to X$ such that the following diagram commutes $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K') & \operatorname{Spec}(K) & U & X \\ \operatorname{Spec}(A') & \operatorname{Spec}(A) & \phantom{X} & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K') & \longrightarrow \operatorname{Spec}(K) \\ \operatorname{Spec}(K') & \longrightarrow \operatorname{Spec}(A') \\ \operatorname{Spec}(K) & \longrightarrow U \\ U & \longrightarrow X \\ X & \longrightarrow Y \\ \operatorname{Spec}(A') & \longrightarrow \operatorname{Spec}(A) \\ \operatorname{Spec}(A') & \longrightarrow X \\ \operatorname{Spec}(A) & \longrightarrow Y\end{aligned}\end{gathered}$$
then $f$ is universally closed. If moreover
- $f$ is quasi-separated
then $f$ is separated and universally closed.
Proof. Assume (1), (2), (3), and (4). We will verify the existence part of the valuative criterion for $f$ which will imply $f$ is universally closed by Lemma Morphisms of algebraic spaces. To do this, consider a commutative diagram
$$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & X \\ \operatorname{Spec}(A) & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \longrightarrow X \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(A) \\ X & \longrightarrow Y \\ \operatorname{Spec}(A) & \longrightarrow Y\end{aligned}\end{gathered}$$ where $A$ is a valuation ring and $K$ is the fraction field of $A$. Note that since valuation rings and fields are reduced, we may replace $U$, $X$, and $S$ by their respective reductions by Properties of Spaces, Lemma Étale geometry of algebraic spaces. In this case the assumption that $h(U)$ is dense means that the scheme theoretic image of $h : U \to X$ is $X$, see Lemma Morphisms of algebraic spaces.
Reduction to the case $Y$ affine. Choose an étale morphism $\operatorname{Spec}(R) \to Y$ such that the closed point of $\operatorname{Spec}(A)$ maps to an element of $\operatorname{Im}(|\operatorname{Spec}(R)| \to |Y|)$. By Lemma Lifting flatness we can find a local ring map $A \to A'$ of valuation rings and a morphism $\operatorname{Spec}(A') \to \operatorname{Spec}(R)$ fitting into a commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(A') & \operatorname{Spec}(R) \\ \operatorname{Spec}(A) & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(A') & \longrightarrow \operatorname{Spec}(R) \\ \operatorname{Spec}(A') & \longrightarrow \operatorname{Spec}(A) \\ \operatorname{Spec}(R) & \longrightarrow Y \\ \operatorname{Spec}(A) & \longrightarrow Y\end{aligned}\end{gathered}$$ Since in Definition The valuative lifting property we allow for extensions of valuation rings it is clear that we may replace $A$ by $A'$, $Y$ by $\operatorname{Spec}(R)$, $X$ by $X \times_Y \operatorname{Spec}(R)$ and $U$ by $U \times_Y \operatorname{Spec}(R)$.
From now on we assume that $Y = \operatorname{Spec}(R)$ is an affine scheme. Let $\operatorname{Spec}(B) \to X$ be an étale morphism from an affine scheme such that the morphism $\operatorname{Spec}(K) \to X$ is in the image of $|\operatorname{Spec}(B)| \to |X|$. Since we may replace $K$ by an extension $K' \supset K$ and $A$ by a valuation ring $A' \subset K'$ dominating $A$ (which exists by Algebra, Lemma A valuation ring dominating a local domain), we may assume the morphism $\operatorname{Spec}(K) \to X$ factors through $\operatorname{Spec}(B)$ (by definition of $|X|$). In other words, we may think of $K$ as a $B$-algebra. Choose a polynomial algebra $P$ over $B$ and a $B$-algebra surjection $P \to K$. Then $\operatorname{Spec}(P) \to X$ is flat as a composition $\operatorname{Spec}(P) \to \operatorname{Spec}(B) \to X$. Hence the scheme theoretic image of the morphism $U \times_X \operatorname{Spec}(P) \to \operatorname{Spec}(P)$ is $\operatorname{Spec}(P)$ by Lemma Base change for flatness. By Lemma Morphisms of algebraic spaces we can find a commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K') & U \times_X \operatorname{Spec}(P) \\ \operatorname{Spec}(A') & \operatorname{Spec}(P)\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K') & \longrightarrow U \times_X \operatorname{Spec}(P) \\ \operatorname{Spec}(K') & \longrightarrow \operatorname{Spec}(A') \\ U \times_X \operatorname{Spec}(P) & \longrightarrow \operatorname{Spec}(P) \\ \operatorname{Spec}(A') & \longrightarrow \operatorname{Spec}(P)\end{aligned}\end{gathered}$$ where $A'$ is a valuation ring and $K'$ is the fraction field of $A'$ such that the closed point of $\operatorname{Spec}(A')$ maps to $\operatorname{Spec}(K) \subset \operatorname{Spec}(P)$. In other words, there is a $B$-algebra map $\varphi : K \to A'/\mathfrak m_{A'}$. Choose a valuation ring $A'' \subset A'/\mathfrak m_{A'}$ dominating $\varphi(A)$ with field of fractions $K'' = A'/\mathfrak m_{A'}$ (Algebra, Lemma A valuation ring dominating a local domain). We set $$C = \{\lambda \in A' \mid \lambda \bmod \mathfrak m_{A'} \in A''\}.$$ which is a valuation ring by Algebra, Lemma Commutative algebra. As $C$ is an $R$-algebra with fraction field $K'$, we obtain a solid commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K'_1) & \operatorname{Spec}(K') & U & X \\ \operatorname{Spec}(C_1) & \operatorname{Spec}(C) & \phantom{X} & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K'_1) & \dashrightarrow \operatorname{Spec}(K') \\ \operatorname{Spec}(K'_1) & \dashrightarrow \operatorname{Spec}(C_1) \\ \operatorname{Spec}(K') & \longrightarrow U \\ \operatorname{Spec}(K') & \longrightarrow \operatorname{Spec}(C) \\ U & \longrightarrow X \\ X & \longrightarrow Y \\ \operatorname{Spec}(C_1) & \dashrightarrow \operatorname{Spec}(C) \\ \operatorname{Spec}(C_1) & \dashrightarrow X \\ \operatorname{Spec}(C) & \longrightarrow Y\end{aligned}\end{gathered}$$ as in the statement of the lemma. Thus assumption (4) produces $C \to C_1$ and the dotted arrows making the diagram commute. Let $A_1' = (C_1)_\mathfrak p$ be the localization of $C_1$ at a prime $\mathfrak p \subset C_1$ lying over $\mathfrak m_{A'} \subset C$. Since $C \to C_1$ is flat by More on Algebra, Lemma Projective, locally free modules and flatness such a prime $\mathfrak p$ exists by Algebra, Lemmas Flatness and local algebra and Faithfully flat ring maps. Note that $A'$ is the localization of $C$ at $\mathfrak m_{A'}$ and that $A'_1$ is a valuation ring (Algebra, Lemma Commutative algebra). In other words, $A' \to A'_1$ is a local ring map of valuation rings. Assumption (3) implies $$\begin{gathered}\begin{matrix}\operatorname{Spec}(A'_1) & \operatorname{Spec}(C_1) & X \\ \operatorname{Spec}(A') & \operatorname{Spec}(P) & \operatorname{Spec}(B)\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(A'_1) & \longrightarrow \operatorname{Spec}(C_1) \\ \operatorname{Spec}(A'_1) & \longrightarrow \operatorname{Spec}(A') \\ \operatorname{Spec}(C_1) & \longrightarrow X \\ \operatorname{Spec}(A') & \longrightarrow \operatorname{Spec}(P) \\ \operatorname{Spec}(P) & \longrightarrow \operatorname{Spec}(B) \\ \operatorname{Spec}(B) & \longrightarrow X\end{aligned}\end{gathered}$$ commutes. Hence the restriction of the morphism $\operatorname{Spec}(C_1) \to X$ to $\operatorname{Spec}(C_1/\mathfrak p)$ restricts to the composition $$\operatorname{Spec}(\kappa(\mathfrak p)) \to \operatorname{Spec}(A'/\mathfrak m_{A'}) = \operatorname{Spec}(K'') \to \operatorname{Spec}(K) \to X$$ on the generic point of $\operatorname{Spec}(C_1/\mathfrak p)$. Moreover, $C_1/\mathfrak p$ is a valuation ring (Algebra, Lemma Commutative algebra) dominating $A''$ which dominates $A$. Thus the morphism $\operatorname{Spec}(C_1/\mathfrak p) \to X$ witnesses the existence part of the valuative criterion for the diagram (the displayed identity) as desired.
Next, suppose that (5) is satisfied as well, i.e., the morphism $\Delta : X \to X \times_S X$ is quasi-compact. In this case assumptions (1) -- (4) hold for $h$ and $\Delta$. Hence the first part of the proof shows that $\Delta$ is universally closed. By Lemma Proper morphisms and diagonals and separation we conclude that $f$ is separated. $\square$
Lemma. Lifting flatness
Let $S$ be a scheme. Let $f : X \to Y$ be a flat morphism of algebraic spaces over $S$. Let $\operatorname{Spec}(A) \to Y$ be a morphism where $A$ is a valuation ring. If the closed point of $\operatorname{Spec}(A)$ maps to a point of $|Y|$ in the image of $|X| \to |Y|$, then there exists a commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(A') & X \\ \operatorname{Spec}(A) & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(A') & \longrightarrow X \\ \operatorname{Spec}(A') & \longrightarrow \operatorname{Spec}(A) \\ X & \longrightarrow Y \\ \operatorname{Spec}(A) & \longrightarrow Y\end{aligned}\end{gathered}$$ where $A \to A'$ is an extension of valuation rings (More on Algebra, Definition Derived commutative algebra).
Proof. The base change $X_A \to \operatorname{Spec}(A)$ is flat (Lemma Base change for flatness) and the closed point of $\operatorname{Spec}(A)$ is in the image of $|X_A| \to |\operatorname{Spec}(A)|$ (Properties of Spaces, Lemma Étale geometry of algebraic spaces). Thus we may assume $Y = \operatorname{Spec}(A)$. Let $U \to X$ be a surjective étale morphism where $U$ is a scheme. Let $u \in U$ map to the closed point of $\operatorname{Spec}(A)$. Consider the flat local ring map $A \to B = \mathcal{O}_{U, u}$. By Algebra, Lemma Faithfully flat ring maps there exists a prime ideal $\mathfrak q \subset B$ such that $\mathfrak q$ lies over $(0) \subset A$. By Algebra, Lemma A valuation ring dominating a local domain we can find a valuation ring $A' \subset \kappa(\mathfrak q)$ dominating $B/\mathfrak q$. The induced morphism $\operatorname{Spec}(A') \to U \to X$ is a solution to the problem posed by the lemma. $\square$
Lemma. Noetherian rings and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. If $f$ is locally of finite type and $Y$ is locally Noetherian, then $X$ is locally Noetherian.
Proof. Let $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ be a commutative diagram where $U$, $V$ are schemes and the vertical arrows are surjective étale. If $f$ is locally of finite type, then $U \to V$ is locally of finite type. If $Y$ is locally Noetherian, then $V$ is locally Noetherian. By Morphisms, Lemma Noetherian rings and finite algebras (uncovered prerequisite) we see that $U$ is locally Noetherian, which means that $X$ is locally Noetherian. $\square$
Lemma. Finite presentation and Noetherian rings
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$.
-
If $Y$ is locally Noetherian and $f$ locally of finite type then $f$ is locally of finite presentation.
-
If $Y$ is locally Noetherian and $f$ of finite type and quasi-separated then $f$ is of finite presentation.
Proof. Assume $f : X \to Y$ locally of finite type and $Y$ locally Noetherian. This means there exists a diagram as in Lemma Local algebra with $h$ locally of finite type and surjective vertical arrow $a$. By Morphisms, Lemma Finite presentation and Noetherian rings (uncovered prerequisite) $h$ is locally of finite presentation. Hence $X \to Y$ is locally of finite presentation by definition. This proves (1). If $f$ is of finite type and quasi-separated then it is also quasi-compact and quasi-separated and (2) follows immediately. $\square$
Lemma. Finite presentation and Noetherian rings
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. If $f$ is of finite presentation and $Y$ is Noetherian, then $X$ is Noetherian.
Proof. Assume $f$ is of finite presentation and $Y$ Noetherian. By Lemmas Finite presentation and finite algebras and Noetherian rings and finite algebras we see that $X$ is locally Noetherian. As $f$ is quasi-compact and $Y$ is quasi-compact we see that $X$ is quasi-compact. As $f$ is of finite presentation it is quasi-separated (see Definition Finite presentation and finite algebras) and as $Y$ is Noetherian it is quasi-separated (see Properties of Spaces, Definition Noetherian algebraic spaces). Hence $X$ is quasi-separated by Lemma Diagonals and separation. Hence we have checked all three conditions of Properties of Spaces, Definition Noetherian algebraic spaces and we win. $\square$
Lemma. Diagonals, separation and affine neighbourhoods
A closed immersion is affine.
Proof. Follows immediately from the corresponding statement for morphisms of schemes, see Morphisms, Lemma Diagonals, separation and affine neighbourhoods (uncovered prerequisite). $\square$
Lemma. Composition and proper morphisms
A composition of proper morphisms is proper.
Proof. See Lemmas Composition and diagonals and separation, Composition and finite algebras, and Composition and morphisms of algebraic spaces. $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Consider a commutative diagram of algebraic spaces $$\begin{gathered}\begin{matrix}X & \phantom{X} & Y \\ \phantom{X} & B & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow Y \\ X & \longrightarrow B \\ Y & \longrightarrow B\end{aligned}\end{gathered}$$ over $S$.
-
If $X \to B$ is universally closed and $Y \to B$ is separated, then the morphism $X \to Y$ is universally closed. In particular, the image of $|X|$ in $|Y|$ is closed.
-
If $X \to B$ is proper and $Y \to B$ is separated, then the morphism $X \to Y$ is proper.
Proof. Assume $X \to B$ is universally closed and $Y \to B$ is separated. We factor the morphism as $X \to X \times_B Y \to Y$. The first morphism is a closed immersion, see Lemma Diagonals and separation hence universally closed. The projection $X \times_B Y \to Y$ is the base change of a universally closed morphism and hence universally closed, see Lemma Base change for morphisms of algebraic spaces. Thus $X \to Y$ is universally closed as the composition of universally closed morphisms, see Lemma Composition and morphisms of algebraic spaces. This proves (1). To deduce (2) combine (1) with Lemmas Composition and diagonals and separation, Morphisms of algebraic spaces, and Finite algebras. $\square$
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $i : Z \to X$ be an immersion of algebraic spaces over $S$. Then $|i| : |Z| \to |X|$ is a homeomorphism onto a locally closed subset, and $i$ is a closed immersion if and only if the image $|i|(|Z|) \subset |X|$ is a closed subset.
Proof. The first statement is Properties of Spaces, Lemma Étale geometry of algebraic spaces. Let $U$ be a scheme and let $U \to X$ be a surjective étale morphism. By assumption $T = U \times_X Z$ is a scheme and the morphism $j : T \to U$ is an immersion of schemes. By Lemma Diagonals, separation and local algebra the morphism $i$ is a closed immersion if and only if $j$ is a closed immersion. By Schemes, Lemma Diagonals and separation (uncovered prerequisite) this is true if and only if $j(T)$ is closed in $U$. However, the subset $j(T) \subset U$ is the inverse image of $|i|(|Z|) \subset |X|$, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. This finishes the proof. $\square$
Lemma. Diagonals and separation
Properties of the graph of a morphism of algebraic spaces as a consequence of separation properties of the target.
Let $S$ be a scheme. Let $T$ be an algebraic space over $S$. Let $g : X \to Y$ be a morphism of algebraic spaces over $T$. Consider the graph $i : X \to X \times_T Y$ of $g$. Then
-
$i$ is representable, locally of finite type, locally quasi-finite, separated and a monomorphism,
-
if $Y \to T$ is locally separated, then $i$ is an immersion,
-
if $Y \to T$ is separated, then $i$ is a closed immersion, and
-
if $Y \to T$ is quasi-separated, then $i$ is quasi-compact.
Proof. This is a special case of Lemma Tensor products and direct sums applied to the morphism $X = X \times_Y Y \to X \times_T Y$. $\square$
Lemma. Closed support and finite algebras
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Then
-
The support of $\mathcal{F}$ is closed.
-
For a geometric point $\overline{x}$ lying over $x \in |X|$ we have $$x \in \text{Supp}(\mathcal{F}) \Leftrightarrow \mathcal{F}_{\overline{x}} \not = 0 \Leftrightarrow \mathcal{F}_{\overline{x}} \otimes_{\mathcal{O}_{X, \overline{x}}} \kappa(\overline{x}) \not = 0.$$
-
For any morphism of algebraic spaces $f : Y \to X$ the pullback $f^*\mathcal{F}$ is of finite type as well and we have $\text{Supp}(f^*\mathcal{F}) = f^{-1}(\text{Supp}(\mathcal{F}))$.
Proof. Choose a scheme $U$ and a surjective étale morphism $\varphi : U \to X$. By Lemma Closed support the inverse image of the support of $\mathcal{F}$ is the support of $\varphi^*\mathcal{F}$ which is closed by Morphisms, Lemma Closed support and finite algebras (uncovered prerequisite). Thus (1) follows from the definition of the topology on $|X|$.
The first equivalence in (2) is the definition of support. The second equivalence follows from Nakayama's lemma, see Algebra, Lemma Nakayama's lemma.
Let $f : Y \to X$ be as in (3). Note that $f^*\mathcal{F}$ is of finite type by Properties of Spaces, Section Proper morphisms and modules. For the final assertion, let $\overline{y}$ be a geometric point of $Y$ mapping to the geometric point $\overline{x}$ on $X$. Recall that $$(f^*\mathcal{F})_{\overline{y}} = \mathcal{F}_{\overline{x}} \otimes_{\mathcal{O}_{X, \overline{x}}} \mathcal{O}_{Y, \overline{y}},$$ see Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. Hence $(f^*\mathcal{F})_{\overline{y}} \otimes \kappa(\overline{y})$ is nonzero if and only if $\mathcal{F}_{\overline{x}} \otimes \kappa(\overline{x})$ is nonzero. By (2) this implies $x \in \text{Supp}(\mathcal{F})$ if and only if $y \in \text{Supp}(f^*\mathcal{F})$, which is the content of assertion (3). $\square$
Lemma. Proper morphisms
Let $S$ be a scheme. Let $B$ be an algebraic space over $S$. Let $f : X \to Y$ be a morphism of algebraic spaces over $B$. If $X$ is universally closed over $B$ and $f$ is surjective then $Y$ is universally closed over $B$. In particular, if also $Y$ is separated and of finite type over $B$, then $Y$ is proper over $B$.
Proof. Assume $X$ is universally closed and $f$ surjective. Denote $p : X \to B$, $q : Y \to B$ the structure morphisms. Let $B' \to B$ be a morphism of algebraic spaces over $S$. The base change $f' : X_{B'} \to Y_{B'}$ is surjective (Lemma Base change for morphisms of algebraic spaces), and the base change $p' : X_{B'} \to B'$ is closed. If $T \subset Y_{B'}$ is closed, then $(f')^{-1}(T) \subset X_{B'}$ is closed, hence $p'((f')^{-1}(T)) = q'(T)$ is closed. So $q'$ is closed. $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a separated morphism of algebraic spaces over $S$. Let $V \subset Y$ be an open subspace such that $V \to Y$ is quasi-compact. Let $s : V \to X$ be a morphism such that $f \circ s = \text{id}_V$. Let $Y'$ be the scheme theoretic image of $s$. Then $Y' \to Y$ is an isomorphism over $V$.
Proof. By Lemma Morphisms of algebraic spaces the morphism $s : V \to X$ is quasi-compact. Hence the construction of the scheme theoretic image $Y'$ of $s$ commutes with restriction to opens by Lemma Morphisms of algebraic spaces. In particular, we see that $Y' \cap f^{-1}(V)$ is the scheme theoretic image of a section of the separated morphism $f^{-1}(V) \to V$. Since a section of a separated morphism is a closed immersion (Lemma Diagonals and separation), we conclude that $Y' \cap f^{-1}(V) \to V$ is an isomorphism as desired. $\square$
Lemma. Finite presentation and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ and $Y \to Z$ be morphisms of algebraic spaces over $S$. If $X$ is locally of finite presentation over $Z$, and $Y$ is locally of finite type over $Z$, then $f$ is locally of finite presentation.
Proof. Choose a scheme $W$ and a surjective étale morphism $W \to Z$. Then choose a scheme $V$ and a surjective étale morphism $V \to W \times_Z Y$. Finally choose a scheme $U$ and a surjective étale morphism $U \to V \times_Y X$. By definition $U$ is locally of finite presentation over $W$ and $V$ is locally of finite type over $W$. By Morphisms, Lemma Finite presentation and finite algebras (uncovered prerequisite) the morphism $U \to V$ is locally of finite presentation. Hence $f$ is locally of finite presentation. $\square$
Definition. Closed support
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. The scheme theoretic support of $\mathcal{F}$ is the closed subspace $Z \subset X$ constructed in Lemma Closed support.
Lemma. Groupoids and equivalence relations
Let $S$ be a scheme. Let $i : Z \to X$ be a closed immersion of algebraic spaces over $S$. Let $\mathcal{I} \subset \mathcal{O}_X$ be the quasi-coherent sheaf of ideals cutting out $Z$.
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For any $\mathcal{O}_X$-module $\mathcal{F}$ the adjunction map $\mathcal{F} \to i_*i^*\mathcal{F}$ induces an isomorphism $\mathcal{F}/\mathcal{I}\mathcal{F} \cong i_*i^*\mathcal{F}$.
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The functor $i^*$ is a left inverse to $i_*$, i.e., for any $\mathcal{O}_Z$-module $\mathcal{G}$ the adjunction map $i^*i_*\mathcal{G} \to \mathcal{G}$ is an isomorphism.
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The functor $$i_* : \mathrm{QCoh}(\mathcal{O}_Z) \longrightarrow \mathrm{QCoh}(\mathcal{O}_X)$$ is exact, fully faithful, with essential image those quasi-coherent $\mathcal{O}_X$-modules $\mathcal{F}$ such that $\mathcal{I}\mathcal{F} = 0$.
Proof. During this proof we work exclusively with sheaves on the small étale sites, and we use $i_*, i^{-1}, \ldots$ to denote pushforward and pullback of sheaves of abelian groups instead of $i_{small, *}, i_{small}^{-1}$.
Let $\mathcal{F}$ be an $\mathcal{O}_X$-module. By Lemma Diagonals and separation applied with $\mathcal{A} = \mathcal{O}_X$ and $\mathcal{G} = \mathcal{B} = \mathcal{O}_Z$ we see that $i_*i^*\mathcal{F} = \mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{O}_Z$. By Lemma Diagonals and separation we see that we have a short exact sequence $$0 \to \mathcal{I} \to \mathcal{O}_X \to i_*\mathcal{O}_Z \to 0$$ It follows from properties of the tensor product that $\mathcal{F} \otimes_{\mathcal{O}_X} i_*\mathcal{O}_Z = \mathcal{F}/\mathcal{I}\mathcal{F}$. This proves (1) (except that we omit the verification that the map is induced by the adjunction mapping).
Let $\mathcal{G}$ be any $\mathcal{O}_Z$-module. By Lemma Diagonals and separation we see that $i^{-1}i_*\mathcal{G} = \mathcal{G}$. Hence to prove (2) we have to show that the canonical map $\mathcal{G} \otimes_{i^{-1}\mathcal{O}_X} \mathcal{O}_Z \to \mathcal{G}$ is an isomorphism. This follows from general properties of tensor products if we can show that $i^{-1}\mathcal{O}_X \to \mathcal{O}_Z$ is surjective. By Lemma Diagonals and separation it suffices to prove that $i_*i^{-1}\mathcal{O}_X \to i_*\mathcal{O}_Z$ is surjective. Since the surjective map $\mathcal{O}_X \to i_*\mathcal{O}_Z$ factors through this map we see that (2) holds.
Finally we prove the most interesting part of the lemma, namely part (3). A closed immersion is quasi-compact and separated, see Lemmas Diagonals and separation and Diagonals and separation. Hence Lemma Direct images and morphisms of algebraic spaces applies and the pushforward of a quasi-coherent sheaf on $Z$ is indeed a quasi-coherent sheaf on $X$. Thus we obtain our functor $i^{QCoh}_* : \mathrm{QCoh}(\mathcal{O}_Z) \to \mathrm{QCoh}(\mathcal{O}_X)$. It is clear from part (2) that $i^{QCoh}_*$ is fully faithful since it has a left inverse, namely $i^*$.
Now we turn to the description of the essential image of the functor $i_*$. It is clear that $\mathcal{I}(i_*\mathcal{G}) = 0$ for any $\mathcal{O}_Z$-module, since $\mathcal{I}$ is the kernel of the map $\mathcal{O}_X \to i_*\mathcal{O}_Z$ which is the map we use to put an $\mathcal{O}_X$-module structure on $i_*\mathcal{G}$. Next, suppose that $\mathcal{F}$ is any quasi-coherent $\mathcal{O}_X$-module such that $\mathcal{I}\mathcal{F} = 0$. Then we see that $\mathcal{F}$ is an $i_*\mathcal{O}_Z$-module because $i_*\mathcal{O}_Z = \mathcal{O}_X/\mathcal{I}$. Hence in particular its support is contained in $|Z|$. We apply Lemma Diagonals and separation to see that $\mathcal{F} \cong i_*\mathcal{G}$ for some $\mathcal{O}_Z$-module $\mathcal{G}$. The only small detail left over is to see why $\mathcal{G}$ is quasi-coherent. This is true because $\mathcal{G} \cong i^*\mathcal{F}$ by part (2) and Properties of Spaces, Lemma Pullback of quasi-coherent complexes and coherent sheaves. $\square$
Proposition. Diagonals, separation and finite algebras
Let $S$ be a scheme. Let $f : X \to T$ be a morphism of algebraic spaces over $S$. Assume
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$T$ is representable,
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$f$ is locally quasi-finite, and
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$f$ is separated.
Then $X$ is representable.
Proof. Let $T = \bigcup T_i$ be an affine open covering of the scheme $T$. If we can show that the open subspaces $X_i = f^{-1}(T_i)$ are representable, then $X$ is representable, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. Note that $X_i = T_i \times_T X$ and that locally quasi-finite and separated are both stable under base change, see Lemmas Base change for diagonals and separation and Base change for finite algebras. Hence we may assume $T$ is an affine scheme.
By Properties of Spaces, Lemma Étale geometry of algebraic spaces there exists a Zariski covering $X = \bigcup X_i$ such that each $X_i$ has a surjective étale covering by an affine scheme. By Properties of Spaces, Lemma Étale geometry of algebraic spaces again it suffices to prove the proposition for each $X_i$. Hence we may assume there exists an affine scheme $U$ and a surjective étale morphism $U \to X$. This reduces us to the situation in the next paragraph.
Assume we have $$U \longrightarrow X \longrightarrow T$$ where $U$ and $T$ are affine schemes, $U \to X$ is étale surjective, and $X \to T$ is separated and locally quasi-finite. By Lemmas Étale morphisms and finite algebras and Composition and finite algebras the morphism $U \to T$ is locally quasi-finite. Since $U$ and $T$ are affine it is quasi-finite. Set $R = U \times_X U$. Then $X = U/R$, see Spaces, Lemma The geometric construction (uncovered prerequisite). As $X \to T$ is separated the morphism $R \to U \times_T U$ is a closed immersion, see Lemma Tensor products and direct sums. In particular $R$ is an affine scheme also. As $U \to X$ is étale the projection morphisms $t, s : R \to U$ are étale as well. In particular $s$ and $t$ are quasi-finite, flat and of finite presentation (see Morphisms, Lemmas Étale morphisms and finite algebras (uncovered prerequisite), Étale morphisms and flatness (uncovered prerequisite) and Étale morphisms and finite presentation (uncovered prerequisite)).
Let $(U, R, s, t, c)$ be the groupoid associated to the étale equivalence relation $R$ on $U$. Let $u \in U$ be a point, and denote $p \in T$ its image. We are going to use More on Groupoids, Lemma Quasi-finite groupoids with proper relation map for the groupoid $(U, R, s, t, c)$ over the scheme $T$ with points $p$ and $u$ as above. By the discussion in the previous paragraph all the assumptions (1) -- (7) of that lemma are satisfied. Hence we get an étale neighbourhood $(T', p') \to (T, p)$ and disjoint union decompositions $$U_{T'} = U' \amalg W, \quad R_{T'} = R' \amalg W'$$ and $u' \in U'$ satisfying conclusions (a), (b), (c), (d), (e), (f), (g), and (h) of the aforementioned More on Groupoids, Lemma Quasi-finite groupoids with proper relation map. We may and do assume that $T'$ is affine (after possibly shrinking $T'$). Conclusion (h) implies that $R' = U' \times_{X_{T'}} U'$ with projection mappings identified with the restrictions of $s'$ and $t'$. Thus $(U', R', s'|_{R'}, t'|_{R'}, c'|_{R' \times_{t', U', s'} R'})$ of conclusion (g) is an étale equivalence relation. By Spaces, Lemma The geometric construction (uncovered prerequisite) we conclude that $U'/R'$ is an open subspace of $X_{T'}$. By conclusion (d) the schemes $U'$, $R'$ are affine and the morphisms $s'|_{R'}, t'|_{R'}$ are finite étale. Hence Groupoids, Proposition Flatness and groupoids and equivalence relations kicks in and we see that $U'/R'$ is an affine scheme.
We conclude that for every pair of points $(u, p)$ as above we can find an étale neighbourhood $(T', p') \to (T, p)$ with $\kappa(p) = \kappa(p')$ and a point $u' \in U_{T'}$ mapping to $u$ such that the image $x'$ of $u'$ in $|X_{T'}|$ has an open neighbourhood $V'$ in $X_{T'}$ which is an affine scheme. We apply Lemma Morphisms of algebraic spaces to obtain an open subspace $W \subset X$ which is a scheme, and which contains $x$ (the image of $u$ in $|X|$). Since this works for every $x$ we see that $X$ is a scheme by Properties of Spaces, Lemma Étale geometry of algebraic spaces. This ends the proof. $\square$
Definition. The dimension of a fibre
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $x \in |X|$. Let $d, r \in \{0, 1, 2, \ldots, \infty\}$.
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We say the dimension of the local ring of the fibre of $f$ at $x$ is $d$ if the equivalent conditions of Lemma Local algebra hold for the property $\mathcal{P}_d$ described in Descent, Lemma Dimension, codimension and local algebra.
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We say the transcendence degree of $x/f(x)$ is $r$ if the equivalent conditions of Lemma Local algebra hold for the property $\mathcal{P}_r$ described in Descent, Lemma The geometric construction.
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We say $f$ has relative dimension $d$ at $x$ if the equivalent conditions of Lemma Local algebra hold for the property $\mathcal{P}_d$ described in Descent, Lemma Dimension and codimension.
Lemma. Base change for finite algebras
A base change of a finite type morphism is finite type. The same holds for locally of finite type.
Proof. See Remark Base change for morphisms of algebraic spaces and Morphisms, Lemma Base change for finite algebras (uncovered prerequisite). $\square$
Lemma. Base change for finite presentation and finite algebras
A base change of a morphism of finite presentation is of finite presentation. The same holds for locally of finite presentation.
Proof. See Remark Base change for morphisms of algebraic spaces and Morphisms, Lemma Base change for finite presentation and finite algebras (uncovered prerequisite). Also use the result for quasi-compact and for quasi-separated morphisms (Lemmas Base change for morphisms of algebraic spaces and Base change for diagonals and separation). $\square$
Lemma. Base change for flatness
The base change of a flat morphism is flat.
Proof. See Remark Base change for morphisms of algebraic spaces and Morphisms, Lemma Base change for flatness (uncovered prerequisite). $\square$
Lemma. Base change for proper morphisms
A base change of a proper morphism is proper.
Proof. See Lemmas Base change for diagonals and separation, Base change for finite algebras, and Base change for morphisms of algebraic spaces. $\square$
Definition. Relative dimension
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $d \in \{0, 1, 2, \ldots\}$.
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We say $f$ has relative dimension $\leq d$ if $f$ has relative dimension $\leq d$ at all $x \in |X|$.
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We say $f$ has relative dimension $d$ if $f$ has relative dimension $d$ at all $x \in |X|$.
Lemma. Base change for dimension and codimension
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ be a fibre product diagram of algebraic spaces over $S$. Let $x' \in |X'|$. Set $x = g'(x')$. Assume $f$ locally of finite type. Then
- $$\begin{matrix} \text{relative dimension of }f\text{ at }x \\ = \\ \text{relative dimension of }f'\text{ at }x' \end{matrix}$$
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we have $$\begin{matrix} \text{dimension of local ring of the fibre of }f'\text{ at }x' \
- \ \text{dimension of local ring of the fibre of }f\text{ at }x \ = \ \text{transcendence degree of }x/f(x) \
- \ \text{transcendence degree of }x'/f'(x') \end{matrix}$$ and the common value is $\geq 0$,
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given $x$ and $y' \in |Y'|$ mapping to the same $y \in |Y|$ there exists a choice of $x'$ such that the integer in (2) is $0$.
Proof. Choose a surjective étale morphism $V \to Y$ with $V$ a scheme. Choose a surjective étale morphism $U \to V \times_Y X$ with $U$ a scheme. Choose a surjective étale morphism $V' \to V \times_Y Y'$ with $V'$ a scheme. Set $U' = V' \times_V U$. Then the induced morphism $U' \to X'$ is also surjective and étale (argument omitted). Choose $u' \in U'$ mapping to $x'$. At this point parts (1) and (2) follow by applying Morphisms, Lemma Base change for dimension and codimension (uncovered prerequisite) to the diagram of schemes involving $U', U, V', V$ and the point $u'$. To prove (3) first choose $v \in V$ mapping to $y$. Then using Properties of Spaces, Lemma Étale geometry of algebraic spaces we can choose $v' \in V'$ mapping to $y'$ and $v$ and $u \in U$ mapping to $x$ and $v$. Finally, according to Morphisms, Lemma Base change for dimension and codimension (uncovered prerequisite) we can choose $u' \in U'$ mapping to $v'$ and $u$ such that the integer is zero. Then taking $x' \in |X'|$ the image of $u'$ works. $\square$
Lemma. Étale morphisms and finite algebras
An étale morphism of algebraic spaces is locally quasi-finite.
Proof. Let $X \to Y$ be an étale morphism of algebraic spaces, see Properties of Spaces, Definition Étale ring maps. By Properties of Spaces, Lemma Étale morphisms and local algebra we see this means there exists a diagram as in Lemma Local algebra with $h$ étale and surjective vertical arrow $a$. By Morphisms, Lemma Étale morphisms and finite algebras (uncovered prerequisite) $h$ is locally quasi-finite. Hence $X \to Y$ is locally quasi-finite by definition. $\square$
Lemma. Proper morphisms and diagonals and separation
Let $S$ be a scheme contained in $\mathrm{Sch}_{fppf}$. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $\Delta_{X/Y} : X \to X \times_Y X$ be the diagonal morphism. Then
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$\Delta_{X/Y}$ is representable,
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$\Delta_{X/Y}$ is locally of finite type,
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$\Delta_{X/Y}$ is a monomorphism,
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$\Delta_{X/Y}$ is separated, and
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$\Delta_{X/Y}$ is locally quasi-finite.
Proof. We are going to use the fact that $\Delta_{X/S}$ is representable (by definition of an algebraic space) and that it satisfies properties (2) -- (5), see Spaces, Lemma Proper morphisms and diagonals and separation (uncovered prerequisite). Note that we have a factorization $$X \longrightarrow X \times_Y X \longrightarrow X \times_S X$$ of the diagonal $\Delta_{X/S} : X \to X \times_S X$. Since $X \times_Y X \to X \times_S X$ is a monomorphism, and since $\Delta_{X/S}$ is representable, it follows formally that $\Delta_{X/Y}$ is representable. In particular, the rest of the statements now make sense, see Section Morphisms of algebraic spaces.
Choose a surjective étale morphism $U \to X$, with $U$ a scheme. Consider the diagram $$\begin{gathered}\begin{matrix}R = U \times_X U & U \times_Y U & U \times_S U \\ X & X \times_Y X & X \times_S X\end{matrix} \\[6pt] \begin{aligned}R = U \times_X U & \longrightarrow U \times_Y U \\ R = U \times_X U & \longrightarrow X \\ U \times_Y U & \longrightarrow X \times_Y X \\ U \times_Y U & \longrightarrow U \times_S U \\ U \times_S U & \longrightarrow X \times_S X \\ X & \longrightarrow X \times_Y X \\ X \times_Y X & \longrightarrow X \times_S X\end{aligned}\end{gathered}$$ Both squares are cartesian, hence so is the outer rectangle. The top row consists of schemes, and the vertical arrows are surjective étale morphisms. By Spaces, Lemma Proper morphisms (uncovered prerequisite) the properties (2) -- (5) for $\Delta_{X/Y}$ are equivalent to those of $R \to U \times_Y U$. In the proof of Spaces, Lemma Proper morphisms and diagonals and separation (uncovered prerequisite) we have seen that $R \to U \times_S U$ has properties (2) -- (5). The morphism $U \times_Y U \to U \times_S U$ is a monomorphism of schemes. These facts imply that $R \to U \times_Y U$ have properties (2) -- (5).
Namely: For (3), note that $R \to U \times_Y U$ is a monomorphism as the composition $R \to U \times_S U$ is a monomorphism. For (2), note that $R \to U \times_Y U$ is locally of finite type, as the composition $R \to U \times_S U$ is locally of finite type (Morphisms, Lemma Finite algebras (uncovered prerequisite)). A monomorphism which is locally of finite type is locally quasi-finite because it has finite fibres (Morphisms, Lemma Finite algebras (uncovered prerequisite)), hence (5). A monomorphism is separated (Schemes, Lemma Diagonals and separation (uncovered prerequisite)), hence (4). $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume
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$f$ is quasi-compact, and
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$f$ satisfies the existence part of the valuative criterion.
Then $f$ is universally closed.
Proof. By Lemmas Base change for morphisms of algebraic spaces and Base change for morphisms of algebraic spaces (uncovered prerequisite) properties (1) and (2) are preserved under any base change. By Lemma Local algebra (uncovered prerequisite) we only have to show that $|T \times_Y X| \to |T|$ is closed, whenever $T$ is an affine scheme over $S$ mapping into $Y$. Hence it suffices to prove: If $Y$ is an affine scheme, $f : X \to Y$ is quasi-compact and satisfies the existence part of the valuative criterion, then $f : |X| \to |Y|$ is closed. In this situation $X$ is a quasi-compact algebraic space. By Properties of Spaces, Lemma Affine neighbourhoods there exists an affine scheme $U$ and a surjective étale morphism $\varphi : U \to X$. Let $T \subset |X|$ closed. The inverse image $\varphi^{-1}(T) \subset U$ is closed, and hence is the set of points of an affine closed subscheme $Z \subset U$. Thus, by Algebra, Lemma Closed images stable under specialization (uncovered prerequisite) we see that $f(T) = f(\varphi(|Z|)) \subset |Y|$ is closed if it is closed under specialization.
Let $y' \leadsto y$ be a specialization in $Y$ with $y' \in f(T)$. Choose a point $x' \in T \subset |X|$ mapping to $y'$ under $f$. We may represent $x'$ by a morphism $\operatorname{Spec}(K) \to X$ for some field $K$. Thus we have the following diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & X \\ \operatorname{Spec}(\mathcal{O}_{Y, y}) & Y,\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \xrightarrow{x'} X \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(\mathcal{O}_{Y, y}) \\ X & \xrightarrow{f} Y, \\ \operatorname{Spec}(\mathcal{O}_{Y, y}) & \longrightarrow Y,\end{aligned}\end{gathered}$$ see Schemes, Section The geometric construction for the existence of the left vertical map. Choose a valuation ring $A \subset K$ dominating the image of the ring map $\mathcal{O}_{Y, y} \to K$ (this is possible since the image is a local ring and not a field as $y' \not = y$, see Algebra, Lemma A valuation ring dominating a local domain). By assumption there exists a field extension $K'/K$ and a valuation ring $A' \subset K'$ dominating $A$, and a morphism $\operatorname{Spec}(A') \to X$ fitting into the commutative diagram. Since $A'$ dominates $A$, and $A$ dominates $\mathcal{O}_{Y, y}$ we see that the closed point of $\operatorname{Spec}(A')$ maps to a point $x \in X$ with $f(x) = y$ which is a specialization of $x'$. Hence $x \in T$ as $T$ is closed, and hence $y \in f(T)$ as desired. $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume $X$ is reduced. Then
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the scheme theoretic image $Z$ of $f$ is the reduced induced algebraic space structure on $\overline{|f|(|X|)}$, and
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for any étale morphism $V \to Y$ the scheme theoretic image of $X \times_Y V \to V$ is equal to $Z \times_Y V$.
Proof. Part (1) is true because the reduced induced algebraic space structure on $\overline{|f|(|X|)}$ is the smallest closed subspace of $Y$ through which $f$ factors, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. Part (2) follows from (1), the fact that $|V| \to |Y|$ is open, and the fact that being reduced is preserved under étale localization. $\square$
Definition. The valuative lifting property
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. We say $f$ satisfies the uniqueness part of the valuative criterion if given any commutative solid diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & X \\ \operatorname{Spec}(A) & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \longrightarrow X \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(A) \\ X & \longrightarrow Y \\ \operatorname{Spec}(A) & \longrightarrow Y \\ \operatorname{Spec}(A) & \dashrightarrow X\end{aligned}\end{gathered}$$ where $A$ is a valuation ring with field of fractions $K$, there exists at most one dotted arrow (without requiring existence). We say $f$ satisfies the existence part of the valuative criterion if given any solid diagram as above there exists an extension $K'/K$ of fields, a valuation ring $A' \subset K'$ dominating $A$ and a morphism $\operatorname{Spec}(A') \to X$ such that the following diagram commutes $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K') & \operatorname{Spec}(K) & X \\ \operatorname{Spec}(A') & \operatorname{Spec}(A) & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K') & \longrightarrow \operatorname{Spec}(K) \\ \operatorname{Spec}(K') & \longrightarrow \operatorname{Spec}(A') \\ \operatorname{Spec}(K) & \longrightarrow X \\ X & \longrightarrow Y \\ \operatorname{Spec}(A') & \longrightarrow \operatorname{Spec}(A) \\ \operatorname{Spec}(A') & \longrightarrow X \\ \operatorname{Spec}(A) & \longrightarrow Y\end{aligned}\end{gathered}$$ We say $f$ satisfies the valuative criterion if $f$ satisfies both the existence and uniqueness part.
Lemma. Base change for flatness
Let $S$ be a scheme. Let $f : X \to Y$ be a flat morphism of algebraic spaces over $S$. Let $g : V \to Y$ be a quasi-compact morphism of algebraic spaces. Let $Z \subset Y$ be the scheme theoretic image of $g$ and let $Z' \subset X$ be the scheme theoretic image of the base change $V \times_Y X \to X$. Then $Z' = f^{-1}Z$.
Proof. Let $Y' \to Y$ be a surjective étale morphism such that $Y'$ is a disjoint union of affine schemes (Properties of Spaces, Lemma Affine neighbourhoods (uncovered prerequisite)). Let $X' \to X \times_Y Y'$ be a surjective étale morphism such that $X'$ is a disjoint union of affine schemes. By Lemma Flatness and local algebra the morphism $X' \to Y'$ is flat. Set $V' = V \times_Y Y'$. By Lemma Morphisms of algebraic spaces the inverse image of $Z$ in $Y'$ is the scheme theoretic image of $V' \to Y'$ and the inverse image of $Z'$ in $X'$ is the scheme theoretic image of $V' \times_{Y'} X' \to X'$. Since $X' \to X$ is surjective étale, it suffices to prove the result in the case of the morphisms $X' \to Y'$ and $V' \to Y'$. Thus we may assume $X$ and $Y$ are affine schemes. In this case $V$ is a quasi-compact algebraic space. Choose an affine scheme $W$ and a surjective étale morphism $W \to V$ (Properties of Spaces, Lemma Affine neighbourhoods). It is clear that the scheme theoretic image of $V \to Y$ agrees with the scheme theoretic image of $W \to Y$ and similarly for $V \times_Y X \to Y$ and $W \times_Y X \to X$. Thus we reduce to the case of schemes which is Morphisms, Lemma Base change for flatness (uncovered prerequisite). $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-compact morphism of algebraic spaces over $S$. Let $Z$ be the scheme theoretic image of $f$. Let $z \in |Z|$. There exists a valuation ring $A$ with fraction field $K$ and a commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & \phantom{X} & X \\ \operatorname{Spec}(A) & Z & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \longrightarrow X \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(A) \\ X & \longrightarrow Y \\ X & \longrightarrow Z \\ \operatorname{Spec}(A) & \longrightarrow Z \\ Z & \longrightarrow Y\end{aligned}\end{gathered}$$ such that the closed point of $\operatorname{Spec}(A)$ maps to $z$.
Proof. Choose an affine scheme $V$ with a point $z' \in V$ and an étale morphism $V \to Y$ mapping $z'$ to $z$. Let $Z' \subset V$ be the scheme theoretic image of $X \times_Y V \to V$. By Lemma Morphisms of algebraic spaces we have $Z' = Z \times_Y V$. Thus $z' \in Z'$. Since $f$ is quasi-compact and $V$ is affine we see that $X \times_Y V$ is quasi-compact. Hence there exists an affine scheme $W$ and a surjective étale morphism $W \to X \times_Y V$. Then $Z' \subset V$ is also the scheme theoretic image of $W \to V$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) we can choose a diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(K) & W & X \times_Y V & X \\ \operatorname{Spec}(A) & Z' & V & Y\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(K) & \longrightarrow W \\ \operatorname{Spec}(K) & \longrightarrow \operatorname{Spec}(A) \\ W & \longrightarrow X \times_Y V \\ W & \longrightarrow Z' \\ X \times_Y V & \longrightarrow V \\ X \times_Y V & \longrightarrow X \\ X & \longrightarrow Y \\ \operatorname{Spec}(A) & \longrightarrow Z' \\ Z' & \longrightarrow V \\ V & \longrightarrow Y\end{aligned}\end{gathered}$$ such that the closed point of $\operatorname{Spec}(A)$ maps to $z'$. Composing with $Z' \to Z$ and $W \to X \times_Y V \to X$ we obtain a solution. $\square$
Lemma. Proper morphisms and diagonals and separation
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent:
-
$f$ is separated,
-
$\Delta_{X/Y} : X \to X \times_Y X$ is universally closed, and
-
$\Delta_{X/Y} : X \to X \times_Y X$ is proper.
Proof. The implication (1) $\Rightarrow$ (3) follows from Lemma Proper morphisms and diagonals and separation. We will use Spaces, Lemma Proper morphisms (uncovered prerequisite) without further mention in the rest of the proof. Recall that $\Delta_{X/Y}$ is a representable monomorphism which is locally of finite type, see Lemma Proper morphisms and diagonals and separation. Since proper $\Rightarrow$ universally closed for morphisms of schemes we conclude that (3) implies (2). If $\Delta_{X/Y}$ is universally closed then Étale Morphisms, Lemma Étale morphisms and diagonals and separation (uncovered prerequisite) implies that it is a closed immersion. Thus (2) $\Rightarrow$ (1) and we win. $\square$
Lemma. Local algebra
Let $\mathcal{P}$ be a property of morphisms of schemes which is étale local on the source-and-target. Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Consider commutative diagrams $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{a} X \\ U & \xrightarrow{h} V \\ V & \xrightarrow{b} Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes and the vertical arrows are étale. The following are equivalent
-
for any diagram as above the morphism $h$ has property $\mathcal{P}$, and
-
for some diagram as above with $a : U \to X$ surjective the morphism $h$ has property $\mathcal{P}$.
If $X$ and $Y$ are representable, then this is also equivalent to $f$ (as a morphism of schemes) having property $\mathcal{P}$. If $\mathcal{P}$ is also preserved under any base change, and fppf local on the base, then for representable morphisms $f$ this is also equivalent to $f$ having property $\mathcal{P}$ in the sense of Section Morphisms of algebraic spaces.
Proof. Let us prove the equivalence of (1) and (2). The implication (1) $\Rightarrow$ (2) is immediate (taking into account Spaces, Lemma Lifting the geometric construction (uncovered prerequisite)). Assume $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \xrightarrow{h} V \\ V & \longrightarrow Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered} \quad\quad \begin{gathered}\begin{matrix}U' & V' \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U' & \longrightarrow X \\ U' & \xrightarrow{h'} V' \\ V' & \longrightarrow Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ are two diagrams as in the lemma. Assume $U \to X$ is surjective and $h$ has property $\mathcal{P}$. To show that (2) implies (1) we have to prove that $h'$ has $\mathcal{P}$. To do this consider the diagram $$\begin{gathered}\begin{matrix}U & U \times_X U' & U' \\ V & V \times_Y V' & V'\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{h} V \\ U \times_X U' & \longrightarrow U \\ U \times_X U' & \xrightarrow{(h, h')} V \times_Y V' \\ U \times_X U' & \longrightarrow U' \\ U' & \xrightarrow{h'} V' \\ V \times_Y V' & \longrightarrow V \\ V \times_Y V' & \longrightarrow V'\end{aligned}\end{gathered}$$ By Descent, Lemma Local algebra (uncovered prerequisite) we see that $h$ has $\mathcal{P}$ implies $(h, h')$ has $\mathcal{P}$ and since $U \times_X U' \to U'$ is surjective this implies (by the same lemma) that $h'$ has $\mathcal{P}$.
If $X$ and $Y$ are representable, then Descent, Lemma Local algebra (uncovered prerequisite) applies which shows that (1) and (2) are equivalent to $f$ having $\mathcal{P}$.
Finally, suppose $f$ is representable, and $U, V, a, b, h$ are as in part (2) of the lemma, and that $\mathcal{P}$ is preserved under arbitrary base change. We have to show that for any scheme $Z$ and morphism $Z \to X$ the base change $Z \times_Y X \to Z$ has property $\mathcal{P}$. Consider the diagram $$\begin{gathered}\begin{matrix}Z \times_Y U & Z \times_Y V \\ Z \times_Y X & Z\end{matrix} \\[6pt] \begin{aligned}Z \times_Y U & \longrightarrow Z \times_Y X \\ Z \times_Y U & \longrightarrow Z \times_Y V \\ Z \times_Y V & \longrightarrow Z \\ Z \times_Y X & \longrightarrow Z\end{aligned}\end{gathered}$$ Note that the top horizontal arrow is a base change of $h$ and hence has property $\mathcal{P}$. The left vertical arrow is étale and surjective and the right vertical arrow is étale. Thus Descent, Lemma Local algebra (uncovered prerequisite) once again kicks in and shows that $Z \times_Y X \to Z$ has property $\mathcal{P}$. $\square$
Lemma. Finite presentation and finite algebras
A morphism which is locally of finite presentation is locally of finite type. A morphism of finite presentation is of finite type.
Proof. Let $f : X \to Y$ be a morphism of algebraic spaces which is locally of finite presentation. This means there exists a diagram as in Lemma Local algebra with $h$ locally of finite presentation and surjective vertical arrow $a$. By Morphisms, Lemma Finite presentation and finite algebras (uncovered prerequisite) $h$ is locally of finite type. Hence $X \to Y$ is locally of finite type by definition. If $f$ is of finite presentation then it is quasi-compact and it follows that $f$ is of finite type. $\square$
Definition. Finite presentation and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$.
-
We say $f$ is locally of finite presentation if the equivalent conditions of Lemma Local algebra hold with $\mathcal{P} =$"locally of finite presentation".
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Let $x \in |X|$. We say $f$ is of finite presentation at $x$ if there exists an open neighbourhood $X' \subset X$ of $x$ such that $f|_{X'} : X' \to Y$ is locally of finite presentation[^1].
-
A morphism of algebraic spaces $f : X \to Y$ is of finite presentation if it is locally of finite presentation, quasi-compact and quasi-separated.
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$.
-
If $Y$ is separated and $f$ is separated, then $X$ is separated.
-
If $Y$ is quasi-separated and $f$ is quasi-separated, then $X$ is quasi-separated.
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If $Y$ is locally separated and $f$ is locally separated, then $X$ is locally separated.
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If $Y$ is separated over $S$ and $f$ is separated, then $X$ is separated over $S$.
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If $Y$ is quasi-separated over $S$ and $f$ is quasi-separated, then $X$ is quasi-separated over $S$.
-
If $Y$ is locally separated over $S$ and $f$ is locally separated, then $X$ is locally separated over $S$.
Proof. Parts (4), (5), and (6) follow immediately from Lemma Composition and diagonals and separation and Spaces, Definition Diagonals and separation. Parts (1), (2), and (3) reduce to parts (4), (5), and (6) by thinking of $X$ and $Y$ as algebraic spaces over $\operatorname{Spec}(\mathbf{Z})$, see Properties of Spaces, Definition Diagonals and separation. $\square$
Lemma. Composition and diagonals and separation
All of the separation axioms listed in Definition Diagonals and separation are stable under composition of morphisms.
Proof. Let $f : X \to Y$ and $g : Y \to Z$ be morphisms of algebraic spaces to which the axiom in question applies. The diagonal $\Delta_{X/Z}$ is the composition $$X \longrightarrow X \times_Y X \longrightarrow X \times_Z X.$$ Our separation axiom is defined by requiring the diagonal to have some property $\mathcal{P}$. By Lemma Tensor products and direct sums above we see that the second arrow also has this property. Hence the lemma follows since the composition of (representable) morphisms with property $\mathcal{P}$ also is a morphism with property $\mathcal{P}$, see Section Morphisms of algebraic spaces. $\square$
Lemma. Composition and finite algebras
The composition of finite type morphisms is of finite type. The same holds for locally of finite type.
Proof. See Remark Composition and morphisms of algebraic spaces and Morphisms, Lemma Composition and finite algebras (uncovered prerequisite). $\square$
Lemma. Composition and morphisms of algebraic spaces
The composition of a pair of (universally) closed morphisms of algebraic spaces is (universally) closed.
Proof. Omitted. $\square$
Lemma. Base change for morphisms of algebraic spaces
The base change of a universally closed morphism of algebraic spaces by any morphism of algebraic spaces is universally closed.
Proof. This is immediate from the definition. $\square$
Lemma. Composition and diagonals and separation
Let $S$ be a scheme. Let $f : X \to Y$ and $g : Y \to Z$ be morphisms of algebraic spaces over $S$.
-
If $g \circ f$ is separated then so is $f$.
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If $g \circ f$ is locally separated then so is $f$.
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If $g \circ f$ is quasi-separated then so is $f$.
Proof. Consider the factorization $$X \to X \times_Y X \to X \times_Z X$$ of the diagonal morphism of $g \circ f$. In any case the last morphism is a monomorphism. Hence for any scheme $T$ and morphism $T \to X \times_Y X$ we have the equality $$X \times_{(X \times_Y X)} T = X \times_{(X \times_Z X)} T.$$ Hence the result is clear. $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ and $g : Y \to Z$ be morphisms of algebraic spaces over $S$. If $g \circ f$ is quasi-compact and $g$ is quasi-separated then $f$ is quasi-compact.
Proof. This is true because $f$ equals the composition $(1, f) : X \to X \times_Z Y \to Y$. The first map is quasi-compact by Lemma Diagonals and separation because it is a section of the quasi-separated morphism $X \times_Z Y \to X$ (a base change of $g$, see Lemma Base change for diagonals and separation). The second map is quasi-compact as it is the base change of $g \circ f$, see Lemma Base change for morphisms of algebraic spaces. And compositions of quasi-compact morphisms are quasi-compact, see Lemma Composition and morphisms of algebraic spaces (uncovered prerequisite). $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $f : X \to Y$, $g : Y \to Z$ be morphisms of algebraic spaces over $S$. If $g \circ f : X \to Z$ is locally of finite type, then $f : X \to Y$ is locally of finite type.
Proof. We can find a diagram $$\begin{gathered}\begin{matrix}U & V & W \\ X & Y & Z\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow V \\ U & \longrightarrow X \\ V & \longrightarrow W \\ V & \longrightarrow Y \\ W & \longrightarrow Z \\ X & \longrightarrow Y \\ Y & \longrightarrow Z\end{aligned}\end{gathered}$$ where $U$, $V$, $W$ are schemes, the vertical arrows are étale and surjective, see Spaces, Lemma Lifting the geometric construction (uncovered prerequisite). At this point we can use Lemma Finite algebras and local algebra (uncovered prerequisite) and Morphisms, Lemma Finite algebras (uncovered prerequisite) to conclude. $\square$
Lemma. Diagonals, separation and local algebra
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent:
-
$f$ is a closed immersion (resp. open immersion, resp. immersion),
-
for every scheme $Z$ and any morphism $Z \to Y$ the morphism $Z \times_Y X \to Z$ is a closed immersion (resp. open immersion, resp. immersion),
-
for every affine scheme $Z$ and any morphism $Z \to Y$ the morphism $Z \times_Y X \to Z$ is a closed immersion (resp. open immersion, resp. immersion),
-
there exists a scheme $V$ and a surjective étale morphism $V \to Y$ such that $V \times_Y X \to V$ is a closed immersion (resp. open immersion, resp. immersion), and
-
there exists a Zariski covering $Y = \bigcup Y_i$ such that each of the morphisms $f^{-1}(Y_i) \to Y_i$ is a closed immersion (resp. open immersion, resp. immersion).
Proof. Using that a base change of a closed immersion (resp. open immersion, resp. immersion) is another one it is clear that (1) implies (2) and (2) implies (3). Also (3) implies (4) since we can take $V$ to be a disjoint union of affines, see Properties of Spaces, Lemma Affine neighbourhoods (uncovered prerequisite).
Assume $V \to Y$ is as in (4). Let $\mathcal{P}$ be the property closed immersion (resp. open immersion, resp. immersion) of morphisms of schemes. Note that property $\mathcal{P}$ is preserved under any base change and fppf local on the base (see Section Morphisms of algebraic spaces). Moreover, morphisms of type $\mathcal{P}$ are separated and locally quasi-finite (in each of the three cases, see Schemes, Lemma Diagonals and separation (uncovered prerequisite), and Morphisms, Lemma Diagonals, separation and finite algebras (uncovered prerequisite)). Hence by More on Morphisms, Lemma Diagonals, separation and finite algebras the morphisms of type $\mathcal{P}$ satisfy descent for fppf covering. Thus Spaces, Lemma Étale morphisms (uncovered prerequisite) applies and we see that $X \to Y$ is representable and has property $\mathcal{P}$, in other words (1) holds.
The equivalence of (1) and (5) follows from the fact that $\mathcal{P}$ is Zariski local on the target (since we saw above that $\mathcal{P}$ is in fact fppf local on the target). $\square$
Lemma. Tensor products and direct sums
The top arrow of a "magic diagram" of algebraic spaces has nice immersion-like properties, and under separatedness hypotheses these get stronger.
Let $S$ be a scheme. Let $f : X \to Z$, $g : Y \to Z$ and $Z \to T$ be morphisms of algebraic spaces over $S$. Consider the induced morphism $i : X \times_Z Y \to X \times_T Y$. Then
-
$i$ is representable, locally of finite type, locally quasi-finite, separated and a monomorphism,
-
if $Z \to T$ is locally separated, then $i$ is an immersion,
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if $Z \to T$ is separated, then $i$ is a closed immersion, and
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if $Z \to T$ is quasi-separated, then $i$ is quasi-compact.
Proof. By general category theory the following diagram $$\begin{gathered}\begin{matrix}X \times_Z Y & X \times_T Y \\ Z & Z \times_T Z\end{matrix} \\[6pt] \begin{aligned}X \times_Z Y & \xrightarrow{i} X \times_T Y \\ X \times_Z Y & \longrightarrow Z \\ X \times_T Y & \longrightarrow Z \times_T Z \\ Z & \xrightarrow{\Delta_{Z/T}} Z \times_T Z \\ Z & \longrightarrow Z \times_T Z\end{aligned}\end{gathered}$$ is a fibre product diagram. Hence $i$ is the base change of the diagonal morphism $\Delta_{Z/T}$. Thus the lemma follows from Lemma Proper morphisms and diagonals and separation, and the material in Section Morphisms of algebraic spaces. $\square$
Lemma. Closed support
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Let $U$ be a scheme and let $\varphi : U \to X$ be an étale morphism. Then $$\text{Supp}(\varphi^*\mathcal{F}) = |\varphi|^{-1}(\text{Supp}(\mathcal{F}))$$ where the left hand side is the support of $\varphi^*\mathcal{F}$ as a quasi-coherent module on the scheme $U$.
Proof. Let $u\in U$ be a (usual) point and let $\overline{x}$ be a geometric point lying over $u$. By Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves we have $(\varphi^*\mathcal{F})_u \otimes_{\mathcal{O}_{U, u}} \mathcal{O}_{X, \overline{x}} = \mathcal{F}_{\overline{x}}$. Since $\mathcal{O}_{U, u} \to \mathcal{O}_{X, \overline{x}}$ is the strict henselization by Properties of Spaces, Lemma Étale morphisms and local algebra we see that it is faithfully flat (see More on Algebra, Lemma Henselian local rings and henselization, Sections 4 and 6, Proposition 6.1). Thus we see that $(\varphi^*\mathcal{F})_u = 0$ if and only if $\mathcal{F}_{\overline{x}} = 0$. This proves the lemma. $\square$
Lemma. Direct images and morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. If $f$ is quasi-compact and quasi-separated, then $f_*$ transforms quasi-coherent $\mathcal{O}_X$-modules into quasi-coherent $\mathcal{O}_Y$-modules.
Proof. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. We have to show that $f_*\mathcal{F}$ is a quasi-coherent sheaf on $Y$. For this it suffices to show that for any affine scheme $V$ and étale morphism $V \to Y$ the restriction of $f_*\mathcal{F}$ to $V$ is quasi-coherent, see Properties of Spaces, Lemma Criteria for quasi-coherent complexes and coherent sheaves. Let $f' : V \times_Y X \to V$ be the base change of $f$ by $V \to Y$. Note that $f'$ is also quasi-compact and quasi-separated, see Lemmas Base change for morphisms of algebraic spaces and Base change for diagonals and separation. By (Morphisms of algebraic spaces) we know that the restriction of $f_*\mathcal{F}$ to $V$ is $f'_*$ of the restriction of $\mathcal{F}$ to $V \times_Y X$. Hence we may replace $f$ by $f'$, and assume that $Y$ is an affine scheme.
Assume $Y$ is an affine scheme. Since $f$ is quasi-compact we see that $X$ is quasi-compact. Thus we may choose an affine scheme $U$ and a surjective étale morphism $U \to X$, see Properties of Spaces, Lemma Affine neighbourhoods. By Lemma Morphisms of algebraic spaces (uncovered prerequisite) we get an exact sequence $$0 \to f_*\mathcal{F} \to a_*(\mathcal{F}|_U) \to b_*(\mathcal{F}|_R).$$ where $R = U \times_X U$. As $X \to Y$ is quasi-separated we see that $R \to U \times_Y U$ is a quasi-compact monomorphism. This implies that $R$ is a quasi-compact separated scheme (as $U$ and $Y$ are affine at this point). Hence $a : U \to Y$ and $b : R \to Y$ are quasi-compact and quasi-separated morphisms of schemes. Thus by Descent, Proposition Quasi-coherent complexes and coherent sheaves the sheaves $a_*(\mathcal{F}|_U)$ and $b_*(\mathcal{F}|_R)$ are quasi-coherent (see also the discussion preceding this lemma). This implies that $f_*\mathcal{F}$ is a kernel of quasi-coherent modules, and hence itself quasi-coherent, see Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Diagonals, separation and finite algebras
A closed immersion is finite (and a fortiori integral).
Proof. Omitted. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $X_i \to Y$, $i = 1, \ldots, n$ be finite morphisms of algebraic spaces over $S$. Then $X_1 \amalg \ldots \amalg X_n \to Y$ is finite too.
Proof. Follows from the case of schemes (Morphisms, Lemma Finite algebras (uncovered prerequisite)) by étale localization. $\square$
Lemma. Proper morphisms and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent
-
$f$ is finite, and
-
$f$ is affine and proper.
Proof. In both cases the morphism is representable, and you can check the condition after base change to an affine scheme mapping into $Y$, see Lemmas Integral extensions and local algebra (uncovered prerequisite), Affine neighbourhoods and local algebra (uncovered prerequisite), and Proper morphisms and local algebra. Hence the result follows from Morphisms, Lemma Proper morphisms and finite algebras (uncovered prerequisite). $\square$
Definition. Flat morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$.
-
We say $f$ is flat if the equivalent conditions of Lemma Local algebra with $\mathcal{P} =$"flat".
-
Let $x \in |X|$. We say $f$ is flat at $x$ if the equivalent conditions of Lemma Local algebra hold with $\mathcal{Q} =$"induced map local rings is flat".
Note that the second part makes sense by Descent, Lemma Flatness (uncovered prerequisite).
Lemma. Proper morphisms and diagonals and separation
A closed immersion of algebraic spaces is a proper morphism of algebraic spaces.
Proof. As a closed immersion is by definition representable this follows from Spaces, Lemma Proper morphisms (uncovered prerequisite) and the corresponding result for morphisms of schemes, see Morphisms, Lemma Proper morphisms and diagonals and separation (uncovered prerequisite). $\square$
Lemma. Base change for affine neighbourhoods
The base change of an affine morphism is affine.
Proof. Omitted. Hint: Transitivity of fibre products. $\square$
Lemma. Base change for morphisms of algebraic spaces
The base change of a surjective morphism is surjective.
Proof. Follows immediately from Properties of Spaces, Lemma Étale geometry of algebraic spaces. $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $Z \subset Y$ be the scheme theoretic image of $f$. If $f$ is quasi-compact then
-
the sheaf of ideals $\mathcal{I} = \operatorname{Ker}(\mathcal{O}_Y \to f_*\mathcal{O}_X)$ is quasi-coherent,
-
the scheme theoretic image $Z$ is the closed subspace corresponding to $\mathcal{I}$,
-
for any étale morphism $V \to Y$ the scheme theoretic image of $X \times_Y V \to V$ is equal to $Z \times_Y V$, and
-
the image $|f|(|X|) \subset |Z|$ is a dense subset of $|Z|$.
Proof. To prove (3) it suffices to prove (1) and (2) since the formation of $\mathcal{I}$ commutes with étale localization. If (1) holds then in the proof of Lemma Morphisms of algebraic spaces (uncovered prerequisite) we showed (2). Let us prove that $\mathcal{I}$ is quasi-coherent. Since the property of being quasi-coherent is étale local we may assume $Y$ is an affine scheme. As $f$ is quasi-compact, we can find an affine scheme $U$ and a surjective étale morphism $U \to X$. Denote $f'$ the composition $U \to X \to Y$. Then $f_*\mathcal{O}_X$ is a subsheaf of $f'_*\mathcal{O}_U$, and hence $\mathcal{I} = \operatorname{Ker}(\mathcal{O}_Y \to \mathcal{O}_{X'})$. By Lemma Direct images and morphisms of algebraic spaces the sheaf $f'_*\mathcal{O}_U$ is quasi-coherent on $Y$. Hence $\mathcal{I}$ is quasi-coherent as a kernel of a map between coherent modules. Finally, part (4) follows from parts (1), (2), and (3) as the ideal $\mathcal{I}$ will be the unit ideal in any point of $|Y|$ which is not contained in the closure of $|f|(|X|)$. $\square$
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $f : X \to T$ be a morphism of algebraic spaces over $S$. Let $s : T \to X$ be a section of $f$ (in a formula $f \circ s = \text{id}_T$). Then
-
$s$ is representable, locally of finite type, locally quasi-finite, separated and a monomorphism,
-
if $f$ is locally separated, then $s$ is an immersion,
-
if $f$ is separated, then $s$ is a closed immersion, and
-
if $f$ is quasi-separated, then $s$ is quasi-compact.
Proof. This is a special case of Lemma Diagonals and separation applied to $g = s$ so the morphism $i = s : T \to T \times_T X$. $\square$
Lemma. Closed support
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. There exists a smallest closed subspace $i : Z \to X$ such that there exists a quasi-coherent $\mathcal{O}_Z$-module $\mathcal{G}$ with $i_*\mathcal{G} \cong \mathcal{F}$. Moreover:
-
If $U$ is a scheme and $\varphi : U \to X$ is an étale morphism then $Z \times_X U$ is the scheme theoretic support of $\varphi^*\mathcal{F}$.
-
The quasi-coherent sheaf $\mathcal{G}$ is unique up to unique isomorphism.
-
The quasi-coherent sheaf $\mathcal{G}$ is of finite type.
-
The support of $\mathcal{G}$ and of $\mathcal{F}$ is $|Z|$.
Proof. Choose a scheme $U$ and a surjective étale morphism $\varphi : U \to X$. Let $R = U \times_X U$ with projections $s, t : R \to U$. Let $i' : Z' \to U$ be the scheme theoretic support of $\varphi^*\mathcal{F}$ and let $\mathcal{G}'$ be the (unique up to unique isomorphism) finite type quasi-coherent $\mathcal{O}_{Z'}$-module with $i'_*\mathcal{G}' = \varphi^*\mathcal{F}$, see Morphisms, Lemma Closed support (uncovered prerequisite). As $s^*\varphi^*\mathcal{F} = t^*\varphi^*\mathcal{F}$ we see that $R' = s^{-1}Z' = t^{-1}Z'$ as closed subschemes of $R$ by Morphisms, Lemma Flatness and closed support (uncovered prerequisite). Thus we may apply Properties of Spaces, Lemma Étale geometry of algebraic spaces (uncovered prerequisite) to find a closed subspace $i : Z \to X$ whose pullback to $U$ is $Z'$. Writing $s', t' : R' \to Z'$ the projections and $j' : R' \to R$ the given closed immersion, we see that $$j'_* (s')^*\mathcal{G}' = s^* i'_*\mathcal{G}' = s^*\varphi^*\mathcal{F} = t^*\varphi^*\mathcal{F} = t^*i'_*\mathcal{G}' = j'_*(t')^*\mathcal{G}'$$ (the first and the last equality by Cohomology of Schemes, Lemma Base change for sheaf cohomology and flatness (uncovered prerequisite)). Hence the uniqueness of Morphisms, Lemma Flatness and closed support (uncovered prerequisite) applied to $R' \to R$ gives an isomorphism $\alpha : (t')^*\mathcal{G}' \to (s')^*\mathcal{G}'$ compatible with the canonical isomorphism $t^*\varphi^*\mathcal{F} = s^*\varphi^*\mathcal{F}$ via $j'_*$. Clearly $\alpha$ satisfies the cocycle condition, hence we may apply Properties of Spaces, Proposition Quasi-coherent complexes and coherent sheaves to obtain a quasi-coherent module $\mathcal{G}$ on $Z$ whose restriction to $Z'$ is $\mathcal{G}'$ compatible with $\alpha$. Again using the equivalence of the proposition mentioned above (this time for $X$) we conclude that $i_*\mathcal{G} \cong \mathcal{F}$.
This proves existence. The other properties of the lemma follow by comparing with the result for schemes using Lemma Closed support. Detailed proofs omitted. $\square$
Lemma. Composition and finite algebras
The composition of quasi-finite morphisms is quasi-finite. The same holds for locally quasi-finite.
Proof. See Remark Composition and morphisms of algebraic spaces and Morphisms, Lemma Composition and finite algebras (uncovered prerequisite). $\square$
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $i : Z \to X$ be a closed immersion of algebraic spaces over $S$. Let $\mathcal{A}$ be a sheaf of rings on $X_\mathrm{\acute{e}tale}$. Let $\mathcal{B}$ be a sheaf of rings on $Z_\mathrm{\acute{e}tale}$. Let $\varphi : \mathcal{A} \to i_{small, *}\mathcal{B}$ be a homomorphism of sheaves of rings so that we obtain a morphism of ringed topoi $$f : (\operatorname{Sh}(Z_\mathrm{\acute{e}tale}), \mathcal{B}) \longrightarrow (\operatorname{Sh}(X_\mathrm{\acute{e}tale}), \mathcal{A}).$$ For a sheaf of $\mathcal{A}$-modules $\mathcal{F}$ and a sheaf of $\mathcal{B}$-modules $\mathcal{G}$ the canonical map $$\mathcal{F} \otimes_\mathcal{A} f_*\mathcal{G} \longrightarrow f_*(f^*\mathcal{F} \otimes_\mathcal{B} \mathcal{G}).$$ is an isomorphism.
Proof. The map is the map adjoint to the map $$f^*\mathcal{F} \otimes_\mathcal{B} f^* f_*\mathcal{G} = f^*(\mathcal{F} \otimes_\mathcal{A} f_*\mathcal{G}) \longrightarrow f^*\mathcal{F} \otimes_\mathcal{B} \mathcal{G}$$ coming from $\text{id} : f^*\mathcal{F} \to f^*\mathcal{F}$ and the adjunction map $f^* f_*\mathcal{G} \to \mathcal{G}$. To see this map is an isomorphism, we may check on stalks (Properties of Spaces, Theorem Sheaves on ringed sites). Let $\overline{z} : \operatorname{Spec}(k) \to Z$ be a geometric point with image $\overline{x} = i \circ \overline{z} : \operatorname{Spec}(k) \to X$. Working out what our maps does on stalks, we see that we have to show $$\mathcal{F}_{\overline{x}} \otimes_{\mathcal{A}_{\overline{x}}} \mathcal{G}_{\overline{z}} = (\mathcal{F}_{\overline{x}} \otimes_{\mathcal{A}_{\overline{x}}} \mathcal{B}_{\overline{z}}) \otimes_{\mathcal{B}_{\overline{z}}} \mathcal{G}_{\overline{z}}$$ which holds true. Here we have used that taking tensor products commutes with taking stalks, the behaviour of stalks under pullback Properties of Spaces, Lemma Sheaves on ringed sites, and the behaviour of stalks under pushforward along a closed immersion Lemma Sheaves on ringed sites (uncovered prerequisite). $\square$
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. For every closed immersion $i : Z \to X$ the sheaf $i_*\mathcal{O}_Z$ is a quasi-coherent $\mathcal{O}_X$-module, the map $i^\sharp : \mathcal{O}_X \to i_*\mathcal{O}_Z$ is surjective and its kernel is a quasi-coherent sheaf of ideals. The rule $Z \mapsto \operatorname{Ker}(\mathcal{O}_X \to i_*\mathcal{O}_Z)$ defines an inclusion reversing bijection $$\begin{matrix} \text{closed subspaces}\\ Z \subset X \end{matrix} \longrightarrow \begin{matrix} \text{quasi-coherent sheaves}\\ \text{of ideals }\mathcal{I} \subset \mathcal{O}_X \end{matrix}$$ Moreover, given a closed subscheme $Z$ corresponding to the quasi-coherent sheaf of ideals $\mathcal{I} \subset \mathcal{O}_X$ a morphism of algebraic spaces $h : Y \to X$ factors through $Z$ if and only if the map $h^*\mathcal{I} \to h^*\mathcal{O}_X = \mathcal{O}_Y$ is zero.
Proof. Let $U \to X$ be a surjective étale morphism whose source is a scheme. Consider the diagram $$\begin{gathered}\begin{matrix}U \times_X Z & Z \\ U & X\end{matrix} \\[6pt] \begin{aligned}U \times_X Z & \longrightarrow Z \\ U \times_X Z & \xrightarrow{i'} U \\ Z & \xrightarrow{i} X \\ U & \longrightarrow X\end{aligned}\end{gathered}$$ By Lemma Diagonals, separation and local algebra we see that $i$ is a closed immersion if and only if $i'$ is a closed immersion. By Properties of Spaces, Lemma Base change for étale morphisms and modules we see that $i'_*\mathcal{O}_{U \times_X Z}$ is the restriction of $i_*\mathcal{O}_Z$ to $U$. Hence the assertions on $\mathcal{O}_X \to i_*\mathcal{O}_Z$ are equivalent to the corresponding assertions on $\mathcal{O}_U \to i'_*\mathcal{O}_{U \times_X Z}$. And since $i'$ is a closed immersion of schemes, these results follow from Morphisms, Lemma Diagonals and separation (uncovered prerequisite).
Let us prove that given a quasi-coherent sheaf of ideals $\mathcal{I} \subset \mathcal{O}_X$ the formula $$Z(T) = \{h : T \to X \mid h^*\mathcal{I} \to \mathcal{O}_T \text{ is zero}\}$$ defines a closed subspace of $X$. It is clearly a subfunctor of $X$. To show that $Z \to X$ is representable by closed immersions, let $\varphi : U \to X$ be a morphism from a scheme towards $X$. Then $Z \times_X U$ is represented by the analogous subfunctor of $U$ corresponding to the sheaf of ideals $\operatorname{Im}(\varphi^*\mathcal{I} \to \mathcal{O}_U)$. By Properties of Spaces, Lemma Pullback of quasi-coherent complexes and coherent sheaves the $\mathcal{O}_U$-module $\varphi^*\mathcal{I}$ is quasi-coherent on $U$, and hence $\operatorname{Im}(\varphi^*\mathcal{I} \to \mathcal{O}_U)$ is a quasi-coherent sheaf of ideals on $U$. By Schemes, Lemma Criteria for the geometric construction (uncovered prerequisite) we conclude that $Z \times_X U$ is represented by the closed subscheme of $U$ associated to $\operatorname{Im}(\varphi^*\mathcal{I} \to \mathcal{O}_U)$. Thus $Z$ is a closed subspace of $X$.
In the formula for $Z$ above the inputs $T$ are schemes since algebraic spaces are sheaves on $(\mathrm{Sch}/S)_{fppf}$. We omit the verification that the same formula remains true if $T$ is an algebraic space. $\square$
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $i : Z \to X$ be a closed immersion of algebraic spaces over $S$.
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The functor $$i_{small, *} : \operatorname{Sh}(Z_\mathrm{\acute{e}tale}) \longrightarrow \operatorname{Sh}(X_\mathrm{\acute{e}tale})$$ is fully faithful and its essential image is those sheaves of sets $\mathcal{F}$ on $X_\mathrm{\acute{e}tale}$ whose restriction to $X \setminus Z$ is isomorphic to $*$, and
-
the functor $$i_{small, *} : \textit{Ab}(Z_\mathrm{\acute{e}tale}) \longrightarrow \textit{Ab}(X_\mathrm{\acute{e}tale})$$ is fully faithful and its essential image is those abelian sheaves on $X_\mathrm{\acute{e}tale}$ whose support is contained in $|Z|$.
In both cases $i_{small}^{-1}$ is a left inverse to the functor $i_{small, *}$.
Proof. Let $U$ be a scheme and let $U \to X$ be surjective étale. Set $V = Z \times_X U$. Then $V$ is a scheme and $i' : V \to U$ is a closed immersion of schemes. By Properties of Spaces, Lemma Base change for étale morphisms for any sheaf $\mathcal{G}$ on $Z$ we have $$(i_{small}^{-1}i_{small, *}\mathcal{G})|_V = (i')_{small}^{-1}i'_{small, *}(\mathcal{G}|_V)$$ By Étale Cohomology, Proposition Diagonals and separation (uncovered prerequisite) the map $(i')_{small}^{-1}i'_{small, *}(\mathcal{G}|_V) \to \mathcal{G}|_V$ is an isomorphism. Since $V \to Z$ is surjective and étale this implies that $i_{small}^{-1}i_{small, *}\mathcal{G} \to \mathcal{G}$ is an isomorphism. This clearly implies that $i_{small, *}$ is fully faithful, see Sites, Lemma Proper morphisms (uncovered prerequisite). To prove the statement on the essential image, consider a sheaf of sets $\mathcal{F}$ on $X_\mathrm{\acute{e}tale}$ whose restriction to $X \setminus Z$ is isomorphic to $*$. As in the proof of Étale Cohomology, Proposition Diagonals and separation (uncovered prerequisite) we consider the adjunction mapping $$\mathcal{F} \longrightarrow i_{small, *}i_{small}^{-1}\mathcal{F}.$$ As in the first part we see that the restriction of this map to $U$ is an isomorphism by the corresponding result for the case of schemes. Since $U$ is an étale covering of $X$ we conclude it is an isomorphism. $\square$
Lemma. Diagonals and separation
A closed immersion of algebraic spaces is quasi-compact.
Proof. This follows from Schemes, Lemma Diagonals and separation (uncovered prerequisite) by general principles, see Spaces, Lemma Proper morphisms (uncovered prerequisite). $\square$
Lemma. Diagonals and separation
A closed immersion of algebraic spaces is separated.
Proof. This follows from Schemes, Lemma Diagonals and separation (uncovered prerequisite) by general principles, see Spaces, Lemma Proper morphisms (uncovered prerequisite). $\square$
Lemma. Base change for diagonals and separation
All of the separation axioms listed in Definition Diagonals and separation are stable under base change.
Proof. Let $f : X \to Y$ and $Y' \to Y$ be morphisms of algebraic spaces. Let $f' : X' \to Y'$ be the base change of $f$ by $Y' \to Y$. Then $\Delta_{X'/Y'}$ is the base change of $\Delta_{X/Y}$ by the morphism $X' \times_{Y'} X' \to X \times_Y X$. By the results of Section Morphisms of algebraic spaces each of the properties of the diagonal used in Definition Diagonals and separation is stable under base change. Hence the lemma is true. $\square$
Lemma. Base change for finite algebras
A base change of a quasi-finite morphism is quasi-finite. The same holds for locally quasi-finite.
Proof. Immediate consequence of Lemma Base change for finite algebras (uncovered prerequisite). $\square$
Lemma. Morphisms of algebraic spaces
Let $S$ be a scheme. Consider a commutative diagram $$\begin{gathered}\begin{matrix}V' & T' \times_T X & X \\ \phantom{X} & T' & T\end{matrix} \\[6pt] \begin{aligned}V' & \longrightarrow T' \times_T X \\ V' & \longrightarrow T' \\ T' \times_T X & \longrightarrow X \\ T' \times_T X & \longrightarrow T' \\ X & \longrightarrow T \\ T' & \longrightarrow T\end{aligned}\end{gathered}$$ of algebraic spaces over $S$. Assume
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$T' \to T$ is an étale morphism of affine schemes,
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$X \to T$ is a separated, locally quasi-finite morphism,
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$V'$ is an open subspace of $T' \times_T X$, and
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$V' \to T'$ is quasi-affine.
In this situation the image $U$ of $V'$ in $X$ is a quasi-compact open subspace of $X$ which is representable.
Proof. We first make some trivial observations. Note that $V'$ is representable by Lemma Affine neighbourhoods and local algebra (uncovered prerequisite). It is also quasi-compact (as a quasi-affine scheme over an affine scheme, see Morphisms, Lemma Diagonals, separation and affine neighbourhoods (uncovered prerequisite)). Since $T' \times_T X \to X$ is étale (Properties of Spaces, Lemma Base change for étale morphisms (uncovered prerequisite)) the map $|T' \times_T X| \to |X|$ is open, see Properties of Spaces, Lemma Étale morphisms (uncovered prerequisite). Let $U \subset X$ be the open subspace corresponding to the image of $|V'|$, see Properties of Spaces, Lemma Étale geometry of algebraic spaces (uncovered prerequisite). As $|V'|$ is quasi-compact we see that $|U|$ is quasi-compact, hence $U$ is a quasi-compact algebraic space, by Properties of Spaces, Lemma Étale geometry of algebraic spaces (uncovered prerequisite).
By Morphisms, Lemma Finite algebras and local algebra (uncovered prerequisite) the morphism $T' \to T$ is universally bounded. Hence we can do induction on the integer $n$ bounding the degree of the fibres of $T' \to T$, see Morphisms, Lemma Étale morphisms (uncovered prerequisite) for a description of this integer in the case of an étale morphism. If $n = 1$, then $T' \to T$ is an open immersion (see Étale Morphisms, Theorem Étale morphisms (uncovered prerequisite)), and the result is clear. Assume $n > 1$.
Consider the affine scheme $T'' = T' \times_T T'$. As $T' \to T$ is étale we have a decomposition (into open and closed affine subschemes) $T'' = \Delta(T') \amalg T^*$. Namely $\Delta = \Delta_{T'/T}$ is open by Morphisms, Lemma Unramified morphisms and diagonals and separation (uncovered prerequisite) and closed because $T' \to T$ is separated as a morphism of affines. As a base change the degrees of the fibres of the second projection $\text{pr}_1 : T' \times_T T' \to T'$ are bounded by $n$, see Morphisms, Lemma Base change for the geometric construction (uncovered prerequisite). On the other hand, $\text{pr}_1|_{\Delta(T')} : \Delta(T') \to T'$ is an isomorphism and every fibre has exactly one point. Thus, on applying Morphisms, Lemma Étale morphisms (uncovered prerequisite) we conclude the degrees of the fibres of the restriction $\text{pr}_1|_{T^*} : T^* \to T'$ are bounded by $n - 1$. Hence the induction hypothesis applied to the diagram $$\begin{gathered}\begin{matrix}p_0^{-1}(V') \cap X^* & X^* & X' \\ \phantom{X} & T^* & T'\end{matrix} \\[6pt] \begin{aligned}p_0^{-1}(V') \cap X^* & \longrightarrow X^* \\ p_0^{-1}(V') \cap X^* & \longrightarrow T^* \\ X^* & \xrightarrow{p_1|_{X^*}} X' \\ X^* & \longrightarrow T^* \\ X' & \longrightarrow T' \\ T^* & \xrightarrow{\text{pr}_1|_{T^*}} T'\end{aligned}\end{gathered}$$ gives that $p_1(p_0^{-1}(V') \cap X^*)$ is a quasi-compact scheme. Here we set $X'' = T'' \times_T X$, $X^* = T^* \times_T X$, and $X' = T' \times_T X$, and $p_0, p_1 : X'' \to X'$ are the base changes of $\text{pr}_0, \text{pr}_1$. Most of the hypotheses of the lemma imply by base change the corresponding hypothesis for the diagram above. For example $p_0^{-1}(V') = T'' \times_{T'} V'$ is a scheme quasi-affine over $T''$ as a base change. Some verifications omitted.
By Properties of Spaces, Lemma Étale geometry of algebraic spaces we conclude that $$p_1(p_0^{-1}(V')) = V' \cup p_1(p_0^{-1}(V') \cap X^*)$$ is a quasi-compact scheme. Moreover, it is clear that $p_1(p_0^{-1}(V'))$ is the inverse image of the quasi-compact open subspace $U \subset X$ discussed in the first paragraph of the proof. In other words, $T' \times_T U$ is a scheme! Note that $T' \times_T U$ is quasi-compact and separated and locally quasi-finite over $T'$, as $T' \times_T X \to T'$ is locally quasi-finite and separated being a base change of the original morphism $X \to T$ (see Lemmas Base change for diagonals and separation and Base change for finite algebras). This implies by More on Morphisms, Lemma Diagonals, separation and affine neighbourhoods that $T' \times_T U \to T'$ is quasi-affine.
By Descent, Lemma Descent of the geometric construction this gives a descent datum on $T' \times_T U / T'$ relative to the étale covering $\{T' \to W\}$, where $W \subset T$ is the image of the morphism $T' \to T$. Because $U'$ is quasi-affine over $T'$ we see from Descent, Lemma Affine neighbourhoods that this datum is effective, and by the last part of Descent, Lemma Descent of the geometric construction this implies that $U$ is a scheme as desired. Some minor details omitted. $\square$
Lemma. Local algebra
Let $\mathcal{Q}$ be a property of morphisms of germs which is étale local on the source-and-target. Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $x \in |X|$ be a point of $X$. Consider the diagrams $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{a} X \\ U & \xrightarrow{h} V \\ V & \xrightarrow{b} Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered} \quad\quad \begin{gathered}\begin{matrix}u & v \\ x & y\end{matrix} \\[6pt] \begin{aligned}u & \longrightarrow x \\ u & \longrightarrow v \\ v & \longrightarrow y \\ x & \longrightarrow y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes, $a, b$ are étale, and $u, v, x, y$ are points of the corresponding spaces. The following are equivalent
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for any diagram as above we have $\mathcal{Q}((U, u) \to (V, v))$, and
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for some diagram as above we have $\mathcal{Q}((U, u) \to (V, v))$.
If $X$ and $Y$ are representable, then this is also equivalent to $\mathcal{Q}((X, x) \to (Y, y))$.
Proof. Omitted. Hint: Very similar to the proof of Lemma Local algebra. $\square$
Remark. Base change for morphisms of algebraic spaces
Let $S$ be a scheme. Let $\mathcal{P}$ be a property of morphisms of schemes which is étale local on the source-and-target. Suppose that moreover $\mathcal{P}$ is stable under base change. Then the class of morphisms of algebraic spaces having property $\mathcal{P}$ is stable under base change.
Lemma. Base change for morphisms of algebraic spaces
The base change of a quasi-compact morphism of algebraic spaces by any morphism of algebraic spaces is quasi-compact.
Proof. Omitted. Hint: Transitivity of fibre products. $\square$
Lemma. Flatness and local algebra
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent:
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$f$ is flat,
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for every $x \in |X|$ the morphism $f$ is flat at $x$,
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for every scheme $Z$ and any morphism $Z \to Y$ the morphism $Z \times_Y X \to Z$ is flat,
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for every affine scheme $Z$ and any morphism $Z \to Y$ the morphism $Z \times_Y X \to Z$ is flat,
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there exists a scheme $V$ and a surjective étale morphism $V \to Y$ such that $V \times_Y X \to V$ is flat,
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there exists a scheme $U$ and a surjective étale morphism $\varphi : U \to X$ such that the composition $f \circ \varphi$ is flat,
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for every commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U$, $V$ are schemes and the vertical arrows are étale the top horizontal arrow is flat,
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there exists a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U$, $V$ are schemes, the vertical arrows are étale, and $U \to X$ is surjective such that the top horizontal arrow is flat, and
-
there exists a Zariski coverings $Y = \bigcup Y_i$ and $f^{-1}(Y_i) = \bigcup X_{ij}$ such that each morphism $X_{ij} \to Y_i$ is flat.
Proof. Omitted. $\square$
Lemma. Proper morphisms and local algebra
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent
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$f$ is proper,
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for every scheme $Z$ and every morphism $Z \to Y$ the projection $Z \times_Y X \to Z$ is proper,
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for every affine scheme $Z$ and every morphism $Z \to Y$ the projection $Z \times_Y X \to Z$ is proper,
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there exists a scheme $V$ and a surjective étale morphism $V \to Y$ such that $V \times_Y X \to V$ is proper, and
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there exists a Zariski covering $Y = \bigcup Y_i$ such that each of the morphisms $f^{-1}(Y_i) \to Y_i$ is proper.
Proof. Combine Lemmas Diagonals, separation and local algebra (uncovered prerequisite), Finite algebras and local algebra (uncovered prerequisite), Local algebra (uncovered prerequisite), and Local algebra (uncovered prerequisite). $\square$
Lemma. Base change for integral extensions
The base change of an integral (resp. finite) morphism is integral (resp. finite).
Proof. Omitted. $\square$
Lemma. Base change for morphisms of algebraic spaces
The base change of a monomorphism is a monomorphism.
Proof. This is a general fact about fibre products in a category of sheaves. $\square$
Remark. Diagonals and separation
Let $S$ be a scheme. Let $i : Z \to X$ be an immersion of algebraic spaces over $S$. Since $i$ is a monomorphism we may think of $|Z|$ as a subset of $|X|$; in the rest of this remark we do so. Let $\partial |Z|$ be the boundary of $|Z|$ in the topological space $|X|$. In a formula $$\partial |Z| = \overline{|Z|} \setminus |Z|.$$ Let $\partial Z$ be the reduced closed subspace of $X$ with $|\partial Z| = \partial |Z|$ obtained by taking the reduced induced closed subspace structure, see Properties of Spaces, Definition Étale geometry of algebraic spaces. By construction we see that $|Z|$ is closed in $|X| \setminus |\partial Z| = |X \setminus \partial Z|$. Hence it is true that any immersion of algebraic spaces can be factored as a closed immersion followed by an open immersion (but not the other way in general, see Morphisms, Example The geometric construction (uncovered prerequisite)).
Lemma. Base change for projective, locally free modules and finite algebras
The base change of a finite locally free morphism is finite locally free.
Proof. Omitted. $\square$
Lemma. Étale morphisms and injective resolutions
Universally injective étale maps are open immersions.
Let $S$ be a scheme. Let $f : X \to Y$ be an étale and universally injective morphism of algebraic spaces over $S$. Then $f$ is an open immersion.
Proof. Let $T \to Y$ be a morphism from a scheme into $Y$. If we can show that $X \times_Y T \to T$ is an open immersion, then we are done. Since being étale and being universally injective are properties of morphisms stable under base change (see Lemmas Base change for étale morphisms (uncovered prerequisite) and Base change for injective resolutions (uncovered prerequisite)) we may assume that $Y$ is a scheme. Note that the diagonal $\Delta_{X/Y} : X \to X \times_Y X$ is étale, a monomorphism, and surjective by Lemma Injective resolutions (uncovered prerequisite). Hence we see that $\Delta_{X/Y}$ is an isomorphism (see Spaces, Lemma Finite presentation and flatness (uncovered prerequisite)), in particular we see that $X$ is separated over $Y$. It follows that $X$ is a scheme too, by Proposition Diagonals, separation and finite algebras. Finally, $X \to Y$ is an open immersion by the fundamental theorem for étale morphisms of schemes, see Étale Morphisms, Theorem Étale morphisms (uncovered prerequisite). $\square$
Lemma. Flatness and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent:
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$f$ is finite locally free,
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$f$ is finite, flat, and locally of finite presentation.
If $Y$ is locally Noetherian these are also equivalent to
- $f$ is finite and flat.
Proof. In each of the three cases the morphism is representable and you can check the property after base change by a surjective étale morphism $V \to Y$, see Lemmas Integral extensions and local algebra (uncovered prerequisite), Projective, locally free modules and finite algebras (uncovered prerequisite), Flatness and local algebra, and Finite presentation and finite algebras (uncovered prerequisite). If $Y$ is locally Noetherian, then $V$ is locally Noetherian. Hence the result follows from the corresponding result in the schemes case, see Morphisms, Lemma Flatness and finite algebras (uncovered prerequisite). $\square$
[^1]: It seems awkward to use "locally of finite presentation at $x$", but the current terminology may be misleading in the sense that "of finite presentation at $x$" does not mean that there is an open neighbourhood $X' \subset X$ such that $f|_{X'}$ is of finite presentation.
Coherent cohomology on algebraic spaces
Lemma. The initial cohomological property
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{P}$ be a property of coherent sheaves on $X$. Assume
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For any short exact sequence of coherent sheaves $$0 \to \mathcal{F}_1 \to \mathcal{F} \to \mathcal{F}_2 \to 0$$ if $\mathcal{F}_i$, $i = 1, 2$ have property $\mathcal{P}$ then so does $\mathcal{F}$.
-
For every reduced closed subspace $Z \subset X$ with $|Z|$ irreducible and every quasi-coherent sheaf of ideals $\mathcal{I} \subset \mathcal{O}_Z$ we have $\mathcal{P}$ for $i_*\mathcal{I}$.
Then property $\mathcal{P}$ holds for every coherent sheaf on $X$.
Proof. First note that if $\mathcal{F}$ is a coherent sheaf with a filtration $$0 = \mathcal{F}_0 \subset \mathcal{F}_1 \subset \ldots \subset \mathcal{F}_m = \mathcal{F}$$ by coherent subsheaves such that each of $\mathcal{F}_i/\mathcal{F}_{i - 1}$ has property $\mathcal{P}$, then so does $\mathcal{F}$. This follows from the property (1) for $\mathcal{P}$. On the other hand, by Lemma Coherent sheaves we can filter any $\mathcal{F}$ with successive subquotients as in (2). Hence the lemma follows. $\square$
Lemma. Filtering a coherent sheaf by irreducible supports
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a coherent sheaf on $X$. Assume that the scheme theoretic support of $\mathcal{F}$ is a reduced $Z \subset X$ with $|Z|$ irreducible. Then there exist an integer $r > 0$, a nonzero sheaf of ideals $\mathcal{I} \subset \mathcal{O}_Z$, and an injective map of coherent sheaves $$i_*\left(\mathcal{I}^{\oplus r}\right) \to \mathcal{F}$$ whose cokernel is supported on a proper closed subspace of $Z$.
Proof. By assumption there exists a coherent $\mathcal{O}_Z$-module $\mathcal{G}$ with support $Z$ and $\mathcal{F} \cong i_*\mathcal{G}$, see Lemma Coherent sheaves and closed support. Hence it suffices to prove the lemma for the case $Z = X$ and $i = \text{id}$.
By Properties of Spaces, Proposition Diagonals, separation and local algebra there exists a dense open subspace $U \subset X$ which is a scheme. Note that $U$ is a Noetherian integral scheme. After shrinking $U$ we may assume that $\mathcal{F}|_U \cong \mathcal{O}_U^{\oplus r}$ (for example by Cohomology of Schemes, Lemma Filtering a coherent sheaf by irreducible supports (uncovered prerequisite) or by a direct algebra argument). Let $\mathcal{I} \subset \mathcal{O}_X$ be a quasi-coherent sheaf of ideals whose associated closed subspace is the complement of $U$ in $X$ (see for example Properties of Spaces, Section Étale geometry of algebraic spaces). By Lemma Quasi-coherent cohomology there exists an $n \geq 0$ and a morphism $\mathcal{I}^n(\mathcal{O}_X^{\oplus r}) \to \mathcal{F}$ which recovers our isomorphism over $U$. Since $\mathcal{I}^n(\mathcal{O}_X^{\oplus r}) = (\mathcal{I}^n)^{\oplus r}$ we get a map as in the lemma. It is injective: namely, if $\sigma$ is a nonzero section of $\mathcal{I}^{\oplus r}$ over a scheme $W$ étale over $X$, then because $X$ hence $W$ is reduced the support of $\sigma$ contains a nonempty open of $W$. But the kernel of $(\mathcal{I}^n)^{\oplus r} \to \mathcal{F}$ is zero over a dense open, hence $\sigma$ cannot be a section of the kernel. $\square$
Lemma. Coherent sheaves
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a coherent sheaf on $X$. There exists a filtration $$0 = \mathcal{F}_0 \subset \mathcal{F}_1 \subset \ldots \subset \mathcal{F}_m = \mathcal{F}$$ by coherent subsheaves such that for each $j = 1, \ldots, m$ there exists a reduced closed subspace $Z_j \subset X$ with $|Z_j|$ irreducible and a sheaf of ideals $\mathcal{I}_j \subset \mathcal{O}_{Z_j}$ such that $$\mathcal{F}_j/\mathcal{F}_{j - 1} \cong (Z_j \to X)_* \mathcal{I}_j$$
Proof. Consider the collection $$\mathcal{T} = \left\{ \begin{matrix} T \subset |X| \text{ closed such that there exists a coherent sheaf } \mathcal{F} \\ \text{ with } \text{Supp}(\mathcal{F}) = T \text{ for which the lemma is wrong} \end{matrix} \right\}$$ We are trying to show that $\mathcal{T}$ is empty. If not, then because $|X|$ is Noetherian (Properties of Spaces, Lemma The topology of a Noetherian spectrum) we can choose a minimal element $T \in \mathcal{T}$. This means that there exists a coherent sheaf $\mathcal{F}$ on $X$ whose support is $T$ and for which the lemma does not hold. Clearly $T \not = \emptyset$ since the only sheaf whose support is empty is the zero sheaf for which the lemma does hold (with $m = 0$).
If $T$ is not irreducible, then we can write $T = Z_1 \cup Z_2$ with $Z_1, Z_2$ closed and strictly smaller than $T$. Then we can apply Lemma Filtering a coherent sheaf by its support to get a short exact sequence of coherent sheaves $$0 \to \mathcal{G}_1 \to \mathcal{F} \to \mathcal{G}_2 \to 0$$ with $\text{Supp}(\mathcal{G}_i) \subset Z_i$. By minimality of $T$ each of $\mathcal{G}_i$ has a filtration as in the statement of the lemma. By considering the induced filtration on $\mathcal{F}$ we arrive at a contradiction. Hence we conclude that $T$ is irreducible.
Suppose $T$ is irreducible. Let $\mathcal{J}$ be the sheaf of ideals defining the reduced induced closed subspace structure on $T$, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. By Lemma Sheaves on ringed sites we see there exists an $n \geq 0$ such that $\mathcal{J}^n\mathcal{F} = 0$. Hence we obtain a filtration $$0 = \mathcal{I}^n\mathcal{F} \subset \mathcal{I}^{n - 1}\mathcal{F} \subset \ldots \subset \mathcal{I}\mathcal{F} \subset \mathcal{F}$$ each of whose successive subquotients is annihilated by $\mathcal{J}$. Hence if each of these subquotients has a filtration as in the statement of the lemma then also $\mathcal{F}$ does. In other words we may assume that $\mathcal{J}$ does annihilate $\mathcal{F}$.
Assume $T$ is irreducible and $\mathcal{J}\mathcal{F} = 0$ where $\mathcal{J}$ is as above. Then the scheme theoretic support of $\mathcal{F}$ is $T$, see Morphisms of Spaces, Lemma Groupoids and equivalence relations. Hence we can apply Lemma Filtering a coherent sheaf by irreducible supports. This gives a short exact sequence $$0 \to i_*(\mathcal{I}^{\oplus r}) \to \mathcal{F} \to \mathcal{Q} \to 0$$ where the support of $\mathcal{Q}$ is a proper closed subset of $T$. Hence we see that $\mathcal{Q}$ has a filtration of the desired type by minimality of $T$. But then clearly $\mathcal{F}$ does too, which is our final contradiction. $\square$
Lemma. Coherent sheaves and Noetherian rings
Let $S$ be a scheme. Let $X$ be a locally Noetherian algebraic space over $S$. Let $\mathcal{F}$ be an $\mathcal{O}_X$-module. The following are equivalent
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$\mathcal{F}$ is coherent,
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$\mathcal{F}$ is a quasi-coherent, finite type $\mathcal{O}_X$-module,
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$\mathcal{F}$ is a finitely presented $\mathcal{O}_X$-module,
-
for any étale morphism $\varphi : U \to X$ where $U$ is a scheme the pullback $\varphi^*\mathcal{F}$ is a coherent module on $U$, and
-
there exists a surjective étale morphism $\varphi : U \to X$ where $U$ is a scheme such that the pullback $\varphi^*\mathcal{F}$ is a coherent module on $U$.
In particular $\mathcal{O}_X$ is coherent, any invertible $\mathcal{O}_X$-module is coherent, and more generally any finite locally free $\mathcal{O}_X$-module is coherent.
Proof. To be sure, if $X$ is a locally Noetherian algebraic space and $U \to X$ is an étale morphism, then $U$ is locally Noetherian, see Properties of Spaces, Section Proper morphisms. The lemma then follows from the points (1) -- (5) made in Properties of Spaces, Section Proper morphisms and modules and the corresponding result for coherent modules on locally Noetherian schemes, see Cohomology of Schemes, Lemma Coherent sheaves and Noetherian rings (uncovered prerequisite). $\square$
Lemma. Coherent sheaves and Noetherian rings
Let $S$ be a scheme. Let $X$ be a locally Noetherian algebraic space over $S$. The category of coherent $\mathcal{O}_X$-modules is abelian. More precisely, the kernel and cokernel of a map of coherent $\mathcal{O}_X$-modules are coherent. Any extension of coherent sheaves is coherent.
Proof. Choose a scheme $U$ and a surjective étale morphism $f : U \to X$. Pullback $f^*$ is an exact functor as it equals a restriction functor, see Properties of Spaces, Equation (Modules). By Lemma Coherent sheaves and Noetherian rings we can check whether an $\mathcal{O}_X$-module $\mathcal{F}$ is coherent by checking whether $f^*\mathcal{F}$ is coherent. Hence the lemma follows from the case of schemes which is Cohomology of Schemes, Lemma Coherent sheaves and Noetherian rings (uncovered prerequisite). $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be a locally Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a coherent $\mathcal{O}_X$-module. Any quasi-coherent submodule of $\mathcal{F}$ is coherent. Any quasi-coherent quotient module of $\mathcal{F}$ is coherent.
Proof. Choose a scheme $U$ and a surjective étale morphism $f : U \to X$. Pullback $f^*$ is an exact functor as it equals a restriction functor, see Properties of Spaces, Equation (Modules). By Lemma Coherent sheaves and Noetherian rings we can check whether an $\mathcal{O}_X$-module $\mathcal{G}$ is coherent by checking whether $f^*\mathcal{H}$ is coherent. Hence the lemma follows from the case of schemes which is Cohomology of Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite). $\square$
Lemma. Affine neighbourhoods
Let $S$ be a scheme. Let $f : X \to Y$ be an affine morphism of algebraic spaces over $S$. Then $R^if_*\mathcal{F} = 0$ for $i > 0$ and any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$.
Proof. Recall that an affine morphism of algebraic spaces is representable. Hence this follows from (Quasi-coherent cohomology) and Cohomology of Schemes, Lemma Affine neighbourhoods (uncovered prerequisite). $\square$
Lemma. Quasi-coherent cohomology
Let $S$ be a scheme. Consider a commutative diagram $$\begin{gathered}\begin{matrix}X & \mathbf{P}^n_Y \\ \phantom{X} & Y\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{i} \mathbf{P}^n_Y \\ X & \xrightarrow{f} Y \\ \mathbf{P}^n_Y & \longrightarrow Y\end{aligned}\end{gathered}$$ of algebraic spaces over $S$. Assume $i$ is a closed immersion and $Y$ Noetherian. Set $\mathcal{L} = i^*\mathcal{O}_{\mathbf{P}^n_Y}(1)$. Let $\mathcal{F}$ be a coherent module on $X$. Then there exists an integer $d_0$ such that for all $d \geq d_0$ we have $R^pf_*(\mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{L}^{\otimes d}) = 0$ for all $p > 0$.
Proof. Checking whether $R^pf_*(\mathcal{F} \otimes \mathcal{L}^{\otimes d})$ is zero can be done étale locally on $Y$, see Equation (Quasi-coherent cohomology). Hence we may assume $Y$ is the spectrum of a Noetherian ring. In this case $X$ is a scheme and the result follows from Cohomology of Schemes, Lemma The geometric construction (uncovered prerequisite). $\square$
Lemma. Vanishing and quasi-coherent cohomology
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume that
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$f$ is quasi-compact and quasi-separated, and
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$Y$ is quasi-compact.
Then there exists an integer $n(X \to Y)$ such that for any algebraic space $Y'$, any morphism $Y' \to Y$ and any quasi-coherent sheaf $\mathcal{F}'$ on $X' = Y' \times_Y X$ the higher direct images $R^if'_*\mathcal{F}'$ are zero for $i \geq n(X \to Y)$.
Proof. Let $V \to Y$ be a surjective étale morphism where $V$ is an affine scheme, see Properties of Spaces, Lemma Affine neighbourhoods. Suppose we prove the result for the base change $f_V : V \times_Y X \to V$. Then the result holds for $f$ with $n(X \to Y) = n(X_V \to V)$. Namely, if $Y' \to Y$ and $\mathcal{F}'$ are as in the lemma, then $R^if'_*\mathcal{F}'|_{V \times_Y Y'}$ is equal to $R^if'_{V, *}\mathcal{F}'|_{X'_V}$ where $f'_V : X'_V = V \times_Y Y' \times_Y X \to V \times_Y Y' = Y'_V$, see Properties of Spaces, Lemma Base change for étale morphisms and modules. Thus we may assume that $Y$ is an affine scheme.
Moreover, to prove the vanishing for all $Y' \to Y$ and $\mathcal{F}'$ it suffices to do so when $Y'$ is an affine scheme. In this case, $R^if'_*\mathcal{F}'$ is quasi-coherent by Lemma Quasi-coherent cohomology. Hence it suffices to prove that $H^i(X', \mathcal{F}') = 0$, because $H^i(X', \mathcal{F}') = H^0(Y', R^if'_*\mathcal{F}')$ by Cohomology on Sites, Lemma Acyclicity and the Leray spectral sequence and the vanishing of higher cohomology of quasi-coherent sheaves on affine algebraic spaces (Proposition Vanishing and quasi-coherent cohomology).
Choose $U \to X$, $d$, $V_p \to U_p$ and $d_p$ as in Lemma Vanishing and diagonals and separation. For any affine scheme $Y'$ and morphism $Y' \to Y$ denote $X' = Y' \times_Y X$, $U' = Y' \times_Y U$, $V'_p = Y' \times_Y V_p$. Then $U' \to X'$, $d' = d$, $V'_p \to U'_p$ and $d'_p = d$ is a collection of choices as in Lemma Vanishing and diagonals and separation for the algebraic space $X'$ (details omitted). Hence we see that $H^i(X', \mathcal{F}') = 0$ for $i \geq \max(p + d_p)$ and we win. $\square$
Lemma. Quasi-coherent cohomology
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. If $f$ is quasi-compact and quasi-separated, then $R^if_*$ transforms quasi-coherent $\mathcal{O}_X$-modules into quasi-coherent $\mathcal{O}_Y$-modules.
Proof. Let $V \to Y$ be an étale morphism where $V$ is an affine scheme. Set $U = V \times_Y X$ and denote $f' : U \to V$ the induced morphism. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. By Properties of Spaces, Lemma Base change for étale morphisms and modules we have $R^if'_*(\mathcal{F}|_U) = (R^if_*\mathcal{F})|_V$. Since the property of being a quasi-coherent module is local in the étale topology on $Y$ (see Properties of Spaces, Lemma Criteria for quasi-coherent complexes and coherent sheaves) we may replace $Y$ by $V$, i.e., we may assume $Y$ is an affine scheme.
Assume $Y$ is affine. Since $f$ is quasi-compact we see that $X$ is quasi-compact. Thus we may choose an affine scheme $U$ and a surjective étale morphism $g : U \to X$, see Properties of Spaces, Lemma Affine neighbourhoods. Picture $$\begin{gathered}\begin{matrix}U & X \\ \phantom{X} & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{g} X \\ U & \xrightarrow{f \circ g} Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ The morphism $g : U \to X$ is representable, separated and quasi-compact because $X$ is quasi-separated. Hence the lemma holds for $g$ (by the discussion above the lemma). It also holds for $f \circ g : U \to Y$ (as this is a morphism of affine schemes).
In the situation described in the previous paragraph we will show by induction on $n$ that $IH_n$: for any quasi-coherent sheaf $\mathcal{F}$ on $X$ the sheaves $R^if\mathcal{F}$ are quasi-coherent for $i \leq n$. The case $n = 0$ follows from Morphisms of Spaces, Lemma Direct images and morphisms of algebraic spaces. Assume $IH_n$. In the rest of the proof we show that $IH_{n + 1}$ holds.
Let $\mathcal{H}$ be a quasi-coherent $\mathcal{O}_U$-module. Consider the Leray spectral sequence $$E_2^{p, q} = R^pf_* R^qg_* \mathcal{H} \Rightarrow R^{p + q}(f \circ g)_*\mathcal{H}$$ Cohomology on Sites, Lemma Sheaf cohomology. As $R^qg_*\mathcal{H}$ is quasi-coherent by $IH_n$ all the sheaves $R^pf_*R^qg_*\mathcal{H}$ are quasi-coherent for $p \leq n$. The sheaves $R^{p + q}(f \circ g)_*\mathcal{H}$ are all quasi-coherent (in fact zero for $p + q > 0$ but we do not need this). Looking in degrees $\leq n + 1$ the only module which we do not yet know is quasi-coherent is $E_2^{n + 1, 0} = R^{n + 1}f_*g_*\mathcal{H}$. Moreover, the differentials $d_r^{n + 1, 0} : E_r^{n + 1, 0} \to E_r^{n + 1 + r, 1 - r}$ are zero as the target is zero. Using that $\mathrm{QCoh}(\mathcal{O}_X)$ is a weak Serre subcategory of $\textit{Mod}(\mathcal{O}_X)$ (Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves) it follows that $R^{n + 1}f_*g_*\mathcal{H}$ is quasi-coherent (details omitted).
Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Set $\mathcal{H} = g^*\mathcal{F}$. The adjunction mapping $\mathcal{F} \to g_*g^*\mathcal{F} = g_*\mathcal{H}$ is injective as $U \to X$ is surjective étale. Consider the exact sequence $$0 \to \mathcal{F} \to g_*\mathcal{H} \to \mathcal{G} \to 0$$ where $\mathcal{G}$ is the cokernel of the first map and in particular quasi-coherent. Applying the long exact cohomology sequence we obtain $$R^nf_*g_*\mathcal{H} \to R^nf_*\mathcal{G} \to R^{n + 1}f_*\mathcal{F} \to R^{n + 1}f_*g_*\mathcal{H} \to R^{n + 1}f_*\mathcal{G}$$ The cokernel of the first arrow is quasi-coherent and we have seen above that $R^{n + 1}f_*g_*\mathcal{H}$ is quasi-coherent. Thus $R^{n + 1}f_*\mathcal{F}$ has a $2$-step filtration where the first step is quasi-coherent and the second a submodule of a quasi-coherent sheaf. Since $\mathcal{F}$ is an arbitrary quasi-coherent $\mathcal{O}_X$-module, this result also holds for $\mathcal{G}$. Thus we can choose an exact sequence $0 \to \mathcal{A} \to R^{n + 1}f_*\mathcal{G} \to \mathcal{B}$ with $\mathcal{A}$, $\mathcal{B}$ quasi-coherent $\mathcal{O}_Y$-modules. Then the kernel $\mathcal{K}$ of $R^{n + 1}f_*g_*\mathcal{H} \to R^{n + 1}f_*\mathcal{G} \to \mathcal{B}$ is quasi-coherent, whereupon we obtain a map $\mathcal{K} \to \mathcal{A}$ whose kernel $\mathcal{K}'$ is quasi-coherent too. Hence $R^{n + 1}f_*\mathcal{F}$ sits in an exact sequence $$R^nf_*g_*\mathcal{H} \to R^nf_*\mathcal{G} \to R^{n + 1}f_*\mathcal{F} \to \mathcal{K}' \to 0$$ with all modules quasi-coherent except for possibly $R^{n + 1}f_*\mathcal{F}$. We conclude that $R^{n + 1}f_*\mathcal{F}$ is quasi-coherent, i.e., $IH_{n + 1}$ holds as desired. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-separated and quasi-compact morphism of algebraic spaces over $S$. For any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ and any affine object $V$ of $Y_\mathrm{\acute{e}tale}$ we have $$H^q(V \times_Y X, \mathcal{F}) = H^0(V, R^qf_*\mathcal{F})$$ for all $q \in \mathbf{Z}$.
Proof. Since formation of $Rf_*$ commutes with étale localization (Properties of Spaces, Lemma Base change for étale morphisms and modules) we may replace $Y$ by $V$ and assume $Y = V$ is affine. Consider the Leray spectral sequence $E_2^{p, q} = H^p(Y, R^qf_*\mathcal{F})$ converging to $H^{p + q}(X, \mathcal{F})$, see Cohomology on Sites, Lemma The Leray spectral sequence. By Lemma Quasi-coherent cohomology we see that the sheaves $R^qf_*\mathcal{F}$ are quasi-coherent. By Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite) we see that $E_2^{p, q} = 0$ when $p > 0$. Hence the spectral sequence degenerates at $E_2$ and we win. $\square$
Lemma. Coherent sheaves and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ be a finite morphism of algebraic spaces over $S$ with $Y$ locally Noetherian. Let $\mathcal{F}$ be a coherent $\mathcal{O}_X$-module. Assume $f$ is finite and $Y$ locally Noetherian. Then $R^pf_*\mathcal{F} = 0$ for $p > 0$ and $f_*\mathcal{F}$ is coherent.
Proof. Choose a scheme $V$ and a surjective étale morphism $V \to Y$. Then $V \times_Y X \to V$ is a finite morphism of locally Noetherian schemes. By (Quasi-coherent cohomology) we reduce to the case of schemes which is Cohomology of Schemes, Lemma Coherent sheaves and finite algebras (uncovered prerequisite). $\square$
Lemma. Affine neighbourhoods and Noetherian rings
Let $S$ be a scheme. Let $f : Y \to X$ be a morphism of algebraic spaces over $S$. Assume
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$f$ finite,
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$f$ surjective,
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$Y$ affine, and
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$X$ Noetherian.
Then $X$ is affine.
Proof. We will prove that under the assumptions of the lemma for any coherent $\mathcal{O}_X$-module $\mathcal{F}$ we have $H^1(X, \mathcal{F}) = 0$. This implies that $H^1(X, \mathcal{F}) = 0$ for every quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ by Lemmas Filtered limits and coherent sheaves and Filtered limits and quasi-coherent cohomology. Then it follows that $X$ is affine from Proposition Vanishing and affine neighbourhoods.
Let $\mathcal{P}$ be the property of coherent sheaves $\mathcal{F}$ on $X$ defined by the rule $$\mathcal{P}(\mathcal{F}) \Leftrightarrow H^1(X, \mathcal{F}) = 0.$$ We are going to apply Lemma Sheaf cohomology and proper morphisms. Thus we have to verify (1), (2) and (3) of that lemma for $\mathcal{P}$. Property (1) follows from the long exact cohomology sequence associated to a short exact sequence of sheaves. Property (2) follows since $H^1(X, -)$ is an additive functor. To see (3) let $i : Z \to X$ be a reduced closed subspace with $|Z|$ irreducible. Let $i' : Z' \to Y$ and $f' : Z' \to Z$ be as in Lemma Noetherian rings and finite algebras and set $\mathcal{G} = f'_*\mathcal{O}_{Z'}$. We claim that $\mathcal{G}$ satisfies properties (3)(a) and (3)(b) of Lemma Sheaf cohomology and proper morphisms which will finish the proof. Property (3)(a) we have seen in Lemma Noetherian rings and finite algebras. To see (3)(b) let $\mathcal{I}$ be a nonzero quasi-coherent sheaf of ideals on $Z$. Denote $\mathcal{I}' \subset \mathcal{O}_{Z'}$ the quasi-coherent ideal $(f')^{-1}\mathcal{I} \mathcal{O}_{Z'}$, i.e., the image of $(f')^*\mathcal{I} \to \mathcal{O}_{Z'}$. By Lemma Affine neighbourhoods we have $f_*\mathcal{I}' = \mathcal{I} \mathcal{G}$. We claim the common value $\mathcal{G}' = \mathcal{I} \mathcal{G} = f'_*\mathcal{I}'$ satisfies the condition expressed in (3)(b). First, it is clear that the support of $\mathcal{G}/\mathcal{G}'$ is contained in the support of $\mathcal{O}_Z/\mathcal{I}$ which is a proper subspace of $|Z|$ as $\mathcal{I}$ is a nonzero ideal sheaf on the reduced and irreducible algebraic space $Z$. The morphism $f'$ is affine, hence $R^1f'_*\mathcal{I}' = 0$ by Lemma Affine neighbourhoods. As $Z'$ is affine (as a closed subscheme of an affine scheme) we have $H^1(Z', \mathcal{I}') = 0$. Hence the Leray spectral sequence (in the form Cohomology on Sites, Lemma Acyclicity and the Leray spectral sequence) implies that $H^1(Z, f'_*\mathcal{I}') = 0$. Since $i : Z \to X$ is affine we conclude that $R^1i_*f'_*\mathcal{I}' = 0$ hence $H^1(X, i_*f'_*\mathcal{I}') = 0$ by Leray again. In other words, we have $H^1(X, i_*\mathcal{G}') = 0$ as desired. $\square$
Lemma. Coherent sheaves and closed support
Let $S$ be a scheme. Let $X$ be a locally Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a coherent $\mathcal{O}_X$-module. Let $i : Z \to X$ be the scheme theoretic support of $\mathcal{F}$ and $\mathcal{G}$ the quasi-coherent $\mathcal{O}_Z$-module such that $i_*\mathcal{G} = \mathcal{F}$, see Morphisms of Spaces, Definition Closed support. Then $\mathcal{G}$ is a coherent $\mathcal{O}_Z$-module.
Proof. The statement of the lemma makes sense as a coherent module is in particular of finite type. Moreover, as $Z \to X$ is a closed immersion it is locally of finite type and hence $Z$ is locally Noetherian, see Morphisms of Spaces, Lemmas Diagonals, separation and finite algebras (uncovered prerequisite) and Noetherian rings and finite algebras. Finally, as $\mathcal{G}$ is of finite type it is a coherent $\mathcal{O}_Z$-module by Lemma Coherent sheaves and Noetherian rings $\square$
Lemma. Quasi-coherent cohomology
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Let $\mathcal{G}$ be a coherent $\mathcal{O}_X$-module. Let $\mathcal{I} \subset \mathcal{O}_X$ be a quasi-coherent sheaf of ideals. Denote $Z \subset X$ the corresponding closed subspace and set $U = X \setminus Z$. There is a canonical isomorphism $$\mathop{\operatorname{colim}}_n \operatorname{Hom}_{\mathcal{O}_X}(\mathcal{I}^n\mathcal{G}, \mathcal{F}) \longrightarrow \operatorname{Hom}_{\mathcal{O}_U}(\mathcal{G}|_U, \mathcal{F}|_U).$$ In particular we have an isomorphism $$\mathop{\operatorname{colim}}_n \operatorname{Hom}_{\mathcal{O}_X}(\mathcal{I}^n, \mathcal{F}) \longrightarrow \Gamma(U, \mathcal{F}).$$
Proof. Let $W$ be an affine scheme and let $W \to X$ be a surjective étale morphism (see Properties of Spaces, Lemma Affine neighbourhoods). Set $R = W \times_X W$. Then $W$ and $R$ are Noetherian schemes, see Morphisms of Spaces, Lemma Noetherian rings and finite algebras. Hence the result hold for the restrictions of $\mathcal{F}$, $\mathcal{G}$, and $\mathcal{I}$, $U$, $Z$ to $W$ and $R$ by Cohomology of Schemes, Lemma The geometric construction (uncovered prerequisite). It follows formally that the result holds over $X$. $\square$
Lemma. Filtering a coherent sheaf by its support
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a coherent sheaf on $X$. Suppose that $\text{Supp}(\mathcal{F}) = Z \cup Z'$ with $Z$, $Z'$ closed. Then there exists a short exact sequence of coherent sheaves $$0 \to \mathcal{G}' \to \mathcal{F} \to \mathcal{G} \to 0$$ with $\text{Supp}(\mathcal{G}') \subset Z'$ and $\text{Supp}(\mathcal{G}) \subset Z$.
Proof. Let $\mathcal{I} \subset \mathcal{O}_X$ be the sheaf of ideals defining the reduced induced closed subspace structure on $Z$, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. Consider the subsheaves $\mathcal{G}'_n = \mathcal{I}^n\mathcal{F}$ and the quotients $\mathcal{G}_n = \mathcal{F}/\mathcal{I}^n\mathcal{F}$. For each $n$ we have a short exact sequence $$0 \to \mathcal{G}'_n \to \mathcal{F} \to \mathcal{G}_n \to 0$$ For every geometric point $\overline{x}$ of $Z' \setminus Z$ we have $\mathcal{I}_{\overline{x}} = \mathcal{O}_{X, \overline{x}}$ and hence $\mathcal{G}_{n, \overline{x}} = 0$. Thus we see that $\text{Supp}(\mathcal{G}_n) \subset Z$. Note that $X \setminus Z'$ is a Noetherian algebraic space. Hence by Lemma Sheaves on ringed sites there exists an $n$ such that $\mathcal{G}'_n|_{X \setminus Z'} = \mathcal{I}^n\mathcal{F}|_{X \setminus Z'} = 0$. For such an $n$ we see that $\text{Supp}(\mathcal{G}'_n) \subset Z'$. Thus setting $\mathcal{G}' = \mathcal{G}'_n$ and $\mathcal{G} = \mathcal{G}_n$ works. $\square$
Lemma. Sheaves on ringed sites
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a coherent sheaf on $X$. Let $\mathcal{I} \subset \mathcal{O}_X$ be a quasi-coherent sheaf of ideals corresponding to a closed subspace $Z \subset X$. Then there is some $n \geq 0$ such that $\mathcal{I}^n\mathcal{F} = 0$ if and only if $\text{Supp}(\mathcal{F}) \subset Z$ (set theoretically).
Proof. Choose an affine scheme $U$ and a surjective étale morphism $U \to X$ (see Properties of Spaces, Lemma Affine neighbourhoods). Then $U$ is a Noetherian scheme (by Morphisms of Spaces, Lemma Noetherian rings and finite algebras). Note that $\mathcal{I}^n\mathcal{F}|_U = 0$ if and only if $\mathcal{I}^n\mathcal{F} = 0$ and similarly for the condition on the support. Hence the result follows from the case of schemes, see Cohomology of Schemes, Lemma Sheaves on ringed sites (uncovered prerequisite). $\square$
Proposition. Vanishing and quasi-coherent cohomology
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Assume $X$ is quasi-compact and separated. Let $U$ be an affine scheme, and let $f : U \to X$ be a surjective étale morphism. Let $d$ be an upper bound for the size of the fibres of $|U| \to |X|$. Then for any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ we have $H^q(X, \mathcal{F}) = 0$ for $q \geq d$.
Proof. We will use the spectral sequence of Lemma Quasi-coherent cohomology. The lemma applies since $f$ is separated as $U$ is separated, see Morphisms of Spaces, Lemma Composition and diagonals and separation. Since $X$ is separated the scheme $U \times_X \ldots \times_X U$ is a closed subscheme of $U \times_{\operatorname{Spec}(\mathbf{Z})} \ldots \times_{\operatorname{Spec}(\mathbf{Z})} U$ hence is affine. Thus $W_p$ is affine. Hence $U_p = W_p/S_{p + 1}$ is an affine scheme by Groupoids, Proposition Flatness and groupoids and equivalence relations. The discussion in Section Quasi-coherent cohomology shows that cohomology of quasi-coherent sheaves on $W_p$ (as an algebraic space) agrees with the cohomology of the corresponding quasi-coherent sheaf on the underlying affine scheme, hence vanishes in positive degrees by Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). By Lemma Quasi-coherent complexes and coherent sheaves the sheaves $\mathcal{F}|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p)$ are quasi-coherent. Hence $H^q(W_p, \mathcal{F}|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p))$ is zero when $q > 0$. By our definition of the integer $d$ we see that $W_p = \emptyset$ for $p \geq d$. Hence also $H^0(W_p, \mathcal{F}|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p))$ is zero when $p \geq d$. This proves the proposition. $\square$
Lemma. Vanishing and diagonals and separation
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Assume $X$ is quasi-compact and quasi-separated. Then we can choose
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an affine scheme $U$,
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a surjective étale morphism $f : U \to X$,
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an integer $d$ bounding the degrees of the fibres of $U \to X$,
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for every $p = 0, 1, \ldots, d$ a surjective étale morphism $V_p \to U_p$ from an affine scheme $V_p$ where $U_p$ is as in Lemma Quasi-coherent cohomology, and
-
an integer $d_p$ bounding the degree of the fibres of $V_p \to U_p$.
Moreover, whenever we have (1) -- (5), then for any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ we have $H^q(X, \mathcal{F}) = 0$ for $q \geq \max(d_p + p)$.
Proof. Since $X$ is quasi-compact we can find a surjective étale morphism $U \to X$ with $U$ affine, see Properties of Spaces, Lemma Affine neighbourhoods. By Decent Spaces, Lemma Schematic neighbourhoods the fibres of $f$ are universally bounded, hence we can find $d$. We have $U_p = W_p/S_{p + 1}$ and $W_p \subset U \times_X \ldots \times_X U$ is open and closed. Since $X$ is quasi-separated the schemes $W_p$ are quasi-compact, hence $U_p$ is quasi-compact. Since $U$ is separated, the schemes $W_p$ are separated, hence $U_p$ is separated by (the absolute version of) Spaces, Lemma Diagonals, separation and finite algebras (uncovered prerequisite). By Properties of Spaces, Lemma Affine neighbourhoods we can find the morphisms $V_p \to W_p$. By Decent Spaces, Lemma Schematic neighbourhoods we can find the integers $d_p$.
At this point the proof uses the spectral sequence $$E_1^{p, q} = H^q(U_p, \mathcal{F}|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p)) \Rightarrow H^{p + q}(X, \mathcal{F})$$ see Lemma Quasi-coherent cohomology. By definition of the integer $d$ we see that $U_p = 0$ for $p \geq d$. By Proposition Vanishing and quasi-coherent cohomology and Lemma Quasi-coherent complexes and coherent sheaves we see that $H^q(U_p, \mathcal{F}|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p))$ is zero for $q \geq d_p$ for $p = 0, \ldots, d$. Whence the lemma. $\square$
Lemma. Étale morphisms
Let $f : X \to Y$ be a quasi-compact, separated, étale morphism of algebraic spaces. Then for any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ the map $f^*f_*\mathcal{F} \to \mathcal{F}$ is split.
Proof. Consider the cartesian diagram $$\begin{gathered}\begin{matrix}X \times_Y X & X \\ X & Y\end{matrix} \\[6pt] \begin{aligned}X \times_Y X & \xrightarrow{p} X \\ X \times_Y X & \xrightarrow{q} X \\ X & \xrightarrow{f} Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ By Lemma Base change for affine neighbourhoods we have $f^*f_*\mathcal{F} = q_*p^*\mathcal{F}$. The morphism $\Delta : X \to X \times_Y X$ is open (as a morphism between algebraic spaces étale over $Y$) and closed as $f$ is separated. Thus we see that $p^*\mathcal{F}$ is a direct sum of $\Delta_*\mathcal{F}$ and a quasi-coherent module supported on the (open and closed) complement of $\Delta(X)$. Tracing the maps the reader verifies that $$\mathcal{F} = q_*\Delta_*\mathcal{F} \to q_*p^*\mathcal{F} = f^*f_*\mathcal{F} \to \mathcal{F}$$ is the identity map. Details omitted. $\square$
Lemma. Filtered limits and sheaf cohomology
Higher direct images of qcqs morphisms commute with filtered colimits of sheaves.
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-compact and quasi-separated morphism of algebraic spaces over $S$. Let $\mathcal{F} = \mathop{\operatorname{colim}} \mathcal{F}_i$ be a filtered colimit of abelian sheaves on $X_\mathrm{\acute{e}tale}$. Then for any $p \geq 0$ we have $$R^pf_*\mathcal{F} = \mathop{\operatorname{colim}} R^pf_*\mathcal{F}_i.$$
Proof. We will use that the morphism of topoi $f_{small} : X_{small} \to Y_{small}$ comes from the morphism of sites $f_{spaces, \mathrm{\acute{e}tale}} : X_{spaces, \mathrm{\acute{e}tale}} \to Y_{spaces, \mathrm{\acute{e}tale}}$ corresponding to the continuous functor $V \longmapsto X \times_Y V$, see Properties of Spaces, Lemma Étale morphisms and sheaves on ringed sites (uncovered prerequisite). We will apply Cohomology on Sites, Lemma Filtered limits and derived modules on ringed sites (uncovered prerequisite) to this morphism of sites. Since every object of $Y_{spaces, \mathrm{\acute{e}tale}}$ has a covering by affine objects, it suffices to show that for $V$ affine and étale over $Y$ we have $H^p(X \times_Y V, \mathcal{F}) = \mathop{\operatorname{colim}} H^p(X \times_Y V, \mathcal{F}_i)$. Since $V$ is affine, the algebraic space $X \times_Y V$ is quasi-compact and quasi-separated. Hence we can apply Lemma Filtered limits and quasi-coherent cohomology to conclude. $\square$
Proposition. Vanishing and affine neighbourhoods
Serre's criterion for affineness in the setting of algebraic spaces.
A quasi-compact and quasi-separated algebraic space is affine if and only if all higher cohomology groups of quasi-coherent sheaves vanish. More precisely, any algebraic space as in Situation Vanishing and quasi-coherent cohomology is an affine scheme.
Proof. Choose an affine scheme $U = \operatorname{Spec}(B)$ and a surjective étale morphism $\varphi : U \to X$. Set $R = U \times_X U$. As $p$ is separated (Lemma Vanishing and diagonals and separation) we see that $R$ is a closed subscheme of $U \times_{\operatorname{Spec}(A)} U = \operatorname{Spec}(B \otimes_A B)$. Hence $R = \operatorname{Spec}(C)$ is affine too and the ring map $$B \otimes_A B \longrightarrow C$$ is surjective. Let us denote the two maps $s, t : B \to C$ as usual. Pick $g_1, \ldots, g_m \in B$ such that $s(g_1), \ldots, s(g_m)$ generate $C$ over $t : B \to C$ (which is possible as $t : B \to C$ is of finite presentation and the displayed map is surjective). Then $g_1, \ldots, g_m$ give global sections of $\varphi_*\mathcal{O}_U$ and the map $$\mathcal{O}_X[z_1, \ldots, z_n] \longrightarrow \varphi_*\mathcal{O}_U, \quad z_j \longmapsto g_j$$ is surjective: you can check this by restricting to $U$. Namely, $\varphi^*\varphi_*\mathcal{O}_U = t_*\mathcal{O}_R$ (by Lemma Base change for sheaf cohomology and flatness) hence you get exactly the condition that $s(g_i)$ generate $C$ over $t : B \to C$. By the vanishing of $H^1$ of the kernel we see that $$\Gamma(X, \mathcal{O}_X[x_1, \ldots, x_n]) = A[x_1, \ldots, x_n] \longrightarrow \Gamma(X, \varphi_*\mathcal{O}_U) = \Gamma(U, \mathcal{O}_U) = B$$ is surjective. Thus we conclude that $B$ is a finite type $A$-algebra. Hence $X \to \operatorname{Spec}(A)$ is of finite type and separated. By Lemma Vanishing and injective resolutions and Morphisms of Spaces, Lemma Finite algebras and local algebra (uncovered prerequisite) it is also locally quasi-finite. Hence $X \to \operatorname{Spec}(A)$ is representable by Morphisms of Spaces, Lemma Diagonals, separation and finite algebras (uncovered prerequisite) and $X$ is a scheme. Finally $X$ is affine, hence equal to $\operatorname{Spec}(A)$, by an application of Cohomology of Schemes, Lemma The geometric construction (uncovered prerequisite). $\square$
Lemma. Filtered limits and coherent sheaves
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Every quasi-coherent $\mathcal{O}_X$-module is the filtered colimit of its coherent submodules.
Proof. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. If $\mathcal{G}, \mathcal{H} \subset \mathcal{F}$ are coherent $\mathcal{O}_X$-submodules then the image of $\mathcal{G} \oplus \mathcal{H} \to \mathcal{F}$ is another coherent $\mathcal{O}_X$-submodule which contains both of them (see Lemmas Coherent sheaves and Noetherian rings and Quasi-coherent complexes and coherent sheaves). In this way we see that the system is directed. Hence it now suffices to show that $\mathcal{F}$ can be written as a filtered colimit of coherent modules, as then we can take the images of these modules in $\mathcal{F}$ to conclude there are enough of them.
Let $U$ be an affine scheme and $U \to X$ a surjective étale morphism. Set $R = U \times_X U$ so that $X = U/R$ as usual. By Properties of Spaces, Proposition Quasi-coherent complexes and coherent sheaves we see that $\mathrm{QCoh}(\mathcal{O}_X) = \mathrm{QCoh}(U, R, s, t, c)$. Hence we reduce to showing the corresponding thing for $\mathrm{QCoh}(U, R, s, t, c)$. Thus the result follows from the more general Groupoids, Lemma Filtered limits and coherent sheaves (uncovered prerequisite). $\square$
Lemma. Filtered limits and quasi-coherent cohomology
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. If $X$ is quasi-compact and quasi-separated, then $$\mathop{\operatorname{colim}}_i H^p(X, \mathcal{F}_i) \longrightarrow H^p(X, \mathop{\operatorname{colim}}_i \mathcal{F}_i)$$ is an isomorphism for every filtered diagram of abelian sheaves on $X_\mathrm{\acute{e}tale}$.
Proof. This follows from Cohomology on Sites, Lemma Derived modules on ringed sites (uncovered prerequisite). Namely, let $\mathcal{B} \subset \operatorname{Ob}(X_{spaces, \mathrm{\acute{e}tale}})$ be the set of quasi-compact and quasi-separated spaces étale over $X$. Note that if $U \in \mathcal{B}$ then, because $U$ is quasi-compact, the collection of finite coverings $\{U_i \to U\}$ with $U_i \in \mathcal{B}$ is cofinal in the set of coverings of $U$ in $X_{spaces, \mathrm{\acute{e}tale}}$. By Morphisms of Spaces, Lemma Diagonals and separation (uncovered prerequisite) the set $\mathcal{B}$ satisfies all the assumptions of Cohomology on Sites, Lemma Derived modules on ringed sites (uncovered prerequisite). Since $X \in \mathcal{B}$ we win. $\square$
Lemma. Sheaf cohomology and proper morphisms
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{P}$ be a property of coherent sheaves on $X$. Assume
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For any short exact sequence of coherent sheaves $$0 \to \mathcal{F}_1 \to \mathcal{F} \to \mathcal{F}_2 \to 0$$ if $\mathcal{F}_i$, $i = 1, 2$ have property $\mathcal{P}$ then so does $\mathcal{F}$.
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If $\mathcal{P}$ holds for $\mathcal{F}^{\oplus r}$ for some $r \geq 1$, then it holds for $\mathcal{F}$.
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For every reduced closed subspace $i : Z \to X$ with $|Z|$ irreducible there exists a coherent sheaf $\mathcal{G}$ on $Z$ such that
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$\text{Supp}(\mathcal{G}) = Z$,
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for every nonzero quasi-coherent sheaf of ideals $\mathcal{I} \subset \mathcal{O}_Z$ there exists a quasi-coherent subsheaf $\mathcal{G}' \subset \mathcal{I}\mathcal{G}$ such that $\text{Supp}(\mathcal{G}/\mathcal{G}')$ is proper closed in $|Z|$ and such that $\mathcal{P}$ holds for $i_*\mathcal{G}'$.
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Then property $\mathcal{P}$ holds for every coherent sheaf on $X$.
Proof. Consider the collection $$\mathcal{T} = \left\{ \begin{matrix} T \subset |X| \text{ nonempty closed such that there exists a coherent sheaf } \\ \mathcal{F} \text{ with } \text{Supp}(\mathcal{F}) = T \text{ for which the lemma is wrong} \end{matrix} \right\}$$ We are trying to show that $\mathcal{T}$ is empty. If not, then because $|X|$ is Noetherian (Properties of Spaces, Lemma The topology of a Noetherian spectrum) we can choose a minimal element $T \in \mathcal{T}$. This means that there exists a coherent sheaf $\mathcal{F}$ on $X$ whose support is $T$ and for which the lemma does not hold.
If $T$ is not irreducible, then we can write $T = Z_1 \cup Z_2$ with $Z_1, Z_2$ closed and strictly smaller than $T$. Then we can apply Lemma Filtering a coherent sheaf by its support to get a short exact sequence of coherent sheaves $$0 \to \mathcal{G}_1 \to \mathcal{F} \to \mathcal{G}_2 \to 0$$ with $\text{Supp}(\mathcal{G}_i) \subset Z_i$. By minimality of $T$ each of $\mathcal{G}_i$ has $\mathcal{P}$. Hence $\mathcal{F}$ has property $\mathcal{P}$ by (1), a contradiction.
Suppose $T$ is irreducible. Let $\mathcal{J}$ be the sheaf of ideals defining the reduced induced closed subspace structure on $T$, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. By Lemma Sheaves on ringed sites we see there exists an $n \geq 0$ such that $\mathcal{J}^n\mathcal{F} = 0$. Hence we obtain a filtration $$0 = \mathcal{J}^n\mathcal{F} \subset \mathcal{J}^{n - 1}\mathcal{F} \subset \ldots \subset \mathcal{J}\mathcal{F} \subset \mathcal{F}$$ each of whose successive subquotients is annihilated by $\mathcal{J}$. Hence if each of these subquotients has a filtration as in the statement of the lemma then also $\mathcal{F}$ does by (1). In other words we may assume that $\mathcal{J}$ does annihilate $\mathcal{F}$.
Assume $T$ is irreducible and $\mathcal{J}\mathcal{F} = 0$ where $\mathcal{J}$ is as above. Denote $i : Z \to X$ the closed subspace corresponding to $\mathcal{J}$. Then $\mathcal{F} = i_*\mathcal{H}$ for some coherent $\mathcal{O}_Z$-module $\mathcal{H}$, see Morphisms of Spaces, Lemma Groupoids and equivalence relations and Lemma Coherent sheaves and closed support. Let $\mathcal{G}$ be the coherent sheaf on $Z$ satisfying (3)(a) and (3)(b). We apply Lemma Filtering a coherent sheaf by irreducible supports to get injective maps $$\mathcal{I}_1^{\oplus r_1} \to \mathcal{H} \quad\text{and}\quad \mathcal{I}_2^{\oplus r_2} \to \mathcal{G}$$ where the support of the cokernels are proper closed in $Z$. Hence we find an nonempty open $V \subset Z$ such that $$\mathcal{H}^{\oplus r_2}_V \cong \mathcal{G}^{\oplus r_1}_V$$ Let $\mathcal{I} \subset \mathcal{O}_Z$ be a quasi-coherent ideal sheaf cutting out $Z \setminus V$ we obtain (Lemma Quasi-coherent cohomology) a map $$\mathcal{I}^n\mathcal{G}^{\oplus r_1} \longrightarrow \mathcal{H}^{\oplus r_2}$$ which is an isomorphism over $V$. The kernel is supported on $Z \setminus V$ hence annihilated by some power of $\mathcal{I}$, see Lemma Sheaves on ringed sites. Thus after increasing $n$ we may assume the displayed map is injective, see Lemma The Artin–Rees lemma. Applying (3)(b) we find $\mathcal{G}' \subset \mathcal{I}^n\mathcal{G}$ such that $$(i_*\mathcal{G}')^{\oplus r_1} \longrightarrow i_*\mathcal{H}^{\oplus r_2} = \mathcal{F}^{\oplus r_2}$$ is injective with cokernel supported in a proper closed subset of $Z$ and such that property $\mathcal{P}$ holds for $i_*\mathcal{G}'$. By (1) property $\mathcal{P}$ holds for $(i_*\mathcal{G}')^{\oplus r_1}$. By (1) and minimality of $T = |Z|$ property $\mathcal{P}$ holds for $\mathcal{F}^{\oplus r_2}$. And finally by (2) property $\mathcal{P}$ holds for $\mathcal{F}$ which is the desired contradiction. $\square$
Lemma. Noetherian rings and finite algebras
Let $S$ be a scheme. Let $f : Y \to X$ be a morphism of algebraic spaces over $S$. Assume $f$ is finite, surjective and $X$ locally Noetherian. Let $i : Z \to X$ be a closed immersion. Denote $i' : Z' \to Y$ the inverse image of $Z$ (Morphisms of Spaces, Section Diagonals and separation) and $f' : Z' \to Z$ the induced morphism. Then $\mathcal{G} = f'_*\mathcal{O}_{Z'}$ is a coherent $\mathcal{O}_Z$-module whose support is $Z$.
Proof. Observe that $f'$ is the base change of $f$ and hence is finite and surjective by Morphisms of Spaces, Lemmas Base change for morphisms of algebraic spaces and Base change for integral extensions. Note that $Y$, $Z$, and $Z'$ are locally Noetherian by Morphisms of Spaces, Lemma Noetherian rings and finite algebras (and the fact that closed immersions and finite morphisms are of finite type). By Lemma Coherent sheaves and finite algebras we see that $\mathcal{G}$ is a coherent $\mathcal{O}_Z$-module. The support of $\mathcal{G}$ is closed in $|Z|$, see Morphisms of Spaces, Lemma Closed support and finite algebras. Hence if the support of $\mathcal{G}$ is not equal to $|Z|$, then after replacing $X$ by an open subspace we may assume $\mathcal{G} = 0$ but $Z \not = \emptyset$. This would mean that $f'_*\mathcal{O}_{Z'} = 0$. In particular the section $1 \in \Gamma(Z', \mathcal{O}_{Z'}) = \Gamma(Z, f'_*\mathcal{O}_{Z'})$ would be zero which would imply $Z' = \emptyset$ is the empty algebraic space. This is impossible as $Z' \to Z$ is surjective. $\square$
Lemma. Affine neighbourhoods
Let $S$ be a scheme. Let $f : Y \to X$ be a morphism of algebraic spaces over $S$. Let $\mathcal{F}$ be a quasi-coherent sheaf on $Y$. Let $\mathcal{I}$ be a quasi-coherent sheaf of ideals on $X$. If $f$ is affine then $\mathcal{I}f_*\mathcal{F} = f_*(f^{-1}\mathcal{I}\mathcal{F})$ (with notation as explained in the proof).
Proof. The notation means the following. Since $f^{-1}$ is an exact functor we see that $f^{-1}\mathcal{I}$ is a sheaf of ideals of $f^{-1}\mathcal{O}_X$. Via the map $f^\sharp : f^{-1}\mathcal{O}_X \to \mathcal{O}_Y$ on $Y_\mathrm{\acute{e}tale}$ this acts on $\mathcal{F}$. Then $f^{-1}\mathcal{I}\mathcal{F}$ is the subsheaf generated by sums of local sections of the form $as$ where $a$ is a local section of $f^{-1}\mathcal{I}$ and $s$ is a local section of $\mathcal{F}$. It is a quasi-coherent $\mathcal{O}_Y$-submodule of $\mathcal{F}$ because it is also the image of a natural map $f^*\mathcal{I} \otimes_{\mathcal{O}_Y} \mathcal{F} \to \mathcal{F}$.
Having said this the proof is straightforward. Namely, the question is étale local on $X$ and hence we may assume $X$ is an affine scheme. In this case the result is a consequence of the corresponding result for schemes, see Cohomology of Schemes, Lemma Affine neighbourhoods (uncovered prerequisite). $\square$
Lemma. Base change for sheaf cohomology and flatness (Flat base change)
Let $S$ be a scheme. Consider a cartesian diagram of algebraic spaces $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{f'} Y' \\ X' & \xrightarrow{g'} X \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module with pullback $\mathcal{F}' = (g')^*\mathcal{F}$. Assume that $g$ is flat and that $f$ is quasi-compact and quasi-separated. For any $i \geq 0$
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the base change map of Cohomology on Sites, Lemma Base change for flatness (uncovered prerequisite) is an isomorphism $$g^*R^if_*\mathcal{F} \longrightarrow R^if'_*\mathcal{F}',$$
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if $Y = \operatorname{Spec}(A)$ and $Y' = \operatorname{Spec}(B)$, then $H^i(X, \mathcal{F}) \otimes_A B = H^i(X', \mathcal{F}')$.
Proof. The morphism $g'$ is flat by Morphisms of Spaces, Lemma Base change for flatness. Note that flatness of $g$ and $g'$ is equivalent to flatness of the morphisms of small étale ringed sites, see Morphisms of Spaces, Lemma Flatness and sheaves on ringed sites (uncovered prerequisite). Hence we can apply Cohomology on Sites, Lemma Base change for flatness (uncovered prerequisite) to obtain a base change map $$g^*R^pf_*\mathcal{F} \longrightarrow R^pf'_*\mathcal{F}'$$ To prove this map is an isomorphism we can work locally in the étale topology on $Y'$. Thus we may assume that $Y$ and $Y'$ are affine schemes. Say $Y = \operatorname{Spec}(A)$ and $Y' = \operatorname{Spec}(B)$. In this case we are really trying to show that the map $$H^p(X, \mathcal{F}) \otimes_A B \longrightarrow H^p(X_B, \mathcal{F}_B)$$ is an isomorphism where $X_B = \operatorname{Spec}(B) \times_{\operatorname{Spec}(A)} X$ and $\mathcal{F}_B$ is the pullback of $\mathcal{F}$ to $X_B$. In other words, it suffices to prove (2).
Fix $A \to B$ a flat ring map and let $X$ be a quasi-compact and quasi-separated algebraic space over $A$. Note that $g' : X_B \to X$ is affine as a base change of $\operatorname{Spec}(B) \to \operatorname{Spec}(A)$. Hence the higher direct images $R^i(g')_*\mathcal{F}_B$ are zero by Lemma Affine neighbourhoods. Thus $H^p(X_B, \mathcal{F}_B) = H^p(X, g'_*\mathcal{F}_B)$, see Cohomology on Sites, Lemma Acyclicity and the Leray spectral sequence. Moreover, we have $$g'_*\mathcal{F}_B = \mathcal{F} \otimes_{\underline{A}} \underline{B}$$ where $\underline{A}$, $\underline{B}$ denotes the constant sheaf of rings with value $A$, $B$. Namely, it is clear that there is a map from right to left. For any affine scheme $U$ étale over $X$ we have $$\begin{aligned} g'_*\mathcal{F}_B(U) & = \mathcal{F}_B(\operatorname{Spec}(B) \times_{\operatorname{Spec}(A)} U) \\ & = \Gamma(\operatorname{Spec}(B) \times_{\operatorname{Spec}(A)} U, (\operatorname{Spec}(B) \times_{\operatorname{Spec}(A)} U \to U)^*\mathcal{F}|_U) \\ & = B \otimes_A \mathcal{F}(U) \end{aligned}$$ hence the map is an isomorphism. Write $B = \mathop{\operatorname{colim}} M_i$ as a filtered colimit of finite free $A$-modules $M_i$ using Lazard's theorem, see Algebra, Theorem Commutative algebra (uncovered prerequisite). We deduce that $$\begin{aligned} H^p(X, g'_*\mathcal{F}_B) & = H^p(X, \mathcal{F} \otimes_{\underline{A}} \underline{B}) \\ & = H^p(X, \mathop{\operatorname{colim}}_i \mathcal{F} \otimes_{\underline{A}} \underline{M_i}) \\ & = \mathop{\operatorname{colim}}_i H^p(X, \mathcal{F} \otimes_{\underline{A}} \underline{M_i}) \\ & = \mathop{\operatorname{colim}}_i H^p(X, \mathcal{F}) \otimes_A M_i \\ & = H^p(X, \mathcal{F}) \otimes_A \mathop{\operatorname{colim}}_i M_i \\ & = H^p(X, \mathcal{F}) \otimes_A B \end{aligned}$$ The first equality because $g'_*\mathcal{F}_B = \mathcal{F} \otimes_{\underline{A}} \underline{B}$ as seen above. The second because $\otimes$ commutes with colimits. The third equality because cohomology on $X$ commutes with colimits (see Lemma Filtered limits and quasi-coherent cohomology). The fourth equality because $M_i$ is finite free (i.e., because cohomology commutes with finite direct sums). The fifth because $\otimes$ commutes with colimits. The sixth by choice of our system. $\square$
Lemma. Quasi-coherent cohomology
Let $S$ be a scheme. Let $f : U \to X$ be a surjective, étale, and separated morphism of algebraic spaces over $S$. For $p \geq 0$ set $$W_p = U \times_X \ldots \times_X U \setminus \text{all diagonals}$$ (with $p + 1$ factors) as in Lemma Computation of quasi-coherent cohomology. Let $\chi_p : S_{p + 1} \to \{+1, -1\}$ be the sign character. Let $U_p = W_p/S_{p + 1}$ and $\underline{\mathbf{Z}}(\chi_p)$ be as in Lemma Twisting a cohomological comparison. Then the spectral sequence of Lemma Sheaf cohomology has $E_1$-page $$E_1^{p, q} = H^q(U_p, \mathcal{F}|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p))$$ and converges to $H^{p + q}(X, \mathcal{F})$.
Proof. Note that since the action of $S_{p + 1}$ on $W_p$ is over $X$ we do obtain a morphism $U_p \to X$. Since $W_p \to X$ is étale and since $W_p \to U_p$ is surjective étale, it follows that also $U_p \to X$ is étale, see Morphisms of Spaces, Lemma Étale morphisms and local algebra (uncovered prerequisite). Therefore an injective object of $\textit{Ab}(X_\mathrm{\acute{e}tale})$ restricts to an injective object of $\textit{Ab}(U_{p, \mathrm{\acute{e}tale}})$, see Cohomology on Sites, Lemma Sheaf cohomology (uncovered prerequisite). Moreover, the functor $\mathcal{G} \mapsto \mathcal{G} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p)$ is an auto-equivalence of $\textit{Ab}(U_{p, \mathrm{\acute{e}tale}})$, whence transforms injective objects into injective objects and is exact (because $\underline{\mathbf{Z}}(\chi_p)$ is an invertible $\underline{\mathbf{Z}}$-module). Thus given an injective resolution $\mathcal{F} \to \mathcal{I}^\bullet$ in $\textit{Ab}(X_\mathrm{\acute{e}tale})$ the complex $$\Gamma(U_p, \mathcal{I}^0|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p)) \to \Gamma(U_p, \mathcal{I}^1|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p)) \to \Gamma(U_p, \mathcal{I}^2|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p)) \to \ldots$$ computes $H^*(U_p, \mathcal{F}|_{U_p} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi_p))$. On the other hand, by Lemma Twisting a cohomological comparison it is equal to the complex of $S_{p + 1}$-anti-invariants in $$\Gamma(W_p, \mathcal{I}^0) \to \Gamma(W_p, \mathcal{I}^1) \to \Gamma(W_p, \mathcal{I}^2) \to \ldots$$ which by Lemma Computation of quasi-coherent cohomology is equal to the complex $$\operatorname{Hom}(K^p, \mathcal{I}^0) \to \operatorname{Hom}(K^p, \mathcal{I}^1) \to \operatorname{Hom}(K^p, \mathcal{I}^2) \to \ldots$$ which computes $\operatorname{Ext}^*_{\textit{Ab}(X_\mathrm{\acute{e}tale})}(K^p, \mathcal{F})$. Putting everything together we win. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
With $S$, $W$, $G$, $U$, $\chi$ as in Lemma Twisting a cohomological comparison. If $\mathcal{F}$ is a quasi-coherent $\mathcal{O}_U$-module, then so is $\mathcal{F} \otimes_{\mathbf{Z}} \underline{\mathbf{Z}}(\chi)$.
Proof. The $\mathcal{O}_U$-module structure is clear. To check that $\mathcal{F} \otimes_{\mathbf{Z}} \underline{\mathbf{Z}}(\chi)$ is quasi-coherent it suffices to check étale locally. Hence the lemma follows as $\underline{\mathbf{Z}}(\chi)$ is finite locally free as a $\underline{\mathbf{Z}}$-module. $\square$
Lemma. Base change for affine neighbourhoods
Let $S$ be a scheme. Let $f : X \to Y$ be an affine morphism of algebraic spaces over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. In this case $f_*\mathcal{F} \cong Rf_*\mathcal{F}$ is a quasi-coherent sheaf, and for every diagram (Base change for quasi-coherent cohomology) we have $$g^*f_*\mathcal{F} = f'_*(g')^*\mathcal{F}.$$
Proof. By the discussion surrounding (Quasi-coherent cohomology) this reduces to the case of an affine morphism of schemes which is treated in Cohomology of Schemes, Lemma Base change for affine neighbourhoods (uncovered prerequisite). $\square$
Situation. Vanishing and quasi-coherent cohomology
Here $S$ is a scheme and $X$ is a quasi-compact and quasi-separated algebraic space over $S$ with the following property: For every quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ we have $H^1(X, \mathcal{F}) = 0$. We set $A = \Gamma(X, \mathcal{O}_X)$.
Lemma. Vanishing and diagonals and separation
In Situation Vanishing and quasi-coherent cohomology the morphism $p : X \to \operatorname{Spec}(A)$ is separated.
Proof. By Decent Spaces, Lemma Integral extensions we can find a scheme $Y$ and a surjective integral morphism $Y \to X$. Since an integral morphism is affine, we can apply Lemma Base change for quasi-coherent cohomology to see that $H^1(Y, \mathcal{G}) = 0$ for every quasi-coherent $\mathcal{O}_Y$-module $\mathcal{G}$. Since $Y \to X$ is quasi-compact and $X$ is quasi-compact, we see that $Y$ is quasi-compact. Since $Y$ is a scheme, we may apply Cohomology of Schemes, Lemma The geometric construction (uncovered prerequisite) to see that $Y$ is affine. Hence $Y$ is separated. Note that an integral morphism is affine and universally closed, see Morphisms of Spaces, Lemma Integral extensions (uncovered prerequisite). By Morphisms of Spaces, Lemma Diagonals and separation (uncovered prerequisite) we see that $X$ is a separated algebraic space. $\square$
Lemma. Vanishing and injective resolutions
In Situation Vanishing and quasi-coherent cohomology the morphism $p : X \to \operatorname{Spec}(A)$ is universally injective.
Proof. Let $A \to k$ be a ring homomorphism where $k$ is a field. It suffices to show that $\operatorname{Spec}(k) \times_{\operatorname{Spec}(A)} X$ has at most one point (see Morphisms of Spaces, Lemma Injective resolutions and local algebra (uncovered prerequisite)). Using Lemma Base change for quasi-coherent cohomology we may assume that $A$ is a field and we have to show that $|X|$ has at most one point.
Let's think of $X$ as an algebraic space over $\operatorname{Spec}(k)$ and let's use the notation $X(K)$ to denote $K$-valued points of $X$ for any extension $K/k$, see Morphisms of Spaces, Section Field extensions. If $K/k$ is an algebraically closed field extension of large transcendence degree, then we see that $X(K) \to |X|$ is surjective, see Morphisms of Spaces, Lemma Morphisms of algebraic spaces (uncovered prerequisite). Hence, after replacing $k$ by $K$, we see that it suffices to prove that $X(k)$ is a singleton (in the case $A = k)$.
Let $x, x' \in X(k)$. By Decent Spaces, Lemma Field extensions (uncovered prerequisite) we see that $x$ and $x'$ are closed points of $|X|$. Hence $x$ and $x'$ map to distinct points of $\operatorname{Spec}(k)$ if $x \not = x'$ by Lemma Vanishing and quasi-coherent cohomology. We conclude that $x = x'$ as desired. $\square$
Lemma. The Artin--Rees lemma (Artin-Rees)
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $\mathcal{F}$ be a coherent sheaf on $X$. Let $\mathcal{G} \subset \mathcal{F}$ be a quasi-coherent subsheaf. Let $\mathcal{I} \subset \mathcal{O}_X$ be a quasi-coherent sheaf of ideals. Then there exists a $c \geq 0$ such that for all $n \geq c$ we have $$\mathcal{I}^{n - c}(\mathcal{I}^c\mathcal{F} \cap \mathcal{G})
\mathcal{I}^n\mathcal{F} \cap \mathcal{G}$$
Proof. Choose an affine scheme $U$ and a surjective étale morphism $U \to X$ (see Properties of Spaces, Lemma Affine neighbourhoods). Then $U$ is a Noetherian scheme (by Morphisms of Spaces, Lemma Noetherian rings and finite algebras). The equality of the lemma holds if and only if it holds after restricting to $U$. Hence the result follows from the case of schemes, see Cohomology of Schemes, Lemma The Artin–Rees lemma (uncovered prerequisite). $\square$
Lemma. Computation of quasi-coherent cohomology
Let $S$ be a scheme. Let $f : U \to X$ be a surjective, étale, and separated morphism of algebraic spaces over $S$. For $p \geq 0$ set $$W_p = U \times_X \ldots \times_X U \setminus \text{all diagonals}$$ where the fibre product has $p + 1$ factors. There is a free action of $S_{p + 1}$ on $W_p$ over $X$ and $$\operatorname{Hom}(K^p, \mathcal{F}) = S_{p + 1}\text{-anti-invariant elements of } \mathcal{F}(W_p)$$ functorially in $\mathcal{F}$ where $K^p = \wedge^{p + 1}f_!\underline{\mathbf{Z}}$.
Proof. Because $U \to X$ is separated the diagonal $U \to U \times_X U$ is a closed immersion. Since $U \to X$ is étale the diagonal $U \to U \times_X U$ is an open immersion, see Morphisms of Spaces, Lemmas Étale morphisms and unramified morphisms and Unramified morphisms and diagonals and separation. Hence $W_p$ is an open and closed subspace of $U^{p + 1} = U \times_X \ldots \times_X U$. The action of $S_{p + 1}$ on $W_p$ is free as we've thrown out the fixed points of the action. By Lemma Tensor products and direct sums we see that $$(f_!\underline{\mathbf{Z}})^{\otimes p + 1} = f^{p + 1}_!\underline{\mathbf{Z}} = (W_p \to X)_!\underline{\mathbf{Z}} \oplus Rest$$ where $f^{p + 1} : U^{p + 1} \to X$ is the structure morphism. Looking at stalks over a geometric point $\overline{x}$ of $X$ we see that $$\left( \bigoplus\nolimits_{\overline{u} \mapsto \overline{x}} \mathbf{Z} \right)^{\otimes p + 1} \longrightarrow (W_p \to X)_!\underline{\mathbf{Z}}_{\overline{x}}$$ is the quotient whose kernel is generated by all tensors $1_{\overline{u}_0} \otimes \ldots \otimes 1_{\overline{u}_p}$ where $\overline{u}_i = \overline{u}_j$ for some $i \not = j$. Thus the quotient map $$(f_!\underline{\mathbf{Z}})^{\otimes p + 1} \longrightarrow \wedge^{p + 1}f_!\underline{\mathbf{Z}}$$ factors through $(W_p \to X)_!\underline{\mathbf{Z}}$, i.e., we get $$(f_!\underline{\mathbf{Z}})^{\otimes p + 1} \longrightarrow (W_p \to X)_!\underline{\mathbf{Z}} \longrightarrow \wedge^{p + 1}f_!\underline{\mathbf{Z}}$$ This already proves that $\operatorname{Hom}(K^p, \mathcal{F})$ is (functorially) a subgroup of $$\operatorname{Hom}((W_p \to X)_!\underline{\mathbf{Z}}, \mathcal{F}) = \mathcal{F}(W_p)$$ To identify it with the $S_{p + 1}$-anti-invariants we have to prove that the surjection $(W_p \to X)_!\underline{\mathbf{Z}} \to \wedge^{p + 1}f_!\underline{\mathbf{Z}}$ is the maximal $S_{p + 1}$-anti-invariant quotient. In other words, we have to show that $\wedge^{p + 1}f_!\underline{\mathbf{Z}}$ is the quotient of $(W_p \to X)_!\underline{\mathbf{Z}}$ by the subsheaf generated by the local sections $s - \text{sign}(\sigma)\sigma(s)$ where $s$ is a local section of $(W_p \to X)_!\underline{\mathbf{Z}}$. This can be checked on the stalks, where it is clear. $\square$
Lemma. Twisting a cohomological comparison
Let $S$ be a scheme. Let $W$ be an algebraic space over $S$. Let $G$ be a finite group acting freely on $W$. Let $U = W/G$, see Properties of Spaces, Lemma Étale geometry of algebraic spaces (uncovered prerequisite). Let $\chi : G \to \{+1, -1\}$ be a character. Then there exists a rank 1 locally free sheaf of $\mathbf{Z}$-modules $\underline{\mathbf{Z}}(\chi)$ on $U_\mathrm{\acute{e}tale}$ such that for every abelian sheaf $\mathcal{F}$ on $U_\mathrm{\acute{e}tale}$ we have $$H^0(W, \mathcal{F}|_W)^\chi = H^0(U, \mathcal{F} \otimes_{\mathbf{Z}} \underline{\mathbf{Z}}(\chi))$$
Proof. The quotient morphism $q : W \to U$ is a $G$-torsor, i.e., there exists a surjective étale morphism $U' \to U$ such that $W \times_U U' = \coprod_{g \in G} U'$ as spaces with $G$-action over $U'$. (Namely, $U' = W$ works.) Hence $q_*\underline{\mathbf{Z}}$ is a finite locally free $\mathbf{Z}$-module with an action of $G$. For any geometric point $\overline{u}$ of $U$, then we get $G$-equivariant isomorphisms $$(q_*\underline{\mathbf{Z}})_{\overline{u}} = \bigoplus\nolimits_{\overline{w} \mapsto \overline{u}} \mathbf{Z} = \bigoplus\nolimits_{g \in G} \mathbf{Z} = \mathbf{Z}[G]$$ where the second $=$ uses a geometric point $\overline{w}_0$ lying over $\overline{u}$ and maps the summand corresponding to $g \in G$ to the summand corresponding to $g(\overline{w}_0)$. We have $$H^0(W, \mathcal{F}|_W) = H^0(U, \mathcal{F} \otimes_\mathbf{Z} q_*\underline{\mathbf{Z}})$$ because $q_*\mathcal{F}|_W = \mathcal{F} \otimes_\mathbf{Z} q_*\underline{\mathbf{Z}}$ as one can check by restricting to $U'$. Let $$\underline{\mathbf{Z}}(\chi) = (q_*\underline{\mathbf{Z}})^\chi \subset q_*\underline{\mathbf{Z}}$$ be the subsheaf of sections that transform according to $\chi$. For any geometric point $\overline{u}$ of $U$ we have $$\underline{\mathbf{Z}}(\chi)_{\overline{u}} = \mathbf{Z} \cdot \sum\nolimits_g \chi(g) g \subset \mathbf{Z}[G] = (q_*\underline{\mathbf{Z}})_{\overline{u}}$$ It follows that $\underline{\mathbf{Z}}(\chi)$ is locally free of rank 1 (more precisely, this should be checked after restricting to $U'$). Note that for any $\mathbf{Z}$-module $M$ the $\chi$-semi-invariants of $M[G]$ are the elements of the form $m \cdot \sum\nolimits_g \chi(g) g$. Thus we see that for any abelian sheaf $\mathcal{F}$ on $U$ we have $$\left(\mathcal{F} \otimes_\mathbf{Z} q_*\underline{\mathbf{Z}}\right)^\chi
\mathcal{F} \otimes_\mathbf{Z} \underline{\mathbf{Z}}(\chi)$$ because we have equality at all stalks. The result of the lemma follows by taking global sections. $\square$
Lemma. Sheaf cohomology
Let $S$ be a scheme. Let $f : U \to X$ be a surjective étale morphism of algebraic spaces over $S$. Let $\mathcal{F}$ be an object of $\textit{Ab}(X_\mathrm{\acute{e}tale})$. There exists a canonical map $$\check{\mathcal{C}}^\bullet_{alt}(f, \mathcal{F}) \longrightarrow R\Gamma(X, \mathcal{F})$$ in $D(\textit{Ab})$. Moreover, there is a spectral sequence with $E_1$-page $$E_1^{p, q} = \operatorname{Ext}_{\textit{Ab}(X_\mathrm{\acute{e}tale})}^q(K^p, \mathcal{F})$$ converging to $H^{p + q}(X, \mathcal{F})$ where $K^p = \wedge^{p + 1}f_!\underline{\mathbf{Z}}$.
Proof. Recall that we have the quasi-isomorphism $K^\bullet \to \underline{\mathbf{Z}}[0]$, see (Quasi-coherent cohomology). Choose an injective resolution $\mathcal{F} \to \mathcal{I}^\bullet$ in $\textit{Ab}(X_\mathrm{\acute{e}tale})$. Consider the double complex $\operatorname{Hom}(K^\bullet, \mathcal{I}^\bullet)$ with terms $\operatorname{Hom}(K^p, \mathcal{I}^q)$. The differential $d_1^{p, q} : A^{p, q} \to A^{p + 1, q}$ is the one coming from the differential $K^{p + 1} \to K^p$ and the differential $d_2^{p, q} : A^{p, q} \to A^{p, q + 1}$ is the one coming from the differential $\mathcal{I}^q \to \mathcal{I}^{q + 1}$. Denote $\text{Tot}(\operatorname{Hom}(K^\bullet, \mathcal{I}^\bullet))$ the associated total complex, see Homology, Section Derived categories. We will use the two spectral sequences $({}'E_r, {}'d_r)$ and $({}''E_r, {}''d_r)$ associated to this double complex, see Homology, Section Derived categories.
Because $K^\bullet$ is a resolution of $\underline{\mathbf{Z}}$ we see that the complexes $$\operatorname{Hom}(K^\bullet, \mathcal{I}^q) : \operatorname{Hom}(K^0, \mathcal{I}^q) \to \operatorname{Hom}(K^1, \mathcal{I}^q) \to \operatorname{Hom}(K^2, \mathcal{I}^q) \to \ldots$$ are acyclic in positive degrees and have $H^0$ equal to $\Gamma(X, \mathcal{I}^q)$. Hence by Homology, Lemma Derived categories (uncovered prerequisite) the natural map $$\mathcal{I}^\bullet(X) \longrightarrow \text{Tot}(\operatorname{Hom}(K^\bullet, \mathcal{I}^\bullet))$$ is a quasi-isomorphism of complexes of abelian groups. In particular we conclude that $H^n(\text{Tot}(\operatorname{Hom}(K^\bullet, \mathcal{I}^\bullet))) = H^n(X, \mathcal{F})$.
The map $\check{\mathcal{C}}^\bullet_{alt}(f, \mathcal{F}) \to R\Gamma(X, \mathcal{F})$ of the lemma is the composition of $\check{\mathcal{C}}^\bullet_{alt}(f, \mathcal{F}) \to \text{Tot}(\operatorname{Hom}(K^\bullet, \mathcal{I}^\bullet))$ with the inverse of the displayed quasi-isomorphism.
Finally, consider the spectral sequence $({}'E_r, {}'d_r)$. We have $$E_1^{p, q} = q\text{th cohomology of } \operatorname{Hom}(K^p, \mathcal{I}^0) \to \operatorname{Hom}(K^p, \mathcal{I}^1) \to \operatorname{Hom}(K^p, \mathcal{I}^2) \to \ldots$$ This proves the lemma. $\square$
Lemma. Base change for quasi-coherent cohomology
In Situation Vanishing and quasi-coherent cohomology.
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Given an affine morphism $X' \to X$ of algebraic spaces, we have $H^1(X', \mathcal{F}') = 0$ for every quasi-coherent $\mathcal{O}_{X'}$-module $\mathcal{F}'$.
-
Given an $A$-algebra $A'$ setting $X' = X \times_{\operatorname{Spec}(A)} \operatorname{Spec}(A')$ the morphism $X' \to X$ is affine and $\Gamma(X', \mathcal{O}_{X'}) = A'$.
Proof. Part (1) follows from Lemma Affine neighbourhoods and the Leray spectral sequence (Cohomology on Sites, Lemma The Leray spectral sequence). Let $A \to A'$ be as in (2). Then $X' \to X$ is affine because affine morphisms are preserved under base change (Morphisms of Spaces, Lemma Base change for affine neighbourhoods) and the fact that a morphism of affine schemes is affine. The equality $\Gamma(X', \mathcal{O}_{X'}) = A'$ follows as $(X' \to X)_*\mathcal{O}_{X'} = A' \otimes_A \mathcal{O}_X$ by Lemma Base change for affine neighbourhoods and thus $$\Gamma(X', \mathcal{O}_{X'}) = \Gamma(X, (X' \to X)_*\mathcal{O}_{X'}) = \Gamma(X, A' \otimes_A \mathcal{O}_X) = A'$$ by Lemma Computation of a cohomological vanishing condition. $\square$
Lemma. Vanishing and quasi-coherent cohomology
In Situation Vanishing and quasi-coherent cohomology. Let $Z_0, Z_1 \subset |X|$ be disjoint closed subsets. Then there exists an $a \in A$ such that $Z_0 \subset V(a)$ and $Z_1 \subset V(a - 1)$.
Proof. We may and do endow $Z_0$, $Z_1$ with the reduced induced subspace structure (Properties of Spaces, Definition Étale geometry of algebraic spaces) and we denote $i_0 : Z_0 \to X$ and $i_1 : Z_1 \to X$ the corresponding closed immersions. Since $Z_0 \cap Z_1 = \emptyset$ we see that the canonical map of quasi-coherent $\mathcal{O}_X$-modules $$\mathcal{O}_X \longrightarrow i_{0, *}\mathcal{O}_{Z_0} \oplus i_{1, *}\mathcal{O}_{Z_1}$$ is surjective (look at stalks at geometric points). Since $H^1(X, -)$ is zero on the kernel of this map the induced map of global sections is surjective. Thus we can find $a \in A$ which maps to the global section $(0, 1)$ of the right hand side. $\square$
Lemma. Tensor products and direct sums
Let $S$ be a scheme. Let $f_i : U_i \to X$ be étale morphisms of algebraic spaces over $S$. Then there are isomorphisms $$f_{1, !}\underline{\mathbf{Z}} \otimes_{\mathbf{Z}} f_{2, !}\underline{\mathbf{Z}} \longrightarrow f_{12, !}\underline{\mathbf{Z}}$$ where $f_{12} : U_1 \times_X U_2 \to X$ is the structure morphism and $$(f_1 \amalg f_2)_! \underline{\mathbf{Z}} \longrightarrow f_{1, !}\underline{\mathbf{Z}} \oplus f_{2, !}\underline{\mathbf{Z}}$$
Proof. Once we have defined the map it will be an isomorphism by our description of stalks above. To define the map it suffices to work on the level of presheaves. Thus we have to define a map $$\left(\bigoplus\nolimits_{\varphi_1 \in \operatorname{Mor}_X(V, U_1)} \mathbf{Z}\right) \otimes_{\mathbf{Z}} \left(\bigoplus\nolimits_{\varphi_2 \in \operatorname{Mor}_X(V, U_2)} \mathbf{Z}\right) \longrightarrow \bigoplus\nolimits_{\varphi \in \operatorname{Mor}_X(V, U_1 \times_X U_2)} \mathbf{Z}$$ We map the element $1_{\varphi_1} \otimes 1_{\varphi_2}$ to the element $1_{\varphi_1 \times \varphi_2}$ with obvious notation. We omit the proof of the second equality. $\square$
Lemma. Computation of a cohomological vanishing condition
In Situation Vanishing and quasi-coherent cohomology for an $A$-module $M$ we have $p_*(M \otimes_A \mathcal{O}_X) = \widetilde{M}$ and $\Gamma(X, M \otimes_A \mathcal{O}_X) = M$.
Proof. The equality $p_*(M \otimes_A \mathcal{O}_X) = \widetilde{M}$ follows from the equality $\Gamma(X, M \otimes_A \mathcal{O}_X) = M$ as $p_*(M \otimes_A \mathcal{O}_X)$ is a quasi-coherent module on $\operatorname{Spec}(A)$ by Morphisms of Spaces, Lemma Direct images and morphisms of algebraic spaces. Observe that $\Gamma(X, \bigoplus_{i \in I} \mathcal{O}_X) = \bigoplus_{i \in I} A$ by Lemma Filtered limits and quasi-coherent cohomology. Hence the lemma holds for free modules. Choose a short exact sequence $F_1 \to F_0 \to M$ where $F_0, F_1$ are free $A$-modules. Since $H^1(X, -)$ is zero the global sections functor is right exact. Moreover the pullback $p^*$ is right exact as well. Hence we see that $$\Gamma(X, F_1 \otimes_A \mathcal{O}_X) \to \Gamma(X, F_0 \otimes_A \mathcal{O}_X) \to \Gamma(X, M \otimes_A \mathcal{O}_X) \to 0$$ is exact. The result follows. $\square$
Quasi-coherent sheaves on algebraic spaces
Lemma. Base change for étale morphisms and modules
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ be a cartesian square of algebraic spaces over $S$. Let $\mathcal{F} \in \textit{Mod}(\mathcal{O}_X)$. If $g$ is étale, then $f'_*(\mathcal{F}|_{X'}) = (f_*\mathcal{F})|_{Y'}$[^1] and $R^if'_*(\mathcal{F}|_{X'}) = (R^if_*\mathcal{F})|_{Y'}$ in $\textit{Mod}(\mathcal{O}_{Y'})$.
Proof. This is a reformulation of Lemma Base change for étale morphisms in the case of modules. $\square$
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $X$ be a Zariski locally quasi-separated algebraic space over $S$. Then the topological space $|X|$ is sober (see Topology, Definition The geometric construction).
Proof. Combining Topology, Lemma Local algebra (uncovered prerequisite) and Lemma Diagonals and separation we see that we may assume that there exists an affine scheme $U$ and a surjective, quasi-compact, étale morphism $U \to X$. Set $R = U \times_X U$ with projection maps $s, t : R \to U$. Applying Lemma Finite algebras we see that the fibres of $s, t$ are finite. It follows all the assumptions of Topology, Lemma The geometric construction (uncovered prerequisite) are met, and we conclude that $|X|$ is Kolmogorov[^2].
It remains to show that every irreducible closed subset $T \subset |X|$ has a generic point. By Lemma Étale geometry of algebraic spaces there exists a closed subspace $Z \subset X$ with $|Z| = |T|$. Note that $U \times_X Z \to Z$ is a quasi-compact, surjective, étale morphism from an affine scheme to $Z$, hence $Z$ is Zariski locally quasi-separated by Lemma Diagonals and separation. By Proposition Diagonals, separation and local algebra we see that there exists an open dense subspace $Z' \subset Z$ which is a scheme. This means that $|Z'| \subset T$ is open dense. Hence the topological space $|Z'|$ is irreducible, which means that $Z'$ is an irreducible scheme. By Schemes, Lemma The geometric construction (uncovered prerequisite) we conclude that $|Z'|$ is the closure of a single point $\eta \in |Z'| \subset T$ and hence also $T = \overline{\{\eta\}}$, and we win. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $\mathcal{G}$ be a quasi-coherent $\mathcal{O}_Y$-module. Let $\overline{x}$ be a geometric point of $X$ and let $\overline{y} = f \circ \overline{x}$ be the image in $Y$. Then there is a canonical isomorphism $$(f^*\mathcal{G})_{\overline{x}} = \mathcal{G}_{\overline{y}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{X, \overline{x}}$$ of the stalk of the pullback with the tensor product of the stalk with the local ring of $X$ at $\overline{x}$.
Proof. Since $f^*\mathcal{G} = f_{small}^{-1}\mathcal{G} \otimes_{f_{small}^{-1}\mathcal{O}_Y} \mathcal{O}_X$ this follows from the description of stalks of pullbacks in Lemma Sheaves on ringed sites and the fact that taking stalks commutes with tensor products. A more direct way to see this is as follows. Choose a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{p} X \\ U & \xrightarrow{\alpha} V \\ V & \xrightarrow{q} Y \\ X & \xrightarrow{a} Y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes, and $p$ and $q$ are surjective étale. By Lemma Étale geometry of algebraic spaces we can choose a geometric point $\overline{u}$ of $U$ such that $\overline{x} = p \circ \overline{u}$. Set $\overline{v} = \alpha \circ \overline{u}$. Then we see that $$\begin{aligned} (f^*\mathcal{G})_{\overline{x}} & = (p^*f^*\mathcal{G})_u \otimes_{\mathcal{O}_{U, u}} \mathcal{O}_{X, \overline{x}} \\ & = (\alpha^*q^*\mathcal{G})_u \otimes_{\mathcal{O}_{U, u}} \mathcal{O}_{X, \overline{x}} \\ & = (q^*\mathcal{G})_v \otimes_{\mathcal{O}_{V, v}} \mathcal{O}_{U, u} \otimes_{\mathcal{O}_{U, u}} \mathcal{O}_{X, \overline{x}} \\ & = (q^*\mathcal{G})_v \otimes_{\mathcal{O}_{V, v}} \mathcal{O}_{X, \overline{x}} \\ & = (q^*\mathcal{G})_v \otimes_{\mathcal{O}_{V, v}} \mathcal{O}_{Y, \overline{y}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{X, \overline{x}} \\ & = \mathcal{G}_{\overline{y}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{X, \overline{x}} \end{aligned}$$ Here we have used Lemma Quasi-coherent complexes and coherent sheaves (twice) and the corresponding result for pullbacks of quasi-coherent sheaves on schemes, see Sheaves, Lemma Modules and sheaves on ringed sites (uncovered prerequisite). $\square$
Lemma. Étale morphisms and local algebra
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent:
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$f$ is étale,
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there exists a surjective étale morphism $\varphi : U \to X$, where $U$ is a scheme, such that the composition $f \circ \varphi$ is étale (as a morphism of algebraic spaces),
-
there exists a surjective étale morphism $\psi : V \to Y$, where $V$ is a scheme, such that the base change $V \times_Y X \to V$ is étale (as a morphism of algebraic spaces),
-
there exists a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U$, $V$ are schemes, the vertical arrows are étale, and the left vertical arrow is surjective such that the horizontal arrow is étale.
Proof. Let us prove that (4) implies (1). Assume a diagram as in (4) given. Let $W \to X$ be an étale morphism with $W$ a scheme. Then we see that $W \times_X U \to U$ is étale. Hence $W \times_X U \to V$ is étale as the composition of the étale morphisms of schemes $W \times_X U \to U$ and $U \to V$. Therefore $W \times_X U \to Y$ is étale by Lemma Étale morphisms (1). Since also the projection $W \times_X U \to W$ is surjective and étale, we conclude from Lemma Étale morphisms (3) that $W \to Y$ is étale.
Let us prove that (1) implies (4). Assume (1). Choose a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U \to X$ and $V \to Y$ are surjective and étale, see Spaces, Lemma Lifting the geometric construction (uncovered prerequisite). By assumption the morphism $U \to Y$ is étale, and hence $U \to V$ is étale by Lemma Étale morphisms (2).
We omit the proof that (2) and (3) are also equivalent to (1). $\square$
Definition. Dimension, codimension and local algebra
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $x \in |X|$ be a point. The dimension of the local ring of $X$ at $x$ is the element $d \in \{0, 1, 2, \ldots, \infty\}$ satisfying the equivalent conditions of Lemma Dimension, codimension and local algebra. In this case we will also say $x$ is a point of codimension $d$ on $X$.
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. The following are equivalent
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$X$ is Zariski locally quasi-separated over $S$,
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$X$ is Zariski locally quasi-separated,
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there exists a Zariski open covering $X = \bigcup X_i$ such that for each $i$ there exists an affine scheme $U_i$ and a quasi-compact surjective étale morphism $U_i \to X_i$, and
-
there exists a Zariski open covering $X = \bigcup X_i$ such that for each $i$ there exists an affine scheme $U_i$ which maps into an affine open of $S$ and a quasi-compact surjective étale morphism $U_i \to X_i$.
Proof. Assume $U_i \to X_i \subset X$ are as in (3). To prove (4) choose for each $i$ a finite affine open covering $U_i = U_{i1} \cup \ldots \cup U_{in_i}$ such that each $U_{ij}$ maps into an affine open of $S$. The compositions $U_{ij} \to U_i \to X_i$ are étale and quasi-compact (see Spaces, Lemma Composition and proper morphisms (uncovered prerequisite)). Let $X_{ij} \subset X_i$ be the open subspace corresponding to the image of $|U_{ij}| \to |X_i|$, see Lemma Étale morphisms (uncovered prerequisite). Note that $U_{ij} \to X_{ij}$ is quasi-compact as $X_{ij} \subset X_i$ is a monomorphism and as $U_{ij} \to X$ is quasi-compact. Then $X = \bigcup X_{ij}$ is a covering as in (4). The implication (4) $\Rightarrow$ (3) is immediate.
Assume (4). To show that $X$ is Zariski locally quasi-separated over $S$ it suffices to show that $X_i$ is quasi-separated over $S$. Hence we may assume there exists an affine scheme $U$ mapping into an affine open of $S$ and a quasi-compact surjective étale morphism $U \to X$. Consider the fibre product square $$\begin{gathered}\begin{matrix}U \times_X U & U \times_S U \\ X & X \times_S X\end{matrix} \\[6pt] \begin{aligned}U \times_X U & \longrightarrow U \times_S U \\ U \times_X U & \longrightarrow X \\ U \times_S U & \longrightarrow X \times_S X \\ X & \xrightarrow{\Delta_{X/S}} X \times_S X\end{aligned}\end{gathered}$$ The right vertical arrow is surjective étale (see Spaces, Lemma Proper morphisms and tensor products and direct sums (uncovered prerequisite)) and $U \times_S U$ is affine (as $U$ maps into an affine open of $S$, see Schemes, Section Tensor products and direct sums), and $U \times_X U$ is quasi-compact because the projection $U \times_X U \to U$ is quasi-compact as a base change of $U \to X$. It follows from Spaces, Lemma Proper morphisms (uncovered prerequisite) that $\Delta_{X/S}$ is quasi-compact as desired.
Assume (1). To prove (3) there is an immediate reduction to the case where $X$ is quasi-separated over $S$. By Lemma Étale geometry of algebraic spaces we can find a Zariski open covering $X = \bigcup X_i$ such that each $X_i$ maps into an affine open of $S$, and such that there exist affine schemes $U_i$ and surjective étale morphisms $U_i \to X_i$. Since $U_i \to S$ maps into an affine open of $S$ we see that $U_i \times_S U_i$ is affine, see Schemes, Section Tensor products and direct sums. As $X$ is quasi-separated over $S$, the morphisms $$R_i = U_i \times_{X_i} U_i = U_i \times_X U_i \longrightarrow U_i \times_S U_i$$ as base changes of $\Delta_{X/S}$ are quasi-compact. Hence we conclude that $R_i$ is a quasi-compact scheme. This in turn implies that each projection $R_i \to U_i$ is quasi-compact. Hence, applying Spaces, Lemma Proper morphisms (uncovered prerequisite) to the covering $U_i \to X_i$ and the morphism $U_i \to X_i$ we conclude that the morphisms $U_i \to X_i$ are quasi-compact as desired.
At this point we see that (1), (3), and (4) are equivalent. Since (3) does not refer to the base scheme we conclude that these are also equivalent with (2). $\square$
Definition. Étale geometry of algebraic spaces
Let $S$ be a scheme, and let $X$ be an algebraic space over $S$. Let $Z \subset |X|$ be a closed subset. An algebraic space structure on $Z$ is given by a closed subspace $Z'$ of $X$ with $|Z'|$ equal to $Z$. The reduced induced algebraic space structure on $Z$ is the one constructed in Lemma Étale geometry of algebraic spaces. The reduction $X_{red}$ of $X$ is the reduced induced algebraic space structure on $|X|$.
Lemma. Étale morphisms
Let $S$ be a scheme. Let $X, Y, Z$ be algebraic spaces. Let $g : X \to Z$, $h : Y \to Z$ be étale morphisms and let $f : X \to Y$ be a morphism such that $h \circ f = g$. Then $f$ is étale.
Proof. Choose a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \xrightarrow{\chi} V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U \to X$ and $V \to Y$ are surjective and étale, see Spaces, Lemma Lifting the geometric construction (uncovered prerequisite). By assumption the morphisms $\varphi : U \to X \to Z$ and $\psi : V \to Y \to Z$ are étale. Moreover, $\psi \circ \chi = \varphi$ by our assumption on $f, g, h$. Hence $U \to V$ is étale by Lemma Étale morphisms part (2). $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $X$, $Y$ be algebraic spaces over $S$. Let $Z \subset X$ be a closed subspace. Assume $Y$ is reduced. A morphism $f : Y \to X$ factors through $Z$ if and only if $f(|Y|) \subset |Z|$.
Proof. Assume $f(|Y|) \subset |Z|$. Choose a diagram $$\begin{gathered}\begin{matrix}V & U \\ Y & X\end{matrix} \\[6pt] \begin{aligned}V & \xrightarrow{b} Y \\ V & \xrightarrow{h} U \\ U & \xrightarrow{a} X \\ Y & \xrightarrow{f} X\end{aligned}\end{gathered}$$ where $U$, $V$ are schemes, and the vertical arrows are surjective and étale. The scheme $V$ is reduced, see Lemma Proper morphisms (uncovered prerequisite). Hence $h$ factors through $a^{-1}(Z)$ by Schemes, Lemma The geometric construction (uncovered prerequisite). So $a \circ h$ factors through $Z$. As $Z \subset X$ is a subsheaf, and $V \to Y$ is a surjection of sheaves on $(\mathrm{Sch}/S)_{fppf}$ we conclude that $X \to Y$ factors through $Z$. $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}Z \times_Y X & X \\ Z & Y\end{matrix} \\[6pt] \begin{aligned}Z \times_Y X & \longrightarrow X \\ Z \times_Y X & \longrightarrow Z \\ X & \longrightarrow Y \\ Z & \longrightarrow Y\end{aligned}\end{gathered}$$ be a cartesian diagram of algebraic spaces over $S$. Then the map of sets of points $$|Z \times_Y X| \longrightarrow |Z| \times_{|Y|} |X|$$ is surjective.
Proof. Namely, suppose given fields $K$, $L$ and morphisms $\operatorname{Spec}(K) \to X$, $\operatorname{Spec}(L) \to Z$, then the assumption that they agree as elements of $|Y|$ means that there is a common extension $M/K$ and $M/L$ such that $\operatorname{Spec}(M) \to \operatorname{Spec}(K) \to X \to Y$ and $\operatorname{Spec}(M) \to \operatorname{Spec}(L) \to Z \to Y$ agree. And this is exactly the condition which says you get a morphism $\operatorname{Spec}(M) \to Z \times_Y X$. $\square$
Proposition. Diagonals, separation and local algebra
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. If $X$ is Zariski locally quasi-separated (for example if $X$ is quasi-separated), then there exists a dense open subspace $X'$ of $X$ which is a scheme. More precisely, every point $x \in |X|$ of codimension $0$ on $X$ is contained in $X'$.
Proof. The question is local on $X$ by Lemma Étale geometry of algebraic spaces. Thus by Lemma Diagonals and separation we may assume that there exists an affine scheme $U$ and a surjective, quasi-compact, étale morphism $U \to X$. Moreover $U \to X$ is separated (Lemma Diagonals and separation (uncovered prerequisite)). Set $R = U \times_X U$ and denote $s, t : R \to U$ the projections as usual. Then $s, t$ are surjective, quasi-compact, separated, and étale. Hence $s, t$ are also quasi-finite and have finite fibres (Morphisms, Lemmas Étale morphisms and finite algebras (uncovered prerequisite), Finite algebras and local algebra (uncovered prerequisite), and Finite algebras (uncovered prerequisite)). By Morphisms, Lemma Finite algebras (uncovered prerequisite) for every $\eta \in U$ which is the generic point of an irreducible component of $U$, there exists an open neighbourhood $V \subset U$ of $\eta$ such that $s^{-1}(V) \to V$ is finite. By Descent, Lemma Descent of proper morphisms and finite algebras (uncovered prerequisite) being finite is fpqc (and in particular étale) local on the target. Hence we may apply More on Groupoids, Lemma Proper morphisms (uncovered prerequisite) which says that the largest open $W \subset U$ over which $s$ is finite is $R$-invariant. By the above $W$ contains every generic point of an irreducible component of $U$. The restriction $R_W$ of $R$ to $W$ equals $R_W = s^{-1}(W) = t^{-1}(W)$ (see Groupoids, Definition The geometric construction and discussion following it). By construction $s_W, t_W : R_W \to W$ are finite étale. Consider the open subspace $X' = W/R_W \subset X$ (see Spaces, Lemma The geometric construction (uncovered prerequisite)). By construction the inclusion map $X' \to X$ induces a bijection on points of codimension $0$. This reduces us to Lemma Étale morphisms and diagonals and separation (uncovered prerequisite). $\square$
Lemma. The topology of a Noetherian spectrum
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$.
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If $X$ is locally Noetherian then $|X|$ is a locally Noetherian topological space.
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If $X$ is quasi-compact and locally Noetherian, then $|X|$ is a Noetherian topological space.
Proof. Assume $X$ is locally Noetherian. Choose a scheme $U$ and a surjective étale morphism $U \to X$. As $X$ is locally Noetherian we see that $U$ is locally Noetherian. By Properties, Lemma The topology of a Noetherian spectrum (uncovered prerequisite) this means that $|U|$ is a locally Noetherian topological space. Since $|U| \to |X|$ is open and surjective we conclude that $|X|$ is locally Noetherian by Topology, Lemma Noetherian rings (uncovered prerequisite). This proves (1). If $X$ is quasi-compact and locally Noetherian, then $|X|$ is quasi-compact and locally Noetherian. Hence $|X|$ is Noetherian by Topology, Lemma Noetherian rings and local algebra (uncovered prerequisite). $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $T \subset |X|$ be a closed subset. There exists a unique closed subspace $Z \subset X$ with the following properties: (a) we have $|Z| = T$, and (b) $Z$ is reduced.
Proof. Let $U \to X$ be a surjective étale morphism, where $U$ is a scheme. Set $R = U \times_X U$, so that $X = U/R$, see Spaces, Lemma The geometric construction (uncovered prerequisite). As usual we denote $s, t : R \to U$ the two projection morphisms. By Lemma Étale geometry of algebraic spaces we see that $T$ corresponds to a closed subset $T' \subset |U|$ such that $s^{-1}(T') = t^{-1}(T')$. Let $Z' \subset U$ be the reduced induced scheme structure on $T'$. In this case the fibre products $Z' \times_{U, t} R$ and $Z' \times_{U, s} R$ are closed subschemes of $R$ (Schemes, Lemma Base change for diagonals and separation (uncovered prerequisite)) which are étale over $Z'$ (Morphisms, Lemma Base change for étale morphisms (uncovered prerequisite)), and hence reduced (because being reduced is local in the étale topology, see Remark Étale morphisms and proper morphisms). Since they have the same underlying topological space (see above) we conclude that $Z' \times_{U, t} R = Z' \times_{U, s} R$. Thus we can apply Lemma Étale geometry of algebraic spaces (uncovered prerequisite) to obtain a closed subspace $Z \subset X$ whose pullback to $U$ is $Z'$. By construction $|Z| = T$ and $Z$ is reduced. This proves existence. We omit the proof of uniqueness. $\square$
Lemma. Base change for étale morphisms
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ be a cartesian square of algebraic spaces over $S$. Let $\mathcal{F}$ be a sheaf on $X_\mathrm{\acute{e}tale}$. If $g$ is étale, then
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$f'_{small, *}(\mathcal{F}|_{X'}) = (f_{small, *}\mathcal{F})|_{Y'}$ in $\operatorname{Sh}(Y'_\mathrm{\acute{e}tale})$[^3], and
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if $\mathcal{F}$ is an abelian sheaf, then $R^if'_{small, *}(\mathcal{F}|_{X'}) = (R^if_{small, *}\mathcal{F})|_{Y'}$.
Proof. Consider the following diagram of functors $$\begin{gathered}\begin{matrix}X'_{spaces, \mathrm{\acute{e}tale}} & X_{spaces, \mathrm{\acute{e}tale}} \\ Y'_{spaces, \mathrm{\acute{e}tale}} & Y_{spaces, \mathrm{\acute{e}tale}}\end{matrix} \\[6pt] \begin{aligned}X'_{spaces, \mathrm{\acute{e}tale}} & \xrightarrow{j} X_{spaces, \mathrm{\acute{e}tale}} \\ Y'_{spaces, \mathrm{\acute{e}tale}} & \xrightarrow{j} Y_{spaces, \mathrm{\acute{e}tale}} \\ Y'_{spaces, \mathrm{\acute{e}tale}} & \xrightarrow{V' \mapsto V' \times_{Y'} X'} X'_{spaces, \mathrm{\acute{e}tale}} \\ Y_{spaces, \mathrm{\acute{e}tale}} & \xrightarrow{V \mapsto V \times_Y X} X_{spaces, \mathrm{\acute{e}tale}}\end{aligned}\end{gathered}$$ The horizontal arrows are localizations and the vertical arrows induce morphisms of sites. Hence the last statement of Sites, Lemma Localization of local algebra (uncovered prerequisite) gives (1). To see (2) apply (1) to an injective resolution of $\mathcal{F}$ and use that restriction is exact and preserves injectives (see Cohomology on Sites, Lemma Sheaf cohomology (uncovered prerequisite)). $\square$
Definition. Noetherian algebraic spaces
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. We say $X$ is Noetherian if $X$ is quasi-compact, quasi-separated and locally Noetherian.
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $Z \to X$ be an immersion of algebraic spaces. Then $|Z| \to |X|$ is a homeomorphism of $|Z|$ onto a locally closed subset of $|X|$.
Proof. Let $U$ be a scheme and $U \to X$ a surjective étale morphism. Then $Z \times_X U \to U$ is an immersion of schemes, hence gives a homeomorphism of $|Z \times_X U|$ with a locally closed subset $T'$ of $|U|$. By Lemma Étale geometry of algebraic spaces the subset $T'$ is the inverse image of the image $T$ of $|Z| \to |X|$. The map $|Z| \to |X|$ is injective because the transformation of functors $Z \to X$ is injective, see Spaces, Section The geometric construction. By Topology, Lemma The geometric construction (uncovered prerequisite) we see that $T$ is locally closed in $|X|$. Moreover, the continuous map $|Z| \to T$ is a homeomorphism as the map $|Z \times_X U| \to T'$ is a homeomorphism and $|Z \times_Y U| \to |Z|$ is submersive. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $U$ be a scheme. Let $\varphi : U \to X$ be an étale morphism such that the projections $R = U \times_X U \to U$ are quasi-compact; for example if $\varphi$ is quasi-compact. Then the fibres of $$|U| \to |X| \quad\text{and}\quad |R| \to |X|$$ are finite.
Proof. Denote $R = U \times_X U$, and $s, t : R \to U$ the projections. Let $u \in U$ be a point, and let $x \in |X|$ be its image. The fibre of $|U| \to |X|$ over $x$ is equal to $s(t^{-1}(\{u\}))$ by Lemma Étale geometry of algebraic spaces, and the fibre of $|R| \to |X|$ over $x$ is $t^{-1}(s(t^{-1}(\{u\})))$. Since $t : R \to U$ is étale and quasi-compact, it has finite fibres (as its fibres are disjoint unions of spectra of fields by Morphisms, Lemma Étale morphisms and field extensions (uncovered prerequisite) and quasi-compact). Hence we win. $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $X = U/R$ be a presentation of $X$, see Spaces, Definition The geometric construction. Then the image of $|R| \to |U| \times |U|$ is an equivalence relation and $|X|$ is the quotient of $|U|$ by this equivalence relation.
Proof. The assumption means that $U$ is a scheme, $p : U \to X$ is a surjective, étale morphism, $R = U \times_X U$ is a scheme and defines an étale equivalence relation on $U$ such that $X = U/R$ as sheaves. By Lemma Criteria for étale geometry of algebraic spaces (uncovered prerequisite) we see that $|U| \to |X|$ is surjective. By Lemma Étale geometry of algebraic spaces the map $$|R| \longrightarrow |U| \times_{|X|} |U|$$ is surjective. Hence the image of $|R| \to |U| \times |U|$ is exactly the set of pairs $(u_1, u_2) \in |U| \times |U|$ such that $u_1$ and $u_2$ have the same image in $|X|$. Combining these two statements we get the result of the lemma. $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. There exists a unique topology on the sets of points of algebraic spaces over $S$ with the following properties:
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if $X$ is a scheme over $S$, then the topology on $|X|$ is the usual one (via the identification of Lemma Étale geometry of algebraic spaces (uncovered prerequisite)),
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for every morphism of algebraic spaces $X \to Y$ over $S$ the map $|X| \to |Y|$ is continuous, and
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for every étale morphism $U \to X$ with $U$ a scheme the map of topological spaces $|U| \to |X|$ is continuous and open.
Proof. Let $X$ be an algebraic space over $S$. Let $p : U \to X$ be a surjective étale morphism where $U$ is a scheme over $S$. We define $W \subset |X|$ is open if and only if $|p|^{-1}(W)$ is an open subset of $|U|$. This is a topology on $|X|$ (it is the quotient topology on $|X|$, see Topology, Lemma The geometric construction (uncovered prerequisite)).
Let us prove that the topology is independent of the choice of the presentation. To do this it suffices to show that if $U'$ is a scheme, and $U' \to X$ is an étale morphism, then the map $|U'| \to |X|$ (with topology on $|X|$ defined using $U \to X$ as above) is open and continuous; which in addition will prove that (3) holds. Set $U'' = U \times_X U'$, so that we have the commutative diagram $$\begin{gathered}\begin{matrix}U'' & U' \\ U & X\end{matrix} \\[6pt] \begin{aligned}U'' & \longrightarrow U' \\ U'' & \longrightarrow U \\ U' & \longrightarrow X \\ U & \longrightarrow X\end{aligned}\end{gathered}$$ As $U \to X$ and $U' \to X$ are étale we see that both $U'' \to U$ and $U'' \to U'$ are étale morphisms of schemes. Moreover, $U'' \to U'$ is surjective. Hence we get a commutative diagram of maps of sets $$\begin{gathered}\begin{matrix}|U''| & |U'| \\ |U| & |X|\end{matrix} \\[6pt] \begin{aligned}|U''| & \longrightarrow |U'| \\ |U''| & \longrightarrow |U| \\ |U'| & \longrightarrow |X| \\ |U| & \longrightarrow |X|\end{aligned}\end{gathered}$$ The lower horizontal arrow is surjective (see Lemma Criteria for étale geometry of algebraic spaces (uncovered prerequisite) or Lemma Étale geometry of algebraic spaces) and continuous by definition of the topology on $|X|$. The top horizontal arrow is surjective, continuous, and open by Morphisms, Lemma Étale morphisms (uncovered prerequisite). The left vertical arrow is continuous and open (by Morphisms, Lemma Étale morphisms (uncovered prerequisite) again.) Hence it follows formally that the right vertical arrow is continuous and open.
To finish the proof we prove (2). Let $a : X \to Y$ be a morphism of algebraic spaces. According to Spaces, Lemma Lifting the geometric construction (uncovered prerequisite) we can find a diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{p} X \\ U & \xrightarrow{\alpha} V \\ V & \xrightarrow{q} Y \\ X & \xrightarrow{a} Y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes, and $p$ and $q$ are surjective and étale. This gives rise to the diagram $$\begin{gathered}\begin{matrix}|U| & |V| \\ |X| & |Y|\end{matrix} \\[6pt] \begin{aligned}|U| & \xrightarrow{p} |X| \\ |U| & \xrightarrow{\alpha} |V| \\ |V| & \xrightarrow{q} |Y| \\ |X| & \xrightarrow{a} |Y|\end{aligned}\end{gathered}$$ where all but the lower horizontal arrows are known to be continuous and the two vertical arrows are surjective and open. It follows that the lower horizontal arrow is continuous as desired. $\square$
Lemma. Sheaves on ringed sites
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$.
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The functor $f_{small}^{-1} : \textit{Ab}(Y_\mathrm{\acute{e}tale}) \to \textit{Ab}(X_\mathrm{\acute{e}tale})$ is exact.
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The functor $f_{small}^{-1} : \operatorname{Sh}(Y_\mathrm{\acute{e}tale}) \to \operatorname{Sh}(X_\mathrm{\acute{e}tale})$ is exact, i.e., it commutes with finite limits and colimits, see Categories, Definition The geometric construction.
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For any étale morphism $V \to Y$ of algebraic spaces we have $f_{small}^{-1}h_V = h_{X \times_Y V}$.
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Let $\overline{x} \to X$ be a geometric point. Let $\mathcal{G}$ be a sheaf on $Y_\mathrm{\acute{e}tale}$. Then there is a canonical identification $$(f_{small}^{-1}\mathcal{G})_{\overline{x}} = \mathcal{G}_{\overline{y}}.$$ where $\overline{y} = f \circ \overline{x}$.
Proof. Recall that $f_{small}$ is defined via $f_{spaces, small}$ in Lemma Étale morphisms and sheaves on ringed sites (uncovered prerequisite). Parts (1), (2) and (3) are general consequences of the fact that $f_{spaces, \mathrm{\acute{e}tale}} : X_{spaces, \mathrm{\acute{e}tale}} \to Y_{spaces, \mathrm{\acute{e}tale}}$ is a morphism of sites, see Sites, Definition Sheaves on ringed sites for (2), Modules on Sites, Lemma Exactness of flat pullback for (1), and Sites, Lemma Pullback of sheaves on ringed sites (uncovered prerequisite) for (3).
Proof of (4). This statement is a special case of Sites, Lemma Sheaves on ringed sites (uncovered prerequisite) via Lemma Sheaves on ringed sites (uncovered prerequisite). We also provide a direct proof. Note that by Lemma Sheaves on ringed sites (uncovered prerequisite). taking stalks commutes with sheafification. Let $\mathcal{G}'$ be the sheaf on $Y_{spaces, \mathrm{\acute{e}tale}}$ whose restriction to $Y_\mathrm{\acute{e}tale}$ is $\mathcal{G}$. Recall that $f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{G}'$ is the sheaf associated to the presheaf $$U \longrightarrow \mathop{\operatorname{colim}}_{U \to X \times_Y V} \mathcal{G}'(V),$$ see Sites, Sections The geometric construction and The geometric construction. Thus we have $$\begin{aligned} (f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{G}')_{\overline{x}} & = \mathop{\operatorname{colim}}_{(U, \overline{u})} f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{G}'(U) \\ & = \mathop{\operatorname{colim}}_{(U, \overline{u})} \mathop{\operatorname{colim}}_{a : U \to X \times_Y V} \mathcal{G}'(V) \\ & = \mathop{\operatorname{colim}}_{(V, \overline{v})} \mathcal{G}'(V) \\ & = \mathcal{G}'_{\overline{y}} \end{aligned}$$ in the third equality the pair $(U, \overline{u})$ and the map $a : U \to X \times_Y V$ corresponds to the pair $(V, a \circ \overline{u})$. Since the stalk of $\mathcal{G}'$ (resp. $f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{G}'$) agrees with the stalk of $\mathcal{G}$ (resp. $f_{small}^{-1}\mathcal{G}$), see Equation (Étale morphisms and sheaves on ringed sites) the result follows. $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\overline{x} : \operatorname{Spec}(k) \to X$ be a geometric point of $X$ lying over $x \in |X|$. Let $\varphi : U \to X$ be an étale morphism of algebraic spaces and let $u \in |U|$ with $\varphi(u) = x$. Then there exists a geometric point $\overline{u} : \operatorname{Spec}(k) \to U$ lying over $u$ with $\overline{x} = \varphi \circ \overline{u}$.
Proof. Choose an affine scheme $U'$ with $u' \in U'$ and an étale morphism $U' \to U$ which maps $u'$ to $u$. If we can prove the lemma for $(U', u') \to (X, x)$ then the lemma follows. Hence we may assume that $U$ is a scheme, in particular that $U \to X$ is representable. Then look at the cartesian diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(k) \times_{\overline{x}, X, \varphi} U & U \\ \operatorname{Spec}(k) & X\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(k) \times_{\overline{x}, X, \varphi} U & \xrightarrow{\text{pr}_1} \operatorname{Spec}(k) \\ \operatorname{Spec}(k) \times_{\overline{x}, X, \varphi} U & \xrightarrow{\text{pr}_2} U \\ U & \xrightarrow{\varphi} X \\ \operatorname{Spec}(k) & \xrightarrow{\overline{x}} X\end{aligned}\end{gathered}$$ The projection $\text{pr}_1$ is the base change of an étale morphisms so it is étale, see Lemma Base change for étale morphisms (uncovered prerequisite). Therefore, the scheme $\operatorname{Spec}(k) \times_{\overline{x}, X, \varphi} U$ is a disjoint union of finite separable extensions of $k$, see Morphisms, Lemma Étale morphisms and field extensions (uncovered prerequisite). But $k$ is algebraically closed, so all these extensions are trivial, so $\operatorname{Spec}(k) \times_{\overline{x}, X, \varphi} U$ is a disjoint union of copies of $\operatorname{Spec}(k)$ and each of these corresponds to a geometric point $\overline{u}$ with $\varphi \circ \overline{u} = \overline{x}$. By Lemma Étale geometry of algebraic spaces the map $$|\operatorname{Spec}(k) \times_{\overline{x}, X, \varphi} U| \longrightarrow |\operatorname{Spec}(k)| \times_{|X|} |U|$$ is surjective, hence we can pick $\overline{u}$ to lie over $u$. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Let $x \in |X|$ be a point and let $\overline{x}$ be a geometric point lying over $x$. Finally, let $\varphi : (U, \overline{u}) \to (X, \overline{x})$ be an étale neighbourhood where $U$ is a scheme. Then $$(\varphi^*\mathcal{F})_u \otimes_{\mathcal{O}_{U, u}} \mathcal{O}_{X, \overline{x}} = \mathcal{F}_{\overline{x}}$$ where $u \in U$ is the image of $\overline{u}$.
Proof. Note that $\mathcal{O}_{X, \overline{x}} = \mathcal{O}_{U, u}^{sh}$ by Lemma Étale morphisms and local algebra hence the tensor product makes sense. Moreover, from Definition Sheaves on ringed sites it is clear that $$\mathcal{F}_{\overline{u}} = \mathop{\operatorname{colim}} (\varphi^*\mathcal{F})_u$$ where the colimit is over $\varphi : (U, \overline{u}) \to (X, \overline{x})$ as in the lemma. Hence there is a canonical map from left to right in the statement of the lemma. We have a similar colimit description for $\mathcal{O}_{X, \overline{x}}$ and by Lemma Criteria for étale morphisms and quasi-coherent complexes we have $$((\varphi')^*\mathcal{F})_{u'} = (\varphi^*\mathcal{F})_u \otimes_{\mathcal{O}_{U, u}} \mathcal{O}_{U', u'}$$ whenever $(U', \overline{u}') \to (U, \overline{u})$ is a morphism of étale neighbourhoods. To complete the proof we use that $\otimes$ commutes with colimits. $\square$
Lemma. Criteria for quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\mathcal{F}$ be a sheaf of $\mathcal{O}_X$-modules. The following are equivalent
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$\mathcal{F}$ is a quasi-coherent $\mathcal{O}_X$-module,
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there exists an étale morphism $f : Y \to X$ of algebraic spaces over $S$ with $|f| : |Y| \to |X|$ surjective such that $f^*\mathcal{F}$ is quasi-coherent on $Y$,
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there exists a scheme $U$ and a surjective étale morphism $\varphi : U \to X$ such that $\varphi^*\mathcal{F}$ is a quasi-coherent $\mathcal{O}_U$-module, and
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for every affine scheme $U$ and étale morphism $\varphi : U \to X$ the restriction $\varphi^*\mathcal{F}$ is a quasi-coherent $\mathcal{O}_U$-module.
Proof. It is clear that (1) implies (2) by considering $\text{id}_X$. Assume $f : Y \to X$ is as in (2), and let $V \to Y$ be a surjective étale morphism from a scheme towards $Y$. Then the composition $V \to X$ is surjective étale as well and by Lemma Pullback of quasi-coherent complexes and coherent sheaves the pullback of $\mathcal{F}$ to $V$ is quasi-coherent as well. Hence we see that (2) implies (3).
Let $U \to X$ be as in (3). Let us use the abuse of notation introduced in Equation (Modules). As $\mathcal{F}|_{U_\mathrm{\acute{e}tale}}$ is quasi-coherent there exists an étale covering $\{U_i \to U\}$ such that $\mathcal{F}|_{U_{i, \mathrm{\acute{e}tale}}}$ has a global presentation, see Modules on Sites, Definition The geometric construction and Lemma Locality at a final object. Let $V \to X$ be an object of $X_\mathrm{\acute{e}tale}$. Since $U \to X$ is surjective and étale, the family of maps $\{U_i \times_X V \to V\}$ is an étale covering of $V$. Via the morphisms $U_i \times_X V \to U_i$ we can restrict the global presentations of $\mathcal{F}|_{U_{i, \mathrm{\acute{e}tale}}}$ to get a global presentation of $\mathcal{F}|_{(U_i \times_X V)_\mathrm{\acute{e}tale}}$ Hence the sheaf $\mathcal{F}$ on $X_\mathrm{\acute{e}tale}$ satisfies the condition of Modules on Sites, Definition Local ringed sites and hence is quasi-coherent.
The equivalence of (3) and (4) comes from the fact that any scheme has an affine open covering. $\square$
Lemma. Affine neighbourhoods
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Then $X$ is quasi-compact if and only if there exists an étale surjective morphism $U \to X$ with $U$ an affine scheme.
Proof. If there exists an étale surjective morphism $U \to X$ with $U$ affine then $X$ is quasi-compact by Definition Étale geometry of algebraic spaces. Conversely, if $X$ is quasi-compact, then $|X|$ is quasi-compact. Let $U = \coprod_{i \in I} U_i$ be a disjoint union of affine schemes with an étale and surjective map $\varphi : U \to X$ (Lemma Affine neighbourhoods (uncovered prerequisite)). Then $|X| = \bigcup \varphi(|U_i|)$ and by quasi-compactness there is a finite subset $i_1, \ldots, i_n$ such that $|X| = \bigcup \varphi(|U_{i_j}|)$. Hence $U_{i_1} \cup \ldots \cup U_{i_n}$ is an affine scheme with a finite surjective morphism towards $X$. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. The category $\mathrm{QCoh}(\mathcal{O}_X)$ of quasi-coherent sheaves on $X$ has the following properties:
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Any direct sum of quasi-coherent sheaves is quasi-coherent.
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Any colimit of quasi-coherent sheaves is quasi-coherent.
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The kernel and cokernel of a morphism of quasi-coherent sheaves is quasi-coherent.
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Given a short exact sequence of $\mathcal{O}_X$-modules $0 \to \mathcal{F}_1 \to \mathcal{F}_2 \to \mathcal{F}_3 \to 0$ if two out of three are quasi-coherent so is the third.
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Given two quasi-coherent $\mathcal{O}_X$-modules the tensor product is quasi-coherent.
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Given two quasi-coherent $\mathcal{O}_X$-modules $\mathcal{F}$, $\mathcal{G}$ such that $\mathcal{F}$ is of finite presentation (see Section Proper morphisms and modules), then the internal hom $\mathcal{H}om_{\mathcal{O}_X}(\mathcal{F}, \mathcal{G})$ is quasi-coherent.
Proof. If $X$ is a scheme, then this is Descent, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite). We will reduce the lemma to this case by étale localization.
Choose a scheme $U$ and a surjective étale morphism $\varphi : U \to X$. Our notation will be that $\textit{Mod}(\mathcal{O}_U) = \textit{Mod}(U_\mathrm{\acute{e}tale}, \mathcal{O}_U)$ and $\mathrm{QCoh}(\mathcal{O}_U) = \mathrm{QCoh}(U_\mathrm{\acute{e}tale}, \mathcal{O}_U)$; in other words, even though $U$ is a scheme we think of quasi-coherent modules on $U$ as modules on the small étale site of $U$. By Lemma Pullback of quasi-coherent complexes and coherent sheaves we have a commutative diagram $$\begin{gathered}\begin{matrix}\mathrm{QCoh}(\mathcal{O}_X) & \mathrm{QCoh}(\mathcal{O}_U) \\ \textit{Mod}(\mathcal{O}_X) & \textit{Mod}(\mathcal{O}_U)\end{matrix} \\[6pt] \begin{aligned}\mathrm{QCoh}(\mathcal{O}_X) & \xrightarrow{\varphi^*} \mathrm{QCoh}(\mathcal{O}_U) \\ \mathrm{QCoh}(\mathcal{O}_X) & \longrightarrow \textit{Mod}(\mathcal{O}_X) \\ \mathrm{QCoh}(\mathcal{O}_U) & \longrightarrow \textit{Mod}(\mathcal{O}_U) \\ \textit{Mod}(\mathcal{O}_X) & \xrightarrow{\varphi^*} \textit{Mod}(\mathcal{O}_U)\end{aligned}\end{gathered}$$ The bottom horizontal arrow is the restriction functor (Modules) $\mathcal{G} \mapsto \mathcal{G}|_{U_\mathrm{\acute{e}tale}}$. This functor has both a left adjoint and a right adjoint, see Modules on Sites, Section Localization of local algebra, hence commutes with all limits and colimits. Moreover, we know that an object of $\textit{Mod}(\mathcal{O}_X)$ is in $\mathrm{QCoh}(\mathcal{O}_X)$ if and only if its restriction to $U$ is in $\mathrm{QCoh}(\mathcal{O}_U)$, see Lemma Criteria for quasi-coherent complexes and coherent sheaves. With these preliminaries out of the way we can start the proof.
Proof of (1). Let $\mathcal{F}_i$, $i \in I$ be a family of quasi-coherent $\mathcal{O}_X$-modules. By the discussion above we have $$\Big(\bigoplus \mathcal{F}_i\Big)|_{U_\mathrm{\acute{e}tale}} = \bigoplus \mathcal{F}_i|_{U_\mathrm{\acute{e}tale}}$$ Each of the modules $\mathcal{F}_i|_{U_\mathrm{\acute{e}tale}}$ is quasi-coherent. Hence the direct sum is quasi-coherent by the case of schemes. Hence $\bigoplus \mathcal{F}_i$ is quasi-coherent as a module restricting to a quasi-coherent module on $U$.
Proof of (2). Let $\mathcal{I} \to \mathrm{QCoh}(\mathcal{O}_X)$, $i \mapsto \mathcal{F}_i$ be a diagram. Then $$(\mathop{\operatorname{colim}} \mathcal{F}_i)|_{U_\mathrm{\acute{e}tale}} = \mathop{\operatorname{colim}} \mathcal{F}_i|_{U_\mathrm{\acute{e}tale}}$$ by the discussion above and we conclude in the same manner.
Proof of (3). Let $a : \mathcal{F} \to \mathcal{F}'$ be an arrow of $\mathrm{QCoh}(\mathcal{O}_X)$. Then we have $\operatorname{Ker}(a)|_{U_\mathrm{\acute{e}tale}} = \operatorname{Ker}(a|_{U_\mathrm{\acute{e}tale}})$ and $\operatorname{Coker}(a)|_{U_\mathrm{\acute{e}tale}} = \operatorname{Coker}(a|_{U_\mathrm{\acute{e}tale}})$ and we conclude in the same manner.
Proof of (4). The restriction $0 \to \mathcal{F}_1|_{U_\mathrm{\acute{e}tale}} \to \mathcal{F}_2|_{U_\mathrm{\acute{e}tale}} \to \mathcal{F}_3|_{U_\mathrm{\acute{e}tale}} \to 0$ is short exact. Hence we have the 2-out-of-3 property for this sequence and we conclude as before.
Proof of (5). Let $\mathcal{F}$ and $\mathcal{G}$ be in $\mathrm{QCoh}(\mathcal{O}_X)$. Then we have $$(\mathcal{F} \otimes_{\mathcal{O}_X} \mathcal{G})_{U_\mathrm{\acute{e}tale}} = \mathcal{F}|_{U_\mathrm{\acute{e}tale}} \otimes_{\mathcal{O}_U} \mathcal{G}|_{U_\mathrm{\acute{e}tale}}$$ and we conclude as before.
Proof of (6). Let $\mathcal{F}$ and $\mathcal{G}$ be in $\mathrm{QCoh}(\mathcal{O}_X)$ with $\mathcal{F}$ of finite presentation. We have $$\mathcal{H}om_{\mathcal{O}_X}(\mathcal{F}, \mathcal{G})|_{U_\mathrm{\acute{e}tale}} = \mathcal{H}om_{\mathcal{O}_U}(\mathcal{F}|_{U_\mathrm{\acute{e}tale}}, \mathcal{G}|_{U_\mathrm{\acute{e}tale}})$$ Namely, restriction is a localization, see Section Localization of local algebra, especially formula (Localization of local algebra)) and formation of internal hom commutes with localization, see Modules on Sites, Lemma Derived Hom and Ext (uncovered prerequisite). Thus we conclude as before. $\square$
Theorem. Sheaves on ringed sites
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. A map $a : \mathcal{F} \to \mathcal{G}$ of sheaves of sets is injective (resp. surjective) if and only if the map on stalks $a_{\overline{x}} : \mathcal{F}_{\overline{x}} \to \mathcal{G}_{\overline{x}}$ is injective (resp. surjective) for all geometric points of $X$. A sequence of abelian sheaves on $X_\mathrm{\acute{e}tale}$ is exact if and only if it is exact on all stalks at geometric points of $S$.
Proof. We know the theorem is true if $X$ is a scheme, see Étale Cohomology, Theorem Sheaves on ringed sites (uncovered prerequisite). Choose a surjective étale morphism $f : U \to X$ where $U$ is a scheme. Since $\{U \to X\}$ is a covering (in $X_{spaces, \mathrm{\acute{e}tale}}$) we can check whether a map of sheaves is injective, or surjective by restricting to $U$. Now if $\overline{u} : \operatorname{Spec}(k) \to U$ is a geometric point of $U$, then $(\mathcal{F}|_U)_{\overline{u}} = \mathcal{F}_{\overline{x}}$ where $\overline{x} = f \circ \overline{u}$. (This is clear from the colimits defining the stalks at $\overline{u}$ and $\overline{x}$, but it also follows from Lemma Sheaves on ringed sites.) Hence the result for $U$ implies the result for $X$ and we win. $\square$
Lemma. Étale morphisms and local algebra
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $\overline{x}$ be a geometric point of $X$. Let $(U, \overline{u})$ be an étale neighbourhood of $\overline{x}$ where $U$ is a scheme. Then we have $$\mathcal{O}_{X, \overline{x}} = \mathcal{O}_{U, \overline{u}} = \mathcal{O}_{U, u}^{sh}$$ where the left hand side is the stalk of the structure sheaf of $X$, and the right hand side is the strict henselization of the local ring of $U$ at the point $u$ at which $\overline{u}$ is centered.
Proof. We know that the structure sheaf $\mathcal{O}_U$ on $U_\mathrm{\acute{e}tale}$ is the restriction of the structure sheaf of $X$. Hence the first equality follows from Lemma Sheaves on ringed sites part (4). The second equality is explained in Étale Cohomology, Lemma Étale morphisms and local algebra (uncovered prerequisite). $\square$
Proposition. Quasi-coherent complexes and coherent sheaves
With $S$, $\varphi : U \to X$, and $(U, R, s, t, c)$ as above. For any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ the sheaf $\varphi^*\mathcal{F}$ comes equipped with a canonical isomorphism $$\alpha : t^*\varphi^*\mathcal{F} \longrightarrow s^*\varphi^*\mathcal{F}$$ which satisfies the conditions of Groupoids, Definition Modules and groupoids and equivalence relations and therefore defines a quasi-coherent sheaf on $(U, R, s, t, c)$. The functor $\mathcal{F} \mapsto (\varphi^*\mathcal{F}, \alpha)$ defines an equivalence of categories $$\begin{matrix} \text{Quasi-coherent} \\ \mathcal{O}_X\text{-modules} \end{matrix} \longleftrightarrow \begin{matrix} \text{Quasi-coherent modules}\\ \text{on }(U, R, s, t, c) \end{matrix}$$
Proof. In the statement of the proposition, and in this proof we think of a quasi-coherent sheaf on a scheme as a quasi-coherent sheaf on the small étale site of that scheme. This is permissible by the results of Descent, Sections Quasi-coherent complexes and coherent sheaves, Quasi-coherent complexes and sheaf cohomology, and Quasi-coherent complexes and coherent sheaves.
The existence of $\alpha$ comes from the fact that $\varphi \circ t = \varphi \circ s$ and that pullback is functorial in the morphism, see discussion surrounding Equation (Étale geometry of algebraic spaces). In exactly the same way, i.e., by functoriality of pullback, we see that the isomorphism $\alpha$ satisfies condition (1) of Groupoids, Definition Modules and groupoids and equivalence relations. To see condition (2) of the definition it suffices to see that $\alpha$ is an isomorphism which is clear. The construction $\mathcal{F} \mapsto (\varphi^*\mathcal{F}, \alpha)$ is clearly functorial in the quasi-coherent sheaf $\mathcal{F}$. Hence we obtain the functor from left to right in the displayed formula of the lemma.
Conversely, suppose that $(\mathcal{F}, \alpha)$ is a quasi-coherent sheaf on $(U, R, s, t, c)$. Let $V \to X$ be an object of $X_\mathrm{\acute{e}tale}$. In this case the morphism $V' = U \times_X V \to V$ is a surjective étale morphism of schemes, and hence $\{V' \to V\}$ is an étale covering of $V$. Moreover, the quasi-coherent sheaf $\mathcal{F}$ pulls back to a quasi-coherent sheaf $\mathcal{F}'$ on $V'$. Since $R = U \times_X U$ with $t = \text{pr}_0$ and $s = \text{pr}_0$ we see that $V' \times_V V' = R \times_X V$ with projection maps $V' \times_V V' \to V'$ equal to the pullbacks of $t$ and $s$. Hence $\alpha$ pulls back to an isomorphism $\alpha' : \text{pr}_0^*\mathcal{F}' \to \text{pr}_1^*\mathcal{F}'$, and the pair $(\mathcal{F}', \alpha')$ is a descend datum for quasi-coherent sheaves with respect to $\{V' \to V\}$. By Descent, Proposition Quasi-coherent complexes and coherent sheaves this descent datum is effective, and we obtain a quasi-coherent $\mathcal{O}_V$-module $\mathcal{F}_V$ on $V_\mathrm{\acute{e}tale}$. To see that this gives a quasi-coherent sheaf on $X_\mathrm{\acute{e}tale}$ we have to show (by Lemma Criteria for étale morphisms and quasi-coherent complexes) that for any morphism $f : V_1 \to V_2$ in $X_\mathrm{\acute{e}tale}$ there is a canonical isomorphism $c_f : \mathcal{F}_{V_1} \to \mathcal{F}_{V_2}$ compatible with compositions of morphisms. We omit the verification. We also omit the verification that this defines a functor from the category on the right to the category on the left which is inverse to the functor described above. $\square$
Lemma. Pullback of quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The pullback functor $f^* : \textit{Mod}(\mathcal{O}_Y) \to \textit{Mod}(\mathcal{O}_X)$ preserves quasi-coherent sheaves.
Proof. This is a general fact, see Modules on Sites, Lemma Local pullback on a ringed site. $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. There exists a largest open subspace $X' \subset X$ which is a scheme.
Proof. Let $U \to X$ be an étale surjective morphism, where $U$ is a scheme. Let $R = U \times_X U$. The open subspaces of $X$ correspond $1 - 1$ with open subschemes of $U$ which are $R$-invariant. Hence there is a set of them. Let $X_i$, $i \in I$ be the set of open subspaces of $X$ which are schemes, i.e., are representable. Consider the open subspace $X' \subset X$ whose underlying set of points is the open $\bigcup |X_i|$ of $|X|$. By Lemma Criteria for étale geometry of algebraic spaces (uncovered prerequisite) we see that $$\coprod X_i \longrightarrow X'$$ is a surjective map of sheaves on $(\mathrm{Sch}/S)_{fppf}$. But since each $X_i \to X'$ is representable by open immersions we see that in fact the map is surjective in the Zariski topology. Namely, if $T \to X'$ is a morphism from a scheme into $X'$, then $X_i \times_{X'} T$ is an open subscheme of $T$. Hence we can apply Schemes, Lemma The geometric construction (uncovered prerequisite) to see that $X'$ is a scheme. $\square$
Lemma. Étale geometry of algebraic spaces
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. There exists a Zariski covering $X = \bigcup X_i$ such that each algebraic space $X_i$ has a surjective étale covering by an affine scheme. We may in addition assume each $X_i$ maps into an affine open of $S$.
Proof. By Lemma Affine neighbourhoods (uncovered prerequisite) we can find a surjective étale morphism $U = \coprod U_i \to X$, with $U_i$ affine and mapping into an affine open of $S$. Let $X_i \subset X$ be the open subspace of $X$ such that $U_i \to X$ factors through an étale surjective morphism $U_i \to X_i$, see Lemma Étale morphisms (uncovered prerequisite). Since $U = \bigcup U_i$ we see that $X = \bigcup X_i$. As $U_i \to X_i$ is surjective it follows that $X_i \to S$ maps into an affine open of $S$. $\square$
Lemma. Étale morphisms
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $U$, $U'$ be schemes over $S$.
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If $U \to U'$ is an étale morphism of schemes, and if $U' \to X$ is an étale morphism from $U'$ to $X$, then the composition $U \to X$ is an étale morphism from $U$ to $X$.
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If $\varphi : U \to X$ and $\varphi' : U' \to X$ are étale morphisms towards $X$, and if $\chi : U \to U'$ is a morphism of schemes such that $\varphi = \varphi' \circ \chi$, then $\chi$ is an étale morphism of schemes.
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If $\chi : U \to U'$ is a surjective étale morphism of schemes and $\varphi' : U' \to X$ is a morphism such that $\varphi = \varphi' \circ \chi$ is étale, then $\varphi'$ is étale.
Proof. Recall that our definition of an étale morphism from a scheme into an algebraic space comes from Spaces, Definition Proper morphisms via the fact that any morphism from a scheme into an algebraic space is representable.
Part (1) of the lemma follows from this, the fact that étale morphisms are preserved under composition (Morphisms, Lemma Composition and étale morphisms (uncovered prerequisite)) and Spaces, Lemmas Composition and proper morphisms (uncovered prerequisite) and Proper morphisms (uncovered prerequisite) (which are formal).
To prove part (2) choose a scheme $W$ over $S$ and a surjective étale morphism $W \to X$. Consider the base change $\chi_W : W \times_X U \to W \times_X U'$ of $\chi$. As $W \times_X U$ and $W \times_X U'$ are étale over $W$, we conclude that $\chi_W$ is étale, by Morphisms, Lemma Étale morphisms (uncovered prerequisite). On the other hand, in the commutative diagram $$\begin{gathered}\begin{matrix}W \times_X U & W \times_X U' \\ U & U'\end{matrix} \\[6pt] \begin{aligned}W \times_X U & \longrightarrow W \times_X U' \\ W \times_X U & \longrightarrow U \\ W \times_X U' & \longrightarrow U' \\ U & \longrightarrow U'\end{aligned}\end{gathered}$$ the two vertical arrows are étale and surjective. Hence by Descent, Lemma Étale morphisms and smooth morphisms (uncovered prerequisite) we conclude that $U \to U'$ is étale.
To prove part (3) choose a scheme $W$ over $S$ and a morphism $W \to X$. As above we consider the diagram $$\begin{gathered}\begin{matrix}W \times_X U & W \times_X U' & W \\ U & U' & X\end{matrix} \\[6pt] \begin{aligned}W \times_X U & \longrightarrow W \times_X U' \\ W \times_X U & \longrightarrow U \\ W \times_X U' & \longrightarrow U' \\ W \times_X U' & \longrightarrow W \\ W & \longrightarrow X \\ U & \longrightarrow U' \\ U' & \longrightarrow X\end{aligned}\end{gathered}$$ Now we know that $W \times_X U \to W \times_X U'$ is surjective étale (as a base change of $U \to U'$) and that $W \times_X U \to W$ is étale. Thus $W \times_X U' \to W$ is étale by Descent, Lemma Étale morphisms and smooth morphisms (uncovered prerequisite). By definition this means that $\varphi'$ is étale. $\square$
Lemma. Sheaves on ringed sites
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Then there is a canonical map $f^\sharp : f_{small}^{-1}\mathcal{O}_Y \to \mathcal{O}_X$ such that $$(f_{small}, f^\sharp) : (\operatorname{Sh}(X_\mathrm{\acute{e}tale}), \mathcal{O}_X) \longrightarrow (\operatorname{Sh}(Y_\mathrm{\acute{e}tale}), \mathcal{O}_Y)$$ is a morphism of ringed topoi. Furthermore,
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The construction $f \mapsto (f_{small}, f^\sharp)$ is compatible with compositions.
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If $f$ is a morphism of schemes, then $f^\sharp$ is the map described in Descent, Remark The geometric construction.
Proof. By Lemma Étale geometry of algebraic spaces (uncovered prerequisite) it suffices to give an $f$-map from $\mathcal{O}_Y$ to $\mathcal{O}_X$. In other words, for every commutative diagram $$\begin{gathered}\begin{matrix}U & X \\ V & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{g} V \\ U & \longrightarrow X \\ X & \xrightarrow{f} Y \\ V & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U \in X_\mathrm{\acute{e}tale}$, $V \in Y_\mathrm{\acute{e}tale}$ we have to give a map of rings $(f^\sharp)_{(U, V, g)} : \Gamma(V, \mathcal{O}_V) \to \Gamma(U, \mathcal{O}_U).$ Of course we just take $(f^\sharp)_{(U, V, g)} = g^\sharp$. It is clear that this is compatible with restriction mappings and hence indeed gives an $f$-map. We omit checking compatibility with compositions and agreement with the construction in Descent, Remark The geometric construction. $\square$
Theorem. Étale geometry of algebraic spaces
Let $X$, $Y$ be algebraic spaces over $\operatorname{Spec}(\mathbf{Z})$. Let $$(g, g^\sharp) : (\operatorname{Sh}(X_\mathrm{\acute{e}tale}), \mathcal{O}_X) \longrightarrow (\operatorname{Sh}(Y_\mathrm{\acute{e}tale}), \mathcal{O}_Y)$$ be a morphism of locally ringed topoi. Then there exists a unique morphism of algebraic spaces $f : X \to Y$ such that $(g, g^\sharp)$ is isomorphic to $(f_{small}, f^\sharp)$. In other words, the construction $$\textit{Spaces}/\operatorname{Spec}(\mathbf{Z}) \longrightarrow \textit{Locally ringed topoi}, \quad X \longrightarrow (X_\mathrm{\acute{e}tale}, \mathcal{O}_X)$$ is fully faithful (morphisms up to $2$-isomorphisms on the right hand side).
Proof. The uniqueness we have seen in Lemma Étale geometry of algebraic spaces (uncovered prerequisite). Thus it suffices to prove existence. In this proof we will freely use the identifications of Equation (Localization of local algebra) as well as the result of Lemma Local algebra (uncovered prerequisite).
Let $U \in \operatorname{Ob}(X_\mathrm{\acute{e}tale})$, let $V \in \operatorname{Ob}(Y_\mathrm{\acute{e}tale})$ and let $s \in g^{-1}h_V(U)$ be a section. We may think of $s$ as a map of sheaves $s : h_U \to g^{-1}h_V$. By Modules on Sites, Lemma Sheaves on ringed sites and local algebra (uncovered prerequisite) we obtain a commutative diagram of morphisms of ringed topoi $$\begin{gathered}\begin{matrix}(\operatorname{Sh}(X_\mathrm{\acute{e}tale}/U), \mathcal{O}_U) & \phantom{X} & (\operatorname{Sh}(X_\mathrm{\acute{e}tale}), \mathcal{O}_X) \\ (\operatorname{Sh}(V_\mathrm{\acute{e}tale}), \mathcal{O}_V) & \phantom{X} & (\operatorname{Sh}(Y_\mathrm{\acute{e}tale}), \mathcal{O}_Y).\end{matrix} \\[6pt] \begin{aligned}(\operatorname{Sh}(X_\mathrm{\acute{e}tale}/U), \mathcal{O}_U) & \xrightarrow{(j, j^\sharp)} (\operatorname{Sh}(X_\mathrm{\acute{e}tale}), \mathcal{O}_X) \\ (\operatorname{Sh}(X_\mathrm{\acute{e}tale}/U), \mathcal{O}_U) & \xrightarrow{(g_s, g_s^\sharp)} (\operatorname{Sh}(V_\mathrm{\acute{e}tale}), \mathcal{O}_V) \\ (\operatorname{Sh}(X_\mathrm{\acute{e}tale}), \mathcal{O}_X) & \xrightarrow{(g, g^\sharp)} (\operatorname{Sh}(Y_\mathrm{\acute{e}tale}), \mathcal{O}_Y). \\ (\operatorname{Sh}(V_\mathrm{\acute{e}tale}), \mathcal{O}_V) & \longrightarrow (\operatorname{Sh}(Y_\mathrm{\acute{e}tale}), \mathcal{O}_Y).\end{aligned}\end{gathered}$$ By Étale Cohomology, Theorem The geometric construction (uncovered prerequisite) we obtain a unique morphism of schemes $f_s : U \to V$ such that $(g_s, g_s^\sharp)$ is $2$-isomorphic to $(f_{s, small}, f_s^\sharp)$. The construction $(U, V, s) \leadsto f_s$ just explained satisfies the following functoriality property: Suppose given morphisms $a : U' \to U$ in $X_\mathrm{\acute{e}tale}$ and $b : V' \to V$ in $Y_\mathrm{\acute{e}tale}$ and a map $s' : h_{U'} \to g^{-1}h_{V'}$ such that the diagram $$\begin{gathered}\begin{matrix}h_{U'} & g^{-1}h_{V'} \\ h_U & g^{-1}h_V\end{matrix} \\[6pt] \begin{aligned}h_{U'} & \xrightarrow{a} h_U \\ h_{U'} & \xrightarrow{s'} g^{-1}h_{V'} \\ g^{-1}h_{V'} & \xrightarrow{g^{-1}b} g^{-1}h_V \\ h_U & \xrightarrow{s} g^{-1}h_V\end{aligned}\end{gathered}$$ commutes. Then the diagram $$\begin{gathered}\begin{matrix}U' & u(V') \\ U & u(V)\end{matrix} \\[6pt] \begin{aligned}U' & \xrightarrow{f_{s'}} u(V') \\ U' & \xrightarrow{a} U \\ u(V') & \xrightarrow{u(b)} u(V) \\ U & \xrightarrow{f_s} u(V)\end{aligned}\end{gathered}$$ of schemes commutes. The reason this is true is that the same condition holds for the morphisms $(g_s, g_s^\sharp)$ constructed in Modules on Sites, Lemma Sheaves on ringed sites and local algebra (uncovered prerequisite) and the uniqueness in Étale Cohomology, Theorem The geometric construction (uncovered prerequisite).
The problem is to glue the morphisms $f_s$ to a morphism of algebraic spaces. To do this first choose a scheme $V$ and a surjective étale morphism $V \to Y$. This means that $h_V \to *$ is surjective and hence $g^{-1}h_V \to *$ is surjective too. This means there exists a scheme $U$ and a surjective étale morphism $U \to X$ and a morphism $s : h_U \to g^{-1}h_V$. Next, set $R = V \times_Y V$ and $R' = U \times_X U$. Then we get $g^{-1}h_R = g^{-1}h_V \times g^{-1}h_V$ as $g^{-1}$ is exact. Thus $s$ induces a morphism $s \times s : h_{R'} \to g^{-1}h_R$. Applying the constructions above we see that we get a commutative diagram of morphisms of schemes $$\begin{gathered}\begin{matrix}R' & \phantom{X} & R \\ U & \phantom{X} & V\end{matrix} \\[6pt] \begin{aligned}R' & \longrightarrow U \\ R' & \longrightarrow U \\ R' & \xrightarrow{f_{s \times s}} R \\ R & \longrightarrow V \\ R & \longrightarrow V \\ U & \xrightarrow{f_s} V\end{aligned}\end{gathered}$$ Since we have $X = U/R'$ and $Y = V/R$ (see Spaces, Lemma The geometric construction (uncovered prerequisite)) we conclude that this diagram defines a morphism of algebraic spaces $f : X \to Y$ fitting into an obvious commutative diagram. Now we still have to show that $(f_{small}, f^\sharp)$ is $2$-isomorphic to $(g, g^\sharp)$. Let $t_V : f_{s, small}^{-1} \to g_s^{-1}$ and $t_R : f_{s \times s, small}^{-1} \to g_{s \times s}^{-1}$ be the $2$-isomorphisms which are given to us by the construction above. Let $\mathcal{G}$ be a sheaf on $Y_\mathrm{\acute{e}tale}$. Then we see that $t_V$ defines an isomorphism $$f_{small}^{-1}\mathcal{G}|{U\mathrm{\acute{e}tale}}
f_{s, small}^{-1}\mathcal{G}|{V\mathrm{\acute{e}tale}} \xrightarrow{t_V} g_s^{-1}\mathcal{G}|{V\mathrm{\acute{e}tale}}
g^{-1}\mathcal{G}|{U\mathrm{\acute{e}tale}}.$$ Moreover, this isomorphism pulled back to $R'$ via either projection $R' \to U$ is the isomorphism $$f_{small}^{-1}\mathcal{G}|{R'\mathrm{\acute{e}tale}}
f_{s \times s, small}^{-1}\mathcal{G}|{R\mathrm{\acute{e}tale}} \xrightarrow{t_R} g_{s \times s}^{-1}\mathcal{G}|{R\mathrm{\acute{e}tale}}
g^{-1}\mathcal{G}|{R'\mathrm{\acute{e}tale}}.$$ Since ${U \to X}$ is a covering in the site $X_{spaces, \mathrm{\acute{e}tale}}$ this means the first displayed isomorphism descends to an isomorphism $t : f_{small}^{-1}\mathcal{G} \to g^{-1}\mathcal{G}$ of sheaves (small detail omitted). The isomorphism is functorial in $\mathcal{G}$ since $t_V$ and $t_R$ are transformations of functors. Finally, $t$ is compatible with $f^\sharp$ and $g^\sharp$ as $t_V$ and $t_R$ are (some details omitted). This finishes the proof of the theorem. $\square$
Lemma. Local algebra
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The morphism of ringed topoi $(f_{small}, f^\sharp)$ associated to $f$ is a morphism of locally ringed topoi, see Modules on Sites, Definition Morphisms of locally ringed topoi.
Proof. Note that the assertion makes sense since we have seen that $(X_\mathrm{\acute{e}tale}, \mathcal{O}_{X_\mathrm{\acute{e}tale}})$ and $(Y_\mathrm{\acute{e}tale}, \mathcal{O}_{Y_\mathrm{\acute{e}tale}})$ are locally ringed sites, see Lemma Étale morphisms and sheaves on ringed sites (uncovered prerequisite). Moreover, we know that $X_\mathrm{\acute{e}tale}$ has enough points, see Theorem Sheaves on ringed sites. Hence it suffices to prove that $(f_{small}, f^\sharp)$ satisfies condition (3) of Modules on Sites, Lemma Local algebra (uncovered prerequisite). To see this take a point $p$ of $X_\mathrm{\acute{e}tale}$. By Lemma Étale morphisms and sheaves on ringed sites (uncovered prerequisite) $p$ corresponds to a geometric point $\overline{x}$ of $X$. By Lemma Sheaves on ringed sites the point $q = f_{small} \circ p$ corresponds to the geometric point $\overline{y} = f \circ \overline{x}$ of $Y$. Hence the assertion we have to prove is that the induced map of étale local rings $$\mathcal{O}_{Y, \overline{y}} \longrightarrow \mathcal{O}_{X, \overline{x}}$$ is a local ring map. You can prove this directly, but instead we deduce it from the corresponding result for schemes. To do this choose a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \xrightarrow{\psi} V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes, and the vertical arrows are surjective étale (see Spaces, Lemma Lifting the geometric construction (uncovered prerequisite)). Choose a lift $\overline{u} : \overline{x} \to U$ (possible by Lemma Étale geometry of algebraic spaces (uncovered prerequisite)). Set $\overline{v} = \psi \circ \overline{u}$. We obtain a commutative diagram of étale local rings $$\begin{gathered}\begin{matrix}\mathcal{O}_{U, \overline{u}} & \mathcal{O}_{V, \overline{v}} \\ \mathcal{O}_{X, \overline{x}} & \mathcal{O}_{Y, \overline{y}}.\end{matrix} \\[6pt] \begin{aligned}\mathcal{O}_{V, \overline{v}} & \longrightarrow \mathcal{O}_{U, \overline{u}} \\ \mathcal{O}_{X, \overline{x}} & \longrightarrow \mathcal{O}_{U, \overline{u}} \\ \mathcal{O}_{Y, \overline{y}}. & \longrightarrow \mathcal{O}_{X, \overline{x}} \\ \mathcal{O}_{Y, \overline{y}}. & \longrightarrow \mathcal{O}_{V, \overline{v}}\end{aligned}\end{gathered}$$ By Étale Cohomology, Lemma Local algebra (uncovered prerequisite) the top horizontal arrow is a local ring map. Finally by Lemma Étale morphisms and local algebra the vertical arrows are isomorphisms. Hence we win. $\square$
Lemma. Descent of sheaves on ringed sites
With $S$, $\varphi : U \to X$, and $(U, R, s, t, c, e, i)$ as above. For any sheaf $\mathcal{F}$ on $X_\mathrm{\acute{e}tale}$ the sheaf[^4] $\mathcal{G} = \varphi^{-1}\mathcal{F}$ comes equipped with a canonical isomorphism $$\alpha : t^{-1}\mathcal{G} \longrightarrow s^{-1}\mathcal{G}$$ such that the diagram $$\begin{gathered}\begin{matrix}\phantom{X} & \text{pr}_1^{-1}t^{-1}\mathcal{G} & \text{pr}_1^{-1}s^{-1}\mathcal{G} & \phantom{X} \\ \text{pr}_0^{-1}s^{-1}\mathcal{G} & \phantom{X} & \phantom{X} & c^{-1}s^{-1}\mathcal{G} \\ \phantom{X} & \text{pr}_0^{-1}t^{-1}\mathcal{G} & c^{-1}t^{-1}\mathcal{G}\end{matrix} \\[6pt] \begin{aligned}\text{pr}_1^{-1}t^{-1}\mathcal{G} & \xrightarrow{\text{pr}_1^{-1}\alpha} \text{pr}_1^{-1}s^{-1}\mathcal{G} \\ \text{pr}_1^{-1}s^{-1}\mathcal{G} & \mathrel{=} c^{-1}s^{-1}\mathcal{G} \\ \text{pr}_0^{-1}s^{-1}\mathcal{G} & \mathrel{=} \text{pr}_1^{-1}t^{-1}\mathcal{G} \\ \text{pr}_0^{-1}t^{-1}\mathcal{G} & \xrightarrow{\text{pr}_0^{-1}\alpha} \text{pr}_0^{-1}s^{-1}\mathcal{G} \\ \text{pr}_0^{-1}t^{-1}\mathcal{G} & \mathrel{=} c^{-1}t^{-1}\mathcal{G} \\ c^{-1}t^{-1}\mathcal{G} & \xrightarrow{c^{-1}\alpha} c^{-1}s^{-1}\mathcal{G}\end{aligned}\end{gathered}$$ is a commutative. The functor $\mathcal{F} \mapsto (\mathcal{G}, \alpha)$ defines an equivalence of categories between sheaves on $X_\mathrm{\acute{e}tale}$ and pairs $(\mathcal{G}, \alpha)$ as above.
First proof of Lemma Descent of sheaves on ringed sites. Let \(\mathcal{C} = X_{spaces, \mathrm{\acute{e}tale}}\). By Lemma Étale morphisms and sheaves on ringed sites (uncovered prerequisite) and its proof we have \(U_{spaces, \mathrm{\acute{e}tale}} = \mathcal{C}/U\) and the pullback functor \(\varphi^{-1}\) is just the restriction functor. Moreover, \(\{U \to X\}\) is a covering of the site \(\mathcal{C}\) and \(R = U \times_X U\). The isomorphism \(\alpha\) is just the canonical identification
\[ \left(\mathcal{F}|_{\mathcal{C}/U}\right)|_{\mathcal{C}/U \times_X U} = \left(\mathcal{F}|_{\mathcal{C}/U}\right)|_{\mathcal{C}/U \times_X U} \]and the commutativity of the diagram is the cocycle condition for glueing data. Hence this lemma is a special case of glueing of sheaves, see Sites, Section The geometric construction. \(\square\)
Second proof of Lemma Descent of sheaves on ringed sites. The existence of $\alpha$ comes from the fact that $\varphi \circ t = \varphi \circ s$ and that pullback is functorial in the morphism, see Lemma Étale morphisms and sheaves on ringed sites (uncovered prerequisite). In exactly the same way, i.e., by functoriality of pullback, we see that the isomorphism $\alpha$ fits into the commutative diagram. The construction $\mathcal{F} \mapsto (\varphi^{-1}\mathcal{F}, \alpha)$ is clearly functorial in the sheaf $\mathcal{F}$. Hence we obtain the functor.
Conversely, suppose that $(\mathcal{G}, \alpha)$ is a pair. Let $V \to X$ be an object of $X_\mathrm{\acute{e}tale}$. In this case the morphism $V' = U \times_X V \to V$ is a surjective étale morphism of schemes, and hence $\{V' \to V\}$ is an étale covering of $V$. Set $\mathcal{G}' = (V' \to V)^{-1}\mathcal{G}$. Since $R = U \times_X U$ with $t = \text{pr}_0$ and $s = \text{pr}_0$ we see that $V' \times_V V' = R \times_X V$ with projection maps $s', t' : V' \times_V V' \to V'$ equal to the pullbacks of $t$ and $s$. Hence $\alpha$ pulls back to an isomorphism $\alpha' : (t')^{-1}\mathcal{G}' \to (s')^{-1}\mathcal{G}'$. Having said this we simply define $$\begin{gathered}\begin{matrix}\mathcal{F}(V) & \text{Equalizer}(\mathcal{G}(V') & \mathcal{G}(V' \times_V V').\end{matrix} \\[6pt] \begin{aligned}\mathcal{F}(V) & \mathrel{=} \text{Equalizer}(\mathcal{G}(V') \\ \text{Equalizer}(\mathcal{G}(V') & \longrightarrow \mathcal{G}(V' \times_V V'). \\ \text{Equalizer}(\mathcal{G}(V') & \longrightarrow \mathcal{G}(V' \times_V V').\end{aligned}\end{gathered}$$ We omit the verification that this defines a sheaf. To see that $\mathcal{G}(V) = \mathcal{F}(V)$ if there exists a morphism $V \to U$ note that in this case the equalizer is $H^0(\{V' \to V\}, \mathcal{G}) = \mathcal{G}(V)$. $\square$
Lemma. Dimension, codimension and local algebra
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $x \in |X|$ be a point. Let $d \in \{0, 1, 2, \ldots, \infty\}$. The following are equivalent
-
for some scheme $U$ and étale morphism $a : U \to X$ and point $u \in U$ with $a(u) = x$ we have $\dim(\mathcal{O}_{U, u}) = d$,
-
for any scheme $U$, any étale morphism $a : U \to X$, and any point $u \in U$ with $a(u) = x$ we have $\dim(\mathcal{O}_{U, u}) = d$.
If $X$ is a scheme, this is equivalent to $\dim(\mathcal{O}_{X, x}) = d$.
Proof. Combine Lemma Local algebra (uncovered prerequisite) and Descent, Lemma Dimension, codimension and local algebra (uncovered prerequisite). $\square$
Lemma. Criteria for étale morphisms and quasi-coherent complexes
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. A quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ is given by the following data:
-
for every $U \in \operatorname{Ob}(X_\mathrm{\acute{e}tale})$ a quasi-coherent $\mathcal{O}_U$-module $\mathcal{F}_U$ on $U_\mathrm{\acute{e}tale}$,
-
for every $f : U' \to U$ in $X_\mathrm{\acute{e}tale}$ an isomorphism $c_f : f_{small}^*\mathcal{F}_U \to \mathcal{F}_{U'}$.
These data are subject to the condition that given any $f : U' \to U$ and $g : U'' \to U'$ in $X_\mathrm{\acute{e}tale}$ the composition $c_g \circ g_{small}^*c_f$ is equal to $c_{f \circ g}$.
Proof. Combine Lemmas Pullback of quasi-coherent complexes and coherent sheaves and Criteria for étale morphisms and modules (uncovered prerequisite). $\square$
[^1]: Also $(f')^*(\mathcal{G}|_{Y'}) = (f^*\mathcal{G})|_{X'}$ by commutativity of the diagram and (Modules)
[^2]: Actually we use here also Schemes, Lemma The geometric construction (uncovered prerequisite) (soberness schemes), Morphisms, Lemmas Étale morphisms and flatness (uncovered prerequisite) and Flatness (uncovered prerequisite) (generalizations lift along étale morphisms), Lemma Étale geometry of algebraic spaces (points on an algebraic space in terms of a presentation), and Lemma Étale geometry of algebraic spaces (openness quotient map).
[^3]: Also $(f')_{small}^{-1}(\mathcal{G}|_{Y'}) = (f_{small}^{-1}\mathcal{G})|_{X'}$ because of commutativity of the diagram and (Étale geometry of algebraic spaces)
[^4]: In this lemma and its proof we write simply $\varphi^{-1}$ instead of $\varphi_{small}^{-1}$ and similarly for all the other pullbacks.
Derived modules on ringed sites
Lemma. Sheaf cohomology (Relative Leray spectral sequence)
Let $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ and $g : (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D}) \to (\operatorname{Sh}(\mathcal{E}), \mathcal{O}_\mathcal{E})$ be morphisms of ringed topoi. Let $\mathcal{F}$ be an $\mathcal{O}_\mathcal{C}$-module. There is a spectral sequence with $$E_2^{p, q} = R^pg_*(R^qf_*\mathcal{F})$$ converging to $R^{p + q}(g \circ f)_*\mathcal{F}$. This spectral sequence is functorial in $\mathcal{F}$, and there is a version for bounded below complexes of $\mathcal{O}_\mathcal{C}$-modules.
Proof. This is a Grothendieck spectral sequence for composition of functors, see Derived Categories, Lemma Triangulated categories and Lemmas Direct images and injective resolutions and sheaves on ringed sites and Acyclic resolutions on a ringed site. $\square$
Lemma. Derived categories
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $(K_n)$ be an inverse system of objects of $D(\mathcal{O})$. Let $\mathcal{B} \subset \operatorname{Ob}(\mathcal{C})$ be a subset. Assume
-
every object of $\mathcal{C}$ has a covering whose members are elements of $\mathcal{B}$,
-
for all $U \in \mathcal{B}$ and all $q \in \mathbf{Z}$ we have
-
$H^p(U, H^q(K_n)) = 0$ for $p > 0$,
-
the inverse system $H^0(U, H^q(K_n))$ has vanishing $R^1\varprojlim$.
-
Then $H^q(R\varprojlim K_n) = \varprojlim H^q(K_n)$ for $q \in \mathbf{Z}$.
Proof. Set $K = R\varprojlim K_n$. We will use notation as in Remark Derived categories. Let $U \in \mathcal{B}$. By Lemma Sheaf cohomology and (2)(a) we have $H^q(U, K_n) = H^0(U, H^q(K_n))$. Using that the functor $R\Gamma(U, -)$ commutes with derived limits we have $$H^q(U, K) = H^q(R\varprojlim R\Gamma(U, K_n)) = \varprojlim H^0(U, H^q(K_n))$$ where the final equality follows from More on Algebra, Remark Comparison for derived categories and assumption (2)(b). Thus $H^q(U, K)$ is the inverse limit of the sections of the sheaves $H^q(K_n)$ over $U$. Since $\varprojlim H^q(K_n)$ is a sheaf we find using assumption (1) that $H^q(K)$, which is the sheafification of the presheaf $U \mapsto H^q(U, K)$, is equal to $\varprojlim H^q(K_n)$. This proves the lemma. $\square$
Lemma. Derived categories
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $(\mathcal{F}_n)$ be an inverse system of $\mathcal{O}$-modules. Let $\mathcal{B} \subset \operatorname{Ob}(\mathcal{C})$ be a subset. Assume
-
every object of $\mathcal{C}$ has a covering whose members are elements of $\mathcal{B}$,
-
$H^p(U, \mathcal{F}_n) = 0$ for $p > 0$ and $U \in \mathcal{B}$,
-
the inverse system $\mathcal{F}_n(U)$ has vanishing $R^1\varprojlim$ for $U \in \mathcal{B}$.
Then $R\varprojlim \mathcal{F}_n = \varprojlim \mathcal{F}_n$ and we have $H^p(U, \varprojlim \mathcal{F}_n) = 0$ for $p > 0$ and $U \in \mathcal{B}$.
Proof. Set $K_n = \mathcal{F}_n$ and $K = R\varprojlim \mathcal{F}_n$. Using the notation of Remark Derived categories and assumption (2) we see that for $U \in \mathcal{B}$ we have $\underline{\mathcal{H}}_n^m(U) = 0$ when $m \not = 0$ and $\underline{\mathcal{H}}_n^0(U) = \mathcal{F}_n(U)$. From Equation (the displayed identity) and assumption (3) we see that $\underline{\mathcal{H}}^m(U) = 0$ when $m \not = 0$ and equal to $\varprojlim \mathcal{F}_n(U)$ when $m = 0$. Sheafifying using (1) we find that $\mathcal{H}^m = 0$ when $m \not = 0$ and equal to $\varprojlim \mathcal{F}_n$ when $m = 0$. Hence $K = \varprojlim \mathcal{F}_n$. Since $H^m(U, K) = \underline{\mathcal{H}}^m(U) = 0$ for $m > 0$ (see above) we see that the second assertion holds. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site and $m \in \mathbf{Z}$. Let $(K, L, M, f, g, h)$ be a distinguished triangle in $D(\mathcal{O})$.
-
If $K$ is $(m + 1)$-pseudo-coherent and $L$ is $m$-pseudo-coherent then $M$ is $m$-pseudo-coherent.
-
If $K$ and $M$ are $m$-pseudo-coherent, then $L$ is $m$-pseudo-coherent.
-
If $L$ is $(m + 1)$-pseudo-coherent and $M$ is $m$-pseudo-coherent, then $K$ is $(m + 1)$-pseudo-coherent.
Proof. Proof of (1). Let $U$ be an object of $\mathcal{C}$. Choose a covering $\{U_i \to U\}$ and maps $\alpha_i : \mathcal{K}_i^\bullet \to K|_{U_i}$ in $D(\mathcal{O}_{U_i})$ with $\mathcal{K}_i^\bullet$ strictly perfect and $H^j(\alpha_i)$ isomorphisms for $j > m + 1$ and surjective for $j = m + 1$. We may replace $\mathcal{K}_i^\bullet$ by $\sigma_{\geq m + 1}\mathcal{K}_i^\bullet$ and hence we may assume that $\mathcal{K}_i^j = 0$ for $j < m + 1$. After refining the covering we may choose maps $\beta_i : \mathcal{L}_i^\bullet \to L|_{U_i}$ in $D(\mathcal{O}_{U_i})$ with $\mathcal{L}_i^\bullet$ strictly perfect such that $H^j(\beta_i)$ is an isomorphism for $j > m$ and surjective for $j = m$. By Lemma Lifting derived modules on ringed sites we can, after refining the covering, find maps of complexes $\gamma_i : \mathcal{K}_i^\bullet \to \mathcal{L}_i^\bullet$ such that the diagrams $$\begin{gathered}\begin{matrix}K|_{U_i} & L|_{U_i} \\ \mathcal{K}_i^\bullet & \mathcal{L}_i^\bullet\end{matrix} \\[6pt] \begin{aligned}K|_{U_i} & \longrightarrow L|_{U_i} \\ \mathcal{K}_i^\bullet & \xrightarrow{\alpha_i} K|_{U_i} \\ \mathcal{K}_i^\bullet & \xrightarrow{\gamma_i} \mathcal{L}_i^\bullet \\ \mathcal{L}_i^\bullet & \xrightarrow{\beta_i} L|_{U_i}\end{aligned}\end{gathered}$$ are commutative in $D(\mathcal{O}_{U_i})$ (this requires representing the maps $\alpha_i$, $\beta_i$ and $K|_{U_i} \to L|_{U_i}$ by actual maps of complexes; some details omitted). The cone $C(\gamma_i)^\bullet$ is strictly perfect (Lemma Derived categories). The commutativity of the diagram implies that there exists a morphism of distinguished triangles $$(\mathcal{K}_i^\bullet, \mathcal{L}_i^\bullet, C(\gamma_i)^\bullet) \longrightarrow (K|_{U_i}, L|_{U_i}, M|_{U_i}).$$ It follows from the induced map on long exact cohomology sequences and Homology, Lemmas The geometric construction (uncovered prerequisite) and The geometric construction (uncovered prerequisite) that $C(\gamma_i)^\bullet \to M|_{U_i}$ induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. Hence $M$ is $m$-pseudo-coherent by Lemma Pseudo-coherent complexes and coherent sheaves.
Assertions (2) and (3) follow from (1) by rotating the distinguished triangle. $\square$
Lemma. Perfect complexes
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $(K, L, M, f, g, h)$ be a distinguished triangle in $D(\mathcal{O})$. If two out of three of $K, L, M$ are perfect then the third is also perfect.
Proof. First proof: Combine Lemmas Perfect complexes, Pseudo-coherent complexes and coherent sheaves, and Derived tensor products, Tor amplitude and derived categories. Second proof (sketch): Say $K$ and $L$ are perfect. Let $U$ be an object of $\mathcal{C}$. After replacing $U$ by the members of a covering we may assume that $K|_U$ and $L|_U$ are represented by strictly perfect complexes $\mathcal{K}^\bullet$ and $\mathcal{L}^\bullet$. After replacing $U$ by the members of a covering we may assume the map $K|_U \to L|_U$ is given by a map of complexes $\alpha : \mathcal{K}^\bullet \to \mathcal{L}^\bullet$, see Lemma A local representative for a derived object. Then $M|_U$ is isomorphic to the cone of $\alpha$ which is strictly perfect by Lemma Derived categories. $\square$
Lemma. Perfect complexes
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $E$ be an object of $D(\mathcal{O})$. The following are equivalent
-
$E$ is perfect, and
-
$E$ is pseudo-coherent and locally has finite tor dimension.
Proof. Assume (1). Let $U$ be an object of $\mathcal{C}$. By definition there exists a covering $\{U_i \to U\}$ such that $E|_{U_i}$ is represented by a strictly perfect complex. Thus $E$ is pseudo-coherent (i.e., $m$-pseudo-coherent for all $m$) by Lemma Pseudo-coherent complexes and coherent sheaves. Moreover, a direct summand of a finite free module is flat, hence $E|_{U_i}$ has finite Tor dimension by Lemma Derived tensor products and Tor amplitude. Thus (2) holds.
Assume (2). Let $U$ be an object of $\mathcal{C}$. After replacing $U$ by the members of a covering we may assume there exist integers $a \leq b$ such that $E|_U$ has tor amplitude in $[a, b]$. Since $E|_U$ is $m$-pseudo-coherent for all $m$ we conclude using Lemma Perfect complexes. $\square$
Lemma. Derived categories
Let $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \to (\operatorname{Sh}(\mathcal{C}'), \mathcal{O}')$ be a morphism of ringed topoi. There is a canonical bifunctorial isomorphism $$\mathcal{F}^\bullet \otimes_\mathcal{O}^{\mathbf{L}} Lf^*\mathcal{G}^\bullet
\mathcal{F}^\bullet \otimes_{f^{-1}\mathcal{O}'}^{\mathbf{L}} f^{-1}\mathcal{G}^\bullet$$ for $\mathcal{F}^\bullet$ in $D(\mathcal{O})$ and $\mathcal{G}^\bullet$ in $D(\mathcal{O}')$.
Proof. Let $\mathcal{F}$ be an $\mathcal{O}$-module and let $\mathcal{G}$ be an $\mathcal{O}'$-module. Then $\mathcal{F} \otimes_{\mathcal{O}} f^*\mathcal{G} = \mathcal{F} \otimes_{f^{-1}\mathcal{O}'} f^{-1}\mathcal{G}$ because $f^*\mathcal{G} = \mathcal{O} \otimes_{f^{-1}\mathcal{O}'} f^{-1}\mathcal{G}$. The lemma follows from this and the definitions. $\square$
Lemma. Perfect complexes and derived categories
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $K$ be a perfect object of $D(\mathcal{O})$. Then $K^\vee = R\mathcal{H}om(K, \mathcal{O})$ is a perfect object too and $(K^\vee)^\vee \cong K$. There are functorial isomorphisms $$M \otimes^\mathbf{L}_\mathcal{O} K^\vee = R\mathcal{H}om_\mathcal{O}(K, M)$$ and $$H^0(\mathcal{C}, M \otimes^\mathbf{L}_\mathcal{O} K^\vee) = \operatorname{Hom}_{D(\mathcal{O})}(K, M)$$ for $M$ in $D(\mathcal{O})$.
Proof. We will use without further mention that formation of internal hom commutes with restriction (Lemma Derived Hom and Ext). Let $U$ be an arbitrary object of $\mathcal{C}$. To check that $K^\vee$ is perfect, it suffices to show that there exists a covering $\{U_i \to U\}$ such that $K^\vee|_{U_i}$ is perfect for all $i$. There is a canonical map $$K = R\mathcal{H}om(\mathcal{O}, \mathcal{O}) \otimes_{\mathcal{O}}^\mathbf{L} K \longrightarrow R\mathcal{H}om(R\mathcal{H}om(K, \mathcal{O}), \mathcal{O}) = (K^\vee)^\vee$$ see Lemma Derived Hom and Ext. It suffices to prove there is a covering $\{U_i \to U\}$ such that the restriction of this map to $\mathcal{C}/U_i$ is an isomorphism for all $i$. By Lemma Derived modules on ringed sites to see the final statement it suffices to check that the map (the displayed identity) $$M \otimes^\mathbf{L}_\mathcal{O} K^\vee \longrightarrow R\mathcal{H}om(K, M)$$ is an isomorphism. This is a local question as well (in the sense above). Hence it suffices to prove the lemma when $K$ is represented by a strictly perfect complex.
Assume $K$ is represented by the strictly perfect complex $\mathcal{E}^\bullet$. Then it follows from Lemma Perfect complexes and derived Hom and Ext that $K^\vee$ is represented by the complex whose terms are $(\mathcal{E}^n)^\vee = \mathcal{H}om_\mathcal{O}(\mathcal{E}^n, \mathcal{O})$ in degree $-n$. Since $\mathcal{E}^n$ is a direct summand of a finite free $\mathcal{O}$-module, so is $(\mathcal{E}^n)^\vee$. Hence $K^\vee$ is represented by a strictly perfect complex too and we see that $K^\vee$ is perfect. The map $K \to (K^\vee)^\vee$ is an isomorphism as it is given up to sign by the evaluation maps $\mathcal{E}^n \to ((\mathcal{E}^n)^\vee)^\vee$ which are isomorphisms. To see that (the displayed identity) is an isomorphism, represent $M$ by a K-flat complex $\mathcal{F}^\bullet$. By Lemma Perfect complexes and derived Hom and Ext the complex $R\mathcal{H}om(K, M)$ is represented by the complex with terms $$\bigoplus\nolimits_{n = p + q} \mathcal{H}om_\mathcal{O}(\mathcal{E}^{-q}, \mathcal{F}^p)$$ On the other hand, the object $M \otimes^\mathbf{L}_\mathcal{O} K^\vee$ is represented by the complex with terms $$\bigoplus\nolimits_{n = p + q} \mathcal{F}^p \otimes_\mathcal{O} (\mathcal{E}^{-q})^\vee$$ Thus the assertion that (the displayed identity) is an isomorphism reduces to the assertion that the canonical map $$\mathcal{F} \otimes_\mathcal{O} \mathcal{H}om_\mathcal{O}(\mathcal{E}, \mathcal{O}) \longrightarrow \mathcal{H}om_\mathcal{O}(\mathcal{E}, \mathcal{F})$$ is an isomorphism when $\mathcal{E}$ is a direct summand of a finite free $\mathcal{O}$-module and $\mathcal{F}$ is any $\mathcal{O}$-module. This follows immediately from the corresponding statement when $\mathcal{E}$ is finite free. $\square$
Remark. Sheaf cohomology
As a consequence of the results above we find that Derived Categories, Lemma Composition and derived categories applies to a number of situations. For example, given a morphism $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ of ringed topoi we have $$R\Gamma(\mathcal{D}, Rf_*\mathcal{F}) = R\Gamma(\mathcal{C}, \mathcal{F})$$ for any sheaf of $\mathcal{O}_\mathcal{C}$-modules $\mathcal{F}$. Namely, for an injective $\mathcal{O}_\mathcal{C}$-module $\mathcal{I}$ the $\mathcal{O}_\mathcal{D}$-module $f_*\mathcal{I}$ is totally acyclic by Lemma Direct images and injective resolutions and sheaves on ringed sites and a totally acyclic sheaf is acyclic for $\Gamma(\mathcal{D}, -)$ by Lemma Acyclic resolutions on a ringed site.
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $(f, f^\sharp) : (\mathcal{C}, \mathcal{O}_\mathcal{C}) \to (\mathcal{D}, \mathcal{O}_\mathcal{D})$ be a morphism of ringed sites. Let $E$ be an object of $D(\mathcal{O}_\mathcal{C})$. If $E$ is $m$-pseudo-coherent, then $Lf^*E$ is $m$-pseudo-coherent.
Proof. Say $f$ is given by the functor $u : \mathcal{D} \to \mathcal{C}$. Let $U$ be an object of $\mathcal{C}$. By Sites, Lemma Sheaves on ringed sites (uncovered prerequisite) we can find a covering $\{U_i \to U\}$ and for each $i$ a morphism $U_i \to u(V_i)$ for some object $V_i$ of $\mathcal{D}$. By Lemma Pseudo-coherent complexes and coherent sheaves it suffices to show that $Lf^*E|_{U_i}$ is $m$-pseudo-coherent. To do this it is enough to show that $Lf^*E|_{u(V_i)}$ is $m$-pseudo-coherent, since $Lf^*E|_{U_i}$ is the restriction of $Lf^*E|_{u(V_i)}$ to $\mathcal{C}/U_i$ (via Modules on Sites, Lemma Compatibility of successive localizations of ringed sites). By the commutative diagram of Modules on Sites, Lemma Localization of a morphism of ringed sites it suffices to prove the lemma for the morphism of ringed sites $(\mathcal{C}/u(V_i), \mathcal{O}_{u(V_i)}) \to (\mathcal{D}/V_i, \mathcal{O}_{V_i})$. Thus we may assume $\mathcal{D}$ has a final object $Y$ such that $X = u(Y)$ is a final object of $\mathcal{C}$.
Let $\{V_i \to Y\}$ be a covering such that for each $i$ there exists a strictly perfect complex $\mathcal{F}_i^\bullet$ of $\mathcal{O}_{V_i}$-modules and a morphism $\alpha_i : \mathcal{F}_i^\bullet \to E|_{V_i}$ of $D(\mathcal{O}_{V_i})$ such that $H^j(\alpha_i)$ is an isomorphism for $j > m$ and $H^m(\alpha_i)$ is surjective. Arguing as above it suffices to prove the result for $(\mathcal{C}/u(V_i), \mathcal{O}_{u(V_i)}) \to (\mathcal{D}/V_i, \mathcal{O}_{V_i})$. Hence we may assume that there exists a strictly perfect complex $\mathcal{F}^\bullet$ of $\mathcal{O}_\mathcal{D}$-modules and a morphism $\alpha : \mathcal{F}^\bullet \to E$ of $D(\mathcal{O}_\mathcal{D})$ such that $H^j(\alpha)$ is an isomorphism for $j > m$ and $H^m(\alpha)$ is surjective. In this case, choose a distinguished triangle $$\mathcal{F}^\bullet \to E \to C \to \mathcal{F}^\bullet[1]$$ The assumption on $\alpha$ means exactly that the cohomology sheaves $H^j(C)$ are zero for all $j \geq m$. Applying $Lf^*$ we obtain the distinguished triangle $$Lf^*\mathcal{F}^\bullet \to Lf^*E \to Lf^*C \to Lf^*\mathcal{F}^\bullet[1]$$ By the construction of $Lf^*$ as a left derived functor we see that $H^j(Lf^*C) = 0$ for $j \geq m$ (by the dual of Derived Categories, Lemma Vanishing in negative degrees). Hence $H^j(Lf^*\alpha)$ is an isomorphism for $j > m$ and $H^m(Lf^*\alpha)$ is surjective. On the other hand, since $\mathcal{F}^\bullet$ is a bounded above complex of flat $\mathcal{O}_\mathcal{D}$-modules we see that $Lf^*\mathcal{F}^\bullet = f^*\mathcal{F}^\bullet$. Applying Lemma Perfect complexes we conclude. $\square$
Lemma. Direct images and injective resolutions and sheaves on ringed sites
Let $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi. Then for any injective object $\mathcal{I}$ in $\textit{Mod}(\mathcal{O}_\mathcal{C})$ the pushforward $f_*\mathcal{I}$ is totally acyclic.
Proof. Let $K$ be a sheaf of sets on $\mathcal{D}$. By Modules on Sites, Lemma Derived Hom, Ext and sheaves on ringed sites (uncovered prerequisite) we may replace $\mathcal{C}$, $\mathcal{D}$ by "larger" sites such that $f$ comes from a morphism of ringed sites induced by a continuous functor $u : \mathcal{D} \to \mathcal{C}$ such that $K = h_V$ for some object $V$ of $\mathcal{D}$.
Thus we have to show that \(H^q(V, f_*\mathcal{I})\) is zero for \(q > 0\) and all objects \(V\) of \(\mathcal{D}\) when \(f\) is given by a morphism of ringed sites. Let \(\mathcal{V} = \{V_j \to V\}\) be any covering of \(\mathcal{D}\). Since \(u\) is continuous we see that \(\mathcal{U} = \{u(V_j) \to u(V)\}\) is a covering of \(\mathcal{C}\). Then we have an equality of Čech complexes
\[ \check{\mathcal{C}}^\bullet(\mathcal{V}, f_*\mathcal{I}) = \check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{I}) \]by the definition of \(f_*\). By Lemma Sheaf cohomology and injective resolutions (uncovered prerequisite) we see that the cohomology of this complex is zero in positive degrees. We win by Lemma Sheaf cohomology (uncovered prerequisite). \(\square\)
Lemma. Acyclic resolutions on a ringed site
Let $(\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C})$ be a ringed topos. A totally acyclic sheaf is right acyclic for the following functors:
-
the functor $H^0(U, -)$ for any object $U$ of $\mathcal{C}$,
-
the functor $\mathcal{F} \mapsto \mathcal{F}(K)$ for any presheaf of sets $K$,
-
the functor $\Gamma(\mathcal{C}, -)$ of global sections,
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the functor $f_*$ for any morphism $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ of ringed topoi.
Proof. Part (2) is the definition of a totally acyclic sheaf. Part (1) is a consequence of (2) as pointed out in the discussion following the definition of totally acyclic sheaves. Part (3) is a special case of (2) where $K = e$ is the final object of $\operatorname{Sh}(\mathcal{C})$.
To prove (4) we may assume, by Modules on Sites, Lemma Derived Hom, Ext and sheaves on ringed sites (uncovered prerequisite) that $f$ is given by a morphism of sites. In this case we see that $R^if_*$, $i > 0$ of a totally acyclic sheaf are zero by the description of higher direct images in Lemma Derived modules on ringed sites (uncovered prerequisite). $\square$
Remark. Derived categories
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $(K_n)$ be an inverse system in $D(\mathcal{O})$. Set $K = R\varprojlim K_n$. For each $n$ and $m$ let $\mathcal{H}^m_n = H^m(K_n)$ be the $m$th cohomology sheaf of $K_n$ and similarly set $\mathcal{H}^m = H^m(K)$. Let us denote $\underline{\mathcal{H}}^m_n$ the presheaf $$U \longmapsto \underline{\mathcal{H}}^m_n(U) = H^m(U, K_n)$$ Similarly we set $\underline{\mathcal{H}}^m(U) = H^m(U, K)$. By Lemma Sheaf cohomology and sheaves on ringed sites (uncovered prerequisite) we see that $\mathcal{H}^m_n$ is the sheafification of $\underline{\mathcal{H}}^m_n$ and $\mathcal{H}^m$ is the sheafification of $\underline{\mathcal{H}}^m$. Here is a diagram $$\begin{gathered}\begin{matrix}K & \underline{\mathcal{H}}^m & \mathcal{H}^m \\ R\varprojlim K_n & \varprojlim \underline{\mathcal{H}}^m_n & \varprojlim \mathcal{H}^m_n\end{matrix} \\[6pt] \begin{aligned}K & \mathrel{=} R\varprojlim K_n \\ \underline{\mathcal{H}}^m & \longrightarrow \varprojlim \underline{\mathcal{H}}^m_n \\ \underline{\mathcal{H}}^m & \longrightarrow \mathcal{H}^m \\ \mathcal{H}^m & \longrightarrow \varprojlim \mathcal{H}^m_n \\ \varprojlim \underline{\mathcal{H}}^m_n & \longrightarrow \varprojlim \mathcal{H}^m_n\end{aligned}\end{gathered}$$ In general it may not be the case that $\varprojlim \mathcal{H}^m_n$ is the sheafification of $\varprojlim \underline{\mathcal{H}}^m_n$. If $U \in \mathcal{C}$, then we have short exact sequences
$$0 \to R^1\varprojlim \underline{\mathcal{H}}^{m - 1}_n(U) \to \underline{\mathcal{H}}^m(U) \to \varprojlim \underline{\mathcal{H}}^m_n(U) \to 0$$ by Lemma Derived modules on ringed sites (uncovered prerequisite).
Lemma. Sheaf cohomology
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $K$ be an object of $D(\mathcal{O})$. Let $\mathcal{B} \subset \operatorname{Ob}(\mathcal{C})$ be a subset. Assume
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every object of $\mathcal{C}$ has a covering whose members are elements of $\mathcal{B}$,
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$H^p(U, H^q(K)) = 0$ for all $p > 0$, $q \in \mathbf{Z}$, and $U \in \mathcal{B}$.
Then $H^q(U, K) = H^0(U, H^q(K))$ for $q \in \mathbf{Z}$ and $U \in \mathcal{B}$.
Proof. Observe that $K = R\varprojlim \tau_{\geq -n} K$ by Lemma Dimension and codimension (uncovered prerequisite) with $d = 0$. Let $U \in \mathcal{B}$. By Equation (the displayed identity) we get a short exact sequence $$0 \to R^1\varprojlim H^{q - 1}(U, \tau_{\geq -n}K) \to H^q(U, K) \to \varprojlim H^q(U, \tau_{\geq -n}K) \to 0$$ Condition (2) implies $H^q(U, \tau_{\geq -n} K) = H^0(U, H^q(\tau_{\geq -n} K))$ for all $q$ by using the spectral sequence of Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories. The spectral sequence converges because $\tau_{\geq -n}K$ is bounded below. If $n > -q$ then we have $H^q(\tau_{\geq -n}K) = H^q(K)$. Thus the systems on the left and the right of the displayed short exact sequence are eventually constant with values $H^0(U, H^{q - 1}(K))$ and $H^0(U, H^q(K))$ and the lemma follows. $\square$
Lemma. Acyclicity and the Leray spectral sequence
Let $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi. Let $\mathcal{F}$ be an $\mathcal{O}_\mathcal{C}$-module.
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If $R^qf_*\mathcal{F} = 0$ for $q > 0$, then $H^p(\mathcal{C}, \mathcal{F}) = H^p(\mathcal{D}, f_*\mathcal{F})$ for all $p$.
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If $H^p(\mathcal{D}, R^qf_*\mathcal{F}) = 0$ for all $q$ and $p > 0$, then $H^q(\mathcal{C}, \mathcal{F}) = H^0(\mathcal{D}, R^qf_*\mathcal{F})$ for all $q$.
Proof. These are two simple conditions that force the Leray spectral sequence to degenerate. You can also prove these facts directly (without using the spectral sequence) which is a good exercise in cohomology of sheaves. $\square$
Lemma. The Leray spectral sequence
Let $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi. Let $\mathcal{F}^\bullet$ be a bounded below complex of $\mathcal{O}_\mathcal{C}$-modules. There is a spectral sequence $$E_2^{p, q} = H^p(\mathcal{D}, R^qf_*(\mathcal{F}^\bullet))$$ converging to $H^{p + q}(\mathcal{C}, \mathcal{F}^\bullet)$.
Proof. This is just the Grothendieck spectral sequence Derived Categories, Lemma Triangulated categories coming from the composition of functors $\Gamma(\mathcal{C}, -) = \Gamma(\mathcal{D}, -) \circ f_*$. To see that the assumptions of Derived Categories, Lemma Triangulated categories are satisfied, see Lemmas Direct images and injective resolutions and sheaves on ringed sites and Acyclic resolutions on a ringed site. $\square$
Lemma. Injective resolutions
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $U$ be an object of $\mathcal{C}$. The restriction of a K-injective complex of $\mathcal{O}$-modules to $\mathcal{C}/U$ is a K-injective complex of $\mathcal{O}_U$-modules.
Proof. Follows immediately from Derived Categories, Lemma Injective resolutions (uncovered prerequisite) and the fact that the restriction functor has the exact left adjoint $j_!$. See discussion above. $\square$
Lemma. Derived modules on ringed sites
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $U$ be an object of $\mathcal{C}$. Denote $j : (\operatorname{Sh}(\mathcal{C}/U), \mathcal{O}_U) \to (\operatorname{Sh}(\mathcal{C}), \mathcal{O})$ the corresponding localization morphism. The restriction functor $D(\mathcal{O}) \to D(\mathcal{O}_U)$ is a right adjoint to extension by zero $j_! : D(\mathcal{O}_U) \to D(\mathcal{O})$.
Proof. We have to show that $$\operatorname{Hom}_{D(\mathcal{O})}(j_!E, F) = \operatorname{Hom}_{D(\mathcal{O}_U)}(E, F|_U)$$ Choose a complex $\mathcal{E}^\bullet$ of $\mathcal{O}_U$-modules representing $E$ and choose a K-injective complex $\mathcal{I}^\bullet$ representing $F$. By Lemma Injective resolutions the complex $\mathcal{I}^\bullet|_U$ is K-injective as well. Hence we see that the formula above becomes $$\operatorname{Hom}_{D(\mathcal{O})}(j_!\mathcal{E}^\bullet, \mathcal{I}^\bullet) = \operatorname{Hom}_{D(\mathcal{O}_U)}(\mathcal{E}^\bullet, \mathcal{I}^\bullet|_U)$$ which holds as $|_U$ and $j_!$ are adjoint functors (Modules on Sites, Lemma The geometric construction (uncovered prerequisite)) and Derived Categories, Lemma Injective resolutions (uncovered prerequisite). $\square$
Definition. Pseudo-coherent complexes
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $\mathcal{E}^\bullet$ be a complex of $\mathcal{O}$-modules. Let $m \in \mathbf{Z}$.
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We say $\mathcal{E}^\bullet$ is $m$-pseudo-coherent if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}$ and for each $i$ a morphism of complexes $\alpha_i : \mathcal{E}_i^\bullet \to \mathcal{E}^\bullet|_{U_i}$ where $\mathcal{E}_i^\bullet$ is a strictly perfect complex of $\mathcal{O}_{U_i}$-modules and $H^j(\alpha_i)$ is an isomorphism for $j > m$ and $H^m(\alpha_i)$ is surjective.
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We say $\mathcal{E}^\bullet$ is pseudo-coherent if it is $m$-pseudo-coherent for all $m$.
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We say an object $E$ of $D(\mathcal{O})$ is $m$-pseudo-coherent (resp. pseudo-coherent) if and only if it can be represented by a $m$-pseudo-coherent (resp. pseudo-coherent) complex of $\mathcal{O}$-modules.
Lemma. Finiteness of cohomology groups
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $K$ be an object of $D(\mathcal{O})$. Let $m \in \mathbf{Z}$.
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If $K$ is $m$-pseudo-coherent and $H^i(K) = 0$ for $i > m$, then $H^m(K)$ is a finite type $\mathcal{O}$-module.
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If $K$ is $m$-pseudo-coherent and $H^i(K) = 0$ for $i > m + 1$, then $H^{m + 1}(K)$ is a finitely presented $\mathcal{O}$-module.
Proof. Proof of (1). Let $U$ be an object of $\mathcal{C}$. We have to show that $H^m(K)$ can be generated by finitely many sections over the members of a covering of $U$ (see Modules on Sites, Definition Local ringed sites). Thus during the proof we may (finitely often) choose a covering $\{U_i \to U\}$ and replace $\mathcal{C}$ by $\mathcal{C}/U_i$ and $U$ by $U_i$. In particular, by our definitions we may assume there exists a strictly perfect complex $\mathcal{E}^\bullet$ and a map $\alpha : \mathcal{E}^\bullet \to K$ which induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. It suffices to prove the result for $\mathcal{E}^\bullet$. Let $n$ be the largest integer such that $\mathcal{E}^n \not = 0$. If $n = m$, then $H^m(\mathcal{E}^\bullet)$ is a quotient of $\mathcal{E}^n$ and the result is clear. If $n > m$, then $\mathcal{E}^{n - 1} \to \mathcal{E}^n$ is surjective as $H^n(\mathcal{E}^\bullet) = 0$. By Lemma Local algebra (uncovered prerequisite) we can (after replacing $U$ by the members of a covering) find a section of this surjection and write $\mathcal{E}^{n - 1} = \mathcal{E}' \oplus \mathcal{E}^n$. Hence it suffices to prove the result for the complex $(\mathcal{E}')^\bullet$ which is the same as $\mathcal{E}^\bullet$ except has $\mathcal{E}'$ in degree $n - 1$ and $0$ in degree $n$. We win by induction on $n$.
Proof of (2). Pick an object $U$ of $\mathcal{C}$. As in the proof of (1) we may work locally on $U$. Hence we may assume there exists a strictly perfect complex $\mathcal{E}^\bullet$ and a map $\alpha : \mathcal{E}^\bullet \to K$ which induces an isomorphism on cohomology in degrees $> m$ and a surjection in degree $m$. As in the proof of (1) we can reduce to the case that $\mathcal{E}^i = 0$ for $i > m + 1$. Then we see that $H^{m + 1}(K) \cong H^{m + 1}(\mathcal{E}^\bullet) = \operatorname{Coker}(\mathcal{E}^m \to \mathcal{E}^{m + 1})$ which is of finite presentation. $\square$
Lemma. Perfect complexes
Let $(f, f^\sharp) : (\mathcal{C}, \mathcal{O}_\mathcal{C}) \to (\mathcal{D}, \mathcal{O}_\mathcal{D})$ be a morphism of ringed sites. Let $E$ be an object of $D(\mathcal{O}_\mathcal{D})$. If $E$ is perfect in $D(\mathcal{O}_\mathcal{D})$, then $Lf^*E$ is perfect in $D(\mathcal{O}_\mathcal{C})$.
Proof. This follows from Lemma Perfect complexes, Derived tensor products and Tor amplitude (uncovered prerequisite), and Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Lifting derived modules on ringed sites
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $U$ be an object of $\mathcal{C}$. Given a solid diagram of complexes of $\mathcal{O}_U$-modules $$\begin{gathered}\begin{matrix}\mathcal{E}^\bullet & \mathcal{F}^\bullet \\ \phantom{X} & \mathcal{G}^\bullet\end{matrix} \\[6pt] \begin{aligned}\mathcal{E}^\bullet & \cdots\!\!\rightarrow \mathcal{G}^\bullet \\ \mathcal{E}^\bullet & \xrightarrow{\alpha} \mathcal{F}^\bullet \\ \mathcal{G}^\bullet & \xrightarrow{f} \mathcal{F}^\bullet\end{aligned}\end{gathered}$$ with $\mathcal{E}^\bullet$ strictly perfect, $\mathcal{E}^j = 0$ for $j < a$ and $H^j(f)$ an isomorphism for $j > a$ and surjective for $j = a$, then there exists a covering $\{U_i \to U\}$ and for each $i$ a dotted arrow over $U_i$ making the diagram commute up to homotopy.
Proof. Our assumptions on $f$ imply the cone $C(f)^\bullet$ has vanishing cohomology sheaves in degrees $\geq a$. Hence Lemma Local algebra (uncovered prerequisite) guarantees there is a covering $\{U_i \to U\}$ such that the composition $\mathcal{E}^\bullet \to \mathcal{F}^\bullet \to C(f)^\bullet$ is homotopic to zero over $U_i$. Since $$\mathcal{G}^\bullet \to \mathcal{F}^\bullet \to C(f)^\bullet \to \mathcal{G}^\bullet[1]$$ restricts to a distinguished triangle in $K(\mathcal{O}_{U_i})$ we see that we can lift $\alpha|_{U_i}$ up to homotopy to a map $\alpha_i : \mathcal{E}^\bullet|_{U_i} \to \mathcal{G}^\bullet|_{U_i}$ as desired. $\square$
Lemma. Derived categories
The cone on a morphism of strictly perfect complexes is strictly perfect.
Proof. This is immediate from the definitions. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $E$ be an object of $D(\mathcal{O})$.
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If $\mathcal{C}$ has a final object $X$ and if there exist a covering $\{U_i \to X\}$, strictly perfect complexes $\mathcal{E}_i^\bullet$ of $\mathcal{O}_{U_i}$-modules, and maps $\alpha_i : \mathcal{E}_i^\bullet \to E|_{U_i}$ in $D(\mathcal{O}_{U_i})$ with $H^j(\alpha_i)$ an isomorphism for $j > m$ and $H^m(\alpha_i)$ surjective, then $E$ is $m$-pseudo-coherent.
-
If $E$ is $m$-pseudo-coherent, then any complex of $\mathcal{O}$-modules representing $E$ is $m$-pseudo-coherent.
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If for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}$ such that $E|_{U_i}$ is $m$-pseudo-coherent, then $E$ is $m$-pseudo-coherent.
Proof. Let $\mathcal{F}^\bullet$ be any complex representing $E$ and let $X$, $\{U_i \to X\}$, and $\alpha_i : \mathcal{E}_i \to E|_{U_i}$ be as in (1). We will show that $\mathcal{F}^\bullet$ is $m$-pseudo-coherent as a complex, which will prove (1) and (2) in case $\mathcal{C}$ has a final object. By Lemma A local representative for a derived object we can after refining the covering $\{U_i \to X\}$ represent the maps $\alpha_i$ by maps of complexes $\alpha_i : \mathcal{E}_i^\bullet \to \mathcal{F}^\bullet|_{U_i}$. By assumption $H^j(\alpha_i)$ are isomorphisms for $j > m$, and $H^m(\alpha_i)$ is surjective whence $\mathcal{F}^\bullet$ is $m$-pseudo-coherent.
Proof of (2). By the above we see that $\mathcal{F}^\bullet|_U$ is $m$-pseudo-coherent as a complex of $\mathcal{O}_U$-modules for all objects $U$ of $\mathcal{C}$. It is a formal consequence of the definitions that $\mathcal{F}^\bullet$ is $m$-pseudo-coherent.
Proof of (3). Follows from the definitions and Sites, Definition Sheaves on ringed sites part (2). $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $(K, L, M, f, g, h)$ be a distinguished triangle in $D(\mathcal{O})$. Let $a, b \in \mathbf{Z}$.
-
If $K$ has tor-amplitude in $[a + 1, b + 1]$ and $L$ has tor-amplitude in $[a, b]$ then $M$ has tor-amplitude in $[a, b]$.
-
If $K$ and $M$ have tor-amplitude in $[a, b]$, then $L$ has tor-amplitude in $[a, b]$.
-
If $L$ has tor-amplitude in $[a + 1, b + 1]$ and $M$ has tor-amplitude in $[a, b]$, then $K$ has tor-amplitude in $[a + 1, b + 1]$.
Proof. Omitted. Hint: This just follows from the long exact cohomology sequence associated to a distinguished triangle and the fact that $- \otimes_\mathcal{O}^{\mathbf{L}} \mathcal{F}$ preserves distinguished triangles. The easiest one to prove is (2) and the others follow from it by translation. $\square$
Lemma. A local representative for a derived object
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $U$ be an object of $\mathcal{C}$. Let $\mathcal{E}^\bullet$, $\mathcal{F}^\bullet$ be complexes of $\mathcal{O}_U$-modules with $\mathcal{E}^\bullet$ strictly perfect.
-
For any element $\alpha \in \operatorname{Hom}_{D(\mathcal{O}_U)}(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ there exists a covering $\{U_i \to U\}$ such that $\alpha|_{U_i}$ is given by a morphism of complexes $\alpha_i : \mathcal{E}^\bullet|_{U_i} \to \mathcal{F}^\bullet|_{U_i}$.
-
Given a morphism of complexes $\alpha : \mathcal{E}^\bullet \to \mathcal{F}^\bullet$ whose image in the group $\operatorname{Hom}_{D(\mathcal{O}_U)}(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ is zero, there exists a covering $\{U_i \to U\}$ such that $\alpha|_{U_i}$ is homotopic to zero.
Proof. Proof of (1). By the construction of the derived category we can find a quasi-isomorphism $f : \mathcal{F}^\bullet \to \mathcal{G}^\bullet$ and a map of complexes $\beta : \mathcal{E}^\bullet \to \mathcal{G}^\bullet$ such that $\alpha = f^{-1}\beta$. Thus the result follows from Lemma Lifting derived modules on ringed sites. We omit the proof of (2). $\square$
Lemma. Sheaf cohomology
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $\mathcal{F}$ be a sheaf of $\mathcal{O}$-modules. Let $U$ be an object of $\mathcal{C}$. Let $n > 0$ and let $\xi \in H^n(U, \mathcal{F})$. Then there exists a covering $\{U_i \to U\}$ of $\mathcal{C}$ such that $\xi|_{U_i} = 0$ for all $i \in I$.
Proof. Let $\mathcal{F} \to \mathcal{I}^\bullet$ be an injective resolution. Then $$H^n(U, \mathcal{F}) = \frac{\operatorname{Ker}(\mathcal{I}^n(U) \to \mathcal{I}^{n + 1}(U))} {\operatorname{Im}(\mathcal{I}^{n - 1}(U) \to \mathcal{I}^n(U))}.$$ Pick an element $\tilde \xi \in \mathcal{I}^n(U)$ representing the cohomology class in the presentation above. Since $\mathcal{I}^\bullet$ is an injective resolution of $\mathcal{F}$ and $n > 0$ we see that the complex $\mathcal{I}^\bullet$ is exact in degree $n$. Hence $\operatorname{Im}(\mathcal{I}^{n - 1} \to \mathcal{I}^n) = \operatorname{Ker}(\mathcal{I}^n \to \mathcal{I}^{n + 1})$ as sheaves. Since $\tilde \xi$ is a section of the kernel sheaf over $U$ we conclude there exists a covering $\{U_i \to U\}$ of the site such that $\tilde \xi|_{U_i}$ is the image under $d$ of a section $\xi_i \in \mathcal{I}^{n - 1}(U_i)$. By our definition of the restriction $\xi|_{U_i}$ as corresponding to the class of $\tilde \xi|_{U_i}$ we conclude. $\square$
Lemma. Perfect complexes
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $E$ be an object of $D(\mathcal{O})$.
-
If $\mathcal{C}$ has a final object $X$ and there exist a covering $\{U_i \to X\}$, strictly perfect complexes $\mathcal{E}_i^\bullet$ of $\mathcal{O}_{U_i}$-modules, and isomorphisms $\alpha_i : \mathcal{E}_i^\bullet \to E|_{U_i}$ in $D(\mathcal{O}_{U_i})$, then $E$ is perfect.
-
If $E$ is perfect, then any complex representing $E$ is perfect.
Proof. Identical to the proof of Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Remark. The comparison maps for derived base change
Let $h : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \to (\operatorname{Sh}(\mathcal{C}'), \mathcal{O}')$ be a morphism of ringed topoi. Let $K, L$ be objects of $D(\mathcal{O}')$. We claim there is a canonical map $$Lh^*R\mathcal{H}om(K, L) \longrightarrow R\mathcal{H}om(Lh^*K, Lh^*L)$$ in $D(\mathcal{O})$. Namely, by (Derived Hom and Ext) proved in Lemma Derived Hom and Ext (uncovered prerequisite) such a map is the same thing as a map $$Lh^*R\mathcal{H}om(K, L) \otimes^\mathbf{L} Lh^*K \longrightarrow Lh^*L$$ The source of this arrow is $Lh^*(\mathcal{H}om(K, L) \otimes^\mathbf{L} K)$ by Lemma Pullback of tensor products and direct sums hence it suffices to construct a canonical map $$R\mathcal{H}om(K, L) \otimes^\mathbf{L} K \longrightarrow L.$$ For this we take the arrow corresponding to $$\text{id} : R\mathcal{H}om(K, L) \longrightarrow R\mathcal{H}om(K, L)$$ via (Derived Hom and Ext).
Lemma. Derived tensor products and Tor amplitude
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $E$ be an object of $D(\mathcal{O})$. Let $a, b \in \mathbf{Z}$ with $a \leq b$. The following are equivalent
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$E$ has tor-amplitude in $[a, b]$.
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$E$ is represented by a complex $\mathcal{E}^\bullet$ of flat $\mathcal{O}$-modules with $\mathcal{E}^i = 0$ for $i \not \in [a, b]$.
Proof. If (2) holds, then we may compute $E \otimes_\mathcal{O}^\mathbf{L} \mathcal{F} = \mathcal{E}^\bullet \otimes_\mathcal{O} \mathcal{F}$ and it is clear that (1) holds.
Assume that (1) holds. We may represent $E$ by a bounded above complex of flat $\mathcal{O}$-modules $\mathcal{K}^\bullet$, see Section Flatness. Let $n$ be the largest integer such that $\mathcal{K}^n \not = 0$. If $n > b$, then $\mathcal{K}^{n - 1} \to \mathcal{K}^n$ is surjective as $H^n(\mathcal{K}^\bullet) = 0$. As $\mathcal{K}^n$ is flat we see that $\operatorname{Ker}(\mathcal{K}^{n - 1} \to \mathcal{K}^n)$ is flat (Modules on Sites, Lemma Flat modules in a short exact sequence (uncovered prerequisite)). Hence we may replace $\mathcal{K}^\bullet$ by $\tau_{\leq n - 1}\mathcal{K}^\bullet$. Thus, by induction on $n$, we reduce to the case that $\mathcal{K}^\bullet$ is a complex of flat $\mathcal{O}$-modules with $\mathcal{K}^i = 0$ for $i > b$.
Set $\mathcal{E}^\bullet = \tau_{\geq a}\mathcal{K}^\bullet$. Everything is clear except that $\mathcal{E}^a$ is flat which follows immediately from Lemma Flatness (uncovered prerequisite) and the definitions. $\square$
Lemma. Perfect complexes
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $E$ be an object of $D(\mathcal{O})$. Let $a \leq b$ be integers. If $E$ has tor amplitude in $[a, b]$ and is $(a - 1)$-pseudo-coherent, then $E$ is perfect.
Proof. Let $U$ be an object of $\mathcal{C}$. After replacing $U$ by the members of a covering and $\mathcal{C}$ by the localization $\mathcal{C}/U$ we may assume there exists a strictly perfect complex $\mathcal{E}^\bullet$ and a map $\alpha : \mathcal{E}^\bullet \to E$ such that $H^i(\alpha)$ is an isomorphism for $i \geq a$. We may and do replace $\mathcal{E}^\bullet$ by $\sigma_{\geq a - 1}\mathcal{E}^\bullet$. Choose a distinguished triangle $$\mathcal{E}^\bullet \to E \to C \to \mathcal{E}^\bullet[1]$$ From the vanishing of cohomology sheaves of $E$ and $\mathcal{E}^\bullet$ and the assumption on $\alpha$ we obtain $C \cong \mathcal{K}[2 - a]$ with $\mathcal{K} = \operatorname{Ker}(\mathcal{E}^{a - 1} \to \mathcal{E}^a)$. Let $\mathcal{F}$ be an $\mathcal{O}$-module. Applying $- \otimes_\mathcal{O}^\mathbf{L} \mathcal{F}$ the assumption that $E$ has tor amplitude in $[a, b]$ implies $\mathcal{K} \otimes_\mathcal{O} \mathcal{F} \to \mathcal{E}^{a - 1} \otimes_\mathcal{O} \mathcal{F}$ has image $\operatorname{Ker}(\mathcal{E}^{a - 1} \otimes_\mathcal{O} \mathcal{F} \to \mathcal{E}^a \otimes_\mathcal{O} \mathcal{F})$. It follows that $\text{Tor}_1^\mathcal{O}(\mathcal{E}', \mathcal{F}) = 0$ where $\mathcal{E}' = \operatorname{Coker}(\mathcal{E}^{a - 1} \to \mathcal{E}^a)$. Hence $\mathcal{E}'$ is flat (Lemma Tor vanishing for a flat module (uncovered prerequisite)). Thus there exists a covering $\{U_i \to U\}$ such that $\mathcal{E}'|_{U_i}$ is a direct summand of a finite free module by Modules on Sites, Lemma Finite presentation and flatness (uncovered prerequisite). Thus the complex $$\mathcal{E}'|_{U_i} \to \mathcal{E}^{a + 1}|_{U_i} \to \ldots \to \mathcal{E}^b|_{U_i}$$ is quasi-isomorphic to $E|_{U_i}$ and $E$ is perfect. $\square$
Lemma. Pullback of tensor products and direct sums
Let $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}')$ be a morphism of ringed topoi. There is a canonical bifunctorial isomorphism $$Lf^*( \mathcal{F}^\bullet \otimes_{\mathcal{O}'}^{\mathbf{L}} \mathcal{G}^\bullet ) = Lf^*\mathcal{F}^\bullet \otimes_{\mathcal{O}}^{\mathbf{L}} Lf^*\mathcal{G}^\bullet$$ for $\mathcal{F}^\bullet, \mathcal{G}^\bullet \in \operatorname{Ob}(D(\mathcal{O}'))$.
Proof. By our construction of derived pullback in Lemma Base change for derived categories (uncovered prerequisite). and the existence of resolutions in Lemma Derived tensor products, Tor amplitude and flatness (uncovered prerequisite) we may replace $\mathcal{F}^\bullet$ and $\mathcal{G}^\bullet$ by complexes of $\mathcal{O}'$-modules which are K-flat and have flat terms. In this case $\mathcal{F}^\bullet \otimes_{\mathcal{O}'}^{\mathbf{L}} \mathcal{G}^\bullet$ is just the total complex associated to the double complex $\mathcal{F}^\bullet \otimes_{\mathcal{O}'} \mathcal{G}^\bullet$. The complex $\text{Tot}(\mathcal{F}^\bullet \otimes_{\mathcal{O}'} \mathcal{G}^\bullet)$ is K-flat with flat terms by Lemma Derived tensor products, Tor amplitude and flatness (uncovered prerequisite) and Modules on Sites, Lemma Flatness and tensor products and direct sums (uncovered prerequisite). Hence the isomorphism of the lemma comes from the isomorphism $$\text{Tot}(f^*\mathcal{F}^\bullet \otimes_{\mathcal{O}} f^*\mathcal{G}^\bullet) \longrightarrow f^*\text{Tot}(\mathcal{F}^\bullet \otimes_{\mathcal{O}'} \mathcal{G}^\bullet)$$ whose constituents are the isomorphisms $f^*\mathcal{F}^p \otimes_{\mathcal{O}} f^*\mathcal{G}^q \to f^*(\mathcal{F}^p \otimes_{\mathcal{O}'} \mathcal{G}^q)$ of Modules on Sites, Lemma Tensor products and direct sums (uncovered prerequisite). $\square$
Lemma. Adjunction for derived direct image
Let $f : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}')$ be a morphism of ringed topoi. The functor $Rf_*$ defined above and the functor $Lf^*$ defined in Lemma Base change for derived categories (uncovered prerequisite) are adjoint: $$\operatorname{Hom}_{D(\mathcal{O})}(Lf^*\mathcal{G}^\bullet, \mathcal{F}^\bullet)
\operatorname{Hom}{D(\mathcal{O}')}(\mathcal{G}^\bullet, Rf*\mathcal{F}^\bullet)$$ bifunctorially in $\mathcal{F}^\bullet \in \operatorname{Ob}(D(\mathcal{O}))$ and $\mathcal{G}^\bullet \in \operatorname{Ob}(D(\mathcal{O}'))$.
Proof. This follows formally from the fact that $Rf_*$ and $Lf^*$ exist, see Derived Categories, Lemma Derived categories (uncovered prerequisite). $\square$
Lemma. Derived Hom and Ext
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $K, L$ be objects of $D(\mathcal{O})$. The construction of $R\mathcal{H}om(K, L)$ commutes with restrictions, i.e., for every object $U$ of $\mathcal{C}$ we have $R\mathcal{H}om(K|_U, L|_U) = R\mathcal{H}om(K, L)|_U$.
Proof. This is clear from the construction and Lemma Injective resolutions. $\square$
Lemma. Derived Hom and Ext
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $K, L, M$ be objects of $D(\mathcal{O})$. There is a canonical morphism $$R\mathcal{H}om(L, M) \otimes_\mathcal{O}^\mathbf{L} K \longrightarrow R\mathcal{H}om(R\mathcal{H}om(K, L), M)$$ in $D(\mathcal{O})$ functorial in $K, L, M$.
Proof. Choose a K-injective complex $\mathcal{I}^\bullet$ representing $M$, a K-injective complex $\mathcal{J}^\bullet$ representing $L$, and a K-flat complex $\mathcal{K}^\bullet$ representing $K$. The map is defined using the map $$\text{Tot}(\mathcal{H}om^\bullet(\mathcal{J}^\bullet, \mathcal{I}^\bullet) \otimes_\mathcal{O} \mathcal{K}^\bullet) \longrightarrow \mathcal{H}om^\bullet(\mathcal{H}om^\bullet(\mathcal{K}^\bullet, \mathcal{J}^\bullet), \mathcal{I}^\bullet)$$ of Lemma Derived modules on ringed sites (uncovered prerequisite). By our particular choice of complexes the left hand side represents $R\mathcal{H}om(L, M) \otimes_\mathcal{O}^\mathbf{L} K$ and the right hand side represents $R\mathcal{H}om(R\mathcal{H}om(K, L), M)$. We omit the proof that this is functorial in all three objects of $D(\mathcal{O})$. $\square$
Lemma. Derived modules on ringed sites
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $L$ be an object of $D(\mathcal{O})$. Set $L^\vee = R\mathcal{H}om(L, \mathcal{O})$. For $M$ in $D(\mathcal{O})$ there is a canonical map
$$M \otimes^\mathbf{L}_\mathcal{O} L^\vee \longrightarrow R\mathcal{H}om(L, M)$$ which induces a canonical map $$H^0(\mathcal{C}, M \otimes_\mathcal{O}^\mathbf{L} L^\vee) \longrightarrow \operatorname{Hom}_{D(\mathcal{O})}(L, M)$$ functorial in $M$ in $D(\mathcal{O})$.
Proof. The map (the displayed identity) is a special case of Lemma Derived Hom and Ext (uncovered prerequisite) using the identification $M = R\mathcal{H}om(\mathcal{O}, M)$. $\square$
Lemma. Perfect complexes and derived Hom and Ext
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $\mathcal{E}^\bullet$, $\mathcal{F}^\bullet$ be complexes of $\mathcal{O}$-modules with $\mathcal{E}^\bullet$ strictly perfect. Then the internal hom $R\mathcal{H}om(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ is represented by the complex $\mathcal{H}^\bullet$ with terms $$\mathcal{H}^n = \bigoplus\nolimits_{n = p + q} \mathcal{H}om_\mathcal{O}(\mathcal{E}^{-q}, \mathcal{F}^p)$$ and differential as described in Section Derived Hom and Ext.
Proof. Choose a quasi-isomorphism $\mathcal{F}^\bullet \to \mathcal{I}^\bullet$ into a K-injective complex. Let $(\mathcal{H}')^\bullet$ be the complex with terms $$(\mathcal{H}')^n = \prod\nolimits_{n = p + q} \mathcal{H}om_\mathcal{O}(\mathcal{E}^{-q}, \mathcal{I}^p)$$ which represents $R\mathcal{H}om(\mathcal{E}^\bullet, \mathcal{F}^\bullet)$ by the construction in Section Derived Hom and Ext. It suffices to show that the map $$\mathcal{H}^\bullet \longrightarrow (\mathcal{H}')^\bullet$$ is a quasi-isomorphism. Given an object $U$ of $\mathcal{C}$ we have by inspection $$H^0(\mathcal{H}^\bullet(U)) = \operatorname{Hom}_{K(\mathcal{O}_U)}(\mathcal{E}^\bullet|_U, \mathcal{I}^\bullet|_U) \to H^0((\mathcal{H}')^\bullet(U)) = \operatorname{Hom}_{D(\mathcal{O}_U)}(\mathcal{E}^\bullet|_U, \mathcal{I}^\bullet|_U)$$ By Lemma A local representative for a derived object the sheafification of $U \mapsto H^0(\mathcal{H}^\bullet(U))$ is equal to the sheafification of $U \mapsto H^0((\mathcal{H}')^\bullet(U))$. A similar argument can be given for the other cohomology sheaves. Thus $\mathcal{H}^\bullet$ is quasi-isomorphic to $(\mathcal{H}')^\bullet$ which proves the lemma. $\square$
Remark. Base change for derived modules on ringed sites
The construction of unbounded derived functor $Lf^*$ and $Rf_*$ allows one to construct the base change map in full generality. Namely, suppose that $$\begin{gathered}\begin{matrix}(\operatorname{Sh}(\mathcal{C}'), \mathcal{O}_{\mathcal{C}'}) & (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \\ (\operatorname{Sh}(\mathcal{D}'), \mathcal{O}_{\mathcal{D}'}) & (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})\end{matrix} \\[6pt] \begin{aligned}(\operatorname{Sh}(\mathcal{C}'), \mathcal{O}_{\mathcal{C}'}) & \xrightarrow{g'} (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \\ (\operatorname{Sh}(\mathcal{C}'), \mathcal{O}_{\mathcal{C}'}) & \xrightarrow{f'} (\operatorname{Sh}(\mathcal{D}'), \mathcal{O}_{\mathcal{D}'}) \\ (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) & \xrightarrow{f} (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D}) \\ (\operatorname{Sh}(\mathcal{D}'), \mathcal{O}_{\mathcal{D}'}) & \xrightarrow{g} (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})\end{aligned}\end{gathered}$$ is a commutative diagram of ringed topoi. Let $K$ be an object of $D(\mathcal{O}_\mathcal{C})$. Then there exists a canonical base change map $$Lg^*Rf_*K \longrightarrow R(f')_*L(g')^*K$$ in $D(\mathcal{O}_{\mathcal{D}'})$. Namely, this map is adjoint to a map $L(f')^*Lg^*Rf_*K \to L(g')^*K$. Since $L(f')^* \circ Lg^* = L(g')^* \circ Lf^*$ we see this is the same as a map $L(g')^*Lf^*Rf_*K \to L(g')^*K$ which we can take to be $L(g')^*$ of the adjunction map $Lf^*Rf_*K \to K$.
Lemma. Perfect complexes
Let $(f, f^\sharp) : (\mathcal{C}, \mathcal{O}_\mathcal{C}) \to (\mathcal{D}, \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi. If $\mathcal{F}^\bullet$ is a strictly perfect complex of $\mathcal{O}_\mathcal{D}$-modules, then $f^*\mathcal{F}^\bullet$ is a strictly perfect complex of $\mathcal{O}_\mathcal{C}$-modules.
Proof. We have seen in Modules on Sites, Lemma Global pullback on a ringed site that the pullback of a finite free module is finite free. The functor $f^*$ is additive functor hence preserves direct summands. The lemma follows. $\square$
Lemma. Derived Hom and Ext
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $L, M$ be objects of $D(\mathcal{O})$. For every object $U$ of $\mathcal{C}$ we have $$H^0(U, R\mathcal{H}om(L, M)) = \operatorname{Hom}_{D(\mathcal{O}_U)}(L|_U, M|_U)$$ and we have $H^0(\mathcal{C}, R\mathcal{H}om(L, M)) = \operatorname{Hom}_{D(\mathcal{O})}(L, M)$.
Proof. Choose a K-injective complex $\mathcal{I}^\bullet$ of $\mathcal{O}$-modules representing $M$ and a K-flat complex $\mathcal{L}^\bullet$ representing $L$. Then $\mathcal{H}om^\bullet(\mathcal{L}^\bullet, \mathcal{I}^\bullet)$ is K-injective by Lemma Derived Hom, Ext and derived tensor products and Tor amplitude (uncovered prerequisite). Hence we can compute cohomology over $U$ by simply taking sections over $U$ and the result follows from Lemma Derived Hom, Ext and injective resolutions (uncovered prerequisite). $\square$
Derived quasi-coherent constructions
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $E$ be an object of $D(\mathcal{O}_X)$. The following are equivalent
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$E$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$,
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for every étale morphism $\varphi : U \to X$ where $U$ is an affine scheme $\varphi^*E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_U)$,
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for every étale morphism $\varphi : U \to X$ where $U$ is a scheme $\varphi^*E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_U)$,
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there exists a surjective étale morphism $\varphi : U \to X$ where $U$ is a scheme such that $\varphi^*E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_U)$, and
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there exists a surjective étale morphism of algebraic spaces $f : Y \to X$ such that $Lf^*E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_Y)$.
Proof. This follows immediately from the discussion preceding the lemma and Properties of Spaces, Lemma Criteria for quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Computing derived Hom with a quasi-coherent K-injective model
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $F : \textit{Mod}(\mathcal{O}_X) \to \textit{Ab}$ be a functor and $N \geq 0$ an integer. Assume that
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$F$ is left exact,
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$F$ commutes with countable direct products,
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$R^pF(\mathcal{F}) = 0$ for all $p \geq N$ and $\mathcal{F}$ quasi-coherent.
Then for $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$
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$H^i(RF(\tau_{\leq a}E)) \to H^i(RF(E))$ is an isomorphism for $i \leq a$,
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$H^i(RF(E)) \to H^i(RF(\tau_{\geq b - N + 1}E))$ is an isomorphism for $i \geq b$,
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if $H^i(E) = 0$ for $i \not \in [a, b]$ for some $-\infty \leq a \leq b \leq \infty$, then $H^i(RF(E)) = 0$ for $i \not \in [a, b + N - 1]$.
Proof. Statement (1) is Derived Categories, Lemma Vanishing in negative degrees.
Proof of statement (2). Write $E_n = \tau_{\geq -n}E$. We have $E = R\varprojlim E_n$, see Lemma A K-injective representative compatible with quasi-coherence. Thus $RF(E) = R\varprojlim RF(E_n)$ in $D(\textit{Ab})$ by Injectives, Lemma The geometric construction (uncovered prerequisite). Thus for every $i \in \mathbf{Z}$ we have a short exact sequence $$0 \to R^1\varprojlim H^{i - 1}(RF(E_n)) \to H^i(RF(E)) \to \varprojlim H^i(RF(E_n)) \to 0$$ see More on Algebra, Remark Comparison for derived categories. To prove (2) we will show that the term on the left is zero and that the term on the right equals $H^i(RF(E_{-b + N - 1})$ for any $b$ with $i \geq b$.
For every $n$ we have a distinguished triangle $$H^{-n}(E)[n] \to E_n \to E_{n - 1} \to H^{-n}(E)[n + 1]$$ (Derived Categories, Remark Derived categories) in $D(\mathcal{O}_X)$. Since $H^{-n}(E)$ is quasi-coherent we have $$H^i(RF(H^{-n}(E)[n])) = R^{i + n}F(H^{-n}(E)) = 0$$ for $i + n \geq N$ and $$H^i(RF(H^{-n}(E)[n + 1])) = R^{i + n + 1}F(H^{-n}(E)) = 0$$ for $i + n + 1 \geq N$. We conclude that $$H^i(RF(E_n)) \to H^i(RF(E_{n - 1}))$$ is an isomorphism for $n \geq N - i$. Thus the systems $H^i(RF(E_n))$ all satisfy the ML condition and the $R^1\varprojlim$ term in our short exact sequence is zero (see discussion in More on Algebra, Section Derived commutative algebra). Moreover, the system $H^i(RF(E_n))$ is constant starting with $n = N - i - 1$ as desired.
Proof of (3). Under the assumption on $E$ we have $\tau_{\leq a - 1}E = 0$ and we get the vanishing of $H^i(RF(E))$ for $i \leq a - 1$ from (1). Similarly, we have $\tau_{\geq b + 1}E = 0$ and hence we get the vanishing of $H^i(RF(E))$ for $i \geq b + N$ from part (2). $\square$
Lemma. Proper morphisms and modules
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $\mathcal{F}$ be a finite type, quasi-coherent $\mathcal{O}_X$-module. The following are equivalent
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the support of $\mathcal{F}$ is proper over $Y$,
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the scheme theoretic support of $\mathcal{F}$ (Morphisms of Spaces, Definition Closed support) is proper over $Y$, and
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there exists a closed subspace $Z \subset X$ and a finite type, quasi-coherent $\mathcal{O}_Z$-module $\mathcal{G}$ such that (a) $Z \to Y$ is proper, and (b) $(Z \to X)_*\mathcal{G} = \mathcal{F}$.
Proof. The support $\text{Supp}(\mathcal{F})$ of $\mathcal{F}$ is a closed subset of $|X|$, see Morphisms of Spaces, Lemma Closed support and finite algebras. Hence we can apply Definition Proper morphisms. Since the scheme theoretic support of $\mathcal{F}$ is a closed subspace whose underlying closed subset is $\text{Supp}(\mathcal{F})$ we see that (1) and (2) are equivalent by Definition Proper morphisms. It is clear that (2) implies (3). Conversely, if (3) is true, then $\text{Supp}(\mathcal{F}) \subset |Z|$ and hence $\text{Supp}(\mathcal{F})$ is proper over $Y$ for example by Lemma Proper morphisms. $\square$
Lemma. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $(U \subset W, f : V \to W)$ be an elementary distinguished square of algebraic spaces over $S$.
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If $V' \subset V$ and $U \subset U' \subset W$ are open subspaces and $W' = U' \cup f(V')$ then $(U' \subset W', f|_{V'} : V' \to W')$ is an elementary distinguished square.
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If $p : W' \to W$ is a morphism of algebraic spaces, then $(p^{-1}(U) \subset W', V \times_W W' \to W')$ is an elementary distinguished square.
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If $S' \to S$ is a morphism of schemes, then $(S' \times_S U \subset S' \times_S W, S' \times_S V \to S' \times_S W)$ is an elementary distinguished square.
Proof. Omitted. $\square$
Lemma. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Given an étale morphism $V \to Y$, set $U = V \times_Y X$ and denote $g : U \to V$ the projection morphism. Then $(Rf_*E)|_V = Rg_*(E|_U)$ for $E$ in $D(\mathcal{O}_X)$.
Proof. Represent $E$ by a K-injective complex $\mathcal{I}^\bullet$ of $\mathcal{O}_X$-modules. Then $Rf_*(E) = f_*\mathcal{I}^\bullet$ and $Rg_*(E|_U) = g_*(\mathcal{I}^\bullet|_U)$ by Cohomology on Sites, Lemma Injective resolutions. Hence the result follows from Properties of Spaces, Lemma Base change for étale morphisms and modules. $\square$
Lemma. Direct images and closed support
Let $S$ be a scheme. Let $(U \subset X, j : V \to X)$ be an elementary distinguished square of algebraic spaces over $S$. Set $T = |X| \setminus |U|$.
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If $E$ is an object of $D(\mathcal{O}_X)$ supported on $T$, then (a) $E \to Rj_*(E|_V)$ and (b) $j_!(E|_V) \to E$ are isomorphisms.
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If $F$ is an object of $D(\mathcal{O}_V)$ supported on $j^{-1}T$, then (a) $F \to (j_!F)|_V$, (b) $(Rj_*F)|_V \to F$, and (c) $j_!F \to Rj_*F$ are isomorphisms.
Proof. Let $E$ be an object of $D(\mathcal{O}_X)$ whose cohomology sheaves are supported on $T$. Then we see that $E|_U = 0$ and $E|_{U \times_X V} = 0$ as $T$ doesn't meet $U$ and $j^{-1}T$ doesn't meet $U \times_X V$. Thus (1)(a) follows from Lemma Derived quasi-coherent complexes. In exactly the same way (1)(b) follows from Lemma Derived quasi-coherent complexes.
Let $F$ be an object of $D(\mathcal{O}_V)$ whose cohomology sheaves are supported on $j^{-1}T$. By Lemma Derived quasi-coherent complexes we have $(Rj_*F)|_U = Rj_{W, *}(F|_W) = 0$ because $F|_W = 0$ by our assumption. Similarly $(j_!F)|_U = j_{W!}(F|_W) = 0$ by Lemma Derived quasi-coherent complexes. Thus $j_!F$ and $Rj_*F$ are supported on $T$ and $(j_!F)|_V$ and $(Rj_*F)|_V$ are supported on $j^{-1}(T)$. To check that the maps (2)(a), (b), (c) are isomorphisms in the derived category, it suffices to check that these map induce isomorphisms on stalks of cohomology sheaves at geometric points of $T$ and $j^{-1}(T)$ by Properties of Spaces, Theorem Sheaves on ringed sites. This we may do after replacing $X$ by $V$, $U$ by $U \times_X V$, $V$ by $V \times_X V$ and $F$ by $F|_{V \times_X V}$ (restriction via first projection), see Lemmas Derived quasi-coherent complexes, Derived quasi-coherent complexes, and Derived quasi-coherent complexes. Since $V \times_X V \to V$ has a section this reduces (2) to the case that $j : V \to X$ has a section.
Assume $j$ has a section $\sigma : X \to V$. Set $V' = \sigma(X)$. This is an open subspace of $V$. Set $U' = j^{-1}(U)$. This is another open subspace of $V$. Then $(U' \subset V, V' \to V)$ is an elementary distinguished square. Observe that $F|_{U'} = 0$ and $F|_{V' \cap U'} = 0$ because $F$ is supported on $j^{-1}(T)$. Denote $j' : V' \to V$ the open immersion and $j_{V'} : V' \to X$ the composition $V' \to V \to X$ which is the inverse of $\sigma$. Set $F' = \sigma^*F$. The distinguished triangles of Lemmas Derived quasi-coherent complexes and Derived quasi-coherent complexes show that $F = j'_!(F|_{V'})$ and $F = Rj'_*(F|_{V'})$. It follows that $j_!F = j_!j'_!(F|_{V'}) = j_{V'!}F = F'$ because $j_{V'} : V' \to X$ is an isomorphism and the inverse of $\sigma$. Similarly, $Rj_*F = Rj_*Rj'_*F = Rj_{V', *}F = F'$. This proves (2)(c). To prove (2)(a) and (2)(b) it suffices to show that $F = F'|_V$. This is clear because both $F$ and $F'|_V$ restrict to zero on $U'$ and $U' \cap V'$ and the same object on $V'$. $\square$
Lemma. Derived Hom and Ext
Let $S$ be a scheme. Let $(U \subset X, V \to X)$ be an elementary distinguished square of algebraic spaces over $S$. For objects $E$, $F$ of $D(\mathcal{O}_X)$ we have a Mayer-Vietoris sequence $$\begin{gathered}\begin{matrix}\phantom{X} & \ldots & \operatorname{Ext}^{-1}(E_{U \times_X V}, F_{U \times_X V}) \\ \operatorname{Hom}(E, F) & \operatorname{Hom}(E_U, F_U) \oplus \operatorname{Hom}(E_V, F_V) & \operatorname{Hom}(E_{U \times_X V}, F_{U \times_X V})\end{matrix} \\[6pt] \begin{aligned}\ldots & \longrightarrow \operatorname{Ext}^{-1}(E_{U \times_X V}, F_{U \times_X V}) \\ \operatorname{Ext}^{-1}(E_{U \times_X V}, F_{U \times_X V}) & \longrightarrow \operatorname{Hom}(E, F) \\ \operatorname{Hom}(E, F) & \longrightarrow \operatorname{Hom}(E_U, F_U) \oplus \operatorname{Hom}(E_V, F_V) \\ \operatorname{Hom}(E_U, F_U) \oplus \operatorname{Hom}(E_V, F_V) & \longrightarrow \operatorname{Hom}(E_{U \times_X V}, F_{U \times_X V})\end{aligned}\end{gathered}$$ where the subscripts denote restrictions to the relevant opens and the $\operatorname{Hom}$'s are taken in the relevant derived categories.
Proof. Use the distinguished triangle of Lemma Derived quasi-coherent complexes to obtain a long exact sequence of $\operatorname{Hom}$'s (from Derived Categories, Lemma Representability of a homological functor) and use that $\operatorname{Hom}(j_{U!}E|_U, F) = \operatorname{Hom}(E|_U, F|_U)$ by Cohomology on Sites, Lemma Derived modules on ringed sites. $\square$
Lemma. Étale morphisms and quasi-coherent complexes
Let $X$ be a scheme. The functor $\epsilon^* : D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_\mathrm{\acute{e}tale})$ defined above is an equivalence.
Proof. We will prove this by showing the functor $R\epsilon_* : D(\mathcal{O}_\mathrm{\acute{e}tale}) \to D(\mathcal{O}_X)$ induces a quasi-inverse. We will use freely that $\epsilon_*$ is given by restriction to $X_{Zar} \subset X_\mathrm{\acute{e}tale}$ and the description of $\epsilon^* = \text{id}_{small, \mathrm{\acute{e}tale}, Zar}^*$ in Descent, Lemma Comparison for sheaves on ringed sites.
For a quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ the adjunction map $\mathcal{F} \to \epsilon_*\epsilon^*\mathcal{F}$ is an isomorphism by the fact that $\mathcal{F}^a$ (Descent, Definition The structure sheaf on the descent site) is a sheaf as proved in Descent, Lemma Sheaves on ringed sites. Conversely, every quasi-coherent $\mathcal{O}_\mathrm{\acute{e}tale}$-module $\mathcal{H}$ is of the form $\epsilon^*\mathcal{F}$ for some quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$, see Descent, Proposition Quasi-coherent complexes and coherent sheaves. Then $\mathcal{F} = \epsilon_*\mathcal{H}$ by what we just said and we conclude that the adjunction map $\epsilon^*\epsilon_*\mathcal{H} \to \mathcal{H}$ is an isomorphism for all quasi-coherent $\mathcal{O}_\mathrm{\acute{e}tale}$-modules $\mathcal{H}$.
Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_\mathrm{\acute{e}tale})$ and denote $\mathcal{H}^q = H^q(E)$ its $q$th cohomology sheaf. Let $\mathcal{B}$ be the set of affine objects of $X_\mathrm{\acute{e}tale}$. Then $H^p(U, \mathcal{H}^q) = 0$ for all $p > 0$, all $q \in \mathbf{Z}$, and all $U \in \mathcal{B}$, see Descent, Proposition Quasi-coherent complexes and sheaf cohomology and Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). By Cohomology on Sites, Lemma Sheaf cohomology this means that $$H^q(U, E) = H^0(U, \mathcal{H}^q)$$ for all $U \in \mathcal{B}$. In particular, we find that this holds for affine opens $U \subset X$. It follows that the $q$th cohomology of $R\epsilon_*E$ over $U$ is the value of the sheaf $\epsilon_*\mathcal{H}^q$ over $U$. Applying sheafification we obtain $$H^q(R\epsilon_*E) = \epsilon_*\mathcal{H}^q$$ which in particular shows that $R\epsilon_*$ induces a functor $D_\mathrm{QCoh}(\mathcal{O}_\mathrm{\acute{e}tale}) \to D_\mathrm{QCoh}(\mathcal{O}_X)$. Since $\epsilon^*$ is exact we then obtain $H^q(\epsilon^*R\epsilon_*E) = \epsilon^*\epsilon_*\mathcal{H}^q = \mathcal{H}^q$ (by discussion above). Thus the adjunction map $\epsilon^*R\epsilon_*E \to E$ is an isomorphism.
Conversely, for $F \in D_\mathrm{QCoh}(\mathcal{O}_X)$ the adjunction map $F \to R\epsilon_*\epsilon^*F$ is an isomorphism for the same reason, i.e., because the cohomology sheaves of $R\epsilon_*\epsilon^*F$ are isomorphic to $\epsilon_*H^m(\epsilon^*F) = \epsilon_*\epsilon^*H^m(F) = H^m(F)$. $\square$
Lemma. Descent of pseudo-coherent complexes and coherent sheaves
Let $X$ be a scheme. Let $E$ be an object of $D(\mathcal{O}_X)$. The following are equivalent
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$E$ is $m$-pseudo-coherent, and
-
$\epsilon^*E$ is $m$-pseudo-coherent on the small étale site of $X$.
Here $\epsilon$ is as in (Derived quasi-coherent complexes).
Proof. The implication (1) $\Rightarrow$ (2) is a general fact, see Cohomology on Sites, Lemma Pseudo-coherent complexes and coherent sheaves. Assume $\epsilon^*E$ is $m$-pseudo-coherent. We will use without further mention that $\epsilon^*$ is an exact functor and that therefore $$\epsilon^*H^i(E) = H^i(\epsilon^*E).$$ To show that $E$ is $m$-pseudo-coherent we may work locally on $X$, hence we may assume that $X$ is quasi-compact (for example affine). Since $X$ is quasi-compact every étale covering $\{U_i \to X\}$ has a finite refinement. Thus we see that $\epsilon^*E$ is an object of $D^{-}(\mathcal{O}_\mathrm{\acute{e}tale})$, see comments following Cohomology on Sites, Definition Pseudo-coherent complexes. By Lemma Flatness it follows that $E$ is an object of $D^-(\mathcal{O}_X)$.
Let $n \in \mathbf{Z}$ be the largest integer such that $H^n(E)$ is nonzero; then $n$ is also the largest integer such that $H^n(\epsilon^*E)$ is nonzero. We will prove the lemma by induction on $n - m$. If $n < m$, then the lemma is clearly true. If $n \geq m$, then $H^n(\epsilon^*E)$ is a finite $\mathcal{O}_\mathrm{\acute{e}tale}$-module, see Cohomology on Sites, Lemma Finiteness of cohomology groups. Hence $H^n(E)$ is a finite $\mathcal{O}_X$-module, see Lemma Descent of finite algebras. After replacing $X$ by the members of an open covering, we may assume there exists a surjection $\mathcal{O}_X^{\oplus t} \to H^n(E)$. We may locally on $X$ lift this to a map of complexes $\alpha : \mathcal{O}_X^{\oplus t}[-n] \to E$ (details omitted). Choose a distinguished triangle $$\mathcal{O}_X^{\oplus t}[-n] \to E \to C \to \mathcal{O}_X^{\oplus t}[-n + 1]$$ Then $C$ has vanishing cohomology in degrees $\geq n$. On the other hand, the complex $\epsilon^*C$ is $m$-pseudo-coherent, see Cohomology on Sites, Lemma Pseudo-coherent complexes and coherent sheaves. Hence by induction we see that $C$ is $m$-pseudo-coherent. Applying Cohomology on Sites, Lemma Pseudo-coherent complexes and coherent sheaves once more we conclude. $\square$
Lemma. Flatness
The morphism $\epsilon$ of (Derived quasi-coherent complexes) is a flat morphism of ringed sites. In particular the functor $\epsilon^* : \textit{Mod}(\mathcal{O}_X) \to \textit{Mod}(\mathcal{O}_\mathrm{\acute{e}tale})$ is exact. Moreover, if $\epsilon^*\mathcal{F} = 0$, then $\mathcal{F} = 0$.
Proof. The flatness of the morphism $\epsilon$ is Descent, Lemma Comparison for étale morphisms and flatness. Here is another proof. We have to show that $\mathcal{O}_\mathrm{\acute{e}tale}$ is a flat $\epsilon^{-1}\mathcal{O}_X$-module. To do this it suffices to check $\mathcal{O}_{X, x} \to \mathcal{O}_{\mathrm{\acute{e}tale}, \overline{x}}$ is flat for any geometric point $\overline{x}$ of $X$, see Modules on Sites, Lemma Testing flatness at stalks, Sites, Lemma Sheaves on ringed sites (uncovered prerequisite), and Étale Cohomology, Remarks The geometric construction. By Étale Cohomology, Lemma Étale morphisms and local algebra (uncovered prerequisite) we see that $\mathcal{O}_{\mathrm{\acute{e}tale}, \overline{x}}$ is the strict henselization of $\mathcal{O}_{X, x}$. Thus $\mathcal{O}_{X, x} \to \mathcal{O}_{\mathrm{\acute{e}tale}, \overline{x}}$ is faithfully flat by More on Algebra, Lemma Henselian local rings and henselization, Sections 4 and 6, Proposition 6.1.
The exactness of $\epsilon^*$ follows from the flatness of $\epsilon$ by Modules on Sites, Lemma Exactness of flat pullback.
Let $\mathcal{F}$ be an $\mathcal{O}_X$-module. If $\epsilon^*\mathcal{F} = 0$, then with notation as above $$0 = \epsilon^*\mathcal{F}_{\overline{x}} = \mathcal{F}_x \otimes_{\mathcal{O}_{X, x}} \mathcal{O}_{\mathrm{\acute{e}tale}, \overline{x}}$$ (Modules on Sites, Lemma Stalks of a pullback) for all geometric points $\overline{x}$. By faithful flatness of $\mathcal{O}_{X, x} \to \mathcal{O}_{\mathrm{\acute{e}tale}, \overline{x}}$ we conclude $\mathcal{F}_x = 0$ for all $x \in X$. $\square$
Lemma. Descent of perfect complexes
Let $X$ be a scheme. Let $E$ be an object of $D(\mathcal{O}_X)$. Then $E$ is a perfect object of $D(\mathcal{O}_X)$ if and only if $\epsilon^*E$ is a perfect object of $D(\mathcal{O}_\mathrm{\acute{e}tale})$. Here $\epsilon$ is as in (Derived quasi-coherent complexes).
Proof. The easy implication follows from the general result contained in Cohomology on Sites, Lemma Perfect complexes. For the converse, we can use the equivalence of Cohomology on Sites, Lemma Perfect complexes and the corresponding results for pseudo-coherent and complexes of finite tor dimension, namely Lemmas Descent of pseudo-coherent complexes and coherent sheaves and Descent of derived tensor products and Tor amplitude. Some details omitted. $\square$
Remark. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of representable algebraic spaces $X$ and $Y$ over $S$. Let $f_0 : X_0 \to Y_0$ be a morphism of schemes representing $f$ (awkward but temporary notation). Then the diagram
\[ \begin{gathered}\begin{matrix}D_\mathrm{QCoh}(\mathcal{O}_{X_0}) & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & D_\mathrm{QCoh}(\mathcal{O}_X) \\ D_\mathrm{QCoh}(\mathcal{O}_{Y_0}) & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & D_\mathrm{QCoh}(\mathcal{O}_Y)\end{matrix} \\[6pt] \begin{aligned}D_\mathrm{QCoh}(\mathcal{O}_{X_0}) & \overset{\text{Lemma Étale morphisms and quasi-coherent complexes}}{\mathrel{=}} D_\mathrm{QCoh}(\mathcal{O}_X) \\ D_\mathrm{QCoh}(\mathcal{O}_{Y_0}) & \xrightarrow{Lf^*_0} D_\mathrm{QCoh}(\mathcal{O}_{X_0}) \\ D_\mathrm{QCoh}(\mathcal{O}_{Y_0}) & \overset{\text{Lemma Étale morphisms and quasi-coherent complexes}}{\mathrel{=}} D_\mathrm{QCoh}(\mathcal{O}_Y) \\ D_\mathrm{QCoh}(\mathcal{O}_Y) & \xrightarrow{Lf^*} D_\mathrm{QCoh}(\mathcal{O}_X)\end{aligned}\end{gathered} \](Lemma Quasi-coherent complexes and coherent sheaves and Derived Categories of Schemes, Lemma Quasi-coherent complexes and coherent sheaves) is commutative. This follows as the equivalences $D_\mathrm{QCoh}(\mathcal{O}_{X_0}) \to D_\mathrm{QCoh}(\mathcal{O}_X)$ and $D_\mathrm{QCoh}(\mathcal{O}_{Y_0}) \to D_\mathrm{QCoh}(\mathcal{O}_Y)$ of Lemma Étale morphisms and quasi-coherent complexes come from pulling back by the (flat) morphisms of ringed sites $\epsilon : X_\mathrm{\acute{e}tale} \to X_{0, Zar}$ and $\epsilon : Y_\mathrm{\acute{e}tale} \to Y_{0, Zar}$ and the diagram of ringed sites $$\begin{gathered}\begin{matrix}X_{0, Zar} & X_\mathrm{\acute{e}tale} \\ Y_{0, Zar} & Y_\mathrm{\acute{e}tale}\end{matrix} \\[6pt] \begin{aligned}X_{0, Zar} & \xrightarrow{f_0} Y_{0, Zar} \\ X_\mathrm{\acute{e}tale} & \xrightarrow{\epsilon} X_{0, Zar} \\ X_\mathrm{\acute{e}tale} & \xrightarrow{f} Y_\mathrm{\acute{e}tale} \\ Y_\mathrm{\acute{e}tale} & \xrightarrow{\epsilon} Y_{0, Zar}\end{aligned}\end{gathered}$$ is commutative (details omitted). If $f$ is quasi-compact and quasi-separated, equivalently if $f_0$ is quasi-compact and quasi-separated, then we claim
\[ \begin{gathered}\begin{matrix}D_\mathrm{QCoh}(\mathcal{O}_{X_0}) & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & D_\mathrm{QCoh}(\mathcal{O}_X) \\ D_\mathrm{QCoh}(\mathcal{O}_{Y_0}) & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & D_\mathrm{QCoh}(\mathcal{O}_Y)\end{matrix} \\[6pt] \begin{aligned}D_\mathrm{QCoh}(\mathcal{O}_{X_0}) & \xrightarrow{Rf_{0, *}} D_\mathrm{QCoh}(\mathcal{O}_{Y_0}) \\ D_\mathrm{QCoh}(\mathcal{O}_{X_0}) & \overset{\text{Lemma Étale morphisms and quasi-coherent complexes}}{\mathrel{=}} D_\mathrm{QCoh}(\mathcal{O}_X) \\ D_\mathrm{QCoh}(\mathcal{O}_X) & \xrightarrow{Rf_*} D_\mathrm{QCoh}(\mathcal{O}_Y) \\ D_\mathrm{QCoh}(\mathcal{O}_{Y_0}) & \overset{\text{Lemma Étale morphisms and quasi-coherent complexes}}{\mathrel{=}} D_\mathrm{QCoh}(\mathcal{O}_Y)\end{aligned}\end{gathered} \](Lemma Quasi-coherent complexes and coherent sheaves and Derived Categories of Schemes, Lemma Quasi-coherent complexes and coherent sheaves) is commutative as well. This also follows from the commutative diagram of sites displayed above as the proof of Lemma Étale morphisms and quasi-coherent complexes shows that the functor $R\epsilon_*$ gives the equivalences $D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_{X_0})$ and $D_\mathrm{QCoh}(\mathcal{O}_Y) \to D_\mathrm{QCoh}(\mathcal{O}_{Y_0})$.
Lemma. Tensor products and direct sums
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $W$ be a quasi-compact open subspace of $X$. Let $P$ be a perfect object of $D(\mathcal{O}_W)$. Then $P$ is a direct summand of the restriction of a perfect object of $D(\mathcal{O}_X)$.
Proof. Special case of Lemma Lifting maps from support-preserving perfect complexes. $\square$
Definition. Derived quasi-coherent complexes
Let $S$ be a scheme. A commutative diagram $$\begin{gathered}\begin{matrix}U \times_W V & V \\ U & W\end{matrix} \\[6pt] \begin{aligned}U \times_W V & \longrightarrow V \\ U \times_W V & \longrightarrow U \\ V & \xrightarrow{f} W \\ U & \xrightarrow{j} W\end{aligned}\end{gathered}$$ of algebraic spaces over $S$ is called an elementary distinguished square if
-
$U$ is an open subspace of $W$ and $j$ is the inclusion morphism,
-
$f$ is étale, and
-
setting $T = W \setminus U$ (with reduced induced subspace structure) the morphism $f^{-1}(T) \to T$ is an isomorphism.
We will indicate this by saying: "Let $(U \subset W, f : V \to W)$ be an elementary distinguished square."
Lemma. Derived tensor products, Tor amplitude and affine neighbourhoods
Let $S$ be a scheme. Let $X$ be an affine algebraic space over $S$. Set $A = \Gamma(X, \mathcal{O}_X)$. Then
-
$Q_X : \textit{Mod}(\mathcal{O}_X) \to \mathrm{QCoh}(\mathcal{O}_X)$ is the functor which sends $\mathcal{F}$ to the quasi-coherent $\mathcal{O}_X$-module associated to the $A$-module $\Gamma(X, \mathcal{F})$,
-
$RQ_X : D(\mathcal{O}_X) \to D(\mathrm{QCoh}(\mathcal{O}_X))$ is the functor which sends $E$ to the complex of quasi-coherent $\mathcal{O}_X$-modules associated to the object $R\Gamma(X, E)$ of $D(A)$,
-
restricted to $D_\mathrm{QCoh}(\mathcal{O}_X)$ the functor $RQ_X$ defines a quasi-inverse to (Comparison of derived quasi-coherent categories).
Proof. Let $X_0 = \operatorname{Spec}(A)$ be the affine scheme representing $X$. Recall that there is a morphism of ringed sites $\epsilon : X_\mathrm{\acute{e}tale} \to X_{0, Zar}$ which induces equivalences $$\begin{gathered}\begin{matrix}\mathrm{QCoh}(\mathcal{O}_X) & \mathrm{QCoh}(\mathcal{O}_{X_0})\end{matrix} \\[6pt] \begin{aligned}\mathrm{QCoh}(\mathcal{O}_X) & \xrightarrow{{\epsilon_*}} \mathrm{QCoh}(\mathcal{O}_{X_0}) \\ \mathrm{QCoh}(\mathcal{O}_{X_0}) & \xrightarrow{{\epsilon^*}} \mathrm{QCoh}(\mathcal{O}_X)\end{aligned}\end{gathered}$$ see Lemma Étale morphisms and quasi-coherent complexes. Hence we see that $Q_X = \epsilon^* \circ Q_{X_0} \circ \epsilon_*$ by uniqueness of adjoint functors. Hence (1) follows from the description of $Q_{X_0}$ in Derived Categories of Schemes, Lemma Derived tensor products, Tor amplitude and affine neighbourhoods and the fact that $\Gamma(X_0, \epsilon_*\mathcal{F}) = \Gamma(X, \mathcal{F})$. Part (2) follows from (1) and the fact that the functor from $A$-modules to quasi-coherent $\mathcal{O}_X$-modules is exact. The third assertion now follows from the result for schemes (Derived Categories of Schemes, Lemma Derived tensor products, Tor amplitude and affine neighbourhoods) and Lemma Étale morphisms and quasi-coherent complexes. $\square$
Lemma. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $(U \subset X, V \to X)$ be an elementary distinguished square of algebraic spaces over $S$.
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For every sheaf of $\mathcal{O}_X$-modules $\mathcal{F}$ we have a short exact sequence $$0 \to \mathcal{F} \to j_{U, *}\mathcal{F}|_U \oplus j_{V, *}\mathcal{F}|_V \to j_{U \times_X V, *}\mathcal{F}|_{U \times_X V} \to 0$$
-
For any object $E$ of $D(\mathcal{O}_X)$ we have a distinguished triangle $$E \to Rj_{U, *}E|_U \oplus Rj_{V, *}E|_V \to Rj_{U \times_X V, *}E|_{U \times_X V} \to E[1]$$ in $D(\mathcal{O}_X)$.
Proof. Let $W$ be an object of $X_\mathrm{\acute{e}tale}$. We claim the sequence $$0 \to \mathcal{F}(W) \to \mathcal{F}(W \times_X U) \oplus \mathcal{F}(W \times_X V) \to \mathcal{F}(W \times_X U \times_X V)$$ is exact and that an element of the last group can locally on $W$ be lifted to the middle one. By Lemma Derived quasi-coherent complexes the pair $(W \times_X U \subset W, V \times_X W \to W)$ is an elementary distinguished square. Thus we may assume $W = X$ and it suffices to prove the same thing for $$0 \to \mathcal{F}(X) \to \mathcal{F}(U) \oplus \mathcal{F}(V) \to \mathcal{F}(U \times_X V)$$ We have seen that $$0 \to j_{U \times_X V!}\mathcal{O}_{U \times_X V} \to j_{U!}\mathcal{O}_U \oplus j_{V!}\mathcal{O}_V \to \mathcal{O}_X \to 0$$ is a exact sequence of $\mathcal{O}_X$-modules in Lemma Derived quasi-coherent complexes and applying the left exact functor $\operatorname{Hom}_{\mathcal{O}_X}(- , \mathcal{F})$ gives the sequence above. This also means that the obstruction to lifting $s \in \mathcal{F}(U \times_X V)$ to an element of $\mathcal{F}(U) \oplus \mathcal{F}(V)$ lies in $\operatorname{Ext}^1_{\mathcal{O}_X}(\mathcal{O}_X, \mathcal{F}) = H^1(X, \mathcal{F})$. By locality of cohomology (Cohomology on Sites, Lemma Sheaf cohomology) this obstruction vanishes étale locally on $X$ and the proof of (1) is complete.
Proof of (2). Choose a K-injective complex $\mathcal{I}^\bullet$ representing $E$ whose terms $\mathcal{I}^n$ are injective objects of $\textit{Mod}(\mathcal{O}_X)$, see Injectives, Theorem Injective resolutions (uncovered prerequisite). Then $\mathcal{I}^\bullet|U$ is a K-injective complex (Cohomology on Sites, Lemma Injective resolutions). Hence $Rj_{U, *}E|_U$ is represented by $j_{U, *}\mathcal{I}^\bullet|_U$. Similarly for $V$ and $U \times_X V$. Hence the distinguished triangle of the lemma is the distinguished triangle associated (by Derived Categories, Section Derived tensor products and Tor amplitude and especially Lemma Derived tensor products, Tor amplitude and derived categories) to the short exact sequence of complexes $$0 \to \mathcal{I}^\bullet \to j_{U, *}\mathcal{I}^\bullet|_U \oplus j_{V, *}\mathcal{I}^\bullet|_V \to j_{U \times_X V, *}\mathcal{I}^\bullet|_{U \times_X V} \to 0.$$ This sequence is exact by (1). $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Then $D_\mathrm{QCoh}(\mathcal{O}_X)$ has direct sums.
Proof. By Injectives, Lemma Derived categories and tensor products and direct sums (uncovered prerequisite) the derived category $D(\mathcal{O}_X)$ has direct sums and they are computed by taking termwise direct sums of any representatives. Thus it is clear that the cohomology sheaf of a direct sum is the direct sum of the cohomology sheaves as taking direct sums is an exact functor (in any Grothendieck abelian category). The lemma follows as the direct sum of quasi-coherent sheaves is quasi-coherent, see Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. $\square$
Proposition. Compact objects are perfect
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. An object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ is compact if and only if it is perfect.
Proof. If $K$ is a perfect object of $D(\mathcal{O}_X)$ with dual $K^\vee$ (Cohomology on Sites, Lemma Perfect complexes and derived categories) we have $$\operatorname{Hom}_{D(\mathcal{O}_X)}(K, M) = H^0(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} M)$$ functorially in $M$. Since $K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} -$ commutes with direct sums and since $H^0(X, -)$ commutes with direct sums on $D_\mathrm{QCoh}(\mathcal{O}_X)$ by Lemma Quasi-coherent complexes and coherent sheaves we conclude that $K$ is compact in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Conversely, let $K$ be a compact object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. To show that $K$ is perfect, it suffices to show that $K|_U$ is perfect for every affine scheme $U$ étale over $X$, see Cohomology on Sites, Lemma Perfect complexes. Observe that $j : U \to X$ is a quasi-compact and separated morphism. Hence $Rj_* : D_\mathrm{QCoh}(\mathcal{O}_U) \to D_\mathrm{QCoh}(\mathcal{O}_X)$ commutes with direct sums, see Lemma Quasi-coherent complexes and coherent sheaves. Thus the adjointness of restriction to $U$ and $Rj_*$ implies that $K|_U$ is a perfect object of $D_\mathrm{QCoh}(\mathcal{O}_U)$. Hence we reduce to the case that $X$ is affine, in particular a quasi-compact and quasi-separated scheme. Via Lemma Étale morphisms and quasi-coherent complexes and Descent of perfect complexes we reduce to the case of schemes, i.e., to Derived Categories of Schemes, Proposition Compact objects are perfect. $\square$
Remark. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $(U \subset X, f : V \to X)$ be an elementary distinguished square of algebraic spaces over $S$. Assume $X$, $U$, $V$ are quasi-compact and quasi-separated. By Lemma The derived quasi-coherator the functors $DQ_X$, $DQ_U$, $DQ_V$, $DQ_{U \times_X V}$ exist. Moreover, there is a canonical distinguished triangle $$DQ_X(K) \to Rj_{U, *}DQ_U(K|_U) \oplus Rj_{V, *}DQ_V(K|_V) \to Rj_{U \times_X V, *}DQ_{U \times_X V}(K|_{U \times_X V}) \to$$ for any $K \in D(\mathcal{O}_X)$. This follows by applying the exact functor $DQ_X$ to the distinguished triangle of Lemma Derived quasi-coherent complexes and using Lemma Direct images and the derived quasi-coherator three times.
Lemma. Base change for derived categories
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ be a cartesian diagram of algebraic spaces over $S$. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ and let $L(g')^*K \to K'$ be a map in $D_\mathrm{QCoh}(\mathcal{O}_{X'})$. If
-
the equivalent conditions of Lemma Base change for derived categories hold, and
-
$f$ is quasi-compact and quasi-separated,
then the composition $Lg^*Rf_*K \to Rf'_*L(g')^*K \to Rf'_*K'$ is an isomorphism.
Proof. To check the map is an isomorphism we may work étale locally on $Y'$. Hence we may assume $g : Y' \to Y$ is a morphism of affine schemes. In this case, we will use the induction principle of Lemma Induction by elementary distinguished squares to prove that for a quasi-compact and quasi-separated algebraic space $U$ étale over $X$ the similarly constructed map $Lg^*R(U \to Y)_*K|_U \to R(U' \to Y')_*K'|_{U'}$ is an isomorphism. Here $U' = X' \times_{g', X} U = Y' \times_{g, Y} U$.
If $U$ is a scheme (for example affine), then the result holds. Namely, then $Y, Y', U, U'$ are schemes, $K$ and $K'$ come from objects of the derived category of the underlying schemes by Lemma Étale morphisms and quasi-coherent complexes and the condition of Derived Categories of Schemes, Lemma Base change for derived categories holds for these complexes by Lemma Base change for derived categories. Thus (by the compatibilities explained in Remark Derived quasi-coherent complexes) we can apply the result in the case of schemes which is Derived Categories of Schemes, Lemma Base change for derived categories.
The induction step. Let $(U \subset W, V \to W)$ be an elementary distinguished square with $W$ a quasi-compact and quasi-separated algebraic space étale over $X$, with $U$ quasi-compact, $V$ affine and the result holds for $U$, $V$, and $U \times_W V$. To easy notation we replace $W$ by $X$ (this is permissible at this point). Denote $a : U \to Y$, $b : V \to Y$, and $c : U \times_X V \to Y$ the obvious morphisms. Let $a' : U' \to Y'$, $b' : V' \to Y'$ and $c' : U' \times_{X'} V' \to Y'$ be the base changes of $a$, $b$, and $c$. Using the distinguished triangles from relative Mayer-Vietoris (Lemma Relative Mayer–Vietoris for unbounded complexes) we obtain a commutative diagram $$\begin{gathered}\begin{matrix}Lg^*Rf_*K & Rf'_*K' \\ Lg^*Ra_*K|_U \oplus Lg^*Rb_*K|_V & Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} \\ Lg^*Rc_*K|_{U \times_X V} & Rc'_*K'|_{U' \times_{X'} V'} \\ Lg^*Rf_* K[1] & Rf'_* K'[1]\end{matrix} \\[6pt] \begin{aligned}Lg^*Rf_*K & \longrightarrow Rf'_*K' \\ Lg^*Rf_*K & \longrightarrow Lg^*Ra_*K|_U \oplus Lg^*Rb_*K|_V \\ Rf'_*K' & \longrightarrow Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} \\ Lg^*Ra_*K|_U \oplus Lg^*Rb_*K|_V & \longrightarrow Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} \\ Lg^*Ra_*K|_U \oplus Lg^*Rb_*K|_V & \longrightarrow Lg^*Rc_*K|_{U \times_X V} \\ Ra'_* K'|_{U'} \oplus Rb'_* K'|_{V'} & \longrightarrow Rc'_*K'|_{U' \times_{X'} V'} \\ Lg^*Rc_*K|_{U \times_X V} & \longrightarrow Rc'_*K'|_{U' \times_{X'} V'} \\ Lg^*Rc_*K|_{U \times_X V} & \longrightarrow Lg^*Rf_* K[1] \\ Rc'_*K'|_{U' \times_{X'} V'} & \longrightarrow Rf'_* K'[1] \\ Lg^*Rf_* K[1] & \longrightarrow Rf'_* K'[1]\end{aligned}\end{gathered}$$ Since the 2nd and 3rd horizontal arrows are isomorphisms so is the first (Derived Categories, Lemma Derived categories) and the proof of the lemma is finished. $\square$
Lemma. Inheritance of a cohomological base-change condition
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ be a cartesian diagram of algebraic spaces over $S$. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ and let $L(g')^*K \to K'$ be a map in $D_\mathrm{QCoh}(\mathcal{O}_{X'})$. If the equivalent conditions of Lemma Base change for derived categories hold, then
-
for $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$ the equivalent conditions of Lemma Base change for derived categories hold for $L(g')^*(E \otimes^\mathbf{L} K) \to L(g')^*E \otimes^\mathbf{L} K'$,
-
if $E$ in $D(\mathcal{O}_X)$ is perfect the equivalent conditions of Lemma Base change for derived categories hold for $L(g')^*R\mathcal{H}om(E, K) \to R\mathcal{H}om(L(g')^*E, K')$, and
-
if $K$ is bounded below and $E$ in $D(\mathcal{O}_X)$ pseudo-coherent the equivalent conditions of Lemma Base change for derived categories hold for $L(g')^*R\mathcal{H}om(E, K) \to R\mathcal{H}om(L(g')^*E, K')$.
Proof. The statement makes sense as the complexes involved have quasi-coherent cohomology sheaves by Lemmas Quasi-coherent complexes and coherent sheaves, Quasi-coherent complexes and coherent sheaves, and Quasi-coherent complexes and derived Hom and Ext and Cohomology on Sites, Lemmas Pseudo-coherent complexes and coherent sheaves and Perfect complexes. Having said this, we can check the maps (Derived quasi-coherent complexes) are isomorphisms in case (1) by computing the source and target of (Derived quasi-coherent complexes) using the transitive property of tensor product, see More on Algebra, Lemma Tensor products and direct sums. The map in (2) and (3) is the composition $$L(g')^*R\mathcal{H}om(E, K) \to R\mathcal{H}om(L(g')^*E, L(g')^*K) \to R\mathcal{H}om(L(g')^*E, K')$$ where the first arrow is Cohomology on Sites, Remark The comparison maps for derived base change and the second arrow comes from the given map $L(g')^*K \to K'$. To prove the maps (Derived quasi-coherent complexes) are isomorphisms one represents $E_x$ by a bounded complex of finite projective $\mathcal{O}_{X. x}$-modules in case (2) or by a bounded above complex of finite free modules in case (3) and computes the source and target of the arrow. Some details omitted. $\square$
Lemma. Base change for derived categories
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ be a cartesian diagram of algebraic spaces over $S$. Let $K \in D_\mathrm{QCoh}(\mathcal{O}_X)$ and let $L(g')^*K \to K'$ be a map in $D_\mathrm{QCoh}(\mathcal{O}_{X'})$. The following are equivalent
-
for any $x' \in X'$ and $i \in \mathbf{Z}$ the map (Derived quasi-coherent complexes) is an isomorphism,
-
for any commutative diagram $$\begin{gathered}\begin{matrix}\phantom{X} & U \\ V' & V & X \\ \phantom{X} & Y' & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow V \\ U & \xrightarrow{a} X \\ V' & \longrightarrow V \\ V' & \xrightarrow{c} Y' \\ V & \xrightarrow{b} Y \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ with $a, b, c$ étale, $U, V, V'$ schemes, and with $U' = V' \times_V U$ the equivalent conditions of Derived Categories of Schemes, Lemma Base change for derived categories hold for $(U \to X)^*K$ and $(U' \to X')^*K'$, and
-
there is some diagram as in (2) with $U' \to X'$ surjective.
Proof. Observe that (1) is étale local on $X'$. Working through formal implications of what is known, we see that it suffices to prove condition (1) of this lemma is equivalent to condition (1) of Derived Categories of Schemes, Lemma Base change for derived categories if $X, Y, Y', X'$ are representable by schemes $X_0, Y_0, Y'_0, X'_0$. Denote $f_0, g_0, g'_0, f'_0$ the morphisms between these schemes corresponding to $f, g, g', f'$. We may assume $K = \epsilon^*K_0$ and $K' = \epsilon^*K'_0$ for some objects $K_0 \in D_\mathrm{QCoh}(\mathcal{O}_{X_0})$ and $K'_0 \in D_\mathrm{QCoh}(\mathcal{O}_{X'_0})$, see Lemma Étale morphisms and quasi-coherent complexes. Moreover, the map $Lg^*K \to K'$ is the pullback of a map $L(g_0)^*K_0 \to K'_0$ with notation as in Remark Derived quasi-coherent complexes. Recall that $\mathcal{O}_{X, \overline{x}}$ is the strict henselization of $\mathcal{O}_{X, x}$ (Properties of Spaces, Lemma Étale morphisms and local algebra) and that we have $$K_{\overline{x}} = K_{0, x} \otimes_{\mathcal{O}_{X, x}}^\mathbf{L} \mathcal{O}_{X, \overline{x}} \quad\text{and}\quad K'_{\overline{x}'} = K'_{0, x'} \otimes_{\mathcal{O}_{X', x'}}^\mathbf{L} \mathcal{O}_{X', \overline{x}'}$$ (akin to Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves). Consider the commutative diagram $$\begin{gathered}\begin{matrix}H^i(K_{\overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}}^\mathbf{L} \mathcal{O}_{Y', \overline{y}'}) \otimes_{(\mathcal{O}_{X, \overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{Y', \overline{y}'})} \mathcal{O}_{X', \overline{x}'} & H^i(K'_{\overline{x}'}) \\ H^i(K_{0, x} \otimes_{\mathcal{O}_{Y, y}}^\mathbf{L} \mathcal{O}_{Y', y'}) \otimes_{(\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{Y, y}} \mathcal{O}_{Y', y'})} \mathcal{O}_{X', x'} & H^i(K'_{0, x'})\end{matrix} \\[6pt] \begin{aligned}H^i(K_{\overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}}^\mathbf{L} \mathcal{O}_{Y', \overline{y}'}) \otimes_{(\mathcal{O}_{X, \overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{Y', \overline{y}'})} \mathcal{O}_{X', \overline{x}'} & \longrightarrow H^i(K'_{\overline{x}'}) \\ H^i(K_{0, x} \otimes_{\mathcal{O}_{Y, y}}^\mathbf{L} \mathcal{O}_{Y', y'}) \otimes_{(\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{Y, y}} \mathcal{O}_{Y', y'})} \mathcal{O}_{X', x'} & \longrightarrow H^i(K_{\overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}}^\mathbf{L} \mathcal{O}_{Y', \overline{y}'}) \otimes_{(\mathcal{O}_{X, \overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{Y', \overline{y}'})} \mathcal{O}_{X', \overline{x}'} \\ H^i(K_{0, x} \otimes_{\mathcal{O}_{Y, y}}^\mathbf{L} \mathcal{O}_{Y', y'}) \otimes_{(\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{Y, y}} \mathcal{O}_{Y', y'})} \mathcal{O}_{X', x'} & \longrightarrow H^i(K'_{0, x'}) \\ H^i(K'_{0, x'}) & \longrightarrow H^i(K'_{\overline{x}'})\end{aligned}\end{gathered}$$ We have to show that the lower horizontal arrow is an isomorphism if and only if the upper horizontal arrow is an isomorphism. Since $\mathcal{O}_{X', x'} \to \mathcal{O}_{X', \overline{x}'}$ is faithfully flat (More on Algebra, Lemma Henselian local rings and henselization, Sections 4 and 6, Proposition 6.1) it suffices to show that the top arrow is the base change of the bottom arrow by this map. This follows immediately from the relationships between stalks given above for the objects on the right. For the objects on the left it suffices to show that $$\begin{aligned} & H^i\left( (K_{0, x} \otimes_{\mathcal{O}_{X, x}}^\mathbf{L} \mathcal{O}_{X, \overline{x}}) \otimes_{\mathcal{O}_{Y, \overline{y}}}^\mathbf{L} \mathcal{O}_{Y', \overline{y}'}\right) \\ & = H^i(K_{0, x} \otimes_{\mathcal{O}_{Y, y}}^\mathbf{L} \mathcal{O}_{Y', y'}) \otimes_{(\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{Y, y}} \mathcal{O}_{Y', y'})} (\mathcal{O}_{X, \overline{x}} \otimes_{\mathcal{O}_{Y, \overline{y}}} \mathcal{O}_{Y', \overline{y}'}) \end{aligned}$$ This follows from More on Algebra, Lemma Derived tensor products, Tor amplitude and flatness. The flatness assumptions of this lemma hold by what was said above as well as Algebra, Lemma Lifting residue maps between strictly henselian rings implying that $\mathcal{O}_{X, \overline{x}}$ is the strict henselization of $\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{Y, y}} \mathcal{O}_{Y, \overline{y}}$ and that $\mathcal{O}_{Y', \overline{y}'}$ is the strict henselization of $\mathcal{O}_{Y', y'} \otimes_{\mathcal{O}_{Y, y}} \mathcal{O}_{Y, \overline{y}}$. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be a Noetherian algebraic space over $S$. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. For $m \in \mathbf{Z}$ the following are equivalent
-
$H^i(E)$ is coherent for $i \geq m$ and zero for $i \gg 0$, and
-
$E$ is $m$-pseudo-coherent.
In particular, $E$ is pseudo-coherent if and only if $E$ is an object of $D^-_{\textit{Coh}}(\mathcal{O}_X)$.
Proof. As $X$ is quasi-compact we can find an affine scheme $U$ and a surjective étale morphism $U \to X$ (Properties of Spaces, Lemma Affine neighbourhoods). Observe that $U$ is Noetherian. Note that $E$ is $m$-pseudo-coherent if and only if $E|_U$ is $m$-pseudo-coherent (follows from the definition or from Cohomology on Sites, Lemma Pseudo-coherent complexes and coherent sheaves). Similarly, $H^i(E)$ is coherent if and only if $H^i(E)|_U = H^i(E|_U)$ is coherent (see Cohomology of Spaces, Lemma Coherent sheaves and Noetherian rings). Thus we may assume that $X$ is representable.
If $X$ is representable by a scheme $X_0$ then (Lemma Étale morphisms and quasi-coherent complexes) we can write $E = \epsilon^*E_0$ where $E_0$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_{X_0})$ and $\epsilon : X_\mathrm{\acute{e}tale} \to (X_0)_{Zar}$ is as in (Derived quasi-coherent complexes). In this case $E$ is $m$-pseudo-coherent if and only if $E_0$ is by Lemma Descent of pseudo-coherent complexes and coherent sheaves. Similarly, $H^i(E_0)$ is of finite type (i.e., coherent) if and only if $H^i(E)$ is by Lemma Descent of finite algebras. Finally, $H^i(E_0) = 0$ if and only if $H^i(E) = 0$ by Lemma Flatness. Thus we reduce to the case of schemes which is Derived Categories of Schemes, Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Tor amplitude on a quasi-compact quasi-separated scheme
Let $S$ be a scheme. Let $X$ be a quasi-separated algebraic space over $S$. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Let $a \leq b$. The following are equivalent
-
$E$ has tor amplitude in $[a, b]$, and
-
for all $\mathcal{F}$ in $\mathrm{QCoh}(\mathcal{O}_X)$ we have $H^i(E \otimes_{\mathcal{O}_X}^\mathbf{L} \mathcal{F}) = 0$ for $i \not \in [a, b]$.
Proof. It is clear that (1) implies (2). Assume (2). Let $j : U \to X$ be an étale morphism with $U$ affine. As $X$ is quasi-separated, we see that $j$ is both quasi-compact and separated. Hence $j_*$ transforms quasi-coherent modules into quasi-coherent modules (Morphisms of Spaces, Lemma Direct images and morphisms of algebraic spaces). Take any quasi-coherent module $\mathcal{G}$ on $U$. By assumption we see that $H^i(E \otimes_{\mathcal{O}_X}^\mathbf{L} j_*\mathcal{G})$ vanishes for $i \not \in [a, b]$. Pulling back by the flat morphism $j$ we find that $H^i(E|_U \otimes_{\mathcal{O}_U}^\mathbf{L} j^*j_*\mathcal{G})$ vanishes for $i \not \in [a, b]$. By Cohomology of Spaces, Lemma Étale morphisms we see that $\mathcal{G}$ is a direct summand of $j^*j_*\mathcal{G}$. It follows that condition (2) implies the vanishing of $H^i(E|_U \otimes_{\mathcal{O}_U}^\mathbf{L} \mathcal{G})$ for $i \not \in [a, b]$ for all quasi-coherent $\mathcal{O}_U$-modules $\mathcal{G}$. Since it suffices to prove that $E|_U$ has tor amplitude in $[a, b]$ we reduce to the case where $X$ is representable.
If \(X\) is representable by a scheme \(X_0\) then (Lemma Étale morphisms and quasi-coherent complexes) we can write \(E = \epsilon^*E_0\) where \(E_0\) is an object of \(D_\mathrm{QCoh}(\mathcal{O}_{X_0})\) and \(\epsilon : X_\mathrm{\acute{e}tale} \to (X_0)_{Zar}\) is as in (Derived quasi-coherent complexes). For every quasi-coherent module \(\mathcal{F}_0\) on \(X_0\) the module \(\epsilon^*\mathcal{F}_0\) is quasi-coherent on \(X\) and
\[ H^i(E \otimes_{\mathcal{O}_X}^\mathbf{L} \epsilon^*\mathcal{F}_0) = \epsilon^*H^i(E_0 \otimes_{\mathcal{O}_{X_0}}^\mathbf{L} \mathcal{F}_0) \]as \(\epsilon\) is flat (Lemma Flatness). Moreover, the vanishing of these sheaves for \(i \not \in [a, b]\) implies the same thing for \(H^i(E_0 \otimes_{\mathcal{O}_{X_0}}^\mathbf{L} \mathcal{F}_0)\) by the same lemma. Thus we've reduced the problem to the case of schemes which is treated in Derived Categories of Schemes, Lemma Tor amplitude on a quasi-compact quasi-separated scheme. \(\square\)
Lemma. Proper morphisms
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $T_i \subset |X|$, $i = 1, \ldots, n$ be closed subsets. If $T_i$, $i = 1, \ldots, n$ are proper over $Y$, then the same is true for $T_1 \cup \ldots \cup T_n$.
Proof. Let $Z_i$ be the reduced induced closed subscheme structure on $T_i$. The morphism $$Z_1 \amalg \ldots \amalg Z_n \longrightarrow X$$ is finite by Morphisms of Spaces, Lemmas Diagonals, separation and finite algebras and Finite algebras. As finite morphisms are universally closed (Morphisms of Spaces, Lemma Proper morphisms and finite algebras) and since $Z_1 \amalg \ldots \amalg Z_n$ is proper over $S$ we conclude by Lemma Proper morphisms part (2) that the image $Z_1 \cup \ldots \cup Z_n$ is proper over $S$. $\square$
Lemma. Base change for sheaf cohomology
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-compact and quasi-separated morphism of algebraic spaces over $S$. For $E$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and $K$ in $D_\mathrm{QCoh}(\mathcal{O}_Y)$ we have $$Rf_*(E) \otimes_{\mathcal{O}_Y}^\mathbf{L} K = Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*K)$$
Proof. Without any assumptions there is a map $Rf_*(E) \otimes_{\mathcal{O}_Y}^\mathbf{L} K \to Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*K)$. Namely, it is the adjoint to the canonical map $$Lf^*(Rf_*(E) \otimes_{\mathcal{O}_Y}^\mathbf{L} K) = Lf^*(Rf_*(E)) \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*K \longrightarrow E \otimes_{\mathcal{O}_X}^\mathbf{L} Lf^*K$$ coming from the map $Lf^*Rf_*E \to E$. See Cohomology on Sites, Lemmas Pullback of tensor products and direct sums and Adjunction for derived direct image. To check it is an isomorphism we may work étale locally on $Y$. Hence we reduce to the case that $Y$ is an affine scheme.
Suppose that $K = \bigoplus K_i$ is a direct sum of some complexes $K_i \in D_\mathrm{QCoh}(\mathcal{O}_Y)$. If the statement holds for each $K_i$, then it holds for $K$. Namely, the functors $Lf^*$ and $\otimes^\mathbf{L}$ preserve direct sums by construction and $Rf_*$ commutes with direct sums (for complexes with quasi-coherent cohomology sheaves) by Lemma Quasi-coherent complexes and coherent sheaves. Moreover, suppose that $K \to L \to M \to K[1]$ is a distinguished triangle in $D_\mathrm{QCoh}(Y)$. Then if the statement of the lemma holds for two of $K, L, M$, then it holds for the third (as the functors involved are exact functors of triangulated categories).
Assume $Y$ affine, say $Y = \operatorname{Spec}(A)$. The functor $\widetilde{\ } : D(A) \to D_\mathrm{QCoh}(\mathcal{O}_Y)$ is an equivalence by Lemma Étale morphisms and quasi-coherent complexes and Derived Categories of Schemes, Lemma Bounded comparison of affine derived categories. Let $T$ be the property for $K \in D(A)$ that the statement of the lemma holds for $\widetilde{K}$. The discussion above and More on Algebra, Remark Derived commutative algebra shows that it suffices to prove $T$ holds for $A[k]$. This finishes the proof, as the statement of the lemma is clear for shifts of the structure sheaf. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $K \in D(\mathcal{O}_X)$. The following are equivalent
-
$K$ is pseudo-coherent, and
-
$K = \text{hocolim} K_n$ where $K_n$ is perfect and $\tau_{\geq -n}K_n \to \tau_{\geq -n}K$ is an isomorphism for all $n$.
Proof. The implication (2) $\Rightarrow$ (1) is true on any ringed site. Namely, assume (2) holds. Recall that a perfect object of the derived category is pseudo-coherent, see Cohomology on Sites, Lemma Perfect complexes. Then it follows from the definitions that $\tau_{\geq -n}K_n$ is $(-n + 1)$-pseudo-coherent and hence $\tau_{\geq -n}K$ is $(-n + 1)$-pseudo-coherent, hence $K$ is $(-n + 1)$-pseudo-coherent. This is true for all $n$, hence $K$ is pseudo-coherent, see Cohomology on Sites, Definition Pseudo-coherent complexes.
Assume (1). We start by choosing an approximation $K_1 \to K$ of $(X, K, -2)$ by a perfect complex $K_1$, see Definitions Bounds for perfect approximation and Perfect approximation with prescribed cohomology and Theorem Perfect approximation with prescribed closed support. Suppose by induction we have $$K_1 \to K_2 \to \ldots \to K_n \to K$$ with $K_i$ perfect such that such that $\tau_{\geq -i}K_i \to \tau_{\geq -i}K$ is an isomorphism for all $1 \leq i \leq n$. Then we pick $a \leq b$ as in Lemma Ext from a perfect complex to bounded quasi-coherent cohomology for the perfect object $K_n$. Choose an approximation $K_{n + 1} \to K$ of $(X, K, \min(a - 1, -n - 1))$. Choose a distinguished triangle $$K_{n + 1} \to K \to C \to K_{n + 1}[1]$$ Then we see that $C \in D_\mathrm{QCoh}(\mathcal{O}_X)$ has $H^i(C) = 0$ for $i \geq a$. Thus by our choice of $a, b$ we see that $\operatorname{Hom}_{D(\mathcal{O}_X)}(K_n, C) = 0$. Hence the composition $K_n \to K \to C$ is zero. Hence by Derived Categories, Lemma Representability of a homological functor we can factor $K_n \to K$ through $K_{n + 1}$ proving the induction step.
We still have to prove that $K = \text{hocolim} K_n$. This follows by an application of Derived Categories, Lemma Sheaf cohomology to the functors $H^i( - ) : D(\mathcal{O}_X) \to \textit{Mod}(\mathcal{O}_X)$ and our choice of $K_n$. $\square$
Lemma. Perfect complexes
In Situation A filtered inverse system for descent the category of perfect objects of $D(\mathcal{O}_X)$ is the colimit of the categories of perfect objects of $D(\mathcal{O}_{X_i})$.
Proof. For every quasi-compact and quasi-separated object $U_0$ of $(X_0)_{spaces, \mathrm{\acute{e}tale}}$ consider the condition $P$ that the functor $$\mathop{\operatorname{colim}}_{i \geq 0} D_{perf}(\mathcal{O}_{U_i}) \longrightarrow D_{perf}(\mathcal{O}_U)$$ is an equivalence where ${}_{perf}$ indicates the full subcategory of perfect objects and where $U = X \times_{X_0} U_0$ and $U_i = X_i \times_{X_0} U_0$. We will prove $P$ holds for every $U_0$ by the induction principle of Lemma Induction by elementary distinguished squares. First, we observe that we already know the functor is fully faithful by Lemma Descent of derived quasi-coherent complexes. Thus it suffices to prove essential surjectivity.
We first check condition (2) of the induction principle. Thus suppose that we have an elementary distinguished square $(U_0 \subset X_0, V_0 \to X_0)$ and that $P$ holds for $U_0$, $V_0$, and $U_0 \times_{X_0} V_0$. Let $E$ be a perfect object of $D(\mathcal{O}_X)$. We can find $i \geq 0$ and $E_{U, i}$ perfect on $U_i$ and $E_{V, i}$ perfect on $V_i$ whose pullback to $U$ and $V$ are isomorphic to $E|_U$ and $E|_V$. Denote $$a : E_{U, i} \to (R(X \to X_i)_*E)|_{U_i} \quad\text{and}\quad b : E_{V, i} \to (R(X \to X_i)_*E)|_{V_i}$$ the maps adjoint to the isomorphisms $L(U \to U_i)^*E_{U, i} \to E|_U$ and $L(V \to V_i)^*E_{V, i} \to E|_V$. By fully faithfulness, after increasing $i$, we can find an isomorphism $c : E_{U, i}|_{U_i \times_{X_i} V_i} \to E_{V, i}|_{U_i \times_{X_i} V_i}$ which pulls back to the identifications $$L(U \to U_i)^*E_{U, i}|_{U \times_X V} \to E|_{U \times_X V} \to L(V \to V_i)^*E_{V, i}|_{U \times_X V}.$$ Apply Lemma Derived gluing across an elementary distinguished square to get an object $E_i$ on $X_i$ and a map $d : E_i \to R(X \to X_i)_*E$ which restricts to the maps $a$ and $b$ over $U_i$ and $V_i$. Then it is clear that $E_i$ is perfect and that $d$ is adjoint to an isomorphism $L(X \to X_i)^*E_i \to E$.
Finally, we check condition (1) of the induction principle, in other words, we check the lemma holds when $X_0$ is affine. This follows from the case of schemes, see Derived Categories of Schemes, Lemma Descent of perfect complexes. To see this use the equivalence of Lemma Étale morphisms and quasi-coherent complexes and use the translation of Lemma Descent of perfect complexes. $\square$
Lemma. Perfect direct images for proper morphisms of finite presentation
Let $S$ be a scheme. Let $f : X \to Y$ be a proper morphism of finite presentation of algebraic spaces over $S$.
-
Let $E \in D(\mathcal{O}_X)$ be perfect and $f$ flat. Then $Rf_*E$ is a perfect object of $D(\mathcal{O}_Y)$ and its formation commutes with arbitrary base change.
-
Let $\mathcal{G}$ be an $\mathcal{O}_X$-module of finite presentation, flat over $Y$. Then $Rf_*\mathcal{G}$ is a perfect object of $D(\mathcal{O}_Y)$ and its formation commutes with arbitrary base change.
Proof. Special cases of Lemma Perfect proper-support direct images over arbitrary bases applied with (1) $\mathcal{G}^\bullet$ equal to $\mathcal{O}_X$ in degree $0$ and (2) $E = \mathcal{O}_X$ and $\mathcal{G}^\bullet$ consisting of $\mathcal{G}$ sitting in degree $0$. $\square$
Lemma. Mayer--Vietoris for unbounded quasi-coherent complexes
Let $S$ be a scheme. Let $(U \subset X, V \to X)$ be an elementary distinguished square of algebraic spaces over $S$. For an object $E$ of $D(\mathcal{O}_X)$ we have a distinguished triangle $$R\Gamma(X, E) \to R\Gamma(U, E) \oplus R\Gamma(V, E) \to R\Gamma(U \times_X V, E) \to R\Gamma(X, E)[1]$$ and in particular a long exact cohomology sequence $$\ldots \to H^n(X, E) \to H^n(U, E) \oplus H^n(V, E) \to H^n(U \times_X V, E) \to H^{n + 1}(X, E) \to \ldots$$ The construction of the distinguished triangle and the long exact sequence is functorial in $E$.
Proof. Choose a K-injective complex $\mathcal{I}^\bullet$ representing $E$ whose terms $\mathcal{I}^n$ are injective objects of $\textit{Mod}(\mathcal{O}_X)$, see Injectives, Theorem Injective resolutions (uncovered prerequisite). In the proof of Lemma Derived quasi-coherent complexes we found a short exact sequence of complexes $$0 \to \mathcal{I}^\bullet \to j_{U, *}\mathcal{I}^\bullet|_U \oplus j_{V, *}\mathcal{I}^\bullet|_V \to j_{U \times_X V, *}\mathcal{I}^\bullet|_{U \times_X V} \to 0$$ Since $H^1(X, \mathcal{I}^n) = 0$, we see that taking global sections gives an exact sequence of complexes $$0 \to \Gamma(X, \mathcal{I}^\bullet) \to \Gamma(U, \mathcal{I}^\bullet) \oplus \Gamma(V, \mathcal{I}^\bullet) \to \Gamma(U \times_X V, \mathcal{I}^\bullet) \to 0$$ Since these complexes represent $R\Gamma(X, E)$, $R\Gamma(U, E)$, $R\Gamma(V, E)$, and $R\Gamma(U \times_X V, E)$ we get a distinguished triangle by Derived Categories, Section Derived tensor products and Tor amplitude and especially Lemma Derived tensor products, Tor amplitude and derived categories. $\square$
Theorem. Quasi-coherent complexes
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Then there exist a differential graded algebra $(E, \text{d})$ with only a finite number of nonzero cohomology groups $H^i(E)$ such that $D_\mathrm{QCoh}(\mathcal{O}_X)$ is equivalent to $D(E, \text{d})$.
Proof. Let $K^\bullet$ be a K-injective complex of $\mathcal{O}$-modules which is perfect and generates $D_\mathrm{QCoh}(\mathcal{O}_X)$. Such a thing exists by Theorem A perfect generator for a quasi-compact algebraic space and the existence of K-injective resolutions. We will show the theorem holds with $$(E, \text{d}) = \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O}_X)}(K^\bullet, K^\bullet)$$ where $\text{Comp}^{dg}(\mathcal{O}_X)$ is the differential graded category of complexes of $\mathcal{O}$-modules. Please see Differential Graded Algebra, Section Base change for differential graded modules. Since $K^\bullet$ is K-injective we have
$$H^n(E) = \operatorname{Ext}^n_{D(\mathcal{O}_X)}(K^\bullet, K^\bullet)$$ for all $n \in \mathbf{Z}$. Only a finite number of these Exts are nonzero by Lemma Ext from a perfect complex to bounded quasi-coherent cohomology. Consider the functor $$- \otimes_E^\mathbf{L} K^\bullet : D(E, \text{d}) \longrightarrow D(\mathcal{O}_X)$$ of Differential Graded Algebra, Lemma Derived categories and tensor products and direct sums. Since $K^\bullet$ is perfect, it defines a compact object of $D(\mathcal{O}_X)$, see Proposition Compact objects are perfect. Combined with (the displayed identity) the functor above is fully faithful as follows from Differential Graded Algebra, Lemmas Differential graded modules. It has a right adjoint $$R\operatorname{Hom}(K^\bullet, - ) : D(\mathcal{O}_X) \longrightarrow D(E, \text{d})$$ by Differential Graded Algebra, Lemmas Derived Hom, Ext and derived categories which is a left quasi-inverse functor by generalities on adjoint functors. On the other hand, it follows from Lemma Quasi-coherent complexes and derived categories that we obtain $$- \otimes_E^\mathbf{L} K^\bullet : D(E, \text{d}) \longrightarrow D_\mathrm{QCoh}(\mathcal{O}_X)$$ and by our choice of $K^\bullet$ as a generator of $D_\mathrm{QCoh}(\mathcal{O}_X)$ the kernel of the adjoint restricted to $D_\mathrm{QCoh}(\mathcal{O}_X)$ is zero. A formal argument shows that we obtain the desired equivalence, see Derived Categories, Lemma Triangulated categories. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a quasi-separated and quasi-compact morphism of algebraic spaces over $S$. Then $Rf_* : D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_Y)$ commutes with direct sums.
Proof. Let $E_i$ be a family of objects of $D_\mathrm{QCoh}(\mathcal{O}_X)$ and set $E = \bigoplus E_i$. We want to show that the map $$\bigoplus Rf_*E_i \longrightarrow Rf_*E$$ is an isomorphism. We will show it induces an isomorphism on cohomology sheaves in degree $0$ which will imply the lemma. Choose an integer $N$ as in Lemma Quasi-coherent complexes and coherent sheaves. Then $R^0f_*E = R^0f_*\tau_{\geq -N}E$ and $R^0f_*E_i = R^0f_*\tau_{\geq -N}E_i$ by the lemma cited. Observe that $\tau_{\geq -N}E = \bigoplus \tau_{\geq -N}E_i$. Thus we may assume all of the $E_i$ have vanishing cohomology sheaves in degrees $< -N$. Next we use the spectral sequences $$R^pf_*H^q(E) \Rightarrow R^{p + q}f_*E \quad\text{and}\quad R^pf_*H^q(E_i) \Rightarrow R^{p + q}f_*E_i$$ (Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories) to reduce to the case of a direct sum of quasi-coherent sheaves. This case is handled by Cohomology of Spaces, Lemma Filtered limits and sheaf cohomology. $\square$
Lemma. Base change for derived quasi-coherent complexes
Let $S$ be a scheme. Let $g : Y' \to Y$ be a morphism of algebraic spaces over $S$. Let $f : X \to Y$ be a quasi-compact and quasi-separated morphism of algebraic spaces over $S$. Consider the base change diagram $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ If $X$ and $Y'$ are Tor independent over $Y$, then for all $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$ we have $Rf'_*L(g')^*E = Lg^*Rf_*E$.
Proof. For any object $E$ of $D(\mathcal{O}_X)$ we can use Cohomology on Sites, Remark Base change for derived modules on ringed sites to get a canonical base change map $Lg^*Rf_*E \to Rf'_*L(g')^*E$. To check this is an isomorphism we may work étale locally on $Y'$. Hence we may assume $g : Y' \to Y$ is a morphism of affine schemes. In particular, $g$ is affine and it suffices to show that $$Rg_*Lg^*Rf_*E \to Rg_*Rf'_*L(g')^*E = Rf_*(Rg'_* L(g')^* E)$$ is an isomorphism, see Lemma Affine neighbourhoods (and use Lemmas Quasi-coherent complexes and coherent sheaves, Quasi-coherent complexes and coherent sheaves, and Quasi-coherent complexes and coherent sheaves to see that the objects $Rf'_*L(g')^*E$ and $Lg^*Rf_*E$ have quasi-coherent cohomology sheaves). Note that $g'$ is affine as well (Morphisms of Spaces, Lemma Base change for affine neighbourhoods). By Lemma Affine neighbourhoods the map becomes a map $$Rf_*E \otimes_{\mathcal{O}_Y}^\mathbf{L} g_*\mathcal{O}_{Y'} \longrightarrow Rf_*(E \otimes_{\mathcal{O}_X}^\mathbf{L} g'_*\mathcal{O}_{X'})$$ Observe that $g'_*\mathcal{O}_{X'} = f^*g_*\mathcal{O}_{Y'}$. Thus by Lemma Base change for sheaf cohomology it suffices to prove that $Lf^*g_*\mathcal{O}_{Y'} = f^*g_*\mathcal{O}_{Y'}$. This follows from our assumption that $X$ and $Y'$ are Tor independent over $Y$. Namely, to check it we may work étale locally on $X$, hence we may also assume $X$ is affine. Say $X = \operatorname{Spec}(A)$, $Y = \operatorname{Spec}(R)$ and $Y' = \operatorname{Spec}(R')$. Our assumption implies that $A$ and $R'$ are Tor independent over $R$ (see Lemma Derived tensor products and Tor amplitude and More on Algebra, Lemma Derived tensor products and Tor amplitude), i.e., $\text{Tor}_i^R(A, R') = 0$ for $i > 0$. In other words $A \otimes_R^\mathbf{L} R' = A \otimes_R R'$ which exactly means that $Lf^*g_*\mathcal{O}_{Y'} = f^*g_*\mathcal{O}_{Y'}$. $\square$
Lemma. Derived tensor products and Tor amplitude
Let $S$ be a scheme. Let $B$ be an algebraic space over $S$. Let $X$, $Y$ be algebraic spaces over $B$. The following are equivalent
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$X$ and $Y$ are Tor independent over $B$,
-
for every commutative diagram $$\begin{gathered}\begin{matrix}U & W & V \\ X & B & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow W \\ W & \longrightarrow B \\ V & \longrightarrow Y \\ V & \longrightarrow W \\ X & \longrightarrow B \\ Y & \longrightarrow B\end{aligned}\end{gathered}$$ with étale vertical arrows $U$ and $V$ are Tor independent over $W$,
-
for some commutative diagram as in (2) with (a) $W \to B$ étale surjective, (b) $U \to X \times_B W$ étale surjective, (c) $V \to Y \times_B W$ étale surjective, the spaces $U$ and $V$ are Tor independent over $W$, and
-
for some commutative diagram as in (3) with $U$, $V$, $W$ schemes, the schemes $U$ and $V$ are Tor independent over $W$ in the sense of Derived Categories of Schemes, Definition Tor-independent pairs.
Proof. For an étale morphism $\varphi : U \to X$ of algebraic spaces and geometric point $\overline{u}$ the map of local rings $\mathcal{O}_{X, \varphi(\overline{u})} \to \mathcal{O}_{U, \overline{u}}$ is an isomorphism. Hence the equivalence of (1) and (2) follows. So does the implication (1) $\Rightarrow$ (3). Assume (3) and pick a diagram of geometric points as in Definition Tor-independent pairs. The assumptions imply that we can first lift $\overline{b}$ to a geometric point $\overline{w}$ of $W$, then lift the geometric point $(\overline{x}, \overline{b})$ to a geometric point $\overline{u}$ of $U$, and finally lift the geometric point $(\overline{y}, \overline{b})$ to a geometric point $\overline{v}$ of $V$. Use Properties of Spaces, Lemma Étale geometry of algebraic spaces to find the lifts. Using the remark on local rings above we conclude that the condition of the definition is satisfied for the given diagram.
Having made these initial points, it is clear that (4) comes down to the statement that Definition Tor-independent pairs agrees with Derived Categories of Schemes, Definition Tor-independent pairs when $X$, $Y$, and $B$ are schemes.
Let $\overline{x}, \overline{b}, \overline{y}$ be as in Definition Tor-independent pairs lying over the points $x, y, b$. Recall that $\mathcal{O}_{X, \overline{x}} = \mathcal{O}_{X, x}^{sh}$ (Properties of Spaces, Lemma Étale morphisms and local algebra) and similarly for the other two. By Algebra, Lemma Lifting residue maps between strictly henselian rings we see that $\mathcal{O}_{X, \overline{x}}$ is a strict henselization of $\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{B, b}} \mathcal{O}_{B, \overline{b}}$. In particular, the ring map $$\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{B, b}} \mathcal{O}_{B, \overline{b}} \longrightarrow \mathcal{O}_{X, \overline{x}}$$ is flat (More on Algebra, Lemma Henselian local rings and henselization, Sections 4 and 6, Proposition 6.1). By More on Algebra, Lemma Derived tensor products, Tor amplitude and flatness we see that $$\text{Tor}i^{\mathcal{O}{B, b}}(\mathcal{O}{X, x}, \mathcal{O}{Y, y}) \otimes_{\mathcal{O}{X, x} \otimes{\mathcal{O}{B, b}} \mathcal{O}{Y, y}} (\mathcal{O}{X, \overline{x}} \otimes{\mathcal{O}{B, \overline{b}}} \mathcal{O}{Y, \overline y})
\text{Tor}i^{\mathcal{O}{B, \overline{b}}}( \mathcal{O}{X, \overline{x}}, \mathcal{O}{Y, \overline{y}})$$ Hence it follows that if $X$ and $Y$ are Tor independent over $B$ as schemes, then $X$ and $Y$ are Tor independent as algebraic spaces over $B$.
For the converse, we may assume $X$, $Y$, and $B$ are affine. Observe that the ring map $$\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{B, b}} \mathcal{O}_{Y, y} \longrightarrow \mathcal{O}_{X, \overline{x}} \otimes_{\mathcal{O}_{B, \overline{b}}} \mathcal{O}_{Y, \overline y}$$ is flat by the observations given above. Moreover, the image of the map on spectra includes all primes $\mathfrak s \subset \mathcal{O}_{X, x} \otimes_{\mathcal{O}_{B, b}} \mathcal{O}_{Y, y}$ lying over $\mathfrak m_x$ and $\mathfrak m_y$. Hence from this and the displayed formula of Tor's above we see that if $X$ and $Y$ are Tor independent over $B$ as algebraic spaces, then $$\text{Tor}_i^{\mathcal{O}_{B, b}} (\mathcal{O}_{X, x}, \mathcal{O}_{Y, y})_\mathfrak s = 0$$ for all $i > 0$ and all $\mathfrak s$ as above. By More on Algebra, Lemma Derived tensor products and Tor amplitude applied to the ring maps $\Gamma(B, \mathcal{O}_B) \to \Gamma(X, \mathcal{O}_X)$ and $\Gamma(B, \mathcal{O}_B) \to \Gamma(X, \mathcal{O}_X)$ this implies that $X$ and $Y$ are Tor independent over $B$. $\square$
Example. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $(\mathcal{F}_n)$ be an inverse system of quasi-coherent sheaves on $X$. Since $DQ_X$ is a right adjoint it commutes with products and therefore with derived limits. Hence we see that $$DQ_X(R\varprojlim \mathcal{F}_n) = (R\varprojlim\text{ in }D_\mathrm{QCoh}(\mathcal{O}_X))(\mathcal{F}_n)$$ where the first $R\varprojlim$ is taken in $D(\mathcal{O}_X)$. In fact, let's write $K = R\varprojlim \mathcal{F}_n$ for this. For any affine $U$ étale over $X$ we have $$H^i(U, K) = H^i(R\Gamma(U, R\varprojlim \mathcal{F}_n)) = H^i(R\varprojlim R\Gamma(U, \mathcal{F}_n)) = H^i(R\varprojlim \Gamma(U, \mathcal{F}_n))$$ since cohomology commutes with derived limits and since the quasi-coherent sheaves $\mathcal{F}_n$ have no higher cohomology on affines. By the computation of $R\varprojlim$ in the category of abelian groups, we see that $H^i(U, K) = 0$ unless $i \in [0, 1]$. Then finally we conclude that the $R\varprojlim$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$, which is $DQ_X(K)$ by the above, is in $D^b_\mathrm{QCoh}(\mathcal{O}_X)$ and has vanishing cohomology sheaves in negative degrees by Lemma Bounds for the derived quasi-coherator.
Lemma. Derived Hom, Ext and finite algebras
Let $A$ be a Noetherian ring. Let $X$ be a proper algebraic space over $A$. For $L$ in $D^+_{\textit{Coh}}(\mathcal{O}_X)$ and $K$ in $D^-_{\textit{Coh}}(\mathcal{O}_X)$, the $A$-modules $\operatorname{Ext}_{\mathcal{O}_X}^n(K, L)$ are finite.
Proof. Recall that $$\operatorname{Ext}_{\mathcal{O}_X}^n(K, L) = H^n(X, R\mathcal{H}om_{\mathcal{O}_X}(K, L)) = H^n(\operatorname{Spec}(A), Rf_*R\mathcal{H}om_{\mathcal{O}_X}(K, L))$$ see Cohomology on Sites, Lemma Derived Hom and Ext and Cohomology on Sites, Section Sheaf cohomology. Thus the result follows from Lemmas Derived Hom, Ext and coherent sheaves and Direct images and coherent sheaves. $\square$
Lemma. A K-injective representative compatible with quasi-coherence
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Then the map $E \to R\varprojlim \tau_{\geq -n}E$ of Derived Categories, Remark Derived categories is an isomorphism[^1].
Proof. Denote $\mathcal{H}^i = H^i(E)$ the $i$th cohomology sheaf of $E$. Let $\mathcal{B}$ be the set of affine objects of $X_\mathrm{\acute{e}tale}$. Then $H^p(U, \mathcal{H}^i) = 0$ for all $p > 0$, all $i \in \mathbf{Z}$, and all $U \in \mathcal{B}$ as $U$ is an affine scheme. See discussion in Cohomology of Spaces, Section Quasi-coherent cohomology and Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). Thus the lemma follows from Cohomology on Sites, Lemma Dimension and codimension (uncovered prerequisite) with $d = 0$. $\square$
Definition. Proper morphisms
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $T \subset |X|$ be a closed subset. We say $T$ is proper over $Y$ if the equivalent conditions of Lemma Proper morphisms are satisfied.
Lemma. Proper morphisms
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $T' \subset T \subset |X|$ be closed subsets. If $T$ is proper over $Y$, then the same is true for $T'$.
Proof. Omitted. $\square$
Lemma. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $(U \subset X, V \to X)$ be an elementary distinguished square of algebraic spaces over $S$.
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For a sheaf of $\mathcal{O}_X$-modules $\mathcal{F}$ we have a short exact sequence $$0 \to j_{U \times_X V!}\mathcal{F}|_{U \times_X V} \to j_{U!}\mathcal{F}|_U \oplus j_{V!}\mathcal{F}|_V \to \mathcal{F} \to 0$$
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For an object $E$ of $D(\mathcal{O}_X)$ we have a distinguished triangle $$j_{U \times_X V!}E|_{U \times_X V} \to j_{U!}E|_U \oplus j_{V!}E|_V \to E \to j_{U \times_X V!}E|_{U \times_X V}[1]$$ in $D(\mathcal{O}_X)$.
Proof. To show the sequence of (1) is exact we may check on stalks at geometric points by Properties of Spaces, Theorem Sheaves on ringed sites. Let $\overline{x}$ be a geometric point of $X$. By Equations (Sheaves on ringed sites) and (Sheaves on ringed sites) taking stalks at $\overline{x}$ we obtain the sequence $$0 \to \bigoplus\nolimits_{(\overline{u}, \overline{v})} \mathcal{F}_{\overline{x}} \to \bigoplus\nolimits_{\overline{u}} \mathcal{F}_{\overline{x}} \oplus \bigoplus\nolimits_{\overline{v}} \mathcal{F}_{\overline{x}} \to \mathcal{F}_{\overline{x}} \to 0$$ This sequence is exact because for every $\overline{x}$ there either is exactly one $\overline{u}$ mapping to $\overline{x}$, or there is no $\overline{u}$ and exactly one $\overline{v}$ mapping to $\overline{x}$.
Proof of (2). We have seen in Cohomology on Sites, Section Injective resolutions and proper morphisms that the restriction functors and the extension by zero functors on derived categories are computed by just applying the functor to any complex. Let $\mathcal{E}^\bullet$ be a complex of $\mathcal{O}_X$-modules representing $E$. The distinguished triangle of the lemma is the distinguished triangle associated (by Derived Categories, Section Derived tensor products and Tor amplitude and especially Lemma Derived tensor products, Tor amplitude and derived categories) to the short exact sequence of complexes of $\mathcal{O}_X$-modules $$0 \to j_{U \times_X V!}\mathcal{E}^\bullet|_{U \times_X V} \to j_{U!}\mathcal{E}^\bullet|_U \oplus j_{V!}\mathcal{E}^\bullet|_V \to \mathcal{E}^\bullet \to 0$$ which is short exact by (1). $\square$
Lemma. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $j : U \to X$ be a étale morphism of algebraic spaces over $S$. Given an étale morphism $V \to X$, set $W = V \times_X U$ and denote $j_W : W \to V$ the projection morphism. Then $(j_!E)|_V = j_{W!}(E|_W)$ for $E$ in $D(\mathcal{O}_U)$.
Proof. This is true because $(j_!\mathcal{F})|_V = j_{W!}(\mathcal{F}|_W)$ for an $\mathcal{O}_X$-module $\mathcal{F}$ as follows immediately from the construction of the functors $j_!$ and $j_{W!}$, see Modules on Sites, Lemma The geometric construction (uncovered prerequisite). $\square$
Lemma. Descent of finite algebras
Let $X$ be a scheme. Let $\mathcal{F}$ be an $\mathcal{O}_X$-module. The following are equivalent
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$\mathcal{F}$ is of finite type as an $\mathcal{O}_X$-module, and
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$\epsilon^*\mathcal{F}$ is of finite type as an $\mathcal{O}_\mathrm{\acute{e}tale}$-module on the small étale site of $X$.
Here $\epsilon$ is as in (Derived quasi-coherent complexes).
Proof. The implication (1) $\Rightarrow$ (2) is a general fact, see Modules on Sites, Lemma Local pullback on a ringed site. Assume (2). By assumption there exists an étale covering $\{f_i : X_i \to X\}$ such that $\epsilon^*\mathcal{F}|_{(X_i)_\mathrm{\acute{e}tale}}$ is generated by finitely many sections. Let $x \in X$. We will show that $\mathcal{F}$ is generated by finitely many sections in a neighbourhood of $x$. Say $x$ is in the image of $X_i \to X$ and denote $X' = X_i$. Let $s_1, \ldots, s_n \in \Gamma(X', \epsilon^*\mathcal{F}|_{X'_\mathrm{\acute{e}tale}})$ be generating sections. As $\epsilon^*\mathcal{F} = \epsilon^{-1}\mathcal{F} \otimes_{\epsilon^{-1}\mathcal{O}_X} \mathcal{O}_\mathrm{\acute{e}tale}$ we can find an étale morphism $X'' \to X'$ such that $x$ is in the image of $X'' \to X$ and such that $s_i|_{X''} = \sum s_{ij} \otimes a_{ij}$ for some sections $s_{ij} \in \epsilon^{-1}\mathcal{F}(X'')$ and $a_{ij} \in \mathcal{O}_\mathrm{\acute{e}tale}(X'')$. Denote $U \subset X$ the image of $X'' \to X$. This is an open subscheme as $f'' : X'' \to X$ is étale (Morphisms, Lemma Étale morphisms (uncovered prerequisite)). After possibly shrinking $X''$ more we may assume $s_{ij}$ come from elements $t_{ij} \in \mathcal{F}(U)$ as follows from the construction of the inverse image functor $\epsilon^{-1}$. Now we claim that $t_{ij}$ generate $\mathcal{F}|_U$ which finishes the proof of the lemma. Namely, the corresponding map $\mathcal{O}_U^{\oplus N} \to \mathcal{F}|_U$ has the property that its pullback by $f''$ to $X''$ is surjective. Since $f'' : X'' \to U$ is a surjective flat morphism of schemes, this implies that $\mathcal{O}_U^{\oplus N} \to \mathcal{F}|_U$ is surjective by looking at stalks and using that $\mathcal{O}_{U, f''(z)} \to \mathcal{O}_{X'', z}$ is faithfully flat for all $z \in X''$. $\square$
Lemma. Descent of derived tensor products and Tor amplitude
Let $X$ be a scheme. Let $E$ be an object of $D(\mathcal{O}_X)$. Then
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$E$ has tor amplitude in $[a, b]$ if and only if $\epsilon^*E$ has tor amplitude in $[a, b]$.
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$E$ has finite tor dimension if and only if $\epsilon^*E$ has finite tor dimension.
Here $\epsilon$ is as in (Derived quasi-coherent complexes).
Proof. The easy implication follows from Cohomology on Sites, Lemma Derived tensor products and Tor amplitude (uncovered prerequisite). For the converse, assume that \(\epsilon^*E\) has tor amplitude in \([a, b]\). Let \(\mathcal{F}\) be an \(\mathcal{O}_X\)-module. As \(\epsilon\) is a flat morphism of ringed sites (Lemma Flatness) we have
\[ \epsilon^*(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{F}) = \epsilon^*E \otimes^\mathbf{L}_{\mathcal{O}_\mathrm{\acute{e}tale}} \epsilon^*\mathcal{F} \]Thus the (assumed) vanishing of cohomology sheaves on the right hand side implies the desired vanishing of the cohomology sheaves of \(E \otimes^\mathbf{L}_{\mathcal{O}_X} \mathcal{F}\) via Lemma Flatness. \(\square\)
Lemma. Lifting maps from support-preserving perfect complexes
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $W \subset X$ be a quasi-compact open. Let $T \subset |X|$ be a closed subset such that $X \setminus T \to X$ is a quasi-compact morphism. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Let $\alpha : P \to E|_W$ be a map where $P$ is a perfect object of $D(\mathcal{O}_W)$ supported on $T \cap W$. Then there exists a map $\beta : R \to E$ where $R$ is a perfect object of $D(\mathcal{O}_X)$ supported on $T$ such that $P$ is a direct summand of $R|_W$ in $D(\mathcal{O}_W)$ compatible $\alpha$ and $\beta|_W$.
Proof. We will use the induction principle of Lemma Derived quasi-coherent complexes to prove this. Thus we immediately reduce to the case where we have an elementary distinguished square $(W \subset X, f : V \to X)$ with $V$ affine and $P \to E|_W$ as in the statement of the lemma. In the rest of the proof we will use Lemma Étale morphisms and quasi-coherent complexes (and the compatibilities of Remark Derived quasi-coherent complexes) for the representable algebraic spaces $V$ and $W \times_X V$. We will also use the fact that perfectness on the Zariski site and étale site agree, see Lemma Descent of perfect complexes.
By Derived Categories of Schemes, Lemma Lifting perfect complexes while retaining support we can choose a perfect object $Q$ in $D(\mathcal{O}_V)$ supported on $f^{-1}T$ and an isomorphism $Q|_{W \times_X V} \to (P \oplus P[1])|_{W \times_X V}$. By Derived Categories of Schemes, Lemma Extending a morphism after finite denominators are cleared we can replace $Q$ by $Q \otimes^\mathbf{L} I$ (still supported on $f^{-1}T$) and assume that the map $$Q|_{W \times_X V} \to (P \oplus P[1])|_{W \times_X V} \longrightarrow P|_{W \times_X V} \longrightarrow E|_{W \times_X V}$$ lifts to $Q \to E|_V$. By Lemma Derived gluing across an elementary distinguished square we find an morphism $a : R \to E$ of $D(\mathcal{O}_X)$ such that $a|_W$ is isomorphic to $P \oplus P[1] \to E|_W$ and $a|_V$ isomorphic to $Q \to E|_V$. Thus $R$ is perfect and supported on $T$ as desired. $\square$
Lemma. Relative Mayer--Vietoris for unbounded complexes
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $(U \subset X, V \to X)$ be an elementary distinguished square. Denote $a = f|_U : U \to Y$, $b = f|_V : V \to Y$, and $c = f|_{U \times_X V} : U \times_X V \to Y$ the restrictions. For every object $E$ of $D(\mathcal{O}_X)$ there exists a distinguished triangle $$Rf_*E \to Ra_*(E|_U) \oplus Rb_*(E|_V) \to Rc_*(E|_{U \times_X V}) \to Rf_*E[1]$$ in $D(\mathcal{O}_Y)$. This triangle is functorial in $E$.
Proof. Choose a K-injective complex $\mathcal{I}^\bullet$ representing $E$. We may assume $\mathcal{I}^n$ is an injective object of $\textit{Mod}(\mathcal{O}_X)$ for all $n$, see Injectives, Theorem Injective resolutions (uncovered prerequisite). Then $Rf_*E$ is computed by $f_*\mathcal{I}^\bullet$. Similarly for $U$, $V$, and $U \times_X V$ by Cohomology on Sites, Lemma Injective resolutions. Hence the distinguished triangle of the lemma is the distinguished triangle associated (by Derived Categories, Section Derived tensor products and Tor amplitude and especially Lemma Derived tensor products, Tor amplitude and derived categories) to the short exact sequence of complexes $$0 \to f_*\mathcal{I}^\bullet \to a_*\mathcal{I}^\bullet|_U \oplus b_*\mathcal{I}^\bullet|_V \to c_*\mathcal{I}^\bullet|_{U \times_X V} \to 0.$$ To see this is a short exact sequence of complexes we argue as follows. Pick an injective object $\mathcal{I}$ of $\textit{Mod}(\mathcal{O}_X)$. Apply $f_*$ to the short exact sequence $$0 \to \mathcal{I} \to j_{U, *}\mathcal{I}|_U \oplus j_{V, *}\mathcal{I}|_V \to j_{U \times_X V, *}\mathcal{I}|_{U \times_X V} \to 0$$ of Lemma Derived quasi-coherent complexes and use that $R^1f_*\mathcal{I} = 0$ to get a short exact sequence $$0 \to f_*\mathcal{I} \to f_*j_{U, *}\mathcal{I}|_U \oplus f_*j_{V, *}\mathcal{I}|_V \to f_*j_{U \times_X V, *}\mathcal{I}|_{U \times_X V} \to 0$$ The proof is finished by observing that $a_* = f_*j_{U, *}$ and similarly for $b_*$ and $c_*$. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. For objects $K, L$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ the derived tensor product $K \otimes^\mathbf{L} L$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Proof. Let $\varphi : U \to X$ be a surjective étale morphism from a scheme $U$. Since $\varphi^*(K \otimes_{\mathcal{O}_X}^\mathbf{L} L) = \varphi^*K \otimes_{\mathcal{O}_U}^\mathbf{L} \varphi^*L$ we see from Lemma Quasi-coherent complexes and coherent sheaves that this follows from the case of schemes which is Derived Categories of Schemes, Lemma Quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Quasi-coherent complexes and derived Hom and Ext
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $L, K$ be objects of $D(\mathcal{O}_X)$. If either
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$L$ in $D^+_\mathrm{QCoh}(\mathcal{O}_X)$ and $K$ is pseudo-coherent,
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$L$ in $D_\mathrm{QCoh}(\mathcal{O}_X)$ and $K$ is perfect,
then $R\mathcal{H}om(K, L)$ is in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Proof. This follows from the analogue for schemes (Derived Categories of Schemes, Lemma Quasi-coherent complexes and derived Hom and Ext) via the criterion of Lemma Quasi-coherent complexes and coherent sheaves, the criterion of Lemmas Descent of pseudo-coherent complexes and coherent sheaves and Descent of perfect complexes, and the result of Lemma Descent of derived Hom and Ext. $\square$
Lemma. Proper morphisms
Let $S$ be a scheme. Let $B$ be an algebraic space over $S$. Let $f : X \to Y$ be a morphism of algebraic spaces which are locally of finite type over $B$.
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If $Y$ is separated over $B$ and $T \subset |X|$ is a closed subset proper over $B$, then $|f|(T)$ is a closed subset of $|Y|$ proper over $B$.
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If $f$ is universally closed and $T \subset |X|$ is a closed subset proper over $B$, then $|f|(T)$ is a closed subset of $Y$ proper over $B$.
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If $f$ is proper and $T \subset |Y|$ is a closed subset proper over $B$, then $|f|^{-1}(T)$ is a closed subset of $|X|$ proper over $B$.
Proof. Proof of (1). Assume $Y$ is separated over $B$ and $T \subset |X|$ is a closed subset proper over $B$. Let $Z$ be the reduced induced closed subspace structure on $T$ and apply Morphisms of Spaces, Lemma Proper morphisms (uncovered prerequisite) to $Z \to Y$ over $B$ to conclude.
Proof of (2). Assume $f$ is universally closed and $T \subset |X|$ is a closed subset proper over $B$. Let $Z$ be the reduced induced closed subspace structure on $T$ and let $Z'$ be the reduced induced closed subspace structure on $|f|(T)$. We obtain an induced morphism $Z \to Z'$. Denote $Z'' = f^{-1}(Z')$ the scheme theoretic inverse image. Then $Z'' \to Z'$ is universally closed as a base change of $f$ (Morphisms of Spaces, Lemma Base change for proper morphisms). Hence $Z \to Z'$ is universally closed as a composition of the closed immersion $Z \to Z''$ and $Z'' \to Z'$ (Morphisms of Spaces, Lemmas Proper morphisms and diagonals and separation and Composition and proper morphisms). We conclude that $Z' \to B$ is separated by Morphisms of Spaces, Lemma Diagonals and separation (uncovered prerequisite). Since $Z \to B$ is quasi-compact and $Z \to Z'$ is surjective we see that $Z' \to B$ is quasi-compact. Since $Z' \to B$ is the composition of $Z' \to Y$ and $Y \to B$ we see that $Z' \to B$ is locally of finite type (Morphisms of Spaces, Lemmas Diagonals, separation and finite algebras (uncovered prerequisite) and Composition and finite algebras). Finally, since $Z \to B$ is universally closed, we see that the same thing is true for $Z' \to B$ by Morphisms of Spaces, Lemma Proper morphisms. This finishes the proof.
Proof of (3). Assume $f$ is proper and $T \subset |Y|$ is a closed subset proper over $B$. Let $Z$ be the reduced induced closed subspace structure on $T$. Denote $Z' = f^{-1}(Z)$ the scheme theoretic inverse image. Then $Z' \to Z$ is proper as a base change of $f$ (Morphisms of Spaces, Lemma Base change for proper morphisms). Whence $Z' \to B$ is proper as the composition of $Z' \to Z$ and $Z \to B$ (Morphisms of Spaces, Lemma Composition and proper morphisms). This finishes the proof. $\square$
Lemma. Ext from a perfect complex to bounded quasi-coherent cohomology
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $K$ be a perfect object of $D(\mathcal{O}_X)$. Then
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there exist integers $a \leq b$ such that $\operatorname{Hom}_{D(\mathcal{O}_X)}(K, L) = 0$ for $L \in D_\mathrm{QCoh}(\mathcal{O}_X)$ with $H^i(L) = 0$ for $i \in [a, b]$, and
-
if $L$ is bounded, then $\operatorname{Ext}^n_{D(\mathcal{O}_X)}(K, L)$ is zero for all but finitely many $n$.
Proof. Part (2) follows from (1) as $\operatorname{Ext}^n_{D(\mathcal{O}_X)}(K, L) = \operatorname{Hom}_{D(\mathcal{O}_X)}(K, L[n])$. We prove (1). Since $K$ is perfect we have $$\operatorname{Ext}^i_{D(\mathcal{O}_X)}(K, L) = H^i(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$$ where $K^\vee$ is the "dual" perfect complex to $K$, see Cohomology on Sites, Lemma Perfect complexes and derived categories. Note that $P = K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L$ is in $D_\mathrm{QCoh}(X)$ by Lemmas Quasi-coherent complexes and coherent sheaves and Pseudo-coherent complexes and coherent sheaves (to see that a perfect complex has quasi-coherent cohomology sheaves). Say $K^\vee$ has tor amplitude in $[a, b]$. Then the spectral sequence $$E_1^{p, q} = H^p(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} H^q(L)) \Rightarrow H^{p + q}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$$ shows that $H^j(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$ is zero if $H^q(L) = 0$ for $q \in [j - b, j - a]$. Let $N$ be the integer $\max(d_p + p)$ of Cohomology of Spaces, Lemma Vanishing and diagonals and separation. Then $H^0(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$ vanishes if the cohomology sheaves $$H^{-N}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L), \ H^{-N + 1}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L), \ \ldots, \ H^0(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L)$$ are zero. Namely, by the lemma cited and Lemma Computing derived Hom with a quasi-coherent K-injective model, we have $$H^0(X, K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L) = H^0(X, \tau_{\geq -N}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L))$$ and by the vanishing of cohomology sheaves, this is equal to $H^0(X, \tau_{\geq 1}(K^\vee \otimes_{\mathcal{O}_X}^\mathbf{L} L))$ which is zero by Derived Categories, Lemma Vanishing in negative degrees. It follows that $\operatorname{Hom}_{D(\mathcal{O}_X)}(K, L)$ is zero if $H^i(L) = 0$ for $i \in [-b - N, -a]$. $\square$
Situation. A filtered inverse system for descent
Let $S$ be a scheme. Let $X = \varprojlim_{i \in I} X_i$ be a limit of a directed system of algebraic spaces over $S$ with affine transition morphisms $f_{i'i} : X_{i'} \to X_i$. We denote $f_i : X \to X_i$ the projection. We assume that $X_i$ is quasi-compact and quasi-separated for all $i \in I$. We also choose an element $0 \in I$.
Lemma. Descent of derived quasi-coherent complexes
In Situation A filtered inverse system for descent. Let $E_0$ and $K_0$ be objects of $D(\mathcal{O}_{X_0})$. Set $E_i = Lf_{i0}^*E_0$ and $K_i = Lf_{i0}^*K_0$ for $i \geq 0$ and set $E = Lf_0^*E_0$ and $K = Lf_0^*K_0$. Then the map $$\mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{D(\mathcal{O}_{X_i})}(E_i, K_i) \longrightarrow \operatorname{Hom}_{D(\mathcal{O}_X)}(E, K)$$ is an isomorphism if either
-
$E_0$ is perfect and $K_0 \in D_\mathrm{QCoh}(\mathcal{O}_{X_0})$, or
-
$E_0$ is pseudo-coherent and $K_0 \in D_\mathrm{QCoh}(\mathcal{O}_{X_0})$ has finite tor dimension.
Proof. For every quasi-compact and quasi-separated object $U_0$ of $(X_0)_{spaces, \mathrm{\acute{e}tale}}$ consider the condition $P$ that the canonical map $$\mathop{\operatorname{colim}}_{i \geq 0} \operatorname{Hom}_{D(\mathcal{O}_{U_i})}(E_i|_{U_i}, K_i|_{U_i}) \longrightarrow \operatorname{Hom}_{D(\mathcal{O}_U)}(E|_U, K|_U)$$ is an isomorphism, where $U = X \times_{X_0} U_0$ and $U_i = X_i \times_{X_0} U_0$. We will prove $P$ holds for each $U_0$ by the induction principle of Lemma Induction by elementary distinguished squares. Condition (2) of this lemma follows immediately from Mayer-Vietoris for hom in the derived category, see Lemma Derived Hom and Ext. Thus it suffices to prove the lemma when $X_0$ is affine.
If $X_0$ is affine, then the result follows from the case of schemes, see Derived Categories of Schemes, Lemma Descent of perfect complexes. To see this use the equivalence of Lemma Étale morphisms and quasi-coherent complexes and use the translation of properties explained in Lemmas Descent of pseudo-coherent complexes and coherent sheaves, Descent of derived tensor products and Tor amplitude, and Descent of perfect complexes. $\square$
Lemma. Quasi-coherent complexes and derived categories
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. Let $K^\bullet$ be a complex of $\mathcal{O}_X$-modules whose cohomology sheaves are quasi-coherent. Let $(E, d) = \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O}_X)}(K^\bullet, K^\bullet)$ be the endomorphism differential graded algebra. Then the functor $$- \otimes_E^\mathbf{L} K^\bullet : D(E, \text{d}) \longrightarrow D(\mathcal{O}_X)$$ of Differential Graded Algebra, Lemma Derived categories and tensor products and direct sums has image contained in $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Proof. Let $P$ be a differential graded $E$-module with property $P$. Let $F_\bullet$ be a filtration on $P$ as in Differential Graded Algebra, Section Differential graded modules. Then we have $$P \otimes_E K^\bullet = \text{hocolim}\ F_iP \otimes_E K^\bullet$$ Each of the $F_iP$ has a finite filtration whose graded pieces are direct sums of $E[k]$. The result follows easily. $\square$
Lemma. Affine neighbourhoods
Let $S$ be a scheme. Let $f : X \to Y$ be an affine morphism of algebraic spaces over $S$. Then $Rf_* : D_\mathrm{QCoh}(\mathcal{O}_X) \to D_\mathrm{QCoh}(\mathcal{O}_Y)$ reflects isomorphisms.
Proof. The statement means that a morphism $\alpha : E \to F$ of $D_\mathrm{QCoh}(\mathcal{O}_X)$ is an isomorphism if $Rf_*\alpha$ is an isomorphism. We may check this on cohomology sheaves. In particular, the question is étale local on $Y$. Hence we may assume $Y$ and therefore $X$ is affine. In this case the problem reduces to the case of schemes (Derived Categories of Schemes, Lemma Affine neighbourhoods) via Lemma Étale morphisms and quasi-coherent complexes and Remark Derived quasi-coherent complexes. $\square$
Lemma. Affine neighbourhoods
Let $S$ be a scheme. Let $f : X \to Y$ be an affine morphism of algebraic spaces over $S$. For $E$ in $D_\mathrm{QCoh}(\mathcal{O}_Y)$ we have $Rf_* Lf^* E = E \otimes^\mathbf{L}_{\mathcal{O}_Y} f_*\mathcal{O}_X$.
Proof. Since $f$ is affine the map $f_*\mathcal{O}_X \to Rf_*\mathcal{O}_X$ is an isomorphism (Cohomology of Spaces, Lemma Affine neighbourhoods). There is a canonical map $E \otimes^\mathbf{L} f_*\mathcal{O}_X = E \otimes^\mathbf{L} Rf_*\mathcal{O}_X \to Rf_* Lf^* E$ adjoint to the map $$Lf^*(E \otimes^\mathbf{L} Rf_*\mathcal{O}_X) = Lf^*E \otimes^\mathbf{L} Lf^*Rf_*\mathcal{O}_X \longrightarrow Lf^* E \otimes^\mathbf{L} \mathcal{O}_X = Lf^* E$$ coming from $1 : Lf^*E \to Lf^*E$ and the canonical map $Lf^*Rf_*\mathcal{O}_X \to \mathcal{O}_X$. To check the map so constructed is an isomorphism we may work locally on $Y$. Hence we may assume $Y$ and therefore $X$ is affine. In this case the problem reduces to the case of schemes (Derived Categories of Schemes, Lemma Affine neighbourhoods) via Lemma Étale morphisms and quasi-coherent complexes and Remark Derived quasi-coherent complexes. $\square$
Definition. Tor-independent pairs
Let $S$ be a scheme. Let $B$ be an algebraic space over $S$. Let $X$, $Y$ be algebraic spaces over $B$. We say $X$ and $Y$ are Tor independent over $B$ if and only if for every commutative diagram $$\begin{gathered}\begin{matrix}\operatorname{Spec}(k) & X \\ Y & B\end{matrix} \\[6pt] \begin{aligned}\operatorname{Spec}(k) & \xrightarrow{\overline{y}} Y \\ \operatorname{Spec}(k) & \xrightarrow{\overline{b}} B \\ \operatorname{Spec}(k) & \xrightarrow{\overline{x}} X \\ X & \longrightarrow B \\ Y & \longrightarrow B\end{aligned}\end{gathered}$$ of geometric points the rings $\mathcal{O}_{X, \overline{x}}$ and $\mathcal{O}_{Y, \overline{y}}$ are Tor independent over $\mathcal{O}_{B, \overline{b}}$ (see More on Algebra, Definition Tor-independent pairs).
Lemma. Derived Hom, Ext and coherent sheaves
Let $S$ be a scheme. Let $X$ be a locally Noetherian algebraic space over $S$. If $L$ is in $D^+_{\textit{Coh}}(\mathcal{O}_X)$ and $K$ in $D^-_{\textit{Coh}}(\mathcal{O}_X)$, then $R\mathcal{H}om(K, L)$ is in $D^+_{\textit{Coh}}(\mathcal{O}_X)$.
Proof. We can check whether an object of $D(\mathcal{O}_X)$ is in $D_{\textit{Coh}}(\mathcal{O}_X)$ étale locally on $X$, see Cohomology of Spaces, Lemma Coherent sheaves and Noetherian rings. Hence this lemma follows from the case of schemes, see Derived Categories of Schemes, Lemma Derived Hom, Ext and coherent sheaves. $\square$
Lemma. Direct images and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume $f$ is locally of finite type and $Y$ is Noetherian. Let $E$ be an object of $D^+_{\textit{Coh}}(\mathcal{O}_X)$ such that the support of $H^i(E)$ is proper over $S$ for all $i$. Then $Rf_*E$ is an object of $D^+_{\textit{Coh}}(\mathcal{O}_Y)$.
Proof. The proof is the same as the proof of Lemma Direct images and coherent sheaves. You can also deduce it from Lemma Direct images and coherent sheaves by considering what the exact functor $Rf_*$ does to the distinguished triangles $\tau_{\leq a}E \to E \to \tau_{\geq a + 1}E \to \tau_{\leq a}E[1]$. $\square$
Lemma. Proper morphisms
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $T \subset |X|$ be a closed subset. The following are equivalent
-
the morphism $Z \to Y$ is proper if $Z$ is the reduced induced algebraic space structure on $T$ (Properties of Spaces, Definition Étale geometry of algebraic spaces),
-
for some closed subspace $Z \subset X$ with $|Z| = T$ the morphism $Z \to Y$ is proper, and
-
for any closed subspace $Z \subset X$ with $|Z| = T$ the morphism $Z \to Y$ is proper.
Proof. The implications (3) $\Rightarrow$ (1) and (1) $\Rightarrow$ (2) are immediate. Thus it suffices to prove that (2) implies (3). We urge the reader to find their own proof of this fact. Let $Z'$ and $Z''$ be closed subspaces with $T = |Z'| = |Z''|$ such that $Z' \to Y$ is a proper morphism of algebraic spaces. We have to show that $Z'' \to Y$ is proper too. Let $Z''' = Z' \cup Z''$ be the scheme theoretic union, see Morphisms of Spaces, Definition Morphisms of algebraic spaces. Then $Z'''$ is another closed subspace with $|Z'''| = T$. This follows for example from the description of scheme theoretic unions in Morphisms of Spaces, Lemma Morphisms of algebraic spaces (uncovered prerequisite). Since $Z'' \to Z'''$ is a closed immersion it suffices to prove that $Z''' \to Y$ is proper (see Morphisms of Spaces, Lemmas Proper morphisms and diagonals and separation and Composition and proper morphisms). The morphism $Z' \to Z'''$ is a bijective closed immersion and in particular surjective and universally closed. Then the fact that $Z' \to Y$ is separated implies that $Z''' \to Y$ is separated, see Morphisms of Spaces, Lemma Diagonals and separation (uncovered prerequisite). Moreover $Z''' \to Y$ is locally of finite type as $X \to Y$ is locally of finite type (Morphisms of Spaces, Lemmas Diagonals, separation and finite algebras (uncovered prerequisite) and Composition and finite algebras). Since $Z' \to Y$ is quasi-compact and $Z' \to Z'''$ is a universal homeomorphism we see that $Z''' \to Y$ is quasi-compact. Finally, since $Z' \to Y$ is universally closed, we see that the same thing is true for $Z''' \to Y$ by Morphisms of Spaces, Lemma Proper morphisms. This finishes the proof. $\square$
Lemma. Derived quasi-coherent complexes
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $W \subset X$ be a quasi-compact open subspace. Let $P$ be a property of quasi-compact open subspaces of $X$. Assume that
-
$P$ holds for $W$, and
-
for every elementary distinguished square $(W_1 \subset W_2, f : V \to W_2)$ such that
-
$W_1$, $W_2$ are quasi-compact open subspaces of $X$,
-
$W \subset W_1$,
-
$V$ is affine, and
-
$P$ holds for $W_1$,
then $P$ holds for $W_2$.
-
Then $P$ holds for $X$.
Proof. We can deduce this from Lemma Diagonals and separation, but instead we will give a direct argument by explicitly redoing the proof of Lemma Induction by elementary distinguished squares. We will use the filtration $$\emptyset = U_{n + 1} \subset U_n \subset U_{n - 1} \subset \ldots \subset U_1 = X$$ and the morphisms $f_p : V_p \to U_p$ of Decent Spaces, Lemma Diagonals and separation. We will prove that $P$ holds for $W_p = W \cup U_p$ by descending induction on $p$. This will finish the proof as $W_1 = X$. Note that $P$ holds for $W_{n + 1} = W \cup U_{n + 1} = W$ by (1). Assume $P$ holds for $W_{p + 1}$. Observe that $W_p \setminus W_{p + 1}$ (with reduced induced subspace structure) is a closed subspace of $U_p \setminus U_{p + 1}$. Since $(U_{p + 1} \subset U_p, f_p : V_p \to U_p)$ is an elementary distinguished square, the same is true for $(W_{p + 1} \subset W_p, f_p : V_p \to W_p)$. However (2) may not apply as $V_p$ may not be affine. However, as $V_p$ is a quasi-compact scheme we may choose a finite affine open covering $V_p = V_{p, 1} \cup \ldots \cup V_{p, m}$. Set $W_{p, 0} = W_{p + 1}$ and $$W_{p, i} = W_{p + 1} \cup f_p(V_{p, 1} \cup \ldots \cup V_{p, i})$$ for $i = 1, \ldots, m$. These are quasi-compact open subspaces of $X$ containing $W$. Then we have $$W_{p + 1} = W_{p, 0} \subset W_{p, 1} \subset \ldots \subset W_{p, m} = W_p$$ and the pairs $$(W_{p, 0} \subset W_{p, 1}, f_p|_{V_{p, 1}}), (W_{p, 1} \subset W_{p, 2}, f_p|_{V_{p, 2}}),\ldots, (W_{p, m - 1} \subset W_{p, m}, f_p|_{V_{p, m}})$$ are elementary distinguished squares by Lemma Derived quasi-coherent complexes. Now (2) applies to each of these and we inductively conclude $P$ holds for $W_{p, 1}, \ldots, W_{p, m} = W_p$. $\square$
Lemma. Descent of derived Hom and Ext
Let $X$ be a scheme. Let $E, F$ be objects of $D(\mathcal{O}_X)$. Assume either
-
$E$ is pseudo-coherent and $F$ lies in $D^+(\mathcal{O}_X)$, or
-
$E$ is perfect and $F$ arbitrary,
then there is a canonical isomorphism $$\epsilon^*R\mathcal{H}om(E, F) \longrightarrow R\mathcal{H}om(\epsilon^*E, \epsilon^*F)$$ Here $\epsilon$ is as in (Derived quasi-coherent complexes).
Proof. Recall that $\epsilon$ is flat (Lemma Flatness) and hence $\epsilon^* = L\epsilon^*$. There is a canonical map from left to right by Cohomology on Sites, Remark The comparison maps for derived base change. To see this is an isomorphism we can work locally, i.e., we may assume $X$ is an affine scheme.
In case (1) we can represent $E$ by a bounded above complex $\mathcal{E}^\bullet$ of finite free $\mathcal{O}_X$-modules, see Derived Categories of Schemes, Lemma Lifting pseudo-coherent complexes and coherent sheaves. We may also represent $F$ by a bounded below complex $\mathcal{F}^\bullet$ of $\mathcal{O}_X$-modules. Applying Cohomology, Lemma Derived Hom, Ext and projective and locally free modules (uncovered prerequisite) we see that $R\mathcal{H}om(E, F)$ is represented by the complex with terms $$\bigoplus\nolimits_{n = - p + q} \mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}^p, \mathcal{F}^q)$$ Applying Cohomology on Sites, Lemma Derived Hom, Ext and projective and locally free modules (uncovered prerequisite) we see that $R\mathcal{H}om(\epsilon^*E, \epsilon^*F)$ is represented by the complex with terms $$\bigoplus\nolimits_{n = - p + q} \mathcal{H}om_{\mathcal{O}_\mathrm{\acute{e}tale}} (\epsilon^*\mathcal{E}^p, \epsilon^*\mathcal{F}^q)$$ Thus the statement of the lemma boils down to the true fact that the canonical map $$\epsilon^*\mathcal{H}om_{\mathcal{O}_X}(\mathcal{E}, \mathcal{F}) \longrightarrow \mathcal{H}om_{\mathcal{O}_\mathrm{\acute{e}tale}} (\epsilon^*\mathcal{E}, \epsilon^*\mathcal{F})$$ is an isomorphism for any $\mathcal{O}_X$-module $\mathcal{F}$ and finite free $\mathcal{O}_X$-module $\mathcal{E}$.
In case (2) we can represent $E$ by a strictly perfect complex $\mathcal{E}^\bullet$ of $\mathcal{O}_X$-modules, use Derived Categories of Schemes, Lemmas Bounded comparison of affine derived categories and Perfect complexes on an affine scheme and the fact that a perfect complex of modules is represented by a finite complex of finite projective modules. Thus we can do the exact same proof as above, replacing the reference to Cohomology, Lemma Derived Hom, Ext and projective and locally free modules (uncovered prerequisite) by a reference to Cohomology, Lemma Perfect complexes and derived Hom and Ext. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $X$ be an algebraic space over $S$. If $E$ is an $m$-pseudo-coherent object of $D(\mathcal{O}_X)$, then $H^i(E)$ is a quasi-coherent $\mathcal{O}_X$-module for $i > m$. If $E$ is pseudo-coherent, then $E$ is an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$.
Proof. Locally $H^i(E)$ is isomorphic to $H^i(\mathcal{E}^\bullet)$ with $\mathcal{E}^\bullet$ strictly perfect. The sheaves $\mathcal{E}^i$ are direct summands of finite free modules, hence quasi-coherent. The lemma follows. $\square$
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $X$ be a quasi-compact and quasi-separated algebraic space over $S$. Let $\mathcal{B} \subset \operatorname{Ob}(X_{spaces, \mathrm{\acute{e}tale}})$. Let $P$ be a property of the elements of $\mathcal{B}$. Assume that
-
every $W \in \mathcal{B}$ is quasi-compact and quasi-separated,
-
if $W \in \mathcal{B}$ and $U \subset W$ is quasi-compact open, then $U \in \mathcal{B}$,
-
if $V \in \operatorname{Ob}(X_{spaces, \mathrm{\acute{e}tale}})$ is affine, then (a) $V \in \mathcal{B}$ and (b) $P$ holds for $V$,
-
for every elementary distinguished square $(U \subset W, f : V \to W)$ such that
-
$W \in \mathcal{B}$,
-
$U$ is quasi-compact,
-
$V$ is affine, and
-
$P$ holds for $U$, $V$, and $U \times_W V$,
then $P$ holds for $W$.
-
Then $P$ holds for every $W \in \mathcal{B}$.
Proof. This is proved in exactly the same manner as the proof of Lemma Induction by elementary distinguished squares. (We remark that (4)(d) makes sense as $U \times_W V$ is a quasi-compact open of $V$ hence an element of $\mathcal{B}$ by conditions (2) and (3).) $\square$
[^1]: In particular, $E$ has a K-injective representative, see Derived Categories, Lemma Injective resolutions (uncovered prerequisite).
Differential graded models and countable approximation
Lemma. Countable approximation by perfect objects
Let $(A, \text{d})$ be a differential graded algebra with $H^i(A)$ countable for each $i$. Let $M$ be an object of $D(A, \text{d})$. Then the following are equivalent
-
$M = \text{hocolim} E_n$ with $E_n$ compact in $D(A, \text{d})$, and
-
$H^i(M)$ is countable for each $i$.
Proof. Assume (1) holds. Then we have $H^i(M) = \mathop{\operatorname{colim}} H^i(E_n)$ by Derived Categories, Lemma Sheaf cohomology. Thus it suffices to prove that $H^i(E_n)$ is countable for each $n$. By Proposition Differential graded modules we see that $E_n$ is isomorphic in $D(A, \text{d})$ to a direct summand of a differential graded module $P$ which has a finite filtration $F_\bullet$ by differential graded submodules such that $F_jP/F_{j - 1}P$ are finite direct sums of shifts of $A$. By assumption the groups $H^i(F_jP/F_{j - 1}P)$ are countable. Arguing by induction on the length of the filtration and using the long exact cohomology sequence we conclude that (2) is true. The interesting implication is the other one.
We claim there is a countable differential graded subalgebra $A' \subset A$ such that the inclusion map $A' \to A$ defines an isomorphism on cohomology. To construct $A'$ we choose countable differential graded subalgebras $$A_1 \subset A_2 \subset A_3 \subset \ldots$$ such that (a) $H^i(A_1) \to H^i(A)$ is surjective, and (b) for $n > 1$ the kernel of the map $H^i(A_{n - 1}) \to H^i(A_n)$ is the same as the kernel of the map $H^i(A_{n - 1}) \to H^i(A)$. To construct $A_1$ take any countable collection of cochains $S \subset A$ generating the cohomology of $A$ (as a ring or as a graded abelian group) and let $A_1$ be the differential graded subalgebra of $A$ generated by $S$. To construct $A_n$ given $A_{n - 1}$ for each cochain $a \in A_{n - 1}^i$ which maps to zero in $H^i(A)$ choose $s_a \in A^{i - 1}$ with $\text{d}(s_a) = a$ and let $A_n$ be the differential graded subalgebra of $A$ generated by $A_{n - 1}$ and the elements $s_a$. Finally, take $A' = \bigcup A_n$.
By Lemma Groupoids and equivalence relations the restriction map $D(A, \text{d}) \to D(A', \text{d})$, $M \mapsto M_{A'}$ is an equivalence. Since the cohomology groups of $M$ and $M_{A'}$ are the same, we see that it suffices to prove the implication (2) $\Rightarrow$ (1) for $(A', \text{d})$.
Assume $A$ is countable. By the exact same type of argument as given above we see that for $M$ in $D(A, \text{d})$ the following are equivalent: $H^i(M)$ is countable for each $i$ and $M$ can be represented by a countable differential graded module. Hence in order to prove the implication (2) $\Rightarrow$ (1) we reduce to the situation described in the next paragraph.
Assume $A$ is countable and that $M$ is a countable differential graded module over $A$. We claim there exists a homomorphism $P \to M$ of differential graded $A$-modules such that
-
$P \to M$ is a quasi-isomorphism,
-
$P$ has property (P), and
-
$P$ is countable.
Looking at the proof of the construction of P-resolutions in Lemma Differential graded modules we see that it suffices to show that we can prove Lemma A differential graded quotient suitable for approximation in the setting of countable differential graded modules. This is immediate from the proof.
Assume that $A$ is countable and that $M$ is a countable differential graded module with property (P). Choose a filtration $$0 = F_{-1}P \subset F_0P \subset F_1P \subset \ldots \subset P$$ by differential graded submodules such that we have
-
$P = \bigcup F_pP$,
-
$F_iP \to F_{i + 1}P$ is an admissible monomorphism,
-
isomorphisms of differential graded modules $F_iP/F_{i - 1}P \to \bigoplus_{j \in J_i} A[k_j]$ for some sets $J_i$ and integers $k_j$.
Of course $J_i$ is countable for each $i$. For each $i$ and $j \in J_i$ choose $x_{i, j} \in F_iP$ of degree $k_j$ whose image in $F_iP/F_{i - 1}P$ generates the summand corresponding to $j$.
Claim: Given $n$ and finite subsets $S_i \subset J_i$, $i = 1, \ldots, n$ there exist finite subsets $S_i \subset T_i \subset J_i$, $i = 1, \ldots, n$ such that $P' = \bigoplus_{i \leq n} \bigoplus_{j \in T_i} Ax_{i, j}$ is a differential graded submodule of $P$. This was shown in the proof of Lemma Factoring a compact-object map through a finite-cell submodule but it is also easily shown directly: the elements $x_{i, j}$ freely generate $P$ as a right $A$-module. The structure of $P$ shows that $$\text{d}(x_{i, j}) = \sum\nolimits_{i' < i} x_{i', j'}a_{i', j'}$$ where of course the sum is finite. Thus given $S_0, \ldots, S_n$ we can first choose $S_0 \subset S'_0, \ldots, S_{n - 1} \subset S'_{n - 1}$ with $\text{d}(x_{n, j}) \in \bigoplus_{i' < n, j' \in S'_{i'}} x_{i', j'}A$ for all $j \in S_n$. Then by induction on $n$ we can choose $S'_0 \subset T_0, \ldots, S'_{n - 1} \subset T_{n - 1}$ to make sure that $\bigoplus_{i' < n, j' \in T_{i'}} x_{i', j'}A$ is a differential graded $A$-submodule. Setting $T_n = S_n$ we find that $P' = \bigoplus_{i \leq n, j \in T_i} x_{i, j}A$ is as desired.
From the claim it is clear that $P = \bigcup P'_n$ is a countable rising union of $P'_n$ as above. By construction each $P'_n$ is a differential graded module with property (P) such that the filtration is finite and the successive quotients are finite direct sums of shifts of $A$. Hence $P'_n$ defines a compact object of $D(A, \text{d})$, see for example Proposition Differential graded modules. Since $P = \text{hocolim} P'_n$ in $D(A, \text{d})$ by Lemma Filtered limits and differential graded modules the proof of the implication (2) $\Rightarrow$ (1) is complete. $\square$
Lemma. Derived categories and tensor products and direct sums
The functor $K(\text{Mod}_{(E, \text{d})}) \to K(\mathcal{O})$ of Lemma Derived categories and tensor products and direct sums has a left derived version defined on all of $D(E, \text{d})$. We denote it $- \otimes_E^\mathbf{L} K^\bullet : D(E, \text{d}) \to D(\mathcal{O})$.
Proof. We will use Derived Categories, Lemma Triangulated categories (uncovered prerequisite) to prove this. As our collection $\mathcal{P}$ of objects we will use the objects with property (P). Property (1) was shown in Lemma Differential graded modules. Property (2) holds because if $s : P \to P'$ is a quasi-isomorphism of modules with property (P), then $s$ is a homotopy equivalence by Lemma Derived Hom, Ext and derived categories. $\square$
Lemma. Differential graded modules
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $K^\bullet$ be a complex of $\mathcal{O}$-modules. Assume
-
$K^\bullet$ represents a compact object of $D(\mathcal{O})$, and
-
$E = \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O})}(K^\bullet, K^\bullet)$ computes the ext groups of $K^\bullet$ in $D(\mathcal{O})$.
Then the functor $$- \otimes_E^\mathbf{L} K^\bullet : D(E, \text{d}) \longrightarrow D(\mathcal{O})$$ of Lemma Derived categories and tensor products and direct sums is fully faithful.
Proof. Because our functor has a left adjoint given by $R\operatorname{Hom}(K^\bullet, -)$ by Lemma Derived Hom, Ext and derived categories it suffices to show for a differential graded $E$-module $M$ that the map $$H^0(M) \longrightarrow \operatorname{Hom}_{D(\mathcal{O})}(K^\bullet, M \otimes_E^\mathbf{L} K^\bullet)$$ is an isomorphism. We may assume that $M = P$ is a differential graded $E$-module which has property (P). Since $K^\bullet$ defines a compact object, we reduce using Lemma Proper morphisms to the case where $P$ has a finite filtration whose graded pieces are direct sums of $E[k]$. Again using compactness we reduce to the case $P = E[k]$. The assumption on $K^\bullet$ is that the result holds for these. $\square$
Lemma. Derived Hom, Ext and derived categories
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $K^\bullet$ be a complex of $\mathcal{O}$-modules. Then the functor $$- \otimes_E^\mathbf{L} K^\bullet : D(E, \text{d}) \longrightarrow D(\mathcal{O})$$ of Lemma Derived categories and tensor products and direct sums is a left adjoint of the functor $$R\operatorname{Hom}(K^\bullet, -) : D(\mathcal{O}) \longrightarrow D(E, \text{d})$$ of Lemma Derived categories.
Proof. The statement means that we have $$\operatorname{Hom}_{D(E, \text{d})}(M, R\operatorname{Hom}(K^\bullet, L^\bullet)) = \operatorname{Hom}_{D(\mathcal{O})}(M \otimes^\mathbf{L}_E K^\bullet, L^\bullet)$$ bifunctorially in $M$ and $L^\bullet$. To see this we may replace $M$ by a differential graded $E$-module $P$ with property (P). We also may replace $L^\bullet$ by a K-injective complex of $\mathcal{O}$-modules $I^\bullet$. The computation of the derived functors given in the lemmas referenced in the statement combined with Lemma Derived Hom, Ext and derived categories translates the above into $$\operatorname{Hom}_{K(\text{Mod}_{(E, \text{d})})} (P, \operatorname{Hom}_\mathcal{B}(K^\bullet, I^\bullet)) = \operatorname{Hom}_{K(\mathcal{O})}(P \otimes_E K^\bullet, I^\bullet)$$ where $\mathcal{B} = \text{Comp}^{dg}(\mathcal{O})$. There is an evaluation map from right to left functorial in $P$ and $I^\bullet$ (details omitted). Choose a filtration $F_\bullet$ on $P$ as in the definition of property (P). By Lemma Proper morphisms and the fact that both sides of the equation are homological functors in $P$ on $K(\text{Mod}_{(E, \text{d})})$ we reduce to the case where $P$ is replaced by the differential graded $E$-module $\bigoplus F_iP$. Since both sides turn direct sums in the variable $P$ into direct products we reduce to the case where $P$ is one of the differential graded $E$-modules $F_iP$. Since each $F_iP$ has a finite filtration (given by admissible monomorphisms) whose graded pieces are graded projective $E$-modules we reduce to the case where $P$ is a graded projective $E$-module. In this case we clearly have $$\operatorname{Hom}_{\text{Mod}^{dg}_{(E, \text{d})}} (P, \operatorname{Hom}_\mathcal{B}(K^\bullet, I^\bullet)) = \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O})}(P \otimes_E K^\bullet, I^\bullet)$$ as graded $\mathbf{Z}$-modules (because this statement reduces to the case $P = E[k]$ where it is obvious). As the isomorphism is compatible with differentials we conclude. $\square$
Proposition. Differential graded modules
Let $(A, \text{d})$ be a differential graded algebra. Let $E$ be an object of $D(A, \text{d})$. Then the following are equivalent
-
$E$ is a compact object,
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$E$ is a direct summand of an object of $D(A, \text{d})$ which is represented by a differential graded module $P$ which has a finite filtration $F_\bullet$ by differential graded submodules such that $F_iP/F_{i - 1}P$ are finite direct sums of shifts of $A$.
Proof. Assume $E$ is compact. By Lemma Differential graded modules we may assume that $E$ is represented by a differential graded $A$-module $P$ with property (P). Consider the distinguished triangle $$\bigoplus F_iP \to \bigoplus F_iP \to P \xrightarrow{\delta} \bigoplus F_iP[1]$$ coming from the admissible short exact sequence of Lemma Proper morphisms. Since $E$ is compact we have $\delta = \sum_{i = 1, \ldots, n} \delta_i$ for some $\delta_i : P \to F_iP[1]$. Since the composition of $\delta$ with the map $\bigoplus F_iP[1] \to \bigoplus F_iP[1]$ is zero (Derived Categories, Lemma Composition and triangulated categories) it follows that $\delta = 0$ (follows as $\bigoplus F_iP \to \bigoplus F_iP$ maps the summand $F_iP$ via the difference of $\text{id}$ and the inclusion map into $F_{i - 1}P$). Thus we see that the identity on $E$ factors through $\bigoplus F_iP$ in $D(A, \text{d})$ (by Derived Categories, Lemma Splitting an exact triangle). Next, we use that $P$ is compact again to see that the map $E \to \bigoplus F_iP$ factors through $\bigoplus_{i = 1, \ldots, n} F_iP$ for some $n$. In other words, the identity on $E$ factors through $\bigoplus_{i = 1, \ldots, n} F_iP$. By Lemma Factoring a compact-object map through a finite-cell submodule we see that the identity of $E$ factors as $E \to P \to E$ where $P$ is as in part (2) of the statement of the lemma. In other words, we have proven that (1) implies (2).
Assume (2). By Derived Categories, Lemma Triangulated categories (uncovered prerequisite) it suffices to show that $P$ gives a compact object. Observe that $P$ has property (P), hence we have $$\operatorname{Hom}_{D(A, \text{d})}(P, M) = \operatorname{Hom}_{K(A, \text{d})}(P, M)$$ for any differential graded module $M$ by Lemma Derived Hom, Ext and derived categories. As direct sums in $D(A, \text{d})$ are given by direct sums of graded modules (Lemma Derived categories and tensor products and direct sums) we reduce to showing that $\operatorname{Hom}_{K(A, \text{d})}(P, M)$ commutes with direct sums. Using that $K(A, \text{d})$ is a triangulated category, that $\operatorname{Hom}$ is a cohomological functor in the first variable, and the filtration on $P$, we reduce to the case that $P$ is a finite direct sum of shifts of $A$. Thus we reduce to the case $P = A[k]$ which is clear. $\square$
Lemma. Groupoids and equivalence relations
Let $R$ be a ring. Let $(A, \text{d}) \to (B, \text{d})$ be a homomorphism of differential graded algebras over $R$, which induces an isomorphism on cohomology algebras. Then $$- \otimes_A^\mathbf{L} B : D(A, \text{d}) \to D(B, \text{d})$$ gives an $R$-linear equivalence of triangulated categories with quasi-inverse the restriction functor $N \mapsto N_A$.
Proof. By Lemma Tensor products and direct sums the functor $M \longmapsto M \otimes_A^\mathbf{L} B$ is fully faithful. By Lemma Derived Hom, Ext and tensor products and direct sums the functor $N \longmapsto R\operatorname{Hom}(B, N) = N_A$ is a right adjoint, see Example Derived Hom, Ext and tensor products and direct sums. It is clear that the kernel of $R\operatorname{Hom}(B, -)$ is zero. Hence the result follows from Derived Categories, Lemma Triangulated categories. $\square$
Lemma. Differential graded modules
Let $(A, \text{d})$ be a differential graded algebra. Let $M$ be a differential graded $A$-module. There exists a homomorphism $P \to M$ of differential graded $A$-modules such that
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$P \to M$ is a quasi-isomorphism, and
-
$P$ has property (P).
Proof. Set $M = M_0$. We inductively choose short exact sequences $$0 \to M_{i + 1} \to P_i \to M_i \to 0$$ where the maps $P_i \to M_i$ are chosen as in Lemma A differential graded quotient suitable for approximation. This gives a "resolution" $$\ldots \to P_2 \xrightarrow{f_2} P_1 \xrightarrow{f_1} P_0 \to M \to 0$$ Then we set $$P = \bigoplus\nolimits_{i \geq 0} P_i$$ as an $A$-module with grading given by $P^n = \bigoplus_{a + b = n} P_{-a}^b$ and differential (as in the construction of the total complex associated to a double complex) by $$\text{d}_P(x) = f_{-a}(x) + (-1)^a \text{d}_{P_{-a}}(x)$$ for $x \in P_{-a}^b$. With these conventions $P$ is indeed a differential graded $A$-module. Recalling that each $P_i$ has a two step filtration $0 \to P_i' \to P_i \to P_i'' \to 0$ we set $$F_{2i}P = \bigoplus\nolimits_{i \geq j \geq 0} P_j \subset \bigoplus\nolimits_{i \geq 0} P_i = P$$ and we add $P'_{i + 1}$ to $F_{2i}P$ to get $F_{2i + 1}$. These are differential graded submodules and the successive quotients are direct sums of shifts of $A$. By Lemma Projective and locally free modules we see that the inclusions $F_iP \to F_{i + 1}P$ are admissible monomorphisms. Finally, we have to show that the map $P \to M$ (given by the augmentation $P_0 \to M$) is a quasi-isomorphism. This follows from Homology, Lemma The geometric construction (uncovered prerequisite). $\square$
Lemma. A differential graded quotient suitable for approximation
Let $(A, \text{d})$ be a differential graded algebra. Let $M$ be a differential graded $A$-module. There exists a homomorphism $P \to M$ of differential graded $A$-modules with the following properties
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$P \to M$ is surjective,
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$\operatorname{Ker}(\text{d}_P) \to \operatorname{Ker}(\text{d}_M)$ is surjective, and
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$P$ sits in an admissible short exact sequence $0 \to P' \to P \to P'' \to 0$ where $P'$, $P''$ are direct sums of shifts of $A$.
Proof. Let $P_k$ be the free $A$-module with generators $x, y$ in degrees $k$ and $k + 1$. Define the structure of a differential graded $A$-module on $P_k$ by setting $\text{d}(x) = y$ and $\text{d}(y) = 0$. For every element $m \in M^k$ there is a homomorphism $P_k \to M$ sending $x$ to $m$ and $y$ to $\text{d}(m)$. Thus we see that there is a surjection from a direct sum of copies of $P_k$ to $M$. This clearly produces $P \to M$ having properties (1) and (3). To obtain property (2) note that if $m \in \operatorname{Ker}(\text{d}_M)$ has degree $k$, then there is a map $A[k] \to M$ mapping $1$ to $m$. Hence we can achieve (2) by adding a direct sum of copies of shifts of $A$. $\square$
Lemma. Factoring a compact-object map through a finite-cell submodule
Let $(A, \text{d})$ be a differential graded algebra. Let $E$ be a compact object of $D(A, \text{d})$. Let $P$ be a differential graded $A$-module which has a finite filtration $$0 = F_{-1}P \subset F_0P \subset F_1P \subset \ldots \subset F_nP = P$$ by differential graded submodules such that $$F_{i + 1}P/F_iP \cong \bigoplus\nolimits_{j \in J_i} A[k_{i, j}]$$ as differential graded $A$-modules for some sets $J_i$ and integers $k_{i, j}$. Let $E \to P$ be a morphism of $D(A, \text{d})$. Then there exists a differential graded submodule $P' \subset P$ such that $F_{i + 1}P \cap P'/(F_iP \cap P')$ is equal to $\bigoplus_{j \in J'_i} A[k_{i, j}]$ for some finite subsets $J'_i \subset J_i$ and such that $E \to P$ factors through $P'$.
Proof. We will prove by induction on $-1 \leq m \leq n$ that there exists a differential graded submodule $P' \subset P$ such that
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$F_mP \subset P'$,
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for $i \geq m$ the quotient $F_{i + 1}P \cap P'/(F_iP \cap P')$ is isomorphic to $\bigoplus_{j \in J'_i} A[k_{i, j}]$ for some finite subsets $J'_i \subset J_i$, and
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$E \to P$ factors through $P'$.
The base case is $m = n$ where we can take $P' = P$.
Induction step. Assume $P'$ works for $m$. For $i \geq m$ and $j \in J'_i$ let $x_{i, j} \in F_{i + 1}P \cap P'$ be a homogeneous element of degree $k_{i, j}$ whose image in $F_{i + 1}P \cap P'/(F_iP \cap P')$ is the generator in the summand corresponding to $j \in J_i$. The $x_{i, j}$ generate $P'/F_mP$ as an $A$-module. Write $$\text{d}(x_{i, j}) = \sum x_{i', j'} a_{i, j}^{i', j'} + y_{i, j}$$ with $y_{i, j} \in F_mP$ and $a_{i, j}^{i', j'} \in A$. There exists a finite subset $J'_{m - 1} \subset J_{m - 1}$ such that each $y_{i, j}$ maps to an element of the submodule $\bigoplus_{j \in J'_{m - 1}} A[k_{m - 1, j}]$ of $F_mP/F_{m - 1}P$. Let $P'' \subset F_mP$ be the inverse image of $\bigoplus_{j \in J'_{m - 1}} A[k_{m - 1, j}]$ under the map $F_mP \to F_mP/F_{m - 1}P$. Then we see that the $A$-submodule $$P'' + \sum x_{i, j}A$$ is a differential graded submodule of the type we are looking for. Moreover $$P'/(P'' + \sum x_{i, j}A) = \bigoplus\nolimits_{j \in J_{m - 1} \setminus J'_{m - 1}} A[k_{m - 1, j}]$$ Since $E$ is compact, the composition of the given map $E \to P'$ with the quotient map, factors through a finite direct subsum of the module displayed above. Hence after enlarging $J'_{m - 1}$ we may assume $E \to P'$ factors through $P'' + \sum x_{i, j}A$ as desired. $\square$
Lemma. Filtered limits and differential graded modules
Let $(A, \text{d})$ be a differential graded algebra. Let $M_n$ be a system of differential graded modules. Then the derived colimit $\text{hocolim} M_n$ in $D(A, \text{d})$ is represented by the differential graded module $\mathop{\operatorname{colim}} M_n$.
Proof. Set $M = \mathop{\operatorname{colim}} M_n$. We have an exact sequence of differential graded modules $$0 \to \bigoplus M_n \to \bigoplus M_n \to M \to 0$$ by Derived Categories, Lemma Computation of a homotopy colimit (applied the underlying complexes of abelian groups). The direct sums are direct sums in $D(\mathcal{A})$ by Lemma Derived categories and tensor products and direct sums. Thus the result follows from the definition of derived colimits in Derived Categories, Definition Filtered limits and derived categories and the fact that a short exact sequence of complexes gives a distinguished triangle (Lemma Derived tensor products, Tor amplitude and derived categories). $\square$
Lemma. Derived categories and tensor products and direct sums
Let $R$ be a ring. Let $\mathcal{C}$ be a site. Let $\mathcal{O}$ be a sheaf of commutative $R$-algebras. Let $K^\bullet$ be a complex of $\mathcal{O}$-modules. The functor of Lemma Derived categories and tensor products and direct sums has the following property: For every $M$, $N$ in $D(E, \text{d})$ there is a canonical map $$R\operatorname{Hom}(M, N) \longrightarrow R\operatorname{Hom}_\mathcal{O}(M \otimes_E^\mathbf{L} K^\bullet, N \otimes_E^\mathbf{L} K^\bullet)$$ in $D(R)$ which on cohomology modules gives the maps $$\operatorname{Ext}^n_{D(E, \text{d})}(M, N) \to \operatorname{Ext}^n_{D(\mathcal{O})} (M \otimes_E^\mathbf{L} K^\bullet, N \otimes_E^\mathbf{L} K^\bullet)$$ induced by the functor $- \otimes_E^\mathbf{L} K^\bullet$.
Proof. The right hand side of the arrow is the global derived hom introduced in Cohomology on Sites, Section Derived Hom and Ext which has the correct cohomology modules. For the left hand side we think of $M$ as a $(R, A)$-bimodule and we have the derived $\operatorname{Hom}$ introduced in Section Differential graded modules which also has the correct cohomology modules. To prove the lemma we may assume $M$ and $N$ are differential graded $E$-modules with property (P); this does not change the left hand side of the arrow by Lemma Derived categories. By Lemma Derived categories this means that the left hand side of the arrow becomes $\operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(M, N)$. In Lemmas Derived categories and tensor products and direct sums, Derived categories and tensor products and direct sums, and Derived categories and tensor products and direct sums we have constructed a functor $$- \otimes_E K^\bullet : \text{Mod}^{dg}_{(E, \text{d})} \longrightarrow \text{Comp}^{dg}(\mathcal{O})$$ of differential graded categories and we have shown that $- \otimes_E^\mathbf{L} K^\bullet$ is computed by evaluating this functor on differential graded $E$-modules with property (P). Hence we obtain a map of complexes of $R$-modules $$\operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(M, N) \longrightarrow \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O})} (M \otimes_E K^\bullet, N \otimes_E K^\bullet)$$ For any complexes of $\mathcal{O}$-modules $\mathcal{F}^\bullet$, $\mathcal{G}^\bullet$ there is a canonical map $$\operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{O})} (\mathcal{F}^\bullet, \mathcal{G}^\bullet) = \Gamma(\mathcal{C}, \mathcal{H}om^\bullet(\mathcal{F}^\bullet, \mathcal{G}^\bullet)) \longrightarrow R\operatorname{Hom}_\mathcal{O}(\mathcal{F}^\bullet, \mathcal{G}^\bullet).$$ Combining these maps we obtain the desired map of the lemma. $\square$
Lemma. Derived categories and tensor products and direct sums
The functor of Lemma Derived categories and tensor products and direct sums defines an exact functor of triangulated categories $K(\text{Mod}_{(E, \text{d})}) \to K(\mathcal{O})$.
Proof. The functor induces a functor between homotopy categories by Lemma Functoriality of the lifting construction. We have to show that $- \otimes_E K^\bullet$ transforms distinguished triangles into distinguished triangles. Suppose that $0 \to K \to L \to M \to 0$ is an admissible short exact sequence of differential graded $E$-modules. Let $s : M \to L$ be a graded $E$-module homomorphism which is left inverse to $L \to M$. Then $s$ defines a map $M \otimes_E K^\bullet \to L \otimes_E K^\bullet$ of graded $\mathcal{O}$-modules (i.e., respecting $\mathcal{O}$-module structure and grading, but not differentials) which is left inverse to $L \otimes_E K^\bullet \to M \otimes_E K^\bullet$. Thus we see that $$0 \to K \otimes_E K^\bullet \to L \otimes_E K^\bullet \to M \otimes_E K^\bullet \to 0$$ is a termwise split short exact sequences of complexes, i.e., a defines a distinguished triangle in $K(\mathcal{O})$. $\square$
Lemma. Derived Hom, Ext and derived categories
Let $(A, \text{d})$ be a differential graded algebra. Let $M$ and $N$ be differential graded $A$-modules.
-
Let $P \to M$ be a P-resolution as in Lemma Differential graded modules. Then $$\operatorname{Hom}_{D(A, \text{d})}(M, N) = \operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(P, N)$$
-
Let $N \to I$ be an I-resolution as in Lemma A resolution for right differential graded modules. Then $$\operatorname{Hom}_{D(A, \text{d})}(M, N) = \operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(M, I)$$
Proof. Let $P \to M$ be as in (1). Since $P \to M$ is a quasi-isomorphism we see that $$\operatorname{Hom}_{D(A, \text{d})}(P, N) = \operatorname{Hom}_{D(A, \text{d})}(M, N)$$ by definition of the derived category. A morphism $f : P \to N$ in $D(A, \text{d})$ is equal to $s^{-1}f'$ where $f' : P \to N'$ is a morphism and $s : N \to N'$ is a quasi-isomorphism. Choose a distinguished triangle $$N \to N' \to Q \to N[1]$$ As $s$ is a quasi-isomorphism, we see that $Q$ is acyclic. Thus $\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(P, Q[k]) = 0$ for all $k$ by Lemma Property P gives a K-projective differential graded module. Since $\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(P, -)$ is cohomological, we conclude that we can lift $f' : P \to N'$ uniquely to a morphism $f : P \to N$. This finishes the proof.
The proof of (2) is dual to that of (1) using Lemma Property I gives a K-injective differential graded module in stead of Lemma Property P gives a K-projective differential graded module. $\square$
Lemma. Proper morphisms
Let $(A, \text{d})$ be a differential graded algebra. Let $P$ be a differential graded $A$-module. If $F_\bullet$ is a filtration as in property (P), then we obtain an admissible short exact sequence $$0 \to \bigoplus\nolimits F_iP \to \bigoplus\nolimits F_iP \to P \to 0$$ of differential graded $A$-modules.
Proof. The second map is the direct sum of the inclusion maps. The first map on the summand $F_iP$ of the source is the sum of the identity $F_iP \to F_iP$ and the negative of the inclusion map $F_iP \to F_{i + 1}P$. Choose homomorphisms $s_i : F_{i + 1}P \to F_iP$ of graded $A$-modules which are left inverse to the inclusion maps. Composing gives maps $s_{j, i} : F_jP \to F_iP$ for all $j > i$. Then a left inverse of the first arrow maps $x \in F_jP$ to $(s_{j, 0}(x), s_{j, 1}(x), \ldots, s_{j, j - 1}(x), 0, \ldots)$ in $\bigoplus F_iP$. $\square$
Lemma. Derived categories
In the situation above. If the right derived functor $R\operatorname{Hom}(K^\bullet, -)$ of $\operatorname{Hom}(K^\bullet, -) : K(\mathcal{A}) \to D(\textit{Ab})$ is everywhere defined on $D(\mathcal{A})$, then we obtain a canonical exact functor $$R\operatorname{Hom}(K^\bullet, -) : D(\mathcal{A}) \longrightarrow D(E, \text{d})$$ of triangulated categories which reduces to the usual one on taking associated complexes of abelian groups.
Proof. Note that we have an associated functor $K(\mathcal{A}) \to K(\text{Mod}_{(E, \text{d})})$ by Lemma Construction of a differential graded resolution. We claim this functor is an exact functor of triangulated categories. Namely, let $f : A^\bullet \to B^\bullet$ be a map of complexes of $\mathcal{A}$. Then a computation shows that $$\operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{A})}(K^\bullet, C(f)^\bullet)
C\left( \operatorname{Hom}{\text{Comp}^{dg}(\mathcal{A})}(K^\bullet, A^\bullet) \to \operatorname{Hom}{\text{Comp}^{dg}(\mathcal{A})}(K^\bullet, B^\bullet) \right)$$ where the right hand side is the cone in $\text{Mod}{(E, \text{d})}$ defined earlier in this chapter. This shows that our functor is compatible with cones, hence with distinguished triangles. Let $X^\bullet$ be an object of $K(\mathcal{A})$. Consider the category of quasi-isomorphisms $s : X^\bullet \to Y^\bullet$. We are given that the functor $(s : X^\bullet \to Y^\bullet) \mapsto \operatorname{Hom}\mathcal{A}(K^\bullet, Y^\bullet)$ is essentially constant when viewed in $D(\textit{Ab})$. But since the forgetful functor $D(E, \text{d}) \to D(\textit{Ab})$ is compatible with taking cohomology, the same thing is true in $D(E, \text{d})$. This proves the lemma. $\square$
Lemma. Derived categories and tensor products and direct sums
Let $(A, \text{d})$ be a differential graded algebra. Then
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$D(A, \text{d})$ has both direct sums and products,
-
direct sums are obtained by taking direct sums of differential graded modules,
-
products are obtained by taking products of differential graded modules.
Proof. We will use that $\text{Mod}_{(A, \text{d})}$ is an abelian category with arbitrary direct sums and products, and that these give rise to direct sums and products in $K(\text{Mod}_{(A, \text{d})})$. See Lemmas The abelian category of differential graded modules and Tensor products and direct sums.
Let $M_j$ be a family of differential graded $A$-modules. Consider the graded direct sum $M = \bigoplus M_j$ which is a differential graded $A$-module with the obvious. For a differential graded $A$-module $N$ choose a quasi-isomorphism $N \to I$ where $I$ is a differential graded $A$-module with property (I). See Lemma A resolution for right differential graded modules. Using Lemma Derived Hom, Ext and derived categories we have $$\begin{aligned} \operatorname{Hom}_{D(A, \text{d})}(M, N) & = \operatorname{Hom}_{K(A, \text{d})}(M, I) \\ & = \prod \operatorname{Hom}_{K(A, \text{d})}(M_j, I) \\ & = \prod \operatorname{Hom}_{D(A, \text{d})}(M_j, N) \end{aligned}$$ whence the existence of direct sums in $D(A, \text{d})$ as given in part (2) of the lemma.
Let $M_j$ be a family of differential graded $A$-modules. Consider the product $M = \prod M_j$ of differential graded $A$-modules. For a differential graded $A$-module $N$ choose a quasi-isomorphism $P \to N$ where $P$ is a differential graded $A$-module with property (P). See Lemma Differential graded modules. Using Lemma Derived Hom, Ext and derived categories we have $$\begin{aligned} \operatorname{Hom}_{D(A, \text{d})}(N, M) & = \operatorname{Hom}_{K(A, \text{d})}(P, M) \\ & = \prod \operatorname{Hom}_{K(A, \text{d})}(P, M_j) \\ & = \prod \operatorname{Hom}_{D(A, \text{d})}(N, M_j) \end{aligned}$$ whence the existence of direct sums in $D(A, \text{d})$ as given in part (3) of the lemma. $\square$
Lemma. Tensor products and direct sums
With notation and assumptions as in Lemma Derived Hom, Ext and tensor products and direct sums. Assume
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$N$ defines a compact object of $D(B, \text{d})$, and
-
the map $H^k(A) \to \operatorname{Hom}_{D(B, \text{d})}(N, N[k])$ is an isomorphism for all $k \in \mathbf{Z}$.
Then the functor $-\otimes_A^\mathbf{L} N$ is fully faithful.
Proof. Our functor has a left adjoint given by $R\operatorname{Hom}(N, -)$ by Lemma Derived Hom, Ext and tensor products and direct sums. By Categories, Lemma The geometric construction (uncovered prerequisite) it suffices to show that for a differential graded $A$-module $M$ the map $$M \longrightarrow R\operatorname{Hom}(N, M \otimes_A^\mathbf{L} N)$$ is an isomorphism in $D(A, \text{d})$. For this it suffices to show that $$H^n(M) \longrightarrow \text{Ext}^n_{D(B, \text{d})}(N, M \otimes_A^\mathbf{L} N)$$ is an isomorphism, see Lemma Derived categories. Since $N$ is a compact object the right hand side commutes with direct sums. Thus by Remark Differential graded modules it suffices to prove this map is an isomorphism for $M = A[k]$. Since $(A[k] \otimes_A^\mathbf{L} N) = N[k]$ by Remark Tensor products and direct sums, assumption (2) on $N$ is that the result holds for these. $\square$
Lemma. Derived Hom, Ext and tensor products and direct sums
Let $R$ be a ring. Let $(A, \text{d})$ and $(B, \text{d})$ be differential graded $R$-algebras. Let $N$ be a differential graded $(A, B)$-bimodule. Then the functor $$- \otimes_A^\mathbf{L} N : D(A, \text{d}) \longrightarrow D(B, \text{d})$$ of Lemma Base change in a differential graded derived category is a left adjoint to the functor $$R\operatorname{Hom}(N, -) : D(B, \text{d}) \longrightarrow D(A, \text{d})$$ of Lemma Restriction in a differential graded derived category.
Proof. This follows from Derived Categories, Lemma Derived categories (uncovered prerequisite) and the fact that $- \otimes_A N$ and $\operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(N, -)$ are adjoint by Lemma Derived Hom, Ext and tensor products and direct sums. $\square$
Example. Derived Hom, Ext and tensor products and direct sums
Let $R$ be a ring. Let $(A, \text{d}) \to (B, \text{d})$ be a homomorphism of differential graded $R$-algebras. Then we can view $B$ as a differential graded $(A, B)$-bimodule and we get a functor $$- \otimes_A B : D(A, \text{d}) \longrightarrow D(B, \text{d})$$ By Lemma Derived Hom, Ext and tensor products and direct sums the left adjoint of this is the functor $R\operatorname{Hom}(B, -)$. For a differential graded $B$-module let us denote $N_A$ the differential graded $A$-module obtained from $N$ by restriction via $A \to B$. Then we clearly have a canonical isomorphism $$\operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(B, N) \longrightarrow N_A,\quad f \longmapsto f(1)$$ functorial in the $B$-module $N$. Thus we see that $R\operatorname{Hom}(B, -)$ is the restriction functor and we obtain $$\operatorname{Hom}_{D(A, \text{d})}(M, N_A) = \operatorname{Hom}_{D(B, \text{d})}(M \otimes^\mathbf{L}_A B, N)$$ bifunctorially in $M$ and $N$ exactly as in the case of commutative rings. Finally, observe that restriction is a tensor functor as well, since $N_A = N \otimes_B {}_BB_A = N \otimes_B^\mathbf{L} {}_BB_A$ where ${}_BB_A$ is $B$ viewed as a differential graded $(B, A)$-bimodule.
Lemma. Projective and locally free modules
Let $(A, \text{d})$ be a differential graded algebra. Let $M \to P$ be a surjective homomorphism of differential graded $A$-modules. If $P$ is projective as a graded $A$-module, then $M \to P$ is an admissible epimorphism.
Proof. This is immediate from the definitions. $\square$
Lemma. Derived tensor products, Tor amplitude and derived categories
Let $(A, \text{d})$ be a differential graded algebra. The functor $\text{Mod}_{(A, \text{d})} \to D(A, \text{d})$ defined has the natural structure of a $\delta$-functor, with $$\delta_{K \to L \to M} = - p \circ q^{-1}$$ with $p$ and $q$ as explained above.
Proof. We have already seen that this choice leads to a distinguished triangle whenever given a short exact sequence of complexes. We have to show functoriality of this construction, see Derived Categories, Definition Derived tensor products and Tor amplitude. This follows from Lemma Derived categories with a bit of work. Compare with Derived Categories, Lemma Derived tensor products, Tor amplitude and derived categories. $\square$
Lemma. Derived categories
Let $R$ be a ring. Let $(A, \text{d})$ and $(B, \text{d})$ be differential graded $R$-algebras. Let $f : N \to N'$ be a homomorphism of differential graded $(A, B)$-bimodules. Then $f$ induces a morphism of functors $$- \circ f : R\operatorname{Hom}(N', -) \longrightarrow R\operatorname{Hom}(N, -)$$ If $f$ is a quasi-isomorphism, then $f \circ -$ is an isomorphism of functors.
Proof. Write $\mathcal{B} = \text{Mod}^{dg}_{(B, \text{d})}$ the differential graded category of differential graded $B$-modules, see Example The differential graded category of differential graded modules. Let $I$ be a differential graded $B$-module with property (I). Then $f \circ - : \operatorname{Hom}_\mathcal{B}(N', I) \to \operatorname{Hom}_\mathcal{B}(N, I)$ is a map of differential graded $A$-modules. Moreover, this is functorial with respect to $I$. Since the functors $R\operatorname{Hom}(N', -)$ and $R\operatorname{Hom}(N, -)$ are computed by applying $\operatorname{Hom}_\mathcal{B}$ into objects with property (I) (Lemma Restriction in a differential graded derived category) we obtain a transformation of functors as indicated.
Assume that $f$ is a quasi-isomorphism. Let $F_\bullet$ be the given filtration on $I$. Since $I = \varprojlim I/F_pI$ we see that $\operatorname{Hom}_\mathcal{B}(N', I) = \varprojlim \operatorname{Hom}_\mathcal{B}(N', I/F_pI)$ and $\operatorname{Hom}_\mathcal{B}(N, I) = \varprojlim \operatorname{Hom}_\mathcal{B}(N, I/F_pI)$. Since the transition maps in the system $I/F_pI$ are split as graded modules, we see that the transition maps in the systems $\operatorname{Hom}_\mathcal{B}(N', I/F_pI)$ and $\operatorname{Hom}_\mathcal{B}(N, I/F_pI)$ are surjective. Hence $\operatorname{Hom}_\mathcal{B}(N', I)$, resp. $\operatorname{Hom}_\mathcal{B}(N, I)$ viewed as a complex of abelian groups computes $R\varprojlim$ of the system of complexes $\operatorname{Hom}_\mathcal{B}(N', I/F_pI)$, resp. $\operatorname{Hom}_\mathcal{B}(N, I/F_pI)$. See More on Algebra, Lemma Computation of a derived inverse limit. Thus it suffices to prove each $$\operatorname{Hom}_\mathcal{B}(N', I/F_pI) \to \operatorname{Hom}_\mathcal{B}(N, I/F_pI)$$ is a quasi-isomorphism. Since the surjections $I/F_{p + 1}I \to I/F_pI$ are split as maps of graded $B$-modules we see that $$0 \to \operatorname{Hom}_\mathcal{B}(N', F_pI/F_{p + 1}I) \to \operatorname{Hom}_\mathcal{B}(N', I/F_{p + 1}I) \to \operatorname{Hom}_\mathcal{B}(N', I/F_pI) \to 0$$ is a short exact sequence of differential graded $A$-modules. There is a similar sequence for $N$ and $f$ induces a map of short exact sequences. Hence by induction on $p$ (starting with $p = 0$ when $I/F_0I = 0$) we conclude that it suffices to show that the map $\operatorname{Hom}_\mathcal{B}(N', F_pI/F_{p + 1}I) \to \operatorname{Hom}_\mathcal{B}(N, F_pI/F_{p + 1}I)$ is a quasi-isomorphism. Since $F_pI/F_{p + 1}I$ is a product of shifts of $A^\vee$ it suffice to prove $\operatorname{Hom}_\mathcal{B}(N', B^\vee[k]) \to \operatorname{Hom}_\mathcal{B}(N, B^\vee[k])$ is a quasi-isomorphism. By Lemma Derived Hom, Ext and projective and locally free modules it suffices to show $(N')^\vee \to N^\vee$ is a quasi-isomorphism. This is true because $f$ is a quasi-isomorphism and $(\ )^\vee$ is an exact functor. $\square$
Lemma. Derived categories
Let $R$ be a ring. Let $(A, \text{d})$ and $(B, \text{d})$ be differential graded $R$-algebras. Let $N$ be a differential graded $(A, B)$-bimodule. If $\operatorname{Hom}_{D(B, \text{d})}(N, N') = \operatorname{Hom}_{K(\text{Mod}_{(B, \text{d})})}(N, N')$ for all $N' \in K(B, \text{d})$, for example if $N$ has property (P) as a differential graded $B$-module, then $$R\operatorname{Hom}(N, M) = \operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(N, M)$$ functorially in $M$ in $D(B, \text{d})$.
Proof. By construction (Lemma Restriction in a differential graded derived category) to find $R\operatorname{Hom}(N, M)$ we choose a quasi-isomorphism $M \to I$ where $I$ is a differential graded $B$-module with property (I) and we set $R\operatorname{Hom}(N, M) = \operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(N, I)$. By assumption the map $$\operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(N, M) \longrightarrow \operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(N, I)$$ induced by $M \to I$ is a quasi-isomorphism, see discussion in Example The differential graded category of differential graded modules. This proves the lemma. If $N$ has property (P) as a $B$-module, then we see that the assumption is satisfied by Lemma Derived Hom, Ext and derived categories. $\square$
Lemma. Derived categories and tensor products and direct sums
In the situation above there is a functor $$- \otimes_E K^\bullet : \text{Mod}^{dg}_{(E, \text{d})} \longrightarrow \text{Comp}^{dg}(\mathcal{O})$$ of differential graded categories. This functor sends $E$ to $K^\bullet$ and commutes with direct sums.
Proof. Let $M$ be a differential graded $E$-module. For every object $U$ of $\mathcal{C}$ the complex $K^\bullet(U)$ is a left differential graded $E$-module as well as a right $\mathcal{O}(U)$-module. The actions commute, so we have a bimodule. Thus, by the constructions in Sections Tensor products and direct sums and Modules we can form the tensor product $$M \otimes_E K^\bullet(U)$$ which is a differential graded $\mathcal{O}(U)$-module, i.e., a complex of $\mathcal{O}(U)$-modules. This construction is functorial with respect to $U$, hence we can sheafify to get a complex of $\mathcal{O}$-modules which we denote $$M \otimes_E K^\bullet$$ Moreover, for each $U$ the construction determines a functor $\text{Mod}^{dg}_{(E, \text{d})} \to \text{Comp}^{dg}(\mathcal{O}(U))$ of differential graded categories by Lemma Tensor products and direct sums. It is therefore clear that we obtain a functor as stated in the lemma. $\square$
Lemma. Functoriality of the lifting construction
Let $R$ be a ring. A functor $F : \mathcal{A} \to \mathcal{B}$ of differential graded categories over $R$ induces functors $\text{Comp}(\mathcal{A}) \to \text{Comp}(\mathcal{B})$ and $K(\mathcal{A}) \to K(\mathcal{B})$.
Proof. Omitted. $\square$
Lemma. A resolution for right differential graded modules
Let $(A, \text{d})$ be a differential graded algebra. Let $M$ be a differential graded $A$-module. There exists a homomorphism $M \to I$ of differential graded $A$-modules such that
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$M \to I$ is a quasi-isomorphism, and
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$I$ has property (I).
Proof. Set $M = M_0$. We inductively choose short exact sequences $$0 \to M_i \to I_i \to M_{i + 1} \to 0$$ where the maps $M_i \to I_i$ are chosen as in Lemma A differential graded submodule suitable for approximation. This gives a "resolution" $$0 \to M \to I_0 \xrightarrow{f_0} I_1 \xrightarrow{f_1} I_1 \to \ldots$$ Denote $I$ the differential graded $A$-module with graded parts $$I^n = \prod\nolimits_{i \geq 0} I^{n - i}_i$$ and differential defined by $$\text{d}_I(x) = f_i(x) + (-1)^i \text{d}_{I_i}(x)$$ for $x \in I_i^{n - i}$. With these conventions $I$ is indeed a differential graded $A$-module. Recalling that each $I_i$ has a two step filtration $0 \to I_i' \to I_i \to I_i'' \to 0$ we set $$F_{2i}I^n = \prod\nolimits_{j \geq i} I^{n - j}_j \subset \prod\nolimits_{i \geq 0} I^{n - i}_i = I^n$$ and we add a factor $I'_{i + 1}$ to $F_{2i}I$ to get $F_{2i + 1}I$. These are differential graded submodules and the successive quotients are products of shifts of $A^\vee$. By Lemma Injective resolutions we see that the inclusions $F_{i + 1}I \to F_iI$ are admissible monomorphisms. Finally, we have to show that the map $M \to I$ (given by the augmentation $M \to I_0$) is a quasi-isomorphism. This follows from Homology, Lemma The geometric construction (uncovered prerequisite). $\square$
Lemma. Property P gives a K-projective differential graded module
Let $(A, \text{d})$ be a differential graded algebra. Let $P$ be a differential graded $A$-module with property (P). Then $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(P, N) = 0$$ for all acyclic differential graded $A$-modules $N$.
Proof. We will use that $K(\text{Mod}_{(A, \text{d})})$ is a triangulated category (Proposition Derived categories). Let $F_\bullet$ be a filtration on $P$ as in property (P). The short exact sequence of Lemma Proper morphisms produces a distinguished triangle. Hence by Derived Categories, Lemma Representability of a homological functor it suffices to show that $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(F_iP, N) = 0$$ for all acyclic differential graded $A$-modules $N$ and all $i$. Each of the differential graded modules $F_iP$ has a finite filtration by admissible monomorphisms, whose graded pieces are direct sums of shifts $A[k]$. Thus it suffices to prove that $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(A[k], N) = 0$$ for all acyclic differential graded $A$-modules $N$ and all $k$. This follows from Lemma Derived Hom, Ext and projective and locally free modules. $\square$
Lemma. Property I gives a K-injective differential graded module
Let $(A, \text{d})$ be a differential graded algebra. Let $I$ be a differential graded $A$-module with property (I). Then $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(N, I) = 0$$ for all acyclic differential graded $A$-modules $N$.
Proof. We will use that $K(\text{Mod}_{(A, \text{d})})$ is a triangulated category (Proposition Derived categories). Let $F_\bullet$ be a filtration on $I$ as in property (I). The short exact sequence of Lemma Constructing a differential graded module with property I produces a distinguished triangle. Hence by Derived Categories, Lemma Representability of a homological functor it suffices to show that $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(N, I/F_iI) = 0$$ for all acyclic differential graded $A$-modules $N$ and all $i$. Each of the differential graded modules $I/F_iI$ has a finite filtration by admissible monomorphisms, whose graded pieces are products of $A^\vee[k]$. Thus it suffices to prove that $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(N, A^\vee[k]) = 0$$ for all acyclic differential graded $A$-modules $N$ and all $k$. This follows from Lemma Derived Hom, Ext and projective and locally free modules and the fact that $(-)^\vee$ is an exact functor. $\square$
Lemma. Construction of a differential graded resolution
Let $R$ be a ring. Let $\mathcal{A}$ be a differential graded category over $R$. Let $x$ be an object of $\mathcal{A}$. Let $$(E, \text{d}) = \operatorname{Hom}_\mathcal{A}(x, x)$$ be the differential graded $R$-algebra of endomorphisms of $x$. We obtain a functor $$\mathcal{A} \longrightarrow \text{Mod}^{dg}_{(E, \text{d})},\quad y \longmapsto \operatorname{Hom}_\mathcal{A}(x, y)$$ of differential graded categories by letting $E$ act on $\operatorname{Hom}_\mathcal{A}(x, y)$ via composition in $\mathcal{A}$. This functor induces functors $$\text{Comp}(\mathcal{A}) \to \text{Mod}_{(A, \text{d})} \quad\text{and}\quad K(\mathcal{A}) \to K(\text{Mod}_{(A, \text{d})})$$ by an application of Lemma Functoriality of the lifting construction.
Proof. This lemma proves itself. $\square$
Lemma. The abelian category of differential graded modules
Let $(A, d)$ be a differential graded algebra. The category $\text{Mod}_{(A, \text{d})}$ is abelian and has arbitrary limits and colimits.
Proof. Kernels and cokernels commute with taking underlying $A$-modules. Similarly for direct sums and colimits. In other words, these operations in $\text{Mod}_{(A, \text{d})}$ commute with the forgetful functor to the category of $A$-modules. This is not the case for products and limits. Namely, if $N_i$, $i \in I$ is a family of differential graded $A$-modules, then the product $\prod N_i$ in $\text{Mod}_{(A, \text{d})}$ is given by setting $(\prod N_i)^n = \prod N_i^n$ and $\prod N_i = \bigoplus_n (\prod N_i)^n$. Thus we see that the product does commute with the forgetful functor to the category of graded $A$-modules. A category with products and equalizers has limits, see Categories, Lemma Filtered limits and tensor products and direct sums (uncovered prerequisite). $\square$
Lemma. Tensor products and direct sums
Let $(A, \text{d})$ be a differential graded algebra. The homotopy category $K(\text{Mod}_{(A, \text{d})})$ has direct sums and products.
Proof. Omitted. Hint: Just use the direct sums and products as in Lemma The abelian category of differential graded modules. This works because we saw that these functors commute with the forgetful functor to the category of graded $A$-modules and because $\prod$ is an exact functor on the category of families of abelian groups. $\square$
Lemma. Derived categories
Let $(A, \text{d})$ and $(B, \text{d})$ be differential graded algebras over a ring $R$. Let $N$ be a differential graded $(A, B)$-bimodule. Then for every $n \in \mathbf{Z}$ there are isomorphisms $$H^n(R\operatorname{Hom}(N, M)) = \operatorname{Ext}^n_{D(B, \text{d})}(N, M)$$ of $R$-modules functorial in $M$. It is also functorial in $N$ with respect to the operation described in Lemma Derived categories.
Proof. In the proof of Lemma Restriction in a differential graded derived category we have seen $$R\operatorname{Hom}(N, M) = \operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(N, I)$$ as a differential graded $A$-module where $M \to I$ is a quasi-isomorphism of $M$ into a differential graded $B$-module with property (I). Hence this complex has the correct cohomology modules by Lemma Derived Hom, Ext and derived categories. We omit a discussion of the functorial nature of these identifications. $\square$
Remark. Differential graded modules
Let $R$ be a ring. Let $(A, \text{d})$ be a differential graded $R$-algebra. Using P-resolutions we can sometimes reduce statements about general objects of $D(A, \text{d})$ to statements about $A[k]$. Namely, let $T$ be a property of objects of $D(A, \text{d})$ and assume that
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if $K_i$, $i \in I$ is a family of objects of $D(A, \text{d})$ and $T(K_i)$ holds for all $i \in I$, then $T(\bigoplus K_i)$,
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if $K \to L \to M \to K[1]$ is a distinguished triangle of $D(A, \text{d})$ and $T$ holds for two, then $T$ holds for the third object, and
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$T(A[k])$ holds for all $k \in \mathbf{Z}$.
Then $T$ holds for all objects of $D(A, \text{d})$. This is clear from Lemmas Proper morphisms and Differential graded modules.
Remark. Tensor products and direct sums
Let $R$ be a ring. Let $(A, \text{d})$ and $(B, \text{d})$ be differential graded algebras over $R$. Let $N$ be a differential graded $(A, B)$-bimodule. Let $M$ be a right differential graded $A$-module. Then for every $k \in \mathbf{Z}$ there is an isomorphism $$(M \otimes_A N)[k] \longrightarrow M[k] \otimes_A N$$ of right differential graded $B$-modules defined without the intervention of signs, see More on Algebra, Section Derived commutative algebra.
Lemma. Base change in a differential graded derived category
In the situation above, the left derived functor of $F$ exists. We denote it $- \otimes_A^\mathbf{L} N : D(A, \text{d}) \to D(B, \text{d})$.
Proof. We will use Derived Categories, Lemma Triangulated categories (uncovered prerequisite) to prove this. As our collection $\mathcal{P}$ of objects we will use the objects with property (P). Property (1) was shown in Lemma Differential graded modules. Property (2) holds because if $s : P \to P'$ is a quasi-isomorphism of modules with property (P), then $s$ is a homotopy equivalence by Lemma Derived Hom, Ext and derived categories. $\square$
Lemma. Restriction in a differential graded derived category
In the situation above, the right derived functor of $F$ exists. We denote it $R\operatorname{Hom}(N, -) : D(B, \text{d}) \to D(A, \text{d})$.
Proof. We will use Derived Categories, Lemma Triangulated categories (uncovered prerequisite) to prove this. As our collection $\mathcal{I}$ of objects we will use the objects with property (I). Property (1) was shown in Lemma A resolution for right differential graded modules. Property (2) holds because if $s : I \to I'$ is a quasi-isomorphism of modules with property (I), then $s$ is a homotopy equivalence by Lemma Derived Hom, Ext and derived categories. $\square$
Lemma. Derived Hom, Ext and tensor products and direct sums
Let $R$ be a ring. Let $A$ and $B$ be $R$-algebras. Let $M$ be a right $A$-module, $N$ an $(A, B)$-bimodule, and $N'$ a right $B$-module. Then we have a canonical isomorphism $$\operatorname{Hom}_B(M \otimes_A N, N') = \operatorname{Hom}_A(M, \operatorname{Hom}_B(N, N'))$$ of $R$-modules. If $A$, $B$, $M$, $N$, $N'$ are compatibly graded, then we have a canonical isomorphism $$\operatorname{Hom}_{\text{Mod}_B^{gr}}(M \otimes_A N, N') = \operatorname{Hom}_{\text{Mod}_A^{gr}}(M, \operatorname{Hom}_{\text{Mod}_B^{gr}}(N, N'))$$ of graded $R$-modules If $A$, $B$, $M$, $N$, $N'$ are compatibly differential graded, then we have a canonical isomorphism $$\operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(M \otimes_A N, N') = \operatorname{Hom}_{\text{Mod}^{dg}_{(A, \text{d})}}(M, \operatorname{Hom}_{\text{Mod}^{dg}_{(B, \text{d})}}(N, N'))$$ of complexes of $R$-modules.
Proof. Omitted. Hint: in the ungraded case interpret both sides as $A$-bilinear maps $\psi : M \times N \to N'$ which are $B$-linear on the right. In the (differential) graded case, use the isomorphism of More on Algebra, Lemma Composition and derived commutative algebra and check it is compatible with the module structures. Alternatively, use the isomorphism of Lemma Morphisms in the differential graded derived category and show that it is compatible with the $B$-module structures. $\square$
Lemma. Derived categories
Let $(A, \text{d})$ be a differential graded algebra. Suppose that $$\begin{gathered}\begin{matrix}K_1 & L_1 \\ K_2 & L_2\end{matrix} \\[6pt] \begin{aligned}K_1 & \xrightarrow{f_1} L_1 \\ K_1 & \xrightarrow{a} K_2 \\ L_1 & \xrightarrow{b} L_2 \\ K_2 & \xrightarrow{f_2} L_2\end{aligned}\end{gathered}$$ is a diagram of homomorphisms of differential graded $A$-modules which is commutative up to homotopy. Then there exists a morphism $c : C(f_1) \to C(f_2)$ which gives rise to a morphism of triangles $$(a, b, c) : (K_1, L_1, C(f_1), f_1, i_1, p_1) \to (K_1, L_1, C(f_1), f_2, i_2, p_2)$$ in $K(\text{Mod}_{(A, \text{d})})$.
Proof. Let $h : K_1 \to L_2$ be a homotopy between $f_2 \circ a$ and $b \circ f_1$. Define $c$ by the matrix $$c = \left( \begin{matrix} b & h \\ 0 & a \end{matrix} \right) : L_1 \oplus K_1 \to L_2 \oplus K_2$$ A matrix computation show that $c$ is a morphism of differential graded modules. It is trivial that $c \circ i_1 = i_2 \circ b$, and it is trivial also to check that $p_2 \circ c = a \circ p_1$. $\square$
Example. The differential graded category of differential graded modules
Let \((A, \text{d})\) be a differential graded algebra over a ring \(R\). We will construct a differential graded category \(\text{Mod}^{dg}_{(A, \text{d})}\) over \(R\) whose category of complexes is \(\text{Mod}_{(A, \text{d})}\) and whose homotopy category is \(K(\text{Mod}_{(A, \text{d})})\). As objects of \(\text{Mod}^{dg}_{(A, \text{d})}\) we take the differential graded \(A\)-modules. Given differential graded \(A\)-modules \(L\) and \(M\) we set
\[ \operatorname{Hom}_{\text{Mod}^{dg}_{(A, \text{d})}}(L, M) = \operatorname{Hom}_{\text{Mod}^{gr}_A}(L, M) = \bigoplus \operatorname{Hom}^n(L, M) \]as a graded \(R\)-module where the right hand side is defined as in Example The graded category of graded modules. In other words, the \(n\)th graded piece \(\operatorname{Hom}^n(L, M)\) is the \(R\)-module of right \(A\)-module maps homogeneous of degree \(n\). For an element \(f \in \operatorname{Hom}^n(L, M)\) we set
\[ \text{d}(f) = \text{d}_M \circ f - (-1)^n f \circ \text{d}_L \]To make sense of this we think of \(\text{d}_M\) and \(\text{d}_L\) as graded \(R\)-module maps and we use composition of graded \(R\)-module maps. It is clear that \(\text{d}(f)\) is homogeneous of degree \(n + 1\) as a graded \(R\)-module map, and it is \(A\)-linear because
\[ \begin{aligned} \text{d}(f)(xa) & = \text{d}_M(f(x) a) - (-1)^n f (\text{d}_L(xa)) \\ & = \text{d}_M(f(x)) a + (-1)^{\deg(x) + n} f(x) \text{d}(a) - (-1)^n f(\text{d}_L(x)) a - (-1)^{n + \deg(x)} f(x) \text{d}(a) \\ & = \text{d}(f)(x) a \end{aligned} \]as desired (observe that this calculation would not work without the sign in the definition of our differential on \(\operatorname{Hom}\)). Similar formulae to those of Example The differential graded category of complexes hold for the differential of \(f\) in terms of components. The reader checks (in the same way as in Example The differential graded category of complexes) that
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$\text{d}$ has square zero,
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an element $f$ in $\operatorname{Hom}^n(L, M)$ has $\text{d}(f) = 0$ if and only if $f : L \to M[n]$ is a homomorphism of differential graded $A$-modules,
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in particular, the category of complexes of $\text{Mod}^{dg}_{(A, \text{d})}$ is $\text{Mod}_{(A, \text{d})}$,
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the homomorphism defined by $f$ as in (2) is homotopy equivalent to zero if and only if $f = \text{d}(g)$ for some $g \in \operatorname{Hom}^{n - 1}(L, M)$.
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in particular, we obtain a canonical isomorphism $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(L, M) \longrightarrow H^0(\operatorname{Hom}_{\text{Mod}^{dg}_{(A, \text{d})}}(L, M))$$ and the homotopy category of $\text{Mod}^{dg}_{(A, \text{d})}$ is $K(\text{Mod}_{(A, \text{d})})$.
Given differential graded $A$-modules $K$, $L$, $M$ we define composition $$\operatorname{Hom}^m(L, M) \times \operatorname{Hom}^n(K, L) \longrightarrow \operatorname{Hom}^{n + m}(K, M)$$ by composition of homogeneous right $A$-module maps $(g, f) \mapsto g \circ f$. This defines a map of differential graded modules $$\operatorname{Hom}_{\text{Mod}^{dg}_{(A, \text{d})}}(L, M) \otimes_R \operatorname{Hom}_{\text{Mod}^{dg}_{(A, \text{d})}}(K, L) \longrightarrow \operatorname{Hom}_{\text{Mod}^{dg}_{(A, \text{d})}}(K, M)$$ as required in Definition Differential graded categories because $$\begin{aligned} \text{d}(g \circ f) & = \text{d}_M \circ g \circ f - (-1)^{n + m} g \circ f \circ \text{d}_K \\ & = \left(\text{d}_M \circ g - (-1)^m g \circ \text{d}_L\right) \circ f + (-1)^m g \circ \left(\text{d}_L \circ f - (-1)^n f \circ \text{d}_K\right) \\ & = \text{d}(g) \circ f + (-1)^m g \circ \text{d}(f) \end{aligned}$$ as desired.
Lemma. Derived Hom, Ext and projective and locally free modules
Let $(A, \text{d})$ be a differential graded algebra. Then we have $$\operatorname{Hom}_{\text{Mod}_{(A, \text{d})}}(M, A^\vee[k]) = \operatorname{Ker}(\text{d} : (M^\vee)^k \to (M^\vee)^{k + 1})$$ and $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(M, A^\vee[k]) = H^k(M^\vee)$$ as functors in the differential graded $A$-module $M$.
Proof. This is clear from the discussion above. $\square$
Lemma. Tensor products and direct sums
Let $R$ be a ring. Let $(A, \text{d})$ and $(B, \text{d})$ be differential graded algebras over $R$. Let $N$ be a differential graded $(A, B)$-bimodule. Then $M \mapsto M \otimes_A N$ defines a functor $$- \otimes_A N : \text{Mod}^{dg}_{(A, \text{d})} \longrightarrow \text{Mod}^{dg}_{(B, \text{d})}$$ of differential graded categories. This functor induces functors $$\text{Mod}_{(A, \text{d})} \to \text{Mod}_{(B, \text{d})} \quad\text{and}\quad K(\text{Mod}_{(A, \text{d})}) \to K(\text{Mod}_{(B, \text{d})})$$ by an application of Lemma Functoriality of the lifting construction.
Proof. Above we have seen how the construction defines a functor of underlying graded categories. Thus it suffices to show that the construction is compatible with differentials. Let $M$ and $M'$ be differential graded $A$-modules and let $f : M \to M'$ be an $A$-module homomorphism which is homogeneous of degree $n$. Then we have $$\text{d}(f) = \text{d}_{M'} \circ f - (-1)^n f \circ \text{d}_M$$ On the other hand, we have $$\text{d}(f \otimes \text{id}N) = \text{d}{M' \otimes_A N} \circ (f \otimes \text{id}_N)
- (-1)^n (f \otimes \text{id}N) \circ \text{d}{M \otimes_A N}$$ Applying this to an element $x \otimes y$ with $x \in M$ and $y \in N$ homogeneous we get $$\begin{aligned} \text{d}(f \otimes \text{id}N)(x \otimes y) = & \text{d}{M'}(f(x)) \otimes y + (-1)^{n + \deg(x)}f(x) \otimes \text{d}_N(y) \ & - (-1)^n f(\text{d}_M(x)) \otimes y
- (-1)^{n + \deg(x)}f(x) \otimes \text{d}_N(y) \ = & \text{d}(f) (x \otimes y) \end{aligned}$$ Thus we see that $\text{d}(f) \otimes \text{id}_N = \text{d}(f \otimes \text{id}_N)$ and the proof is complete. $\square$
Lemma. A differential graded submodule suitable for approximation
Let $(A, \text{d})$ be a differential graded algebra. Let $M$ be a differential graded $A$-module. There exists a homomorphism $M \to I$ of differential graded $A$-modules with the following properties
-
$M \to I$ is injective,
-
$\operatorname{Coker}(\text{d}_M) \to \operatorname{Coker}(\text{d}_I)$ is injective, and
-
$I$ sits in an admissible short exact sequence $0 \to I' \to I \to I'' \to 0$ where $I'$, $I''$ are products of shifts of $A^\vee$.
Proof. We will use the functors $N \mapsto N^\vee$ (from left to right differential graded modules and from right to left differential graded modules) constructed in Section Cotangent complexes, differentials and modules and all of their properties. For every $k \in \mathbf{Z}$ let $Q_k$ be the free left $A$-module with generators $x, y$ in degrees $k$ and $k + 1$. Define the structure of a left differential graded $A$-module on $Q_k$ by setting $\text{d}(x) = y$ and $\text{d}(y) = 0$. Arguing exactly as in the proof of Lemma A differential graded quotient suitable for approximation we find a surjection $$\bigoplus\nolimits_{i \in I} Q_{k_i} \longrightarrow M^\vee$$ of left differential graded $A$-modules. Then we can consider the injection $$M \to (M^\vee)^\vee \to (\bigoplus\nolimits_{i \in I} Q_{k_i})^\vee = \prod\nolimits_{i \in I} I_{k_i}$$ where $I_k = Q_{-k}^\vee$ is the "dual" right differential graded $A$-module. Further, the short exact sequence $0 \to A[-k - 1] \to Q_k \to A[-k] \to 0$ produces a short exact sequence $0 \to A^\vee[k] \to I_k \to A^\vee[k + 1] \to 0$.
The result of the previous paragraph produces $M \to I$ having properties (1) and (3). To obtain property (2), suppose $\overline{m} \in \operatorname{Coker}(\text{d}_M)$ is a nonzero element of degree $k$. Pick a map $\lambda : M^k \to \mathbf{Q}/\mathbf{Z}$ which vanishes on $\operatorname{Im}(M^{k - 1} \to M^k)$ but not on $m$. By Lemma Derived Hom, Ext and projective and locally free modules this corresponds to a homomorphism $M \to A^\vee[k]$ of differential graded $A$-modules which does not vanish on $m$. Hence we can achieve (2) by adding a product of copies of shifts of $A^\vee$. $\square$
Lemma. Injective resolutions
Let $(A, \text{d})$ be a differential graded algebra. Let $I \to M$ be an injective homomorphism of differential graded $A$-modules. If $I$ is graded injective, then $I \to M$ is an admissible monomorphism.
Proof. This is immediate from the definitions. $\square$
Proposition. Derived categories
Let $(A, \text{d})$ be a differential graded algebra. The homotopy category $K(\text{Mod}_{(A, \text{d})})$ of differential graded $A$-modules with its natural translation functors and distinguished triangles is a triangulated category.
Proof. We know that $K(\text{Mod}_{(A, \text{d})})$ is a pre-triangulated category. Hence it suffices to prove TR4 and to prove it we can use Derived Categories, Lemma Triangulated categories (uncovered prerequisite). Let $K \to L$ and $L \to M$ be composable morphisms of $K(\text{Mod}_{(A, \text{d})})$. By Lemma Differential graded modules we may assume that $K \to L$ and $L \to M$ are admissible monomorphisms. In this case the result follows from Lemma Differential graded modules. $\square$
Lemma. Derived Hom, Ext and projective and locally free modules
Let $(A, d)$ be a differential graded algebra. Then we have $$\operatorname{Hom}_{\text{Mod}_{(A, \text{d})}}(A[k], M) = \operatorname{Ker}(\text{d} : M^{-k} \to M^{-k + 1})$$ and $$\operatorname{Hom}_{K(\text{Mod}_{(A, \text{d})})}(A[k], M) = H^{-k}(M)$$ for any differential graded $A$-module $M$.
Proof. Immediate from the definitions. $\square$
Lemma. Constructing a differential graded module with property I
Let $(A, \text{d})$ be a differential graded algebra. Let $I$ be a differential graded $A$-module. If $F_\bullet$ is a filtration as in property (I), then we obtain an admissible short exact sequence $$0 \to I \to \prod\nolimits I/F_iI \to \prod\nolimits I/F_iI \to 0$$ of differential graded $A$-modules.
Proof. Omitted. Hint: This is dual to Lemma Proper morphisms. $\square$
Lemma. Morphisms in the differential graded derived category
Let $R$ be a ring. Let $(A, \text{d})$ be a differential graded $R$-algebra. Let $M'$ be a right differential graded $A$-module and let $M$ be a left differential graded $A$-module. Let $N^\bullet$ be a complex of $R$-modules. Then we have $$\operatorname{Hom}_{\text{Mod}_{(A, d)}}(M', \operatorname{Hom}(M, N^\bullet)) = \operatorname{Hom}_{\text{Comp}(R)}(M' \otimes_A M, N^\bullet)$$ where $M \otimes_A M$ is viewed as a complex of $R$-modules as in Section Tensor products and direct sums.
Proof. Let us show that both sides correspond to graded $A$-bilinear maps $$M' \times M \longrightarrow N^\bullet$$ compatible with differentials. We have seen this is true for the right hand side in Section Tensor products and direct sums. Given an element $g$ of the left hand side, the equality of More on Algebra, Lemma Composition and derived commutative algebra determines a map of complexes of $R$-modules $g' : \text{Tot}(M' \otimes_R M) \to N^\bullet$. In other words, we obtain a graded $R$-bilinear map $g'' : M' \times M \to N^\bullet$ compatible with differentials. The $A$-linearity of $g$ translates immediately into $A$-bilinarity of $g''$. $\square$
Example. The graded category of graded modules
Let $A$ be a $\mathbf{Z}$-graded algebra over a ring $R$. We will construct a graded category $\text{Mod}^{gr}_A$ over $R$ whose associated category $(\text{Mod}^{gr}_A)^0$ is the category of graded $A$-modules. As objects of $\text{Mod}^{gr}_A$ we take right graded $A$-modules (see Section Projective and locally free modules). Given graded $A$-modules $L$ and $M$ we set $$\operatorname{Hom}_{\text{Mod}^{gr}_A}(L, M) = \bigoplus\nolimits_{n \in \mathbf{Z}} \operatorname{Hom}^n(L, M)$$ where $\operatorname{Hom}^n(L, M)$ is the set of right $A$-module maps $L \to M$ which are homogeneous of degree $n$, i.e., $f(L^i) \subset M^{i + n}$ for all $i \in \mathbf{Z}$. In terms of components, we have that $$\operatorname{Hom}^n(L, M) \subset \prod\nolimits_{p + q = n} \operatorname{Hom}_R(L^{-q}, M^p)$$ (observe reversal of indices) is the subset consisting of those $f = (f_{p, q})$ such that $$f_{p, q}(m a) = f_{p - i, q + i}(m)a$$ for $a \in A^i$ and $m \in L^{-q - i}$. For graded $A$-modules $K$, $L$, $M$ we define composition in $\text{Mod}^{gr}_A$ via the maps $$\operatorname{Hom}^m(L, M) \times \operatorname{Hom}^n(K, L) \longrightarrow \operatorname{Hom}^{n + m}(K, M)$$ by simple composition of right $A$-module maps: $(g, f) \mapsto g \circ f$.
Example. The differential graded category of complexes
Let $\mathcal{B}$ be an additive category. We will construct a differential graded category $\text{Comp}^{dg}(\mathcal{B})$ over $R = \mathbf{Z}$ whose associated category of complexes is $\text{Comp}(\mathcal{B})$ and whose associated homotopy category is $K(\mathcal{B})$. As objects of $\text{Comp}^{dg}(\mathcal{B})$ we take complexes of $\mathcal{B}$. Given complexes $A^\bullet$ and $B^\bullet$ of $\mathcal{B}$, we sometimes also denote $A^\bullet$ and $B^\bullet$ the corresponding graded objects of $\mathcal{B}$ (i.e., forget about the differential). Using this abuse of notation, we set $$\operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{B})}(A^\bullet, B^\bullet) = \operatorname{Hom}_{\text{Gr}^{gr}(\mathcal{B})}(A^\bullet, B^\bullet) = \bigoplus\nolimits_{n \in \mathbf{Z}} \operatorname{Hom}^n(A, B)$$ as a graded $\mathbf{Z}$-module with notation and definitions as in Example A graded category of graded objects. In other words, the $n$th graded piece is the abelian group of homogeneous morphism of degree $n$ of graded objects $$\operatorname{Hom}^n(A^\bullet, B^\bullet) = \prod\nolimits_{p + q = n} \operatorname{Hom}_\mathcal{B}(A^{-q}, B^p)$$ Observe reversal of indices and observe we have a direct product and not a direct sum. For an element $f \in \operatorname{Hom}^n(A^\bullet, B^\bullet)$ of degree $n$ we set $$\text{d}(f) = \text{d}_B \circ f - (-1)^n f \circ \text{d}_A$$ The sign is exactly as in More on Algebra, Section Derived commutative algebra. To make sense of this we think of $\text{d}_B$ and $\text{d}_A$ as maps of graded objects of $\mathcal{B}$ homogeneous of degree $1$ and we use composition in the category $\text{Gr}^{gr}(\mathcal{B})$ on the right hand side. In terms of components, if $f = (f_{p, q})$ with $f_{p, q} : A^{-q} \to B^p$ we have
$$\text{d}(f_{p, q}) = \text{d}_B \circ f_{p, q} - (-1)^{p + q} f_{p, q} \circ \text{d}_A$$ Note that the first term of this expression is in $\operatorname{Hom}_\mathcal{B}(A^{-q}, B^{p + 1})$ and the second term is in $\operatorname{Hom}_\mathcal{B}(A^{-q - 1}, B^p)$. The reader checks that
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$\text{d}$ has square zero,
-
an element $f$ in $\operatorname{Hom}^n(A^\bullet, B^\bullet)$ has $\text{d}(f) = 0$ if and only if the morphism $f : A^\bullet \to B^\bullet[n]$ of graded objects of $\mathcal{B}$ is actually a map of complexes,
-
in particular, the category of complexes of $\text{Comp}^{dg}(\mathcal{B})$ is equal to $\text{Comp}(\mathcal{B})$,
-
the morphism of complexes defined by $f$ as in (2) is homotopy equivalent to zero if and only if $f = \text{d}(g)$ for some $g \in \operatorname{Hom}^{n - 1}(A^\bullet, B^\bullet)$.
-
in particular, we obtain a canonical isomorphism $$\operatorname{Hom}_{K(\mathcal{B})}(A^\bullet, B^\bullet) \longrightarrow H^0(\operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{B})}(A^\bullet, B^\bullet))$$ and the homotopy category of $\text{Comp}^{dg}(\mathcal{B})$ is equal to $K(\mathcal{B})$.
Given complexes $A^\bullet$, $B^\bullet$, $C^\bullet$ we define composition $$\operatorname{Hom}^m(B^\bullet, C^\bullet) \times \operatorname{Hom}^n(A^\bullet, B^\bullet) \longrightarrow \operatorname{Hom}^{n + m}(A^\bullet, C^\bullet)$$ by composition $(g, f) \mapsto g \circ f$ in the graded category $\text{Gr}^{gr}(\mathcal{B})$, see Example A graded category of graded objects. This defines a map of differential graded modules $$\operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{B})}(B^\bullet, C^\bullet) \otimes_R \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{B})}(A^\bullet, B^\bullet) \longrightarrow \operatorname{Hom}_{\text{Comp}^{dg}(\mathcal{B})}(A^\bullet, C^\bullet)$$ as required in Definition Differential graded categories because $$\begin{aligned} \text{d}(g \circ f) & = \text{d}_C \circ g \circ f - (-1)^{n + m} g \circ f \circ \text{d}_A \\ & = \left(\text{d}_C \circ g - (-1)^m g \circ \text{d}_B\right) \circ f + (-1)^m g \circ \left(\text{d}_B \circ f - (-1)^n f \circ \text{d}_A\right) \\ & = \text{d}(g) \circ f + (-1)^m g \circ \text{d}(f) \end{aligned}$$ as desired.
Definition. Differential graded categories
Let $R$ be a ring. A differential graded category $\mathcal{A}$ over $R$ is a category where every morphism set is given the structure of a differential graded $R$-module and where for $x, y, z \in \operatorname{Ob}(\mathcal{A})$ composition is $R$-bilinear and induces a homomorphism $$\operatorname{Hom}_\mathcal{A}(y, z) \otimes_R \operatorname{Hom}_\mathcal{A}(x, y) \longrightarrow \operatorname{Hom}_\mathcal{A}(x, z)$$ of differential graded $R$-modules.
Lemma. Differential graded modules
Let $(A, \text{d})$ be a differential graded algebra. Let $L_1 \to L_2 \to \ldots \to L_n$ be a sequence of composable homomorphisms of differential graded $A$-modules. There exists a commutative diagram $$\begin{gathered}\begin{matrix}L_1 & L_2 & \ldots & L_n \\ M_1 & M_2 & \ldots & M_n\end{matrix} \\[6pt] \begin{aligned}L_1 & \longrightarrow L_2 \\ L_2 & \longrightarrow \ldots \\ \ldots & \longrightarrow L_n \\ M_1 & \longrightarrow M_2 \\ M_1 & \longrightarrow L_1 \\ M_2 & \longrightarrow \ldots \\ M_2 & \longrightarrow L_2 \\ \ldots & \longrightarrow M_n \\ M_n & \longrightarrow L_n\end{aligned}\end{gathered}$$ in $\text{Mod}_{(A, \text{d})}$ such that each $M_i \to M_{i + 1}$ is an admissible monomorphism and each $M_i \to L_i$ is a homotopy equivalence.
Proof. The case $n = 1$ is without content. Lemma Construction of a differential graded injective resolution is the case $n = 2$. Suppose we have constructed the diagram except for $M_n$. Apply Lemma Construction of a differential graded injective resolution to the composition $M_{n - 1} \to L_{n - 1} \to L_n$. The result is a factorization $M_{n - 1} \to M_n \to L_n$ as desired. $\square$
Lemma. Differential graded modules
Let $(A, \text{d})$ be a differential graded algebra. Suppose that $\alpha : K \to L$ and $\beta : L \to M$ are admissible monomorphisms of differential graded $A$-modules. Then there exist distinguished triangles $(K, L, Q_1, \alpha, p_1, d_1)$, $(K, M, Q_2, \beta \circ \alpha, p_2, d_2)$ and $(L, M, Q_3, \beta, p_3, d_3)$ for which TR4 holds.
Proof. Say $\pi_1 : L \to K$ and $\pi_3 : M \to L$ are homomorphisms of graded $A$-modules which are left inverse to $\alpha$ and $\beta$. Then also $K \to M$ is an admissible monomorphism with left inverse $\pi_2 = \pi_1 \circ \pi_3$. Let us write $Q_1$, $Q_2$ and $Q_3$ for the cokernels of $K \to L$, $K \to M$, and $L \to M$. Then we obtain identifications (as graded $A$-modules) $Q_1 = \operatorname{Ker}(\pi_1)$, $Q_3 = \operatorname{Ker}(\pi_3)$ and $Q_2 = \operatorname{Ker}(\pi_2)$. Then $L = K \oplus Q_1$ and $M = L \oplus Q_3$ as graded $A$-modules. This implies $M = K \oplus Q_1 \oplus Q_3$. Note that $\pi_2 = \pi_1 \circ \pi_3$ is zero on both $Q_1$ and $Q_3$. Hence $Q_2 = Q_1 \oplus Q_3$. Consider the commutative diagram $$\begin{matrix} 0 & \to & K & \to & L & \to & Q_1 & \to & 0 \\ & & \downarrow & & \downarrow & & \downarrow & \\ 0 & \to & K & \to & M & \to & Q_2 & \to & 0 \\ & & \downarrow & & \downarrow & & \downarrow & \\ 0 & \to & L & \to & M & \to & Q_3 & \to & 0 \end{matrix}$$ The rows of this diagram are admissible short exact sequences, and hence determine distinguished triangles by definition. Moreover downward arrows in the diagram above are compatible with the chosen splittings and hence define morphisms of triangles $$(K \to L \to Q_1 \to K[1]) \longrightarrow (K \to M \to Q_2 \to K[1])$$ and $$(K \to M \to Q_2 \to K[1]) \longrightarrow (L \to M \to Q_3 \to L[1]).$$ Note that the splittings $Q_3 \to M$ of the bottom sequence in the diagram provides a splitting for the split sequence $0 \to Q_1 \to Q_2 \to Q_3 \to 0$ upon composing with $M \to Q_2$. It follows easily from this that the morphism $\delta : Q_3 \to Q_1[1]$ in the corresponding distinguished triangle $$(Q_1 \to Q_2 \to Q_3 \to Q_1[1])$$ is equal to the composition $Q_3 \to L[1] \to Q_1[1]$. Hence we get a structure as in the conclusion of axiom TR4. $\square$
Example. A graded category of graded objects
Let $\mathcal{B}$ be an additive category. Recall that we have defined the category $\text{Gr}(\mathcal{B})$ of graded objects of $\mathcal{B}$ in Homology, Definition The geometric construction. In this example, we will construct a graded category $\text{Gr}^{gr}(\mathcal{B})$ over $R = \mathbf{Z}$ whose associated category $\text{Gr}^{gr}(\mathcal{B})^0$ recovers $\text{Gr}(\mathcal{B})$. As objects of $\text{Gr}^{gr}(\mathcal{B})$ we take graded objects of $\mathcal{B}$. Then, given graded objects $A = (A^i)$ and $B = (B^i)$ of $\mathcal{B}$ we set $$\operatorname{Hom}_{\text{Gr}^{gr}(\mathcal{B})}(A, B) = \bigoplus\nolimits_{n \in \mathbf{Z}} \operatorname{Hom}^n(A, B)$$ where the graded piece of degree $n$ is the abelian group of homogeneous maps of degree $n$ from $A$ to $B$. Explicitly we have $$\operatorname{Hom}^n(A, B) = \prod\nolimits_{p + q = n} \operatorname{Hom}_\mathcal{B}(A^{-q}, B^p)$$ (observe reversal of indices and observe that we have a product here and not a direct sum). In other words, a degree $n$ morphism $f$ from $A$ to $B$ can be seen as a system $f = (f_{p, q})$ where $p, q \in \mathbf{Z}$, $p + q = n$ with $f_{p, q} : A^{-q} \to B^p$ a morphism of $\mathcal{B}$. Given graded objects $A$, $B$, $C$ of $\mathcal{B}$ composition of morphisms in $\text{Gr}^{gr}(\mathcal{B})$ is defined via the maps $$\operatorname{Hom}^m(B, C) \times \operatorname{Hom}^n(A, B) \longrightarrow \operatorname{Hom}^{n + m}(A, C)$$ by simple composition $(g, f) \mapsto g \circ f$ of homogeneous maps of graded objects. In terms of components we have $$(g \circ f)_{p, r} = g_{p, q} \circ f_{-q, r}$$ where $q$ is such that $p + q = m$ and $-q + r = n$.
Lemma. Construction of a differential graded injective resolution
Let $(A, \text{d})$ be a differential graded algebra. Let $\alpha : K \to L$ be a homomorphism of differential graded $A$-modules. There exists a factorization $$\begin{gathered}\begin{matrix}K & \tilde L & L\end{matrix} \\[6pt] \begin{aligned}K & \xrightarrow{\tilde \alpha} \tilde L \\ K & \xrightarrow{1} L \\ \tilde L & \xrightarrow{\pi} L\end{aligned}\end{gathered}$$ in $\text{Mod}_{(A, \text{d})}$ such that
-
$\tilde \alpha$ is an admissible monomorphism (see Definition Admissible short exact sequences of differential graded modules),
-
there is a morphism $s : L \to \tilde L$ such that $\pi \circ s = \text{id}_L$ and such that $s \circ \pi$ is homotopic to $\text{id}_{\tilde L}$.
Proof. The proof is identical to the proof of Derived Categories, Lemma Construction of a differential graded injective resolution (uncovered prerequisite). Namely, we set $\tilde L = L \oplus C(1_K)$ and we use elementary properties of the cone construction. $\square$
Definition. Admissible short exact sequences of differential graded modules
Let $(A, \text{d})$ be a differential graded algebra.
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A homomorphism $K \to L$ of differential graded $A$-modules is an admissible monomorphism if there exists a graded $A$-module map $L \to K$ which is left inverse to $K \to L$.
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A homomorphism $L \to M$ of differential graded $A$-modules is an admissible epimorphism if there exists a graded $A$-module map $M \to L$ which is right inverse to $L \to M$.
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A short exact sequence $0 \to K \to L \to M \to 0$ of differential graded $A$-modules is an admissible short exact sequence if it is split as a sequence of graded $A$-modules.
Infinitesimal morphisms and relative finiteness
Lemma. Derived tensor products and Tor amplitude
Consider a commutative diagram of schemes $$\begin{gathered}\begin{matrix}Z' & Y' \\ X' & S'\end{matrix} \\[6pt] \begin{aligned}Z' & \longrightarrow X' \\ Z' & \longrightarrow Y' \\ Y' & \longrightarrow S' \\ X' & \longrightarrow S'\end{aligned}\end{gathered}$$ Let $S \to S'$ be a morphism. Denote by $X$ and $Y$ the base changes of $X'$ and $Y'$ to $S$. Assume $Y' \to S'$ and $Z' \to X'$ are flat. Then $X \times_S Y$ and $Z'$ are Tor independent over $X' \times_{S'} Y'$.
Proof. The question is local, hence we may assume all schemes are affine (some details omitted). Observe that $$\begin{gathered}\begin{matrix}X \times_S Y & X' \times_{S'} Y' \\ X & X'\end{matrix} \\[6pt] \begin{aligned}X \times_S Y & \longrightarrow X' \times_{S'} Y' \\ X \times_S Y & \longrightarrow X \\ X' \times_{S'} Y' & \longrightarrow X' \\ X & \longrightarrow X'\end{aligned}\end{gathered}$$ is cartesian with flat vertical arrows. Write $X = \operatorname{Spec}(A)$, $X' = \operatorname{Spec}(A')$, $X' \times_{S'} Y' = \operatorname{Spec}(B')$. Then $X \times_S Y = \operatorname{Spec}(A \otimes_{A'} B')$. Write $Z' = \operatorname{Spec}(C')$. We have to show $$\text{Tor}_p^{B'}(A \otimes_{A'} B', C') = 0, \quad\text{for } p > 0$$ Since $A' \to B'$ is flat we have $A \otimes_{A'} B' = A \otimes_{A'}^\mathbf{L} B'$. Hence $$(A \otimes_{A'} B') \otimes_{B'}^\mathbf{L} C' = (A \otimes_{A'}^\mathbf{L} B') \otimes_{B'}^\mathbf{L} C' = A \otimes_{A'}^\mathbf{L} C' = A \otimes_{A'} C'$$ The second equality by More on Algebra, Lemma Base change for derived commutative algebra. The last equality because $A' \to C'$ is flat. This proves the lemma. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $$\begin{gathered}\begin{matrix}X & \phantom{X} & P \\ \phantom{X} & S\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X & \xrightarrow{i} P \\ P & \longrightarrow S\end{aligned}\end{gathered}$$ be a commutative diagram of schemes. Assume $i$ is a closed immersion and $P \to S$ flat and locally of finite presentation. Let $E$ be an object of $D(\mathcal{O}_X)$. Then the following are equivalent
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$E$ is $m$-pseudo-coherent relative to $S$,
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$Ri_*E$ is $m$-pseudo-coherent relative to $S$, and
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$Ri_*E$ is $m$-pseudo-coherent on $P$.
Proof. The equivalence of (1) and (2) is Lemma Pseudo-coherent complexes and coherent sheaves. The equivalence of (2) and (3) follows from Lemma Composition and pseudo-coherent complexes and coherent sheaves applied to $\text{id} : P \to P$ provided we can show that $\mathcal{O}_P$ is pseudo-coherent relative to $S$. This follows from More on Algebra, Lemma Perfect complexes and finite presentation and the definitions. $\square$
Lemma. Proper morphisms and line bundles and ampleness
Let $(f, f') : (X \subset X') \to (S \subset S')$ be a morphism of thickenings. Let $\mathcal{L}'$ be an invertible sheaf on $X'$ and denote $\mathcal{L}$ the restriction to $X$. Then $\mathcal{L}'$ is $f'$-ample if and only if $\mathcal{L}$ is $f$-ample.
Proof. Recall that being relatively ample is a condition for each affine open in the base, see Morphisms, Definition Line bundles and ampleness. By Lemma Affine neighbourhoods and nilpotent thickenings there is a 1-to-1 correspondence between affine opens of $S$ and $S'$. Thus we may assume $S$ and $S'$ are affine and we reduce to proving that $\mathcal{L}'$ is ample if and only if $\mathcal{L}$ is ample. This is Limits, Lemma Line bundles and ampleness. $\square$
Theorem. The geometric construction (Stein factorization; general case)
Let $S$ be a scheme. Let $f : X \to S$ be a proper morphism. There exists a factorization $$\begin{gathered}\begin{matrix}X & \phantom{X} & S' \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{\pi} S\end{aligned}\end{gathered}$$ with the following properties:
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the morphism $f'$ is proper with geometrically connected fibres,
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the morphism $\pi : S' \to S$ is integral,
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we have $f'_*\mathcal{O}_X = \mathcal{O}_{S'}$,
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we have $S' = \underline{\operatorname{Spec}}_S(f_*\mathcal{O}_X)$, and
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$S'$ is the normalization of $S$ in $X$, see Morphisms, Definition The geometric construction.
Proof. We may apply Lemma The geometric construction to get the morphism $f' : X \to S'$. Note that besides the conclusions of Lemma The geometric construction we also have that $f'$ is separated (Schemes, Lemma Composition and diagonals and separation (uncovered prerequisite)) and finite type (Morphisms, Lemma Finite algebras (uncovered prerequisite)). Hence $f'$ is proper. At this point we have proved all of the statements except for the statement that $f'$ has geometrically connected fibres.
We may assume that $S = \operatorname{Spec}(R)$ is affine. Set $R' = \Gamma(X, \mathcal{O}_X)$. Then $S' = \operatorname{Spec}(R')$. Thus we may replace $S$ by $S'$ and assume that $S = \operatorname{Spec}(R)$ is affine $R = \Gamma(X, \mathcal{O}_X)$. Next, let $s \in S$ be a point. Let $U \to S$ be an étale morphism of affine schemes and let $u \in U$ be a point mapping to $s$. Let $X_U \to U$ be the base change of $X$. By Lemma Criteria for the geometric construction it suffices to show that the fibre of $X_U \to U$ over $u$ is connected. By Cohomology of Schemes, Lemma Base change for sheaf cohomology and flatness (uncovered prerequisite) we see that $\Gamma(X_U, \mathcal{O}_{X_U}) = \Gamma(U, \mathcal{O}_U)$. Hence we have to show: Given $S = \operatorname{Spec}(R)$ affine, $X \to S$ proper with $\Gamma(X, \mathcal{O}_X) = R$ and $s \in S$ is a point, the fibre $X_s$ is connected.
To do this it suffices to show that the only idempotents $e \in H^0(X_s, \mathcal{O}_{X_s})$ are $0$ and $1$ (we already know that $X_s$ is nonempty by Lemma The geometric construction). By Derived Categories of Schemes, Lemma Proper morphisms after replacing $R$ by a principal localization we may assume $e$ is the image of an element of $R$. Since $R \to H^0(X_s, \mathcal{O}_{X_s})$ factors through $\kappa(s)$ we conclude. $\square$
Lemma. Diagonals, separation and finite algebras
Let $S$ be a scheme. Let $\{X_i \to S\}_{i\in I}$ be an fppf covering, see Topologies, Definition The geometric construction. Let $(V_i/X_i, \varphi_{ij})$ be a descent datum relative to $\{X_i \to S\}$. If each morphism $V_i \to X_i$ is separated and locally quasi-finite, then the descent datum is effective.
Proof. Being separated and being locally quasi-finite are properties of morphisms of schemes which are preserved under any base change, see Schemes, Lemma Diagonals and separation (uncovered prerequisite) and Morphisms, Lemma Base change for finite algebras (uncovered prerequisite). Hence Descent, Lemma Descent of the geometric construction applies and it suffices to prove the statement of the lemma in case the fppf-covering is given by a single $\{X \to S\}$ flat surjective morphism of finite presentation of affines. Say $X = \operatorname{Spec}(A)$ and $S = \operatorname{Spec}(R)$ so that $R \to A$ is a faithfully flat ring map. Let $(V, \varphi)$ be a descent datum relative to $X$ over $S$ and assume that $\pi : V \to X$ is separated and locally quasi-finite.
Let $W^1 \subset V$ be any affine open. Consider $W = \text{pr}_1(\varphi(W^1 \times_S X)) \subset V$. Here is a picture $$\begin{gathered}\begin{matrix}W^1 \times_S X & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & \varphi(W^1 \times_S X) \\ \phantom{X} & V \times_S X & \phantom{X} & \phantom{X} & X \times_S V & \phantom{X} \\ \phantom{X} & \phantom{X} & X \times_S X & X \times_S X & \phantom{X} & \phantom{X} \\ W^1 & V & X & X & V & W\end{matrix} \\[6pt] \begin{aligned}W^1 \times_S X & \longrightarrow \varphi(W^1 \times_S X) \\ W^1 \times_S X & \longrightarrow W^1 \\ W^1 \times_S X & \longrightarrow V \times_S X \\ \varphi(W^1 \times_S X) & \longrightarrow W \\ \varphi(W^1 \times_S X) & \longrightarrow X \times_S V \\ V \times_S X & \xrightarrow{\varphi} X \times_S V \\ V \times_S X & \longrightarrow X \times_S X \\ V \times_S X & \longrightarrow V \\ X \times_S V & \longrightarrow X \times_S X \\ X \times_S V & \longrightarrow V \\ X \times_S X & \xrightarrow{1} X \times_S X \\ X \times_S X & \xrightarrow{\text{pr}_0} X \\ X \times_S X & \xrightarrow{\text{pr}_1} X \\ W^1 & \longrightarrow V \\ V & \longrightarrow X \\ V & \longrightarrow X \\ W & \longrightarrow V\end{aligned}\end{gathered}$$ Ok, and now since $X \to S$ is flat and of finite presentation it is universally open (Morphisms, Lemma The geometric construction (uncovered prerequisite)). Hence we conclude that $W$ is open. Moreover, it is also clearly the case that $W$ is quasi-compact, and $W^1 \subset W$. Moreover, we note that $\varphi(W \times_S X) = X \times_S W$ by the cocycle condition for $\varphi$. Hence we obtain a new descent datum $(W, \varphi')$ by restricting $\varphi$ to $W \times_S X$. Note that the morphism $W \to X$ is quasi-compact, separated and locally quasi-finite. This implies that it is separated and quasi-finite by definition. Hence it is quasi-affine by Lemma Diagonals, separation and affine neighbourhoods. Thus by Descent, Lemma Affine neighbourhoods we see that the descent datum $(W, \varphi')$ is effective.
In other words, we find that there exists an open covering $V = \bigcup W_i$ by quasi-compact opens $W_i$ which are stable for the descent morphism $\varphi$. Moreover, for each such quasi-compact open $W \subset V$ the corresponding descent data $(W, \varphi')$ is effective. This means the original descent datum is effective by glueing the schemes obtained from descending the opens $W_i$, see Descent, Lemma Local algebra. $\square$
Lemma. Groupoids and equivalence relations
Let $X \to X'$ be a thickening of schemes and let $X \to Y$ be an affine morphism of schemes. Let $Y' = Y \amalg_X X'$ be the pushout (see Lemma Pushouts along a thickening of algebraic spaces). Base change gives a functor $$F : (\mathrm{Sch}/Y') \longrightarrow (\mathrm{Sch}/Y) \times_{(\mathrm{Sch}/X)} (\mathrm{Sch}/X')$$ given by $V' \longmapsto (V' \times_{Y'} Y, V' \times_{Y'} X', 1)$ which has a left adjoint $$G : (\mathrm{Sch}/Y) \times_{(\mathrm{Sch}/X)} (\mathrm{Sch}/X') \longrightarrow (\mathrm{Sch}/Y')$$ which sends the triple $(V, U', \varphi)$ to the pushout $V \amalg_{(V \times_Y X)} U'$. Finally, $F \circ G$ is isomorphic to the identity functor.
Proof. Let $(V, U', \varphi)$ be an object of the fibre product category. Set $U = U' \times_{X'} X$. Note that $U \to U'$ is a thickening. Since $\varphi : V \times_Y X \to U' \times_{X'} X = U$ is an isomorphism we have a morphism $U \to V$ over $X \to Y$ which identifies $U$ with the fibre product $X \times_Y V$. In particular $U \to V$ is affine, see Morphisms, Lemma Base change for affine neighbourhoods (uncovered prerequisite). Hence we can apply Lemma Pushouts along a thickening of algebraic spaces to get a pushout $V' = V \amalg_U U'$. Denote $V' \to Y'$ the morphism we obtain in virtue of the fact that $V'$ is a pushout and because we are given morphisms $V \to Y$ and $U' \to X'$ agreeing on $U$ as morphisms into $Y'$. Setting $G(V, U', \varphi) = V'$ gives the functor $G$.
Let us prove that $G$ is a left adjoint to $F$. Let $Z$ be a scheme over $Y'$. We have to show that $$\operatorname{Mor}(V', Z) = \operatorname{Mor}((V, U', \varphi), F(Z))$$ where the morphism sets are taking in their respective categories. Let $g' : V' \to Z$ be a morphism. Denote $\tilde g$, resp. $\tilde f'$ the composition of $g'$ with the morphism $V \to V'$, resp. $U' \to V'$. Base change $\tilde g$, resp. $\tilde f'$ by $Y \to Y'$, resp. $X' \to Y'$ to get a morphism $g : V \to Z \times_{Y'} Y$, resp. $f' : U' \to Z \times_{Y'} X'$. Then $(g, f')$ is an element of the right hand side of the equation above (details omitted). Conversely, suppose that $(g, f') : (V, U', \varphi) \to F(Z)$ is an element of the right hand side. We may consider the composition $\tilde g : V \to Z$, resp. $\tilde f' : U' \to Z$ of $g$, resp. $f$ by $Z \times_{Y'} X' \to Z$, resp. $Z \times_{Y'} Y \to Z$. Then $\tilde g$ and $\tilde f'$ agree as morphism from $U$ to $Z$. By the universal property of pushout, we obtain a morphism $g' : V' \to Z$, i.e., an element of the left hand side. We omit the verification that these constructions are mutually inverse.
To prove that $F \circ G$ is isomorphic to the identity we have to show that the adjunction mapping $(V, U', \varphi) \to F(G(V, U', \varphi))$ is an isomorphism. To do this we may work affine locally. Say $X = \operatorname{Spec}(A)$, $X' = \operatorname{Spec}(A')$, and $Y = \operatorname{Spec}(B)$. Then $A' \to A$ and $B \to A$ are ring maps as in More on Algebra, Lemma Modules and tensor products and direct sums and $Y' = \operatorname{Spec}(B')$ with $B' = B \times_A A'$. Next, suppose that $V = \operatorname{Spec}(D)$, $U' = \operatorname{Spec}(C')$ and $\varphi$ is given by an $A$-algebra isomorphism $D \otimes_B A \to C' \otimes_{A'} A = C'/IC'$. Set $D' = D \times_{C'/IC'} C'$. In this case the statement we have to prove is that $D' \otimes_{B'} B \cong D$ and $D' \otimes_{B'} A' \cong C'$. This is a special case of More on Algebra, Lemma Modules and tensor products and direct sums. $\square$
Lemma. Pushouts along a thickening of algebraic spaces
Let $X \to X'$ be a thickening of schemes and let $X \to Y$ be an affine morphism of schemes. Then there exists a pushout $$\begin{gathered}\begin{matrix}X & X' \\ Y & Y'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow X' \\ X & \xrightarrow{f} Y \\ X' & \xrightarrow{f'} Y' \\ Y & \longrightarrow Y'\end{aligned}\end{gathered}$$ in the category of schemes. Moreover, $Y \subset Y'$ is a thickening, $X = Y \times_{Y'} X'$, and $$\mathcal{O}_{Y'} = \mathcal{O}_Y \times_{f_*\mathcal{O}_X} f'_*\mathcal{O}_{X'}$$ as sheaves on $|Y| = |Y'|$.
Proof. We first construct $Y'$ as a ringed space. Namely, as topological space we take $Y' = Y$. Denote $f' : X' \to Y'$ the map of topological spaces which equals $f$. As structure sheaf $\mathcal{O}_{Y'}$ we take the right hand side of the equation of the lemma. To see that $Y'$ is a scheme, we have to show that any point has an affine neighbourhood. Since the formation of the fibre product of sheaves commutes with restricting to opens, we may assume $Y$ is affine. Then $X$ is affine (as $f$ is affine) and $X'$ is affine as well (see Lemma Affine neighbourhoods and nilpotent thickenings). Say $Y \leftarrow X \rightarrow X'$ corresponds to $B \rightarrow A \leftarrow A'$. Set $B' = B \times_A A'$; this is the global sections of $\mathcal{O}_{Y'}$. As $A' \to A$ is surjective with locally nilpotent kernel we see that $B' \to B$ is surjective with locally nilpotent kernel. Hence $\operatorname{Spec}(B') = \operatorname{Spec}(B)$ (as topological spaces). We claim that $Y' = \operatorname{Spec}(B')$. To see this we will show for $g' \in B'$ with image $g \in B$ that $\mathcal{O}_{Y'}(D(g)) = B'_{g'}$. Namely, by More on Algebra, Lemma Localizing a commutative ring diagram we see that $$(B')_{g'} = B_g \times_{A_h} A'_{h'}$$ where $h \in A$, $h' \in A'$ are the images of $g'$. Since $B_g$, resp. $A_h$, resp. $A'_{h'}$ is equal to $\mathcal{O}_Y(D(g))$, resp. $f_*\mathcal{O}_X(D(g))$, resp. $f'_*\mathcal{O}_{X'}(D(g))$ the claim follows.
It remains to show that $Y'$ is the pushout. The discussion above shows the scheme $Y'$ has an affine open covering $Y' = \bigcup W'_i$ such that the corresponding opens $U'_i \subset X'$, $W_i \subset Y$, and $U_i \subset X$ are affine open. Moreover, if $A'_i$, $B_i$, $A_i$ are the rings corresponding to $U'_i$, $W_i$, $U_i$, then $W'_i$ corresponds to $B_i \times_{A_i} A'_i$. Thus we can apply Lemmas Line bundles and ampleness and Local algebra to conclude our construction is a pushout in the category of schemes. $\square$
Lemma. Flatness and groupoids and equivalence relations
In the situation of Lemma Groupoids and equivalence relations. If $V' = G(V, U', \varphi)$ for some triple $(V, U', \varphi)$, then
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$V' \to Y'$ is locally of finite type if and only if $V \to Y$ and $U' \to X'$ are locally of finite type,
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$V' \to Y'$ is flat if and only if $V \to Y$ and $U' \to X'$ are flat,
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$V' \to Y'$ is flat and locally of finite presentation if and only if $V \to Y$ and $U' \to X'$ are flat and locally of finite presentation,
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$V' \to Y'$ is smooth if and only if $V \to Y$ and $U' \to X'$ are smooth,
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$V' \to Y'$ is étale if and only if $V \to Y$ and $U' \to X'$ are étale, and
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add more here as needed.
If $W'$ is flat over $Y'$, then the adjunction mapping $G(F(W')) \to W'$ is an isomorphism. Hence $F$ and $G$ define mutually quasi-inverse functors between the category of schemes flat over $Y'$ and the category of triples $(V, U', \varphi)$ with $V \to Y$ and $U' \to X'$ flat.
Proof. Looking over affine pieces the assertions of this lemma are equivalent to the corresponding assertions of More on Algebra, Lemma Proper morphisms and tensor products and direct sums. $\square$
Lemma. Flatness and modules
Let $X \to X'$ be a thickening of schemes and let $X \to Y$ be an affine morphism of schemes. Let $Y' = Y \amalg_X X'$ be the pushout (see Lemma Pushouts along a thickening of algebraic spaces). Let $V' \to Y'$ be a morphism of schemes. Set $V = Y \times_{Y'} V'$, $U' = X' \times_{Y'} V'$, and $U = X \times_{Y'} V'$. There is an equivalence of categories between
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quasi-coherent $\mathcal{O}_{V'}$-modules flat over $Y'$, and
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the category of triples $(\mathcal{G}, \mathcal{F}', \varphi)$ where
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$\mathcal{G}$ is a quasi-coherent $\mathcal{O}_V$-module flat over $Y$,
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$\mathcal{F}'$ is a quasi-coherent $\mathcal{O}_{U'}$-module flat over $X'$, and
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$\varphi : (U \to V)^*\mathcal{G} \to (U \to U')^*\mathcal{F}'$ is an isomorphism of $\mathcal{O}_U$-modules.
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The equivalence maps $\mathcal{G}'$ to $((V \to V')^*\mathcal{G}', (U' \to V')^*\mathcal{G}', can)$. Suppose $\mathcal{G}'$ corresponds to the triple $(\mathcal{G}, \mathcal{F}', \varphi)$. Then
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$\mathcal{G}'$ is a finite type $\mathcal{O}_{V'}$-module if and only if $\mathcal{G}$ and $\mathcal{F}'$ are finite type $\mathcal{O}_Y$ and $\mathcal{O}_{U'}$-modules.
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if $V' \to Y'$ is locally of finite presentation, then $\mathcal{G}'$ is an $\mathcal{O}_{V'}$-module of finite presentation if and only if $\mathcal{G}$ and $\mathcal{F}'$ are $\mathcal{O}_Y$ and $\mathcal{O}_{U'}$-modules of finite presentation.
Proof. A quasi-inverse functor assigns to the triple $(\mathcal{G}, \mathcal{F}', \varphi)$ the fibre product $$(V \to V')_*\mathcal{G} \times_{(U \to V')_*\mathcal{F}} (U' \to V')_*\mathcal{F}'$$ where $\mathcal{F} = (U \to U')^*\mathcal{F}'$. This works, because on affines we recover the equivalence of More on Algebra, Lemma Relative flat modules over a ring fibre product. Some details omitted.
Parts (a) and (b) follow from More on Algebra, Lemmas Modules and tensor products and direct sums and Finite presentation under flat module patching. $\square$
Lemma. Projective, locally free modules and flatness
Let $f : X \to S$ be a morphism of schemes of finite presentation. Let $\mathcal{F}$ be a finitely presented $\mathcal{O}_X$-module. Let $x \in X$ with image $s \in S$. If $\mathcal{F}$ is flat at $x$ over $S$ and $(\mathcal{F}_s)_x$ is a flat $\mathcal{O}_{X_s, x}$-module, then $\mathcal{F}$ is finite free in a neighbourhood of $x$.
Proof. If $\mathcal{F}_x \otimes \kappa(x)$ is zero, then $\mathcal{F}_x = 0$ by Nakayama's lemma (Algebra, Lemma Nakayama's lemma) and hence $\mathcal{F}$ is zero in a neighbourhood of $x$ (Modules, Lemma Sheaves on ringed sites and finite algebras (uncovered prerequisite)) and the lemma holds. Thus we may assume $\mathcal{F}_x \otimes \kappa(x)$ is not zero and we see that Theorem Criteria for flatness applies with $f = \text{id} : X \to X$. We conclude that $\mathcal{F}_x$ is flat over $\mathcal{O}_{X, x}$. Hence $\mathcal{F}_x$ is free, see Algebra, Lemma Finite flat modules over a local ring for example. Choose an open neighbourhood $x \in U \subset X$ and sections $s_1, \ldots, s_r \in \mathcal{F}(U)$ which map to a basis in $\mathcal{F}_x$. The corresponding map $\psi : \mathcal{O}_U^{\oplus r} \to \mathcal{F}|_U$ is surjective after shrinking $U$ (Modules, Lemma Sheaves on ringed sites and finite algebras (uncovered prerequisite)). Then $\operatorname{Ker}(\psi)$ is of finite type (see Modules, Lemma Projective, locally free modules and finite presentation (uncovered prerequisite)) and $\operatorname{Ker}(\psi)_x = 0$. Whence after shrinking $U$ once more $\psi$ is an isomorphism. $\square$
Lemma. Proper morphisms and nilpotent thickenings
Let $(f, f') : (X \subset X') \to (S \subset S')$ be a morphism of thickenings such that $X = S \times_{S'} X'$. If $S \subset S'$ is a finite order thickening, then
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$f$ is a closed immersion if and only if $f'$ is a closed immersion,
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$f$ is locally of finite type if and only if $f'$ is locally of finite type,
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$f$ is locally quasi-finite if and only if $f'$ is locally quasi-finite,
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$f$ is locally of finite type of relative dimension $d$ if and only if $f'$ is locally of finite type of relative dimension $d$,
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$\Omega_{X/S} = 0$ if and only if $\Omega_{X'/S'} = 0$,
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$f$ is unramified if and only if $f'$ is unramified,
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$f$ is proper if and only if $f'$ is proper,
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$f$ is finite if and only if $f'$ is finite,
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$f$ is a monomorphism if and only if $f'$ is a monomorphism,
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$f$ is an immersion if and only if $f'$ is an immersion, and
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add more here.
Proof. The properties $\mathcal{P}$ listed in the lemma are all stable under base change, hence if $f'$ has property $\mathcal{P}$, then so does $f$. See Schemes, Lemmas Base change for diagonals and separation (uncovered prerequisite) and Base change for the geometric construction (uncovered prerequisite) and Morphisms, Lemmas Base change for finite algebras (uncovered prerequisite), Base change for finite algebras (uncovered prerequisite), Base change for dimension and codimension (uncovered prerequisite), Base change for cotangent complexes and differentials (uncovered prerequisite), Base change for unramified morphisms (uncovered prerequisite), Base change for proper morphisms (uncovered prerequisite), and Base change for finite algebras (uncovered prerequisite).
The interesting direction in each case is therefore to assume that $f$ has the property and deduce that $f'$ has it too. By induction on the order of the thickening we may assume that $S \subset S'$ is a first order thickening, see discussion immediately following Definition Thickenings.
Most of the proofs will use a reduction to the affine case. Let $U' \subset S'$ be an affine open and let $V' \subset X'$ be an affine open lying over $U'$. Let $U' = \operatorname{Spec}(A')$ and denote $I \subset A'$ be the ideal defining the closed subscheme $U' \cap S$. Say $V' = \operatorname{Spec}(B')$. Then $V' \cap X = \operatorname{Spec}(B'/IB')$. Setting $A = A'/I$ and $B = B'/IB'$ we get a commutative diagram $$\begin{gathered}\begin{matrix}0 & IB' & B' & B & 0 \\ 0 & IA' & A' & A & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow IB' \\ IB' & \longrightarrow B' \\ B' & \longrightarrow B \\ B & \longrightarrow 0 \\ 0 & \longrightarrow IA' \\ IA' & \longrightarrow A' \\ IA' & \longrightarrow IB' \\ A' & \longrightarrow A \\ A' & \longrightarrow B' \\ A & \longrightarrow 0 \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ with exact rows and $I^2 = 0$.
The translation of (1) into algebra: If $A \to B$ is surjective, then $A' \to B'$ is surjective. This follows from Nakayama's lemma (Algebra, Lemma Nakayama's lemma).
The translation of (2) into algebra: If $A \to B$ is a finite type ring map, then $A' \to B'$ is a finite type ring map. This follows from Nakayama's lemma (Algebra, Lemma Nakayama's lemma) applied to a map $A'[x_1, \ldots, x_n] \to B'$ such that $A[x_1, \ldots, x_n] \to B$ is surjective.
Proof of (3). Follows from (2) and that quasi-finiteness of a morphism which is locally of finite type can be checked on fibres, see Morphisms, Lemma Finite algebras (uncovered prerequisite).
Proof of (4). Follows from (2) and that the additional property of "being of relative dimension $d$" can be checked on fibres (by definition, see Morphisms, Definition Dimension and codimension.
The translation of (5) into algebra: If $\Omega_{B/A} = 0$, then $\Omega_{B'/A'} = 0$. By Algebra, Lemma Base change of Kähler differentials we have $0 = \Omega_{B/A} = \Omega_{B'/A'}/I\Omega_{B'/A'}$. Hence $\Omega_{B'/A'} = 0$ by Nakayama's lemma (Algebra, Lemma Nakayama's lemma).
The translation of (6) into algebra: If $A \to B$ is unramified map, then $A' \to B'$ is unramified. Since $A \to B$ is of finite type we see that $A' \to B'$ is of finite type by (2) above. Since $A \to B$ is unramified we have $\Omega_{B/A} = 0$. By part (5) we have $\Omega_{B'/A'} = 0$. Thus $A' \to B'$ is unramified.
Proof of (7). Follows by combining (2) with results of Lemma Proper morphisms and nilpotent thickenings and the fact that proper equals quasi-compact $+$ separated $+$ locally of finite type $+$ universally closed.
Proof of (8). Follows by combining (2) with results of Lemma Proper morphisms and nilpotent thickenings and using the fact that finite equals integral $+$ locally of finite type (Morphisms, Lemma Integral extensions and finite algebras (uncovered prerequisite)).
Proof of (9). As $f$ is a monomorphism we have $X = X \times_S X$. We may apply the results proved so far to the morphism of thickenings $(X \subset X') \to (X \times_S X \subset X' \times_{S'} X')$. We conclude $X' \to X' \times_{S'} X'$ is a closed immersion by (1). In fact, it is a first order thickening as the ideal defining the closed immersion $X' \to X' \times_{S'} X'$ is contained in the pullback of the ideal $\mathcal{I} \subset \mathcal{O}_{S'}$ cutting out $S$ in $S'$. Indeed, $X = X \times_S X = (X' \times_{S'} X') \times_{S'} S$ is contained in $X'$. Hence by Morphisms, Lemma Cotangent complexes, differentials and diagonals and separation (uncovered prerequisite) it suffices to show that $\Omega_{X'/S'} = 0$ which follows from (5) and the corresponding statement for $X/S$.
Proof of (10). If $f : X \to S$ is an immersion, then it factors as $X \to U \to S$ where $U \to S$ is an open immersion and $X \to U$ is a closed immersion. Let $U' \subset S'$ be the open subscheme whose underlying topological space is the same as $U$. Then $X' \to S'$ factors through $U'$ and we conclude that $X' \to U'$ is a closed immersion by part (1). This finishes the proof. $\square$
Lemma. Projective, locally free modules and finite algebras
Let $f : X \to S$ be a morphism of schemes which is locally of finite presentation. Let $\mathcal{F}$ be a finitely presented $\mathcal{O}_X$-module flat over $S$. Then the set $$\{x \in X : \mathcal{F}\text{ free in a neighbourhood of }x\}$$ is open in $X$ and its formation commutes with arbitrary base change $S' \to S$.
Proof. Openness holds trivially. Let $x \in X$ mapping to $s \in S$. By Lemma Projective, locally free modules and flatness we see that $x$ is in our set if and only if $\mathcal{F}|_{X_s}$ is flat at $x$ over $X_s$. Clearly this is also equivalent to $\mathcal{F}$ being flat at $x$ over $X$ (because this statement is implied by freeness of $\mathcal{F}_x$ and implies flatness of $\mathcal{F}|_{X_s}$ at $x$ over $X_s$). Thus the base change statement follows from Lemma Base change for flatness applied to $\text{id} : X \to X$ over $S$. $\square$
Lemma. Line bundles and ampleness
Source credit: the original source citation EGA (IV Corollary 9.6.4)
Let $f : X \to Y$ be a proper morphism of schemes. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Let $y \in Y$ be a point such that $\mathcal{L}_y$ is ample on $X_y$. Then there is an open neighbourhood $V \subset Y$ of $y$ such that $\mathcal{L}|_{f^{-1}(V)}$ is ample on $f^{-1}(V)/V$.
Proof. We may assume $Y$ is affine. Then we find a directed set $I$ and an inverse system of morphisms $X_i \to Y_i$ of schemes with $Y_i$ of finite type over $\mathbf{Z}$, with affine transition morphisms $X_i \to X_{i'}$ and $Y_i \to Y_{i'}$, with $X_i \to Y_i$ proper, such that $X \to Y = \varprojlim (X_i \to Y_i)$. See Limits, Lemma Finite presentation and proper morphisms. After shrinking $I$ we can assume we have a compatible system of invertible $\mathcal{O}_{X_i}$-modules $\mathcal{L}_i$ pulling back to $\mathcal{L}$, see Limits, Lemma Descent of finite locally free and invertible modules. Let $y_i \in Y_i$ be the image of $y$. Then $\kappa(y) = \mathop{\operatorname{colim}} \kappa(y_i)$. Hence for some $i$ we have $\mathcal{L}_{i, y_i}$ is ample on $X_{i, y_i}$ by Limits, Lemma Filtered limits and line bundles and ampleness. By Cohomology of Schemes, Lemma Line bundles and ampleness (uncovered prerequisite) we find an open neighbourhood $V_i \subset Y_i$ of $y_i$ such that $\mathcal{L}_i$ restricted to $f_i^{-1}(V_i)$ is ample relative to $V_i$. Letting $V \subset Y$ be the inverse image of $V_i$ finishes the proof (hints: use Morphisms, Lemma Base change for line bundles and ampleness (uncovered prerequisite) and the fact that $X \to Y \times_{Y_i} X_i$ is affine and the fact that the pullback of an ample invertible sheaf by an affine morphism is ample by Morphisms, Lemma Pullback of line bundles, ampleness and tensor products and direct sums (uncovered prerequisite)). $\square$
Lemma. Derived tensor products, Tor amplitude and flatness
Let $f : X \to S$ be a morphism of locally Noetherian schemes. Let $Z \subset S$ be a closed subscheme with $n$th infinitesimal neighbourhood $Z_n \subset S$. Set $X_n = Z_n \times_S X$. If $X_n \to Z_n$ is flat for all $n$, then $f$ is flat at every point of $f^{-1}(Z)$.
Proof. This is a translation of Algebra, Lemma Flatness and modules into the language of schemes. $\square$
Lemma. Flatness and dimension and codimension
Let $f : X \to Y$ be a proper, flat morphism of schemes of finite presentation. Let $n_{X/Y}$ be the function on $Y$ giving the dimension of fibres of $f$ introduced in Lemma Base change for dimension and codimension. Then $n_{X/Y}$ is locally constant.
Proof. Immediate consequence of Lemmas Flatness and dimension and codimension and Dimension, codimension and proper morphisms. $\square$
Lemma. Diagonals, separation and finite algebras (Zariski's Main Theorem)
Source credit: the original source citation EGA (IV Corollary 18.12.13)
Let $f : X \to S$ be a morphism of schemes. Assume $f$ is quasi-finite and separated and assume that $S$ is quasi-compact and quasi-separated. Then there exists a factorization $$\begin{gathered}\begin{matrix}X & \phantom{X} & T \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f} S \\ X & \xrightarrow{j} T \\ T & \xrightarrow{\pi} S\end{aligned}\end{gathered}$$ where $j$ is a quasi-compact open immersion and $\pi$ is finite.
Proof. Let $X \to S' \to S$ be as in the conclusion of Lemma Diagonals, separation and affine neighbourhoods. By Properties, Lemma Filtered limits and integral extensions and finite algebras we can write $\nu_*\mathcal{O}_{S'} = \mathop{\operatorname{colim}}_{i \in I} \mathcal{A}_i$ as a directed colimit of finite quasi-coherent $\mathcal{O}_S$-algebras $\mathcal{A}_i \subset \nu_*\mathcal{O}_{S'}$. Then $\pi_i : T_i = \underline{\operatorname{Spec}}_S(\mathcal{A}_i) \to S$ is a finite morphism for each $i$. Note that the transition morphisms $T_{i'} \to T_i$ are affine and that $S' = \varprojlim T_i$.
By Limits, Lemma Descent of finite-presentation descent there exists an $i$ and a quasi-compact open $U_i \subset T_i$ whose inverse image in $S'$ equals $f'(X)$. For $i' \geq i$ let $U_{i'}$ be the inverse image of $U_i$ in $T_{i'}$. Then $X \cong f'(X) = \varprojlim_{i' \geq i} U_{i'}$, see Limits, Lemma Finite-presentation descent. By Limits, Lemma Finite algebras we see that $X \to U_{i'}$ is a closed immersion for some $i' \geq i$. (In fact $X \cong U_{i'}$ for sufficiently large $i'$ but we don't need this.) Hence $X \to T_{i'}$ is an immersion. By Morphisms, Lemma Derived tensor products, Tor amplitude and diagonals and separation (uncovered prerequisite) we can factor this as $X \to T \to T_{i'}$ where the first arrow is an open immersion and the second a closed immersion. Thus we win. $\square$
Lemma. Finite presentation and flatness
Let $f : X \to S$ be flat, locally of finite presentation, separated, locally quasi-finite with universally bounded fibres. Then there exist closed subsets $$\emptyset = Z_{-1} \subset Z_0 \subset Z_1 \subset Z_2 \subset \ldots \subset Z_n = S$$ such that with $S_r = Z_r \setminus Z_{r - 1}$ the stratification $S = \coprod_{r = 0, \ldots, n} S_r$ is characterized by the following universal property: Given $g : T \to S$ the projection $X \times_S T \to T$ is finite locally free of degree $r$ if and only if $g(T) \subset S_r$ (set theoretically).
Proof. Let $n$ be an integer bounding the degree of the fibres of $X \to S$. By Morphisms, Lemma Base change for the geometric construction (uncovered prerequisite) we see that any base change has degrees of fibres bounded by $n$ also. In particular, all the integers $r$ that occur in the statement of the lemma will be $\leq n$. We will prove the lemma by induction on $n$. The base case is $n = 0$ which is obvious.
We claim the set of points $s \in S$ with $\deg_{\kappa(s)}(X_s) = n$ is an open subset $S_n \subset S$ and that $X \times_S S_n \to S_n$ is finite locally free of degree $n$. Namely, suppose that $s \in S$ is such a point. Choose an elementary étale morphism $(U, u) \to (S, s)$ and a decomposition $U \times_S X = W \amalg V$ as in Lemma Étale morphisms and finite algebras (uncovered prerequisite). Since $V \to U$ is finite, flat, and locally of finite presentation, we see that $V \to U$ is finite locally free, see Morphisms, Lemma Flatness and finite algebras (uncovered prerequisite). After shrinking $U$ to a smaller neighbourhood of $u$ we may assume $V \to U$ is finite locally free of some degree $d$, see Morphisms, Lemma Projective, locally free modules and finite algebras (uncovered prerequisite). As $u \mapsto s$ and $W_u = \emptyset$ we see that $d = n$. Since $n$ is the maximum degree of a fibre we see that $W = \emptyset$! Thus $U \times_S X \to U$ is finite locally free of degree $n$. By Descent, Lemma Descent of projective, locally free modules and proper morphisms we conclude that $X \to S$ is finite locally free of degree $n$ over $\operatorname{Im}(U \to S)$ which is an open neighbourhood of $s$ (Morphisms, Lemma Étale morphisms (uncovered prerequisite)). This proves the claim.
Let $S' = S \setminus S_n$ endowed with the reduced induced scheme structure and set $X' = X \times_S S'$. Note that the degrees of fibres of $X' \to S'$ are universally bounded by $n - 1$. By induction we find a stratification $S' = S_0 \amalg \ldots \amalg S_{n - 1}$ adapted to the morphism $X' \to S'$. We claim that $S = \coprod_{r = 0, \ldots, n} S_r$ works for the morphism $X \to S$. Let $g : T \to S$ be a morphism of schemes and assume that $X \times_S T \to T$ is finite locally free of degree $r$. As remarked above this implies that $r \leq n$. If $r = n$, then it is clear that $T \to S$ factors through $S_n$. If $r < n$, then $g(T) \subset S' = S \setminus S_d$ (set theoretically) hence $T_{red} \to S$ factors through $S'$, see Schemes, Lemma The geometric construction (uncovered prerequisite). Note that $X \times_S T_{red} \to T_{red}$ is also finite locally free of degree $r$ as a base change. By the universal property of the stratification $S' = \coprod_{r = 0, \ldots, n - 1} S_r$ we see that $g(T) = g(T_{red})$ is contained in $S_r$. Conversely, suppose that we have $g : T \to S$ such that $g(T) \subset S_r$ (set theoretically). If $r = n$, then $g$ factors through $S_n$ and it is clear that $X \times_S T \to T$ is finite locally free of degree $n$ as a base change. If $r < n$, then $X \times_S T \to T$ is a morphism which is separated, flat, and locally of finite presentation, such that the restriction to $T_{red}$ is finite locally free of degree $r$. Since $T_{red} \to T$ is a universal homeomorphism, we conclude that $X \times_S T_{red} \to X \times_S T$ is a universal homeomorphism too and hence $X \times_S T \to T$ is universally closed (as this is true for the finite morphism $X \times_S T_{red} \to T_{red}$). It follows that $X \times_S T \to T$ is finite, for example by Lemma Criteria for finite algebras (uncovered prerequisite). Then we can use Morphisms, Lemma Flatness and finite algebras (uncovered prerequisite) to see that $X \times_S T \to T$ is finite locally free. Finally, the degree is $r$ as all the fibres have degree $r$. $\square$
Lemma. Pseudo-coherent complexes and coherent sheaves
Let $\pi : X \to Y$ be a finite morphism of schemes locally of finite type over a base scheme $S$. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Then $E$ is $m$-pseudo-coherent relative to $S$ if and only if $R\pi_*E$ is $m$-pseudo-coherent relative to $S$.
Proof. Translation of the result of More on Algebra, Lemma Pseudo-coherent complexes and coherent sheaves into the language of schemes. Observe that $R\pi_*$ indeed maps $D_\mathrm{QCoh}(\mathcal{O}_X)$ into $D_\mathrm{QCoh}(\mathcal{O}_Y)$ by Derived Categories of Schemes, Lemma Quasi-coherent complexes and coherent sheaves. To do the translation use Lemma Pseudo-coherent complexes and coherent sheaves (uncovered prerequisite). $\square$
Lemma. Composition and pseudo-coherent complexes and coherent sheaves
Let $f : X \to Y$ be a morphism of schemes locally of finite type over a base $S$. Let $m \in \mathbf{Z}$. Let $E$ be an object of $D(\mathcal{O}_X)$. Assume $\mathcal{O}_Y$ is pseudo-coherent relative to $S$[^1]. Then the following are equivalent
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$E$ is $m$-pseudo-coherent relative to $Y$, and
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$E$ is $m$-pseudo-coherent relative to $S$.
Proof. The question is local on $X$, hence we may assume $X$, $Y$, and $S$ are affine. Arguing as in the proof of More on Algebra, Lemma Pullback of pseudo-coherent complexes and coherent sheaves we can find a commutative diagram $$\begin{gathered}\begin{matrix}X & \mathbf{A}^m_Y & \mathbf{A}^{n + m}_S \\ Y & \mathbf{A}^n_S\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{i} \mathbf{A}^m_Y \\ X & \xrightarrow{f} Y \\ \mathbf{A}^m_Y & \xrightarrow{j} \mathbf{A}^{n + m}_S \\ \mathbf{A}^m_Y & \xrightarrow{p} Y \\ \mathbf{A}^{n + m}_S & \longrightarrow \mathbf{A}^n_S \\ Y & \longrightarrow \mathbf{A}^n_S\end{aligned}\end{gathered}$$ The assumption that $\mathcal{O}_Y$ is pseudo-coherent relative to $S$ implies that $\mathcal{O}_{\mathbf{A}^m_Y}$ is pseudo-coherent relative to $\mathbf{A}^m_S$ (by flat base change; this can be seen by using for example Lemma Base change for pseudo-coherent complexes and coherent sheaves (uncovered prerequisite)). This in turn implies that $j_*\mathcal{O}_{\mathbf{A}^n_Y}$ is pseudo-coherent as an $\mathcal{O}_{\mathbf{A}^{n + m}_S}$-module. Then the equivalence of the lemma follows from Derived Categories of Schemes, Lemma Pseudo-coherent complexes and coherent sheaves. $\square$
Lemma. Affine neighbourhoods and nilpotent thickenings
Affineness is insensitive to thickenings
Source credit: The case of a finite order thickening is the original source citation EGA1 (Proposition 5.1.9).
Any thickening of an affine scheme is affine.
Proof. This is a special case of Limits, Proposition Affine neighbourhoods. $\square$
Proof for a finite order thickening. Suppose that $X \subset X'$ is a finite order thickening with $X$ affine. Then we may use Serre's criterion to prove $X'$ is affine. More precisely, we will use Cohomology of Schemes, Lemma The geometric construction (uncovered prerequisite). Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_{X'}$-module. It suffices to show that $H^1(X', \mathcal{F}) = 0$. Denote $i : X \to X'$ the given closed immersion and denote $\mathcal{I} = \operatorname{Ker}(i^\sharp : \mathcal{O}_{X'} \to i_*\mathcal{O}_X)$. By our discussion of finite order thickenings (following Definition Thickenings) there exists an $n \geq 0$ and a filtration $$0 = \mathcal{F}_{n + 1} \subset \mathcal{F}_n \subset \mathcal{F}_{n - 1} \subset \ldots \subset \mathcal{F}_0 = \mathcal{F}$$ by quasi-coherent submodules such that $\mathcal{F}_a/\mathcal{F}_{a + 1}$ is annihilated by $\mathcal{I}$. Namely, we can take $\mathcal{F}_a = \mathcal{I}^a\mathcal{F}$. Then $\mathcal{F}_a/\mathcal{F}_{a + 1} = i_*\mathcal{G}_a$ for some quasi-coherent $\mathcal{O}_X$-module $\mathcal{G}_a$, see Morphisms, Lemma Groupoids and equivalence relations (uncovered prerequisite). We obtain $$H^1(X', \mathcal{F}_a/\mathcal{F}_{a + 1}) = H^1(X', i_*\mathcal{G}_a) = H^1(X, \mathcal{G}_a) = 0$$ The second equality comes from Cohomology of Schemes, Lemma Sheaf cohomology and affine neighbourhoods (uncovered prerequisite) and the last equality from Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). Thus $\mathcal{F}$ has a finite filtration whose successive quotients have vanishing first cohomology and it follows by a simple induction argument that $H^1(X', \mathcal{F}) = 0$. $\square$
Lemma. The geometric construction
Let $S$ be a scheme. Let $f : X \to S$ be a universally closed and quasi-separated morphism. There exists a factorization $$\begin{gathered}\begin{matrix}X & \phantom{X} & S' \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{\pi} S\end{aligned}\end{gathered}$$ with the following properties:
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the morphism $f'$ is universally closed, quasi-compact, quasi-separated, and surjective,
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the morphism $\pi : S' \to S$ is integral,
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we have $f'_*\mathcal{O}_X = \mathcal{O}_{S'}$,
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we have $S' = \underline{\operatorname{Spec}}_S(f_*\mathcal{O}_X)$, and
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$S'$ is the normalization of $S$ in $X$, see Morphisms, Definition The geometric construction.
Formation of the factorization $f = \pi \circ f'$ commutes with flat base change.
Proof. By Morphisms, Lemma The geometric construction (uncovered prerequisite) the morphism $f$ is quasi-compact. Hence the normalization $S'$ of $S$ in $X$ is defined (Morphisms, Definition The geometric construction) and we have the factorization $X \to S' \to S$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) we have (2), (4), and (5). The morphism $f'$ is universally closed by Morphisms, Lemma Proper morphisms (uncovered prerequisite). It is quasi-compact by Schemes, Lemma The geometric construction (uncovered prerequisite) and quasi-separated by Schemes, Lemma Composition and diagonals and separation (uncovered prerequisite).
To show the remaining statements we may assume the base scheme $S$ is affine, say $S = \operatorname{Spec}(R)$. Then $S' = \operatorname{Spec}(A)$ with $A = \Gamma(X, \mathcal{O}_X)$ an integral $R$-algebra. Thus it is clear that $f'_*\mathcal{O}_X$ is $\mathcal{O}_{S'}$ (because $f'_*\mathcal{O}_X$ is quasi-coherent, by Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite), and hence equal to $\widetilde{A}$). This proves (3).
Let us show that $f'$ is surjective. As $f'$ is universally closed (see above) the image of $f'$ is a closed subset $V(I) \subset S' = \operatorname{Spec}(A)$. Pick $h \in I$. Then $h|_X = f^\sharp(h)$ is a global section of the structure sheaf of $X$ which vanishes at every point. As $X$ is quasi-compact this means that $h|_X$ is a nilpotent section, i.e., $h^n|X = 0$ for some $n > 0$. But $A = \Gamma(X, \mathcal{O}_X)$, hence $h^n = 0$. As every element of $I$ is nilpotent, we conclude that $V(I) = S'$ as desired.
By Cohomology of Schemes, Lemma Base change for sheaf cohomology and flatness (uncovered prerequisite) we see that formation of $f_*\mathcal{O}_X$ commutes with flat base change. Formation of the relative spectrum commutes with any base change by Constructions, Lemma Proper morphisms and prime spectra and associated points (uncovered prerequisite). Thus formation of the factorization commutes with flat base change. $\square$
Lemma. Criteria for the geometric construction
Let $f : X \to S$ be a morphism of schemes. Let $s \in S$. Then $X_s$ is geometrically connected, if and only if for every étale neighbourhood $(U, u) \to (S, s)$ the base change $X_U \to U$ has connected fibre $X_u$.
Proof. If $X_s$ is geometrically connected, then any base change of it is connected. On the other hand, suppose that $X_s$ is not geometrically connected. Then by Varieties, Lemma Criteria for the geometric construction (uncovered prerequisite) we see that $X_s \times_{\operatorname{Spec}(\kappa(s))} \operatorname{Spec}(k)$ is disconnected for some finite separable field extension $k/\kappa(s)$. By Lemma Étale morphisms and field extensions (uncovered prerequisite) there exists an affine étale neighbourhood $(U, u) \to (S, s)$ such that $\kappa(u)/\kappa(s)$ is identified with $k/\kappa(s)$. In this case $X_u$ is disconnected. $\square$
Lemma. Diagonals, separation and affine neighbourhoods
Quasi-finite, separated morphisms are quasi-affine
Let $f : X \to S$ be a morphism of schemes. Assume $f$ is quasi-finite and separated. Let $S'$ be the normalization of $S$ in $X$, see Morphisms, Definition The geometric construction. Picture: $$\begin{gathered}\begin{matrix}X & \phantom{X} & S' \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f} S \\ X & \xrightarrow{f'} S' \\ S' & \xrightarrow{\nu} S\end{aligned}\end{gathered}$$ Then $f'$ is a quasi-compact open immersion and $\nu$ is integral. In particular $f$ is quasi-affine.
Proof. This follows from Lemma Diagonals, separation and finite algebras (uncovered prerequisite). Namely, by that lemma there exists an open subscheme $U' \subset S'$ such that $(f')^{-1}(U') = X$ and $X \to U'$ is an isomorphism. In other words, $f'$ is an open immersion. Note that $f'$ is quasi-compact as $f$ is quasi-compact and $\nu : S' \to S$ is separated (Schemes, Lemma The geometric construction (uncovered prerequisite)). It follows that $f$ is quasi-affine by Morphisms, Lemma Criteria for affine neighbourhoods (uncovered prerequisite). $\square$
Lemma. Prime spectra and associated points
Let $f : X \to Y$ be a morphism of finite presentation. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite presentation. Let $U \subset X$ be an open subscheme such that $U \to Y$ is quasi-compact. Then the set $$E = \{y \in Y \mid \text{Ass}_{X_y}(\mathcal{F}_y) \subset U_y\}$$ is locally constructible in $Y$.
Proof. Let $y \in Y$. We have to show that there exists an open neighbourhood $V$ of $y$ in $Y$ such that $E \cap V$ is constructible in $V$. Thus we may assume that $Y$ is affine. Write $Y = \operatorname{Spec}(A)$ and $A = \mathop{\operatorname{colim}} A_i$ as a directed limit of finite type $\mathbf{Z}$-algebras. By Limits, Lemma Descent of finite presentation and finite algebras we can find an $i$ and a morphism $f_i : X_i \to \operatorname{Spec}(A_i)$ of finite presentation whose base change to $Y$ recovers $f$. After possibly increasing $i$ we may assume there exists a quasi-coherent $\mathcal{O}_{X_i}$-module $\mathcal{F}_i$ of finite presentation whose pullback to $X$ is isomorphic to $\mathcal{F}$, see Limits, Lemma Descent of finite presentation and modules. After possibly increasing $i$ one more time we may assume there exists an open subscheme $U_i \subset X_i$ whose inverse image in $X$ is $U$, see Limits, Lemma Descent of finite-presentation descent. By Lemma Base change for prime spectra and associated points (uncovered prerequisite) it suffices to prove the lemma for $f_i$. Thus we reduce to the case where $Y$ is the spectrum of a Noetherian ring.
We will use the criterion of Topology, Lemma Criteria for Noetherian rings (uncovered prerequisite) to prove that $E$ is constructible in case $Y$ is a Noetherian scheme. To see this let $Z \subset Y$ be an irreducible closed subscheme. We have to show that $E \cap Z$ either contains a nonempty open subset or is not dense in $Z$. This follows from Lemmas The geometric construction (uncovered prerequisite) and The geometric construction (uncovered prerequisite) applied to the base change $(X, \mathcal{F}, U) \times_Y Z$ over $Z$. $\square$
Lemma. Base change for flatness
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} S' \\ X & \xrightarrow{f} S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ be a cartesian diagram of schemes. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Let $x' \in X'$ with images $x = g'(x')$ and $s' = f'(x')$.
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If $\mathcal{F}$ is flat over $S$ at $x$, then $(g')^*\mathcal{F}$ is flat over $S'$ at $x'$.
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If $g$ is flat at $s'$ and $(g')^*\mathcal{F}$ is flat over $S'$ at $x'$, then $\mathcal{F}$ is flat over $S$ at $x$.
In particular, if $g$ is flat, $f$ is locally of finite presentation, and $\mathcal{F}$ is locally of finite presentation, then formation of the open subset of Theorem Openness of the flat locus commutes with base change.
Proof. Consider the commutative diagram of local rings $$\begin{gathered}\begin{matrix}\mathcal{O}_{X', x'} & \mathcal{O}_{X, x} \\ \mathcal{O}_{S', s'} & \mathcal{O}_{S, s}\end{matrix} \\[6pt] \begin{aligned}\mathcal{O}_{X, x} & \longrightarrow \mathcal{O}_{X', x'} \\ \mathcal{O}_{S', s'} & \longrightarrow \mathcal{O}_{X', x'} \\ \mathcal{O}_{S, s} & \longrightarrow \mathcal{O}_{S', s'} \\ \mathcal{O}_{S, s} & \longrightarrow \mathcal{O}_{X, x}\end{aligned}\end{gathered}$$ Note that $\mathcal{O}_{X', x'}$ is a localization of $\mathcal{O}_{X, x} \otimes_{\mathcal{O}_{S, s}} \mathcal{O}_{S', s'}$, and that $((g')^*\mathcal{F})_{x'}$ is equal to $\mathcal{F}_x \otimes_{\mathcal{O}_{X, x}} \mathcal{O}_{X', x'}$. Hence the lemma follows from Algebra, Lemma Base change for flatness (uncovered prerequisite). $\square$
Theorem. Openness of the flat locus
Source credit: the original source citation EGA (IV Theorem 11.3.1)
Let $S$ be a scheme. Let $f : X \to S$ be a morphism which is locally of finite presentation. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module which is locally of finite presentation. Then $$U = \{x \in X \mid \mathcal{F}\text{ is flat over }S\text{ at }x\}$$ is open in $X$.
Proof. We may test for openness locally on $X$ hence we may assume that $f$ is a morphism of affine schemes. In this case the theorem is exactly Algebra, Theorem Openness of the flat locus. $\square$
Lemma. Line bundles and ampleness
Let $A' \to A$ be a surjection of rings and let $B \to A$ be a ring map. Let $B' = B \times_A A'$ be the fibre product of rings. Set $S = \operatorname{Spec}(A)$, $S' = \operatorname{Spec}(A')$, $T = \operatorname{Spec}(B)$, and $T' = \operatorname{Spec}(B')$. Then $$\begin{gathered}\begin{matrix}S & S' \\ T & T'\end{matrix} \\[6pt] \begin{aligned}S & \xrightarrow{i} S' \\ S & \xrightarrow{f} T \\ S' & \xrightarrow{f'} T' \\ T & \xrightarrow{i'} T'\end{aligned}\end{gathered} \quad\text{corresponding to}\quad \begin{gathered}\begin{matrix}A & A' \\ B & B'\end{matrix} \\[6pt] \begin{aligned}A' & \longrightarrow A \\ B & \longrightarrow A \\ B' & \longrightarrow B \\ B' & \longrightarrow A'\end{aligned}\end{gathered}$$ is a pushout of schemes.
Proof. By More on Algebra, Lemma Tensor products and direct sums we have $T' = T \amalg_S S'$ as topological spaces, i.e., the diagram is a pushout in the category of topological spaces. Next, consider the map $$((i')^\sharp, (f')^\sharp) : \mathcal{O}_{T'} \longrightarrow i'_*\mathcal{O}_T \times_{g_*\mathcal{O}_S} f'_*\mathcal{O}_{S'}$$ where $g = i' \circ f = f' \circ i$. We claim this map is an isomorphism of sheaves of rings. Namely, we can view both sides as quasi-coherent $\mathcal{O}_{T'}$-modules (use Schemes, Lemmas Quasi-coherent complexes and coherent sheaves (uncovered prerequisite) for the right hand side) and the map is $\mathcal{O}_{T'}$-linear. Thus it suffices to show the map is an isomorphism on the level of global sections (Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite)). On global sections we recover the identification $B' \to B \times_A A'$ from statement of the lemma (this is how we chose $B'$).
Let $X$ be a scheme. Suppose we are given morphisms of schemes $m' : S' \to X$ and $n : T \to X$ such that $m' \circ i = n \circ f$ (call this $m$). We get a unique map of topological spaces $n' : T' \to X$ compatible with $m'$ and $n$ as $T' = T \amalg_S S'$ (see above). By the description of $\mathcal{O}_{T'}$ in the previous paragraph we obtain a unique homomorphism of sheaves of rings $$(n')^\sharp : \mathcal{O}_X \longrightarrow (n')_*\mathcal{O}_{T'} = m'_*\mathcal{O}_T \times_{m_*\mathcal{O}_T} n_*\mathcal{O}_S$$ given by $(m')^\sharp$ and $n^\sharp$. Thus $(n', (n')^\sharp)$ is the unique morphism of ringed spaces $T' \to X$ compatible with $m'$ and $n$. To finish the proof it suffices to show that $n'$ is a morphism of schemes, i.e., a morphism of locally ringed spaces.
Let $t' \in T'$ with image $x \in X$. We have to show that $\mathcal{O}_{X, x} \to \mathcal{O}_{T', t'}$ is local. If $t' \not \in T$, then $t'$ is the image of a unique point $s' \in S'$ and $\mathcal{O}_{T', t'} = \mathcal{O}_{S', s'}$. Namely, $S' \setminus S \to T' \setminus T$ is an isomorphism of schemes as $B' \to A'$ induces an isomorphism $\operatorname{Ker}(B' \to B) = \operatorname{Ker}(A' \to A)$. If $t'$ is the image of $t \in T$, then we know that the composition $\mathcal{O}_{X, x} \to \mathcal{O}_{T', t'} \to \mathcal{O}_{T, t}$ is local and we conclude also. $\square$
Lemma. Local algebra
Let $\mathcal{I} \to (\mathrm{Sch}/S)_{fppf}$, $i \mapsto X_i$ be a diagram of schemes. Let $(W, X_i \to W)$ be a cocone for the diagram in the category of schemes (Categories, Remark Derived categories). If there exists a fpqc covering $\{W_a \to W\}_{a \in A}$ of schemes such that
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for all $a \in A$ we have $W_a = \mathop{\operatorname{colim}} X_i \times_W W_a$ in the category of schemes, and
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for all $a, b \in A$ we have $W_a \times_W W_b = \mathop{\operatorname{colim}} X_i \times_W W_a \times_W W_b$ in the category of schemes,
then $W = \mathop{\operatorname{colim}} X_i$ in the category of schemes.
Proof. Namely, for a scheme $T$ a morphism $W \to T$ is the same thing as collection of morphism $W_a \to T$, $a \in A$ which agree on the overlaps $W_a \times_W W_b$, see Descent, Lemma The geometric construction. $\square$
Lemma. Square-zero deformations and their comparison maps
Let $(f, f') : (X \subset X') \to (S \subset S')$ be a morphism of first order thickenings. Assume that $f$ is flat. Then the following are equivalent
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$f'$ is flat and $X = S \times_{S'} X'$, and
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the canonical map $f^*\mathcal{C}_{S/S'} \to \mathcal{C}_{X/X'}$ is an isomorphism.
Proof. As the problem is local on $X'$ we may assume that $X, X', S, S'$ are affine schemes. Say $S' = \operatorname{Spec}(A')$, $X' = \operatorname{Spec}(B')$, $S = \operatorname{Spec}(A)$, $X = \operatorname{Spec}(B)$ with $A = A'/I$ and $B = B'/J$ for some square zero ideals. Then we obtain the following commutative diagram $$\begin{gathered}\begin{matrix}0 & J & B' & B & 0 \\ 0 & I & A' & A & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow J \\ J & \longrightarrow B' \\ B' & \longrightarrow B \\ B & \longrightarrow 0 \\ 0 & \longrightarrow I \\ I & \longrightarrow A' \\ I & \longrightarrow J \\ A' & \longrightarrow A \\ A' & \longrightarrow B' \\ A & \longrightarrow 0 \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ with exact rows. The canonical map of the lemma is the map $$I \otimes_A B = I \otimes_{A'} B' \longrightarrow J.$$ The assumption that $f$ is flat signifies that $A \to B$ is flat.
Assume (1). Then $A' \to B'$ is flat and $J = IB'$. Flatness implies $\text{Tor}_1^{A'}(B', A) = 0$ (see Algebra, Lemma Criteria for flatness (uncovered prerequisite)). This means $I \otimes_{A'} B' \to B'$ is injective (see Algebra, Remark Tor for a quotient by an ideal). Hence we see that $I \otimes_A B \to J$ is an isomorphism.
Assume (2). Then it follows that $J = IB'$, so that $X = S \times_{S'} X'$. Moreover, we get $\text{Tor}_1^{A'}(B', A'/I) = 0$ by reversing the implications in the previous paragraph. Hence $B'$ is flat over $A'$ by Algebra, Lemma A reformulation of the local algebraic condition. $\square$
Lemma. Nilpotent thickenings
Let $X$ be a scheme over a base $S$. Consider a short exact sequence $$0 \to \mathcal{I} \to \mathcal{A} \to \mathcal{O}_X \to 0$$ of sheaves on $X$ where $\mathcal{A}$ is a sheaf of $f^{-1}\mathcal{O}_S$-algebras, $\mathcal{A} \to \mathcal{O}_X$ is a surjection of sheaves of $f^{-1}\mathcal{O}_S$-algebras, and $\mathcal{I}$ is its kernel. If
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$\mathcal{I}$ is an ideal of square zero in $\mathcal{A}$, and
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$\mathcal{I}$ is quasi-coherent as an $\mathcal{O}_X$-module
then $X' = (X, \mathcal{A})$ is a scheme and $X \to X'$ is a first order thickening over $S$. Moreover, any first order thickening over $S$ is of this form.
Proof. It is clear that $X'$ is a locally ringed space. Let $U = \operatorname{Spec}(B)$ be an affine open of $X$. Set $A = \Gamma(U, \mathcal{A})$. Note that since $H^1(U, \mathcal{I}) = 0$ (see Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite)) the map $A \to B$ is surjective. By assumption the kernel $I = \mathcal{I}(U)$ is an ideal of square zero in the ring $A$. By Schemes, Lemma Affine neighbourhoods (uncovered prerequisite) there is a canonical morphism of locally ringed spaces $$(U, \mathcal{A}|_U) \longrightarrow \operatorname{Spec}(A)$$ coming from the map $B \to \Gamma(U, \mathcal{A})$. Since this morphism fits into the commutative diagram $$\begin{gathered}\begin{matrix}(U, \mathcal{O}_X|_U) & \operatorname{Spec}(B) \\ (U, \mathcal{A}|_U) & \operatorname{Spec}(A)\end{matrix} \\[6pt] \begin{aligned}(U, \mathcal{O}_X|_U) & \longrightarrow (U, \mathcal{A}|_U) \\ (U, \mathcal{O}_X|_U) & \longrightarrow \operatorname{Spec}(B) \\ \operatorname{Spec}(B) & \longrightarrow \operatorname{Spec}(A) \\ (U, \mathcal{A}|_U) & \longrightarrow \operatorname{Spec}(A)\end{aligned}\end{gathered}$$ we see that it is a homeomorphism on underlying topological spaces. Thus to see that it is an isomorphism, it suffices to check it induces an isomorphism on the local rings. For $u \in U$ corresponding to the prime $\mathfrak p \subset A$ we obtain a commutative diagram of short exact sequences $$\begin{gathered}\begin{matrix}0 & I_{\mathfrak p} & A_{\mathfrak p} & B_{\mathfrak p} & 0 \\ 0 & \mathcal{I}_u & \mathcal{A}_u & \mathcal{O}_{X, u} & 0.\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow I_{\mathfrak p} \\ I_{\mathfrak p} & \longrightarrow A_{\mathfrak p} \\ I_{\mathfrak p} & \longrightarrow \mathcal{I}_u \\ A_{\mathfrak p} & \longrightarrow B_{\mathfrak p} \\ A_{\mathfrak p} & \longrightarrow \mathcal{A}_u \\ B_{\mathfrak p} & \longrightarrow 0 \\ B_{\mathfrak p} & \longrightarrow \mathcal{O}_{X, u} \\ 0 & \longrightarrow \mathcal{I}_u \\ \mathcal{I}_u & \longrightarrow \mathcal{A}_u \\ \mathcal{A}_u & \longrightarrow \mathcal{O}_{X, u} \\ \mathcal{O}_{X, u} & \longrightarrow 0.\end{aligned}\end{gathered}$$ The left and right vertical arrows are isomorphisms because $\mathcal{I}$ and $\mathcal{O}_X$ are quasi-coherent sheaves. Hence also the middle map is an isomorphism. Hence every point of $X' = (X, \mathcal{A})$ has an affine neighbourhood and $X'$ is a scheme as desired. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $f : X \to Y$ be a morphism of schemes. The cohomology sheaves of the complex $\mathrm{NL}_{X/Y}$ are quasi-coherent, zero outside degrees $-1$, $0$ and equal to $\Omega_{X/Y}$ in degree $0$.
Proof. By construction of the naive cotangent complex in Modules, Section The naive cotangent complex we have that $\mathrm{NL}_{X/Y}$ is a complex sitting in degrees $-1$, $0$ and that its cohomology in degree $0$ is $\Omega_{X/Y}$. The sheaf of differentials is quasi-coherent (by Morphisms, Lemma Cotangent complexes, differentials and diagonals and separation (uncovered prerequisite)). To finish the proof it suffices to show that $H^{-1}(\mathrm{NL}_{X/Y})$ is quasi-coherent. This follows by checking over affines using Lemma Cotangent complexes, differentials and affine neighbourhoods (uncovered prerequisite). $\square$
Lemma. Finite presentation from a finite-type flat family
Let $f : X \to Y$ be a morphism of schemes. If $f$ is locally of finite presentation, then $\mathrm{NL}_{X/Y}$ is locally on $X$ quasi-isomorphic to a complex $$\ldots \to 0 \to \mathcal{F}^{-1} \to \mathcal{F}^0 \to 0 \to \ldots$$ of quasi-coherent $\mathcal{O}_X$-modules with $\mathcal{F}^0$ of finite presentation and $\mathcal{F}^{-1}$ of finite type.
Proof. By Lemma Cotangent complexes, differentials and affine neighbourhoods (uncovered prerequisite) it suffices to show that $\mathrm{NL}_{A/R}$ has this shape if $R \to A$ is a finitely presented ring map. Write $A = R[x_1, \ldots, x_n]/I$ with $I$ finitely generated. Then $I/I^2$ is a finite $A$-module and $\mathrm{NL}_{A/R}$ is quasi-isomorphic to $$\ldots \to 0 \to I/I^2 \to \bigoplus\nolimits_{i = 1, \ldots, n} A\text{d}x_i \to 0 \to \ldots$$ by Algebra, Section The naive cotangent complex and in particular Algebra, Lemma Kähler differentials, Theorems 3.1–3.3, Proposition 3.4 and Theorem 7.1. $\square$
Lemma. Properties preserved under a square-zero deformation
Consider a commutative diagram $$\begin{gathered}\begin{matrix}(X \subset X') & \phantom{X} & (Y \subset Y') \\ \phantom{X} & (S \subset S')\end{matrix} \\[6pt] \begin{aligned}(X \subset X') & \xrightarrow{(f, f')} (Y \subset Y') \\ (X \subset X') & \longrightarrow (S \subset S') \\ (Y \subset Y') & \longrightarrow (S \subset S')\end{aligned}\end{gathered}$$ of thickenings. Assume $S \subset S'$ is a finite order thickening, $X'$ flat over $S'$, $X = S \times_{S'} X'$, and $Y = S \times_{S'} Y'$. Then
-
$f$ is flat if and only if $f'$ is flat,
-
$f$ is an isomorphism if and only if $f'$ is an isomorphism,
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$f$ is an open immersion if and only if $f'$ is an open immersion,
-
$f$ is quasi-compact if and only if $f'$ is quasi-compact,
-
$f$ is universally closed if and only if $f'$ is universally closed,
-
$f$ is (quasi-)separated if and only if $f'$ is (quasi-)separated,
-
$f$ is a monomorphism if and only if $f'$ is a monomorphism,
-
$f$ is surjective if and only if $f'$ is surjective,
-
$f$ is universally injective if and only if $f'$ is universally injective,
-
$f$ is affine if and only if $f'$ is affine,
$f$ is locally of finite type if and only if $f'$ is locally of finite type,
-
$f$ is locally quasi-finite if and only if $f'$ is locally quasi-finite,
-
$f$ is locally of finite presentation if and only if $f'$ is locally of finite presentation,
-
$f$ is locally of finite type of relative dimension $d$ if and only if $f'$ is locally of finite type of relative dimension $d$,
-
$f$ is universally open if and only if $f'$ is universally open,
-
$f$ is syntomic if and only if $f'$ is syntomic,
-
$f$ is smooth if and only if $f'$ is smooth,
-
$f$ is unramified if and only if $f'$ is unramified,
-
$f$ is étale if and only if $f'$ is étale,
-
$f$ is proper if and only if $f'$ is proper,
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$f$ is integral if and only if $f'$ is integral,
-
$f$ is finite if and only if $f'$ is finite,
-
$f$ is finite locally free (of rank $d$) if and only if $f'$ is finite locally free (of rank $d$), and
-
add more here.
Proof. The assumptions on $X$ and $Y$ mean that $f$ is the base change of $f'$ by $X \to X'$. The properties $\mathcal{P}$ listed in (1) -- (23) above are all stable under base change, hence if $f'$ has property $\mathcal{P}$, then so does $f$. See Schemes, Lemmas Base change for diagonals and separation (uncovered prerequisite), Base change for the geometric construction (uncovered prerequisite), Diagonals and separation (uncovered prerequisite), and Base change for the geometric construction (uncovered prerequisite) and Morphisms, Lemmas Base change for the geometric construction (uncovered prerequisite), Base change for injective resolutions (uncovered prerequisite), Base change for affine neighbourhoods (uncovered prerequisite), Base change for finite algebras (uncovered prerequisite), Base change for finite algebras (uncovered prerequisite), Base change for finite presentation and finite algebras (uncovered prerequisite), Base change for dimension and codimension (uncovered prerequisite), Base change for the geometric construction (uncovered prerequisite), Base change of smooth ring maps (uncovered prerequisite), Base change for unramified morphisms (uncovered prerequisite), Base change for étale morphisms (uncovered prerequisite), Base change for proper morphisms (uncovered prerequisite), Base change for finite algebras (uncovered prerequisite), and Base change for projective, locally free modules and finite algebras (uncovered prerequisite).
The interesting direction in each case is therefore to assume that $f$ has the property and deduce that $f'$ has it too. By induction on the order of the thickening we may assume that $S \subset S'$ is a first order thickening, see discussion immediately following Definition Thickenings. We make a couple of general remarks which we will use without further mention in the arguments below. (I) Let $W' \subset S'$ be an affine open and let $U' \subset X'$ and $V' \subset Y'$ be affine opens lying over $W'$ with $f'(U') \subset V'$. Let $W' = \operatorname{Spec}(R')$ and denote $I \subset R'$ be the ideal defining the closed subscheme $W' \cap S$. Say $U' = \operatorname{Spec}(B')$ and $V' = \operatorname{Spec}(A')$. Then we get a commutative diagram $$\begin{gathered}\begin{matrix}0 & IB' & B' & B & 0 \\ 0 & IA' & A' & A & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow IB' \\ IB' & \longrightarrow B' \\ B' & \longrightarrow B \\ B & \longrightarrow 0 \\ 0 & \longrightarrow IA' \\ IA' & \longrightarrow A' \\ IA' & \longrightarrow IB' \\ A' & \longrightarrow A \\ A' & \longrightarrow B' \\ A & \longrightarrow 0 \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ with exact rows. Moreover $IB' \cong I \otimes_R B$, see proof of Lemma Square-zero deformations and their comparison maps. (II) The morphisms $X \to X'$ and $Y \to Y'$ are universal homeomorphisms. Hence the topology of the maps $f$ and $f'$ (after any base change) is identical. (III) If $f$ is flat, then $f'$ is flat and $Y' \to S'$ is flat at every point in the image of $f'$, see Lemma Flatness and nilpotent thickenings (uncovered prerequisite).
Ad (the indicated step). This is general remark (III).
Ad (the indicated step). Assume $f$ is an isomorphism. By (III) we see that $Y' \to S'$ is flat. Choose an affine open $V' \subset Y'$ and set $U' = (f')^{-1}(V')$. Then $V = Y \cap V'$ is affine which implies that $V \cong f^{-1}(V) = U = Y \times_{Y'} U'$ is affine. By Lemma Affine neighbourhoods and nilpotent thickenings we see that $U'$ is affine. Thus we have a diagram as in the general remark (I) and moreover $IA \cong I \otimes_R A$ because $R' \to A'$ is flat. Then $IB' \cong I \otimes_R B \cong I \otimes_R A \cong IA'$ and $A \cong B$. By the exactness of the rows in the diagram above we see that $A' \cong B'$, i.e., $U' \cong V'$. Thus $f'$ is an isomorphism.
Ad (the indicated step). Assume $f$ is an open immersion. Then $f$ is an isomorphism of $X$ with an open subscheme $V \subset Y$. Let $V' \subset Y'$ be the open subscheme whose underlying topological space is $V$. Then $f'$ is a map from $X'$ to $V'$ which is an isomorphism by (the indicated step). Hence $f'$ is an open immersion.
Ad (the indicated step). Immediate from remark (II). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Immediate from remark (II). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Note that $X \times_Y X = Y \times_{Y'} (X' \times_{Y'} X')$ so that $X' \times_{Y'} X'$ is a thickening of $X \times_Y X$. Hence the topology of the maps $\Delta_{X/Y}$ and $\Delta_{X'/Y'}$ matches and we win. See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Assume $f$ is a monomorphism. Consider the diagonal morphism $\Delta_{X'/Y'} : X' \to X' \times_{Y'} X'$. The base change of $\Delta_{X'/Y'}$ by $S \to S'$ is $\Delta_{X/Y}$ which is an isomorphism by assumption. By (the indicated step) we conclude that $\Delta_{X'/Y'}$ is an isomorphism.
Ad (the indicated step). This is clear. See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Immediate from remark (II). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Assume $f$ is affine. Choose an affine open $V' \subset Y'$ and set $U' = (f')^{-1}(V')$. Then $V = Y \cap V'$ is affine which implies that $U = Y \times_{Y'} U'$ is affine. By Lemma Affine neighbourhoods and nilpotent thickenings we see that $U'$ is affine. Hence $f'$ is affine. See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Via remark (I) comes down to proving $A' \to B'$ is of finite type if $A \to B$ is of finite type. Suppose that $x_1, \ldots, x_n \in B'$ are elements whose images in $B$ generate $B$ as an $A$-algebra. Then $A'[x_1, \ldots, x_n] \to B$ is surjective as both $A'[x_1, \ldots, x_n] \to B$ is surjective and $I \otimes_R A[x_1, \ldots, x_n] \to I \otimes_R B$ is surjective. See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Follows from (the indicated step) and that quasi-finiteness of a morphism of finite type can be checked on fibres, see Morphisms, Lemma Finite algebras (uncovered prerequisite). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Via remark (I) comes down to proving $A' \to B'$ is of finite presentation if $A \to B$ is of finite presentation. We may assume that $B' = A'[x_1, \ldots, x_n]/K'$ for some ideal $K'$ by (the indicated step). We get a short exact sequence $$0 \to K' \to A'[x_1, \ldots, x_n] \to B' \to 0$$ As $B'$ is flat over $R'$ we see that $K' \otimes_{R'} R$ is the kernel of the surjection $A[x_1, \ldots, x_n] \to B$. By assumption on $A \to B$ there exist finitely many $f'_1, \ldots, f'_m \in K'$ whose images in $A[x_1, \ldots, x_n]$ generate this kernel. Since $I$ is nilpotent we see that $f'_1, \ldots, f'_m$ generate $K'$ by Nakayama's lemma, see Algebra, Lemma Nakayama's lemma.
Ad (the indicated step). Follows from (the indicated step) and general remark (II). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Immediate from general remark (II). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Assume $f$ is syntomic. By (the indicated step) $f'$ is locally of finite presentation, by general remark (III) $f'$ is flat and the fibres of $f'$ are the fibres of $f$. Hence $f'$ is syntomic by Morphisms, Lemma Flatness (uncovered prerequisite).
Ad (the indicated step). Assume $f$ is smooth. By (the indicated step) $f'$ is locally of finite presentation, by general remark (III) $f'$ is flat, and the fibres of $f'$ are the fibres of $f$. Hence $f'$ is smooth by Morphisms, Lemma Flatness and smooth morphisms (uncovered prerequisite).
Ad (the indicated step). Assume $f$ unramified. By (the indicated step) $f'$ is locally of finite type and the fibres of $f'$ are the fibres of $f$. Hence $f'$ is unramified by Morphisms, Lemma Étale morphisms and unramified morphisms (uncovered prerequisite). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Assume $f$ étale. By (the indicated step) $f'$ is locally of finite presentation, by general remark (III) $f'$ is flat, and the fibres of $f'$ are the fibres of $f$. Hence $f'$ is étale by Morphisms, Lemma Étale morphisms and flatness (uncovered prerequisite).
Ad (the indicated step). This follows from a combination of (the indicated step), (the indicated step), (the indicated step), and (the indicated step). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Combine (the indicated step) and (the indicated step) with Morphisms, Lemma Integral extensions (uncovered prerequisite). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Combine (the indicated step), and (the indicated step) with Morphisms, Lemma Integral extensions and finite algebras (uncovered prerequisite). See also Lemma Proper morphisms and nilpotent thickenings for a more general statement.
Ad (the indicated step). Assume $f$ finite locally free. By (the indicated step) we see that $f'$ is finite, by general remark (III) $f'$ is flat, and by (the indicated step) $f'$ is locally of finite presentation. Hence $f'$ is finite locally free by Morphisms, Lemma Flatness and finite algebras (uncovered prerequisite). $\square$
Theorem. Criteria for flatness
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of schemes over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Assume
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$X$ is locally of finite presentation over $S$,
-
$\mathcal{F}$ an $\mathcal{O}_X$-module of finite presentation, and
-
$Y$ is locally of finite type over $S$.
Let $x \in X$. Set $y = f(x)$ and let $s \in S$ be the image of $x$ in $S$. If $\mathcal{F}_x \not = 0$, then the following are equivalent:
-
$\mathcal{F}$ is flat over $S$ at $x$, and $\mathcal{F}_s$ is flat over $Y_s$ at $x$, and
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$Y$ is flat over $S$ at $y$ and $\mathcal{F}$ is flat over $Y$ at $x$.
Moreover, the set of points $x$ where (1) and (2) hold is open in $\text{Supp}(\mathcal{F})$.
Proof. Consider the ring maps $$\mathcal{O}_{S, s} \longrightarrow \mathcal{O}_{Y, y} \longrightarrow \mathcal{O}_{X, x}$$ and the module $\mathcal{F}_x$. The stalk of $\mathcal{F}_s$ at $x$ is the module $\mathcal{F}_x/\mathfrak m_s \mathcal{F}_x$ and the local ring of $Y_s$ at $y$ is $\mathcal{O}_{Y, y}/\mathfrak m_s \mathcal{O}_{Y, y}$. Thus the implication (1) $\Rightarrow$ (2) is Algebra, Lemma Criteria for finite presentation and flatness (uncovered prerequisite). If (2) holds, then the first ring map is faithfully flat and $\mathcal{F}_x$ is flat over $\mathcal{O}_{Y, y}$ so by Algebra, Lemma Composition and flatness (uncovered prerequisite) we see that $\mathcal{F}_x$ is flat over $\mathcal{O}_{S, s}$. Moreover, $\mathcal{F}_x/\mathfrak m_s \mathcal{F}_x$ is the base change of the flat module $\mathcal{F}_x$ by $\mathcal{O}_{Y, y} \to \mathcal{O}_{Y, y}/\mathfrak m_s \mathcal{O}_{Y, y}$, hence flat by Algebra, Lemma Base change of flat modules (uncovered prerequisite).
By Morphisms, Lemma Finite presentation and finite algebras (uncovered prerequisite) the morphism $f$ is locally of finite presentation. Consider the set
$$U = \{x \in X \mid \mathcal{F} \text{ flat at }x \text{ over both }Y\text{ and }S\}.$$ This set is open in $X$ by Theorem Openness of the flat locus. Note that if $x \in U$, then $\mathcal{F}_s$ is flat at $x$ over $Y_s$ as a base change of a flat module under the morphism $Y_s \to Y$, see Morphisms, Lemma Base change for flatness and modules (uncovered prerequisite). Hence at every point of $U \cap \text{Supp}(\mathcal{F})$ condition (1) is satisfied. On the other hand, it is clear that if $x \in \text{Supp}(\mathcal{F})$ satisfies (1) and (2), then $x \in U$. Thus the open set we are looking for is $U \cap \text{Supp}(\mathcal{F})$. $\square$
Definition. Thickenings
Thickenings.
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We say a scheme $X'$ is a thickening of a scheme $X$ if $X$ is a closed subscheme of $X'$ and the underlying topological spaces are equal.
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We say a scheme $X'$ is a first order thickening of a scheme $X$ if $X$ is a closed subscheme of $X'$ and the quasi-coherent sheaf of ideals $\mathcal{I} \subset \mathcal{O}_{X'}$ defining $X$ has square zero.
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We say a scheme $X'$ is a finite order thickening of a scheme $X$ if $X$ is a closed subscheme of $X'$ and the quasi-coherent sheaf of ideals $\mathcal{I} \subset \mathcal{O}_{X'}$ defining $X$ is nilpotent, i.e., there exists an integer $n \geq 0$ such that $\mathcal{I}^{n + 1} = 0$.
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We say a scheme $X'$ is an $n$th order thickening of a scheme $X$ if $X$ is a closed subscheme of $X'$ and $\mathcal{I}^{n + 1} = 0$ where $\mathcal{I} \subset \mathcal{O}_{X'}$ is the quasi-coherent sheaf of ideals defining $X$.
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Given two thickenings $X \subset X'$ and $Y \subset Y'$ a morphism of thickenings is a morphism $f' : X' \to Y'$ such that $f'(X) \subset Y$, i.e., such that $f'|_X$ factors through the closed subscheme $Y$. In this situation we set $f = f'|_X : X \to Y$ and we say that $(f, f') : (X \subset X') \to (Y \subset Y')$ is a morphism of thickenings.
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Let $S$ be a scheme. We similarly define thickenings over $S$, and morphisms of thickenings over $S$. This means that the schemes $X, X', Y, Y'$ above are schemes over $S$, and that the morphisms $X \to X'$, $Y \to Y'$ and $f' : X' \to Y'$ are morphisms over $S$.
Lemma. Proper morphisms and nilpotent thickenings
Let $(f, f') : (X \subset X') \to (S \subset S')$ be a morphism of thickenings. Then
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$f$ is an affine morphism if and only if $f'$ is an affine morphism,
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$f$ is a surjective morphism if and only if $f'$ is a surjective morphism,
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$f$ is quasi-compact if and only if $f'$ quasi-compact,
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$f$ is universally closed if and only if $f'$ is universally closed,
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$f$ is integral if and only if $f'$ is integral,
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$f$ is (quasi-)separated if and only if $f'$ is (quasi-)separated,
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$f$ is universally injective if and only if $f'$ is universally injective,
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$f$ is universally open if and only if $f'$ is universally open,
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$f$ is quasi-affine if and only if $f'$ is quasi-affine, and
-
add more here.
Proof. Observe that $S \to S'$ and $X \to X'$ are universal homeomorphisms (see for example Morphisms, Lemma The geometric construction (uncovered prerequisite)). This immediately implies parts (2), (3), (4), (7), and (8). Part (1) follows from Lemma Affine neighbourhoods and nilpotent thickenings which tells us that there is a 1-to-1 correspondence between affine opens of $S$ and $S'$ and between affine opens of $X$ and $X'$. Part (9) follows from Limits, Lemma Affine neighbourhoods and nilpotent thickenings (uncovered prerequisite) and the remark just made about affine opens of $S$ and $S'$. Part (5) follows from (1) and (4) by Morphisms, Lemma Integral extensions (uncovered prerequisite). Finally, note that $$S \times_X S = S \times_{X'} S \to S \times_{X'} S' \to S' \times_{X'} S'$$ is a thickening (the two arrows are thickenings by Lemma Base change for nilpotent thickenings (uncovered prerequisite)). Hence applying (3) and (4) to the morphism $(S \subset S') \to (S \times_X S \to S' \times_{X'} S')$ we obtain (6). $\square$
Lemma. Base change for flatness
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of schemes over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Assume
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$X$ is locally of finite presentation over $S$,
-
$\mathcal{F}$ an $\mathcal{O}_X$-module of finite presentation,
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$\mathcal{F}$ is flat over $S$, and
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$Y$ is locally of finite type over $S$.
Then the set $$U = \{x \in X \mid \mathcal{F} \text{ flat at }x \text{ over }Y\}.$$ is open in $X$ and its formation commutes with arbitrary base change: If $S' \to S$ is a morphism of schemes, and $U'$ is the set of points of $X' = X \times_S S'$ where $\mathcal{F}' = \mathcal{F} \times_S S'$ is flat over $Y' = Y \times_S S'$, then $U' = U \times_S S'$.
Proof. By Morphisms, Lemma Finite presentation and finite algebras (uncovered prerequisite) the morphism $f$ is locally of finite presentation. Hence $U$ is open by Theorem Openness of the flat locus. Because we have assumed that $\mathcal{F}$ is flat over $S$ we see that Theorem Criteria for flatness implies $$U = \{x \in X \mid \mathcal{F}_s \text{ flat at }x \text{ over }Y_s\}.$$ where $s$ always denotes the image of $x$ in $S$. (This description also works trivially when $\mathcal{F}_x = 0$.) Moreover, the assumptions of the lemma remain in force for the morphism $f' : X' \to Y'$ and the sheaf $\mathcal{F}'$. Hence $U'$ has a similar description. In other words, it suffices to prove that given $s' \in S'$ mapping to $s \in S$ we have $$\{x' \in X'_{s'} \mid \mathcal{F}'_{s'} \text{ flat at }x' \text{ over }Y'_{s'}\}$$ is the inverse image of the corresponding locus in $X_s$. This is true by Lemma Base change for flatness because in the cartesian diagram $$\begin{gathered}\begin{matrix}X'_{s'} & X_s \\ Y'_{s'} & Y_s\end{matrix} \\[6pt] \begin{aligned}X'_{s'} & \longrightarrow Y'_{s'} \\ X'_{s'} & \longrightarrow X_s \\ X_s & \longrightarrow Y_s \\ Y'_{s'} & \longrightarrow Y_s\end{aligned}\end{gathered}$$ the horizontal morphisms are flat as they are base changes by the flat morphism $\operatorname{Spec}(\kappa(s')) \to \operatorname{Spec}(\kappa(s))$. $\square$
Lemma. Base change for dimension and codimension
Let $f : X \to Y$ be a morphism of finite type. Let $$n_{X/Y} : Y \to \{0, 1, 2, 3, \ldots, \infty\}$$ be the function which associates to $y \in Y$ the dimension of $X_y$. If $g : Y' \to Y$ is a morphism then $$n_{X'/Y'} = n_{X/Y} \circ g$$ where $X' \to Y'$ is the base change of $f$.
Proof. This follows from Morphisms, Lemma Base change for dimension and codimension (uncovered prerequisite). $\square$
Lemma. Flatness and dimension and codimension
Let $f : X \to Y$ be a flat morphism of schemes of finite presentation. Let $n_{X/Y}$ be the function on $Y$ giving the dimension of fibres of $f$ introduced in Lemma Base change for dimension and codimension. Then $n_{X/Y}$ is lower semi-continuous.
Proof. Let $W \subset X$, $W = \coprod_{d \geq 0} U_d$ be the open constructed in Lemmas Finite presentation and flatness (uncovered prerequisite) and Finite presentation and flatness (uncovered prerequisite). Let $y \in Y$ be a point. If $n_{X/Y}(y) = \dim(X_y) = n$, then $y$ is in the image of $U_n \to Y$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) we see that $f(U_n)$ is open in $Y$. Hence there is an open neighbourhood of $y$ where $n_{X/Y}$ is $\geq n$. $\square$
Lemma. Dimension, codimension and proper morphisms
Let $f : X \to Y$ be a proper morphism of schemes. Let $n_{X/Y}$ be the function on $Y$ giving the dimension of fibres of $f$ introduced in Lemma Base change for dimension and codimension. Then $n_{X/Y}$ is upper semi-continuous.
Proof. Let $Z_d = \{x \in X \mid \dim_x(X_{f(x)}) > d\}$. Then $Z_d$ is a closed subset of $X$ by Morphisms, Lemma Dimension and codimension (uncovered prerequisite). Since $f$ is proper $f(Z_d)$ is closed. Since $y \in f(Z_d) \Leftrightarrow n_{X/Y}(y) > d$ we see that the lemma is true. $\square$
Lemma. Finite algebras
Let $\pi : X \to Y$ be a finite morphism. Let $x \in X$ with $y = \pi(x)$ such that $\pi^{-1}(\{y\}) = \{x\}$. Then
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For every neighbourhood $U \subset X$ of $x$ in $X$, there exists a neighbourhood $V \subset Y$ of $y$ such that $\pi^{-1}(V) \subset U$.
-
The ring map $\mathcal{O}_{Y, y} \to \mathcal{O}_{X, x}$ is finite.
-
If $\pi$ is of finite presentation, then $\mathcal{O}_{Y, y} \to \mathcal{O}_{X, x}$ is of finite presentation.
-
For any quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ we have $\mathcal{F}_x = \pi_*\mathcal{F}_y$ as $\mathcal{O}_{Y, y}$-modules.
Proof. The first assertion is purely topological; use that $\pi$ is a continuous and closed map such that $\pi^{-1}(\{y\}) = \{x\}$. To prove the second and third parts we may assume $X = \operatorname{Spec}(B)$ and $Y = \operatorname{Spec}(A)$. Then $A \to B$ is a finite ring map and $y$ corresponds to a prime $\mathfrak p$ of $A$ such that there exists a unique prime $\mathfrak q$ of $B$ lying over $\mathfrak p$. Then $B_{\mathfrak q} = B_{\mathfrak p}$, see Algebra, Lemma Prime spectra, associated points and local algebra (uncovered prerequisite). In other words, the map $A_{\mathfrak p} \to B_{\mathfrak q}$ is equal to the map $A_{\mathfrak p} \to B_{\mathfrak p}$ you get from localizing $A \to B$ at $\mathfrak p$. Thus (2) and (3) follow from simple properties of localization (some details omitted). For the final statement, suppose that $\mathcal{F} = \widetilde M$ for some $B$-module $M$. Then $\mathcal{F} = M_{\mathfrak q}$ and $\pi_*\mathcal{F}_y = M_{\mathfrak p}$. By the above these localizations agree. Alternatively you can use part (1) and the definition of stalks to see that $\mathcal{F}_x = \pi_*\mathcal{F}_y$ directly. $\square$
Lemma. The geometric construction
Let $h : Y \to S$ be a morphism of schemes. Let $s \in S$ be a point. Let $T \subset Y_s$ be an open subscheme. Assume
-
$h$ is of finite presentation,
-
$h$ is normal, and
-
$T$ is geometrically irreducible over $\kappa(s)$.
Then we can find an affine elementary étale neighbourhood $(S', s') \to (S, s)$ and a quasi-compact open $V \subset Y_{S'}$ such that
-
all fibres of $V \to S'$ are geometrically integral,
-
$V_{s'} = T \times_s s'$.
Proof. Apply Lemma The geometric construction (uncovered prerequisite) to find an affine elementary étale neighbourhood $(S', s') \to (S, s)$ and a quasi-compact open $V \subset Y_{S'}$ such that all fibres of $V \to S'$ are geometrically connected and $V_{s'} = T \times_s s'$. As $V$ is an open of the base change of $h$ all fibres of $V \to S'$ are geometrically normal, see Lemma The geometric construction (uncovered prerequisite). In particular, they are geometrically reduced. To finish the proof we have to show they are geometrically irreducible. But, if $t \in S'$ then $V_t$ is of finite type over $\kappa(t)$ and hence $V_t \times_{\kappa(t)} \overline{\kappa(t)}$ is of finite type over $\overline{\kappa(t)}$ hence Noetherian. By choice of $S' \to S$ the scheme $V_t \times_{\kappa(t)} \overline{\kappa(t)}$ is connected. Hence $V_t \times_{\kappa(t)} \overline{\kappa(t)}$ is irreducible by Properties, Lemma Noetherian rings (uncovered prerequisite) and we win. $\square$
Lemma. Smoothness from lifting Artinian tests at a point
Let $f : X \to S$ be a morphism of schemes. Let $x \in X$. Assume that $S$ is locally Noetherian and $f$ locally of finite type. The following are equivalent:
-
$f$ is smooth at $x$,
-
for every solid commutative diagram $$\begin{gathered}\begin{matrix}X & \operatorname{Spec}(B) \\ S & \operatorname{Spec}(B')\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f} S \\ \operatorname{Spec}(B) & \xrightarrow{i} \operatorname{Spec}(B') \\ \operatorname{Spec}(B) & \xrightarrow{\alpha} X \\ \operatorname{Spec}(B') & \xrightarrow{\beta} S \\ \operatorname{Spec}(B') & \dashrightarrow X\end{aligned}\end{gathered}$$ where $B' \to B$ is a surjection of local rings with $\operatorname{Ker}(B' \to B)$ of square zero, and $\alpha$ mapping the closed point of $\operatorname{Spec}(B)$ to $x$ there exists a dotted arrow making the diagram commute,
-
same as in (2) but with $B' \to B$ ranging over small extensions (see Algebra, Definition Commutative algebra), and
-
same as in (2) but with $B' \to B$ ranging over small extensions such that $\alpha$ induces an isomorphism $\kappa(x) \to \kappa(\mathfrak m)$ where $\mathfrak m \subset B$ is the maximal ideal.
Proof. Choose an affine neighbourhood $V \subset S$ of $f(x)$ and choose an affine neighbourhood $U \subset X$ of $x$ such that $f(U) \subset V$. For any "test" diagram as in (2) the morphism $\alpha$ will map $\operatorname{Spec}(B)$ into $U$ and the morphism $\beta$ will map $\operatorname{Spec}(B')$ into $V$ (see Schemes, Section The geometric construction). Hence the lemma reduces to the morphism $f|_U : U \to V$ of affines. (Indeed, $V$ is Noetherian and $f|_U$ is of finite type, see Properties, Lemma Noetherian rings and local algebra (uncovered prerequisite) and Morphisms, Lemma Finite algebras and local algebra (uncovered prerequisite).) In this affine case the lemma is identical to Algebra, Lemma Smooth morphisms and Artinian rings (uncovered prerequisite). $\square$
[^1]: This means $Y \to S$ is pseudo-coherent, see Definition Pseudo-coherent complexes.
Étale thickenings and relative complexes
Definition. Pseudo-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $E$ be an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Fix $m \in \mathbf{Z}$.
-
We say $E$ is $m$-pseudo-coherent relative to $Y$ if the equivalent conditions of Lemma Pseudo-coherent complexes and quasi-coherent complexes are satisfied.
-
We say $E$ is pseudo-coherent relative to $Y$ if $E$ is $m$-pseudo-coherent relative to $Y$ for all $m \in \mathbf{Z}$.
-
We say $\mathcal{F}$ is $m$-pseudo-coherent relative to $Y$ if $\mathcal{F}$ viewed as an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ is $m$-pseudo-coherent relative to $Y$.
-
We say $\mathcal{F}$ is pseudo-coherent relative to $Y$ if $\mathcal{F}$ viewed as an object of $D_\mathrm{QCoh}(\mathcal{O}_X)$ is pseudo-coherent relative to $Y$.
Lemma. Nilpotent thickenings and groupoids and equivalence relations
Let $S$ be a scheme. Let $X \subset X'$ be a thickening of algebraic spaces over $S$. The functor $$V' \longmapsto V = X \times_{X'} V'$$ defines an equivalence of categories $X'_\mathrm{\acute{e}tale} \to X_\mathrm{\acute{e}tale}$.
Proof. The functor $V' \mapsto V$ defines an equivalence of categories $X'_{spaces, \mathrm{\acute{e}tale}} \to X_{spaces, \mathrm{\acute{e}tale}}$, see Theorem The geometric construction. Thus it suffices to show that $V$ is a scheme if and only if $V'$ is a scheme. This is the content of Lemma Nilpotent thickenings. $\square$
Lemma. Square-zero deformations and their comparison maps
Let $S$ be a scheme. Let $(f, f') : (X \subset X') \to (Y \subset Y')$ be a morphism of first order thickenings of algebraic spaces over $S$. Assume that $f$ is flat. Then the following are equivalent
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$f'$ is flat and $X = Y \times_{Y'} X'$, and
-
the canonical map $f^*\mathcal{C}_{Y/Y'} \to \mathcal{C}_{X/X'}$ is an isomorphism.
Proof. Choose a scheme $V'$ and a surjective étale morphism $V' \to Y'$. Choose a scheme $U'$ and a surjective étale morphism $U' \to X' \times_{Y'} V'$. Set $U = X \times_{X'} U'$ and $V = Y \times_{Y'} V'$. According to our definition of a flat morphism of algebraic spaces we see that the induced map $g : U \to V$ is a flat morphism of schemes and that $f'$ is flat if and only if the corresponding morphism $g' : U' \to V'$ is flat. Also, $X = Y \times_{Y'} X'$ if and only if $U = V \times_{V'} V'$. Finally, the map $f^*\mathcal{C}_{Y/Y'} \to \mathcal{C}_{X/X'}$ is an isomorphism if and only if $g^*\mathcal{C}_{V/V'} \to \mathcal{C}_{U/U'}$ is an isomorphism. Hence the lemma follows from its analogue for morphisms of schemes, see More on Morphisms, Lemma Square-zero deformations and their comparison maps. $\square$
Lemma. Nilpotent thickenings
Let $S$ be a scheme. Let $B$ be an algebraic space over $S$. Let $X \subset X'$ and $Y \subset Y'$ be thickenings of algebraic spaces over $B$. Let $f : X \to Y$ be a morphism of algebraic spaces over $B$. Given any map of $\mathcal{O}_B$-algebras $$\alpha : f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_{Y'} \to \mathcal{O}_{X'}$$ such that $$\begin{gathered}\begin{matrix}f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_Y & \mathcal{O}_X \\ f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_{Y'} & \mathcal{O}_{X'}\end{matrix} \\[6pt] \begin{aligned}f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_Y & \xrightarrow{f^\sharp} \mathcal{O}_X \\ f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_Y & \longrightarrow \mathcal{O}_X \\ f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_{Y'} & \xrightarrow{\alpha} \mathcal{O}_{X'} \\ f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_{Y'} & \xrightarrow{i_Y^\sharp} f_{spaces, \mathrm{\acute{e}tale}}^{-1}\mathcal{O}_Y \\ \mathcal{O}_{X'} & \xrightarrow{i_X^\sharp} \mathcal{O}_X\end{aligned}\end{gathered}$$ commutes, there exists a unique morphism of $(f, f')$ of thickenings over $B$ such that $\alpha = (f')^\sharp$.
Proof. To find $f'$, by Properties of Spaces, Theorem Étale geometry of algebraic spaces, all we have to do is show that the morphism of ringed topoi $$(f_{spaces, \mathrm{\acute{e}tale}}, \alpha) : (\operatorname{Sh}(X_{spaces, \mathrm{\acute{e}tale}}), \mathcal{O}_{X'}) \longrightarrow (\operatorname{Sh}(Y_{spaces, \mathrm{\acute{e}tale}}), \mathcal{O}_{Y'})$$ is a morphism of locally ringed topoi. This follows directly from the definition of morphisms of locally ringed topoi (Modules on Sites, Definition Morphisms of locally ringed topoi), the fact that $(f, f^\sharp)$ is a morphism of locally ringed topoi (Properties of Spaces, Lemma Local algebra), that $\alpha$ fits into the given commutative diagram, and the fact that the kernels of $i_X^\sharp$ and $i_Y^\sharp$ are locally nilpotent. Finally, the fact that $f' \circ i_X = i_Y \circ f$ follows from the commutativity of the diagram and another application of Properties of Spaces, Theorem Étale geometry of algebraic spaces. We omit the verification that $f'$ is a morphism over $B$. $\square$
Lemma. Nilpotent thickenings
Let $S$ be a scheme. Let $f : X \to B$ be a morphism of algebraic spaces over $S$. Consider a short exact sequence $$0 \to \mathcal{I} \to \mathcal{A} \to \mathcal{O}_X \to 0$$ of sheaves on $X_\mathrm{\acute{e}tale}$ where $\mathcal{A}$ is a sheaf of $f^{-1}\mathcal{O}_B$-algebras, $\mathcal{A} \to \mathcal{O}_X$ is a surjection of sheaves of $f^{-1}\mathcal{O}_B$-algebras, and $\mathcal{I}$ is its kernel. If
-
$\mathcal{I}$ is an ideal of square zero in $\mathcal{A}$, and
-
$\mathcal{I}$ is quasi-coherent as an $\mathcal{O}_X$-module
then there exists a first order thickening $X \subset X'$ over $B$ and an isomorphism $\mathcal{O}_{X'} \to \mathcal{A}$ of $f^{-1}\mathcal{O}_B$-algebras compatible with the surjections to $\mathcal{O}_X$.
Proof. In this proof we redo some of the arguments used in the proofs of Lemmas Nilpotent thickenings and Nilpotent thickenings. We first handle the case $B = S = \operatorname{Spec}(\mathbf{Z})$. Let $U$ be an affine scheme, and let $U \to X$ be étale. Then $$0 \to \mathcal{I}(U) \to \mathcal{A}(U) \to \mathcal{O}_X(U) \to 0$$ is exact as $H^1(U_\mathrm{\acute{e}tale}, \mathcal{I}) = 0$ as $\mathcal{I}$ is quasi-coherent, see Descent, Proposition Quasi-coherent complexes and sheaf cohomology and Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). If $V \to U$ is a morphism of affine objects of $X_{spaces, \mathrm{\acute{e}tale}}$ then $$\mathcal{I}(V) = \mathcal{I}(U) \otimes_{\mathcal{O}_X(U)} \mathcal{O}_X(V)$$ since $\mathcal{I}$ is a quasi-coherent $\mathcal{O}_X$-module, see Descent, Proposition Quasi-coherent complexes and coherent sheaves. Hence $\mathcal{A}(U) \to \mathcal{A}(V)$ is an étale ring map, see Algebra, Lemma Lifting étale morphisms and finite algebras. Hence we see that $$U \longmapsto U' = \operatorname{Spec}(\mathcal{A}(U))$$ is a functor from $X_{affine, \mathrm{\acute{e}tale}}$ to the category of affine schemes and étale morphisms. In fact, we claim that this functor can be extended to a functor $U \mapsto U'$ on all of $X_\mathrm{\acute{e}tale}$. To see this, if $U$ is an object of $X_\mathrm{\acute{e}tale}$, note that $$0 \to \mathcal{I}|_{U_{Zar}} \to \mathcal{A}|_{U_{Zar}} \to \mathcal{O}_X|_{U_{Zar}} \to 0$$ and $\mathcal{I}|_{U_{Zar}}$ is a quasi-coherent sheaf on $U$, see Descent, Proposition Quasi-coherent complexes and coherent sheaves. Hence by More on Morphisms, Lemma Nilpotent thickenings we obtain a first order thickening $U \subset U'$ of schemes such that $\mathcal{O}_{U'}$ is isomorphic to $\mathcal{A}|_{U_{Zar}}$. It is clear that this construction is compatible with the construction for affines above.
Choose a presentation $X = U/R$, see Spaces, Definition The geometric construction so that $s, t : R \to U$ define an étale equivalence relation. Applying the functor above we obtain an étale equivalence relation $s', t' : R' \to U'$ in schemes. Consider the algebraic space $X' = U'/R'$ (see Spaces, Theorem The geometric construction (uncovered prerequisite)). The morphism $X = U/R \to U'/R' = X'$ is a first order thickening. Consider $\mathcal{O}_{X'}$ viewed as a sheaf on $X_\mathrm{\acute{e}tale}$. By construction we have an isomorphism $$\gamma : \mathcal{O}_{X'}|_{U_\mathrm{\acute{e}tale}} \longrightarrow \mathcal{A}|_{U_\mathrm{\acute{e}tale}}$$ such that $s^{-1}\gamma$ agrees with $t^{-1}\gamma$ on $R_\mathrm{\acute{e}tale}$. Hence by Properties of Spaces, Lemma Descent of sheaves on ringed sites this implies that $\gamma$ comes from a unique isomorphism $\mathcal{O}_{X'} \to \mathcal{A}$ as desired.
To handle the case of a general base algebraic space $B$, we first construct $X'$ as an algebraic space over $\mathbf{Z}$ as above. Then we use the isomorphism $\mathcal{O}_{X'} \to \mathcal{A}$ to define $f^{-1}\mathcal{O}_B \to \mathcal{O}_{X'}$. According to Lemma Nilpotent thickenings this defines a morphism $X' \to B$ compatible with the given morphism $X \to B$ and we are done. $\square$
Lemma. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The cohomology sheaves of the complex $\mathrm{NL}_{X/Y}$ are quasi-coherent, zero outside degrees $-1$, $0$ and equal to $\Omega_{X/Y}$ in degree $0$.
Proof. By construction of the naive cotangent complex in Modules on Sites, Section The naive cotangent complex we have that $\mathrm{NL}_{X/Y}$ is a complex sitting in degrees $-1$, $0$ and that its cohomology in degree $0$ is $\Omega_{X/Y}$ (by our construction of $\Omega_{X/Y}$ in Section Cotangent complexes, differentials and sheaves on ringed sites). The sheaf of differentials is quasi-coherent (by Lemma Cotangent complexes, differentials and quasi-coherent complexes). To finish the proof it suffices to show that $H^{-1}(\mathrm{NL}_{X/Y})$ is quasi-coherent. This follows by checking étale locally (allowed by Lemma Cotangent complexes, differentials and étale morphisms and Properties of Spaces, Lemma Criteria for quasi-coherent complexes and coherent sheaves) reducing to the case of schemes (Lemma Cotangent complexes and differentials) and finally using the result in the case of schemes (More on Morphisms, Lemma Quasi-coherent complexes and coherent sheaves). $\square$
Lemma. Proper morphisms and nilpotent thickenings
Let $S$ be a scheme. Let $(f, f') : (X \subset X') \to (Y \subset Y')$ be a morphism of thickenings of algebraic spaces over $S$ such that $X = Y \times_{Y'} X'$. If $X \subset X'$ is a finite order thickening, then
-
$f$ is a closed immersion if and only if $f'$ is a closed immersion,
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$f$ is locally of finite type if and only if $f'$ is locally of finite type,
-
$f$ is locally quasi-finite if and only if $f'$ is locally quasi-finite,
-
$f$ is locally of finite type of relative dimension $d$ if and only if $f'$ is locally of finite type of relative dimension $d$,
-
$\Omega_{X/Y} = 0$ if and only if $\Omega_{X'/Y'} = 0$,
-
$f$ is unramified if and only if $f'$ is unramified,
-
$f$ is proper if and only if $f'$ is proper,
-
$f$ is a finite morphism if and only if $f'$ is an finite morphism,
-
$f$ is a monomorphism if and only if $f'$ is a monomorphism,
-
$f$ is an immersion if and only if $f'$ is an immersion, and
-
add more here.
Proof. Choose a scheme $V'$ and a surjective étale morphism $V' \to Y'$. Choose a scheme $U'$ and a surjective étale morphism $U' \to X' \times_{Y'} V'$. Set $V = Y \times_{Y'} V'$ and $U = X \times_{X'} U'$. Then for étale local properties of morphisms we can reduce to the morphism of thickenings of schemes $(U \subset U') \to (V \subset V')$ and apply More on Morphisms, Lemma Proper morphisms and nilpotent thickenings. This proves (2), (3), (4), (5), and (6).
The properties of morphisms in (1), (7), (8), (9), (10) are stable under base change, hence if $f'$ has property $\mathcal{P}$, then so does $f$. See Spaces, Lemma Base change for diagonals and separation (uncovered prerequisite), and Morphisms of Spaces, Lemmas Base change for proper morphisms, Base change for integral extensions, and Base change for morphisms of algebraic spaces.
The interesting direction in (1), (7), (8), (9), (10) is to assume that $f$ has the property and deduce that $f'$ has it too. By induction on the order of the thickening we may assume that $Y \subset Y'$ is a first order thickening, see discussion on finite order thickenings above.
Proof of (1). Choose a scheme $V'$ and a surjective étale morphism $V' \to Y'$. Set $V = Y \times_{Y'} V'$, $U' = X' \times_{Y'} V'$ and $U = X \times_Y V$. Then $U \to V$ is a closed immersion, which implies that $U$ is a scheme, which in turn implies that $U'$ is a scheme (Lemma Nilpotent thickenings). Thus we can apply the lemma in the case of schemes (More on Morphisms, Lemma Proper morphisms and nilpotent thickenings) to $(U \subset U') \to (V \subset V')$ to conclude.
Proof of (7). Follows by combining (2) with results of Lemma Proper morphisms and nilpotent thickenings and the fact that proper equals quasi-compact $+$ separated $+$ locally of finite type $+$ universally closed.
Proof of (8). Follows by combining (2) with results of Lemma Proper morphisms and nilpotent thickenings and using the fact that finite equals integral $+$ locally of finite type (Morphisms, Lemma Integral extensions and finite algebras (uncovered prerequisite)).
Proof of (9). As $f$ is a monomorphism we have $X = X \times_Y X$. We may apply the results proved so far to the morphism of thickenings $(X \subset X') \to (X \times_Y X \subset X' \times_{Y'} X')$. We conclude $X' \to X' \times_{Y'} X'$ is a closed immersion by (1). In fact, it is a first order thickening as the ideal defining the closed immersion $X' \to X' \times_{Y'} X'$ is contained in the pullback of the ideal $\mathcal{I} \subset \mathcal{O}_{Y'}$ cutting out $Y$ in $Y'$. Indeed, $X = X \times_Y X = (X' \times_{Y'} X') \times_{Y'} Y$ is contained in $X'$. The conormal sheaf of the closed immersion $\Delta : X' \to X' \times_{Y'} X'$ is equal to $\Omega_{X'/Y'}$ (this is the analogue of Morphisms, Lemma Cotangent complexes, differentials and diagonals and separation (uncovered prerequisite) for algebraic spaces and follows either by étale localization or by combining Lemmas Cotangent complexes, differentials and diagonals and separation and Cotangent complexes, differentials and tensor products and direct sums; some details omitted). Thus it suffices to show that $\Omega_{X'/Y'} = 0$ which follows from (5) and the corresponding statement for $X/Y$.
Proof of (10). If $f : X \to Y$ is an immersion, then it factors as $X \to V \to Y$ where $V \to Y$ is an open subspace and $X \to V$ is a closed immersion, see Morphisms of Spaces, Remark Diagonals and separation. Let $V' \subset Y'$ be the open subspace whose underlying topological space $|V'|$ is the same as $|V| \subset |Y| = |Y'|$. Then $X' \to Y'$ factors through $V'$ and we conclude that $X' \to V'$ is a closed immersion by part (1). This finishes the proof. $\square$
Lemma. Finite presentation from a finite-type flat family
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. If $f$ is locally of finite presentation, then $\mathrm{NL}_{X/Y}$ is étale locally on $X$ quasi-isomorphic to a complex $$\ldots \to 0 \to \mathcal{F}^{-1} \to \mathcal{F}^0 \to 0 \to \ldots$$ of quasi-coherent $\mathcal{O}_X$-modules with $\mathcal{F}^0$ of finite presentation and $\mathcal{F}^{-1}$ of finite type.
Proof. Formation of the naive cotangent complex commutes with étale localization by Lemma Cotangent complexes, differentials and étale morphisms. This reduces us to the case of schemes by Lemma Cotangent complexes and differentials. The result in the case of schemes is More on Morphisms, Lemma Finite presentation from a finite-type flat family. $\square$
Lemma. Properties preserved under a square-zero deformation
Let $S$ be a scheme. Consider a commutative diagram $$\begin{gathered}\begin{matrix}(X \subset X') & \phantom{X} & (Y \subset Y') \\ \phantom{X} & (B \subset B')\end{matrix} \\[6pt] \begin{aligned}(X \subset X') & \xrightarrow{(f, f')} (Y \subset Y') \\ (X \subset X') & \longrightarrow (B \subset B') \\ (Y \subset Y') & \longrightarrow (B \subset B')\end{aligned}\end{gathered}$$ of thickenings of algebraic spaces over $S$. Assume $B \subset B'$ is a finite order thickening, $X'$ flat over $B'$, $X = B \times_{B'} X'$, and $Y = B \times_{B'} Y'$. Then
-
$f$ is representable if and only if $f'$ is representable,
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$f$ is flat if and only if $f'$ is flat,
-
$f$ is an isomorphism if and only if $f'$ is an isomorphism,
-
$f$ is an open immersion if and only if $f'$ is an open immersion,
-
$f$ is quasi-compact if and only if $f'$ is quasi-compact,
-
$f$ is universally closed if and only if $f'$ is universally closed,
-
$f$ is (quasi-)separated if and only if $f'$ is (quasi-)separated,
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$f$ is a monomorphism if and only if $f'$ is a monomorphism,
-
$f$ is surjective if and only if $f'$ is surjective,
-
$f$ is universally injective if and only if $f'$ is universally injective,
-
$f$ is affine if and only if $f'$ is affine,
$f$ is locally of finite type if and only if $f'$ is locally of finite type,
-
$f$ is locally quasi-finite if and only if $f'$ is locally quasi-finite,
-
$f$ is locally of finite presentation if and only if $f'$ is locally of finite presentation,
$f$ is locally of finite type of relative dimension $d$ if and only if $f'$ is locally of finite type of relative dimension $d$,
-
$f$ is universally open if and only if $f'$ is universally open,
-
$f$ is syntomic if and only if $f'$ is syntomic,
-
$f$ is smooth if and only if $f'$ is smooth,
-
$f$ is unramified if and only if $f'$ is unramified,
-
$f$ is étale if and only if $f'$ is étale,
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$f$ is proper if and only if $f'$ is proper,
-
$f$ is integral if and only if $f'$ is integral,
-
$f$ is finite if and only if $f'$ is finite,
-
$f$ is finite locally free (of rank $d$) if and only if $f'$ is finite locally free (of rank $d$), and
-
add more here.
Proof. Case (the indicated step) follows from Lemma Proper morphisms and nilpotent thickenings.
Choose a scheme $U'$ and a surjective étale morphism $U' \to B'$. Choose a scheme $V'$ and a surjective étale morphism $V' \to U' \times_{B'} Y'$. Choose a scheme $W'$ and a surjective étale morphism $W' \to V' \times_{Y'} X'$. Let $U, V, W$ be the base change of $U', V', W'$ by $B \to B'$. Consider the diagram $$\begin{gathered}\begin{matrix}(W \subset W') & \phantom{X} & (V \subset V') \\ \phantom{X} & (U \subset U')\end{matrix} \\[6pt] \begin{aligned}(W \subset W') & \longrightarrow (V \subset V') \\ (W \subset W') & \longrightarrow (U \subset U') \\ (V \subset V') & \longrightarrow (U \subset U')\end{aligned}\end{gathered}$$ of thickenings of schemes. For any of the properties which are étale local on the source-and-target the result follows immediately from the corresponding result for morphisms of thickenings of schemes applied to the diagram above. Thus cases (the indicated step), (the indicated step), (the indicated step), (the indicated step), (the indicated step), (the indicated step), (the indicated step), (the indicated step), (the indicated step) follow from the corresponding cases of More on Morphisms, Lemma Properties preserved under a square-zero deformation.
Since $X \to X'$ and $Y \to Y'$ are universal homeomorphisms we see that any question about the topology of the maps $X \to Y$ and $X' \to Y'$ has the same answer. Thus we see that cases (the indicated step), (the indicated step), (the indicated step), (the indicated step), and (the indicated step) hold.
In each of the remaining cases we only prove the implication $f\text{ has }P \Rightarrow f'\text{ has }P$ since the other implication follows from the fact that $P$ is stable under base change, see Spaces, Lemma Base change for diagonals and separation (uncovered prerequisite) and Morphisms of Spaces, Lemmas Base change for diagonals and separation, Base change for morphisms of algebraic spaces, Base change for affine neighbourhoods, Base change for proper morphisms, Base change for integral extensions, and Base change for projective, locally free modules and finite algebras.
The case (the indicated step). Assume $f$ is an open immersion. Then $f'$ is étale by (the indicated step) and universally injective by (the indicated step) hence $f'$ is an open immersion, see Morphisms of Spaces, Lemma Étale morphisms and injective resolutions. You can avoid using this lemma at the cost of first using (the indicated step) to reduce to the case of schemes.
The case (the indicated step). Follows from cases (the indicated step) and (the indicated step).
The case (the indicated step). See Lemma Proper morphisms and nilpotent thickenings.
The case (the indicated step). Assume $f$ is a monomorphism. Consider the diagonal morphism $\Delta_{X'/Y'} : X' \to X' \times_{Y'} X'$. The base change of $\Delta_{X'/Y'}$ by $B \to B'$ is $\Delta_{X/Y}$ which is an isomorphism by assumption. By (the indicated step) we conclude that $\Delta_{X'/Y'}$ is an isomorphism and hence $f'$ is a monomorphism.
The case (the indicated step). See Lemma Proper morphisms and nilpotent thickenings.
The case (the indicated step). See Lemma Proper morphisms and nilpotent thickenings.
The case (the indicated step). See Lemma Proper morphisms and nilpotent thickenings.
The case (the indicated step). See Lemma Proper morphisms and nilpotent thickenings.
The case (the indicated step). Assume $f$ finite locally free. By (the indicated step) we see that $f'$ is finite. By (the indicated step) we see that $f'$ is flat. By (the indicated step) $f'$ is locally of finite presentation. Hence $f'$ is finite locally free by Morphisms of Spaces, Lemma Flatness and finite algebras. $\square$
Lemma. Pseudo-coherent complexes and quasi-coherent complexes
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$ which is locally of finite type. Let $m \in \mathbf{Z}$. Let $E \in D_\mathrm{QCoh}(\mathcal{O}_X)$. With notation as explained in Remark Pseudo-coherent complexes and coherent sheaves the following are equivalent:
-
for every commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U$, $V$ are schemes and the vertical arrows are étale, the complex $E|_U$ is $m$-pseudo-coherent relative to $V$,
-
for some commutative diagram as in (1) with $U \to X$ surjective, the complex $E|_U$ is $m$-pseudo-coherent relative to $V$,
-
for every commutative diagram as in (1) with $U$ and $V$ affine the complex $R\Gamma(U, E)$ of $\mathcal{O}_X(U)$-modules is $m$-pseudo-coherent relative to $\mathcal{O}_Y(V)$.
Proof. Part (1) implies (3) by More on Morphisms, Lemma Pseudo-coherent complexes and quasi-coherent complexes (uncovered prerequisite).
Assume (3). Pick any commutative diagram as in (1) with $U \to X$ surjective. Choose an affine open covering $V = \bigcup V_j$ and affine open coverings $(U \to V)^{-1}(V_j) = \bigcup U_{ij}$. By (3) and More on Morphisms, Lemma Pseudo-coherent complexes and quasi-coherent complexes (uncovered prerequisite) we see that $E|_U$ is $m$-pseudo-coherent relative to $V$. Thus (3) implies (2).
Assume (2). Choose a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \longrightarrow V \\ V & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ where $U$, $V$ are schemes, the vertical arrows are étale, the morphism $U \to X$ is surjective, and $E|_U$ is $m$-pseudo-coherent relative to $V$. Next, suppose given a second commutative diagram $$\begin{gathered}\begin{matrix}U' & V' \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U' & \longrightarrow X \\ U' & \longrightarrow V' \\ V' & \longrightarrow Y \\ X & \longrightarrow Y\end{aligned}\end{gathered}$$ with étale vertical arrows and $U', V'$ schemes. We want to show that $E|_{U'}$ is $m$-pseudo-coherent relative to $V'$. The morphism $U'' = U \times_X U' \to U'$ is surjective étale and $U'' \to V'$ factors through $V'' = V' \times_Y V$ which is étale over $V'$. Hence it suffices to show that $E|_{U''}$ is $m$-pseudo-coherent relative to $V''$, see More on Morphisms, Lemmas Pseudo-coherent complexes and coherent sheaves (uncovered prerequisite) and Pseudo-coherent complexes and coherent sheaves (uncovered prerequisite). Using the second lemma once more it suffices to show that $E|_{U''}$ is $m$-pseudo-coherent relative to $V$. This is true by More on Morphisms, Lemma Pullback of pseudo-coherent complexes and coherent sheaves (uncovered prerequisite) and the fact that an étale morphism of schemes is pseudo-coherent by More on Morphisms, Lemma Pseudo-coherent complexes and finite presentation (uncovered prerequisite). $\square$
Theorem. The geometric construction
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume $f$ is integral, universally injective and surjective. The functor $$V \longmapsto V_X = X \times_Y V$$ defines an equivalence of categories $Y_{spaces, \mathrm{\acute{e}tale}} \to X_{spaces, \mathrm{\acute{e}tale}}$.
Proof. The morphism $f$ is representable and a universal homeomorphism, see Morphisms of Spaces, Section Morphisms of algebraic spaces.
We first prove that the functor is faithful. Suppose that $V', V$ are objects of $Y_{spaces, \mathrm{\acute{e}tale}}$ and that $a, b : V' \to V$ are distinct morphisms over $Y$. Since $V', V$ are étale over $Y$ the equalizer $$E = V' \times_{(a, b), V \times_Y V, \Delta_{V/Y}} V$$ of $a, b$ is étale over $Y$ also. Hence $E \to V'$ is an étale monomorphism (i.e., an open immersion) which is an isomorphism if and only if it is surjective. Since $X \to Y$ is a universal homeomorphism we see that this is the case if and only if $E_X = V'_X$, i.e., if and only if $a_X = b_X$.
Next, we prove that the functor is fully faithful. Suppose that $V', V$ are objects of $Y_{spaces, \mathrm{\acute{e}tale}}$ and that $c : V'_X \to V_X$ is a morphism over $X$. We want to construct a morphism $a : V' \to V$ over $Y$ such that $a_X = c$. Let $a' : V'' \to V'$ be a surjective étale morphism such that $V''$ is a separated algebraic space. If we can construct a morphism $a'' : V'' \to V$ such that $a''_X = c \circ a'_X$, then the two compositions $$V'' \times_{V'} V'' \xrightarrow{\text{pr}_i} V'' \xrightarrow{a''} V$$ will be equal by the faithfulness of the functor proved in the first paragraph. Hence $a''$ will factor through a unique morphism $a : V' \to V$ as $V'$ is (as a sheaf) the quotient of $V''$ by the equivalence relation $V'' \times_{V'} V''$. Hence we may assume that $V'$ is separated. In this case the graph $$\Gamma_c \subset (V' \times_Y V)_X$$ is open and closed (details omitted). Since $X \to Y$ is a universal homeomorphism, there exists an open and closed subspace $\Gamma \subset V' \times_Y V$ such that $\Gamma_X = \Gamma_c$. The projection $\Gamma \to V'$ is an étale morphism whose base change to $X$ is an isomorphism. Hence $\Gamma \to V'$ is étale, universally injective, and surjective, so an isomorphism by Morphisms of Spaces, Lemma Étale morphisms and injective resolutions. Thus $\Gamma$ is the graph of a morphism $a : V' \to V$ as desired.
Finally, we prove that the functor is essentially surjective. Suppose that $U$ is an object of $X_{spaces, \mathrm{\acute{e}tale}}$. We have to find an object $V$ of $Y_{spaces, \mathrm{\acute{e}tale}}$ such that $V_X \cong U$. Let $U' \to U$ be a surjective étale morphism such that $U' \cong V'_X$ and $U' \times_U U' \cong V''_X$ for some objects $V'', V'$ of $Y_{spaces, \mathrm{\acute{e}tale}}$. Then by fully faithfulness of the functor we obtain morphisms $s, t : V'' \to V'$ with $t_X = \text{pr}_0$ and $s_X = \text{pr}_1$ as morphisms $U' \times_U U' \to U'$. Using that $(\text{pr}_0, \text{pr}_1) : U' \times_U U' \to U' \times_S U'$ is an étale equivalence relation, and that $U' \to V'$ and $U' \times_U U' \to V''$ are universally injective and surjective we deduce that $(t, s) : V'' \to V' \times_S V'$ is an étale equivalence relation. Then the quotient $V = V'/V''$ (see Spaces, Theorem The geometric construction (uncovered prerequisite)) is an algebraic space $V$ over $Y$. There is a morphism $V' \to V$ such that $V'' = V' \times_V V'$. Thus we obtain a morphism $V \to Y$ (see Descent on Spaces, Lemma The geometric construction (uncovered prerequisite)). On base change to $X$ we see that we have a morphism $U' \to V_X$ and a compatible isomorphism $U' \times_{V_X} U' = U' \times_U U'$, which implies that $V_X \cong U$ (by the lemma just cited once more).
Pick a scheme $W$ and a surjective étale morphism $W \to Y$. Pick a scheme $U'$ and a surjective étale morphism $U' \to U \times_X W_X$. Note that $U'$ and $U' \times_U U'$ are schemes étale over $X$ whose structure morphism to $X$ factors through the scheme $W_X$. Hence by Étale Cohomology, Theorem The geometric construction (uncovered prerequisite) there exist schemes $V', V''$ étale over $W$ whose base change to $W_X$ is isomorphic to respectively $U'$ and $U' \times_U U'$. This finishes the proof. $\square$
Lemma. Nilpotent thickenings
Let $S$ be a scheme. Let $X \subset X'$ be a thickening of algebraic spaces over $S$. If $X$ is (representable by) a scheme, then so is $X'$.
Proof. Note that $X'_{red} = X_{red}$. Hence if $X$ is a scheme, then $X'_{red}$ is a scheme. Thus the result follows from Limits of Spaces, Lemma Descent of algebraic spaces (uncovered prerequisite). Below we give a direct proof for finite order thickenings which is the case most often used in practice. $\square$
Proof for finite order thickenings. It suffices to prove this when $X'$ is a first order thickening of $X$. By Properties of Spaces, Lemma Étale geometry of algebraic spaces there is a largest open subspace of $X'$ which is a scheme. Thus we have to show that every point $x$ of $|X'| = |X|$ is contained in an open subspace of $X'$ which is a scheme. Using Lemma Nilpotent thickenings (uncovered prerequisite) we may replace $X \subset X'$ by $U \subset U'$ with $x \in U$ and $U$ an affine scheme. Hence we may assume that $X$ is affine. Thus we reduce to the case discussed in the next paragraph.
Assume $X \subset X'$ is a first order thickening where $X$ is an affine scheme. Set $A = \Gamma(X, \mathcal{O}_X)$ and $A' = \Gamma(X', \mathcal{O}_{X'})$. By Lemma Nilpotent thickenings the map $A' \to A$ is surjective. The kernel $I$ is an ideal of square zero. By Properties of Spaces, Lemma Affine neighbourhoods (uncovered prerequisite) we obtain a canonical morphism $f : X' \to \operatorname{Spec}(A')$ which fits into the following commutative diagram $$\begin{gathered}\begin{matrix}X & X' \\ \operatorname{Spec}(A) & \operatorname{Spec}(A')\end{matrix} \\[6pt] \begin{aligned}X & \mathrel{=} \operatorname{Spec}(A) \\ X & \longrightarrow X' \\ X' & \xrightarrow{f} \operatorname{Spec}(A') \\ \operatorname{Spec}(A) & \longrightarrow \operatorname{Spec}(A')\end{aligned}\end{gathered}$$ Because the horizontal arrows are thickenings it is clear that $f$ is universally injective and surjective. Hence it suffices to show that $f$ is étale, since then Morphisms of Spaces, Lemma Étale morphisms and injective resolutions will imply that $f$ is an isomorphism.
To prove that $f$ is étale choose an affine scheme $U'$ and an étale morphism $U' \to X'$. It suffices to show that $U' \to X' \to \operatorname{Spec}(A')$ is étale, see Properties of Spaces, Definition Étale ring maps. Write $U' = \operatorname{Spec}(B')$. Set $U = X \times_{X'} U'$. Since $U$ is a closed subspace of $U'$, it is a closed subscheme, hence $U = \operatorname{Spec}(B)$ with $B' \to B$ surjective. Denote $J = \operatorname{Ker}(B' \to B)$ and note that $J = \Gamma(U, \mathcal{I})$ where $\mathcal{I} = \operatorname{Ker}(\mathcal{O}_{X'} \to \mathcal{O}_X)$ on $X_{spaces, \mathrm{\acute{e}tale}}$ as in the proof of Lemma Nilpotent thickenings. The morphism $U' \to X' \to \operatorname{Spec}(A')$ induces a commutative diagram $$\begin{gathered}\begin{matrix}0 & J & B' & B & 0 \\ 0 & I & A' & A & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow J \\ J & \longrightarrow B' \\ B' & \longrightarrow B \\ B & \longrightarrow 0 \\ 0 & \longrightarrow I \\ I & \longrightarrow A' \\ I & \longrightarrow J \\ A' & \longrightarrow A \\ A' & \longrightarrow B' \\ A & \longrightarrow 0 \\ A & \longrightarrow B\end{aligned}\end{gathered}$$ Now, since $\mathcal{I}$ is a quasi-coherent $\mathcal{O}_X$-module we have $\mathcal{I} = (\widetilde I)^a$, see Descent, Definition The structure sheaf on the descent site for notation and Descent, Proposition Quasi-coherent complexes and coherent sheaves for why this is true. Hence we see that $J = I \otimes_A B$. Finally, note that $A \to B$ is étale as $U \to X$ is étale as the base change of the étale morphism $U' \to X'$. We conclude that $A' \to B'$ is étale by Algebra, Lemma Lifting étale morphisms and finite algebras. $\square$
Lemma. Nilpotent thickenings
Let $S$ be a scheme. Let $X \subset X'$ be a thickening of algebraic spaces over $S$. Let $U$ be an affine object of $X_{spaces, \mathrm{\acute{e}tale}}$. Then $$\Gamma(U, \mathcal{O}_{X'}) \to \Gamma(U, \mathcal{O}_X)$$ is surjective where we think of $\mathcal{O}_{X'}$ as a sheaf on $X_{spaces, \mathrm{\acute{e}tale}}$ via (Groupoids and equivalence relations).
Proof. Let $U' \to X'$ be the étale morphism of algebraic spaces such that $U = X \times_{X'} U'$, see Theorem The geometric construction. By Limits of Spaces, Lemma Affine neighbourhoods (uncovered prerequisite) we see that $U'$ is an affine scheme. Hence $\Gamma(U, \mathcal{O}_{X'}) = \Gamma(U', \mathcal{O}_{U'}) \to \Gamma(U, \mathcal{O}_U)$ is surjective as $U \to U'$ is a closed immersion of affine schemes. Below we give a direct proof for finite order thickenings which is the case most used in practice. $\square$
Proof for finite order thickenings. We may assume that $X \subset X'$ is a first order thickening by the principle explained above. Denote $\mathcal{I}$ the kernel of the surjection $\mathcal{O}_{X'} \to \mathcal{O}_X$. As $\mathcal{I}$ is a quasi-coherent $\mathcal{O}_{X'}$-module and since $\mathcal{I}^2 = 0$ by the definition of a first order thickening we may apply Morphisms of Spaces, Lemma Groupoids and equivalence relations to see that $\mathcal{I}$ is a quasi-coherent $\mathcal{O}_X$-module. Hence the lemma follows from the long exact cohomology sequence associated to the short exact sequence $$0 \to \mathcal{I} \to \mathcal{O}_{X'} \to \mathcal{O}_X \to 0$$ and the fact that $H^1_\mathrm{\acute{e}tale}(U, \mathcal{I}) = 0$ as $\mathcal{I}$ is quasi-coherent, see Descent, Proposition Quasi-coherent complexes and sheaf cohomology and Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). $\square$
Lemma. Cotangent complexes, differentials and quasi-coherent complexes
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Then $\Omega_{X/Y}$ is a quasi-coherent $\mathcal{O}_X$-module.
Proof. Choose a diagram as in Lemma Localization of cotangent complexes, differentials and local algebra (uncovered prerequisite) with $a$ and $b$ surjective and $U$ and $V$ schemes. Then we see that $\Omega_{X/Y}|_U = \Omega_{U/V}$ which is quasi-coherent (for example by Morphisms, Lemma Cotangent complexes, differentials and diagonals and separation (uncovered prerequisite)). Hence we conclude that $\Omega_{X/Y}$ is quasi-coherent by Properties of Spaces, Lemma Criteria for quasi-coherent complexes and coherent sheaves. $\square$
Lemma. Cotangent complexes, differentials and étale morphisms
Let $S$ be a scheme. Consider a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \xrightarrow{p} X \\ U & \xrightarrow{g} V \\ V & \xrightarrow{q} Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ of algebraic spaces over $S$ with $p$ and $q$ étale. Then there is a canonical identification $\mathrm{NL}_{X/Y}|_{U_\mathrm{\acute{e}tale}} = \mathrm{NL}_{U/V}$ in $D(\mathcal{O}_U)$.
Proof. Formation of the naive cotangent complex commutes with pullback (Modules on Sites, Lemma Pullback of cotangent complexes and differentials (uncovered prerequisite)) and we have $p_{small}^{-1}\mathcal{O}_X = \mathcal{O}_U$ and $g_{small}^{-1}\mathcal{O}_{V_\mathrm{\acute{e}tale}} = p_{small}^{-1}f_{small}^{-1}\mathcal{O}_{Y_\mathrm{\acute{e}tale}}$ because $q_{small}^{-1}\mathcal{O}_{Y_\mathrm{\acute{e}tale}} = \mathcal{O}_{V_\mathrm{\acute{e}tale}}$ by Properties of Spaces, Lemma Étale morphisms (uncovered prerequisite). Tracing through the definitions we conclude that $\mathrm{NL}_{X/Y}|_{U_\mathrm{\acute{e}tale}} = \mathrm{NL}_{U/V}$. $\square$
Lemma. Cotangent complexes and differentials
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume $X$ and $Y$ representable by schemes $X_0$ and $Y_0$. Then there is a canonical identification $\mathrm{NL}_{X/Y} = \epsilon^*\mathrm{NL}_{X_0/Y_0}$ in $D(\mathcal{O}_X)$ where $\epsilon$ is as in Derived Categories of Spaces, Section Étale morphisms and quasi-coherent complexes and $\mathrm{NL}_{X_0/Y_0}$ is as in More on Morphisms, Definition The geometric construction.
Proof. Let $f_0 : X_0 \to Y_0$ be the morphism of schemes corresponding to $f$. There is a canonical map $\epsilon^{-1}f_0^{-1}\mathcal{O}_{Y_0} \to f_{small}^{-1}\mathcal{O}_Y$ compatible with $\epsilon^\sharp : \epsilon^{-1}\mathcal{O}_{X_0} \to \mathcal{O}_X$ because there is a commutative diagram $$\begin{gathered}\begin{matrix}X_{0, Zar} & X_\mathrm{\acute{e}tale} \\ Y_{0, Zar} & Y_\mathrm{\acute{e}tale}\end{matrix} \\[6pt] \begin{aligned}X_{0, Zar} & \xrightarrow{f_0} Y_{0, Zar} \\ X_\mathrm{\acute{e}tale} & \xrightarrow{\epsilon} X_{0, Zar} \\ X_\mathrm{\acute{e}tale} & \xrightarrow{f} Y_\mathrm{\acute{e}tale} \\ Y_\mathrm{\acute{e}tale} & \xrightarrow{\epsilon} Y_{0, Zar}\end{aligned}\end{gathered}$$ see Derived Categories of Spaces, Remark Derived quasi-coherent complexes. Thus we obtain a canonical map $$\epsilon^{-1}\mathrm{NL}_{X_0/Y_0} = \epsilon^{-1}\mathrm{NL}_{\mathcal{O}_{X_0}/f_0^{-1}\mathcal{O}_{Y_0}} = \mathrm{NL}_{\epsilon^{-1}\mathcal{O}_{X_0}/\epsilon^{-1}f_0^{-1}\mathcal{O}_{Y_0}} \to \mathrm{NL}_{\mathcal{O}_X/f^{-1}_{small}\mathcal{O}_Y} = \mathrm{NL}_{X/Y}$$ by functoriality of the naive cotangent complex. To see that the induced map $\epsilon^*\mathrm{NL}_{X_0/Y_0} \to \mathrm{NL}_{X/Y}$ is an isomorphism in $D(\mathcal{O}_X)$ we may check on stalks at geometric points (Properties of Spaces, Theorem Sheaves on ringed sites). Let $\overline{x} : \operatorname{Spec}(k) \to X_0$ be a geometric point lying over $x \in X_0$, with $\overline{y} = f \circ \overline{x}$ lying over $y \in Y_0$. Then $$\mathrm{NL}_{X/Y, \overline{x}} = \mathrm{NL}_{\mathcal{O}_{X, \overline{x}}/\mathcal{O}_{Y, \overline{y}}}$$ This is true because taking stalks at $\overline{x}$ is the same as taking inverse image via $\overline{x} : \operatorname{Spec}(k) \to X$ and we may apply Modules on Sites, Lemma Pullback of cotangent complexes and differentials (uncovered prerequisite). On the other hand we have $$(\epsilon^*\mathrm{NL}_{X_0/Y_0})_{\overline{x}} = \mathrm{NL}_{X_0/Y_0, x} \otimes_{\mathcal{O}_{X_0, x}} \mathcal{O}_{X, \overline{x}} = \mathrm{NL}_{\mathcal{O}_{X_0, x}/\mathcal{O}_{Y_0, y}} \otimes_{\mathcal{O}_{X_0, x}} \mathcal{O}_{X, \overline{x}}$$ Some details omitted (hint: use that the stalk of a pullback is the stalk at the image point, see Sites, Lemma Sheaves on ringed sites (uncovered prerequisite), as well as the corresponding result for modules, see Modules on Sites, Lemma Stalks of a pullback). Observe that $\mathcal{O}_{X, \overline{x}}$ is the strict henselization of $\mathcal{O}_{X_0, x}$ and similarly for $\mathcal{O}_{Y, \overline{y}}$ (Properties of Spaces, Lemma Étale morphisms and local algebra). Thus the result follows from More on Algebra, Lemma Cotangent complexes, differentials and henselian rings. $\square$
Lemma. Proper morphisms and nilpotent thickenings
Let $S$ be a scheme. Let $(f, f') : (X \subset X') \to (Y \subset Y')$ be a morphism of thickenings of algebraic spaces over $S$. Then
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$f$ is an affine morphism if and only if $f'$ is an affine morphism,
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$f$ is a surjective morphism if and only if $f'$ is a surjective morphism,
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$f$ is quasi-compact if and only if $f'$ quasi-compact,
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$f$ is universally closed if and only if $f'$ is universally closed,
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$f$ is integral if and only if $f'$ is integral,
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$f$ is (quasi-)separated if and only if $f'$ is (quasi-)separated,
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$f$ is universally injective if and only if $f'$ is universally injective,
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$f$ is universally open if and only if $f'$ is universally open,
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$f$ is representable if and only if $f'$ is representable, and
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add more here.
Proof. Observe that $Y \to Y'$ and $X \to X'$ are integral and universal homeomorphisms. This immediately implies parts (2), (3), (4), (7), and (8). Part (1) follows from Limits of Spaces, Proposition Affine neighbourhoods (uncovered prerequisite) which tells us that there is a 1-to-1 correspondence between affine schemes étale over $X$ and $X'$ and between affine schemes étale over $Y$ and $Y'$. Part (5) follows from (1) and (4) by Morphisms of Spaces, Lemma Integral extensions (uncovered prerequisite). Finally, note that $$X \times_Y X = X \times_{Y'} X \to X \times_{Y'} X' \to X' \times_{Y'} X'$$ is a thickening (the two arrows are thickenings by Lemma Base change for nilpotent thickenings (uncovered prerequisite)). Hence applying (3) and (4) to the morphism $(X \subset X') \to (X \times_Y X \to X' \times_{Y'} X')$ we obtain (6). Finally, part (9) follows from the fact that an algebraic space thickening of a scheme is again a scheme, see Lemma Nilpotent thickenings. $\square$
Lemma. Cotangent complexes, differentials and diagonals and separation
Let $S$ be a scheme. Let $B$ be an algebraic space over $S$. Let $i : Z \to X$ be an immersion of algebraic spaces over $B$, and assume $i$ (étale locally) has a left inverse. Then the canonical sequence $$0 \to \mathcal{C}_{Z/X} \to i^*\Omega_{X/B} \to \Omega_{Z/B} \to 0$$ of Lemma Cotangent complexes, differentials and diagonals and separation (uncovered prerequisite) is (étale locally) split exact.
Proof. Clarification: we claim that if $g : X \to Z$ is a left inverse of $i$ over $B$, then $i^*c_g$ is a right inverse of the map $i^*\Omega_{X/B} \to \Omega_{Z/B}$. Having said this, the result follows from the corresponding result for morphisms of schemes by étale localization, see Lemmas Localization of cotangent complexes, differentials and local algebra (uncovered prerequisite) and Cotangent complexes, differentials and étale morphisms (uncovered prerequisite). $\square$
Lemma. Cotangent complexes, differentials and tensor products and direct sums
Let $S$ be a scheme. Let $f : X \to B$ and $g : Y \to B$ be morphisms of algebraic spaces over $S$ with the same target. Let $p : X \times_B Y \to X$ and $q : X \times_B Y \to Y$ be the projection morphisms. The maps from Lemma Cotangent complexes and differentials (uncovered prerequisite) $$p^*\Omega_{X/B} \oplus q^*\Omega_{Y/B} \longrightarrow \Omega_{X \times_B Y/B}$$ give an isomorphism.
Proof. Follows from the schemes version, see Morphisms, Lemma Cotangent complexes, differentials and tensor products and direct sums (uncovered prerequisite) and étale localization, see Lemma Localization of cotangent complexes, differentials and local algebra (uncovered prerequisite). $\square$
Lemma. Formal smoothness and smooth morphisms (Infinitesimal lifting criterion)
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent:
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The morphism $f$ is smooth.
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The morphism $f$ is locally of finite presentation, and formally smooth.
Proof. Assume $f : X \to S$ is locally of finite presentation and formally smooth. Consider a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \xrightarrow{\psi} V \\ V & \longrightarrow Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes and the vertical arrows are étale and surjective. By Lemma Formal smoothness and smooth morphisms (uncovered prerequisite) we see $\psi : U \to V$ is formally smooth. By Morphisms of Spaces, Lemma Finite presentation and finite algebras (uncovered prerequisite) the morphism $\psi$ is locally of finite presentation. Hence by the case of schemes the morphism $\psi$ is smooth, see More on Morphisms, Lemma Formal smoothness and smooth morphisms (uncovered prerequisite). Hence $f$ is smooth, see Morphisms of Spaces, Lemma Smooth morphisms and local algebra (uncovered prerequisite).
Conversely, assume that $f : X \to Y$ is smooth. Consider a solid commutative diagram $$\begin{gathered}\begin{matrix}X & T \\ Y & T'\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f} Y \\ T & \xrightarrow{i} T' \\ T & \xrightarrow{a} X \\ T' & \longrightarrow Y \\ T' & \dashrightarrow X\end{aligned}\end{gathered}$$ as in Definition Formally smooth ring maps. We will show the dotted arrow exists thereby proving that $f$ is formally smooth. Let $\mathcal{F}$ be the sheaf of sets on $(T')_{spaces, \mathrm{\acute{e}tale}}$ of Lemma Sheaves on ringed sites (uncovered prerequisite) as in the special case discussed in Remark The geometric construction. Let $$\mathcal{H} = \mathcal{H}om_{\mathcal{O}_T}(a^*\Omega_{X/Y}, \mathcal{C}_{T/T'})$$ be the sheaf of $\mathcal{O}_T$-modules on $T_{spaces, \mathrm{\acute{e}tale}}$ with action $\mathcal{H} \times \mathcal{F} \to \mathcal{F}$ as in Lemma Sheaves on ringed sites (uncovered prerequisite). The action $\mathcal{H} \times \mathcal{F} \to \mathcal{F}$ turns $\mathcal{F}$ into a pseudo $\mathcal{H}$-torsor, see Cohomology on Sites, Definition Derived modules on ringed sites. Our goal is to show that $\mathcal{F}$ is a trivial $\mathcal{H}$-torsor. There are two steps: (I) To show that $\mathcal{F}$ is a torsor we have to show that $\mathcal{F}$ has étale locally a section. (II) To show that $\mathcal{F}$ is the trivial torsor it suffices to show that $H^1(T_\mathrm{\acute{e}tale}, \mathcal{H}) = 0$, see Cohomology on Sites, Lemma Derived modules on ringed sites (uncovered prerequisite).
First we prove (I). To see this choose a commutative diagram $$\begin{gathered}\begin{matrix}U & V \\ X & Y\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow X \\ U & \xrightarrow{\psi} V \\ V & \longrightarrow Y \\ X & \xrightarrow{f} Y\end{aligned}\end{gathered}$$ where $U$ and $V$ are schemes and the vertical arrows are étale and surjective. As $f$ is assumed smooth we see that $\psi$ is smooth and hence formally smooth by Lemma Proper morphisms (uncovered prerequisite). By the same lemma the morphism $V \to Y$ is formally étale. Thus by Lemma Composition and formal smoothness and étale morphisms (uncovered prerequisite) the composition $U \to Y$ is formally smooth. Then (I) follows from Lemma Étale morphisms (uncovered prerequisite) part (4).
Finally we prove (II). By Lemma Cotangent complexes, differentials and finite presentation (uncovered prerequisite) we see that $\Omega_{X/S}$ is of finite presentation. Hence $a^*\Omega_{X/S}$ is of finite presentation (see Properties of Spaces, Section Proper morphisms and modules). Hence the sheaf $\mathcal{H} = \mathcal{H}om_{\mathcal{O}_T}(a^*\Omega_{X/Y}, \mathcal{C}_{T/T'})$ is quasi-coherent by Properties of Spaces, Lemma Quasi-coherent complexes and coherent sheaves. Thus by Descent, Proposition Quasi-coherent complexes and sheaf cohomology and Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite) we have $$H^1(T_{spaces, \mathrm{\acute{e}tale}}, \mathcal{H}) = H^1(T_\mathrm{\acute{e}tale}, \mathcal{H}) = H^1(T, \mathcal{H}) = 0$$ as desired. $\square$
Finite-presentation descent through inverse limits
Lemma. Descent of finite presentation and modules
Let $I$ be a directed set. Let $(S_i, f_{ii'})$ be an inverse system of schemes over $I$. Assume
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all the morphisms $f_{ii'} : S_i \to S_{i'}$ are affine,
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all the schemes $S_i$ are quasi-compact and quasi-separated.
Let $S = \varprojlim_i S_i$. Then we have the following:
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For any sheaf of $\mathcal{O}_S$-modules $\mathcal{F}$ of finite presentation there exists an index $i \in I$ and a sheaf of $\mathcal{O}_{S_i}$-modules of finite presentation $\mathcal{F}_i$ such that $\mathcal{F} \cong f_i^*\mathcal{F}_i$.
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Suppose given an index $i \in I$, sheaves of $\mathcal{O}_{S_i}$-modules $\mathcal{F}_i$, $\mathcal{G}_i$ of finite presentation and a morphism $\varphi : f_i^*\mathcal{F}_i \to f_i^*\mathcal{G}_i$ over $S$. Then there exists an index $i' \geq i$ and a morphism $\varphi_{i'} : f_{i'i}^*\mathcal{F}_i \to f_{i'i}^*\mathcal{G}_i$ whose base change to $S$ is $\varphi$.
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Suppose given an index $i \in I$, sheaves of $\mathcal{O}_{S_i}$-modules $\mathcal{F}_i$, $\mathcal{G}_i$ of finite presentation and a pair of morphisms $\varphi_i, \psi_i : \mathcal{F}_i \to \mathcal{G}_i$. Assume that the base changes are equal: $f_i^*\varphi_i = f_i^*\psi_i$. Then there exists an index $i' \geq i$ such that $f_{i'i}^*\varphi_i = f_{i'i}^*\psi_i$.
In other words, the category of modules of finite presentation over $S$ is the colimit over $I$ of the categories modules of finite presentation over $S_i$.
Proof. We sketch two proofs, but we omit the details.
First proof. If $S$ and $S_i$ are affine schemes, then this lemma is equivalent to Algebra, Lemma Finite module presentations in a filtered colimit. In the general case, use Zariski glueing to deduce it from the affine case.
Second proof. We use
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there is an equivalence of categories between quasi-coherent $\mathcal{O}_S$-modules and vector bundles over $S$, see Constructions, Section Derived tensor products and Tor amplitude, and
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a vector bundle $\mathbf{V}(\mathcal{F}) \to S$ is of finite presentation over $S$ if and only if $\mathcal{F}$ is an $\mathcal{O}_S$-module of finite presentation.
Having said this, we can use Lemma Descent of finite presentation and finite algebras to show that the category of vector bundles of finite presentation over $S$ is the colimit over $I$ of the categories of vector bundles over $S_i$. $\square$
Lemma. Descent of finite locally free and invertible modules
Let $S = \varprojlim S_i$ be the limit of a directed system of quasi-compact and quasi-separated schemes $S_i$ with affine transition morphisms. Then
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any finite locally free $\mathcal{O}_S$-module is the pullback of a finite locally free $\mathcal{O}_{S_i}$-module for some $i$,
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any invertible $\mathcal{O}_S$-module is the pullback of an invertible $\mathcal{O}_{S_i}$-module for some $i$, and
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any finite type quasi-coherent ideal $\mathcal{I} \subset \mathcal{O}_S$ is of the form $\mathcal{I}_i \cdot \mathcal{O}_S$ for some $i$ and some finite type quasi-coherent ideal $\mathcal{I}_i \subset \mathcal{O}_{S_i}$.
Proof. Let $\mathcal{E}$ be a finite locally free $\mathcal{O}_S$-module. Since finite locally free modules are of finite presentation we can find an $i$ and an $\mathcal{O}_{S_i}$-module $\mathcal{E}_i$ of finite presentation such that $f_i^*\mathcal{E}_i \cong \mathcal{E}$, see Lemma Descent of finite presentation and modules. After increasing $i$ we may assume $\mathcal{E}_i$ is a flat $\mathcal{O}_{S_i}$-module, see Algebra, Lemma Lesson 3, Section 5.6.7, C.1. (Using this lemma is not necessary, but it is convenient.) Then $\mathcal{E}_i$ is finite locally free by Algebra, Lemma Characterizations of finite projective modules.
If $\mathcal{L}$ is an invertible $\mathcal{O}_S$-module, then by the above we can find an $i$ and finite locally free $\mathcal{O}_{S_i}$-modules $\mathcal{L}_i$ and $\mathcal{N}_i$ pulling back to $\mathcal{L}$ and $\mathcal{L}^{\otimes -1}$. After possible increasing $i$ we see that the map $\mathcal{L} \otimes_{\mathcal{O}_X} \mathcal{L}^{\otimes -1} \to \mathcal{O}_X$ descends to a map $\mathcal{L}_i \otimes_{\mathcal{O}_{S_i}} \mathcal{N}_i \to \mathcal{O}_{S_i}$. And after increasing $i$ further, we may assume it is an isomorphism. It follows that $\mathcal{L}_i$ is an invertible module (Modules, Lemma Line bundles and ampleness (uncovered prerequisite)) and the proof of (2) is complete.
Given $\mathcal{I}$ as in (3) we see that $\mathcal{O}_S \to \mathcal{O}_S/\mathcal{I}$ is a map of finitely presented $\mathcal{O}_S$-modules. Hence by Lemma Descent of finite presentation and modules this is the pullback of some map $\mathcal{O}_{S_i} \to \mathcal{F}_i$ of finitely presented $\mathcal{O}_{S_i}$-modules. After increasing $i$ we may assume this map is surjective (details omitted; hint: use Algebra, Lemma Filtered limits and proper morphisms and modules on affine open cover). Then the kernel of $\mathcal{O}_{S_i} \to \mathcal{F}_i$ is a finite type quasi-coherent ideal in $\mathcal{O}_{S_i}$ whose pullback gives $\mathcal{I}$. $\square$
Lemma. Proper morphisms
If the base change of a scheme to a limit is proper, then already the base change is proper at a finite level.
Assumptions and notation as in Situation A property to be descended through a filtered inverse system. If
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$f$ is proper, and
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$f_0$ is locally of finite type,
then there exists an $i$ such that $f_i$ is proper.
Proof. By Lemma Descent of finite presentation and diagonals and separation we see that $f_i$ is separated for some $i \geq 0$. Replacing $0$ by $i$ we may assume that $f_0$ is separated. Observe that $f_0$ is quasi-compact, see Schemes, Lemma The geometric construction (uncovered prerequisite). By Lemma Finite algebras we can choose a diagram $$\begin{gathered}\begin{matrix}X_0 & X_0' & \mathbf{P}^n_{Y_0} \\ \phantom{X} & Y_0 & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X_0 & \longrightarrow Y_0 \\ X_0' & \longrightarrow Y_0 \\ X_0' & \xrightarrow{\pi} X_0 \\ X_0' & \longrightarrow \mathbf{P}^n_{Y_0} \\ \mathbf{P}^n_{Y_0} & \longrightarrow Y_0\end{aligned}\end{gathered}$$ where $X_0' \to \mathbf{P}^n_{Y_0}$ is an immersion, and $\pi : X_0' \to X_0$ is proper and surjective. Introduce $X' = X_0' \times_{Y_0} Y$ and $X_i' = X_0' \times_{Y_0} Y_i$. By Morphisms, Lemmas Composition and proper morphisms (uncovered prerequisite) and Base change for proper morphisms (uncovered prerequisite) we see that $X' \to Y$ is proper. Hence $X' \to \mathbf{P}^n_Y$ is a closed immersion (Morphisms, Lemma Proper morphisms (uncovered prerequisite)). By Morphisms, Lemma Proper morphisms (uncovered prerequisite) it suffices to prove that $X'_i \to Y_i$ is proper for some $i$. By Lemma Descent of finite presentation and diagonals and separation we find that $X'_i \to \mathbf{P}^n_{Y_i}$ is a closed immersion for $i$ large enough. Then $X'_i \to Y_i$ is proper and we win. $\square$
Lemma. Descent of finite presentation and flatness
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. If
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$f$ is flat,
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$f_0$ is locally of finite presentation,
then $f_i$ is flat for some $i \geq 0$.
Proof. Choose a finite affine open covering $Y_0 = \bigcup_{j = 1, \ldots, m} Y_{j, 0}$ such that each $Y_{j, 0}$ maps into an affine open $S_{j, 0} \subset S_0$. For each $j$ let $f_0^{-1}Y_{j, 0} = \bigcup_{k = 1, \ldots, n_j} X_{k, 0}$ be a finite affine open covering. Since the property of being flat is local we see that it suffices to prove the lemma for the morphisms of affines $X_{k, i} \to Y_{j, i} \to S_{j, i}$ which are the base changes of $X_{k, 0} \to Y_{j, 0} \to S_{j, 0}$ to $S_i$. Thus we reduce to the case that $X_0, Y_0, S_0$ are affine
In the affine case we reduce to the following algebra result. Suppose that $R = \mathop{\operatorname{colim}}_{i \in I} R_i$. For some $0 \in I$ suppose given an $R_0$-algebra map $A_i \to B_i$ of finite presentation. If $R \otimes_{R_0} A_0 \to R \otimes_{R_0} B_0$ is flat, then for some $i \geq 0$ the map $R_i \otimes_{R_0} A_0 \to R_i \otimes_{R_0} B_0$ is flat. This follows from Algebra, Lemma Lesson 3, Section 5.6.7, C.1 part (3). $\square$
Lemma. Filtered limits and line bundles and ampleness
In Situation A filtered inverse system for descent let $\mathcal{L}_0$ be an invertible sheaf of modules on $S_0$. If the pullback $\mathcal{L}$ to $S$ is ample, then for some $i \in I$ the pullback $\mathcal{L}_i$ to $S_i$ is ample.
Proof. The assumption means there are finitely many sections $s_1, \ldots, s_m \in \Gamma(S, \mathcal{L})$ such that $S_{s_j}$ is affine and such that $S = \bigcup S_{s_j}$, see Properties, Definition Ample invertible sheaves. By Lemma Descent of finite-presentation descent we can find an $i \in I$ and sections $s_{i, j} \in \Gamma(S_i, \mathcal{L}_i)$ mapping to $s_j$. By Lemma Filtered limits and affine neighbourhoods we may, after increasing $i$, assume that $(S_i)_{s_{i, j}}$ is affine for $j = 1, \ldots, m$. By Lemma Descent of finite-presentation descent we may, after increasing $i$ a last time, assume that $S_i = \bigcup (S_i)_{s_{i, j}}$. Then $\mathcal{L}_i$ is ample by definition. $\square$
Lemma. Finite algebras
Let $S$ be a quasi-compact and quasi-separated scheme. Let $f : X \to S$ be a separated morphism of finite type. Then there exists an $n \geq 0$ and a diagram $$\begin{gathered}\begin{matrix}X & X' & \mathbf{P}^n_S \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \longrightarrow S \\ X' & \xrightarrow{\pi} X \\ X' & \longrightarrow \mathbf{P}^n_S \\ \mathbf{P}^n_S & \longrightarrow S\end{aligned}\end{gathered}$$ where $X' \to \mathbf{P}^n_S$ is an immersion, and $\pi : X' \to X$ is proper and surjective.
Proof. By Proposition Finite presentation and diagonals and separation we can find a closed immersion $X \to Y$ where $Y$ is separated and of finite presentation over $S$. Clearly, if we prove the assertion for $Y$, then the result follows for $X$. Hence we may assume that $X$ is of finite presentation over $S$.
Write $S = \varprojlim_i S_i$ as a directed limit of Noetherian schemes, see Proposition Finite-presentation descent. By Lemma Descent of finite presentation and finite algebras we can find an index $i \in I$ and a scheme $X_i \to S_i$ of finite presentation so that $X = S \times_{S_i} X_i$. By Lemma Descent of finite presentation and diagonals and separation we may assume that $X_i \to S_i$ is separated. Clearly, if we prove the assertion for $X_i$ over $S_i$, then the assertion holds for $X$. The case $X_i \to S_i$ is treated by Cohomology of Schemes, Lemma Noetherian rings (uncovered prerequisite). $\square$
Lemma. Affine neighbourhoods
Let $X$ be a scheme which is set theoretically the union of finitely many affine closed subschemes. Then $X$ is affine.
Proof. Let $Z_i \subset X$, $i = 1, \ldots, n$ be affine closed subschemes such that $X = \bigcup Z_i$ set theoretically. Then $\coprod Z_i \to X$ is surjective and integral with affine source. Hence $X$ is affine by Proposition Affine neighbourhoods. $\square$
Lemma. Descent of finite presentation and finite algebras
Let $I$ be a directed set. Let $(S_i, f_{ii'})$ be an inverse system of schemes over $I$. Assume
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the morphisms $f_{ii'} : S_i \to S_{i'}$ are affine,
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the schemes $S_i$ are quasi-compact and quasi-separated.
Let $S = \varprojlim_i S_i$. Then we have the following:
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For any morphism of finite presentation $X \to S$ there exists an index $i \in I$ and a morphism of finite presentation $X_i \to S_i$ such that $X \cong X_{i, S}$ as schemes over $S$.
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Given an index $i \in I$, schemes $X_i$, $Y_i$ of finite presentation over $S_i$, and a morphism $\varphi : X_{i, S} \to Y_{i, S}$ over $S$, there exists an index $i' \geq i$ and a morphism $\varphi_{i'} : X_{i, S_{i'}} \to Y_{i, S_{i'}}$ whose base change to $S$ is $\varphi$.
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Given an index $i \in I$, schemes $X_i$, $Y_i$ of finite presentation over $S_i$ and a pair of morphisms $\varphi_i, \psi_i : X_i \to Y_i$ whose base changes $\varphi_{i, S} = \psi_{i, S}$ are equal, there exists an index $i' \geq i$ such that $\varphi_{i, S_{i'}} = \psi_{i, S_{i'}}$.
In other words, the category of schemes of finite presentation over $S$ is the colimit over $I$ of the categories of schemes of finite presentation over $S_i$.
Proof. In case each of the schemes $S_i$ is affine, and we consider only affine schemes of finite presentation over $S_i$, resp. $S$ this lemma is equivalent to Algebra, Lemma Filtered limits and finite presentation. We claim that the affine case implies the lemma in general.
Let us prove (3). Suppose given an index $i \in I$, schemes $X_i$, $Y_i$ of finite presentation over $S_i$ and a pair of morphisms $\varphi_i, \psi_i : X_i \to Y_i$. Assume that the base changes are equal: $\varphi_{i, S} = \psi_{i, S}$. We will use the notation $X_{i'} = X_{i, S_{i'}}$ and $Y_{i'} = Y_{i, S_{i'}}$ for $i' \geq i$. We also set $X = X_{i, S}$ and $Y = Y_{i, S}$. Note that according to Lemma Finite-presentation descent we have $X = \varprojlim_{i' \geq i} X_{i'}$ and similarly for $Y$. Additionally we denote $\varphi_{i'}$ and $\psi_{i'}$ (resp. $\varphi$ and $\psi$) the base change of $\varphi_i$ and $\psi_i$ to $S_{i'}$ (resp. $S$). So our assumption means that $\varphi = \psi$. Since $Y_i$ and $X_i$ are of finite presentation over $S_i$, and since $S_i$ is quasi-compact and quasi-separated, also $X_i$ and $Y_i$ are quasi-compact and quasi-separated (see Morphisms, Lemma Finite presentation and diagonals and separation (uncovered prerequisite)). Hence we may choose a finite affine open covering $Y_i = \bigcup V_{j, i}$ such that each $V_{j, i}$ maps into an affine open of $S_i$. As above, denote $V_{j, i'}$ the inverse image of $V_{j, i}$ in $Y_{i'}$ and $V_j$ the inverse image in $Y$. The immersions $V_{j, i'} \to Y_{i'}$ are quasi-compact, and the inverse images $U_{j, i'} = \varphi_i^{-1}(V_{j, i'})$ and $U_{j, i'}' = \psi_i^{-1}(V_{j, i'})$ are quasi-compact opens of $X_{i'}$. By assumption the inverse images of $V_j$ under $\varphi$ and $\psi$ in $X$ are equal. Hence by Lemma Descent of finite-presentation descent there exists an index $i' \geq i$ such that of $U_{j, i'} = U_{j, i'}'$ in $X_{i'}$. Choose an finite affine open covering $U_{j, i'} = U_{j, i'}' = \bigcup W_{j, k, i'}$ which induce coverings $U_{j, i''} = U_{j, i''}' = \bigcup W_{j, k, i''}$ for all $i'' \geq i'$. By the affine case there exists an index $i''$ such that $\varphi_{i''}|_{W_{j, k, i''}} = \psi_{i''}|_{W_{j, k, i''}}$ for all $j, k$. Then $i''$ is an index such that $\varphi_{i''} = \psi_{i''}$ and (3) is proved.
Let us prove (2). Suppose given an index $i \in I$, schemes $X_i$, $Y_i$ of finite presentation over $S_i$ and a morphism $\varphi : X_{i, S} \to Y_{i, S}$. We will use the notation $X_{i'} = X_{i, S_{i'}}$ and $Y_{i'} = Y_{i, S_{i'}}$ for $i' \geq i$. We also set $X = X_{i, S}$ and $Y = Y_{i, S}$. Note that according to Lemma Finite-presentation descent we have $X = \varprojlim_{i' \geq i} X_{i'}$ and similarly for $Y$. Since $Y_i$ and $X_i$ are of finite presentation over $S_i$, and since $S_i$ is quasi-compact and quasi-separated, also $X_i$ and $Y_i$ are quasi-compact and quasi-separated (see Morphisms, Lemma Finite presentation and diagonals and separation (uncovered prerequisite)). Hence we may choose a finite affine open covering $Y_i = \bigcup V_{j, i}$ such that each $V_{j, i}$ maps into an affine open of $S_i$. As above, denote $V_{j, i'}$ the inverse image of $V_{j, i}$ in $Y_{i'}$ and $V_j$ the inverse image in $Y$. The immersions $V_j \to Y$ are quasi-compact, and the inverse images $U_j = \varphi^{-1}(V_j)$ are quasi-compact opens of $X$. Hence by Lemma Descent of finite-presentation descent there exists an index $i' \geq i$ and quasi-compact opens $U_{j, i'}$ of $X_{i'}$ whose inverse image in $X$ is $U_j$. Choose an finite affine open covering $U_{j, i'} = \bigcup W_{j, k, i'}$ which induce affine open coverings $U_{j, i''} = \bigcup W_{j, k, i''}$ for all $i'' \geq i'$ and an affine open covering $U_j = \bigcup W_{j, k}$. By the affine case there exists an index $i''$ and morphisms $\varphi_{j, k, i''} : W_{j, k, i''} \to V_{j, i''}$ such that $\varphi|_{W_{j, k}} = \varphi_{j, k, i'', S}$ for all $j, k$. By part (3) proved above, there is a further index $i''' \geq i''$ such that $$\varphi_{j_1, k_1, i'', S_{i'''}}|{W{j_1, k_1, i'''} \cap W_{j_2, k_2, i'''}}
\varphi_{j_2, k_2, i'', S_{i'''}}|{W{j_1, k_1, i'''} \cap W_{j_2, k_2, i'''}}$$ for all $j_1, j_2, k_1, k_2$. Then $i'''$ is an index such that there exists a morphism $\varphi_{i'''} : X_{i'''} \to Y_{i'''}$ whose base change to $S$ gives $\varphi$. Hence (2) holds.
Let us prove (1). Suppose given a scheme \(X\) of finite presentation over \(S\). Since \(X\) is of finite presentation over \(S\), and since \(S\) is quasi-compact and quasi-separated, also \(X\) is quasi-compact and quasi-separated (see Morphisms, Lemma Finite presentation and diagonals and separation (uncovered prerequisite)). Choose a finite affine open covering \(X = \bigcup U_j\) such that each \(U_j\) maps into an affine open \(V_j \subset S\). Denote \(U_{j_1j_2} = U_{j_1} \cap U_{j_2}\) and \(U_{j_1j_2j_3} = U_{j_1} \cap U_{j_2} \cap U_{j_3}\). By Lemmas Descent of finite-presentation descent and Filtered limits and affine neighbourhoods we can find an index \(i_1\) and affine opens \(V_{j, i_1} \subset S_{i_1}\) such that each \(V_j\) is the inverse of this in \(S\). Let \(V_{j, i}\) be the inverse image of \(V_{j, i_1}\) in \(S_i\) for \(i \geq i_1\). By the affine case we may find an index \(i_2 \geq i_1\) and affine schemes \(U_{j, i_2} \to V_{j, i_2}\) such that \(U_j = S \times_{S_{i_2}} U_{j, i_2}\) is the base change. Denote \(U_{j, i} = S_i \times_{S_{i_2}} U_{j, i_2}\) for \(i \geq i_2\). By Lemma Descent of finite-presentation descent there exists an index \(i_3 \geq i_2\) and open subschemes \(W_{j_1, j_2, i_3} \subset U_{j_1, i_3}\) whose base change to \(S\) is equal to \(U_{j_1j_2}\). Denote \(W_{j_1, j_2, i} = S_i \times_{S_{i_3}} W_{j_1, j_2, i_3}\) for \(i \geq i_3\). By part (2) shown above there exists an index \(i_4 \geq i_3\) and morphisms \(\varphi_{j_1, j_2, i_4} : W_{j_1, j_2, i_4} \to W_{j_2, j_1, i_4}\) whose base change to \(S\) gives the identity morphism \(U_{j_1j_2} = U_{j_2j_1}\) for all \(j_1, j_2\). For all \(i \geq i_4\) denote \(\varphi_{j_1, j_2, i} = \text{id}_S \times \varphi_{j_1, j_2, i_4}\) the base change. We claim that for some \(i_5 \geq i_4\) the system \(((U_{j, i_5})_j, (W_{j_1, j_2, i_5})_{j_1, j_2}, (\varphi_{j_1, j_2, i_5})_{j_1, j_2})\) forms a glueing datum as in Schemes, Section The geometric construction. In order to see this we have to verify that for \(i\) large enough we have
\[ \varphi_{j_1, j_2, i}^{-1}(W_{j_2, j_1, i} \cap W_{j_2, j_3, i}) = W_{j_1, j_2, i} \cap W_{j_1, j_3, i} \]and that for large enough \(i\) the cocycle condition holds. The first condition follows from Lemma Descent of finite-presentation descent and the fact that \(U_{j_2j_1j_3} = U_{j_1j_2j_3}\). The second from part (3) of the lemma proved above and the fact that the cocycle condition holds for the maps \(\text{id} : U_{j_1j_2} \to U_{j_2j_1}\). Ok, so now we can use Schemes, Lemma The geometric construction (uncovered prerequisite) to glue the system \(((U_{j, i_5})_j, (W_{j_1, j_2, i_5})_{j_1, j_2}, (\varphi_{j_1, j_2, i_5})_{j_1, j_2})\) to get a scheme \(X_{i_5} \to S_{i_5}\). By construction the base change of \(X_{i_5}\) to \(S\) is formed by glueing the open affines \(U_j\) along the opens \(U_{j_1} \leftarrow U_{j_1j_2} \rightarrow U_{j_2}\). Hence \(S \times_{S_{i_5}} X_{i_5} \cong X\) as desired. \(\square\)
Lemma. Descent of étale morphisms
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. If
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$f$ is étale,
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$f_0$ is locally of finite presentation,
then $f_i$ is étale for some $i \geq 0$.
Proof. Being étale is local on the source and the target (Morphisms, Lemma Étale morphisms (uncovered prerequisite)) hence we may assume $S_0, X_0, Y_0$ affine (details omitted). The corresponding algebra fact is Algebra, Lemma Filtered limits and étale morphisms (uncovered prerequisite). $\square$
Lemma. Descent of finite-presentation descent
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. If
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$f$ is a monomorphism, and
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$f_0$ is locally of finite type,
then $f_i$ is a monomorphism for some $i \geq 0$.
Proof. Recall that a morphism of schemes $V \to W$ is a monomorphism if and only if the diagonal $V \to V \times_W V$ is an isomorphism (Schemes, Lemma The geometric construction (uncovered prerequisite)). The morphism $X_0 \to X_0 \times_{Y_0} X_0$ is locally of finite presentation by Morphisms, Lemma Diagonals, separation and finite algebras (uncovered prerequisite). Since $X_0 \times_{Y_0} X_0$ is quasi-compact and quasi-separated (Schemes, Remark Diagonals and separation) we conclude from Lemma Descent of finite-presentation descent (uncovered prerequisite) that $\Delta_i : X_i \to X_i \times_{Y_i} X_i$ is an isomorphism for some $i \geq 0$. For this $i$ the morphism $f_i$ is a monomorphism. $\square$
Lemma. Descent of finite presentation and flatness
With notation and assumptions as in Lemma Descent of finite presentation and finite algebras. Let $i \in I$. Suppose that $\varphi_i : X_i \to Y_i$ is a morphism of schemes of finite presentation over $S_i$ and that $\mathcal{F}_i$ is a quasi-coherent $\mathcal{O}_{X_i}$-module of finite presentation. If the pullback of $\mathcal{F}_i$ to $X_i \times_{S_i} S$ is flat over $Y_i \times_{S_i} S$, then there exists an index $i' \geq i$ such that the pullback of $\mathcal{F}_i$ to $X_i \times_{S_i} S_{i'}$ is flat over $Y_i \times_{S_i} S_{i'}$.
Proof. (This lemma is the analogue of Lemma Descent of finite presentation and flatness for modules.) For $i' \geq i$ denote $X_{i'} = S_{i'} \times_{S_i} X_i$, $\mathcal{F}_{i'} = (X_{i'} \to X_i)^*\mathcal{F}_i$ and similarly for $Y_{i'}$. Denote $\varphi_{i'}$ the base change of $\varphi_i$ to $S_{i'}$. Also set $X = S \times_{S_i} X_i$, $Y =S \times_{S_i} X_i$, $\mathcal{F} = (X \to X_i)^*\mathcal{F}_i$ and $\varphi$ the base change of $\varphi_i$ to $S$. Let $Y_i = \bigcup_{j = 1, \ldots, m} V_{j, i}$ be a finite affine open covering such that each $V_{j, i}$ maps into some affine open of $S_i$. For each $j = 1, \ldots m$ let $\varphi_i^{-1}(V_{j, i}) = \bigcup_{k = 1, \ldots, m(j)} U_{k, j, i}$ be a finite affine open covering. For $i' \geq i$ we denote $V_{j, i'}$ the inverse image of $V_{j, i}$ in $Y_{i'}$ and $U_{k, j, i'}$ the inverse image of $U_{k, j, i}$ in $X_{i'}$. Similarly we have $U_{k, j} \subset X$ and $V_j \subset Y$. Then $U_{k, j} = \varprojlim_{i' \geq i} U_{k, j, i'}$ and $V_j = \varprojlim_{i' \geq i} V_j$ (see Lemma Finite-presentation descent). Since $X_{i'} = \bigcup_{k, j} U_{k, j, i'}$ is a finite open covering it suffices to prove the lemma for each of the morphisms $U_{k, j, i} \to V_{j, i}$ and the sheaf $\mathcal{F}_i|_{U_{k, j, i}}$. Hence we see that the lemma reduces to the case that $X_i$ and $Y_i$ are affine and map into an affine open of $S_i$, i.e., we may also assume that $S$ is affine.
In the affine case we reduce to the following algebra result. Suppose that $R = \mathop{\operatorname{colim}}_{i \in I} R_i$. For some $i \in I$ suppose given a map $A_i \to B_i$ of finitely presented $R_i$-algebras. Let $N_i$ be a finitely presented $B_i$-module. Then, if $R \otimes_{R_i} N_i$ is flat over $R \otimes_{R_i} A_i$, then for some $i' \geq i$ the module $R_{i'} \otimes_{R_i} N_i$ is flat over $R_{i'} \otimes_{R_i} A$. This is exactly the result proved in Algebra, Lemma Lesson 3, Section 5.6.7, C.1 part (3). $\square$
Lemma. Line bundles and ampleness
Let $i : Z \to X$ be a closed immersion of schemes inducing a homeomorphism of underlying topological spaces. Let $\mathcal{L}$ be an invertible sheaf on $X$. Then $i^*\mathcal{L}$ is ample on $Z$, if and only if $\mathcal{L}$ is ample on $X$.
Proof. If $\mathcal{L}$ is ample, then $i^*\mathcal{L}$ is ample for example by Morphisms, Lemma Pullback of line bundles, ampleness and tensor products and direct sums (uncovered prerequisite). Assume $i^*\mathcal{L}$ is ample. Then $Z$ is quasi-compact (Properties, Definition Ample invertible sheaves) and separated (Properties, Lemma Line bundles, ampleness and diagonals and separation (uncovered prerequisite)). Since $i$ is surjective, we see that $X$ is quasi-compact. Since $i$ is universally closed and surjective, we see that $X$ is separated (Morphisms, Lemma Diagonals and separation (uncovered prerequisite)).
By Proposition Finite-presentation descent we can write $X = \varprojlim X_i$ as a directed limit of finite type schemes over $\mathbf{Z}$ with affine transition morphisms. We can find an $i$ and an invertible sheaf $\mathcal{L}_i$ on $X_i$ whose pullback to $X$ is isomorphic to $\mathcal{L}$, see Lemma Descent of finite presentation and modules.
For each $i$ let $Z_i \subset X_i$ be the scheme theoretic image of the morphism $Z \to X_i$. If $\operatorname{Spec}(A_i) \subset X_i$ is an affine open subscheme with inverse image of $\operatorname{Spec}(A)$ in $X$ and if $Z \cap \operatorname{Spec}(A)$ is defined by the ideal $I \subset A$, then $Z_i \cap \operatorname{Spec}(A_i)$ is defined by the ideal $I_i \subset A_i$ which is the inverse image of $I$ in $A_i$ under the ring map $A_i \to A$, see Morphisms, Example The geometric construction (uncovered prerequisite). Since $\mathop{\operatorname{colim}} A_i/I_i = A/I$ it follows that $\varprojlim Z_i = Z$. By Lemma Filtered limits and line bundles and ampleness we see that $\mathcal{L}_i|_{Z_i}$ is ample for some $i$. Since $Z$ and hence $X$ maps into $Z_i$ set theoretically, we see that $X_{i'} \to X_i$ maps into $Z_i$ set theoretically for some $i' \geq i$, see Lemma Filtered limits and finite-presentation descent (uncovered prerequisite). (Observe that since $X_i$ is Noetherian, every closed subset of $X_i$ is constructible.) Let $T \subset X_{i'}$ be the scheme theoretic inverse image of $Z_i$ in $X_{i'}$. Observe that $\mathcal{L}_{i'}|_T$ is the pullback of $\mathcal{L}_i|_{Z_i}$ and hence ample by Morphisms, Lemma Pullback of line bundles, ampleness and tensor products and direct sums (uncovered prerequisite) and the fact that $T \to Z_i$ is an affine morphism. Thus we see that $\mathcal{L}_{i'}$ is ample on $X_{i'}$ by Cohomology of Schemes, Lemma Line bundles and ampleness (uncovered prerequisite). Pulling back to $X$ (using the same lemma as above) we find that $\mathcal{L}$ is ample. $\square$
Situation. A property to be descended through a filtered inverse system
Let $S = \varprojlim S_i$ be a limit of a directed system of schemes with affine transition morphisms (Lemma Finite-presentation descent). Let $0 \in I$ and let $f_0 : X_0 \to Y_0$ be a morphism of schemes over $S_0$. Assume $S_0$, $X_0$, $Y_0$ are quasi-compact and quasi-separated. Let $f_i : X_i \to Y_i$ be the base change of $f_0$ to $S_i$ and let $f : X \to Y$ be the base change of $f_0$ to $S$.
Lemma. Descent of finite presentation and diagonals and separation
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. If $f$ is separated, then $f_i$ is separated for some $i \geq 0$.
Proof. Apply Lemma Descent of finite presentation and diagonals and separation to the diagonal morphism $\Delta_{X_0/S_0} : X_0 \to X_0 \times_{S_0} X_0$. (This is permissible as diagonal morphisms are locally of finite type and the fibre product $X_0 \times_{S_0} X_0$ is quasi-compact and quasi-separated, see Schemes, Lemma Diagonals and separation (uncovered prerequisite), Morphisms, Lemma Diagonals, separation and finite algebras (uncovered prerequisite), and Schemes, Remark Diagonals and separation. $\square$
Lemma. Descent of finite presentation and diagonals and separation
Notation and assumptions as in Situation A property to be descended through a filtered inverse system. If
-
$f$ is a closed immersion, and
-
$f_0$ is locally of finite type,
then there exists an $i \geq 0$ such that $f_i$ is a closed immersion.
Proof. A closed immersion is affine, see Morphisms, Lemma Diagonals, separation and affine neighbourhoods (uncovered prerequisite). Hence by Lemma Descent of finite presentation and affine neighbourhoods (uncovered prerequisite) above after increasing $0$ we may assume that $f_0$ is affine. By writing $Y_0$ as a finite union of affines we reduce to proving the result when $X_0$ and $Y_0$ are affine and map into a common affine $W \subset S_0$. The corresponding algebra statement is a consequence of Algebra, Lemma Filtered limits and commutative algebra (uncovered prerequisite). $\square$
Situation. A filtered inverse system for descent
Let $S = \varprojlim_{i \in I} S_i$ be the limit of a directed system of schemes with affine transition morphisms $f_{i'i} : S_{i'} \to S_i$ (Lemma Finite-presentation descent). We assume that $S_i$ is quasi-compact and quasi-separated for all $i \in I$. We denote $f_i : S \to S_i$ the projection. We also choose an element $0 \in I$.
Lemma. Descent of finite-presentation descent
In Situation A filtered inverse system for descent. Suppose that $\mathcal{F}_0$ is a quasi-coherent sheaf on $S_0$. Set $\mathcal{F}_i = f_{i0}^*\mathcal{F}_0$ for $i \geq 0$ and set $\mathcal{F} = f_0^*\mathcal{F}_0$. Then $$\Gamma(S, \mathcal{F}) = \mathop{\operatorname{colim}}_{i \geq 0} \Gamma(S_i, \mathcal{F}_i)$$
Proof. Write $\mathcal{A}_j = f_{i0, *} \mathcal{O}_{S_i}$. This is a quasi-coherent sheaf of $\mathcal{O}_{S_0}$-algebras (see Morphisms, Lemma Affine neighbourhoods and groupoids and equivalence relations (uncovered prerequisite)) and $S_i$ is the relative spectrum of $\mathcal{A}_i$ over $S_0$. In the proof of Lemma Finite-presentation descent we constructed $S$ as the relative spectrum of $\mathcal{A} = \mathop{\operatorname{colim}}_{i \geq 0} \mathcal{A}_i$ over $S_0$. Set $$\mathcal{M}_i = \mathcal{F}_0 \otimes_{\mathcal{O}_{S_0}} \mathcal{A}_i$$ and $$\mathcal{M} = \mathcal{F}_0 \otimes_{\mathcal{O}_{S_0}} \mathcal{A}.$$ Then we have $f_{i0, *} \mathcal{F}_i = \mathcal{M}_i$ and $f_{0, *}\mathcal{F} = \mathcal{M}$. Since $\mathcal{A}$ is the colimit of the sheaves $\mathcal{A}_i$ and since tensor product commutes with directed colimits, we conclude that $\mathcal{M} = \mathop{\operatorname{colim}}_{i \geq 0} \mathcal{M}_i$. Since $S_0$ is quasi-compact and quasi-separated we see that $$\begin{eqnarray*} \Gamma(S, \mathcal{F}) & = & \Gamma(S_0, \mathcal{M}) \\ & = & \Gamma(S_0, \mathop{\operatorname{colim}}_{i \geq 0} \mathcal{M}_i) \\ & = & \mathop{\operatorname{colim}}_{i \geq 0} \Gamma(S_0, \mathcal{M}_i) \\ & = & \mathop{\operatorname{colim}}_{i \geq 0} \Gamma(S_i, \mathcal{F}_i) \end{eqnarray*}$$ see Sheaves, Lemma The geometric construction (uncovered prerequisite) and Topology, Lemma Diagonals and separation (uncovered prerequisite) for the middle equality. $\square$
Lemma. Filtered limits and affine neighbourhoods
In Situation A filtered inverse system for descent if $S$ is affine, then for some $i_0 \in I$ the schemes $S_i$ for $i \geq i_0$ are affine.
Proof. By Lemma Filtered limits and affine neighbourhoods (uncovered prerequisite) we may assume that $S_0$ is quasi-affine for some $0 \in I$. Set $R_0 = \Gamma(S_0, \mathcal{O}_{S_0})$. Then $S_0$ is a quasi-compact open of $T_0 = \operatorname{Spec}(R_0)$. Denote $j_0 : S_0 \to T_0$ the corresponding quasi-compact open immersion. For $i \geq 0$ set $\mathcal{A}_i = f_{i0, *}\mathcal{O}_{S_i}$. Since $f_{i0}$ is affine we see that $S_i = \underline{\operatorname{Spec}}_{S_0}(\mathcal{A}_i)$. Set $T_i = \underline{\operatorname{Spec}}_{T_0}(j_{0, *}\mathcal{A}_i)$. Then $T_i \to T_0$ is affine, hence $T_i$ is affine. Thus $T_i$ is the spectrum of $$R_i = \Gamma(T_0, j_{0, *}\mathcal{A}_i) = \Gamma(S_0, \mathcal{A}_i) = \Gamma(S_i, \mathcal{O}_{S_i}).$$ Write $S = \operatorname{Spec}(R)$. We have $R = \mathop{\operatorname{colim}}_i R_i$ by Lemma Descent of finite-presentation descent. Hence also $S = \varprojlim_i T_i$. As formation of the relative spectrum commutes with base change, the inverse image of the open $S_0 \subset T_0$ in $T_i$ is $S_i$. Let $Z_0 = T_0 \setminus S_0$ and let $Z_i \subset T_i$ be the inverse image of $Z_0$. As $S_i = T_i \setminus Z_i$, it suffices to show that $Z_i$ is empty for some $i$. Assume $Z_i$ is nonempty for all $i$ to get a contradiction. By Lemma Filtered limits and finite-presentation descent (uncovered prerequisite) there exists a point $s$ of $S = \varprojlim T_i$ which maps to a point of $Z_i$ for every $i$. But $S = \varprojlim_i S_i$, and hence we arrive at a contradiction by Lemma Finite-presentation descent (uncovered prerequisite). $\square$
Lemma. Descent of finite-presentation descent
In Situation A filtered inverse system for descent we have the following:
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Given any quasi-compact open $V \subset S = \varprojlim_i S_i$ there exists an $i \in I$ and a quasi-compact open $V_i \subset S_i$ such that $f_i^{-1}(V_i) = V$.
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Given $V_i \subset S_i$ and $V_{i'} \subset S_{i'}$ quasi-compact opens such that $f_i^{-1}(V_i) = f_{i'}^{-1}(V_{i'})$ there exists an index $i'' \geq i, i'$ such that $f_{i''i}^{-1}(V_i) = f_{i''i'}^{-1}(V_{i'})$.
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If $V_{1, i}, \ldots, V_{n, i} \subset S_i$ are quasi-compact opens and $S = f_i^{-1}(V_{1, i}) \cup \ldots \cup f_i^{-1}(V_{n, i})$ then $S_{i'} = f_{i'i}^{-1}(V_{1, i}) \cup \ldots \cup f_{i'i}^{-1}(V_{n, i})$ for some $i' \geq i$.
Proof. Choose $i_0 \in I$. Note that $I$ is nonempty as the limit is directed. For convenience we write $S_0 = S_{i_0}$ and $i_0 = 0$. Choose an affine open covering $S_0 = U_{1, 0} \cup \ldots \cup U_{m, 0}$. Denote $U_{j, i} \subset S_i$ the inverse image of $U_{j, 0}$ under the transition morphism for $i \geq 0$. Denote $U_j$ the inverse image of $U_{j, 0}$ in $S$. Note that $U_j = \varprojlim_i U_{j, i}$ is a limit of affine schemes.
We first prove the uniqueness statement: Let $V_i \subset S_i$ and $V_{i'} \subset S_{i'}$ quasi-compact opens such that $f_i^{-1}(V_i) = f_{i'}^{-1}(V_{i'})$. It suffices to show that $f_{i''i}^{-1}(V_i \cap U_{j, i''})$ and $f_{i''i'}^{-1}(V_{i'} \cap U_{j, i''})$ become equal for $i''$ large enough. Hence we reduce to the case of a limit of affine schemes. In this case write $S = \operatorname{Spec}(R)$ and $S_i = \operatorname{Spec}(R_i)$ for all $i \in I$. We may write $V_i = S_i \setminus V(h_1, \ldots, h_m)$ and $V_{i'} = S_{i'} \setminus V(g_1, \ldots, g_n)$. The assumption means that the ideals $\sum g_jR$ and $\sum h_jR$ have the same radical in $R$. This means that $g_j^N = \sum a_{jj'}h_{j'}$ and $h_j^N = \sum b_{jj'} g_{j'}$ for some $N \gg 0$ and $a_{jj'}$ and $b_{jj'}$ in $R$. Since $R = \mathop{\operatorname{colim}}_i R_i$ we can chose an index $i'' \geq i$ such that the equations $g_j^N = \sum a_{jj'}h_{j'}$ and $h_j^N = \sum b_{jj'} g_{j'}$ hold in $R_{i''}$ for some $a_{jj'}$ and $b_{jj'}$ in $R_{i''}$. This implies that the ideals $\sum g_jR_{i''}$ and $\sum h_jR_{i''}$ have the same radical in $R_{i''}$ as desired.
We prove existence: If $S_0$ is affine, then $S_i = \operatorname{Spec}(R_i)$ for all $i \geq 0$ and $S = \operatorname{Spec}(R)$ with $R = \mathop{\operatorname{colim}} R_i$. Then $V = S \setminus V(g_1, \ldots, g_n)$ for some $g_1, \ldots, g_n \in R$. Choose any $i$ large enough so that each of the $g_j$ comes from an element $g_{j, i} \in R_i$ and take $V_i = S_i \setminus V(g_{1, i}, \ldots, g_{n, i})$. If $S_0$ is general, then the opens $V \cap U_j$ are quasi-compact because $S$ is quasi-separated. Hence by the affine case we see that for each $j = 1, \ldots, m$ there exists an $i_j \in I$ and a quasi-compact open $V_{i_j} \subset U_{j, i_j}$ whose inverse image in $U_j$ is $V \cap U_j$. Set $i = \max(i_1, \ldots, i_m)$ and let $V_i = \bigcup f_{ii_j}^{-1}(V_{i_j})$.
The statement on coverings follows from the uniqueness statement for the opens $V_{1, i} \cup \ldots \cup V_{n, i}$ and $S_i$ of $S_i$. $\square$
Proposition. Finite presentation and diagonals and separation
Let $f : X \to S$ be a morphism of schemes. Assume
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$f$ is of finite type and separated, and
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$S$ is quasi-compact and quasi-separated.
Then there exists a separated morphism of finite presentation $f' : X' \to S$ and a closed immersion $X \to X'$ of schemes over $S$.
Proof. Apply Lemma Finite presentation and finite algebras (uncovered prerequisite) and note that $X_i \to S$ is separated for large $i$ by Lemma Diagonals and separation (uncovered prerequisite) as we have assumed that $X \to S$ is separated. $\square$
Proposition. Finite-presentation descent
Let $S$ be a quasi-compact and quasi-separated scheme. There exist a directed set $I$ and an inverse system of schemes $(S_i, f_{ii'})$ over $I$ such that
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the transition morphisms $f_{ii'}$ are affine
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each $S_i$ is of finite type over $\mathbf{Z}$, and
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$S = \varprojlim_i S_i$.
Proof. This is a special case of Lemma Approximation of a marked family with its associated graded algebra (uncovered prerequisite) with $V = \emptyset$. $\square$
Lemma. Dimension and codimension
Let $S$ be a quasi-compact and quasi-separated scheme. Let $f : X \to S$ be a morphism of finite presentation. Let $d \geq 0$ be an integer. If $Z \subset X$ be a closed subscheme such that $\dim(Z_s) \leq d$ for all $s \in S$, then there exists a closed subscheme $Z' \subset X$ such that
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$Z \subset Z'$,
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$Z' \to X$ is of finite presentation, and
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$\dim(Z'_s) \leq d$ for all $s \in S$.
Proof. By Proposition Finite-presentation descent we can write $S = \varprojlim S_i$ as the limit of a directed inverse system of Noetherian schemes with affine transition maps. By Lemma Descent of finite presentation and finite algebras we may assume that there exist a system of morphisms $f_i : X_i \to S_i$ of finite presentation such that $X_{i'} = X_i \times_{S_i} S_{i'}$ for all $i' \geq i$ and such that $X = X_i \times_{S_i} S$. Let $Z_i \subset X_i$ be the scheme theoretic image of $Z \to X \to X_i$. Then for $i' \geq i$ the morphism $X_{i'} \to X_i$ maps $Z_{i'}$ into $Z_i$ and the induced morphism $Z_{i'} \to Z_i \times_{S_i} S_{i'}$ is a closed immersion. By Lemma Filtered limits and dimension and codimension we see that the dimension of the fibres of $Z_i \to S_i$ all have dimension $\leq d$ for a suitable $i \in I$. Fix such an $i$ and set $Z' = Z_i \times_{S_i} S \subset X$. Since $S_i$ is Noetherian, we see that $X_i$ is Noetherian, and hence the morphism $Z_i \to X_i$ is of finite presentation. Therefore also the base change $Z' \to X$ is of finite presentation. Moreover, the fibres of $Z' \to S$ are base changes of the fibres of $Z_i \to S_i$ and hence have dimension $\leq d$. $\square$
Lemma. Filtered limits and dimension and codimension
Let $I$ be a directed set. Let $(f_i : X_i \to S_i)$ be an inverse system of morphisms of schemes over $I$. Assume
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all the morphisms $S_{i'} \to S_i$ are affine,
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all the schemes $S_i$ are quasi-compact and quasi-separated,
-
the morphisms $f_i$ are of finite type, and
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the morphisms $X_{i'} \to X_i \times_{S_i} S_{i'}$ are closed immersions.
Let $f : X = \varprojlim_i X_i \to S = \varprojlim_i S_i$ be the limit. Let $d \geq 0$. If every fibre of $f$ has dimension $\leq d$, then for some $i$ every fibre of $f_i$ has dimension $\leq d$.
Proof. For each $i$ let $U_i = \{x \in X_i \mid \dim_x((X_i)_{f_i(x)}) \leq d\}$. This is an open subset of $X_i$, see Morphisms, Lemma Dimension and codimension (uncovered prerequisite). Set $Z_i = X_i \setminus U_i$ (with reduced induced scheme structure). We have to show that $Z_i = \emptyset$ for some $i$. If not, then $Z = \varprojlim Z_i \not = \emptyset$, see Lemma Filtered limits and finite-presentation descent (uncovered prerequisite). Say $z \in Z$ is a point. Note that $Z \subset X$ is a closed subscheme. Set $s = f(z)$. For each $i$ let $s_i \in S_i$ be the image of $s$. We remark that $Z_s$ is the limit of the schemes $(Z_i)_{s_i}$ and $Z_s$ is also the limit of the schemes $(Z_i)_{s_i}$ base changed to $\kappa(s)$. Moreover, all the morphisms $$Z_s \longrightarrow (Z_{i'})_{s_{i'}} \times_{\operatorname{Spec}(\kappa(s_{i'}))} \operatorname{Spec}(\kappa(s)) \longrightarrow (Z_i)_{s_i} \times_{\operatorname{Spec}(\kappa(s_i))} \operatorname{Spec}(\kappa(s)) \longrightarrow X_s$$ are closed immersions by assumption (4). Hence $Z_s$ is the scheme theoretic intersection of the closed subschemes $(Z_i)_{s_i} \times_{\operatorname{Spec}(\kappa(s_i))} \operatorname{Spec}(\kappa(s))$ in $X_s$. Since all the irreducible components of the schemes $(Z_i)_{s_i} \times_{\operatorname{Spec}(\kappa(s_i))} \operatorname{Spec}(\kappa(s))$ have dimension $> d$ and contain $z$ we conclude that $Z_s$ contains an irreducible component of dimension $> d$ passing through $z$ which contradicts the fact that $Z_s \subset X_s$ and $\dim(X_s) \leq d$. $\square$
Proposition. Affine neighbourhoods
A scheme admitting a surjective integral map from an affine scheme is affine.
Let $f : X \to S$ be a morphism of schemes. Assume $X$ is affine and that $f$ is surjective and universally closed[^1]. Then $S$ is affine.
Proof. By Morphisms, Lemma Diagonals and separation (uncovered prerequisite) the scheme $S$ is separated. Then by Morphisms, Lemma Affine neighbourhoods (uncovered prerequisite) we find that $f$ is affine. Whereupon by Morphisms, Lemma Integral extensions (uncovered prerequisite) we see that $f$ is integral.
By the preceding paragraph, we may assume $f : X \to S$ is surjective and integral, $X$ is affine, and $S$ is separated. Since $f$ is surjective and $X$ is quasi-compact we also deduce that $S$ is quasi-compact.
By Lemma Finite presentation and integral extensions (uncovered prerequisite) we can write $X = \varprojlim_i X_i$ with $X_i \to S$ finite. By Lemma Filtered limits and affine neighbourhoods we see that for $i$ sufficiently large the scheme $X_i$ is affine. Moreover, since $X \to S$ factors through each $X_i$ we see that $X_i \to S$ is surjective. Hence we conclude that $S$ is affine by Lemma Affine neighbourhoods (uncovered prerequisite). $\square$
Lemma. Finite-presentation descent
Let $I$ be a directed set. Let $(S_i, f_{ii'})$ be an inverse system of schemes over $I$. Assume all the morphisms $f_{ii'} : S_i \to S_{i'}$ are affine, Let $S = \varprojlim_i S_i$. Let $0 \in I$. Suppose that $T$ is a scheme over $S_0$. Then $$T \times_{S_0} S = \varprojlim_{i \geq 0} T \times_{S_0} S_i$$
Proof. The right hand side is a scheme by Lemma Finite-presentation descent. The equality is formal, see Categories, Lemma Filtered limits and the geometric construction (uncovered prerequisite). $\square$
Lemma. Finite presentation and proper morphisms
Let $f : X \to S$ be a proper morphism with $S$ quasi-compact and quasi-separated. Then there exists a directed set $I$, an inverse system $(f_i : X_i \to S_i)$ of morphisms of schemes over $I$, such that the transition morphisms $X_i \to X_{i'}$ and $S_i \to S_{i'}$ are affine, such that $f_i$ is proper, such that $S_i$ is of finite type over $\mathbf{Z}$, and such that $(X \to S) = \varprojlim (X_i \to S_i)$.
Proof. By Lemma Finite presentation and proper morphisms (uncovered prerequisite) we can write $X = \varprojlim_{k \in K} X_k$ with $X_k \to S$ proper and of finite presentation. Next, by absolute Noetherian approximation (Proposition Finite-presentation descent) we can write $S = \varprojlim_{j \in J} S_j$ with $S_j$ of finite type over $\mathbf{Z}$. For each $k$ there exists a $j$ and a morphism $X_{k, j} \to S_j$ of finite presentation with $X_k \cong S \times_{S_j} X_{k, j}$ as schemes over $S$, see Lemma Descent of finite presentation and finite algebras. After increasing $j$ we may assume $X_{k, j} \to S_j$ is proper, see Lemma Proper morphisms. The set $I$ will be consist of these pairs $(k, j)$ and the corresponding morphism is $X_{k, j} \to S_j$. For every $k' \geq k$ we can find a $j' \geq j$ and a morphism $X_{j', k'} \to X_{j, k}$ over $S_{j'} \to S_j$ whose base change to $S$ gives the morphism $X_{k'} \to X_k$ (follows again from Lemma Descent of finite presentation and finite algebras). These morphisms form the transition morphisms of the system. Some details omitted. $\square$
Remark. Filtered limits and finite-presentation descent
Let $S$ be a scheme. Let us say that a functor $F : (\mathrm{Sch}/S)^{opp} \to \textit{Sets}$ is limit preserving if for every directed inverse system $\{T_i\}_{i \in I}$ of affine schemes with limit $T$ we have $F(T) = \mathop{\operatorname{colim}}_i F(T_i)$. Let $X$ be a scheme over $S$, and let $h_X : (\mathrm{Sch}/S)^{opp} \to \textit{Sets}$ be its functor of points, see Schemes, Section The geometric construction. In this terminology Proposition Criteria for finite presentation and finite algebras (uncovered prerequisite) says that a scheme $X$ is locally of finite presentation over $S$ if and only if $h_X$ is limit preserving.
Lemma. Finite-presentation descent
Let $I$ be a directed set. Let $(S_i, f_{ii'})$ be an inverse system of schemes over $I$. If all the morphisms $f_{ii'} : S_i \to S_{i'}$ are affine, then the limit $S = \varprojlim_i S_i$ exists in the category of schemes. Moreover,
-
each of the morphisms $f_i : S \to S_i$ is affine,
-
for an element $0 \in I$ and any open subscheme $U_0 \subset S_0$ we have $$f_0^{-1}(U_0) = \varprojlim_{i \geq 0} f_{i0}^{-1}(U_0)$$ in the category of schemes.
Proof. Choose an element $0 \in I$. Note that $I$ is nonempty as the limit is directed. For every $i \geq 0$ consider the quasi-coherent sheaf of $\mathcal{O}_{S_0}$-algebras $\mathcal{A}_i = f_{i0, *}\mathcal{O}_{S_i}$. Recall that $S_i = \underline{\operatorname{Spec}}_{S_0}(\mathcal{A}_i)$, see Morphisms, Lemma Criteria for affine neighbourhoods (uncovered prerequisite). Set $\mathcal{A} = \mathop{\operatorname{colim}}_{i \geq 0} \mathcal{A}_i$. This is a quasi-coherent sheaf of $\mathcal{O}_{S_0}$-algebras, see Schemes, Section Quasi-coherent complexes and coherent sheaves. Set $S = \underline{\operatorname{Spec}}_{S_0}(\mathcal{A})$. By Morphisms, Lemma Affine neighbourhoods and groupoids and equivalence relations (uncovered prerequisite) we get for $i \geq 0$ morphisms $f_i : S \to S_i$ compatible with the transition morphisms. Note that the morphisms $f_i$ are affine by Morphisms, Lemma Affine neighbourhoods (uncovered prerequisite) for example. By Lemma Affine neighbourhoods (uncovered prerequisite) above we see that for any affine open $U_0 \subset S_0$ the inverse image $U = f_0^{-1}(U_0) \subset S$ is the limit of the system of opens $U_i = f_{i0}^{-1}(U_0)$, $i \geq 0$ in the category of schemes.
Let $T$ be a scheme. Let $g_i : T \to S_i$ be a compatible system of morphisms. To show that $S = \varprojlim_i S_i$ we have to prove there is a unique morphism $g : T \to S$ with $g_i = f_i \circ g$ for all $i \in I$. For every $t \in T$ there exists an affine open $U_0 \subset S_0$ containing $g_0(t)$. Let $V \subset g_0^{-1}(U_0)$ be an affine open neighbourhood containing $t$. By the remarks above we obtain a unique morphism $g_V : V \to U = f_0^{-1}(U_0)$ such that $f_i \circ g_V = g_i|_{U_i}$ for all $i$. The open sets $V \subset T$ so constructed form a basis for the topology of $T$. The morphisms $g_V$ glue to a morphism $g : T \to S$ because of the uniqueness property. This gives the desired morphism $g : T \to S$.
The final statement is clear from the construction of the limit above. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $X = \varprojlim X_i$ be a directed limit of schemes over $S$ with affine transition morphisms. Let $Y \to X$ be a morphism of schemes over $S$.
-
If $Y \to X$ is a closed immersion, $X_i$ quasi-compact, and $Y$ locally of finite type over $S$, then $Y \to X_i$ is a closed immersion for $i$ large enough.
-
If $Y \to X$ is an immersion, $X_i$ quasi-separated, $Y \to S$ locally of finite type, and $Y$ quasi-compact, then $Y \to X_i$ is an immersion for $i$ large enough.
-
If $Y \to X$ is an isomorphism, $X_i$ quasi-compact, $X_i \to S$ locally of finite type, the transition morphisms $X_{i'} \to X_i$ are closed immersions, and $Y \to S$ is locally of finite presentation, then $Y \to X_i$ is an isomorphism for $i$ large enough.
Proof. Proof of (1). Choose $0 \in I$ and a finite affine open covering $X_0 = U_{0, 1} \cup \ldots \cup U_{0, m}$ with the property that $U_{0, j}$ maps into an affine open $W_j \subset S$. Let $V_j \subset Y$, resp. $U_{i, j} \subset X_i$, $i \geq 0$, resp. $U_j \subset X$ be the inverse image of $U_{0, j}$. It suffices to prove that $V_j \to U_{i, j}$ is a closed immersion for $i$ sufficiently large and we know that $V_j \to U_j$ is a closed immersion. Thus we reduce to the following algebra fact: If $A = \mathop{\operatorname{colim}} A_i$ is a directed colimit of $R$-algebras, $A \to B$ is a surjection of $R$-algebras, and $B$ is a finitely generated $R$-algebra, then $A_i \to B$ is surjective for $i$ sufficiently large.
Proof of (2). Choose $0 \in I$. Choose a quasi-compact open $X'_0 \subset X_0$ such that $Y \to X_0$ factors through $X'_0$. After replacing $X_i$ by the inverse image of $X'_0$ for $i \geq 0$ we may assume all $X_i'$ are quasi-compact and quasi-separated. Let $U \subset X$ be a quasi-compact open such that $Y \to X$ factors through a closed immersion $Y \to U$ ($U$ exists as $Y$ is quasi-compact). By Lemma Descent of finite-presentation descent we may assume that $U = \varprojlim U_i$ with $U_i \subset X_i$ quasi-compact open. By part (1) we see that $Y \to U_i$ is a closed immersion for some $i$. Thus (2) holds.
Proof of (3). Working affine locally on $X_0$ for some $0 \in I$ as in the proof of (1) we reduce to the following algebra fact: If $A = \varprojlim A_i$ is a directed colimit of $R$-algebras with surjective transition maps and $A$ of finite presentation over $A_0$, then $A = A_i$ for some $i$. Namely, write $A = A_0/(f_1, \ldots, f_n)$. Pick $i$ such that $f_1, \ldots, f_n$ map to zero under the surjective map $A_0 \to A_i$. $\square$
[^1]: An integral morphism is universally closed, see Morphisms, Lemma Integral extensions (uncovered prerequisite).
Purity and flattening on algebraic spaces
Situation. Purity near a specified fibre
Let $S$ be a scheme. Let $f : X \to Y$ be a finite type, decent[^1] morphism of algebraic spaces over $S$. Also, $\mathcal{F}$ is a finite type quasi-coherent $\mathcal{O}_X$-module. Finally $y \in |Y|$ is a point of $Y$.
Lemma. A module supported on a closed subspace
In Situation Purity near a specified fibre. Let $i : Z \to X$ be a closed immersion and assume that $\mathcal{F} = i_*\mathcal{G}$ for some finite type, quasi-coherent sheaf $\mathcal{G}$ on $Z$. Then $\mathcal{G}$ is (universally) pure above $y$ if and only if $\mathcal{F}$ is (universally) pure above $y$.
Proof. This follows from Divisors on Spaces, Lemma Prime spectra, associated points and finite algebras. $\square$
Lemma. Quasi-finite base change
In Situation Purity near a specified fibre. Let $(Y', y') \to (Y, y)$ be a morphism of pointed algebraic spaces. If $Y' \to Y$ is quasi-finite at $y'$ and $\mathcal{F}$ is pure above $y$, then $\mathcal{F}_{Y'}$ is pure above $y'$.
Proof. It $(T \to Y', t' \leadsto t, \xi)$ is an impurity of $\mathcal{F}_{Y'}$ above $y'$ with $T \to Y'$ quasi-finite at $t$, then $(T \to Y, t' \to t, \xi)$ is an impurity of $\mathcal{F}$ above $y$ with $T \to Y$ quasi-finite at $t$, see Morphisms of Spaces, Lemma Composition and finite algebras. Hence the lemma follows immediately from the definition of purity. $\square$
[^1]: Quasi-separated morphisms are decent, see Decent Spaces, Lemma Proper morphisms. For any morphism $\operatorname{Spec}(k) \to Y$ where $k$ is a field, the algebraic space $X_k$ is of finite presentation over $k$ because it is of finite type over $k$ and quasi-separated by Decent Spaces, Lemma Diagonals, separation and Noetherian rings.
Geometric support constructions
Lemma. Descent of the geometric construction
Let $\tau \in \{Zariski, fppf, \mathrm{\acute{e}tale}, smooth, syntomic\}$[^1]. Let $\mathrm{Sch}_\tau$ be a big $\tau$-site. Let $S \in \operatorname{Ob}(\mathrm{Sch}_\tau)$. Let $\{S_i \to S\}_{i \in I}$ be a covering in the site $(\mathrm{Sch}/S)_\tau$. There is an equivalence of categories $$\left\{ \begin{matrix} \text{descent data }(X_i, \varphi_{ii'})\text{ such that}\\ \text{each }X_i \in \operatorname{Ob}((\mathrm{Sch}/S)_\tau) \end{matrix} \right\} \leftrightarrow \left\{ \begin{matrix} \text{sheaves }F\text{ on }(\mathrm{Sch}/S)_\tau\text{ such that}\\ \text{each }h_{S_i} \times F\text{ is representable} \end{matrix} \right\}.$$ Moreover,
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the objects representing $h_{S_i} \times F$ on the right hand side correspond to the schemes $X_i$ on the left hand side, and
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the sheaf $F$ is representable if and only if the corresponding descent datum $(X_i, \varphi_{ii'})$ is effective.
Proof. We have seen in Section The geometric construction that representable presheaves are sheaves on the site $(\mathrm{Sch}/S)_\tau$. Moreover, the Yoneda lemma (Categories, Lemma The geometric construction (uncovered prerequisite)) guarantees that maps between representable sheaves correspond one to one with maps between the representing objects. We will use these remarks without further mention during the proof.
Let us construct the functor from right to left. Let $F$ be a sheaf on $(\mathrm{Sch}/S)_\tau$ such that each $h_{S_i} \times F$ is representable. In this case let $X_i$ be a representing object in $(\mathrm{Sch}/S)_\tau$. It comes equipped with a morphism $X_i \to S_i$. Then both $X_i \times_S S_{i'}$ and $S_i \times_S X_{i'}$ represent the sheaf $h_{S_i} \times F \times h_{S_{i'}}$ and hence we obtain an isomorphism $$\varphi_{ii'} : X_i \times_S S_{i'} \to S_i \times_S X_{i'}$$ It is straightforward to see that the maps $\varphi_{ii'}$ are morphisms over $S_i \times_S S_{i'}$ and satisfy the cocycle condition. The functor from right to left is given by this construction $F \mapsto (X_i, \varphi_{ii'})$.
Let us construct a functor from left to right. For each $i$ denote by $F_i$ the sheaf $h_{X_i}$. The isomorphisms $\varphi_{ii'}$ give isomorphisms $$\varphi_{ii'} : F_i \times h_{S_{i'}} \longrightarrow h_{S_i} \times F_{i'}$$ over $h_{S_i} \times h_{S_{i'}}$. Set $F$ equal to the coequalizer in the following diagram $$\begin{gathered}\begin{matrix}\coprod_{i, i'} F_i \times h_{S_{i'}} & \phantom{X} & \coprod_i F_i & F\end{matrix} \\[6pt] \begin{aligned}\coprod_{i, i'} F_i \times h_{S_{i'}} & \xrightarrow{\text{pr}_0} \coprod_i F_i \\ \coprod_{i, i'} F_i \times h_{S_{i'}} & \xrightarrow{\text{pr}_1 \circ \varphi_{ii'}} \coprod_i F_i \\ \coprod_i F_i & \longrightarrow F\end{aligned}\end{gathered}$$ The cocycle condition guarantees that $h_{S_i} \times F$ is isomorphic to $F_i$ and hence representable. The functor from left to right is given by this construction $(X_i, \varphi_{ii'}) \mapsto F$.
We omit the verification that these constructions are mutually quasi-inverse functors. The final statements (1) and (2) follow from the constructions. $\square$
Lemma. Descent of proper morphisms
The property $\mathcal{P}(f) =$"$f$ is a monomorphism" is fpqc local on the base.
Proof. Let $f : X \to S$ be a morphism of schemes. Let $\{S_i \to S\}$ be an fpqc covering, and assume each of the base changes $f_i : X_i \to S_i$ of $f$ is a monomorphism. Let $a, b : T \to X$ be two morphisms such that $f \circ a = f \circ b$. We have to show that $a = b$. Since $f_i$ is a monomorphism we see that $a_i = b_i$, where $a_i, b_i : S_i \times_S T \to X_i$ are the base changes. In particular the compositions $S_i \times_S T \to T \to X$ are equal. Since $\coprod S_i \times_S T \to T$ is an epimorphism (see e.g. Lemma The geometric construction) we conclude $a = b$. $\square$
Lemma. Descent of finite presentation and proper morphisms
The property $\mathcal{P}(f) =$"$f$ is of finite presentation" is fpqc local on the base.
Proof. Combine Lemmas Descent of proper morphisms, Descent of proper morphisms and diagonals and separation and Descent of finite presentation and proper morphisms. $\square$
Lemma. Descent of projective, locally free modules and proper morphisms
The property $\mathcal{P}(f) =$"$f$ is finite locally free" is fpqc local on the base. Let $d \geq 0$. The property $\mathcal{P}(f) =$"$f$ is finite locally free of degree $d$" is fpqc local on the base.
Proof. Being finite locally free is equivalent to being finite, flat and locally of finite presentation (Morphisms, Lemma Flatness and finite algebras (uncovered prerequisite)). Hence this follows from Lemmas Descent of proper morphisms and finite algebras (uncovered prerequisite), Descent of flatness and proper morphisms, and Descent of finite presentation and proper morphisms. If $f : Z \to U$ is finite locally free, and $\{U_i \to U\}$ is a surjective family of morphisms such that each pullback $Z \times_U U_i \to U_i$ has degree $d$, then $Z \to U$ has degree $d$, for example because we can read off the degree in a point $u \in U$ from the fibre $(f_*\mathcal{O}_Z)_u \otimes_{\mathcal{O}_{U, u}} \kappa(u)$. $\square$
Lemma. Comparison for sheaves on ringed sites
Let $S$ be a scheme. Denote $$\begin{matrix} \text{id}_{\tau, Zar} & : & (\mathrm{Sch}/S)_\tau \to S_{Zar}, & \tau \in \{Zar, \mathrm{\acute{e}tale}, smooth, syntomic, fppf\} \\ \text{id}_{\tau, \mathrm{\acute{e}tale}} & : & (\mathrm{Sch}/S)_\tau \to S_\mathrm{\acute{e}tale}, & \tau \in \{\mathrm{\acute{e}tale}, smooth, syntomic, fppf\} \\ \text{id}_{small, \mathrm{\acute{e}tale}, Zar} & : & S_\mathrm{\acute{e}tale} \to S_{Zar}, \end{matrix}$$ the morphisms of ringed sites of Remark The geometric construction. Let $\mathcal{F}$ be a sheaf of $\mathcal{O}_S$-modules which we view a sheaf of $\mathcal{O}$-modules on $S_{Zar}$. Then
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$(\text{id}_{\tau, Zar})^*\mathcal{F}$ is the $\tau$-sheafification of the Zariski sheaf $$(f : T \to S) \longmapsto \Gamma(T, f^*\mathcal{F})$$ on $(\mathrm{Sch}/S)_\tau$, and
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$(\text{id}_{small, \mathrm{\acute{e}tale}, Zar})^*\mathcal{F}$ is the étale sheafification of the Zariski sheaf $$(f : T \to S) \longmapsto \Gamma(T, f^*\mathcal{F})$$ on $S_\mathrm{\acute{e}tale}$.
Let $\mathcal{G}$ be a sheaf of $\mathcal{O}$-modules on $S_\mathrm{\acute{e}tale}$. Then
- $(\text{id}_{\tau, \mathrm{\acute{e}tale}})^*\mathcal{G}$ is the $\tau$-sheafification of the étale sheaf $$(f : T \to S) \longmapsto \Gamma(T, f_{small}^*\mathcal{G})$$ where $f_{small} : T_\mathrm{\acute{e}tale} \to S_\mathrm{\acute{e}tale}$ is the morphism of ringed small étale sites of Remark The geometric construction.
Proof. Proof of (1). We first note that the result is true when $\tau = Zar$ because in that case we have the morphism of topoi $i_f : \operatorname{Sh}(T_{Zar}) \to \operatorname{Sh}((\mathrm{Sch}/S)_{Zar})$ such that $\text{id}_{\tau, Zar} \circ i_f = f_{small}$ as morphisms $T_{Zar} \to S_{Zar}$, see Topologies, Lemmas The geometric construction (uncovered prerequisite) and The geometric construction (uncovered prerequisite). Since pullback is transitive (see Modules on Sites, Lemma Modules (uncovered prerequisite)) we see that $i_f^*(\text{id}_{\tau, Zar})^*\mathcal{F} = f_{small}^*\mathcal{F}$ as desired. Hence, by the remark preceding this lemma we see that $(\text{id}_{\tau, Zar})^*\mathcal{F}$ is the $\tau$-sheafification of the presheaf $T \mapsto \Gamma(T, f^*\mathcal{F})$.
The proof of (3) is exactly the same as the proof of (1), except that it uses Topologies, Lemmas Étale morphisms (uncovered prerequisite) and Étale morphisms (uncovered prerequisite). We omit the proof of (2). $\square$
Definition. The structure sheaf on the descent site
Let \(\tau \in \{Zariski, \mathrm{\acute{e}tale}, smooth, syntomic, fppf\}\). Let $S$ be a scheme. Let $\mathrm{Sch}_\tau$ be a big site containing $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_S$-module.
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The structure sheaf of the big site $(\mathrm{Sch}/S)_\tau$ is the sheaf of rings $T/S \mapsto \Gamma(T, \mathcal{O}_T)$ which is denoted $\mathcal{O}$ or $\mathcal{O}_S$.
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If $\tau = Zariski$ or $\tau = \mathrm{\acute{e}tale}$ the structure sheaf of the small site $S_{Zar}$ or $S_\mathrm{\acute{e}tale}$ is the sheaf of rings $T/S \mapsto \Gamma(T, \mathcal{O}_T)$ which is denoted $\mathcal{O}$ or $\mathcal{O}_S$.
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The sheaf of $\mathcal{O}$-modules associated to $\mathcal{F}$ on the big site $(\mathrm{Sch}/S)_\tau$ is the sheaf of $\mathcal{O}$-modules $(f : T \to S) \mapsto \Gamma(T, f^*\mathcal{F})$ which is denoted $\mathcal{F}^a$ (and often simply $\mathcal{F}$).
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If $\tau = Zariski$ or $\tau = \mathrm{\acute{e}tale}$ the sheaf of $\mathcal{O}$-modules associated to $\mathcal{F}$ on the small site $S_{Zar}$ or $S_\mathrm{\acute{e}tale}$ is the sheaf of $\mathcal{O}$-modules $(f : T \to S) \mapsto \Gamma(T, f^*\mathcal{F})$ which is denoted $\mathcal{F}^a$ (and often simply $\mathcal{F}$).
Lemma. Sheaves on ringed sites
Let $S$ be a scheme. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_S$-module. Let \(\tau \in \{Zariski, \mathrm{\acute{e}tale}, smooth, syntomic, fppf, fpqc\}\). The functor defined in (Quasi-coherent complexes and coherent sheaves) satisfies the sheaf condition with respect to any $\tau$-covering $\{T_i \to T\}_{i \in I}$ of any scheme $T$ over $S$.
Proof. For \(\tau \in \{Zariski, \mathrm{\acute{e}tale}, smooth, syntomic, fppf\}\) a $\tau$-covering is also a fpqc-covering, see the results in Topologies, Lemmas Étale morphisms (uncovered prerequisite), Étale morphisms and smooth morphisms (uncovered prerequisite), Étale morphisms and smooth morphisms (uncovered prerequisite), Étale morphisms and smooth morphisms (uncovered prerequisite), and Étale morphisms and smooth morphisms (uncovered prerequisite). Hence it suffices to prove the theorem for a fpqc covering. Assume that $\{f_i : T_i \to T\}_{i \in I}$ is an fpqc covering where $f : T \to S$ is given. Suppose that we have a family of sections $s_i \in \Gamma(T_i , f_i^*f^*\mathcal{F})$ such that $s_i|_{T_i \times_T T_j} = s_j|_{T_i \times_T T_j}$. We have to find the correspond section $s \in \Gamma(T, f^*\mathcal{F})$. We can reinterpret the $s_i$ as a family of maps $\varphi_i : f_i^*\mathcal{O}_T = \mathcal{O}_{T_i} \to f_i^*f^*\mathcal{F}$ compatible with the canonical descent data associated to the quasi-coherent sheaves $\mathcal{O}_T$ and $f^*\mathcal{F}$ on $T$. Hence by Proposition Quasi-coherent complexes and coherent sheaves we see that we may (uniquely) descend these to a map $\mathcal{O}_T \to f^*\mathcal{F}$ which gives us our section $s$. $\square$
Proposition. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let \(\tau \in \{Zariski, \mathrm{\acute{e}tale}, smooth, syntomic, fppf\}\).
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The functor $\mathcal{F} \mapsto \mathcal{F}^a$ defines an equivalence of categories $$\mathrm{QCoh}(\mathcal{O}_S) \longrightarrow \mathrm{QCoh}((\mathrm{Sch}/S)_\tau, \mathcal{O})$$ between the category of quasi-coherent sheaves on $S$ and the category of quasi-coherent $\mathcal{O}$-modules on the big $\tau$ site of $S$.
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Let $\tau = Zariski$ or $\tau = \mathrm{\acute{e}tale}$. The functor $\mathcal{F} \mapsto \mathcal{F}^a$ defines an equivalence of categories $$\mathrm{QCoh}(\mathcal{O}_S) \longrightarrow \mathrm{QCoh}(S_\tau, \mathcal{O})$$ between the category of quasi-coherent sheaves on $S$ and the category of quasi-coherent $\mathcal{O}$-modules on the small $\tau$ site of $S$.
Proof. We have seen in Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite) that the functor is well defined. By Lemma Prime spectra and associated points (uncovered prerequisite) the functor is fully faithful. To finish the proof we will show that a quasi-coherent $\mathcal{O}$-module on $(\mathrm{Sch}/S)_\tau$ gives rise to a descent datum for quasi-coherent sheaves relative to a $\tau$-covering of $S$. Having produced this descent datum we will appeal to Proposition Quasi-coherent complexes and coherent sheaves to get the corresponding quasi-coherent sheaf on $S$.
Let $\mathcal{G}$ be a quasi-coherent $\mathcal{O}$-modules on the big $\tau$ site of $S$. By Modules on Sites, Definition Local ringed sites there exists a $\tau$-covering $\{S_i \to S\}_{i \in I}$ of $S$ such that each of the restrictions $\mathcal{G}|_{(\mathrm{Sch}/S_i)_\tau}$ has a global presentation $$\bigoplus\nolimits_{k \in K_i} \mathcal{O}|_{(\mathrm{Sch}/S_i)_\tau} \longrightarrow \bigoplus\nolimits_{j \in J_i} \mathcal{O}|_{(\mathrm{Sch}/S_i)_\tau} \longrightarrow \mathcal{G}|_{(\mathrm{Sch}/S_i)_\tau} \longrightarrow 0$$ for some index sets $J_i$ and $K_i$. We claim that this implies that $\mathcal{G}|_{(\mathrm{Sch}/S_i)_\tau}$ is $\mathcal{F}_i^a$ for some quasi-coherent sheaf $\mathcal{F}_i$ on $S_i$. Namely, this is clear for the direct sums $\bigoplus\nolimits_{k \in K_i} \mathcal{O}|_{(\mathrm{Sch}/S_i)_\tau}$ and $\bigoplus\nolimits_{j \in J_i} \mathcal{O}|_{(\mathrm{Sch}/S_i)_\tau}$. Hence we see that $\mathcal{G}|_{(\mathrm{Sch}/S_i)_\tau}$ is a cokernel of a map $\varphi : \mathcal{K}_i^a \to \mathcal{L}_i^a$ for some quasi-coherent sheaves $\mathcal{K}_i$, $\mathcal{L}_i$ on $S_i$. By the fully faithfulness of $(\ )^a$ we see that $\varphi = \phi^a$ for some map of quasi-coherent sheaves $\phi : \mathcal{K}_i \to \mathcal{L}_i$ on $S_i$. Then it is clear that $\mathcal{G}|_{(\mathrm{Sch}/S_i)_\tau} \cong \operatorname{Coker}(\phi)^a$ as claimed.
Since $\mathcal{G}$ lives on all of the category $(\mathrm{Sch}/S)_\tau$ we see that $$(\text{pr}_0^*\mathcal{F}_i)^a \cong \mathcal{G}|_{(\mathrm{Sch}/(S_i \times_S S_j))_\tau} \cong (\text{pr}_1^*\mathcal{F})^a$$ as $\mathcal{O}$-modules on $(\mathrm{Sch}/(S_i \times_S S_j))_\tau$. Hence, using fully faithfulness again we get canonical isomorphisms $$\phi_{ij} : \text{pr}_0^*\mathcal{F}_i \longrightarrow \text{pr}_1^*\mathcal{F}_j$$ of quasi-coherent modules over $S_i \times_S S_j$. We omit the verification that these satisfy the cocycle condition. Since they do we see by effectivity of descent for quasi-coherent sheaves and the covering $\{S_i \to S\}$ (Proposition Quasi-coherent complexes and coherent sheaves) that there exists a quasi-coherent sheaf $\mathcal{F}$ on $S$ with $\mathcal{F}|_{S_i} \cong \mathcal{F}_i$ compatible with the given descent data. In other words we are given $\mathcal{O}$-module isomorphisms $$\phi_i : \mathcal{F}^a|_{(\mathrm{Sch}/S_i)_\tau} \longrightarrow \mathcal{G}|_{(\mathrm{Sch}/S_i)_\tau}$$ which agree over $S_i \times_S S_j$. Hence, since $\mathcal{H}om_\mathcal{O}(\mathcal{F}^a, \mathcal{G})$ is a sheaf (Modules on Sites, Lemma Derived Hom and Ext (uncovered prerequisite)), we conclude that there is a morphism of $\mathcal{O}$-modules $\mathcal{F}^a \to \mathcal{G}$ recovering the isomorphisms $\phi_i$ above. Hence this is an isomorphism and we win.
The case of the sites $S_\mathrm{\acute{e}tale}$ and $S_{Zar}$ is proved in the exact same manner. $\square$
Proposition. Quasi-coherent complexes and sheaf cohomology
Cohomology of quasi-coherent sheaves is the same no matter which topology you use.
Let $S$ be a scheme. Let $\mathcal{F}$ be a quasi-coherent sheaf on $S$. Let \(\tau \in \{Zariski, \mathrm{\acute{e}tale}, smooth, syntomic, fppf\}\).
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There is a canonical isomorphism $$H^q(S, \mathcal{F}) = H^q((\mathrm{Sch}/S)_\tau, \mathcal{F}^a).$$
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There are canonical isomorphisms $$H^q(S, \mathcal{F}) = H^q(S_{Zar}, \mathcal{F}^a) = H^q(S_\mathrm{\acute{e}tale}, \mathcal{F}^a).$$
Proof. The result for $q = 0$ is clear from the definition of $\mathcal{F}^a$. Let $\mathcal{C} = (\mathrm{Sch}/S)_\tau$, or $\mathcal{C} = S_\mathrm{\acute{e}tale}$, or $\mathcal{C} = S_{Zar}$.
We are going to apply Cohomology on Sites, Lemma Sheaf cohomology (uncovered prerequisite) with $\mathcal{F} = \mathcal{F}^a$, $\mathcal{B} \subset \operatorname{Ob}(\mathcal{C})$ the set of affine schemes in $\mathcal{C}$, and $\text{Cov} \subset \text{Cov}_\mathcal{C}$ the set of standard affine $\tau$-coverings. Assumption (3) of the lemma is satisfied by Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). Hence we conclude that $H^p(U, \mathcal{F}^a) = 0$ for every affine object $U$ of $\mathcal{C}$.
Next, let $U \in \operatorname{Ob}(\mathcal{C})$ be any separated object. Denote $f : U \to S$ the structure morphism. Let $U = \bigcup U_i$ be an affine open covering. We may also think of this as a $\tau$-covering $\mathcal{U} = \{U_i \to U\}$ of $U$ in $\mathcal{C}$. Note that $U_{i_0} \times_U \ldots \times_U U_{i_p} = U_{i_0} \cap \ldots \cap U_{i_p}$ is affine as we assumed $U$ separated. By Cohomology on Sites, Lemma Sheaf cohomology (uncovered prerequisite) and the result above we see that $$H^p(U, \mathcal{F}^a) = \check{H}^p(\mathcal{U}, \mathcal{F}^a) = H^p(U, f^*\mathcal{F})$$ the last equality by Cohomology of Schemes, Lemma Quasi-coherent complexes and sheaf cohomology (uncovered prerequisite). In particular, if $S$ is separated we can take $U = S$ and $f = \text{id}_S$ and the proposition is proved. We suggest the reader skip the rest of the proof (or rewrite it to give a clearer exposition).
Choose an injective resolution $\mathcal{F} \to \mathcal{I}^\bullet$ on $S$. Choose an injective resolution $\mathcal{F}^a \to \mathcal{J}^\bullet$ on $\mathcal{C}$. Denote $\mathcal{J}^n|_S$ the restriction of $\mathcal{J}^n$ to opens of $S$; this is a sheaf on the topological space $S$ as open coverings are $\tau$-coverings. We get a complex $$0 \to \mathcal{F} \to \mathcal{J}^0|_S \to \mathcal{J}^1|_S \to \ldots$$ which is exact since its sections over any affine open $U \subset S$ is exact (by the vanishing of $H^p(U, \mathcal{F}^a)$, $p > 0$ seen above). Hence by Derived Categories, Lemma Triangulated categories (uncovered prerequisite) there exists map of complexes $\mathcal{J}^\bullet|_S \to \mathcal{I}^\bullet$ which in particular induces a map $$R\Gamma(\mathcal{C}, \mathcal{F}^a)
\Gamma(S, \mathcal{J}^\bullet) \longrightarrow \Gamma(S, \mathcal{I}^\bullet)
R\Gamma(S, \mathcal{F}).$$ Taking cohomology gives the map $H^n(\mathcal{C}, \mathcal{F}^a) \to H^n(S, \mathcal{F})$ which we have to prove is an isomorphism. Let $\mathcal{U} : S = \bigcup U_i$ be an affine open covering which we may think of as a $\tau$-covering also. By the above we get a map of double complexes $$\check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{J})
\check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{J}|_S) \longrightarrow \check{\mathcal{C}}^\bullet(\mathcal{U}, \mathcal{I}).$$ This map induces a map of spectral sequences $${}^\tau! E_2^{p, q} = \check{H}^p(\mathcal{U}, \underline{H}^q(\mathcal{F}^a)) \longrightarrow E_2^{p, q} = \check{H}^p(\mathcal{U}, \underline{H}^q(\mathcal{F}))$$ The first spectral sequence converges to $H^{p + q}(\mathcal{C}, \mathcal{F})$ and the second to $H^{p + q}(S, \mathcal{F})$. On the other hand, we have seen that the induced maps ${}^\tau! E_2^{p, q} \to E_2^{p, q}$ are bijections (as all the intersections are separated being opens in affines). Whence also the maps $H^n(\mathcal{C}, \mathcal{F}^a) \to H^n(S, \mathcal{F})$ are isomorphisms, and we win. $\square$
Lemma. Comparison for étale morphisms and flatness
In Lemma Comparison for sheaves on ringed sites the morphism of ringed sites $\text{id}_{small, \mathrm{\acute{e}tale}, Zar} : S_\mathrm{\acute{e}tale} \to S_{Zar}$ is flat.
Proof. Let us denote $\epsilon = \text{id}_{small, \mathrm{\acute{e}tale}, Zar}$ and $\mathcal{O}_\mathrm{\acute{e}tale}$ and $\mathcal{O}_{Zar}$ the structure sheaves on $S_\mathrm{\acute{e}tale}$ and $S_{Zar}$. We have to show that $\mathcal{O}_\mathrm{\acute{e}tale}$ is a flat $\epsilon^{-1}\mathcal{O}_{Zar}$-module. Recall that étale morphisms are open, see Morphisms, Lemma Étale morphisms (uncovered prerequisite). It follows (from the construction of pullback on sheaves) that $\epsilon^{-1}\mathcal{O}_{Zar}$ is the sheafification of the presheaf $\mathcal{O}'$ on $S_\mathrm{\acute{e}tale}$ which sends an étale morphism $f : V \to S$ to $\mathcal{O}_S(f(V))$. If both $V$ and $U = f(V) \subset S$ are affine, then $V \to U$ is an étale morphism of affines, hence corresponds to an étale ring map. Since étale ring maps are flat, we see that $\mathcal{O}_S(U) = \mathcal{O}'(V) \to \mathcal{O}_\mathrm{\acute{e}tale}(V) = \mathcal{O}_V(V)$ is flat. Finally, for every étale morphism $f : V \to S$, i.e., object of $S_\mathrm{\acute{e}tale}$, there is an affine open covering $V = \bigcup V_i$ such that $f(V_i)$ is an affine open in $S$ for all $i$[^2]. Thus the result by Modules on Sites, Lemma Flatness and sheaves on ringed sites (uncovered prerequisite). $\square$
Lemma. Descent of the geometric construction
Let $\mathcal{P}$ be a property of morphisms of schemes over a base. Let $\tau \in \{fpqc, fppf, \mathrm{\acute{e}tale}, smooth, syntomic\}$. Suppose that
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$\mathcal{P}$ is stable under any base change (see Schemes, Definition Base change for the geometric construction),
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if $Y_j \to V_j$, $j = 1, \ldots, m$ have $\mathcal{P}$, then so does $\coprod Y_j \to \coprod V_j$, and
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for any surjective morphism of affines $X \to S$ which is flat, flat of finite presentation, étale, smooth or syntomic depending on whether $\tau$ is fpqc, fppf, étale, smooth, or syntomic, any descent datum $(V, \varphi)$ relative to $X$ over $S$ such that $\mathcal{P}$ holds for $V \to X$ is effective.
Then morphisms of type $\mathcal{P}$ satisfy descent for $\tau$-coverings.
Proof. Let $S$ be a scheme. Let $\mathcal{U} = \{\varphi_i : U_i \to S\}_{i \in I}$ be a $\tau$-covering of $S$. Let $(X_i, \varphi_{ii'})$ be a descent datum relative to $\mathcal{U}$ and assume that each morphism $X_i \to U_i$ has property $\mathcal{P}$. We have to show there exists a scheme $X \to S$ such that $(X_i, \varphi_{ii'}) \cong (U_i \times_S X, can)$.
Before we start the proof proper we remark that for any family of morphisms $\mathcal{V} : \{V_j \to S\}$ and any morphism of families $\mathcal{V} \to \mathcal{U}$, if we pull back the descent datum $(X_i, \varphi_{ii'})$ to a descent datum $(Y_j, \varphi_{jj'})$ over $\mathcal{V}$, then each of the morphisms $Y_j \to V_j$ has property $\mathcal{P}$ also. This is true because of assumption (1) that $\mathcal{P}$ is stable under any base change and the definition of pullback (see Definition Pullback of derived tensor products and Tor amplitude). We will use this without further mention.
First, let us prove the lemma when $S$ is affine. By Topologies, Lemma Affine neighbourhoods (uncovered prerequisite), Affine neighbourhoods (uncovered prerequisite), Étale morphisms and affine neighbourhoods (uncovered prerequisite), Smooth morphisms and affine neighbourhoods (uncovered prerequisite), or Affine neighbourhoods (uncovered prerequisite) there exists a standard $\tau$-covering $\mathcal{V} : \{V_j \to S\}_{j = 1, \ldots, m}$ which refines $\mathcal{U}$. The pullback functor $DD(\mathcal{U}) \to DD(\mathcal{V})$ between categories of descent data is fully faithful by Lemma The geometric construction (uncovered prerequisite). Hence it suffices to prove that the descent datum over the standard $\tau$-covering $\mathcal{V}$ is effective. By assumption (2) we see that $\coprod Y_j \to \coprod V_j$ has property $\mathcal{P}$. By Lemma The geometric construction (uncovered prerequisite) this reduces us to the covering $\{\coprod_{j = 1, \ldots, m} V_j \to S\}$ for which we have assumed the result in assumption (3) of the lemma. Hence the lemma holds when $S$ is affine.
Assume $S$ is general. Let $V \subset S$ be an affine open. By the properties of site the family $\mathcal{U}_V = \{V \times_S U_i \to V\}_{i \in I}$ is a $\tau$-covering of $V$. Denote $(X_i, \varphi_{ii'})_V$ the restriction (or pullback) of the given descent datum to $\mathcal{U}_V$. Hence by what we just saw we obtain a scheme $X_V$ over $V$ whose canonical descent datum with respect to $\mathcal{U}_V$ is isomorphic to $(X_i, \varphi_{ii'})_V$. Suppose that $V' \subset V$ is an affine open of $V$. Then both $X_{V'}$ and $V' \times_V X_V$ have canonical descent data isomorphic to $(X_i, \varphi_{ii'})_{V'}$. Hence, by Lemma The geometric construction (uncovered prerequisite) again we obtain a canonical morphism $\rho^V_{V'} : X_{V'} \to X_V$ over $S$ which identifies $X_{V'}$ with the inverse image of $V'$ in $X_V$. We omit the verification that given affine opens $V'' \subset V' \subset V$ of $S$ we have $\rho^V_{V''} = \rho^V_{V'} \circ \rho^{V'}_{V''}$.
By Constructions, Lemma The geometric construction (uncovered prerequisite) the data $(X_V, \rho^V_{V'})$ glue to a scheme $X \to S$. Moreover, we are given isomorphisms $V \times_S X \to X_V$ which recover the maps $\rho^V_{V'}$. Unwinding the construction of the schemes $X_V$ we obtain isomorphisms $$V \times_S U_i \times_S X \longrightarrow V \times_S X_i$$ compatible with the maps $\varphi_{ii'}$ and compatible with restricting to smaller affine opens in $S$. This implies that the canonical descent datum on $U_i \times_S X$ is isomorphic to the given descent datum and we win. $\square$
Lemma. Affine neighbourhoods
Let $S$ be a scheme. Let $\{X_i \to S\}_{i\in I}$ be an fpqc covering, see Topologies, Definition The geometric construction. Let $(V_i/X_i, \varphi_{ij})$ be a descent datum relative to $\{X_i \to S\}$. If each morphism $V_i \to X_i$ is quasi-affine, then the descent datum is effective.
Proof. Being quasi-affine is a property of morphisms of schemes which is preserved under any base change, see Morphisms, Lemmas Criteria for affine neighbourhoods (uncovered prerequisite) and Base change for affine neighbourhoods (uncovered prerequisite). Hence Lemma Descent of the geometric construction applies and it suffices to prove the statement of the lemma in case the fpqc-covering is given by a single $\{X \to S\}$ flat surjective morphism of affines. Say $X = \operatorname{Spec}(A)$ and $S = \operatorname{Spec}(R)$ so that $R \to A$ is a faithfully flat ring map. Let $(V, \varphi)$ be a descent datum relative to $X$ over $S$ and assume that $\pi : V \to X$ is quasi-affine.
According to Morphisms, Lemma Criteria for affine neighbourhoods (uncovered prerequisite) this means that $$V \longrightarrow \underline{\operatorname{Spec}}_X(\pi_*\mathcal{O}_V) = W$$ is a quasi-compact open immersion of schemes over $X$. The projections $\text{pr}_i : X \times_S X \to X$ are flat and hence we have $$\text{pr}_0^*\pi_*\mathcal{O}_V = (\pi \times \text{id}_X)_*\mathcal{O}_{V \times_S X}, \quad \text{pr}_1^*\pi_*\mathcal{O}_V = (\text{id}_X \times \pi)_*\mathcal{O}_{X \times_S V}$$ by flat base change (Cohomology of Schemes, Lemma Base change for sheaf cohomology and flatness (uncovered prerequisite)). Thus the isomorphism $\varphi : V \times_S X \to X \times_S V$ (which is an isomorphism over $X \times_S X$) induces an isomorphism of quasi-coherent sheaves of algebras $$\varphi^\sharp : \text{pr}_0^*\pi_*\mathcal{O}_V \longrightarrow \text{pr}_1^*\pi_*\mathcal{O}_V$$ on $X \times_S X$. The cocycle condition for $\varphi$ implies the cocycle condition for $\varphi^\sharp$. Another way to say this is that it produces a descent datum $\varphi'$ on the affine scheme $W$ relative to $X$ over $S$, which moreover has the property that the morphism $V \to W$ is a morphism of descent data. Hence by Lemma Affine neighbourhoods (uncovered prerequisite) (or by effectivity of descent for quasi-coherent algebras) we obtain a scheme $U' \to S$ with an isomorphism $(W, \varphi') \cong (X \times_S U', can)$ of descent data. We note in passing that $U'$ is affine by Lemma Descent of proper morphisms and affine neighbourhoods (uncovered prerequisite).
And now we can think of $V$ as a (quasi-compact) open $V \subset X \times_S U'$ with the property that it is stable under the descent datum $$can : X \times_S U' \times_S X \to X \times_S X \times_S U', (x_0, u', x_1) \mapsto (x_0, x_1, u').$$ In other words $(x_0, u') \in V \Rightarrow (x_1, u') \in V$ for any $x_0, x_1, u'$ mapping to the same point of $S$. Because $X \to S$ is surjective we immediately find that $V$ is the inverse image of a subset $U \subset U'$ under the morphism $X \times_S U' \to U'$. Because $X \to S$ is quasi-compact, flat and surjective also $X \times_S U' \to U'$ is quasi-compact flat and surjective. Hence by Morphisms, Lemma The geometric construction (uncovered prerequisite) this subset $U \subset U'$ is open and we win. $\square$
Lemma. Local algebra
Let $X \to S$ be a surjective, quasi-compact, flat morphism of schemes. Let $(V, \varphi)$ be a descent datum relative to $X/S$. Suppose that for all $v \in V$ there exists an open subscheme $v \in W \subset V$ such that $\varphi(W \times_S X) \subset X \times_S W$ and such that the descent datum $(W, \varphi|_{W \times_S X})$ is effective. Then $(V, \varphi)$ is effective.
Proof. Let $V = \bigcup W_i$ be an open covering with $\varphi(W_i \times_S X) \subset X \times_S W_i$ and such that the descent datum $(W_i, \varphi|_{W_i \times_S X})$ is effective. Let $U_i \to S$ be a scheme and let $\alpha_i : (X \times_S U_i, can) \to (W_i, \varphi|_{W_i \times_S X})$ be an isomorphism of descent data. For each pair of indices $(i, j)$ consider the open $\alpha_i^{-1}(W_i \cap W_j) \subset X \times_S U_i$. Because everything is compatible with descent data and since $\{X \to S\}$ is an fpqc covering, we may apply Lemma The geometric construction (uncovered prerequisite) to find an open $U_{ij} \subset U_i$ such that $\alpha_i^{-1}(W_i \cap W_j) = X \times_S U_{ij}$. Now the identity morphism on $W_i \cap W_j$ is compatible with descent data, hence comes from a unique morphism $\varphi_{ij} : U_{ij} \to U_{ji}$ over $S$ (see Remark The geometric construction). Then $(U_i, U_{ij}, \varphi_{ij})$ is a glueing datum as in Schemes, Section The geometric construction (proof omitted). Thus we may assume there is a scheme $U$ over $S$ such that $U_i \subset U$ is open, $U_{ij} = U_i \cap U_j$ and $\varphi_{ij} = \text{id}_{U_i \cap U_j}$, see Schemes, Lemma Derived gluing across an elementary distinguished square (uncovered prerequisite). Pulling back to $X$ we can use the $\alpha_i$ to get the desired isomorphism $\alpha : X \times_S U \to V$. $\square$
Lemma. The geometric construction
Let $\{T_i \to T\}$ be an fpqc covering, see Topologies, Definition The geometric construction. Then $\{T_i \to T\}$ is a universal effective epimorphism in the category of schemes, see Sites, Definition The geometric construction. In other words, every representable functor on the category of schemes satisfies the sheaf condition for the fpqc topology, see Topologies, Definition Proper morphisms and sheaves on ringed sites.
Proof. Let $S$ be a scheme. We have to show the following: Given morphisms $\varphi_i : T_i \to S$ such that $\varphi_i|_{T_i \times_T T_j} = \varphi_j|_{T_i \times_T T_j}$ there exists a unique morphism $T \to S$ which restricts to $\varphi_i$ on each $T_i$. In other words, we have to show that the functor $h_S = \operatorname{Mor}_{\mathrm{Sch}}( - , S)$ satisfies the sheaf property for the fpqc topology.
If $\{T_i \to T\}$ is a Zariski covering, then this follows from Schemes, Lemma Derived gluing across an elementary distinguished square (uncovered prerequisite). Thus Topologies, Lemma Proper morphisms and sheaves on ringed sites (uncovered prerequisite) reduces us to the case of a covering $\{X \to Y\}$ given by a single surjective flat morphism of affines.
First proof. By Lemma Sheaves on ringed sites we have the sheaf condition for quasi-coherent modules for $\{X \to Y\}$. By Lemma The geometric construction (uncovered prerequisite) the morphism $X \to Y$ is universally submersive. Hence we may apply Lemma The geometric construction (uncovered prerequisite) to see that $\{X \to Y\}$ is a universal effective epimorphism.
Second proof. Let $R \to A$ be the faithfully flat ring map corresponding to our surjective flat morphism $\pi : X \to Y$. Let $f : X \to S$ be a morphism such that $f \circ \text{pr}_1 = f \circ \text{pr}_2$ as morphisms $X \times_Y X = \operatorname{Spec}(A \otimes_R A) \to S$. By Lemma Tensor products and direct sums (uncovered prerequisite) we see that as a map on the underlying sets $f$ is of the form $f = g \circ \pi$ for some (set theoretic) map $g : \operatorname{Spec}(R) \to S$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) and the fact that $f$ is continuous we see that $g$ is continuous.
Pick $y \in Y = \operatorname{Spec}(R)$. Choose $U \subset S$ affine open containing $g(y)$. Say $U = \operatorname{Spec}(B)$. By the above we may choose an $r \in R$ such that $y \in D(r) \subset g^{-1}(U)$. The restriction of $f$ to $\pi^{-1}(D(r))$ into $U$ corresponds to a ring map $B \to A_r$. The two induced ring maps $B \to A_r \otimes_{R_r} A_r = (A \otimes_R A)_r$ are equal by assumption on $f$. Note that $R_r \to A_r$ is faithfully flat. By Lemma The geometric construction (uncovered prerequisite) the equalizer of the two arrows $A_r \to A_r \otimes_{R_r} A_r$ is $R_r$. We conclude that $B \to A_r$ factors uniquely through a map $B \to R_r$. This map in turn gives a morphism of schemes $D(r) \to U \to S$, see Schemes, Lemma Affine neighbourhoods (uncovered prerequisite).
What have we proved so far? We have shown that for any prime $\mathfrak p \subset R$, there exists a standard affine open $D(r) \subset \operatorname{Spec}(R)$ such that the morphism $f|_{\pi^{-1}(D(r))} : \pi^{-1}(D(r)) \to S$ factors uniquely through some morphism of schemes $D(r) \to S$. We omit the verification that these morphisms glue to the desired morphism $\operatorname{Spec}(R) \to S$. $\square$
Lemma. Descent of proper morphisms
The property $\mathcal{P}(f) =$"$f$ is quasi-compact" is fpqc local on the base.
Proof. A base change of a quasi-compact morphism is quasi-compact, see Schemes, Lemma Base change for the geometric construction (uncovered prerequisite). Being quasi-compact is Zariski local on the base, see Schemes, Lemma Affine neighbourhoods (uncovered prerequisite). Finally, let $S' \to S$ be a flat surjective morphism of affine schemes, and let $f : X \to S$ be a morphism. Assume that the base change $f' : X' \to S'$ is quasi-compact. Then $X'$ is quasi-compact, and $X' \to X$ is surjective. Hence $X$ is quasi-compact. This implies that $f$ is quasi-compact. Therefore Lemma Descent of proper morphisms (uncovered prerequisite) applies and we win. $\square$
Lemma. Descent of proper morphisms and diagonals and separation
The property $\mathcal{P}(f) =$"$f$ is quasi-separated" is fpqc local on the base.
Proof. Any base change of a quasi-separated morphism is quasi-separated, see Schemes, Lemma Diagonals and separation (uncovered prerequisite). Being quasi-separated is Zariski local on the base (from the definition or by Schemes, Lemma Criteria for diagonals and separation (uncovered prerequisite)). Finally, let $S' \to S$ be a flat surjective morphism of affine schemes, and let $f : X \to S$ be a morphism. Assume that the base change $f' : X' \to S'$ is quasi-separated. This means that $\Delta' : X' \to X'\times_{S'} X'$ is quasi-compact. Note that $\Delta'$ is the base change of $\Delta : X \to X \times_S X$ via $S' \to S$. By Lemma Descent of proper morphisms this implies $\Delta$ is quasi-compact, and hence $f$ is quasi-separated. Therefore Lemma Descent of proper morphisms (uncovered prerequisite) applies and we win. $\square$
Lemma. Descent of finite presentation and proper morphisms
The property $\mathcal{P}(f) =$"$f$ is locally of finite presentation" is fpqc local on the base.
Proof. Being locally of finite presentation is preserved under base change, see Morphisms, Lemma Base change for finite presentation and finite algebras (uncovered prerequisite). Being locally of finite type is Zariski local on the base, see Morphisms, Lemma Finite presentation and finite algebras (uncovered prerequisite). Finally, let $S' \to S$ be a flat surjective morphism of affine schemes, and let $f : X \to S$ be a morphism. Assume that the base change $f' : X' \to S'$ is locally of finite presentation. Let $U \subset X$ be an affine open. Then $U' = S' \times_S U$ is affine and of finite type over $S'$. Write $S = \operatorname{Spec}(R)$, $S' = \operatorname{Spec}(R')$, $U = \operatorname{Spec}(A)$, and $U' = \operatorname{Spec}(A')$. We know that $R \to R'$ is faithfully flat, $A' = R' \otimes_R A$ and $R' \to A'$ is of finite presentation. We have to show that $R \to A$ is of finite presentation. This is the result of Algebra, Lemma Finite presentation and finite algebras (uncovered prerequisite). It follows that $f$ is locally of finite presentation. Therefore Lemma Descent of proper morphisms (uncovered prerequisite) applies and we win. $\square$
Lemma. Dimension, codimension and local algebra
Let $d \in \{0, 1, 2, \ldots, \infty\}$. The property of morphisms of germs $$\mathcal{P}_d((X, x) \to (S, s)) = \text{the local ring } \mathcal{O}_{X_s, x} \text{ of the fibre has dimension }d$$ is étale local on the source-and-target.
Proof. Given a diagram as in Definition Local algebra we obtain an étale morphism of fibres $U'_{v'} \to U_v$ mapping $u'$ to $u$, see Lemma Étale morphisms (uncovered prerequisite). Hence the result follows from Lemma Dimension, codimension and local algebra (uncovered prerequisite). $\square$
Lemma. The geometric construction
Let $r \in \{0, 1, 2, \ldots, \infty\}$. The property of morphisms of germs $$\mathcal{P}_r((X, x) \to (S, s)) \Leftrightarrow \text{trdeg}_{\kappa(s)} \kappa(x) = r$$ is étale local on the source-and-target.
Proof. Given a diagram as in Definition Local algebra we obtain the following diagram of local homomorphisms of local rings $$\begin{gathered}\begin{matrix}\mathcal{O}_{U', u'} & \mathcal{O}_{V', v'} \\ \mathcal{O}_{U, u} & \mathcal{O}_{V, v}\end{matrix} \\[6pt] \begin{aligned}\mathcal{O}_{V', v'} & \longrightarrow \mathcal{O}_{U', u'} \\ \mathcal{O}_{U, u} & \longrightarrow \mathcal{O}_{U', u'} \\ \mathcal{O}_{V, v} & \longrightarrow \mathcal{O}_{U, u} \\ \mathcal{O}_{V, v} & \longrightarrow \mathcal{O}_{V', v'}\end{aligned}\end{gathered}$$ Note that the vertical arrows are localizations of étale ring maps, in particular they are unramified (see Algebra, Section Étale morphisms). Hence $\kappa(u')/\kappa(u)$ and $\kappa(v')/\kappa(v)$ are finite separable field extensions. Thus we have $\text{trdeg}_{\kappa(v)} \kappa(u) = \text{trdeg}_{\kappa(v')} \kappa(u')$ which proves the lemma. $\square$
Lemma. Dimension and codimension
Let $d \in \{0, 1, 2, \ldots, \infty\}$. The property of morphisms of germs $$\mathcal{P}_d((X, x) \to (S, s)) \Leftrightarrow \dim_x (X_s) = d$$ is étale local on the source-and-target.
Proof. Given a diagram as in Definition Local algebra we obtain an étale morphism of fibres $U'_{v'} \to U_v$ mapping $u'$ to $u$, see Lemma Étale morphisms (uncovered prerequisite). Hence now the equality $\dim_u(U_v) = \dim_{u'}(U'_{v'})$ follows from Lemma Dimension, codimension and local algebra. $\square$
Lemma. Dimension, codimension and local algebra
Let $f : U \to V$ be an étale morphism of schemes. Let $u \in U$ and $v = f(u)$. Then $\dim_u(U) = \dim_v(V)$.
Proof. In the statement $\dim_u(U)$ is the dimension of $U$ at $u$ as defined in Topology, Definition The geometric construction as the minimum of the Krull dimensions of open neighbourhoods of $u$ in $U$. Similarly for $\dim_v(V)$.
Let us show that $\dim_v(V) \geq \dim_u(U)$. Let $V'$ be an open neighbourhood of $v$ in $V$. Then there exists an open neighbourhood $U'$ of $u$ in $U$ contained in $f^{-1}(V')$ such that $\dim_u(U) = \dim(U')$. Suppose that $Z_0 \subset Z_1 \subset \ldots \subset Z_n$ is a chain of irreducible closed subschemes of $U'$. If $\xi_i \in Z_i$ is the generic point then we have specializations $\xi_n \leadsto \xi_{n - 1} \leadsto \ldots \leadsto \xi_0$. This gives specializations $f(\xi_n) \leadsto f(\xi_{n - 1}) \leadsto \ldots \leadsto f(\xi_0)$ in $V'$. Note that $f(\xi_j) \not = f(\xi_i)$ if $i \not = j$ as the fibres of $f$ are discrete (see Morphisms, Lemma Étale morphisms and field extensions (uncovered prerequisite)). Hence we see that $\dim(V') \geq n$. The inequality $\dim_v(V) \geq \dim_u(U)$ follows formally.
Let us show that $\dim_u(U) \geq \dim_v(V)$. Let $U'$ be an open neighbourhood of $u$ in $U$. Note that $V' = f(U')$ is an open neighbourhood of $v$ by Morphisms, Lemma The geometric construction (uncovered prerequisite). Hence $\dim(V') \geq \dim_v(V)$. Pick a chain $Z_0 \subset Z_1 \subset \ldots \subset Z_n$ of irreducible closed subschemes of $V'$. Let $\xi_i \in Z_i$ be the generic point, so we have specializations $\xi_n \leadsto \xi_{n - 1} \leadsto \ldots \leadsto \xi_0$. Since $\xi_0 \in f(U')$ we can find a point $\eta_0 \in U'$ with $f(\eta_0) = \xi_0$. Consider the map of local rings $$\mathcal{O}_{V', \xi_0} \longrightarrow \mathcal{O}_{U', \eta_0}$$ which is a flat local ring map by Morphisms, Lemma Étale morphisms and flatness (uncovered prerequisite). Note that the points $\xi_i$ correspond to primes of the ring on the left by Schemes, Lemma The geometric construction (uncovered prerequisite). Hence by going down (see Algebra, Section Commutative algebra) for the displayed ring map we can find a sequence of specializations $\eta_n \leadsto \eta_{n - 1} \leadsto \ldots \leadsto \eta_0$ in $U'$ mapping to the sequence $\xi_n \leadsto \xi_{n - 1} \leadsto \ldots \leadsto \xi_0$ under $f$. This implies that $\dim_u(U) \geq \dim_v(V)$. $\square$
Proposition. Quasi-coherent complexes and coherent sheaves
Let $f : T \to S$ be a morphism of schemes.
-
The equivalences of categories of Proposition Quasi-coherent complexes and coherent sheaves are compatible with pullback. More precisely, we have $f^*(\mathcal{G}^a) = (f^*\mathcal{G})^a$ for any quasi-coherent sheaf $\mathcal{G}$ on $S$.
-
The equivalences of categories of Proposition Quasi-coherent complexes and coherent sheaves part (1) are not compatible with pushforward in general.
-
If $f$ is quasi-compact and quasi-separated, and $\tau \in \{Zariski, \mathrm{\acute{e}tale}\}$ then $f_*$ and $f_{small, *}$ preserve quasi-coherent sheaves and the diagram $$\begin{gathered}\begin{matrix}\mathrm{QCoh}(\mathcal{O}_T) & \phantom{X} & \mathrm{QCoh}(\mathcal{O}_S) \\ \mathrm{QCoh}(T_\tau, \mathcal{O}) & \phantom{X} & \mathrm{QCoh}(S_\tau, \mathcal{O})\end{matrix} \\[6pt] \begin{aligned}\mathrm{QCoh}(\mathcal{O}_T) & \xrightarrow{f_*} \mathrm{QCoh}(\mathcal{O}_S) \\ \mathrm{QCoh}(\mathcal{O}_T) & \xrightarrow{\mathcal{F} \mapsto \mathcal{F}^a} \mathrm{QCoh}(T_\tau, \mathcal{O}) \\ \mathrm{QCoh}(\mathcal{O}_S) & \xrightarrow{\mathcal{G} \mapsto \mathcal{G}^a} \mathrm{QCoh}(S_\tau, \mathcal{O}) \\ \mathrm{QCoh}(T_\tau, \mathcal{O}) & \xrightarrow{f_{small, *}} \mathrm{QCoh}(S_\tau, \mathcal{O})\end{aligned}\end{gathered}$$ is commutative, i.e., $f_{small, *}(\mathcal{F}^a) = (f_*\mathcal{F})^a$.
Proof. Part (1) follows from the discussion in Remark Sheaves on ringed sites. Part (2) is just a warning, and can be explained in the following way: First the statement cannot be made precise since $f_*$ does not transform quasi-coherent sheaves into quasi-coherent sheaves in general. Even if this is the case for $f$ (and any base change of $f$), then the compatibility over the big sites would mean that formation of $f_*\mathcal{F}$ commutes with any base change, which does not hold in general. An explicit example is the quasi-compact open immersion $j : X = \mathbf{A}^2_k \setminus \{0\} \to \mathbf{A}^2_k = Y$ where $k$ is a field. We have $j_*\mathcal{O}_X = \mathcal{O}_Y$ but after base change to $\operatorname{Spec}(k)$ by the $0$ map we see that the pushforward is zero.
Let us prove (3) in case $\tau = \mathrm{\acute{e}tale}$. Note that $f$, and any base change of $f$, transforms quasi-coherent sheaves into quasi-coherent sheaves, see Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite). The equality $f_{small, *}(\mathcal{F}^a) = (f_*\mathcal{F})^a$ means that for any étale morphism $g : U \to S$ we have $\Gamma(U, g^*f_*\mathcal{F}) = \Gamma(U \times_S T, (g')^*\mathcal{F})$ where $g' : U \times_S T \to T$ is the projection. This is true by Cohomology of Schemes, Lemma Base change for sheaf cohomology and flatness (uncovered prerequisite). $\square$
Lemma. Descent of flatness and proper morphisms
The property $\mathcal{P}(f) =$"$f$ is flat" is fpqc local on the base.
Proof. Being flat is preserved under arbitrary base change, see Morphisms, Lemma Base change for flatness (uncovered prerequisite). Being flat is Zariski local on the base by definition. Finally, let $S' \to S$ be a flat surjective morphism of affine schemes, and let $f : X \to S$ be a morphism. Assume that the base change $f' : X' \to S'$ is flat. Let $U \subset X$ be an affine open. Then $U' = S' \times_S U$ is affine. Write $S = \operatorname{Spec}(R)$, $S' = \operatorname{Spec}(R')$, $U = \operatorname{Spec}(A)$, and $U' = \operatorname{Spec}(A')$. We know that $R \to R'$ is faithfully flat, $A' = R' \otimes_R A$ and $R' \to A'$ is flat. Goal: Show that $R \to A$ is flat. This follows immediately from Algebra, Lemma Flatness (uncovered prerequisite). Hence $f$ is flat. Therefore Lemma Descent of proper morphisms (uncovered prerequisite) applies and we win. $\square$
Proposition. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $\mathcal{U} = \{\varphi_i : U_i \to S\}$ be an fpqc covering, see Topologies, Definition The geometric construction. Any descent datum on quasi-coherent sheaves for $\mathcal{U} = \{U_i \to S\}$ is effective. Moreover, the functor from the category of quasi-coherent $\mathcal{O}_S$-modules to the category of descent data with respect to $\mathcal{U}$ is fully faithful.
Proof. Let $S = \bigcup_{j \in J} V_j$ be an affine open covering. For $j, j' \in J$ we denote $V_{jj'} = V_j \cap V_{j'}$ the intersection (which need not be affine). For $V \subset S$ open we denote $\mathcal{U}_V = \{V \times_S U_i \to V\}_{i \in I}$ which is a fpqc-covering (Topologies, Lemma The geometric construction (uncovered prerequisite)). By definition of an fpqc covering, we can find for each $j \in J$ a finite set $K_j$, a map $\underline{i} : K_j \to I$, affine opens $U_{\underline{i}(k), k} \subset U_{\underline{i}(k)}$, $k \in K_j$ such that $\mathcal{V}_j = \{U_{\underline{i}(k), k} \to V_j\}_{k \in K_j}$ is a standard fpqc covering of $V_j$. And of course, $\mathcal{V}_j$ is a refinement of $\mathcal{U}_{V_j}$. Picture $$\begin{gathered}\begin{matrix}\mathcal{V}_j & \mathcal{U}_{V_j} & \mathcal{U} \\ V_j & V_j & S\end{matrix} \\[6pt] \begin{aligned}\mathcal{V}_j & \longrightarrow \mathcal{U}_{V_j} \\ \mathcal{V}_j & \rightsquigarrow V_j \\ \mathcal{U}_{V_j} & \longrightarrow \mathcal{U} \\ \mathcal{U}_{V_j} & \rightsquigarrow V_j \\ \mathcal{U} & \rightsquigarrow S \\ V_j & \mathrel{=} V_j \\ V_j & \longrightarrow S\end{aligned}\end{gathered}$$ where the top horizontal arrows are morphisms of families of morphisms with fixed target (see Sites, Definition The geometric construction).
To prove the proposition you show successively the faithfulness, fullness, and essential surjectivity of the functor from quasi-coherent sheaves to descent data.
Faithfulness. Let $\mathcal{F}$, $\mathcal{G}$ be quasi-coherent sheaves on $S$ and let $a, b : \mathcal{F} \to \mathcal{G}$ be homomorphisms of $\mathcal{O}_S$-modules. Suppose $\varphi_i^*(a) = \varphi_i^*(b)$ for all $i$. Pick $s \in S$. Then $s = \varphi_i(u)$ for some $i \in I$ and $u \in U_i$. Since $\mathcal{O}_{S, s} \to \mathcal{O}_{U_i, u}$ is flat, hence faithfully flat (Algebra, Lemma Flatness and local algebra) we see that $a_s = b_s : \mathcal{F}_s \to \mathcal{G}_s$. Hence $a = b$.
Fully faithfulness. Let $\mathcal{F}$, $\mathcal{G}$ be quasi-coherent sheaves on $S$ and let $a_i : \varphi_i^*\mathcal{F} \to \varphi_i^*\mathcal{G}$ be homomorphisms of $\mathcal{O}_{U_i}$-modules such that $\text{pr}_0^*a_i = \text{pr}_1^*a_j$ on $U_i \times_U U_j$. We can pull back these morphisms to get morphisms $$a_k : \varphi_{i(k)}^*\mathcal{F}|_{U_{\underline{i}(k), k}} \longrightarrow \varphi_{i(k)}^*\mathcal{G}|_{U_{\underline{i}(k), k}}$$ $k \in K_j$ with notation as above. Moreover, Lemma The geometric construction (uncovered prerequisite) assures us that these define a morphism between (canonical) descent data on $\mathcal{V}_j$. Hence, by Lemma The geometric construction (uncovered prerequisite), we get correspondingly unique morphisms $a_j : \mathcal{F}|_{V_j} \to \mathcal{G}|_{V_j}$. To see that $a_j|_{V_{jj'}} = a_{j'}|_{V_{jj'}}$ we use that both $a_j$ and $a_{j'}$ agree with the pullback of the morphism $(a_i)_{i \in I}$ of (canonical) descent data to any covering refining both $\mathcal{V}_{j, V_{jj'}}$ and $\mathcal{V}_{j', V_{jj'}}$, and using the faithfulness already shown. For example the covering $\mathcal{V}_{jj'} = \{V_k \times_S V_{k'} \to V_{jj'}\}_{k \in K_j, k' \in K_{j'}}$ will do.
Essential surjectivity. Let $\xi = (\mathcal{F}_i, \varphi_{ii'})$ be a descent datum for quasi-coherent sheaves relative to the covering $\mathcal{U}$. Pull back this descent datum to get descent data $\xi_j$ for quasi-coherent sheaves relative to the coverings $\mathcal{V}_j$ of $V_j$. By Lemma The geometric construction (uncovered prerequisite) once again there exist quasi-coherent sheaves $\mathcal{F}_j$ on $V_j$ whose associated canonical descent datum is isomorphic to $\xi_j$. By fully faithfulness (proved above) we see there are isomorphisms $$\phi_{jj'} : \mathcal{F}_j|_{V_{jj'}} \longrightarrow \mathcal{F}_{j'}|_{V_{jj'}}$$ corresponding to the isomorphism of descent data between the pullback of $\xi_j$ and $\xi_{j'}$ to $\mathcal{V}_{jj'}$. To see that these maps $\phi_{jj'}$ satisfy the cocycle condition we use faithfulness (proved above) over the triple intersections $V_{jj'j''}$. Hence, by Lemma The geometric construction (uncovered prerequisite) we see that the sheaves $\mathcal{F}_j$ glue to a quasi-coherent sheaf $\mathcal{F}$ as desired. We still have to verify that the canonical descent datum relative to $\mathcal{U}$ associated to $\mathcal{F}$ is isomorphic to the descent datum we started out with. This verification is omitted. $\square$
Lemma. Descent of proper morphisms and diagonals and separation
The property $\mathcal{P}(f) =$"$f$ is an immersion" is fppf local on the base.
Proof. The property of being an immersion is stable under base change, see Schemes, Lemma Base change for diagonals and separation (uncovered prerequisite). The property of being an immersion is Zariski local on the base. Finally, let $\pi : S' \to S$ be a surjective morphism of affine schemes, which is flat and locally of finite presentation. Note that $\pi : S' \to S$ is open by Morphisms, Lemma The geometric construction (uncovered prerequisite). Let $f : X \to S$ be a morphism. Assume that the base change $f' : X' \to S'$ is an immersion. In particular we see that $f'(X') = \pi^{-1}(f(X))$ is locally closed. Hence by Topology, Lemma The geometric construction (uncovered prerequisite) we see that $f(X) \subset S$ is locally closed. Let $Z \subset S$ be the closed subset $Z = \overline{f(X)} \setminus f(X)$. By Topology, Lemma The geometric construction (uncovered prerequisite) again we see that $f'(X')$ is closed in $S' \setminus Z'$. Hence we may apply Lemma Descent of proper morphisms and diagonals and separation (uncovered prerequisite) to the fpqc covering $\{S' \setminus Z' \to S \setminus Z\}$ and conclude that $f : X \to S \setminus Z$ is a closed immersion. In other words, $f$ is an immersion. Therefore Lemma Descent of proper morphisms (uncovered prerequisite) applies and we win. $\square$
[^1]: The fact that fpqc is missing is not a typo. See discussion in Topologies, Section The geometric construction.
[^2]: Namely, for $y \in V$, we pick an affine open $y \in V' \subset V$ with $f(V')$ contained in an affine open $U \subset S$. Then we pick an affine open $f(y) \in U' \subset f(V')$. Then $V'' = f^{-1}(U') \subset V'$ is affine as it is equal to $U' \times_U V'$ and $f(V'') = U'$ is affine too.
Relative associated points on algebraic spaces
Lemma. Prime spectra and associated points
Let $Y$ be a scheme. Let $X$ be an algebraic space of finite presentation over $Y$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite presentation. Let $U \subset X$ be an open subspace such that $U \to Y$ is quasi-compact. Then the set $$E = \{y \in Y \mid \text{Ass}_{X_y}(\mathcal{F}_y) \subset |U_y|\}$$ is locally constructible in $Y$.
Proof. Note that since $Y$ is a scheme, it makes sense to take the fibres $X_y = \operatorname{Spec}(\kappa(y)) \times_Y X$. (Also, by our definitions, the set $\text{Ass}_{X_y}(\mathcal{F}_y)$ is exactly the fibre of $\text{Ass}_{X/Y}(\mathcal{F}) \to Y$ over $y$, but we won't need this.) The question is local on $Y$, indeed, we have to show that $E$ is constructible if $Y$ is affine. In this case $X$ is quasi-compact. Choose an affine scheme $W$ and a surjective étale morphism $\varphi : W \to X$. Then $\text{Ass}_{X_y}(\mathcal{F}_y)$ is the image of $\text{Ass}_{W_y}(\varphi^*\mathcal{F}_y)$ for all $y \in Y$. Hence the lemma follows from the case of schemes for the open $\varphi^{-1}(U) \subset W$ and the morphism $W \to Y$. The case of schemes is More on Morphisms, Lemma Prime spectra and associated points. $\square$
Lemma. Prime spectra, associated points and finite algebras
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $i : Z \to X$ be a finite morphism. Let $\mathcal{G}$ be a quasi-coherent $\mathcal{O}_Z$-module. Then $\text{WeakAss}_{X/Y}(i_*\mathcal{G}) = i(\text{WeakAss}_{Z/Y}(\mathcal{G}))$.
Proof. Follows from the case of schemes (Divisors, Lemma Prime spectra, associated points and finite algebras (uncovered prerequisite)) by étale localization. Details omitted. $\square$
Lemma. Base change for line bundles and ampleness
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Let $Y' \to Y$ be a morphism of algebraic spaces over $S$. Let $f' : X' \to Y'$ be the base change of $f$ and denote $\mathcal{L}'$ the pullback of $\mathcal{L}$ to $X'$. If $\mathcal{L}$ is $f$-ample, then $\mathcal{L}'$ is $f'$-ample.
Proof. This follows immediately from the definition! (Hint: transitivity of base change.) $\square$
Lemma. Line bundles, ampleness and local algebra
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. The following are equivalent
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$\mathcal{L}$ is ample on $X/Y$,
-
for every scheme $Z$ and every morphism $Z \to Y$ the algebraic space $X_Z = Z \times_Y X$ is a scheme and the pullback $\mathcal{L}_Z$ is ample on $X_Z/Z$,
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for every affine scheme $Z$ and every morphism $Z \to Y$ the algebraic space $X_Z = Z \times_Y X$ is a scheme and the pullback $\mathcal{L}_Z$ is ample on $X_Z/Z$,
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there exists a scheme $V$ and a surjective étale morphism $V \to Y$ such that the algebraic space $X_V = V \times_Y X$ is a scheme and the pullback $\mathcal{L}_V$ is ample on $X_V/V$.
Proof. Parts (1) and (2) are equivalent by definition. The implication (2) $\Rightarrow$ (3) is immediate. If (3) holds and $Z \to Y$ is as in (2), then we see that $X_Z \to Z$ is affine locally on $Z$ representable. Hence $X_Z$ is a scheme for example by Properties of Spaces, Lemma Étale geometry of algebraic spaces. Then it follows that $\mathcal{L}_Z$ is ample on $X_Z/Z$ because it holds locally on $Z$ and we can use Morphisms, Lemma Criteria for line bundles and ampleness (uncovered prerequisite). Thus (1), (2), and (3) are equivalent. Clearly these conditions imply (4).
Assume (4). Let $Z \to Y$ be a morphism with $Z$ affine. Then $U = V \times_Y Z \to Z$ is a surjective étale morphism such that the pullback of $\mathcal{L}_Z$ by $X_U \to X_Z$ is relatively ample on $X_U/U$. Of course we may replace $U$ by an affine open. It follows that $\mathcal{L}_Z$ is ample on $X_Z/Z$ by Lemma Descent of line bundles and ampleness (uncovered prerequisite). Thus (4) $\Rightarrow$ (3) and the proof is complete. $\square$
Lemma. Proper morphisms and line bundles and ampleness
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. If there exists an $f$-ample invertible sheaf, then $f$ is representable, quasi-compact, and separated.
Proof. This is clear from the definitions and Morphisms, Lemma Line bundles, ampleness and diagonals and separation (uncovered prerequisite). (If in doubt, take a look at the principle of Algebraic Spaces, Lemma Proper morphisms (uncovered prerequisite).) $\square$
Lemma. Line bundles and ampleness
With assumptions and notation as above. The morphism $\psi$ induces a canonical morphism of algebraic spaces over $Y$ $$r_{\mathcal{L}, \psi} : U(\psi) \longrightarrow \underline{\text{Proj}}_Y(\mathcal{A})$$ together with a map of graded $\mathcal{O}_{U(\psi)}$-algebras $$\theta : r_{\mathcal{L}, \psi}^*\left( \bigoplus\nolimits_{d \geq 0} \mathcal{O}_{\underline{\text{Proj}}_Y(\mathcal{A})}(d) \right) \longrightarrow \bigoplus\nolimits_{d \geq 0} \mathcal{L}^{\otimes d}|_{U(\psi)}$$ characterized by the following properties:
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For $V \to Y$ étale and $d \geq 0$ the diagram $$\begin{gathered}\begin{matrix}\mathcal{A}_d(V) & \Gamma(V \times_Y X, \mathcal{L}^{\otimes d}) \\ \Gamma(V \times_Y \underline{\text{Proj}}_Y(\mathcal{A}), \mathcal{O}_{\underline{\text{Proj}}_Y(\mathcal{A})}(d)) & \Gamma(V \times_Y U(\psi), \mathcal{L}^{\otimes d})\end{matrix} \\[6pt] \begin{aligned}\mathcal{A}_d(V) & \xrightarrow{\psi} \Gamma(V \times_Y \underline{\text{Proj}}_Y(\mathcal{A}), \mathcal{O}_{\underline{\text{Proj}}_Y(\mathcal{A})}(d)) \\ \mathcal{A}_d(V) & \xrightarrow{\psi} \Gamma(V \times_Y X, \mathcal{L}^{\otimes d}) \\ \Gamma(V \times_Y X, \mathcal{L}^{\otimes d}) & \xrightarrow{restrict} \Gamma(V \times_Y U(\psi), \mathcal{L}^{\otimes d}) \\ \Gamma(V \times_Y \underline{\text{Proj}}_Y(\mathcal{A}), \mathcal{O}_{\underline{\text{Proj}}_Y(\mathcal{A})}(d)) & \xrightarrow{\theta} \Gamma(V \times_Y U(\psi), \mathcal{L}^{\otimes d})\end{aligned}\end{gathered}$$ is commutative.
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For any $d \geq 1$ and any morphism $W \to X$ where $W$ is a scheme such that $\psi|_W : f^*\mathcal{A}_d|_W \to \mathcal{L}^{\otimes d}|_W$ is surjective we have (a) $W \to X$ factors through $U(\psi)$ and (b) composition of $W \to U(\psi)$ with $r_{\mathcal{L}, \psi}$ agrees with the morphism $W \to \underline{\text{Proj}}_Y(\mathcal{A})$ which exists by the construction of $\underline{\text{Proj}}_Y(\mathcal{A})$, see Definition The geometric construction.
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Consider a commutative diagram $$\begin{gathered}\begin{matrix}X' & X \\ Y' & Y\end{matrix} \\[6pt] \begin{aligned}X' & \xrightarrow{g'} X \\ X' & \xrightarrow{f'} Y' \\ X & \xrightarrow{f} Y \\ Y' & \xrightarrow{g} Y\end{aligned}\end{gathered}$$ where $X'$ and $Y'$ are schemes, set $\mathcal{A}' = g^*\mathcal{A}$ and $\mathcal{L}' = (g')^*\mathcal{L}$ and denote $\psi' : (f')^*\mathcal{A} \to \bigoplus_{d \geq 0} (\mathcal{L}')^{\otimes d}$ the pullback of $\psi$. Let $U(\psi')$, $r_{\psi', \mathcal{L}'}$, and $\theta'$ be the open, morphism, and homomorphism constructed in Constructions, Lemma Line bundles and ampleness. Then $U(\psi') = (g')^{-1}(U(\psi))$ and $r_{\psi', \mathcal{L}'}$ agrees with the base change of $r_{\psi, \mathcal{L}}$ via the isomorphism $\underline{\text{Proj}}_{Y'}(\mathcal{A}') = Y' \times_Y \underline{\text{Proj}}_Y(\mathcal{A})$ of Lemma Base change for the geometric construction (uncovered prerequisite). Moreover, $\theta'$ is the pullback of $\theta$.
Proof. Omitted. Hints: First we observe that for a quasi-compact scheme $W$ over $X$ the following are equivalent
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$W \to X$ factors through $U(\psi)$, and
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there exists a $d$ such that $\psi|_W : f^*\mathcal{A}_d|_W \to \mathcal{L}^{\otimes d}|_W$ is surjective.
This gives a description of $U(\psi)$ as a subfunctor of $X$ on our base category $(\mathrm{Sch}/S)_{fppf}$. For such a $W$ and $d$ we consider the quadruple $(d, W \to Y, \mathcal{L}|_W, \psi^{(d)}|_W)$. By definition of $\underline{\text{Proj}}_Y(\mathcal{A})$ we obtain a morphism $W \to \underline{\text{Proj}}_Y(\mathcal{A})$. By our notion of equivalence of quadruples one sees that this morphism is independent of the choice of $d$. This clearly defines a transformation of functors $r_{\psi, \mathcal{L}} : U(\psi) \to \underline{\text{Proj}}_Y(\mathcal{A})$, i.e., a morphism of algebraic spaces. By construction this morphism satisfies (2). Since the morphism constructed in Constructions, Lemma Line bundles and ampleness (uncovered prerequisite) satisfies the same property, we see that (3) is true.
To construct $\theta$ and check the compatibility (1) of the lemma, work étale locally on $Y$ and $X$, arguing as in the discussion following Definition The geometric construction. $\square$
Dévissage and universal flattening
Definition. Flatness and dimension of a fibre module
Let $f : X \to S$ be a morphism of schemes which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $n \geq 0$. We say $\mathcal{F}$ is flat over $S$ in dimensions $\geq n$ if the equivalent conditions of Lemma The local flatness dimension test are satisfied.
Lemma. The local flatness dimension test
Let $f : X \to S$ be a morphism of schemes which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $n \geq 0$. The following are equivalent
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for $s \in S$ the closed subset $Z \subset X_s$ of points where $\mathcal{F}$ is not flat over $S$ (see Lemma Flatness) satisfies $\dim(Z) < n$, and
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for $x \in X$ such that $\mathcal{F}$ is not flat at $x$ over $S$ we have $\text{trdeg}_{\kappa(f(x))}(\kappa(x)) < n$.
If this is true, then it remains true after any base change.
Proof. Let $x \in X$ be a point over $s \in S$. Then the dimension of the closure of $\{x\}$ in $X_s$ is $\text{trdeg}_{\kappa(s)}(\kappa(x))$ by Varieties, Lemma Dimension, codimension and local algebra. Conversely, if $Z \subset X_s$ is a closed subset of dimension $d$, then there exists a point $x \in Z$ with $\text{trdeg}_{\kappa(s)}(\kappa(x)) = d$ (same reference). Therefore the equivalence of (1) and (2) holds (even fibre by fibre). The statement on base change follows from Morphisms, Lemmas Base change for flatness and modules (uncovered prerequisite) and Base change for dimension and codimension (uncovered prerequisite). $\square$
Lemma. The flatness dimension stratum
In Situation The universal flatness dimension stratum.
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The functor $F_n$ satisfies the sheaf property for the fpqc topology.
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If $f$ is quasi-compact and locally of finite presentation and $\mathcal{F}$ is of finite presentation, then the functor $F_n$ is limit preserving.
Proof. Let $\{T_i \to T\}_{i \in I}$ be an fpqc covering of schemes over $S$. Set $X_i = X_{T_i} = X \times_S T_i$ and denote $\mathcal{F}_i$ the pullback of $\mathcal{F}$ to $X_i$. Assume that $\mathcal{F}_i$ is flat over $T_i$ in dimensions $\geq n$ for all $i$. Let $t \in T$. Choose an index $i$ and a point $t_i \in T_i$ mapping to $t$. Consider the cartesian diagram $$\begin{gathered}\begin{matrix}X_{\operatorname{Spec}(\mathcal{O}_{T, t})} & X_{\operatorname{Spec}(\mathcal{O}_{T_i, t_i})} \\ \operatorname{Spec}(\mathcal{O}_{T, t}) & \operatorname{Spec}(\mathcal{O}_{T_i, t_i})\end{matrix} \\[6pt] \begin{aligned}X_{\operatorname{Spec}(\mathcal{O}_{T, t})} & \longrightarrow \operatorname{Spec}(\mathcal{O}_{T, t}) \\ X_{\operatorname{Spec}(\mathcal{O}_{T_i, t_i})} & \longrightarrow \operatorname{Spec}(\mathcal{O}_{T_i, t_i}) \\ X_{\operatorname{Spec}(\mathcal{O}_{T_i, t_i})} & \longrightarrow X_{\operatorname{Spec}(\mathcal{O}_{T, t})} \\ \operatorname{Spec}(\mathcal{O}_{T_i, t_i}) & \longrightarrow \operatorname{Spec}(\mathcal{O}_{T, t})\end{aligned}\end{gathered}$$ As the lower horizontal morphism is flat we see from More on Morphisms, Lemma Base change for flatness that the set $Z_i \subset X_{t_i}$ where $\mathcal{F}_i$ is not flat over $T_i$ and the set $Z \subset X_t$ where $\mathcal{F}_T$ is not flat over $T$ are related by the rule $Z_i = Z_{\kappa(t_i)}$. Hence we see that $\mathcal{F}_T$ is flat over $T$ in dimensions $\geq n$ by Morphisms, Lemma Base change for dimension and codimension (uncovered prerequisite).
Assume that $f$ is quasi-compact and locally of finite presentation and that $\mathcal{F}$ is of finite presentation. In this paragraph we first reduce the proof of (2) to the case where $f$ is of finite presentation. Let $T = \varprojlim_{i \in I} T_i$ be a directed limit of affine $S$-schemes and assume that $\mathcal{F}_T$ is flat in dimensions $\geq n$. Set $X_i = X_{T_i} = X \times_S T_i$ and denote $\mathcal{F}_i$ the pullback of $\mathcal{F}$ to $X_i$. We have to show that $\mathcal{F}_i$ is flat in dimensions $\geq n$ for some $i$. Pick $i_0 \in I$ and replace $I$ by $\{i \mid i \geq i_0\}$. Since $T_{i_0}$ is affine (hence quasi-compact) there exist finitely many affine opens $W_j \subset S$, $j = 1, \ldots, m$ and an affine open overing $T_{i_0} = \bigcup_{j = 1, \ldots, m} V_{j, i_0}$ such that $T_{i_0} \to S$ maps $V_{j, i_0}$ into $W_j$. For $i \geq i_0$ denote $V_{j, i}$ the inverse image of $V_{j, i_0}$ in $T_i$. If we can show, for each $j$, that there exists an $i$ such that $\mathcal{F}_{V_{j, i_0}}$ is flat in dimensions $\geq n$, then we win. In this way we reduce to the case that $S$ is affine. In this case $X$ is quasi-compact and we can choose a finite affine open covering $X = W_1 \cup \ldots \cup W_m$. In this case the result for $(X \to S, \mathcal{F})$ is equivalent to the result for $(\coprod W_j, \coprod \mathcal{F}|_{W_j})$. Hence we may assume that $f$ is of finite presentation.
Assume $f$ is of finite presentation and $\mathcal{F}$ is of finite presentation. Let $U \subset X_T$ denote the open subscheme of points where $\mathcal{F}_T$ is flat over $T$, see More on Morphisms, Theorem Openness of the flat locus. By assumption the dimension of every fibre of $Z = X_T \setminus U$ over $T$ has dimension $< n$. By Limits, Lemma Dimension and codimension we can find a closed subscheme $Z \subset Z' \subset X_T$ such that $\dim(Z'_t) < n$ for all $t \in T$ and such that $Z' \to X_T$ is of finite presentation. By Limits, Lemmas Descent of finite presentation and finite algebras and Descent of finite presentation and diagonals and separation there exists an $i \in I$ and a closed subscheme $Z'_i \subset X_i$ of finite presentation whose base change to $T$ is $Z'$. By Limits, Lemma Filtered limits and dimension and codimension we may assume all fibres of $Z'_i \to T_i$ have dimension $< n$. By Limits, Lemma Descent of finite presentation and flatness we may assume that $\mathcal{F}_i|_{X_i \setminus T'_i}$ is flat over $T_i$. This implies that $\mathcal{F}_i$ is flat in dimensions $\geq n$; here we use that $Z' \to X_T$ is of finite presentation, and hence the complement $X_T \setminus Z'$ is quasi-compact! Thus part (2) is proved and the proof of the lemma is complete. $\square$
Lemma. Localization of a flatness dimension stratum
In Situation The universal flatness dimension stratum. Let $h : X' \to X$ be an étale morphism. Set $\mathcal{F}' = h^*\mathcal{F}$ and $f' = f \circ h$. Let $F_n'$ be (the displayed identity) associated to $(f' : X' \to S, \mathcal{F}')$. Then $F_n$ is a subfunctor of $F_n'$ and if $h(X') \supset \text{Ass}_{X/S}(\mathcal{F})$, then $F_n = F'_n$.
Proof. Let $T \to S$ be any morphism. Then $h_T : X'_T \to X_T$ is étale as a base change of the étale morphism $g$. For $t \in T$ denote $Z \subset X_t$ the set of points where $\mathcal{F}_T$ is not flat over $T$, and similarly denote $Z' \subset X'_t$ the set of points where $\mathcal{F}'_T$ is not flat over $T$. As $\mathcal{F}'_T = h_T^*\mathcal{F}_T$ we see that $Z' = h_t^{-1}(Z)$, see Morphisms, Lemma Permanence of flat ring maps (uncovered prerequisite). Hence $Z' \to Z$ is an étale morphism, so $\dim(Z') \leq \dim(Z)$ (for example by Descent, Lemma Dimension, codimension and local algebra or just because an étale morphism is smooth of relative dimension $0$). This implies that $F_n \subset F_n'$.
Finally, suppose that $h(X') \supset \text{Ass}_{X/S}(\mathcal{F})$ and that $T \to S$ is a morphism such that $F_n'(T)$ is nonempty, i.e., such that $\mathcal{F}'_T$ is flat in dimensions $\geq n$ over $T$. Pick a point $t \in T$ and let $Z \subset X_t$ and $Z' \subset X'_t$ be as above. To get a contradiction assume that $\dim(Z) \geq n$. Pick a generic point $\xi \in Z$ corresponding to a component of dimension $\geq n$. Let $x \in \text{Ass}_{X_t}(\mathcal{F}_t)$ be a generalization of $\xi$. Then $x$ maps to a point of $\text{Ass}_{X/S}(\mathcal{F})$ by Divisors, Lemma Base change for prime spectra and associated points and Remark Base change for prime spectra and associated points. Thus we see that $x$ is in the image of $h_T$, say $x = h_T(x')$ for some $x' \in X'_T$. But $x' \not \in Z'$ as $x \leadsto \xi$ and $\dim(Z') < n$. Hence $\mathcal{F}'_T$ is flat over $T$ at $x'$ which implies that $\mathcal{F}_T$ is flat at $x$ over $T$ (by Morphisms, Lemma Permanence of flat ring maps (uncovered prerequisite)). Since this holds for every such $x$ we conclude that $\mathcal{F}_T$ is flat over $T$ at $\xi$ by Theorem Derived tensor products, Tor amplitude and flatness which is the desired contradiction. $\square$
Lemma. Purity and dévissage
Let $f : X \to S$ be morphism of schemes which is locally of finite type. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Let $x \in X$ with image $s = f(x)$ in $S$. Then there exists a commutative diagram of pointed schemes $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (S', s') \\ \phantom{X}\end{matrix} \\[6pt] \begin{aligned}(X, x) & \xrightarrow{f} (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ such that $(S', s') \to (S, s)$ and $(X', x') \to (X, x)$ are elementary étale neighbourhoods, and such that $g^*\mathcal{F}/X'/S'$ has a one step dévissage at $x'$.
Proof. This is immediate from Definition Purity and dévissage and Lemma Purity and dévissage. $\square$
Lemma. A generic free presentation in dévissage
Let $S$, $X$, $\mathcal{F}$, $s$ be as in Definition Purity and dévissage. Let $(Z, Y, i, \pi, \mathcal{G})$ be a one step dévissage of $\mathcal{F}/X/S$ over $s$. Let $\xi \in Y_s$ be the (unique) generic point. Then there exists an integer $r > 0$ and an $\mathcal{O}_Y$-module map $$\alpha : \mathcal{O}_Y^{\oplus r} \longrightarrow \pi_*\mathcal{G}$$ such that $$\alpha : \kappa(\xi)^{\oplus r} \longrightarrow (\pi_*\mathcal{G})_\xi \otimes_{\mathcal{O}_{Y, \xi}} \kappa(\xi)$$ is an isomorphism. Moreover, in this case we have $$\dim(\text{Supp}(\operatorname{Coker}(\alpha)_s)) < \dim(\text{Supp}(\mathcal{F}_s)).$$
Proof. By assumption the schemes $S$ and $Y$ are affine. Write $S = \operatorname{Spec}(A)$ and $Y = \operatorname{Spec}(B)$. As $\pi$ is finite the $\mathcal{O}_Y$-module $\pi_*\mathcal{G}$ is a finite type quasi-coherent $\mathcal{O}_Y$-module. Hence $\pi_*\mathcal{G} = \widetilde{N}$ for some finite $B$-module $N$. Let $\mathfrak p \subset B$ be the prime ideal corresponding to $\xi$. To obtain $\alpha$ set $r = \dim_{\kappa(\mathfrak p)} N \otimes_B \kappa(\mathfrak p)$ and pick $x_1, \ldots, x_r \in N$ which form a basis of $N \otimes_B \kappa(\mathfrak p)$. Take $\alpha : B^{\oplus r} \to N$ to be the map given by the formula $\alpha(b_1, \ldots, b_r) = \sum b_ix_i$. It is clear that $\alpha : \kappa(\mathfrak p)^{\oplus r} \to N \otimes_B \kappa(\mathfrak p)$ is an isomorphism as desired. Finally, suppose $\alpha$ is any map with this property. Then $N' = \operatorname{Coker}(\alpha)$ is a finite $B$-module such that $N' \otimes \kappa(\mathfrak p) = 0$. By Nakayama's lemma (Algebra, Lemma Nakayama's lemma) we see that $N'_{\mathfrak p} = 0$. Since the fibre $Y_s$ is geometrically irreducible of dimension $n$ with generic point $\xi$ and since we have just seen that $\xi$ is not in the support of $\operatorname{Coker}(\alpha)$ the last assertion of the lemma holds. $\square$
Lemma. Restriction of a dévissage to a neighbourhood
With assumption and notation as in Definition Shrinking a dévissage we have:
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If $S' \subset S$ is a standard open neighbourhood of $s$, then setting $X' = X_{S'}$, $Z' = Z_{S'}$ and $Y' = Y_{S'}$ we obtain a standard shrinking.
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Let $W \subset Y$ be a standard open neighbourhood of $y$. Then there exists a standard shrinking with $Y' = W \times_S S'$.
Let $U \subset X$ be an open neighbourhood of $x$. Then there exists a standard shrinking with $X' \subset U$.
Proof. Part (1) is immediate from Lemma Base change for purity and dévissage and the fact that the inverse image of a standard open under a morphism of affine schemes is a standard open, see Algebra, Lemma Functoriality of affine spectra.
Let $W \subset Y$ as in (2). Because $Y \to S$ is smooth it is open, see Morphisms, Lemma Smooth morphisms (uncovered prerequisite). Hence we can find a standard open neighbourhood $S'$ of $s$ contained in the image of $W$. Then the fibres of $W_{S'} \to S'$ are nonempty open subschemes of the fibres of $Y \to S$ over $S'$ and hence geometrically irreducible too. Setting $Y' = W_{S'}$ and $Z' = \pi^{-1}(Y')$ we see that $Z' \subset Z$ is a standard open neighbourhood of $z$. Let $\overline{h} \in \Gamma(Z, \mathcal{O}_Z)$ be a function such that $Z' = D(\overline{h})$. As $i : Z \to X$ is a closed immersion, we can find a function $h \in \Gamma(X, \mathcal{O}_X)$ such that $i^\sharp(h) = \overline{h}$. Take $X' = D(h) \subset X$. In this way we obtain a standard shrinking as in (2).
Let $U \subset X$ be as in (3). We may after shrinking $U$ assume that $U$ is a standard open. By More on Morphisms, Lemma Finite algebras there exists a standard open $W \subset Y$ neighbourhood of $y$ such that $\pi^{-1}(W) \subset i^{-1}(U)$. Apply (2) to get a standard shrinking $X', S', Z', Y'$ with $Y' = W_{S'}$. Since $Z' \subset \pi^{-1}(W) \subset i^{-1}(U)$ we may replace $X'$ by $X' \cap U$ (still a standard open as $U$ is also standard open) without violating any of the conditions defining a standard shrinking. Hence we win. $\square$
Lemma. Étale morphisms
Let $S$, $X$, $\mathcal{F}$, $x$, $s$ be as in Definition Purity and dévissage. Let $(Z, Y, i, \pi, \mathcal{G}, z, y)$ be a one step dévissage of $\mathcal{F}/X/S$ at $x$. Let $$\begin{gathered}\begin{matrix}(Y, y) & (Y', y') \\ (S, s) & (S', s')\end{matrix} \\[6pt] \begin{aligned}(Y, y) & \longrightarrow (S, s) \\ (Y', y') & \longrightarrow (Y, y) \\ (Y', y') & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ be a commutative diagram of pointed schemes such that the horizontal arrows are elementary étale neighbourhoods. Then there exists a commutative diagram $$\begin{gathered}\begin{matrix}\phantom{X} & \phantom{X} & (X'', x'') & (Z'', z'') \\ (X, x) & (Z, z) & (S'', s'') & (Y'', y'') \\ (S, s) & (Y, y)\end{matrix} \\[6pt] \begin{aligned}(X'', x'') & \longrightarrow (X, x) \\ (X'', x'') & \longrightarrow (S'', s'') \\ (Z'', z'') & \longrightarrow (X'', x'') \\ (Z'', z'') & \longrightarrow (Z, z) \\ (Z'', z'') & \longrightarrow (Y'', y'') \\ (X, x) & \longrightarrow (S, s) \\ (Z, z) & \longrightarrow (X, x) \\ (Z, z) & \longrightarrow (Y, y) \\ (S'', s'') & \longrightarrow (S, s) \\ (Y'', y'') & \longrightarrow (Y, y) \\ (Y'', y'') & \longrightarrow (S'', s'') \\ (Y, y) & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ of pointed schemes with the following properties:
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$(S'', s'') \to (S', s')$ is an elementary étale neighbourhood and the morphism $S'' \to S$ is the composition $S'' \to S' \to S$,
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$Y''$ is an open subscheme of $Y' \times_{S'} S''$,
-
$Z'' = Z \times_Y Y''$,
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$(X'', x'') \to (X, x)$ is an elementary étale neighbourhood, and
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$(Z'', Y'', i'', \pi'', \mathcal{G}'', z'', y'')$ is a one step dévissage at $x''$ of the sheaf $\mathcal{F}''$.
Here $\mathcal{F}''$ (resp. $\mathcal{G}''$) is the pullback of $\mathcal{F}$ (resp. $\mathcal{G}$) via the morphism $X'' \to X$ (resp. $Z'' \to Z$) and $i'' : Z'' \to X''$ and $\pi'' : Z'' \to Y''$ are as in the diagram.
Proof. Let $(S'', s'') \to (S', s')$ be any elementary étale neighbourhood with $S''$ affine. Let $Y'' \subset Y' \times_{S'} S''$ be any affine open neighbourhood containing the point $y'' = (y', s'')$. Then we obtain an affine $(Z'', z'')$ by (3). Moreover $Z_{S''} \to X_{S''}$ is a closed immersion and $Z'' \to Z_{S''}$ is an étale morphism. Hence Lemma Lifting étale morphisms applies and we can find an étale morphism $X'' \to X_{S'}$ of affines such that $Z'' \cong X'' \times_{X_{S'}} Z_{S'}$. Denote $i'' : Z'' \to X''$ the corresponding closed immersion. Setting $x'' = i''(z'')$ we obtain a commutative diagram as in the lemma. Properties (1), (2), (3), and (4) hold by construction. Thus it suffices to show that (5) holds for a suitable choice of $(S'', s'') \to (S', s')$ and $Y''$.
We first list those properties which hold for any choice of $(S'', s'') \to (S', s')$ and $Y''$ as in the first paragraph. As we have $Z'' = X'' \times_X Z$ by construction we see that $i''_*\mathcal{G}'' = \mathcal{F}''$ (with notation as in the statement of the lemma), see Cohomology of Schemes, Lemma Base change for affine neighbourhoods (uncovered prerequisite). Set $n = \dim(\text{Supp}(\mathcal{F}_s)) = \dim_x(\text{Supp}(\mathcal{F}_s))$. The morphism $Y'' \to S''$ is smooth of relative dimension $n$ (because $Y' \to S'$ is smooth of relative dimension $n$ as the composition $Y' \to Y_{S'} \to S'$ of an étale and smooth morphism of relative dimension $n$ and because base change preserves smooth morphisms of relative dimension $n$). We have $\kappa(y'') = \kappa(y)$ and $\kappa(s) = \kappa(s'')$ hence $\kappa(y'')$ is a purely transcendental extension of $\kappa(s'')$. The morphism of fibres $X''_{s''} \to X_s$ is an étale morphism of affine schemes over $\kappa(s) = \kappa(s'')$ mapping the point $x''$ to the point $x$ and pulling back $\mathcal{F}_s$ to $\mathcal{F}''_{s''}$. Hence $$\dim(\text{Supp}(\mathcal{F}''_{s''})) = \dim(\text{Supp}(\mathcal{F}_s)) = n = \dim_x(\text{Supp}(\mathcal{F}_s)) = \dim_{x''}(\text{Supp}(\mathcal{F}''_{s''}))$$ because dimension is invariant under étale localization, see Descent, Lemma Dimension, codimension and local algebra. As $\pi'' : Z'' \to Y''$ is the base change of $\pi$ we see that $\pi''$ is finite and as $\kappa(y) = \kappa(y'')$ we see that $\pi^{-1}(\{y''\}) = \{z''\}$.
At this point we have verified all the conditions of Definition Purity and dévissage except we have not verified that $Y'' \to S''$ has geometrically irreducible fibres. Of course in general this is not going to be true, and it is at this point that we will use that $\kappa(s) \subset \kappa(y)$ is purely transcendental. Namely, let $T \subset Y'_{s'}$ be the irreducible component of $Y'_{s'}$ containing $y' = (y, s')$. Note that $T$ is an open subscheme of $Y'_{s'}$ as this is a smooth scheme over $\kappa(s')$. By Varieties, Lemma The geometric construction we see that $T$ is geometrically connected because $\kappa(s') = \kappa(s)$ is algebraically closed in $\kappa(y') = \kappa(y)$. As $T$ is smooth we see that $T$ is geometrically irreducible. Hence More on Morphisms, Lemma The geometric construction applies and we can find an elementary étale morphism $(S'', s'') \to (S', s')$ and an affine open $Y'' \subset Y'_{S''}$ such that all fibres of $Y'' \to S''$ are geometrically irreducible and such that $T = Y''_{s''}$. After shrinking (first $Y''$ and then $S''$) we may assume that both $Y''$ and $S''$ are affine. This finishes the proof of the lemma. $\square$
Lemma. Base change for complete rings and formal power series
Let $S$, $X$, $\mathcal{F}$, $x$, $s$ be as in Definition Complete rings and formal power series. Let $(S', s') \to (S, s)$ be a morphism of pointed schemes which induces an isomorphism $\kappa(s) = \kappa(s')$. Let $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k, z_k, y_k)_{k = 1, \ldots, n}$ be a complete dévissage of $\mathcal{F}/X/S$ at $x$. Let $(Z'_k, Y'_k, i'_k, \pi'_k, \mathcal{G}'_k, \alpha'_k)_{k = 1, \ldots, n}$ be as constructed in Lemma Base change for complete rings and formal power series and let $x' \in X'$ (resp. $z'_k \in Z'$, $y'_k \in Y'$) be the unique point mapping to both $x \in X$ (resp. $z_k \in Z_k$, $y_k \in Y_k$) and $s' \in S'$. If $S'$ is affine, then $(Z'_k, Y'_k, i'_k, \pi'_k, \mathcal{G}'_k, \alpha'_k, z'_k, y'_k)_{k = 1, \ldots, n}$ is a complete dévissage of $\mathcal{F}'/X'/S'$ at $x'$.
Proof. Combine Lemma Base change for complete rings and formal power series and Lemma Base change for purity and dévissage. $\square$
Lemma. Restriction of a complete dévissage
With assumption and notation as in Definition Shrinking a complete dévissage we have:
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If $S' \subset S$ is a standard open neighbourhood of $s$, then setting $X' = X_{S'}$, $Z'_k = Z_{S'}$ and $Y'_k = Y_{S'}$ we obtain a standard shrinking.
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Let $W \subset Y_n$ be a standard open neighbourhood of $y$. Then there exists a standard shrinking with $Y'_n = W \times_S S'$.
Let $U \subset X$ be an open neighbourhood of $x$. Then there exists a standard shrinking with $X' \subset U$.
Proof. Part (1) is immediate from Lemmas Base change for complete rings and formal power series and Restriction of a dévissage to a neighbourhood.
Proof of (2). For convenience denote $X = Y_0$. We apply Lemma Restriction of a dévissage to a neighbourhood (the indicated step) to find a standard shrinking $S', Y'_{n - 1}, Z'_n, Y'_n$ of the one step dévissage of $\operatorname{Coker}(\alpha_{n - 1})/Y_{n - 1}/S$ at $y_{n - 1}$ with $Y'_n = W \times_S S'$. We may repeat this procedure and find a standard shrinking $S'', Y''_{n - 2}, Z''_{n - 1}, Y''_{n - 1}$ of the one step dévissage of $\operatorname{Coker}(\alpha_{n - 2})/Y_{n - 2}/S$ at $y_{n - 2}$ with $Y''_{n - 1} = Y'_{n - 1} \times_S S''$. We may continue in this manner until we obtain $S^{(n)}, Y^{(n)}_0, Z^{(n)}_1, Y^{(n)}_1$. At this point it is clear that we obtain our desired standard shrinking by taking $S^{(n)}$, $X^{(n)}$, $Z_k^{(n - k)} \times_S S^{(n)}$, and $Y_k^{(n - k)} \times_S S^{(n)}$ with the desired property.
Proof of (3). We use induction on the length of the complete dévissage. First we apply Lemma Restriction of a dévissage to a neighbourhood (the indicated step) to find a standard shrinking $S', X', Z'_1, Y'_1$ of the one step dévissage of $\mathcal{F}/X/S$ at $x$ with $X' \subset U$. If $n = 1$, then we are done. If $n > 1$, then by induction we can find a standard shrinking $S''$, $Y''_1$, $Z''_k$, and $Y''_k$ of the complete dévissage $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k, z_k, y_k)_{k = 2, \ldots, n}$ of $\operatorname{Coker}(\alpha_1)/Y_1/S$ at $x$ such that $Y''_1 \subset Y'_1$. Using Lemma Restriction of a dévissage to a neighbourhood (the indicated step) we can find $S''' \subset S'$, $X''' \subset X'$, $Z'''_1$ and $Y'''_1 = Y''_1 \times_S S'''$ which is a standard shrinking. The solution to our problem is to take $$S''', X''', Z'''_1, Y'''_1, Z''_2 \times_S S''', Y''_2 \times_S S''', \ldots, Z''_n \times_S S''', Y''_n \times_S S'''$$ This ends the proof of the lemma. $\square$
Lemma. Base change for complete rings and formal power series
Let $S$, $X$, $\mathcal{F}$, $s$ be as in Definition Complete dévissage. Let $(S', s') \to (S, s)$ be any morphism of pointed schemes. Let $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k)_{k = 1, \ldots, n}$ be a complete dévissage of $\mathcal{F}/X/S$ over $s$. Given this data let $X', Z'_k, Y'_k, i'_k, \pi'_k$ be the base changes of $X, Z_k, Y_k, i_k, \pi_k$ via $S' \to S$. Let $\mathcal{F}'$ be the pullback of $\mathcal{F}$ to $X'$ and let $\mathcal{G}'_k$ be the pullback of $\mathcal{G}_k$ to $Z'_k$. Let $\alpha'_k$ be the pullback of $\alpha_k$ to $Y'_k$. If $S'$ is affine, then $(Z'_k, Y'_k, i'_k, \pi'_k, \mathcal{G}'_k, \alpha'_k)_{k = 1, \ldots, n}$ is a complete dévissage of $\mathcal{F}'/X'/S'$ over $s'$.
Proof. By Lemma Base change for purity and dévissage we know that the base change of a one step dévissage is a one step dévissage. Hence it suffices to prove that formation of $\operatorname{Coker}(\alpha_k)$ commutes with base change and that condition (2) of Definition Complete dévissage is preserved by base change. The first is true as $\pi'_{k, *}\mathcal{G}'_k$ is the pullback of $\pi_{k, *}\mathcal{G}_k$ (by Cohomology of Schemes, Lemma Base change for affine neighbourhoods (uncovered prerequisite)) and because $\otimes$ is right exact. The second because by the same token we have $$(\pi_{k, *}\mathcal{G}_k)_{\xi_k} \otimes_{\mathcal{O}_{Y_k, \xi_k}} \kappa(\xi_k) \otimes_{\kappa(\xi_k)} \kappa(\xi'_k) \cong (\pi'_{k, *}\mathcal{G}'_k)_{\xi'_k} \otimes_{\mathcal{O}_{Y'_k, \xi'_k}} \kappa(\xi'_k)$$ with obvious notation. $\square$
Situation. The universal flatness dimension stratum
Let $f : X \to S$ be a morphism of schemes which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. For any scheme $T$ over $S$ we will denote $\mathcal{F}_T$ the base change of $\mathcal{F}$ to $T$, in other words, $\mathcal{F}_T$ is the pullback of $\mathcal{F}$ via the projection morphism $X_T = X \times_S T \to X$. Note that $X_T \to T$ is of finite type and that $\mathcal{F}_T$ is an $\mathcal{O}_{X_T}$-module of finite type (Morphisms, Lemma Base change for finite algebras (uncovered prerequisite) and Modules, Lemma Pullback of finite algebras (uncovered prerequisite)). Let $n \geq 0$. By Definition Flatness and dimension of a fibre module and Lemma The local flatness dimension test we obtain a functor
$$F_n : (\mathrm{Sch}/S)^{opp} \longrightarrow \textit{Sets}, \quad T \longrightarrow \left\{ \begin{matrix} \{*\} & \text{if }\mathcal{F}_T\text{ is flat over }T\text{ in }\dim \geq n, \\ \emptyset & \text{else.} \end{matrix} \right.$$Definition. Complete dévissage
Let $S$ be a scheme. Let $X$ be locally of finite type over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $s \in S$ be a point. A complete dévissage of $\mathcal{F}/X/S$ over $s$ is given by a diagram $$\begin{gathered}\begin{matrix}X & Z_1 \\ \phantom{X} & Y_1 & Z_2 \\ \phantom{X} & \phantom{X} & Y_2 & Z_3 \\ \phantom{X} & \phantom{X} & \phantom{X} & ... & ... \\ \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & Y_n\end{matrix} \\[6pt] \begin{aligned}Z_1 & \xrightarrow{i_1} X \\ Z_1 & \xrightarrow{\pi_1} Y_1 \\ Z_2 & \xrightarrow{i_2} Y_1 \\ Z_2 & \xrightarrow{\pi_2} Y_2 \\ Z_3 & \longrightarrow Y_2 \\ Z_3 & \longrightarrow ... \\ ... & \longrightarrow ... \\ ... & \longrightarrow Y_n\end{aligned}\end{gathered}$$ of schemes over $S$, finite type quasi-coherent $\mathcal{O}_{Z_k}$-modules $\mathcal{G}_k$, and $\mathcal{O}_{Y_k}$-module maps $$\alpha_k : \mathcal{O}_{Y_k}^{\oplus r_k} \longrightarrow \pi_{k, *}\mathcal{G}_k, \quad k = 1, \ldots, n$$ satisfying the following properties:
-
$(Z_1, Y_1, i_1, \pi_1, \mathcal{G}_1)$ is a one step dévissage of $\mathcal{F}/X/S$ over $s$,
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the map $\alpha_k$ induces an isomorphism $$\kappa(\xi_k)^{\oplus r_k} \longrightarrow (\pi_{k, *}\mathcal{G}_k)_{\xi_k} \otimes_{\mathcal{O}_{Y_k, \xi_k}} \kappa(\xi_k)$$ where $\xi_k \in (Y_k)_s$ is the unique generic point,
-
for $k = 2, \ldots, n$ the system $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k)$ is a one step dévissage of $\operatorname{Coker}(\alpha_{k - 1})/Y_{k - 1}/S$ over $s$,
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$\operatorname{Coker}(\alpha_n) = 0$.
In this case we say that $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k)_{k = 1, \ldots, n}$ is a complete dévissage of $\mathcal{F}/X/S$ over $s$.
Definition. Purity and dévissage
Let $S$ be a scheme. Let $X$ be locally of finite type over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $s \in S$ be a point. A one step dévissage of $\mathcal{F}/X/S$ over $s$ is given by morphisms of schemes over $S$ $$\begin{gathered}\begin{matrix}X & Z & Y\end{matrix} \\[6pt] \begin{aligned}Z & \xrightarrow{i} X \\ Z & \xrightarrow{\pi} Y\end{aligned}\end{gathered}$$ and a quasi-coherent $\mathcal{O}_Z$-module $\mathcal{G}$ of finite type such that
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$X$, $S$, $Z$ and $Y$ are affine,
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$i$ is a closed immersion of finite presentation,
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$\mathcal{F} \cong i_*\mathcal{G}$,
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$\pi$ is finite, and
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the structure morphism $Y \to S$ is smooth with geometrically irreducible fibres of dimension $\dim(\text{Supp}(\mathcal{F}_s))$.
In this case we say $(Z, Y, i, \pi, \mathcal{G})$ is a one step dévissage of $\mathcal{F}/X/S$ over $s$.
Lemma. Finite presentation
Let $R$ be a ring. Let $R \to S$ be a finitely presented flat ring map with geometrically integral fibres. Let $\mathfrak q \subset S$ be a prime ideal lying over the prime $\mathfrak r \subset R$. Set $\mathfrak p = \mathfrak r S$. Let $N$ be a finitely presented $S$-module. There exists $r \geq 0$ and an $S$-module map $$\alpha : S^{\oplus r} \longrightarrow N$$ such that $\alpha : \kappa(\mathfrak p)^{\oplus r} \to N \otimes_S \kappa(\mathfrak p)$ is an isomorphism. For any such $\alpha$ the following are equivalent:
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$N_{\mathfrak q}$ is $R$-flat,
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there exists an $f \in R$, $f \not \in \mathfrak r$ such that $\alpha_f : S_f^{\oplus r} \to N_f$ is $R_f$-universally injective and a $g \in S$, $g \not \in \mathfrak q$ such that $\operatorname{Coker}(\alpha)_g$ is $R$-flat,
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$\alpha_{\mathfrak r}$ is $R_{\mathfrak r}$-universally injective and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat
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$\alpha_{\mathfrak r}$ is injective and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat,
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$\alpha_{\mathfrak p}$ is an isomorphism and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat, and
-
$\alpha_{\mathfrak q}$ is injective and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat.
Proof. To obtain $\alpha$ set $r = \dim_{\kappa(\mathfrak p)} N \otimes_S \kappa(\mathfrak p)$ and pick $x_1, \ldots, x_r \in N$ which form a basis of $N \otimes_S \kappa(\mathfrak p)$. Define $\alpha(s_1, \ldots, s_r) = \sum s_i x_i$. This proves the existence.
Fix a choice of $\alpha$. We may apply Lemma Extending perfect approximation across a distinguished square to the map $\alpha_{\mathfrak r} : S_{\mathfrak r}^{\oplus r} \to N_{\mathfrak r}$. Hence we see that (1), (3), (4), (5), and (6) are all equivalent. Since it is also clear that (2) implies (3) we see that all we have to do is show that (1) implies (2).
Assume (1). By openness of flatness, see Algebra, Theorem Openness of the flat locus, the set $$U_1 = \{\mathfrak q' \subset S \mid N_{\mathfrak q'}\text{ is flat over }R\}$$ is open in $\operatorname{Spec}(S)$. It contains $\mathfrak q$ by assumption and hence $\mathfrak p$. Because $S^{\oplus r}$ and $N$ are finitely presented $S$-modules the set $$U_2 = \{\mathfrak q' \subset S \mid \alpha_{\mathfrak q'}\text{ is an isomorphism}\}$$ is open in $\operatorname{Spec}(S)$, see Algebra, Lemma Finite presentation and finite algebras. It contains $\mathfrak p$ by (5). As $R \to S$ is finitely presented and flat the map $\Phi : \operatorname{Spec}(S) \to \operatorname{Spec}(R)$ is open, see Algebra, Proposition Openness of flat finitely presented maps. For any prime $\mathfrak r' \in \Phi(U_1 \cap U_2)$ we see that there exists a prime $\mathfrak q'$ lying over $\mathfrak r'$ such that $N_{\mathfrak q'}$ is flat and such that $\alpha_{\mathfrak q'}$ is an isomorphism, which implies that $\alpha \otimes \kappa(\mathfrak p')$ is an isomorphism where $\mathfrak p' = \mathfrak r' S$. Thus $\alpha_{\mathfrak r'}$ is $R_{\mathfrak r'}$-universally injective by the implication (1) $\Rightarrow$ (3). Hence if we pick $f \in R$, $f \not \in \mathfrak r$ such that $D(f) \subset \Phi(U_1 \cap U_2)$ then we conclude that $\alpha_f$ is $R_f$-universally injective, see Algebra, Lemma Injective resolutions and sheaves on ringed sites. The same reasoning also shows that for any $\mathfrak q' \in U_1 \cap \Phi^{-1}(\Phi(U_1 \cap U_2))$ the module $\operatorname{Coker}(\alpha)_{\mathfrak q'}$ is $R$-flat. Note that $\mathfrak q \in U_1 \cap \Phi^{-1}(\Phi(U_1 \cap U_2))$. Hence we can find a $g \in S$, $g \not \in \mathfrak q$ such that $D(g) \subset U_1 \cap \Phi^{-1}(\Phi(U_1 \cap U_2))$ and we win. $\square$
Lemma. Comparison for purity and dévissage
Assume that $X \to S$ is a smooth morphism of affine schemes with geometrically irreducible fibres of dimension $d$ and that $\mathcal{F}$ is a quasi-coherent $\mathcal{O}_X$-module of finite presentation. Then $F_d = \coprod_{p = 0, \ldots, c} H_p$ for some $c \geq 0$ with $F_d$ as in (the displayed identity) and $H_p$ as in (the displayed identity).
Proof. As $X$ is affine and $\mathcal{F}$ is quasi-coherent of finite presentation we know that $\mathcal{F}$ can be generated by $c \geq 0$ elements. Then $\dim_{\kappa(x)}(\mathcal{F}_x \otimes \kappa(x))$ in any point $x \in X$ never exceeds $c$. In particular $H_p = \emptyset$ for $p > c$. Moreover, note that there certainly is an inclusion $\coprod H_p \to F_d$. Having said this the content of the lemma is that, if a base change $\mathcal{F}_T$ is flat in dimensions $\geq d$ over $T$ and if $t \in T$, then $\mathcal{F}_T$ is free of some rank $r$ in an open neighbourhood $U \subset X_T$ of the unique generic point $\xi$ of $X_t$. Namely, then $H_r$ contains the image of $U$ which is an open neighbourhood of $t$. The existence of $U$ follows from More on Morphisms, Lemma Projective, locally free modules and flatness. $\square$
Lemma. Projective and locally free modules
In Situation A module free at the generic points of a fibre. For each $p \geq 0$ the functor $H_p$ (the displayed identity) is representable by a locally closed immersion $S_p \to S$. If $\mathcal{F}$ is of finite presentation, then $S_p \to S$ is of finite presentation.
Proof. For each $S$ we will prove the statement for all $p \geq 0$ concurrently. The functor $H_p$ is a sheaf for the fppf topology by Lemma Projective and locally free modules. Hence combining Descent, Lemma Descent of the geometric construction, More on Morphisms, Lemma Diagonals, separation and finite algebras , and Descent, Lemma Descent of proper morphisms and diagonals and separation we see that the question is local for the étale topology on $S$. In particular, the question is Zariski local on $S$.
For $s \in S$ denote $\xi_s$ the unique generic point of the fibre $X_s$. Note that for every $s \in S$ the restriction $\mathcal{F}_s$ of $\mathcal{F}$ is locally free of some rank $p(s) \geq 0$ in some neighbourhood of $\xi_s$. (As $X_s$ is irreducible and smooth this follows from generic flatness for $\mathcal{F}_s$ over $X_s$, see Algebra, Lemma Flatness and Noetherian rings although this is overkill.) For future reference we note that $$p(s) = \dim_{\kappa(\xi_s)}( \mathcal{F}_{\xi_s} \otimes_{\mathcal{O}_{X, \xi_s}} \kappa(\xi_s) ).$$ In particular $H_{p(s)}(s)$ is nonempty and $H_q(s)$ is empty if $q \not = p(s)$.
Let $U \subset X$ be an open subscheme. As $f : X \to S$ is smooth, it is open. It is immediate from (the displayed identity) that the functor $H_p$ for the pair $(f|_U : U \to f(U), \mathcal{F}|_U)$ and the functor $H_p$ for the pair $(f|_{f^{-1}(f(U))}, \mathcal{F}|_{f^{-1}(f(U))})$ are the same. Hence to prove the existence of $S_p$ over $f(U)$ we may always replace $X$ by $U$.
Pick $s \in S$. There exists an affine open neighbourhood $U$ of $\xi_s$ such that $\mathcal{F}|_U$ can be generated by at most $p(s)$ elements. By the arguments above we see that in order to prove the statement for $H_{p(s)}$ in an neighbourhood of $s$ we may assume that $\mathcal{F}$ is generated by $p(s)$ elements, i.e., that there exists a surjection $$u : \mathcal{O}_X^{\oplus p(s)} \longrightarrow \mathcal{F}$$ In this case it is clear that $H_{p(s)}$ is equal to $F_{iso}$ (the displayed identity) for the map $u$ (this follows immediately from Lemma Flatness but also from Lemma Finite presentation after shrinking a bit more so that both $S$ and $X$ are affine.) Thus we may apply Theorem Flatness to see that $H_{p(s)}$ is representable by a closed immersion in a neighbourhood of $s$.
The result follows formally from the above. Namely, the arguments above show that locally on $S$ the function $s \mapsto p(s)$ is bounded. Hence we may use induction on $p = \max_{s \in S} p(s)$. The functor $H_p$ is representable by a closed immersion $S_p \to S$ by the above. Replace $S$ by $S \setminus S_p$ which drops the maximum by at least one and we win by induction hypothesis.
Assume $\mathcal{F}$ is of finite presentation. Then $S_p \to S$ is locally of finite presentation by Lemma Projective and locally free modules part (2) combined with Limits, Remark Filtered limits and finite-presentation descent. Then we redo the induction argument in the paragraph to see that each $S_p$ is quasi-compact when $S$ is affine: first if $p = \max_{s \in S} p(s)$, then $S_p \subset S$ is closed (see above) hence quasi-compact. Then $U = S \setminus S_p$ is quasi-compact open in $S$ because $S_p \to S$ is a closed immersion of finite presentation (see discussion in Morphisms, Section The geometric construction for example). Then $S_{p - 1} \to U$ is a closed immersion of finite presentation, and so $S_{p - 1}$ is quasi-compact and $U' = S \setminus (S_p \cup S_{p - 1})$ is quasi-compact. And so on. $\square$
Lemma. Flatness
Let $f : X \to S$ be a morphism of schemes which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $s \in S$. Then the set $$\{x \in X_s \mid \mathcal{F} \text{ flat over }S\text{ at }x\}$$ is open in the fibre $X_s$.
Proof. Suppose $x \in U$. Choose an elementary étale neighbourhood $(S', s') \to (S, s)$ and open $V \subset X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ as in Proposition Flatness and finite algebras. Note that $X_{s'} = X_s$ as $\kappa(s) = \kappa(s')$. If $x' \in V \cap X_{s'}$, then the pullback of $\mathcal{F}$ to $X \times_S S'$ is flat over $S'$ at $x'$. Hence $\mathcal{F}$ is flat at $x'$ over $S$, see Morphisms, Lemma Permanence of flat ring maps (uncovered prerequisite). In other words $X_s \cap V \subset U$ is an open neighbourhood of $x$ in $U$. $\square$
Theorem. Derived tensor products, Tor amplitude and flatness
Let $f : X \to S$ be locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $x \in X$ with image $s \in S$. The following are equivalent
-
$\mathcal{F}$ is flat at $x$ over $S$, and
-
for every $x' \in \text{Ass}_{X_s}(\mathcal{F}_s)$ which specializes to $x$ we have that $\mathcal{F}$ is flat at $x'$ over $S$.
Proof. It is clear that (1) implies (2) as $\mathcal{F}_{x'}$ is a localization of $\mathcal{F}_x$ for every point which specializes to $x$. Set $A = \mathcal{O}_{S, s}$, $B = \mathcal{O}_{X, x}$ and $N = \mathcal{F}_x$. Let $\Sigma \subset B$ be the multiplicative subset of $B$ of elements which act as nonzerodivisors on $N/\mathfrak m_AN$. Assumption (2) implies that $\Sigma^{-1}N$ is $A$-flat by the description of $\operatorname{Spec}(\Sigma^{-1}N)$ in Lemma Localization at fibrewise nonzerodivisors. On the other hand, the map $N \to \Sigma^{-1}N$ is injective modulo $\mathfrak m_A$ by construction. Hence applying Lemma Injective resolutions and flatness we win. $\square$
Definition. Purity and dévissage
Let $S$ be a scheme. Let $X$ be locally of finite type over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $x \in X$ be a point with image $s$ in $S$. A one step dévissage of $\mathcal{F}/X/S$ at $x$ is a system $(Z, Y, i, \pi, \mathcal{G}, z, y)$, where $(Z, Y, i, \pi, \mathcal{G})$ is a one step dévissage of $\mathcal{F}/X/S$ over $s$ and
-
$\dim_x(\text{Supp}(\mathcal{F}_s)) = \dim(\text{Supp}(\mathcal{F}_s))$,
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$z \in Z$ is a point with $i(z) = x$ and $\pi(z) = y$,
-
we have $\pi^{-1}(\{y\}) = \{z\}$,
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the extension $\kappa(y)/\kappa(s)$ is purely transcendental.
Lemma. Purity and dévissage
Let $f : X \to S$ be morphism of schemes which is locally of finite type. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Let $x \in X$ with image $s = f(x)$ in $S$. Set $\mathcal{F}_s = \mathcal{F}|_{X_s}$ and $n = \dim_x(\text{Supp}(\mathcal{F}_s))$. Then we can construct
-
elementary étale neighbourhoods $g : (X', x') \to (X, x)$, $e : (S', s') \to (S, s)$,
-
a commutative diagram $$\begin{gathered}\begin{matrix}X & X' & Z' \\ \phantom{X} & \phantom{X} & Y' \\ S & S' & S'\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f} S \\ X' & \longrightarrow S' \\ X' & \xrightarrow{g} X \\ Z' & \xrightarrow{i} X' \\ Z' & \xrightarrow{\pi} Y' \\ Y' & \xrightarrow{h} S' \\ S' & \xrightarrow{e} S \\ S' & \mathrel{=} S'\end{aligned}\end{gathered}$$
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a point $z' \in Z'$ with $i(z') = x'$, $y' = \pi(z')$, $h(y') = s'$,
-
a finite type quasi-coherent $\mathcal{O}_{Z'}$-module $\mathcal{G}$,
such that the following properties hold
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$X'$, $Z'$, $Y'$, $S'$ are affine schemes,
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$i$ is a closed immersion of finite presentation,
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$i_*(\mathcal{G}) \cong g^*\mathcal{F}$,
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$\pi$ is finite and $\pi^{-1}(\{y'\}) = \{z'\}$,
-
the extension $\kappa(y')/\kappa(s')$ is purely transcendental,
-
$h$ is smooth of relative dimension $n$ with geometrically integral fibres.
Proof. Let $V \subset S$ be an affine neighbourhood of $s$. Let $U \subset f^{-1}(V)$ be an affine neighbourhood of $x$. Then it suffices to prove the lemma for $f|_U : U \to V$ and $\mathcal{F}|_U$. Hence in the rest of the proof we assume that $X$ and $S$ are affine.
First, suppose that $X_s = \text{Supp}(\mathcal{F}_s)$, in particular $n = \dim_x(X_s)$. Apply More on Morphisms, Lemmas Finite algebras and local algebra (uncovered prerequisite) and Affine neighbourhoods and finite algebras (uncovered prerequisite). This gives us a commutative diagram $$\begin{gathered}\begin{matrix}X & X' \\ \phantom{X} & Y' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \xrightarrow{\pi} Y' \\ Y' & \xrightarrow{h} S' \\ S' & \xrightarrow{e} S\end{aligned}\end{gathered}$$ and point $x' \in X'$. We set $Z' = X'$, $i = \text{id}$, and $\mathcal{G} = g^*\mathcal{F}$ to obtain a solution in this case.
In general choose a closed immersion $Z \to X$ and a sheaf $\mathcal{G}$ on $Z$ as in Lemma A sheaf carried by a closed subscheme. Applying the result of the previous paragraph to $Z \to S$ and $\mathcal{G}$ we obtain a diagram $$\begin{gathered}\begin{matrix}X & Z & Z' \\ \phantom{X} & \phantom{X} & Y' \\ S & S & S'\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f} S \\ Z & \longrightarrow X \\ Z & \xrightarrow{f|_Z} S \\ Z' & \xrightarrow{g} Z \\ Z' & \xrightarrow{\pi} Y' \\ Y' & \xrightarrow{h} S' \\ S & \mathrel{=} S \\ S' & \xrightarrow{e} S\end{aligned}\end{gathered}$$ and point $z' \in Z'$ satisfying all the required properties. We will use Lemma Lifting étale morphisms to embed $Z'$ into a scheme étale over $X$. We cannot apply the lemma directly as we want $X'$ to be a scheme over $S'$. Instead we consider the morphisms $$\begin{gathered}\begin{matrix}Z' & Z \times_S S' & X \times_S S'\end{matrix} \\[6pt] \begin{aligned}Z' & \longrightarrow Z \times_S S' \\ Z \times_S S' & \longrightarrow X \times_S S'\end{aligned}\end{gathered}$$ The first morphism is étale by Morphisms, Lemma Étale morphisms (uncovered prerequisite). The second is a closed immersion as a base change of a closed immersion. Finally, as $X$, $S$, $S'$, $Z$, $Z'$ are all affine we may apply Lemma Lifting étale morphisms to get an étale morphism of affine schemes $X' \to X \times_S S'$ such that $$Z' = (Z \times_S S') \times_{(X \times_S S')} X' = Z \times_X X'.$$ As $Z \to X$ is a closed immersion of finite presentation, so is $Z' \to X'$. Let $x' \in X'$ be the point corresponding to $z' \in Z'$. Then the completed diagram $$\begin{gathered}\begin{matrix}X & X' & Z' \\ \phantom{X} & \phantom{X} & Y' \\ S & S' & S'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \longrightarrow S' \\ X' & \longrightarrow X \\ Z' & \xrightarrow{i} X' \\ Z' & \xrightarrow{\pi} Y' \\ Y' & \xrightarrow{h} S' \\ S' & \xrightarrow{e} S \\ S' & \mathrel{=} S'\end{aligned}\end{gathered}$$ is a solution of the original problem. $\square$
Definition. Shrinking a dévissage
Let $S$, $X$, $\mathcal{F}$, $x$, $s$ be as in Definition Purity and dévissage. Let $(Z, Y, i, \pi, \mathcal{G}, z, y)$ be a one step dévissage of $\mathcal{F}/X/S$ at $x$. Let us define a standard shrinking of this situation to be given by standard opens $S' \subset S$, $X' \subset X$, $Z' \subset Z$, and $Y' \subset Y$ such that $s \in S'$, $x \in X'$, $z \in Z'$, and $y \in Y'$ and such that $$(Z', Y', i|_{Z'}, \pi|_{Z'}, \mathcal{G}|_{Z'}, z, y)$$ is a one step dévissage of $\mathcal{F}|_{X'}/X'/S'$ at $x$.
Lemma. Base change for purity and dévissage
Let $S$, $X$, $\mathcal{F}$, $x$, $s$ be as in Definition Purity and dévissage. Let $(Z, Y, i, \pi, \mathcal{G}, z, y)$ be a one step dévissage of $\mathcal{F}/X/S$ at $x$. Let $(S', s') \to (S, s)$ be a morphism of pointed schemes which induces an isomorphism $\kappa(s) = \kappa(s')$. Let $(Z', Y', i', \pi', \mathcal{G}')$ be as constructed in Lemma Base change for purity and dévissage and let $x' \in X'$ (resp. $z' \in Z'$, $y' \in Y'$) be the unique point mapping to both $x \in X$ (resp. $z \in Z$, $y \in Y$) and $s' \in S'$. If $S'$ is affine, then $(Z', Y', i', \pi', \mathcal{G}', z', y')$ is a one step dévissage of $\mathcal{F}'/X'/S'$ at $x'$.
Proof. By Lemma Base change for purity and dévissage $(Z', Y', i', \pi', \mathcal{G}')$ is a one step dévissage of $\mathcal{F}'/X'/S'$ over $s'$. Properties (1) -- (4) of Definition Purity and dévissage hold for $(Z', Y', i', \pi', \mathcal{G}', z', y')$ as the assumption that $\kappa(s) = \kappa(s')$ insures that the fibres $X'_{s'}$, $Z'_{s'}$, and $Y'_{s'}$ are isomorphic to $X_s$, $Z_s$, and $Y_s$. $\square$
Lemma. Lifting étale morphisms
Let $i : Z \to X$ be a closed immersion of affine schemes. Let $Z' \to Z$ be an étale morphism with $Z'$ affine. Then there exists an étale morphism $X' \to X$ with $X'$ affine such that $Z' \cong Z \times_X X'$ as schemes over $Z$.
Proof. See Algebra, Lemma Lifting étale morphisms. $\square$
Definition. Complete rings and formal power series
Let $S$ be a scheme. Let $X$ be locally of finite type over $S$. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $x \in X$ be a point with image $s \in S$. A complete dévissage of $\mathcal{F}/X/S$ at $x$ is given by a system $$(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k, z_k, y_k)_{k = 1, \ldots, n}$$ such that $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k)$ is a complete dévissage of $\mathcal{F}/X/S$ over $s$, and such that
-
$(Z_1, Y_1, i_1, \pi_1, \mathcal{G}_1, z_1, y_1)$ is a one step dévissage of $\mathcal{F}/X/S$ at $x$,
-
for $k = 2, \ldots, n$ the system $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, z_k, y_k)$ is a one step dévissage of $\operatorname{Coker}(\alpha_{k - 1})/Y_{k - 1}/S$ at $y_{k - 1}$.
Definition. Shrinking a complete dévissage
Let $S$, $X$, $\mathcal{F}$, $x$, $s$ be as in Definition Complete rings and formal power series. Consider a complete dévissage $(Z_k, Y_k, i_k, \pi_k, \mathcal{G}_k, \alpha_k, z_k, y_k)_{k = 1, \ldots, n}$ of $\mathcal{F}/X/S$ at $x$. Let us define a standard shrinking of this situation to be given by standard opens $S' \subset S$, $X' \subset X$, $Z'_k \subset Z_k$, and $Y'_k \subset Y_k$ such that $s_k \in S'$, $x_k \in X'$, $z_k \in Z'$, and $y_k \in Y'$ and such that $$(Z'_k, Y'_k, i'_k, \pi'_k, \mathcal{G}'_k, \alpha'_k, z_k, y_k)_{k = 1, \ldots, n}$$ is a one step dévissage of $\mathcal{F}'/X'/S'$ at $x$ where $\mathcal{G}'_k = \mathcal{G}_k|_{Z'_k}$ and $\mathcal{F}' = \mathcal{F}|_{X'}$.
Lemma. Base change for purity and dévissage
Let $S$, $X$, $\mathcal{F}$, $s$ be as in Definition Purity and dévissage. Let $(Z, Y, i, \pi, \mathcal{G})$ be a one step dévissage of $\mathcal{F}/X/S$ over $s$. Let $(S', s') \to (S, s)$ be any morphism of pointed schemes. Given this data let $X', Z', Y', i', \pi'$ be the base changes of $X, Z, Y, i, \pi$ via $S' \to S$. Let $\mathcal{F}'$ be the pullback of $\mathcal{F}$ to $X'$ and let $\mathcal{G}'$ be the pullback of $\mathcal{G}$ to $Z'$. If $S'$ is affine, then $(Z', Y', i', \pi', \mathcal{G}')$ is a one step dévissage of $\mathcal{F}'/X'/S'$ over $s'$.
Proof. Fibre products of affines are affine, see Schemes, Lemma Affine neighbourhoods and tensor products and direct sums (uncovered prerequisite). Base change preserves closed immersions, morphisms of finite presentation, finite morphisms, smooth morphisms, morphisms with geometrically irreducible fibres, and morphisms of relative dimension $n$, see Morphisms, Lemmas Base change for diagonals and separation (uncovered prerequisite), Base change for finite presentation and finite algebras (uncovered prerequisite), Base change for finite algebras (uncovered prerequisite), Base change of smooth ring maps (uncovered prerequisite), Base change for dimension and codimension (uncovered prerequisite), and More on Morphisms, Lemma Base change for the geometric construction (uncovered prerequisite). We have $i'_*\mathcal{G}' \cong \mathcal{F}'$ because pushforward along the finite morphism $i$ commutes with base change, see Cohomology of Schemes, Lemma Base change for affine neighbourhoods (uncovered prerequisite). We have $\dim(\text{Supp}(\mathcal{F}_s)) = \dim(\text{Supp}(\mathcal{F}'_{s'}))$ by Morphisms, Lemma Base change for dimension and codimension (uncovered prerequisite) because $$\text{Supp}(\mathcal{F}_s) \times_s s' = \text{Supp}(\mathcal{F}'_{s'}).$$ This proves the lemma. $\square$
Lemma. Extending perfect approximation across a distinguished square
Let $(R, \mathfrak m)$ be a local ring. Let $R \to S$ be a finitely presented flat ring map with geometrically integral fibres. Write $\mathfrak p = \mathfrak mS$. Let $\mathfrak q \subset S$ be a prime ideal lying over $\mathfrak m$. Let $N$ be a finite $S$-module. There exist $r \geq 0$ and an $S$-module map $$\alpha : S^{\oplus r} \longrightarrow N$$ such that $\alpha : \kappa(\mathfrak p)^{\oplus r} \to N \otimes_S \kappa(\mathfrak p)$ is an isomorphism. For any such $\alpha$ the following are equivalent:
-
$N_{\mathfrak q}$ is $R$-flat,
-
$\alpha$ is $R$-universally injective and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat,
-
$\alpha$ is injective and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat,
-
$\alpha_{\mathfrak p}$ is an isomorphism and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat, and
-
$\alpha_{\mathfrak q}$ is injective and $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat.
Proof. To obtain $\alpha$ set $r = \dim_{\kappa(\mathfrak p)} N \otimes_S \kappa(\mathfrak p)$ and pick $x_1, \ldots, x_r \in N$ which form a basis of $N \otimes_S \kappa(\mathfrak p)$. Define $\alpha(s_1, \ldots, s_r) = \sum s_i x_i$. This proves the existence.
Fix an $\alpha$. The most interesting implication is (1) $\Rightarrow$ (2) which we prove first. Assume (1). Because $S/\mathfrak mS$ is a domain with fraction field $\kappa(\mathfrak p)$ we see that $(S/\mathfrak mS)^{\oplus r} \to N_{\mathfrak p}/\mathfrak mN_{\mathfrak p} = N \otimes_S \kappa(\mathfrak p)$ is injective. Hence by Lemmas Injective resolutions and local algebra and Projective, locally free modules and flatness. the map $S^{\oplus r} \to N_{\mathfrak p}$ is $R$-universally injective. It follows that $S^{\oplus r} \to N$ is $R$-universally injective, see Algebra, Lemma Injective resolutions (uncovered prerequisite). Then also the localization $\alpha_{\mathfrak q}$ is $R$-universally injective, see Algebra, Lemma Injective resolutions and local algebra (uncovered prerequisite). We conclude that $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $R$-flat by Algebra, Lemma Flatness (uncovered prerequisite).
The implication (2) $\Rightarrow$ (3) is immediate. If (3) holds, then $\alpha_{\mathfrak p}$ is injective as a localization of an injective module map. By Nakayama's lemma (Algebra, Lemma Nakayama's lemma) $\alpha_{\mathfrak p}$ is surjective too. Hence (3) $\Rightarrow$ (4). If (4) holds, then $\alpha_{\mathfrak p}$ is an isomorphism, so $\alpha$ is injective as $S_{\mathfrak q} \to S_{\mathfrak p}$ is injective. Namely, elements of $S \setminus \mathfrak p$ are nonzerodivisors on $S$ by a combination of Lemmas Injective resolutions and Projective, locally free modules and flatness. Hence (4) $\Rightarrow$ (5). Finally, if (5) holds, then $N_{\mathfrak q}$ is $R$-flat as an extension of flat modules, see Algebra, Lemma Flat modules in a short exact sequence (uncovered prerequisite). Hence (5) $\Rightarrow$ (1) and the proof is finished. $\square$
Situation. A module free at the generic points of a fibre
Let $f : X \to S$ be a smooth morphism with geometrically irreducible fibres. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. For any scheme $T$ over $S$ we will denote $\mathcal{F}_T$ the base change of $\mathcal{F}$ to $T$, in other words, $\mathcal{F}_T$ is the pullback of $\mathcal{F}$ via the projection morphism $X_T = X \times_S T \to X$. Note that $X_T \to T$ is smooth with geometrically irreducible fibres, see Morphisms, Lemma Base change of smooth ring maps (uncovered prerequisite) and More on Morphisms, Lemma Base change for the geometric construction (uncovered prerequisite). Let $p \geq 0$ be an integer. Given a point $t \in T$ consider the condition
$$\mathcal{F}_T \text{ is free of rank }p\text{ in a neighbourhood of }\xi_t$$ where $\xi_t$ is the generic point of the fibre $X_t$. This condition for all $t \in T$ is stable under base change, and hence we obtain a functor
\[ H_p : (\mathrm{Sch}/S)^{opp} \longrightarrow \textit{Sets}, \quad T \longrightarrow \left\{ \begin{matrix} \{*\} & \text{if }\mathcal{F}_T\text{ satisfies (the displayed identity) }\forall t\in T, \\ \emptyset & \text{else.} \end{matrix} \right. \]Lemma. Projective and locally free modules
In Situation A module free at the generic points of a fibre.
-
The functor $H_p$ satisfies the sheaf property for the fpqc topology.
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If $\mathcal{F}$ is of finite presentation, then functor $H_p$ is limit preserving.
Proof. Let $\{T_i \to T\}_{i \in I}$ be an fpqc[^1] covering of schemes over $S$. Set $X_i = X_{T_i} = X \times_S T_i$ and denote $\mathcal{F}_i$ the pullback of $\mathcal{F}$ to $X_i$. Assume that $\mathcal{F}_i$ satisfies (the displayed identity) for all $i$. Pick $t \in T$ and let $\xi_t \in X_T$ denote the generic point of $X_t$. We have to show that $\mathcal{F}$ is free in a neighbourhood of $\xi_t$. For some $i \in I$ we can find a $t_i \in T_i$ mapping to $t$. Let $\xi_i \in X_i$ denote the generic point of $X_{t_i}$, so that $\xi_i$ maps to $\xi_t$. The fact that $\mathcal{F}_i$ is free of rank $p$ in a neighbourhood of $\xi_i$ implies that $(\mathcal{F}_i)_{x_i} \cong \mathcal{O}_{X_i, x_i}^{\oplus p}$ which implies that $\mathcal{F}_{T, \xi_t} \cong \mathcal{O}_{X_T, \xi_t}^{\oplus p}$ as $\mathcal{O}_{X_T, \xi_t} \to \mathcal{O}_{X_i, x_i}$ is flat, see for example Algebra, Lemma Projective, locally free modules and finite algebras (uncovered prerequisite). Thus there exists an affine neighbourhood $U$ of $\xi_t$ in $X_T$ and a surjection $\mathcal{O}_U^{\oplus p} \to \mathcal{F}_U = \mathcal{F}_T|_U$, see Modules, Lemma Sheaves on ringed sites and finite algebras (uncovered prerequisite). After shrinking $T$ we may assume that $U \to T$ is surjective. Hence $U \to T$ is a smooth morphism of affines with geometrically irreducible fibres. Moreover, for every $t' \in T$ we see that the induced map $$\alpha : \mathcal{O}_{U, \xi_{t'}}^{\oplus p} \longrightarrow \mathcal{F}_{U, \xi_{t'}}$$ is an isomorphism (since by the same argument as before the module on the right is free of rank $p$). It follows from Lemma Extending perfect approximation across a distinguished square that $$\Gamma(U, \mathcal{O}_U^{\oplus p}) \otimes_{\Gamma(T, \mathcal{O}_T)} \mathcal{O}_{T, t'} \longrightarrow \Gamma(U, \mathcal{F}_U) \otimes_{\Gamma(T, \mathcal{O}_T)} \mathcal{O}_{T, t'}$$ is injective for every $t' \in T$. Hence we see the surjection $\alpha$ is an isomorphism. This finishes the proof of (1).
Assume that $\mathcal{F}$ is of finite presentation. Let $T = \varprojlim_{i \in I} T_i$ be a directed limit of affine $S$-schemes and assume that $\mathcal{F}_T$ satisfies (the displayed identity). Set $X_i = X_{T_i} = X \times_S T_i$ and denote $\mathcal{F}_i$ the pullback of $\mathcal{F}$ to $X_i$. Let $U \subset X_T$ denote the open subscheme of points where $\mathcal{F}_T$ is flat over $T$, see More on Morphisms, Theorem Openness of the flat locus. By assumption every generic point of every fibre is a point of $U$, i.e., $U \to T$ is a smooth surjective morphism with geometrically irreducible fibres. We may shrink $U$ a bit and assume that $U$ is quasi-compact. Using Limits, Lemma Descent of finite-presentation descent we can find an $i \in I$ and a quasi-compact open $U_i \subset X_i$ whose inverse image in $X_T$ is $U$. After increasing $i$ we may assume that $\mathcal{F}_i|_{U_i}$ is flat over $T_i$, see Limits, Lemma Descent of finite presentation and flatness. In particular, $\mathcal{F}_i|_{U_i}$ is finite locally free hence defines a locally constant rank function $\rho : U_i \to \{0, 1, 2, \ldots \}$. Let $(U_i)_p \subset U_i$ denote the open and closed subset where $\rho$ has value $p$. Let $V_i \subset T_i$ be the image of $(U_i)_p$; note that $V_i$ is open and quasi-compact. By assumption the image of $T \to T_i$ is contained in $V_i$. Hence there exists an $i' \geq i$ such that $T_{i'} \to T_i$ factors through $V_i$ by Limits, Lemma Descent of finite-presentation descent. Then $\mathcal{F}_{i'}$ satisfies (the displayed identity) as desired. Some details omitted. $\square$
Situation. The family of module isomorphisms
Let $f : X \to S$ be a morphism of schemes. Let $u : \mathcal{F} \to \mathcal{G}$ be a homomorphism of quasi-coherent $\mathcal{O}_X$-modules. For any scheme $T$ over $S$ we will denote $u_T : \mathcal{F}_T \to \mathcal{G}_T$ the base change of $u$ to $T$, in other words, $u_T$ is the pullback of $u$ via the projection morphism $X_T = X \times_S T \to X$. In this situation we can consider the functor
$$F_{iso} : (\mathrm{Sch}/S)^{opp} \longrightarrow \textit{Sets}, \quad T \longrightarrow \left\{ \begin{matrix} \{*\} & \text{if} & u_T \text{ is an isomorphism}, \\ \emptyset & \text{else.} & \end{matrix} \right.$$ There are variants $F_{inj}$, $F_{surj}$, $F_{zero}$ where we ask that $u_T$ is injective, surjective, or zero.
Lemma. Flatness
Let $f : X \to S$ be a morphism of finite type. Let $\mathcal{F}$ be a quasi-coherent sheaf of finite type on $X$. Assume $S$ is local with closed point $s$. Assume $\mathcal{F}$ is pure along $X_s$ and that $\mathcal{F}$ is flat over $S$. Let $\varphi : \mathcal{F} \to \mathcal{G}$ of quasi-coherent $\mathcal{O}_X$-modules. Then the following are equivalent
-
the map on stalks $\varphi_x$ is injective for all $x \in \text{Ass}_{X_s}(\mathcal{F}_s)$, and
-
$\varphi$ is injective.
Proof. Let $\mathcal{K} = \operatorname{Ker}(\varphi)$. Our goal is to prove that $\mathcal{K} = 0$. In order to do this it suffices to prove that $\text{WeakAss}_X(\mathcal{K}) = \emptyset$, see Divisors, Lemma The geometric construction (uncovered prerequisite). We have $\text{WeakAss}_X(\mathcal{K}) \subset \text{WeakAss}_X(\mathcal{F})$, see Divisors, Lemma The geometric construction (uncovered prerequisite). As $\mathcal{F}$ is flat we see from Lemma Finite algebras that $\text{WeakAss}_X(\mathcal{F}) \subset \text{Ass}_{X/S}(\mathcal{F})$. By purity any point $x'$ of $\text{Ass}_{X/S}(\mathcal{F})$ is a generalization of a point of $X_s$, and hence is the specialization of a point $x \in \text{Ass}_{X_s}(\mathcal{F}_s)$, by Lemma Prime spectra and associated points. Hence the injectivity of $\varphi_x$ implies the injectivity of $\varphi_{x'}$, whence $\mathcal{K}_{x'} = 0$. $\square$
Theorem. Flatness
In Situation The family of module isomorphisms assume
-
$f$ is of finite presentation,
-
$\mathcal{F}$ is of finite presentation, flat over $S$, and pure relative to $S$, and
-
$u$ is surjective.
Then $F_{iso}$ is representable by a closed immersion $Z \to S$. Moreover $Z \to S$ is of finite presentation if $\mathcal{G}$ is of finite presentation.
Proof. We will use without further mention that $\mathcal{F}$ is universally pure over $S$, see Lemma Flatness and finite algebras. By Lemma The sheaf of module isomorphisms and Descent, Lemmas Diagonals and separation (uncovered prerequisite) and Descent of the geometric construction the question is local for the étale topology on $S$. Hence it suffices to prove, given $s \in S$, that there exists an étale neighbourhood of $(S, s)$ so that the theorem holds.
Using Lemma Finite presentation and flatness and after replacing $S$ by an elementary étale neighbourhood of $s$ we may assume there exists a commutative diagram $$\begin{gathered}\begin{matrix}X & \phantom{X} & X' \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow S\end{aligned}\end{gathered}$$ of schemes of finite presentation over $S$, where $g$ is étale, $X_s \subset g(X')$, the schemes $X'$ and $S$ are affine, $\Gamma(X', g^*\mathcal{F})$ a projective $\Gamma(S, \mathcal{O}_S)$-module. Note that $g^*\mathcal{F}$ is universally pure over $S$, see Lemma Projective, locally free modules and affine neighbourhoods. Hence by Lemma A local criterion for the flattening map we see that the open $g(X')$ contains the points of $\text{Ass}_{X/S}(\mathcal{F})$ lying over $\operatorname{Spec}(\mathcal{O}_{S, s})$. Set $$E = \{t \in S \mid \text{Ass}_{X_t}(\mathcal{F}_t) \subset g(X') \}.$$ By More on Morphisms, Lemma Prime spectra and associated points $E$ is a constructible subset of $S$. We have seen that $\operatorname{Spec}(\mathcal{O}_{S, s}) \subset E$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) we see that $E$ contains an open neighbourhood of $s$. Hence after replacing $S$ by a smaller affine neighbourhood of $s$ we may assume that $\text{Ass}_{X/S}(\mathcal{F}) \subset g(X')$.
Since we have assumed that $u$ is surjective we have $F_{iso} = F_{inj}$. From Lemma Purity and dévissage it follows that $u : \mathcal{F} \to \mathcal{G}$ is injective if and only if $g^*u : g^*\mathcal{F} \to g^*\mathcal{G}$ is injective, and the same remains true after any base change. Hence we have reduced to the case where, in addition to the assumptions in the theorem, $X \to S$ is a morphism of affine schemes and $\Gamma(X, \mathcal{F})$ is a projective $\Gamma(S, \mathcal{O}_S)$-module. This case follows immediately from Lemma Flatness and modules.
To see that $Z$ is of finite presentation if $\mathcal{G}$ is of finite presentation, combine Lemma The sheaf of module isomorphisms part (4) with Limits, Remark Filtered limits and finite-presentation descent. $\square$
Proposition. Flatness and finite algebras
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Let $x \in X$ with image $s \in S$. Assume that
-
$f$ is locally of finite presentation,
-
$\mathcal{F}$ is of finite type, and
-
$\mathcal{F}$ is flat at $x$ over $S$.
Then there exists an elementary étale neighbourhood $(S', s') \to (S, s)$ and an open subscheme $$V \subset X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$$ which contains the unique point of $X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ mapping to $x$ such that the pullback of $\mathcal{F}$ to $V$ is an $\mathcal{O}_V$-module of finite presentation and flat over $\mathcal{O}_{S', s'}$.
First proof. This proof is longer but does not use the existence of a complete dévissage. The problem is local around $x$ and $s$, hence we may assume that $X$ and $S$ are affine. During the proof we will finitely many times replace $S$ by an elementary étale neighbourhood of $(S, s)$. The goal is then to find (after such a replacement) an open $V \subset X \times_S \operatorname{Spec}(\mathcal{O}_{S, s})$ containing $x$ such that $\mathcal{F}|_V$ is flat over $S$ and finitely presented. Of course we may also replace $S$ by $\operatorname{Spec}(\mathcal{O}_{S, s})$ at any point of the proof, i.e., we may assume $S$ is a local scheme. We will prove the proposition by induction on the integer $n = \dim_x(\text{Supp}(\mathcal{F}_s))$.
We can choose
-
elementary étale neighbourhoods $g : (X', x') \to (X, x)$, $e : (S', s') \to (S, s)$,
-
a commutative diagram $$\begin{gathered}\begin{matrix}X & X' & Z' \\ \phantom{X} & \phantom{X} & Y' \\ S & S' & S'\end{matrix} \\[6pt] \begin{aligned}X & \xrightarrow{f} S \\ X' & \longrightarrow S' \\ X' & \xrightarrow{g} X \\ Z' & \xrightarrow{i} X' \\ Z' & \xrightarrow{\pi} Y' \\ Y' & \xrightarrow{h} S' \\ S' & \xrightarrow{e} S \\ S' & \mathrel{=} S'\end{aligned}\end{gathered}$$
-
a point $z' \in Z'$ with $i(z') = x'$, $y' = \pi(z')$, $h(y') = s'$,
-
a finite type quasi-coherent $\mathcal{O}_{Z'}$-module $\mathcal{G}$,
as in Lemma Purity and dévissage. We are going to replace $S$ by $\operatorname{Spec}(\mathcal{O}_{S', s'})$, see remarks in first paragraph of the proof. Consider the diagram $$\begin{gathered}\begin{matrix}X_{\mathcal{O}_{S', s'}} & X'_{\mathcal{O}_{S', s'}} & Z'_{\mathcal{O}_{S', s'}} \\ \phantom{X} & \phantom{X} & Y'_{\mathcal{O}_{S', s'}} \\ \phantom{X} & \operatorname{Spec}(\mathcal{O}_{S', s'})\end{matrix} \\[6pt] \begin{aligned}X_{\mathcal{O}_{S', s'}} & \xrightarrow{f} \operatorname{Spec}(\mathcal{O}_{S', s'}) \\ X'_{\mathcal{O}_{S', s'}} & \longrightarrow \operatorname{Spec}(\mathcal{O}_{S', s'}) \\ X'_{\mathcal{O}_{S', s'}} & \xrightarrow{g} X_{\mathcal{O}_{S', s'}} \\ Z'_{\mathcal{O}_{S', s'}} & \xrightarrow{i} X'_{\mathcal{O}_{S', s'}} \\ Z'_{\mathcal{O}_{S', s'}} & \xrightarrow{\pi} Y'_{\mathcal{O}_{S', s'}} \\ Y'_{\mathcal{O}_{S', s'}} & \xrightarrow{h} \operatorname{Spec}(\mathcal{O}_{S', s'})\end{aligned}\end{gathered}$$ Here we have base changed the schemes $X', Z', Y'$ over $S'$ via $\operatorname{Spec}(\mathcal{O}_{S', s'}) \to S'$ and the scheme $X$ over $S$ via $\operatorname{Spec}(\mathcal{O}_{S', s'}) \to S$. It is still the case that $g$ is étale, see Lemma Étale morphisms. After replacing $X$ by $X_{\mathcal{O}_{S', s'}}$, $X'$ by $X'_{\mathcal{O}_{S', s'}}$, $Z'$ by $Z'_{\mathcal{O}_{S', s'}}$, and $Y'$ by $Y'_{\mathcal{O}_{S', s'}}$ we may assume we have a diagram as Lemma Purity and dévissage where in addition $S = S'$ is a local scheme with closed point $s$. By Lemmas Finite presentation and finite algebras and Flatness the result for $Y' \to S$, the sheaf $\pi_*\mathcal{G}$, and the point $y'$ implies the result for $X \to S$, $\mathcal{F}$ and $x$. Hence we may assume that $S$ is local and $X \to S$ is a smooth morphism of affines with geometrically irreducible fibres of dimension $n$.
The base case of the induction: $n = 0$. As $X \to S$ is smooth with geometrically irreducible fibres of dimension $0$ we see that $X \to S$ is an open immersion, see Descent, Lemma Étale morphisms and injective resolutions (uncovered prerequisite). As $S$ is local and the closed point is in the image of $X \to S$ we conclude that $X = S$. Thus we see that $\mathcal{F}$ corresponds to a finite flat $\mathcal{O}_{S, s}$ module. In this case the result follows from Algebra, Lemma Finite flat modules over a local ring which tells us that $\mathcal{F}$ is in fact finite free.
The induction step. Assume the result holds whenever the dimension of the support in the closed fibre is $< n$. Write $S = \operatorname{Spec}(A)$, $X = \operatorname{Spec}(B)$ and $\mathcal{F} = \widetilde{N}$ for some $B$-module $N$. Note that $A$ is a local ring; denote its maximal ideal $\mathfrak m$. Then $\mathfrak p = \mathfrak mB$ is the unique minimal prime lying over $\mathfrak m$ as $X \to S$ has geometrically irreducible fibres. Finally, let $\mathfrak q \subset B$ be the prime corresponding to $x$. By Lemma Extending perfect approximation across a distinguished square we can choose a map $$\alpha : B^{\oplus r} \to N$$ such that $\kappa(\mathfrak p)^{\oplus r} \to N \otimes_B \kappa(\mathfrak p)$ is an isomorphism. Moreover, as $N_{\mathfrak q}$ is $A$-flat the lemma also shows that $\alpha$ is injective and that $\operatorname{Coker}(\alpha)_{\mathfrak q}$ is $A$-flat. Set $Q = \operatorname{Coker}(\alpha)$. Note that the support of $Q/\mathfrak mQ$ does not contain $\mathfrak p$. Hence it is certainly the case that $\dim_{\mathfrak q}(\text{Supp}(Q/\mathfrak mQ)) < n$. Combining everything we know about $Q$ we see that the induction hypothesis applies to $Q$. It follows that there exists an elementary étale morphism $(S', s) \to (S, s)$ such that the conclusion holds for $Q \otimes_A A'$ over $B \otimes_A A'$ where $A' = \mathcal{O}_{S', s'}$. After replacing $A$ by $A'$ we have an exact sequence $$0 \to B^{\oplus r} \to N \to Q \to 0$$ (here we use that $\alpha$ is injective as mentioned above) of finite $B$-modules and we also get an element $g \in B$, $g \not \in \mathfrak q$ such that $Q_g$ is finitely presented over $B_g$ and flat over $A$. Since localization is exact we see that $$0 \to B_g^{\oplus r} \to N_g \to Q_g \to 0$$ is still exact. As $B_g$ and $Q_g$ are flat over $A$ we conclude that $N_g$ is flat over $A$, see Algebra, Lemma Flat modules in a short exact sequence (uncovered prerequisite), and as $B_g$ and $Q_g$ are finitely presented over $B_g$ the same holds for $N_g$, see Algebra, Lemma Commutative algebra. $\square$
Second proof. We apply Proposition Complete dévissage at a point to find a commutative diagram $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (S', s')\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ of pointed schemes such that the horizontal arrows are elementary étale neighbourhoods and such that $g^*\mathcal{F}/X'/S'$ has a complete dévissage at $x$. (In particular $S'$ and $X'$ are affine.) By Morphisms, Lemma Permanence of flat ring maps (uncovered prerequisite) we see that $g^*\mathcal{F}$ is flat at $x'$ over $S$ and by Lemma Étale morphisms and flatness we see that it is flat at $x'$ over $S'$. Via Remark Agreement of the two purity conditions we deduce that $$\Gamma(X', g^*\mathcal{F})/ \Gamma(X', \mathcal{O}_{X'})/ \Gamma(S', \mathcal{O}_{S'})$$ has a complete dévissage at the prime of $\Gamma(X', \mathcal{O}_{X'})$ corresponding to $x'$. We may base change this complete dévissage to the local ring $\mathcal{O}_{S', s'}$ of $\Gamma(S', \mathcal{O}_{S'})$ at the prime corresponding to $s'$. Thus Lemma Complete rings, formal power series and flatness implies that $$\Gamma(X', \mathcal{F}') \otimes_{\Gamma(S', \mathcal{O}_{S'})} \mathcal{O}_{S', s'}$$ is flat over $\mathcal{O}_{S', s'}$ and of finite presentation over $\Gamma(X', \mathcal{O}_{X'}) \otimes_{\Gamma(S', \mathcal{O}_{S'})} \mathcal{O}_{S', s'}$. In other words, the restriction of $\mathcal{F}$ to $X' \times_{S'} \operatorname{Spec}(\mathcal{O}_{S', s'})$ is of finite presentation and flat over $\mathcal{O}_{S', s'}$. Since the morphism $X' \times_{S'} \operatorname{Spec}(\mathcal{O}_{S', s'}) \to X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ is étale (Lemma Étale morphisms) its image $V \subset X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ is an open subscheme, and by étale descent the restriction of $\mathcal{F}$ to $V$ is of finite presentation and flat over $\mathcal{O}_{S', s'}$. (Results used: Morphisms, Lemma Étale morphisms (uncovered prerequisite), Descent, Lemma Finite presentation and finite algebras (uncovered prerequisite), and Morphisms, Lemma Permanence of flat ring maps (uncovered prerequisite).) $\square$
Lemma. Localization at fibrewise nonzerodivisors
Let $R \to S$ be a ring map. Let $N$ be a $S$-module. Assume
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$R$ is a local ring with maximal ideal $\mathfrak m$,
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$\overline{S} = S/\mathfrak m S$ is Noetherian, and
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$\overline{N} = N/\mathfrak m_R N$ is a finite $\overline{S}$-module.
Let $\Sigma \subset S$ be the multiplicative subset of elements which are not a zerodivisor on $\overline{N}$. Then $\Sigma^{-1}S$ is a semi-local ring whose spectrum consists of primes $\mathfrak q \subset S$ contained in an element of $\text{Ass}_S(\overline{N})$. Moreover, any maximal ideal of $\Sigma^{-1}S$ corresponds to an associated prime of $\overline{N}$ over $\overline{S}$.
Proof. Note that $\text{Ass}_S(\overline{N}) = \text{Ass}_{\overline{S}}(\overline{N})$, see Algebra, Lemma Commutative algebra (uncovered prerequisite). This is a finite set by Algebra, Lemma Finite algebras (uncovered prerequisite). Say $\{\mathfrak q_1, \ldots, \mathfrak q_r\} = \text{Ass}_S(\overline{N})$. We have $\Sigma = S \setminus (\bigcup \mathfrak q_i)$ by Algebra, Lemma Commutative algebra (uncovered prerequisite). By the description of $\operatorname{Spec}(\Sigma^{-1}S)$ in Algebra, Lemma The spectrum of a localization (uncovered prerequisite) and by Algebra, Lemma An elementary algebraic comparison (uncovered prerequisite) we see that the primes of $\Sigma^{-1}S$ correspond to the primes of $S$ contained in one of the $\mathfrak q_i$. Hence the maximal ideals of $\Sigma^{-1}S$ correspond one-to-one with the maximal (w.r.t. inclusion) elements of the set $\{\mathfrak q_1, \ldots, \mathfrak q_r\}$. This proves the lemma. $\square$
Lemma. Injective resolutions and flatness
Let $A \to B$ be a local ring homomorphism of local rings which is essentially of finite type. Let $u : N \to M$ be a $B$-module map. If $N$ is a finite $B$-module, $M$ is flat over $A$, and $\overline{u} : N/\mathfrak m_A N \to M/\mathfrak m_A M$ is injective, then $u$ is $A$-universally injective, $N$ is of finite presentation over $B$, and $N$ is flat over $A$.
Proof. Let $A \to A^h$ be the henselization of $A$. Let $B'$ be the localization of $B \otimes_A A^h$ at the maximal ideal $\mathfrak m_B \otimes A^h + B \otimes \mathfrak m_{A^h}$. Since $B \to B'$ is flat (hence faithfully flat, see Algebra, Lemma Flatness and local algebra), we may replace $A \to B$ with $A^h \to B'$, the module $M$ by $M \otimes_B B'$, the module $N$ by $N \otimes_B B'$, and $u$ by $u \otimes \text{id}_{B'}$, see Algebra, Lemmas Descent of proper morphisms and modules (uncovered prerequisite) and Descent of flatness (uncovered prerequisite). Thus we may assume that $A$ is a henselian local ring. In this case our lemma follows from the more general Lemma Henselian rings and injective resolutions. $\square$
Lemma. A sheaf carried by a closed subscheme
Let $f : X \to S$ be a finite type morphism of affine schemes. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Let $x \in X$ with image $s = f(x)$ in $S$. Set $\mathcal{F}_s = \mathcal{F}|_{X_s}$. Then there exist a closed immersion $i : Z \to X$ of finite presentation, and a quasi-coherent finite type $\mathcal{O}_Z$-module $\mathcal{G}$ such that $i_*\mathcal{G} = \mathcal{F}$ and $Z_s = \text{Supp}(\mathcal{F}_s)$.
Proof. Say the morphism $f : X \to S$ is given by the ring map $A \to B$ and that $\mathcal{F}$ is the quasi-coherent sheaf associated to the $B$-module $M$. By Morphisms, Lemma Finite algebras and local algebra (uncovered prerequisite) we know that $A \to B$ is a finite type ring map, and by Properties, Lemma Modules and finite algebras we know that $M$ is a finite $B$-module. In particular the support of $\mathcal{F}$ is the closed subscheme of $\operatorname{Spec}(B)$ cut out by the annihilator $I = \{x \in B \mid xm = 0\ \forall m \in M\}$ of $M$, see Algebra, Lemma Closed support (uncovered prerequisite). Let $\mathfrak q \subset B$ be the prime ideal corresponding to $x$ and let $\mathfrak p \subset A$ be the prime ideal corresponding to $s$. Note that $X_s = \operatorname{Spec}(B \otimes_A \kappa(\mathfrak p))$ and that $\mathcal{F}_s$ is the quasi-coherent sheaf associated to the $B \otimes_A \kappa(\mathfrak p)$ module $M \otimes_A \kappa(\mathfrak p)$. By Morphisms, Lemma Closed support and finite algebras (uncovered prerequisite) the support of $\mathcal{F}_s$ is equal to $V(I(B \otimes_A \kappa(\mathfrak p)))$. Since $B \otimes_A \kappa(\mathfrak p)$ is of finite type over $\kappa(\mathfrak p)$ there exist finitely many elements $f_1, \ldots, f_m \in I$ such that $$I(B \otimes_A \kappa(\mathfrak p)) = (f_1, \ldots, f_n)(B \otimes_A \kappa(\mathfrak p)).$$ Denote $i : Z \to X$ the closed subscheme cut out by $(f_1, \ldots, f_m)$, in a formula $Z = \operatorname{Spec}(B/(f_1, \ldots, f_m))$. Since $M$ is annihilated by $I$ we can think of $M$ as an $B/(f_1, \ldots, f_m)$-module. In other words, $\mathcal{F}$ is the pushforward of a finite type module on $Z$. As $Z_s = \text{Supp}(\mathcal{F}_s)$ by construction, this proves the lemma. $\square$
Lemma. Injective resolutions and local algebra
Let $(R, \mathfrak m)$ be a local ring. Let $u : M \to N$ be an $R$-module map. If $M$ is a projective $R$-module, $N$ is a flat $R$-module, and $\overline{u} : M/\mathfrak mM \to N/\mathfrak mN$ is injective then $u$ is universally injective.
Proof. By Algebra, Theorem Projective, locally free modules and local algebra (uncovered prerequisite) the module $M$ is free. If we show the result holds for every finitely generated direct summand of $M$, then the lemma follows. Hence we may assume that $M$ is finite free. Write $N = \mathop{\operatorname{colim}}_i N_i$ as a directed colimit of finite free modules, see Algebra, Theorem Commutative algebra (uncovered prerequisite). Note that $u : M \to N$ factors through $N_i$ for some $i$ (as $M$ is finite free). Denote $u_i : M \to N_i$ the corresponding $R$-module map. As $\overline{u}$ is injective we see that $\overline{u_i} : M/\mathfrak mM \to N_i/\mathfrak mN_i$ is injective and remains injective on composing with the maps $N_i/\mathfrak mN_i \to N_{i'}/\mathfrak mN_{i'}$ for all $i' \geq i$. As $M$ and $N_{i'}$ are finite free over the local ring $R$ this implies that $M \to N_{i'}$ is a split injection for all $i' \geq i$. Hence for any $R$-module $Q$ we see that $M \otimes_R Q \to N_{i'} \otimes_R Q$ is injective for all $i' \geq i$. As $- \otimes_R Q$ commutes with colimits we conclude that $M \otimes_R Q \to N_{i'} \otimes_R Q$ is injective as desired. $\square$
Lemma. Projective, locally free modules and flatness
Let $R$ be a ring. Let $R \to S$ be a ring map. Assume
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$R \to S$ is of finite presentation and flat, and
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every fibre ring $S \otimes_R \kappa(\mathfrak p)$ is geometrically integral over $\kappa(\mathfrak p)$.
Then $S$ is projective as an $R$-module.
Proof. We can find a cocartesian diagram of rings
\[ \begin{gathered}\begin{matrix}S_0 & S \\ R_0 & R\end{matrix} \\[6pt] \begin{aligned}S_0 & \longrightarrow S \\ R_0 & \longrightarrow S_0 \\ R_0 & \longrightarrow R \\ R & \longrightarrow S\end{aligned}\end{gathered} \]such that \(R_0\) is of finite type over \(\mathbf{Z}\), the map \(R_0 \to S_0\) is of finite type and flat with geometrically integral fibres, see More on Morphisms, Lemmas Flatness and Noetherian rings (uncovered prerequisite), Noetherian rings (uncovered prerequisite), Noetherian rings (uncovered prerequisite), and Noetherian rings (uncovered prerequisite). By Lemma Projective, locally free modules and flatness we see that \(S_0\) is a projective \(R_0\)-module. Hence \(S = S_0 \otimes_{R_0} R\) is a projective \(R\)-module, see Algebra, Lemma Proper morphisms and modules (uncovered prerequisite). \(\square\)
Lemma. Injective resolutions
Assumption and notation as in Lemma Localization at fibrewise nonzerodivisors. Assume moreover that $N$ is projective as an $R$-module. Then each $s \in \Sigma$ defines a universally injective $R$-module map $s : N \to N$, and the map $N \to \Sigma^{-1}N$ is $R$-universally injective.
Proof. Pick $s \in \Sigma$. By Lemma Injective resolutions and local algebra the map $s : N \to N$ is universally injective. The map $N \to \Sigma^{-1}N$ is universally injective as the directed colimit of the maps $s : N \to N$. $\square$
Lemma. Finite algebras
Let $f : X \to S$ be a morphism which is locally of finite type. Let $\mathcal{F}$ be a finite type quasi-coherent sheaf on $X$ which is flat over $S$. Let $\mathcal{G}$ be a quasi-coherent sheaf on $S$. Then we have $$\text{WeakAss}_X(\mathcal{F} \otimes_{\mathcal{O}_X} f^*\mathcal{G}) = \bigcup\nolimits_{s \in \text{WeakAss}_S(\mathcal{G})} \text{Ass}_{X_s}(\mathcal{F}_s)$$
Proof. Immediate consequence of Lemma Finite algebras. $\square$
Lemma. Prime spectra and associated points
Let $f : X \to S$ be a morphism of schemes of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $s \in S$. Assume that $\mathcal{F}$ is flat over $S$ at all points of $X_s$. Let $x' \in \text{Ass}_{X/S}(\mathcal{F})$ with $f(x') = s'$ such that $s' \leadsto s$ is a specialization in $S$. If $x'$ specializes to a point of $X_s$, then $x' \leadsto x$ with $x \in \text{Ass}_{X_s}(\mathcal{F}_s)$.
Proof. Say $x' \leadsto t$ with $t \in X_s$. Then we can find specializations $x' \leadsto x \leadsto t$ with $x$ corresponding to a generic point of an irreducible component of $\overline{\{x'\}} \cap f^{-1}(\{s\})$. By assumption $\mathcal{F}$ is flat over $S$ at $x$. By More on Morphisms, Lemma Prime spectra and associated points (uncovered prerequisite) we see that $x \in \text{Ass}_{X/S}(\mathcal{F})$ as desired. $\square$
Lemma. Flatness and finite algebras
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Let $s \in S$. Assume
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$f$ is of finite type,
-
$\mathcal{F}$ is of finite type,
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$\mathcal{F}$ is flat over $S$ at all points of $X_s$, and
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$\mathcal{F}$ is pure along $X_s$.
Then $\mathcal{F}$ is universally pure along $X_s$.
Proof. We first make a preliminary remark. Suppose that $(S', s') \to (S, s)$ is an elementary étale neighbourhood. Denote $\mathcal{F}'$ the pullback of $\mathcal{F}$ to $X' = X \times_S S'$. By the discussion following Definition Universal purity of a quasi-coherent module we see that $\mathcal{F}'$ is pure along $X'_{s'}$. Moreover, $\mathcal{F}'$ is flat over $S'$ along $X'_{s'}$. Then it suffices to prove that $\mathcal{F}'$ is universally pure along $X'_{s'}$. Namely, given any morphism $(T, t) \to (S, s)$ of pointed schemes the fibre product $(T', t') = (T \times_S S', (t, s'))$ is flat over $(T, t)$ and hence if $\mathcal{F}_{T'}$ is pure along $X_{t'}$ then $\mathcal{F}_T$ is pure along $X_t$ by Lemma Flatness. Thus during the proof we may always replace $(s, S)$ by an elementary étale neighbourhood. We may also replace $S$ by $\operatorname{Spec}(\mathcal{O}_{S, s})$ due to the local nature of the problem.
Choose an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram $$\begin{gathered}\begin{matrix}X & X' \\ S & \operatorname{Spec}(\mathcal{O}_{S', s'})\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow \operatorname{Spec}(\mathcal{O}_{S', s'}) \\ \operatorname{Spec}(\mathcal{O}_{S', s'}) & \longrightarrow S\end{aligned}\end{gathered}$$ such that $X' \to X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ is étale, $X_s = g((X')_{s'})$, the scheme $X'$ is affine, and such that $\Gamma(X', g^*\mathcal{F})$ is a free $\mathcal{O}_{S', s'}$-module, see Lemma Projective, locally free modules and flatness. Note that $X' \to \operatorname{Spec}(\mathcal{O}_{S', s'})$ is of finite type (as a quasi-compact morphism which is the composition of an étale morphism and the base change of a finite type morphism). By our preliminary remarks in the first paragraph of the proof we may replace $S$ by $\operatorname{Spec}(\mathcal{O}_{S', s'})$. Hence we may assume there exists a commutative diagram $$\begin{gathered}\begin{matrix}X & \phantom{X} & X' \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow S\end{aligned}\end{gathered}$$ of schemes of finite type over $S$, where $g$ is étale, $X_s \subset g(X')$, with $S$ local with closed point $s$, with $X'$ affine, and with $\Gamma(X', g^*\mathcal{F})$ a free $\Gamma(S, \mathcal{O}_S)$-module. Note that in this case $g^*\mathcal{F}$ is universally pure over $S$, see Lemma Projective, locally free modules and affine neighbourhoods.
In this situation we apply Lemma A local criterion for the flattening map to deduce that $\text{Ass}_{X/S}(\mathcal{F}) \subset g(X')$ from our assumption that $\mathcal{F}$ is pure along $X_s$ and flat over $S$ along $X_s$. By Divisors, Lemma Base change for prime spectra and associated points and Remark Base change for prime spectra and associated points we see that for any morphism of pointed schemes $(T, t) \to (S, s)$ we have $$\text{Ass}_{X_T/T}(\mathcal{F}_T) \subset (X_T \to X)^{-1}(\text{Ass}_{X/S}(\mathcal{F})) \subset g(X') \times_S T = g_T(X'_T).$$ Hence by Lemma A local criterion for the flattening map applied to the base change of our displayed diagram to $(T, t)$ we conclude that $\mathcal{F}_T$ is pure along $X_t$ as desired. $\square$
Lemma. The sheaf of module isomorphisms
In Situation The family of module isomorphisms.
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Each of the functors $F_{iso}$, $F_{inj}$, $F_{surj}$, $F_{zero}$ satisfies the sheaf property for the fpqc topology.
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If $f$ is quasi-compact and $\mathcal{G}$ is of finite type, then $F_{surj}$ is limit preserving.
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If $f$ is quasi-compact and $\mathcal{F}$ of finite type, then $F_{zero}$ is limit preserving.
-
If $f$ is quasi-compact, $\mathcal{F}$ is of finite type, and $\mathcal{G}$ is of finite presentation, then $F_{iso}$ is limit preserving.
Proof. Let $\{T_i \to T\}_{i \in I}$ be an fpqc covering of schemes over $S$. Set $X_i = X_{T_i} = X \times_S T_i$ and $u_i = u_{T_i}$. Note that $\{X_i \to X_T\}_{i \in I}$ is an fpqc covering of $X_T$, see Topologies, Lemma The geometric construction (uncovered prerequisite). In particular, for every $x \in X_T$ there exists an $i \in I$ and an $x_i \in X_i$ mapping to $x$. Since $\mathcal{O}_{X_T, x} \to \mathcal{O}_{X_i, x_i}$ is flat, hence faithfully flat (see Algebra, Lemma Flatness and local algebra) we conclude that $(u_i)_{x_i}$ is injective, surjective, bijective, or zero if and only if $(u_T)_x$ is injective, surjective, bijective, or zero. Whence part (1) of the lemma.
Proof of (2). Assume $f$ quasi-compact and $\mathcal{G}$ of finite type. Let $T = \varprojlim_{i \in I} T_i$ be a directed limit of affine $S$-schemes and assume that $u_T$ is surjective. Set $X_i = X_{T_i} = X \times_S T_i$ and $u_i = u_{T_i} : \mathcal{F}_i = \mathcal{F}_{T_i} \to \mathcal{G}_i = \mathcal{G}_{T_i}$. To prove part (2) we have to show that $u_i$ is surjective for some $i$. Pick $i_0 \in I$ and replace $I$ by $\{i \mid i \geq i_0\}$. Since $f$ is quasi-compact the scheme $X_{i_0}$ is quasi-compact. Hence we may choose affine opens $W_1, \ldots, W_m \subset X$ and an affine open covering $X_{i_0} = U_{1, i_0} \cup \ldots \cup U_{m, i_0}$ such that $U_{j, i_0}$ maps into $W_j$ under the projection morphism $X_{i_0} \to X$. For any $i \in I$ let $U_{j, i}$ be the inverse image of $U_{j, i_0}$. Setting $U_j = \varprojlim_i U_{j, i}$ we see that $X_T = U_1 \cup \ldots \cup U_m$ is an affine open covering of $X_T$. Now it suffices to show, for a given $j \in \{1, \ldots, m\}$ that $u_i|_{U_{j, i}}$ is surjective for some $i = i(j) \in I$. Using Properties, Lemma Modules and finite algebras this translates into the following algebra problem: Let $A$ be a ring and let $u : M \to N$ be an $A$-module map. Suppose that $R = \mathop{\operatorname{colim}}_{i \in I} R_i$ is a directed colimit of $A$-algebras. If $N$ is a finite $A$-module and if $u \otimes 1 : M \otimes_A R \to N \otimes_A R$ is surjective, then for some $i$ the map $u \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$ is surjective. This is Algebra, Lemma Filtered limits and proper morphisms and modules part (2).
Proof of (3). Exactly the same arguments as given in the proof of (2) reduces this to the following algebra problem: Let $A$ be a ring and let $u : M \to N$ be an $A$-module map. Suppose that $R = \mathop{\operatorname{colim}}_{i \in I} R_i$ is a directed colimit of $A$-algebras. If $M$ is a finite $A$-module and if $u \otimes 1 : M \otimes_A R \to N \otimes_A R$ is zero, then for some $i$ the map $u \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$ is zero. This is Algebra, Lemma Filtered limits and proper morphisms and modules part (1).
Proof of (4). Assume $f$ quasi-compact and $\mathcal{F}, \mathcal{G}$ of finite presentation. Arguing in exactly the same manner as in the previous paragraph (using in addition also Properties, Lemma Finite presentation and modules) part (3) translates into the following algebra statement: Let $A$ be a ring and let $u : M \to N$ be an $A$-module map. Suppose that $R = \mathop{\operatorname{colim}}_{i \in I} R_i$ is a directed colimit of $A$-algebras. Assume $M$ is a finite $A$-module, $N$ is a finitely presented $A$-module, and $u \otimes 1 : M \otimes_A R \to N \otimes_A R$ is an isomorphism. Then for some $i$ the map $u \otimes 1 : M \otimes_A R_i \to N \otimes_A R_i$ is an isomorphism. This is Algebra, Lemma Filtered limits and proper morphisms and modules part (3). $\square$
Lemma. Finite presentation and flatness
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Let $s \in S$. Assume that
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$f$ is of finite presentation,
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$\mathcal{F}$ is of finite presentation, and
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$\mathcal{F}$ is flat over $S$ at every point of the fibre $X_s$.
Then there exists an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram of schemes $$\begin{gathered}\begin{matrix}X & X' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow S' \\ S' & \longrightarrow S\end{aligned}\end{gathered}$$ such that $g$ is étale, $X_s \subset g(X')$, the schemes $X'$, $S'$ are affine, and such that $\Gamma(X', g^*\mathcal{F})$ is a projective $\Gamma(S', \mathcal{O}_{S'})$-module.
Proof. For every point \(x \in X_s\) we can use Proposition Finite presentation and flatness to find a commutative diagram
\[ \begin{gathered}\begin{matrix}(X, x) & (Y_x, y_x) \\ (S, s) & (S_x, s_x)\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (Y_x, y_x) & \xrightarrow{g_x} (X, x) \\ (Y_x, y_x) & \longrightarrow (S_x, s_x) \\ (S_x, s_x) & \longrightarrow (S, s)\end{aligned}\end{gathered} \]whose horizontal arrows are elementary étale neighbourhoods such that \(Y_x\), \(S_x\) are affine and such that \(\Gamma(Y_x, g_x^*\mathcal{F})\) is a projective \(\Gamma(S_x, \mathcal{O}_{S_x})\)-module. In particular \(g_x(Y_x) \cap X_s\) is an open neighbourhood of \(x\) in \(X_s\). Because \(X_s\) is quasi-compact we can find a finite number of points \(x_1, \ldots, x_n \in X_s\) such that \(X_s\) is the union of the \(g_{x_i}(Y_{x_i}) \cap X_s\). Choose an elementary étale neighbourhood \((S' , s') \to (S, s)\) which dominates each of the neighbourhoods \((S_{x_i}, s_{x_i})\), see More on Morphisms, Lemma Étale morphisms (uncovered prerequisite). We may also assume that \(S'\) is affine. Set \(X' = \coprod Y_{x_i} \times_{S_{x_i}} S'\) and endow it with the obvious morphism \(g : X' \to X\). By construction \(g(X')\) contains \(X_s\) and
\[ \Gamma(X', g^*\mathcal{F}) = \bigoplus \Gamma(Y_{x_i}, g_{x_i}^*\mathcal{F}) \otimes_{\Gamma(S_{x_i}, \mathcal{O}_{S_{x_i}})} \Gamma(S', \mathcal{O}_{S'}). \]This is a projective \(\Gamma(S', \mathcal{O}_{S'})\)-module, see Algebra, Lemma Proper morphisms and modules (uncovered prerequisite). \(\square\)
Lemma. Projective, locally free modules and affine neighbourhoods
Let $f : X \to S$ be a finite type, affine morphism of schemes. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module such that $f_*\mathcal{F}$ is locally projective on $S$, see Properties, Definition Projective, locally free modules and local algebra. Then $\mathcal{F}$ is universally pure over $S$.
Proof. After reducing to the case where $S$ is the spectrum of a henselian local ring this follows from Lemma Purity and dévissage. $\square$
Lemma. A local criterion for the flattening map
Let $f : X \to S$ be a morphism of schemes of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite type. Let $s \in S$. Let $(S', s') \to (S, s)$ be an elementary étale neighbourhood and let $$\begin{gathered}\begin{matrix}X & X' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow S' \\ S' & \longrightarrow S\end{aligned}\end{gathered}$$ be a commutative diagram of morphisms of schemes. Assume
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$\mathcal{F}$ is flat over $S$ at all points of $X_s$,
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$X' \to S'$ is of finite type,
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$g^*\mathcal{F}$ is pure along $X'_{s'}$,
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$g : X' \to X$ is étale, and
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$g(X')$ contains $\text{Ass}_{X_s}(\mathcal{F}_s)$.
In this situation $\mathcal{F}$ is pure along $X_s$ if and only if the image of $X' \to X \times_S S'$ contains the points of $\text{Ass}_{X \times_S S'/S'}(\mathcal{F} \times_S S')$ lying over points in $S'$ which specialize to $s'$.
Proof. Since the morphism $S' \to S$ is étale, we see that if $\mathcal{F}$ is pure along $X_s$, then $\mathcal{F} \times_S S'$ is pure along $X_s$, see Lemma Quasi-finite base change. Since purity satisfies flat descent, see Lemma Flatness, we see that if $\mathcal{F} \times_S S'$ is pure along $X_{s'}$, then $\mathcal{F}$ is pure along $X_s$. Hence we may replace $S$ by $S'$ and assume that $S = S'$ so that $g : X' \to X$ is an étale morphism between schemes of finite type over $S$. Moreover, we may replace $S$ by $\operatorname{Spec}(\mathcal{O}_{S, s})$ and assume that $S$ is local.
First, assume that $\mathcal{F}$ is pure along $X_s$. In this case every point of $\text{Ass}_{X/S}(\mathcal{F})$ specializes to a point of $X_s$ by purity. Hence by Lemma Prime spectra and associated points we see that every point of $\text{Ass}_{X/S}(\mathcal{F})$ specializes to a point of $\text{Ass}_{X_s}(\mathcal{F}_s)$. Thus every point of $\text{Ass}_{X/S}(\mathcal{F})$ is in the image of $g$ (as the image is open and contains $\text{Ass}_{X_s}(\mathcal{F}_s)$).
Conversely, assume that $g(X')$ contains $\text{Ass}_{X/S}(\mathcal{F})$. Let $S^h = \operatorname{Spec}(\mathcal{O}_{S, s}^h)$ be the henselization of $S$ at $s$. Denote $g^h : (X')^h \to X^h$ the base change of $g$ by $S^h \to S$, and denote $\mathcal{F}^h$ the pullback of $\mathcal{F}$ to $X^h$. By Divisors, Lemma Base change for prime spectra and associated points and Remark Base change for prime spectra and associated points the relative assassin $\text{Ass}_{X^h/S^h}(\mathcal{F}^h)$ is the inverse image of $\text{Ass}_{X/S}(\mathcal{F})$ via the projection $X^h \to X$. As we have assumed that $g(X')$ contains $\text{Ass}_{X/S}(\mathcal{F})$ we conclude that the base change $g^h((X')^h) = g(X') \times_S S^h$ contains $\text{Ass}_{X^h/S^h}(\mathcal{F}^h)$. In this way we reduce to the case where $S$ is the spectrum of a henselian local ring. Let $x \in \text{Ass}_{X/S}(\mathcal{F})$. To finish the proof of the lemma we have to show that $x$ specializes to a point of $X_s$, see criterion (4) for purity in discussion following Definition Universal purity of a quasi-coherent module. By assumption there exists a $x' \in X'$ such that $g(x') = x$. As $g : X' \to X$ is étale, we see that $x' \in \text{Ass}_{X'/S}(g^*\mathcal{F})$, see Lemma Étale morphisms and prime spectra and associated points (applied to the morphism of fibres $X'_w \to X_w$ where $w \in S$ is the image of $x'$). Since $g^*\mathcal{F}$ is pure along $X'_s$ we see that $x' \leadsto y$ for some $y \in X'_s$. Hence $x = g(x') \leadsto g(y)$ and $g(y) \in X_s$ as desired. $\square$
Lemma. Purity and dévissage
Let $S$ be a scheme. Let $g : X' \to X$ be a flat morphism of schemes over $S$ with $X$ locally of finite type over $S$. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module which is flat over $S$. If $\text{Ass}_{X/S}(\mathcal{F}) \subset g(X')$ then the canonical map $$\mathcal{F} \longrightarrow g_*g^*\mathcal{F}$$ is injective, and remains injective after any base change.
Proof. The final assertion means that $\mathcal{F}_T \to (g_T)_*g_T^*\mathcal{F}_T$ is injective for any morphism $T \to S$. The assumption $\text{Ass}_{X/S}(\mathcal{F}) \subset g(X')$ is preserved by base change, see Divisors, Lemma Base change for prime spectra and associated points and Remark Base change for prime spectra and associated points. The same holds for the assumption of flatness and finite type. Hence it suffices to prove the injectivity of the displayed arrow. Let $\mathcal{K} = \operatorname{Ker}(\mathcal{F} \to g_*g^*\mathcal{F})$. Our goal is to prove that $\mathcal{K} = 0$. In order to do this it suffices to prove that $\text{WeakAss}_X(\mathcal{K}) = \emptyset$, see Divisors, Lemma The geometric construction (uncovered prerequisite). We have $\text{WeakAss}_X(\mathcal{K}) \subset \text{WeakAss}_X(\mathcal{F})$, see Divisors, Lemma The geometric construction (uncovered prerequisite). As $\mathcal{F}$ is flat we see from Lemma Finite algebras that $\text{WeakAss}_X(\mathcal{F}) \subset \text{Ass}_{X/S}(\mathcal{F})$. By assumption any point $x$ of $\text{Ass}_{X/S}(\mathcal{F})$ is the image of some $x' \in X'$. Since $g$ is flat the local ring map $\mathcal{O}_{X, x} \to \mathcal{O}_{X', x'}$ is faithfully flat, hence the map $$\mathcal{F}_x \longrightarrow g^*\mathcal{F}_{x'} = \mathcal{F}_x \otimes_{\mathcal{O}_{X, x}} \mathcal{O}_{X', x'}$$ is injective (see Algebra, Lemma Universal injectivity of a faithfully flat ring map (uncovered prerequisite)). This implies that $\mathcal{K}_x = 0$ as desired. $\square$
Lemma. Flatness and modules
Let $A$ be a ring. Let $u : M \to N$ be a surjective map of $A$-modules. If $M$ is projective as an $A$-module, then there exists an ideal $I \subset A$ such that for any ring map $\varphi : A \to B$ the following are equivalent
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$u \otimes 1 : M \otimes_A B \to N \otimes_A B$ is an isomorphism, and
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$\varphi(I) = 0$.
Proof. As $M$ is projective we can find a projective $A$-module $C$ such that $F = M \oplus C$ is a free $A$-module. By replacing $u$ by $u \oplus 1 : F = M \oplus C \to N \oplus C$ we see that we may assume $M$ is free. In this case let $I$ be the ideal of $A$ generated by coefficients of all the elements of $\operatorname{Ker}(u)$ with respect to some (fixed) basis of $M$. The reason this works is that, since $u$ is surjective and $\otimes_A B$ is right exact, $\operatorname{Ker}(u \otimes 1)$ is the image of $\operatorname{Ker}(u) \otimes_A B$ in $M \otimes_A B$. $\square$
Lemma. Étale morphisms
Let $$\begin{gathered}\begin{matrix}X & X' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \longrightarrow X \\ X' & \longrightarrow S' \\ S' & \longrightarrow S\end{aligned}\end{gathered}$$ be a commutative diagram of schemes with $X' \to X$ and $S' \to S$ étale. Let $s' \in S'$ be a point. Then $$X' \times_{S'} \operatorname{Spec}(\mathcal{O}_{S', s'}) \longrightarrow X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$$ is étale.
Proof. This is true because $X' \to X_{S'}$ is étale as a morphism of schemes étale over $X$, see Morphisms, Lemma Étale morphisms (uncovered prerequisite) and the base change of an étale morphism is étale, see Morphisms, Lemma Base change for étale morphisms (uncovered prerequisite). $\square$
Lemma. Finite presentation and finite algebras
Assumptions and notation as in Lemma Purity and dévissage. If $f$ is locally of finite presentation then $\pi$ is of finite presentation. In this case the following are equivalent
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$\mathcal{F}$ is an $\mathcal{O}_X$-module of finite presentation in a neighbourhood of $x$,
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$\mathcal{G}$ is an $\mathcal{O}_{Z'}$-module of finite presentation in a neighbourhood of $z'$, and
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$\pi_*\mathcal{G}$ is an $\mathcal{O}_{Y'}$-module of finite presentation in a neighbourhood of $y'$.
Still assuming $f$ locally of finite presentation the following are equivalent to each other
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$\mathcal{F}_x$ is an $\mathcal{O}_{X, x}$-module of finite presentation,
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$\mathcal{G}_{z'}$ is an $\mathcal{O}_{Z', z'}$-module of finite presentation, and
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$(\pi_*\mathcal{G})_{y'}$ is an $\mathcal{O}_{Y', y'}$-module of finite presentation.
Proof. Assume $f$ locally of finite presentation. Then $Z' \to S$ is locally of finite presentation as a composition of such, see Morphisms, Lemma Composition and finite presentation and finite algebras (uncovered prerequisite). Note that $Y' \to S$ is also locally of finite presentation as a composition of a smooth and an étale morphism. Hence Morphisms, Lemma Finite presentation and finite algebras (uncovered prerequisite) implies $\pi$ is locally of finite presentation. Since $\pi$ is finite we conclude that it is also separated and quasi-compact, hence $\pi$ is actually of finite presentation.
To prove the equivalence of (1), (2), and (3) we also consider: (4) $g^*\mathcal{F}$ is a $\mathcal{O}_{X'}$-module of finite presentation in a neighbourhood of $x'$. The pullback of a module of finite presentation is of finite presentation, see Modules, Lemma Pullback of finite presentation and finite algebras (uncovered prerequisite). Hence (1) $\Rightarrow$ (4). The étale morphism $g$ is open, see Morphisms, Lemma Étale morphisms (uncovered prerequisite). Hence for any open neighbourhood $U' \subset X'$ of $x'$, the image $g(U')$ is an open neighbourhood of $x$ and the map $\{U' \to g(U')\}$ is an étale covering. Thus (4) $\Rightarrow$ (1) by Descent, Lemma Finite presentation and finite algebras (uncovered prerequisite). Using Descent, Lemma Finite presentation and modules (uncovered prerequisite) and some easy topological arguments (see More on Morphisms, Lemma Finite algebras) we see that (4) $\Leftrightarrow$ (2) $\Leftrightarrow$ (3).
To prove the equivalence of (a), (b), (c) consider the ring maps $$\mathcal{O}_{X, x} \to \mathcal{O}_{X', x'} \to \mathcal{O}_{Z', z'} \leftarrow \mathcal{O}_{Y', y'}$$ The first ring map is faithfully flat. Hence $\mathcal{F}_x$ is of finite presentation over $\mathcal{O}_{X, x}$ if and only if $g^*\mathcal{F}_{x'}$ is of finite presentation over $\mathcal{O}_{X', x'}$, see Algebra, Lemma Descent of proper morphisms and modules (uncovered prerequisite). The second ring map is surjective (hence finite) and finitely presented by assumption, hence $g^*\mathcal{F}_{x'}$ is of finite presentation over $\mathcal{O}_{X', x'}$ if and only if $\mathcal{G}_{z'}$ is of finite presentation over $\mathcal{O}_{Z', z'}$, see Algebra, Lemma Finite presentation and finite algebras. Because $\pi$ is finite, of finite presentation, and $\pi^{-1}(\{y'\}) = \{x'\}$ the ring homomorphism $\mathcal{O}_{Y', y'} \leftarrow \mathcal{O}_{Z', z'}$ is finite and of finite presentation, see More on Morphisms, Lemma Finite algebras. Hence $\mathcal{G}_{z'}$ is of finite presentation over $\mathcal{O}_{Z', z'}$ if and only if $\pi_*\mathcal{G}_{y'}$ is of finite presentation over $\mathcal{O}_{Y', y'}$, see Algebra, Lemma Finite presentation and finite algebras. $\square$
Lemma. Flatness
Assumptions and notation as in Lemma Purity and dévissage. The following are equivalent
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$\mathcal{F}$ is flat over $S$ in a neighbourhood of $x$,
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$\mathcal{G}$ is flat over $S'$ in a neighbourhood of $z'$, and
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$\pi_*\mathcal{G}$ is flat over $S'$ in a neighbourhood of $y'$.
The following are equivalent also
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$\mathcal{F}_x$ is flat over $\mathcal{O}_{S, s}$,
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$\mathcal{G}_{z'}$ is flat over $\mathcal{O}_{S', s'}$, and
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$(\pi_*\mathcal{G})_{y'}$ is flat over $\mathcal{O}_{S', s'}$.
Proof. To prove the equivalence of (1), (2), and (3) we also consider: (4) $g^*\mathcal{F}$ is flat over $S$ in a neighbourhood of $x'$. We will use Lemma Étale morphisms and flatness to equate flatness over $S$ and $S'$ without further mention. The étale morphism $g$ is flat and open, see Morphisms, Lemma Étale morphisms (uncovered prerequisite). Hence for any open neighbourhood $U' \subset X'$ of $x'$, the image $g(U')$ is an open neighbourhood of $x$ and the map $U' \to g(U')$ is surjective and flat. Thus (4) $\Leftrightarrow$ (1) by Morphisms, Lemma Permanence of flat ring maps (uncovered prerequisite). Note that $$\Gamma(X', g^*\mathcal{F}) = \Gamma(Z', \mathcal{G}) = \Gamma(Y', \pi_*\mathcal{G})$$ Hence the flatness of $g^*\mathcal{F}$, $\mathcal{G}$ and $\pi_*\mathcal{G}$ over $S'$ are all equivalent (this uses that $X'$, $Z'$, $Y'$, and $S'$ are all affine). Some omitted topological arguments (compare More on Morphisms, Lemma Finite algebras) regarding affine neighbourhoods now show that (4) $\Leftrightarrow$ (2) $\Leftrightarrow$ (3).
To prove the equivalence of (a), (b), (c) consider the commutative diagram of local ring maps $$\begin{gathered}\begin{matrix}\mathcal{O}_{X', x'} & \mathcal{O}_{Z', z'} & \mathcal{O}_{Y', y'} & \mathcal{O}_{S', s'} \\ \mathcal{O}_{X, x} & \phantom{X} & \phantom{X} & \mathcal{O}_{S, s}\end{matrix} \\[6pt] \begin{aligned}\mathcal{O}_{X', x'} & \xrightarrow{\iota} \mathcal{O}_{Z', z'} \\ \mathcal{O}_{Y', y'} & \xrightarrow{\alpha} \mathcal{O}_{Z', z'} \\ \mathcal{O}_{S', s'} & \xrightarrow{\beta} \mathcal{O}_{Y', y'} \\ \mathcal{O}_{X, x} & \xrightarrow{\gamma} \mathcal{O}_{X', x'} \\ \mathcal{O}_{S, s} & \xrightarrow{\varphi} \mathcal{O}_{X, x} \\ \mathcal{O}_{S, s} & \xrightarrow{\epsilon} \mathcal{O}_{S', s'}\end{aligned}\end{gathered}$$ We will use Lemma Étale morphisms and flatness to equate flatness over $\mathcal{O}_{S, s}$ and $\mathcal{O}_{S', s'}$ without further mention. The map $\gamma$ is faithfully flat. Hence $\mathcal{F}_x$ is flat over $\mathcal{O}_{S, s}$ if and only if $g^*\mathcal{F}_{x'}$ is flat over $\mathcal{O}_{S', s'}$, see Algebra, Lemma Descent of flatness (uncovered prerequisite). As $\mathcal{O}_{S', s'}$-modules the modules $g^*\mathcal{F}_{x'}$, $\mathcal{G}_{z'}$, and $\pi_*\mathcal{G}_{y'}$ are all isomorphic, see More on Morphisms, Lemma Finite algebras. This finishes the proof. $\square$
Lemma. Étale morphisms and flatness
Let $X \to T \to S$ be morphisms of schemes with $T \to S$ étale. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Let $x \in X$ be a point. Then $$\mathcal{F}\text{ flat over }S\text{ at }x \Leftrightarrow \mathcal{F}\text{ flat over }T\text{ at }x$$ In particular $\mathcal{F}$ is flat over $S$ if and only if $\mathcal{F}$ is flat over $T$.
Proof. As an étale morphism is a flat morphism (see Morphisms, Lemma Étale morphisms and flatness (uncovered prerequisite)) the implication "$\Leftarrow$" follows from Algebra, Lemma Composition and flatness (uncovered prerequisite). For the converse assume that $\mathcal{F}$ is flat at $x$ over $S$. Denote $\tilde x \in X \times_S T$ the point lying over $x$ in $X$ and over the image of $x$ in $T$ in $T$. Then $(X \times_S T \to X)^*\mathcal{F}$ is flat at $\tilde x$ over $T$ via $\text{pr}_2 : X \times_S T \to T$, see Morphisms, Lemma Base change for flatness and modules (uncovered prerequisite). The diagonal $\Delta_{T/S} : T \to T \times_S T$ is an open immersion; combine Morphisms, Lemmas Unramified morphisms and diagonals and separation (uncovered prerequisite) and Étale morphisms and smooth morphisms (uncovered prerequisite). So $X$ is identified with open subscheme of $X \times_S T$, the restriction of $\text{pr}_2$ to this open is the given morphism $X \to T$, the point $\tilde x$ corresponds to the point $x$ in this open, and $(X \times_S T \to X)^*\mathcal{F}$ restricted to this open is $\mathcal{F}$. Whence we see that $\mathcal{F}$ is flat at $x$ over $T$. $\square$
Remark. Agreement of the two purity conditions
Let $A \to B$ be a finite type ring map and let $N$ be a finite $B$-module. Let $\mathfrak q$ be a prime of $B$ lying over the prime $\mathfrak r$ of $A$. Set $X = \operatorname{Spec}(B)$, $S = \operatorname{Spec}(A)$ and $\mathcal{F} = \widetilde{N}$ on $X$. Let $x$ be the point corresponding to $\mathfrak q$ and let $s \in S$ be the point corresponding to $\mathfrak p$. Then
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if there exists a complete dévissage of $\mathcal{F}/X/S$ over $s$ then there exists a complete dévissage of $N/B/A$ over $\mathfrak p$, and
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there exists a complete dévissage of $\mathcal{F}/X/S$ at $x$ if and only if there exists a complete dévissage of $N/B/A$ at $\mathfrak q$.
There is just a small twist in that we omitted the condition on the relative dimension in the formulation of "a complete dévissage of $N/B/A$ over $\mathfrak p$" which is why the implication in (1) only goes in one direction. The notion of a complete dévissage at $\mathfrak q$ does have this condition built in. In any case we will only use that existence for $\mathcal{F}/X/S$ implies the existence for $N/B/A$.
Lemma. Complete rings, formal power series and flatness
Let $(R, \mathfrak m)$ be a local ring. Let $R \to S$ be a ring map of finite presentation. Let $N$ be a finite $S$-module. Let $\mathfrak q$ be a prime of $S$ lying over $\mathfrak m$. Assume that $N_{\mathfrak q}$ is flat over $R$, and assume there exists a complete dévissage of $N/S/R$ at $\mathfrak q$. Then $N$ is a finitely presented $S$-module, free as an $R$-module, and there exists an isomorphism $$N \cong B_1^{\oplus r_1} \oplus \ldots \oplus B_n^{\oplus r_n}$$ as $R$-modules where each $B_i$ is a smooth $R$-algebra with geometrically irreducible fibres.
Proof. Let $(A_i, B_i, M_i, \alpha_i, \mathfrak q_i)_{i = 1, \ldots, n}$ be the given complete dévissage. We prove the lemma by induction on $n$. Note that $N$ is finitely presented as an $S$-module if and only if $M_1$ is finitely presented as an $B_1$-module, see Remark Finite presentation and finite algebras. Note that $N_{\mathfrak q} \cong (M_1)_{\mathfrak q_1}$ as $R$-modules because (a) $N_{\mathfrak q} \cong (M_1)_{\mathfrak q'_1}$ where $\mathfrak q'_1$ is the unique prime in $A_1$ lying over $\mathfrak q_1$ and (b) $(A_1)_{\mathfrak q'_1} = (A_1)_{\mathfrak q_1}$ by Algebra, Lemma Prime spectra, associated points and local algebra (uncovered prerequisite), so (c) $(M_1)_{\mathfrak q'_1} \cong (M_1)_{\mathfrak q_1}$. Hence $(M_1)_{\mathfrak q_1}$ is a flat $R$-module. Thus we may replace $(S, N)$ by $(B_1, M_1)$ in order to prove the lemma. By Lemma Extending perfect approximation across a distinguished square the map $\alpha_1 : B_1^{\oplus r_1} \to M_1$ is $R$-universally injective and $\operatorname{Coker}(\alpha_1)_{\mathfrak q}$ is $R$-flat. Note that $(A_i, B_i, M_i, \alpha_i, \mathfrak q_i)_{i = 2, \ldots, n}$ is a complete dévissage of $\operatorname{Coker}(\alpha_1)/B_1/R$ at $\mathfrak q_1$. Hence the induction hypothesis implies that $\operatorname{Coker}(\alpha_1)$ is finitely presented as a $B_1$-module, free as an $R$-module, and has a decomposition as in the lemma. This implies that $M_1$ is finitely presented as a $B_1$-module, see Algebra, Lemma Commutative algebra. It further implies that $M_1 \cong B_1^{\oplus r_1} \oplus \operatorname{Coker}(\alpha_1)$ as $R$-modules, hence a decomposition as in the lemma. Finally, $B_1$ is projective as an $R$-module by Lemma Projective, locally free modules and flatness hence free as an $R$-module by Algebra, Theorem Projective, locally free modules and local algebra (uncovered prerequisite). This finishes the proof. $\square$
Lemma. Henselian rings and injective resolutions
If in Situation Injective resolutions the ring $A$ is henselian then the lemma holds.
Proof. It suffices to prove this when $B$ is essentially of finite presentation over $A$ and $N$ is of finite presentation over $B$, see Lemma Injective resolutions and flatness. Let us temporarily make the additional assumption that $N$ is flat over $A$. Then $N$ is a filtered colimit $N = \mathop{\operatorname{colim}}_i F_i$ of free $A$-modules $F_i$ such that the transition maps $u_{ii'} : F_i \to F_{i'}$ are injective modulo $\mathfrak m_A$, see Lemma Filtered limits and projective, locally free modules and flatness. Each of the compositions $u_i : F_i \to M$ is $A$-universally injective by Lemma Injective resolutions and local algebra wherefore $u = \mathop{\operatorname{colim}} u_i$ is $A$-universally injective as desired.
Assume $A$ is a henselian local ring, $B$ is essentially of finite presentation over $A$, $N$ of finite presentation over $B$. By Theorem Flatness and local algebra there exists a finitely generated ideal $I \subset A$ such that $N/IN$ is flat over $A/I$ and such that $N/I^2N$ is not flat over $A/I^2$ unless $I = 0$. The result of the previous paragraph shows that the lemma holds for $u \bmod I : N/IN \to M/IM$ over $A/I$. Consider the commutative diagram $$\begin{gathered}\begin{matrix}0 & M \otimes_A I/I^2 & M/I^2M & M/IM & 0 \\ \phantom{X} & N \otimes_A I/I^2 & N/I^2N & N/IN & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow M \otimes_A I/I^2 \\ M \otimes_A I/I^2 & \longrightarrow M/I^2M \\ M/I^2M & \longrightarrow M/IM \\ M/IM & \longrightarrow 0 \\ N \otimes_A I/I^2 & \longrightarrow N/I^2N \\ N \otimes_A I/I^2 & \xrightarrow{u} M \otimes_A I/I^2 \\ N/I^2N & \longrightarrow N/IN \\ N/I^2N & \xrightarrow{u} M/I^2M \\ N/IN & \longrightarrow 0 \\ N/IN & \xrightarrow{u} M/IM\end{aligned}\end{gathered}$$ whose rows are exact by right exactness of $\otimes$ and the fact that $M$ is flat over $A$. Note that the left vertical arrow is the map $N/IN \otimes_{A/I} I/I^2 \to M/IM \otimes_{A/I} I/I^2$, hence is injective. A diagram chase shows that the lower left arrow is injective, i.e., $\text{Tor}^1_{A/I^2}(I/I^2, M/I^2) = 0$ see Algebra, Remark Tor for a quotient by an ideal. Hence $N/I^2N$ is flat over $A/I^2$ by Algebra, Lemma A reformulation of the local algebraic condition a contradiction unless $I = 0$. $\square$
Lemma. Projective, locally free modules and flatness
Let $R$ be a ring. Let $R \to S$ be a ring map. Assume
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$R$ is Noetherian,
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$R \to S$ is of finite type and flat, and
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every fibre ring $S \otimes_R \kappa(\mathfrak p)$ is geometrically integral over $\kappa(\mathfrak p)$.
Then $S$ is projective as an $R$-module.
Proof. Consider the set $$\{I \subset R \mid S/IS\text{ not projective as }R/I\text{-module}\}$$ We have to show this set is empty. To get a contradiction assume it is nonempty. Then it contains a maximal element $I$. Let $J = \sqrt{I}$ be its radical. If $I \not = J$, then $S/JS$ is projective as a $R/J$-module, and $S/IS$ is flat over $R/I$ and $J/I$ is a nilpotent ideal in $R/I$. Applying Algebra, Lemma Lifting projective and locally free modules (uncovered prerequisite) we see that $S/IS$ is a projective $R/I$-module, which is a contradiction. Hence we may assume that $I$ is a radical ideal. In other words we are reduced to proving the lemma in case $R$ is a reduced ring and $S/IS$ is a projective $R/I$-module for every nonzero ideal $I$ of $R$.
Assume $R$ is a reduced ring and $S/IS$ is a projective $R/I$-module for every nonzero ideal $I$ of $R$. By generic flatness, Algebra, Lemma Flatness and Noetherian rings (applied to a localization $R_g$ which is a domain) or the more general Algebra, Lemma Flatness (uncovered prerequisite) there exists a nonzero $f \in R$ such that $S_f$ is free as an $R_f$-module. Denote $R^\wedge = \varprojlim R/(f^n)$ the $(f)$-adic completion of $R$. Note that the ring map $$R \longrightarrow R_f \times R^\wedge$$ is a faithfully flat ring map, see Algebra, Lemma Complete rings, formal power series and flatness (uncovered prerequisite). Hence by faithfully flat descent of projectivity, see Algebra, Theorem Commutative algebra (uncovered prerequisite) it suffices to prove that $S \otimes_R R^\wedge$ is a projective $R^\wedge$-module. To see this we will use the criterion of Lemma Complete rings, formal power series and projective and locally free modules. First of all, note that $S/fS = (S \otimes_R R^\wedge)/f(S \otimes_R R^\wedge)$ is a projective $R/(f)$-module and that $S \otimes_R R^\wedge$ is flat and of finite type over $R^\wedge$ as a base change of such. Next, suppose that $\mathfrak p^\wedge$ is a prime ideal of $R^\wedge$. Let $\mathfrak p \subset R$ be the corresponding prime of $R$. As $R \to S$ has geometrically integral fibre rings, the same is true for the fibre rings of any base change. Hence $\mathfrak q^\wedge = \mathfrak p^\wedge(S \otimes_R R^\wedge)$, is a prime ideals lying over $\mathfrak p^\wedge$ and it is the unique associated prime of $S \otimes_R \kappa(\mathfrak p^\wedge)$. Thus we win if $f(S \otimes_R R^\wedge) + \mathfrak q^\wedge \not = S \otimes_R R^\wedge$. This is true because $\mathfrak p^\wedge + fR^\wedge \not = R^\wedge$ as $f$ lies in the Jacobson radical of the $f$-adically complete ring $R^\wedge$ and because $R^\wedge \to S \otimes_R R^\wedge$ is surjective on spectra as its fibres are nonempty (irreducible spaces are nonempty). $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $f : X \to S$ be locally of finite type. Let $x \in X$ with image $s \in S$. Let $\mathcal{F}$ be a finite type quasi-coherent sheaf on $X$. Let $\mathcal{G}$ be a quasi-coherent sheaf on $S$. If $\mathcal{F}$ is flat at $x$ over $S$, then $$x \in \text{WeakAss}_X(\mathcal{F} \otimes_{\mathcal{O}_X} f^*\mathcal{G}) \Leftrightarrow s \in \text{WeakAss}_S(\mathcal{G}) \text{ and } x \in \text{Ass}_{X_s}(\mathcal{F}_s).$$
Proof. In this paragraph we reduce to $f$ being of finite presentation. The question is local on $X$ and $S$, hence we may assume $X$ and $S$ are affine. Write $X = \operatorname{Spec}(B)$, $S = \operatorname{Spec}(A)$ and write $B = A[x_1, \ldots, x_n]/I$. In other words we obtain a closed immersion $i : X \to \mathbf{A}^n_S$ over $S$. Denote $t = i(x) \in \mathbf{A}^n_S$. Note that $i_*\mathcal{F}$ is a finite type quasi-coherent sheaf on $\mathbf{A}^n_S$ which is flat at $t$ over $S$ and note that $$i_*(\mathcal{F} \otimes_{\mathcal{O}_X} f^*\mathcal{G}) = i_*\mathcal{F} \otimes_{\mathcal{O}_{\mathbf{A}^n_S}} p^*\mathcal{G}$$ where $p : \mathbf{A}^n_S \to S$ is the projection. Note that $t$ is a weakly associated point of $i_*(\mathcal{F} \otimes_{\mathcal{O}_X} f^*\mathcal{G})$ if and only if $x$ is a weakly associated point of $\mathcal{F} \otimes_{\mathcal{O}_X} f^*\mathcal{G}$, see Divisors, Lemma Prime spectra, associated points and finite algebras (uncovered prerequisite). Similarly $x \in \text{Ass}_{X_s}(\mathcal{F}_s)$ if and only if $t \in \text{Ass}_{\mathbf{A}^n_s}((i_*\mathcal{F})_s)$ (see Algebra, Lemma Commutative algebra (uncovered prerequisite)). Hence it suffices to prove the lemma in case $X = \mathbf{A}^n_S$. Thus we may assume that $X \to S$ is of finite presentation.
In this paragraph we reduce to $\mathcal{F}$ being of finite presentation and flat over $S$. Choose an elementary étale neighbourhood $e : (S', s') \to (S, s)$ and an open $V \subset X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ as in Proposition Flatness and finite algebras. Let $x' \in X' = X \times_S S'$ be the unique point mapping to $x$ and $s'$. Then it suffices to prove the statement for $X' \to S'$, $x'$, $s'$, $(X' \to X)^*\mathcal{F}$, and $e^*\mathcal{G}$, see Lemma Étale morphisms and prime spectra and associated points. Let $v \in V$ the unique point mapping to $x'$ and let $s' \in \operatorname{Spec}(\mathcal{O}_{S', s'})$ be the closed point. Then $\mathcal{O}_{V, v} = \mathcal{O}_{X', x'}$ and $\mathcal{O}_{\operatorname{Spec}(\mathcal{O}_{S', s'}), s'} = \mathcal{O}_{S', s'}$ and similarly for the stalks of pullbacks of $\mathcal{F}$ and $\mathcal{G}$. Also $V_{s'} \subset X'_{s'}$ is an open subscheme. Since the condition of being a weakly associated point depend only on the stalk of the sheaf, we may replace $X' \to S'$, $x'$, $s'$, $(X' \to X)^*\mathcal{F}$, and $e^*\mathcal{G}$ by $V \to \operatorname{Spec}(\mathcal{O}_{S', s'})$, $v$, $s'$, $(V \to X)^*\mathcal{F}$, and $(\operatorname{Spec}(\mathcal{O}_{S', s'}) \to S)^*\mathcal{G}$. Thus we may assume that $f$ is of finite presentation and $\mathcal{F}$ of finite presentation and flat over $S$.
Assume $f$ is of finite presentation and $\mathcal{F}$ of finite presentation and flat over $S$. After shrinking $X$ and $S$ to affine neighbourhoods of $x$ and $s$, this case is handled by Lemma A preliminary relative associated-prime criterion. $\square$
Definition. Universal purity of a quasi-coherent module
Let $f : X \to S$ be a morphism of schemes which is of finite type. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module.
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Let $s \in S$. We say $\mathcal{F}$ is pure along $X_s$ if there is no impurity $(g : T \to S, t' \leadsto t, \xi)$ of $\mathcal{F}$ above $s$ with $(T, t) \to (S, s)$ an elementary étale neighbourhood.
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We say $\mathcal{F}$ is universally pure along $X_s$ if there does not exist any impurity of $\mathcal{F}$ above $s$.
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We say that $X$ is pure along $X_s$ if $\mathcal{O}_X$ is pure along $X_s$.
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We say $\mathcal{F}$ is universally $S$-pure, or universally pure relative to $S$ if $\mathcal{F}$ is universally pure along $X_s$ for every $s \in S$.
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We say $\mathcal{F}$ is $S$-pure, or pure relative to $S$ if $\mathcal{F}$ is pure along $X_s$ for every $s \in S$.
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We say that $X$ is $S$-pure or pure relative to $S$ if $\mathcal{O}_X$ is pure relative to $S$.
Lemma. Flatness
Let $f : X \to S$ be a morphism of schemes which is of finite type. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Let $s \in S$. Let $(S', s') \to (S, s)$ be a morphism of pointed schemes. Assume $S' \to S$ is flat at $s'$.
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If $\mathcal{F}_{S'}$ is pure along $X_{s'}$, then $\mathcal{F}$ is pure along $X_s$.
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If $\mathcal{F}_{S'}$ is universally pure along $X_{s'}$, then $\mathcal{F}$ is universally pure along $X_s$.
Proof. Let $(T \to S, t' \leadsto t, \xi)$ be an impurity of $\mathcal{F}$ above $s$. Set $T_1 = T \times_S S'$, and let $t_1$ be the unique point of $T_1$ mapping to $t$ and $s'$. Since $T_1 \to T$ is flat at $t_1$, see Morphisms, Lemma Base change for flatness (uncovered prerequisite), there exists a specialization $t'_1 \leadsto t_1$ lying over $t' \leadsto t$, see Algebra, Section Commutative algebra. Choose a point $\xi_1 \in X_{t'_1}$ which corresponds to a generic point of $\operatorname{Spec}(\kappa(t'_1) \otimes_{\kappa(t')} \kappa(\xi))$, see Schemes, Lemma Tensor products and direct sums (uncovered prerequisite). By Divisors, Lemma Base change for prime spectra and associated points we see that $\xi_1 \in \text{Ass}_{X_{T_1}/T_1}(\mathcal{F}_{T_1})$. As the Zariski closure of $\{\xi_1\}$ in $X_{T_1}$ maps into the Zariski closure of $\{\xi\}$ in $X_T$ we conclude that this closure is disjoint from $X_{t_1}$. Hence $(T_1 \to S', t'_1 \leadsto t_1, \xi_1)$ is an impurity of $\mathcal{F}_{S'}$ above $s'$. In other words we have proved the contrapositive to part (2) of the lemma. Finally, if $(T, t) \to (S, s)$ is an elementary étale neighbourhood, then $(T_1, t_1) \to (S', s')$ is an elementary étale neighbourhood too, and in this way we see that (1) holds. $\square$
Lemma. Projective, locally free modules and flatness
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Let $s \in S$. Assume that
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$f$ is of finite type,
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$\mathcal{F}$ is of finite type, and
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$\mathcal{F}$ is flat over $S$ at all points of $X_s$.
Then there exists an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram of schemes $$\begin{gathered}\begin{matrix}X & X' \\ S & \operatorname{Spec}(\mathcal{O}_{S', s'})\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow \operatorname{Spec}(\mathcal{O}_{S', s'}) \\ \operatorname{Spec}(\mathcal{O}_{S', s'}) & \longrightarrow S\end{aligned}\end{gathered}$$ such that $X' \to X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ is étale, $X_s = g((X')_{s'})$, the scheme $X'$ is affine, and such that $\Gamma(X', g^*\mathcal{F})$ is a free $\mathcal{O}_{S', s'}$-module.
Proof. (The only difference with Lemma Projective, locally free modules and flatness is that we do not assume $f$ is of finite presentation.) For every point $x \in X_s$ we can use Lemma Projective, locally free modules and flatness to find an elementary étale neighbourhood $(S_x , s_x) \to (S, s)$ and a commutative diagram $$\begin{gathered}\begin{matrix}(X, x) & (Y_x, y_x) \\ (S, s) & (\operatorname{Spec}(\mathcal{O}_{S_x, s_x}), s_x)\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (Y_x, y_x) & \xrightarrow{g_x} (X, x) \\ (Y_x, y_x) & \longrightarrow (\operatorname{Spec}(\mathcal{O}_{S_x, s_x}), s_x) \\ (\operatorname{Spec}(\mathcal{O}_{S_x, s_x}), s_x) & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ such that $Y_x \to X \times_S \operatorname{Spec}(\mathcal{O}_{S_x, s_x})$ is étale, $\kappa(x) = \kappa(y_x)$, the scheme $Y_x$ is affine, and such that $\Gamma(Y_x, g_x^*\mathcal{F})$ is a free $\mathcal{O}_{S_x, s_x}$-module. In particular $g_x((Y_x)_{s_x})$ is an open neighbourhood of $x$ in $X_s$. Because $X_s$ is quasi-compact we can find a finite number of points $x_1, \ldots, x_n \in X_s$ such that $X_s$ is the union of the $g_{x_i}((Y_{x_i})_{s_{x_i}})$. Choose an elementary étale neighbourhood $(S' , s') \to (S, s)$ which dominates each of the neighbourhoods $(S_{x_i}, s_{x_i})$, see More on Morphisms, Lemma Étale morphisms (uncovered prerequisite). Set $$X' = \coprod Y_{x_i} \times_{\operatorname{Spec}(\mathcal{O}_{S_{x_i}, s_{x_i}})} \operatorname{Spec}(\mathcal{O}_{S', s'})$$ and endow it with the obvious morphism $g : X' \to X$. By construction $X_s = g(X'_{s'})$ and $$\Gamma(X', g^*\mathcal{F})
\bigoplus \Gamma(Y_{x_i}, g_{x_i}^*\mathcal{F}) \otimes_{\mathcal{O}{S{x_i}, s_{x_i}}} \mathcal{O}{S', s'}.$$ This is a free $\mathcal{O}{S', s'}$-module as a direct sum of base changes of free modules. $\square$
Proposition. Finite presentation and flatness
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Let $x \in X$ with image $s \in S$. Assume that
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$f$ is locally of finite presentation,
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$\mathcal{F}$ is of finite presentation, and
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$\mathcal{F}$ is flat at $x$ over $S$.
Then there exists a commutative diagram of pointed schemes $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (S', s')\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (S', s') \\ (S', s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ whose horizontal arrows are elementary étale neighbourhoods such that $X'$, $S'$ are affine and such that $\Gamma(X', g^*\mathcal{F})$ is a projective $\Gamma(S', \mathcal{O}_{S'})$-module.
Proof. By openness of flatness, see More on Morphisms, Theorem Openness of the flat locus we may replace $X$ by an open neighbourhood of $x$ and assume that $\mathcal{F}$ is flat over $S$. Next, we apply Proposition Complete dévissage at a point to find a diagram as in the statement of the proposition such that $g^*\mathcal{F}/X'/S'$ has a complete dévissage over $s'$. (In particular $S'$ and $X'$ are affine.) By Morphisms, Lemma Permanence of flat ring maps (uncovered prerequisite) we see that $g^*\mathcal{F}$ is flat over $S$ and by Lemma Étale morphisms and flatness we see that it is flat over $S'$. Via Remark Agreement of the two purity conditions we deduce that $$\Gamma(X', g^*\mathcal{F})/ \Gamma(X', \mathcal{O}_{X'})/ \Gamma(S', \mathcal{O}_{S'})$$ has a complete dévissage over the prime of $\Gamma(S', \mathcal{O}_{S'})$ corresponding to $s'$. Thus Lemma Complete rings, formal power series and finite presentation implies that the result of the proposition holds after replacing $S'$ by a standard open neighbourhood of $s'$. $\square$
Lemma. Purity and dévissage
Let $R$ be a local ring with maximal ideal $\mathfrak m$. Let $R \to S$ be a ring map. Let $N$ be an $S$-module. Assume
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$N$ is projective as an $R$-module, and
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$S/\mathfrak mS$ is Noetherian and $N/\mathfrak mN$ is a finite $S/\mathfrak mS$-module.
Then for any prime $\mathfrak q \subset S$ which is an associated prime of $N \otimes_R \kappa(\mathfrak p)$ where $\mathfrak p = R \cap \mathfrak q$ we have $\mathfrak q + \mathfrak m S \not = S$.
Proof. Note that the hypotheses of Lemmas Localization at fibrewise nonzerodivisors and Injective resolutions are satisfied. We will use the conclusions of these lemmas without further mention. Let $\Sigma \subset S$ be the multiplicative set of elements which are not zerodivisors on $N/\mathfrak mN$. The map $N \to \Sigma^{-1}N$ is $R$-universally injective. Hence we see that any $\mathfrak q \subset S$ which is an associated prime of $N \otimes_R \kappa(\mathfrak p)$ is also an associated prime of $\Sigma^{-1}N \otimes_R \kappa(\mathfrak p)$. Clearly this implies that $\mathfrak q$ corresponds to a prime of $\Sigma^{-1}S$. Thus $\mathfrak q \subset \mathfrak q'$ where $\mathfrak q'$ corresponds to an associated prime of $N/\mathfrak mN$ and we win. $\square$
Lemma. Quasi-finite base change
Let $f : X \to S$ be a morphism of schemes which is of finite type. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_X$-module. Let $s \in S$. Let $(S', s') \to (S, s)$ be a morphism of pointed schemes. If $S' \to S$ is quasi-finite at $s'$ and $\mathcal{F}$ is pure along $X_s$, then $\mathcal{F}_{S'}$ is pure along $X_{s'}$.
Proof. It $(T \to S', t' \leadsto t, \xi)$ is an impurity of $\mathcal{F}_{S'}$ above $s'$ with $T \to S'$ quasi-finite at $t$, then $(T \to S, t' \to t, \xi)$ is an impurity of $\mathcal{F}$ above $s$ with $T \to S$ quasi-finite at $t$, see Morphisms, Lemma Composition and finite algebras (uncovered prerequisite). Hence the lemma follows immediately from the characterization (2) of purity given following Definition Universal purity of a quasi-coherent module. $\square$
Lemma. Étale morphisms and prime spectra and associated points
Let $h : U \to S$ be an étale morphism of schemes. Let $\mathcal{G}$ be a quasi-coherent $\mathcal{O}_S$-module. Let $u \in U$ be a point with image $s \in S$. Then $$u \in \text{WeakAss}(h^*\mathcal{G}) \Leftrightarrow s \in \text{WeakAss}(\mathcal{G})$$
Proof. After replacing $S$ and $U$ by affine neighbourhoods of $s$ and $u$ we may assume that $g$ is a standard étale morphism of affines, see Morphisms, Lemma Étale morphisms and local algebra (uncovered prerequisite). Thus we may assume $S = \operatorname{Spec}(A)$ and $X = \operatorname{Spec}(A[x, 1/g]/(f))$, where $f$ is monic and $f'$ is invertible in $A[x, 1/g]$. Note that $A[x, 1/g]/(f) = (A[x]/(f))_g$ is also the localization of the finite free $A$-algebra $A[x]/(f)$. Hence we may think of $U$ as an open subscheme of the scheme $T = \operatorname{Spec}(A[x]/(f))$ which is finite locally free over $S$. This reduces us to Lemma Flatness and prime spectra and associated points above. $\square$
Lemma. Étale morphisms and flatness
Let $T \to S$ be an étale morphism. Let $t \in T$ with image $s \in S$. Let $M$ be a $\mathcal{O}_{T, t}$-module. Then $$M\text{ flat over }\mathcal{O}_{S, s} \Leftrightarrow M\text{ flat over }\mathcal{O}_{T, t}.$$
Proof. We may replace $S$ by an affine neighbourhood of $s$ and after that $T$ by an affine neighbourhood of $t$. Set $\mathcal{F} = (\operatorname{Spec}(\mathcal{O}_{T, t}) \to T)_*\widetilde M$. This is a quasi-coherent sheaf (see Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite) or argue directly) on $T$ whose stalk at $t$ is $M$ (details omitted). Apply Lemma Étale morphisms and flatness. $\square$
Remark. Finite presentation and finite algebras
Note that the $R$-algebras $B_i$ for all $i$ and $A_i$ for $i \geq 2$ are of finite presentation over $R$. If $S$ is of finite presentation over $R$, then it is also the case that $A_1$ is of finite presentation over $R$. In this case all the ring maps in the complete dévissage are of finite presentation. See Algebra, Lemma Composition of finite-type ring maps. Still assuming $S$ of finite presentation over $R$ the following are equivalent
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$M$ is of finite presentation over $S$,
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$M_1$ is of finite presentation over $A_1$,
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$M_1$ is of finite presentation over $B_1$,
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each $M_i$ is of finite presentation both as an $A_i$-module and as a $B_i$-module.
The equivalences (1) $\Leftrightarrow$ (2) and (2) $\Leftrightarrow$ (3) follow from Algebra, Lemma Finite presentation and finite algebras. If $M_1$ is finitely presented, so is $\operatorname{Coker}(\alpha_1)$ (see Algebra, Lemma Commutative algebra) and hence $M_2$, etc.
Situation. Injective resolutions
Let $\varphi : A \to B$ be a local ring homomorphism of local rings which is essentially of finite type. Let $M$ be a flat $A$-module, $N$ a finite $B$-module and $u : N \to M$ an $A$-module map such that $\overline{u} : N/\mathfrak m_AN \to M/\mathfrak m_AM$ is injective.
Lemma. Injective resolutions and flatness
Let $A_0$ be a local ring. If the lemma holds for every Situation Injective resolutions with $A = A_0$, with $B$ a localization of a polynomial algebra over $A$, and $N$ of finite presentation over $B$, then the lemma holds for every Situation Injective resolutions with $A = A_0$.
Proof. Let $A \to B$, $u : N \to M$ be as in Situation Injective resolutions. Write $B = C/I$ where $C$ is the localization of a polynomial algebra over $A$ at a prime. If we can show that $N$ is finitely presented as a $C$-module, then a fortiori this shows that $N$ is finitely presented as a $B$-module (see Algebra, Lemma Finite presentation and finite algebras). Hence we may assume that $B$ is the localization of a polynomial algebra. Next, write $N = B^{\oplus n}/K$ for some submodule $K \subset B^{\oplus n}$. Since $B/\mathfrak m_AB$ is Noetherian (as it is essentially of finite type over a field), there exist finitely many elements $k_1, \ldots, k_s \in K$ such that for $K' = \sum Bk_i$ and $N' = B^{\oplus n}/K'$ the canonical surjection $N' \to N$ induces an isomorphism $N'/\mathfrak m_AN' \cong N/\mathfrak m_AN$. Now, if the lemma holds for the composition $u' : N' \to M$, then $u'$ is injective, hence $N' = N$ and $u' = u$. Thus the lemma holds for the original situation. $\square$
Lemma. Filtered limits and projective, locally free modules and flatness
Let $A \to B$ be a local ring map of local rings which is essentially of finite type. Let $N$ be a finite $B$-module which is flat as an $A$-module. If $A$ is henselian, then $N$ is a filtered colimit $$N = \mathop{\operatorname{colim}}_i F_i$$ of free $A$-modules $F_i$ such that all transition maps $u_i : F_i \to F_{i'}$ of the system induce injective maps $\overline{u}_i : F_i/\mathfrak m_AF_i \to F_{i'}/\mathfrak m_AF_{i'}$. Also, $N$ is a Mittag-Leffler $A$-module.
Proof. We can find a morphism of finite type $X \to S = \operatorname{Spec}(A)$ and a point $x \in X$ lying over the closed point $s$ of $S$ and a finite type quasi-coherent $\mathcal{O}_X$-module $\mathcal{F}$ such that $\mathcal{F}_x \cong N$ as an $A$-module. After shrinking $X$ we may assume that each point of $\text{Ass}_{X_s}(\mathcal{F}_s)$ specializes to $x$. By Lemma Projective, locally free modules and flatness we see that there exists a fundamental system of affine open neighbourhoods $U_i \subset X$ of $x$ such that $\Gamma(U_i, \mathcal{F})$ is a free $A$-module $F_i$. Note that if $U_{i'} \subset U_i$, then $$F_i/\mathfrak m_AF_i = \Gamma(U_{i, s}, \mathcal{F}_s) \longrightarrow \Gamma(U_{i', s}, \mathcal{F}_s) = F_{i'}/\mathfrak m_AF_{i'}$$ is injective because a section of the kernel would be supported at a closed subset of $X_s$ not meeting $x$ which is a contradiction to our choice of $X$ above. Since the maps $F_i \to F_{i'}$ are $A$-universally injective (Lemma Injective resolutions and local algebra) it follows that $N$ is Mittag-Leffler by Algebra, Lemma Filtered limits and injective resolutions (uncovered prerequisite). $\square$
Theorem. Flatness and local algebra
In Situation Flatness assume $A$ is henselian, $B$ is essentially of finite type over $A$, and $M$ is a finite $B$-module. Then there exists an ideal $I \subset A$ such that $A/I$ corepresents the functor $F_{lf}$ on the category $\mathcal{C}$. In other words given a local homomorphism of local rings $\varphi : A \to A'$ with $B' = B \otimes_A A'$ and $M' = M \otimes_A A'$ the following are equivalent:
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$\forall \mathfrak q \in V(\mathfrak m_{A'}B' + \mathfrak m_B B') \subset \operatorname{Spec}(B') : M'_{\mathfrak q}\text{ is flat over }A'$, and
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$\varphi(I) = 0$.
If $B$ is essentially of finite presentation over $A$ and $M$ of finite presentation over $B$, then $I$ is a finitely generated ideal.
Proof. Choose a finite type ring map $A \to C$ and a finite $C$-module $N$ and a prime $\mathfrak q$ of $C$ such that $B = C_{\mathfrak q}$ and $M = N_{\mathfrak q}$. In the following, when we say "the theorem holds for $(N/C/A, \mathfrak q)$ we mean that it holds for $(A \to B, M)$ where $B = C_{\mathfrak q}$ and $M = N_{\mathfrak q}$. By Lemma Flatness the functor $F_{lf}$ is unchanged if we replace $B$ by a local ring flat over $B$. Hence, since $A$ is henselian, we may apply Lemma Construction of an algebraic dévissage and assume that there exists a complete dévissage of $N/C/A$ at $\mathfrak q$.
Let $(A_i, B_i, M_i, \alpha_i, \mathfrak q_i)_{i = 1, \ldots, n}$ be such a complete dévissage of $N/C/A$ at $\mathfrak q$. Let $\mathfrak q'_i \subset A_i$ be the unique prime lying over $\mathfrak q_i \subset B_i$ as in Definition Complete algebraic dévissage at a point. Since $C \to A_1$ is surjective and $N \cong M_1$ as $C$-modules, we see by Lemma Flatness and finite algebras it suffices to prove the theorem holds for $(M_1/A_1/A, \mathfrak q'_1)$. Since $B_1 \to A_1$ is finite and $\mathfrak q_1$ is the only prime of $B_1$ over $\mathfrak q'_1$ we see that $(A_1)_{\mathfrak q'_1} \to (B_1)_{\mathfrak q_1}$ is finite (see Algebra, Lemma Prime spectra, associated points and local algebra (uncovered prerequisite) or More on Morphisms, Lemma Finite algebras). Hence by Lemma Flatness and finite algebras it suffices to prove the theorem holds for $(M_1/B_1/A, \mathfrak q_1)$.
At this point we may assume, by induction on the length $n$ of the dévissage, that the theorem holds for $(M_2/B_2/A, \mathfrak q_2)$. (If $n = 1$, then $M_2 = 0$ which is flat over $A$.) Reversing the last couple of steps of the previous paragraph, using that $M_2 \cong \operatorname{Coker}(\alpha_2)$ as $B_1$-modules, we see that the theorem holds for $(\operatorname{Coker}(\alpha_1)/B_1/A, \mathfrak q_1)$.
Let $A'$ be an object of $\mathcal{C}$. At this point we use Lemma Extending perfect approximation across a distinguished square to see that if $(M_1 \otimes_A A')_{\mathfrak q'}$ is flat over $A'$ for a prime $\mathfrak q'$ of $B_1 \otimes_A A'$ lying over $\mathfrak m_{A'}$, then $(\operatorname{Coker}(\alpha_1) \otimes_A A')_{\mathfrak q'}$ is flat over $A'$. Hence we conclude that $F_{lf}$ is a subfunctor of the functor $F'_{lf}$ associated to the module $\operatorname{Coker}(\alpha_1)_{\mathfrak q_1}$ over $(B_1)_{\mathfrak q_1}$. By the previous paragraph we know $F'_{lf}$ is corepresented by $A/J$ for some ideal $J \subset A$. Hence we may replace $A$ by $A/J$ and assume that $\operatorname{Coker}(\alpha_1)_{\mathfrak q_1}$ is flat over $A$.
Since $\operatorname{Coker}(\alpha_1)$ is a $B_1$-module for which there exist a complete dévissage of $N_1/B_1/A$ at $\mathfrak q_1$ and since $\operatorname{Coker}(\alpha_1)_{\mathfrak q_1}$ is flat over $A$ by Lemma Complete rings, formal power series and flatness we see that $\operatorname{Coker}(\alpha_1)$ is free as an $A$-module, in particular flat as an $A$-module. Hence Lemma Extending perfect approximation across a distinguished square implies $F_{lf}(A')$ is nonempty if and only if $\alpha \otimes 1_{A'}$ is injective. Let $N_1 = \operatorname{Im}(\alpha_1) \subset M_1$ so that we have exact sequences $$0 \to N_1 \to M_1 \to \operatorname{Coker}(\alpha_1) \to 0 \quad\text{and}\quad B_1^{\oplus r_1} \to N_1 \to 0$$ The flatness of $\operatorname{Coker}(\alpha_1)$ implies the first sequence is universally exact (see Algebra, Lemma Injective resolutions and flatness (uncovered prerequisite)). Hence $\alpha \otimes 1_{A'}$ is injective if and only if $B_1^{\oplus r_1} \otimes_A A' \to N_1 \otimes_A A'$ is an isomorphism. Finally, Theorem Flatness applies to show this functor is corepresentable by $A/I$ for some ideal $I$ and we conclude $F_{lf}$ is corepresentable by $A/I$ also.
To prove the final statement, suppose that $A \to B$ is essentially of finite presentation and $M$ of finite presentation over $B$. Let $I \subset A$ be the ideal such that $F_{lf}$ is corepresented by $A/I$. Write $I = \bigcup I_\lambda$ where $I_\lambda$ ranges over the finitely generated ideals contained in $I$. Then, since $F_{lf}(A/I) = \{*\}$ we see that $F_{lf}(A/I_\lambda) = \{*\}$ for some $\lambda$, see Lemma Flatness part (2). Clearly this implies that $I = I_\lambda$. $\square$
Lemma. Complete rings, formal power series and projective and locally free modules
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $R \to S$ be a ring map, and $N$ an $S$-module. Assume
-
$R$ is Noetherian and $I$-adically complete,
-
$R \to S$ is of finite type,
-
$N$ is a finite $S$-module,
-
$N$ is flat over $R$,
-
$N/IN$ is projective as a $R/I$-module, and
-
for any prime $\mathfrak q \subset S$ which is an associated prime of $N \otimes_R \kappa(\mathfrak p)$ where $\mathfrak p = R \cap \mathfrak q$ we have $IS + \mathfrak q \not = S$.
Then $N$ is projective as an $R$-module.
Proof. By Lemma Complete rings, formal power series and injective resolutions the map $N \to N^\wedge$ is universally injective. By Lemma Lifting the Mittag–Leffler condition the module $N^\wedge$ is Mittag-Leffler. By Algebra, Lemma Modules (uncovered prerequisite) we conclude that $N$ is Mittag-Leffler. Hence $N$ is countably generated, flat and Mittag-Leffler as an $R$-module, whence projective by Algebra, Lemma Projective and locally free modules (uncovered prerequisite). $\square$
Lemma. A preliminary relative associated-prime criterion
Let $R \to S$ be a ring map of finite presentation. Let $N$ be a finitely presented $S$-module which is flat as an $R$-module. Let $M$ be an $R$-module. Let $\mathfrak q$ be a prime of $S$ lying over $\mathfrak p \subset R$. Then $$\mathfrak q \in \text{WeakAss}_S(M \otimes_R N) \Leftrightarrow \Big( \mathfrak p \in \text{WeakAss}_R(M) \text{ and } \overline{\mathfrak q} \in \text{Ass}_{\overline{S}}(\overline{N}) \Big)$$ Here $\overline{S} = S \otimes_R \kappa(\mathfrak p)$, $\overline{\mathfrak q} = \mathfrak q \overline{S}$, and $\overline{N} = N \otimes_R \kappa(\mathfrak p)$.
Proof. Pick $g \in S$ as in Lemma The local algebra for the relative associated-prime criterion. Apply Proposition Finite presentation and flatness to the morphism of schemes $\operatorname{Spec}(S_g) \to \operatorname{Spec}(R)$, the quasi-coherent module associated to $N_g$, and the points corresponding to the primes $\mathfrak qS_g$ and $\mathfrak p$. Translating into algebra we obtain a commutative diagram of rings $$\begin{gathered}\begin{matrix}S & S_g & S' \\ \phantom{X} & R & R'\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow S_g \\ S_g & \longrightarrow S' \\ R & \longrightarrow S \\ R & \longrightarrow S_g \\ R & \longrightarrow R' \\ R' & \longrightarrow S'\end{aligned}\end{gathered} \quad\quad \begin{gathered}\begin{matrix}\mathfrak q & \mathfrak qS_g & \mathfrak q' \\ \phantom{X} & \mathfrak p & \mathfrak p'\end{matrix} \\[6pt] \begin{aligned}\mathfrak q & \mathrel{-} \mathfrak qS_g \\ \mathfrak q & \mathrel{-} \mathfrak p \\ \mathfrak qS_g & \mathrel{-} \mathfrak p \\ \mathfrak qS_g & \mathrel{-} \mathfrak q' \\ \mathfrak q' & \mathrel{-} \mathfrak p' \\ \mathfrak p & \mathrel{-} \mathfrak p'\end{aligned}\end{gathered}$$ endowed with primes as shown, the horizontal arrows are étale, and $N \otimes_S S'$ is projective as an $R'$-module. Set $N' = N \otimes_S S'$, $M' = M \otimes_R R'$, $\overline{S}' = S' \otimes_{R'} \kappa(\mathfrak q')$, $\overline{\mathfrak q}' = \mathfrak q' \overline{S}'$, and $$\overline{N}' = N' \otimes_{R'} \kappa(\mathfrak p') = \overline{N} \otimes_{\overline{S}} \overline{S}'$$ By Lemma Étale morphisms and prime spectra and associated points we have $$\begin{aligned} \text{WeakAss}_{S'}(M' \otimes_{R'} N') & = (\operatorname{Spec}(S') \to \operatorname{Spec}(S))^{-1}\text{WeakAss}_S(M \otimes_R N) \\ \text{WeakAss}_{R'}(M') & = (\operatorname{Spec}(R') \to \operatorname{Spec}(R))^{-1}\text{WeakAss}_R(M) \\ \text{Ass}_{\overline{S}'}(\overline{N}') & = (\operatorname{Spec}(\overline{S}') \to \operatorname{Spec}(\overline{S}))^{-1} \text{Ass}_{\overline{S}}(\overline{N}) \end{aligned}$$ Use Algebra, Lemma Commutative algebra (uncovered prerequisite) for $\overline{N}$ and $\overline{N}'$. In particular we have $$\begin{aligned} \mathfrak q \in \text{WeakAss}_S(M \otimes_R N) & \Leftrightarrow \mathfrak q' \in \text{WeakAss}_{S'}(M' \otimes_{R'} N') \\ \mathfrak p \in \text{WeakAss}_R(M) & \Leftrightarrow \mathfrak p' \in \text{WeakAss}_{R'}(M') \\ \overline{\mathfrak q} \in \text{Ass}_{\overline{S}}(\overline{N}) & \Leftrightarrow \overline{\mathfrak q}' \in \text{WeakAss}_{\overline{S}'}(\overline{N}') \end{aligned}$$ Our careful choice of $g$ and the formula for $\text{Ass}_{\overline{S}'}(\overline{N}')$ above shows that
$$\text{if }\mathfrak r' \in \text{Ass}_{\overline{S}'}(\overline{N}') \text{ lies over }\mathfrak r \subset \overline{S}\text{ then } \mathfrak r \subset \overline{\mathfrak q}$$ This will be a key observation later in the proof. We will use the characterization of weakly associated primes given in Algebra, Lemma Local algebra (uncovered prerequisite) without further mention.
Suppose that $\overline{\mathfrak q} \not \in \text{Ass}_{\overline{S}}(\overline{N})$. Then $\overline{\mathfrak q}' \not \in \text{Ass}_{\overline{S}'}(\overline{N}')$. By Algebra, Lemmas Commutative algebra (uncovered prerequisite), Finite algebras (uncovered prerequisite), and An elementary algebraic comparison (uncovered prerequisite) there exists an element $\overline{a}' \in \overline{\mathfrak q}'$ which is not a zerodivisor on $\overline{N}'$. After replacing $\overline{a}'$ by $\lambda \overline{a}'$ for some nonzero $\lambda \in \kappa(\mathfrak p)$ we can find $a' \in \mathfrak q'$ mapping to $\overline{a}'$. By Lemma Injective resolutions the map $a' : N'_{\mathfrak p'} \to N'_{\mathfrak p'}$ is $R'_{\mathfrak p'}$-universally injective. In particular we see that $a' : M' \otimes_{R'} N' \to M' \otimes_{R'} N'$ is injective after localizing at $\mathfrak p'$ and hence after localizing at $\mathfrak q'$. Clearly this implies that $\mathfrak q' \not \in \text{WeakAss}_{S'}(M' \otimes_{R'} N')$. We conclude that $\mathfrak q \in \text{WeakAss}_S(M \otimes_R N)$ implies $\overline{\mathfrak q} \in \text{Ass}_{\overline{S}}(\overline{N})$.
Assume $\mathfrak q \in \text{WeakAss}_S(M \otimes_R N)$. We want to show $\mathfrak p \in \text{WeakAss}_S(M)$. Let $z \in M \otimes_R N$ be an element such that $\mathfrak q$ is minimal over $J = \text{Ann}_S(z)$. Let $f_i \in \mathfrak p$, $i \in I$ be a set of generators of the ideal $\mathfrak p$. Since $\mathfrak q$ lies over $\mathfrak p$, for every $i$ we can choose an $n_i \geq 1$ and $g_i \in S$, $g_i \not \in \mathfrak q$ with $g_i f_i^{n_i} \in J$, i.e., $g_i f_i^{n_i} z = 0$. Let $z' \in (M' \otimes_{R'} N')_{\mathfrak p'}$ be the image of $z$. Observe that $z'$ is nonzero because $z$ has nonzero image in $(M \otimes_R N)_\mathfrak q$ and because $S_\mathfrak q \to S'_{\mathfrak q'}$ is faithfully flat. We claim that $f_i^{n_i} z' = 0$.
Proof of the claim: Let $g'_i \in S'$ be the image of $g_i$. By the key observation (the displayed identity) we find that the image $\overline{g}'_i \in \overline{S}'$ is not contained in $\mathfrak r'$ for any $\mathfrak r' \in \text{Ass}_{\overline{S}'}(\overline{N})$. Hence by Lemma Injective resolutions we see that $g'_i : N'_{\mathfrak p'} \to N'_{\mathfrak p'}$ is $R'_{\mathfrak p'}$-universally injective. In particular we see that $g'_i : M' \otimes_{R'} N' \to M' \otimes_{R'} N'$ is injective after localizating at $\mathfrak p'$. The claim follows because $g_i f_i^{n_i} z' = 0$.
Our claim shows that the annihilator of $z'$ in $R'_{\mathfrak p'}$ contains the elements $f_i^{n_i}$. As $R \to R'$ is étale we have $\mathfrak p'R'_{\mathfrak p'} = \mathfrak pR'_{\mathfrak p'}$ by Algebra, Lemma Étaleness at a prime ideal (uncovered prerequisite). Hence the annihilator of $z'$ in $R'_{\mathfrak p'}$ has radical equal to $\mathfrak p' R_{\mathfrak p'}$ (here we use $z'$ is not zero). On the other hand $$z' \in (M' \otimes_{R'} N')_{\mathfrak p'} = M'_{\mathfrak p'} \otimes_{R'_{\mathfrak p'}} N'_{\mathfrak p'}$$ The module $N'_{\mathfrak p'}$ is projective over the local ring $R'_{\mathfrak p'}$ and hence free (Algebra, Theorem Projective, locally free modules and local algebra (uncovered prerequisite)). Thus we can find a finite free direct summand $F' \subset N'_{\mathfrak p'}$ such that $z' \in M'_{\mathfrak p'} \otimes_{R'_{\mathfrak p'}} F'$. If $F'$ has rank $n$, then we deduce that $\mathfrak p' R'_{\mathfrak p'} \in \text{WeakAss}_{R'_{\mathfrak p'}}({M'_{\mathfrak p'}}^{\oplus n})$. This implies $\mathfrak p'R'_{\mathfrak p'} \in \text{WeakAss}(M'_{\mathfrak p'})$ for example by Algebra, Lemma Commutative algebra (uncovered prerequisite). Then $\mathfrak p' \in \text{WeakAss}_{R'}(M')$ which in turn gives $\mathfrak p \in \text{WeakAss}_R(M)$. This finishes the proof of the implication "$\Rightarrow$" of the equivalence of the lemma.
Assume that $\mathfrak p \in \text{WeakAss}_R(M)$ and $\overline{\mathfrak q} \in \text{Ass}_{\overline{S}}(\overline{N})$. We want to show that $\mathfrak q$ is weakly associated to $M \otimes_R N$. Note that $\overline{\mathfrak q}'$ is a maximal element of $\text{Ass}_{\overline{S}'}(\overline{N}')$. This is a consequence of (the displayed identity) and the fact that there are no inclusions among the primes of $\overline{S}'$ lying over $\overline{\mathfrak q}$ (as fibres of étale morphisms are discrete Morphisms, Lemma Étale morphisms and field extensions (uncovered prerequisite)). Thus, after replacing $R, S, \mathfrak p, \mathfrak q, M, N$ by $R', S', \mathfrak p', \mathfrak q', M', N'$ we may assume, in addition to the assumptions of the lemma, that
-
$\mathfrak p \in \text{WeakAss}_R(M)$,
-
$\overline{\mathfrak q} \in \text{Ass}_{\overline{S}}(\overline{N})$,
-
$N$ is projective as an $R$-module, and
-
$\overline{\mathfrak q}$ is maximal in $\text{Ass}_{\overline{S}}(\overline{N})$.
There is one more reduction, namely, we may replace $R, S, M, N$ by their localizations at $\mathfrak p$. This leads to one more condition, namely,
- $R$ is a local ring with maximal ideal $\mathfrak p$.
We will finish by showing that (1) -- (5) imply $\mathfrak q \in \text{WeakAss}(M \otimes_R N)$.
Since $R$ is local and $\mathfrak p \in \text{WeakAss}_R(M)$ we can pick a $y \in M$ whose annihilator $I$ has radical equal to $\mathfrak p$. Write $\overline{\mathfrak q} = (\overline{g}_1, \ldots, \overline{g}_n)$ for some $\overline{g}_i \in \overline{S}$. Choose $g_i \in S$ mapping to $\overline{g}_i$. Then $\mathfrak q = \mathfrak pS + g_1S + \ldots + g_nS$. Consider the map $$\Psi : N/IN \longrightarrow (N/IN)^{\oplus n}, \quad z \longmapsto (g_1z, \ldots, g_nz).$$ This is a homomorphism of projective $R/I$-modules. The local ring $R/I$ is auto-associated (More on Algebra, Definition Auto-associated local rings) as $\mathfrak p/I$ is locally nilpotent. The map $\Psi \otimes \kappa(\mathfrak p)$ is not injective, because $\overline{\mathfrak q} \in \text{Ass}_{\overline{S}}(\overline{N})$. Hence More on Algebra, Lemma Equivalent splitting conditions for injections of finite projectives implies $\Psi$ is not injective. Pick $z \in N/IN$ nonzero in the kernel of $\Psi$. The annihilator $J = \text{Ann}_S(z)$ contains $IS$ and $g_i$ by construction. Thus $\sqrt{J} \subset S$ contains $\mathfrak q$. Let $\mathfrak s \subset S$ be a prime minimal over $J$. Then $\mathfrak q \subset \mathfrak s$, $\mathfrak s$ lies over $\mathfrak p$, and $\mathfrak s \in \text{WeakAss}_S(N/IN)$. The last fact by definition of weakly associated primes. Apply the "$\Rightarrow$" part of the lemma (which we've already proven) to the ring map $R \to S$ and the modules $R/I$ and $N$ to conclude that $\overline{\mathfrak s} \in \text{Ass}_{\overline{S}}(\overline{N})$. Since $\overline{\mathfrak q} \subset \overline{\mathfrak s}$ the maximality of $\overline{\mathfrak q}$, see condition (4) above, implies that $\overline{\mathfrak q} = \overline{\mathfrak s}$. This shows that $\mathfrak q = \mathfrak s$ and we conlude what we want. $\square$
Lemma. Projective, locally free modules and flatness
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Let $s \in S$. Assume that
-
$f$ is of finite presentation,
-
$\mathcal{F}$ is of finite type, and
-
$\mathcal{F}$ is flat over $S$ at all points of $X_s$.
Then there exists an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram of schemes $$\begin{gathered}\begin{matrix}X & X' \\ S & \operatorname{Spec}(\mathcal{O}_{S', s'})\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow \operatorname{Spec}(\mathcal{O}_{S', s'}) \\ \operatorname{Spec}(\mathcal{O}_{S', s'}) & \longrightarrow S\end{aligned}\end{gathered}$$ such that $X' \to X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ is étale, $X_s = g((X')_{s'})$, the scheme $X'$ is affine of finite presentation over $\mathcal{O}_{S', s'}$, the sheaf $g^*\mathcal{F}$ is of finite presentation over $\mathcal{O}_{X'}$, and such that $\Gamma(X', g^*\mathcal{F})$ is a free $\mathcal{O}_{S', s'}$-module.
Proof. For every point $x \in X_s$ we can use Lemma Projective, locally free modules and flatness to find an elementary étale neighbourhood $(S_x , s_x) \to (S, s)$ and a commutative diagram $$\begin{gathered}\begin{matrix}(X, x) & (Y_x, y_x) \\ (S, s) & (\operatorname{Spec}(\mathcal{O}_{S_x, s_x}), s_x)\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (Y_x, y_x) & \xrightarrow{g_x} (X, x) \\ (Y_x, y_x) & \longrightarrow (\operatorname{Spec}(\mathcal{O}_{S_x, s_x}), s_x) \\ (\operatorname{Spec}(\mathcal{O}_{S_x, s_x}), s_x) & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ such that $Y_x \to X \times_S \operatorname{Spec}(\mathcal{O}_{S_x, s_x})$ is étale, $\kappa(x) = \kappa(y_x)$, the scheme $Y_x$ is affine of finite presentation over $\mathcal{O}_{S_x, s_x}$, the sheaf $g_x^*\mathcal{F}$ is of finite presentation over $\mathcal{O}_{Y_x}$, and such that $\Gamma(Y_x, g_x^*\mathcal{F})$ is a free $\mathcal{O}_{S_x, s_x}$-module. In particular $g_x((Y_x)_{s_x})$ is an open neighbourhood of $x$ in $X_s$. Because $X_s$ is quasi-compact we can find a finite number of points $x_1, \ldots, x_n \in X_s$ such that $X_s$ is the union of the $g_{x_i}((Y_{x_i})_{s_{x_i}})$. Choose an elementary étale neighbourhood $(S' , s') \to (S, s)$ which dominates each of the neighbourhoods $(S_{x_i}, s_{x_i})$, see More on Morphisms, Lemma Étale morphisms (uncovered prerequisite). Set $$X' = \coprod Y_{x_i} \times_{\operatorname{Spec}(\mathcal{O}_{S_{x_i}, s_{x_i}})} \operatorname{Spec}(\mathcal{O}_{S', s'})$$ and endow it with the obvious morphism $g : X' \to X$. By construction $X_s = g(X'_{s'})$ and $$\Gamma(X', g^*\mathcal{F})
\bigoplus \Gamma(Y_{x_i}, g_{x_i}^*\mathcal{F}) \otimes_{\mathcal{O}{S{x_i}, s_{x_i}}} \mathcal{O}{S', s'}.$$ This is a free $\mathcal{O}{S', s'}$-module as a direct sum of base changes of free modules. Some minor details omitted. $\square$
Lemma. Projective, locally free modules and flatness
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Let $x \in X$ with image $s \in S$. Assume that
-
$f$ is locally of finite type,
-
$\mathcal{F}$ is of finite type, and
-
$\mathcal{F}$ is flat at $x$ over $S$.
Then there exists an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram of pointed schemes $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (\operatorname{Spec}(\mathcal{O}_{S', s'}), s')\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (\operatorname{Spec}(\mathcal{O}_{S', s'}), s') \\ (\operatorname{Spec}(\mathcal{O}_{S', s'}), s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ such that $X' \to X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ is étale, $\kappa(x) = \kappa(x')$, the scheme $X'$ is affine, and such that $\Gamma(X', g^*\mathcal{F})$ is a free $\mathcal{O}_{S', s'}$-module.
Proof. (The only difference with Lemma Projective, locally free modules and flatness is that we do not assume $f$ is of finite presentation.) The problem is local on $X$ and $S$. Hence we may assume $X$ and $S$ are affine, say $X = \operatorname{Spec}(B)$ and $S = \operatorname{Spec}(A)$. Since $B$ is a finite type $A$-algebra we can find a surjection $A[x_1, \ldots, x_n] \to B$. In other words, we can choose a closed immersion $i : X \to \mathbf{A}^n_S$. Set $t = i(x)$ and $\mathcal{G} = i_*\mathcal{F}$. Note that $\mathcal{G}_t \cong \mathcal{F}_x$ are $\mathcal{O}_{S, s}$-modules. Hence $\mathcal{G}$ is flat over $S$ at $t$. We apply Lemma Projective, locally free modules and flatness to the morphism $\mathbf{A}^n_S \to S$, the point $t$, and the sheaf $\mathcal{G}$. Thus we can find an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram of pointed schemes $$\begin{gathered}\begin{matrix}(\mathbf{A}^n_S, t) & (Y, y) \\ (S, s) & (\operatorname{Spec}(\mathcal{O}_{S', s'}), s')\end{matrix} \\[6pt] \begin{aligned}(\mathbf{A}^n_S, t) & \longrightarrow (S, s) \\ (Y, y) & \xrightarrow{h} (\mathbf{A}^n_S, t) \\ (Y, y) & \longrightarrow (\operatorname{Spec}(\mathcal{O}_{S', s'}), s') \\ (\operatorname{Spec}(\mathcal{O}_{S', s'}), s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ such that $Y \to \mathbf{A}^n_{\mathcal{O}_{S', s'}}$ is étale, $\kappa(t) = \kappa(y)$, the scheme $Y$ is affine, and such that $\Gamma(Y, h^*\mathcal{G})$ is a projective $\mathcal{O}_{S', s'}$-module. Then a solution to the original problem is given by the closed subscheme $X' = Y \times_{\mathbf{A}^n_S} X$ of $Y$. $\square$
Lemma. Complete rings, formal power series and finite presentation
Let $R \to S$ be a ring map of finite presentation. Let $N$ be a finitely presented $S$-module flat over $R$. Let $\mathfrak r \subset R$ be a prime ideal. Assume there exists a complete dévissage of $N/S/R$ over $\mathfrak r$. Then there exists an $f \in R$, $f \not \in \mathfrak r$ such that $$N_f \cong B_1^{\oplus r_1} \oplus \ldots \oplus B_n^{\oplus r_n}$$ as $R$-modules where each $B_i$ is a smooth $R_f$-algebra with geometrically irreducible fibres. Moreover, $N_f$ is projective as an $R_f$-module.
Proof. Let $(A_i, B_i, M_i, \alpha_i)_{i = 1, \ldots, n}$ be the given complete dévissage. We prove the lemma by induction on $n$. Note that the assertions of the lemma are entirely about the structure of $N$ as an $R$-module. Hence we may replace $N$ by $M_1$, and we may think of $M_1$ as a $B_1$-module. See Remark Finite presentation and finite algebras in order to see why $M_1$ is of finite presentation as a $B_1$-module. By Lemma Finite presentation we may, after replacing $R$ by $R_f$ for some $f \in R$, $f \not \in \mathfrak r$, assume the map $\alpha_1 : B_1^{\oplus r_1} \to M_1$ is $R$-universally injective. Since $M_1$ and $B_1^{\oplus r_1}$ are $R$-flat and finitely presented as $B_1$-modules we see that $\operatorname{Coker}(\alpha_1)$ is $R$-flat (Algebra, Lemma Flatness (uncovered prerequisite)) and finitely presented as a $B_1$-module. Note that $(A_i, B_i, M_i, \alpha_i)_{i = 2, \ldots, n}$ is a complete dévissage of $\operatorname{Coker}(\alpha_1)$. Hence the induction hypothesis implies that, after replacing $R$ by $R_f$ for some $f \in R$, $f \not \in \mathfrak r$, we may assume that $\operatorname{Coker}(\alpha_1)$ has a decomposition as in the lemma and is projective. In particular $M_1 = B_1^{\oplus r_1} \oplus \operatorname{Coker}(\alpha_1)$. This proves the statement regarding the decomposition. The statement on projectivity follows as $B_1$ is projective as an $R$-module by Lemma Projective, locally free modules and flatness. $\square$
Lemma. Flatness and prime spectra and associated points
Let $g : T \to S$ be a finite flat morphism of schemes. Let $\mathcal{G}$ be a quasi-coherent $\mathcal{O}_S$-module. Let $t \in T$ be a point with image $s \in S$. Then $$t \in \text{WeakAss}(g^*\mathcal{G}) \Leftrightarrow s \in \text{WeakAss}(\mathcal{G})$$
Proof. The implication "$\Leftarrow$" follows immediately from Divisors, Lemma The geometric construction (uncovered prerequisite). Assume $t \in \text{WeakAss}(g^*\mathcal{G})$. Let $\operatorname{Spec}(A) \subset S$ be an affine open neighbourhood of $s$. Let $\mathcal{G}$ be the quasi-coherent sheaf associated to the $A$-module $M$. Let $\mathfrak p \subset A$ be the prime ideal corresponding to $s$. As $g$ is finite flat we have $g^{-1}(\operatorname{Spec}(A)) = \operatorname{Spec}(B)$ for some finite flat $A$-algebra $B$. Note that $g^*\mathcal{G}$ is the quasi-coherent $\mathcal{O}_{\operatorname{Spec}(B)}$-module associated to the $B$-module $M \otimes_A B$ and $g_*g^*\mathcal{G}$ is the quasi-coherent $\mathcal{O}_{\operatorname{Spec}(A)}$-module associated to the $A$-module $M \otimes_A B$. By Algebra, Lemma Finite flat modules over a local ring we have $B_{\mathfrak p} \cong A_{\mathfrak p}^{\oplus n}$ for some integer $n \geq 0$. Note that $n \geq 1$ as we assumed there exists at least one point of $T$ lying over $s$. Hence we see by looking at stalks that $$s \in \text{WeakAss}(\mathcal{G}) \Leftrightarrow s \in \text{WeakAss}(g_*g^*\mathcal{G})$$ Now the assumption that $t \in \text{WeakAss}(g^*\mathcal{G})$ implies that $s \in \text{WeakAss}(g_*g^*\mathcal{G})$ by Divisors, Lemma Prime spectra, associated points and finite algebras (uncovered prerequisite) and hence by the above $s \in \text{WeakAss}(\mathcal{G})$. $\square$
Lemma. Projective, locally free modules and flatness
Let $f : X \to S$ be a morphism which is locally of finite type. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module which is of finite type. Let $x \in X$ with $s = f(x) \in S$. If $\mathcal{F}$ is flat at $x$ over $S$ there exists an affine elementary étale neighbourhood $(S', s') \to (S, s)$ and an affine open $U' \subset X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ which contains $x' = (x, s')$ such that $\Gamma(U', \mathcal{F}|_{U'})$ is a free $\mathcal{O}_{S', s'}$-module.
Proof. The question is Zariski local on $X$ and $S$. Hence we may assume that $X$ and $S$ are affine. Then we can find a closed immersion $i : X \to \mathbf{A}^n_S$ over $S$. It is clear that it suffices to prove the lemma for the sheaf $i_*\mathcal{F}$ on $\mathbf{A}^n_S$ and the point $i(x)$. In this way we reduce to the case where $X \to S$ is of finite presentation. After replacing $S$ by $\operatorname{Spec}(\mathcal{O}_{S', s'})$ and $X$ by an open of $X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ we may assume that $\mathcal{F}$ is of finite presentation, see Proposition Flatness and finite algebras. In this case we may appeal to Lemma Projective, locally free modules and finite presentation and Algebra, Theorem Projective, locally free modules and local algebra (uncovered prerequisite) to conclude. $\square$
Situation. Flatness
Let $(A, \mathfrak m_A)$ be a local ring. Denote $\mathcal{C}$ the category whose objects are $A$-algebras $A'$ which are local rings such that the algebra structure $A \to A'$ is a local homomorphism of local rings. A morphism between objects $A', A''$ of $\mathcal{C}$ is a local homomorphism $A' \to A''$ of $A$-algebras. Let $A \to B$ be a local ring map of local rings and let $M$ be a $B$-module. If $A'$ is an object of $\mathcal{C}$ we set $B' = B \otimes_A A'$ and we set $M' = M \otimes_A A'$ as a $B'$-module. Given $A' \in \operatorname{Ob}(\mathcal{C})$, consider the condition
$$\forall \mathfrak q \in V(\mathfrak m_{A'}B' + \mathfrak m_B B') \subset \operatorname{Spec}(B') : M'_{\mathfrak q}\text{ is flat over }A'.$$ Note the similarity with More on Algebra, Equation (Flatness and prime spectra and associated points). In particular, if $A' \to A''$ is a morphism of $\mathcal{C}$ and (the displayed identity) holds for $A'$, then it holds for $A''$, see More on Algebra, Lemma Base change for flatness and prime spectra and associated points. Hence we obtain a functor
$$F_{lf} : \mathcal{C} \longrightarrow \textit{Sets}, \quad A' \longrightarrow \left\{ \begin{matrix} \{*\} & \text{if }(\text{the displayed identity})\text{ holds}, \\ \emptyset & \text{else.} & \end{matrix} \right.$$Lemma. Flatness
In Situation Flatness suppose that $B \to C$ is a flat local homomorphism of local rings. Set $N = M \otimes_B C$. Denote $F'_{lf} : \mathcal{C} \to \textit{Sets}$ the functor associated to the pair $(C, N)$. Then $F_{lf} = F'_{lf}$.
Proof. Let \(A'\) be an object of \(\mathcal{C}\). Set \(C' = C \otimes_A A'\) and \(N' = N \otimes_A A' = M' \otimes_{B'} C'\) similarly to the definitions of \(B'\), \(M'\) in Situation Flatness. Note that
\[ V(\mathfrak m_{A'}B' + \mathfrak m_B B') = \operatorname{Spec}( \kappa(\mathfrak m_B) \otimes_A \kappa(\mathfrak m_{A'}) ) \]and similarly for \(V(\mathfrak m_{A'}C' + \mathfrak m_C C')\). The ring map
\[ \kappa(\mathfrak m_B) \otimes_A \kappa(\mathfrak m_{A'}) \longrightarrow \kappa(\mathfrak m_C) \otimes_A \kappa(\mathfrak m_{A'}) \]is faithfully flat, hence \(V(\mathfrak m_{A'}C' + \mathfrak m_C C') \to V(\mathfrak m_{A'}B' + \mathfrak m_B B')\) is surjective. Finally, if \(\mathfrak r \in V(\mathfrak m_{A'}C' + \mathfrak m_C C')\) maps to \(\mathfrak q \in V(\mathfrak m_{A'}B' + \mathfrak m_B B')\), then \(M'_{\mathfrak q}\) is flat over \(A'\) if and only if \(N'_{\mathfrak r}\) is flat over \(A'\) because \(B' \to C'\) is flat, see Algebra, Lemma Descent of flatness (uncovered prerequisite). The lemma follows formally from these remarks. \(\square\)
Lemma. Construction of an algebraic dévissage
Let $R \to S$ be a finite type ring map. Let $M$ be a finite $S$-module. Let $\mathfrak q$ be a prime ideal of $S$. There exists an elementary étale localization $R' \to S', \mathfrak q', \mathfrak p'$ of the ring map $R \to S$ at $\mathfrak q$ such that there exists a complete dévissage of $(M \otimes_S S')/S'/R'$ at $\mathfrak q'$.
Proof. This is a reformulation of Proposition Complete dévissage at a point via Remark Agreement of the two purity conditions $\square$
Definition. Complete algebraic dévissage at a point
Let $R \to S$ be a finite type ring map. Let $\mathfrak q$ be a prime of $S$ lying over the prime $\mathfrak r$ of $R$. Let $N$ be a finite $S$-module. A complete dévissage of $N/S/R$ at $\mathfrak q$ is given by a complete dévissage $(A_i, B_i, M_i, \alpha_i)_{i = 1, \ldots, n}$ of $N/S/R$ over $\mathfrak r$ and prime ideals $\mathfrak q_i \subset B_i$ lying over $\mathfrak r$ such that
-
$\kappa(\mathfrak r) \subset \kappa(\mathfrak q_i)$ is purely transcendental,
-
there is a unique prime $\mathfrak q'_i \subset A_i$ lying over $\mathfrak q_i \subset B_i$,
-
$\mathfrak q = \mathfrak q'_1 \cap S$ and $\mathfrak q_i = \mathfrak q'_{i + 1} \cap A_i$,
-
$R \to B_i$ has relative dimension $\dim_{\mathfrak q_i}(\text{Supp}(M_i \otimes_R \kappa(\mathfrak r)))$.
Lemma. Flatness and finite algebras
In Situation Flatness. Let $B \to C$ is a local map of local $A$-algebras and $N$ a $C$-module. Denote $F'_{lf} : \mathcal{C} \to \textit{Sets}$ the functor associated to the pair $(C, N)$. If $M \cong N$ as $B$-modules and $B \to C$ is finite, then $F_{lf} = F'_{lf}$.
Proof. Let \(A'\) be an object of \(\mathcal{C}\). Set \(C' = C \otimes_A A'\) and \(N' = N \otimes_A A'\) similarly to the definitions of \(B'\), \(M'\) in Situation Flatness. Note that \(M' \cong N'\) as \(B'\)-modules. The assumption that \(B \to C\) is finite has two consequences: (a) \(\mathfrak m_C = \sqrt{\mathfrak m_B C}\) and (b) \(B' \to C'\) is finite. Consequence (a) implies that
\[ V(\mathfrak m_{A'}C' + \mathfrak m_C C') = \left( \operatorname{Spec}(C') \to \operatorname{Spec}(B') \right)^{-1}V(\mathfrak m_{A'}B' + \mathfrak m_B B'). \]Suppose \(\mathfrak q \subset V(\mathfrak m_{A'}B' + \mathfrak m_B B')\). Then \(M'_{\mathfrak q}\) is flat over \(A'\) if and only if the \(C'_{\mathfrak q}\)-module \(N'_{\mathfrak q}\) is flat over \(A'\) (because these are isomorphic as \(A'\)-modules) if and only if for every maximal ideal \(\mathfrak r\) of \(C'_{\mathfrak q}\) the module \(N'_{\mathfrak r}\) is flat over \(A'\) (see Algebra, Lemma Localization of a flat module (uncovered prerequisite)). As \(B'_{\mathfrak q} \to C'_{\mathfrak q}\) is finite by (b), the maximal ideals of \(C'_{\mathfrak q}\) correspond exactly to the primes of \(C'\) lying over \(\mathfrak q\) (see Algebra, Lemma Going up for integral ring maps) and these primes are all contained in \(V(\mathfrak m_{A'}C' + \mathfrak m_C C')\) by the displayed equation above. Thus the result of the lemma holds. \(\square\)
Lemma. Flatness
In Situation Flatness.
-
If $A' \to A''$ is a flat morphism in $\mathcal{C}$ then $F_{lf}(A') = F_{lf}(A'')$.
-
If $A \to B$ is essentially of finite presentation and $M$ is a $B$-module of finite presentation, then $F_{lf}$ is limit preserving: If $\{A_i\}_{i \in I}$ is a directed system of objects of $\mathcal{C}$, then $F_{lf}(\mathop{\operatorname{colim}}_i A_i) = \mathop{\operatorname{colim}}_i F_{lf}(A_i)$.
Proof. Part (1) is a special case of More on Algebra, Lemma Flatness and prime spectra and associated points. Part (2) is a special case of More on Algebra, Lemma Filtered limits and flatness and prime spectra and associated points. $\square$
Lemma. Complete rings, formal power series and injective resolutions
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $R \to S$ be a ring map, and $N$ an $S$-module. Assume
-
$R$ is a Noetherian ring,
-
$S$ is a Noetherian ring,
-
$N$ is a finite $S$-module,
-
$N$ is flat over $R$, and
-
for any prime $\mathfrak q \subset S$ which is an associated prime of $N \otimes_R \kappa(\mathfrak p)$ where $\mathfrak p = R \cap \mathfrak q$ we have $IS + \mathfrak q \not = S$.
Then the map $N \to N^\wedge$ of $N$ into the $I$-adic completion of $N$ is universally injective as a map of $R$-modules.
Proof. This follows from Lemma Complete rings, formal power series and injective resolutions because Algebra, Lemma Commutative algebra (uncovered prerequisite) and Remark Commutative algebra guarantee that the set of associated primes of tensor products $N \otimes_R Q$ are contained in the set of associated primes of the modules $N \otimes_R \kappa(\mathfrak p)$. $\square$
Lemma. Lifting the Mittag--Leffler condition
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $M$ be an $R$-module. Assume
-
$R$ is Noetherian and $I$-adically complete,
-
$M$ is flat over $R$, and
-
$M/IM$ is a projective $R/I$-module.
Then the $I$-adic completion $M^\wedge$ is a flat Mittag-Leffler $R$-module.
Proof. Choose a surjection $F \to M$ where $F$ is a free $R$-module. By Algebra, Lemma Complete rings and formal power series (uncovered prerequisite) the module $M^\wedge$ is a direct summand of the module $F^\wedge$. Hence it suffices to prove the lemma for $F$. In this case the lemma follows from Lemma The Mittag–Leffler condition for a completed direct sum. $\square$
Lemma. The local algebra for the relative associated-prime criterion
Let $R \to S$ be a ring map of finite presentation. Let $N$ be a finitely presented $S$-module. Let $\mathfrak q \subset S$ be a prime ideal lying over $\mathfrak p \subset R$. Set $\overline{S} = S \otimes_R \kappa(\mathfrak p)$, $\overline{\mathfrak q} = \mathfrak q \overline{S}$, and $\overline{N} = N \otimes_R \kappa(\mathfrak p)$. Then we can find a $g \in S$ with $g \not \in \mathfrak q$ such that $\overline{g} \in \mathfrak r$ for all $\mathfrak r \in \text{Ass}_{\overline{S}}(\overline{N})$ such that $\mathfrak r \not \subset \overline{\mathfrak q}$.
Proof. Namely, if $\text{Ass}_{\overline{S}}(\overline{N}) = \{\mathfrak r_1, \ldots, \mathfrak r_n\}$ (finiteness by Algebra, Lemma Finite algebras (uncovered prerequisite)), then after renumbering we may assume that $$\mathfrak r_1 \subset \overline{\mathfrak q}, \ldots, \mathfrak r_r \subset \overline{\mathfrak q}, \quad \mathfrak r_{r + 1} \not \subset \overline{\mathfrak q}, \ldots, \mathfrak r_n \not \subset \overline{\mathfrak q}$$ Since $\overline{\mathfrak q}$ is a prime ideal we see that the product $\mathfrak r_{r + 1} \ldots \mathfrak r_n$ is not contained in $\overline{\mathfrak q}$ and hence we can pick an element $a$ of $\overline{S}$ contained in $\mathfrak r_{r + 1}, \ldots, \mathfrak r_n$ but not in $\overline{\mathfrak q}$. If there exists $g \in S$ mapping to $a$, then $g$ works. In general we can find a nonzero element $\lambda \in \kappa(\mathfrak p)$ such that $\lambda a$ is the image of a $g \in S$. $\square$
Lemma. Projective, locally free modules and flatness
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent sheaf on $X$. Let $x \in X$ with image $s \in S$. Assume that
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$f$ is locally of finite presentation,
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$\mathcal{F}$ is of finite type, and
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$\mathcal{F}$ is flat at $x$ over $S$.
Then there exists an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram of pointed schemes $$\begin{gathered}\begin{matrix}(X, x) & (X', x') \\ (S, s) & (\operatorname{Spec}(\mathcal{O}_{S', s'}), s')\end{matrix} \\[6pt] \begin{aligned}(X, x) & \longrightarrow (S, s) \\ (X', x') & \xrightarrow{g} (X, x) \\ (X', x') & \longrightarrow (\operatorname{Spec}(\mathcal{O}_{S', s'}), s') \\ (\operatorname{Spec}(\mathcal{O}_{S', s'}), s') & \longrightarrow (S, s)\end{aligned}\end{gathered}$$ such that $X' \to X \times_S \operatorname{Spec}(\mathcal{O}_{S', s'})$ is étale, $\kappa(x) = \kappa(x')$, the scheme $X'$ is affine of finite presentation over $\mathcal{O}_{S', s'}$, the sheaf $g^*\mathcal{F}$ is of finite presentation over $\mathcal{O}_{X'}$, and such that $\Gamma(X', g^*\mathcal{F})$ is a free $\mathcal{O}_{S', s'}$-module.
Proof. To prove the lemma we may replace $(S, s)$ by any elementary étale neighbourhood, and we may also replace $S$ by $\operatorname{Spec}(\mathcal{O}_{S, s})$. Hence by Proposition Flatness and finite algebras we may assume that $\mathcal{F}$ is finitely presented and flat over $S$ in a neighbourhood of $x$. In this case the result follows from Proposition Finite presentation and flatness because Algebra, Theorem Projective, locally free modules and local algebra (uncovered prerequisite) assures us that projective $=$ free over a local ring. $\square$
Lemma. Projective, locally free modules and finite presentation
Let $f : X \to S$ be a morphism which is locally of finite presentation. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module which is of finite presentation. Let $x \in X$ with $s = f(x) \in S$. If $\mathcal{F}$ is flat at $x$ over $S$ there exists an affine elementary étale neighbourhood $(S', s') \to (S, s)$ and an affine open $U' \subset X \times_S S'$ which contains $x' = (x, s')$ such that $\Gamma(U', \mathcal{F}|_{U'})$ is a projective $\Gamma(S', \mathcal{O}_{S'})$-module.
Proof. During the proof we may replace $X$ by an open neighbourhood of $x$ and we may replace $S$ by an elementary étale neighbourhood of $s$. Hence, by openness of flatness (see More on Morphisms, Theorem Openness of the flat locus) we may assume that $\mathcal{F}$ is flat over $S$. We may assume $S$ and $X$ are affine. After shrinking $X$ some more we may assume that any point of $\text{Ass}_{X_s}(\mathcal{F}_s)$ is a generalization of $x$. This property is preserved on replacing $(S, s)$ by an elementary étale neighbourhood. Hence we may apply Lemma Finite presentation and flatness to arrive at the situation where there exists a diagram $$\begin{gathered}\begin{matrix}X & \phantom{X} & X' \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow S\end{aligned}\end{gathered}$$ of schemes affine and of finite presentation over $S$, where $g$ is étale, $X_s \subset g(X')$, and with $\Gamma(X', g^*\mathcal{F})$ a projective $\Gamma(S, \mathcal{O}_S)$-module. Note that in this case $g^*\mathcal{F}$ is universally pure over $S$, see Lemma Projective, locally free modules and affine neighbourhoods.
Let $U \subset g(X')$ be an affine open neighbourhood of $x$. We claim that $\mathcal{F}|_U$ is pure along $U_s$. If we prove this, then the lemma follows because $\mathcal{F}|_U$ will be pure relative to $S$ after shrinking $S$, see Lemma Finite presentation and flatness, whereupon the projectivity follows from Proposition Projective, locally free modules and finite presentation. To prove the claim we have to show, after replacing $(S, s)$ by an arbitrary elementary étale neighbourhood, that any point $\xi$ of $\text{Ass}_{U/S}(\mathcal{F}|_U)$ lying over some $s' \in S$, $s' \leadsto s$ specializes to a point of $U_s$. Since $U \subset g(X')$ we can find a $\xi' \in X'$ with $g(\xi') = \xi$. Because $g^*\mathcal{F}$ is pure over $S$, using Lemma Prime spectra and associated points, we see there exists a specialization $\xi' \leadsto x'$ with $x' \in \text{Ass}_{X'_s}(g^*\mathcal{F}_s)$. Then $g(x') \in \text{Ass}_{X_s}(\mathcal{F}_s)$ (see for example Lemma Étale morphisms and prime spectra and associated points applied to the étale morphism $X'_s \to X_s$ of Noetherian schemes) and hence $g(x') \leadsto x$ by our choice of $X$ above! Since $x \in U$ we conclude that $g(x') \in U$. Thus $\xi = g(\xi') \leadsto g(x') \in U_s$ as desired. $\square$
Lemma. Complete rings, formal power series and injective resolutions
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $R \to S$ be a ring map, and $N$ an $S$-module. Assume
-
$R$ is a Noetherian ring,
-
$S$ is a Noetherian ring,
-
$N$ is a finite $S$-module, and
-
for any finite $R$-module $Q$, any $\mathfrak q \in \text{Ass}_S(Q \otimes_R N)$ satisfies $IS + \mathfrak q \not = S$.
Then the map $N \to N^\wedge$ of $N$ into the $I$-adic completion of $N$ is universally injective as a map of $R$-modules.
Proof. We have to show that for any finite $R$-module $Q$ the map $Q \otimes_R N \to Q \otimes_R N^\wedge$ is injective, see Algebra, Theorem Commutative algebra (uncovered prerequisite). As there is a canonical map $Q \otimes_R N^\wedge \to (Q \otimes_R N)^\wedge$ it suffices to prove that the canonical map $Q \otimes_R N \to (Q \otimes_R N)^\wedge$ is injective. Hence we may replace $N$ by $Q \otimes_R N$ and it suffices to prove the injectivity for the map $N \to N^\wedge$.
Let $K = \operatorname{Ker}(N \to N^\wedge)$. It suffices to show that $K_{\mathfrak q} = 0$ for $\mathfrak q \in \text{Ass}(N)$ as $N$ is a submodule of $\prod_{\mathfrak q \in \text{Ass}(N)} N_{\mathfrak q}$, see Algebra, Lemma Commutative algebra (uncovered prerequisite). Pick $\mathfrak q \in \text{Ass}(N)$. By the last assumption we see that there exists a prime $\mathfrak q' \supset IS + \mathfrak q$. Since $K_{\mathfrak q}$ is a localization of $K_{\mathfrak q'}$ it suffices to prove the vanishing of $K_{\mathfrak q'}$. Note that $K = \bigcap I^nN$, hence $K_{\mathfrak q'} \subset \bigcap I^nN_{\mathfrak q'}$. Hence $K_{\mathfrak q'} = 0$ by Algebra, Lemma Krull's intersection theorem (uncovered prerequisite). $\square$
Lemma. The Mittag--Leffler condition for a completed direct sum
Let $R$ be a ring. Let $I \subset R$ be an ideal. Let $A$ be a set. Assume $R$ is Noetherian and complete with respect to $I$. The completion $(\bigoplus\nolimits_{\alpha \in A} R)^\wedge$ is flat and Mittag-Leffler.
Proof. By More on Algebra, Lemma Universal injectivity from a completed direct sum into a product the map $(\bigoplus\nolimits_{\alpha \in A} R)^\wedge \to \prod_{\alpha \in A} R$ is universally injective. Thus, by Algebra, Lemmas Flatness (uncovered prerequisite) and Modules (uncovered prerequisite) it suffices to show that $\prod_{\alpha \in A} R$ is flat and Mittag-Leffler. By Algebra, Proposition Criteria for coherent sheaves (uncovered prerequisite) (and Algebra, Lemma Coherent sheaves and Noetherian rings (uncovered prerequisite)) we see that $\prod_{\alpha \in A} R$ is flat. Thus we conclude because a product of copies of $R$ is Mittag-Leffler, see Algebra, Lemma Noetherian rings and tensor products and direct sums (uncovered prerequisite). $\square$
Lemma. Finite presentation and flatness
Let $f : X \to S$ be a morphism of finite presentation. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite presentation flat over $S$. Then the set $$U = \{s \in S \mid \mathcal{F}\text{ is pure along }X_s\}$$ is open in $S$.
Proof. Let $s \in U$. Using Lemma Finite presentation and flatness we can find an elementary étale neighbourhood $(S', s') \to (S, s)$ and a commutative diagram $$\begin{gathered}\begin{matrix}X & X' \\ S & S'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow S' \\ S' & \longrightarrow S\end{aligned}\end{gathered}$$ such that $g$ is étale, $X_s \subset g(X')$, the schemes $X'$, $S'$ are affine, and such that $\Gamma(X', g^*\mathcal{F})$ is a projective $\Gamma(S', \mathcal{O}_{S'})$-module. Note that $g^*\mathcal{F}$ is universally pure over $S'$, see Lemma Projective, locally free modules and affine neighbourhoods. Set $W' \subset X \times_S S'$ equal to the image of the étale morphism $X' \to X \times_S S'$. Note that $W$ is open and quasi-compact over $S'$. Set $$E = \{t \in S' \mid \text{Ass}_{X_t}(\mathcal{F}_t) \subset W' \}.$$ By More on Morphisms, Lemma Prime spectra and associated points $E$ is a constructible subset of $S'$. By Lemma A local criterion for the flattening map we see that $\operatorname{Spec}(\mathcal{O}_{S', s'}) \subset E$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) we see that $E$ contains an open neighbourhood $V'$ of $s'$. Applying Lemma A local criterion for the flattening map once more we see that for any point $s_1$ in the image of $V'$ in $S$ the sheaf $\mathcal{F}$ is pure along $X_{s_1}$. Since $S' \to S$ is étale the image of $V'$ in $S$ is open and we win. $\square$
Proposition. Projective, locally free modules and finite presentation
Let $f : X \to S$ be an affine, finitely presented morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module of finite presentation, flat over $S$. Then the following are equivalent
-
$f_*\mathcal{F}$ is locally projective on $S$, and
-
$\mathcal{F}$ is pure relative to $S$.
In particular, given a ring map $A \to B$ of finite presentation and a finitely presented $B$-module $N$ flat over $A$ we have: $N$ is projective as an $A$-module if and only if $\widetilde{N}$ on $\operatorname{Spec}(B)$ is pure relative to $\operatorname{Spec}(A)$.
Proof. The implication (1) $\Rightarrow$ (2) is Lemma Projective, locally free modules and affine neighbourhoods. Assume $\mathcal{F}$ is pure relative to $S$. Note that by Lemma Flatness and finite algebras this implies $\mathcal{F}$ remains pure after any base change. By Descent, Lemma Projective, locally free modules and local algebra (uncovered prerequisite) it suffices to prove $f_*\mathcal{F}$ is fpqc locally projective on $S$. Pick $s \in S$. We will prove that the restriction of $f_*\mathcal{F}$ to an étale neighbourhood of $s$ is locally projective. Namely, by Lemma Finite presentation and flatness, after replacing $S$ by an affine elementary étale neighbourhood of $s$, we may assume there exists a diagram $$\begin{gathered}\begin{matrix}X & \phantom{X} & X' \\ \phantom{X} & S & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow S \\ X' & \xrightarrow{g} X \\ X' & \longrightarrow S\end{aligned}\end{gathered}$$ of schemes affine and of finite presentation over $S$, where $g$ is étale, $X_s \subset g(X')$, and with $\Gamma(X', g^*\mathcal{F})$ a projective $\Gamma(S, \mathcal{O}_S)$-module. Note that in this case $g^*\mathcal{F}$ is universally pure over $S$, see Lemma Projective, locally free modules and affine neighbourhoods. Hence by Lemma A local criterion for the flattening map we see that the open $g(X')$ contains the points of $\text{Ass}_{X/S}(\mathcal{F})$ lying over $\operatorname{Spec}(\mathcal{O}_{S, s})$. Set $$E = \{t \in S \mid \text{Ass}_{X_t}(\mathcal{F}_t) \subset g(X') \}.$$ By More on Morphisms, Lemma Prime spectra and associated points $E$ is a constructible subset of $S$. We have seen that $\operatorname{Spec}(\mathcal{O}_{S, s}) \subset E$. By Morphisms, Lemma The geometric construction (uncovered prerequisite) we see that $E$ contains an open neighbourhood of $s$. Hence after replacing $S$ by an affine neighbourhood of $s$ we may assume that $\text{Ass}_{X/S}(\mathcal{F}) \subset g(X')$. By Lemma Universal injectivity under flat base change this means that $$\Gamma(X, \mathcal{F}) \longrightarrow \Gamma(X', g^*\mathcal{F})$$ is $\Gamma(S, \mathcal{O}_S)$-universally injective. By Algebra, Lemma Modules (uncovered prerequisite) we conclude that $\Gamma(X, \mathcal{F})$ is Mittag-Leffler as an $\Gamma(S, \mathcal{O}_S)$-module. Since $\Gamma(X, \mathcal{F})$ is countably generated and flat as a $\Gamma(S, \mathcal{O}_S)$-module, we conclude it is projective by Algebra, Lemma Projective and locally free modules (uncovered prerequisite). $\square$
Lemma. Universal injectivity under flat base change
Let $R \to S$ be a ring map. Let $N$ be an $S$-module. Let $S \to S'$ be a ring map. Assume
-
$R \to S$ is of finite presentation and $N$ is of finite presentation over $S$,
-
$N$ is flat over $R$,
-
$S \to S'$ is flat, and
-
the image of $\operatorname{Spec}(S') \to \operatorname{Spec}(S)$ contains all primes $\mathfrak q$ such that $\mathfrak q$ is an associated prime of $N \otimes_R \kappa(\mathfrak p)$ where $\mathfrak p$ is the inverse image of $\mathfrak q$ in $R$.
Then $N \to N \otimes_S S'$ is $R$-universally injective.
Proof. By Algebra, Lemma Injective resolutions and sheaves on ringed sites it suffices to show that $N_{\mathfrak q} \to (N \otimes_R S')_{\mathfrak q}$ is a $R_{\mathfrak p}$-universally injective for any prime $\mathfrak q$ of $S$ lying over $\mathfrak p$ in $R$. Thus we may apply Lemma Universal injectivity under local flat base change to the ring maps $R_{\mathfrak p} \to S_{\mathfrak q} \to S'_{\mathfrak q}$ and the module $N_{\mathfrak q}$. $\square$
Lemma. Universal injectivity under local flat base change
Let $R \to S$ be a ring map. Let $N$ be an $S$-module. Let $S \to S'$ be a ring map. Assume
-
$R \to S$ is a local homomorphism of local rings
-
$S$ is essentially of finite presentation over $R$,
-
$N$ is of finite presentation over $S$,
-
$N$ is flat over $R$,
-
$S \to S'$ is flat, and
-
the image of $\operatorname{Spec}(S') \to \operatorname{Spec}(S)$ contains all primes $\mathfrak q$ of $S$ lying over $\mathfrak m_R$ such that $\mathfrak q$ is an associated prime of $N/\mathfrak m_R N$.
Then $N \to N \otimes_S S'$ is $R$-universally injective.
Proof. Set $N' = N \otimes_R S'$. Consider the commutative diagram $$\begin{gathered}\begin{matrix}N & N' \\ \Sigma^{-1}N & \Sigma^{-1}N'\end{matrix} \\[6pt] \begin{aligned}N & \longrightarrow \Sigma^{-1}N \\ N & \longrightarrow N' \\ N' & \longrightarrow \Sigma^{-1}N' \\ \Sigma^{-1}N & \longrightarrow \Sigma^{-1}N'\end{aligned}\end{gathered}$$ where $\Sigma \subset S$ is the set of elements which are not a zerodivisor on $N/\mathfrak m_R N$. If we can show that the map $N \to \Sigma^{-1}N'$ is universally injective, then $N \to N'$ is too (see Algebra, Lemma Injective resolutions (uncovered prerequisite)).
By Lemma Localization at fibrewise nonzerodivisors the ring $\Sigma^{-1}S$ is a semi-local ring whose maximal ideals correspond to associated primes of $N/\mathfrak m_R N$. Hence the image of $\operatorname{Spec}(\Sigma^{-1}S') \to \operatorname{Spec}(\Sigma^{-1}S)$ contains all these maximal ideals by assumption. By Algebra, Lemma Faithfully flat ring maps the ring map $\Sigma^{-1}S \to \Sigma^{-1}S'$ is faithfully flat. Hence $\Sigma^{-1}N \to \Sigma^{-1}N'$, which is the map $$N \otimes_S \Sigma^{-1}S \longrightarrow N \otimes_S \Sigma^{-1}S'$$ is universally injective, see Algebra, Lemmas Universal injectivity of a faithfully flat ring map (uncovered prerequisite) and Injective resolutions and tensor products and direct sums (uncovered prerequisite). Finally, we apply Lemma Universal injectivity of fibrewise nonzerodivisor multiplication to see that $N \to \Sigma^{-1}N$ is universally injective. As the composition of universally injective module maps is universally injective (see Algebra, Lemma Composition and injective resolutions (uncovered prerequisite)) we conclude that $N \to \Sigma^{-1}N'$ is universally injective and we win. $\square$
Lemma. Universal injectivity of fibrewise nonzerodivisor multiplication
Assumption and notation as in Lemma Localization at fibrewise nonzerodivisors. Assume moreover that
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$S$ is local and $R \to S$ is a local homomorphism,
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$S$ is essentially of finite presentation over $R$,
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$N$ is finitely presented over $S$, and
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$N$ is flat over $R$.
Then each $s \in \Sigma$ defines a universally injective $R$-module map $s : N \to N$, and the map $N \to \Sigma^{-1}N$ is $R$-universally injective.
Proof. By Algebra, Lemma The general fibrewise injectivity criterion for module maps (uncovered prerequisite) the sequence $0 \to N \to N \to N/sN \to 0$ is exact and $N/sN$ is flat over $R$. This implies that $s : N \to N$ is universally injective, see Algebra, Lemma Tor vanishing for a flat module. The map $N \to \Sigma^{-1}N$ is universally injective as the directed colimit of the maps $s : N \to N$. $\square$
[^1]: It is quite easy to show that $H_p$ is a sheaf for the fppf topology using that flat morphisms of finite presentation are open. This is all we really need later on. But it is kind of fun to prove directly that it also satisfies the sheaf condition for the fpqc topology.
Modules and differentials on ringed sites
Lemma. Local pullback on a ringed site
Let $(f, f^\sharp) : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi. Let $\mathcal{F}$ be an $\mathcal{O}_\mathcal{D}$-module.
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If $\mathcal{F}$ is locally free then $f^*\mathcal{F}$ is locally free.
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If $\mathcal{F}$ is finite locally free then $f^*\mathcal{F}$ is finite locally free.
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If $\mathcal{F}$ is locally generated by sections then $f^*\mathcal{F}$ is locally generated by sections.
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If $\mathcal{F}$ is locally generated by $r$ sections then $f^*\mathcal{F}$ is locally generated by $r$ sections.
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If $\mathcal{F}$ is of finite type then $f^*\mathcal{F}$ is of finite type.
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If $\mathcal{F}$ is quasi-coherent then $f^*\mathcal{F}$ is quasi-coherent.
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If $\mathcal{F}$ is of finite presentation then $f^*\mathcal{F}$ is of finite presentation.
Proof. According to the discussion in Section The geometric construction we need only check preservation under pullback for a morphism of ringed sites $(f, f^\sharp) : (\mathcal{C}, \mathcal{O}_\mathcal{C}) \to (\mathcal{D}, \mathcal{O}_\mathcal{D})$ such that $f$ is given by a left exact, continuous functor $u : \mathcal{D} \to \mathcal{C}$ between sites which have all finite limits. Let $\mathcal{G}$ be a sheaf of $\mathcal{O}_\mathcal{D}$-modules which has one of the properties (1) -- (6) of Definition Local ringed sites. We know $\mathcal{D}$ has a final object $Y$ and $X = u(Y)$ is a final object for $\mathcal{C}$. By assumption we have a covering $\{Y_i \to Y\}$ such that $\mathcal{G}|_{\mathcal{D}/Y_i}$ has the corresponding global property. Set $X_i = u(Y_i)$ so that $\{X_i \to X\}$ is a covering in $\mathcal{C}$. We get a commutative diagram of morphisms ringed sites $$\begin{gathered}\begin{matrix}(\mathcal{C}/X_i, \mathcal{O}_\mathcal{C}|_{X_i}) & (\mathcal{C}, \mathcal{O}_\mathcal{C}) \\ (\mathcal{D}/Y_i, \mathcal{O}_\mathcal{D}|_{Y_i}) & (\mathcal{D}, \mathcal{O}_\mathcal{D})\end{matrix} \\[6pt] \begin{aligned}(\mathcal{C}/X_i, \mathcal{O}_\mathcal{C}|_{X_i}) & \longrightarrow (\mathcal{C}, \mathcal{O}_\mathcal{C}) \\ (\mathcal{C}/X_i, \mathcal{O}_\mathcal{C}|_{X_i}) & \longrightarrow (\mathcal{D}/Y_i, \mathcal{O}_\mathcal{D}|_{Y_i}) \\ (\mathcal{C}, \mathcal{O}_\mathcal{C}) & \longrightarrow (\mathcal{D}, \mathcal{O}_\mathcal{D}) \\ (\mathcal{D}/Y_i, \mathcal{O}_\mathcal{D}|_{Y_i}) & \longrightarrow (\mathcal{D}, \mathcal{O}_\mathcal{D})\end{aligned}\end{gathered}$$ by Sites, Lemma Localization of local algebra (uncovered prerequisite). Hence by Lemma Global pullback on a ringed site that $f^*\mathcal{G}|_{X_i}$ has the corresponding global property. Hence we conclude that $\mathcal{G}$ has the local property we started out with by Lemma Locality at a final object. $\square$
Lemma. Testing flatness at stalks
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $\mathcal{F}$ be a sheaf of $\mathcal{O}$-modules. Let $\{p_i\}_{i \in I}$ be a conservative family of points of $\mathcal{C}$. Then $\mathcal{F}$ is flat if and only if $\mathcal{F}_{p_i}$ is a flat $\mathcal{O}_{p_i}$-module for all $i \in I$.
Proof. By Lemma Derived tensor products, Tor amplitude and flatness (uncovered prerequisite) we see one of the implications. For the converse, use that $(\mathcal{F} \otimes_\mathcal{O} \mathcal{G})_p = \mathcal{F}_p \otimes_{\mathcal{O}_p} \mathcal{G}_p$ by Lemma Tensor products and direct sums (uncovered prerequisite) (as taking stalks at $p$ is given by $p^{-1}$) and Lemma Sheaves on ringed sites (uncovered prerequisite). $\square$
Lemma. Exactness of flat pullback
Let $f : \operatorname{Sh}(\mathcal{C}) \to \operatorname{Sh}(\mathcal{C}')$ be a morphism of ringed topoi. Then $$f^{-1} : \textit{Ab}(\mathcal{C}') \longrightarrow \textit{Ab}(\mathcal{C}), \quad \mathcal{F} \longmapsto f^{-1}\mathcal{F}$$ is exact. If $(f, f^\sharp) : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \to (\operatorname{Sh}(\mathcal{C}'), \mathcal{O}')$ is a flat morphism of ringed topoi then $$f^* : \textit{Mod}(\mathcal{O}') \longrightarrow \textit{Mod}(\mathcal{O}), \quad \mathcal{F} \longmapsto f^*\mathcal{F}$$ is exact.
Proof. Given an abelian sheaf $\mathcal{G}$ on $\mathcal{C}'$ the underlying sheaf of sets of $f^{-1}\mathcal{G}$ is the same as $f^{-1}$ of the underlying sheaf of sets of $\mathcal{G}$, see Sites, Section The geometric construction. Hence the exactness of $f^{-1}$ for sheaves of sets (required in the definition of a morphism of topoi, see Sites, Definition Sheaves on ringed sites) implies the exactness of $f^{-1}$ as a functor on abelian sheaves.
To see the statement on modules recall that $f^*\mathcal{F}$ is defined as the tensor product $f^{-1}\mathcal{F} \otimes_{f^{-1}\mathcal{O}', f^\sharp} \mathcal{O}$. Hence $f^*$ is a composition of functors both of which are exact. $\square$
Lemma. Stalks of a pullback
Let $(f, f^\sharp) : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi or ringed sites. Let $p$ be a point of $\mathcal{C}$ or $\operatorname{Sh}(\mathcal{C})$ and set $q = f \circ p$. Then $$(f^*\mathcal{F})_p = \mathcal{F}_q \otimes_{\mathcal{O}_{\mathcal{D}, q}} \mathcal{O}_{\mathcal{C}, p}$$ for any $\mathcal{O}_\mathcal{D}$-module $\mathcal{F}$.
Proof. We have $$f^*\mathcal{F} = f^{-1}\mathcal{F} \otimes_{f^{-1}\mathcal{O}_\mathcal{D}} \mathcal{O}_\mathcal{C}$$ by definition. Since taking stalks at $p$ (i.e., applying $p^{-1}$) commutes with $\otimes$ by Lemma Tensor products and direct sums (uncovered prerequisite) we win by the relation between the stalk of pullbacks at $p$ and stalks at $q$ explained in Sites, Lemma Sheaves on ringed sites (uncovered prerequisite) or Sites, Lemma Sheaves on ringed sites (uncovered prerequisite). $\square$
Lemma. Compatibility of successive localizations of ringed sites
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $f : V \to U$ be a morphism of $\mathcal{C}$. Then there exists a commutative diagram $$\begin{gathered}\begin{matrix}(\operatorname{Sh}(\mathcal{C}/V), \mathcal{O}_V) & \phantom{X} & (\operatorname{Sh}(\mathcal{C}/U), \mathcal{O}_U) \\ \phantom{X} & (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) & \phantom{X}\end{matrix} \\[6pt] \begin{aligned}(\operatorname{Sh}(\mathcal{C}/V), \mathcal{O}_V) & \xrightarrow{(j_V, j_V^\sharp)} (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \\ (\operatorname{Sh}(\mathcal{C}/V), \mathcal{O}_V) & \xrightarrow{(j, j^\sharp)} (\operatorname{Sh}(\mathcal{C}/U), \mathcal{O}_U) \\ (\operatorname{Sh}(\mathcal{C}/U), \mathcal{O}_U) & \xrightarrow{(j_U, j_U^\sharp)} (\operatorname{Sh}(\mathcal{C}), \mathcal{O})\end{aligned}\end{gathered}$$ of ringed topoi. Here $(j, j^\sharp)$ is the localization morphism associated to the object $V/U$ of the ringed site $(\mathcal{C}/U, \mathcal{O}_U)$.
Proof. The only thing to check is that $j_V^\sharp = j^\sharp \circ j^{-1}(j_U^\sharp)$, since everything else follows directly from Sites, Lemma Compatibility of successive localizations of ringed sites (uncovered prerequisite) and Sites, Equation (Local algebra). We omit the verification of the equality. $\square$
Lemma. Localization of a morphism of ringed sites
Let $(f, f^\sharp) : (\mathcal{C}, \mathcal{O}) \longrightarrow (\mathcal{D}, \mathcal{O}')$ be a morphism of ringed sites where $f$ is given by the continuous functor $u : \mathcal{D} \to \mathcal{C}$. Let $V$ be an object of $\mathcal{D}$ and set $U = u(V)$. Then there is a canonical map of sheaves of rings $(f')^\sharp$ such that the diagram of Sites, Lemma Localization of local algebra (uncovered prerequisite) is turned into a commutative diagram of ringed topoi $$\begin{gathered}\begin{matrix}(\operatorname{Sh}(\mathcal{C}/U), \mathcal{O}_U) & \phantom{X} & (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \\ (\operatorname{Sh}(\mathcal{D}/V), \mathcal{O}'_V) & \phantom{X} & (\operatorname{Sh}(\mathcal{D}), \mathcal{O}').\end{matrix} \\[6pt] \begin{aligned}(\operatorname{Sh}(\mathcal{C}/U), \mathcal{O}_U) & \xrightarrow{(j_U, j_U^\sharp)} (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) \\ (\operatorname{Sh}(\mathcal{C}/U), \mathcal{O}_U) & \xrightarrow{(f', (f')^\sharp)} (\operatorname{Sh}(\mathcal{D}/V), \mathcal{O}'_V) \\ (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) & \xrightarrow{(f, f^\sharp)} (\operatorname{Sh}(\mathcal{D}), \mathcal{O}'). \\ (\operatorname{Sh}(\mathcal{D}/V), \mathcal{O}'_V) & \xrightarrow{(j_V, j_V^\sharp)} (\operatorname{Sh}(\mathcal{D}), \mathcal{O}').\end{aligned}\end{gathered}$$ Moreover, in this situation we have $f'_*j_U^{-1} = j_V^{-1}f_*$ and $f'_*j_U^* = j_V^*f_*$.
Proof. Just take $(f')^\sharp$ to be $$(f')^{-1}\mathcal{O}'_V = (f')^{-1}j_V^{-1}\mathcal{O}' = j_U^{-1}f^{-1}\mathcal{O}' \xrightarrow{j_U^{-1}f^\sharp} j_U^{-1}\mathcal{O} = \mathcal{O}_U$$ and everything else follows from Sites, Lemma Localization of local algebra (uncovered prerequisite). (Note that $j^{-1} = j^*$ on sheaves of modules if $j$ is a localization morphism, hence the first equality of functors implies the second.) $\square$
Definition. Local ringed sites
Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $\mathcal{F}$ be a sheaf of $\mathcal{O}$-modules. We will freely use the notions defined in Definition The geometric construction.
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We say $\mathcal{F}$ is locally free if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}_{i \in I}$ of $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/U_i}$ is a free $\mathcal{O}_{U_i}$-module.
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We say $\mathcal{F}$ is finite locally free if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}_{i \in I}$ of $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/U_i}$ is a finite free $\mathcal{O}_{U_i}$-module.
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We say $\mathcal{F}$ is locally generated by sections if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}_{i \in I}$ of $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/U_i}$ is an $\mathcal{O}_{U_i}$-module generated by global sections.
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Given $r \geq 0$ we say $\mathcal{F}$ is locally generated by $r$ sections if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}_{i \in I}$ of $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/U_i}$ is an $\mathcal{O}_{U_i}$-module generated by $r$ global sections.
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We say $\mathcal{F}$ is of finite type if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}_{i \in I}$ of $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/U_i}$ is an $\mathcal{O}_{U_i}$-module generated by finitely many global sections.
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We say $\mathcal{F}$ is quasi-coherent if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}_{i \in I}$ of $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/U_i}$ is an $\mathcal{O}_{U_i}$-module which has a global presentation.
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We say $\mathcal{F}$ is of finite presentation if for every object $U$ of $\mathcal{C}$ there exists a covering $\{U_i \to U\}_{i \in I}$ of $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/U_i}$ is an $\mathcal{O}_{U_i}$-module which has a finite global presentation.
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We say $\mathcal{F}$ is coherent if and only if $\mathcal{F}$ is of finite type, and for every object $U$ of $\mathcal{C}$ and any $s_1, \ldots, s_n \in \mathcal{F}(U)$ the kernel of the map $\bigoplus_{i = 1, \ldots, n} \mathcal{O}_U \to \mathcal{F}|_U$ is of finite type on $(\mathcal{C}/U, \mathcal{O}_U)$.
Lemma. Global pullback on a ringed site
Let $(f, f^\sharp) : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi. Let $\mathcal{F}$ be an $\mathcal{O}_\mathcal{D}$-module.
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If $\mathcal{F}$ is free then $f^*\mathcal{F}$ is free.
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If $\mathcal{F}$ is finite free then $f^*\mathcal{F}$ is finite free.
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If $\mathcal{F}$ is generated by global sections then $f^*\mathcal{F}$ is generated by global sections.
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Given $r \geq 0$ if $\mathcal{F}$ is generated by $r$ global sections, then $f^*\mathcal{F}$ is generated by $r$ global sections.
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If $\mathcal{F}$ is generated by finitely many global sections then $f^*\mathcal{F}$ is generated by finitely many global sections.
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If $\mathcal{F}$ has a global presentation then $f^*\mathcal{F}$ has a global presentation.
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If $\mathcal{F}$ has a finite global presentation then $f^*\mathcal{F}$ has a finite global presentation.
Proof. This is true because $f^*$ commutes with arbitrary colimits (Lemma The geometric construction (uncovered prerequisite)) and $f^*\mathcal{O}_\mathcal{D} = \mathcal{O}_\mathcal{C}$. $\square$
Lemma. Locality at a final object
Let $(\operatorname{Sh}(\mathcal{C}), \mathcal{O})$ be a ringed topos. Let $\mathcal{F}$ be an $\mathcal{O}$-module. Assume that the site $\mathcal{C}$ has a final object $X$. Then
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The following are equivalent
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$\mathcal{F}$ is locally free,
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is a locally free $\mathcal{O}_{X_i}$-module, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is a free $\mathcal{O}_{X_i}$-module.
-
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The following are equivalent
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$\mathcal{F}$ is finite locally free,
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is a finite locally free $\mathcal{O}_{X_i}$-module, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is a finite free $\mathcal{O}_{X_i}$-module.
-
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The following are equivalent
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$\mathcal{F}$ is locally generated by sections,
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module locally generated by sections, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module globally generated by sections.
-
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Given $r \geq 0$, the following are equivalent
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$\mathcal{F}$ is locally generated by $r$ sections,
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module locally generated by $r$ sections, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module globally generated by $r$ sections.
-
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The following are equivalent
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$\mathcal{F}$ is of finite type,
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module of finite type, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module globally generated by finitely many sections.
-
-
The following are equivalent
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$\mathcal{F}$ is quasi-coherent,
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is a quasi-coherent $\mathcal{O}_{X_i}$-module, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module which has a global presentation.
-
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The following are equivalent
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$\mathcal{F}$ is of finite presentation,
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module of finite presentation, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is an $\mathcal{O}_{X_i}$-module has a finite global presentation.
-
-
The following are equivalent
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$\mathcal{F}$ is coherent, and
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there exists a covering $\{X_i \to X\}$ in $\mathcal{C}$ such that each restriction $\mathcal{F}|_{\mathcal{C}/X_i}$ is a coherent $\mathcal{O}_{X_i}$-module.
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Proof. In each case we have (a) $\Rightarrow (b)$. In each of the cases (1) - (6) condition (b) implies condition (c) by axiom (2) of a site (see Sites, Definition Sheaves on ringed sites) and the definition of the local types of modules. Suppose $\{X_i \to X\}$ is a covering. Then for every object $U$ of $\mathcal{C}$ we get an induced covering $\{X_i \times_X U \to U\}$. Moreover, the global property for $\mathcal{F}|_{\mathcal{C}/X_i}$ in part (c) implies the corresponding global property for $\mathcal{F}|_{\mathcal{C}/X_i \times_X U}$ by Lemma Global pullback on a ringed site, hence the sheaf has property (a) by definition. We omit the proof of (b) $\Rightarrow$ (a) in case (7). $\square$
Lemma. Flatness over a square-zero thickening
Let $\mathcal{C}$ be a site. Let $\mathcal{O}' \to \mathcal{O}$ be a surjection of sheaves of rings whose kernel $\mathcal{I}$ is an ideal of square zero. Let $\mathcal{F}'$ be an $\mathcal{O}'$-module and set $\mathcal{F} = \mathcal{F}'/\mathcal{I}\mathcal{F}'$. The following are equivalent
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$\mathcal{F}'$ is a flat $\mathcal{O}'$-module, and
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$\mathcal{F}$ is a flat $\mathcal{O}$-module and $\mathcal{I} \otimes_\mathcal{O} \mathcal{F} \to \mathcal{F}'$ is injective.
Proof. If (1) holds, then $\mathcal{F} = \mathcal{F}' \otimes_{\mathcal{O}'} \mathcal{O}$ is flat over $\mathcal{O}$ by Lemma Flatness (uncovered prerequisite) and we see the map $\mathcal{I} \otimes_\mathcal{O} \mathcal{F} \to \mathcal{F}'$ is injective by applying $- \otimes_{\mathcal{O}'} \mathcal{F}'$ to the exact sequence $0 \to \mathcal{I} \to \mathcal{O}' \to \mathcal{O} \to 0$, see Lemma Tor vanishing for a flat module (uncovered prerequisite). Assume (2). In the rest of the proof we will use without further mention that $\mathcal{K} \otimes_{\mathcal{O}'} \mathcal{F}' = \mathcal{K} \otimes_\mathcal{O} \mathcal{F}$ for any $\mathcal{O}'$-module $\mathcal{K}$ annihilated by $\mathcal{I}$. Let $\alpha : \mathcal{G}' \to \mathcal{H}'$ be an injective map of $\mathcal{O}'$-modules. Let $\mathcal{G} \subset \mathcal{G}'$, resp. $\mathcal{H} \subset \mathcal{H}'$ be the subsheaf of sections annihilated by $\mathcal{I}$. Consider the diagram $$\begin{gathered}\begin{matrix}\mathcal{G} \otimes_{\mathcal{O}'} \mathcal{F}' & \mathcal{G}' \otimes_{\mathcal{O}'} \mathcal{F}' & \mathcal{G}'/\mathcal{G} \otimes_{\mathcal{O}'} \mathcal{F}' & 0 \\ \mathcal{H} \otimes_{\mathcal{O}'} \mathcal{F}' & \mathcal{H}' \otimes_{\mathcal{O}'} \mathcal{F}' & \mathcal{H}'/\mathcal{H} \otimes_{\mathcal{O}'} \mathcal{F}' & 0\end{matrix} \\[6pt] \begin{aligned}\mathcal{G} \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow \mathcal{G}' \otimes_{\mathcal{O}'} \mathcal{F}' \\ \mathcal{G} \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow \mathcal{H} \otimes_{\mathcal{O}'} \mathcal{F}' \\ \mathcal{G}' \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow \mathcal{G}'/\mathcal{G} \otimes_{\mathcal{O}'} \mathcal{F}' \\ \mathcal{G}' \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow \mathcal{H}' \otimes_{\mathcal{O}'} \mathcal{F}' \\ \mathcal{G}'/\mathcal{G} \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow 0 \\ \mathcal{G}'/\mathcal{G} \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow \mathcal{H}'/\mathcal{H} \otimes_{\mathcal{O}'} \mathcal{F}' \\ \mathcal{H} \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow \mathcal{H}' \otimes_{\mathcal{O}'} \mathcal{F}' \\ \mathcal{H}' \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow \mathcal{H}'/\mathcal{H} \otimes_{\mathcal{O}'} \mathcal{F}' \\ \mathcal{H}'/\mathcal{H} \otimes_{\mathcal{O}'} \mathcal{F}' & \longrightarrow 0\end{aligned}\end{gathered}$$ Note that $\mathcal{G}'/\mathcal{G}$ and $\mathcal{H}'/\mathcal{H}$ are annihilated by $\mathcal{I}$ and that $\mathcal{G}'/\mathcal{G} \to \mathcal{H}'/\mathcal{H}$ is injective. Thus the right vertical arrow is injective as $\mathcal{F}$ is flat over $\mathcal{O}$. The same is true for the left vertical arrow. Hence the middle vertical arrow is injective and $\mathcal{F}'$ is flat. $\square$
Definition. Morphisms of locally ringed topoi
Let $(f, f^\sharp) : (\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C}) \to (\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ be a morphism of ringed topoi. Assume $(\operatorname{Sh}(\mathcal{C}), \mathcal{O}_\mathcal{C})$ and $(\operatorname{Sh}(\mathcal{D}), \mathcal{O}_\mathcal{D})$ are locally ringed topoi. We say that $(f, f^\sharp)$ is a morphism of locally ringed topoi if and only if the diagram of sheaves $$\begin{gathered}\begin{matrix}f^{-1}(\mathcal{O}^*_\mathcal{D}) & \mathcal{O}^*_\mathcal{C} \\ f^{-1}(\mathcal{O}_\mathcal{D}) & \mathcal{O}_\mathcal{C}\end{matrix} \\[6pt] \begin{aligned}f^{-1}(\mathcal{O}^*_\mathcal{D}) & \xrightarrow{f^\sharp} \mathcal{O}^*_\mathcal{C} \\ f^{-1}(\mathcal{O}^*_\mathcal{D}) & \longrightarrow f^{-1}(\mathcal{O}_\mathcal{D}) \\ \mathcal{O}^*_\mathcal{C} & \longrightarrow \mathcal{O}_\mathcal{C} \\ f^{-1}(\mathcal{O}_\mathcal{D}) & \xrightarrow{f^\sharp} \mathcal{O}_\mathcal{C}\end{aligned}\end{gathered}$$ (see Lemma Local algebra (uncovered prerequisite)) is cartesian. If $(f, f^\sharp)$ is a morphism of ringed sites, then we say that it is a morphism of locally ringed sites if the associated morphism of ringed topoi is a morphism of locally ringed topoi.
Lemma. Pullback of Kähler differentials
Let $f : \operatorname{Sh}(\mathcal{D}) \to \operatorname{Sh}(\mathcal{C})$ be a morphism of topoi. Let $\varphi : \mathcal{O}_1 \to \mathcal{O}_2$ be a homomorphism of sheaves of rings on $\mathcal{C}$. Then there is a canonical identification $f^{-1}\Omega_{\mathcal{O}_2/\mathcal{O}_1} = \Omega_{f^{-1}\mathcal{O}_2/f^{-1}\mathcal{O}_1}$ compatible with universal derivations.
Proof. This holds because the sheaf $\Omega_{\mathcal{O}_2/\mathcal{O}_1}$ is the cokernel of the map (Cotangent complexes, differentials and modules) and a similar statement holds for $\Omega_{f^{-1}\mathcal{O}_2/f^{-1}\mathcal{O}_1}$, because the functor $f^{-1}$ is exact, and because $f^{-1}(\mathcal{O}_2[\mathcal{O}_2]) = f^{-1}\mathcal{O}_2[f^{-1}\mathcal{O}_2]$, $f^{-1}(\mathcal{O}_2[\mathcal{O}_2 \times \mathcal{O}_2]) = f^{-1}\mathcal{O}_2[f^{-1}\mathcal{O}_2 \times f^{-1}\mathcal{O}_2]$, and $f^{-1}(\mathcal{O}_2[\mathcal{O}_1]) = f^{-1}\mathcal{O}_2[f^{-1}\mathcal{O}_1]$. $\square$
Lemma. The naive cotangent complex up to quasi-isomorphism
In the situation above there is a canonical isomorphism $\mathrm{NL}(\alpha) = \mathrm{NL}_{\mathcal{B}/\mathcal{A}}$ in $D(\mathcal{B})$.
Proof. Observe that $\mathrm{NL}_{\mathcal{B}/\mathcal{A}} = \mathrm{NL}(\text{id}_\mathcal{B})$. Thus it suffices to show that given two maps $\alpha_i : \mathcal{E}_i \to \mathcal{B}$ as above, there is a canonical quasi-isomorphism $\mathrm{NL}(\alpha_1) = \mathrm{NL}(\alpha_2)$ in $D(\mathcal{B})$. To see this set $\mathcal{E} = \mathcal{E}_1 \amalg \mathcal{E}_2$ and $\alpha = \alpha_1 \amalg \alpha_2 : \mathcal{E} \to \mathcal{B}$. Set $\mathcal{J}_i = \operatorname{Ker}(\mathcal{A}[\mathcal{E}_i] \to \mathcal{B})$ and $\mathcal{J} = \operatorname{Ker}(\mathcal{A}[\mathcal{E}] \to \mathcal{B})$. We obtain maps $\mathcal{A}[\mathcal{E}_i] \to \mathcal{A}[\mathcal{E}]$ which send $\mathcal{J}_i$ into $\mathcal{J}$. Thus we obtain canonical maps of complexes $$\mathrm{NL}(\alpha_i) \longrightarrow \mathrm{NL}(\alpha)$$ and it suffices to show these maps are quasi-isomorphism. To see this we argue as follows. First, observe that $H^0(\mathrm{NL}(\alpha_i)) = \Omega_{\mathcal{B}/\mathcal{A}}$ and $H^0(\mathrm{NL}(\alpha)) = \Omega_{\mathcal{B}/\mathcal{A}}$ by Lemma Cotangent complexes and differentials (uncovered prerequisite) hence the map is an isomorphism on cohomology sheaves in degree $0$. Similarly, we claim that $H^{-1}(\mathrm{NL}(\alpha_i))$ and $H^{-1}(\mathrm{NL}(\alpha))$ are the sheaves associated to the presheaf $U \mapsto H_1(L_{\mathcal{B}(U)/\mathcal{A}(U)})$ where $H_1(L_{-/-})$ is as in Algebra, Definition Cotangent complexes, differentials and derived categories. If the claim holds, then the proof is finished.
Proof of the claim. Let $\alpha : \mathcal{E} \to \mathcal{B}$ be as above. Let $\mathcal{B}' \subset \mathcal{B}$ be the subpresheaf of $\mathcal{A}$-algebras whose value on $U$ is the image of $\mathcal{A}(U)[\mathcal{E}(U)] \to \mathcal{B}(U)$. Let $\mathcal{I}'$ be the presheaf whose value on $U$ is the kernel of $\mathcal{A}(U)[\mathcal{E}(U)] \to \mathcal{B}(U)$. Then $\mathcal{I}$ is the sheafification of $\mathcal{I}'$ and $\mathcal{B}$ is the sheafification of $\mathcal{B}'$. Similarly, $H^{-1}(\mathrm{NL}(\alpha))$ is the sheafification of the presheaf $$U \longmapsto \operatorname{Ker}(\mathcal{I}'(U)/\mathcal{I}'(U)^2 \to \Omega_{\mathcal{A}(U)[\mathcal{E}(U)]/\mathcal{A}(U)} \otimes_{\mathcal{A}(U)[\mathcal{E}(U)]} \mathcal{B}'(U))$$ by Lemma Cotangent complexes, differentials and sheaves on ringed sites (uncovered prerequisite). By Algebra, Lemma Kähler differentials, Theorems 3.1–3.3, Proposition 3.4 and Theorem 7.1 we conclude $H^{-1}(\mathrm{NL}(\alpha))$ is the sheaf associated to the presheaf $U \mapsto H_1(L_{\mathcal{B}'(U)/\mathcal{A}(U)})$. Thus we have to show that the maps $H_1(L_{\mathcal{B}'(U)/\mathcal{A}(U)}) \to H_1(L_{\mathcal{B}(U)/\mathcal{A}(U)})$ induce an isomorphism $\mathcal{H}'_1 \to \mathcal{H}_1$ of sheafifications.
Injectivity of $\mathcal{H}'_1 \to \mathcal{H}_1$. Let $f \in H_1(L_{\mathcal{B}'(U)/\mathcal{A}(U)})$ map to zero in $\mathcal{H}_1(U)$. To show: $f$ maps to zero in $\mathcal{H}'_1(U)$. The assumption means there is a covering $\{U_i \to U\}$ such that $f$ maps to zero in $H_1(L_{\mathcal{B}(U_i)/\mathcal{A}(U_i)})$ for all $i$. Replace $U$ by $U_i$ to get to the point where $f$ maps to zero in $H_1(L_{\mathcal{B}(U)/\mathcal{A}(U)})$. By Algebra, Lemma Filtered colimits of naive cotangent complexes (uncovered prerequisite) we can find a finitely generated subalgebra $\mathcal{B}'(U) \subset B \subset \mathcal{B}(U)$ such that $f$ maps to zero in $H_1(L_{B/\mathcal{A}(U)})$. Since $\mathcal{B} = (\mathcal{B}')^\#$ we can find a covering $\{U_i \to U\}$ such that $B \to \mathcal{B}(U_i)$ factors through $\mathcal{B}'(U_i)$. Hence $f$ maps to zero in $H_1(L_{\mathcal{B}'(U_i)/\mathcal{A}(U_i)})$ as desired.
The surjectivity of $\mathcal{H}'_1 \to \mathcal{H}_1$ is proved in exactly the same way. $\square$
Geometric support constructions
Lemma. Categories of spaces over a pushout
Let $S$ be a base scheme. Let $X \to X'$ be a thickening of algebraic spaces over $S$ and let $X \to Y$ be an affine morphism of algebraic spaces over $S$. Let $Y' = Y \amalg_X X'$ be the pushout (see Lemma Pushouts along a thickening of algebraic spaces). Base change gives a functor $$F : (\textit{Spaces}/Y') \longrightarrow (\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X')$$ given by $V' \longmapsto (V' \times_{Y'} Y, V' \times_{Y'} X', 1)$ which sends $(\mathrm{Sch}/Y')$ into $(\mathrm{Sch}/Y) \times_{(\mathrm{Sch}/Y')} (\mathrm{Sch}/X')$. The functor $F$ has a left adjoint $$G : (\textit{Spaces}/Y) \times_{(\textit{Spaces}/X)} (\textit{Spaces}/X') \longrightarrow (\textit{Spaces}/Y')$$ which sends the triple $(V, U', \varphi)$ to the pushout $V \amalg_{(V \times_Y X)} U'$ in the category of algebraic spaces over $S$. The functor $G$ sends $(\mathrm{Sch}/Y) \times_{(\mathrm{Sch}/Y')} (\mathrm{Sch}/X')$ into $(\mathrm{Sch}/Y')$.
Proof. The proof is completely formal. Since the morphisms $X \to X'$ and $X \to Y$ are representable it is clear that $F$ sends $(\mathrm{Sch}/Y')$ into $(\mathrm{Sch}/Y) \times_{(\mathrm{Sch}/Y')} (\mathrm{Sch}/X')$.
Let us construct $G$. Let $(V, U', \varphi)$ be an object of the fibre product category. Set $U = U' \times_{X'} X$. Note that $U \to U'$ is a thickening. Since $\varphi : V \times_Y X \to U' \times_{X'} X = U$ is an isomorphism we have a morphism $U \to V$ over $X \to Y$ which identifies $U$ with the fibre product $X \times_Y V$. In particular $U \to V$ is affine, see Morphisms of Spaces, Lemma Base change for affine neighbourhoods. Hence we can apply Lemma Pushouts along a thickening of algebraic spaces to get a pushout $V' = V \amalg_U U'$. Denote $V' \to Y'$ the morphism we obtain in virtue of the fact that $V'$ is a pushout and because we are given morphisms $V \to Y$ and $U' \to X'$ agreeing on $U$ as morphisms into $Y'$. Setting $G(V, U', \varphi) = V'$ gives the functor $G$.
If $(V, U', \varphi)$ is an object of $(\mathrm{Sch}/Y) \times_{(\mathrm{Sch}/Y')} (\mathrm{Sch}/X')$ then $U = U' \times_{X'} X$ is a scheme too and we can form the pushout $V' = V \amalg_U U'$ in the category of schemes by More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces. By Lemma Pushouts along a thickening of schemes this is also a pushout in the category of schemes, hence $G$ sends $(\mathrm{Sch}/Y) \times_{(\mathrm{Sch}/Y')} (\mathrm{Sch}/X')$ into $(\mathrm{Sch}/Y')$.
Let us prove that $G$ is a left adjoint to $F$. Let $Z$ be an algebraic space over $Y'$. We have to show that $$\operatorname{Mor}(V', Z) = \operatorname{Mor}((V, U', \varphi), F(Z))$$ where the morphism sets are taking in their respective categories. Let $g' : V' \to Z$ be a morphism. Denote $\tilde g$, resp. $\tilde f'$ the composition of $g'$ with the morphism $V \to V'$, resp. $U' \to V'$. Base change $\tilde g$, resp. $\tilde f'$ by $Y \to Y'$, resp. $X' \to Y'$ to get a morphism $g : V \to Z \times_{Y'} Y$, resp. $f' : U' \to Z \times_{Y'} X'$. Then $(g, f')$ is an element of the right hand side of the equation above (details omitted). Conversely, suppose that $(g, f') : (V, U', \varphi) \to F(Z)$ is an element of the right hand side. We may consider the composition $\tilde g : V \to Z$, resp. $\tilde f' : U' \to Z$ of $g$, resp. $f$ by $Z \times_{Y'} X' \to Z$, resp. $Z \times_{Y'} Y \to Z$. Then $\tilde g$ and $\tilde f'$ agree as morphism from $U$ to $Z$. By the universal property of pushout, we obtain a morphism $g' : V' \to Z$, i.e., an element of the left hand side. We omit the verification that these constructions are mutually inverse. $\square$
Lemma. Pushouts along a thickening of algebraic spaces
Let $S$ be a scheme. Let $X \to X'$ be a thickening of algebraic spaces over $S$ and let $X \to Y$ be an affine morphism of algebraic spaces over $S$. Then there exists a pushout $$\begin{gathered}\begin{matrix}X & X' \\ Y & Y \amalg_X X'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow X' \\ X & \xrightarrow{f} Y \\ X' & \xrightarrow{f'} Y \amalg_X X' \\ Y & \longrightarrow Y \amalg_X X'\end{aligned}\end{gathered}$$ in the category of algebraic spaces over $S$. Moreover $Y' = Y \amalg_X X'$ is a thickening of $Y$ and $$\mathcal{O}_{Y'} = \mathcal{O}_Y \times_{f_*\mathcal{O}_X} f'_*\mathcal{O}_{X'}$$ as sheaves on $Y_\mathrm{\acute{e}tale} = (Y')_\mathrm{\acute{e}tale}$.
Proof. Choose a scheme $V$ and a surjective étale morphism $V \to Y$. Set $U = V \times_Y X$. This is a scheme affine over $V$ with a surjective étale morphism $U \to X$. By More on Morphisms of Spaces, Lemma Nilpotent thickenings and groupoids and equivalence relations there exists a $U' \to X'$ surjective étale with $U = U' \times_{X'} X$. In particular the morphism of schemes $U \to U'$ is a thickening too. Apply More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces to obtain a pushout $V' = V \amalg_U U'$ in the category of schemes.
We repeat this procedure to construct a pushout $$\begin{gathered}\begin{matrix}U \times_X U & U' \times_{X'} U' \\ V \times_Y V & R'\end{matrix} \\[6pt] \begin{aligned}U \times_X U & \longrightarrow V \times_Y V \\ U \times_X U & \longrightarrow U' \times_{X'} U' \\ U' \times_{X'} U' & \longrightarrow R' \\ V \times_Y V & \longrightarrow R'\end{aligned}\end{gathered}$$ in the category of schemes. Consider the morphisms $$U \times_X U \to U \to V',\quad U' \times_{X'} U' \to U' \to V',\quad V \times_Y V \to V \to V'$$ where we use the first projection in each case. Clearly these glue to give a morphism $t' : R' \to V'$ which is étale by More on Morphisms, Lemma Flatness and groupoids and equivalence relations. Similarly, we obtain $s' : R' \to V'$ étale. The morphism $j' = (t', s') : R' \to V' \times_S V'$ is unramified (as $t'$ is étale) and a monomorphism when restricted to the closed subscheme $V \times_Y V \subset R'$. As $V \times_Y V \subset R'$ is a thickening it follows that $j'$ is a monomorphism too. Finally, $j'$ is an equivalence relation as we can use the functoriality of pushouts of schemes to construct a morphism $c' : R' \times_{s', V', t'} R' \to R'$ (details omitted). At this point we set $Y' = V'/R'$, see Spaces, Theorem The geometric construction (uncovered prerequisite).
We have morphisms $X' = U'/U' \times_{X'} U' \to V'/R' = Y'$ and $Y = V/V \times_Y V \to V'/R' = Y'$. By construction these fit into the commutative diagram $$\begin{gathered}\begin{matrix}X & X' \\ Y & Y'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow X' \\ X & \xrightarrow{f} Y \\ X' & \xrightarrow{f'} Y' \\ Y & \longrightarrow Y'\end{aligned}\end{gathered}$$ Since $Y \to Y'$ is a thickening we have $Y_\mathrm{\acute{e}tale} = (Y')_\mathrm{\acute{e}tale}$, see More on Morphisms of Spaces, Lemma Nilpotent thickenings and groupoids and equivalence relations. The commutativity of the diagram gives a map of sheaves $$\mathcal{O}_{Y'} \longrightarrow \mathcal{O}_Y \times_{f_*\mathcal{O}_X} f'_*\mathcal{O}_{X'}$$ on this set. By More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces this map is an isomorphism when we restrict to the scheme $V'$, hence it is an isomorphism.
To finish the proof we show that the diagram above is a pushout in the category of algebraic spaces. To see this, let $Z$ be an algebraic space and let $a' : X' \to Z$ and $b : Y \to Z$ be morphisms of algebraic spaces. By Lemma Pushouts along a thickening of schemes we obtain a unique morphism $h : V' \to Z$ fitting into the commutative diagrams $$\begin{gathered}\begin{matrix}U' & V' \\ X' & Z\end{matrix} \\[6pt] \begin{aligned}U' & \longrightarrow X' \\ U' & \longrightarrow V' \\ V' & \xrightarrow{h} Z \\ X' & \xrightarrow{a'} Z\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}V & V' \\ Y & Z\end{matrix} \\[6pt] \begin{aligned}V & \longrightarrow V' \\ V & \longrightarrow Y \\ V' & \xrightarrow{h} Z \\ Y & \xrightarrow{b} Z\end{aligned}\end{gathered}$$ The uniqueness shows that $h \circ t' = h \circ s'$. Hence $h$ factors uniquely as $V' \to Y' \to Z$ and we win. $\square$
Lemma. Pushouts along a thickening of schemes
Let $S$ be a scheme. Let $X \to X'$ be a thickening of schemes over $S$ and let $X \to Y$ be an affine morphism of schemes over $S$. Let $Y' = Y \amalg_X X'$ be the pushout in the category of schemes (see More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces). Then $Y'$ is also a pushout in the category of algebraic spaces over $S$.
Proof. This is an immediate consequence of Lemma Agreement of the sheaf and algebraic-space pushouts and More on Morphisms, Lemmas Pushouts along a thickening of algebraic spaces, Groupoids and equivalence relations, and Flatness and groupoids and equivalence relations. $\square$
Lemma. The cartesian squares defining the pushout
Let $S$ be a scheme. Let $$\begin{gathered}\begin{matrix}A & C & E \\ B & D & F\end{matrix} \\[6pt] \begin{aligned}A & \longrightarrow C \\ A & \longrightarrow B \\ C & \longrightarrow D \\ C & \longrightarrow E \\ E & \longrightarrow F \\ B & \longrightarrow D \\ D & \longrightarrow F\end{aligned}\end{gathered}$$ be a commutative diagram of algebraic spaces over $S$. Assume that $A, B, C, D$ and $A, B, E, F$ form cartesian squares and that $B \to D$ is surjective étale. Then $C, D, E, F$ is a cartesian square.
Proof. This is formal. $\square$
Lemma. Agreement of the sheaf and algebraic-space pushouts
Let $S$ be a scheme. Let $\mathcal{I} \to (\mathrm{Sch}/S)_{fppf}$, $i \mapsto X_i$ be a diagram of schemes over $S$ as above. Assume that
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$X = \mathop{\operatorname{colim}} X_i$ exists in the category of schemes,
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$\coprod X_i \to X$ is surjective,
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if $U \to X$ is étale and $U_i = X_i \times_X U$, then $U = \mathop{\operatorname{colim}} U_i$ in the category of schemes, and
-
every object $(U_i \to X_i)$ of $\varprojlim X_{i, \mathrm{\acute{e}tale}}$ with $U_i \to X_i$ separated is in the essential image of the functor $X_\mathrm{\acute{e}tale} \to \varprojlim X_{i, \mathrm{\acute{e}tale}}$.
Then $X = \mathop{\operatorname{colim}} X_i$ in the category of algebraic spaces over $S$ also.
Proof. Let $Z$ be an algebraic space over $S$. Suppose that $f_i : X_i \to Z$ is a family of morphisms such that for each $i \to j$ the composition $X_i \to X_j \to Z$ is equal to $f_i$. We have to construct a morphism of algebraic spaces $f : X \to Z$ such that we can recover $f_i$ as the composition $X_i \to X \to Z$. Let $W \to Z$ be a surjective étale morphism of a scheme to $Z$. We may assume that $W$ is a disjoint union of affines and in particular we may assume that $W \to Z$ is separated. For each $i$ set $U_i = W \times_{Z, f_i} X_i$ and denote $h_i : U_i \to W$ the projection. Then $U_i \to X_i$ forms an object of $\varprojlim X_{i, \mathrm{\acute{e}tale}}$ with $U_i \to X_i$ separated. By assumption (4) we can find an étale morphism $U \to X$ and (functorial) isomorphisms $U_i = X_i \times_X U$. By assumption (3) there exists a morphism $h : U \to W$ such that the compositions $U_i \to U \to W$ are $h_i$. Let $g : U \to Z$ be the composition of $h$ with the map $W \to Z$. To finish the proof we have to show that $g : U \to Z$ descends to a morphism $X \to Z$. To do this, consider the morphism $(h, h) : U \times_X U \to W \times_S W$. Composing with $U_i \times_{X_i} U_i \to U \times_X U$ we obtain $(h_i, h_i)$ which factors through $W \times_Z W$. Since $U \times_X U$ is the colimit of the schemes $U_i \times_{X_i} U_i$ by (3) we see that $(h, h)$ factors through $W \times_Z W$. Hence the two compositions $U \times_X U \to U \to W \to Z$ are equal. Because each $U_i \to X_i$ is surjective and assumption (2) we see that $U \to X$ is surjective. As $Z$ is a sheaf for the étale topology, we conclude that $g : U \to Z$ descends to $f : X \to Z$ as desired. $\square$
Square-zero extensions and their obstruction maps
Lemma. Matching square-zero thickenings and their markings
Let $S$ be a scheme. Let $i : Z \to Z'$ be a morphism of algebraic spaces over $S$. The following are equivalent
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$i$ is a thickening of algebraic spaces as defined in More on Morphisms of Spaces, Section Nilpotent thickenings, and
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the associated morphism $i_{small} : (\operatorname{Sh}(Z_\mathrm{\acute{e}tale}), \mathcal{O}_Z) \to (\operatorname{Sh}(Z'_\mathrm{\acute{e}tale}), \mathcal{O}_{Z'})$ of ringed topoi (Properties of Spaces, Lemma Sheaves on ringed sites) is a thickening in the sense of Section Nilpotent thickenings and sheaves on ringed sites.
Proof. We stress that this is not a triviality.
Assume (1). By More on Morphisms of Spaces, Lemma Nilpotent thickenings and groupoids and equivalence relations the morphism $i$ induces an equivalence of small étale sites and in particular of topoi. Of course $i^\sharp$ is surjective with locally nilpotent kernel by definition of thickenings.
Assume (2). (This direction is less important and more of a curiosity.) For any étale morphism $Y' \to Z'$ we see that $Y = Z \times_{Z'} Y'$ has the same étale topos as $Y'$. In particular, $Y'$ is quasi-compact if and only if $Y$ is quasi-compact because being quasi-compact is a topos theoretic notion (Sites, Lemma Quasi-compactness of an affine spectrum (uncovered prerequisite)). Having said this we see that $Y'$ is quasi-compact and quasi-separated if and only if $Y$ is quasi-compact and quasi-separated (because you can characterize $Y'$ being quasi-separated by saying that for all $Y'_1, Y'_2$ quasi-compact algebraic spaces étale over $Y'$ we have that $Y'_1 \times_{Y'} Y'_2$ is quasi-compact). Take $Y'$ affine. Then the algebraic space $Y$ is quasi-compact and quasi-separated. For any quasi-coherent $\mathcal{O}_Y$-module $\mathcal{F}$ we have $H^q(Y, \mathcal{F}) = H^q(Y', (Y \to Y')_*\mathcal{F})$ because the étale topoi are the same. Then $H^q(Y', (Y \to Y')_*\mathcal{F}) = 0$ because the pushforward is quasi-coherent (Morphisms of Spaces, Lemma Direct images and morphisms of algebraic spaces) and $Y$ is affine. It follows that $Y'$ is affine by Cohomology of Spaces, Proposition Vanishing and affine neighbourhoods (there surely is a proof of this direction of the lemma avoiding this reference). Hence $i$ is an affine morphism. In the affine case it follows easily from the conditions in Section Nilpotent thickenings and sheaves on ringed sites that $i$ is a thickening of algebraic spaces. $\square$
Lemma. Deformations of modules on ringed topoi
Let $(f, f')$ be a morphism of first order thickenings of ringed topoi as in Situation A morphism between thickenings of ringed topoi. Let $\mathcal{F}'$ be an $\mathcal{O}'$-module and set $\mathcal{F} = i^*\mathcal{F}'$. Assume that $\mathcal{F}$ is flat over $\mathcal{O}_\mathcal{B}$ and that $(f, f')$ is a strict morphism of thickenings (Definition Strict morphisms of thickenings of ringed topoi). Then the following are equivalent
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$\mathcal{F}'$ is flat over $\mathcal{O}_{\mathcal{B}'}$, and
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the canonical map $f^*\mathcal{J} \otimes_\mathcal{O} \mathcal{F} \to \mathcal{I}\mathcal{F}'$ is an isomorphism.
Moreover, in this case the maps $$f^*\mathcal{J} \otimes_\mathcal{O} \mathcal{F} \to \mathcal{I} \otimes_\mathcal{O} \mathcal{F} \to \mathcal{I}\mathcal{F}'$$ are isomorphisms.
Proof. The map $f^*\mathcal{J} \to \mathcal{I}$ is surjective as $(f, f')$ is a strict morphism of thickenings. Hence the final statement is a consequence of (2).
Proof of the equivalence of (1) and (2). By definition flatness over $\mathcal{O}_\mathcal{B}$ means flatness over $f^{-1}\mathcal{O}_\mathcal{B}$. Similarly for flatness over $f^{-1}\mathcal{O}_{\mathcal{B}'}$. Note that the strictness of $(f, f')$ and the assumption that $\mathcal{F} = i^*\mathcal{F}'$ imply that $$\mathcal{F} = \mathcal{F}'/(f^{-1}\mathcal{J})\mathcal{F}'$$ as sheaves on $\mathcal{C}$. Moreover, observe that $f^*\mathcal{J} \otimes_\mathcal{O} \mathcal{F} = f^{-1}\mathcal{J} \otimes_{f^{-1}\mathcal{O}_\mathcal{B}} \mathcal{F}$. Hence the equivalence of (1) and (2) follows from Modules on Sites, Lemma Flatness over a square-zero thickening. $\square$
Lemma. Choices in a square-zero extension of ringed topoi
If there exists a solution to (Sheaves on ringed sites), then the set of isomorphism classes of solutions is principal homogeneous under $\operatorname{Ext}^1_\mathcal{O}( \mathrm{NL}_{\mathcal{O}/\mathcal{O}_\mathcal{B}}, \mathcal{G})$.
Proof. We observe right away that given two solutions $\mathcal{O}'_1$ and $\mathcal{O}'_2$ to (Sheaves on ringed sites) we obtain by Lemma Compatibility of the square-zero extension maps on ringed topoi an obstruction element $o(\mathcal{O}'_1, \mathcal{O}'_2) \in \operatorname{Ext}^1_\mathcal{O}( \mathrm{NL}_{\mathcal{O}/\mathcal{O}_\mathcal{B}}, \mathcal{G})$ to the existence of a map $\mathcal{O}'_1 \to \mathcal{O}'_2$. Clearly, this element is the obstruction to the existence of an isomorphism, hence separates the isomorphism classes. To finish the proof it therefore suffices to show that given a solution $\mathcal{O}'$ and an element $\xi \in \operatorname{Ext}^1_\mathcal{O}( \mathrm{NL}_{\mathcal{O}/\mathcal{O}_\mathcal{B}}, \mathcal{G})$ we can find a second solution $\mathcal{O}'_\xi$ such that $o(\mathcal{O}', \mathcal{O}'_\xi) = \xi$.
Pick $\alpha : \mathcal{E} \to \mathcal{O}$ as in Lemma Representing a square-zero extension by the naive cotangent complex for the class $\xi$. Consider the surjection $f^{-1}\mathcal{O}_\mathcal{B}[\mathcal{E}] \to \mathcal{O}$ with kernel $\mathcal{I}$ and corresponding naive cotangent complex $\mathrm{NL}(\alpha) = (\mathcal{I}/\mathcal{I}^2 \to \Omega_{f^{-1}\mathcal{O}_\mathcal{B}[\mathcal{E}]/ f^{-1}\mathcal{O}_\mathcal{B}} \otimes_{f^{-1}\mathcal{O}_\mathcal{B}[\mathcal{E}]} \mathcal{O})$. By the lemma $\xi$ is the class of a morphism $\delta : \mathcal{I}/\mathcal{I}^2 \to \mathcal{G}$. After replacing $\mathcal{E}$ by $\mathcal{E} \times_\mathcal{O} \mathcal{O}'$ we may also assume that $\alpha$ factors through a map $\alpha' : \mathcal{E} \to \mathcal{O}'$.
These choices determine an $f^{-1}\mathcal{O}_{\mathcal{B}'}$-algebra map $\varphi : \mathcal{O}_{\mathcal{B}'}[\mathcal{E}] \to \mathcal{O}'$. Let $\mathcal{I}' = \operatorname{Ker}(\varphi)$. Observe that $\varphi$ induces a map $\varphi|_{\mathcal{I}'} : \mathcal{I}' \to \mathcal{G}$ and that $\mathcal{O}'$ is the pushout, as in the following diagram $$\begin{gathered}\begin{matrix}0 & \mathcal{G} & \mathcal{O}' & \mathcal{O} & 0 \\ 0 & \mathcal{I}' & f^{-1}\mathcal{O}_{\mathcal{B}'}[\mathcal{E}] & \mathcal{O} & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \mathcal{G} \\ \mathcal{G} & \longrightarrow \mathcal{O}' \\ \mathcal{O}' & \longrightarrow \mathcal{O} \\ \mathcal{O} & \longrightarrow 0 \\ 0 & \longrightarrow \mathcal{I}' \\ \mathcal{I}' & \xrightarrow{\varphi|_{\mathcal{I}'}} \mathcal{G} \\ \mathcal{I}' & \longrightarrow f^{-1}\mathcal{O}_{\mathcal{B}'}[\mathcal{E}] \\ f^{-1}\mathcal{O}_{\mathcal{B}'}[\mathcal{E}] & \longrightarrow \mathcal{O}' \\ f^{-1}\mathcal{O}_{\mathcal{B}'}[\mathcal{E}] & \longrightarrow \mathcal{O} \\ \mathcal{O} & \xrightarrow{=} \mathcal{O} \\ \mathcal{O} & \longrightarrow 0\end{aligned}\end{gathered}$$ Let $\psi : \mathcal{I}' \to \mathcal{G}$ be the sum of the map $\varphi|_{\mathcal{I}'}$ and the composition $$\mathcal{I}' \to \mathcal{I}'/(\mathcal{I}')^2 \to \mathcal{I}/\mathcal{I}^2 \xrightarrow{\delta} \mathcal{G}.$$ Then the pushout along $\psi$ is an other ring extension $\mathcal{O}'_\xi$ fitting into a diagram as above. A calculation (omitted) shows that $o(\mathcal{O}', \mathcal{O}'_\xi) = \xi$ as desired. $\square$
Lemma. Compatibility of the square-zero extension maps on ringed topoi
Assume given a commutative diagram of morphisms ringed topoi
$$\begin{gathered}\begin{matrix}\phantom{X} & (\operatorname{Sh}(\mathcal{C}_2), \mathcal{O}_2) & (\operatorname{Sh}(\mathcal{C}'_2), \mathcal{O}'_2) \\ \phantom{X} & (\operatorname{Sh}(\mathcal{B}_2), \mathcal{O}_{\mathcal{B}_2}) & (\operatorname{Sh}(\mathcal{B}'_2), \mathcal{O}_{\mathcal{B}'_2}) \\ (\operatorname{Sh}(\mathcal{C}_1), \mathcal{O}_1) & (\operatorname{Sh}(\mathcal{C}'_1), \mathcal{O}'_1) \\ (\operatorname{Sh}(\mathcal{B}_1), \mathcal{O}_{\mathcal{B}_1}) & (\operatorname{Sh}(\mathcal{B}'_1), \mathcal{O}_{\mathcal{B}'_1})\end{matrix} \\[6pt] \begin{aligned}(\operatorname{Sh}(\mathcal{C}_2), \mathcal{O}_2) & \xrightarrow{i_2} (\operatorname{Sh}(\mathcal{C}'_2), \mathcal{O}'_2) \\ (\operatorname{Sh}(\mathcal{C}_2), \mathcal{O}_2) & \xrightarrow{f_2} (\operatorname{Sh}(\mathcal{B}_2), \mathcal{O}_{\mathcal{B}_2}) \\ (\operatorname{Sh}(\mathcal{C}_2), \mathcal{O}_2) & \xrightarrow{g} (\operatorname{Sh}(\mathcal{C}_1), \mathcal{O}_1) \\ (\operatorname{Sh}(\mathcal{C}'_2), \mathcal{O}'_2) & \xrightarrow{f'_2} (\operatorname{Sh}(\mathcal{B}'_2), \mathcal{O}_{\mathcal{B}'_2}) \\ (\operatorname{Sh}(\mathcal{B}_2), \mathcal{O}_{\mathcal{B}_2}) & \xrightarrow{t_2} (\operatorname{Sh}(\mathcal{B}'_2), \mathcal{O}_{\mathcal{B}'_2}) \\ (\operatorname{Sh}(\mathcal{B}_2), \mathcal{O}_{\mathcal{B}_2}) & \longrightarrow (\operatorname{Sh}(\mathcal{B}_1), \mathcal{O}_{\mathcal{B}_1}) \\ (\operatorname{Sh}(\mathcal{B}'_2), \mathcal{O}_{\mathcal{B}'_2}) & \longrightarrow (\operatorname{Sh}(\mathcal{B}'_1), \mathcal{O}_{\mathcal{B}'_1}) \\ (\operatorname{Sh}(\mathcal{C}_1), \mathcal{O}_1) & \xrightarrow{i_1} (\operatorname{Sh}(\mathcal{C}'_1), \mathcal{O}'_1) \\ (\operatorname{Sh}(\mathcal{C}_1), \mathcal{O}_1) & \xrightarrow{f_1} (\operatorname{Sh}(\mathcal{B}_1), \mathcal{O}_{\mathcal{B}_1}) \\ (\operatorname{Sh}(\mathcal{C}'_1), \mathcal{O}'_1) & \xrightarrow{f'_1} (\operatorname{Sh}(\mathcal{B}'_1), \mathcal{O}_{\mathcal{B}'_1}) \\ (\operatorname{Sh}(\mathcal{B}_1), \mathcal{O}_{\mathcal{B}_1}) & \xrightarrow{t_1} (\operatorname{Sh}(\mathcal{B}'_1), \mathcal{O}_{\mathcal{B}'_1})\end{aligned}\end{gathered}$$ whose horizontal arrows are first order thickenings. Set $\mathcal{G}_j = \operatorname{Ker}(i_j^\sharp)$ and assume given a map of $g^{-1}\mathcal{O}_1$-modules $\nu : g^{-1}\mathcal{G}_1 \to \mathcal{G}_2$ giving rise to the commutative diagram
$$\begin{gathered}\begin{matrix}\phantom{X} & 0 & \mathcal{G}_2 & \mathcal{O}'_2 & \mathcal{O}_2 & 0 \\ \phantom{X} & 0 & f_2^{-1}\mathcal{J}_2 & f_2^{-1}\mathcal{O}_{\mathcal{B}'_2} & f_2^{-1}\mathcal{O}_{\mathcal{B}_2} & 0 \\ 0 & \mathcal{G}_1 & \mathcal{O}'_1 & \mathcal{O}_1 & 0 \\ 0 & f_1^{-1}\mathcal{J}_1 & f_1^{-1}\mathcal{O}_{\mathcal{B}'_1} & f_1^{-1}\mathcal{O}_{\mathcal{B}_1} & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \mathcal{G}_2 \\ \mathcal{G}_2 & \longrightarrow \mathcal{O}'_2 \\ \mathcal{O}'_2 & \longrightarrow \mathcal{O}_2 \\ \mathcal{O}_2 & \longrightarrow 0 \\ 0 & \longrightarrow f_2^{-1}\mathcal{J}_2 \\ f_2^{-1}\mathcal{J}_2 & \xrightarrow{c_2} \mathcal{G}_2 \\ f_2^{-1}\mathcal{J}_2 & \longrightarrow f_2^{-1}\mathcal{O}_{\mathcal{B}'_2} \\ f_2^{-1}\mathcal{O}_{\mathcal{B}'_2} & \longrightarrow \mathcal{O}'_2 \\ f_2^{-1}\mathcal{O}_{\mathcal{B}'_2} & \longrightarrow f_2^{-1}\mathcal{O}_{\mathcal{B}_2} \\ f_2^{-1}\mathcal{O}_{\mathcal{B}_2} & \longrightarrow \mathcal{O}_2 \\ f_2^{-1}\mathcal{O}_{\mathcal{B}_2} & \longrightarrow 0 \\ 0 & \longrightarrow \mathcal{G}_1 \\ \mathcal{G}_1 & \longrightarrow \mathcal{G}_2 \\ \mathcal{G}_1 & \longrightarrow \mathcal{O}'_1 \\ \mathcal{O}'_1 & \longrightarrow \mathcal{O}_1 \\ \mathcal{O}_1 & \longrightarrow \mathcal{O}_2 \\ \mathcal{O}_1 & \longrightarrow 0 \\ 0 & \longrightarrow f_1^{-1}\mathcal{J}_1 \\ f_1^{-1}\mathcal{J}_1 & \longrightarrow f_2^{-1}\mathcal{J}_2 \\ f_1^{-1}\mathcal{J}_1 & \xrightarrow{c_1} \mathcal{G}_1 \\ f_1^{-1}\mathcal{J}_1 & \longrightarrow f_1^{-1}\mathcal{O}_{\mathcal{B}'_1} \\ f_1^{-1}\mathcal{O}_{\mathcal{B}'_1} & \longrightarrow f_2^{-1}\mathcal{O}_{\mathcal{B}'_2} \\ f_1^{-1}\mathcal{O}_{\mathcal{B}'_1} & \longrightarrow \mathcal{O}'_1 \\ f_1^{-1}\mathcal{O}_{\mathcal{B}'_1} & \longrightarrow f_1^{-1}\mathcal{O}_{\mathcal{B}_1} \\ f_1^{-1}\mathcal{O}_{\mathcal{B}_1} & \longrightarrow f_2^{-1}\mathcal{O}_{\mathcal{B}_2} \\ f_1^{-1}\mathcal{O}_{\mathcal{B}_1} & \longrightarrow \mathcal{O}_1 \\ f_1^{-1}\mathcal{O}_{\mathcal{B}_1} & \longrightarrow 0\end{aligned}\end{gathered}$$ with front and back solutions to (Sheaves on ringed sites). (The north-north-west arrows are maps on $\mathcal{C}_2$ after applying $g^{-1}$ to the source.)
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There exist a canonical element in $\operatorname{Ext}^1_{\mathcal{O}_2}( Lg^*\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}, \mathcal{G}_2)$ whose vanishing is a necessary and sufficient condition for the existence of a morphism of ringed topoi $(\operatorname{Sh}(\mathcal{C}'_2), \mathcal{O}'_2) \to (\operatorname{Sh}(\mathcal{C}'_1), \mathcal{O}'_1)$ fitting into (the displayed identity) compatibly with $\nu$.
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If there exists a morphism $(\operatorname{Sh}(\mathcal{C}'_2), \mathcal{O}'_2) \to (\operatorname{Sh}(\mathcal{C}'_1), \mathcal{O}'_1)$ fitting into (the displayed identity) compatibly with $\nu$ the set of all such morphisms is a principal homogeneous space under $$\operatorname{Hom}_{\mathcal{O}_1}( \Omega_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}, g_*\mathcal{G}_2) = \operatorname{Hom}_{\mathcal{O}_2}( g^*\Omega_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}, \mathcal{G}_2) = \operatorname{Ext}^0_{\mathcal{O}_2}( Lg^*\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}, \mathcal{G}_2).$$
Proof. The proof of this lemma is identical to the proof of Lemma Compatibility of square-zero deformation maps on ringed spaces. We urge the reader to read that proof instead of this one. We will identify the underlying topoi for every thickening in sight (we have already used this convention in the statement). The equalities in the last statement of the lemma are immediate from the definitions. Thus we will work with the groups $\operatorname{Ext}^k_{\mathcal{O}_2}( Lg^*\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}, \mathcal{G}_2)$, $k = 0, 1$ in the rest of the proof. We first argue that we can reduce to the case where the underlying topos of all ringed topoi in the lemma is the same.
To do this, observe that $g^{-1}\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}$ is equal to the naive cotangent complex of the homomorphism of sheaves of rings $g^{-1}f_1^{-1}\mathcal{O}_{\mathcal{B}_1} \to g^{-1}\mathcal{O}_1$, see Modules on Sites, Lemma Pullback of Kähler differentials. Moreover, the degree $0$ term of $\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}$ is a flat $\mathcal{O}_1$-module, hence the canonical map $$Lg^*\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}} \longrightarrow g^{-1}\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}} \otimes_{g^{-1}\mathcal{O}_1} \mathcal{O}_2$$ induces an isomorphism on cohomology sheaves in degrees $0$ and $-1$. Thus we may replace the Ext groups of the lemma with $$\operatorname{Ext}^k_{g^{-1}\mathcal{O}_1}( g^{-1}\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}, \mathcal{G}_2) = \operatorname{Ext}^k_{g^{-1}\mathcal{O}_1}( \mathrm{NL}_{g^{-1}\mathcal{O}_1/g^{-1}f_1^{-1}\mathcal{O}_{\mathcal{B}_1}}, \mathcal{G}_2)$$ The set of morphism of ringed topoi $(\operatorname{Sh}(\mathcal{C}'_2), \mathcal{O}'_2) \to (\operatorname{Sh}(\mathcal{C}'_1), \mathcal{O}'_1)$ fitting into (the displayed identity) compatibly with $\nu$ is in one-to-one bijection with the set of homomorphisms of $g^{-1}f_1^{-1}\mathcal{O}_{\mathcal{B}'_1}$-algebras $g^{-1}\mathcal{O}'_1 \to \mathcal{O}'_2$ which are compatible with $f^\sharp$ and $\nu$. In this way we see that we may assume we have a diagram (the displayed identity) of sheaves on a site $\mathcal{C}$ (with $f_1 = f_2 = \text{id}$ on underlying topoi) and we are looking to find a homomorphism of sheaves of rings $\mathcal{O}'_1 \to \mathcal{O}'_2$ fitting into it.
In the rest of the proof of the lemma we assume all underlying topological spaces are the same, i.e., we have a diagram (the displayed identity) of sheaves on a site $\mathcal{C}$ (with $f_1 = f_2 = \text{id}$ on underlying topoi) and we are looking for homomorphisms of sheaves of rings $\mathcal{O}'_1 \to \mathcal{O}'_2$ fitting into it. As ext groups we will use $\operatorname{Ext}^k_{\mathcal{O}_1}( \mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}, \mathcal{G}_2)$, $k = 0, 1$.
Step 1. Construction of the obstruction class. Consider the sheaf of sets $$\mathcal{E} = \mathcal{O}'_1 \times_{\mathcal{O}_2} \mathcal{O}'_2$$ This comes with a surjective map $\alpha : \mathcal{E} \to \mathcal{O}_1$ and hence we can use $\mathrm{NL}(\alpha)$ instead of $\mathrm{NL}_{\mathcal{O}_1/\mathcal{O}_{\mathcal{B}_1}}$, see Modules on Sites, Lemma The naive cotangent complex up to quasi-isomorphism. Set $$\mathcal{I}' = \operatorname{Ker}(\mathcal{O}_{\mathcal{B}'_1}[\mathcal{E}] \to \mathcal{O}_1) \quad\text{and}\quad \mathcal{I} = \operatorname{Ker}(\mathcal{O}_{\mathcal{B}_1}[\mathcal{E}] \to \mathcal{O}_1)$$ There is a surjection $\mathcal{I}' \to \mathcal{I}$ whose kernel is $\mathcal{J}_1\mathcal{O}_{\mathcal{B}'_1}[\mathcal{E}]$. We obtain two homomorphisms of $\mathcal{O}_{\mathcal{B}'_2}$-algebras $$a : \mathcal{O}_{\mathcal{B}'_1}[\mathcal{E}] \to \mathcal{O}'_1 \quad\text{and}\quad b : \mathcal{O}_{\mathcal{B}'_1}[\mathcal{E}] \to \mathcal{O}'_2$$ which induce maps $a|_{\mathcal{I}'} : \mathcal{I}' \to \mathcal{G}_1$ and $b|_{\mathcal{I}'} : \mathcal{I}' \to \mathcal{G}_2$. Both $a$ and $b$ annihilate $(\mathcal{I}')^2$. Moreover $a$ and $b$ agree on $\mathcal{J}_1\mathcal{O}_{\mathcal{B}'_1}[\mathcal{E}]$ as maps into $\mathcal{G}_2$ because the left hand square of (the displayed identity) is commutative. Thus the difference $b|_{\mathcal{I}'} - \nu \circ a|_{\mathcal{I}'}$ induces a well defined $\mathcal{O}_1$-linear map $$\xi : \mathcal{I}/\mathcal{I}^2 \longrightarrow \mathcal{G}_2$$ which sends the class of a local section $f$ of $\mathcal{I}$ to $a(f') - \nu(b(f'))$ where $f'$ is a lift of $f$ to a local section of $\mathcal{I}'$. We let $[\xi] \in \operatorname{Ext}^1_{\mathcal{O}_1}(\mathrm{NL}(\alpha), \mathcal{G}_2)$ be the image (see below).
Step 2. Vanishing of $[\xi]$ is necessary. Let us write $\Omega = \Omega_{\mathcal{O}_{\mathcal{B}_1}[\mathcal{E}]/\mathcal{O}_{\mathcal{B}_1}} \otimes_{\mathcal{O}_{\mathcal{B}_1}[\mathcal{E}]} \mathcal{O}_1$. Observe that $\mathrm{NL}(\alpha) = (\mathcal{I}/\mathcal{I}^2 \to \Omega)$ fits into a distinguished triangle $$\Omega[0] \to \mathrm{NL}(\alpha) \to \mathcal{I}/\mathcal{I}^2[1] \to \Omega[1]$$ Thus we see that $[\xi]$ is zero if and only if $\xi$ is a composition $\mathcal{I}/\mathcal{I}^2 \to \Omega \to \mathcal{G}_2$ for some map $\Omega \to \mathcal{G}_2$. Suppose there exists a homomorphisms of sheaves of rings $\varphi : \mathcal{O}'_1 \to \mathcal{O}'_2$ fitting into (the displayed identity). In this case consider the map $\mathcal{O}'_1[\mathcal{E}] \to \mathcal{G}_2$, $f' \mapsto b(f') - \varphi(a(f'))$. A calculation shows this annihilates $\mathcal{J}_1\mathcal{O}_{\mathcal{B}'_1}[\mathcal{E}]$ and induces a derivation $\mathcal{O}_{\mathcal{B}_1}[\mathcal{E}] \to \mathcal{G}_2$. The resulting linear map $\Omega \to \mathcal{G}_2$ witnesses the fact that $[\xi] = 0$ in this case.
Step 3. Vanishing of $[\xi]$ is sufficient. Let $\theta : \Omega \to \mathcal{G}_2$ be a $\mathcal{O}_1$-linear map such that $\xi$ is equal to $\theta \circ (\mathcal{I}/\mathcal{I}^2 \to \Omega)$. Then a calculation shows that $$b + \theta \circ d : \mathcal{O}_{\mathcal{B}'_1}[\mathcal{E}] \longrightarrow \mathcal{O}'_2$$ annihilates $\mathcal{I}'$ and hence defines a map $\mathcal{O}'_1 \to \mathcal{O}'_2$ fitting into (the displayed identity).
Proof of (2) in the special case above. Omitted. Hint: This is exactly the same as the proof of (2) of Lemma Compatibility of the square-zero deformation maps. $\square$
Situation. A morphism between thickenings of ringed topoi
A morphism of thickenings of ringed topoi $(f, f')$ is given by a commutative diagram
$$\begin{gathered}\begin{matrix}(\operatorname{Sh}(\mathcal{C}), \mathcal{O}) & (\operatorname{Sh}(\mathcal{D}), \mathcal{O}') \\ (\operatorname{Sh}(\mathcal{B}), \mathcal{O}_\mathcal{B}) & (\operatorname{Sh}(\mathcal{B}'), \mathcal{O}_{\mathcal{B}'})\end{matrix} \\[6pt] \begin{aligned}(\operatorname{Sh}(\mathcal{C}), \mathcal{O}) & \xrightarrow{i} (\operatorname{Sh}(\mathcal{D}), \mathcal{O}') \\ (\operatorname{Sh}(\mathcal{C}), \mathcal{O}) & \xrightarrow{f} (\operatorname{Sh}(\mathcal{B}), \mathcal{O}_\mathcal{B}) \\ (\operatorname{Sh}(\mathcal{D}), \mathcal{O}') & \xrightarrow{f'} (\operatorname{Sh}(\mathcal{B}'), \mathcal{O}_{\mathcal{B}'}) \\ (\operatorname{Sh}(\mathcal{B}), \mathcal{O}_\mathcal{B}) & \xrightarrow{t} (\operatorname{Sh}(\mathcal{B}'), \mathcal{O}_{\mathcal{B}'})\end{aligned}\end{gathered}$$ of ringed topoi whose horizontal arrows are thickenings. In this situation we set $\mathcal{I} = \operatorname{Ker}(i^\sharp) \subset \mathcal{O}'$ and $\mathcal{J} = \operatorname{Ker}(t^\sharp) \subset \mathcal{O}_{\mathcal{B}'}$. As $f = f'$ on underlying topoi we will identify the pullback functors $f^{-1}$ and $(f')^{-1}$. Observe that $(f')^\sharp : f^{-1}\mathcal{O}_{\mathcal{B}'} \to \mathcal{O}'$ induces in particular a map $f^{-1}\mathcal{J} \to \mathcal{I}$ and therefore a map of $\mathcal{O}'$-modules $$(f')^*\mathcal{J} \longrightarrow \mathcal{I}$$ If $i$ and $t$ are first order thickenings, then $(f')^*\mathcal{J} = f^*\mathcal{J}$ and the map above becomes a map $f^*\mathcal{J} \to \mathcal{I}$.
Definition. Strict morphisms of thickenings of ringed topoi
In Situation A morphism between thickenings of ringed topoi we say that $(f, f')$ is a strict morphism of thickenings if the map $(f')^*\mathcal{J} \longrightarrow \mathcal{I}$ is surjective.
Lemma. Representing a square-zero extension by the naive cotangent complex
Let $\mathcal{C}$ be a site. Let $\mathcal{A} \to \mathcal{B}$ be a homomorphism of sheaves of rings on $\mathcal{C}$. Let $\mathcal{G}$ be a $\mathcal{B}$-module. Let $\xi \in \operatorname{Ext}^1_\mathcal{B}(\mathrm{NL}_{\mathcal{B}/\mathcal{A}}, \mathcal{G})$. There exists a map of sheaves of sets $\alpha : \mathcal{E} \to \mathcal{B}$ such that $\xi \in \operatorname{Ext}^1_\mathcal{B}(\mathrm{NL}(\alpha), \mathcal{G})$ is the class of a map $\mathcal{I}/\mathcal{I}^2 \to \mathcal{G}$ (see proof for notation).
Proof. Recall that given $\alpha : \mathcal{E} \to \mathcal{B}$ such that $\mathcal{A}[\mathcal{E}] \to \mathcal{B}$ is surjective with kernel $\mathcal{I}$ the complex $\mathrm{NL}(\alpha) = (\mathcal{I}/\mathcal{I}^2 \to \Omega_{\mathcal{A}[\mathcal{E}]/\mathcal{A}} \otimes_{\mathcal{A}[\mathcal{E}]} \mathcal{B})$ is canonically isomorphic to $\mathrm{NL}_{\mathcal{B}/\mathcal{A}}$, see Modules on Sites, Lemma The naive cotangent complex up to quasi-isomorphism. Observe moreover, that $\Omega = \Omega_{\mathcal{A}[\mathcal{E}]/\mathcal{A}} \otimes_{\mathcal{A}[\mathcal{E}]} \mathcal{B}$ is the sheaf associated to the presheaf $U \mapsto \bigoplus_{e \in \mathcal{E}(U)} \mathcal{B}(U)$. In other words, $\Omega$ is the free $\mathcal{B}$-module on the sheaf of sets $\mathcal{E}$ and in particular there is a canonical map $\mathcal{E} \to \Omega$.
Having said this, pick some $\mathcal{E}$ (for example $\mathcal{E} = \mathcal{B}$ as in the definition of the naive cotangent complex). The obstruction to writing $\xi$ as the class of a map $\mathcal{I}/\mathcal{I}^2 \to \mathcal{G}$ is an element in $\operatorname{Ext}^1_\mathcal{B}(\Omega, \mathcal{G})$. Say this is represented by the extension $0 \to \mathcal{G} \to \mathcal{H} \to \Omega \to 0$ of $\mathcal{B}$-modules. Consider the sheaf of sets $\mathcal{E}' = \mathcal{E} \times_\Omega \mathcal{H}$ which comes with an induced map $\alpha' : \mathcal{E}' \to \mathcal{B}$. Let $\mathcal{I}' = \operatorname{Ker}(\mathcal{A}[\mathcal{E}'] \to \mathcal{B})$ and $\Omega' = \Omega_{\mathcal{A}[\mathcal{E}']/\mathcal{A}} \otimes_{\mathcal{A}[\mathcal{E}']} \mathcal{B}$. The pullback of $\xi$ under the quasi-isomorphism $\mathrm{NL}(\alpha') \to \mathrm{NL}(\alpha)$ maps to zero in $\operatorname{Ext}^1_\mathcal{B}(\Omega', \mathcal{G})$ because the pullback of the extension $\mathcal{H}$ by the map $\Omega' \to \Omega$ is split as $\Omega'$ is the free $\mathcal{B}$-module on the sheaf of sets $\mathcal{E}'$ and since by construction there is a commutative diagram $$\begin{gathered}\begin{matrix}\mathcal{E}' & \mathcal{E} \\ \mathcal{H} & \Omega\end{matrix} \\[6pt] \begin{aligned}\mathcal{E}' & \longrightarrow \mathcal{E} \\ \mathcal{E}' & \longrightarrow \mathcal{H} \\ \mathcal{E} & \longrightarrow \Omega \\ \mathcal{H} & \longrightarrow \Omega\end{aligned}\end{gathered}$$ This finishes the proof. $\square$
Lemma. Compatibility of square-zero deformation maps on ringed spaces
Assume given a commutative diagram of morphisms of ringed spaces
$$\begin{gathered}\begin{matrix}\phantom{X} & (X_2, \mathcal{O}_{X_2}) & (X'_2, \mathcal{O}_{X'_2}) \\ \phantom{X} & (S_2, \mathcal{O}_{S_2}) & (S'_2, \mathcal{O}_{S'_2}) \\ (X_1, \mathcal{O}_{X_1}) & (X'_1, \mathcal{O}_{X'_1}) \\ (S_1, \mathcal{O}_{S_1}) & (S'_1, \mathcal{O}_{S'_1})\end{matrix} \\[6pt] \begin{aligned}(X_2, \mathcal{O}_{X_2}) & \xrightarrow{i_2} (X'_2, \mathcal{O}_{X'_2}) \\ (X_2, \mathcal{O}_{X_2}) & \xrightarrow{f_2} (S_2, \mathcal{O}_{S_2}) \\ (X_2, \mathcal{O}_{X_2}) & \xrightarrow{g} (X_1, \mathcal{O}_{X_1}) \\ (X'_2, \mathcal{O}_{X'_2}) & \xrightarrow{f'_2} (S'_2, \mathcal{O}_{S'_2}) \\ (S_2, \mathcal{O}_{S_2}) & \xrightarrow{t_2} (S'_2, \mathcal{O}_{S'_2}) \\ (S_2, \mathcal{O}_{S_2}) & \longrightarrow (S_1, \mathcal{O}_{S_1}) \\ (S'_2, \mathcal{O}_{S'_2}) & \longrightarrow (S'_1, \mathcal{O}_{S'_1}) \\ (X_1, \mathcal{O}_{X_1}) & \xrightarrow{i_1} (X'_1, \mathcal{O}_{X'_1}) \\ (X_1, \mathcal{O}_{X_1}) & \xrightarrow{f_1} (S_1, \mathcal{O}_{S_1}) \\ (X'_1, \mathcal{O}_{X'_1}) & \xrightarrow{f'_1} (S'_1, \mathcal{O}_{S'_1}) \\ (S_1, \mathcal{O}_{S_1}) & \xrightarrow{t_1} (S'_1, \mathcal{O}_{S'_1})\end{aligned}\end{gathered}$$ whose horizontal arrows are first order thickenings. Set $\mathcal{G}_j = \operatorname{Ker}(i_j^\sharp)$ and assume given a $g$-map $\nu : \mathcal{G}_1 \to \mathcal{G}_2$ of modules giving rise to the commutative diagram
$$\begin{gathered}\begin{matrix}\phantom{X} & 0 & \mathcal{G}_2 & \mathcal{O}_{X'_2} & \mathcal{O}_{X_2} & 0 \\ \phantom{X} & 0 & \mathcal{J}_2 & \mathcal{O}_{S'_2} & \mathcal{O}_{S_2} & 0 \\ 0 & \mathcal{G}_1 & \mathcal{O}_{X'_1} & \mathcal{O}_{X_1} & 0 \\ 0 & \mathcal{J}_1 & \mathcal{O}_{S'_1} & \mathcal{O}_{S_1} & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow \mathcal{G}_2 \\ \mathcal{G}_2 & \longrightarrow \mathcal{O}_{X'_2} \\ \mathcal{O}_{X'_2} & \longrightarrow \mathcal{O}_{X_2} \\ \mathcal{O}_{X_2} & \longrightarrow 0 \\ 0 & \longrightarrow \mathcal{J}_2 \\ \mathcal{J}_2 & \xrightarrow{c_2} \mathcal{G}_2 \\ \mathcal{J}_2 & \longrightarrow \mathcal{O}_{S'_2} \\ \mathcal{O}_{S'_2} & \longrightarrow \mathcal{O}_{X'_2} \\ \mathcal{O}_{S'_2} & \longrightarrow \mathcal{O}_{S_2} \\ \mathcal{O}_{S_2} & \longrightarrow \mathcal{O}_{X_2} \\ \mathcal{O}_{S_2} & \longrightarrow 0 \\ 0 & \longrightarrow \mathcal{G}_1 \\ \mathcal{G}_1 & \longrightarrow \mathcal{G}_2 \\ \mathcal{G}_1 & \longrightarrow \mathcal{O}_{X'_1} \\ \mathcal{O}_{X'_1} & \longrightarrow \mathcal{O}_{X_1} \\ \mathcal{O}_{X_1} & \longrightarrow \mathcal{O}_{X_2} \\ \mathcal{O}_{X_1} & \longrightarrow 0 \\ 0 & \longrightarrow \mathcal{J}_1 \\ \mathcal{J}_1 & \longrightarrow \mathcal{J}_2 \\ \mathcal{J}_1 & \xrightarrow{c_1} \mathcal{G}_1 \\ \mathcal{J}_1 & \longrightarrow \mathcal{O}_{S'_1} \\ \mathcal{O}_{S'_1} & \longrightarrow \mathcal{O}_{S'_2} \\ \mathcal{O}_{S'_1} & \longrightarrow \mathcal{O}_{X'_1} \\ \mathcal{O}_{S'_1} & \longrightarrow \mathcal{O}_{S_1} \\ \mathcal{O}_{S_1} & \longrightarrow \mathcal{O}_{S_2} \\ \mathcal{O}_{S_1} & \longrightarrow \mathcal{O}_{X_1} \\ \mathcal{O}_{S_1} & \longrightarrow 0\end{aligned}\end{gathered}$$ with front and back solutions to (The geometric construction).
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There exist a canonical element in $\operatorname{Ext}^1_{\mathcal{O}_{X_2}}(Lg^*\mathrm{NL}_{X_1/S_1}, \mathcal{G}_2)$ whose vanishing is a necessary and sufficient condition for the existence of a morphism of ringed spaces $X'_2 \to X'_1$ fitting into (the displayed identity) compatibly with $\nu$.
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If there exists a morphism $X'_2 \to X'_1$ fitting into (the displayed identity) compatibly with $\nu$ the set of all such morphisms is a principal homogeneous space under $$\operatorname{Hom}_{\mathcal{O}_{X_1}}(\Omega_{X_1/S_1}, g_*\mathcal{G}_2) = \operatorname{Hom}_{\mathcal{O}_{X_2}}(g^*\Omega_{X_1/S_1}, \mathcal{G}_2) = \operatorname{Ext}^0_{\mathcal{O}_{X_2}}(Lg^*\mathrm{NL}_{X_1/S_1}, \mathcal{G}_2).$$
Proof. The naive cotangent complex $\mathrm{NL}_{X_1/S_1}$ is defined in Modules, Definition Cotangent complexes, differentials and sheaves on ringed sites. The equalities in the last statement of the lemma follow from the fact that $g^*$ is adjoint to $g_*$, the fact that $H^0(\mathrm{NL}_{X_1/S_1}) = \Omega_{X_1/S_1}$ (by construction of the naive cotangent complex) and the fact that $Lg^*$ is the left derived functor of $g^*$. Thus we will work with the groups $\operatorname{Ext}^k_{\mathcal{O}_{X_2}}(Lg^*\mathrm{NL}_{X_1/S_1}, \mathcal{G}_2)$, $k = 0, 1$ in the rest of the proof. We first argue that we can reduce to the case where the underlying topological spaces of all ringed spaces in the lemma is the same.
To do this, observe that $g^{-1}\mathrm{NL}_{X_1/S_1}$ is equal to the naive cotangent complex of the homomorphism of sheaves of rings $g^{-1}f_1^{-1}\mathcal{O}_{S_1} \to g^{-1}\mathcal{O}_{X_1}$, see Modules, Lemma Pullback of cotangent complexes and differentials (uncovered prerequisite). Moreover, the degree $0$ term of $\mathrm{NL}_{X_1/S_1}$ is a flat $\mathcal{O}_{X_1}$-module, hence the canonical map $$Lg^*\mathrm{NL}_{X_1/S_1} \longrightarrow g^{-1}\mathrm{NL}_{X_1/S_1} \otimes_{g^{-1}\mathcal{O}_{X_1}} \mathcal{O}_{X_2}$$ induces an isomorphism on cohomology sheaves in degrees $0$ and $-1$. Thus we may replace the Ext groups of the lemma with $$\operatorname{Ext}^k_{g^{-1}\mathcal{O}_{X_1}}(g^{-1}\mathrm{NL}_{X_1/S_1}, \mathcal{G}_2) = \operatorname{Ext}^k_{g^{-1}\mathcal{O}_{X_1}}( \mathrm{NL}_{g^{-1}\mathcal{O}_{X_1}/g^{-1}f_1^{-1}\mathcal{O}_{S_1}}, \mathcal{G}_2)$$ The set of morphism of ringed spaces $X'_2 \to X'_1$ fitting into (the displayed identity) compatibly with $\nu$ is in one-to-one bijection with the set of homomorphisms of $g^{-1}f_1^{-1}\mathcal{O}_{S'_1}$-algebras $g^{-1}\mathcal{O}_{X'_1} \to \mathcal{O}_{X'_2}$ which are compatible with $f^\sharp$ and $\nu$. In this way we see that we may assume we have a diagram (the displayed identity) of sheaves on $X$ and we are looking to find a homomorphism of sheaves of rings $\mathcal{O}_{X'_1} \to \mathcal{O}_{X'_2}$ fitting into it.
In the rest of the proof of the lemma we assume all underlying topological spaces are the same, i.e., we have a diagram (the displayed identity) of sheaves on a space $X$ and we are looking for homomorphisms of sheaves of rings $\mathcal{O}_{X'_1} \to \mathcal{O}_{X'_2}$ fitting into it. As ext groups we will use $\operatorname{Ext}^k_{\mathcal{O}_{X_1}}( \mathrm{NL}_{\mathcal{O}_{X_1}/\mathcal{O}_{S_1}}, \mathcal{G}_2)$, $k = 0, 1$.
Step 1. Construction of the obstruction class. Consider the sheaf of sets $$\mathcal{E} = \mathcal{O}_{X'_1} \times_{\mathcal{O}_{X_2}} \mathcal{O}_{X'_2}$$ This comes with a surjective map $\alpha : \mathcal{E} \to \mathcal{O}_{X_1}$ and hence we can use $\mathrm{NL}(\alpha)$ instead of $\mathrm{NL}_{\mathcal{O}_{X_1}/\mathcal{O}_{S_1}}$, see Modules, Lemma The naive cotangent complex up to quasi-isomorphism (uncovered prerequisite). Set $$\mathcal{I}' = \operatorname{Ker}(\mathcal{O}_{S'_1}[\mathcal{E}] \to \mathcal{O}_{X_1}) \quad\text{and}\quad \mathcal{I} = \operatorname{Ker}(\mathcal{O}_{S_1}[\mathcal{E}] \to \mathcal{O}_{X_1})$$ There is a surjection $\mathcal{I}' \to \mathcal{I}$ whose kernel is $\mathcal{J}_1\mathcal{O}_{S'_1}[\mathcal{E}]$. We obtain two homomorphisms of $\mathcal{O}_{S'_1}$-algebras $$a : \mathcal{O}_{S'_1}[\mathcal{E}] \to \mathcal{O}_{X'_1} \quad\text{and}\quad b : \mathcal{O}_{S'_1}[\mathcal{E}] \to \mathcal{O}_{X'_2}$$ which induce maps $a|_{\mathcal{I}'} : \mathcal{I}' \to \mathcal{G}_1$ and $b|_{\mathcal{I}'} : \mathcal{I}' \to \mathcal{G}_2$. Both $a$ and $b$ annihilate $(\mathcal{I}')^2$. Moreover $a$ and $b$ agree on $\mathcal{J}_1\mathcal{O}_{S'_1}[\mathcal{E}]$ as maps into $\mathcal{G}_2$ because the left hand square of (the displayed identity) is commutative. Thus the difference $b|_{\mathcal{I}'} - \nu \circ a|_{\mathcal{I}'}$ induces a well defined $\mathcal{O}_{X_1}$-linear map $$\xi : \mathcal{I}/\mathcal{I}^2 \longrightarrow \mathcal{G}_2$$ which sends the class of a local section $f$ of $\mathcal{I}$ to $\nu(a(f')) - b(f')$ where $f'$ is a lift of $f$ to a local section of $\mathcal{I}'$. We let $[\xi] \in \operatorname{Ext}^1_{\mathcal{O}_{X_1}}(\mathrm{NL}(\alpha), \mathcal{G}_2)$ be the image (see below).
Step 2. Vanishing of $[\xi]$ is necessary. Let us write $\Omega = \Omega_{\mathcal{O}_{S_1}[\mathcal{E}]/\mathcal{O}_{S_1}} \otimes_{\mathcal{O}_{S_1}[\mathcal{E}]} \mathcal{O}_{X_1}$. Observe that $\mathrm{NL}(\alpha) = (\mathcal{I}/\mathcal{I}^2 \to \Omega)$ fits into a distinguished triangle $$\Omega[0] \to \mathrm{NL}(\alpha) \to \mathcal{I}/\mathcal{I}^2[1] \to \Omega[1]$$ Thus we see that $[\xi]$ is zero if and only if $\xi$ is a composition $\mathcal{I}/\mathcal{I}^2 \to \Omega \to \mathcal{G}_2$ for some map $\Omega \to \mathcal{G}_2$. Suppose there exists a homomorphisms of sheaves of rings $\varphi : \mathcal{O}_{X'_1} \to \mathcal{O}_{X'_2}$ fitting into (the displayed identity). In this case consider the map $\mathcal{O}_{S'_1}[\mathcal{E}] \to \mathcal{G}_2$, $f' \mapsto b(f') - \varphi(a(f'))$. A calculation shows this annihilates $\mathcal{J}_1\mathcal{O}_{S'_1}[\mathcal{E}]$ and induces a derivation $\mathcal{O}_{S_1}[\mathcal{E}] \to \mathcal{G}_2$. The resulting linear map $\Omega \to \mathcal{G}_2$ witnesses the fact that $[\xi] = 0$ in this case.
Step 3. Vanishing of $[\xi]$ is sufficient. Let $\theta : \Omega \to \mathcal{G}_2$ be a $\mathcal{O}_{X_1}$-linear map such that $\xi$ is equal to $\theta \circ (\mathcal{I}/\mathcal{I}^2 \to \Omega)$. Then a calculation shows that $$b + \theta \circ d : \mathcal{O}_{S'_1}[\mathcal{E}] \to \mathcal{O}_{X'_2}$$ restricted to $\mathcal{I}'$ agrees with $\nu \circ a : \mathcal{I}' \to \mathcal{G}_2$. Since $\mathcal{O}_{X'_1}$ is the pushout of $\mathcal{I}' \to \mathcal{O}_{S'_1}[\mathcal{E}]$ and $\mathcal{I}' \to \mathcal{G}_1$ the maps $b + \theta \circ d$ and $a$ define a map $\mathcal{O}_{X'_1} \to \mathcal{O}_{X'_2}$ fitting into (the displayed identity).
Proof of (2) in the special case above. Omitted. Hint: This is exactly the same as the proof of (2) of Lemma Compatibility of the square-zero deformation maps. $\square$
Lemma. Compatibility of the square-zero deformation maps
Given a commutative diagram $$\begin{gathered}\begin{matrix}\phantom{X} & 0 & N_2 & B'_2 & B_2 & 0 \\ \phantom{X} & 0 & I_2 & A'_2 & A_2 & 0 \\ 0 & N_1 & B'_1 & B_1 & 0 \\ 0 & I_1 & A'_1 & A_1 & 0\end{matrix} \\[6pt] \begin{aligned}0 & \longrightarrow N_2 \\ N_2 & \longrightarrow B'_2 \\ B'_2 & \longrightarrow B_2 \\ B_2 & \longrightarrow 0 \\ 0 & \longrightarrow I_2 \\ I_2 & \xrightarrow{c_2} N_2 \\ I_2 & \longrightarrow A'_2 \\ A'_2 & \longrightarrow B'_2 \\ A'_2 & \longrightarrow A_2 \\ A_2 & \longrightarrow B_2 \\ A_2 & \longrightarrow 0 \\ 0 & \longrightarrow N_1 \\ N_1 & \longrightarrow N_2 \\ N_1 & \longrightarrow B'_1 \\ B'_1 & \longrightarrow B_1 \\ B_1 & \longrightarrow B_2 \\ B_1 & \longrightarrow 0 \\ 0 & \longrightarrow I_1 \\ I_1 & \longrightarrow I_2 \\ I_1 & \xrightarrow{c_1} N_1 \\ I_1 & \longrightarrow A'_1 \\ A'_1 & \longrightarrow A'_2 \\ A'_1 & \longrightarrow B'_1 \\ A'_1 & \longrightarrow A_1 \\ A_1 & \longrightarrow A_2 \\ A_1 & \longrightarrow B_1 \\ A_1 & \longrightarrow 0\end{aligned}\end{gathered}$$ with front and back solutions to (The geometric construction) we have
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There exist a canonical element in $\operatorname{Ext}^1_{B_1}(\mathrm{NL}_{B_1/A_1}, N_2)$ whose vanishing is a necessary and sufficient condition for the existence of a ring map $B'_1 \to B'_2$ fitting into the diagram.
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If there exists a map $B'_1 \to B'_2$ fitting into the diagram the set of all such maps is a principal homogeneous space under $\operatorname{Hom}_{B_1}(\Omega_{B_1/A_1}, N_2)$.
Proof. Let $E = B_1$ viewed as a set. Consider the surjection $A_1[E] \to B_1$ with kernel $J$ used to define the naive cotangent complex by the formula $$\mathrm{NL}_{B_1/A_1} = (J/J^2 \to \Omega_{A_1[E]/A_1} \otimes_{A_1[E]} B_1)$$ in Algebra, Section The naive cotangent complex. Since $\Omega_{A_1[E]/A_1} \otimes B_1$ is a free $B_1$-module we have $$\operatorname{Ext}^1_{B_1}(\mathrm{NL}_{B_1/A_1}, N_2) = \frac{\operatorname{Hom}_{B_1}(J/J^2, N_2)} {\operatorname{Hom}_{B_1}(\Omega_{A_1[E]/A_1} \otimes B_1, N_2)}$$ We will construct an obstruction in the module on the right. Let $J' = \operatorname{Ker}(A'_1[E] \to B_1)$. Note that there is a surjection $J' \to J$ whose kernel is $I_1A'_1[E]$. For every $e \in E$ denote $x_e \in A_1[E]$ the corresponding variable. Choose a lift $y_e \in B'_1$ of the image of $x_e$ in $B_1$ and a lift $z_e \in B'_2$ of the image of $x_e$ in $B_2$. These choices determine $A'_1$-algebra maps $$A'_1[E] \to B'_1 \quad\text{and}\quad A'_1[E] \to B'_2$$ The first of these gives a map $J' \to N_1$, $f' \mapsto f'(y_e)$ and the second gives a map $J' \to N_2$, $f' \mapsto f'(z_e)$. A calculation shows that these maps annihilate $(J')^2$. Because the left square of the diagram (involving $c_1$ and $c_2$) commutes we see that these maps agree on $I_1A'_1[E]$ as maps into $N_2$. Observe that $B'_1$ is the pushout of $J' \to A'_1[E]$ and $J' \to N_1$. Thus, if the maps $J' \to N_1 \to N_2$ and $J' \to N_2$ agree, then we obtain a map $B'_1 \to B'_2$ fitting into the diagram. Thus we let the obstruction be the class of the map $$J/J^2 \to N_2,\quad f \mapsto f'(z_e) - \nu(f'(y_e))$$ where $\nu : N_1 \to N_2$ is the given map and where $f' \in J'$ is a lift of $f$. This is well defined by our remarks above. Note that we have the freedom to modify our choices of $z_e$ into $z_e + \delta_{2, e}$ and $y_e$ into $y_e + \delta_{1, e}$ for some $\delta_{i, e} \in N_i$. This will modify the map above into $$f \mapsto f'(z_e + \delta_{2, e}) - \nu(f'(y_e + \delta_{1, e})) = f'(z_e) - \nu(f'(z_e)) + \sum (\delta_{2, e} - \nu(\delta_{1, e}))\frac{\partial f}{\partial x_e}$$ This means exactly that we are modifying the map $J/J^2 \to N_2$ by the composition $J/J^2 \to \Omega_{A_1[E]/A_1} \otimes B_1 \to N_2$ where the second map sends $\text{d}x_e$ to $\delta_{2, e} - \nu(\delta_{1, e})$. Thus our obstruction is well defined and is zero if and only if a lift exists.
Part (2) comes from the observation that given two maps $\varphi, \psi : B'_1 \to B'_2$ fitting into the diagram, then $\varphi - \psi$ factors through a map $D : B_1 \to N_2$ which is an $A_1$-derivation: $$\begin{aligned} D(fg) & = \varphi(f'g') - \psi(f'g') \\ & = \varphi(f')\varphi(g') - \psi(f')\psi(g') \\ & = (\varphi(f') - \psi(f'))\varphi(g') + \psi(f')(\varphi(g') - \psi(g')) \\ & = gD(f) + fD(g) \end{aligned}$$ Thus $D$ corresponds to a unique $B_1$-linear map $\Omega_{B_1/A_1} \to N_2$. Conversely, given such a linear map we get a derivation $D$ and given a ring map $\psi : B'_1 \to B'_2$ fitting into the diagram the map $\psi + D$ is another ring map fitting into the diagram. $\square$
Affine neighbourhoods compatible with finite orbits
Lemma. An invariant affine neighbourhood of points in local dimension at most one
Let $(U, R, s, t, c)$ be a groupoid scheme. Let $u \in U$. Assume
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$s, t$ are finite morphisms,
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$U$ is separated and locally Noetherian,
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$\dim(\mathcal{O}_{U, u'}) \leq 1$ for every point $u'$ in the orbit of $u$.
Then $u$ is contained in an $R$-invariant affine open of $U$.
Proof. The $R$-orbit of $u$ is finite. By conditions (2) and (3) it is contained in an affine open $U'$ of $U$, see Varieties, Proposition Affine neighbourhoods and finite algebras. Then $t(s^{-1}(U \setminus U'))$ is an $R$-invariant closed subset of $U$ which does not contain $u$. Thus $U \setminus t(s^{-1}(U \setminus U'))$ is an $R$-invariant open of $U'$ containing $u$. Replacing $U$ by this open we may assume $U$ is quasi-affine.
By Lemma An invariant affine neighbourhood on an integral scheme we may replace $U$ by its reduction and assume $U$ is reduced. This means $R$-invariant subschemes $W' \subset W \subset U$ of Lemma Finite flat maps over a schematically dense subscheme are equal $W' = W$. As $U = t(s^{-1}(\overline{W}))$ some point $u'$ of the $R$-orbit of $u$ is contained in $\overline{W}$ and by Lemma An invariant affine neighbourhood on an integral scheme we may replace $U$ by $\overline{W}$ and $u$ by $u'$. Hence we may assume there is a dense open $R$-invariant subscheme $W \subset U$ such that the morphisms $s_W, t_W$ of the restriction $(W, R_W, s_W, t_W, c_W)$ are finite locally free.
If $u \in W$ then we are done by Groupoids, Lemma Affine neighbourhoods (because $W$ is quasi-affine so any finite set of points of $W$ is contained in an affine open, see Properties, Lemma Line bundles, ampleness and affine neighbourhoods). Thus we assume $u \not \in W$ and hence none of the points of the orbit of $u$ is in $W$. Let $\xi \in U$ be a point with a nontrivial specialization to a point $u'$ in the orbit of $u$. Since there are no specializations among the points in the orbit of $u$ (Lemma Specializations in a finite groupoid orbit) we see that $\xi$ is not in the orbit. By assumption (3) we see that $\xi$ is a generic point of $U$ and hence $\xi \in W$. As $U$ is Noetherian there are finitely many of these points $\xi_1, \ldots, \xi_m \in W$. Because $s_W, t_W$ are flat the orbit of each $\xi_j$ consists of generic points of irreducible components of $W$ (and hence $U$).
Let $j : U \to \operatorname{Spec}(A)$ be an immersion of $U$ into an affine scheme (this is possible as $U$ is quasi-affine). Let $J \subset A$ be an ideal such that $V(J) \cap j(W) = \emptyset$ and $V(J) \cup j(W)$ is closed. Apply Lemma Constructing an almost invariant function to the groupoid scheme $(W, R_W, s_W, t_W, c_W)$, the morphism $j|_W : W \to \operatorname{Spec}(A)$, the points $\xi_j$, and the ideal $J$ to find an $f \in J$ such that $(j|_W)^{-1}D(f)$ is an $R_W$-invariant affine open containing $\xi_j$ for all $j$. Since $f \in J$ we see that $j^{-1}D(f) \subset W$, i.e., $j^{-1}D(f)$ is an $R$-invariant affine open of $U$ contained in $W$ containing all $\xi_j$.
Let $Z$ be the reduced induced closed subscheme structure on $$U \setminus j^{-1}D(f) = j^{-1}V(f).$$ Then $Z$ is set theoretically $R$-invariant (but it may not be scheme theoretically $R$-invariant). Let $(Z, R_Z, s_Z, t_Z, c_Z)$ be the restriction of $R$ to $Z$. Since $Z \to U$ is finite, it follows that $s_Z$ and $t_Z$ are finite. Since $u \in Z$ the orbit of $u$ is in $Z$ and agrees with the $R_Z$-orbit of $u$ viewed as a point of $Z$. Since $\dim(\mathcal{O}_{U, u'}) \leq 1$ and since $\xi_j \not \in Z$ for all $j$, we see that $\dim(\mathcal{O}_{Z, u'}) \leq 0$ for all $u'$ in the orbit of $u$. In other words, the $R_Z$-orbit of $u$ consists of generic points of irreducible components of $Z$.
Let $I \subset A$ be an ideal such that $V(I) \cap j(U) =\emptyset$ and $V(I) \cup j(U)$ is closed. Apply Lemma Constructing an almost invariant function to the groupoid scheme $(Z, R_Z, s_Z, t_Z, c_Z)$, the restriction $j|_Z$, the ideal $I$, and the point $u \in Z$ to obtain $h \in I$ such that $j^{-1}D(h) \cap Z$ is an $R_Z$-invariant open affine containing $u$.
Consider the $R_W$-invariant (Groupoids, Lemma The determinant trick for a finite groupoid) function $$g = \text{Norm}_{s_W}(t_W^\sharp(j^\sharp(h)|_W)) \in \Gamma(W, \mathcal{O}_W)$$ (In the following we only need the restriction of $g$ to $j^{-1}D(f)$ and in this case the norm is along a finite locally free morphism of affines.) We claim that $$V = (W_g \cap j^{-1}D(f)) \cup (j^{-1}D(h) \cap Z)$$ is an $R$-invariant affine open of $U$ which finishes the proof of the lemma. It is set theoretically $R$-invariant by construction. As $V$ is a constructible set, to see that it is open it suffices to show it is closed under generalization in $U$ (Topology, Lemma Criteria for Noetherian rings (uncovered prerequisite) or the more general Topology, Lemma The geometric construction (uncovered prerequisite)). Since $W_g \cap j^{-1}D(f)$ is open in $U$, it suffices to consider a specialization $u_1 \leadsto u_2$ of $U$ with $u_2 \in j^{-1}D(h) \cap Z$. This means that $h$ is nonzero in $j(u_2)$ and $u_2 \in Z$. If $u_1 \in Z$, then $j(u_1) \leadsto j(u_2)$ and since $h$ is nonzero in $j(u_2)$ it is nonzero in $j(u_1)$ which implies $u_1 \in V$. If $u_1 \not \in Z$ and also not in $W_g \cap j^{-1}D(f)$, then $u_1 \in W$, $u_1 \not \in W_g$ because the complement of $Z = j^{-1}V(f)$ is contained in $W \cap j^{-1}D(f)$. Hence there exists a point $r_1 \in R$ with $s(r_1) = u_1$ such that $h$ is zero in $t(r_1)$. Since $s$ is finite we can find a specialization $r_1 \leadsto r_2$ with $s(r_2) = u_2$. However, then we conclude that $h$ is zero in $u'_2 = t(r_2)$ which contradicts the fact that $j^{-1}D(h) \cap Z$ is $R$-invariant and $u_2$ is in it. Thus $V$ is open.
Observe that $V \subset j^{-1}D(h)$ for our function $h \in I$. Thus we obtain an immersion $$j' : V \longrightarrow \operatorname{Spec}(A_h)$$ Let $f' \in A_h$ be the image of $f$. Then $(j')^{-1}D(f')$ is the principal open determined by $g$ in the affine open $j^{-1}D(f)$ of $U$. Hence $(j')^{-1}D(f')$ is affine. Finally, $j'(V) \cap V(f') = j'(j^{-1}D(h) \cap Z)$ is closed in $\operatorname{Spec}(A_h/(f')) = \operatorname{Spec}((A/f)_h) = D(h) \cap V(f)$ by our choice of $h \in I$ and the ideal $I$. Hence we can apply Lemma Constructing an invariant affine neighbourhood to conclude that $V$ is affine as claimed above. $\square$
Lemma. Quasi-finite groupoids with proper relation map
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme over $S$. Let $p \in S$ be a point, and let $u \in U$ be a point lying over $p$. Assume assumptions (1) -- (6) of Lemma Finite algebras (uncovered prerequisite) hold as well as
- $j : R \to U \times_S U$ is universally closed[^1].
Then we can choose $(S', p') \to (S, p)$ and decompositions $S' \times_S U = U' \amalg W$ and $S' \times_S R = R' \amalg W'$ and $u' \in U'$ such that (a) -- (g) of Lemma Finite algebras (uncovered prerequisite) hold as well as
- $R'$ is the restriction of $S' \times_S R$ to $U'$.
Proof. We apply Lemma Finite algebras (uncovered prerequisite) for the groupoid $(U, R, s, t, c)$ over the scheme $S$ with points $p$ and $u$. Hence we get an étale neighbourhood $(S', p') \to (S, p)$ and disjoint union decompositions $$S' \times_S U = U' \amalg W, \quad S' \times_S R = R' \amalg W'$$ and $u' \in U'$ satisfying conclusions (a), (b), (c), (d), (e), (f), and (g). We may shrink $S'$ to a smaller neighbourhood of $p'$ without affecting the conclusions (a) -- (g). We will show that for a suitable shrinking conclusion (h) holds as well. Let us denote $j'$ the base change of $j$ to $S'$. By conclusion (e) it is clear that $$j'^{-1}(U' \times_{S'} U') = R' \amalg Rest$$ for some open and closed $Rest$ piece. Since $U' \to S'$ is finite by conclusion (d) we see that $U' \times_{S'} U'$ is finite over $S'$. Since $j$ is universally closed, also $j'$ is universally closed, and hence $j'|_{Rest}$ is universally closed too. By conclusions (b) and (c) we see that the fibre of $$(U' \times_{S'} U' \to S') \circ j'|_{Rest} : Rest \longrightarrow S'$$ over $p'$ is empty. Hence, since $Rest \to S'$ is closed as a composition of closed morphisms, after replacing $S'$ by $S' \setminus \operatorname{Im}(Rest \to S')$, we may assume that $Rest = \emptyset$. And this is exactly the condition that $R'$ is the restriction of $S' \times_S R$ to the open subscheme $U' \subset S' \times_S U$, see Groupoids, Lemma Groupoids and equivalence relations (uncovered prerequisite) and its proof. $\square$
Lemma. An invariant affine neighbourhood on an integral scheme
Let $(U, R, s, t, c)$ be a groupoid scheme over a scheme $S$ with $s, t$ integral. Let $g : U' \to U$ be an integral morphism such that every $R$-orbit in $U$ meets $g(U')$. Let $(U', R', s', t', c')$ be the restriction of $R$ to $U'$. If $u' \in U'$ is contained in an $R'$-invariant affine open, then the image $u \in U$ is contained in an $R$-invariant affine open of $U$.
Proof. Let $W' \subset U'$ be an $R'$-invariant affine open. Set $\tilde R = U' \times_{g, U, t} R$ with maps $\text{pr}_0 : \tilde R \to U'$ and $h = s \circ \text{pr}_1 : \tilde R \to U$. Observe that $\text{pr}_0$ and $h$ are integral. It follows that $\tilde W = \text{pr}_0^{-1}(W')$ is affine. Since $W'$ is $R'$-invariant, the image $W = h(\tilde W)$ is set theoretically $R$-invariant and $\tilde W = h^{-1}(W)$ set theoretically (details omitted). Thus, if we can show that $W$ is open, then $W$ is a scheme and the morphism $\tilde W \to W$ is integral surjective which implies that $W$ is affine by Limits, Proposition Affine neighbourhoods. However, our assumption on orbits meeting $U'$ implies that $h : \tilde R \to U$ is surjective. Since an integral surjective morphism is submersive (Topology, Lemma The geometric construction (uncovered prerequisite) and Morphisms, Lemma Integral extensions (uncovered prerequisite)) it follows that $W$ is open. $\square$
Lemma. Finite flat maps over a schematically dense subscheme
Let $(U, R, s, t, c)$ be a groupoid scheme over a scheme $S$. Assume $s, t$ are finite. There exists an open subscheme $W \subset U$ and a closed subscheme $W' \subset W$ such that
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$W$ and $W'$ are $R$-invariant,
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$U = t(s^{-1}(\overline{W}))$ set theoretically,
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$W$ is a thickening of $W'$, and
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the maps $s'$, $t'$ of the restriction $(W', R', s', t', c')$ are finite locally free.
Proof. Consider the stratification $U = Z_0 \supset Z_1 \supset Z_2 \supset \ldots$ of Lemma Finite algebras (uncovered prerequisite).
We will construct disjoint unions $W = \coprod_{r \geq 1} W_r$ and $W' = \coprod_{r \geq 1} W'_r$ with each $W'_r \to W_r$ a thickening of $R$-invariant subschemes of $U$ such that the morphisms $s_r', t_r'$ of the restrictions $(W_r', R_r', s_r', t_r', c_r')$ are finite locally free of rank $r$. To begin we set $W_1 = W'_1 = U \setminus Z_1$. This is an $R$-invariant open subscheme of $U$, it is true that $W_1$ is a thickening of $W'_1$, and the maps $s_1'$, $t_1'$ of the restriction $(W_1', R_1', s_1', t_1', c_1')$ are isomorphisms, i.e., finite locally free of rank $1$. Moreover, every point of $U \setminus Z_1$ is in $t(s^{-1}(\overline{W_1}))$.
Assume we have found subschemes $W'_r \subset W_r \subset U$ for $r \leq n$ such that
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$W_1, \ldots, W_n$ are disjoint,
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$W_r$ and $W_r'$ are $R$-invariant,
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$U \setminus Z_n \subset \bigcup_{r \leq n} t(s^{-1}(\overline{W_r}))$ set theoretically,
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$W_r$ is a thickening of $W'_r$,
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the maps $s_r'$, $t_r'$ of the restriction $(W_r', R_r', s_r', t_r', c_r')$ are finite locally free of rank $r$.
Then we set $$W_{n + 1} = Z_n \setminus \left( Z_{n + 1} \cup \bigcup\nolimits_{r \leq n} t(s^{-1}(\overline{W_r})) \right)$$ set theoretically and $$W'_{n + 1} = Z_n \setminus \left( Z_{n + 1} \cup \bigcup\nolimits_{r \leq n} t(s^{-1}(\overline{W_r})) \right)$$ scheme theoretically. Then $W_{n + 1}$ is an $R$-invariant open subscheme of $U$ because $Z_{n + 1} \setminus \overline{U \setminus Z_{n + 1}}$ is open in $U$ and $\overline{U \setminus Z_{n + 1}}$ is contained in the closed subset $\bigcup\nolimits_{r \leq n} t(s^{-1}(\overline{W_r}))$ we are removing by property (3) and the fact that $t$ is a closed morphism. It is clear that $W'_{n + 1}$ is a closed subscheme of $W_{n + 1}$ with the same underlying topological space. Finally, properties (1), (2) and (3) are clear and property (5) follows from Lemma Finite algebras (uncovered prerequisite).
By Lemma Finite algebras (uncovered prerequisite) we have $\bigcap Z_r = \emptyset$. Hence every point of $U$ is contained in $U \setminus Z_n$ for some $n$. Thus we see that $U = \bigcup_{r \geq 1} t(s^{-1}(\overline{W_r}))$ set theoretically and we see that (2) holds. Thus $W' \subset W$ satisfy (1), (2), (3), and (4). $\square$
Lemma. Specializations in a finite groupoid orbit
Let $(U, R, s, t, c)$ be a groupoid scheme. If $s, t$ are finite, and $u, u' \in U$ are distinct points in the same orbit, then $u'$ is not a specialization of $u$.
Proof. Let $r \in R$ with $s(r) = u$ and $t(r) = u'$. If $u \leadsto u'$ then we can find a nontrivial specialization $r \leadsto r'$ with $s(r') = u'$, see Schemes, Lemma The geometric construction (uncovered prerequisite). Set $u'' = t(r')$. Note that $u'' \not = u'$ as there are no specializations in the fibres of a finite morphism. Hence we can continue and find a nontrivial specialization $r' \leadsto r''$ with $s(r'') = u''$, etc. This shows that the orbit of $u$ contains an infinite sequence $u \leadsto u' \leadsto u'' \leadsto \ldots$ of specializations which is nonsense as the orbit $t(s^{-1}(\{u\}))$ is finite. $\square$
Lemma. Constructing an almost invariant function
Let $(U, R, s, t, c)$ be a groupoid scheme with $s, t$ finite and of finite presentation. Let $u_1, \ldots, u_m \in U$ be points whose $R$-orbits consist of generic points of irreducible components of $U$. Let $j : U \to \operatorname{Spec}(A)$ be an immersion. Let $I \subset A$ be an ideal such that $j(U) \cap V(I) = \emptyset$ and $V(I) \cup j(U)$ is closed in $\operatorname{Spec}(A)$. Then there exists an $h \in I$ such that $j^{-1}D(h)$ is an $R$-invariant affine open subscheme of $U$ containing $u_1, \ldots, u_m$.
Proof. Let $u_1, \ldots, u_m \in V' \subset V \subset U$ be as in Lemma Affine neighbourhoods (uncovered prerequisite). Since $U \setminus V$ is closed in $U$, $j$ an immersion, and $V(I) \cup j(U)$ is closed in $\operatorname{Spec}(A)$, we can find an ideal $J \subset I$ such that $V(J) = V(I) \cup j(U \setminus V)$. For example we can take the ideal of elements of $I$ which vanish on $j(U \setminus V)$. Thus we can replace $(U, R, s, t, c)$, $j : U \to \operatorname{Spec}(A)$, and $I$ by $(V', R', s', t', c')$, $j|_{V'} : V' \to \operatorname{Spec}(A)$, and $J$. In other words, we may assume that $U$ is affine and that $s$ and $t$ are finite locally free. Take any $f \in I$ which does not vanish at all the points in the $R$-orbits of $u_1, \ldots, u_m$ (Algebra, Lemma An elementary algebraic comparison (uncovered prerequisite)). Consider $$g = \text{Norm}_s(t^\sharp(j^\sharp(f))) \in \Gamma(U, \mathcal{O}_U)$$ Since $f \in I$ and since $V(I) \cup j(U)$ is closed we see that $U \cap D(f) \to D(f)$ is a closed immersion. Hence $f^ng$ is the image of an element $h \in I$ for some $n > 0$. We claim that $h$ works. Namely, we have seen in Groupoids, Lemma The determinant trick for a finite groupoid that $g$ is an $R$-invariant function, hence $D(g) \subset U$ is $R$-invariant. Since $f$ does not vanish on the orbit of $u_j$, the function $g$ does not vanish at $u_j$. Moreover, we have $V(g) \supset V(j^\sharp(f))$ and hence $j^{-1}D(h) = D(g)$. $\square$
Lemma. Constructing an invariant affine neighbourhood
Let $j : V \to \operatorname{Spec}(A)$ be a quasi-compact immersion of schemes. Let $f \in A$ be such that $j^{-1}D(f)$ is affine and $j(V) \cap V(f)$ is closed. Then $V$ is affine.
Proof. This follows from Morphisms, Lemma Constructing an invariant affine neighbourhood (uncovered prerequisite) but we will also give a direct proof. Let $A' = \Gamma(V, \mathcal{O}_V)$. Then $j' : V \to \operatorname{Spec}(A')$ is a quasi-compact open immersion, see Properties, Lemma Affine neighbourhoods (uncovered prerequisite). Let $f' \in A'$ be the image of $f$. Then $(j')^{-1}D(f') = j^{-1}D(f)$ is affine. On the other hand, $j'(V) \cap V(f')$ is a subscheme of $\operatorname{Spec}(A')$ which maps isomorphically to the closed subscheme $j(V) \cap V(f)$ of $\operatorname{Spec}(A)$. Hence it is closed in $\operatorname{Spec}(A')$ for example by Schemes, Lemma Diagonals and separation (uncovered prerequisite). Thus we may replace $A$ by $A'$ and assume that $j$ is an open immersion and $A = \Gamma(V, \mathcal{O}_V)$.
In this case we claim that $j(V) = \operatorname{Spec}(A)$ which finishes the proof. If not, then we can find a principal affine open $D(g) \subset \operatorname{Spec}(A)$ which meets the complement and avoids the closed subset $j(V) \cap V(f)$. Note that $j$ maps $j^{-1}D(f)$ isomorphically onto $D(f)$, see Properties, Lemma Affine neighbourhoods (uncovered prerequisite). Hence $D(g)$ meets $V(f)$. On the other hand, $j^{-1}D(g)$ is a principal open of the affine open $j^{-1}D(f)$ hence affine. Hence by Properties, Lemma Affine neighbourhoods (uncovered prerequisite) again we see that $D(g)$ is isomorphic to $j^{-1}D(g) \subset j^{-1}D(f)$ which implies that $D(g) \subset D(f)$. This contradiction finishes the proof. $\square$
[^1]: In view of the other conditions this is equivalent to requiring $j$ to be proper.
Proper field schemes of dimension at most one
Lemma. Derived tensor products, Tor amplitude and dimension and codimension
Let $B$ be a semi-local Noetherian domain of dimension $1$. Let $B'$ be the integral closure of $B$ in its fraction field. Then $B'$ is a semi-local Dedekind domain. Let $x$ be a nonzero element of the Jacobson radical of $B'$. Then for every $y \in B'$ there exists an $n$ such that $x^n y \in B$.
Proof. Let $\mathfrak m_B$ be the Jacobson radical of $B$. The structure of $B'$ results from Algebra, Lemma Integral extensions. Given $x, y \in B'$ as in the statement of the lemma consider the subring $B \subset A \subset B'$ generated by $x$ and $y$. Then $A$ is finite over $B$ (Algebra, Lemma Criteria for integral extensions and finite algebras). Since the fraction fields of $B$ and $A$ are the same we see that the finite module $A/B$ is supported on the set of closed points of $B$. Thus $\mathfrak m_B^n A \subset B$ for a suitable $n$. Moreover, $\operatorname{Spec}(B') \to \operatorname{Spec}(A)$ is surjective (Algebra, Lemma Surjectivity on spectra of an integral overring), hence $A$ is semi-local as well. It also follows that $x$ is in the Jacobson radical $\mathfrak m_A$ of $A$. Note that $\mathfrak m_A = \sqrt{\mathfrak m_B A}$. Thus $x^m y \in \mathfrak m_B A$ for some $m$. Then $x^{nm} y \in B$. $\square$
Lemma. Finite algebras
Let $f : X \to Y$ be a finite morphism of schemes. Assume there exists an open $V \subset Y$ such that $f^{-1}(V) \to V$ is an isomorphism and $Y \setminus V$ is a discrete space. Then every invertible $\mathcal{O}_X$-module is the pullback of an invertible $\mathcal{O}_Y$-module.
Proof. We will use that $\operatorname{Pic}(X) = H^1(X, \mathcal{O}_X^*)$, see Cohomology, Lemma Line bundles and ampleness. Consider the Leray spectral sequence for the abelian sheaf $\mathcal{O}_X^*$ and $f$, see Cohomology, Lemma The Leray spectral sequence. Consider the induced map $$H^1(X, \mathcal{O}_X^*) \longrightarrow H^0(Y, R^1f_*\mathcal{O}_X^*)$$ Divisors, Lemma Line bundles, ampleness and finite algebras says exactly that this map is zero. Hence Leray gives $H^1(X, \mathcal{O}_X^*) = H^1(Y, f_*\mathcal{O}_X^*)$. Next we consider the map $$f^\sharp : \mathcal{O}_Y^* \longrightarrow f_*\mathcal{O}_X^*$$ By assumption the kernel and cokernel of this map are supported on the closed subset $T = Y \setminus V$ of $Y$. Since $T$ is a discrete topological space by assumption the higher cohomology groups of any abelian sheaf on $Y$ supported on $T$ is zero (follows from Cohomology, Lemma Sheaf cohomology and diagonals and separation, Modules, Lemma The geometric construction (uncovered prerequisite), and the fact that $H^i(T, \mathcal{F}) = 0$ for any $i > 0$ and any abelian sheaf $\mathcal{F}$ on $T$). Breaking the displayed map into short exact sequences $$0 \to \operatorname{Ker}(f^\sharp) \to \mathcal{O}_Y^* \to \operatorname{Im}(f^\sharp) \to 0,\quad 0 \to \operatorname{Im}(f^\sharp) \to f_*\mathcal{O}_X^* \to \operatorname{Coker}(f^\sharp) \to 0$$ we first conclude that $H^1(Y, \mathcal{O}_Y^*) \to H^1(Y, \operatorname{Im}(f^\sharp))$ is surjective and then that $H^1(Y, \operatorname{Im}(f^\sharp)) \to H^1(Y, f_*\mathcal{O}_X^*)$ is surjective. Combining all the above we find that $H^1(Y, \mathcal{O}_Y^*) \to H^1(X, \mathcal{O}_X^*)$ is surjective as desired. $\square$
Lemma. Dimension, codimension and local algebra
Source credit: the original source citation FAC (Chapter II, §1, no. 36, p. 230)
Let $k$ be a field. Let $X$ be a locally algebraic $k$-scheme.
The topological space of $X$ is catenary (Topology, Definition [The geometric construction](#context-topology-definition-catenary)).
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For $x \in X$ closed, we have $\dim_x(X) = \dim(\mathcal{O}_{X, x})$.
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For $X$ irreducible we have $\dim(X) = \dim(U)$ for any nonempty open $U \subset X$ and $\dim(X) = \dim_x(X)$ for any $x \in X$.
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For $X$ irreducible any chain of irreducible closed subsets can be extended to a maximal chain and all maximal chains of irreducible closed subsets have length equal to $\dim(X)$.
For $x \in X$ we have $\dim_x(X) = \max \dim(Z) = \min \dim(\mathcal{O}_{X, x'})$ where the maximum is over irreducible components $Z \subset X$ containing $x$ and the minimum is over specializations $x \leadsto x'$ with $x'$ closed in $X$.
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If $X$ is irreducible with generic point $x$, then $\dim(X) = \text{trdeg}_k(\kappa(x))$.
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If $x \leadsto x'$ is an immediate specialization of points of $X$, then we have $\text{trdeg}_k(\kappa(x)) = \text{trdeg}_k(\kappa(x')) + 1$.
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The dimension of $X$ is the supremum of the numbers $\text{trdeg}_k(\kappa(x))$ where $x$ runs over the generic points of the irreducible components of $X$.
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If $x \leadsto x'$ is a nontrivial specialization of points of $X$, then
1. $\dim_x(X) \leq \dim_{x'}(X)$,
2. $\dim(\mathcal{O}_{X, x}) < \dim(\mathcal{O}_{X, x'})$,
3. $\text{trdeg}_k(\kappa(x)) > \text{trdeg}_k(\kappa(x'))$, and
4. any maximal chain of nontrivial specializations $x = x_0 \leadsto x_1 \leadsto \ldots \leadsto x_n = x'$ has length $n = \text{trdeg}_k(\kappa(x)) - \text{trdeg}_k(\kappa(x'))$.
For $x \in X$ we have $\dim_x(X) = \text{trdeg}_k(\kappa(x)) + \dim(\mathcal{O}_{X, x})$.
- If $x \leadsto x'$ is an immediate specialization of points of $X$ and $X$ is irreducible or equidimensional, then $\dim(\mathcal{O}_{X, x'}) = \dim(\mathcal{O}_{X, x}) + 1$.
Proof. Instead on relying on the more general results proved earlier we will reduce the statements to the corresponding statements for finite type $k$-algebras and cite results from the chapter on commutative algebra.
Proof of (the indicated step). This is local on $X$ by Topology, Lemma The geometric construction (uncovered prerequisite). Thus we may assume $X = \operatorname{Spec}(A)$ where $A$ is a finite type $k$-algebra. We have to show that $A$ is catenary (Algebra, Lemma Commutative algebra (uncovered prerequisite)). We can reduce to $k[x_1, \ldots, x_n]$ using Algebra, Lemma Commutative algebra (uncovered prerequisite) and then apply Algebra, Lemma Height and dimension in a polynomial ring (uncovered prerequisite). Alternatively, this holds because $k$ is Cohen-Macaulay (trivially) and Cohen-Macaulay rings are universally catenary (Algebra, Lemma Commutative algebra (uncovered prerequisite)).
Proof of (the indicated step). Choose an affine neighbourhood $U = \operatorname{Spec}(A)$ of $x$. Then $\dim_x(X) = \dim_x(U)$. Hence we reduce to the affine case, which is Algebra, Lemma Dimension, codimension and field extensions (uncovered prerequisite).
Proof of (the indicated step). It suffices to show that any two nonempty affine opens $U, U' \subset X$ have the same dimension (any finite chain of irreducible subsets meets an affine open). Pick a closed point $x$ of $X$ with $x \in U \cap U'$. This is possible because $X$ is irreducible, hence $U \cap U'$ is nonempty, hence there is such a closed point because $X$ is Jacobson by Lemma Finite algebras and local algebra (uncovered prerequisite). Then $\dim(U) = \dim(\mathcal{O}_{X, x}) = \dim(U')$ by Algebra, Lemma Dimension and codimension (uncovered prerequisite) (strictly speaking you have to replace $X$ by its reduction before applying the lemma).
Proof of (the indicated step). Given a chain of irreducible closed subsets we can find an affine open $U \subset X$ which meets the smallest one. Thus the statement follows from Algebra, Lemma Dimension and codimension (uncovered prerequisite) and $\dim(U) = \dim(X)$ which we have seen in (the indicated step).
Proof of (the indicated step). Choose an affine neighbourhood $U = \operatorname{Spec}(A)$ of $x$. Then $\dim_x(X) = \dim_x(U)$. The rule $Z \mapsto Z \cap U$ is a bijection between irreducible components of $X$ passing through $x$ and irreducible components of $U$ passing through $x$. Also, $\dim(Z \cap U) = \dim(Z)$ for such $Z$ by (the indicated step). Hence the statement follows from Algebra, Lemma Dimension, codimension and field extensions (uncovered prerequisite).
Proof of (the indicated step). By (the indicated step) this reduces to the case where $X = \operatorname{Spec}(A)$ is affine. In this case it follows from Algebra, Lemma Prime ideals and dimension in a polynomial ring (uncovered prerequisite) applied to $A_{red}$.
Proof of (the indicated step). Let $Z = \overline{\{x\}} \supset Z' = \overline{\{x'\}}$. Then it follows from (the indicated step) that $Z \supset Z'$ is the start of a maximal chain of irreducible closed subschemes in $Z$ and consequently $\dim(Z) = \dim(Z') + 1$. We conclude by (the indicated step).
Proof of (the indicated step). A simple topological argument shows that $\dim(X) = \sup \dim(Z)$ where the supremum is over the irreducible components of $X$ (hint: use Topology, Lemma Irreducibility of an affine spectrum (uncovered prerequisite)). Thus this follows from (the indicated step).
Proof of (the indicated step). Part (a) follows from the fact that any open $U \subset X$ containing $x'$ also contains $x$. Part (b) follows because $\mathcal{O}_{X, x}$ is a localization of $\mathcal{O}_{X, x'}$ hence any chain of primes in $\mathcal{O}_{X, x}$ corresponds to a chain of primes in $\mathcal{O}_{X, x'}$ which can be extended by adding $\mathfrak m_{x'}$ at the end. Both (c) and (d) follow formally from (the indicated step).
Proof of (the indicated step). Choose an affine neighbourhood $U = \operatorname{Spec}(A)$ of $x$. Then $\dim_x(X) = \dim_x(U)$. Hence we reduce to the affine case, which is Algebra, Lemma Dimension, codimension and field extensions (uncovered prerequisite).
Proof of (the indicated step). If $X$ is equidimensional (Topology, Definition Dimension and codimension) then $\dim(X)$ is equal to the dimension of every irreducible component of $X$, whence $\dim_x(X) = \dim(X) = \dim_{x'}(X)$ by (the indicated step). Thus this follows from (the indicated step). $\square$
Proposition. Affine neighbourhoods and finite algebras
Let $X$ be a separated scheme such that every quasi-compact open has a finite number of irreducible components. Let $x_1, \ldots, x_r \in X$ be points such that $\mathcal{O}_{X, x_i}$ is Noetherian of dimension $\leq 1$. Then there exists an affine open subscheme of $X$ containing all of $x_1, \ldots, x_r$.
Proof. We can replace $X$ by a quasi-compact open containing $x_1, \ldots, x_r$ hence we may assume that $X$ has finitely many irreducible components. By Lemma Affine neighbourhoods and finite algebras (uncovered prerequisite) we reduce to the case where $X$ is integral. This case is Lemma Affine neighbourhoods and finite algebras (uncovered prerequisite). $\square$
Lemma. The geometric construction
Let $k$ be a field. Let $X$ be a scheme over $k$. Assume $X$ is connected and has a point $x$ such that $k$ is algebraically closed in $\kappa(x)$. Then $X$ is geometrically connected. In particular, if $X$ has a $k$-rational point and $X$ is connected, then $X$ is geometrically connected.
Proof. Set $T = \operatorname{Spec}(\kappa(x))$. Let $\overline{k}$ be a separable algebraic closure of $k$. The assumption on $\kappa(x)/k$ implies that $T_{\overline{k}}$ is irreducible, see Algebra, Lemma Field extensions (uncovered prerequisite). Hence by Lemma The geometric construction (uncovered prerequisite) we see that $X_{\overline{k}}$ is connected. By Lemma Criteria for the geometric construction (uncovered prerequisite) we conclude that $X$ is geometrically connected. $\square$
Moduli of sheaves and proper spaces
Proposition. Representability of the morphism functor
Let $S$ be a scheme. Let $Z \to B$ and $X \to B$ be morphisms of algebraic spaces over $S$. Assume $X \to B$ is of finite presentation and separated and $Z \to B$ is of finite presentation, flat, and proper. Then $\mathit{Mor}_B(Z, X)$ is an algebraic space locally of finite presentation over $B$.
Proof. Immediate consequence of Lemma The graph locus in the Hilbert functor and Proposition Representability of the Hilbert functor. $\square$
Remark. Base change of the proper-space groupoid
Let $B$ be an algebraic space over $\operatorname{Spec}(\mathbf{Z})$. Let $B\textit{-Spaces}'_{ft}$ be the category consisting of pairs $(X \to S, h : S \to B)$ where $X \to S$ is an object of $\mathcal{S}\!paces'_{ft}$ and $h : S \to B$ is a morphism. A morphism $(X' \to S', h') \to (X \to S, h)$ in $B\textit{-Spaces}'_{ft}$ is a morphism $(f, g)$ in $\mathcal{S}\!paces'_{ft}$ such that $h \circ g = h'$. In this situation the diagram $$\begin{gathered}\begin{matrix}B\textit{-Spaces}'_{ft} & \mathcal{S}\!paces'_{ft} \\ (\mathrm{Sch}/B)_{fppf} & \mathrm{Sch}_{fppf}\end{matrix} \\[6pt] \begin{aligned}B\textit{-Spaces}'_{ft} & \longrightarrow \mathcal{S}\!paces'_{ft} \\ B\textit{-Spaces}'_{ft} & \longrightarrow (\mathrm{Sch}/B)_{fppf} \\ \mathcal{S}\!paces'_{ft} & \longrightarrow \mathrm{Sch}_{fppf} \\ (\mathrm{Sch}/B)_{fppf} & \longrightarrow \mathrm{Sch}_{fppf}\end{aligned}\end{gathered}$$ is $2$-fibre product square. This trivial remark will occasionally be useful to deduce results from the absolute case $\mathcal{S}\!paces'_{ft}$ to the case of families over a given base algebraic space. Of course, a similar construction works for $B\textit{-Spaces}'_{fp, flat, proper}$
Lemma. The forgetful map from polarized schemes to proper spaces
The functor (Proper morphisms) defines a $1$-morphism $$\mathcal{P}\!ol \to \mathcal{S}\!paces'_{fp, flat, proper}$$ of stacks in groupoids over $\mathrm{Sch}_{fppf}$ which is algebraic in the sense of Criteria for Representability, Definition The geometric construction.
Proof. By Lemmas Descent of proper flat spaces and Descent of polarized proper schemes the statement makes sense. To prove it, we choose a scheme $S$ and an object $\xi = (X \to S)$ of $\mathcal{S}\!paces'_{fp, flat, proper}$ over $S$. We have to show that $$\mathcal{X} = (\mathrm{Sch}/S)_{fppf} \times_{\xi, \mathcal{S}\!paces'_{fp, flat, proper}} \mathcal{P}\!ol$$ is an algebraic stack over $S$. Observe that an object of $\mathcal{X}$ is given by a pair $(T/S, \mathcal{L})$ where $T$ is a scheme over $S$ and $\mathcal{L}$ is an invertible $\mathcal{O}_{X_T}$-module which is ample on $X_T/T$. Morphisms are defined in the obvious manner. In particular, we see immediately that we have an inclusion $$\mathcal{X} \subset \mathcal{P}\!ic_{X/S}$$ of categories over $(\mathrm{Sch}/S)_{fppf}$, inducing equality on morphism sets. Since $\mathcal{P}\!ic_{X/S}$ is an algebraic stack by Proposition Representability of the Picard functor it suffices to show that the inclusion above is representable by open immersions. This is exactly the content of Descent on Spaces, Lemma Line bundles and ampleness. $\square$
Situation. The groupoid of flat sheaves with proper support
Let $S$ be a scheme. Let $f : X \to B$ be a morphism of algebraic spaces over $S$. Assume that $f$ is of finite presentation. We denote $\mathcal{C}\!oh_{X/B}$ the category whose objects are triples $(T, g, \mathcal{F})$ where
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$T$ is a scheme over $S$,
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$g : T \to B$ is a morphism over $S$, and setting $X_T = T \times_{g, B} X$
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$\mathcal{F}$ is a quasi-coherent $\mathcal{O}_{X_T}$-module of finite presentation, flat over $T$, with support proper over $T$.
A morphism $(T, g, \mathcal{F}) \to (T', g', \mathcal{F}')$ is given by a pair $(h, \varphi)$ where
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$h : T \to T'$ is a morphism of schemes over $B$ (i.e., $g' \circ h = g$), and
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$\varphi : (h')^*\mathcal{F}' \to \mathcal{F}$ is an isomorphism of $\mathcal{O}_{X_T}$-modules where $h' : X_T \to X_{T'}$ is the base change of $h$.
Remark. Base change of the polarized moduli stack
Let $B$ be an algebraic space over $\operatorname{Spec}(\mathbf{Z})$. Let $B\textit{-Polarized}$ be the category consisting of triples $(X \to S, \mathcal{L}, h : S \to B)$ where $(X \to S, \mathcal{L})$ is an object of $\mathcal{P}\!ol$ and $h : S \to B$ is a morphism. A morphism $(X' \to S', \mathcal{L}', h') \to (X \to S, \mathcal{L}, h)$ in $B\textit{-Polarized}$ is a morphism $(f, g, \varphi)$ in $\mathcal{P}\!ol$ such that $h \circ g = h'$. In this situation the diagram $$\begin{gathered}\begin{matrix}B\textit{-Polarized} & \mathcal{P}\!ol \\ (\mathrm{Sch}/B)_{fppf} & \mathrm{Sch}_{fppf}\end{matrix} \\[6pt] \begin{aligned}B\textit{-Polarized} & \longrightarrow \mathcal{P}\!ol \\ B\textit{-Polarized} & \longrightarrow (\mathrm{Sch}/B)_{fppf} \\ \mathcal{P}\!ol & \longrightarrow \mathrm{Sch}_{fppf} \\ (\mathrm{Sch}/B)_{fppf} & \longrightarrow \mathrm{Sch}_{fppf}\end{aligned}\end{gathered}$$ is $2$-fibre product square. This trivial remark will occasionally be useful to deduce results from the absolute case $\mathcal{P}\!ol$ to the case of families over a given base algebraic space.
Remark. Base change of the curve-space stack
Let $B$ be an algebraic space over $\operatorname{Spec}(\mathbf{Z})$. Let $B\text{-}\mathcal{C}\!urves$ be the category consisting of pairs $(X \to S, h : S \to B)$ where $X \to S$ is an object of $\mathcal{C}\!urves$ and $h : S \to B$ is a morphism. A morphism $(X' \to S', h') \to (X \to S, h)$ in $B\text{-}\mathcal{C}\!urves$ is a morphism $(f, g)$ in $\mathcal{C}\!urves$ such that $h \circ g = h'$. In this situation the diagram $$\begin{gathered}\begin{matrix}B\text{-}\mathcal{C}\!urves & \mathcal{C}\!urves \\ (\mathrm{Sch}/B)_{fppf} & \mathrm{Sch}_{fppf}\end{matrix} \\[6pt] \begin{aligned}B\text{-}\mathcal{C}\!urves & \longrightarrow \mathcal{C}\!urves \\ B\text{-}\mathcal{C}\!urves & \longrightarrow (\mathrm{Sch}/B)_{fppf} \\ \mathcal{C}\!urves & \longrightarrow \mathrm{Sch}_{fppf} \\ (\mathrm{Sch}/B)_{fppf} & \longrightarrow \mathrm{Sch}_{fppf}\end{aligned}\end{gathered}$$ is $2$-fibre product square. This trivial remark will occasionally be useful to deduce results from the absolute case $\mathcal{C}\!urves$ to the case of families of curves over a given base algebraic space.
Lemma. The graph locus in the Hilbert functor
Assumption and notation as in Lemma The geometric construction (uncovered prerequisite). The transformation $\mathit{Mor}_B(Z, X) \longrightarrow \operatorname{Hilb}_{Z \times_B X/B}$ is representable by open immersions.
Proof. Let $T$ be a scheme over $B$ and let $Y \subset (Z \times_B X)_T$ be an element of $\operatorname{Hilb}_{Z \times_B X/B}(T)$. Then we see that $Y$ is the graph of a morphism $Z_T \to X_T$ over $T$ if and only if $k = \text{pr}_1|_Y : Y \to Z_T$ is an isomorphism. By More on Morphisms of Spaces, Lemma The geometric construction (uncovered prerequisite) there exists an open subscheme $V \subset T$ such that for any morphism of schemes $T' \to T$ we have $k_{T'} : Y_{T'} \to Z_{T'}$ is an isomorphism if and only if $T' \to T$ factors through $V$. This proves the lemma. $\square$
Proposition. Representability of the Hilbert functor
Let $S$ be a scheme. Let $f : X \to B$ be a morphism of algebraic spaces over $S$. If $f$ is of finite presentation and separated, then $\operatorname{Hilb}_{X/B}$ is an algebraic space locally of finite presentation over $B$.
Proof. Immediate consequence of Lemma The geometric construction (uncovered prerequisite) and Proposition The geometric construction (uncovered prerequisite). $\square$
Proposition. Representability of the Picard functor
Let $S$ be a scheme. Let $f : X \to B$ be a morphism of algebraic spaces over $S$. If $f$ is flat, of finite presentation, and proper, then $\mathcal{P}\!ic_{X/B}$ is an algebraic stack.
Proof. Immediate consequence of Lemma Line bundles and ampleness (uncovered prerequisite), Algebraic Stacks, Lemma The geometric construction (uncovered prerequisite) and either Theorem Coherent sheaves (uncovered prerequisite) or Theorem Coherent sheaves (uncovered prerequisite) $\square$
Geometric support constructions
Lemma. Descent of proper morphisms and finite algebras
The property $\mathcal{P}(f) =$"$f$ is of finite type" is fpqc local on the base.
Proof. Combine Lemmas Descent of proper morphisms and Descent of proper morphisms and finite algebras. $\square$
Lemma. Descent of finite presentation and proper morphisms
The property $\mathcal{P}(f) =$"$f$ is of finite presentation" is fpqc local on the base.
Proof. Combine Lemmas Descent of proper morphisms, Descent of proper morphisms and diagonals and separation and Descent of finite presentation and proper morphisms. $\square$
Lemma. Descent of flatness and proper morphisms
The property $\mathcal{P}(f) =$"$f$ is flat" is fpqc local on the base.
Proof. We will use Lemma Descent of proper morphisms to prove this. Assumptions (1) and (2) of that lemma follow from Morphisms of Spaces, Lemma Flatness and local algebra. Let $Z' \to Z$ be a surjective flat morphism of affine schemes over $S$. Let $f : X \to Z$ be a morphism of algebraic spaces, and assume that the base change $f' : Z' \times_Z X \to Z'$ is flat. We have to show that $f$ is flat. Let $U$ be a scheme and let $U \to X$ be surjective and étale. By Morphisms of Spaces, Lemma Flatness and local algebra again, it is enough to show that $U \to Z$ is flat. Since $f'$ is flat, and since $Z' \times_Z U$ is a scheme étale over $Z' \times_Z X$ we conclude (by the same lemma again) that $Z' \times_Z U \to Z'$ is flat. As $\{Z' \to Z\}$ is an fpqc covering we conclude that $U \to Z$ is flat by Descent, Lemma Descent of flatness and proper morphisms as desired. $\square$
Lemma. Descent of proper morphisms
The property $\mathcal{P}(f) =$"$f$ is proper" is fpqc local on the base.
Proof. The lemma follows by combining Lemmas Descent of proper morphisms, Descent of proper morphisms and diagonals and separation and Descent of proper morphisms and finite algebras. $\square$
Proposition. Quasi-coherent complexes and coherent sheaves
Let $S$ be a scheme. Let $\{X_i \to X\}$ be an fpqc covering of algebraic spaces over $S$, see Topologies on Spaces, Definition The geometric construction (uncovered prerequisite). Any descent datum on quasi-coherent sheaves for $\{X_i \to X\}$ is effective. Moreover, the functor from the category of quasi-coherent $\mathcal{O}_X$-modules to the category of descent data with respect to $\{X_i \to X\}$ is fully faithful.
Proof. This is more or less a formal consequence of the corresponding result for schemes, see Descent, Proposition Quasi-coherent complexes and coherent sheaves. Here is a strategy for a proof:
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The fact that $\{X_i \to X\}$ is a refinement of the trivial covering $\{X \to X\}$ gives, via Lemma The geometric construction, a functor $\mathrm{QCoh}(\mathcal{O}_X) \to DD(\{X_i \to X\})$ from the category of quasi-coherent $\mathcal{O}_X$-modules to the category of descent data for the given family.
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In order to prove the proposition we will construct a quasi-inverse functor $back : DD(\{X_i \to X\}) \to \mathrm{QCoh}(\mathcal{O}_X)$.
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Applying again Lemma The geometric construction we see that there is a functor $DD(\{X_i \to X\}) \to DD(\{T_j \to X\})$ if $\{T_j \to X\}$ is a refinement of the given family. Hence in order to construct the functor $back$ we may assume that each $X_i$ is a scheme, see Topologies on Spaces, Lemma The geometric construction (uncovered prerequisite). This reduces us to the case where all the $X_i$ are schemes.
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A quasi-coherent sheaf on $X$ is by definition a quasi-coherent $\mathcal{O}_X$-module on $X_\mathrm{\acute{e}tale}$. Now for any $U \in \operatorname{Ob}(X_\mathrm{\acute{e}tale})$ we get an fppf covering $\{U_i \times_X X_i \to U\}$ by schemes and a morphism $g : \{U_i \times_X X_i \to U\} \to \{X_i \to X\}$ of coverings lying over $U \to X$. Given a descent datum $\xi = (\mathcal{F}_i, \varphi_{ij})$ we obtain a quasi-coherent $\mathcal{O}_U$-module $\mathcal{F}_{\xi, U}$ corresponding to the pullback $g^*\xi$ of Lemma The geometric construction to the covering of $U$ and using effectivity for fppf covering of schemes, see Descent, Proposition Quasi-coherent complexes and coherent sheaves.
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Check that $\xi \mapsto \mathcal{F}_{\xi, U}$ is functorial in $\xi$. Omitted.
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Check that $\xi \mapsto \mathcal{F}_{\xi, U}$ is compatible with morphisms $U \to U'$ of the site $X_\mathrm{\acute{e}tale}$, so that the system of sheaves $\mathcal{F}_{\xi, U}$ corresponds to a quasi-coherent $\mathcal{F}_\xi$ on $X_\mathrm{\acute{e}tale}$, see Properties of Spaces, Lemma Criteria for étale morphisms and quasi-coherent complexes. Details omitted.
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Check that $back : \xi \mapsto \mathcal{F}_\xi$ is quasi-inverse to the functor constructed in (1). Omitted.
This finishes the proof. $\square$
Lemma. Descent of proper morphisms and line bundles and ampleness
Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Let $\{g_i : Y_i \to Y\}_{i \in I}$ be an fpqc covering. Let $f_i : X_i \to Y_i$ be the base change of $f$ and let $\mathcal{L}_i$ be the pullback of $\mathcal{L}$ to $X_i$. The following are equivalent
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$\mathcal{L}$ is ample on $X/Y$, and
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$\mathcal{L}_i$ is ample on $X_i/Y_i$ for every $i \in I$.
Proof. The implication (1) $\Rightarrow$ (2) follows from Divisors on Spaces, Lemma Base change for line bundles and ampleness. Assume (2). To check $\mathcal{L}$ is ample on $X/Y$ we may work étale locally on $Y$, see Divisors on Spaces, Lemma Line bundles, ampleness and local algebra. Thus we may assume that $Y$ is a scheme and then we may in turn assume each $Y_i$ is a scheme too, see Topologies on Spaces, Lemma The geometric construction (uncovered prerequisite). In other words, we may assume that $\{Y_i \to Y\}$ is an fpqc covering of schemes.
By Divisors on Spaces, Lemma Proper morphisms and line bundles and ampleness we see that $X_i \to Y_i$ is representable (i.e., $X_i$ is a scheme), quasi-compact, and separated. Hence $f$ is quasi-compact and separated by Lemmas Descent of proper morphisms and Descent of proper morphisms and diagonals and separation. This means that $\mathcal{A} = \bigoplus_{d \geq 0} f_*\mathcal{L}^{\otimes d}$ is a quasi-coherent graded $\mathcal{O}_Y$-algebra (Morphisms of Spaces, Lemma Direct images and morphisms of algebraic spaces). Moreover, the formation of $\mathcal{A}$ commutes with flat base change by Cohomology of Spaces, Lemma Base change for sheaf cohomology and flatness. In particular, if we set $\mathcal{A}_i = \bigoplus_{d \geq 0} f_{i, *}\mathcal{L}_i^{\otimes d}$ then we have $\mathcal{A}_i = g_i^*\mathcal{A}$. It follows that the natural maps $\psi_d : f^*\mathcal{A}_d \to \mathcal{L}^{\otimes d}$ of $\mathcal{O}_X$ pullback to give the natural maps $\psi_{i, d} : f_i^*(\mathcal{A}_i)_d \to \mathcal{L}_i^{\otimes d}$ of $\mathcal{O}_{X_i}$-modules. Since $\mathcal{L}_i$ is ample on $X_i/Y_i$ we see that for any point $x_i \in X_i$, there exists a $d \geq 1$ such that $f_i^*(\mathcal{A}_i)_d \to \mathcal{L}_i^{\otimes d}$ is surjective on stalks at $x_i$. This follows either directly from the definition of a relatively ample module or from Morphisms, Lemma Criteria for line bundles and ampleness (uncovered prerequisite). If $x \in |X|$, then we can choose an $i$ and an $x_i \in X_i$ mapping to $x$. Since $\mathcal{O}_{X, \overline{x}} \to \mathcal{O}_{X_i, \overline{x}_i}$ is flat hence faithfully flat, we conclude that for every $x \in |X|$ there exists a $d \geq 1$ such that $f^*\mathcal{A}_d \to \mathcal{L}^{\otimes d}$ is surjective on stalks at $x$. This implies that the open subset $U(\psi) \subset X$ of Divisors on Spaces, Lemma Line bundles and ampleness corresponding to the map $\psi : f^*\mathcal{A} \to \bigoplus_{d \geq 0} \mathcal{L}^{\otimes d}$ of graded $\mathcal{O}_X$-algebras is equal to $X$. Consider the corresponding morphism $$r_{\mathcal{L}, \psi} : X \longrightarrow \underline{\text{Proj}}_Y(\mathcal{A})$$ It is clear from the above that the base change of $r_{\mathcal{L}, \psi}$ to $Y_i$ is the morphism $r_{\mathcal{L}_i, \psi_i}$ which is an open immersion by Morphisms, Lemma Criteria for line bundles and ampleness (uncovered prerequisite). Hence $r_{\mathcal{L}, \psi}$ is an open immersion by Lemma Descent of proper morphisms and diagonals and separation. Hence $X$ is a scheme and we conclude $\mathcal{L}$ is ample on $X/Y$ by Morphisms, Lemma Criteria for line bundles and ampleness (uncovered prerequisite). $\square$
Lemma. Descent of proper morphisms
Let $S$ be a scheme. The property $\mathcal{P}(f) =$"$f$ is quasi-compact" is fpqc local on the base on algebraic spaces over $S$.
Proof. We will use Lemma Descent of proper morphisms to prove this. Assumptions (1) and (2) of that lemma follow from Morphisms of Spaces, Lemma Local algebra (uncovered prerequisite). Let $Z' \to Z$ be a surjective flat morphism of affine schemes over $S$. Let $f : X \to Z$ be a morphism of algebraic spaces, and assume that the base change $f' : Z' \times_Z X \to Z'$ is quasi-compact. We have to show that $f$ is quasi-compact. To see this, using Morphisms of Spaces, Lemma Local algebra (uncovered prerequisite) again, it is enough to show that for every affine scheme $Y$ and morphism $Y \to Z$ the fibre product $Y \times_Z X$ is quasi-compact. Here is a picture:
$$\begin{gathered}\begin{matrix}Y \times_Z Z' \times_Z X & \phantom{X} & Z' \times_Z X \\ \phantom{X} & Y \times_Z X & \phantom{X} & X \\ Y \times_Z Z' & \phantom{X} & Z' \\ \phantom{X} & Y & \phantom{X} & Z\end{matrix} \\[6pt] \begin{aligned}Y \times_Z Z' \times_Z X & \longrightarrow Y \times_Z Z' \\ Y \times_Z Z' \times_Z X & \longrightarrow Z' \times_Z X \\ Y \times_Z Z' \times_Z X & \longrightarrow Y \times_Z X \\ Z' \times_Z X & \xrightarrow{f'} Z' \\ Z' \times_Z X & \longrightarrow X \\ Y \times_Z X & \longrightarrow Y \\ Y \times_Z X & \longrightarrow X \\ X & \xrightarrow{f} Z \\ Y \times_Z Z' & \longrightarrow Z' \\ Y \times_Z Z' & \longrightarrow Y \\ Z' & \longrightarrow Z \\ Y & \longrightarrow Z\end{aligned}\end{gathered}$$ Note that all squares are cartesian and the bottom square consists of affine schemes. The assumption that $f'$ is quasi-compact combined with the fact that $Y \times_Z Z'$ is affine implies that $Y \times_Z Z' \times_Z X$ is quasi-compact. Since $$Y \times_Z Z' \times_Z X \longrightarrow Y \times_Z X$$ is surjective as a base change of $Z' \to Z$ we conclude that $Y \times_Z X$ is quasi-compact, see Morphisms of Spaces, Lemma Derived Hom and Ext (uncovered prerequisite). This finishes the proof. $\square$
Lemma. Descent of proper morphisms and finite algebras
The property $\mathcal{P}(f) =$"$f$ is locally of finite type" is fpqc local on the base.
Proof. We will use Lemma Descent of proper morphisms to prove this. Assumptions (1) and (2) of that lemma follow from Morphisms of Spaces, Lemma Finite algebras and local algebra (uncovered prerequisite). Let $Z' \to Z$ be a surjective flat morphism of affine schemes over $S$. Let $f : X \to Z$ be a morphism of algebraic spaces, and assume that the base change $f' : Z' \times_Z X \to Z'$ is locally of finite type. We have to show that $f$ is locally of finite type. Let $U$ be a scheme and let $U \to X$ be surjective and étale. By Morphisms of Spaces, Lemma Finite algebras and local algebra (uncovered prerequisite) again, it is enough to show that $U \to Z$ is locally of finite type. Since $f'$ is locally of finite type, and since $Z' \times_Z U$ is a scheme étale over $Z' \times_Z X$ we conclude (by the same lemma again) that $Z' \times_Z U \to Z'$ is locally of finite type. As $\{Z' \to Z\}$ is an fpqc covering we conclude that $U \to Z$ is locally of finite type by Descent, Lemma Descent of proper morphisms and finite algebras (uncovered prerequisite) as desired. $\square$
Lemma. Descent of proper morphisms and diagonals and separation
Let $S$ be a scheme. The property $\mathcal{P}(f) =$"$f$ is quasi-separated" is fpqc local on the base on algebraic spaces over $S$.
Proof. A base change of a quasi-separated morphism is quasi-separated, see Morphisms of Spaces, Lemma Base change for diagonals and separation. Hence the direct implication in Definition Proper morphisms and local algebra.
Let $\{Y_i \to Y\}_{i \in I}$ be an fpqc covering of algebraic spaces over $S$. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume each base change $X_i := Y_i \times_Y X \to Y_i$ is quasi-separated. This means that each of the morphisms $$\Delta_i : X_i \longrightarrow X_i \times_{Y_i} X_i = Y_i \times_Y (X \times_Y X)$$ is quasi-compact. The base change of a fpqc covering is an fpqc covering, see Topologies on Spaces, Lemma The geometric construction (uncovered prerequisite) hence $\{Y_i \times_Y (X \times_Y X) \to X \times_Y X\}$ is an fpqc covering of algebraic spaces. Moreover, each $\Delta_i$ is the base change of the morphism $\Delta : X \to X \times_Y X$. Hence it follows from Lemma Descent of proper morphisms that $\Delta$ is quasi-compact, i.e., $f$ is quasi-separated. $\square$
Lemma. Descent of finite presentation and proper morphisms
The property $\mathcal{P}(f) =$"$f$ is locally of finite presentation" is fpqc local on the base.
Proof. We will use Lemma Descent of proper morphisms to prove this. Assumptions (1) and (2) of that lemma follow from Morphisms of Spaces, Lemma Finite presentation and finite algebras (uncovered prerequisite). Let $Z' \to Z$ be a surjective flat morphism of affine schemes over $S$. Let $f : X \to Z$ be a morphism of algebraic spaces, and assume that the base change $f' : Z' \times_Z X \to Z'$ is locally of finite presentation. We have to show that $f$ is locally of finite presentation. Let $U$ be a scheme and let $U \to X$ be surjective and étale. By Morphisms of Spaces, Lemma Finite presentation and finite algebras (uncovered prerequisite) again, it is enough to show that $U \to Z$ is locally of finite presentation. Since $f'$ is locally of finite presentation, and since $Z' \times_Z U$ is a scheme étale over $Z' \times_Z X$ we conclude (by the same lemma again) that $Z' \times_Z U \to Z'$ is locally of finite presentation. As $\{Z' \to Z\}$ is an fpqc covering we conclude that $U \to Z$ is locally of finite presentation by Descent, Lemma Descent of finite presentation and proper morphisms as desired. $\square$
Lemma. Descent of proper morphisms
Let $S$ be a scheme. Let $\mathcal{P}$ be a property of morphisms of algebraic spaces over $S$. Assume
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if $X_i \to Y_i$, $i = 1, 2$ have property $\mathcal{P}$ so does $X_1 \amalg X_2 \to Y_1 \amalg Y_2$,
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a morphism of algebraic spaces $f : X \to Y$ has property $\mathcal{P}$ if and only if for every affine scheme $Z$ and morphism $Z \to Y$ the base change $Z \times_Y X \to Z$ of $f$ has property $\mathcal{P}$, and
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for any surjective flat morphism of affine schemes $Z' \to Z$ over $S$ and a morphism $f : X \to Z$ from an algebraic space to $Z$ we have $$f' : Z' \times_Z X \to Z'\text{ has }\mathcal{P} \Rightarrow f\text{ has }\mathcal{P}.$$
Then $\mathcal{P}$ is fpqc local on the base.
Proof. If $\mathcal{P}$ has property (2), then it is automatically stable under any base change. Hence the direct implication in Definition Proper morphisms and local algebra.
Let $\{Y_i \to Y\}_{i \in I}$ be an fpqc covering of algebraic spaces over $S$. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume each base change $f_i : Y_i \times_Y X \to Y_i$ has property $\mathcal{P}$. Our goal is to show that $f$ has $\mathcal{P}$. Let $Z$ be an affine scheme, and let $Z \to Y$ be a morphism. By (2) it suffices to show that the morphism of algebraic spaces $Z \times_Y X \to Z$ has $\mathcal{P}$. Since $\{Y_i \to Y\}_{i \in I}$ is an fpqc covering we know there exists a standard fpqc covering $\{Z_j \to Z\}_{j = 1, \ldots , n}$ and morphisms $Z_j \to Y_{i_j}$ over $Y$ for suitable indices $i_j \in I$. Since $f_{i_j}$ has $\mathcal{P}$ we see that $$Z_j \times_Y X
Z_j \times_{Y_{i_j}} (Y_{i_j} \times_Y X) \longrightarrow Z_j$$ has $\mathcal{P}$ as a base change of $f_{i_j}$ (see first remark of the proof). Set $Z' = \coprod_{j = 1, \ldots, n} Z_j$, so that $Z' \to Z$ is a flat and surjective morphism of affine schemes over $S$. By (1) we conclude that $Z' \times_Y X \to Z'$ has property $\mathcal{P}$. Since this is the base change of the morphism $Z \times_Y X \to Z$ by the morphism $Z' \to Z$ we conclude that $Z \times_Y X \to Z$ has property $\mathcal{P}$ as desired. $\square$
Lemma. Descent of proper morphisms
Let $S$ be a scheme. The property $\mathcal{P}(f) =$"$f$ is universally closed" is fpqc local on the base on algebraic spaces over $S$.
Proof. We will use Lemma Descent of proper morphisms to prove this. Assumptions (1) and (2) of that lemma follow from Morphisms of Spaces, Lemma Local algebra (uncovered prerequisite). Let $Z' \to Z$ be a surjective flat morphism of affine schemes over $S$. Let $f : X \to Z$ be a morphism of algebraic spaces, and assume that the base change $f' : Z' \times_Z X \to Z'$ is universally closed. We have to show that $f$ is universally closed. To see this, using Morphisms of Spaces, Lemma Local algebra (uncovered prerequisite) again, it is enough to show that for every affine scheme $Y$ and morphism $Y \to Z$ the map $|Y \times_Z X| \to |Y|$ is closed. Consider the cube (the displayed identity). The assumption that $f'$ is universally closed implies that $|Y \times_Z Z' \times_Z X| \to |Y \times_Z Z'|$ is closed. As $Y \times_Z Z' \to Y$ is quasi-compact, surjective, and flat as a base change of $Z' \to Z$ we see the map $|Y \times_Z Z'| \to |Y|$ is submersive, see Morphisms, Lemma The geometric construction (uncovered prerequisite). Moreover the map $$|Y \times_Z Z' \times_Z X| \longrightarrow |Y \times_Z Z'| \times_{|Y|} |Y \times_Z X|$$ is surjective, see Properties of Spaces, Lemma Étale geometry of algebraic spaces. It follows by elementary topology that $|Y \times_Z X| \to |Y|$ is closed. $\square$
Lemma. Descent of proper morphisms and diagonals and separation
The property $\mathcal{P}(f) =$"$f$ is separated" is fpqc local on the base.
Proof. A base change of a separated morphism is separated, see Morphisms of Spaces, Lemma Base change for diagonals and separation. Hence the direct implication in Definition Proper morphisms and local algebra.
Let $\{Y_i \to Y\}_{i \in I}$ be an fpqc covering of algebraic spaces over $S$. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. Assume each base change $X_i := Y_i \times_Y X \to Y_i$ is separated. This means that each of the morphisms $$\Delta_i : X_i \longrightarrow X_i \times_{Y_i} X_i = Y_i \times_Y (X \times_Y X)$$ is a closed immersion. The base change of a fpqc covering is an fpqc covering, see Topologies on Spaces, Lemma The geometric construction (uncovered prerequisite) hence $\{Y_i \times_Y (X \times_Y X) \to X \times_Y X\}$ is an fpqc covering of algebraic spaces. Moreover, each $\Delta_i$ is the base change of the morphism $\Delta : X \to X \times_Y X$. Hence it follows from Lemma Descent of proper morphisms and diagonals and separation (uncovered prerequisite) that $\Delta$ is a closed immersion, i.e., $f$ is separated. $\square$
Lemma. The geometric construction
Let $S$ be a scheme. Let $\mathcal{U} = \{U_i \to U\}_{i \in I}$ and $\mathcal{V} = \{V_j \to V\}_{j \in J}$ be families of morphisms of algebraic spaces over $S$ with fixed targets. Let $(g, \alpha : I \to J, (g_i)) : \mathcal{U} \to \mathcal{V}$ be a morphism of families of maps with fixed target, see Sites, Definition The geometric construction. Let $(\mathcal{F}_j, \varphi_{jj'})$ be a descent datum for quasi-coherent sheaves with respect to the family $\{V_j \to V\}_{j \in J}$. Then
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The system $$\left(g_i^*\mathcal{F}_{\alpha(i)}, (g_i \times g_{i'})^*\varphi_{\alpha(i)\alpha(i')}\right)$$ is a descent datum with respect to the family $\{U_i \to U\}_{i \in I}$.
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This construction is functorial in the descent datum $(\mathcal{F}_j, \varphi_{jj'})$.
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Given a second morphism $(g', \alpha' : I \to J, (g'_i))$ of families of maps with fixed target with $g = g'$ there exists a functorial isomorphism of descent data $$(g_i^*\mathcal{F}_{\alpha(i)}, (g_i \times g_{i'})^*\varphi_{\alpha(i)\alpha(i')}) \cong ((g'_i)^*\mathcal{F}_{\alpha'(i)}, (g'_i \times g'_{i'})^*\varphi_{\alpha'(i)\alpha'(i')}).$$
Proof. Omitted. Hint: The maps $g_i^*\mathcal{F}_{\alpha(i)} \to (g'_i)^*\mathcal{F}_{\alpha'(i)}$ which give the isomorphism of descent data in part (3) are the pullbacks of the maps $\varphi_{\alpha(i)\alpha'(i)}$ by the morphisms $(g_i, g'_i) : U_i \to V_{\alpha(i)} \times_V V_{\alpha'(i)}$. $\square$
Lemma. Descent of proper morphisms and diagonals and separation
The property $\mathcal{P}(f) =$"$f$ is an open immersion" is fpqc local on the base.
Proof. We will use Lemma Descent of proper morphisms to prove this. Assumptions (1) and (2) of that lemma follow from Morphisms of Spaces, Lemma Diagonals, separation and local algebra. Consider a cartesian diagram $$\begin{gathered}\begin{matrix}X' & X \\ Z' & Z\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow X \\ X' & \longrightarrow Z' \\ X & \longrightarrow Z \\ Z' & \longrightarrow Z\end{aligned}\end{gathered}$$ of algebraic spaces over $S$ where $Z' \to Z$ is a surjective flat morphism of affine schemes, and $X' \to Z'$ is an open immersion. We have to show that $X \to Z$ is an open immersion. Note that $|X'| \subset |Z'|$ corresponds to an open subscheme $U' \subset Z'$ (isomorphic to $X'$) with the property that $\text{pr}_0^{-1}(U') = \text{pr}_1^{-1}(U')$ as open subschemes of $Z' \times_Z Z'$. Hence there exists an open subscheme $U \subset Z$ such that $X' = (Z' \to Z)^{-1}(U)$, see Descent, Lemma The geometric construction (uncovered prerequisite). By Properties of Spaces, Proposition Sheaves on ringed sites (uncovered prerequisite) we see that $X$ satisfies the sheaf condition for the fpqc topology. Now we have the fpqc covering $\mathcal{U} = \{U' \to U\}$ and the element $U' \to X' \to X \in \check{H}^0(\mathcal{U}, X)$. By the sheaf condition we obtain a morphism $U \to X$ such that $$\begin{gathered}\begin{matrix}U' & U \\ X' & X \\ Z' & Z\end{matrix} \\[6pt] \begin{aligned}U' & \longrightarrow U \\ U' & \xrightarrow{\cong} X' \\ U' & \xrightarrow{3} Z' \\ U & \longrightarrow X \\ U & \xrightarrow{3} Z \\ X' & \longrightarrow X \\ X' & \longrightarrow Z' \\ X & \longrightarrow Z \\ Z' & \longrightarrow Z\end{aligned}\end{gathered}$$ is commutative. On the other hand, we know that for any scheme $T$ over $S$ and $T$-valued point $T \to X$ the composition $T \to X \to Z$ is a morphism such that $Z' \times_Z T \to Z'$ factors through $U'$. Clearly this means that $T \to Z$ factors through $U$. In other words the map of sheaves $U \to X$ is bijective and we win. $\square$
Lemma. Line bundles and ampleness
Let $S$ be a scheme. Let $f : X \to Y$ be a proper morphism of algebraic spaces over $S$. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. There exists an open subspace $V \subset Y$ characterized by the following property: A morphism $Y' \to Y$ of algebraic spaces factors through $V$ if and only if the pullback $\mathcal{L}'$ of $\mathcal{L}$ to $X' = Y' \times_Y X$ is ample on $X'/Y'$ (as in Divisors on Spaces, Definition Line bundles and ampleness).
Proof. Suppose that the lemma holds whenever $Y$ is a scheme. Let $U$ be a scheme and let $U \to Y$ be a surjective étale morphism. Let $R = U \times_Y U$ with projections $t, s : R \to U$. Denote $X_U = U \times_Y X$ and $\mathcal{L}_U$ the pullback. Then we get an open subscheme $V' \subset U$ as in the lemma for $(X_U \to U, \mathcal{L}_U)$. By the functorial characterization we see that $s^{-1}(V') = t^{-1}(V')$. Thus there is an open subspace $V \subset Y$ such that $V'$ is the inverse image of $V$ in $U$. In particular $V' \to V$ is surjective étale and we conclude that $\mathcal{L}_V$ is ample on $X_V/V$ (Divisors on Spaces, Lemma Line bundles, ampleness and local algebra). Now, if $Y' \to Y$ is a morphism such that $\mathcal{L}'$ is ample on $X'/Y'$, then $U \times_Y Y' \to Y'$ must factor through $V'$ and we conclude that $Y' \to Y$ factors through $V$. Hence $V \subset Y$ is as in the statement of the lemma. In this way we reduce to the case dealt with in the next paragraph.
Assume $Y$ is a scheme. Since the question is local on $Y$ we may assume $Y$ is an affine scheme. We will show the following:
- If $\operatorname{Spec}(k) \to Y$ is a morphism such that $\mathcal{L}_k$ is ample on $X_k/k$, then there is an open neighbourhood $V \subset Y$ of the image of $\operatorname{Spec}(k) \to Y$ such that $\mathcal{L}_V$ is ample on $X_V/V$.
It is clear that (A) implies the truth of the lemma.
Let $X \to Y$, $\mathcal{L}$, $\operatorname{Spec}(k) \to Y$ be as in (A). By Lemma Descent of proper morphisms and line bundles and ampleness we may assume that $k = \kappa(y)$ is the residue field of a point $y$ of $Y$.
As $Y$ is affine we can find a directed set $I$ and an inverse system of morphisms $X_i \to Y_i$ of algebraic spaces with $Y_i$ of finite presentation over $\mathbf{Z}$, with affine transition morphisms $X_i \to X_{i'}$ and $Y_i \to Y_{i'}$, with $X_i \to Y_i$ proper and of finite presentation, and such that $X \to Y = \varprojlim (X_i \to Y_i)$. See Limits of Spaces, Lemma Finite presentation and proper morphisms (uncovered prerequisite). After shrinking $I$ we may assume $Y_i$ is an (affine) scheme for all $i$, see Limits of Spaces, Lemma Filtered limits and affine neighbourhoods (uncovered prerequisite). After shrinking $I$ we can assume we have a compatible system of invertible $\mathcal{O}_{X_i}$-modules $\mathcal{L}_i$ pulling back to $\mathcal{L}$, see Limits of Spaces, Lemma Descent of finite locally free and invertible modules. Let $y_i \in Y_i$ be the image of $y$. Then $\kappa(y) = \mathop{\operatorname{colim}} \kappa(y_i)$. Hence $X_y = \varprojlim X_{i, y_i}$ and after shrinking $I$ we may assume $X_{i, y_i}$ is a scheme for all $i$, see Limits of Spaces, Lemma Filtered limits and descent of algebraic spaces. Hence for some $i$ we have $\mathcal{L}_{i, y_i}$ is ample on $X_{i, y_i}$ by Limits, Lemma Filtered limits and line bundles and ampleness. By Divisors on Spaces, Lemma Line bundles and ampleness (uncovered prerequisite) we find an open neighbourhood $V_i \subset Y_i$ of $y_i$ such that $\mathcal{L}_i$ restricted to $f_i^{-1}(V_i)$ is ample relative to $V_i$. Letting $V \subset Y$ be the inverse image of $V_i$ finishes the proof (hints: use Morphisms, Lemma Base change for line bundles and ampleness (uncovered prerequisite) and the fact that $X \to Y \times_{Y_i} X_i$ is affine and the fact that the pullback of an ample invertible sheaf by an affine morphism is ample by Morphisms, Lemma Pullback of line bundles, ampleness and tensor products and direct sums (uncovered prerequisite)). $\square$
Versality and algebraicity criteria
Definition. Limit-preserving deformation groupoids
Let $S$ be a scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. We say $\mathcal{X}$ is limit preserving if for every affine scheme $T$ over $S$ which is a limit $T = \varprojlim T_i$ of a directed inverse system of affine schemes $T_i$ over $S$, we have an equivalence $$\mathop{\operatorname{colim}} \mathcal{X}_{T_i} \longrightarrow \mathcal{X}_T$$ of fibre categories.
Lemma. Lifting properties under infinitesimal patching
Let $S$ be a scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume $\mathcal{X}$ satisfies condition (RS*). Let $A$ be an $S$-algebra and let $x$ be an object of $\mathcal{X}$ over $\operatorname{Spec}(A)$.
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There exists an $A$-linear functor $\text{Inf}_x : \text{Mod}_A \to \text{Mod}_A$ such that given a deformation situation $(x, A' \to A)$ and a lift $x'$ there is an isomorphism $\text{Inf}_x(I) \to \text{Inf}(x'/x)$ where $I = \operatorname{Ker}(A' \to A)$.
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There exists an $A$-linear functor $T_x : \text{Mod}_A \to \text{Mod}_A$ such that
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given $M$ in $\text{Mod}_A$ there is a bijection $T_x(M) \to \text{Lift}(x, A[M])$,
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given a deformation situation $(x, A' \to A)$ there is an action $$T_x(I) \times \text{Lift}(x, A') \to \text{Lift}(x, A')$$ where $I = \operatorname{Ker}(A' \to A)$. It is simply transitive if $\text{Lift}(x, A') \not = \emptyset$.
-
Proof. We define $\text{Inf}_x$ as the functor $$\text{Mod}_A \longrightarrow \textit{Sets},\quad M \longrightarrow \text{Inf}(x'_M/x) = \text{Lift}(\text{id}_x, A[M])$$ mapping $M$ to the group of infinitesimal automorphisms of the trivial deformation $x'_M$ of $x$ to $\operatorname{Spec}(A[M])$ or equivalently the group of lifts of $\text{id}_x$ in $\mathit{Aut}_\mathcal{X}(x'_M)$. We define $T_x$ as the functor $$\text{Mod}_A \longrightarrow \textit{Sets},\quad M \longrightarrow \text{Lift}(x, A[M])$$ of isomorphism classes of infinitesimal deformations of $x$ to $\operatorname{Spec}(A[M])$. We apply Formal Deformation Theory, Lemma Linear functors on deformation modules to $\text{Inf}_x$ and $T_x$. This lemma is applicable, since (RS*) tells us that $$\textit{Lift}(x, A[M \times N]) = \textit{Lift}(x, A[M]) \times \textit{Lift}(x, A[N])$$ as categories (and trivial deformations match up too).
Let $(x, A' \to A)$ be a deformation situation. Consider the ring map $g : A' \times_A A' \to A[I]$ defined by the rule $g(a_1, a_2) = \overline{a_1} \oplus a_2 - a_1$. There is an isomorphism $$A' \times_A A' \longrightarrow A' \times_A A[I]$$ given by $(a_1, a_2) \mapsto (a_1, g(a_1, a_2))$. This isomorphism commutes with the projections to $A'$ on the first factor, and hence with the projections to $A$. Thus applying (RS*) twice we find equivalences of categories $$\begin{aligned} \textit{Lift}(x, A') \times \textit{Lift}(x, A') & = \textit{Lift}(x, A' \times_A A') \\ & = \textit{Lift}(x, A' \times_A A[I]) \\ & = \textit{Lift}(x, A') \times \textit{Lift}(x, A[I]) \end{aligned}$$ Using these maps and projection onto the last factor of the last product we see that we obtain "difference maps" $$\text{Inf}(x'/x) \times \text{Inf}(x'/x) \longrightarrow \text{Inf}_x(I) \quad\text{and}\quad \text{Lift}(x, A') \times \text{Lift}(x, A') \longrightarrow T_x(I)$$ These difference maps satisfy the transitivity rule "$(x'_1 - x'_2) + (x'_2 - x'_3) = x'_1 - x'_3$" because $$\begin{gathered}\begin{matrix}A' \times_A A' \times_A A' & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & A[I] \times_A A[I] = A[I \times I] \\ \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & \phantom{X} & A[I]\end{matrix} \\[6pt] \begin{aligned}A' \times_A A' \times_A A' & \xrightarrow{(a_1, a_2, a_3) \mapsto (g(a_1, a_2), g(a_2, a_3))} A[I] \times_A A[I] = A[I \times I] \\ A' \times_A A' \times_A A' & \xrightarrow{(a_1, a_2, a_3) \mapsto g(a_1, a_3)} A[I] \\ A[I] \times_A A[I] = A[I \times I] & \xrightarrow{+} A[I]\end{aligned}\end{gathered}$$ is commutative. Inverting the string of equivalences above we obtain an action which is free and transitive provided $\text{Inf}(x'/x)$, resp. $\text{Lift}(x, A')$ is nonempty. Note that $\text{Inf}(x'/x)$ is always nonempty as it is a group. $\square$
Remark. Comparing deformation categories (Compatibility with previous tangent spaces)
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume $\mathcal{X}$ has (RS*). Let $k$ be a field of finite type over $S$ and let $x_0$ be an object of $\mathcal{X}$ over $\operatorname{Spec}(k)$. Then we have equalities of $k$-vector spaces $$T\mathcal{F}_{\mathcal{X}, k, x_0} = T_{x_0}(k) \quad\text{and}\quad \text{Inf}(\mathcal{F}_{\mathcal{X}, k, x_0}) = \text{Inf}_{x_0}(k)$$ where the spaces on the left hand side of the equality signs are given in (Versality) and (Finite algebras) and the spaces on the right hand side are given by Lemma Lifting properties under infinitesimal patching.
Lemma. Strong effectivity implies openness of versality
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume
-
$\Delta : \mathcal{X} \to \mathcal{X} \times \mathcal{X}$ is representable by algebraic spaces,
-
$\mathcal{X}$ has (RS*),
-
$\mathcal{X}$ is limit preserving,
-
systems $(\xi_n)$ as in Remark Strong formal effectivity where $\operatorname{Ker}(R_m \to R_n)$ is an ideal of square zero for all $m \geq n$ are effective.
Then $\mathcal{X}$ satisfies openness of versality.
Proof. Choose a scheme $U$ locally of finite type over $S$, a finite type point $u_0$ of $U$, and an object $x$ of $\mathcal{X}$ over $U$ such that $x$ is versal at $u_0$. After shrinking $U$ we may assume $U$ is affine and $U$ maps into an affine open $\operatorname{Spec}(\Lambda)$ of $S$. Let $E \subset U$ be the set of finite type points $u$ such that $x$ is not versal at $u$. By Lemma Versality under generalization if $u \in E$ then $u_0$ is not a specialization of $u$. If openness of versality does not hold, then $u_0$ is in the closure $\overline{E}$ of $E$. By Properties, Lemma Scheme geometry we may choose a countable subset $E' \subset E$ with the same closure as $E$. By Properties, Lemma Scheme geometry we may assume there are no specializations among the points of $E'$. Observe that $E'$ has to be (countably) infinite as $u_0$ isn't the specialization of any point of $E'$ as pointed out above. Thus we can write $E' = \{u_1, u_2, u_3, \ldots\}$, there are no specializations among the $u_i$, and $u_0$ is in the closure of $E'$.
Choose $x \to x_1 \to x_2 \to \ldots$ lying over $U \to U_1 \to U_2 \to \ldots$ as in Lemma A sequence of nonversal points accumulating at a versal point. Write $U_n = \operatorname{Spec}(R_n)$ and $U = \operatorname{Spec}(R_0)$. Set $R = \varprojlim R_n$. Observe that $R \to R_0$ is surjective with kernel an ideal of square zero. By assumption (4) we get $\xi$ over $\operatorname{Spec}(R)$ whose base change to $R_n$ is $x_n$. By assumption (3) we get that $\xi$ comes from an object $\xi'$ over $U' = \operatorname{Spec}(R')$ for some finite type $\Lambda$-subalgebra $R' \subset R$. After increasing $R'$ we may and do assume that $R' \to R_0$ is surjective, so that $U \subset U'$ is a first order thickening. Thus we now have $$x \to x_1 \to x_2 \to \ldots \to \xi' \text{ lying over } U \to U_1 \to U_2 \to \ldots \to U'$$ By assumption (1) there is an algebraic space $Z$ over $S$ representing $$(\mathrm{Sch}/U)_{fppf} \times_{x, \mathcal{X}, \xi'} (\mathrm{Sch}/U')_{fppf}$$ see Algebraic Stacks, Lemma Diagonals and separation (uncovered prerequisite). By construction of $2$-fibre products, a $T$-valued point of $Z$ corresponds to a triple $(a, a', \alpha)$ consisting of morphisms $a : T \to U$, $a' : T \to U'$ and a morphism $\alpha : a^*x \to (a')^*\xi'$. We obtain a commutative diagram $$\begin{gathered}\begin{matrix}U \\ \phantom{X} & Z & U' \\ \phantom{X} & U & S\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow Z \\ U & \longrightarrow U \\ U & \longrightarrow U' \\ Z & \xrightarrow{p'} U' \\ Z & \xrightarrow{p} U \\ U' & \longrightarrow S \\ U & \longrightarrow S\end{aligned}\end{gathered}$$ The morphism $i : U \to Z$ comes from the isomorphism $x \to \xi'|_U$. Let $z_0 = i(u_0) \in Z$. By Lemma Base change of a versal object we see that $Z \to U'$ is smooth at $z_0$. After replacing $U$ by an affine open neighbourhood of $u_0$, replacing $U'$ by the corresponding open, and replacing $Z$ by the intersection of the inverse images of these opens by $p$ and $p'$, we reach the situation where $Z \to U'$ is smooth along $i(U)$. Note that this also involves replacing $u_n$ by a subsequence, namely by those indices such that $u_n$ is in the open. Moreover, condition (3) of Lemma A sequence of nonversal points accumulating at a versal point is clearly preserved by shrinking $U$ (all of the schemes $U$, $U_n$, $U'$ have the same underlying topological space). Since $U \to U'$ is a first order thickening of affine schemes, we can choose a morphism $i' : U' \to Z$ such that $p' \circ i' = \text{id}_{U'}$ and whose restriction to $U$ is $i$ (More on Morphisms of Spaces, Lemma Formal smoothness and smooth morphisms). Pulling back the universal morphism $p^*x \to (p')^*\xi'$ by $i'$ we obtain a morphism $$\xi' \to x$$ lying over $p \circ i' : U' \to U$ such that the composition $$x \to \xi' \to x$$ is the identity. Recall that we have $x_1 \to \xi'$ lying over the morphism $U_1 \to U'$. Composing we get a morphism $x_1 \to x$ whose existence contradicts condition (3) of Lemma A sequence of nonversal points accumulating at a versal point. This contradiction finishes the proof. $\square$
Lemma. Representability of a stack diagonal
Let $S$ be a locally Noetherian scheme. Let $p : \mathcal{X} \to (\mathrm{Sch}/S)_{fppf}$ be a category fibred in groupoids. Assume that
-
$\Delta : \mathcal{X} \to \mathcal{X} \times \mathcal{X}$ is representable by algebraic spaces,
-
$\mathcal{X}$ satisfies axioms [-1], [0], [1], [2], [3] (see Section Artin's algebraicity axioms),
-
every formal object of $\mathcal{X}$ is effective,
-
$\mathcal{X}$ satisfies openness of versality, and
-
$\mathcal{O}_{S, s}$ is a G-ring for all finite type points $s$ of $S$.
Then $\mathcal{X}$ is an algebraic stack.
Proof. Lemma A smooth neighbourhood from versality applies to $\mathcal{X}$. Using this we choose, for every finite type field $k$ over $S$ and every isomorphism class of object $x_0 \in \operatorname{Ob}(\mathcal{X}_{\operatorname{Spec}(k)})$, an affine scheme $U_{k, x_0}$ of finite type over $S$ and a smooth morphism $(\mathrm{Sch}/U_{k, x_0})_{fppf} \to \mathcal{X}$ such that there exists a finite type point $u_{k, x_0} \in U_{k, x_0}$ with residue field $k$ such that $x_0$ is the image of $u_{k, x_0}$. Then $$(\mathrm{Sch}/U)_{fppf} \to \mathcal{X}, \quad\text{with}\quad U = \coprod\nolimits_{k, x_0} U_{k, x_0}$$ is smooth[^1]. To finish the proof it suffices to show this map is surjective, see Criteria for Representability, Lemma Étale morphisms (uncovered prerequisite) (this is where we use axiom [0]). By Criteria for Representability, Lemma Proper morphisms (uncovered prerequisite) it suffices to show that $(\mathrm{Sch}/U)_{fppf} \times_\mathcal{X} (\mathrm{Sch}/V)_{fppf} \to (\mathrm{Sch}/V)_{fppf}$ is surjective for those $y : (\mathrm{Sch}/V)_{fppf} \to \mathcal{X}$ where $V$ is an affine scheme locally of finite presentation over $S$. By assumption (1) the fibre product $(\mathrm{Sch}/U)_{fppf} \times_\mathcal{X} (\mathrm{Sch}/V)_{fppf}$ is representable by an algebraic space $W$. Then $W \to V$ is smooth, hence the image is open. Hence it suffices to show that the image of $W \to V$ contains all finite type points of $V$, see Morphisms, Lemma Finite algebras (uncovered prerequisite). Let $v_0 \in V$ be a finite type point. Then $k = \kappa(v_0)$ is a finite type field over $S$. Set $x_0 = y|_{\operatorname{Spec}(k)}$, the pullback of $y$ by $v_0$. Then $(u_{k, x_0}, v_0)$ will give a morphism $\operatorname{Spec}(k) \to W$ whose composition with $W \to V$ is $v_0$ and we win. $\square$
Remark. Strong formal effectivity (Strong effectiveness)
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume we have
-
an affine open $\operatorname{Spec}(\Lambda) \subset S$,
-
an inverse system $(R_n)$ of $\Lambda$-algebras with surjective transition maps whose kernels are locally nilpotent,
-
a system $(\xi_n)$ of objects of $\mathcal{X}$ lying over the system $(\operatorname{Spec}(R_n))$.
In this situation, set $R = \varprojlim R_n$. We say that $(\xi_n)$ is effective if there exists an object $\xi$ of $\mathcal{X}$ over $\operatorname{Spec}(R)$ whose restriction to $\operatorname{Spec}(R_n)$ gives the system $(\xi_n)$.
Lemma. Versality under generalization
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume
-
$\Delta : \mathcal{X} \to \mathcal{X} \times \mathcal{X}$ is representable by algebraic spaces,
-
$\mathcal{X}$ has (RS*),
-
$\mathcal{X}$ is limit preserving.
Let $x$ be an object of $\mathcal{X}$ over a scheme $U$ of finite type over $S$. Let $u \leadsto u_0$ be a specialization of finite type points of $U$ such that $x$ is versal at $u_0$. Then $x$ is versal at $u$.
Proof. After shrinking $U$ we may assume $U$ is affine and $U$ maps into an affine open $\operatorname{Spec}(\Lambda)$ of $S$. If $x$ is not versal at $u$ then we may pick $x \to y$ lying over $U \to T$ as in Lemma Lesson 7, Lemma 5.1. Write $U = \operatorname{Spec}(R_0)$ and $T = \operatorname{Spec}(R)$. The morphism $U \to T$ corresponds to a surjective ring map $R \to R_0$ whose kernel is an ideal of square zero. By assumption (3) we get that $y$ comes from an object $x'$ over $U' = \operatorname{Spec}(R')$ for some finite type $\Lambda$-subalgebra $R' \subset R$. After increasing $R'$ we may and do assume that $R' \to R_0$ is surjective, so that $U \subset U'$ is a first order thickening. Thus we now have $$x \to y \to x' \text{ lying over } U \to T \to U'$$ By assumption (1) there is an algebraic space $Z$ over $S$ representing $$(\mathrm{Sch}/U)_{fppf} \times_{x, \mathcal{X}, x'} (\mathrm{Sch}/U')_{fppf}$$ see Algebraic Stacks, Lemma Diagonals and separation (uncovered prerequisite). By construction of $2$-fibre products, a $V$-valued point of $Z$ corresponds to a triple $(a, a', \alpha)$ consisting of morphisms $a : V \to U$, $a' : V \to U'$ and a morphism $\alpha : a^*x \to (a')^*x'$. We obtain a commutative diagram $$\begin{gathered}\begin{matrix}U \\ \phantom{X} & Z & U' \\ \phantom{X} & U & S\end{matrix} \\[6pt] \begin{aligned}U & \longrightarrow Z \\ U & \longrightarrow U \\ U & \longrightarrow U' \\ Z & \xrightarrow{p'} U' \\ Z & \xrightarrow{p} U \\ U' & \longrightarrow S \\ U & \longrightarrow S\end{aligned}\end{gathered}$$ The morphism $i : U \to Z$ comes from the isomorphism $x \to x'|_U$. Let $z_0 = i(u_0) \in Z$. By Lemma Base change of a versal object we see that $Z \to U'$ is smooth at $z_0$. After replacing $U$ by an affine open neighbourhood of $u_0$, replacing $U'$ by the corresponding open, and replacing $Z$ by the intersection of the inverse images of these opens by $p$ and $p'$, we reach the situation where $Z \to U'$ is smooth along $i(U)$. Since $u \leadsto u_0$ the point $u$ is in this open. Condition (3) of Lemma Lesson 7, Lemma 5.1 is clearly preserved by shrinking $U$ (all of the schemes $U$, $T$, $U'$ have the same underlying topological space). Since $U \to U'$ is a first order thickening of affine schemes, we can choose a morphism $i' : U' \to Z$ such that $p' \circ i' = \text{id}_{U'}$ and whose restriction to $U$ is $i$ (More on Morphisms of Spaces, Lemma Formal smoothness and smooth morphisms). Pulling back the universal morphism $p^*x \to (p')^*x'$ by $i'$ we obtain a morphism $$x' \to x$$ lying over $p \circ i' : U' \to U$ such that the composition $$x \to x' \to x$$ is the identity. Recall that we have $y \to x'$ lying over the morphism $T \to U'$. Composing we get a morphism $y \to x$ whose existence contradicts condition (3) of Lemma Lesson 7, Lemma 5.1. This contradiction finishes the proof. $\square$
Lemma. A sequence of nonversal points accumulating at a versal point
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$ having (RS*). Let $x$ be an object of $\mathcal{X}$ over an affine scheme $U$ of finite type over $S$. Let $u_n \in U$, $n \geq 1$ be finite type points such that (a) there are no specializations $u_n \leadsto u_m$ for $n \not = m$, and (b) $x$ is not versal at $u_n$ for all $n$. Then there exist morphisms $$x \to x_1 \to x_2 \to \ldots \quad\text{in }\mathcal{X}\text{ lying over }\quad U \to U_1 \to U_2 \to \ldots$$ over $S$ such that
-
for each $n$ the morphism $U \to U_n$ is a first order thickening,
-
for each $n$ we have a short exact sequence $$0 \to \kappa(u_n) \to \mathcal{O}_{U_n} \to \mathcal{O}_{U_{n - 1}} \to 0$$ with $U_0 = U$ for $n = 1$,
-
for each $n$ there does not exist a pair $(W, \alpha)$ consisting of an open neighbourhood $W \subset U_n$ of $u_n$ and a morphism $\alpha : x_n|_W \to x$ such that the composition $$x|_{U \cap W} \xrightarrow{\text{restriction of }x \to x_n} x_n|_W \xrightarrow{\alpha} x$$ is the canonical morphism $x|_{U \cap W} \to x$.
Proof. Since there are no specializations among the points $u_n$ (and in particular the $u_n$ are pairwise distinct), for every $n$ we can find an open $U' \subset U$ such that $u_n \in U'$ and $u_i \not \in U'$ for $i = 1, \ldots, n - 1$. By Lemma Lesson 7, Lemma 5.1 for each $n \geq 1$ we can find $$x \to y_n \quad\text{in }\mathcal{X}\text{ lying over}\quad U \to T_n$$ such that
-
the morphism $U \to T_n$ is a first order thickening,
-
we have a short exact sequence $$0 \to \kappa(u_n) \to \mathcal{O}_{T_n} \to \mathcal{O}_U \to 0$$
-
there does not exist a pair $(W, \beta)$ consisting of an open neighbourhood $W \subset T_n$ of $u_n$ and a morphism $\beta : y_n|_W \to x$ such that the composition $$x|_{U \cap W} \xrightarrow{\text{restriction of }x \to y_n} y_n|_W \xrightarrow{\beta} x$$ is the canonical morphism $x|_{U \cap W} \to x$.
Thus we can define inductively $$U_1 = T_1, \quad U_{n + 1} = U_n \amalg_U T_{n + 1}$$ Setting $x_1 = y_1$ and using (RS*) we find inductively $x_{n + 1}$ over $U_{n + 1}$ restricting to $x_n$ over $U_n$ and $y_{n + 1}$ over $T_{n + 1}$. Property (1) for $U \to U_n$ follows from the construction of the pushout in More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces. Property (2) for $U_n$ similarly follows from property (2) for $T_n$ by the construction of the pushout. After shrinking to an open neighbourhood $U'$ of $u_n$ as discussed above, property (3) for $(U_n, x_n)$ follows from property (3) for $(T_n, y_n)$ simply because the corresponding open subschemes of $T_n$ and $U_n$ are isomorphic. Some details omitted. $\square$
Lemma. Base change of a versal object
Let $S$, $\mathcal{X}$, $U$, $x$, $u_0$ be as in Definition Versal objects. Assume
-
$\Delta : \mathcal{X} \to \mathcal{X} \times \mathcal{X}$ is representable by algebraic spaces,
-
$\Delta$ is locally of finite type (for example if $\mathcal{X}$ is limit preserving), and
-
$\mathcal{X}$ has (RS).
Let $V$ be a scheme locally of finite type over $S$ and let $y$ be an object of $\mathcal{X}$ over $V$. Form the $2$-fibre product $$\begin{gathered}\begin{matrix}\mathcal{Z} & (\mathrm{Sch}/U)_{fppf} \\ (\mathrm{Sch}/V)_{fppf} & \mathcal{X}\end{matrix} \\[6pt] \begin{aligned}\mathcal{Z} & \longrightarrow (\mathrm{Sch}/U)_{fppf} \\ \mathcal{Z} & \longrightarrow (\mathrm{Sch}/V)_{fppf} \\ (\mathrm{Sch}/U)_{fppf} & \xrightarrow{x} \mathcal{X} \\ (\mathrm{Sch}/V)_{fppf} & \xrightarrow{y} \mathcal{X}\end{aligned}\end{gathered}$$ Let $Z$ be the algebraic space representing $\mathcal{Z}$ and let $z_0 \in |Z|$ be a finite type point lying over $u_0$. If $x$ is versal at $u_0$, then the morphism $Z \to V$ is smooth at $z_0$.
Proof. (The parenthetical remark in the statement holds by Lemma Diagonals and separation.) Observe that $Z$ exists by assumption (1) and Algebraic Stacks, Lemma Diagonals and separation (uncovered prerequisite). By assumption (2) we see that $Z \to V \times_S U$ is locally of finite type. Choose a scheme $W$, a closed point $w_0 \in W$, and an étale morphism $W \to Z$ mapping $w_0$ to $z_0$, see Morphisms of Spaces, Definition Finite algebras. Then $W$ is locally of finite type over $S$ and $w_0$ is a finite type point of $W$. Let $l = \kappa(z_0)$. Denote by $z_{l, 0}$, $v_{l, 0}$, $u_{l, 0}$, and $x_{l, 0}$ the objects of $\mathcal{Z}$, $(\mathrm{Sch}/V)_{fppf}$, $(\mathrm{Sch}/U)_{fppf}$, and $\mathcal{X}$ over $\operatorname{Spec}(l)$ obtained by pullback to $\operatorname{Spec}(l) = w_0$. Consider $$\begin{gathered}\begin{matrix}\mathcal{F}_{(\mathrm{Sch}/W)_{fppf}, l, w_0} & \mathcal{F}_{\mathcal{Z}, l, z_{l, 0}} & \mathcal{F}_{(\mathrm{Sch}/U)_{fppf}, l, u_{l, 0}} \\ \phantom{X} & \mathcal{F}_{(\mathrm{Sch}/V)_{fppf}, l, v_{l, 0}} & \mathcal{F}_{\mathcal{X}, l, x_{l, 0}}\end{matrix} \\[6pt] \begin{aligned}\mathcal{F}_{(\mathrm{Sch}/W)_{fppf}, l, w_0} & \longrightarrow \mathcal{F}_{\mathcal{Z}, l, z_{l, 0}} \\ \mathcal{F}_{\mathcal{Z}, l, z_{l, 0}} & \longrightarrow \mathcal{F}_{(\mathrm{Sch}/V)_{fppf}, l, v_{l, 0}} \\ \mathcal{F}_{\mathcal{Z}, l, z_{l, 0}} & \longrightarrow \mathcal{F}_{(\mathrm{Sch}/U)_{fppf}, l, u_{l, 0}} \\ \mathcal{F}_{(\mathrm{Sch}/U)_{fppf}, l, u_{l, 0}} & \longrightarrow \mathcal{F}_{\mathcal{X}, l, x_{l, 0}} \\ \mathcal{F}_{(\mathrm{Sch}/V)_{fppf}, l, v_{l, 0}} & \longrightarrow \mathcal{F}_{\mathcal{X}, l, x_{l, 0}}\end{aligned}\end{gathered}$$ By Lemma Lesson 7, Sections 1.1 and 3 the square is a fibre product of predeformation categories. By Lemma Lesson 7, Lemma 1.3 and Section 3 we see that the right vertical arrow is smooth. By Formal Deformation Theory, Lemma Permanence of smooth deformation morphisms the left vertical arrow is smooth. By Lemma Formal smoothness on deformation categories we see that the left horizontal arrow is smooth. We conclude that the map $$\mathcal{F}_{(\mathrm{Sch}/W)_{fppf}, l, w_0} \to \mathcal{F}_{(\mathrm{Sch}/V)_{fppf}, l, v_{l, 0}}$$ is smooth by Formal Deformation Theory, Lemma Permanence of smooth deformation morphisms. Thus we conclude that $W \to V$ is smooth at $w_0$ by More on Morphisms, Lemma Smoothness from lifting Artinian tests at a point. This exactly means that $Z \to V$ is smooth at $z_0$ and the proof is complete. $\square$
Lemma. A smooth neighbourhood from versality
Let $S$ be a locally Noetherian scheme. Let $p : \mathcal{X} \to (\mathrm{Sch}/S)_{fppf}$ be a category fibred in groupoids. Let $k$ be a finite type field over $S$ and let $x_0$ be an object of $\mathcal{X}$ over $\operatorname{Spec}(k)$ with image $s \in S$. Assume
-
$\Delta : \mathcal{X} \to \mathcal{X} \times \mathcal{X}$ is representable by algebraic spaces,
-
$\mathcal{X}$ satisfies axioms [1], [2], [3] (see Section Artin's algebraicity axioms),
-
every formal object of $\mathcal{X}$ is effective,
-
openness of versality holds for $\mathcal{X}$, and
-
$\mathcal{O}_{S, s}$ is a G-ring.
Then there exist a morphism of finite type $U \to S$ and an object $x$ of $\mathcal{X}$ over $U$ such that $$x : (\mathrm{Sch}/U)_{fppf} \longrightarrow \mathcal{X}$$ is smooth and such that there exists a finite type point $u_0 \in U$ whose residue field is $k$ and such that $x|_{u_0} \cong x_0$.
Proof. By axiom [2], Lemma The deformation category at a field object, and Remark Consequences of the deformation-category axioms we see that $\mathcal{F}_{\mathcal{X}, k, x_0}$ satisfies (S1) and (S2). Since also the tangent space has finite dimension by axiom [3] we deduce from Formal Deformation Theory, Lemma Existence of a versal formal object that $\mathcal{F}_{\mathcal{X}, k, x_0}$ has a versal formal object $\xi$. Assumption (3) says $\xi$ is effective. By axiom [1] and Lemma Lesson 7, Lemma 3.1 there exists a morphism of finite type $U \to S$, an object $x$ of $\mathcal{X}$ over $U$, and a finite type point $u_0$ of $U$ with residue field $k$ such that $x$ is versal at $u_0$ and such that $x|_{\operatorname{Spec}(k)} \cong x_0$. By openness of versality we may shrink $U$ and assume that $x$ is versal at every finite type point of $U$. We claim that $$x : (\mathrm{Sch}/U)_{fppf} \longrightarrow \mathcal{X}$$ is smooth which proves the lemma. Namely, by Lemma Smoothness near a versal point $x$ satisfies (Smooth morphisms) whereupon Lemma Smoothness from the Artinian lifting criterion finishes the proof. $\square$
Definition. Versal objects
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Let $U$ be a scheme locally of finite type over $S$. Let $x$ be an object of $\mathcal{X}$ lying over $U$. Let $u_0$ be a finite type point of $U$. We say $x$ is versal at $u_0$ if the morphism $\hat x$ (Versality) is smooth, see Formal Deformation Theory, Definition Smooth morphisms of deformation categories.
Lemma. Diagonals and separation
Let $S$ be a scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume $\Delta : \mathcal{X} \to \mathcal{X} \times \mathcal{X}$ is representable by algebraic spaces and $\mathcal{X}$ is limit preserving. Then $\Delta$ is locally of finite type.
Proof. We apply Criteria for Representability, Lemma Proper morphisms (uncovered prerequisite). Let $V$ be an affine scheme locally of finite presentation over $S$ and let $\theta$ be an object of $\mathcal{X} \times \mathcal{X}$ over $V$. Let $F_\theta$ be an algebraic space representing $\mathcal{X} \times_{\Delta, \mathcal{X} \times \mathcal{X}, \theta} (\mathrm{Sch}/V)_{fppf}$ and let $f_\theta : F_\theta \to V$ be the canonical morphism (see Algebraic Stacks, Section The geometric construction). It suffices to show that $F_\theta \to V$ has the corresponding properties. By Lemmas Limit preservation in a fibre product of groupoids and Limit preservation for an algebraic space we see that $F_\theta \to S$ is locally of finite presentation. It follows that $F_\theta \to V$ is locally of finite type by Morphisms of Spaces, Lemma Finite algebras. $\square$
Lemma. Formal smoothness on deformation categories
Let $S$ be a locally Noetherian scheme. Let $F : \mathcal{X} \to \mathcal{Y}$ be a $1$-morphism of categories fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume either
-
$F$ is formally smooth on objects (Criteria for Representability, Section Formal smoothness and smooth morphisms),
-
$F$ is representable by algebraic spaces and formally smooth, or
-
$F$ is representable by algebraic spaces and smooth.
Then for every finite type field $k$ over $S$ and object $x_0$ of $\mathcal{X}$ over $k$ the functor (Versality) is smooth in the sense of Formal Deformation Theory, Definition Smooth morphisms of deformation categories.
Proof. Case (1) is a matter of unwinding the definitions. Assumption (2) implies (1) by Criteria for Representability, Lemma Formal smoothness and smooth morphisms (uncovered prerequisite). Assumption (3) implies (2) by More on Morphisms of Spaces, Lemma Formal smoothness and smooth morphisms and the principle of Algebraic Stacks, Lemma Proper morphisms (uncovered prerequisite). $\square$
Lemma. The deformation category at a field object
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$ satisfying (RS). For any field $k$ of finite type over $S$ and any object $x_0$ of $\mathcal{X}$ lying over $k$ the predeformation category $p : \mathcal{F}_{\mathcal{X}, k, x_0} \to \mathcal{C}_\Lambda$ (Nilpotent thickenings) is a deformation category, see Formal Deformation Theory, Definition Deformation categories.
Proof. Set $\mathcal{F} = \mathcal{F}_{\mathcal{X}, k, x_0}$. Let $f_1 : A_1 \to A$ and $f_2 : A_2 \to A$ be ring maps in $\mathcal{C}_\Lambda$ with $f_2$ surjective. We have to show that the functor $$\mathcal{F}(A_1 \times_A A_2) \longrightarrow \mathcal{F}(A_1) \times_{\mathcal{F}(A)} \mathcal{F}(A_2)$$ is an equivalence, see Formal Deformation Theory, Lemma Rim–Schlessinger patching in a fibre square of groupoids. Set $X = \operatorname{Spec}(A)$, $X' = \operatorname{Spec}(A_2)$, $Y = \operatorname{Spec}(A_1)$ and $Y' = \operatorname{Spec}(A_1 \times_A A_2)$. Note that $Y' = Y \amalg_X X'$ in the category of schemes, see More on Morphisms, Lemma Pushouts along a thickening of algebraic spaces. We know that in the diagram of functors of fibre categories $$\begin{gathered}\begin{matrix}\mathcal{X}_{Y'} & \mathcal{X}_Y \times_{\mathcal{X}_X} \mathcal{X}_{X'} \\ \mathcal{X}_{\operatorname{Spec}(k)} & \mathcal{X}_{\operatorname{Spec}(k)}\end{matrix} \\[6pt] \begin{aligned}\mathcal{X}_{Y'} & \longrightarrow \mathcal{X}_Y \times_{\mathcal{X}_X} \mathcal{X}_{X'} \\ \mathcal{X}_{Y'} & \longrightarrow \mathcal{X}_{\operatorname{Spec}(k)} \\ \mathcal{X}_Y \times_{\mathcal{X}_X} \mathcal{X}_{X'} & \longrightarrow \mathcal{X}_{\operatorname{Spec}(k)} \\ \mathcal{X}_{\operatorname{Spec}(k)} & \mathrel{=} \mathcal{X}_{\operatorname{Spec}(k)}\end{aligned}\end{gathered}$$ the top horizontal arrow is an equivalence by Definition Rim–Schlessinger patching. Since $\mathcal{F}(B)$ is the category of objects of $\mathcal{X}_{\operatorname{Spec}(B)}$ with an identification with $x_0$ over $k$ we win. $\square$
Remark. Consequences of the deformation-category axioms
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Let $k$ be a field of finite type over $S$ and $x_0$ an object of $\mathcal{X}$ over $k$. Let $p : \mathcal{F} \to \mathcal{C}_\Lambda$ be as in (Nilpotent thickenings). If $\mathcal{F}$ is a deformation category, i.e., if $\mathcal{F}$ satisfies the Rim-Schlessinger condition (RS), then we see that $\mathcal{F}$ satisfies Schlessinger's conditions (S1) and (S2) by Formal Deformation Theory, Lemma Rim–Schlessinger patching implies Schlessinger's conditions. Let $\overline{\mathcal{F}}$ be the functor of isomorphism classes, see Formal Deformation Theory, Remarks Groupoids and equivalence relations (Derived tensor products, Tor amplitude and prime spectra and associated points). Then $\overline{\mathcal{F}}$ satisfies (S1) and (S2) as well, see Formal Deformation Theory, Lemma The associated deformation functor and Schlessinger's conditions. This holds in particular in the situation of Lemma The deformation category at a field object.
Lemma. Smoothness near a versal point
Let $S$ be a locally Noetherian scheme. Let $\mathcal{X}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Let $U$ be a scheme locally of finite type over $S$. Let $x$ be an object of $\mathcal{X}$ over $U$. Assume that $x$ is versal at every finite type point of $U$ and that $\mathcal{X}$ satisfies (RS). Then $x : (\mathrm{Sch}/U)_{fppf} \to \mathcal{X}$ satisfies (Smooth morphisms).
Proof. Let $\operatorname{Spec}(l) \to U$ be a morphism with $l$ of finite type over $S$. Then the image $u_0 \in U$ is a finite type point of $U$ and $l/\kappa(u_0)$ is a finite extension, see discussion in Morphisms, Section Finite algebras. Hence we see that $\mathcal{F}_{(\mathrm{Sch}/U)_{fppf}, l, u_{l, 0}} \to \mathcal{F}_{\mathcal{X}, l, x_{l, 0}}$ is smooth by Lemma Lesson 7, Lemma 1.3 and Section 3. $\square$
Lemma. Smoothness from the Artinian lifting criterion
Let $S$ be a locally Noetherian scheme. Let $f : \mathcal{X} \to \mathcal{Y}$ be a $1$-morphism of categories fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. Assume
-
$f$ is representable by algebraic spaces,
-
$f$ satisfies (Smooth morphisms),
-
$\mathcal{X} \to (\mathrm{Sch}/S)_{fppf}$ is limit preserving on objects, and
-
$\mathcal{Y}$ is limit preserving.
Then $f$ is smooth.
Proof. The key ingredient of the proof is More on Morphisms, Lemma Smoothness from lifting Artinian tests at a point which (almost) says that a morphism of schemes of finite type over $S$ satisfying (Smooth morphisms) is a smooth morphism. The other arguments of the proof are essentially bookkeeping.
Let $V$ be a scheme over $S$ and let $y$ be an object of $\mathcal{Y}$ over $V$. Let $Z$ be an algebraic space representing the $2$-fibre product $\mathcal{Z} = \mathcal{X} \times_{f, \mathcal{Y}, y} (\mathrm{Sch}/V)_{fppf}$. We have to show that the projection morphism $Z \to V$ is smooth, see Algebraic Stacks, Definition Proper morphisms. In fact, it suffices to do this when $V$ is an affine scheme locally of finite presentation over $S$, see Criteria for Representability, Lemma Proper morphisms (uncovered prerequisite). Then $(\mathrm{Sch}/V)_{fppf}$ is limit preserving by Lemma Limit preservation for an algebraic space. Hence $Z \to S$ is locally of finite presentation by Lemmas Limit preservation in a fibre product of groupoids and Limit preservation for an algebraic space. Choose a scheme $W$ and a surjective étale morphism $W \to Z$. Then $W$ is locally of finite presentation over $S$.
Since $f$ satisfies (Smooth morphisms) we see that so does $\mathcal{Z} \to (\mathrm{Sch}/V)_{fppf}$, see Lemma Base change of smooth ring maps. Next, we see that $(\mathrm{Sch}/W)_{fppf} \to \mathcal{Z}$ satisfies (Smooth morphisms) by Lemma Smooth morphisms. Thus the composition $$(\mathrm{Sch}/W)_{fppf} \to \mathcal{Z} \to (\mathrm{Sch}/V)_{fppf}$$ satisfies (Smooth morphisms) by Lemma Composition and smooth morphisms. More on Morphisms, Lemma Smoothness from lifting Artinian tests at a point shows that the composition $W \to Z \to V$ is smooth at every finite type point $w_0$ of $W$. Since the smooth locus is open we conclude that $W \to V$ is a smooth morphism of schemes by Morphisms, Lemma Finite algebras (uncovered prerequisite). Thus we conclude that $Z \to V$ is a smooth morphism of algebraic spaces by definition. $\square$
Lemma. Limit preservation in a fibre product of groupoids
Let $S$ be a scheme. Let $p : \mathcal{X} \to \mathcal{Y}$ and $q : \mathcal{Z} \to \mathcal{Y}$ be $1$-morphisms of categories fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$.
-
If $\mathcal{X} \to (\mathrm{Sch}/S)_{fppf}$ and $\mathcal{Z} \to (\mathrm{Sch}/S)_{fppf}$ are limit preserving on objects and $\mathcal{Y}$ is limit preserving, then $\mathcal{X} \times_\mathcal{Y} \mathcal{Z} \to (\mathrm{Sch}/S)_{fppf}$ is limit preserving on objects.
-
If $\mathcal{X}$, $\mathcal{Y}$, and $\mathcal{Z}$ are limit preserving, then so is $\mathcal{X} \times_\mathcal{Y} \mathcal{Z}$.
Proof. This is formal. Proof of (1). Let $T = \varprojlim_{i \in I} T_i$ be the directed limit of affine schemes $T_i$ over $S$. We will prove that the functor $\mathop{\operatorname{colim}} (\mathcal{X} \times_\mathcal{Y} \mathcal{Z})_{T_i} \to (\mathcal{X} \times_\mathcal{Y} \mathcal{Z})_T$ is essentially surjective. Recall that an object of the fibre product over $T$ is a quadruple $(T, x, z, \alpha)$ where $x$ is an object of $\mathcal{X}$ lying over $T$, $z$ is an object of $\mathcal{Z}$ lying over $T$, and $\alpha : p(x) \to q(z)$ is a morphism in the fibre category of $\mathcal{Y}$ over $T$. By assumption on $\mathcal{X}$ and $\mathcal{Z}$ we can find an $i$ and objects $x_i$ and $z_i$ over $T_i$ such that $x_i|_T \cong x$ and $z_i|_T \cong z$. Then $\alpha$ corresponds to an isomorphism $p(x_i)|_T \to q(z_i)|_T$ which comes from an isomorphism $\alpha_{i'} : p(x_i)|_{T_{i'}} \to q(z_i)|_{T_{i'}}$ by our assumption on $\mathcal{Y}$. After replacing $i$ by $i'$, $x_i$ by $x_i|_{T_{i'}}$, and $z_i$ by $z_i|_{T_{i'}}$ we see that $(T_i, x_i, z_i, \alpha_i)$ is an object of the fibre product over $T_i$ which restricts to an object isomorphic to $(T, x, z, \alpha)$ over $T$ as desired.
We omit the arguments showing that $\mathop{\operatorname{colim}} (\mathcal{X} \times_\mathcal{Y} \mathcal{Z})_{T_i} \to (\mathcal{X} \times_\mathcal{Y} \mathcal{Z})_T$ is fully faithful in (2). $\square$
Lemma. Limit preservation for an algebraic space
Let $S$ be a scheme. Let $\mathcal{X}$ be an algebraic stack over $S$. Then the following are equivalent
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$\mathcal{X}$ is a stack in setoids and $\mathcal{X} \to (\mathrm{Sch}/S)_{fppf}$ is limit preserving on objects,
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$\mathcal{X}$ is a stack in setoids and limit preserving,
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$\mathcal{X}$ is representable by an algebraic space locally of finite presentation.
Proof. Under each of the three assumptions $\mathcal{X}$ is representable by an algebraic space $X$ over $S$, see Algebraic Stacks, Proposition The geometric construction (uncovered prerequisite). It is clear that (1) and (2) are equivalent as a functor between setoids is an equivalence if and only if it is surjective on isomorphism classes. Finally, (1) and (3) are equivalent by Limits of Spaces, Proposition Criteria for finite presentation and finite algebras. $\square$
Definition. Rim--Schlessinger patching
Let $S$ be a locally Noetherian scheme. Let $\mathcal{Z}$ be a category fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. We say $\mathcal{Z}$ satisfies condition (RS) if for every pushout $$\begin{gathered}\begin{matrix}X & X' \\ Y & Y' = Y \amalg_X X'\end{matrix} \\[6pt] \begin{aligned}X & \longrightarrow X' \\ X & \longrightarrow Y \\ X' & \longrightarrow Y' = Y \amalg_X X' \\ Y & \longrightarrow Y' = Y \amalg_X X'\end{aligned}\end{gathered}$$ in the category of schemes over $S$ where
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$X$, $X'$, $Y$, $Y'$ are spectra of local Artinian rings,
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$X$, $X'$, $Y$, $Y'$ are of finite type over $S$, and
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$X \to X'$ (and hence $Y \to Y'$) is a closed immersion
the functor of fibre categories $$\mathcal{Z}_{Y'} \longrightarrow \mathcal{Z}_Y \times_{\mathcal{Z}_X} \mathcal{Z}_{X'}$$ is an equivalence of categories.
Lemma. Base change of smooth ring maps
Let $S$ be a locally Noetherian scheme. Let $f : \mathcal{X} \to \mathcal{Y}$ and $\mathcal{Z} \to \mathcal{Y}$ be $1$-morphisms of categories fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. If $f$ satisfies (Smooth morphisms) so does the projection $\mathcal{X} \times_\mathcal{Y} \mathcal{Z} \to \mathcal{Z}$.
Proof. This follows immediately from Lemma Lesson 7, Sections 1.1 and 3 and Formal Deformation Theory, Lemma Permanence of smooth deformation morphisms. $\square$
Lemma. Smooth morphisms
Let $S$ be a locally Noetherian scheme. Let $f : \mathcal{X} \to \mathcal{Y}$ be a $1$-morphism of categories fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. If $f$ is formally smooth on objects, then $f$ satisfies (Smooth morphisms). If $f$ is representable by algebraic spaces and smooth, then $f$ satisfies (Smooth morphisms).
Proof. This is a reformulation of Lemma Formal smoothness on deformation categories. $\square$
Lemma. Composition and smooth morphisms
Let $S$ be a locally Noetherian scheme. Let $f : \mathcal{X} \to \mathcal{Y}$ and $g : \mathcal{Y} \to \mathcal{Z}$ be composable $1$-morphisms of categories fibred in groupoids over $(\mathrm{Sch}/S)_{fppf}$. If $f$ and $g$ satisfy (Smooth morphisms) so does $g \circ f$.
Proof. This follows formally from Formal Deformation Theory, Lemma Permanence of smooth deformation morphisms. $\square$
[^1]: Set theoretical remark: This coproduct is (isomorphic to) an object of $(\mathrm{Sch}/S)_{fppf}$ as we have a bound on the index set by axiom [-1], see Sets, Lemma The geometric construction (uncovered prerequisite).
Invertible sheaves and ample line bundles
Lemma. Flatness
Let $S$ be a scheme. Let $\mathcal{A}$ be a quasi-coherent graded $\mathcal{O}_S$-algebra. Let $p : X = \underline{\text{Proj}}_S(\mathcal{A}) \to S$ be the relative Proj of $\mathcal{A}$. If $\mathcal{A}_d$ is a flat $\mathcal{O}_S$-module for $d \gg 0$, then $p$ is flat and $\mathcal{O}_X(d)$ is flat over $S$.
Proof. Affine locally flatness of $X$ over $S$ reduces to the following statement: Let $R$ be a ring, let $A$ be a graded $R$-algebra with $A_d$ flat over $R$ for $d \gg 0$, let $f \in A_d$ for some $d > 0$, then $A_{(f)}$ is flat over $R$. Since $A_{(f)} = \mathop{\operatorname{colim}} A_{nd}$ where the transition maps are given by multiplication by $f$, this follows from Algebra, Lemma Filtered limits and flatness. Argue similarly to get flatness of $\mathcal{O}_X(d)$ over $S$. $\square$
Lemma. Proper morphisms
Let $S$ be a scheme. Let $\mathcal{A}$ be a quasi-coherent graded $\mathcal{O}_S$-algebra. Let $p : X = \underline{\text{Proj}}_S(\mathcal{A}) \to S$ be the relative Proj of $\mathcal{A}$. The following conditions are equivalent
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$\mathcal{A}_0$ is a finite type $\mathcal{O}_S$-module and $\mathcal{A}$ is of finite type as an $\mathcal{A}_0$-algebra,
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$\mathcal{A}_0$ is a finite type $\mathcal{O}_S$-module and $\mathcal{A}$ is of finite type as an $\mathcal{O}_S$-algebra
If these conditions hold, then $p$ is locally projective and in particular proper.
Proof. Assume that $\mathcal{A}_0$ is a finite type $\mathcal{O}_S$-module. Choose an affine open $U = \operatorname{Spec}(R) \subset X$ such that $\mathcal{A}$ corresponds to a graded $R$-algebra $A$ with $A_0$ a finite $R$-module. Condition (1) means that (after possibly localizing further on $S$) that $A$ is a finite type $A_0$-algebra and condition (2) means that (after possibly localizing further on $S$) that $A$ is a finite type $R$-algebra. Thus these conditions imply each other by Algebra, Lemma Composition of finite-type ring maps.
A locally projective morphism is proper, see Morphisms, Lemma Projective, locally free modules and proper morphisms (uncovered prerequisite). Thus we may now assume that $S = \operatorname{Spec}(R)$ and $X = \text{Proj}(A)$ and that $A_0$ is finite over $R$ and $A$ of finite type over $R$. We will show that $X = \text{Proj}(A) \to \operatorname{Spec}(R)$ is projective. We urge the reader to prove this for themselves, by directly constructing a closed immersion of $X$ into a projective space over $R$, instead of reading the argument we give below.
By Lemma Finite algebras we see that $X$ is of finite type over $\operatorname{Spec}(R)$. Constructions, Lemma Line bundles and ampleness (uncovered prerequisite) tells us that $\mathcal{O}_X(d)$ is ample on $X$ for some $d \geq 1$ (see Properties, Section Line bundles and ampleness). Hence $X \to \operatorname{Spec}(R)$ is quasi-projective (by Morphisms, Definition Projective and locally free modules). By Morphisms, Lemma Projective and locally free modules (uncovered prerequisite) we conclude that $X$ is isomorphic to an open subscheme of a scheme projective over $\operatorname{Spec}(R)$. Therefore, to finish the proof, it suffices to show that $X \to \operatorname{Spec}(R)$ is universally closed (use Morphisms, Lemma Proper morphisms (uncovered prerequisite)). This follows from Lemma The geometric construction. $\square$
Lemma. Finite presentation and finite algebras
Let $S$ be a scheme. Let $\mathcal{A}$ be a quasi-coherent graded $\mathcal{O}_S$-algebra. Let $p : X = \underline{\text{Proj}}_S(\mathcal{A}) \to S$ be the relative Proj of $\mathcal{A}$. If $\mathcal{A}$ is a finitely presented $\mathcal{O}_S$-algebra, then $p$ is of finite presentation and $\mathcal{O}_X(d)$ is an $\mathcal{O}_X$-module of finite presentation.
Proof. Affine locally this reduces to the following statement: Let $R$ be a ring and let $A$ be a finitely presented graded $R$-algebra. Then $\text{Proj}(A) \to \operatorname{Spec}(R)$ is of finite presentation and $\mathcal{O}_{\text{Proj}(A)}(d)$ is a $\mathcal{O}_{\text{Proj}(A)}$-module of finite presentation. The finite presentation condition implies we can choose a presentation $$A = R[X_1, \ldots, X_n]/(F_1, \ldots, F_m)$$ where $R[X_1, \ldots, X_n]$ is a polynomial ring graded by giving weights $d_i$ to $X_i$ and $F_1, \ldots, F_m$ are homogeneous polynomials of degree $e_j$. Let $R_0 \subset R$ be the subring generated by the coefficients of the polynomials $F_1, \ldots, F_m$. Then we set $A_0 = R_0[X_1, \ldots, X_n]/(F_1, \ldots, F_m)$. By construction $A = A_0 \otimes_{R_0} R$. Thus by Constructions, Lemma Base change for the geometric construction (uncovered prerequisite) it suffices to prove the result for $X_0 = \text{Proj}(A_0)$ over $R_0$. By Lemma Finite algebras we know $X_0$ is of finite type over $R_0$ and $\mathcal{O}_{X_0}(d)$ is a quasi-coherent $\mathcal{O}_{X_0}$-module of finite type. Since $R_0$ is Noetherian (as a finitely generated $\mathbf{Z}$-algebra) we see that $X_0$ is of finite presentation over $R_0$ (Morphisms, Lemma Finite presentation and Noetherian rings (uncovered prerequisite)) and $\mathcal{O}_{X_0}(d)$ is of finite presentation by Cohomology of Schemes, Lemma Coherent sheaves and Noetherian rings (uncovered prerequisite). This finishes the proof. $\square$
Lemma. Base change for prime spectra and associated points
Let $f : X \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_X$-module. Let $g : S' \to S$ be a morphism of schemes. Consider the base change diagram $$\begin{gathered}\begin{matrix}X' & X \\ S' & S\end{matrix} \\[6pt] \begin{aligned}X' & \longrightarrow S' \\ X' & \xrightarrow{g'} X \\ X & \longrightarrow S \\ S' & \xrightarrow{g} S\end{aligned}\end{gathered}$$ and set $\mathcal{F}' = (g')^*\mathcal{F}$. Let $x' \in X'$ be a point with images $x \in X$, $s' \in S'$ and $s \in S$. Assume $f$ locally of finite type. Then $x' \in \text{Ass}_{X'/S'}(\mathcal{F}')$ if and only if $x \in \text{Ass}_{X/S}(\mathcal{F})$ and $x'$ corresponds to a generic point of an irreducible component of $\operatorname{Spec}(\kappa(s') \otimes_{\kappa(s)} \kappa(x))$.
Proof. Consider the morphism $X'_{s'} \to X_s$ of fibres. As $X_{s'} = X_s \times_{\operatorname{Spec}(\kappa(s))} \operatorname{Spec}(\kappa(s'))$ this is a flat morphism. Moreover $\mathcal{F}'_{s'}$ is the pullback of $\mathcal{F}_s$ via this morphism. As $X_s$ is locally of finite type over the Noetherian scheme $\operatorname{Spec}(\kappa(s))$ we have that $X_s$ is locally Noetherian, see Morphisms, Lemma Noetherian rings and finite algebras (uncovered prerequisite). Thus we may apply Lemma The geometric construction (uncovered prerequisite) and we see that $$\text{Ass}_{X'_{s'}}(\mathcal{F}'_{s'}) = \bigcup\nolimits_{x \in \text{Ass}(\mathcal{F}_s)} \text{Ass}((X'_{s'})_x).$$ Thus to prove the lemma it suffices to show that the associated points of the fibre $(X'_{s'})_x$ of the morphism $X'_{s'} \to X_s$ over $x$ are its generic points. Note that $(X'_{s'})_x = \operatorname{Spec}(\kappa(s') \otimes_{\kappa(s)} \kappa(x))$ as schemes. By Algebra, Lemma Field extensions and tensor products and direct sums (uncovered prerequisite) the ring $\kappa(s') \otimes_{\kappa(s)} \kappa(x)$ is a Noetherian Cohen-Macaulay ring. Hence its associated primes are its minimal primes, see Algebra, Proposition Prime spectra and associated points (uncovered prerequisite) (minimal primes are associated) and Algebra, Lemma Criteria for prime spectra and associated points (uncovered prerequisite) (no embedded primes). $\square$
Remark. Base change for prime spectra and associated points
With notation and assumptions as in Lemma Base change for prime spectra and associated points we see that it is always the case that $(g')^{-1}(\text{Ass}_{X/S}(\mathcal{F})) \supset \text{Ass}_{X'/S'}(\mathcal{F}')$. If the morphism $S' \to S$ is locally quasi-finite, then we actually have $$(g')^{-1}(\text{Ass}_{X/S}(\mathcal{F}))
\text{Ass}{X'/S'}(\mathcal{F}')$$ because in this case the field extensions $\kappa(s')/\kappa(s)$ are always finite. In fact, this holds more generally for any morphism $g : S' \to S$ such that all the field extensions $\kappa(s')/\kappa(s)$ are algebraic, because in this case all prime ideals of $\kappa(s') \otimes{\kappa(s)} \kappa(x)$ are maximal (and minimal) primes, see Algebra, Lemma Integral extensions and field extensions (uncovered prerequisite).
Lemma. Line bundles, ampleness and finite algebras
Let $\pi : X \to Y$ be a finite morphism of schemes. Let $\mathcal{L}$ be an invertible $\mathcal{O}_X$-module. Let $y \in Y$. There exists an open neighbourhood $V \subset Y$ of $y$ such that $\mathcal{L}|_{\pi^{-1}(V)}$ is trivial.
Proof. Clearly we may assume $Y$ and hence $X$ affine. Since $\pi$ is finite the fibre $\pi^{-1}(\{y\})$ over $y$ is finite. Since $X$ is affine, we can pick $s \in \Gamma(X, \mathcal{L})$ not vanishing in any point of $\pi^{-1}(\{y\})$. This follows from Properties, Lemma Line bundles, ampleness and affine neighbourhoods (uncovered prerequisite) but we also give a direct argument. Namely, we can pick a finite set $E \subset X$ of closed points such that every $x \in \pi^{-1}(\{y\})$ specializes to some point of $E$. For $x \in E$ denote $i_x : x \to X$ the closed immersion. Then $\mathcal{L} \to \bigoplus_{x \in E} i_{x, *}i_x^*\mathcal{L}$ is a surjective map of quasi-coherent $\mathcal{O}_X$-modules, and hence the map $$\Gamma(X, \mathcal{L}) \to \bigoplus\nolimits_{x \in E} \mathcal{L}_x/\mathfrak m_x\mathcal{L}_x$$ is surjective (as taking global sections is an exact functor on the category of quasi-coherent $\mathcal{O}_X$-modules, see Schemes, Lemma Quasi-coherent complexes and coherent sheaves (uncovered prerequisite)). Thus we can find an $s \in \Gamma(X, \mathcal{L})$ not vanishing at any point specializing to a point of $E$. Then $X_s \subset X$ is an open neighbourhood of $\pi^{-1}(\{y\})$. Since $\pi$ is finite, hence closed, we conclude that there is an open neighbourhood $V \subset Y$ of $y$ whose inverse image is contained in $X_s$ as desired. $\square$
Lemma. Finite algebras
Let $S$ be a scheme. Let $\mathcal{A}$ be a quasi-coherent graded $\mathcal{O}_S$-algebra. Let $p : X = \underline{\text{Proj}}_S(\mathcal{A}) \to S$ be the relative Proj of $\mathcal{A}$. If $\mathcal{A}$ is of finite type as a sheaf of $\mathcal{O}_S$-algebras, then $p$ is of finite type and $\mathcal{O}_X(d)$ is a finite type $\mathcal{O}_X$-module.
Proof. The assumption implies that $p$ is quasi-compact, see Lemma The geometric construction (uncovered prerequisite). Hence it suffices to show that $p$ is locally of finite type. Thus the question is local on the base and target, see Morphisms, Lemma Finite algebras and local algebra (uncovered prerequisite). Say $S = \operatorname{Spec}(R)$ and $\mathcal{A}$ corresponds to the graded $R$-algebra $A$. After further localizing on $S$ we may assume that $A$ is a finite type $R$-algebra. The scheme $X$ is constructed out of glueing the spectra of the rings $A_{(f)}$ for $f \in A_{+}$ homogeneous. Each of these is of finite type over $R$ by Algebra, Lemma Finite algebras (uncovered prerequisite) part (1). Thus $\text{Proj}(A)$ is of finite type over $R$. To see the statement on $\mathcal{O}_X(d)$ use part (2) of Algebra, Lemma Finite algebras (uncovered prerequisite). $\square$
Lemma. The geometric construction
Let $S$ be a scheme. Let $\mathcal{A}$ be a quasi-coherent graded $\mathcal{O}_S$-algebra. Let $p : X = \underline{\text{Proj}}_S(\mathcal{A}) \to S$ be the relative Proj of $\mathcal{A}$. If $\mathcal{O}_S \to \mathcal{A}_0$ is an integral algebra map[^1] and $\mathcal{A}$ is of finite type as an $\mathcal{A}_0$-algebra, then $p$ is universally closed.
Proof. The question is local on the base. Thus we may assume that $X = \operatorname{Spec}(R)$ is affine. Let $\mathcal{A}$ be the quasi-coherent $\mathcal{O}_X$-algebra associated to the graded $R$-algebra $A$. The assumption is that $R \to A_0$ is integral and $A$ is of finite type over $A_0$. Write $X \to \operatorname{Spec}(R)$ as the composition $X \to \operatorname{Spec}(A_0) \to \operatorname{Spec}(R)$. Since $R \to A_0$ is an integral ring map, we see that $\operatorname{Spec}(A_0) \to \operatorname{Spec}(R)$ is universally closed, see Morphisms, Lemma Integral extensions (uncovered prerequisite). The quasi-compact (see Constructions, Lemma The geometric construction (uncovered prerequisite)) morphism $$X = \text{Proj}(A) \to \operatorname{Spec}(A_0)$$ satisfies the existence part of the valuative criterion by Constructions, Lemma The geometric construction (uncovered prerequisite) and hence it is universally closed by Schemes, Proposition Criteria for the geometric construction (uncovered prerequisite). Thus $X \to \operatorname{Spec}(R)$ is universally closed as a composition of universally closed morphisms. $\square$
[^1]: In other words, the integral closure of $\mathcal{O}_S$ in $\mathcal{A}_0$, see Morphisms, Definition Integral extensions, equals $\mathcal{A}_0$.
Equivalence relations and descent of schemes
Proposition. Flatness and groupoids and equivalence relations
Source credit: the original source citation FGA (Exposé 212, Théorème 5.1 (iv), p. 111).
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme over $S$. Assume
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$U = \operatorname{Spec}(A)$, and $R = \operatorname{Spec}(B)$ are affine,
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$s, t : R \to U$ finite locally free, and
-
$j = (t, s)$ is an equivalence relation.
In this case, let $C \subset A$ be as in (The geometric construction). Then $U \to M = \operatorname{Spec}(C)$ is finite locally free and $R = U \times_M U$. Moreover, $M$ represents the quotient sheaf $U/R$ in the fppf topology (see Definition Sheaves on ringed sites).
Proof. During this proof we use the notation $s, t : A \to B$ instead of the notation $s^\sharp, t^\sharp$. By Lemma Criteria for the geometric construction (uncovered prerequisite) it suffices to show that $C \to A$ is finite locally free and that the map $$t \otimes s : A \otimes_C A \longrightarrow B$$ is an isomorphism. First, note that $j$ is a monomorphism, and also finite (since already $s$ and $t$ are finite). Hence we see that $j$ is a closed immersion by Morphisms, Lemma Finite algebras (uncovered prerequisite). Hence $A \otimes_C A \to B$ is surjective.
We will perform base change by flat ring maps $C \to C'$ as in Lemma Base change for the geometric construction (uncovered prerequisite), and we will use that formation of invariants commutes with flat base change, see part (3) of the lemma cited. We will show below that for every prime $\mathfrak p \subset C$, there exists a local flat ring map $C_{\mathfrak p} \to C_{\mathfrak p}'$ such that the result holds after a base change to $C_{\mathfrak p}'$. This implies immediately that $A \otimes_C A \to B$ is injective (use Algebra, Lemma Detecting a zero module by localization). It also implies that $C \to A$ is flat, by combining Algebra, Lemmas Flatness and local algebra, Localization of a flat module (uncovered prerequisite), and Flatness (uncovered prerequisite). Then since $U \to \operatorname{Spec}(C)$ is surjective also (Lemma The geometric construction (uncovered prerequisite)) we conclude that $C \to A$ is faithfully flat. Then the isomorphism $B \cong A \otimes_C A$ implies that $A$ is a finitely presented $C$-module, see Algebra, Lemma Descent of proper morphisms and modules (uncovered prerequisite). Hence $A$ is finite locally free over $C$, see Algebra, Lemma Characterizations of finite projective modules.
By Lemma Projective, locally free modules and finite algebras (uncovered prerequisite) we know that $A$ is a finite product of rings $A_r$ and $B$ is a finite product of rings $B_r$ such that the groupoid scheme decomposes accordingly (see the proof of Lemma Integral extensions (uncovered prerequisite)). Then also $C$ is a product of rings $C_r$ and correspondingly $C'$ decomposes as a product. Hence we may and do assume that the ring maps $s, t : A \to B$ are finite locally free of a fixed rank $r$.
The local ring maps $C_{\mathfrak p} \to C_{\mathfrak p}'$ we are going to use are any local flat ring maps such that the residue field of $C_{\mathfrak p}'$ is infinite. By Algebra, Lemma Flatness and field extensions (uncovered prerequisite) such local ring maps exist.
Assume $C$ is a local ring with maximal ideal $\mathfrak m$ and infinite residue field, and assume that $s, t : A \to B$ is finite locally free of constant rank $r > 0$. Since $C \subset A$ is integral (Lemma Integral extensions (uncovered prerequisite)) all primes lying over $\mathfrak m$ are maximal, and all maximal ideals of $A$ lie over $\mathfrak m$. Similarly for $C \subset B$. Pick a maximal ideal $\mathfrak m'$ of $A$ lying over $\mathfrak m$ (exists by Lemma The geometric construction (uncovered prerequisite)). Since $t : A \to B$ is finite locally free there exist at most finitely many maximal ideals of $B$ lying over $\mathfrak m'$. Hence we conclude (by Lemma The geometric construction (uncovered prerequisite) again) that $A$ has finitely many maximal ideals, i.e., $A$ is semi-local. This in turn implies that $B$ is semi-local as well. OK, and now, because $t \otimes s : A \otimes_C A \to B$ is surjective, we can apply Algebra, Lemma Modules and local algebra (uncovered prerequisite) to the ring map $C \to A$, the $A$-module $M = B$ (seen as an $A$-module via $t$) and the $C$-submodule $s(A) \subset B$. This lemma implies that there exist $x_1, \ldots, x_r \in A$ such that $M$ is free over $A$ on the basis $s(x_1), \ldots, s(x_r)$. Hence we conclude that $C \to A$ is finite free and $B \cong A \otimes_C A$ by applying Lemma The geometric construction (uncovered prerequisite). $\square$
Lemma. Affine neighbourhoods
Source credit: the original source citation FGA (Exposé 212, proof of Théorème 5.3, pp. 111--112).
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme over $S$. Assume $s$, $t$ are finite locally free. Let $u \in U$ be a point such that $t(s^{-1}(\{u\}))$ is contained in an affine open of $U$. Then there exists an $R$-invariant affine open neighbourhood of $u$ in $U$.
Proof. Since $s$ is finite locally free it has finite fibres. Hence $t(s^{-1}(\{u\})) = \{u_1, \ldots, u_n\}$ is a finite set. Note that $u \in \{u_1, \ldots, u_n\}$. Let $W \subset U$ be an affine open containing $\{u_1, \ldots, u_n\}$, in particular $u \in W$. Consider $Z = R \setminus (s^{-1}(W) \cap t^{-1}(W))$. This is a closed subset of $R$. The image $t(Z)$ is a closed subset of $U$ which can be loosely described as the set of points of $U$ which are $R$-equivalent to a point of $U \setminus W$. Hence $W' = U \setminus t(Z)$ is an $R$-invariant, open subscheme of $U$ contained in $W$, and $\{u_1, \ldots, u_n\} \subset W'$. Picture $$\{u_1, \ldots, u_n\} \subset W' \subset W \subset U.$$ Let $f \in \Gamma(W, \mathcal{O}_W)$ be an element such that $\{u_1, \ldots, u_n\} \subset D(f) \subset W'$. Such an $f$ exists by Algebra, Lemma An elementary algebraic comparison (uncovered prerequisite). By our choice of $W'$ we have $s^{-1}(W') \subset t^{-1}(W)$, and hence we get a diagram $$\begin{gathered}\begin{matrix}s^{-1}(W') & W \\ W'\end{matrix} \\[6pt] \begin{aligned}s^{-1}(W') & \xrightarrow{s} W' \\ s^{-1}(W') & \xrightarrow{t} W\end{aligned}\end{gathered}$$ The vertical arrow is finite locally free by assumption. Set $$g = \text{Norm}_s(t^\sharp f) \in \Gamma(W', \mathcal{O}_{W'})$$ By construction $g$ is a function on $W'$ which is nonzero in $u$, as $t^\sharp(f)$ is nonzero in each of the points of $R$ lying over $u$, since $f$ is nonzero in $u_1, \ldots, u_n$. Similarly, $D(g) \subset W'$ is equal to the set of points $w$ such that $f$ is not zero in any of the points equivalent to $w$. This means that $D(g)$ is an $R$-invariant affine open of $W'$. The final picture is $$\{u_1, \ldots, u_n\} \subset D(g) \subset D(f) \subset W' \subset W \subset U$$ and hence we win. $\square$
Lemma. The determinant trick for a finite groupoid
Let $S$ be a scheme. Let $(U, R, s, t, c)$ be a groupoid scheme over $S$. Assume $U = \operatorname{Spec}(A)$ and $R = \operatorname{Spec}(B)$ are affine and $s, t : R \to U$ finite locally free. Let $C$ be as in (The geometric construction). Let $f \in A$. Then $\text{Norm}_{s^\sharp}(t^\sharp(f)) \in C$.
Proof. Consider the commutative diagram $$\begin{gathered}\begin{matrix}\phantom{X} & U & \phantom{X} \\ R & R \times_{s, U, t} R & R \\ U & R & U\end{matrix} \\[6pt] \begin{aligned}R & \xrightarrow{s} U \\ R & \xrightarrow{t} U \\ R \times_{s, U, t} R & \xrightarrow{\text{pr}_0} R \\ R \times_{s, U, t} R & \xrightarrow{\text{pr}_1} R \\ R \times_{s, U, t} R & \xrightarrow{c} R \\ R & \xrightarrow{s} U \\ R & \xrightarrow{t} U \\ R & \xrightarrow{t} U \\ R & \xrightarrow{s} U\end{aligned}\end{gathered}$$ of Lemma The cartesian squares defining the pushout (uncovered prerequisite). Think of $f \in \Gamma(U, \mathcal{O}_U)$. The commutativity of the top part of the diagram shows that $\text{pr}_0^\sharp(t^\sharp(f)) = c^\sharp(t^\sharp(f))$ as elements of $\Gamma(R \times_{s, U, t} R, \mathcal{O})$. Looking at the right lower cartesian square the compatibility of the norm construction with base change shows that $s^\sharp(\text{Norm}_{s^\sharp}(t^\sharp(f))) = \text{Norm}_{\text{pr}_1^\sharp}(c^\sharp(t^\sharp(f)))$. Similarly we get $t^\sharp(\text{Norm}_{s^\sharp}(t^\sharp(f))) = \text{Norm}_{\text{pr}_1^\sharp}(\text{pr}_0^\sharp(t^\sharp(f)))$. Hence by the first equality of this proof we see that $s^\sharp(\text{Norm}_{s^\sharp}(t^\sharp(f))) = t^\sharp(\text{Norm}_{s^\sharp}(t^\sharp(f)))$ as desired. $\square$
Marked formal deformation groupoids
Lemma. Linear functors on deformation modules
Let $L: \text{Mod}^{fg}_R \to \textit{Sets}$, resp. $L: \text{Mod}_R \to \textit{Sets}$ be a functor. Suppose $L(0)$ is a one element set and $L$ preserves finite products. Then there exists a unique $R$-linear functor $\widetilde{L} : \text{Mod}^{fg}_R \to \text{Mod}_R$, resp. $\widetilde{L} : \text{Mod}_R \to \text{Mod}_R$, such that $$\begin{gathered}\begin{matrix}\phantom{X} & \text{Mod}_R & \phantom{X} \\ \text{Mod}^{fg}_R & \phantom{X} & \textit{Sets}\end{matrix} \\[6pt] \begin{aligned}\text{Mod}_R & \xrightarrow{\text{forget}} \textit{Sets} \\ \text{Mod}^{fg}_R & \xrightarrow{\widetilde{L}} \text{Mod}_R \\ \text{Mod}^{fg}_R & \xrightarrow{L} \textit{Sets}\end{aligned}\end{gathered} \quad\text{resp.}\quad \begin{gathered}\begin{matrix}\phantom{X} & \text{Mod}_R & \phantom{X} \\ \text{Mod}_R & \phantom{X} & \textit{Sets}\end{matrix} \\[6pt] \begin{aligned}\text{Mod}_R & \xrightarrow{\text{forget}} \textit{Sets} \\ \text{Mod}_R & \xrightarrow{\widetilde{L}} \text{Mod}_R \\ \text{Mod}_R & \xrightarrow{L} \textit{Sets}\end{aligned}\end{gathered}$$ commutes.
Proof. We only prove this in case $L: \text{Mod}^{fg}_R \to \textit{Sets}$. Let $M$ be a finitely generated $R$-module. We define $\widetilde{L}(M)$ to be the set $L(M)$ with the following $R$-module structure.
Multiplication: If $r \in R$, multiplication by $r$ on $L(M)$ is defined to be the map $L(M) \to L(M)$ induced by the multiplication map $r \cdot : M \to M$.
Addition: The sum map $M \times M \to M: (m_1, m_2) \mapsto m_1 + m_2$ induces a map $L(M \times M) \to L(M)$. By assumption $L(M \times M)$ is canonically isomorphic to $L(M) \times L(M)$. Addition on $L(M)$ is defined by the map $L(M) \times L(M) \cong L(M \times M) \to L(M)$.
Zero: There is a unique map $0 \to M$. The zero element of $L(M)$ is the image of $L(0) \to L(M)$.
We omit the verification that this defines an $R$-module $\widetilde{L}(M)$, the unique such that is $R$-linearly functorial in $M$. $\square$
Lemma. Permanence of smooth deformation morphisms
Let $\varphi : \mathcal{F} \to \mathcal{G}$ and $\psi : \mathcal{G} \to \mathcal{H}$ be morphisms of categories cofibered in groupoids over $\mathcal{C}_\Lambda$.
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If $\varphi$ and $\psi$ are smooth, then $\psi \circ \varphi$ is smooth.
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If $\varphi$ is essentially surjective and $\psi \circ \varphi$ is smooth, then $\psi$ is smooth.
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If $\mathcal{G}' \to \mathcal{G}$ is a morphism of categories cofibered in groupoids and $\varphi$ is smooth, then $\mathcal{F} \times_\mathcal{G} \mathcal{G}' \to \mathcal{G}'$ is smooth.
Proof. Statements (1) and (2) follow immediately from the definitions. Proof of (3) omitted. Hints: use the formulation of smoothness given in Remark Smoothness in a fibre square of groupoids and use that $\mathcal{F} \times_\mathcal{G} \mathcal{G}'$ is the $2$-fibre product, see Remarks Groupoids and equivalence relations (Tensor products and direct sums). $\square$
Lemma. Existence of a versal formal object
Let $\mathcal{F}$ be a category cofibred in groupoids over $\mathcal{C}_\Lambda$. Assume the following conditions hold:
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$\mathcal{F}$ is a predeformation category.
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$\mathcal{F}$ satisfies (S1).
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$\mathcal{F}$ satisfies (S2).
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$\dim_k T\mathcal{F}$ is finite.
Then $\mathcal{F}$ has a versal formal object.
Proof. Assume (1), (2), (3), and (4) hold. Choose an object $R \in \operatorname{Ob}(\widehat{\mathcal{C}}_\Lambda)$ such that $\underline{R}|_{\mathcal{C}_\Lambda}$ is smooth. See Lemma Construction of a smooth map from a formal base. Let $r = \dim_k T\mathcal{F}$ and put $S = R[[X_1, \ldots, X_r]]$.
We are going to inductively construct for $n \geq 2$ pairs $(J_n, f_{n - 1} : \xi_n \to \xi_{n - 1})$ where $J_n \subset S$ is an decreasing sequence of ideals and $f_{n - 1} : \xi_n \to \xi_{n - 1}$ is a morphism of $\mathcal{F}$ lying over the projection $S/J_n \to S/J_{n - 1}$.
Step 1. Let $J_1 = \mathfrak m_S$. Let $\xi_1$ be the unique (up to unique isomorphism) object of $\mathcal{F}$ over $k = S/J_1 = S/\mathfrak m_S$
Step 2. Let $J_2 = \mathfrak m_S^2 + \mathfrak{m}_R S$. Then $S/J_2 = k[V]$ with $V = kX_1 \oplus \ldots \oplus kX_r$ By (S2) for $\overline{\mathcal{F}}$ we get a bijection $$\overline{\mathcal{F}}(S/J_2) \longrightarrow T\mathcal{F} \otimes_k V,$$ see Lemmas The associated deformation functor and Schlessinger's conditions and The vector-space structure on a tangent space. Choose a basis $\theta_1, \ldots, \theta_r$ for $T\mathcal{F}$ and set $\xi_2 = \sum \theta_i \otimes X_i \in \operatorname{Ob}(\mathcal{F}(S/J_2))$. The point of this choice is that $$d\xi_2 : \operatorname{Mor}_{\mathcal{C}_\Lambda}(S/J_2, k[\epsilon]) \longrightarrow T\mathcal{F}$$ is surjective. Let $f_1 : \xi_2 \to \xi_1$ be the unique morphism.
Induction step. Assume $(J_n, f_{n - 1} : \xi_n \to \xi_{n - 1})$ has been constructed for some $n \geq 2$. There is a minimal element $J_{n + 1}$ of the set of ideals $J \subset S$ satisfying: (a) $\mathfrak m_S J_n \subset J \subset J_n$ and (b) there exists a morphism $\xi_{n + 1} \to \xi_n$ lying over $S/J \to S/J_n$, see Lemma The largest closed subscheme on which a lift exists. Let $f_n : \xi_{n + 1} \to \xi_n$ be any morphism of $\mathcal{F}$ lying over $S/J_{n + 1} \to S/J_n$.
Set $J = \bigcap J_n$. Set $\overline{S} = S/J$. Set $\overline{J}_n = J_n/J$. By Lemma The maximal-ideal-adic topology the sequence of ideals $(\overline{J}_n)$ induces the $\mathfrak m_{\overline{S}}$-adic topology on $\overline{S}$. Since $(\xi_n, f_n)$ is an object of $\widehat{\mathcal{F}}_\mathcal{I}(\overline{S})$, where $\mathcal{I}$ is the filtration $(\overline{J}_n)$ of $\overline{S}$, we see that $(\xi_n, f_n)$ induces an object $\xi$ of $\widehat{\mathcal{F}}(\overline{S})$. see Lemma Independence of the filtration defining a formal object.
We prove $\xi$ is versal. For versality it suffices to check conditions (1) and (2) of Lemma A criterion for a versal formal object. Condition (1) follows from our choice of $\xi_2$ in Step 2 above. Suppose given a diagram in $\widehat{\mathcal{F}}$ $$\begin{gathered}\begin{matrix}\phantom{X} & y \\ \xi & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x \\ \xi & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}\phantom{X} & B \\ \overline{S} & A\end{matrix} \\[6pt] \begin{aligned}B & \xrightarrow{f} A \\ \overline{S} & \longrightarrow A\end{aligned}\end{gathered}$$ in $\widehat{\mathcal{C}}_\Lambda$ with $f: B \to A$ a small extension of Artinian rings. We have to show there is a map $\overline{S} \to B$ fitting into the diagram on the right. Choose $n$ such that $\overline{S} \to A$ factors through $\overline{S} \to S/J_n$. This is possible as the sequence $(\overline{J}_n)$ induces the $\mathfrak m_{\overline{S}}$-adic topology as we saw above. The pushforward of $\xi$ along $\overline{S} \to S/J_n$ is $\xi_n$. We may factor $\xi \to x$ as $\xi \to \xi_n \to x$ hence we get a diagram in $\mathcal{F}$ $$\begin{gathered}\begin{matrix}\phantom{X} & y \\ \xi_n & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x \\ \xi_n & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}\phantom{X} & B \\ S/J_n & A .\end{matrix} \\[6pt] \begin{aligned}B & \xrightarrow{f} A . \\ S/J_n & \longrightarrow A .\end{aligned}\end{gathered}$$ To check condition (2) of Lemma A criterion for a versal formal object it suffices to complete the diagram $$\begin{gathered}\begin{matrix}S/J_{n + 1} & B \\ S/J_n & A\end{matrix} \\[6pt] \begin{aligned}S/J_{n + 1} & \longrightarrow S/J_n \\ S/J_{n + 1} & \dashrightarrow B \\ B & \xrightarrow{f} A \\ S/J_n & \longrightarrow A\end{aligned}\end{gathered}$$ or equivalently, to complete the diagram $$\begin{gathered}\begin{matrix}\phantom{X} & S/J_n \times_A B \\ S/J_{n + 1} & S/J_n.\end{matrix} \\[6pt] \begin{aligned}S/J_n \times_A B & \xrightarrow{p_1} S/J_n. \\ S/J_{n + 1} & \dashrightarrow S/J_n \times_A B \\ S/J_{n + 1} & \longrightarrow S/J_n.\end{aligned}\end{gathered}$$ If $p_1$ has a section we are done. If not, by Lemma Fibre products of Artinian local deformation bases (2) $p_1$ is a small extension, so by Lemma Essential surjectivity of a smooth deformation morphism (4) $p_1$ is an essential surjection. Recall that $S = R[[X_1, \ldots, X_r]]$ and that we chose $R$ such that $\underline{R}|_{\mathcal{C}_\Lambda}$ is smooth. Hence there exists a map $h : R \to B$ lifting the map $R \to S \to S/J_n \to A$. By the universal property of a power series ring there is an $R$-algebra map $h : S = R[[X_1, \ldots, X_r]] \to B$ lifting the given map $S \to S/J_n \to A$. This induces a map $g: S \to S/J_n \times_A B$ making the solid square in the diagram $$\begin{gathered}\begin{matrix}S & S/J_n \times_A B \\ S/J_{n + 1} & S/J_n\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow S/J_{n + 1} \\ S & \xrightarrow{g} S/J_n \times_A B \\ S/J_n \times_A B & \xrightarrow{p_1} S/J_n \\ S/J_{n + 1} & \dashrightarrow S/J_n \times_A B \\ S/J_{n + 1} & \longrightarrow S/J_n\end{aligned}\end{gathered}$$ commute. Then $g$ is a surjection since $p_1$ is an essential surjection. We claim the ideal $K = \operatorname{Ker}(g)$ of $S$ satisfies conditions (a) and (b) of the construction of $J_{n + 1}$ in the induction step above. Namely, $K \subset J_n$ is clear and $\mathfrak m_SJ_n \subset K$ as $p_1$ is a small extension; this proves (a). By (S1) applied to $$\begin{gathered}\begin{matrix}\phantom{X} & y \\ \xi_n & x,\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x, \\ \xi_n & \longrightarrow x,\end{aligned}\end{gathered}$$ there exists a lifting of $\xi_n$ to $S/K \cong S/J_n \times_A B$, so (b) holds. Since $J_{n + 1}$ was the minimal ideal with properties (a) and (b) this implies $J_{n + 1} \subset K$. Thus the desired map $S/J_{n+1} \to S/K \cong S/J_n \times_A B$ exists. $\square$
Definition. Smooth morphisms of deformation categories
Let $\varphi : \mathcal{F} \to \mathcal{G}$ be a morphism of categories cofibered in groupoids over $\mathcal{C}_\Lambda$. We say $\varphi$ is smooth if it satisfies the following condition: Let $B \to A$ be a surjective ring map in $\mathcal{C}_\Lambda$. Let $y \in \operatorname{Ob}(\mathcal{G}(B)), x \in \operatorname{Ob}(\mathcal{F}(A))$, and $y \to \varphi(x)$ be a morphism lying over $B \to A$. Then there exists $x' \in \operatorname{Ob}(\mathcal{F}(B))$, a morphism $x' \to x$ lying over $B \to A$, and a morphism $\varphi(x') \to y$ lying over $\text{id}: B \to B$, such that the diagram $$\begin{gathered}\begin{matrix}\varphi(x') & y \\ \phantom{X} & \varphi(x)\end{matrix} \\[6pt] \begin{aligned}\varphi(x') & \longrightarrow y \\ \varphi(x') & \longrightarrow \varphi(x) \\ y & \longrightarrow \varphi(x)\end{aligned}\end{gathered}$$ commutes.
Remark. Smoothness in a fibre square of groupoids
Let $\varphi : \mathcal{F} \to \mathcal{G}$ be a morphism of categories cofibered in groupoids over $\mathcal{C}_\Lambda$. Let $B \to A$ be a ring map in $\mathcal{C}_\Lambda$. Choices of pushforwards along $B \to A$ for objects in the fiber categories $\mathcal{F}(B)$ and $\mathcal{G}(B)$ determine functors $\mathcal{F}(B) \to \mathcal{F}(A)$ and $\mathcal{G}(B) \to \mathcal{G}(A)$ fitting into a $2$-commutative diagram $$\begin{gathered}\begin{matrix}\mathcal{F}(B) & \mathcal{G}(B) \\ \mathcal{F}(A) & \mathcal{G}(A) .\end{matrix} \\[6pt] \begin{aligned}\mathcal{F}(B) & \xrightarrow{\varphi} \mathcal{G}(B) \\ \mathcal{F}(B) & \longrightarrow \mathcal{F}(A) \\ \mathcal{G}(B) & \longrightarrow \mathcal{G}(A) . \\ \mathcal{F}(A) & \xrightarrow{\varphi} \mathcal{G}(A) .\end{aligned}\end{gathered}$$ Hence there is an induced functor $\mathcal{F}(B) \to \mathcal{F}(A) \times_{\mathcal{G}(A)} \mathcal{G}(B)$. Unwinding the definitions shows that $\varphi : \mathcal{F} \to \mathcal{G}$ is smooth if and only if this induced functor is essentially surjective whenever $B \to A$ is surjective (or equivalently, by Lemma Testing smoothness on small extensions, whenever $B \to A$ is a small extension).
Definition. Deformation categories
A deformation category is a predeformation category $\mathcal{F}$ satisfying (RS). A morphism of deformation categories is a morphism of categories over $\mathcal{C}_\Lambda$.
Lemma. Rim--Schlessinger patching in a fibre square of groupoids
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal{C}_\Lambda$. The following are equivalent
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$\mathcal{F}$ satisfies (RS),
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the functor $\mathcal{F}(A_1 \times_A A_2) \to \mathcal{F}(A_1) \times_{\mathcal{F}(A)} \mathcal{F}(A_2)$ see (Comparison of derived quasi-coherent categories) is an equivalence of categories whenever $A_2 \to A$ is surjective, and
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same as in (2) whenever $A_2 \to A$ is a small extension.
Proof. Assume (1). By Lemma Rim–Schlessinger patching and fibre squares we see that every object of $\mathcal{F}(A_1 \times_A A_2)$ is of the form $x_1 \times_x x_2$. Moreover $$\operatorname{Mor}_{A_1 \times_A A_2}(x_1 \times_x x_2, y_1 \times_y y_2) = \operatorname{Mor}_{A_1}(x_1, y_1) \times_{\operatorname{Mor}_A(x, y)} \operatorname{Mor}_{A_2}(x_2, y_2).$$ Hence we see that $\mathcal{F}(A_1 \times_A A_2)$ is a $2$-fibre product of $\mathcal{F}(A_1)$ with $\mathcal{F}(A_2)$ over $\mathcal{F}(A)$ by Categories, Remark Tensor products and direct sums. In other words, we see that (2) holds.
The implication (2) $\Rightarrow$ (3) is immediate.
Assume (3). Let $q_1 : A_1 \to A$ and $q_2 : A_2 \to A$ be given with $q_2$ a small extension. We will use the description of the $2$-fibre product $\mathcal{F}(A_1) \times_{\mathcal{F}(A)} \mathcal{F}(A_2)$ from Categories, Remark Tensor products and direct sums. Hence let $y \in \mathcal{F}(A_1 \times_A A_2)$ correspond to $(x_1, x_2, x, a_1 : x_1 \to x, a_2 : x_2 \to x)$. Let $z$ be an object of $\mathcal{F}$ lying over $C$. Then $$\begin{aligned} \operatorname{Mor}_\mathcal{F}(z, y) & = \{(f, \alpha) \mid f : C \to A_1 \times_A A_2, \alpha : f_*z \to y\} \\ & = \{(f_1, f_2, \alpha_1, \alpha_2) \mid f_i : C \to A_i, \ \alpha_i : f_{i, *}z \to x_i, \\ & \quad\quad\quad\quad q_1 \circ f_1 = q_2 \circ f_2, \ q_{1, *} \alpha_1 = q_{2, *}\alpha_2\} \\ & = \operatorname{Mor}_\mathcal{F}(z, x_1) \times_{\operatorname{Mor}_\mathcal{F}(z, x)} \operatorname{Mor}_\mathcal{F}(z, x_2) \end{aligned}$$ whence $y$ is a fibre product of $x_1$ and $x_2$ over $x$. Thus we see that $\mathcal{F}$ satisfies (RS) in case $A_2 \to A$ is a small extension. Hence (RS) holds by Lemma Rim–Schlessinger patching for small extensions. $\square$
Lemma. Rim--Schlessinger patching implies Schlessinger's conditions
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal{C}_\Lambda$. The condition (RS) for $\mathcal{F}$ implies both (S1) and (S2) for $\mathcal{F}$.
Proof. Using the reformulation of Lemma Rim–Schlessinger patching in a fibre square of groupoids and the explanation of (S1) following Definition Schlessinger's conditions on a deformation functor it is immediate that (RS) implies (S1). This proves the first part of (S2). The second part of (S2) follows because Lemma Rim–Schlessinger patching and fibre squares tells us that $y = x_1 \times_{d, x_0, e} x_2 = y'$ if $y, y'$ are as in the second part of the definition of (S2) in Definition Schlessinger's conditions on a deformation functor. (In fact the morphism $y \to y'$ is compatible with both $a, a'$ and $c, c'$!) $\square$
Lemma. The associated deformation functor and Schlessinger's conditions
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal{C}_\Lambda$.
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If $\mathcal{F}$ satisfies (S1), then so does $\overline{\mathcal{F}}$.
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If $\mathcal{F}$ satisfies (S2), then so does $\overline{\mathcal{F}}$ provided at least one of the following conditions is satisfied
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$\mathcal{F}$ is a predeformation category,
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the category $\mathcal{F}(k)$ is a set or a setoid, or
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for any morphism $x_\epsilon \to x_0$ of $\mathcal{F}$ lying over $k[\epsilon] \to k$ the pushforward map $\text{Aut}_{k[\epsilon]}(x_\epsilon) \to \text{Aut}_k(x_0)$ is surjective.
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Proof. Assume $\mathcal{F}$ has (S1). Suppose we have ring maps $f_i : A_i \to A$ in $\mathcal{C}_\Lambda$ with $f_2$ surjective. Let $x_i \in \mathcal{F}(A_i)$ such that the pushforwards $f_{1, *}(x_1)$ and $f_{2, *}(x_2)$ are isomorphic. Then we can denote $x$ an object of $\mathcal{F}$ over $A$ isomorphic to both of these and we obtain a diagram as in (S1). Hence we find an object $y$ of $\mathcal{F}$ over $A_1 \times_A A_2$ whose pushforward to $A_1$, resp. $A_2$ is isomorphic to $x_1$, resp. $x_2$. In this way we see that (S1) holds for $\overline{\mathcal{F}}$.
Assume $\mathcal{F}$ has (S2). The first part of (S2) for $\overline{\mathcal{F}}$ follows as in the argument above. The second part of (S2) for $\overline{\mathcal{F}}$ signifies that the map $$\overline{\mathcal{F}}(A \times_k k[\epsilon]) \to \overline{\mathcal{F}}(A) \times_{\overline{\mathcal{F}}(k)} \overline{\mathcal{F}}(k[\epsilon])$$ is injective for any ring $A$ in $\mathcal{C}_\Lambda$. Suppose that $y, y' \in \mathcal{F}(A \times_k k[\epsilon])$. Using the axioms of cofibred categories we can choose commutative diagrams $$\begin{gathered}\begin{matrix}y & x_\epsilon \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y & \xrightarrow{c} x_\epsilon \\ y & \xrightarrow{a} x \\ x_\epsilon & \xrightarrow{e} x_0 \\ x & \xrightarrow{d} x_0\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}y' & x'_\epsilon \\ x' & x'_0\end{matrix} \\[6pt] \begin{aligned}y' & \xrightarrow{c'} x'_\epsilon \\ y' & \xrightarrow{a'} x' \\ x'_\epsilon & \xrightarrow{e'} x'_0 \\ x' & \xrightarrow{d'} x'_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[\epsilon] & k[\epsilon] \\ A & k\end{matrix} \\[6pt] \begin{aligned}A \times_k k[\epsilon] & \longrightarrow A \\ A \times_k k[\epsilon] & \longrightarrow k[\epsilon] \\ k[\epsilon] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ Assume that there exist isomorphisms $\alpha : x \to x'$ in $\mathcal{F}(A)$ and $\beta : x_\epsilon \to x'_\epsilon$ in $\mathcal{F}(k[\epsilon])$. This also means there exists an isomorphism $\gamma : x_0 \to x'_0$ compatible with $\alpha$. To prove (S2) for $\overline{\mathcal{F}}$ we have to show that there exists an isomorphism $y \to y'$ in $\mathcal{F}(A \times_k k[\epsilon])$. By (S2) for $\mathcal{F}$ such a morphism will exist if we can choose the isomorphisms $\alpha$ and $\beta$ and $\gamma$ such that $$\begin{gathered}\begin{matrix}x & x_0 & x_\epsilon \\ x' & x'_0 & x'_\epsilon\end{matrix} \\[6pt] \begin{aligned}x & \xrightarrow{\alpha} x' \\ x & \longrightarrow x_0 \\ x_0 & \xrightarrow{\gamma} x'_0 \\ x_\epsilon & \xrightarrow{\beta} x'_\epsilon \\ x_\epsilon & \xrightarrow{e} x_0 \\ x' & \longrightarrow x'_0 \\ x'_\epsilon & \xrightarrow{e'} x'_0\end{aligned}\end{gathered}$$ is commutative (because then we can replace $x$ by $x'$ and $x_\epsilon$ by $x'_\epsilon$ in the previous displayed diagram). The left hand square commutes by our choice of $\gamma$. We can factor $e' \circ \beta$ as $\gamma' \circ e$ for some second map $\gamma' : x_0 \to x'_0$. Now the question is whether we can arrange it so that $\gamma = \gamma'$? This is clear if $\mathcal{F}(k)$ is a set, or a setoid. Moreover, if $\text{Aut}_{k[\epsilon]}(x_\epsilon) \to \text{Aut}_k(x_0)$ is surjective, then we can adjust the choice of $\beta$ by precomposing with an automorphism of $x_\epsilon$ whose image is $\gamma^{-1} \circ \gamma'$ to make things work. $\square$
Lemma. Construction of a smooth map from a formal base
There exists an $R \in \operatorname{Ob}(\widehat{\mathcal{C}}_\Lambda)$ such that the equivalent conditions of Lemma Smooth morphisms hold and moreover $H_1(L_{k/\Lambda}) = \mathfrak m_R/\mathfrak m_R^2$ and $\Omega_{R/\Lambda} \otimes_R k = \Omega_{k/\Lambda}$.
Proof. In the classical case we choose $R = \Lambda$. More generally, if the residue field extension $k/k'$ is separable, then there exists a unique finite étale extension $\Lambda^\wedge \to R$ (Algebra, Lemmas Completion, Theorems 3.1–3.3, 4.1 and 5.1 and Finite étale algebras over a henselian ring (uncovered prerequisite)) of the completion $\Lambda^\wedge$ of $\Lambda$ inducing the extension $k/k'$ on residue fields.
In the general case we proceed as follows. Choose a smooth $\Lambda$-algebra $P$ and a $\Lambda$-algebra surjection $P \to k$. (For example, let $P$ be a polynomial algebra.) Denote $\mathfrak m_P$ the kernel of $P \to k$. The Jacobi-Zariski sequence, see (Formal deformation groupoids) and Algebra, Lemma The transitivity sequence for the naive cotangent complex (uncovered prerequisite), is an exact sequence $$0 \to H_1(\mathrm{NL}_{k/\Lambda}) \to \mathfrak m_P/\mathfrak m_P^2 \to \Omega_{P/\Lambda} \otimes_P k \to \Omega_{k/\Lambda} \to 0$$ We have the $0$ on the left because $P/k$ is smooth, hence $\mathrm{NL}_{P/\Lambda}$ is quasi-isomorphic to a finite projective module placed in degree $0$, hence $H_1(\mathrm{NL}_{P/\Lambda} \otimes_P k) = 0$. Suppose $f \in \mathfrak m_P$ maps to a nonzero element of $\Omega_{P/\Lambda} \otimes_P k$. Setting $P' = P/(f)$ we have a $\Lambda$-algebra surjection $P' \to k$. Observe that $P'$ is smooth at $\mathfrak m_{P'}$: this follows from More on Morphisms, Lemma Smooth morphisms (uncovered prerequisite). Thus after replacing $P$ by a principal localization of $P'$, we see that $\dim(\mathfrak m_P/\mathfrak m_P^2)$ decreases. Repeating finitely many times, we may assume the map $\mathfrak m_P/\mathfrak m_P^2 \to \Omega_{P/\Lambda} \otimes_P k$ is zero so that the exact sequence breaks into isomorphisms $H_1(L_{k/\Lambda}) = \mathfrak m_P/\mathfrak m_P^2$ and $\Omega_{P/\Lambda} \otimes_P k = \Omega_{k/\Lambda}$.
Let $R$ be the $\mathfrak m_P$-adic completion of $P$. Then $R$ is an object of $\widehat{\mathcal{C}}_\Lambda$. Namely, it is a complete local Noetherian ring (see Algebra, Lemma Complete rings, formal power series and Noetherian rings (uncovered prerequisite)) and its residue field is identified with $k$. We claim that $R$ works.
First observe that the map $P \to R$ induces isomorphisms $\mathfrak m_P/\mathfrak m_P^2 = \mathfrak m_R/\mathfrak m_R^2$ and $\Omega_{P/\Lambda} \otimes_P k = \Omega_{R/\Lambda} \otimes_R k$. This is true because both $\mathfrak m_P/\mathfrak m_P^2$ and $\Omega_{P/\Lambda} \otimes_P k$ only depend on the $\Lambda$-algebra $P/\mathfrak m_P^2$, see Algebra, Lemma Cotangent complexes and differentials (uncovered prerequisite), the same holds for $R$ and we have $P/\mathfrak m_P^2 = R/\mathfrak m_R^2$. Using the functoriality of the Jacobi-Zariski sequence (Formal deformation groupoids) we deduce that $H_1(L_{k/\Lambda}) = \mathfrak m_R/\mathfrak m_R^2$ and $\Omega_{R/\Lambda} \otimes_R k = \Omega_{k/\Lambda}$ as the same is true for $P$.
Finally, since $\Lambda \to P$ is smooth we see that $\Lambda \to P$ is formally smooth by Algebra, Proposition Formal smoothness of smooth algebras (uncovered prerequisite). Then $\Lambda \to P$ is formally smooth for the $\mathfrak m_P$-adic topology by More on Algebra, Lemma Formal smoothness and smooth morphisms. This property is inherited by the completion $R$ by More on Algebra, Lemma Formal smoothness and completion and the proof is complete. In fact, it turns out that whenever $\underline{R}|_{\mathcal{C}_\Lambda}$ is smooth, then $R$ is isomorphic to a completion of a smooth algebra over $\Lambda$, but we won't use this. $\square$
Lemma. The vector-space structure on a tangent space
Let $\mathcal{F}$ be a predeformation category such that $\overline{\mathcal{F}}$ satisfies (S2)[^1]. Then $T \mathcal{F}$ has a natural $k$-vector space structure. For any finite dimensional vector space $V$ we have $\overline{\mathcal{F}}(k[V]) = T\mathcal{F} \otimes_k V$ functorially in $V$.
Proof. Let us write $F = \overline{\mathcal{F}} : \mathcal{C}_\Lambda \to \textit{Sets}$. This is a predeformation functor and $F$ satisfies (S2). By Lemma The tangent condition for a small extension (and the translation of Remark Comparison with Schlessinger's conditions) we see that $$F(A \times_k k[V]) \longrightarrow F(A) \times F(k[V])$$ is a bijection for every finite dimensional vector space $V$ and every $A \in \operatorname{Ob}(\mathcal{C}_\Lambda)$. In particular, if $A = k[W]$ then we see that $F(k[W] \times_k k[V]) = F(k[W]) \times F(k[V])$. In other words, the hypotheses of Lemma The tangent-space functor hold and we see that $TF = T \mathcal{F}$ has a natural $k$-vector space structure. The final assertion follows from Lemma The tangent functor and tensor products. $\square$
Lemma. The largest closed subscheme on which a lift exists
Let $\mathcal{F}$ be a category cofibred in groupoids over $\mathcal{C}_\Lambda$ which has (S1). Let $B \to A$ be a surjection in $\mathcal{C}_\Lambda$ with kernel $I$ annihilated by $\mathfrak m_B$. Let $x \in \mathcal{F}(A)$. The set of ideals $$\mathcal{J} = \{ J \subset I \mid \text{there exists an }y \to x\text{ lying over }B/J \to A\}$$ has a smallest element.
Proof. Note that $\mathcal{J}$ is nonempty as $I \in \mathcal{J}$. Also, if $J \in \mathcal{J}$ and $J \subset J' \subset I$ then $J' \in \mathcal{J}$ because we can pushforward the object $y$ to an object $y'$ over $B/J'$. Let $J$ and $K$ be elements of the displayed set. We claim that $J \cap K \in \mathcal{J}$ which will prove the lemma. Since $I$ is a $k$-vector space we can find an ideal $J \subset J' \subset I$ such that $J \cap K = J' \cap K$ and such that $J' + K = I$. By the above we may replace $J$ by $J'$ and assume that $J + K = I$. In this case $$A/(J \cap K) = A/J \times_{A/I} A/K.$$ Hence the existence of an element $z \in \mathcal{F}(A/(J \cap K))$ mapping to $x$ follows, via (S1), from the existence of the elements we have assumed exist over $A/J$ and $A/K$. $\square$
Lemma. The maximal-ideal-adic topology
Let $R$ be an object of $\widehat{\mathcal{C}}_\Lambda$. Let $(J_n)$ be a decreasing sequence of ideals such that $\mathfrak m_R^n \subset J_n$. Set $J = \bigcap J_n$. Then the sequence $(J_n/J)$ defines the $\mathfrak m_{R/J}$-adic topology on $R/J$.
Proof. It is clear that $\mathfrak m_{R/J}^n \subset J_n/J$. Thus it suffices to show that for every $n$ there exists an $N$ such that $J_N/J \subset \mathfrak m_{R/J}^n$. This is equivalent to $J_N \subset \mathfrak m_R^n + J$. For each $n$ the ring $R/\mathfrak m_R^n$ is Artinian, hence there exists a $N_n$ such that $$J_{N_n} + \mathfrak m_R^n = J_{N_n + 1} + \mathfrak m_R^n = \ldots$$ Set $E_n = (J_{N_n} + \mathfrak m_R^n)/\mathfrak m_R^n$. Set $E = \varprojlim E_n \subset \varprojlim R/\mathfrak m_R^n = R$. Note that $E \subset J$ as for any $f \in E$ and any $m$ we have $f \in J_m + \mathfrak m_R^n$ for all $n \gg 0$, so $f \in J_m$ by Krull's intersection theorem, see Algebra, Lemma Krull's intersection theorem (uncovered prerequisite). Since the transition maps $E_n \to E_{n - 1}$ are all surjective, we see that $J$ surjects onto $E_n$. Hence for $N = N_n$ works. $\square$
Lemma. Independence of the filtration defining a formal object
In the situation above, $\widehat{\mathcal{F}}_\mathcal{I}(R)$ is equivalent to the category $\widehat{\mathcal{F}}(R)$.
Proof. An equivalence $\widehat{\mathcal{F}}_\mathcal{I}(R) \to \widehat{\mathcal{F}}(R)$ can be defined as follows. For each $n$, let $m(n)$ be the least $m$ that $I_m \subset \mathfrak m_R^n$. Given an object $(\xi_n, f_n)$ of $\widehat{\mathcal{F}}_\mathcal{I}(R)$, let $\eta_n$ be the pushforward of $\xi_{m(n)}$ along $R/I_{m(n)} \to R/\mathfrak m_R^n$. Let $g_n : \eta_{n + 1} \to \eta_n$ be the unique morphism of $\mathcal{F}$ lying over $R/\mathfrak m_R^{n + 1} \to R/\mathfrak m_R^n$ such that $$\begin{gathered}\begin{matrix}\xi_{m(n + 1)} & \phantom{X} & \phantom{X} & \xi_{m(n)} \\ \eta_{n + 1} & \phantom{X} & \phantom{X} & \eta_n\end{matrix} \\[6pt] \begin{aligned}\xi_{m(n + 1)} & \xrightarrow{f_{m(n)} \circ \ldots \circ f_{m(n + 1) - 1}} \xi_{m(n)} \\ \xi_{m(n + 1)} & \longrightarrow \eta_{n + 1} \\ \xi_{m(n)} & \longrightarrow \eta_n \\ \eta_{n + 1} & \xrightarrow{g_n} \eta_n\end{aligned}\end{gathered}$$ commutes (existence and uniqueness is guaranteed by the axioms of a cofibred category). The functor $\widehat{\mathcal{F}}_\mathcal{I}(R) \to \widehat{\mathcal{F}}(R)$ sends $(\xi_n, f_n)$ to $(R, \eta_n, g_n)$. We omit the verification that this is indeed an equivalence of categories. $\square$
Lemma. A criterion for a versal formal object
Let $\mathcal{F}$ be a predeformation category satisfying (S1) and (S2). Let $\xi$ be a formal object of $\mathcal{F}$ corresponding to $\underline{\xi} : \underline{R}|_{\mathcal{C}_\Lambda} \to \mathcal{F}$, see Remark Formal objects and the Yoneda correspondence. Then $\xi$ is versal if and only if the following two conditions hold:
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the map $d\underline{\xi} : T\underline{R}|_{\mathcal{C}_\Lambda} \to T\mathcal{F}$ on tangent spaces is surjective, and
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given a diagram in $\widehat{\mathcal{F}}$ $$\begin{gathered}\begin{matrix}\phantom{X} & y \\ \xi & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x \\ \xi & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}\phantom{X} & B \\ R & A\end{matrix} \\[6pt] \begin{aligned}B & \xrightarrow{f} A \\ R & \longrightarrow A\end{aligned}\end{gathered}$$ in $\widehat{\mathcal{C}}_\Lambda$ with $B \to A$ a small extension of Artinian rings, then there exists a ring map $R \to B$ such that $$\begin{gathered}\begin{matrix}\phantom{X} & B \\ R & A\end{matrix} \\[6pt] \begin{aligned}B & \xrightarrow{f} A \\ R & \longrightarrow B \\ R & \longrightarrow A\end{aligned}\end{gathered}$$ commutes.
Proof. If $\xi$ is versal then (1) holds by Lemma Essential surjectivity of a smooth deformation morphism and (2) holds by Remark Versal formal objects. Assume (1) and (2) hold. By Remark Versal formal objects we must show that given a diagram in $\widehat{\mathcal{F}}$ as in (2), there exists $\xi \to y$ such that $$\begin{gathered}\begin{matrix}\phantom{X} & y \\ \xi & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x \\ \xi & \longrightarrow y \\ \xi & \longrightarrow x\end{aligned}\end{gathered}$$ commutes. Let $b : R \to B$ be the map guaranteed by (2). Denote $y' = b_*\xi$ and choose a factorization $\xi \to y' \to x$ lying over $R \to B \to A$ of the given morphism $\xi \to x$. By (S1) we obtain a commutative diagram $$\begin{gathered}\begin{matrix}z & y \\ y' & x\end{matrix} \\[6pt] \begin{aligned}z & \longrightarrow y \\ z & \longrightarrow y' \\ y & \longrightarrow x \\ y' & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}B \times_A B & B \\ B & A .\end{matrix} \\[6pt] \begin{aligned}B \times_A B & \longrightarrow B \\ B \times_A B & \longrightarrow B \\ B & \xrightarrow{f} A . \\ B & \xrightarrow{f} A .\end{aligned}\end{gathered}$$ Set $I = \operatorname{Ker}(f)$. Let $\overline{g} : B \times_A B \to k[I]$ be the ring map $(u, v) \mapsto \overline{u} \oplus (v - u)$, cf. Lemma Lifting a deformation along a small extension. By (1) there exists a morphism $\xi \to \overline{g}_*z$ which lies over a ring map $i : R \to k[\epsilon]$. Choose an Artinian quotient $b_1 : R \to B_1$ such that both $b : R \to B$ and $i : R \to k[\epsilon]$ factor through $R \to B_1$, i.e., giving $h : B_1 \to B$ and $i' : B_1 \to k[\epsilon]$. Choose a pushforward $y_1 = b_{1, *}\xi$, a factorization $\xi \to y_1 \to y'$ lying over $R \to B_1 \to B$ of $\xi \to y'$, and a factorization $\xi \to y_1 \to \overline{g}_*z$ lying over $R \to B_1 \to k[\epsilon]$ of $\xi \to \overline{g}_*z$. Applying (S1) once more we obtain $$\begin{gathered}\begin{matrix}z_1 & z & y \\ y_1 & y' & x\end{matrix} \\[6pt] \begin{aligned}z_1 & \longrightarrow z \\ z_1 & \longrightarrow y_1 \\ z & \longrightarrow y \\ z & \longrightarrow y' \\ y & \longrightarrow x \\ y_1 & \longrightarrow y' \\ y' & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}B_1 \times_A B & B \times_A B & B \\ B_1 & B & A .\end{matrix} \\[6pt] \begin{aligned}B_1 \times_A B & \longrightarrow B_1 \\ B_1 \times_A B & \longrightarrow B \times_A B \\ B \times_A B & \longrightarrow B \\ B \times_A B & \longrightarrow B \\ B & \xrightarrow{f} A . \\ B_1 & \longrightarrow B \\ B & \longrightarrow A .\end{aligned}\end{gathered}$$ Note that the map $g : B_1 \times_A B \to k[I]$ of Lemma Lifting a deformation along a small extension (defined using $h$) is the composition of $B_1 \times_A B \to B \times_A B$ and the map $\overline{g}$ above. By construction there exists a morphism $y_1 \to g_*z_1 \cong \overline{g}_*z$! Hence Lemma Lifting a deformation along a small extension applies (to the outer rectangles in the diagrams above) to give a morphism $y_1 \to y$ and precomposing with $\xi \to y_1$ gives the desired morphism $\xi \to y$. $\square$
Lemma. Fibre products of Artinian local deformation bases
Let $f_1 : A_1 \to A$ and $f_2 : A_2 \to A$ be ring maps in $\mathcal{C}_\Lambda$. Then:
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If $f_1$ or $f_2$ is surjective, then $A_1 \times_A A_2$ is in $\mathcal{C}_\Lambda$.
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If $f_2$ is a small extension, then so is $A_1 \times_A A_2 \to A_1$.
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If the field extension $k/k'$ is separable, then $A_1 \times_A A_2$ is in $\mathcal{C}_\Lambda$.
Proof. The ring $A_1 \times_A A_2$ is a $\Lambda$-algebra via the map $\Lambda \to A_1 \times_A A_2$ induced by the maps $\Lambda \to A_1$ and $\Lambda \to A_2$. It is a local ring with unique maximal ideal $$\mathfrak m_{A_1} \times_{\mathfrak m_A} \mathfrak m_{A_2} = \operatorname{Ker}(A_1 \times_A A_2 \longrightarrow k)$$ A ring is Artinian if and only if it has finite length as a module over itself, see Algebra, Lemma Finite length over an Artinian ring (uncovered prerequisite). Since $A_1$ and $A_2$ are Artinian, Lemma Induction on the length of an Artinian deformation base implies $\text{length}_\Lambda(A_1)$ and $\text{length}_\Lambda(A_2)$, and hence $\text{length}_\Lambda(A_1 \times A_2)$, are all finite. As $A_1 \times_A A_2 \subset A_1 \times A_2$ is a $\Lambda$-submodule, this implies $\text{length}_{A_1 \times_A A_2}(A_1 \times_A A_2) \leq \text{length}_\Lambda(A_1 \times_A A_2)$ is finite. So $A_1 \times_A A_2$ is Artinian. Thus the only thing that is keeping $A_1 \times_A A_2$ from being an object of $\mathcal{C}_\Lambda$ is the possibility that its residue field maps to a proper subfield of $k$ via the map $A_1 \times_A A_2 \to A \to A/\mathfrak m_A = k$ above.
Proof of (1). If $f_2$ is surjective, then the projection $A_1 \times_A A_2 \to A_1$ is surjective. Hence the composition $A_1 \times_A A_2 \to A_1 \to A_1/\mathfrak m_{A_1} = k$ is surjective and we conclude that $A_1 \times_A A_2$ is an object of $\mathcal{C}_\Lambda$.
Proof of (2). If $f_2$ is a small extension then $A_2 \to A$ and $A_1 \times_A A_2 \to A_1$ are both surjective with the same kernel. Hence the kernel of $A_1 \times_A A_2 \to A_1$ is a $1$-dimensional $k$-vector space and we see that $A_1 \times_A A_2 \to A_1$ is a small extension.
Proof of (3). Choose $\overline{x} \in k$ such that $k = k'(\overline{x})$ (see Fields, Lemma The geometric construction (uncovered prerequisite)). Let $P'(T) \in k'[T]$ be the minimal polynomial of $\overline{x}$ over $k'$. Since $k/k'$ is separable we see that $\text{d}P/\text{d}T(\overline{x}) \not = 0$. Choose a monic $P \in \Lambda[T]$ which maps to $P'$ under the surjective map $\Lambda[T] \to k'[T]$. Because $A, A_1, A_2$ are henselian, see Algebra, Lemma Henselianity in local dimension zero (uncovered prerequisite), we can find $x, x_1, x_2 \in A, A_1, A_2$ with $P(x) = 0, P(x_1) = 0, P(x_2) = 0$ and such that the image of $x, x_1, x_2$ in $k$ is $\overline{x}$. Then $(x_1, x_2) \in A_1 \times_A A_2$ because $x_1, x_2$ map to $x \in A$ by uniqueness, see Algebra, Lemma Uniqueness of an étale lifting (uncovered prerequisite). Hence the residue field of $A_1 \times_A A_2$ contains a generator of $k$ over $k'$ and we win. $\square$
Lemma. Essential surjectivity of a smooth deformation morphism
Let $f: B \to A$ be a ring map in $\mathcal{C}_\Lambda$. Notation as in (Formal deformation groupoids).
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The equivalent conditions of Lemma Formal deformation groupoids characterizing when $f$ is surjective are also equivalent to
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$\operatorname{Im}(\text{d}_B) \to \operatorname{Im}(\text{d}_A)$ is surjective, and
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the map $\Omega_{B/\Lambda} \otimes_B k \to \Omega_{A/\Lambda} \otimes_A k$ is surjective.
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The following are equivalent
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$f$ is an essential surjection (see Lemma Essential surjectivity modulo squares of maximal ideals),
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the map $\operatorname{Im}(\text{d}_B) \to \operatorname{Im}(\text{d}_A)$ is an isomorphism, and
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the map $\Omega_{B/\Lambda} \otimes_B k \to \Omega_{A/\Lambda} \otimes_A k$ is an isomorphism.
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If $k/k'$ is separable, then $f$ is an essential surjection if and only if the map $\mathfrak m_B/(\mathfrak m_\Lambda B + \mathfrak m_B^2) \to \mathfrak m_A/(\mathfrak m_\Lambda A + \mathfrak m_A^2)$ is an isomorphism.
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If $f$ is a small extension, then $f$ is not essential if and only if $f$ has a section $s: A \to B$ in $\mathcal{C}_\Lambda$ with $f \circ s = \text{id}_A$.
Proof. Proof of (1). It follows from (Formal deformation groupoids) that (1)(a) and (1)(b) are equivalent. Also, if $A \to B$ is surjective, then (1)(a) and (1)(b) hold. Assume (1)(a). Since the kernel of $\text{d}_A$ is the image of $H_1(L_{k/\Lambda})$ which also maps to $\mathfrak m_B/\mathfrak m_B^2$ we conclude that $\mathfrak m_B/\mathfrak m_B^2 \to \mathfrak m_A/\mathfrak m_A^2$ is surjective. Hence $B \to A$ is surjective by Lemma Formal deformation groupoids. This finishes the proof of (1).
Proof of (2). The equivalence of (2)(b) and (2)(c) is immediate from (Formal deformation groupoids).
Assume (2)(b). Let $g : C \to B$ be a ring map in $\mathcal{C}_\Lambda$ such that $f \circ g$ is surjective. We conclude that $\mathfrak m_C/\mathfrak m_C^2 \to \mathfrak m_A/\mathfrak m_A^2$ is surjective by Lemma Formal deformation groupoids. Hence $\operatorname{Im}(\text{d}_C) \to \operatorname{Im}(\text{d}_A)$ is surjective and by the assumption we see that $\operatorname{Im}(\text{d}_C) \to \operatorname{Im}(\text{d}_B)$ is surjective. It follows that $C \to B$ is surjective by (1).
Assume (2)(a). Then $f$ is surjective and we see that $\Omega_{B/\Lambda} \otimes_B k \to \Omega_{A/\Lambda} \otimes_A k$ is surjective. Let $K$ be the kernel. Note that $K = \text{d}_B(\operatorname{Ker}(\mathfrak m_B/\mathfrak m_B^2 \to \mathfrak m_A/\mathfrak m_A^2))$ by (Formal deformation groupoids). Choose a splitting $$\Omega_{B/\Lambda} \otimes_B k = \Omega_{A/\Lambda} \otimes_A k \oplus K$$ of $k$-vector space. The map $\text{d} : B \to \Omega_{B/\Lambda}$ induces via the projection onto $K$ a map $D : B \to K$. Set $C = \{b \in B \mid D(b) = 0\}$. The Leibniz rule shows that this is a $\Lambda$-subalgebra of $B$. Let $\overline{x} \in k$. Choose $x \in B$ mapping to $\overline{x}$. If $D(x) \not = 0$, then we can find an element $y \in \mathfrak m_B$ such that $D(y) = D(x)$. Hence $x - y \in C$ is an element which maps to $\overline{x}$. Thus $C \to k$ is surjective and $C$ is an object of $\mathcal{C}_\Lambda$. Similarly, pick $\omega \in \operatorname{Im}(\text{d}_A)$. We can find $x \in \mathfrak m_B$ such that $\text{d}_B(x)$ maps to $\omega$ by (1). If $D(x) \not = 0$, then we can find an element $y \in \mathfrak m_B$ which maps to zero in $\mathfrak m_A/\mathfrak m_A^2$ such that $D(y) = D(x)$. Hence $z = x - y$ is an element of $\mathfrak m_C$ whose image $\text{d}_C(z) \in \Omega_{C/k} \otimes_C k$ maps to $\omega$. Hence $\operatorname{Im}(\text{d}_C) \to \operatorname{Im}(\text{d}_A)$ is surjective. We conclude that $C \to A$ is surjective by (1). Hence $C \to B$ is surjective by assumption. Hence $D = 0$, i.e., $K = 0$, i.e., (2)(c) holds. This finishes the proof of (2).
Proof of (3). If $k'/k$ is separable, then $H_1(L_{k/\Lambda}) = \mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k$, see Lemma First cotangent homology in the separable case. Hence $\operatorname{Im}(\text{d}_A) = \mathfrak m_A/(\mathfrak m_\Lambda A + \mathfrak m_A^2)$ and similarly for $B$. Thus (3) follows from (2).
Proof of (4). A section $s$ of $f$ is not surjective (by definition a small extension has nontrivial kernel), hence $f$ is not essentially surjective. Conversely, assume $f$ is a small extension but not an essential surjection. Choose a ring map $C \to B$ in $\mathcal{C}_\Lambda$ which is not surjective, such that $C \to A$ is surjective. Let $C' \subset B$ be the image of $C \to B$. Then $C' \not = B$ but $C'$ surjects onto $A$. Since $f : B \to A$ is a small extension, $\text{length}_C(B) = \text{length}_C(A) + 1$. Thus $\text{length}_C(C') \leq \text{length}_C(A)$ since $C'$ is a proper subring of $B$. But $C' \to A$ is surjective, so in fact we must have $\text{length}_C(C') = \text{length}_C(A)$ and $C' \to A$ is an isomorphism which gives us our section. $\square$
Lemma. Testing smoothness on small extensions
Let $\varphi : \mathcal{F} \to \mathcal{G}$ be a morphism of categories cofibered in groupoids over $\mathcal{C}_\Lambda$. Then $\varphi$ is smooth if the condition in Definition Smooth morphisms of deformation categories is assumed to hold only for small extensions $B \to A$.
Proof. Let $B \to A$ be a surjective ring map in $\mathcal{C}_\Lambda$. Let $y \in \operatorname{Ob}(\mathcal{G}(B))$, $x \in \operatorname{Ob}(\mathcal{F}(A))$, and $y \to \varphi(x)$ be a morphism lying over $B \to A$. By Lemma Factoring a surjection into small extensions we can factor $B \to A$ into small extensions $B = B_n \to B_{n-1} \to \ldots \to B_0 = A$. We argue by induction on $n$. If $n = 1$ the result is true by assumption. If $n > 1$, then denote $f : B = B_n \to B_{n - 1}$ and denote $g : B_{n - 1} \to B_0 = A$. Choose a pushforward $y \to f_* y$ of $y$ along $f$, so that the morphism $y \to \varphi(x)$ factors as $y \to f_* y \to \varphi(x)$. By the induction hypothesis we can find $x_{n - 1} \to x$ lying over $g : B_{n - 1} \to A$ and $a : \varphi(x_{n - 1}) \to f_*y$ lying over $\text{id} : B_{n - 1} \to B_{n - 1}$ such that $$\begin{gathered}\begin{matrix}\varphi(x_{n - 1}) & f_*y \\ \phantom{X} & \varphi(x)\end{matrix} \\[6pt] \begin{aligned}\varphi(x_{n - 1}) & \xrightarrow{a} f_*y \\ \varphi(x_{n - 1}) & \longrightarrow \varphi(x) \\ f_*y & \longrightarrow \varphi(x)\end{aligned}\end{gathered}$$ commutes. We can apply the assumption to the composition $y \to \varphi(x_{n - 1})$ of $y \to f_*y$ with $a^{-1} : f_*y \to \varphi(x_{n - 1})$. We obtain $x_n \to x_{n - 1}$ lying over $B_n \to B_{n - 1}$ and $\varphi(x_n) \to y$ lying over $\text{id} : B_n \to B_n$ so that the diagram $$\begin{gathered}\begin{matrix}\varphi(x_n) & y \\ \varphi(x_{n - 1}) & f_*y \\ \phantom{X} & \varphi(x)\end{matrix} \\[6pt] \begin{aligned}\varphi(x_n) & \longrightarrow y \\ \varphi(x_n) & \longrightarrow \varphi(x_{n - 1}) \\ y & \longrightarrow f_*y \\ \varphi(x_{n - 1}) & \xrightarrow{a} f_*y \\ \varphi(x_{n - 1}) & \longrightarrow \varphi(x) \\ f_*y & \longrightarrow \varphi(x)\end{aligned}\end{gathered}$$ commutes. Then the composition $x_n \to x_{n - 1} \to x$ and $\varphi(x_n) \to y$ are the morphisms required by the definition of smoothness. $\square$
Lemma. Rim--Schlessinger patching and fibre squares
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal{C}_\Lambda$ satisfying (RS). Given a commutative diagram in $\mathcal{F}$ $$\begin{gathered}\begin{matrix}y & x_2 \\ x_1 & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x_2 \\ y & \longrightarrow x_1 \\ x_2 & \longrightarrow x \\ x_1 & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A_1 \times_A A_2 & A_2 \\ A_1 & A.\end{matrix} \\[6pt] \begin{aligned}A_1 \times_A A_2 & \longrightarrow A_2 \\ A_1 \times_A A_2 & \longrightarrow A_1 \\ A_2 & \longrightarrow A. \\ A_1 & \longrightarrow A.\end{aligned}\end{gathered}$$ with $A_2 \to A$ surjective, then it is a fiber square.
Proof. Since $\mathcal{F}$ satisfies (RS), there exists a fiber product diagram $$\begin{gathered}\begin{matrix}x_1 \times_x x_2 & x_2 \\ x_1 & x\end{matrix} \\[6pt] \begin{aligned}x_1 \times_x x_2 & \longrightarrow x_2 \\ x_1 \times_x x_2 & \longrightarrow x_1 \\ x_2 & \longrightarrow x \\ x_1 & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A_1 \times_A A_2 & A_2 \\ A_1 & A.\end{matrix} \\[6pt] \begin{aligned}A_1 \times_A A_2 & \longrightarrow A_2 \\ A_1 \times_A A_2 & \longrightarrow A_1 \\ A_2 & \longrightarrow A. \\ A_1 & \longrightarrow A.\end{aligned}\end{gathered}$$ The induced map $y \to x_1 \times_x x_2$ lies over $\text{id} : A_1 \times_A A_1 \to A_1 \times_A A_1$, hence it is an isomorphism. $\square$
Lemma. Rim--Schlessinger patching for small extensions
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal C_\Lambda$. Then $\mathcal{F}$ satisfies (RS) if the condition in Definition Rim–Schlessinger patching is assumed to hold only when $A_2 \to A$ is a small extension.
Proof. Apply Lemma Factoring a surjection into small extensions. The proof is similar to that of Lemma Testing smoothness on small extensions. $\square$
Definition. Schlessinger's conditions on a deformation functor
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal C_\Lambda$. We define conditions (S1) and (S2) on $\mathcal{F}$ as follows:
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Every diagram in $\mathcal{F}$ $$\begin{gathered}\begin{matrix}\phantom{X} & x_2 \\ x_1 & x\end{matrix} \\[6pt] \begin{aligned}x_2 & \longrightarrow x \\ x_1 & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}\phantom{X} & A_2 \\ A_1 & A\end{matrix} \\[6pt] \begin{aligned}A_2 & \longrightarrow A \\ A_1 & \longrightarrow A\end{aligned}\end{gathered}$$ in $\mathcal{C}_\Lambda$ with $A_2 \to A$ surjective can be completed to a commutative diagram $$\begin{gathered}\begin{matrix}y & x_2 \\ x_1 & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x_2 \\ y & \longrightarrow x_1 \\ x_2 & \longrightarrow x \\ x_1 & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A_1 \times_A A_2 & A_2 \\ A_1 & A.\end{matrix} \\[6pt] \begin{aligned}A_1 \times_A A_2 & \longrightarrow A_2 \\ A_1 \times_A A_2 & \longrightarrow A_1 \\ A_2 & \longrightarrow A. \\ A_1 & \longrightarrow A.\end{aligned}\end{gathered}$$
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The condition of (S1) holds for diagrams in $\mathcal{F}$ lying over a diagram in $\mathcal{C}_\Lambda$ of the form $$\begin{gathered}\begin{matrix}\phantom{X} & k[\epsilon] \\ A & k.\end{matrix} \\[6pt] \begin{aligned}k[\epsilon] & \longrightarrow k. \\ A & \longrightarrow k.\end{aligned}\end{gathered}$$ Moreover, if we have two commutative diagrams in $\mathcal{F}$ $$\begin{gathered}\begin{matrix}y & x_\epsilon \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y & \xrightarrow{c} x_\epsilon \\ y & \xrightarrow{a} x \\ x_\epsilon & \xrightarrow{e} x_0 \\ x & \xrightarrow{d} x_0\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}y' & x_\epsilon \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y' & \xrightarrow{c'} x_\epsilon \\ y' & \xrightarrow{a'} x \\ x_\epsilon & \xrightarrow{e} x_0 \\ x & \xrightarrow{d} x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[\epsilon] & k[\epsilon] \\ A & k\end{matrix} \\[6pt] \begin{aligned}A \times_k k[\epsilon] & \longrightarrow k[\epsilon] \\ A \times_k k[\epsilon] & \longrightarrow A \\ k[\epsilon] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ then there exists a morphism $b : y \to y'$ in $\mathcal{F}(A \times_k k[\epsilon])$ such that $a = a' \circ b$.
Lemma. Smooth morphisms
Let $R \in \operatorname{Ob}(\widehat{\mathcal{C}}_\Lambda)$. The following are equivalent
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$\underline{R}|_{\mathcal{C}_\Lambda}$ is smooth,
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$\Lambda \to R$ is formally smooth in the $\mathfrak m_R$-adic topology,
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$\Lambda \to R$ is flat and $R \otimes_\Lambda k'$ is geometrically regular over $k'$, and
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$\Lambda \to R$ is flat and $k' \to R \otimes_\Lambda k'$ is formally smooth in the $\mathfrak m_R$-adic topology.
In the classical case, these are also equivalent to
- $R$ is isomorphic to $\Lambda[[x_1, \ldots, x_n]]$ for some $n$.
Proof. Smoothness of $p : \underline{R}|_{\mathcal{C}_\Lambda} \to \mathcal{C}_\Lambda$ means that given $B \to A$ surjective in $\mathcal{C}_\Lambda$ and given $R \to A$ we can find the dotted arrow in the diagram $$\begin{gathered}\begin{matrix}R & A \\ \Lambda & B\end{matrix} \\[6pt] \begin{aligned}R & \longrightarrow A \\ R & \dashrightarrow B \\ \Lambda & \longrightarrow B \\ \Lambda & \longrightarrow R \\ B & \longrightarrow A\end{aligned}\end{gathered}$$ This is certainly true if $\Lambda \to R$ is formally smooth in the $\mathfrak m_R$-adic topology, see More on Algebra, Definitions Adically formally smooth ring maps and Formally smooth ring maps. Conversely, if this holds, then we see that $\Lambda \to R$ is formally smooth in the $\mathfrak m_R$-adic topology by More on Algebra, Lemma Formal smoothness and local algebra. Thus (1) and (2) are equivalent.
The equivalence of (2), (3), and (4) is More on Algebra, Proposition Formal smoothness from flatness and formally smooth fibres. The equivalence with (5) follows for example from Lemma Smooth formal morphisms and power-series rings and the fact that $\mathcal{C}_\Lambda$ is the same as $\underline{\Lambda}|_{\mathcal{C}_\Lambda}$ in the classical case. $\square$
Lemma. The tangent condition for a small extension
Let $\mathcal{F}$ be a category cofibred in groupoids over $\mathcal{C}_\Lambda$. If $\mathcal{F}$ satisfies (S2), then the condition of (S2) also holds when $k[\epsilon]$ is replaced by $k[V]$ for any finite dimensional $k$-vector space $V$.
Proof. In the case that $\mathcal{F}$ is cofibred in sets, i.e., corresponds to a functor $F : \mathcal{C}_\Lambda \to \textit{Sets}$ this follows from the description of (S2) for $F$ in Remark Comparison with Schlessinger's conditions and the fact that $k[V] \cong k[\epsilon] \times_k \ldots \times_k k[\epsilon]$ with $\dim_k V$ factors. The case of functors is what we will use in the rest of this chapter.
We prove the general case by induction on $\dim(V)$. If $\dim(V) = 1$, then $k[V] \cong k[\epsilon]$ and the result holds by assumption. If $\dim(V) > 1$ we write $V = V' \oplus k\epsilon$. Pick a diagram $$\begin{gathered}\begin{matrix}\phantom{X} & x_V \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}x_V & \longrightarrow x_0 \\ x & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}\phantom{X} & k[V] \\ A & k\end{matrix} \\[6pt] \begin{aligned}k[V] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ Choose a morphism $x_V \to x_{V'}$ lying over $k[V] \to k[V']$ and a morphism $x_V \to x_\epsilon$ lying over $k[V] \to k[\epsilon]$. Note that the morphism $x_V \to x_0$ factors as $x_V \to x_{V'} \to x_0$ and as $x_V \to x_\epsilon \to x_0$. By induction hypothesis we can find a diagram $$\begin{gathered}\begin{matrix}y' & x_{V'} \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y' & \longrightarrow x \\ y' & \longrightarrow x_{V'} \\ x_{V'} & \longrightarrow x_0 \\ x & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[V'] & k[V'] \\ A & k\end{matrix} \\[6pt] \begin{aligned}A \times_k k[V'] & \longrightarrow A \\ A \times_k k[V'] & \longrightarrow k[V'] \\ k[V'] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ This gives us a commutative diagram $$\begin{gathered}\begin{matrix}\phantom{X} & x_\epsilon \\ y' & x_0\end{matrix} \\[6pt] \begin{aligned}x_\epsilon & \longrightarrow x_0 \\ y' & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}\phantom{X} & k[\epsilon] \\ A \times_k k[V'] & k\end{matrix} \\[6pt] \begin{aligned}k[\epsilon] & \longrightarrow k \\ A \times_k k[V'] & \longrightarrow k\end{aligned}\end{gathered}$$ Hence by (S2) we get a commutative diagram $$\begin{gathered}\begin{matrix}y & x_\epsilon \\ y' & x_0\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow y' \\ y & \longrightarrow x_\epsilon \\ x_\epsilon & \longrightarrow x_0 \\ y' & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}(A \times_k k[V']) \times_k k[\epsilon] & k[\epsilon] \\ A \times_k k[V'] & k\end{matrix} \\[6pt] \begin{aligned}(A \times_k k[V']) \times_k k[\epsilon] & \longrightarrow A \times_k k[V'] \\ (A \times_k k[V']) \times_k k[\epsilon] & \longrightarrow k[\epsilon] \\ k[\epsilon] & \longrightarrow k \\ A \times_k k[V'] & \longrightarrow k\end{aligned}\end{gathered}$$ Note that $(A \times_k k[V']) \times_k k[\epsilon] = A \times_k k[V' \oplus k\epsilon] = A \times_k k[V]$. We claim that $y$ fits into the correct commutative diagram. To see this we let $y \to y_V$ be a morphism lying over $A \times_k k[V] \to k[V]$. We can factor the morphisms $y \to y' \to x_{V'}$ and $y \to x_\epsilon$ through the morphism $y \to y_V$ (by the axioms of categories cofibred in groupoids). Hence we see that both $y_V$ and $x_V$ fit into commutative diagrams $$\begin{gathered}\begin{matrix}y_V & x_\epsilon \\ x_{V'} & x_0\end{matrix} \\[6pt] \begin{aligned}y_V & \longrightarrow x_\epsilon \\ y_V & \longrightarrow x_{V'} \\ x_\epsilon & \longrightarrow x_0 \\ x_{V'} & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}x_V & x_\epsilon \\ x_{V'} & x_0\end{matrix} \\[6pt] \begin{aligned}x_V & \longrightarrow x_\epsilon \\ x_V & \longrightarrow x_{V'} \\ x_\epsilon & \longrightarrow x_0 \\ x_{V'} & \longrightarrow x_0\end{aligned}\end{gathered}$$ and hence by the second part of (S2) there exists an isomorphism $y_V \to x_V$ compatible with $y_V \to x_{V'}$ and $x_V \to x_{V'}$ and in particular compatible with the maps to $x_0$. The composition $y \to y_V \to x_V$ then fits into the required commutative diagram $$\begin{gathered}\begin{matrix}y & x_V \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x_V \\ y & \longrightarrow x \\ x_V & \longrightarrow x_0 \\ x & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[V] & k[V] \\ A & k\end{matrix} \\[6pt] \begin{aligned}A \times_k k[V] & \longrightarrow A \\ A \times_k k[V] & \longrightarrow k[V] \\ k[V] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ In this way we see that the first part of $(S2)$ holds with $k[\epsilon]$ replaced by $k[V]$.
To prove the second part suppose given two commutative diagrams $$\begin{gathered}\begin{matrix}y & x_V \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x_V \\ y & \longrightarrow x \\ x_V & \longrightarrow x_0 \\ x & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}y' & x_V \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y' & \longrightarrow x_V \\ y' & \longrightarrow x \\ x_V & \longrightarrow x_0 \\ x & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[V] & k[V] \\ A & k\end{matrix} \\[6pt] \begin{aligned}A \times_k k[V] & \longrightarrow A \\ A \times_k k[V] & \longrightarrow k[V] \\ k[V] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ We will use the morphisms $x_V \to x_{V'} \to x_0$ and $x_V \to x_\epsilon \to x_0$ introduced in the first paragraph of the proof. Choose morphisms $y \to y_{V'}$ and $y' \to y'_{V'}$ lying over $A \times_k k[V] \to A \times_k k[V']$. The axioms of a cofibred category imply we can find commutative diagrams $$\begin{gathered}\begin{matrix}y_{V'} & x_{V'} \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y_{V'} & \longrightarrow x_{V'} \\ y_{V'} & \longrightarrow x \\ x_{V'} & \longrightarrow x_0 \\ x & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}y'_{V'} & x_{V'} \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y'_{V'} & \longrightarrow x_{V'} \\ y'_{V'} & \longrightarrow x \\ x_{V'} & \longrightarrow x_0 \\ x & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[V'] & k[V'] \\ A & k\end{matrix} \\[6pt] \begin{aligned}A \times_k k[V'] & \longrightarrow A \\ A \times_k k[V'] & \longrightarrow k[V'] \\ k[V'] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ By induction hypothesis we obtain an isomorphism $b : y_{V'} \to y'_{V'}$ compatible with the morphisms $y_{V'} \to x$ and $y'_{V'} \to x$, in particular compatible with the morphisms to $x_0$. Then we have commutative diagrams $$\begin{gathered}\begin{matrix}y & x_\epsilon \\ y'_{V'} & x_0\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x_\epsilon \\ y & \longrightarrow y'_{V'} \\ x_\epsilon & \longrightarrow x_0 \\ y'_{V'} & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{and}\quad \begin{gathered}\begin{matrix}y' & x_\epsilon \\ y'_{V'} & x_0\end{matrix} \\[6pt] \begin{aligned}y' & \longrightarrow x_\epsilon \\ y' & \longrightarrow y'_{V'} \\ x_\epsilon & \longrightarrow x_0 \\ y'_{V'} & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[\epsilon] & k[\epsilon] \\ A & k\end{matrix} \\[6pt] \begin{aligned}A \times_k k[\epsilon] & \longrightarrow A \\ A \times_k k[\epsilon] & \longrightarrow k[\epsilon] \\ k[\epsilon] & \longrightarrow k \\ A & \longrightarrow k\end{aligned}\end{gathered}$$ where the morphism $y \to y'_{V'}$ is the composition $y \to y_{V'} \xrightarrow{b} y'_{V'}$ and where the morphisms $y \to x_\epsilon$ and $y' \to x_\epsilon$ are the compositions of the maps $y \to x_V$ and $y' \to x_V$ with the morphism $x_V \to x_\epsilon$. Then the second part of (S2) guarantees the existence of an isomorphism $y \to y'$ compatible with the maps to $y'_{V'}$, in particular compatible with the maps to $x$ (because $b$ was compatible with the maps to $x$). $\square$
Remark. Comparison with Schlessinger's conditions
When $\mathcal{F}$ is cofibered in sets, conditions (S1) and (S2) are exactly conditions (H1) and (H2) from Schlessinger's paper the original source citation Sch. Namely, for a functor $F: \mathcal{C}_\Lambda \to \textit{Sets}$, conditions (S1) and (S2) state:
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If $A_1 \to A$ and $A_2 \to A$ are maps in $\mathcal{C}_\Lambda$ with $A_2 \to A$ surjective, then the induced map $F(A_1 \times_A A_2) \to F(A_1) \times_{F(A)} F(A_2)$ is surjective.
-
If $A \to k$ is a map in $\mathcal{C}_\Lambda$, then the induced map $F(A \times_k k[\epsilon]) \to F(A) \times_{F(k)} F(k[\epsilon])$ is bijective.
The injectivity of the map $F(A \times_k k[\epsilon]) \to F(A) \times_{F(k)} F(k[\epsilon])$ comes from the second part of condition (S2) and the fact that morphisms are identities.
Lemma. The tangent-space functor
Let $R$ be an $S$-algebra, and let $\mathcal{C}$ be a strictly full subcategory of $S\text{-Alg}/R$ containing $R[M]$ for all $M \in \operatorname{Ob}(\text{Mod}^{fg}_R)$. Let $F: \mathcal{C} \to \textit{Sets}$ be a functor. Suppose that $F(R)$ is a one element set and that for any $M, N \in \operatorname{Ob}(\text{Mod}^{fg}_R)$, the induced map $$F(R[M] \times_R R[N]) \to F(R[M]) \times F(R[N])$$ is a bijection. Then $F(R[M])$ has a natural $R$-module structure for any $M \in \operatorname{Ob}(\text{Mod}^{fg}_R)$.
Proof. Note that $R \cong R[0]$ and $R[M] \times_R R[N] \cong R[M \times N]$ hence $R$ and $R[M] \times_R R[N]$ are objects of $\mathcal{C}$ by our assumptions on $\mathcal{C}$. Thus the conditions on $F$ make sense. The functor $\text{Mod}_R \to S\text{-Alg}/R$ of Lemma Preservation of products by a deformation functor restricts to a functor $\text{Mod}^{fg}_R \to \mathcal{C}$ by the assumption on $\mathcal{C}$. Let $L$ be the composition $\text{Mod}^{fg}_R \to \mathcal{C} \to \textit{Sets}$, i.e., $L(M) = F(R[M])$. Then $L$ preserves finite products by Lemma Preservation of products by a deformation functor and the assumption on $F$. Hence Lemma Linear functors on deformation modules shows that $L(M) = F(R[M])$ has a natural $R$-module structure for any $M \in \operatorname{Ob}(\text{Mod}^{fg}_R)$. $\square$
Lemma. The tangent functor and tensor products
Let $F: \mathcal{C} \to \textit{Sets}$ be a functor satisfying the hypotheses of Lemma The tangent-space functor. Assume $R = K$ is a field. Then $F(K[V]) \cong TF \otimes_K V$ for any finite dimensional $K$-vector space $V$.
Proof. Follows from Lemma Linear deformation functors over a field. $\square$
Remark. Formal objects and the Yoneda correspondence
Let $R$ be an object of $\widehat{\mathcal{C}}_\Lambda$. It defines a functor $\underline{R}: \widehat{\mathcal{C}}_\Lambda \to \textit{Sets}$ as described in Remarks Groupoids and equivalence relations (Formal deformation groupoids). As usual we identify this functor with the associated cofibered set. If $\mathcal{F}$ is a cofibered category over $\mathcal{C}_\Lambda$, then there is an equivalence of categories
$$\operatorname{Mor}_{\mathcal{C}_\Lambda}( \underline{R}|_{\mathcal{C}_\Lambda}, \mathcal{F}) \longrightarrow \widehat{\mathcal{F}}(R).$$ It is given by the composition $$\operatorname{Mor}_{\mathcal{C}_\Lambda}( \underline{R}|_{\mathcal{C}_\Lambda}, \mathcal{F}) \xrightarrow{\Phi} \operatorname{Mor}_{\widehat{\mathcal{C}}_\Lambda}( \underline{R}, \widehat{\mathcal{F}}) \xrightarrow{\sim} \widehat{\mathcal{F}}(R)$$ where $\Phi$ is as in Remark Adjunction between completion and restriction and the second equivalence comes from the 2-Yoneda lemma (the cofibered analogue of Categories, Lemma The geometric construction (uncovered prerequisite)). Explicitly, the equivalence sends a morphism $\varphi : \underline{R}|_{\mathcal{C}_\Lambda} \to \mathcal{F}$ to the formal object $(R, \varphi(R \to R/\mathfrak{m}_R^n), \varphi(f_n))$ in $\widehat{\mathcal{F}}(R)$, where $f_n : R/\mathfrak m_R^{n + 1} \to R/\mathfrak m_R^n$ is the projection.
Assume a choice of pushforwards for $\mathcal{F}$ has been made. Given any $\xi \in \operatorname{Ob}(\widehat{\mathcal{F}}(R))$ we construct an explicit $\underline{\xi} : \underline{R}|_{\mathcal{C}_\Lambda} \to \mathcal{F}$ which maps to $\xi$ under (the displayed identity). Namely, say $\xi = (R, \xi_n, f_n)$. An object $\alpha$ in $\underline{R}|_{\mathcal{C}_\Lambda}$ is the same thing as a morphism $\alpha : R \to A$ of $\widehat{\mathcal{C}}_\Lambda$ with $A$ Artinian. Let $m \in \mathbf{N}$ be minimal such that $\mathfrak m_A^m = 0$. Then $\alpha$ factors through a unique $\alpha_m : R/\mathfrak m_R^m \to A$ and we can set $\underline{\xi}(\alpha) = \alpha_{m, *}\xi_m$. We omit the description of $\underline{\xi}$ on morphisms and we omit the proof that $\underline{\xi}$ maps to $\xi$ via (the displayed identity).
Assume a choice of pushforwards for $\widehat{\mathcal{F}}$ has been made. In this case the proof of Categories, Lemma The geometric construction (uncovered prerequisite) gives an explicit quasi-inverse $$\iota : \widehat{\mathcal{F}}(R) \longrightarrow \operatorname{Mor}_{\widehat{\mathcal{C}}_\Lambda}( \underline{R}, \widehat{\mathcal{F}})$$ to the 2-Yoneda equivalence which takes $\xi$ to the morphism $\iota(\xi) : \underline{R} \to \widehat{\mathcal{F}}$ sending $f \in \underline{R}(S) = \operatorname{Mor}_{\mathcal{C}_\Lambda}(R, S)$ to $f_*\xi$. A quasi-inverse to (the displayed identity) is then $$\widehat{\mathcal{F}}(R) \xrightarrow{\iota} \operatorname{Mor}_{\widehat{\mathcal{C}}_\Lambda}( \underline{R}, \widehat{\mathcal{F}}) \xrightarrow{\Psi} \operatorname{Mor}_{\mathcal{C}_\Lambda}( \underline{R}|_{\mathcal{C}_\Lambda}, \mathcal{F})$$ where $\Psi$ is as in Remark Adjunction between completion and restriction. Given $\xi \in \operatorname{Ob}(\widehat{\mathcal{F}}(R))$ we have $\Psi(\iota(\xi)) \cong \underline{\xi}$ where $\underline{\xi}$ is as in the previous paragraph, because both are mapped to $\xi$ under the equivalence of categories (the displayed identity). Using $\underline{R} = \widehat{\underline{R}|_{\mathcal{C}_\Lambda}}$ (see Remark Restriction of a continuous functor on complete rings) and unwinding the definitions of $\Phi$ and $\Psi$ we conclude that $\iota(\xi)$ is isomorphic to the completion of $\underline{\xi}$.
Lemma. Essential surjectivity of a smooth deformation morphism
Let $\varphi : \mathcal{F} \to \mathcal{G}$ be a smooth morphism of categories cofibered in groupoids over $\mathcal{C}_\Lambda$. Assume $\varphi : \mathcal{F}(k) \to \mathcal{G}(k)$ is essentially surjective. Then $\varphi : \mathcal{F} \to \mathcal{G}$ and $\widehat{\varphi} : \widehat{\mathcal{F}} \to \widehat{\mathcal{G}}$ are essentially surjective.
Proof. Let $y$ be an object of $\mathcal{G}$ lying over $A \in \operatorname{Ob}(\mathcal{C}_\Lambda)$. Let $y \to y_0$ be a pushforward of $y$ along $A \to k$. By the assumption on essential surjectivity of $\varphi : \mathcal{F}(k) \to \mathcal{G}(k)$ there exist an object $x_0$ of $\mathcal{F}$ lying over $k$ and an isomorphism $y_0 \to \varphi(x_0)$. Smoothness of $\varphi$ implies there exists an object $x$ of $\mathcal{F}$ over $A$ whose image $\varphi(x)$ is isomorphic to $y$. Thus $\varphi : \mathcal{F} \to \mathcal{G}$ is essentially surjective.
Let $\eta = (R, \eta_n, g_n)$ be an object of $\widehat{\mathcal{G}}$. We construct an object $\xi$ of $\widehat{\mathcal{F}}$ with an isomorphism $\eta \to \varphi(\xi)$. By the assumption on essential surjectivity of $\varphi : \mathcal{F}(k) \to \mathcal{G}(k)$, there exists a morphism $\eta_1 \to \varphi(\xi_1)$ in $\mathcal{G}(k)$ for some $\xi_1 \in \operatorname{Ob}(\mathcal{F}(k))$. The morphism $\eta_2 \xrightarrow{g_1} \eta_1 \to \varphi(\xi_1)$ lies over the surjective ring map $R/\mathfrak m_R^2 \to k$, hence by smoothness of $\varphi$ there exists $\xi_2 \in \operatorname{Ob}(\mathcal{F}(R/\mathfrak m_R^2))$, a morphism $f_1: \xi_2 \to \xi_1$ lying over $R/\mathfrak m_R^2 \to k$, and a morphism $\eta_2 \to \varphi(\xi_2)$ such that $$\begin{gathered}\begin{matrix}\varphi(\xi_2) & \varphi(\xi_{1}) \\ \eta_2 & \eta_1 \\ \phantom{X}\end{matrix} \\[6pt] \begin{aligned}\varphi(\xi_2) & \xrightarrow{\varphi(f_1)} \varphi(\xi_{1}) \\ \eta_2 & \longrightarrow \varphi(\xi_2) \\ \eta_2 & \xrightarrow{g_1} \eta_1 \\ \eta_1 & \longrightarrow \varphi(\xi_{1})\end{aligned}\end{gathered}$$ commutes. Continuing in this way we construct an object $\xi = (R, \xi_n, f_n)$ of $\widehat{\mathcal{F}}$ and a morphism $\eta \to \varphi(\xi) = (R, \varphi(\xi_n), \varphi(f_n))$ in $\widehat{\mathcal{G}}(R)$. $\square$
Remark. Versal formal objects
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal C_\Lambda$, and let $\xi$ be a formal object of $\mathcal{F}$. It follows from the definition of smoothness that versality of $\xi$ is equivalent to the following condition: If $$\begin{gathered}\begin{matrix}\phantom{X} & y \\ \xi & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x \\ \xi & \longrightarrow x\end{aligned}\end{gathered}$$ is a diagram in $\widehat{\mathcal{F}}$ such that $y \to x$ lies over a surjective map $B \to A$ of Artinian rings (we may assume it is a small extension), then there exists a morphism $\xi \to y$ such that $$\begin{gathered}\begin{matrix}\phantom{X} & y \\ \xi & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x \\ \xi & \longrightarrow x \\ \xi & \longrightarrow y\end{aligned}\end{gathered}$$ commutes. In particular, the condition that $\xi$ be versal does not depend on the choices of pushforwards made in the construction of $\underline{\xi} : \underline{R}|_{\mathcal{C}_\Lambda} \to \mathcal{F}$ in Remark Formal objects and the Yoneda correspondence.
Lemma. Lifting a deformation along a small extension
Consider a commutative diagram in a predeformation category $\mathcal{F}$ $$\begin{gathered}\begin{matrix}y & x_2 \\ x_1 & x\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x_2 \\ y & \longrightarrow x_1 \\ x_2 & \xrightarrow{a_2} x \\ x_1 & \xrightarrow{a_1} x\end{aligned}\end{gathered} \quad\text{lying over} \begin{gathered}\begin{matrix}A_1 \times_A A_2 & A_2 \\ A_1 & A\end{matrix} \\[6pt] \begin{aligned}A_1 \times_A A_2 & \longrightarrow A_2 \\ A_1 \times_A A_2 & \longrightarrow A_1 \\ A_2 & \xrightarrow{f_2} A \\ A_1 & \xrightarrow{f_1} A\end{aligned}\end{gathered}$$ in $\mathcal{C}_\Lambda$ where $f_2 : A_2 \to A$ is a small extension. Assume there is a map $h : A_1 \to A_2$ such that $f_2 = f_1 \circ h$. Let $I = \operatorname{Ker}(f_2)$. Consider the ring map $$g : A_1 \times_A A_2 \longrightarrow k[I] = k \oplus I, \quad (u, v) \longmapsto \overline{u} \oplus (v - h(u))$$ Choose a pushforward $y \to g_*y$. Assume $\mathcal{F}$ satisfies (S2). If there exists a morphism $x_1 \to g_*y$, then there exists a morphism $b: x_1 \to x_2$ such that $a_1 = a_2 \circ b$.
Proof. Note that $\text{id}_{A_1} \times g : A_1 \times_A A_2 \to A_1 \times_k k[I]$ is an isomorphism and that $k[I] \cong k[\epsilon]$. Hence we have a diagram $$\begin{gathered}\begin{matrix}y & g_*y \\ x_1 & x_0\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow g_*y \\ y & \longrightarrow x_1 \\ g_*y & \longrightarrow x_0 \\ x_1 & \longrightarrow x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A_1 \times_k k[\epsilon] & k[\epsilon] \\ A_1 & k.\end{matrix} \\[6pt] \begin{aligned}A_1 \times_k k[\epsilon] & \longrightarrow k[\epsilon] \\ A_1 \times_k k[\epsilon] & \longrightarrow A_1 \\ k[\epsilon] & \longrightarrow k. \\ A_1 & \longrightarrow k.\end{aligned}\end{gathered}$$ where $x_0$ is an object of $\mathcal{F}$ lying over $k$ (every object of $\mathcal{F}$ has a unique morphism to $x_0$, see discussion following Definition Predeformation categories). If we have a morphism $x_1 \to g_*y$ then Lemma Lifting a section in a deformation category provides us with a section $s : x_1 \to y$ of the map $y \to x_1$. Composing this with the map $y \to x_2$ we obtain $b : x_1 \to x_2$ which has the property that $a_1 = a_2 \circ b$ because the diagram of the lemma commutes and because $s$ is a section. $\square$
Lemma. Induction on the length of an Artinian deformation base
Let $A$ be a local $\Lambda$-algebra with residue field $k$. Let $M$ be an $A$-module. Then $[k : k'] \text{length}_A(M) = \text{length}_\Lambda(M)$. In the classical case we have $\text{length}_A(M) = \text{length}_\Lambda(M)$.
Proof. If $M$ is a simple $A$-module then $M \cong k$ as an $A$-module, see Algebra, Lemma Criteria for commutative algebra (uncovered prerequisite). In this case $\text{length}_A(M) = 1$ and $\text{length}_\Lambda(M) = [k' : k]$, see Algebra, Lemma Vector-space dimension and module length (uncovered prerequisite). If $\text{length}_A(M)$ is finite, then the result follows on choosing a filtration of $M$ by $A$-submodules with simple quotients using additivity, see Algebra, Lemma Commutative algebra (uncovered prerequisite). If $\text{length}_A(M)$ is infinite, the result follows from the obvious inequality $\text{length}_A(M) \leq \text{length}_\Lambda(M)$. $\square$
Lemma. Formal deformation groupoids
Let $A \to B$ be a ring map in $\mathcal{C}_\Lambda$. The following are equivalent
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$f$ is surjective,
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$\mathfrak m_A/\mathfrak m_A^2 \to \mathfrak m_B/\mathfrak m_B^2$ is surjective, and
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$\mathfrak m_A/(\mathfrak m_\Lambda A + \mathfrak m_A^2) \to \mathfrak m_B/(\mathfrak m_\Lambda B + \mathfrak m_B^2)$ is surjective.
Proof. For any ring map $f : A \to B$ in $\mathcal{C}_\Lambda$ we have $f(\mathfrak m_A) \subset \mathfrak m_B$ for example because $\mathfrak m_A$, $\mathfrak m_B$ is the set of nilpotent elements of $A$, $B$. Suppose $f$ is surjective. Let $y \in \mathfrak m_B$. Choose $x \in A$ with $f(x) = y$. Since $f$ induces an isomorphism $A/\mathfrak m_A \to B/\mathfrak m_B$ we see that $x \in \mathfrak m_A$. Hence the induced map $\mathfrak m_A/\mathfrak m_A^2 \to \mathfrak m_B/\mathfrak m_B^2$ is surjective. In this way we see that (1) implies (2).
It is clear that (2) implies (3). The map $A \to B$ gives rise to a canonical commutative diagram $$\begin{gathered}\begin{matrix}\mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k & \mathfrak m_A/\mathfrak m_A^2 & \mathfrak m_A/(\mathfrak m_\Lambda A + \mathfrak m_A^2) & 0 \\ \mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k & \mathfrak m_B/\mathfrak m_B^2 & \mathfrak m_B/(\mathfrak m_\Lambda B + \mathfrak m_B^2) & 0\end{matrix} \\[6pt] \begin{aligned}\mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k & \longrightarrow \mathfrak m_A/\mathfrak m_A^2 \\ \mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k & \longrightarrow \mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k \\ \mathfrak m_A/\mathfrak m_A^2 & \longrightarrow \mathfrak m_A/(\mathfrak m_\Lambda A + \mathfrak m_A^2) \\ \mathfrak m_A/\mathfrak m_A^2 & \longrightarrow \mathfrak m_B/\mathfrak m_B^2 \\ \mathfrak m_A/(\mathfrak m_\Lambda A + \mathfrak m_A^2) & \longrightarrow 0 \\ \mathfrak m_A/(\mathfrak m_\Lambda A + \mathfrak m_A^2) & \longrightarrow \mathfrak m_B/(\mathfrak m_\Lambda B + \mathfrak m_B^2) \\ \mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k & \longrightarrow \mathfrak m_B/\mathfrak m_B^2 \\ \mathfrak m_B/\mathfrak m_B^2 & \longrightarrow \mathfrak m_B/(\mathfrak m_\Lambda B + \mathfrak m_B^2) \\ \mathfrak m_B/(\mathfrak m_\Lambda B + \mathfrak m_B^2) & \longrightarrow 0\end{aligned}\end{gathered}$$ with exact rows. Hence if (3) holds, then so does (2).
Assume (2). To show that $A \to B$ is surjective it suffices by Nakayama's lemma (Algebra, Lemma Nakayama's lemma) to show that $A/\mathfrak m_A \to B/\mathfrak m_AB$ is surjective. (Note that $\mathfrak m_A$ is a nilpotent ideal.) As $k = A/\mathfrak m_A = B/\mathfrak m_B$ it suffices to show that $\mathfrak m_AB \to \mathfrak m_B$ is surjective. Applying Nakayama's lemma once more we see that it suffices to see that $\mathfrak m_AB/\mathfrak m_A\mathfrak m_B \to \mathfrak m_B/\mathfrak m_B^2$ is surjective which is what we assumed. $\square$
Lemma. Essential surjectivity modulo squares of maximal ideals
Let $f: B \to A$ be a ring map in $\mathcal{C}_\Lambda$. The following are equivalent
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$f$ is an essential surjection,
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the map $B/\mathfrak m_B^2 \to A/\mathfrak m_A^2$ is an essential surjection, and
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the map $B/(\mathfrak m_\Lambda B + \mathfrak m_B^2) \to A/(\mathfrak m_\Lambda A + \mathfrak m_A^2)$ is an essential surjection.
Proof. Assume (3). Let $C \to B$ be a ring map in $\mathcal{C}_\Lambda$ such that $C \to A$ is surjective. Then $C \to A/(\mathfrak m_\Lambda A + \mathfrak m_A^2)$ is surjective too. We conclude that $C \to B/(\mathfrak m_\Lambda B + \mathfrak m_B^2)$ is surjective by our assumption. Hence $C \to B$ is surjective by applying Lemma Formal deformation groupoids (2 times).
Assume (1). Let $C \to B/(\mathfrak m_\Lambda B + \mathfrak m_B^2)$ be a morphism of $\mathcal{C}_\Lambda$ such that $C \to A/(\mathfrak m_\Lambda A + \mathfrak m_A^2)$ is surjective. Set $C' = C \times_{B/(\mathfrak m_\Lambda B + \mathfrak m_B^2)} B$ which is an object of $\mathcal{C}_\Lambda$ by Lemma Fibre products of Artinian local deformation bases. Note that $C' \to A/(\mathfrak m_\Lambda A + \mathfrak m_A^2)$ is still surjective, hence $C' \to A$ is surjective by Lemma Formal deformation groupoids. Thus $C' \to B$ is surjective by our assumption. This implies that $C' \to B/(\mathfrak m_\Lambda B + \mathfrak m_B^2)$ is surjective, which implies by the construction of $C'$ that $C \to B/(\mathfrak m_\Lambda B + \mathfrak m_B^2)$ is surjective.
In the first paragraph we proved (3) $\Rightarrow$ (1) and in the second paragraph we proved (1) $\Rightarrow$ (3). The equivalence of (2) and (3) is a special case of the equivalence of (1) and (3), hence we are done. $\square$
Lemma. First cotangent homology in the separable case
There is a canonical map $$\mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \longrightarrow H_1(L_{k/\Lambda}).$$ If $k' \subset k$ is separable (for example if the characteristic of $k$ is zero), then this map induces an isomorphism $\mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k = H_1(L_{k/\Lambda})$. If $k = k'$ (for example in the classical case), then $\mathfrak m_\Lambda/\mathfrak m_\Lambda^2 = H_1(L_{k/\Lambda})$. The composition $$\mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \longrightarrow H_1(L_{k/\Lambda}) \longrightarrow \mathfrak m_A/\mathfrak m_A^2$$ comes from the canonical map $\mathfrak m_\Lambda \to \mathfrak m_A$.
Proof. Note that $H_1(L_{k'/\Lambda}) = \mathfrak m_\Lambda/\mathfrak m_\Lambda^2$ as $\Lambda \to k'$ is surjective with kernel $\mathfrak m_\Lambda$. The map arises from functoriality of the naive cotangent complex. If $k' \subset k$ is separable, then $k' \to k$ is an étale ring map, see Algebra, Lemma Formally smooth, unramified and étale ring maps, Theorem 3.1 and Sections 4–7. Thus its naive cotangent complex has trivial homology groups, see Algebra, Definition Étale ring maps. Then Algebra, Lemma The transitivity sequence for the naive cotangent complex (uncovered prerequisite) applied to the ring maps $\Lambda \to k' \to k$ implies that $\mathfrak m_\Lambda/\mathfrak m_\Lambda^2 \otimes_{k'} k = H_1(L_{k/\Lambda})$. We omit the proof of the final statement. $\square$
Lemma. Factoring a surjection into small extensions
Let $f: B \to A$ be a surjective ring map in $\mathcal{C}_\Lambda$. Then $f$ can be factored as a composition of small extensions.
Proof. Let $I$ be the kernel of $f$. The maximal ideal $\mathfrak{m}_B$ is nilpotent since $B$ is Artinian, say $\mathfrak{m}_B^n = 0$. Hence we get a factorization $$B = B/I\mathfrak{m}_B^{n-1} \to B/I\mathfrak{m}_B^{n-2} \to \ldots \to B/I \cong A$$ of $f$ into a composition of surjective maps whose kernels are annihilated by the maximal ideal. Thus it suffices to prove the lemma when $f$ itself is such a map, i.e. when $I$ is annihilated by $\mathfrak{m}_B$. In this case $I$ is a $k$-vector space, which has finite dimension, see Algebra, Lemma Finite length over an Artinian ring (uncovered prerequisite). Take a basis $x_1, \ldots, x_n$ of $I$ as a $k$-vector space to get a factorization $$B \to B/(x_1) \to \ldots \to B/(x_1, \ldots, x_n) \cong A$$ of $f$ into a composition of small extensions. $\square$
Definition. Rim--Schlessinger patching
Let $\mathcal{F}$ be a category cofibered in groupoids over $\mathcal C_\Lambda$. We say that $\mathcal{F}$ satisfies condition (RS) if for every diagram in $\mathcal{F}$ $$\begin{gathered}\begin{matrix}\phantom{X} & x_2 \\ x_1 & x\end{matrix} \\[6pt] \begin{aligned}x_2 & \longrightarrow x \\ x_1 & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}\phantom{X} & A_2 \\ A_1 & A\end{matrix} \\[6pt] \begin{aligned}A_2 & \longrightarrow A \\ A_1 & \longrightarrow A\end{aligned}\end{gathered}$$ in $\mathcal{C}_\Lambda$ with $A_2 \to A$ surjective, there exists a fiber product $x_1 \times_x x_2$ in $\mathcal{F}$ such that the diagram $$\begin{gathered}\begin{matrix}x_1 \times_x x_2 & x_2 \\ x_1 & x\end{matrix} \\[6pt] \begin{aligned}x_1 \times_x x_2 & \longrightarrow x_2 \\ x_1 \times_x x_2 & \longrightarrow x_1 \\ x_2 & \longrightarrow x \\ x_1 & \longrightarrow x\end{aligned}\end{gathered} \quad\text{lies over}\quad \begin{gathered}\begin{matrix}A_1 \times_A A_2 & A_2 \\ A_1 & A.\end{matrix} \\[6pt] \begin{aligned}A_1 \times_A A_2 & \longrightarrow A_2 \\ A_1 \times_A A_2 & \longrightarrow A_1 \\ A_2 & \longrightarrow A. \\ A_1 & \longrightarrow A.\end{aligned}\end{gathered}$$
Lemma. Smooth formal morphisms and power-series rings
Let $R \to S$ be a ring map in $\widehat{\mathcal{C}}_\Lambda$. Then the induced morphism $\underline{S}|_{\mathcal{C}_\Lambda} \to \underline{R}|_{\mathcal{C}_\Lambda}$ is smooth if and only if $S$ is a power series ring over $R$.
Proof. Assume $S$ is a power series ring over $R$. Say $S = R[[x_1, \ldots, x_n]]$. Smoothness of $\underline{S}|_{\mathcal{C}_\Lambda} \to \underline{R}|_{\mathcal{C}_\Lambda}$ means the following (see Remark Comparison with Schlessinger's smoothness condition): Given a surjective ring map $B \to A$ in $\mathcal{C}_\Lambda$, a ring map $R \to B$, a ring map $S \to A$ such that the solid diagram $$\begin{gathered}\begin{matrix}S & A \\ R & B\end{matrix} \\[6pt] \begin{aligned}S & \longrightarrow A \\ S & \cdots\!\!\rightarrow B \\ R & \longrightarrow S \\ R & \longrightarrow B \\ B & \longrightarrow A\end{aligned}\end{gathered}$$ is commutative then a dotted arrow exists making the diagram commute. (Note the similarity with Algebra, Definition Formally smooth ring maps.) To construct the dotted arrow choose elements $b_i \in B$ whose images in $A$ are equal to the images of $x_i$ in $A$. Note that $b_i \in \mathfrak m_B$ as $x_i$ maps to an element of $\mathfrak m_A$. Hence there is a unique $R$-algebra map $R[[x_1, \ldots, x_n]] \to B$ which maps $x_i$ to $b_i$ and which can serve as our dotted arrow.
Conversely, assume $\underline{S}|_{\mathcal{C}_\Lambda} \to \underline{R}|_{\mathcal{C}_\Lambda}$ is smooth. Let $x_1, \ldots, x_n \in S$ be elements whose images form a basis in the relative cotangent space $\mathfrak m_S/(\mathfrak m_R S + \mathfrak m_S^2)$ of $S$ over $R$. Set $T = R[[X_1, \ldots, X_n]]$. Note that both $$S/(\mathfrak m_R S + \mathfrak m_S^2) \cong R/\mathfrak m_R[x_1, \ldots, x_n]/(x_ix_j)$$ and $$T/(\mathfrak m_R T + \mathfrak m_T^2) \cong R/\mathfrak m_R[X_1, \ldots, X_n]/(X_iX_j).$$ Let $S/(\mathfrak m_R S + \mathfrak m_S^2) \to T/(\mathfrak m_R T + \mathfrak m_T^2)$ be the local $R$-algebra isomorphism given by mapping the class of $x_i$ to the class of $X_i$. Let $f_1 : S \to T/(\mathfrak m_R T + \mathfrak m_T^2)$ be the composition $S \to S/(\mathfrak m_R S + \mathfrak m_S^2) \to T/(\mathfrak m_R T + \mathfrak m_T^2)$. The assumption that $\underline{S}|_{\mathcal{C}_\Lambda} \to \underline{R}|_{\mathcal{C}_\Lambda}$ is smooth means we can lift $f_1$ to a map $f_2 : S \to T/\mathfrak{m}_T^2$, then to a map $f_3 : S \to T/\mathfrak{m}_T^3$, and so on, for all $n \geq 1$. Thus we get an induced map $f : S \to T = \varprojlim T/\mathfrak m_T^n$ of local $R$-algebras. By our choice of $f_1$, the map $f$ induces an isomorphism $\mathfrak m_S/(\mathfrak m_R S + \mathfrak m_S^2) \to \mathfrak m_T/(\mathfrak m_R T + \mathfrak m_T^2)$ of relative cotangent spaces. Hence $f$ is surjective by Lemma Surjectivity on cotangent spaces (where we think of $f$ as a map in $\widehat{\mathcal{C}}_R$). Choose preimages $y_i \in S$ of $X_i \in T$ under $f$. As $T$ is a power series ring over $R$ there exists a local $R$-algebra homomorphism $s : T \to S$ mapping $X_i$ to $y_i$. By construction $f \circ s = \text{id}$. Then $s$ is injective. But $s$ induces an isomorphism on relative cotangent spaces since $f$ does, so it is also surjective by Lemma Surjectivity on cotangent spaces again. Hence $s$ and $f$ are isomorphisms. $\square$
Lemma. Preservation of products by a deformation functor
Let $R$ be an $S$-algebra. Then the functor $\text{Mod}_R \to S\text{-Alg}/R$ described above preserves finite products.
Proof. This is merely the statement that if $M$ and $N$ are $R$-modules, then the map $R[M \times N] \to R[M] \times_R R[N]$ is an isomorphism in $S\text{-Alg}/R$. $\square$
Lemma. Linear deformation functors over a field
Let $K$ be a field. Let $L: \text{Mod}^{fg}_K \to \text{Mod}_K$ be a $K$-linear functor. Then $L$ is isomorphic to the functor $L(K) \otimes_K - : \text{Mod}^{fg}_K \to \text{Mod}_K$.
Proof. For $V \in \operatorname{Ob}(\text{Mod}^{fg}_K)$, the isomorphism $L(K) \otimes_K V \to L(V)$ is given on pure tensors by $x \otimes v \mapsto L(f_v)(x)$, where $f_v: K \to V$ is the $K$-linear map sending $1 \mapsto v$. When $V = K$, this is the isomorphism $L(K) \otimes_K K \to L(K)$ given by multiplication by $K$. For general $V$, it is an isomorphism by the case $V = K$ and the fact that $L$ commutes with finite products (Remark The linear deformation functor). $\square$
Remark. Adjunction between completion and restriction
We claim the completion functor of Remark Completion of a deformation morphism and the restriction functor $|_{\mathcal{C}_\Lambda} : \text{Cof}(\widehat{\mathcal{C}}_\Lambda) \to \text{Cof}(\mathcal{C}_\Lambda)$ of Remarks Groupoids and equivalence relations (Formal deformation groupoids) are "2-adjoint" in the following precise sense. Let $\mathcal{F} \in \operatorname{Ob}(\text{Cof}(\mathcal{C}_\Lambda))$ and let $\mathcal{G} \in \operatorname{Ob}(\text{Cof}(\widehat{\mathcal{C}}_\Lambda))$. Then there is an equivalence of categories $$\Phi : \operatorname{Mor}_{\mathcal{C}_\Lambda}( \mathcal{G}|_{\mathcal{C}_\Lambda}, \mathcal{F}) \longrightarrow \operatorname{Mor}_{\widehat{\mathcal{C}}_\Lambda}(\mathcal{G}, \widehat{\mathcal{F}})$$ To describe this equivalence, we define canonical morphisms $\mathcal{G} \to \widehat{\mathcal{G}|_{\mathcal{C}_\Lambda}}$ and $\widehat{\mathcal{F}}|_{\mathcal{C}_\Lambda} \to \mathcal{F}$ as follows
-
Let $R \in \operatorname{Ob}(\widehat{\mathcal{C}}_\Lambda))$ and let $\xi$ be an object of the fiber category $\mathcal{G}(R)$. Choose a pushforward $\xi \to \xi_n$ of $\xi$ to $R/\mathfrak m_R^n$ for each $n \in \mathbf{N}$, and let $f_n : \xi_{n + 1} \to \xi_n$ be the induced morphism. Then $\mathcal{G} \to \widehat{\mathcal{G}|_{\mathcal{C}_\Lambda}}$ sends $\xi$ to $(R, \xi_n, f_n)$.
-
This is the equivalence $can : \widehat{\mathcal{F}}|_{\mathcal{C}_\Lambda} \to \mathcal{F}$ of Remark Restriction of a completed deformation functor.
Having said this, the equivalence $\Phi : \operatorname{Mor}_{\mathcal{C}_\Lambda}( \mathcal{G}|_{\mathcal{C}_\Lambda}, \mathcal{F}) \to \operatorname{Mor}_{\widehat{\mathcal{C}}_\Lambda}(\mathcal{G}, \widehat{\mathcal{F}})$ sends a morphism $\varphi : \mathcal{G}|_{\mathcal{C}_\Lambda} \to \mathcal{F}$ to $$\mathcal{G} \to \widehat{\mathcal{G}|_{\mathcal{C}_\Lambda}} \xrightarrow{\widehat{\varphi}} \widehat{\mathcal{F}}$$ There is a quasi-inverse $\Psi : \operatorname{Mor}_{\widehat{\mathcal{C}}_\Lambda}( \mathcal{G}, \widehat{\mathcal{F}}) \to \operatorname{Mor}_{\mathcal{C}_\Lambda}( \mathcal{G}|_{\mathcal{C}_\Lambda}, \mathcal{F})$ to $\Phi$ which sends $\psi : \mathcal{G} \to \widehat{\mathcal{F}}$ to $$\mathcal{G}|_{\mathcal{C}_\Lambda} \xrightarrow{\psi|_{\mathcal{C}_\Lambda}} \widehat{\mathcal{F}}|_{\mathcal{C}_\Lambda} \to \mathcal{F}.$$ We omit the verification that $\Phi$ and $\Psi$ are quasi-inverse. We also do not address functoriality of $\Phi$ (because it would lead into 3-category territory which we want to avoid at all cost).
Remark. Restriction of a continuous functor on complete rings
Let $G : \widehat{\mathcal{C}}_\Lambda \to \textit{Sets}$ be a functor that commutes with limits. Then the map $G \to \widehat{G|_{\mathcal{C}_\Lambda}}$ described in Remark Adjunction between completion and restriction is an isomorphism. Indeed, if $S$ is an object of $\widehat{\mathcal{C}}_\Lambda$, then we have canonical bijections $$\widehat{G|_{\mathcal{C}_\Lambda}}(S) = \varprojlim_n G(S/\mathfrak{m}_S^n) = G(\varprojlim_n S/\mathfrak{m}_S^n) = G(S).$$ In particular, if $R$ is an object of $\widehat{\mathcal{C}}_\Lambda$ then $\underline{R} = \widehat{\underline{R}|_{\mathcal{C}_\Lambda}}$ because the representable functor $\underline{R}$ commutes with limits by definition of limits.
Definition. Predeformation categories
A predeformation category $\mathcal{F}$ is a category cofibered in groupoids over $\mathcal{C}_\Lambda$ such that $\mathcal{F}(k)$ is equivalent to a category with a single object and a single morphism, i.e., $\mathcal{F}(k)$ contains at least one object and there is a unique morphism between any two objects. A morphism of predeformation categories is a morphism of categories cofibered in groupoids over $\mathcal{C}_\Lambda$.
Lemma. Lifting a section in a deformation category
Let $p: \mathcal{F} \to \mathcal{C}_\Lambda$ be a category cofibered in groupoids. Consider a diagram of $\mathcal{F}$ $$\begin{gathered}\begin{matrix}y & x_\epsilon \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}y & \longrightarrow x_\epsilon \\ y & \xrightarrow{a} x \\ x_\epsilon & \xrightarrow{e} x_0 \\ x & \xrightarrow{d} x_0\end{aligned}\end{gathered} \quad\text{lying over}\quad \begin{gathered}\begin{matrix}A \times_k k[\epsilon] & k[\epsilon] \\ A & k.\end{matrix} \\[6pt] \begin{aligned}A \times_k k[\epsilon] & \longrightarrow k[\epsilon] \\ A \times_k k[\epsilon] & \longrightarrow A \\ k[\epsilon] & \longrightarrow k. \\ A & \longrightarrow k.\end{aligned}\end{gathered}$$ in $\mathcal{C}_\Lambda$. Assume $\mathcal{F}$ satisfies (S2). Then there exists a morphism $s : x \to y$ with $a \circ s = \text{id}_x$ if and only if there exists a morphism $s_\epsilon : x \to x_\epsilon$ with $e \circ s_\epsilon = d$.
Proof. The "only if" direction is clear. Conversely, assume there exists a morphism $s_\epsilon : x \to x_\epsilon$ with $e \circ s_\epsilon = d$. Note that $p(s_\epsilon) : A \to k[\epsilon]$ is a ring map compatible with the map $A \to k$. Hence we obtain $$\sigma = (\text{id}_A, p(s_\epsilon)) : A \to A \times_k k[\epsilon].$$ Choose a pushforward $x \to \sigma_*x$. By construction we can factor $s_\epsilon$ as $x \to \sigma_*x \to x_\epsilon$. Moreover, as $\sigma$ is a section of $A \times_k k[\epsilon] \to A$, we get a morphism $\sigma_*x \to x$ such that $x \to \sigma_*x \to x$ is $\text{id}_x$. Because $e \circ s_\epsilon = d$ we find that the diagram $$\begin{gathered}\begin{matrix}\sigma_*x & x_\epsilon \\ x & x_0\end{matrix} \\[6pt] \begin{aligned}\sigma_*x & \longrightarrow x_\epsilon \\ \sigma_*x & \longrightarrow x \\ x_\epsilon & \xrightarrow{e} x_0 \\ x & \xrightarrow{d} x_0\end{aligned}\end{gathered}$$ is commutative. Hence by (S2) we obtain a morphism $\sigma_*x \to y$ such that $\sigma_*x \to y \to x$ is the given map $\sigma_*x \to x$. The solution to the problem is now to take $a : x \to y$ equal to the composition $x \to \sigma_*x \to y$. $\square$
Remark. Comparison with Schlessinger's smoothness condition
The characterization of smooth morphisms in Remark Smoothness in a fibre square of groupoids is analogous to Schlessinger's notion of a smooth morphism of functors, cf. the original source citation Sch (Definition 2.2.). In fact, when $\mathcal{F}$ and $\mathcal{G}$ are cofibered in sets then our notion is equivalent to Schlessinger's. Namely, in this case let $F, G : \mathcal{C}_\Lambda \to \textit{Sets}$ be the corresponding functors, see Remarks Groupoids and equivalence relations (Formal deformation groupoids). Then $F \to G$ is smooth if and only if for every surjection of rings $B \to A$ in $\mathcal{C}_\Lambda$ the map $F(B) \to F(A) \times_{G(A)} G(B)$ is surjective.
Lemma. Surjectivity on cotangent spaces
Let $f: R \to S$ be a ring map in $\widehat{\mathcal{C}}_\Lambda$. The following are equivalent
-
$f$ is surjective,
-
the map $\mathfrak m_R/\mathfrak m_R^2 \to \mathfrak m_S/\mathfrak m_S^2$ is surjective, and
-
the map $\mathfrak m_R/(\mathfrak m_\Lambda R + \mathfrak m_R^2) \to \mathfrak m_S/(\mathfrak m_\Lambda S + \mathfrak m_S^2)$ is surjective.
Proof. Note that for \(n \geq 2\) we have the equality of relative cotangent spaces
\[ \mathfrak m_R/(\mathfrak m_\Lambda R + \mathfrak m_R^2) = \mathfrak m_{R_n}/(\mathfrak m_\Lambda R_n + \mathfrak m_{R_n}^2) \]and similarly for \(S\). Hence by Lemma Formal deformation groupoids we see that \(R_n \to S_n\) is surjective for all \(n\). Now let \(K_n\) be the kernel of \(R_n \to S_n\). Then the sequences
\[ 0 \to K_n \to R_n \to S_n \to 0 \]form an exact sequence of directed inverse systems. The system \((K_n)\) is Mittag-Leffler since each \(K_n\) is Artinian. Hence by Algebra, Lemma Commutative algebra (uncovered prerequisite) taking limits preserves exactness. So \(\varprojlim R_n \to \varprojlim S_n\) is surjective, i.e., \(f\) is surjective. \(\square\)
Remark. The linear deformation functor
If $L: \text{Mod}^{fg}_R \to \text{Mod}_R$ is an $R$-linear functor, then $L$ preserves finite products and sends the zero module to the zero module, see Homology, Lemma The geometric construction (uncovered prerequisite). On the other hand, if a functor $\text{Mod}^{fg}_R \to \textit{Sets}$ preserves finite products and sends the zero module to a one element set, then it has a unique lift to a $R$-linear functor, see Lemma Linear functors on deformation modules.
Remark. Completion of a deformation morphism
Let $\varphi : \mathcal{F} \to \mathcal{G}$ be a morphism of categories cofibered in groupoids over $\mathcal{C}_\Lambda$. Then there is an induced morphism $\widehat{\varphi}: \widehat{\mathcal{F}} \to \widehat{\mathcal{G}}$ of categories cofibered in groupoids over $\widehat{\mathcal{C}}_\Lambda$. It sends an object $\xi = (R, \xi_n, f_n)$ of $\widehat{\mathcal{F}}$ to $(R, \varphi(\xi_n), \varphi(f_n))$, and it sends a morphism $(a_0 : R \to S, a_n : \xi_n \to \eta_n)$ between objects $\xi$ and $\eta$ of $\widehat{\mathcal{F}}$ to $(a_0 : R \to S, \varphi(a_n) : \varphi(\xi_n) \to \varphi(\eta_n))$. Finally, if $t : \varphi \to \varphi'$ is a $2$-morphism between $1$-morphisms $\varphi, \varphi': \mathcal{F} \to \mathcal{G}$ of categories cofibred in groupoids, then we obtain a $2$-morphism $\widehat{t} : \widehat{\varphi} \to \widehat{\varphi}'$. Namely, for $\xi = (R, \xi_n, f_n)$ as above we set $\widehat{t}_\xi = (t_{\varphi(\xi_n)})$. Hence completion defines a functor between $2$-categories $$\widehat{~} : \text{Cof}(\mathcal{C}_\Lambda) \longrightarrow \text{Cof}(\widehat{\mathcal{C}}_\Lambda)$$ from the $2$-category of categories cofibred in groupoids over $\mathcal{C}_\Lambda$ to the $2$-category of categories cofibred in groupoids over $\widehat{\mathcal{C}}_\Lambda$.
Remark. Restriction of a completed deformation functor
Let $\mathcal{F}$ be a category cofibred in groupoids over $\mathcal{C}_\Lambda$. We claim that there is a canonical equivalence $$can : \widehat{\mathcal{F}}|_{\mathcal{C}_\Lambda} \longrightarrow \mathcal{F}.$$ Namely, let $A \in \operatorname{Ob}(\mathcal{C}_\Lambda)$ and let $(A, \xi_n, f_n)$ be an object of $\widehat{\mathcal{F}}|_{\mathcal{C}_\Lambda}(A)$. Since $A$ is Artinian there is a minimal $m \in \mathbf{N}$ such that $\mathfrak m_A^m = 0$. Then $can$ sends $(A, \xi_n, f_n)$ to $\xi_m$. This functor is an equivalence of categories cofibered in groupoids by Categories, Lemma Groupoids and equivalence relations (uncovered prerequisite) because it is an equivalence on all fibre categories by Lemma Independence of the filtration defining a formal object and the fact that the $\mathfrak m_A$-adic topology on a local Artinian ring $A$ comes from the zero ideal. We will frequently identify $\mathcal{F}$ with a full subcategory of $\widehat{\mathcal{F}}$ via a quasi-inverse to the functor $can$.
[^1]: For example if $\mathcal{F}$ satisfies (S2), see Lemma The associated deformation functor and Schlessinger's conditions.
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Closed subsets of an affine spectrum
Lower native prerequisite: algebra.tex / lemma-spec-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Idempotent ideals and connected components
Lower native prerequisite: algebra.tex / lemma-ideal-is-squared-union-connected. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Characterizations of étale algebras
Lower native prerequisite: algebra.tex / lemma-characterize-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
The fibrewise criterion for flatness
Lower native prerequisite: algebra.tex / lemma-criterion-flatness-fibre. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Étaleness at a prime ideal
Lower native prerequisite: algebra.tex / lemma-etale-at-prime. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, flat.tex.
Modules
Lower native prerequisite: algebra.tex / lemma-cover-module. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Closed images stable under specialization
Lower native prerequisite: algebra.tex / lemma-image-stable-specialization-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, spaces-morphisms.tex.
The geometric construction
Lower native prerequisite: topology.tex / lemma-closed-open-map-specialization. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Henselian rings
Lower native prerequisite: algebra.tex / lemma-henselization-different. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Henselian rings
Lower native prerequisite: algebra.tex / lemma-strict-henselization-different. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Henselian rings
Lower native prerequisite: algebra.tex / lemma-henselian-functorial-improve. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Functoriality of strict henselization
Lower native prerequisite: algebra.tex / lemma-strictly-henselian-functorial. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, more-algebra.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-x-or-x-inverse-valuation-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Faithfully flat modules
Lower native prerequisite: algebra.tex / lemma-ff. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Exactness of localization
Lower native prerequisite: algebra.tex / proposition-localization-exact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, more-algebra.tex.
Successive localizations
Lower native prerequisite: algebra.tex / proposition-localize-twice. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Modules
Lower native prerequisite: algebra.tex / lemma-charpoly-module. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Criteria for flatness
Lower native prerequisite: algebra.tex / lemma-characterize-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, more-algebra.tex, more-morphisms.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-zero-directed-limit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Tensor products and direct sums
Lower native prerequisite: algebra.tex / lemma-tensor-product-exact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Lifting commutative algebra
Lower native prerequisite: algebra.tex / lemma-lift-idempotents-noncommutative. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Characterizations of projective modules
Lower native prerequisite: algebra.tex / lemma-characterize-projective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Hom from a finitely presented module
Lower native prerequisite: algebra.tex / lemma-hom-from-finitely-presented. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Localization of a flat module
Lower native prerequisite: algebra.tex / lemma-flat-localization. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, flat.tex, groupoids.tex, more-algebra.tex, properties.tex.
Nakayama's lemma after localization
Lower native prerequisite: algebra.tex / lemma-NAK-localization. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
The equational criterion for flatness
Lower native prerequisite: algebra.tex / lemma-flat-eq. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, more-algebra.tex.
A characteristic polynomial with coefficients in an ideal
Lower native prerequisite: algebra.tex / lemma-charpoly-module-ideal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Cotangent complexes, differentials and local algebra
Lower native prerequisite: algebra.tex / lemma-differentials-localize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Cotangent complexes, differentials and finite algebras
Lower native prerequisite: algebra.tex / lemma-differentials-finitely-generated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Cotangent complexes and differentials
Lower native prerequisite: algebra.tex / lemma-trivial-differential-surjective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Base change for finite algebras
Lower native prerequisite: algebra.tex / lemma-base-change-finiteness. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, more-algebra.tex.
Cotangent complexes, differentials and diagonals and separation
Lower native prerequisite: algebra.tex / lemma-differentials-diagonal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Noetherian rings
Lower native prerequisite: algebra.tex / lemma-Noetherian-power. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Smooth morphisms
Lower native prerequisite: algebra.tex / example-make-standard-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex.
Étale algebras in standard smooth form
Lower native prerequisite: algebra.tex / lemma-etale-standard-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are algebra.tex, more-algebra.tex.
Characterizations of separable field extensions
Lower native prerequisite: algebra.tex / proposition-characterize-separable-field-extensions. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Prime ideals and dimension in a polynomial ring
Lower native prerequisite: algebra.tex / lemma-dimension-prime-polynomial-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex, varieties.tex.
Localization of the naive cotangent complex
Lower native prerequisite: algebra.tex / lemma-localize-NL. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Syntomic algebras in a filtered colimit
Lower native prerequisite: algebra.tex / lemma-colimit-syntomic. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Complete rings, formal power series and regular rings
Lower native prerequisite: algebra.tex / lemma-regular-complete-containing-coefficient-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
The Artin–Rees lemma
Lower native prerequisite: algebra.tex / lemma-Artin-Rees. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / theorem-universally-exact-criteria. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-algebra.tex.
The transitivity sequence for the naive cotangent complex
Lower native prerequisite: algebra.tex / lemma-exact-sequence-NL. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex, more-algebra.tex.
Base change of the naive cotangent complex
Lower native prerequisite: algebra.tex / lemma-change-base-NL. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Degrees of extensions obtained by adjoining p-th roots
Lower native prerequisite: algebra.tex / lemma-size-extension-pth-roots. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Composition of formally smooth maps
Lower native prerequisite: algebra.tex / lemma-compose-formally-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / theorem-cohen-structure-theorem. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Flatness and regular ring maps
Lower native prerequisite: algebra.tex / lemma-flat-under-regular. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Elementary formally smooth extensions
Lower native prerequisite: algebra.tex / lemma-formally-smooth-extensions-easy. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Injective resolutions
Lower native prerequisite: algebra.tex / lemma-when-injective-covering. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Formal smoothness and smooth morphisms
Lower native prerequisite: algebra.tex / lemma-cohen-ring-formally-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Regular rings are Cohen–Macaulay
Lower native prerequisite: algebra.tex / lemma-regular-ring-CM. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Flatness over a regular local ring
Lower native prerequisite: algebra.tex / lemma-flat-over-regular. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Descent of flatness
Lower native prerequisite: algebra.tex / lemma-flatness-descends-more-general. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-algebra.tex.
Complete rings, formal power series and Noetherian rings
Lower native prerequisite: algebra.tex / lemma-completion-Noetherian-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex, more-algebra.tex.
The universal property of Kähler differentials
Lower native prerequisite: algebra.tex / lemma-universal-omega. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Finite presentation and modules
Lower native prerequisite: algebra.tex / lemma-construct-fp-module. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Base change for flatness
Lower native prerequisite: algebra.tex / lemma-base-change-flat-up-down. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex, more-morphisms.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-universally-exact-split. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Injectivity from a fibrewise injectivity criterion
Lower native prerequisite: algebra.tex / lemma-mod-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Regular rings
Lower native prerequisite: algebra.tex / lemma-regular-quotient-regular. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Finite algebras
Lower native prerequisite: algebra.tex / lemma-hathat-finitely-generated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex, perfect.tex.
Filtered colimits of naive cotangent complexes
Lower native prerequisite: algebra.tex / lemma-colimits-NL. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex, sites-modules.tex.
Tensor products and direct sums
Lower native prerequisite: algebra.tex / lemma-tensor-products-commute-with-limits. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-first-quadrant-ss. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, derived.tex, more-algebra.tex.
Henselian rings
Lower native prerequisite: algebra.tex / lemma-henselian-functorial. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Integral extensions
Lower native prerequisite: algebra.tex / lemma-integral-integral-over-ideal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-find-existence-computes. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex, more-algebra.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-special-direct-system. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Derived categories
Lower native prerequisite: derived.tex / lemma-projectors-have-images-triangulated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-subcategory-left-resolution. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Flatness of a cokernel
Lower native prerequisite: algebra.tex / lemma-cokernel-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Smoothness from flatness and smooth fibres
Lower native prerequisite: algebra.tex / lemma-flat-fibre-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-open-containing-vanishing-jacobson-radical. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Universal injectivity of a faithfully flat ring map
Lower native prerequisite: algebra.tex / lemma-faithfully-flat-universally-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-algebra.tex.
A disjoint spectrum and a product of rings
Lower native prerequisite: algebra.tex / lemma-disjoint-implies-product. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / theorem-lazard. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-algebra.tex, spaces-cohomology.tex.
Tensor products and direct sums
Lower native prerequisite: algebra.tex / proposition-fg-tensor. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Finite presentation and tensor products and direct sums
Lower native prerequisite: algebra.tex / proposition-fp-tensor. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Tensor products and direct sums
Lower native prerequisite: derived.tex / lemma-products. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Tensor products and direct sums
Lower native prerequisite: algebra.tex / lemma-adjoint-tensor-restrict. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Projective and locally free modules
Lower native prerequisite: derived.tex / lemma-projective-resolutions-exist. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Derived categories
Lower native prerequisite: derived.tex / lemma-unbounded-right-derived. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Triangulated categories
Lower native prerequisite: derived.tex / proposition-enough-acyclics. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-Mittag-Leffler. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-subcategory-right-acyclics. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-five-lemma. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, derived.tex, more-algebra.tex, sites-cohomology.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-four-lemma. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, more-algebra.tex, sites-cohomology.tex.
Extending a morphism after finite denominators are cleared
Lower native prerequisite: derived.tex / lemma-lift-map. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
The characteristic polynomial
Lower native prerequisite: algebra.tex / lemma-charpoly. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Étale algebras from polynomial factorizations
Lower native prerequisite: algebra.tex / example-factor-polynomials-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-algebra.tex.
Derived categories
Lower native prerequisite: derived.tex / lemma-higher-derived-functors. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Sheaves on ringed sites
Lower native prerequisite: cohomology.tex / lemma-subsheaf-of-constant-sheaf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Filtered limits and sheaf cohomology and diagonals and separation
Lower native prerequisite: cohomology.tex / lemma-quasi-separated-cohomology-colimit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Sheaves on ringed sites and local algebra
Lower native prerequisite: modules.tex / lemma-generated-by-local-sections-stalk. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-flasque-acyclic. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-before-Leray. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Injective resolutions
Lower native prerequisite: injectives.tex / theorem-K-injective-embedding-grothendieck. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, perfect.tex, spaces-perfect.tex.
Derived sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-mayer-vietoris. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Injective resolutions
Lower native prerequisite: cohomology.tex / lemma-restrict-K-injective-to-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Local algebra
Lower native prerequisite: cohomology.tex / lemma-local-homotopy. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived categories
Lower native prerequisite: derived.tex / lemma-derived-adjoint-functors. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, perfect.tex, sites-cohomology.tex.
Modules
Lower native prerequisite: sheaves.tex / lemma-j-shriek-modules. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Composition and derived sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-compose. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-dual. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived Hom and Ext
Lower native prerequisite: cohomology.tex / lemma-restriction-RHom-to-U. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived Hom and Ext
Lower native prerequisite: cohomology.tex / lemma-internal-hom-evaluate-isom. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived Hom and Ext
Lower native prerequisite: cohomology.tex / lemma-internal-hom-evaluate. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Finite presentation and flatness
Lower native prerequisite: modules.tex / lemma-flat-locally-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Flat modules in a short exact sequence
Lower native prerequisite: modules.tex / lemma-flat-ses. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Base change for derived categories
Lower native prerequisite: cohomology.tex / lemma-derived-base-change. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Dimension and codimension
Lower native prerequisite: cohomology.tex / lemma-is-limit-dimension. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, perfect.tex.
Injective resolutions
Lower native prerequisite: derived.tex / lemma-difficulty-K-injectives. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, perfect.tex, spaces-perfect.tex.
Derived sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-is-limit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Sheaf cohomology and derived categories
Lower native prerequisite: cohomology.tex / lemma-cech-complex-complex. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-project-to-ordered. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Sheaf cohomology and injective resolutions
Lower native prerequisite: cohomology.tex / lemma-injective-trivial-cech. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived categories
Lower native prerequisite: homology.tex / lemma-double-complex-gives-resolution. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, derived.tex, spaces-cohomology.tex.
Projective, locally free modules and line bundles and ampleness
Lower native prerequisite: modules.tex / lemma-invertible-is-locally-free-rank-1. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
The geometric construction
Lower native prerequisite: modules.tex / lemma-i-star-exact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, perfect.tex, varieties.tex.
Noetherian topological spaces
Lower native prerequisite: topology.tex / lemma-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
The geometric construction
Lower native prerequisite: modules.tex / lemma-canonical-exact-sequence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-apply-Mittag-Leffler-again. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex.
Derived categories
Lower native prerequisite: homology.tex / lemma-ss-double-complex. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are cohomology.tex, derived.tex.
Sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-Leray-unbounded. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Sheaf cohomology
Lower native prerequisite: derived.tex / lemma-leray-acyclicity. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex, perfect.tex.
Affine neighbourhoods
Lower native prerequisite: coherent.tex / lemma-relative-affine-vanishing. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex, spaces-cohomology.tex.
Derived tensor products and Tor amplitude
Lower native prerequisite: properties.tex / proposition-coherator. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: schemes.tex / lemma-push-forward-quasi-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, flat.tex, more-morphisms.tex, perfect.tex.
Direct images and perfect complexes
Lower native prerequisite: cohomology.tex / lemma-pushforward-perfect. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Direct images and derived sheaf cohomology
Lower native prerequisite: cohomology.tex / lemma-pushforward-restriction. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: coherent.tex / lemma-quasi-coherence-higher-direct-images. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Proper morphisms and closed support
Lower native prerequisite: coherent.tex / lemma-support-proper-over-base-pushforward. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Affine neighbourhoods
Lower native prerequisite: morphisms.tex / lemma-affine-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex, perfect.tex.
Derived categories
Lower native prerequisite: cohomology.tex / lemma-variant-derived-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Diagonals, separation and Noetherian rings
Lower native prerequisite: morphisms.tex / lemma-finite-type-Noetherian-quasi-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Proper morphisms
Lower native prerequisite: coherent.tex / lemma-union-closed-proper-over-base. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Perfect complexes
Lower native prerequisite: cohomology.tex / lemma-perfect-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Pseudo-coherent complexes and coherent sheaves
Lower native prerequisite: cohomology.tex / lemma-pseudo-coherent-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Diagonals, separation and affine neighbourhoods
Lower native prerequisite: properties.tex / lemma-affine-s-opens-cover-quasi-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex, properties.tex.
The geometric construction
Lower native prerequisite: constructions.tex / lemma-proj-sheaves. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Derived Hom, Ext and Noetherian rings
Lower native prerequisite: algebra.tex / lemma-ext-noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-right-orthogonal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Derived Hom, Ext and projective and locally free modules
Lower native prerequisite: cohomology.tex / lemma-Rhom-complex-of-direct-summands-finite-free. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex, spaces-perfect.tex.
Filtered limits and sheaf cohomology
Lower native prerequisite: coherent.tex / lemma-colimit-cohomology. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Filtered limits and the geometric construction
Lower native prerequisite: categories.tex / lemma-colimits-commute. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex, perfect.tex.
Finite-presentation descent
Lower native prerequisite: limits.tex / lemma-inverse-limit-irreducibles. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Sheaves on ringed sites
Lower native prerequisite: coherent.tex / lemma-formal-functions-stalk. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Perfect complexes and local algebra
Lower native prerequisite: cohomology.tex / lemma-perfect-on-locally-ringed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Proper morphisms and modules
Lower native prerequisite: coherent.tex / lemma-module-support-proper-over-base. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Proper morphisms and closed support
Lower native prerequisite: limits.tex / lemma-eventually-proper-support. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Sheaf cohomology and projective and locally free modules
Lower native prerequisite: coherent.tex / lemma-cohomology-projective-space-over-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Relative Mayer–Vietoris for unbounded complexes
Lower native prerequisite: cohomology.tex / lemma-unbounded-relative-mayer-vietoris. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Perfect complexes
Lower native prerequisite: cohomology.tex / lemma-perfect-independent-representative. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Comparison for the geometric construction
Lower native prerequisite: schemes.tex / lemma-compare-constructions. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: coherent.tex / lemma-quasi-coherence-higher-direct-images-application. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Prime spectra and associated points
Lower native prerequisite: schemes.tex / lemma-spec-sheaves. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex, properties.tex.
Derived tensor products, Tor amplitude and flatness
Lower native prerequisite: cohomology.tex / lemma-check-K-flat-stalks. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Base change for affine neighbourhoods
Lower native prerequisite: coherent.tex / lemma-affine-base-change. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, perfect.tex, spaces-cohomology.tex.
Base change for affine neighbourhoods
Lower native prerequisite: morphisms.tex / lemma-base-change-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, perfect.tex.
Projective, locally free modules and tensor products and direct sums
Lower native prerequisite: modules.tex / lemma-direct-summand-of-locally-free-is-locally-free. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
Vanishing and diagonals, separation and affine neighbourhoods
Lower native prerequisite: coherent.tex / lemma-vanishing-nr-affines-quasi-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
The geometric construction
Lower native prerequisite: injectives.tex / lemma-RF-commutes-with-Rlim. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex, spaces-perfect.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: schemes.tex / lemma-equivalence-quasi-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex, more-morphisms.tex, perfect.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: modules.tex / lemma-construct-quasi-coherent-sheaves. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are perfect.tex.
The geometric construction
Lower native prerequisite: categories.tex / lemma-adjoint-fully-faithful. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex, dga.tex.
Composition and derived categories
Lower native prerequisite: derived.tex / lemma-compose-derived-functors-general. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Filtered limits and triangulated categories
Lower native prerequisite: derived.tex / lemma-write-as-colimit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Derived tensor products and Tor amplitude
Lower native prerequisite: derived.tex / lemma-homological-functor-kernel. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Tensor products and direct sums
Lower native prerequisite: derived.tex / lemma-commutes-with-countable-sums. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
The geometric construction
Lower native prerequisite: categories.tex / lemma-yoneda. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex, descent.tex.
Derived categories
Lower native prerequisite: derived.tex / lemma-triangulated-subcategory. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Derived categories
Lower native prerequisite: derived.tex / lemma-functorial-cone. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-cartan-eilenberg. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-morphisms-lift. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex, descent.tex.
Injective resolutions and derived categories
Lower native prerequisite: derived.tex / lemma-morphisms-into-injective-complex. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-2-out-of-3-defined. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
The geometric construction
Lower native prerequisite: categories.tex / lemma-cofinal-essentially-constant. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
The geometric construction
Lower native prerequisite: categories.tex / lemma-adjoint-exists. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are derived.tex.
Filtered limits and finite presentation and finite algebras
Lower native prerequisite: properties.tex / lemma-finite-algebra-directed-colimit-finite-finitely-presented. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Filtered limits and finite presentation and finite algebras
Lower native prerequisite: modules.tex / lemma-finite-presentation-quasi-compact-colimit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Filtered limits and finite presentation and finite algebras
Lower native prerequisite: properties.tex / lemma-directed-colimit-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Filtered limits and finite algebras
Lower native prerequisite: properties.tex / lemma-algebra-directed-colimit-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Dimension and codimension
Lower native prerequisite: algebra.tex / proposition-dimension. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Scheme geometry
Lower native prerequisite: properties.tex / lemma-extend. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Scheme geometry
Lower native prerequisite: properties.tex / lemma-invert-f-sections. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Criteria for diagonals and separation
Lower native prerequisite: schemes.tex / lemma-characterize-quasi-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, properties.tex.
Line bundles and ampleness
Lower native prerequisite: constructions.tex / lemma-ample-on-proj. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex, properties.tex.
Scheme geometry
Lower native prerequisite: properties.tex / lemma-map-into-proj-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Flatness and sheaves on ringed sites
Lower native prerequisite: modules.tex / lemma-flat-stalks-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Projective, locally free modules and finite presentation
Lower native prerequisite: modules.tex / lemma-kernel-surjection-finite-free-onto-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, properties.tex.
Filtered limits and finite algebras
Lower native prerequisite: modules.tex / lemma-finite-type-quasi-compact-colimit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Tensor products and direct sums
Lower native prerequisite: modules.tex / lemma-tensor-product-globally-generated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Line bundles and ampleness
Lower native prerequisite: constructions.tex / lemma-invertible-map-into-proj. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Line bundles and ampleness
Lower native prerequisite: constructions.tex / lemma-where-invertible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are properties.tex.
Integral extensions
Lower native prerequisite: decent-spaces.tex / lemma-extend-integral-morphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Diagonals, separation and affine neighbourhoods
Lower native prerequisite: spaces-morphisms.tex / lemma-quasi-finite-separated-quasi-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Finite presentation and flatness
Lower native prerequisite: more-morphisms.tex / lemma-stratify-flat-fp-lqf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Criteria for diagonals and separation
Lower native prerequisite: spaces-properties.tex / lemma-characterize-quasi-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Diagonals, separation and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-separated-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-morphisms.tex.
Composition and morphisms of algebraic spaces
Lower native prerequisite: spaces-morphisms.tex / lemma-composition-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: spaces-properties.tex / lemma-quotient-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Flatness and groupoids and equivalence relations
Lower native prerequisite: spaces-properties.tex / proposition-finite-flat-equivalence-global. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Diagonals, separation and affine neighbourhoods
Lower native prerequisite: more-morphisms.tex / lemma-separated-locally-quasi-finite-over-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Composition and the geometric construction
Lower native prerequisite: morphisms.tex / lemma-composition-universally-bounded. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Proper morphisms
Lower native prerequisite: spaces.tex / lemma-representable-morphisms-spaces-property. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-morphisms.tex, spaces-properties.tex.
Étale morphisms
Lower native prerequisite: spaces-properties.tex / lemma-etale-image-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-properties.tex.
Proper morphisms
Lower native prerequisite: spaces.tex / lemma-morphism-schemes-gives-representable-transformation-property. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-properties.tex.
Composition and proper morphisms
Lower native prerequisite: spaces.tex / lemma-composition-representable-transformations-property. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-properties.tex.
Composition and étale morphisms
Lower native prerequisite: morphisms.tex / lemma-composition-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-properties.tex.
Schematic neighbourhoods
Lower native prerequisite: decent-spaces.tex / lemma-universally-bounded-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Finite algebras and local algebra
Lower native prerequisite: morphisms.tex / lemma-locally-quasi-finite-qc-source-universally-bounded. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-morphisms.tex.
Groupoids and equivalence relations
Lower native prerequisite: spaces-properties.tex / lemma-equivalence-class-point-monomorphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Field extensions and prime spectra and associated points
Lower native prerequisite: schemes.tex / lemma-mono-towards-spec-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-quasi-compact-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex, spaces-descent.tex, spaces-morphisms.tex.
Finite algebras
Lower native prerequisite: decent-spaces.tex / lemma-weak-UR-finite-above-x. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-point-like-spaces. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Groupoids and equivalence relations
Lower native prerequisite: groupoids.tex / lemma-quotient-groupoid-restrict. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Injective resolutions and sheaves on ringed sites
Lower native prerequisite: schemes.tex / lemma-injective-points-surjective-stalks. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are decent-spaces.tex.
Flatness and finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex, spaces-morphisms.tex.
Finite presentation and finite algebras
Lower native prerequisite: spaces-morphisms.tex / lemma-finite-presentation-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex, spaces-more-morphisms.tex, spaces-morphisms.tex.
Projective, locally free modules and finite algebras
Lower native prerequisite: spaces-morphisms.tex / lemma-finite-locally-free-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Étale morphisms
Lower native prerequisite: spaces-morphisms.tex / etale-theorem-etale-radicial-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Finite presentation and flatness
Lower native prerequisite: spaces.tex / lemma-surjective-flat-locally-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Injective resolutions
Lower native prerequisite: spaces-morphisms.tex / lemma-universally-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for injective resolutions
Lower native prerequisite: spaces-morphisms.tex / lemma-base-change-universally-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for étale morphisms
Lower native prerequisite: spaces-morphisms.tex / lemma-base-change-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / example-thibaut. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-universally-closed-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex, spaces-morphisms.tex.
Finite algebras and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-finite-type-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex, spaces-morphisms.tex.
Étale morphisms
Lower native prerequisite: morphisms.tex / lemma-etale-universally-bounded. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for the geometric construction
Lower native prerequisite: morphisms.tex / lemma-base-change-universally-bounded. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, spaces-morphisms.tex.
Unramified morphisms and diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-diagonal-unramified-morphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, spaces-morphisms.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-quasi-compact-space. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-open-subspaces. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Étale morphisms
Lower native prerequisite: spaces-properties.tex / lemma-etale-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for étale morphisms
Lower native prerequisite: spaces-properties.tex / lemma-base-change-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex, spaces-properties.tex.
Diagonals, separation and affine neighbourhoods
Lower native prerequisite: morphisms.tex / lemma-quasi-affine-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Affine neighbourhoods and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-quasi-affine-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for finite algebras
Lower native prerequisite: spaces-morphisms.tex / lemma-base-change-quasi-finite-locus. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Proper morphisms
Lower native prerequisite: spaces.tex / lemma-representable-transformations-property-implication. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-divisors.tex, spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: schemes.tex / lemma-immersions-monomorphisms. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: schemes.tex / lemma-closed-immersion-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: etale-cohomology.tex / proposition-closed-immersion-pushforward. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Proper morphisms
Lower native prerequisite: sites.tex / lemma-exactness-properties. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Criteria for the geometric construction
Lower native prerequisite: schemes.tex / lemma-characterize-closed-subspace. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-closed-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Sheaves on ringed sites
Lower native prerequisite: spaces-morphisms.tex / lemma-stalk-push-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Composition and finite algebras
Lower native prerequisite: morphisms.tex / lemma-composition-quasi-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, spaces-morphisms.tex.
Flatness and closed support
Lower native prerequisite: morphisms.tex / lemma-flat-pullback-support. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for sheaf cohomology and flatness
Lower native prerequisite: coherent.tex / lemma-flat-base-change-cohomology. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex, spaces-morphisms.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-subspaces-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex, spaces-properties.tex.
Closed support
Lower native prerequisite: morphisms.tex / lemma-scheme-theoretic-support. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Morphisms of algebraic spaces
Lower native prerequisite: spaces-morphisms.tex / lemma-scheme-theoretic-image. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Proper morphisms and diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-closed-immersion-proper. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Flatness
Lower native prerequisite: descent.tex / lemma-flat-at-point. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Proper morphisms and finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-proper. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Affine neighbourhoods and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-affine-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-union-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Morphisms of algebraic spaces
Lower native prerequisite: spaces-morphisms.tex / lemma-compute-pushforward. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Étale morphisms
Lower native prerequisite: spaces.tex / lemma-morphism-sheaves-with-P-effective-descent-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Diagonals, separation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-immersion-locally-quasi-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Affine neighbourhoods
Lower native prerequisite: spaces-properties.tex / lemma-cover-by-union-affines. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex, spaces-properties.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-permanence-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, spaces-morphisms.tex.
Lifting the geometric construction
Lower native prerequisite: spaces.tex / lemma-lift-morphism-presentations. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex, spaces-properties.tex.
Composition and finite algebras
Lower native prerequisite: morphisms.tex / lemma-composition-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Finite presentation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-presentation-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Local algebra
Lower native prerequisite: descent.tex / lemma-local-source-target-characterize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Étale morphisms and diagonals and separation
Lower native prerequisite: spaces-morphisms.tex / etale-lemma-characterize-closed-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / lemma-reach-points-scheme-theoretic-image. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for flatness
Lower native prerequisite: morphisms.tex / lemma-flat-base-change-scheme-theoretic-image. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Base change for morphisms of algebraic spaces
Lower native prerequisite: spaces-morphisms.tex / lemma-base-change-valuative-criteria. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: schemes.tex / lemma-monomorphism-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-fibre. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Proper morphisms and diagonals and separation
Lower native prerequisite: spaces.tex / lemma-properties-diagonal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Étale morphisms and finite algebras
Lower native prerequisite: morphisms.tex / lemma-etale-locally-quasi-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex, spaces-properties.tex.
Base change for dimension and codimension
Lower native prerequisite: morphisms.tex / lemma-dimension-fibre-after-base-change. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex, spaces-morphisms.tex.
Base change for flatness
Lower native prerequisite: morphisms.tex / lemma-base-change-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, flat.tex, spaces-morphisms.tex.
Base change for finite presentation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-base-change-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, flat.tex, more-morphisms.tex, spaces-morphisms.tex.
Base change for finite algebras
Lower native prerequisite: morphisms.tex / lemma-base-change-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex, spaces-morphisms.tex.
The geometric construction
Lower native prerequisite: spaces.tex / lemma-finding-opens. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex, spaces-properties.tex.
Étale morphisms and finite presentation
Lower native prerequisite: morphisms.tex / lemma-etale-locally-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Étale morphisms and flatness
Lower native prerequisite: morphisms.tex / lemma-etale-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, flat.tex, spaces-morphisms.tex, spaces-properties.tex.
The geometric construction
Lower native prerequisite: spaces.tex / lemma-space-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex, spaces-properties.tex.
Finite presentation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-presentation-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex, spaces-morphisms.tex.
Closed support and finite algebras
Lower native prerequisite: morphisms.tex / lemma-support-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: schemes.tex / lemma-immersion-when-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-morphisms.tex.
Diagonals, separation and affine neighbourhoods
Lower native prerequisite: morphisms.tex / lemma-closed-immersion-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex, spaces-morphisms.tex.
Finite presentation and Noetherian rings
Lower native prerequisite: morphisms.tex / lemma-noetherian-finite-type-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex, spaces-morphisms.tex.
Noetherian rings and finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-type-noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex, spaces-morphisms.tex.
Diagonals and separation
Lower native prerequisite: schemes.tex / lemma-diagonal-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex, spaces-morphisms.tex.
Étale morphisms and smooth morphisms
Lower native prerequisite: morphisms.tex / lemma-etale-smooth-unramified. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, spaces-morphisms.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-quotient. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
The Artin–Rees lemma
Lower native prerequisite: coherent.tex / lemma-Artin-Rees. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Field extensions
Lower native prerequisite: decent-spaces.tex / lemma-algebraic-residue-field-extension-closed-point. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Morphisms of algebraic spaces
Lower native prerequisite: spaces-morphisms.tex / lemma-large-enough. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Injective resolutions and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-universally-injective-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Diagonals and separation
Lower native prerequisite: spaces-morphisms.tex / lemma-image-universally-closed-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex, spaces-perfect.tex.
Integral extensions
Lower native prerequisite: spaces-morphisms.tex / lemma-integral-universally-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex, spaces-more-morphisms.tex.
The geometric construction
Lower native prerequisite: coherent.tex / lemma-quasi-compact-h1-zero-covering. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, spaces-cohomology.tex.
Sheaf cohomology
Lower native prerequisite: sites-cohomology.tex / lemma-cohomology-of-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex, spaces-properties.tex.
Étale morphisms and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-etale-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Base change for flatness
Lower native prerequisite: sites-cohomology.tex / lemma-base-change-map-flat-case. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Flatness and sheaves on ringed sites
Lower native prerequisite: spaces-morphisms.tex / lemma-flat-morphism-sites. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Affine neighbourhoods
Lower native prerequisite: coherent.tex / lemma-affine-morphism-projection-ideal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Derived modules on ringed sites
Lower native prerequisite: sites-cohomology.tex / lemma-colim-works-over-collection. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Diagonals and separation
Lower native prerequisite: spaces-morphisms.tex / lemma-quasi-compact-quasi-separated-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Filtered limits and coherent sheaves
Lower native prerequisite: groupoids.tex / lemma-colimit-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Diagonals, separation and finite algebras
Lower native prerequisite: spaces-morphisms.tex / lemma-locally-quasi-finite-separated-representable. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Finite algebras and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-locally-quasi-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Filtered limits and derived modules on ringed sites
Lower native prerequisite: sites-cohomology.tex / lemma-higher-direct-image-colimit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Étale morphisms and sheaves on ringed sites
Lower native prerequisite: spaces-properties.tex / lemma-functoriality-etale-site. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex, spaces-properties.tex.
Diagonals, separation and finite algebras
Lower native prerequisite: spaces.tex / lemma-quotient-finite-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Sheaves on ringed sites
Lower native prerequisite: coherent.tex / lemma-power-ideal-kills-sheaf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
The geometric construction
Lower native prerequisite: coherent.tex / lemma-homs-over-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Diagonals, separation and finite algebras
Lower native prerequisite: spaces-morphisms.tex / lemma-immersion-locally-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex, spaces-perfect.tex.
Coherent sheaves and finite algebras
Lower native prerequisite: coherent.tex / lemma-finite-pushforward-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
The geometric construction
Lower native prerequisite: coherent.tex / lemma-kill-by-twisting. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: coherent.tex / lemma-coherent-Noetherian-quasi-coherent-sub-quotient. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Coherent sheaves and Noetherian rings
Lower native prerequisite: coherent.tex / lemma-coherent-abelian-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Coherent sheaves and Noetherian rings
Lower native prerequisite: coherent.tex / lemma-coherent-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex, spaces-cohomology.tex.
Filtering a coherent sheaf by irreducible supports
Lower native prerequisite: coherent.tex / lemma-prepare-filter-irreducible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-cohomology.tex.
Criteria for étale morphisms and modules
Lower native prerequisite: spaces-properties.tex / lemma-characterize-module-small-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Dimension, codimension and local algebra
Lower native prerequisite: descent.tex / lemma-dimension-local-ring-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, spaces-properties.tex.
Local algebra
Lower native prerequisite: spaces-properties.tex / lemma-local-source-target-at-point. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms and sheaves on ringed sites
Lower native prerequisite: spaces-properties.tex / lemma-etale-morphism-topoi. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Local algebra
Lower native prerequisite: etale-cohomology.tex / lemma-morphism-locally-ringed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-geometric-lift-to-cover. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms and sheaves on ringed sites
Lower native prerequisite: spaces-properties.tex / lemma-points-small-etale-site. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Local algebra
Lower native prerequisite: sites-modules.tex / lemma-locally-ringed-morphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex, spaces-properties.tex.
Étale morphisms and sheaves on ringed sites
Lower native prerequisite: spaces-properties.tex / lemma-etale-site-locally-ringed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
The geometric construction
Lower native prerequisite: etale-cohomology.tex / theorem-fully-faithful. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Sheaves on ringed sites and local algebra
Lower native prerequisite: sites-modules.tex / lemma-relocalize-morphism-ringed-topoi. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Local algebra
Lower native prerequisite: spaces-properties.tex / lemma-relocalize-morphism-at-schemes. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-faithful. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-f-map. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms and smooth morphisms
Lower native prerequisite: descent.tex / lemma-syntomic-smooth-etale-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms
Lower native prerequisite: morphisms.tex / lemma-etale-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, spaces-properties.tex.
The geometric construction
Lower native prerequisite: schemes.tex / lemma-glue-functors. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Criteria for étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-characterize-surjective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms and local algebra
Lower native prerequisite: etale-cohomology.tex / lemma-describe-etale-local-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-perfect.tex, spaces-properties.tex.
Sheaves on ringed sites
Lower native prerequisite: etale-cohomology.tex / theorem-exactness-stalks. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Derived Hom and Ext
Lower native prerequisite: sites-modules.tex / lemma-internal-hom-restriction. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: descent.tex / lemma-properties-quasi-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms and field extensions
Lower native prerequisite: morphisms.tex / lemma-etale-over-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, flat.tex, spaces-properties.tex.
Sheaves on ringed sites
Lower native prerequisite: spaces-properties.tex / lemma-stalk-exact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Sheaves on ringed sites
Lower native prerequisite: spaces-properties.tex / lemma-stalk-gives-point. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Sheaves on ringed sites
Lower native prerequisite: sites.tex / lemma-point-morphism-sites. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex, spaces-more-morphisms.tex, spaces-perfect.tex, spaces-properties.tex.
Pullback of sheaves on ringed sites
Lower native prerequisite: sites.tex / lemma-pullback-representable-sheaf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms
Lower native prerequisite: morphisms.tex / lemma-etale-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, flat.tex, more-morphisms.tex, spaces-perfect.tex, spaces-properties.tex.
The geometric construction
Lower native prerequisite: topology.tex / lemma-quotient. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale geometry of algebraic spaces
Lower native prerequisite: spaces-properties.tex / lemma-scheme-points. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
The geometric construction
Lower native prerequisite: topology.tex / lemma-open-morphism-quotient-topology. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, spaces-properties.tex.
Localization of local algebra
Lower native prerequisite: sites.tex / lemma-localize-morphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex, spaces-properties.tex.
Base change for étale morphisms
Lower native prerequisite: morphisms.tex / lemma-base-change-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex, spaces-properties.tex.
Base change for diagonals and separation
Lower native prerequisite: schemes.tex / lemma-base-change-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex, spaces-properties.tex.
Noetherian rings and local algebra
Lower native prerequisite: topology.tex / lemma-quasi-compact-locally-Noetherian-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Noetherian rings
Lower native prerequisite: topology.tex / lemma-image-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
The topology of a Noetherian spectrum
Lower native prerequisite: properties.tex / lemma-Noetherian-topology. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Étale morphisms and diagonals and separation
Lower native prerequisite: spaces-properties.tex / lemma-quasi-separated-finite-etale-cover-dense-open-scheme. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Proper morphisms
Lower native prerequisite: more-groupoids.tex / lemma-property-invariant. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Descent of proper morphisms and finite algebras
Lower native prerequisite: descent.tex / lemma-descending-property-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, spaces-properties.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-generically-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-quasi-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Finite algebras and local algebra
Lower native prerequisite: morphisms.tex / lemma-quasi-finite-locally-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Diagonals and separation
Lower native prerequisite: spaces-properties.tex / lemma-separated-cover. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
The geometric construction
Lower native prerequisite: schemes.tex / lemma-map-into-reduction. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, spaces-properties.tex.
Proper morphisms
Lower native prerequisite: spaces-properties.tex / lemma-type-property. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Proper morphisms and tensor products and direct sums
Lower native prerequisite: spaces.tex / lemma-product-representable-transformations-property. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Modules and sheaves on ringed sites
Lower native prerequisite: sheaves.tex / lemma-stalk-pullback-modules. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
The geometric construction
Lower native prerequisite: schemes.tex / lemma-scheme-sober. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Flatness
Lower native prerequisite: morphisms.tex / lemma-generalizations-lift-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
The geometric construction
Lower native prerequisite: topology.tex / lemma-quotient-kolmogorov. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Local algebra
Lower native prerequisite: topology.tex / lemma-sober-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-properties.tex.
Derived Hom, Ext and injective resolutions
Lower native prerequisite: sites-cohomology.tex / lemma-RHom-into-K-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived Hom, Ext and derived tensor products and Tor amplitude
Lower native prerequisite: sites-cohomology.tex / lemma-RHom-from-K-flat-into-K-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived Hom and Ext
Lower native prerequisite: sites-cohomology.tex / lemma-internal-hom-composition. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived modules on ringed sites
Lower native prerequisite: sites-cohomology.tex / lemma-evaluate-and-more. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Base change for derived categories
Lower native prerequisite: sites-cohomology.tex / lemma-derived-base-change. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Tensor products and direct sums
Lower native prerequisite: sites-modules.tex / lemma-tensor-product-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex, sites-modules.tex.
Flatness and tensor products and direct sums
Lower native prerequisite: sites-modules.tex / lemma-tensor-flats. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived tensor products, Tor amplitude and flatness
Lower native prerequisite: sites-cohomology.tex / lemma-tensor-product-K-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived tensor products, Tor amplitude and flatness
Lower native prerequisite: sites-cohomology.tex / lemma-K-flat-resolution. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Finite presentation and flatness
Lower native prerequisite: sites-modules.tex / lemma-flat-locally-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Tor vanishing for a flat module
Lower native prerequisite: sites-cohomology.tex / lemma-flat-tor-zero. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Flatness
Lower native prerequisite: sites-cohomology.tex / lemma-last-one-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Flat modules in a short exact sequence
Lower native prerequisite: sites-modules.tex / lemma-flat-ses. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived Hom and Ext
Lower native prerequisite: sites-cohomology.tex / lemma-internal-hom. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Local algebra
Lower native prerequisite: sites-cohomology.tex / lemma-local-homotopy. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived tensor products and Tor amplitude
Lower native prerequisite: sites-cohomology.tex / lemma-tor-amplitude-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex, spaces-perfect.tex.
Local algebra
Lower native prerequisite: sites-cohomology.tex / lemma-local-lift-map. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Injective resolutions
Lower native prerequisite: derived.tex / lemma-K-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
The geometric construction
Lower native prerequisite: sites-modules.tex / lemma-extension-by-zero. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex, spaces-perfect.tex.
Injective resolutions
Lower native prerequisite: derived.tex / lemma-adjoint-preserve-K-injectives. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Dimension and codimension
Lower native prerequisite: sites-cohomology.tex / lemma-is-limit-dimension. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex, spaces-perfect.tex.
Derived modules on ringed sites
Lower native prerequisite: sites-cohomology.tex / lemma-RGamma-commutes-with-Rlim. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Sheaf cohomology and sheaves on ringed sites
Lower native prerequisite: sites-cohomology.tex / lemma-sheafification-cohomology. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived modules on ringed sites
Lower native prerequisite: sites-cohomology.tex / lemma-higher-direct-images. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived Hom, Ext and sheaves on ringed sites
Lower native prerequisite: sites-modules.tex / lemma-morphism-ringed-topoi-comes-from-morphism-ringed-sites. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Sheaf cohomology
Lower native prerequisite: sites-cohomology.tex / lemma-cech-vanish-collection. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, sites-cohomology.tex.
Sheaf cohomology and injective resolutions
Lower native prerequisite: sites-cohomology.tex / lemma-injective-module-trivial-cech. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Sheaves on ringed sites
Lower native prerequisite: sites.tex / lemma-morphism-of-sites-covering. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-cohomology.tex.
Derived Hom, Ext and projective and locally free modules
Lower native prerequisite: sites-cohomology.tex / lemma-Rhom-complex-of-direct-summands-finite-free. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-perfect.tex.
Morphisms of algebraic spaces
Lower native prerequisite: spaces-morphisms.tex / lemma-scheme-theoretic-union. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-perfect.tex.
Proper morphisms
Lower native prerequisite: spaces-morphisms.tex / lemma-scheme-theoretic-image-is-proper. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-perfect.tex.
Derived categories and tensor products and direct sums
Lower native prerequisite: injectives.tex / lemma-derived-products. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-perfect.tex.
Construction of a differential graded injective resolution
Lower native prerequisite: derived.tex / lemma-make-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-easier-axiom-four. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex.
Filtered limits and tensor products and direct sums
Lower native prerequisite: categories.tex / lemma-limits-products-equalizers. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-good-right-resolution-gives-qis. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex.
Derived categories
Lower native prerequisite: derived.tex / lemma-pre-derived-adjoint-functors-general. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-good-resolution-gives-qis. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex.
Triangulated categories
Lower native prerequisite: derived.tex / lemma-compact-objects-subcategory. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are dga.tex.
Smooth morphisms and Artinian rings
Lower native prerequisite: algebra.tex / lemma-smooth-test-artinian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Finite algebras and local algebra
Lower native prerequisite: morphisms.tex / lemma-locally-finite-type-characterize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex, flat.tex, more-morphisms.tex.
Noetherian rings and local algebra
Lower native prerequisite: properties.tex / lemma-locally-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Noetherian rings
Lower native prerequisite: properties.tex / lemma-normal-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
The geometric construction
Lower native prerequisite: more-morphisms.tex / lemma-normal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
The geometric construction
Lower native prerequisite: more-morphisms.tex / lemma-fibre-geometrically-connected-reduced. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Prime spectra, associated points and local algebra
Lower native prerequisite: algebra.tex / lemma-unique-prime-over-localize-below. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex.
Dimension and codimension
Lower native prerequisite: morphisms.tex / lemma-openness-bounded-dimension-fibres. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex, more-morphisms.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / lemma-fppf-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex.
Finite presentation and flatness
Lower native prerequisite: more-morphisms.tex / lemma-flat-finite-presentation-CM-pieces. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Finite presentation and flatness
Lower native prerequisite: more-morphisms.tex / lemma-flat-finite-presentation-CM-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for nilpotent thickenings
Lower native prerequisite: more-morphisms.tex / lemma-base-change-thickening. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Integral extensions
Lower native prerequisite: morphisms.tex / lemma-integral-universally-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex, limits.tex, more-groupoids.tex, more-morphisms.tex.
Affine neighbourhoods and nilpotent thickenings
Lower native prerequisite: limits.tex / lemma-thickening-quasi-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / lemma-reduction-universal-homeomorphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for flatness and modules
Lower native prerequisite: morphisms.tex / lemma-base-change-module-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex.
Composition and flatness
Lower native prerequisite: algebra.tex / lemma-composition-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex.
Criteria for finite presentation and flatness
Lower native prerequisite: algebra.tex / lemma-criterion-flatness-fibre-fp-over-ft. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Integral extensions and finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-integral. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, spaces-more-morphisms.tex.
Étale morphisms and flatness
Lower native prerequisite: morphisms.tex / lemma-etale-flat-etale-fibres. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Étale morphisms and unramified morphisms
Lower native prerequisite: morphisms.tex / lemma-unramified-etale-fibres. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Flatness and smooth morphisms
Lower native prerequisite: morphisms.tex / lemma-smooth-flat-smooth-fibres. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Flatness
Lower native prerequisite: morphisms.tex / lemma-syntomic-flat-fibres. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-quasi-finite-at-point-characterize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Flatness and nilpotent thickenings
Lower native prerequisite: more-morphisms.tex / lemma-flatness-morphism-thickenings. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for projective, locally free modules and finite algebras
Lower native prerequisite: morphisms.tex / lemma-base-change-finite-locally-free. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for finite algebras
Lower native prerequisite: morphisms.tex / lemma-base-change-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex.
Base change for unramified morphisms
Lower native prerequisite: morphisms.tex / lemma-base-change-unramified. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change of smooth ring maps
Lower native prerequisite: morphisms.tex / lemma-base-change-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex.
Base change for the geometric construction
Lower native prerequisite: morphisms.tex / lemma-base-change-syntomic. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for dimension and codimension
Lower native prerequisite: morphisms.tex / lemma-base-change-relative-dimension-d. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, more-morphisms.tex.
Base change for finite algebras
Lower native prerequisite: morphisms.tex / lemma-base-change-quasi-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for injective resolutions
Lower native prerequisite: morphisms.tex / lemma-base-change-universally-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for the geometric construction
Lower native prerequisite: morphisms.tex / lemma-base-change-surjective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for the geometric construction
Lower native prerequisite: schemes.tex / lemma-base-change-monomorphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Diagonals and separation
Lower native prerequisite: schemes.tex / lemma-separated-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex.
Base change for the geometric construction
Lower native prerequisite: schemes.tex / lemma-quasi-compact-preserved-base-change. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex.
Cotangent complexes, differentials and affine neighbourhoods
Lower native prerequisite: more-morphisms.tex / lemma-NL-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Cotangent complexes, differentials and diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-differentials-diagonal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex, spaces-more-morphisms.tex.
Affine neighbourhoods
Lower native prerequisite: schemes.tex / lemma-morphism-into-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex.
The geometric construction
Lower native prerequisite: more-morphisms.tex / lemma-good-case. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
The geometric construction
Lower native prerequisite: more-morphisms.tex / lemma-bad-case. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Criteria for Noetherian rings
Lower native prerequisite: topology.tex / lemma-characterize-constructible-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for prime spectra and associated points
Lower native prerequisite: more-morphisms.tex / lemma-base-change-assassin-in-U. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Criteria for affine neighbourhoods
Lower native prerequisite: morphisms.tex / lemma-characterize-quasi-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, more-morphisms.tex.
Diagonals, separation and finite algebras
Lower native prerequisite: more-morphisms.tex / lemma-finite-type-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Étale morphisms and field extensions
Lower native prerequisite: more-morphisms.tex / lemma-realize-prescribed-residue-field-extension-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Criteria for the geometric construction
Lower native prerequisite: varieties.tex / lemma-characterize-geometrically-disconnected. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Proper morphisms and prime spectra and associated points
Lower native prerequisite: constructions.tex / lemma-spec-properties. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Composition and diagonals and separation
Lower native prerequisite: schemes.tex / lemma-compose-after-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / lemma-normalization-in-universally-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / lemma-universally-closed-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Sheaf cohomology and affine neighbourhoods
Lower native prerequisite: coherent.tex / lemma-relative-affine-cohomology. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Groupoids and equivalence relations
Lower native prerequisite: morphisms.tex / lemma-i-star-equivalence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for pseudo-coherent complexes and coherent sheaves
Lower native prerequisite: more-morphisms.tex / lemma-base-change-relative-pseudo-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Pseudo-coherent complexes and coherent sheaves
Lower native prerequisite: more-morphisms.tex / lemma-relative-pseudo-coherence-characterize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Criteria for finite algebras
Lower native prerequisite: more-morphisms.tex / lemma-characterize-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Projective, locally free modules and finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-locally-free. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Étale morphisms and finite algebras
Lower native prerequisite: more-morphisms.tex / lemma-etale-splits-off-quasi-finite-part. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Derived tensor products, Tor amplitude and diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-factor-quasi-compact-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Pullback of line bundles, ampleness and tensor products and direct sums
Lower native prerequisite: morphisms.tex / lemma-pullback-ample-tensor-relatively-ample. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex, more-morphisms.tex, spaces-descent.tex.
Line bundles and ampleness
Lower native prerequisite: coherent.tex / lemma-ample-in-neighbourhood. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Base change for cotangent complexes and differentials
Lower native prerequisite: morphisms.tex / lemma-base-change-differentials. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Sheaves on ringed sites and finite algebras
Lower native prerequisite: modules.tex / lemma-finite-type-stalk-zero. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-morphisms.tex.
Cotangent complexes, differentials and finite presentation
Lower native prerequisite: spaces-more-morphisms.tex / lemma-finite-presentation-differentials. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Étale morphisms
Lower native prerequisite: spaces-more-morphisms.tex / lemma-etale-on-top. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Composition and formal smoothness and étale morphisms
Lower native prerequisite: spaces-more-morphisms.tex / lemma-composition-formally-smooth-etale-unramified. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Proper morphisms
Lower native prerequisite: spaces-more-morphisms.tex / lemma-representable-property-formally-property. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Derived modules on ringed sites
Lower native prerequisite: sites-cohomology.tex / lemma-torsors-h1. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Sheaves on ringed sites
Lower native prerequisite: spaces-more-morphisms.tex / lemma-action-sheaf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Sheaves on ringed sites
Lower native prerequisite: spaces-more-morphisms.tex / lemma-sheaf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Smooth morphisms and local algebra
Lower native prerequisite: spaces-morphisms.tex / lemma-smooth-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Formal smoothness and smooth morphisms
Lower native prerequisite: more-morphisms.tex / lemma-smooth-formally-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Formal smoothness and smooth morphisms
Lower native prerequisite: spaces-more-morphisms.tex / lemma-helper-formally-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Localization of cotangent complexes, differentials and local algebra
Lower native prerequisite: spaces-more-morphisms.tex / lemma-localize-differentials. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Cotangent complexes, differentials and tensor products and direct sums
Lower native prerequisite: morphisms.tex / lemma-differential-product. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Cotangent complexes and differentials
Lower native prerequisite: spaces-more-morphisms.tex / lemma-functoriality-differentials. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Cotangent complexes, differentials and étale morphisms
Lower native prerequisite: spaces-more-morphisms.tex / lemma-etale-conormal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Cotangent complexes, differentials and diagonals and separation
Lower native prerequisite: spaces-more-morphisms.tex / lemma-differentials-relative-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Base change for nilpotent thickenings
Lower native prerequisite: spaces-more-morphisms.tex / lemma-base-change-thickening. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Affine neighbourhoods
Lower native prerequisite: spaces-limits.tex / proposition-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Pullback of cotangent complexes and differentials
Lower native prerequisite: sites-modules.tex / lemma-pullback-NL. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Étale morphisms
Lower native prerequisite: spaces-properties.tex / lemma-etale-exact-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Affine neighbourhoods
Lower native prerequisite: spaces-limits.tex / lemma-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Affine neighbourhoods
Lower native prerequisite: spaces-properties.tex / lemma-morphism-to-affine-scheme. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Nilpotent thickenings
Lower native prerequisite: spaces-more-morphisms.tex / lemma-open-subspace-thickening. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Descent of algebraic spaces
Lower native prerequisite: spaces-limits.tex / lemma-reduction-scheme. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
The geometric construction
Lower native prerequisite: etale-cohomology.tex / theorem-topological-invariance. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
The geometric construction
Lower native prerequisite: spaces-descent.tex / lemma-fpqc-universal-effective-epimorphisms. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Pseudo-coherent complexes and finite presentation
Lower native prerequisite: more-morphisms.tex / lemma-flat-finite-presentation-pseudo-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Pullback of pseudo-coherent complexes and coherent sheaves
Lower native prerequisite: more-morphisms.tex / lemma-pull-relative-pseudo-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Pseudo-coherent complexes and coherent sheaves
Lower native prerequisite: more-morphisms.tex / lemma-relative-pseudo-coherent-post-compose. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Pseudo-coherent complexes and coherent sheaves
Lower native prerequisite: more-morphisms.tex / lemma-relative-pseudo-coherent-descends-fppf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Pseudo-coherent complexes and quasi-coherent complexes
Lower native prerequisite: more-morphisms.tex / lemma-qcoh-relative-pseudo-coherence-characterize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Base change for diagonals and separation
Lower native prerequisite: spaces.tex / lemma-base-change-immersions. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-more-morphisms.tex.
Affine neighbourhoods
Lower native prerequisite: limits.tex / lemma-directed-inverse-system-affine-schemes-has-limit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Affine neighbourhoods and groupoids and equivalence relations
Lower native prerequisite: morphisms.tex / lemma-affine-equivalence-algebras. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Criteria for affine neighbourhoods
Lower native prerequisite: morphisms.tex / lemma-characterize-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Finite presentation and proper morphisms
Lower native prerequisite: limits.tex / lemma-proper-limit-of-proper-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Affine neighbourhoods
Lower native prerequisite: limits.tex / lemma-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Finite presentation and integral extensions
Lower native prerequisite: limits.tex / lemma-integral-limit-finite-and-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-image-universally-closed-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Filtered limits and finite-presentation descent
Lower native prerequisite: limits.tex / lemma-limit-nonempty. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Approximation of a marked family with its associated graded algebra
Lower native prerequisite: limits.tex / lemma-approximate. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Diagonals and separation
Lower native prerequisite: limits.tex / lemma-eventually-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Finite presentation and finite algebras
Lower native prerequisite: limits.tex / lemma-finite-type-is-limit-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Finite-presentation descent
Lower native prerequisite: limits.tex / lemma-topology-limit. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Filtered limits and finite-presentation descent
Lower native prerequisite: limits.tex / lemma-limit-closed-nonempty. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Filtered limits and affine neighbourhoods
Lower native prerequisite: limits.tex / lemma-limit-quasi-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Diagonals and separation
Lower native prerequisite: topology.tex / lemma-topology-quasi-separated-scheme. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
The geometric construction
Lower native prerequisite: sheaves.tex / lemma-directed-colimits-sections. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Filtered limits and commutative algebra
Lower native prerequisite: algebra.tex / lemma-colimit-surjective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Descent of finite presentation and affine neighbourhoods
Lower native prerequisite: limits.tex / lemma-descend-affine-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Diagonals, separation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-immersion-locally-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Filtered limits and finite-presentation descent
Lower native prerequisite: limits.tex / lemma-limit-contained-in-constructible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / example-scheme-theoretic-image. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Line bundles, ampleness and diagonals and separation
Lower native prerequisite: properties.tex / lemma-ample-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Descent of finite-presentation descent
Lower native prerequisite: limits.tex / lemma-descend-isomorphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Diagonals, separation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-diagonal-morphism-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
The geometric construction
Lower native prerequisite: schemes.tex / lemma-monomorphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Filtered limits and étale morphisms
Lower native prerequisite: algebra.tex / lemma-colimit-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Étale morphisms
Lower native prerequisite: morphisms.tex / lemma-etale-characterize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
The geometric construction
Lower native prerequisite: schemes.tex / lemma-glue-schemes. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Finite presentation and diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-finite-presentation-quasi-compact-quasi-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Noetherian rings
Lower native prerequisite: coherent.tex / lemma-chow-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Composition and proper morphisms
Lower native prerequisite: morphisms.tex / lemma-composition-proper. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Line bundles and ampleness
Lower native prerequisite: modules.tex / lemma-invertible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are limits.tex.
Descent of proper morphisms
Lower native prerequisite: descent.tex / lemma-descending-properties-morphisms. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Descent of proper morphisms and diagonals and separation
Lower native prerequisite: descent.tex / lemma-descending-property-closed-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-zariski-descent-effective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-standard-fpqc-covering. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-refine-descent-datum. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: topologies.tex / lemma-fpqc. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, flat.tex.
Flatness
Lower native prerequisite: algebra.tex / lemma-flatness-descends. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, groupoids.tex.
The geometric construction
Lower native prerequisite: schemes.tex / lemma-specialize-points. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms
Lower native prerequisite: descent.tex / lemma-etale-on-fiber. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Finite presentation and finite algebras
Lower native prerequisite: algebra.tex / lemma-finite-presentation-descends. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Finite presentation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-locally-finite-presentation-characterize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Affine neighbourhoods
Lower native prerequisite: schemes.tex / lemma-quasi-compact-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-ff-exact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: morphisms.tex / lemma-fpqc-quotient-topology. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, spaces-descent.tex.
Tensor products and direct sums
Lower native prerequisite: descent.tex / lemma-equiv-fibre-product. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-universal-effective-epimorphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-open-fpqc-covering. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex, spaces-descent.tex.
Proper morphisms and sheaves on ringed sites
Lower native prerequisite: topologies.tex / lemma-sheaf-property-fpqc. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Derived gluing across an elementary distinguished square
Lower native prerequisite: schemes.tex / lemma-glue. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Descent of proper morphisms and affine neighbourhoods
Lower native prerequisite: descent.tex / lemma-descending-property-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Affine neighbourhoods
Lower native prerequisite: descent.tex / lemma-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Base change for affine neighbourhoods
Lower native prerequisite: morphisms.tex / lemma-base-change-quasi-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: constructions.tex / lemma-relative-glueing. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-refine-coverings-fully-faithful. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: descent.tex / lemma-family-is-one. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Affine neighbourhoods
Lower native prerequisite: topologies.tex / lemma-syntomic-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Smooth morphisms and affine neighbourhoods
Lower native prerequisite: topologies.tex / lemma-smooth-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms and affine neighbourhoods
Lower native prerequisite: topologies.tex / lemma-etale-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Affine neighbourhoods
Lower native prerequisite: topologies.tex / lemma-fppf-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Affine neighbourhoods
Lower native prerequisite: topologies.tex / lemma-fpqc-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Flatness and sheaves on ringed sites
Lower native prerequisite: sites-modules.tex / lemma-flatness-sheafification-refined. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Quasi-coherent complexes and sheaf cohomology
Lower native prerequisite: coherent.tex / lemma-cech-cohomology-quasi-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Sheaf cohomology
Lower native prerequisite: sites-cohomology.tex / lemma-cech-spectral-sequence-application. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Quasi-coherent complexes and sheaf cohomology
Lower native prerequisite: descent.tex / lemma-standard-covering-Cech-quasi-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Derived Hom and Ext
Lower native prerequisite: sites-modules.tex / lemma-internal-hom. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Prime spectra and associated points
Lower native prerequisite: descent.tex / lemma-fully-faithful-associated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Quasi-coherent complexes and coherent sheaves
Lower native prerequisite: descent.tex / lemma-quasi-coherent-gives-quasi-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms and smooth morphisms
Lower native prerequisite: topologies.tex / lemma-zariski-etale-smooth-syntomic-fppf-fpqc. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms and smooth morphisms
Lower native prerequisite: topologies.tex / lemma-zariski-etale-smooth-syntomic-fppf. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms and smooth morphisms
Lower native prerequisite: topologies.tex / lemma-zariski-etale-smooth-syntomic. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms and smooth morphisms
Lower native prerequisite: topologies.tex / lemma-zariski-etale-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms
Lower native prerequisite: topologies.tex / lemma-zariski-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms
Lower native prerequisite: topologies.tex / lemma-morphism-big-small-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Étale morphisms
Lower native prerequisite: topologies.tex / lemma-put-in-T-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Modules
Lower native prerequisite: sites-modules.tex / lemma-push-pull-composition-modules. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: topologies.tex / lemma-morphism-big-small. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
The geometric construction
Lower native prerequisite: topologies.tex / lemma-put-in-T. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are descent.tex.
Base change for the geometric construction
Lower native prerequisite: spaces-divisors.tex / lemma-relative-proj-base-change. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-divisors.tex.
Line bundles, ampleness and diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-relatively-ample-separated. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-divisors.tex.
Descent of line bundles and ampleness
Lower native prerequisite: spaces-divisors.tex / lemma-descend-relatively-ample. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-divisors.tex.
Prime spectra, associated points and finite algebras
Lower native prerequisite: divisors.tex / lemma-relative-weak-assassin-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-divisors.tex.
The general fibrewise injectivity criterion for module maps
Lower native prerequisite: algebra.tex / lemma-mod-injective-general. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Composition and injective resolutions
Lower native prerequisite: algebra.tex / lemma-composition-universally-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Injective resolutions and tensor products and direct sums
Lower native prerequisite: algebra.tex / lemma-universally-injective-tensor. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Injective resolutions
Lower native prerequisite: algebra.tex / lemma-universally-injective-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Projective and locally free modules
Lower native prerequisite: algebra.tex / lemma-countgen-projective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Modules
Lower native prerequisite: algebra.tex / lemma-pure-submodule-ML. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Projective, locally free modules and local algebra
Lower native prerequisite: descent.tex / lemma-locally-projective-descends. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Noetherian rings and tensor products and direct sums
Lower native prerequisite: algebra.tex / lemma-product-over-Noetherian-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Coherent sheaves and Noetherian rings
Lower native prerequisite: algebra.tex / lemma-Noetherian-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Criteria for coherent sheaves
Lower native prerequisite: algebra.tex / proposition-characterize-coherent. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Flatness
Lower native prerequisite: algebra.tex / lemma-ui-flat-domain. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Krull's intersection theorem
Lower native prerequisite: algebra.tex / lemma-intersect-powers-ideal-module-zero. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, formal-defos.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-zero-at-ass-zero. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Projective, locally free modules and local algebra
Lower native prerequisite: algebra.tex / theorem-projective-free-over-local-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Finite algebras
Lower native prerequisite: algebra.tex / lemma-finite-ass. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Complete rings and formal power series
Lower native prerequisite: algebra.tex / lemma-split-completed-sequence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-bourbaki-fibres. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Prime spectra, associated points and finite algebras
Lower native prerequisite: divisors.tex / lemma-weakly-associated-finite. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
The geometric construction
Lower native prerequisite: divisors.tex / lemma-weakly-ass-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Étale morphisms
Lower native prerequisite: more-morphisms.tex / lemma-elementary-etale-neighbourhoods. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-weakly-ass. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
An elementary algebraic comparison
Lower native prerequisite: algebra.tex / lemma-silly. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, groupoids.tex, more-groupoids.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-ass-zero-divisors. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Local algebra
Lower native prerequisite: algebra.tex / lemma-weakly-ass-local. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-ass-weakly-ass. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Injective resolutions and flatness
Lower native prerequisite: algebra.tex / lemma-flat-universally-injective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Filtered limits and injective resolutions
Lower native prerequisite: algebra.tex / lemma-colimit-universally-injective-ML. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Étale morphisms and local algebra
Lower native prerequisite: morphisms.tex / lemma-etale-locally-standard-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Permanence of flat ring maps
Lower native prerequisite: morphisms.tex / lemma-flat-permanence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Tensor products and direct sums
Lower native prerequisite: schemes.tex / lemma-points-fibre-product. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-ass-quotient-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / theorem-ffdescent-projectivity. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Complete rings, formal power series and flatness
Lower native prerequisite: algebra.tex / lemma-completion-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Flatness
Lower native prerequisite: algebra.tex / lemma-generic-flatness-reduced. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Lifting projective and locally free modules
Lower native prerequisite: algebra.tex / lemma-lift-projective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Descent of proper morphisms and modules
Lower native prerequisite: algebra.tex / lemma-descend-properties-modules. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex, groupoids.tex.
Finite presentation and modules
Lower native prerequisite: descent.tex / lemma-finite-finitely-presented-module. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Finite presentation and finite algebras
Lower native prerequisite: descent.tex / lemma-finite-presentation-descends. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Pullback of finite presentation and finite algebras
Lower native prerequisite: modules.tex / lemma-pullback-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Composition and finite presentation and finite algebras
Lower native prerequisite: morphisms.tex / lemma-composition-finite-presentation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
The geometric construction
Lower native prerequisite: divisors.tex / lemma-ses-weakly-ass. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
The geometric construction
Lower native prerequisite: divisors.tex / lemma-weakly-ass-zero. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Proper morphisms and modules
Lower native prerequisite: algebra.tex / lemma-ascend-properties-modules. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Prime spectra and associated points
Lower native prerequisite: more-morphisms.tex / lemma-associated-point-specializes. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Noetherian rings
Lower native prerequisite: more-morphisms.tex / lemma-Noetherian-approximation-combine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Noetherian rings
Lower native prerequisite: more-morphisms.tex / lemma-Noetherian-approximation-geometrically-irreducible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Noetherian rings
Lower native prerequisite: more-morphisms.tex / lemma-Noetherian-approximation-geometrically-reduced. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Flatness and Noetherian rings
Lower native prerequisite: more-morphisms.tex / lemma-Noetherian-approximation-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
The spectrum of a localization
Lower native prerequisite: algebra.tex / lemma-spec-localization. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Étale morphisms and injective resolutions
Lower native prerequisite: descent.tex / lemma-universally-injective-etale-open-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Diagonals and separation
Lower native prerequisite: descent.tex / lemma-closed-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Sheaves on ringed sites and finite algebras
Lower native prerequisite: modules.tex / lemma-finite-type-surjective-on-stalk. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Projective, locally free modules and finite algebras
Lower native prerequisite: algebra.tex / lemma-finite-projective-descends. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Base change for the geometric construction
Lower native prerequisite: more-morphisms.tex / lemma-base-change-fibres-geometrically-irreducible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Injective resolutions and local algebra
Lower native prerequisite: algebra.tex / lemma-universally-injective-localize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Base change for diagonals and separation
Lower native prerequisite: morphisms.tex / lemma-base-change-closed-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Affine neighbourhoods and tensor products and direct sums
Lower native prerequisite: schemes.tex / lemma-fibre-product-affines. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Affine neighbourhoods and finite algebras
Lower native prerequisite: more-morphisms.tex / lemma-local-local-structure-finite-type-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Finite algebras and local algebra
Lower native prerequisite: more-morphisms.tex / lemma-local-local-structure-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Pullback of finite algebras
Lower native prerequisite: modules.tex / lemma-pullback-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Smooth morphisms
Lower native prerequisite: morphisms.tex / lemma-smooth-open. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are flat.tex.
Cotangent complexes, differentials and sheaves on ringed sites
Lower native prerequisite: sites-modules.tex / lemma-differentials-sheafify. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Cotangent complexes and differentials
Lower native prerequisite: sites-modules.tex / lemma-differential-seq. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Tor vanishing for a flat module
Lower native prerequisite: sites-modules.tex / lemma-flat-tor-zero. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Flatness
Lower native prerequisite: sites-modules.tex / lemma-flat-change-of-rings. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
The geometric construction
Lower native prerequisite: sites-modules.tex / lemma-exactness-pushforward-pullback. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Compatibility of successive localizations of ringed sites
Lower native prerequisite: sites.tex / lemma-relocalize. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Sheaves on ringed sites
Lower native prerequisite: sites.tex / lemma-point-morphism-topoi. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Sheaves on ringed sites
Lower native prerequisite: sites-modules.tex / lemma-check-exactness-stalks. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Derived tensor products, Tor amplitude and flatness
Lower native prerequisite: sites-modules.tex / lemma-stalk-flat. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
Localization of local algebra
Lower native prerequisite: sites.tex / lemma-localize-morphism-strong. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are sites-modules.tex.
The naive cotangent complex up to quasi-isomorphism
Lower native prerequisite: modules.tex / lemma-NL-up-to-qis. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are defos.tex.
Pullback of cotangent complexes and differentials
Lower native prerequisite: modules.tex / lemma-pullback-NL. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are defos.tex.
Quasi-compactness of an affine spectrum
Lower native prerequisite: sites.tex / lemma-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are defos.tex.
Affine neighbourhoods
Lower native prerequisite: properties.tex / lemma-invert-f-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Diagonals and separation
Lower native prerequisite: schemes.tex / lemma-section-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Affine neighbourhoods
Lower native prerequisite: properties.tex / lemma-quasi-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Constructing an invariant affine neighbourhood
Lower native prerequisite: morphisms.tex / lemma-get-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Affine neighbourhoods
Lower native prerequisite: more-groupoids.tex / lemma-invariant-affine-open-around-generic-point. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
The geometric construction
Lower native prerequisite: schemes.tex / lemma-quasi-compact-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Finite algebras
Lower native prerequisite: more-groupoids.tex / lemma-finite-stratify. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Groupoids and equivalence relations
Lower native prerequisite: groupoids.tex / lemma-restrict-groupoid-relation. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Finite algebras
Lower native prerequisite: more-groupoids.tex / lemma-quasi-finite-over-base. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
The geometric construction
Lower native prerequisite: topology.tex / lemma-constructible-stable-specialization-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Criteria for Noetherian rings
Lower native prerequisite: topology.tex / lemma-characterize-closed-Noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are more-groupoids.tex.
Criteria for the geometric construction
Lower native prerequisite: varieties.tex / lemma-characterize-geometrically-connected. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
The geometric construction
Lower native prerequisite: varieties.tex / lemma-geometrically-connected-criterion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Field extensions
Lower native prerequisite: algebra.tex / lemma-field-extension-geometrically-irreducible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Affine neighbourhoods and finite algebras
Lower native prerequisite: varieties.tex / lemma-finite-set-codim-1-points-in-affine. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Affine neighbourhoods and finite algebras
Lower native prerequisite: varieties.tex / lemma-finite-set-codim-1-points-in-affine-per-component. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Dimension, codimension and field extensions
Lower native prerequisite: algebra.tex / lemma-dimension-at-a-point-finite-type-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Irreducibility of an affine spectrum
Lower native prerequisite: topology.tex / lemma-irreducible. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Dimension, codimension and field extensions
Lower native prerequisite: algebra.tex / lemma-dimension-at-a-point-finite-type-over-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Dimension and codimension
Lower native prerequisite: algebra.tex / lemma-dimension-spell-it-out. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Finite algebras and local algebra
Lower native prerequisite: varieties.tex / lemma-locally-finite-type-Jacobson. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Dimension, codimension and field extensions
Lower native prerequisite: algebra.tex / lemma-dimension-closed-point-finite-type-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-CM-ring-catenary. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Height and dimension in a polynomial ring
Lower native prerequisite: algebra.tex / lemma-dimension-height-polynomial-ring. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-quotient-catenary. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-catenary. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
The geometric construction
Lower native prerequisite: topology.tex / lemma-catenary. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are varieties.tex.
Coherent sheaves
Lower native prerequisite: quot.tex / theorem-coherent-algebraic-general. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
Coherent sheaves
Lower native prerequisite: quot.tex / theorem-coherent-algebraic. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
The geometric construction
Lower native prerequisite: algebraic.tex / lemma-representable-morphism-to-algebraic. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
Line bundles and ampleness
Lower native prerequisite: quot.tex / lemma-picard-stack-open-in-coh. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
The geometric construction
Lower native prerequisite: quot.tex / proposition-quot. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
The geometric construction
Lower native prerequisite: quot.tex / lemma-hilb-is-quot. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
The geometric construction
Lower native prerequisite: spaces-more-morphisms.tex / lemma-where-isomorphism. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
The geometric construction
Lower native prerequisite: quot.tex / lemma-Mor-into-Hilb. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are quot.tex.
Line bundles and ampleness
Lower native prerequisite: spaces-divisors.tex / lemma-ample-in-neighbourhood. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
Finite presentation and proper morphisms
Lower native prerequisite: spaces-limits.tex / lemma-proper-limit-of-proper-finite-presentation-noetherian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
Sheaves on ringed sites
Lower native prerequisite: spaces-properties.tex / proposition-sheaf-fpqc. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
Descent of proper morphisms and diagonals and separation
Lower native prerequisite: spaces-descent.tex / lemma-descending-property-closed-immersion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
The geometric construction
Lower native prerequisite: spaces.tex / topologies-lemma-fpqc. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
Descent of proper morphisms and finite algebras
Lower native prerequisite: descent.tex / lemma-descending-property-locally-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
Derived Hom and Ext
Lower native prerequisite: spaces-morphisms.tex / lemma-surjection-from-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
The geometric construction
Lower native prerequisite: spaces.tex / topologies-lemma-refine-fpqc-schemes. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
The geometric construction
Lower native prerequisite: spaces.tex / topologies-definition-fpqc-covering. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are spaces-descent.tex.
The geometric construction
Lower native prerequisite: algebraic.tex / proposition-algebraic-stack-no-automorphisms. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are artin.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-enough-finite-type-points. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are artin.tex.
Proper morphisms
Lower native prerequisite: criteria.tex / lemma-check-property-limit-preserving. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are artin.tex.
Proper morphisms
Lower native prerequisite: algebraic.tex / lemma-representable-transformations-property-implication. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are artin.tex.
Formal smoothness and smooth morphisms
Lower native prerequisite: criteria.tex / lemma-representable-by-spaces-formally-smooth. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are artin.tex.
Étale morphisms
Lower native prerequisite: criteria.tex / lemma-stacks-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are artin.tex.
The geometric construction
Lower native prerequisite: sets.tex / lemma-what-is-in-it. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are artin.tex.
The geometric construction
Lower native prerequisite: constructions.tex / lemma-proj-valuative-criterion. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
The geometric construction
Lower native prerequisite: constructions.tex / lemma-proj-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
Finite algebras
Lower native prerequisite: algebra.tex / lemma-dehomogenize-finite-type. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
The geometric construction
Lower native prerequisite: divisors.tex / lemma-relative-proj-quasi-compact. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
Line bundles, ampleness and affine neighbourhoods
Lower native prerequisite: properties.tex / lemma-quasi-affine-invertible-nonvanishing-section. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
Integral extensions and field extensions
Lower native prerequisite: algebra.tex / lemma-integral-over-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
Criteria for prime spectra and associated points
Lower native prerequisite: algebra.tex / lemma-criterion-no-embedded-primes. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
Prime spectra and associated points
Lower native prerequisite: algebra.tex / proposition-minimal-primes-associated-primes. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
Field extensions and tensor products and direct sums
Lower native prerequisite: algebra.tex / lemma-tensor-fields-CM. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
The geometric construction
Lower native prerequisite: divisors.tex / lemma-bourbaki. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
Projective and locally free modules
Lower native prerequisite: morphisms.tex / lemma-quasi-projective-open-projective. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are divisors.tex.
The cartesian squares defining the pushout
Lower native prerequisite: groupoids.tex / lemma-diagram. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
The geometric construction
Lower native prerequisite: groupoids.tex / lemma-basis. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Modules and local algebra
Lower native prerequisite: algebra.tex / lemma-semi-local-module-basis-in-submodule. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
The geometric construction
Lower native prerequisite: groupoids.tex / lemma-points. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Integral extensions
Lower native prerequisite: groupoids.tex / lemma-integral-over-invariants. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Flatness and field extensions
Lower native prerequisite: algebra.tex / lemma-flat-local-given-residue-field. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Projective, locally free modules and finite algebras
Lower native prerequisite: groupoids.tex / lemma-finite-locally-free-disjoint-free. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Base change for the geometric construction
Lower native prerequisite: groupoids.tex / lemma-invariants-base-change. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Finite algebras
Lower native prerequisite: morphisms.tex / lemma-finite-monomorphism-closed. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Criteria for the geometric construction
Lower native prerequisite: groupoids.tex / lemma-criterion-quotient-representable. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are groupoids.tex.
Groupoids and equivalence relations
Lower native prerequisite: categories.tex / lemma-equivalence-fibred-categories. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
The geometric construction
Lower native prerequisite: homology.tex / lemma-additive-additive. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-ML-exact-sequence. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Finite length over an Artinian ring
Lower native prerequisite: algebra.tex / lemma-artinian-finite-length. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Commutative algebra
Lower native prerequisite: algebra.tex / lemma-length-additive. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Vector-space dimension and module length
Lower native prerequisite: algebra.tex / lemma-dimension-is-length. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Criteria for commutative algebra
Lower native prerequisite: algebra.tex / lemma-characterize-length-1. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
The geometric construction
Lower native prerequisite: categories.tex / lemma-yoneda-2category. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Uniqueness of an étale lifting
Lower native prerequisite: algebra.tex / lemma-uniqueness. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Henselianity in local dimension zero
Lower native prerequisite: algebra.tex / lemma-local-dimension-zero-henselian. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
The geometric construction
Lower native prerequisite: fields.tex / lemma-primitive-element. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Cotangent complexes and differentials
Lower native prerequisite: algebra.tex / lemma-differential-mod-power-ideal. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Smooth morphisms
Lower native prerequisite: more-morphisms.tex / lemma-slice-smooth-given-element. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
Finite étale algebras over a henselian ring
Lower native prerequisite: algebra.tex / lemma-henselian-cat-finite-etale. No separately included proof or exact verified programme binding is claimed for this supporting reference. Its consumers are formal-defos.tex.
| Mathematical foundation | Still uncovered exact claims |
|---|---|
| Schemes, limits and descent | 299 |
| Categories, topology and deformation groupoids | 82 |
| Algebraic spaces and their étale geometry | 132 |
| Commutative algebra and field extensions | 196 |
| Derived modules, homological algebra and ringed sites | 139 |
The accompanying conversion manifest lists every exact source label and its consumers. The full central constructions printed above are not reassigned to future work. A transitive proof-closure claim must wait for the listed lower obligations to be proved or bound to their exact existing programme providers.
Notation and numbered calculations
References to surrounding source sections, notation and numbered calculations retain stable anchors here. Their exact namespaces and correspondence appear in the accompanying manifest. Notation not reproduced in the reader retains its prerequisite status.
Sources and programme proofs
The human Stacks Project proofs and the AI Integrated Stacks edition are credited in the source notice. Stable invisible anchors retain every included statement, step and equation. Exact source correspondence and conversion checks accompany the reusable converter in the control record.
Existing programme proofs are cited only for the matched claims stated in their provider entries. A written provider retains its actual scope and its own dependencies; this conversion does not certify recursive closure.
- Completion, Theorems 3.1–3.3, 4.1 and 5.1, SHA-256 9f7f25fbff8633dc0ca506a3c2a4992bcb711f2518b8f32a704f8207b7ae7f3e.
- Coefficient rings and the Cohen structure theorem, Theorem 6.1 and its Noetherianity consequence, SHA-256 98155272b26f565ff6c0e0732a740aec5ff70e94d29fa98f127d9e5ca86cc765.
- Henselian local rings and henselization, Sections 4 and 6, Proposition 6.1, SHA-256 b2c6ff73da96c68eb54b3268a98af98f613967255ed6b87778c9133ea8b6a4b3.
- Formally smooth, unramified and étale ring maps, Theorem 3.1 and Sections 4–7, SHA-256 0c84318365e0d1f616a5e28c2a198e787997f83c95a3a6d892c17b3170596564.
- Smooth algebras over a field and the Jacobian criterion, Theorems 5.1–6.1 and Sections 1–3, SHA-256 f904cb9dabe15b90dba190a855f3b27229c8178dffadef82180188a81662ae49.
- Regular sequences, depth and Cohen–Macaulay modules, Propositions 1.1–1.3 and Theorem 6.1, SHA-256 2b5e3bf9f723af5187a07ca9fdc1877d1e1c3d22ccd940dfc47fad0ac8e4417b.
- Regular local rings, Theorem 1.1, SHA-256 5ff9e6d477b256fe256719cf51a334f2eb8d47220d035473f51039daed2eabce.
- Kähler differentials, Theorems 3.1–3.3, Proposition 3.4 and Theorem 7.1, SHA-256 87ad4d3d4984ab9d655490856dabdd1e4eda406f929c3b125857c5e745b530fe.
- Faithful flatness and the local criterion for flatness, Theorems 2.1–3.1, 4.2, 5.2 and 5.4, SHA-256 e101e670904bea5f8310d5fe4e6b5ace3cb68cd8d4942ca680ba808d8c58319e.
- Lesson 7, Appendix A, Lemma A.3, SHA-256 89e51708bd3e115a02841fa9b13782186f4411456a8ed545ab82af72f59ed5aa.
- Lesson 7, Lemma 3.1, SHA-256 89e51708bd3e115a02841fa9b13782186f4411456a8ed545ab82af72f59ed5aa.
- Lesson 7, Lemma 1.3 and Section 3, SHA-256 89e51708bd3e115a02841fa9b13782186f4411456a8ed545ab82af72f59ed5aa.
- Lesson 7, Sections 1.1 and 3, SHA-256 89e51708bd3e115a02841fa9b13782186f4411456a8ed545ab82af72f59ed5aa.
- Lesson 7, Lemma 5.1, SHA-256 89e51708bd3e115a02841fa9b13782186f4411456a8ed545ab82af72f59ed5aa.
- Lesson 3, Section 5.6.7, C.1, SHA-256 22fdb7bbcefad3e38d97ecccd151c4965408a305fcb18a72e055e642e215a604.
The complete GNU Free Documentation License 1.2 accompanies this modified chapter. The incorporated human-source component is licensed under version 1.2 or any later version, with no Invariant Sections, Front-Cover Texts or Back-Cover Texts.
History
Source edition. The Stacks Project, by the Stacks Project authors, with its human-source copyright notice above; distributed in the AI Integrated Stacks Project, 2026 edition at revision 565b10e987aba5969b21145a0833f42d69f96790 (30 September 2026). The source publisher is the Stacks Project; the fork distribution and its separately credited AI changes are identified by the pinned repository and its retained source provenance. The source application notice supplies the licence grant, and the pinned transparent source preserves the incorporated source files and their prior network locations.
Modified course edition. Algebraic spaces and stacks — Moduli stacks are algebraic, October 2026, published by the Open Math Courses project, KokunoYumeto/open-math-courses. Adapted and integrated by GPT-6.1 Sol (OpenAI), Codex, Ultra, 5–6 October 2026. The course integrates strong coherent existence, its cohomological and algebraic-space support, polarized proper schemes and all proper flat curve spaces of dimension at most one. It corrects source scope/type errors and supplies the marked return comparisons. Reader display repairs preserve the complete formulas and proofs. Source authorship is retained; no AI copyright holder or human endorsement is asserted. The detailed source loci, exact edition and concrete corrections remain in this chapter. Original eligible expression is additionally dedicated to CC0; the complete inseparable modified chapter retains GFDL 1.2-or-later for component export.